bug_id
stringlengths 1
3
| task_id
stringlengths 64
64
| function_signature
stringlengths 15
364
| prompt_chat
stringlengths 471
20.2k
| code
stringlengths 44
19.8k
| defective
bool 2
classes | project
stringclasses 17
values | prompt_complete
stringlengths 3.07k
22.8k
|
|---|---|---|---|---|---|---|---|
70 | 716a7d9ae35e43b003319dc6deef49a0334a2d3208ff60cbfcd51f005c42b068 | static boolean preserveWhitespace(Node node) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
static boolean preserveWhitespace(Node node) {
// looks only at this element and five levels up, to prevent recursion & needless stack searches
if (node != null && node instanceof Element) {
Element el = (Element) node;
int i = 0;
do {
if (el.tag.preserveWhitespace())
return true;
el = el.parent();
i++;
} while (i < 6 && el != null);
}
return false;
}
```
| static boolean preserveWhitespace(Node node) {
// looks only at this element and five levels up, to prevent recursion & needless stack searches
if (node != null && node instanceof Element) {
Element el = (Element) node;
int i = 0;
do {
if (el.tag.preserveWhitespace())
return true;
el = el.parent();
i++;
} while (i < 6 && el != null);
}
return false;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
static boolean preserveWhitespace(Node node) {
// looks only at this element and five levels up, to prevent recursion & needless stack searches
if (node != null && node instanceof Element) {
Element el = (Element) node;
int i = 0;
do {
if (el.tag.preserveWhitespace())
return true;
el = el.parent();
i++;
} while (i < 6 && el != null);
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 71b33380da77b34e11088737ed631c5c5e1be4b9d4b038bb3f10145d68f69b14 | protected void verifyNonDup(AnnotatedWithParams newOne, int typeIndex, boolean explicit)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected void verifyNonDup(AnnotatedWithParams newOne, int typeIndex, boolean explicit)
{
final int mask = (1 << typeIndex);
_hasNonDefaultCreator = true;
AnnotatedWithParams oldOne = _creators[typeIndex];
// already had an explicitly marked one?
if (oldOne != null) {
boolean verify;
if ((_explicitCreators & mask) != 0) { // already had explicitly annotated, leave as-is
// but skip, if new one not annotated
if (!explicit) {
return;
}
// both explicit: verify
verify = true;
} else {
// otherwise only verify if neither explicitly annotated.
verify = !explicit;
}
// one more thing: ok to override in sub-class
if (verify && (oldOne.getClass() == newOne.getClass())) {
// [databind#667]: avoid one particular class of bogus problems
Class<?> oldType = oldOne.getRawParameterType(0);
Class<?> newType = newOne.getRawParameterType(0);
if (oldType == newType) {
throw new IllegalArgumentException("Conflicting "+TYPE_DESCS[typeIndex]
+" creators: already had explicitly marked "+oldOne+", encountered "+newOne);
}
// otherwise, which one to choose?
if (newType.isAssignableFrom(oldType)) {
// new type more generic, use old
return;
}
// new type more specific, use it
}
}
if (explicit) {
_explicitCreators |= mask;
}
_creators[typeIndex] = _fixAccess(newOne);
}
```
| protected void verifyNonDup(AnnotatedWithParams newOne, int typeIndex, boolean explicit)
{
final int mask = (1 << typeIndex);
_hasNonDefaultCreator = true;
AnnotatedWithParams oldOne = _creators[typeIndex];
// already had an explicitly marked one?
if (oldOne != null) {
boolean verify;
if ((_explicitCreators & mask) != 0) { // already had explicitly annotated, leave as-is
// but skip, if new one not annotated
if (!explicit) {
return;
}
// both explicit: verify
verify = true;
} else {
// otherwise only verify if neither explicitly annotated.
verify = !explicit;
}
// one more thing: ok to override in sub-class
if (verify && (oldOne.getClass() == newOne.getClass())) {
// [databind#667]: avoid one particular class of bogus problems
Class<?> oldType = oldOne.getRawParameterType(0);
Class<?> newType = newOne.getRawParameterType(0);
if (oldType == newType) {
throw new IllegalArgumentException("Conflicting "+TYPE_DESCS[typeIndex]
+" creators: already had explicitly marked "+oldOne+", encountered "+newOne);
}
// otherwise, which one to choose?
if (newType.isAssignableFrom(oldType)) {
// new type more generic, use old
return;
}
// new type more specific, use it
}
}
if (explicit) {
_explicitCreators |= mask;
}
_creators[typeIndex] = _fixAccess(newOne);
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected void verifyNonDup(AnnotatedWithParams newOne, int typeIndex, boolean explicit)
{
final int mask = (1 << typeIndex);
_hasNonDefaultCreator = true;
AnnotatedWithParams oldOne = _creators[typeIndex];
// already had an explicitly marked one?
if (oldOne != null) {
boolean verify;
if ((_explicitCreators & mask) != 0) { // already had explicitly annotated, leave as-is
// but skip, if new one not annotated
if (!explicit) {
return;
}
// both explicit: verify
verify = true;
} else {
// otherwise only verify if neither explicitly annotated.
verify = !explicit;
}
// one more thing: ok to override in sub-class
if (verify && (oldOne.getClass() == newOne.getClass())) {
// [databind#667]: avoid one particular class of bogus problems
Class<?> oldType = oldOne.getRawParameterType(0);
Class<?> newType = newOne.getRawParameterType(0);
if (oldType == newType) {
throw new IllegalArgumentException("Conflicting "+TYPE_DESCS[typeIndex]
+" creators: already had explicitly marked "+oldOne+", encountered "+newOne);
}
// otherwise, which one to choose?
if (newType.isAssignableFrom(oldType)) {
// new type more generic, use old
return;
}
// new type more specific, use it
}
}
if (explicit) {
_explicitCreators |= mask;
}
_creators[typeIndex] = _fixAccess(newOne);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
80 | 7219ad7778a99ef3b0d73170b2a5f80b39782a524709c273724fe7cacfd93873 | void insert(Token.Comment commentToken) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void insert(Token.Comment commentToken) {
Comment comment = new Comment(commentToken.getData());
Node insert = comment;
if (commentToken.bogus) { // xml declarations are emitted as bogus comments (which is right for html, but not xml)
// so we do a bit of a hack and parse the data as an element to pull the attributes out
String data = comment.getData();
if (data.length() > 1 && (data.startsWith("!") || data.startsWith("?"))) {
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri, Parser.xmlParser());
Element el = doc.child(0);
insert = new XmlDeclaration(settings.normalizeTag(el.tagName()), data.startsWith("!"));
insert.attributes().addAll(el.attributes());
}
}
insertNode(insert);
}
```
| void insert(Token.Comment commentToken) {
Comment comment = new Comment(commentToken.getData());
Node insert = comment;
if (commentToken.bogus) { // xml declarations are emitted as bogus comments (which is right for html, but not xml)
// so we do a bit of a hack and parse the data as an element to pull the attributes out
String data = comment.getData();
if (data.length() > 1 && (data.startsWith("!") || data.startsWith("?"))) {
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri, Parser.xmlParser());
Element el = doc.child(0);
insert = new XmlDeclaration(settings.normalizeTag(el.tagName()), data.startsWith("!"));
insert.attributes().addAll(el.attributes());
}
}
insertNode(insert);
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void insert(Token.Comment commentToken) {
Comment comment = new Comment(commentToken.getData());
Node insert = comment;
if (commentToken.bogus) { // xml declarations are emitted as bogus comments (which is right for html, but not xml)
// so we do a bit of a hack and parse the data as an element to pull the attributes out
String data = comment.getData();
if (data.length() > 1 && (data.startsWith("!") || data.startsWith("?"))) {
Document doc = Jsoup.parse("<" + data.substring(1, data.length() -1) + ">", baseUri, Parser.xmlParser());
Element el = doc.child(0);
insert = new XmlDeclaration(settings.normalizeTag(el.tagName()), data.startsWith("!"));
insert.attributes().addAll(el.attributes());
}
}
insertNode(insert);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 72ba902cc8db6fa197d9615bc89f6a5710fa2e8a454ed3e2c9ae5f75d1ddb738 | public void println() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Outputs the record separator.
*
* @throws IOException
* If an I/O error occurs
*/
public void println() throws IOException {
final String recordSeparator = format.getRecordSeparator();
if (recordSeparator != null) {
out.append(recordSeparator);
}
newRecord = true;
}
```
| public void println() throws IOException {
final String recordSeparator = format.getRecordSeparator();
if (recordSeparator != null) {
out.append(recordSeparator);
}
newRecord = true;
} | false | Csv | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Outputs the record separator.
*
* @throws IOException
* If an I/O error occurs
*/
public void println() throws IOException {
final String recordSeparator = format.getRecordSeparator();
if (recordSeparator != null) {
out.append(recordSeparator);
}
newRecord = true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
172 | 72e136b2d897b5e336603109cbaeb847e18c8408928f0fc98308edb63af223d3 | private boolean isQualifiedNameInferred(
String qName, Node n, JSDocInfo info,
Node rhsValue, JSType valueType) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Determines whether a qualified name is inferred.
* NOTE(nicksantos): Determining whether a property is declared or not
* is really really obnoxious.
*
* The problem is that there are two (equally valid) coding styles:
*
* (function() {
* /* The authoritative definition of goog.bar. /
* goog.bar = function() {};
* })();
*
* function f() {
* goog.bar();
* /* Reset goog.bar to a no-op. /
* goog.bar = function() {};
* }
*
* In a dynamic language with first-class functions, it's very difficult
* to know which one the user intended without looking at lots of
* contextual information (the second example demonstrates a small case
* of this, but there are some really pathological cases as well).
*
* The current algorithm checks if either the declaration has
* JsDoc type information, or @const with a known type,
* or a function literal with a name we haven't seen before.
*/
private boolean isQualifiedNameInferred(
String qName, Node n, JSDocInfo info,
Node rhsValue, JSType valueType) {
if (valueType == null) {
return true;
}
// Prototypes of constructors and interfaces are always declared.
if (qName != null && qName.endsWith(".prototype")) {
return false;
}
boolean inferred = true;
if (info != null) {
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (isConstantSymbol(info, n) && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
if (info != null) {
return false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
// Check if this is in a conditional block.
// Functions assigned in conditional blocks are inferred.
for (Node current = n.getParent();
!(current.isScript() || current.isFunction());
current = current.getParent()) {
if (NodeUtil.isControlStructure(current)) {
return true;
}
}
// Check if this is assigned in an inner scope.
// Functions assigned in inner scopes are inferred.
AstFunctionContents contents =
getFunctionAnalysisResults(scope.getRootNode());
if (contents == null ||
!contents.getEscapedQualifiedNames().contains(qName)) {
return false;
}
}
}
return inferred;
}
```
| private boolean isQualifiedNameInferred(
String qName, Node n, JSDocInfo info,
Node rhsValue, JSType valueType) {
if (valueType == null) {
return true;
}
// Prototypes of constructors and interfaces are always declared.
if (qName != null && qName.endsWith(".prototype")) {
return false;
}
boolean inferred = true;
if (info != null) {
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (isConstantSymbol(info, n) && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
if (info != null) {
return false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
// Check if this is in a conditional block.
// Functions assigned in conditional blocks are inferred.
for (Node current = n.getParent();
!(current.isScript() || current.isFunction());
current = current.getParent()) {
if (NodeUtil.isControlStructure(current)) {
return true;
}
}
// Check if this is assigned in an inner scope.
// Functions assigned in inner scopes are inferred.
AstFunctionContents contents =
getFunctionAnalysisResults(scope.getRootNode());
if (contents == null ||
!contents.getEscapedQualifiedNames().contains(qName)) {
return false;
}
}
}
return inferred;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Determines whether a qualified name is inferred.
* NOTE(nicksantos): Determining whether a property is declared or not
* is really really obnoxious.
*
* The problem is that there are two (equally valid) coding styles:
*
* (function() {
* /* The authoritative definition of goog.bar. /
* goog.bar = function() {};
* })();
*
* function f() {
* goog.bar();
* /* Reset goog.bar to a no-op. /
* goog.bar = function() {};
* }
*
* In a dynamic language with first-class functions, it's very difficult
* to know which one the user intended without looking at lots of
* contextual information (the second example demonstrates a small case
* of this, but there are some really pathological cases as well).
*
* The current algorithm checks if either the declaration has
* JsDoc type information, or @const with a known type,
* or a function literal with a name we haven't seen before.
*/
private boolean isQualifiedNameInferred(
String qName, Node n, JSDocInfo info,
Node rhsValue, JSType valueType) {
if (valueType == null) {
return true;
}
// Prototypes of constructors and interfaces are always declared.
if (qName != null && qName.endsWith(".prototype")) {
return false;
}
boolean inferred = true;
if (info != null) {
inferred = !(info.hasType()
|| info.hasEnumParameterType()
|| (isConstantSymbol(info, n) && valueType != null
&& !valueType.isUnknownType())
|| FunctionTypeBuilder.isFunctionTypeDeclaration(info));
}
if (inferred && rhsValue != null && rhsValue.isFunction()) {
if (info != null) {
return false;
} else if (!scope.isDeclared(qName, false) &&
n.isUnscopedQualifiedName()) {
// Check if this is in a conditional block.
// Functions assigned in conditional blocks are inferred.
for (Node current = n.getParent();
!(current.isScript() || current.isFunction());
current = current.getParent()) {
if (NodeUtil.isControlStructure(current)) {
return true;
}
}
// Check if this is assigned in an inner scope.
// Functions assigned in inner scopes are inferred.
AstFunctionContents contents =
getFunctionAnalysisResults(scope.getRootNode());
if (contents == null ||
!contents.getEscapedQualifiedNames().contains(qName)) {
return false;
}
}
}
return inferred;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
39 | 735295c990e4f1991b7201b2f6b40ed063414455e2f1df4c307d351cc678a722 | private static String replaceEach(String text, String[] searchList, String[] replacementList,
boolean repeat, int timeToLive)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Replaces all occurrences of Strings within another String.
* </p>
*
* <p>
* A <code>null</code> reference passed to this method is a no-op, or if
* any "search string" or "string to replace" is null, that replace will be
* ignored.
* </p>
*
* <pre>
* StringUtils.replaceEach(null, *, *, *) = null
* StringUtils.replaceEach("", *, *, *) = ""
* StringUtils.replaceEach("aba", null, null, *) = "aba"
* StringUtils.replaceEach("aba", new String[0], null, *) = "aba"
* StringUtils.replaceEach("aba", null, new String[0], *) = "aba"
* StringUtils.replaceEach("aba", new String[]{"a"}, null, *) = "aba"
* StringUtils.replaceEach("aba", new String[]{"a"}, new String[]{""}, *) = "b"
* StringUtils.replaceEach("aba", new String[]{null}, new String[]{"a"}, *) = "aba"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"w", "t"}, *) = "wcte"
* (example of how it repeats)
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, false) = "dcte"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, true) = "tcte"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "ab"}, *) = IllegalArgumentException
* </pre>
*
* @param text
* text to search and replace in, no-op if null
* @param searchList
* the Strings to search for, no-op if null
* @param replacementList
* the Strings to replace them with, no-op if null
* @param repeat if true, then replace repeatedly
* until there are no more possible replacements or timeToLive < 0
* @param timeToLive
* if less than 0 then there is a circular reference and endless
* loop
* @return the text with any replacements processed, <code>null</code> if
* null String input
* @throws IllegalArgumentException
* if the search is repeating and there is an endless loop due
* to outputs of one being inputs to another
* @throws IndexOutOfBoundsException
* if the lengths of the arrays are not the same (null is ok,
* and/or size 0)
* @since 2.4
*/
private static String replaceEach(String text, String[] searchList, String[] replacementList,
boolean repeat, int timeToLive)
{
// mchyzer Performance note: This creates very few new objects (one major goal)
// let me know if there are performance requests, we can create a harness to measure
if (text == null || text.length() == 0 || searchList == null ||
searchList.length == 0 || replacementList == null || replacementList.length == 0)
{
return text;
}
// if recursing, this shouldnt be less than 0
if (timeToLive < 0) {
throw new IllegalStateException("TimeToLive of " + timeToLive + " is less than 0: " + text);
}
int searchLength = searchList.length;
int replacementLength = replacementList.length;
// make sure lengths are ok, these need to be equal
if (searchLength != replacementLength) {
throw new IllegalArgumentException("Search and Replace array lengths don't match: "
+ searchLength
+ " vs "
+ replacementLength);
}
// keep track of which still have matches
boolean[] noMoreMatchesForReplIndex = new boolean[searchLength];
// index on index that the match was found
int textIndex = -1;
int replaceIndex = -1;
int tempIndex = -1;
// index of replace array that will replace the search string found
// NOTE: logic duplicated below START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i]);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic mostly below END
// no search strings found, we are done
if (textIndex == -1) {
return text;
}
int start = 0;
// get a good guess on the size of the result buffer so it doesnt have to double if it goes over a bit
int increase = 0;
// count the replacement text elements that are larger than their corresponding text being replaced
for (int i = 0; i < searchList.length; i++) {
int greater = replacementList[i].length() - searchList[i].length();
if (greater > 0) {
increase += 3 * greater; // assume 3 matches
}
}
// have upper-bound at 20% increase, then let Java take over
increase = Math.min(increase, text.length() / 5);
StringBuilder buf = new StringBuilder(text.length() + increase);
while (textIndex != -1) {
for (int i = start; i < textIndex; i++) {
buf.append(text.charAt(i));
}
buf.append(replacementList[replaceIndex]);
start = textIndex + searchList[replaceIndex].length();
textIndex = -1;
replaceIndex = -1;
tempIndex = -1;
// find the next earliest match
// NOTE: logic mostly duplicated above START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i], start);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic duplicated above END
}
int textLength = text.length();
for (int i = start; i < textLength; i++) {
buf.append(text.charAt(i));
}
String result = buf.toString();
if (!repeat) {
return result;
}
return replaceEach(result, searchList, replacementList, repeat, timeToLive - 1);
}
```
| private static String replaceEach(String text, String[] searchList, String[] replacementList,
boolean repeat, int timeToLive)
{
// mchyzer Performance note: This creates very few new objects (one major goal)
// let me know if there are performance requests, we can create a harness to measure
if (text == null || text.length() == 0 || searchList == null ||
searchList.length == 0 || replacementList == null || replacementList.length == 0)
{
return text;
}
// if recursing, this shouldnt be less than 0
if (timeToLive < 0) {
throw new IllegalStateException("TimeToLive of " + timeToLive + " is less than 0: " + text);
}
int searchLength = searchList.length;
int replacementLength = replacementList.length;
// make sure lengths are ok, these need to be equal
if (searchLength != replacementLength) {
throw new IllegalArgumentException("Search and Replace array lengths don't match: "
+ searchLength
+ " vs "
+ replacementLength);
}
// keep track of which still have matches
boolean[] noMoreMatchesForReplIndex = new boolean[searchLength];
// index on index that the match was found
int textIndex = -1;
int replaceIndex = -1;
int tempIndex = -1;
// index of replace array that will replace the search string found
// NOTE: logic duplicated below START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i]);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic mostly below END
// no search strings found, we are done
if (textIndex == -1) {
return text;
}
int start = 0;
// get a good guess on the size of the result buffer so it doesnt have to double if it goes over a bit
int increase = 0;
// count the replacement text elements that are larger than their corresponding text being replaced
for (int i = 0; i < searchList.length; i++) {
int greater = replacementList[i].length() - searchList[i].length();
if (greater > 0) {
increase += 3 * greater; // assume 3 matches
}
}
// have upper-bound at 20% increase, then let Java take over
increase = Math.min(increase, text.length() / 5);
StringBuilder buf = new StringBuilder(text.length() + increase);
while (textIndex != -1) {
for (int i = start; i < textIndex; i++) {
buf.append(text.charAt(i));
}
buf.append(replacementList[replaceIndex]);
start = textIndex + searchList[replaceIndex].length();
textIndex = -1;
replaceIndex = -1;
tempIndex = -1;
// find the next earliest match
// NOTE: logic mostly duplicated above START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i], start);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic duplicated above END
}
int textLength = text.length();
for (int i = start; i < textLength; i++) {
buf.append(text.charAt(i));
}
String result = buf.toString();
if (!repeat) {
return result;
}
return replaceEach(result, searchList, replacementList, repeat, timeToLive - 1);
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Replaces all occurrences of Strings within another String.
* </p>
*
* <p>
* A <code>null</code> reference passed to this method is a no-op, or if
* any "search string" or "string to replace" is null, that replace will be
* ignored.
* </p>
*
* <pre>
* StringUtils.replaceEach(null, *, *, *) = null
* StringUtils.replaceEach("", *, *, *) = ""
* StringUtils.replaceEach("aba", null, null, *) = "aba"
* StringUtils.replaceEach("aba", new String[0], null, *) = "aba"
* StringUtils.replaceEach("aba", null, new String[0], *) = "aba"
* StringUtils.replaceEach("aba", new String[]{"a"}, null, *) = "aba"
* StringUtils.replaceEach("aba", new String[]{"a"}, new String[]{""}, *) = "b"
* StringUtils.replaceEach("aba", new String[]{null}, new String[]{"a"}, *) = "aba"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"w", "t"}, *) = "wcte"
* (example of how it repeats)
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, false) = "dcte"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, true) = "tcte"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "ab"}, *) = IllegalArgumentException
* </pre>
*
* @param text
* text to search and replace in, no-op if null
* @param searchList
* the Strings to search for, no-op if null
* @param replacementList
* the Strings to replace them with, no-op if null
* @param repeat if true, then replace repeatedly
* until there are no more possible replacements or timeToLive < 0
* @param timeToLive
* if less than 0 then there is a circular reference and endless
* loop
* @return the text with any replacements processed, <code>null</code> if
* null String input
* @throws IllegalArgumentException
* if the search is repeating and there is an endless loop due
* to outputs of one being inputs to another
* @throws IndexOutOfBoundsException
* if the lengths of the arrays are not the same (null is ok,
* and/or size 0)
* @since 2.4
*/
private static String replaceEach(String text, String[] searchList, String[] replacementList,
boolean repeat, int timeToLive)
{
// mchyzer Performance note: This creates very few new objects (one major goal)
// let me know if there are performance requests, we can create a harness to measure
if (text == null || text.length() == 0 || searchList == null ||
searchList.length == 0 || replacementList == null || replacementList.length == 0)
{
return text;
}
// if recursing, this shouldnt be less than 0
if (timeToLive < 0) {
throw new IllegalStateException("TimeToLive of " + timeToLive + " is less than 0: " + text);
}
int searchLength = searchList.length;
int replacementLength = replacementList.length;
// make sure lengths are ok, these need to be equal
if (searchLength != replacementLength) {
throw new IllegalArgumentException("Search and Replace array lengths don't match: "
+ searchLength
+ " vs "
+ replacementLength);
}
// keep track of which still have matches
boolean[] noMoreMatchesForReplIndex = new boolean[searchLength];
// index on index that the match was found
int textIndex = -1;
int replaceIndex = -1;
int tempIndex = -1;
// index of replace array that will replace the search string found
// NOTE: logic duplicated below START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i]);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic mostly below END
// no search strings found, we are done
if (textIndex == -1) {
return text;
}
int start = 0;
// get a good guess on the size of the result buffer so it doesnt have to double if it goes over a bit
int increase = 0;
// count the replacement text elements that are larger than their corresponding text being replaced
for (int i = 0; i < searchList.length; i++) {
int greater = replacementList[i].length() - searchList[i].length();
if (greater > 0) {
increase += 3 * greater; // assume 3 matches
}
}
// have upper-bound at 20% increase, then let Java take over
increase = Math.min(increase, text.length() / 5);
StringBuilder buf = new StringBuilder(text.length() + increase);
while (textIndex != -1) {
for (int i = start; i < textIndex; i++) {
buf.append(text.charAt(i));
}
buf.append(replacementList[replaceIndex]);
start = textIndex + searchList[replaceIndex].length();
textIndex = -1;
replaceIndex = -1;
tempIndex = -1;
// find the next earliest match
// NOTE: logic mostly duplicated above START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i], start);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic duplicated above END
}
int textLength = text.length();
for (int i = start; i < textLength; i++) {
buf.append(text.charAt(i));
}
String result = buf.toString();
if (!repeat) {
return result;
}
return replaceEach(result, searchList, replacementList, repeat, timeToLive - 1);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
9 | 738af86a4e7632bf744d1e688d9a07f2dab170a22a2db41a1058a673fcebf625 | public TimeSeries createCopy(RegularTimePeriod start, RegularTimePeriod end)
throws CloneNotSupportedException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a new timeseries by copying a subset of the data in this time
* series.
*
* @param start the first time period to copy (<code>null</code> not
* permitted).
* @param end the last time period to copy (<code>null</code> not
* permitted).
*
* @return A time series containing a copy of this time series from start
* until end.
*
* @throws CloneNotSupportedException if there is a cloning problem.
*/
public TimeSeries createCopy(RegularTimePeriod start, RegularTimePeriod end)
throws CloneNotSupportedException {
if (start == null) {
throw new IllegalArgumentException("Null 'start' argument.");
}
if (end == null) {
throw new IllegalArgumentException("Null 'end' argument.");
}
if (start.compareTo(end) > 0) {
throw new IllegalArgumentException(
"Requires start on or before end.");
}
boolean emptyRange = false;
int startIndex = getIndex(start);
if (startIndex < 0) {
startIndex = -(startIndex + 1);
if (startIndex == this.data.size()) {
emptyRange = true; // start is after last data item
}
}
int endIndex = getIndex(end);
if (endIndex < 0) { // end period is not in original series
endIndex = -(endIndex + 1); // this is first item AFTER end period
endIndex = endIndex - 1; // so this is last item BEFORE end
}
if (endIndex < 0) {
emptyRange = true;
}
if (emptyRange) {
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
return copy;
}
else {
return createCopy(startIndex, endIndex);
}
}
```
| public TimeSeries createCopy(RegularTimePeriod start, RegularTimePeriod end)
throws CloneNotSupportedException {
if (start == null) {
throw new IllegalArgumentException("Null 'start' argument.");
}
if (end == null) {
throw new IllegalArgumentException("Null 'end' argument.");
}
if (start.compareTo(end) > 0) {
throw new IllegalArgumentException(
"Requires start on or before end.");
}
boolean emptyRange = false;
int startIndex = getIndex(start);
if (startIndex < 0) {
startIndex = -(startIndex + 1);
if (startIndex == this.data.size()) {
emptyRange = true; // start is after last data item
}
}
int endIndex = getIndex(end);
if (endIndex < 0) { // end period is not in original series
endIndex = -(endIndex + 1); // this is first item AFTER end period
endIndex = endIndex - 1; // so this is last item BEFORE end
}
if (endIndex < 0) {
emptyRange = true;
}
if (emptyRange) {
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
return copy;
}
else {
return createCopy(startIndex, endIndex);
}
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a new timeseries by copying a subset of the data in this time
* series.
*
* @param start the first time period to copy (<code>null</code> not
* permitted).
* @param end the last time period to copy (<code>null</code> not
* permitted).
*
* @return A time series containing a copy of this time series from start
* until end.
*
* @throws CloneNotSupportedException if there is a cloning problem.
*/
public TimeSeries createCopy(RegularTimePeriod start, RegularTimePeriod end)
throws CloneNotSupportedException {
if (start == null) {
throw new IllegalArgumentException("Null 'start' argument.");
}
if (end == null) {
throw new IllegalArgumentException("Null 'end' argument.");
}
if (start.compareTo(end) > 0) {
throw new IllegalArgumentException(
"Requires start on or before end.");
}
boolean emptyRange = false;
int startIndex = getIndex(start);
if (startIndex < 0) {
startIndex = -(startIndex + 1);
if (startIndex == this.data.size()) {
emptyRange = true; // start is after last data item
}
}
int endIndex = getIndex(end);
if (endIndex < 0) { // end period is not in original series
endIndex = -(endIndex + 1); // this is first item AFTER end period
endIndex = endIndex - 1; // so this is last item BEFORE end
}
if (endIndex < 0) {
emptyRange = true;
}
if (emptyRange) {
TimeSeries copy = (TimeSeries) super.clone();
copy.data = new java.util.ArrayList();
return copy;
}
else {
return createCopy(startIndex, endIndex);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
51 | 738f7e3d73f946d49ea55fca0bcdee916b8fe7545cc696d24dfee940cdc8f271 | protected final double doSolve() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
if (x == x1) {
final double delta = FastMath.max(rtol * FastMath.abs(x1),
atol);
// Update formula cannot make any progress: Update the
// search interval.
x0 = 0.5 * (x0 + x1 - delta);
f0 = computeObjectiveValue(x0);
}
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
```
| protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
if (x == x1) {
final double delta = FastMath.max(rtol * FastMath.abs(x1),
atol);
// Update formula cannot make any progress: Update the
// search interval.
x0 = 0.5 * (x0 + x1 - delta);
f0 = computeObjectiveValue(x0);
}
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
protected final double doSolve() {
// Get initial solution
double x0 = getMin();
double x1 = getMax();
double f0 = computeObjectiveValue(x0);
double f1 = computeObjectiveValue(x1);
// If one of the bounds is the exact root, return it. Since these are
// not under-approximations or over-approximations, we can return them
// regardless of the allowed solutions.
if (f0 == 0.0) {
return x0;
}
if (f1 == 0.0) {
return x1;
}
// Verify bracketing of initial solution.
verifyBracketing(x0, x1);
// Get accuracies.
final double ftol = getFunctionValueAccuracy();
final double atol = getAbsoluteAccuracy();
final double rtol = getRelativeAccuracy();
// Keep track of inverted intervals, meaning that the left bound is
// larger than the right bound.
boolean inverted = false;
// Keep finding better approximations.
while (true) {
// Calculate the next approximation.
final double x = x1 - ((f1 * (x1 - x0)) / (f1 - f0));
final double fx = computeObjectiveValue(x);
// If the new approximation is the exact root, return it. Since
// this is not an under-approximation or an over-approximation,
// we can return it regardless of the allowed solutions.
if (fx == 0.0) {
return x;
}
// Update the bounds with the new approximation.
if (f1 * fx < 0) {
// The value of x1 has switched to the other bound, thus inverting
// the interval.
x0 = x1;
f0 = f1;
inverted = !inverted;
} else {
switch (method) {
case ILLINOIS:
f0 *= 0.5;
break;
case PEGASUS:
f0 *= f1 / (f1 + fx);
break;
case REGULA_FALSI:
if (x == x1) {
final double delta = FastMath.max(rtol * FastMath.abs(x1),
atol);
// Update formula cannot make any progress: Update the
// search interval.
x0 = 0.5 * (x0 + x1 - delta);
f0 = computeObjectiveValue(x0);
}
break;
default:
// Should never happen.
throw new MathInternalError();
}
}
// Update from [x0, x1] to [x0, x].
x1 = x;
f1 = fx;
// If the function value of the last approximation is too small,
// given the function value accuracy, then we can't get closer to
// the root than we already are.
if (FastMath.abs(f1) <= ftol) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
if (inverted) {
return x1;
}
break;
case RIGHT_SIDE:
if (!inverted) {
return x1;
}
break;
case BELOW_SIDE:
if (f1 <= 0) {
return x1;
}
break;
case ABOVE_SIDE:
if (f1 >= 0) {
return x1;
}
break;
default:
throw new MathInternalError();
}
}
// If the current interval is within the given accuracies, we
// are satisfied with the current approximation.
if (FastMath.abs(x1 - x0) < FastMath.max(rtol * FastMath.abs(x1),
atol)) {
switch (allowed) {
case ANY_SIDE:
return x1;
case LEFT_SIDE:
return inverted ? x1 : x0;
case RIGHT_SIDE:
return inverted ? x0 : x1;
case BELOW_SIDE:
return (f1 <= 0) ? x1 : x0;
case ABOVE_SIDE:
return (f1 >= 0) ? x1 : x0;
default:
throw new MathInternalError();
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
45 | 73e2b2bf7730b9d0c773e9dc9033fd123269663039c62fcd61972892835e0d31 | void resetInsertionMode() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void resetInsertionMode() {
boolean last = false;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element node = stack.get(pos);
if (pos == 0) {
last = true;
node = contextElement;
}
String name = node.nodeName();
if ("select".equals(name)) {
transition(HtmlTreeBuilderState.InSelect);
break; // frag
} else if (("td".equals(name) || "th".equals(name) && !last)) {
transition(HtmlTreeBuilderState.InCell);
break;
} else if ("tr".equals(name)) {
transition(HtmlTreeBuilderState.InRow);
break;
} else if ("tbody".equals(name) || "thead".equals(name) || "tfoot".equals(name)) {
transition(HtmlTreeBuilderState.InTableBody);
break;
} else if ("caption".equals(name)) {
transition(HtmlTreeBuilderState.InCaption);
break;
} else if ("colgroup".equals(name)) {
transition(HtmlTreeBuilderState.InColumnGroup);
break; // frag
} else if ("table".equals(name)) {
transition(HtmlTreeBuilderState.InTable);
break;
} else if ("head".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
} else if ("body".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break;
} else if ("frameset".equals(name)) {
transition(HtmlTreeBuilderState.InFrameset);
break; // frag
} else if ("html".equals(name)) {
transition(HtmlTreeBuilderState.BeforeHead);
break; // frag
} else if (last) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
}
}
}
```
| void resetInsertionMode() {
boolean last = false;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element node = stack.get(pos);
if (pos == 0) {
last = true;
node = contextElement;
}
String name = node.nodeName();
if ("select".equals(name)) {
transition(HtmlTreeBuilderState.InSelect);
break; // frag
} else if (("td".equals(name) || "th".equals(name) && !last)) {
transition(HtmlTreeBuilderState.InCell);
break;
} else if ("tr".equals(name)) {
transition(HtmlTreeBuilderState.InRow);
break;
} else if ("tbody".equals(name) || "thead".equals(name) || "tfoot".equals(name)) {
transition(HtmlTreeBuilderState.InTableBody);
break;
} else if ("caption".equals(name)) {
transition(HtmlTreeBuilderState.InCaption);
break;
} else if ("colgroup".equals(name)) {
transition(HtmlTreeBuilderState.InColumnGroup);
break; // frag
} else if ("table".equals(name)) {
transition(HtmlTreeBuilderState.InTable);
break;
} else if ("head".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
} else if ("body".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break;
} else if ("frameset".equals(name)) {
transition(HtmlTreeBuilderState.InFrameset);
break; // frag
} else if ("html".equals(name)) {
transition(HtmlTreeBuilderState.BeforeHead);
break; // frag
} else if (last) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
}
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void resetInsertionMode() {
boolean last = false;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element node = stack.get(pos);
if (pos == 0) {
last = true;
node = contextElement;
}
String name = node.nodeName();
if ("select".equals(name)) {
transition(HtmlTreeBuilderState.InSelect);
break; // frag
} else if (("td".equals(name) || "th".equals(name) && !last)) {
transition(HtmlTreeBuilderState.InCell);
break;
} else if ("tr".equals(name)) {
transition(HtmlTreeBuilderState.InRow);
break;
} else if ("tbody".equals(name) || "thead".equals(name) || "tfoot".equals(name)) {
transition(HtmlTreeBuilderState.InTableBody);
break;
} else if ("caption".equals(name)) {
transition(HtmlTreeBuilderState.InCaption);
break;
} else if ("colgroup".equals(name)) {
transition(HtmlTreeBuilderState.InColumnGroup);
break; // frag
} else if ("table".equals(name)) {
transition(HtmlTreeBuilderState.InTable);
break;
} else if ("head".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
} else if ("body".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break;
} else if ("frameset".equals(name)) {
transition(HtmlTreeBuilderState.InFrameset);
break; // frag
} else if ("html".equals(name)) {
transition(HtmlTreeBuilderState.BeforeHead);
break; // frag
} else if (last) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
102 | 740ae59a13fbd79a8ceb2594b86603fdf0b2c8bb9f079eadbdad4d8ab9f65c32 | public double chiSquare(double[] expected, long[] observed)
throws IllegalArgumentException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* {@inheritDoc}
* <p><strong>Note: </strong>This implementation rescales the
* <code>expected</code> array if necessary to ensure that the sum of the
* expected and observed counts are equal.</p>
*
* @param observed array of observed frequency counts
* @param expected array of expected frequency counts
* @return chi-square test statistic
* @throws IllegalArgumentException if preconditions are not met
* or length is less than 2
*/
public double chiSquare(double[] expected, long[] observed)
throws IllegalArgumentException {
if ((expected.length < 2) || (expected.length != observed.length)) {
throw new IllegalArgumentException(
"observed, expected array lengths incorrect");
}
if (!isPositive(expected) || !isNonNegative(observed)) {
throw new IllegalArgumentException(
"observed counts must be non-negative and expected counts must be postive");
}
double sumSq = 0.0d;
double dev = 0.0d;
for (int i = 0; i < observed.length; i++) {
dev = ((double) observed[i] - expected[i]);
sumSq += dev * dev / expected[i];
}
return sumSq;
}
```
| public double chiSquare(double[] expected, long[] observed)
throws IllegalArgumentException {
if ((expected.length < 2) || (expected.length != observed.length)) {
throw new IllegalArgumentException(
"observed, expected array lengths incorrect");
}
if (!isPositive(expected) || !isNonNegative(observed)) {
throw new IllegalArgumentException(
"observed counts must be non-negative and expected counts must be postive");
}
double sumSq = 0.0d;
double dev = 0.0d;
for (int i = 0; i < observed.length; i++) {
dev = ((double) observed[i] - expected[i]);
sumSq += dev * dev / expected[i];
}
return sumSq;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* {@inheritDoc}
* <p><strong>Note: </strong>This implementation rescales the
* <code>expected</code> array if necessary to ensure that the sum of the
* expected and observed counts are equal.</p>
*
* @param observed array of observed frequency counts
* @param expected array of expected frequency counts
* @return chi-square test statistic
* @throws IllegalArgumentException if preconditions are not met
* or length is less than 2
*/
public double chiSquare(double[] expected, long[] observed)
throws IllegalArgumentException {
if ((expected.length < 2) || (expected.length != observed.length)) {
throw new IllegalArgumentException(
"observed, expected array lengths incorrect");
}
if (!isPositive(expected) || !isNonNegative(observed)) {
throw new IllegalArgumentException(
"observed counts must be non-negative and expected counts must be postive");
}
double sumSq = 0.0d;
double dev = 0.0d;
for (int i = 0; i < observed.length; i++) {
dev = ((double) observed[i] - expected[i]);
sumSq += dev * dev / expected[i];
}
return sumSq;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
72 | 7440aecfaf638c753abe940ed8eab6294a05fbb13ab79b7f89d8ba43b7d51394 | private static String cacheString(final char[] charBuf, final String[] stringCache, final int start, final int count) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Caches short strings, as a flywheel pattern, to reduce GC load. Just for this doc, to prevent leaks.
* <p />
* Simplistic, and on hash collisions just falls back to creating a new string, vs a full HashMap with Entry list.
* That saves both having to create objects as hash keys, and running through the entry list, at the expense of
* some more duplicates.
*/
private static String cacheString(final char[] charBuf, final String[] stringCache, final int start, final int count) {
// limit (no cache):
if (count > maxStringCacheLen)
return new String(charBuf, start, count);
// calculate hash:
int hash = 0;
int offset = start;
for (int i = 0; i < count; i++) {
hash = 31 * hash + charBuf[offset++];
}
// get from cache
final int index = hash & stringCache.length - 1;
String cached = stringCache[index];
if (cached == null) { // miss, add
cached = new String(charBuf, start, count);
stringCache[index] = cached;
} else { // hashcode hit, check equality
if (rangeEquals(charBuf, start, count, cached)) { // hit
return cached;
} else { // hashcode conflict
cached = new String(charBuf, start, count);
stringCache[index] = cached; // update the cache, as recently used strings are more likely to show up again
}
}
return cached;
}
```
| private static String cacheString(final char[] charBuf, final String[] stringCache, final int start, final int count) {
// limit (no cache):
if (count > maxStringCacheLen)
return new String(charBuf, start, count);
// calculate hash:
int hash = 0;
int offset = start;
for (int i = 0; i < count; i++) {
hash = 31 * hash + charBuf[offset++];
}
// get from cache
final int index = hash & stringCache.length - 1;
String cached = stringCache[index];
if (cached == null) { // miss, add
cached = new String(charBuf, start, count);
stringCache[index] = cached;
} else { // hashcode hit, check equality
if (rangeEquals(charBuf, start, count, cached)) { // hit
return cached;
} else { // hashcode conflict
cached = new String(charBuf, start, count);
stringCache[index] = cached; // update the cache, as recently used strings are more likely to show up again
}
}
return cached;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Caches short strings, as a flywheel pattern, to reduce GC load. Just for this doc, to prevent leaks.
* <p />
* Simplistic, and on hash collisions just falls back to creating a new string, vs a full HashMap with Entry list.
* That saves both having to create objects as hash keys, and running through the entry list, at the expense of
* some more duplicates.
*/
private static String cacheString(final char[] charBuf, final String[] stringCache, final int start, final int count) {
// limit (no cache):
if (count > maxStringCacheLen)
return new String(charBuf, start, count);
// calculate hash:
int hash = 0;
int offset = start;
for (int i = 0; i < count; i++) {
hash = 31 * hash + charBuf[offset++];
}
// get from cache
final int index = hash & stringCache.length - 1;
String cached = stringCache[index];
if (cached == null) { // miss, add
cached = new String(charBuf, start, count);
stringCache[index] = cached;
} else { // hashcode hit, check equality
if (rangeEquals(charBuf, start, count, cached)) { // hit
return cached;
} else { // hashcode conflict
cached = new String(charBuf, start, count);
stringCache[index] = cached; // update the cache, as recently used strings are more likely to show up again
}
}
return cached;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 7476d3fd4ff7ca43103dd88cac24e21bc51e019f06122b05361d8fe7ac1d6f96 | public Period normalizedStandard(PeriodType type) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Normalizes this period using standard rules, assuming a 12 month year,
* 7 day week, 24 hour day, 60 minute hour and 60 second minute,
* providing control over how the result is split into fields.
* <p>
* This method allows you to normalize a period.
* However to achieve this it makes the assumption that all years are
* 12 months, all weeks are 7 days, all days are 24 hours,
* all hours are 60 minutes and all minutes are 60 seconds. This is not
* true when daylight savings time is considered, and may also not be true
* for some chronologies. However, it is included as it is a useful operation
* for many applications and business rules.
* <p>
* If the period contains years or months, then the months will be
* normalized to be between 0 and 11. The days field and below will be
* normalized as necessary, however this will not overflow into the months
* field. Thus a period of 1 year 15 months will normalize to 2 years 3 months.
* But a period of 1 month 40 days will remain as 1 month 40 days.
* <p>
* The PeriodType parameter controls how the result is created. It allows
* you to omit certain fields from the result if desired. For example,
* you may not want the result to include weeks, in which case you pass
* in <code>PeriodType.yearMonthDayTime()</code>.
*
* @param type the period type of the new period, null means standard type
* @return a normalized period equivalent to this period
* @throws ArithmeticException if any field is too large to be represented
* @throws UnsupportedOperationException if this period contains non-zero
* years or months but the specified period type does not support them
* @since 1.5
*/
//-----------------------------------------------------------------------
public Period normalizedStandard(PeriodType type) {
type = DateTimeUtils.getPeriodType(type);
long millis = getMillis(); // no overflow can happen, even with Integer.MAX_VALUEs
millis += (((long) getSeconds()) * ((long) DateTimeConstants.MILLIS_PER_SECOND));
millis += (((long) getMinutes()) * ((long) DateTimeConstants.MILLIS_PER_MINUTE));
millis += (((long) getHours()) * ((long) DateTimeConstants.MILLIS_PER_HOUR));
millis += (((long) getDays()) * ((long) DateTimeConstants.MILLIS_PER_DAY));
millis += (((long) getWeeks()) * ((long) DateTimeConstants.MILLIS_PER_WEEK));
Period result = new Period(millis, type, ISOChronology.getInstanceUTC());
int years = getYears();
int months = getMonths();
if (years != 0 || months != 0) {
years = FieldUtils.safeAdd(years, months / 12);
months = months % 12;
if (years != 0) {
result = result.withYears(years);
}
if (months != 0) {
result = result.withMonths(months);
}
}
return result;
}
```
| public Period normalizedStandard(PeriodType type) {
type = DateTimeUtils.getPeriodType(type);
long millis = getMillis(); // no overflow can happen, even with Integer.MAX_VALUEs
millis += (((long) getSeconds()) * ((long) DateTimeConstants.MILLIS_PER_SECOND));
millis += (((long) getMinutes()) * ((long) DateTimeConstants.MILLIS_PER_MINUTE));
millis += (((long) getHours()) * ((long) DateTimeConstants.MILLIS_PER_HOUR));
millis += (((long) getDays()) * ((long) DateTimeConstants.MILLIS_PER_DAY));
millis += (((long) getWeeks()) * ((long) DateTimeConstants.MILLIS_PER_WEEK));
Period result = new Period(millis, type, ISOChronology.getInstanceUTC());
int years = getYears();
int months = getMonths();
if (years != 0 || months != 0) {
years = FieldUtils.safeAdd(years, months / 12);
months = months % 12;
if (years != 0) {
result = result.withYears(years);
}
if (months != 0) {
result = result.withMonths(months);
}
}
return result;
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Normalizes this period using standard rules, assuming a 12 month year,
* 7 day week, 24 hour day, 60 minute hour and 60 second minute,
* providing control over how the result is split into fields.
* <p>
* This method allows you to normalize a period.
* However to achieve this it makes the assumption that all years are
* 12 months, all weeks are 7 days, all days are 24 hours,
* all hours are 60 minutes and all minutes are 60 seconds. This is not
* true when daylight savings time is considered, and may also not be true
* for some chronologies. However, it is included as it is a useful operation
* for many applications and business rules.
* <p>
* If the period contains years or months, then the months will be
* normalized to be between 0 and 11. The days field and below will be
* normalized as necessary, however this will not overflow into the months
* field. Thus a period of 1 year 15 months will normalize to 2 years 3 months.
* But a period of 1 month 40 days will remain as 1 month 40 days.
* <p>
* The PeriodType parameter controls how the result is created. It allows
* you to omit certain fields from the result if desired. For example,
* you may not want the result to include weeks, in which case you pass
* in <code>PeriodType.yearMonthDayTime()</code>.
*
* @param type the period type of the new period, null means standard type
* @return a normalized period equivalent to this period
* @throws ArithmeticException if any field is too large to be represented
* @throws UnsupportedOperationException if this period contains non-zero
* years or months but the specified period type does not support them
* @since 1.5
*/
//-----------------------------------------------------------------------
public Period normalizedStandard(PeriodType type) {
type = DateTimeUtils.getPeriodType(type);
long millis = getMillis(); // no overflow can happen, even with Integer.MAX_VALUEs
millis += (((long) getSeconds()) * ((long) DateTimeConstants.MILLIS_PER_SECOND));
millis += (((long) getMinutes()) * ((long) DateTimeConstants.MILLIS_PER_MINUTE));
millis += (((long) getHours()) * ((long) DateTimeConstants.MILLIS_PER_HOUR));
millis += (((long) getDays()) * ((long) DateTimeConstants.MILLIS_PER_DAY));
millis += (((long) getWeeks()) * ((long) DateTimeConstants.MILLIS_PER_WEEK));
Period result = new Period(millis, type, ISOChronology.getInstanceUTC());
int years = getYears();
int months = getMonths();
if (years != 0 || months != 0) {
years = FieldUtils.safeAdd(years, months / 12);
months = months % 12;
if (years != 0) {
result = result.withYears(years);
}
if (months != 0) {
result = result.withMonths(months);
}
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
91 | 7497534e3c646c6f4f744b3e4843c3bf8cd7dac4de54d4c0ec927c3a72ed1e21 | public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Since this pass reports errors only when a global {@code this} keyword
* is encountered, there is no reason to traverse non global contexts.
*/
public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {}; // or
// var a = {x: function() {}};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN ||
// object literal keys
pType == Token.STRING ||
pType == Token.NUMBER)) {
return false;
}
// Don't traverse functions that are getting lent to a prototype.
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
}
```
| public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {}; // or
// var a = {x: function() {}};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN ||
// object literal keys
pType == Token.STRING ||
pType == Token.NUMBER)) {
return false;
}
// Don't traverse functions that are getting lent to a prototype.
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Since this pass reports errors only when a global {@code this} keyword
* is encountered, there is no reason to traverse non global contexts.
*/
public boolean shouldTraverse(NodeTraversal t, Node n, Node parent) {
if (n.getType() == Token.FUNCTION) {
// Don't traverse functions that are constructors or have the @this
// or @override annotation.
JSDocInfo jsDoc = getFunctionJsDocInfo(n);
if (jsDoc != null &&
(jsDoc.isConstructor() ||
jsDoc.isInterface() ||
jsDoc.hasThisType() ||
jsDoc.isOverride())) {
return false;
}
// Don't traverse functions unless they would normally
// be able to have a @this annotation associated with them. e.g.,
// var a = function() { }; // or
// function a() {} // or
// a.x = function() {}; // or
// var a = {x: function() {}};
int pType = parent.getType();
if (!(pType == Token.BLOCK ||
pType == Token.SCRIPT ||
pType == Token.NAME ||
pType == Token.ASSIGN ||
// object literal keys
pType == Token.STRING ||
pType == Token.NUMBER)) {
return false;
}
// Don't traverse functions that are getting lent to a prototype.
}
if (parent != null && parent.getType() == Token.ASSIGN) {
Node lhs = parent.getFirstChild();
Node rhs = lhs.getNext();
if (n == lhs) {
// Always traverse the left side of the assignment. To handle
// nested assignments properly (e.g., (a = this).property = c;),
// assignLhsChild should not be overridden.
if (assignLhsChild == null) {
assignLhsChild = lhs;
}
} else {
// Only traverse the right side if it's not an assignment to a prototype
// property or subproperty.
if (NodeUtil.isGet(lhs)) {
if (lhs.getType() == Token.GETPROP &&
lhs.getLastChild().getString().equals("prototype")) {
return false;
}
Node llhs = lhs.getFirstChild();
if (llhs.getType() == Token.GETPROP &&
llhs.getLastChild().getString().equals("prototype")) {
return false;
}
}
}
}
return true;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 753b8cdf0e48e3ca89cfed7f8bb89dd9ecd76b7273078b963f6a04e875d83e49 | public final Object computeValue(EvalContext context) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public final Object computeValue(EvalContext context) {
return compute(args[0].computeValue(context), args[1].computeValue(context))
? Boolean.TRUE : Boolean.FALSE;
}
```
| public final Object computeValue(EvalContext context) {
return compute(args[0].computeValue(context), args[1].computeValue(context))
? Boolean.TRUE : Boolean.FALSE;
} | true | JxPath | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public final Object computeValue(EvalContext context) {
return compute(args[0].computeValue(context), args[1].computeValue(context))
? Boolean.TRUE : Boolean.FALSE;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
56 | 754b0d37f33b732d9c7b8e3081ad3e208780ef4e00e5db87963c2b1506757919 | public String getLine(int lineNumber) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Gets the source line for the indicated line number.
*
* @param lineNumber the line number, 1 being the first line of the file.
* @return The line indicated. Does not include the newline at the end
* of the file. Returns {@code null} if it does not exist,
* or if there was an IO exception.
*/
public String getLine(int lineNumber) {
String js = "";
try {
// NOTE(nicksantos): Right now, this is optimized for few warnings.
// This is probably the right trade-off, but will be slow if there
// are lots of warnings in one file.
js = getCode();
} catch (IOException e) {
return null;
}
int pos = 0;
int startLine = 1;
// If we've saved a previous offset and it's for a line less than the
// one we're searching for, then start at that point.
if (lineNumber >= lastLine) {
pos = lastOffset;
startLine = lastLine;
}
for (int n = startLine; n < lineNumber; n++) {
int nextpos = js.indexOf('\n', pos);
if (nextpos == -1) {
return null;
}
pos = nextpos + 1;
}
// Remember this offset for the next search we do.
lastOffset = pos;
lastLine = lineNumber;
if (js.indexOf('\n', pos) == -1) {
// If next new line cannot be found, there are two cases
// 1. pos already reaches the end of file, then null should be returned
// 2. otherwise, return the contents between pos and the end of file.
if (pos >= js.length()) {
return null;
} else {
return js.substring(pos, js.length());
}
} else {
return js.substring(pos, js.indexOf('\n', pos));
}
}
```
| public String getLine(int lineNumber) {
String js = "";
try {
// NOTE(nicksantos): Right now, this is optimized for few warnings.
// This is probably the right trade-off, but will be slow if there
// are lots of warnings in one file.
js = getCode();
} catch (IOException e) {
return null;
}
int pos = 0;
int startLine = 1;
// If we've saved a previous offset and it's for a line less than the
// one we're searching for, then start at that point.
if (lineNumber >= lastLine) {
pos = lastOffset;
startLine = lastLine;
}
for (int n = startLine; n < lineNumber; n++) {
int nextpos = js.indexOf('\n', pos);
if (nextpos == -1) {
return null;
}
pos = nextpos + 1;
}
// Remember this offset for the next search we do.
lastOffset = pos;
lastLine = lineNumber;
if (js.indexOf('\n', pos) == -1) {
// If next new line cannot be found, there are two cases
// 1. pos already reaches the end of file, then null should be returned
// 2. otherwise, return the contents between pos and the end of file.
if (pos >= js.length()) {
return null;
} else {
return js.substring(pos, js.length());
}
} else {
return js.substring(pos, js.indexOf('\n', pos));
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Gets the source line for the indicated line number.
*
* @param lineNumber the line number, 1 being the first line of the file.
* @return The line indicated. Does not include the newline at the end
* of the file. Returns {@code null} if it does not exist,
* or if there was an IO exception.
*/
public String getLine(int lineNumber) {
String js = "";
try {
// NOTE(nicksantos): Right now, this is optimized for few warnings.
// This is probably the right trade-off, but will be slow if there
// are lots of warnings in one file.
js = getCode();
} catch (IOException e) {
return null;
}
int pos = 0;
int startLine = 1;
// If we've saved a previous offset and it's for a line less than the
// one we're searching for, then start at that point.
if (lineNumber >= lastLine) {
pos = lastOffset;
startLine = lastLine;
}
for (int n = startLine; n < lineNumber; n++) {
int nextpos = js.indexOf('\n', pos);
if (nextpos == -1) {
return null;
}
pos = nextpos + 1;
}
// Remember this offset for the next search we do.
lastOffset = pos;
lastLine = lineNumber;
if (js.indexOf('\n', pos) == -1) {
// If next new line cannot be found, there are two cases
// 1. pos already reaches the end of file, then null should be returned
// 2. otherwise, return the contents between pos and the end of file.
if (pos >= js.length()) {
return null;
} else {
return js.substring(pos, js.length());
}
} else {
return js.substring(pos, js.indexOf('\n', pos));
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 754bd43895398ebd5aa7bf060e60e4f7c31c93d847ee843e99d626018b605ef7 | public static String encodeBase64String(byte[] binaryData) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Encodes binary data using the base64 algorithm into 76 character blocks separated by CRLF.
*
* @param binaryData
* binary data to encode
* @return String containing Base64 characters.
* @since 1.4
*/
public static String encodeBase64String(byte[] binaryData) {
return StringUtils.newStringUtf8(encodeBase64(binaryData, false));
}
```
| public static String encodeBase64String(byte[] binaryData) {
return StringUtils.newStringUtf8(encodeBase64(binaryData, false));
} | false | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Encodes binary data using the base64 algorithm into 76 character blocks separated by CRLF.
*
* @param binaryData
* binary data to encode
* @return String containing Base64 characters.
* @since 1.4
*/
public static String encodeBase64String(byte[] binaryData) {
return StringUtils.newStringUtf8(encodeBase64(binaryData, false));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | 764df00551717f8053fbacfa8099084ba009de21c7a0f941e2d8def683c263ce | public <T> T createMock(MockCreationSettings<T> settings, MockHandler handler) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public <T> T createMock(MockCreationSettings<T> settings, MockHandler handler) {
if (settings.getSerializableMode() == SerializableMode.ACROSS_CLASSLOADERS) {
throw new MockitoException("Serialization across classloaders not yet supported with ByteBuddyMockMaker");
}
Class<? extends T> mockedProxyType = cachingMockBytecodeGenerator.get(
settings.getTypeToMock(),
settings.getExtraInterfaces()
);
T mockInstance = null;
try {
mockInstance = classInstantiator.instantiate(mockedProxyType);
MockMethodInterceptor.MockAccess mockAccess = (MockMethodInterceptor.MockAccess) mockInstance;
mockAccess.setMockitoInterceptor(new MockMethodInterceptor(asInternalMockHandler(handler), settings));
return ensureMockIsAssignableToMockedType(settings, mockInstance);
} catch (ClassCastException cce) {
throw new MockitoException(join(
"ClassCastException occurred while creating the mockito mock :",
" class to mock : " + describeClass(mockedProxyType),
" created class : " + describeClass(settings.getTypeToMock()),
" proxy instance class : " + describeClass(mockInstance),
" instance creation by : " + classInstantiator.getClass().getSimpleName(),
"",
"You might experience classloading issues, please ask the mockito mailing-list.",
""
),cce);
} catch (org.mockito.internal.creation.instance.InstantiationException e) {
throw new MockitoException("Unable to create mock instance of type '" + mockedProxyType.getSuperclass().getSimpleName() + "'", e);
}
}
```
| public <T> T createMock(MockCreationSettings<T> settings, MockHandler handler) {
if (settings.getSerializableMode() == SerializableMode.ACROSS_CLASSLOADERS) {
throw new MockitoException("Serialization across classloaders not yet supported with ByteBuddyMockMaker");
}
Class<? extends T> mockedProxyType = cachingMockBytecodeGenerator.get(
settings.getTypeToMock(),
settings.getExtraInterfaces()
);
T mockInstance = null;
try {
mockInstance = classInstantiator.instantiate(mockedProxyType);
MockMethodInterceptor.MockAccess mockAccess = (MockMethodInterceptor.MockAccess) mockInstance;
mockAccess.setMockitoInterceptor(new MockMethodInterceptor(asInternalMockHandler(handler), settings));
return ensureMockIsAssignableToMockedType(settings, mockInstance);
} catch (ClassCastException cce) {
throw new MockitoException(join(
"ClassCastException occurred while creating the mockito mock :",
" class to mock : " + describeClass(mockedProxyType),
" created class : " + describeClass(settings.getTypeToMock()),
" proxy instance class : " + describeClass(mockInstance),
" instance creation by : " + classInstantiator.getClass().getSimpleName(),
"",
"You might experience classloading issues, please ask the mockito mailing-list.",
""
),cce);
} catch (org.mockito.internal.creation.instance.InstantiationException e) {
throw new MockitoException("Unable to create mock instance of type '" + mockedProxyType.getSuperclass().getSimpleName() + "'", e);
}
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public <T> T createMock(MockCreationSettings<T> settings, MockHandler handler) {
if (settings.getSerializableMode() == SerializableMode.ACROSS_CLASSLOADERS) {
throw new MockitoException("Serialization across classloaders not yet supported with ByteBuddyMockMaker");
}
Class<? extends T> mockedProxyType = cachingMockBytecodeGenerator.get(
settings.getTypeToMock(),
settings.getExtraInterfaces()
);
T mockInstance = null;
try {
mockInstance = classInstantiator.instantiate(mockedProxyType);
MockMethodInterceptor.MockAccess mockAccess = (MockMethodInterceptor.MockAccess) mockInstance;
mockAccess.setMockitoInterceptor(new MockMethodInterceptor(asInternalMockHandler(handler), settings));
return ensureMockIsAssignableToMockedType(settings, mockInstance);
} catch (ClassCastException cce) {
throw new MockitoException(join(
"ClassCastException occurred while creating the mockito mock :",
" class to mock : " + describeClass(mockedProxyType),
" created class : " + describeClass(settings.getTypeToMock()),
" proxy instance class : " + describeClass(mockInstance),
" instance creation by : " + classInstantiator.getClass().getSimpleName(),
"",
"You might experience classloading issues, please ask the mockito mailing-list.",
""
),cce);
} catch (org.mockito.internal.creation.instance.InstantiationException e) {
throw new MockitoException("Unable to create mock instance of type '" + mockedProxyType.getSuperclass().getSimpleName() + "'", e);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 76b40974b104f38c05885a05aba7fc76b401f77c5916f0c63ac6f07f3d3a915c | public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Creates a random string based on a variety of options, using
* supplied source of randomness.</p>
*
* <p>If start and end are both {@code 0}, start and end are set
* to {@code ' '} and {@code 'z'}, the ASCII printable
* characters, will be used, unless letters and numbers are both
* {@code false}, in which case, start and end are set to
* {@code 0} and {@code Integer.MAX_VALUE}.
*
* <p>If set is not {@code null}, characters between start and
* end are chosen.</p>
*
* <p>This method accepts a user-supplied {@link Random}
* instance to use as a source of randomness. By seeding a single
* {@link Random} instance with a fixed seed and using it for each call,
* the same random sequence of strings can be generated repeatedly
* and predictably.</p>
*
* @param count the length of random string to create
* @param start the position in set of chars to start at
* @param end the position in set of chars to end before
* @param letters only allow letters?
* @param numbers only allow numbers?
* @param chars the set of chars to choose randoms from, must not be empty.
* If {@code null}, then it will use the set of all chars.
* @param random a source of randomness.
* @return the random string
* @throws ArrayIndexOutOfBoundsException if there are not
* {@code (end - start) + 1} characters in the set array.
* @throws IllegalArgumentException if {@code count} < 0 or the provided chars array is empty.
* @since 2.0
*/
public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
}
```
| public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Creates a random string based on a variety of options, using
* supplied source of randomness.</p>
*
* <p>If start and end are both {@code 0}, start and end are set
* to {@code ' '} and {@code 'z'}, the ASCII printable
* characters, will be used, unless letters and numbers are both
* {@code false}, in which case, start and end are set to
* {@code 0} and {@code Integer.MAX_VALUE}.
*
* <p>If set is not {@code null}, characters between start and
* end are chosen.</p>
*
* <p>This method accepts a user-supplied {@link Random}
* instance to use as a source of randomness. By seeding a single
* {@link Random} instance with a fixed seed and using it for each call,
* the same random sequence of strings can be generated repeatedly
* and predictably.</p>
*
* @param count the length of random string to create
* @param start the position in set of chars to start at
* @param end the position in set of chars to end before
* @param letters only allow letters?
* @param numbers only allow numbers?
* @param chars the set of chars to choose randoms from, must not be empty.
* If {@code null}, then it will use the set of all chars.
* @param random a source of randomness.
* @return the random string
* @throws ArrayIndexOutOfBoundsException if there are not
* {@code (end - start) + 1} characters in the set array.
* @throws IllegalArgumentException if {@code count} < 0 or the provided chars array is empty.
* @since 2.0
*/
public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
12 | 76b40974b104f38c05885a05aba7fc76b401f77c5916f0c63ac6f07f3d3a915c | public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Creates a random string based on a variety of options, using
* supplied source of randomness.</p>
*
* <p>If start and end are both {@code 0}, start and end are set
* to {@code ' '} and {@code 'z'}, the ASCII printable
* characters, will be used, unless letters and numbers are both
* {@code false}, in which case, start and end are set to
* {@code 0} and {@code Integer.MAX_VALUE}.
*
* <p>If set is not {@code null}, characters between start and
* end are chosen.</p>
*
* <p>This method accepts a user-supplied {@link Random}
* instance to use as a source of randomness. By seeding a single
* {@link Random} instance with a fixed seed and using it for each call,
* the same random sequence of strings can be generated repeatedly
* and predictably.</p>
*
* @param count the length of random string to create
* @param start the position in set of chars to start at
* @param end the position in set of chars to end before
* @param letters only allow letters?
* @param numbers only allow numbers?
* @param chars the set of chars to choose randoms from, must not be empty.
* If {@code null}, then it will use the set of all chars.
* @param random a source of randomness.
* @return the random string
* @throws ArrayIndexOutOfBoundsException if there are not
* {@code (end - start) + 1} characters in the set array.
* @throws IllegalArgumentException if {@code count} < 0 or the provided chars array is empty.
* @since 2.0
*/
public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
}
```
| public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Creates a random string based on a variety of options, using
* supplied source of randomness.</p>
*
* <p>If start and end are both {@code 0}, start and end are set
* to {@code ' '} and {@code 'z'}, the ASCII printable
* characters, will be used, unless letters and numbers are both
* {@code false}, in which case, start and end are set to
* {@code 0} and {@code Integer.MAX_VALUE}.
*
* <p>If set is not {@code null}, characters between start and
* end are chosen.</p>
*
* <p>This method accepts a user-supplied {@link Random}
* instance to use as a source of randomness. By seeding a single
* {@link Random} instance with a fixed seed and using it for each call,
* the same random sequence of strings can be generated repeatedly
* and predictably.</p>
*
* @param count the length of random string to create
* @param start the position in set of chars to start at
* @param end the position in set of chars to end before
* @param letters only allow letters?
* @param numbers only allow numbers?
* @param chars the set of chars to choose randoms from, must not be empty.
* If {@code null}, then it will use the set of all chars.
* @param random a source of randomness.
* @return the random string
* @throws ArrayIndexOutOfBoundsException if there are not
* {@code (end - start) + 1} characters in the set array.
* @throws IllegalArgumentException if {@code count} < 0 or the provided chars array is empty.
* @since 2.0
*/
public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
47 | 76bbe952dbd2e0484f8cf0d8ee1e2c95659a70660540c49c85d4d24e377b07c7 | public JavaType refineSerializationType(final MapperConfig<?> config,
final Annotated a, final JavaType baseType) throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Method called to find out possible type refinements to use
* for deserialization.
*
* @since 2.7
*/
public JavaType refineSerializationType(final MapperConfig<?> config,
final Annotated a, final JavaType baseType) throws JsonMappingException
{
JavaType type = baseType;
final TypeFactory tf = config.getTypeFactory();
// 10-Oct-2015, tatu: For 2.7, we'll need to delegate back to
// now-deprecated secondary methods; this because while
// direct sub-class not yet retrofitted may only override
// those methods. With 2.8 or later we may consider removal
// of these methods
// Ok: start by refining the main type itself; common to all types
Class<?> serClass = findSerializationType(a);
if (serClass != null) {
if (type.hasRawClass(serClass)) {
// 30-Nov-2015, tatu: As per [databind#1023], need to allow forcing of
// static typing this way
type = type.withStaticTyping();
} else {
Class<?> currRaw = type.getRawClass();
try {
// 11-Oct-2015, tatu: For deser, we call `TypeFactory.constructSpecializedType()`,
// may be needed here too in future?
if (serClass.isAssignableFrom(currRaw)) { // common case
type = tf.constructGeneralizedType(type, serClass);
} else if (currRaw.isAssignableFrom(serClass)) { // specialization, ok as well
type = tf.constructSpecializedType(type, serClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization type %s into %s; types not related",
type, serClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen type %s with annotation (value %s), from '%s': %s",
type, serClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
}
// Then further processing for container types
// First, key type (for Maps, Map-like types):
if (type.isMapLikeType()) {
JavaType keyType = type.getKeyType();
Class<?> keyClass = findSerializationKeyType(a, keyType);
if (keyClass != null) {
if (keyType.hasRawClass(keyClass)) {
keyType = keyType.withStaticTyping();
} else {
Class<?> currRaw = keyType.getRawClass();
try {
// 19-May-2016, tatu: As per [databind#1231], [databind#1178] may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
if (keyClass.isAssignableFrom(currRaw)) { // common case
keyType = tf.constructGeneralizedType(keyType, keyClass);
} else if (currRaw.isAssignableFrom(keyClass)) { // specialization, ok as well
keyType = tf.constructSpecializedType(keyType, keyClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization key type %s into %s; types not related",
keyType, keyClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen key type of %s with concrete-type annotation (value %s), from '%s': %s",
type, keyClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = ((MapLikeType) type).withKeyType(keyType);
}
}
JavaType contentType = type.getContentType();
if (contentType != null) { // collection[like], map[like], array, reference
// And then value types for all containers:
Class<?> contentClass = findSerializationContentType(a, contentType);
if (contentClass != null) {
if (contentType.hasRawClass(contentClass)) {
contentType = contentType.withStaticTyping();
} else {
// 03-Apr-2016, tatu: As per [databind#1178], may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
Class<?> currRaw = contentType.getRawClass();
try {
if (contentClass.isAssignableFrom(currRaw)) { // common case
contentType = tf.constructGeneralizedType(contentType, contentClass);
} else if (currRaw.isAssignableFrom(contentClass)) { // specialization, ok as well
contentType = tf.constructSpecializedType(contentType, contentClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization content type %s into %s; types not related",
contentType, contentClass.getName()));
}
} catch (IllegalArgumentException iae) { // shouldn't really happen
throw new JsonMappingException(null,
String.format("Internal error: failed to refine value type of %s with concrete-type annotation (value %s), from '%s': %s",
type, contentClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = type.withContentType(contentType);
}
}
return type;
}
```
| public JavaType refineSerializationType(final MapperConfig<?> config,
final Annotated a, final JavaType baseType) throws JsonMappingException
{
JavaType type = baseType;
final TypeFactory tf = config.getTypeFactory();
// 10-Oct-2015, tatu: For 2.7, we'll need to delegate back to
// now-deprecated secondary methods; this because while
// direct sub-class not yet retrofitted may only override
// those methods. With 2.8 or later we may consider removal
// of these methods
// Ok: start by refining the main type itself; common to all types
Class<?> serClass = findSerializationType(a);
if (serClass != null) {
if (type.hasRawClass(serClass)) {
// 30-Nov-2015, tatu: As per [databind#1023], need to allow forcing of
// static typing this way
type = type.withStaticTyping();
} else {
Class<?> currRaw = type.getRawClass();
try {
// 11-Oct-2015, tatu: For deser, we call `TypeFactory.constructSpecializedType()`,
// may be needed here too in future?
if (serClass.isAssignableFrom(currRaw)) { // common case
type = tf.constructGeneralizedType(type, serClass);
} else if (currRaw.isAssignableFrom(serClass)) { // specialization, ok as well
type = tf.constructSpecializedType(type, serClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization type %s into %s; types not related",
type, serClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen type %s with annotation (value %s), from '%s': %s",
type, serClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
}
// Then further processing for container types
// First, key type (for Maps, Map-like types):
if (type.isMapLikeType()) {
JavaType keyType = type.getKeyType();
Class<?> keyClass = findSerializationKeyType(a, keyType);
if (keyClass != null) {
if (keyType.hasRawClass(keyClass)) {
keyType = keyType.withStaticTyping();
} else {
Class<?> currRaw = keyType.getRawClass();
try {
// 19-May-2016, tatu: As per [databind#1231], [databind#1178] may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
if (keyClass.isAssignableFrom(currRaw)) { // common case
keyType = tf.constructGeneralizedType(keyType, keyClass);
} else if (currRaw.isAssignableFrom(keyClass)) { // specialization, ok as well
keyType = tf.constructSpecializedType(keyType, keyClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization key type %s into %s; types not related",
keyType, keyClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen key type of %s with concrete-type annotation (value %s), from '%s': %s",
type, keyClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = ((MapLikeType) type).withKeyType(keyType);
}
}
JavaType contentType = type.getContentType();
if (contentType != null) { // collection[like], map[like], array, reference
// And then value types for all containers:
Class<?> contentClass = findSerializationContentType(a, contentType);
if (contentClass != null) {
if (contentType.hasRawClass(contentClass)) {
contentType = contentType.withStaticTyping();
} else {
// 03-Apr-2016, tatu: As per [databind#1178], may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
Class<?> currRaw = contentType.getRawClass();
try {
if (contentClass.isAssignableFrom(currRaw)) { // common case
contentType = tf.constructGeneralizedType(contentType, contentClass);
} else if (currRaw.isAssignableFrom(contentClass)) { // specialization, ok as well
contentType = tf.constructSpecializedType(contentType, contentClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization content type %s into %s; types not related",
contentType, contentClass.getName()));
}
} catch (IllegalArgumentException iae) { // shouldn't really happen
throw new JsonMappingException(null,
String.format("Internal error: failed to refine value type of %s with concrete-type annotation (value %s), from '%s': %s",
type, contentClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = type.withContentType(contentType);
}
}
return type;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Method called to find out possible type refinements to use
* for deserialization.
*
* @since 2.7
*/
public JavaType refineSerializationType(final MapperConfig<?> config,
final Annotated a, final JavaType baseType) throws JsonMappingException
{
JavaType type = baseType;
final TypeFactory tf = config.getTypeFactory();
// 10-Oct-2015, tatu: For 2.7, we'll need to delegate back to
// now-deprecated secondary methods; this because while
// direct sub-class not yet retrofitted may only override
// those methods. With 2.8 or later we may consider removal
// of these methods
// Ok: start by refining the main type itself; common to all types
Class<?> serClass = findSerializationType(a);
if (serClass != null) {
if (type.hasRawClass(serClass)) {
// 30-Nov-2015, tatu: As per [databind#1023], need to allow forcing of
// static typing this way
type = type.withStaticTyping();
} else {
Class<?> currRaw = type.getRawClass();
try {
// 11-Oct-2015, tatu: For deser, we call `TypeFactory.constructSpecializedType()`,
// may be needed here too in future?
if (serClass.isAssignableFrom(currRaw)) { // common case
type = tf.constructGeneralizedType(type, serClass);
} else if (currRaw.isAssignableFrom(serClass)) { // specialization, ok as well
type = tf.constructSpecializedType(type, serClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization type %s into %s; types not related",
type, serClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen type %s with annotation (value %s), from '%s': %s",
type, serClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
}
// Then further processing for container types
// First, key type (for Maps, Map-like types):
if (type.isMapLikeType()) {
JavaType keyType = type.getKeyType();
Class<?> keyClass = findSerializationKeyType(a, keyType);
if (keyClass != null) {
if (keyType.hasRawClass(keyClass)) {
keyType = keyType.withStaticTyping();
} else {
Class<?> currRaw = keyType.getRawClass();
try {
// 19-May-2016, tatu: As per [databind#1231], [databind#1178] may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
if (keyClass.isAssignableFrom(currRaw)) { // common case
keyType = tf.constructGeneralizedType(keyType, keyClass);
} else if (currRaw.isAssignableFrom(keyClass)) { // specialization, ok as well
keyType = tf.constructSpecializedType(keyType, keyClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization key type %s into %s; types not related",
keyType, keyClass.getName()));
}
} catch (IllegalArgumentException iae) {
throw new JsonMappingException(null,
String.format("Failed to widen key type of %s with concrete-type annotation (value %s), from '%s': %s",
type, keyClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = ((MapLikeType) type).withKeyType(keyType);
}
}
JavaType contentType = type.getContentType();
if (contentType != null) { // collection[like], map[like], array, reference
// And then value types for all containers:
Class<?> contentClass = findSerializationContentType(a, contentType);
if (contentClass != null) {
if (contentType.hasRawClass(contentClass)) {
contentType = contentType.withStaticTyping();
} else {
// 03-Apr-2016, tatu: As per [databind#1178], may need to actually
// specialize (narrow) type sometimes, even if more commonly opposite
// is needed.
Class<?> currRaw = contentType.getRawClass();
try {
if (contentClass.isAssignableFrom(currRaw)) { // common case
contentType = tf.constructGeneralizedType(contentType, contentClass);
} else if (currRaw.isAssignableFrom(contentClass)) { // specialization, ok as well
contentType = tf.constructSpecializedType(contentType, contentClass);
} else {
throw new JsonMappingException(null,
String.format("Can not refine serialization content type %s into %s; types not related",
contentType, contentClass.getName()));
}
} catch (IllegalArgumentException iae) { // shouldn't really happen
throw new JsonMappingException(null,
String.format("Internal error: failed to refine value type of %s with concrete-type annotation (value %s), from '%s': %s",
type, contentClass.getName(), a.getName(), iae.getMessage()),
iae);
}
}
type = type.withContentType(contentType);
}
}
return type;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
26 | 76c96ef1e5743e9956e8fb1844e595493a53b6b3bb0ced9422c2b5b786de2031 | public static long skip(InputStream input, long numToSkip) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Skips the given number of bytes by repeatedly invoking skip on
* the given input stream if necessary.
*
* <p>In a case where the stream's skip() method returns 0 before
* the requested number of bytes has been skip this implementation
* will fall back to using the read() method.</p>
*
* <p>This method will only skip less than the requested number of
* bytes if the end of the input stream has been reached.</p>
*
* @param input stream to skip bytes in
* @param numToSkip the number of bytes to skip
* @return the number of bytes actually skipped
* @throws IOException
*/
public static long skip(InputStream input, long numToSkip) throws IOException {
long available = numToSkip;
while (numToSkip > 0) {
long skipped = input.skip(numToSkip);
if (skipped == 0) {
break;
}
numToSkip -= skipped;
}
if (numToSkip > 0) {
byte[] skipBuf = new byte[SKIP_BUF_SIZE];
while (numToSkip > 0) {
int read = readFully(input, skipBuf, 0,
(int) Math.min(numToSkip, SKIP_BUF_SIZE));
if (read < 1) {
break;
}
numToSkip -= read;
}
}
return available - numToSkip;
}
```
| public static long skip(InputStream input, long numToSkip) throws IOException {
long available = numToSkip;
while (numToSkip > 0) {
long skipped = input.skip(numToSkip);
if (skipped == 0) {
break;
}
numToSkip -= skipped;
}
if (numToSkip > 0) {
byte[] skipBuf = new byte[SKIP_BUF_SIZE];
while (numToSkip > 0) {
int read = readFully(input, skipBuf, 0,
(int) Math.min(numToSkip, SKIP_BUF_SIZE));
if (read < 1) {
break;
}
numToSkip -= read;
}
}
return available - numToSkip;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Skips the given number of bytes by repeatedly invoking skip on
* the given input stream if necessary.
*
* <p>In a case where the stream's skip() method returns 0 before
* the requested number of bytes has been skip this implementation
* will fall back to using the read() method.</p>
*
* <p>This method will only skip less than the requested number of
* bytes if the end of the input stream has been reached.</p>
*
* @param input stream to skip bytes in
* @param numToSkip the number of bytes to skip
* @return the number of bytes actually skipped
* @throws IOException
*/
public static long skip(InputStream input, long numToSkip) throws IOException {
long available = numToSkip;
while (numToSkip > 0) {
long skipped = input.skip(numToSkip);
if (skipped == 0) {
break;
}
numToSkip -= skipped;
}
if (numToSkip > 0) {
byte[] skipBuf = new byte[SKIP_BUF_SIZE];
while (numToSkip > 0) {
int read = readFully(input, skipBuf, 0,
(int) Math.min(numToSkip, SKIP_BUF_SIZE));
if (read < 1) {
break;
}
numToSkip -= read;
}
}
return available - numToSkip;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
41 | 7715ba94feed09cb7f6c57998728d7ac82c041339e14bddb4be5d8de949e9326 | public ZipArchiveEntry getNextZipEntry() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public ZipArchiveEntry getNextZipEntry() throws IOException {
boolean firstEntry = true;
if (closed || hitCentralDirectory) {
return null;
}
if (current != null) {
closeEntry();
firstEntry = false;
}
try {
if (firstEntry) {
// split archives have a special signature before the
// first local file header - look for it and fail with
// the appropriate error message if this is a split
// archive.
readFirstLocalFileHeader(LFH_BUF);
} else {
readFully(LFH_BUF);
}
} catch (final EOFException e) {
return null;
}
final ZipLong sig = new ZipLong(LFH_BUF);
if (sig.equals(ZipLong.CFH_SIG) || sig.equals(ZipLong.AED_SIG)) {
hitCentralDirectory = true;
skipRemainderOfArchive();
}
if (!sig.equals(ZipLong.LFH_SIG)) {
return null;
}
int off = WORD;
current = new CurrentEntry();
final int versionMadeBy = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
current.entry.setPlatform((versionMadeBy >> ZipFile.BYTE_SHIFT) & ZipFile.NIBLET_MASK);
final GeneralPurposeBit gpFlag = GeneralPurposeBit.parse(LFH_BUF, off);
final boolean hasUTF8Flag = gpFlag.usesUTF8ForNames();
final ZipEncoding entryEncoding = hasUTF8Flag ? ZipEncodingHelper.UTF8_ZIP_ENCODING : zipEncoding;
current.hasDataDescriptor = gpFlag.usesDataDescriptor();
current.entry.setGeneralPurposeBit(gpFlag);
off += SHORT;
current.entry.setMethod(ZipShort.getValue(LFH_BUF, off));
off += SHORT;
final long time = ZipUtil.dosToJavaTime(ZipLong.getValue(LFH_BUF, off));
current.entry.setTime(time);
off += WORD;
ZipLong size = null, cSize = null;
if (!current.hasDataDescriptor) {
current.entry.setCrc(ZipLong.getValue(LFH_BUF, off));
off += WORD;
cSize = new ZipLong(LFH_BUF, off);
off += WORD;
size = new ZipLong(LFH_BUF, off);
off += WORD;
} else {
off += 3 * WORD;
}
final int fileNameLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final int extraLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final byte[] fileName = new byte[fileNameLen];
readFully(fileName);
current.entry.setName(entryEncoding.decode(fileName), fileName);
final byte[] extraData = new byte[extraLen];
readFully(extraData);
current.entry.setExtra(extraData);
if (!hasUTF8Flag && useUnicodeExtraFields) {
ZipUtil.setNameAndCommentFromExtraFields(current.entry, fileName, null);
}
processZip64Extra(size, cSize);
if (current.entry.getCompressedSize() != ArchiveEntry.SIZE_UNKNOWN) {
if (current.entry.getMethod() == ZipMethod.UNSHRINKING.getCode()) {
current.in = new UnshrinkingInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.IMPLODING.getCode()) {
current.in = new ExplodingInputStream(
current.entry.getGeneralPurposeBit().getSlidingDictionarySize(),
current.entry.getGeneralPurposeBit().getNumberOfShannonFanoTrees(),
new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.BZIP2.getCode()) {
current.in = new BZip2CompressorInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
}
}
entriesRead++;
return current.entry;
}
```
| public ZipArchiveEntry getNextZipEntry() throws IOException {
boolean firstEntry = true;
if (closed || hitCentralDirectory) {
return null;
}
if (current != null) {
closeEntry();
firstEntry = false;
}
try {
if (firstEntry) {
// split archives have a special signature before the
// first local file header - look for it and fail with
// the appropriate error message if this is a split
// archive.
readFirstLocalFileHeader(LFH_BUF);
} else {
readFully(LFH_BUF);
}
} catch (final EOFException e) {
return null;
}
final ZipLong sig = new ZipLong(LFH_BUF);
if (sig.equals(ZipLong.CFH_SIG) || sig.equals(ZipLong.AED_SIG)) {
hitCentralDirectory = true;
skipRemainderOfArchive();
}
if (!sig.equals(ZipLong.LFH_SIG)) {
return null;
}
int off = WORD;
current = new CurrentEntry();
final int versionMadeBy = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
current.entry.setPlatform((versionMadeBy >> ZipFile.BYTE_SHIFT) & ZipFile.NIBLET_MASK);
final GeneralPurposeBit gpFlag = GeneralPurposeBit.parse(LFH_BUF, off);
final boolean hasUTF8Flag = gpFlag.usesUTF8ForNames();
final ZipEncoding entryEncoding = hasUTF8Flag ? ZipEncodingHelper.UTF8_ZIP_ENCODING : zipEncoding;
current.hasDataDescriptor = gpFlag.usesDataDescriptor();
current.entry.setGeneralPurposeBit(gpFlag);
off += SHORT;
current.entry.setMethod(ZipShort.getValue(LFH_BUF, off));
off += SHORT;
final long time = ZipUtil.dosToJavaTime(ZipLong.getValue(LFH_BUF, off));
current.entry.setTime(time);
off += WORD;
ZipLong size = null, cSize = null;
if (!current.hasDataDescriptor) {
current.entry.setCrc(ZipLong.getValue(LFH_BUF, off));
off += WORD;
cSize = new ZipLong(LFH_BUF, off);
off += WORD;
size = new ZipLong(LFH_BUF, off);
off += WORD;
} else {
off += 3 * WORD;
}
final int fileNameLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final int extraLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final byte[] fileName = new byte[fileNameLen];
readFully(fileName);
current.entry.setName(entryEncoding.decode(fileName), fileName);
final byte[] extraData = new byte[extraLen];
readFully(extraData);
current.entry.setExtra(extraData);
if (!hasUTF8Flag && useUnicodeExtraFields) {
ZipUtil.setNameAndCommentFromExtraFields(current.entry, fileName, null);
}
processZip64Extra(size, cSize);
if (current.entry.getCompressedSize() != ArchiveEntry.SIZE_UNKNOWN) {
if (current.entry.getMethod() == ZipMethod.UNSHRINKING.getCode()) {
current.in = new UnshrinkingInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.IMPLODING.getCode()) {
current.in = new ExplodingInputStream(
current.entry.getGeneralPurposeBit().getSlidingDictionarySize(),
current.entry.getGeneralPurposeBit().getNumberOfShannonFanoTrees(),
new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.BZIP2.getCode()) {
current.in = new BZip2CompressorInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
}
}
entriesRead++;
return current.entry;
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public ZipArchiveEntry getNextZipEntry() throws IOException {
boolean firstEntry = true;
if (closed || hitCentralDirectory) {
return null;
}
if (current != null) {
closeEntry();
firstEntry = false;
}
try {
if (firstEntry) {
// split archives have a special signature before the
// first local file header - look for it and fail with
// the appropriate error message if this is a split
// archive.
readFirstLocalFileHeader(LFH_BUF);
} else {
readFully(LFH_BUF);
}
} catch (final EOFException e) {
return null;
}
final ZipLong sig = new ZipLong(LFH_BUF);
if (sig.equals(ZipLong.CFH_SIG) || sig.equals(ZipLong.AED_SIG)) {
hitCentralDirectory = true;
skipRemainderOfArchive();
}
if (!sig.equals(ZipLong.LFH_SIG)) {
return null;
}
int off = WORD;
current = new CurrentEntry();
final int versionMadeBy = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
current.entry.setPlatform((versionMadeBy >> ZipFile.BYTE_SHIFT) & ZipFile.NIBLET_MASK);
final GeneralPurposeBit gpFlag = GeneralPurposeBit.parse(LFH_BUF, off);
final boolean hasUTF8Flag = gpFlag.usesUTF8ForNames();
final ZipEncoding entryEncoding = hasUTF8Flag ? ZipEncodingHelper.UTF8_ZIP_ENCODING : zipEncoding;
current.hasDataDescriptor = gpFlag.usesDataDescriptor();
current.entry.setGeneralPurposeBit(gpFlag);
off += SHORT;
current.entry.setMethod(ZipShort.getValue(LFH_BUF, off));
off += SHORT;
final long time = ZipUtil.dosToJavaTime(ZipLong.getValue(LFH_BUF, off));
current.entry.setTime(time);
off += WORD;
ZipLong size = null, cSize = null;
if (!current.hasDataDescriptor) {
current.entry.setCrc(ZipLong.getValue(LFH_BUF, off));
off += WORD;
cSize = new ZipLong(LFH_BUF, off);
off += WORD;
size = new ZipLong(LFH_BUF, off);
off += WORD;
} else {
off += 3 * WORD;
}
final int fileNameLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final int extraLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final byte[] fileName = new byte[fileNameLen];
readFully(fileName);
current.entry.setName(entryEncoding.decode(fileName), fileName);
final byte[] extraData = new byte[extraLen];
readFully(extraData);
current.entry.setExtra(extraData);
if (!hasUTF8Flag && useUnicodeExtraFields) {
ZipUtil.setNameAndCommentFromExtraFields(current.entry, fileName, null);
}
processZip64Extra(size, cSize);
if (current.entry.getCompressedSize() != ArchiveEntry.SIZE_UNKNOWN) {
if (current.entry.getMethod() == ZipMethod.UNSHRINKING.getCode()) {
current.in = new UnshrinkingInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.IMPLODING.getCode()) {
current.in = new ExplodingInputStream(
current.entry.getGeneralPurposeBit().getSlidingDictionarySize(),
current.entry.getGeneralPurposeBit().getNumberOfShannonFanoTrees(),
new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.BZIP2.getCode()) {
current.in = new BZip2CompressorInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
}
}
entriesRead++;
return current.entry;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
38 | 779fe66d1a2ced9db305ea103a9c2358a250d0e947e829575d25379c2daa1d91 | void addNumber(double x) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void addNumber(double x) {
// This is not pretty printing. This is to prevent misparsing of x- -4 as
// x--4 (which is a syntax error).
char prev = getLastChar();
boolean negativeZero = isNegativeZero(x);
if (x < 0 && prev == '-') {
add(" ");
}
if ((long) x == x && !negativeZero) {
long value = (long) x;
long mantissa = value;
int exp = 0;
if (Math.abs(x) >= 100) {
while (mantissa / 10 * Math.pow(10, exp + 1) == value) {
mantissa /= 10;
exp++;
}
}
if (exp > 2) {
add(Long.toString(mantissa) + "E" + Integer.toString(exp));
} else {
add(Long.toString(value));
}
} else {
add(String.valueOf(x));
}
}
```
| void addNumber(double x) {
// This is not pretty printing. This is to prevent misparsing of x- -4 as
// x--4 (which is a syntax error).
char prev = getLastChar();
boolean negativeZero = isNegativeZero(x);
if (x < 0 && prev == '-') {
add(" ");
}
if ((long) x == x && !negativeZero) {
long value = (long) x;
long mantissa = value;
int exp = 0;
if (Math.abs(x) >= 100) {
while (mantissa / 10 * Math.pow(10, exp + 1) == value) {
mantissa /= 10;
exp++;
}
}
if (exp > 2) {
add(Long.toString(mantissa) + "E" + Integer.toString(exp));
} else {
add(Long.toString(value));
}
} else {
add(String.valueOf(x));
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void addNumber(double x) {
// This is not pretty printing. This is to prevent misparsing of x- -4 as
// x--4 (which is a syntax error).
char prev = getLastChar();
boolean negativeZero = isNegativeZero(x);
if (x < 0 && prev == '-') {
add(" ");
}
if ((long) x == x && !negativeZero) {
long value = (long) x;
long mantissa = value;
int exp = 0;
if (Math.abs(x) >= 100) {
while (mantissa / 10 * Math.pow(10, exp + 1) == value) {
mantissa /= 10;
exp++;
}
}
if (exp > 2) {
add(Long.toString(mantissa) + "E" + Integer.toString(exp));
} else {
add(Long.toString(value));
}
} else {
add(String.valueOf(x));
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
23 | 7805281ddd5279da6e8363ad5c483af98de0c3c34b749b2930f66407498eadf0 | @Override
public DefaultPrettyPrinter createInstance() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Instantiatable impl
/**********************************************************
*/
@Override
public DefaultPrettyPrinter createInstance() {
return new DefaultPrettyPrinter(this);
}
```
| @Override
public DefaultPrettyPrinter createInstance() {
return new DefaultPrettyPrinter(this);
} | true | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Instantiatable impl
/**********************************************************
*/
@Override
public DefaultPrettyPrinter createInstance() {
return new DefaultPrettyPrinter(this);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
161 | 781060108c74b76de8e42cdb8478dc0c43918feb41ffba2c232c31dc4564d3e7 | private Node tryFoldArrayAccess(Node n, Node left, Node right) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private Node tryFoldArrayAccess(Node n, Node left, Node right) {
Node parent = n.getParent();
// If GETPROP/GETELEM is used as assignment target the array literal is
// acting as a temporary we can't fold it here:
// "[][0] += 1"
if (right.getType() != Token.NUMBER) {
// Sometimes people like to use complex expressions to index into
// arrays, or strings to index into array methods.
return n;
}
double index = right.getDouble();
int intIndex = (int) index;
if (intIndex != index) {
error(INVALID_GETELEM_INDEX_ERROR, right);
return n;
}
if (intIndex < 0) {
error(INDEX_OUT_OF_BOUNDS_ERROR, right);
return n;
}
Node elem = left.getFirstChild();
for (int i = 0; elem != null && i < intIndex; i++) {
elem = elem.getNext();
}
if (elem == null) {
error(INDEX_OUT_OF_BOUNDS_ERROR, right);
return n;
}
if (elem.getType() == Token.EMPTY) {
elem = NodeUtil.newUndefinedNode(elem);
} else {
left.removeChild(elem);
}
// Replace the entire GETELEM with the value
n.getParent().replaceChild(n, elem);
reportCodeChange();
return elem;
}
```
| private Node tryFoldArrayAccess(Node n, Node left, Node right) {
Node parent = n.getParent();
// If GETPROP/GETELEM is used as assignment target the array literal is
// acting as a temporary we can't fold it here:
// "[][0] += 1"
if (right.getType() != Token.NUMBER) {
// Sometimes people like to use complex expressions to index into
// arrays, or strings to index into array methods.
return n;
}
double index = right.getDouble();
int intIndex = (int) index;
if (intIndex != index) {
error(INVALID_GETELEM_INDEX_ERROR, right);
return n;
}
if (intIndex < 0) {
error(INDEX_OUT_OF_BOUNDS_ERROR, right);
return n;
}
Node elem = left.getFirstChild();
for (int i = 0; elem != null && i < intIndex; i++) {
elem = elem.getNext();
}
if (elem == null) {
error(INDEX_OUT_OF_BOUNDS_ERROR, right);
return n;
}
if (elem.getType() == Token.EMPTY) {
elem = NodeUtil.newUndefinedNode(elem);
} else {
left.removeChild(elem);
}
// Replace the entire GETELEM with the value
n.getParent().replaceChild(n, elem);
reportCodeChange();
return elem;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private Node tryFoldArrayAccess(Node n, Node left, Node right) {
Node parent = n.getParent();
// If GETPROP/GETELEM is used as assignment target the array literal is
// acting as a temporary we can't fold it here:
// "[][0] += 1"
if (right.getType() != Token.NUMBER) {
// Sometimes people like to use complex expressions to index into
// arrays, or strings to index into array methods.
return n;
}
double index = right.getDouble();
int intIndex = (int) index;
if (intIndex != index) {
error(INVALID_GETELEM_INDEX_ERROR, right);
return n;
}
if (intIndex < 0) {
error(INDEX_OUT_OF_BOUNDS_ERROR, right);
return n;
}
Node elem = left.getFirstChild();
for (int i = 0; elem != null && i < intIndex; i++) {
elem = elem.getNext();
}
if (elem == null) {
error(INDEX_OUT_OF_BOUNDS_ERROR, right);
return n;
}
if (elem.getType() == Token.EMPTY) {
elem = NodeUtil.newUndefinedNode(elem);
} else {
left.removeChild(elem);
}
// Replace the entire GETELEM with the value
n.getParent().replaceChild(n, elem);
reportCodeChange();
return elem;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
77 | 78262346b2f470c98aa392736cf2ff23dee16eb53760ef2ae158a5c00037ff3a | private void popStackToClose(Token.EndTag endTag) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* If the stack contains an element with this tag's name, pop up the stack to remove the first occurrence. If not
* found, skips.
*
* @param endTag tag to close
*/
private void popStackToClose(Token.EndTag endTag) {
String elName = endTag.name();
Element firstFound = null;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
if (next.nodeName().equals(elName)) {
firstFound = next;
break;
}
}
if (firstFound == null)
return; // not found, skip
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
stack.remove(pos);
if (next == firstFound)
break;
}
}
```
| private void popStackToClose(Token.EndTag endTag) {
String elName = endTag.name();
Element firstFound = null;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
if (next.nodeName().equals(elName)) {
firstFound = next;
break;
}
}
if (firstFound == null)
return; // not found, skip
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
stack.remove(pos);
if (next == firstFound)
break;
}
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* If the stack contains an element with this tag's name, pop up the stack to remove the first occurrence. If not
* found, skips.
*
* @param endTag tag to close
*/
private void popStackToClose(Token.EndTag endTag) {
String elName = endTag.name();
Element firstFound = null;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
if (next.nodeName().equals(elName)) {
firstFound = next;
break;
}
}
if (firstFound == null)
return; // not found, skip
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
stack.remove(pos);
if (next == firstFound)
break;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | 78ebb053d4f84d9fc54fffc454f6682d09cb084032b25605c0badaf32e240736 | private JavaType _mapType(Class<?> rawClass)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private JavaType _mapType(Class<?> rawClass)
{
// 28-May-2015, tatu: Properties are special, as per [databind#810]
JavaType[] typeParams = findTypeParameters(rawClass, Map.class);
// ok to have no types ("raw")
if (typeParams == null) {
return MapType.construct(rawClass, _unknownType(), _unknownType());
}
// but exactly 2 types if any found
if (typeParams.length != 2) {
throw new IllegalArgumentException("Strange Map type "+rawClass.getName()+": can not determine type parameters");
}
return MapType.construct(rawClass, typeParams[0], typeParams[1]);
}
```
| private JavaType _mapType(Class<?> rawClass)
{
// 28-May-2015, tatu: Properties are special, as per [databind#810]
JavaType[] typeParams = findTypeParameters(rawClass, Map.class);
// ok to have no types ("raw")
if (typeParams == null) {
return MapType.construct(rawClass, _unknownType(), _unknownType());
}
// but exactly 2 types if any found
if (typeParams.length != 2) {
throw new IllegalArgumentException("Strange Map type "+rawClass.getName()+": can not determine type parameters");
}
return MapType.construct(rawClass, typeParams[0], typeParams[1]);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private JavaType _mapType(Class<?> rawClass)
{
// 28-May-2015, tatu: Properties are special, as per [databind#810]
JavaType[] typeParams = findTypeParameters(rawClass, Map.class);
// ok to have no types ("raw")
if (typeParams == null) {
return MapType.construct(rawClass, _unknownType(), _unknownType());
}
// but exactly 2 types if any found
if (typeParams.length != 2) {
throw new IllegalArgumentException("Strange Map type "+rawClass.getName()+": can not determine type parameters");
}
return MapType.construct(rawClass, typeParams[0], typeParams[1]);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
79 | 7916ae609d5c514e24f25020490ee9e09ca0e88d004868b2f06e7807d3811ed6 | public static double distance(int[] p1, int[] p2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Calculates the L<sub>2</sub> (Euclidean) distance between two points.
*
* @param p1 the first point
* @param p2 the second point
* @return the L<sub>2</sub> distance between the two points
*/
public static double distance(int[] p1, int[] p2) {
double sum = 0;
for (int i = 0; i < p1.length; i++) {
final double dp = p1[i] - p2[i];
sum += dp * dp;
}
return Math.sqrt(sum);
}
```
| public static double distance(int[] p1, int[] p2) {
double sum = 0;
for (int i = 0; i < p1.length; i++) {
final double dp = p1[i] - p2[i];
sum += dp * dp;
}
return Math.sqrt(sum);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Calculates the L<sub>2</sub> (Euclidean) distance between two points.
*
* @param p1 the first point
* @param p2 the second point
* @return the L<sub>2</sub> distance between the two points
*/
public static double distance(int[] p1, int[] p2) {
double sum = 0;
for (int i = 0; i < p1.length; i++) {
final double dp = p1[i] - p2[i];
sum += dp * dp;
}
return Math.sqrt(sum);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | 79ceae334aba4ecd4be06197762f0c216ab57d362617e9750c00947c9a7355a0 | public double[] repairAndDecode(final double[] x) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @param x Normalized objective variables.
* @return the original objective variables, possibly repaired.
*/
public double[] repairAndDecode(final double[] x) {
return boundaries != null && isRepairMode ?
decode(repair(x)) :
decode(x);
}
```
| public double[] repairAndDecode(final double[] x) {
return boundaries != null && isRepairMode ?
decode(repair(x)) :
decode(x);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @param x Normalized objective variables.
* @return the original objective variables, possibly repaired.
*/
public double[] repairAndDecode(final double[] x) {
return boundaries != null && isRepairMode ?
decode(repair(x)) :
decode(x);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
56 | 79ddc6bd5956954d5f22eab69ce3b7032daddea25d7e8dd58f303f784d28cbd5 | public String getLine(int lineNumber) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Gets the source line for the indicated line number.
*
* @param lineNumber the line number, 1 being the first line of the file.
* @return The line indicated. Does not include the newline at the end
* of the file. Returns {@code null} if it does not exist,
* or if there was an IO exception.
*/
public String getLine(int lineNumber) {
String js = "";
try {
// NOTE(nicksantos): Right now, this is optimized for few warnings.
// This is probably the right trade-off, but will be slow if there
// are lots of warnings in one file.
js = getCode();
} catch (IOException e) {
return null;
}
int pos = 0;
int startLine = 1;
// If we've saved a previous offset and it's for a line less than the
// one we're searching for, then start at that point.
if (lineNumber >= lastLine) {
pos = lastOffset;
startLine = lastLine;
}
for (int n = startLine; n < lineNumber; n++) {
int nextpos = js.indexOf('\n', pos);
if (nextpos == -1) {
return null;
}
pos = nextpos + 1;
}
// Remember this offset for the next search we do.
lastOffset = pos;
lastLine = lineNumber;
if (js.indexOf('\n', pos) == -1) {
// If next new line cannot be found, there are two cases
// 1. pos already reaches the end of file, then null should be returned
// 2. otherwise, return the contents between pos and the end of file.
return null;
} else {
return js.substring(pos, js.indexOf('\n', pos));
}
}
```
| public String getLine(int lineNumber) {
String js = "";
try {
// NOTE(nicksantos): Right now, this is optimized for few warnings.
// This is probably the right trade-off, but will be slow if there
// are lots of warnings in one file.
js = getCode();
} catch (IOException e) {
return null;
}
int pos = 0;
int startLine = 1;
// If we've saved a previous offset and it's for a line less than the
// one we're searching for, then start at that point.
if (lineNumber >= lastLine) {
pos = lastOffset;
startLine = lastLine;
}
for (int n = startLine; n < lineNumber; n++) {
int nextpos = js.indexOf('\n', pos);
if (nextpos == -1) {
return null;
}
pos = nextpos + 1;
}
// Remember this offset for the next search we do.
lastOffset = pos;
lastLine = lineNumber;
if (js.indexOf('\n', pos) == -1) {
// If next new line cannot be found, there are two cases
// 1. pos already reaches the end of file, then null should be returned
// 2. otherwise, return the contents between pos and the end of file.
return null;
} else {
return js.substring(pos, js.indexOf('\n', pos));
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Gets the source line for the indicated line number.
*
* @param lineNumber the line number, 1 being the first line of the file.
* @return The line indicated. Does not include the newline at the end
* of the file. Returns {@code null} if it does not exist,
* or if there was an IO exception.
*/
public String getLine(int lineNumber) {
String js = "";
try {
// NOTE(nicksantos): Right now, this is optimized for few warnings.
// This is probably the right trade-off, but will be slow if there
// are lots of warnings in one file.
js = getCode();
} catch (IOException e) {
return null;
}
int pos = 0;
int startLine = 1;
// If we've saved a previous offset and it's for a line less than the
// one we're searching for, then start at that point.
if (lineNumber >= lastLine) {
pos = lastOffset;
startLine = lastLine;
}
for (int n = startLine; n < lineNumber; n++) {
int nextpos = js.indexOf('\n', pos);
if (nextpos == -1) {
return null;
}
pos = nextpos + 1;
}
// Remember this offset for the next search we do.
lastOffset = pos;
lastLine = lineNumber;
if (js.indexOf('\n', pos) == -1) {
// If next new line cannot be found, there are two cases
// 1. pos already reaches the end of file, then null should be returned
// 2. otherwise, return the contents between pos and the end of file.
return null;
} else {
return js.substring(pos, js.indexOf('\n', pos));
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 7a98d2d67d1834ac573cdaf9ae475ede992c911f50ca15431cdcc71408e67467 | protected void _addMethodMixIns(Class<?> targetClass, AnnotatedMethodMap methods,
Class<?> mixInCls, AnnotatedMethodMap mixIns)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected void _addMethodMixIns(Class<?> targetClass, AnnotatedMethodMap methods,
Class<?> mixInCls, AnnotatedMethodMap mixIns)
{
List<Class<?>> parents = new ArrayList<Class<?>>();
parents.add(mixInCls);
ClassUtil.findSuperTypes(mixInCls, targetClass, parents);
for (Class<?> mixin : parents) {
for (Method m : mixin.getDeclaredMethods()) {
if (!_isIncludableMemberMethod(m)) {
continue;
}
AnnotatedMethod am = methods.find(m);
/* Do we already have a method to augment (from sub-class
* that will mask this mixIn)? If so, add if visible
* without masking (no such annotation)
*/
if (am != null) {
_addMixUnders(m, am);
/* Otherwise will have precedence, but must wait
* until we find the real method (mixIn methods are
* just placeholder, can't be called)
*/
} else {
// Well, or, as per [Issue#515], multi-level merge within mixins...
mixIns.add(_constructMethod(m));
}
}
}
}
```
| protected void _addMethodMixIns(Class<?> targetClass, AnnotatedMethodMap methods,
Class<?> mixInCls, AnnotatedMethodMap mixIns)
{
List<Class<?>> parents = new ArrayList<Class<?>>();
parents.add(mixInCls);
ClassUtil.findSuperTypes(mixInCls, targetClass, parents);
for (Class<?> mixin : parents) {
for (Method m : mixin.getDeclaredMethods()) {
if (!_isIncludableMemberMethod(m)) {
continue;
}
AnnotatedMethod am = methods.find(m);
/* Do we already have a method to augment (from sub-class
* that will mask this mixIn)? If so, add if visible
* without masking (no such annotation)
*/
if (am != null) {
_addMixUnders(m, am);
/* Otherwise will have precedence, but must wait
* until we find the real method (mixIn methods are
* just placeholder, can't be called)
*/
} else {
// Well, or, as per [Issue#515], multi-level merge within mixins...
mixIns.add(_constructMethod(m));
}
}
}
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected void _addMethodMixIns(Class<?> targetClass, AnnotatedMethodMap methods,
Class<?> mixInCls, AnnotatedMethodMap mixIns)
{
List<Class<?>> parents = new ArrayList<Class<?>>();
parents.add(mixInCls);
ClassUtil.findSuperTypes(mixInCls, targetClass, parents);
for (Class<?> mixin : parents) {
for (Method m : mixin.getDeclaredMethods()) {
if (!_isIncludableMemberMethod(m)) {
continue;
}
AnnotatedMethod am = methods.find(m);
/* Do we already have a method to augment (from sub-class
* that will mask this mixIn)? If so, add if visible
* without masking (no such annotation)
*/
if (am != null) {
_addMixUnders(m, am);
/* Otherwise will have precedence, but must wait
* until we find the real method (mixIn methods are
* just placeholder, can't be called)
*/
} else {
// Well, or, as per [Issue#515], multi-level merge within mixins...
mixIns.add(_constructMethod(m));
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
128 | 7ab2894bc2b440cc0f2ea34845b50770a7613d0098fa5807f2e284101b2840be | static boolean isSimpleNumber(String s) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
static boolean isSimpleNumber(String s) {
int len = s.length();
if (len == 0) {
return false;
}
for (int index = 0; index < len; index++) {
char c = s.charAt(index);
if (c < '0' || c > '9') {
return false;
}
}
return len == 1 || s.charAt(0) != '0';
}
```
| static boolean isSimpleNumber(String s) {
int len = s.length();
if (len == 0) {
return false;
}
for (int index = 0; index < len; index++) {
char c = s.charAt(index);
if (c < '0' || c > '9') {
return false;
}
}
return len == 1 || s.charAt(0) != '0';
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
static boolean isSimpleNumber(String s) {
int len = s.length();
if (len == 0) {
return false;
}
for (int index = 0; index < len; index++) {
char c = s.charAt(index);
if (c < '0' || c > '9') {
return false;
}
}
return len == 1 || s.charAt(0) != '0';
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
58 | 7aee688e60b41e7f6336a0818452f5ebb404eaf0a698da14fe4662eb53a36a67 | public double[] fit() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Fits a Gaussian function to the observed points.
*
* @return the parameters of the Gaussian function that best fits the
* observed points (in the same order as above).
*/
public double[] fit() {
final double[] guess = (new ParameterGuesser(getObservations())).guess();
return fit(new Gaussian.Parametric(), guess);
}
```
| public double[] fit() {
final double[] guess = (new ParameterGuesser(getObservations())).guess();
return fit(new Gaussian.Parametric(), guess);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Fits a Gaussian function to the observed points.
*
* @return the parameters of the Gaussian function that best fits the
* observed points (in the same order as above).
*/
public double[] fit() {
final double[] guess = (new ParameterGuesser(getObservations())).guess();
return fit(new Gaussian.Parametric(), guess);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
28 | 7b14436f365ed0877b75cecf4c08285d7daf5e0b741002d1fde1d75c02e7aacb | private void injectMockCandidate(Class<?> awaitingInjectionClazz, Set<Object> mocks, Object fieldInstance) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void injectMockCandidate(Class<?> awaitingInjectionClazz, Set<Object> mocks, Object fieldInstance) {
for(Field field : orderedInstanceFieldsFrom(awaitingInjectionClazz)) {
Object injected = mockCandidateFilter.filterCandidate(mocks, field, fieldInstance).thenInject();
mocks.remove(injected);
}
}
```
| private void injectMockCandidate(Class<?> awaitingInjectionClazz, Set<Object> mocks, Object fieldInstance) {
for(Field field : orderedInstanceFieldsFrom(awaitingInjectionClazz)) {
Object injected = mockCandidateFilter.filterCandidate(mocks, field, fieldInstance).thenInject();
mocks.remove(injected);
}
} | false | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void injectMockCandidate(Class<?> awaitingInjectionClazz, Set<Object> mocks, Object fieldInstance) {
for(Field field : orderedInstanceFieldsFrom(awaitingInjectionClazz)) {
Object injected = mockCandidateFilter.filterCandidate(mocks, field, fieldInstance).thenInject();
mocks.remove(injected);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | 7b1ff9cd123fc4b516ca6de57d09cf8aa52ddf68645a913e0bd768e194181fc1 | public LegendItemCollection getLegendItems() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a (possibly empty) collection of legend items for the series
* that this renderer is responsible for drawing.
*
* @return The legend item collection (never <code>null</code>).
*
* @see #getLegendItem(int, int)
*/
public LegendItemCollection getLegendItems() {
LegendItemCollection result = new LegendItemCollection();
if (this.plot == null) {
return result;
}
int index = this.plot.getIndexOf(this);
CategoryDataset dataset = this.plot.getDataset(index);
if (dataset == null) {
return result;
}
int seriesCount = dataset.getRowCount();
if (plot.getRowRenderingOrder().equals(SortOrder.ASCENDING)) {
for (int i = 0; i < seriesCount; i++) {
if (isSeriesVisibleInLegend(i)) {
LegendItem item = getLegendItem(index, i);
if (item != null) {
result.add(item);
}
}
}
}
else {
for (int i = seriesCount - 1; i >= 0; i--) {
if (isSeriesVisibleInLegend(i)) {
LegendItem item = getLegendItem(index, i);
if (item != null) {
result.add(item);
}
}
}
}
return result;
}
```
| public LegendItemCollection getLegendItems() {
LegendItemCollection result = new LegendItemCollection();
if (this.plot == null) {
return result;
}
int index = this.plot.getIndexOf(this);
CategoryDataset dataset = this.plot.getDataset(index);
if (dataset == null) {
return result;
}
int seriesCount = dataset.getRowCount();
if (plot.getRowRenderingOrder().equals(SortOrder.ASCENDING)) {
for (int i = 0; i < seriesCount; i++) {
if (isSeriesVisibleInLegend(i)) {
LegendItem item = getLegendItem(index, i);
if (item != null) {
result.add(item);
}
}
}
}
else {
for (int i = seriesCount - 1; i >= 0; i--) {
if (isSeriesVisibleInLegend(i)) {
LegendItem item = getLegendItem(index, i);
if (item != null) {
result.add(item);
}
}
}
}
return result;
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a (possibly empty) collection of legend items for the series
* that this renderer is responsible for drawing.
*
* @return The legend item collection (never <code>null</code>).
*
* @see #getLegendItem(int, int)
*/
public LegendItemCollection getLegendItems() {
LegendItemCollection result = new LegendItemCollection();
if (this.plot == null) {
return result;
}
int index = this.plot.getIndexOf(this);
CategoryDataset dataset = this.plot.getDataset(index);
if (dataset == null) {
return result;
}
int seriesCount = dataset.getRowCount();
if (plot.getRowRenderingOrder().equals(SortOrder.ASCENDING)) {
for (int i = 0; i < seriesCount; i++) {
if (isSeriesVisibleInLegend(i)) {
LegendItem item = getLegendItem(index, i);
if (item != null) {
result.add(item);
}
}
}
}
else {
for (int i = seriesCount - 1; i >= 0; i--) {
if (isSeriesVisibleInLegend(i)) {
LegendItem item = getLegendItem(index, i);
if (item != null) {
result.add(item);
}
}
}
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 7b6a133ec110ae113020be2b3bfe965df294a79518725a7727226741d00e0a3a | public double density(final double[] vals) throws DimensionMismatchException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
public double density(final double[] vals) throws DimensionMismatchException {
final int dim = getDimension();
if (vals.length != dim) {
throw new DimensionMismatchException(vals.length, dim);
}
return FastMath.pow(2 * FastMath.PI, -dim / 2) *
FastMath.pow(covarianceMatrixDeterminant, -0.5) *
getExponentTerm(vals);
}
```
| public double density(final double[] vals) throws DimensionMismatchException {
final int dim = getDimension();
if (vals.length != dim) {
throw new DimensionMismatchException(vals.length, dim);
}
return FastMath.pow(2 * FastMath.PI, -dim / 2) *
FastMath.pow(covarianceMatrixDeterminant, -0.5) *
getExponentTerm(vals);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
public double density(final double[] vals) throws DimensionMismatchException {
final int dim = getDimension();
if (vals.length != dim) {
throw new DimensionMismatchException(vals.length, dim);
}
return FastMath.pow(2 * FastMath.PI, -dim / 2) *
FastMath.pow(covarianceMatrixDeterminant, -0.5) *
getExponentTerm(vals);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
23 | 7babcd6a64228bb8fbb9b85a865632bffac98a81b5a1619ce40ec22c3c2b71f5 | @Override
InputStream decode(final InputStream in, final Coder coder,
byte[] password) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
InputStream decode(final InputStream in, final Coder coder,
byte[] password) throws IOException {
byte propsByte = coder.properties[0];
long dictSize = coder.properties[1];
for (int i = 1; i < 4; i++) {
dictSize |= (coder.properties[i + 1] & 0xffl) << (8 * i);
}
if (dictSize > LZMAInputStream.DICT_SIZE_MAX) {
throw new IOException("Dictionary larger than 4GiB maximum size");
}
return new LZMAInputStream(in, -1, propsByte, (int) dictSize);
}
```
| @Override
InputStream decode(final InputStream in, final Coder coder,
byte[] password) throws IOException {
byte propsByte = coder.properties[0];
long dictSize = coder.properties[1];
for (int i = 1; i < 4; i++) {
dictSize |= (coder.properties[i + 1] & 0xffl) << (8 * i);
}
if (dictSize > LZMAInputStream.DICT_SIZE_MAX) {
throw new IOException("Dictionary larger than 4GiB maximum size");
}
return new LZMAInputStream(in, -1, propsByte, (int) dictSize);
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
InputStream decode(final InputStream in, final Coder coder,
byte[] password) throws IOException {
byte propsByte = coder.properties[0];
long dictSize = coder.properties[1];
for (int i = 1; i < 4; i++) {
dictSize |= (coder.properties[i + 1] & 0xffl) << (8 * i);
}
if (dictSize > LZMAInputStream.DICT_SIZE_MAX) {
throw new IOException("Dictionary larger than 4GiB maximum size");
}
return new LZMAInputStream(in, -1, propsByte, (int) dictSize);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 7bb520e213795eab6cfb925f43ec0f0173f33d3afefa0e0efe16cd0ca499ea8c | public Week(Date time, TimeZone zone) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a time period for the week in which the specified date/time
* falls, calculated relative to the specified time zone.
*
* @param time the date/time (<code>null</code> not permitted).
* @param zone the time zone (<code>null</code> not permitted).
*
* @deprecated As of 1.0.7, use {@link #Week(Date, TimeZone, Locale)}.
*/
public Week(Date time, TimeZone zone) {
// defer argument checking...
this(time, zone, Locale.getDefault());
}
```
| public Week(Date time, TimeZone zone) {
// defer argument checking...
this(time, zone, Locale.getDefault());
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a time period for the week in which the specified date/time
* falls, calculated relative to the specified time zone.
*
* @param time the date/time (<code>null</code> not permitted).
* @param zone the time zone (<code>null</code> not permitted).
*
* @deprecated As of 1.0.7, use {@link #Week(Date, TimeZone, Locale)}.
*/
public Week(Date time, TimeZone zone) {
// defer argument checking...
this(time, zone, Locale.getDefault());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 7be43878d8e25247836500266febda4051cc130864cd3859bcea4309932dfac6 | protected void _addMethodMixIns(Class<?> targetClass, AnnotatedMethodMap methods,
Class<?> mixInCls, AnnotatedMethodMap mixIns)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected void _addMethodMixIns(Class<?> targetClass, AnnotatedMethodMap methods,
Class<?> mixInCls, AnnotatedMethodMap mixIns)
{
List<Class<?>> parents = new ArrayList<Class<?>>();
parents.add(mixInCls);
ClassUtil.findSuperTypes(mixInCls, targetClass, parents);
for (Class<?> mixin : parents) {
for (Method m : mixin.getDeclaredMethods()) {
if (!_isIncludableMemberMethod(m)) {
continue;
}
AnnotatedMethod am = methods.find(m);
/* Do we already have a method to augment (from sub-class
* that will mask this mixIn)? If so, add if visible
* without masking (no such annotation)
*/
if (am != null) {
_addMixUnders(m, am);
/* Otherwise will have precedence, but must wait
* until we find the real method (mixIn methods are
* just placeholder, can't be called)
*/
} else {
// Well, or, as per [Issue#515], multi-level merge within mixins...
am = mixIns.find(m);
if (am != null) {
_addMixUnders(m, am);
} else {
mixIns.add(_constructMethod(m));
}
}
}
}
}
```
| protected void _addMethodMixIns(Class<?> targetClass, AnnotatedMethodMap methods,
Class<?> mixInCls, AnnotatedMethodMap mixIns)
{
List<Class<?>> parents = new ArrayList<Class<?>>();
parents.add(mixInCls);
ClassUtil.findSuperTypes(mixInCls, targetClass, parents);
for (Class<?> mixin : parents) {
for (Method m : mixin.getDeclaredMethods()) {
if (!_isIncludableMemberMethod(m)) {
continue;
}
AnnotatedMethod am = methods.find(m);
/* Do we already have a method to augment (from sub-class
* that will mask this mixIn)? If so, add if visible
* without masking (no such annotation)
*/
if (am != null) {
_addMixUnders(m, am);
/* Otherwise will have precedence, but must wait
* until we find the real method (mixIn methods are
* just placeholder, can't be called)
*/
} else {
// Well, or, as per [Issue#515], multi-level merge within mixins...
am = mixIns.find(m);
if (am != null) {
_addMixUnders(m, am);
} else {
mixIns.add(_constructMethod(m));
}
}
}
}
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected void _addMethodMixIns(Class<?> targetClass, AnnotatedMethodMap methods,
Class<?> mixInCls, AnnotatedMethodMap mixIns)
{
List<Class<?>> parents = new ArrayList<Class<?>>();
parents.add(mixInCls);
ClassUtil.findSuperTypes(mixInCls, targetClass, parents);
for (Class<?> mixin : parents) {
for (Method m : mixin.getDeclaredMethods()) {
if (!_isIncludableMemberMethod(m)) {
continue;
}
AnnotatedMethod am = methods.find(m);
/* Do we already have a method to augment (from sub-class
* that will mask this mixIn)? If so, add if visible
* without masking (no such annotation)
*/
if (am != null) {
_addMixUnders(m, am);
/* Otherwise will have precedence, but must wait
* until we find the real method (mixIn methods are
* just placeholder, can't be called)
*/
} else {
// Well, or, as per [Issue#515], multi-level merge within mixins...
am = mixIns.find(m);
if (am != null) {
_addMixUnders(m, am);
} else {
mixIns.add(_constructMethod(m));
}
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
7 | 7bf80d106a24420f58ac76e76101dc8a3b2d0be4e9747100337c180b9a50914f | private void readTypeVariables() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void readTypeVariables() {
for (Type type : typeVariable.getBounds()) {
registerTypeVariablesOn(type);
}
registerTypeVariablesOn(getActualTypeArgumentFor(typeVariable));
}
```
| private void readTypeVariables() {
for (Type type : typeVariable.getBounds()) {
registerTypeVariablesOn(type);
}
registerTypeVariablesOn(getActualTypeArgumentFor(typeVariable));
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void readTypeVariables() {
for (Type type : typeVariable.getBounds()) {
registerTypeVariablesOn(type);
}
registerTypeVariablesOn(getActualTypeArgumentFor(typeVariable));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
8 | 7c35394fa940df4bd9ba9695bcbb00c73e60a21d127b3220f0ac09e99f98e7ef | public Week(Date time, TimeZone zone) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Creates a time period for the week in which the specified date/time
* falls, calculated relative to the specified time zone.
*
* @param time the date/time (<code>null</code> not permitted).
* @param zone the time zone (<code>null</code> not permitted).
*
* @deprecated As of 1.0.7, use {@link #Week(Date, TimeZone, Locale)}.
*/
public Week(Date time, TimeZone zone) {
// defer argument checking...
this(time, RegularTimePeriod.DEFAULT_TIME_ZONE, Locale.getDefault());
}
```
| public Week(Date time, TimeZone zone) {
// defer argument checking...
this(time, RegularTimePeriod.DEFAULT_TIME_ZONE, Locale.getDefault());
} | true | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Creates a time period for the week in which the specified date/time
* falls, calculated relative to the specified time zone.
*
* @param time the date/time (<code>null</code> not permitted).
* @param zone the time zone (<code>null</code> not permitted).
*
* @deprecated As of 1.0.7, use {@link #Week(Date, TimeZone, Locale)}.
*/
public Week(Date time, TimeZone zone) {
// defer argument checking...
this(time, RegularTimePeriod.DEFAULT_TIME_ZONE, Locale.getDefault());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
37 | 7d2a4e23b778162257f70d3eb2d1463133b1eaba29c49a0535a381602737e814 | public String html() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Retrieves the element's inner HTML. E.g. on a {@code <div>} with one empty {@code <p>}, would return
* {@code <p></p>}. (Whereas {@link #outerHtml()} would return {@code <div><p></p></div>}.)
*
* @return String of HTML.
* @see #outerHtml()
*/
public String html() {
StringBuilder accum = new StringBuilder();
html(accum);
return getOutputSettings().prettyPrint() ? accum.toString().trim() : accum.toString();
}
```
| public String html() {
StringBuilder accum = new StringBuilder();
html(accum);
return getOutputSettings().prettyPrint() ? accum.toString().trim() : accum.toString();
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Retrieves the element's inner HTML. E.g. on a {@code <div>} with one empty {@code <p>}, would return
* {@code <p></p>}. (Whereas {@link #outerHtml()} would return {@code <div><p></p></div>}.)
*
* @return String of HTML.
* @see #outerHtml()
*/
public String html() {
StringBuilder accum = new StringBuilder();
html(accum);
return getOutputSettings().prettyPrint() ? accum.toString().trim() : accum.toString();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 7d825c5e3ea5b5ee641e10b4222431b02a2d131bb27c3bb26b22a3fe0f7ab79d | private Attribute parseAttribute() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private Attribute parseAttribute() {
tq.consumeWhitespace();
String key = tq.consumeAttributeKey();
String value = "";
tq.consumeWhitespace();
if (tq.matchChomp("=")) {
tq.consumeWhitespace();
if (tq.matchChomp(SQ)) {
value = tq.chompTo(SQ);
} else if (tq.matchChomp(DQ)) {
value = tq.chompTo(DQ);
} else {
StringBuilder valueAccum = new StringBuilder();
// no ' or " to look for, so scan to end tag or space (or end of stream)
while (!tq.matchesAny("<", "/>", ">") && !tq.matchesWhitespace() && !tq.isEmpty()) {
valueAccum.append(tq.consume());
}
value = valueAccum.toString();
}
tq.consumeWhitespace();
}
if (key.length() != 0)
return Attribute.createFromEncoded(key, value);
else {
if (value.length() == 0) // no key, no val; unknown char, keep popping so not get stuck
tq.advance();
return null;
}
}
```
| private Attribute parseAttribute() {
tq.consumeWhitespace();
String key = tq.consumeAttributeKey();
String value = "";
tq.consumeWhitespace();
if (tq.matchChomp("=")) {
tq.consumeWhitespace();
if (tq.matchChomp(SQ)) {
value = tq.chompTo(SQ);
} else if (tq.matchChomp(DQ)) {
value = tq.chompTo(DQ);
} else {
StringBuilder valueAccum = new StringBuilder();
// no ' or " to look for, so scan to end tag or space (or end of stream)
while (!tq.matchesAny("<", "/>", ">") && !tq.matchesWhitespace() && !tq.isEmpty()) {
valueAccum.append(tq.consume());
}
value = valueAccum.toString();
}
tq.consumeWhitespace();
}
if (key.length() != 0)
return Attribute.createFromEncoded(key, value);
else {
if (value.length() == 0) // no key, no val; unknown char, keep popping so not get stuck
tq.advance();
return null;
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private Attribute parseAttribute() {
tq.consumeWhitespace();
String key = tq.consumeAttributeKey();
String value = "";
tq.consumeWhitespace();
if (tq.matchChomp("=")) {
tq.consumeWhitespace();
if (tq.matchChomp(SQ)) {
value = tq.chompTo(SQ);
} else if (tq.matchChomp(DQ)) {
value = tq.chompTo(DQ);
} else {
StringBuilder valueAccum = new StringBuilder();
// no ' or " to look for, so scan to end tag or space (or end of stream)
while (!tq.matchesAny("<", "/>", ">") && !tq.matchesWhitespace() && !tq.isEmpty()) {
valueAccum.append(tq.consume());
}
value = valueAccum.toString();
}
tq.consumeWhitespace();
}
if (key.length() != 0)
return Attribute.createFromEncoded(key, value);
else {
if (value.length() == 0) // no key, no val; unknown char, keep popping so not get stuck
tq.advance();
return null;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
41 | 7da7a6e53178da93f5483d3c129f74ffe0ea06e5c76405a4d92f5e20458e8ce1 | public ZipArchiveEntry getNextZipEntry() throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public ZipArchiveEntry getNextZipEntry() throws IOException {
boolean firstEntry = true;
if (closed || hitCentralDirectory) {
return null;
}
if (current != null) {
closeEntry();
firstEntry = false;
}
try {
if (firstEntry) {
// split archives have a special signature before the
// first local file header - look for it and fail with
// the appropriate error message if this is a split
// archive.
readFirstLocalFileHeader(LFH_BUF);
} else {
readFully(LFH_BUF);
}
} catch (final EOFException e) {
return null;
}
final ZipLong sig = new ZipLong(LFH_BUF);
if (sig.equals(ZipLong.CFH_SIG) || sig.equals(ZipLong.AED_SIG)) {
hitCentralDirectory = true;
skipRemainderOfArchive();
return null;
}
if (!sig.equals(ZipLong.LFH_SIG)) {
throw new ZipException(String.format("Unexpected record signature: 0X%X", sig.getValue()));
}
int off = WORD;
current = new CurrentEntry();
final int versionMadeBy = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
current.entry.setPlatform((versionMadeBy >> ZipFile.BYTE_SHIFT) & ZipFile.NIBLET_MASK);
final GeneralPurposeBit gpFlag = GeneralPurposeBit.parse(LFH_BUF, off);
final boolean hasUTF8Flag = gpFlag.usesUTF8ForNames();
final ZipEncoding entryEncoding = hasUTF8Flag ? ZipEncodingHelper.UTF8_ZIP_ENCODING : zipEncoding;
current.hasDataDescriptor = gpFlag.usesDataDescriptor();
current.entry.setGeneralPurposeBit(gpFlag);
off += SHORT;
current.entry.setMethod(ZipShort.getValue(LFH_BUF, off));
off += SHORT;
final long time = ZipUtil.dosToJavaTime(ZipLong.getValue(LFH_BUF, off));
current.entry.setTime(time);
off += WORD;
ZipLong size = null, cSize = null;
if (!current.hasDataDescriptor) {
current.entry.setCrc(ZipLong.getValue(LFH_BUF, off));
off += WORD;
cSize = new ZipLong(LFH_BUF, off);
off += WORD;
size = new ZipLong(LFH_BUF, off);
off += WORD;
} else {
off += 3 * WORD;
}
final int fileNameLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final int extraLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final byte[] fileName = new byte[fileNameLen];
readFully(fileName);
current.entry.setName(entryEncoding.decode(fileName), fileName);
final byte[] extraData = new byte[extraLen];
readFully(extraData);
current.entry.setExtra(extraData);
if (!hasUTF8Flag && useUnicodeExtraFields) {
ZipUtil.setNameAndCommentFromExtraFields(current.entry, fileName, null);
}
processZip64Extra(size, cSize);
if (current.entry.getCompressedSize() != ArchiveEntry.SIZE_UNKNOWN) {
if (current.entry.getMethod() == ZipMethod.UNSHRINKING.getCode()) {
current.in = new UnshrinkingInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.IMPLODING.getCode()) {
current.in = new ExplodingInputStream(
current.entry.getGeneralPurposeBit().getSlidingDictionarySize(),
current.entry.getGeneralPurposeBit().getNumberOfShannonFanoTrees(),
new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.BZIP2.getCode()) {
current.in = new BZip2CompressorInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
}
}
entriesRead++;
return current.entry;
}
```
| public ZipArchiveEntry getNextZipEntry() throws IOException {
boolean firstEntry = true;
if (closed || hitCentralDirectory) {
return null;
}
if (current != null) {
closeEntry();
firstEntry = false;
}
try {
if (firstEntry) {
// split archives have a special signature before the
// first local file header - look for it and fail with
// the appropriate error message if this is a split
// archive.
readFirstLocalFileHeader(LFH_BUF);
} else {
readFully(LFH_BUF);
}
} catch (final EOFException e) {
return null;
}
final ZipLong sig = new ZipLong(LFH_BUF);
if (sig.equals(ZipLong.CFH_SIG) || sig.equals(ZipLong.AED_SIG)) {
hitCentralDirectory = true;
skipRemainderOfArchive();
return null;
}
if (!sig.equals(ZipLong.LFH_SIG)) {
throw new ZipException(String.format("Unexpected record signature: 0X%X", sig.getValue()));
}
int off = WORD;
current = new CurrentEntry();
final int versionMadeBy = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
current.entry.setPlatform((versionMadeBy >> ZipFile.BYTE_SHIFT) & ZipFile.NIBLET_MASK);
final GeneralPurposeBit gpFlag = GeneralPurposeBit.parse(LFH_BUF, off);
final boolean hasUTF8Flag = gpFlag.usesUTF8ForNames();
final ZipEncoding entryEncoding = hasUTF8Flag ? ZipEncodingHelper.UTF8_ZIP_ENCODING : zipEncoding;
current.hasDataDescriptor = gpFlag.usesDataDescriptor();
current.entry.setGeneralPurposeBit(gpFlag);
off += SHORT;
current.entry.setMethod(ZipShort.getValue(LFH_BUF, off));
off += SHORT;
final long time = ZipUtil.dosToJavaTime(ZipLong.getValue(LFH_BUF, off));
current.entry.setTime(time);
off += WORD;
ZipLong size = null, cSize = null;
if (!current.hasDataDescriptor) {
current.entry.setCrc(ZipLong.getValue(LFH_BUF, off));
off += WORD;
cSize = new ZipLong(LFH_BUF, off);
off += WORD;
size = new ZipLong(LFH_BUF, off);
off += WORD;
} else {
off += 3 * WORD;
}
final int fileNameLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final int extraLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final byte[] fileName = new byte[fileNameLen];
readFully(fileName);
current.entry.setName(entryEncoding.decode(fileName), fileName);
final byte[] extraData = new byte[extraLen];
readFully(extraData);
current.entry.setExtra(extraData);
if (!hasUTF8Flag && useUnicodeExtraFields) {
ZipUtil.setNameAndCommentFromExtraFields(current.entry, fileName, null);
}
processZip64Extra(size, cSize);
if (current.entry.getCompressedSize() != ArchiveEntry.SIZE_UNKNOWN) {
if (current.entry.getMethod() == ZipMethod.UNSHRINKING.getCode()) {
current.in = new UnshrinkingInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.IMPLODING.getCode()) {
current.in = new ExplodingInputStream(
current.entry.getGeneralPurposeBit().getSlidingDictionarySize(),
current.entry.getGeneralPurposeBit().getNumberOfShannonFanoTrees(),
new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.BZIP2.getCode()) {
current.in = new BZip2CompressorInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
}
}
entriesRead++;
return current.entry;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public ZipArchiveEntry getNextZipEntry() throws IOException {
boolean firstEntry = true;
if (closed || hitCentralDirectory) {
return null;
}
if (current != null) {
closeEntry();
firstEntry = false;
}
try {
if (firstEntry) {
// split archives have a special signature before the
// first local file header - look for it and fail with
// the appropriate error message if this is a split
// archive.
readFirstLocalFileHeader(LFH_BUF);
} else {
readFully(LFH_BUF);
}
} catch (final EOFException e) {
return null;
}
final ZipLong sig = new ZipLong(LFH_BUF);
if (sig.equals(ZipLong.CFH_SIG) || sig.equals(ZipLong.AED_SIG)) {
hitCentralDirectory = true;
skipRemainderOfArchive();
return null;
}
if (!sig.equals(ZipLong.LFH_SIG)) {
throw new ZipException(String.format("Unexpected record signature: 0X%X", sig.getValue()));
}
int off = WORD;
current = new CurrentEntry();
final int versionMadeBy = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
current.entry.setPlatform((versionMadeBy >> ZipFile.BYTE_SHIFT) & ZipFile.NIBLET_MASK);
final GeneralPurposeBit gpFlag = GeneralPurposeBit.parse(LFH_BUF, off);
final boolean hasUTF8Flag = gpFlag.usesUTF8ForNames();
final ZipEncoding entryEncoding = hasUTF8Flag ? ZipEncodingHelper.UTF8_ZIP_ENCODING : zipEncoding;
current.hasDataDescriptor = gpFlag.usesDataDescriptor();
current.entry.setGeneralPurposeBit(gpFlag);
off += SHORT;
current.entry.setMethod(ZipShort.getValue(LFH_BUF, off));
off += SHORT;
final long time = ZipUtil.dosToJavaTime(ZipLong.getValue(LFH_BUF, off));
current.entry.setTime(time);
off += WORD;
ZipLong size = null, cSize = null;
if (!current.hasDataDescriptor) {
current.entry.setCrc(ZipLong.getValue(LFH_BUF, off));
off += WORD;
cSize = new ZipLong(LFH_BUF, off);
off += WORD;
size = new ZipLong(LFH_BUF, off);
off += WORD;
} else {
off += 3 * WORD;
}
final int fileNameLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final int extraLen = ZipShort.getValue(LFH_BUF, off);
off += SHORT;
final byte[] fileName = new byte[fileNameLen];
readFully(fileName);
current.entry.setName(entryEncoding.decode(fileName), fileName);
final byte[] extraData = new byte[extraLen];
readFully(extraData);
current.entry.setExtra(extraData);
if (!hasUTF8Flag && useUnicodeExtraFields) {
ZipUtil.setNameAndCommentFromExtraFields(current.entry, fileName, null);
}
processZip64Extra(size, cSize);
if (current.entry.getCompressedSize() != ArchiveEntry.SIZE_UNKNOWN) {
if (current.entry.getMethod() == ZipMethod.UNSHRINKING.getCode()) {
current.in = new UnshrinkingInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.IMPLODING.getCode()) {
current.in = new ExplodingInputStream(
current.entry.getGeneralPurposeBit().getSlidingDictionarySize(),
current.entry.getGeneralPurposeBit().getNumberOfShannonFanoTrees(),
new BoundedInputStream(in, current.entry.getCompressedSize()));
} else if (current.entry.getMethod() == ZipMethod.BZIP2.getCode()) {
current.in = new BZip2CompressorInputStream(new BoundedInputStream(in, current.entry.getCompressedSize()));
}
}
entriesRead++;
return current.entry;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
6 | 7ebca05fac7bcca4f0d44007c3a826ea819e66d91e45fc30a09fb23eaff9ea12 | private final static int _parseIndex(String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Internal methods
/**********************************************************
*/
private final static int _parseIndex(String str) {
final int len = str.length();
// [core#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
// [core#176]: no leading zeroes allowed
for (int i = 0; i < len; ++i) {
char c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
}
```
| private final static int _parseIndex(String str) {
final int len = str.length();
// [core#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
// [core#176]: no leading zeroes allowed
for (int i = 0; i < len; ++i) {
char c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
} | true | JacksonCore | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Internal methods
/**********************************************************
*/
private final static int _parseIndex(String str) {
final int len = str.length();
// [core#133]: beware of super long indexes; assume we never
// have arrays over 2 billion entries so ints are fine.
if (len == 0 || len > 10) {
return -1;
}
// [core#176]: no leading zeroes allowed
for (int i = 0; i < len; ++i) {
char c = str.charAt(i);
if (c > '9' || c < '0') {
return -1;
}
}
if (len == 10) {
long l = NumberInput.parseLong(str);
if (l > Integer.MAX_VALUE) {
return -1;
}
}
return NumberInput.parseInt(str);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
17 | 7ee5c9100b1a51d88487f2c3406d6dcce9f9bdbf350c9cfffb0907ff31835fa8 | public static String newStringIso8859_1(final byte[] bytes) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Constructs a new <code>String</code> by decoding the specified array of bytes using the ISO-8859-1 charset.
*
* @param bytes
* The bytes to be decoded into characters, may be <code>null</code>
* @return A new <code>String</code> decoded from the specified array of bytes using the ISO-8859-1 charset, or
* <code>null</code> if the input byte array was <code>null</code>.
* @throws NullPointerException
* Thrown if {@link Charsets#ISO_8859_1} is not initialized, which should never happen since it is
* required by the Java platform specification.
* @since As of 1.7, throws {@link NullPointerException} instead of UnsupportedEncodingException
*/
public static String newStringIso8859_1(final byte[] bytes) {
return new String(bytes, Charsets.ISO_8859_1);
}
```
| public static String newStringIso8859_1(final byte[] bytes) {
return new String(bytes, Charsets.ISO_8859_1);
} | true | Codec | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Constructs a new <code>String</code> by decoding the specified array of bytes using the ISO-8859-1 charset.
*
* @param bytes
* The bytes to be decoded into characters, may be <code>null</code>
* @return A new <code>String</code> decoded from the specified array of bytes using the ISO-8859-1 charset, or
* <code>null</code> if the input byte array was <code>null</code>.
* @throws NullPointerException
* Thrown if {@link Charsets#ISO_8859_1} is not initialized, which should never happen since it is
* required by the Java platform specification.
* @since As of 1.7, throws {@link NullPointerException} instead of UnsupportedEncodingException
*/
public static String newStringIso8859_1(final byte[] bytes) {
return new String(bytes, Charsets.ISO_8859_1);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
67 | 7f1740751feb63c74e65aa3d79665fda7495e608297b658868537811050ec651 | private boolean isPrototypePropertyAssign(Node assign) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private boolean isPrototypePropertyAssign(Node assign) {
Node n = assign.getFirstChild();
if (n != null && NodeUtil.isVarOrSimpleAssignLhs(n, assign)
&& n.getType() == Token.GETPROP
) {
// We want to exclude the assignment itself from the usage list
boolean isChainedProperty =
n.getFirstChild().getType() == Token.GETPROP;
if (isChainedProperty) {
Node child = n.getFirstChild().getFirstChild().getNext();
if (child.getType() == Token.STRING &&
child.getString().equals("prototype")) {
return true;
}
}
}
return false;
}
```
| private boolean isPrototypePropertyAssign(Node assign) {
Node n = assign.getFirstChild();
if (n != null && NodeUtil.isVarOrSimpleAssignLhs(n, assign)
&& n.getType() == Token.GETPROP
) {
// We want to exclude the assignment itself from the usage list
boolean isChainedProperty =
n.getFirstChild().getType() == Token.GETPROP;
if (isChainedProperty) {
Node child = n.getFirstChild().getFirstChild().getNext();
if (child.getType() == Token.STRING &&
child.getString().equals("prototype")) {
return true;
}
}
}
return false;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private boolean isPrototypePropertyAssign(Node assign) {
Node n = assign.getFirstChild();
if (n != null && NodeUtil.isVarOrSimpleAssignLhs(n, assign)
&& n.getType() == Token.GETPROP
) {
// We want to exclude the assignment itself from the usage list
boolean isChainedProperty =
n.getFirstChild().getType() == Token.GETPROP;
if (isChainedProperty) {
Node child = n.getFirstChild().getFirstChild().getNext();
if (child.getType() == Token.STRING &&
child.getString().equals("prototype")) {
return true;
}
}
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | 7f701ff91a31b2b4a3971407bc88809af8ec10d153efc1831a2ce288f887f082 | public static long parseOctal(final byte[] buffer, final int offset, final int length) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Trim all trailing NULs and spaces.
// The ustar and POSIX tar specs require a trailing NUL or
// space but some implementations use the extra digit for big
// sizes/uids/gids ...
byte trailer = buffer[end - 1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
trailer = buffer[end - 1];
while (start < end - 1 && (trailer == 0 || trailer == ' ')) {
end--;
trailer = buffer[end - 1];
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
```
| public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Trim all trailing NULs and spaces.
// The ustar and POSIX tar specs require a trailing NUL or
// space but some implementations use the extra digit for big
// sizes/uids/gids ...
byte trailer = buffer[end - 1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
trailer = buffer[end - 1];
while (start < end - 1 && (trailer == 0 || trailer == ' ')) {
end--;
trailer = buffer[end - 1];
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
} | true | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parse an octal string from a buffer.
*
* <p>Leading spaces are ignored.
* The buffer must contain a trailing space or NUL,
* and may contain an additional trailing space or NUL.</p>
*
* <p>The input buffer is allowed to contain all NULs,
* in which case the method returns 0L
* (this allows for missing fields).</p>
*
* <p>To work-around some tar implementations that insert a
* leading NUL this method returns 0 if it detects a leading NUL
* since Commons Compress 1.4.</p>
*
* @param buffer The buffer from which to parse.
* @param offset The offset into the buffer from which to parse.
* @param length The maximum number of bytes to parse - must be at least 2 bytes.
* @return The long value of the octal string.
* @throws IllegalArgumentException if the trailing space/NUL is missing or if a invalid byte is detected.
*/
public static long parseOctal(final byte[] buffer, final int offset, final int length) {
long result = 0;
int end = offset + length;
int start = offset;
if (length < 2){
throw new IllegalArgumentException("Length "+length+" must be at least 2");
}
if (buffer[start] == 0) {
return 0L;
}
// Skip leading spaces
while (start < end){
if (buffer[start] == ' '){
start++;
} else {
break;
}
}
// Trim all trailing NULs and spaces.
// The ustar and POSIX tar specs require a trailing NUL or
// space but some implementations use the extra digit for big
// sizes/uids/gids ...
byte trailer = buffer[end - 1];
if (trailer == 0 || trailer == ' '){
end--;
} else {
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, end-1, trailer));
}
trailer = buffer[end - 1];
while (start < end - 1 && (trailer == 0 || trailer == ' ')) {
end--;
trailer = buffer[end - 1];
}
for ( ;start < end; start++) {
final byte currentByte = buffer[start];
// CheckStyle:MagicNumber OFF
if (currentByte < '0' || currentByte > '7'){
throw new IllegalArgumentException(
exceptionMessage(buffer, offset, length, start, currentByte));
}
result = (result << 3) + (currentByte - '0'); // convert from ASCII
// CheckStyle:MagicNumber ON
}
return result;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
24 | 7f73c80550644cf96204e9c629bda051477277333eb3d188fcc2f242ff6ec927 | private void findAliases(NodeTraversal t) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void findAliases(NodeTraversal t) {
Scope scope = t.getScope();
for (Var v : scope.getVarIterable()) {
Node n = v.getNode();
int type = n.getType();
Node parent = n.getParent();
if (parent.isVar()) {
if (n.hasChildren() && n.getFirstChild().isQualifiedName()) {
String name = n.getString();
Var aliasVar = scope.getVar(name);
aliases.put(name, aliasVar);
String qualifiedName =
aliasVar.getInitialValue().getQualifiedName();
transformation.addAlias(name, qualifiedName);
// Bleeding functions already get a BAD_PARAMETERS error, so just
// do nothing.
// Parameters of the scope function also get a BAD_PARAMETERS
// error.
} else {
// TODO(robbyw): Support using locals for private variables.
report(t, n, GOOG_SCOPE_NON_ALIAS_LOCAL, n.getString());
}
}
}
}
```
| private void findAliases(NodeTraversal t) {
Scope scope = t.getScope();
for (Var v : scope.getVarIterable()) {
Node n = v.getNode();
int type = n.getType();
Node parent = n.getParent();
if (parent.isVar()) {
if (n.hasChildren() && n.getFirstChild().isQualifiedName()) {
String name = n.getString();
Var aliasVar = scope.getVar(name);
aliases.put(name, aliasVar);
String qualifiedName =
aliasVar.getInitialValue().getQualifiedName();
transformation.addAlias(name, qualifiedName);
// Bleeding functions already get a BAD_PARAMETERS error, so just
// do nothing.
// Parameters of the scope function also get a BAD_PARAMETERS
// error.
} else {
// TODO(robbyw): Support using locals for private variables.
report(t, n, GOOG_SCOPE_NON_ALIAS_LOCAL, n.getString());
}
}
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void findAliases(NodeTraversal t) {
Scope scope = t.getScope();
for (Var v : scope.getVarIterable()) {
Node n = v.getNode();
int type = n.getType();
Node parent = n.getParent();
if (parent.isVar()) {
if (n.hasChildren() && n.getFirstChild().isQualifiedName()) {
String name = n.getString();
Var aliasVar = scope.getVar(name);
aliases.put(name, aliasVar);
String qualifiedName =
aliasVar.getInitialValue().getQualifiedName();
transformation.addAlias(name, qualifiedName);
// Bleeding functions already get a BAD_PARAMETERS error, so just
// do nothing.
// Parameters of the scope function also get a BAD_PARAMETERS
// error.
} else {
// TODO(robbyw): Support using locals for private variables.
report(t, n, GOOG_SCOPE_NON_ALIAS_LOCAL, n.getString());
}
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
106 | 7f9ce5cfeb24048f8655e4ea4d0fd3e8a7b9195fd394503c8d9c2e29fa238f56 | public Fraction parse(String source, ParsePosition pos) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses a string to produce a {@link Fraction} object. This method
* expects the string to be formatted as a proper fraction.
* <p>
* Minus signs are only allowed in the whole number part - i.e.,
* "-3 1/2" is legitimate and denotes -7/2, but "-3 -1/2" is invalid and
* will result in a <code>ParseException</code>.
*
* @param source the string to parse
* @param pos input/ouput parsing parameter.
* @return the parsed {@link Fraction} object.
*/
public Fraction parse(String source, ParsePosition pos) {
// try to parse improper fraction
Fraction ret = super.parse(source, pos);
if (ret != null) {
return ret;
}
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse whole
Number whole = getWholeFormat().parse(source, pos);
if (whole == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse numerator
Number num = getNumeratorFormat().parse(source, pos);
if (num == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
if (num.intValue() < 0) {
// minus signs should be leading, invalid expression
pos.setIndex(initialIndex);
return null;
}
// parse '/'
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
switch (c) {
case 0 :
// no '/'
// return num as a fraction
return new Fraction(num.intValue(), 1);
case '/' :
// found '/', continue parsing denominator
break;
default :
// invalid '/'
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse denominator
Number den = getDenominatorFormat().parse(source, pos);
if (den == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
if (den.intValue() < 0) {
// minus signs must be leading, invalid
pos.setIndex(initialIndex);
return null;
}
int w = whole.intValue();
int n = num.intValue();
int d = den.intValue();
return new Fraction(((Math.abs(w) * d) + n) * MathUtils.sign(w), d);
}
```
| public Fraction parse(String source, ParsePosition pos) {
// try to parse improper fraction
Fraction ret = super.parse(source, pos);
if (ret != null) {
return ret;
}
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse whole
Number whole = getWholeFormat().parse(source, pos);
if (whole == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse numerator
Number num = getNumeratorFormat().parse(source, pos);
if (num == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
if (num.intValue() < 0) {
// minus signs should be leading, invalid expression
pos.setIndex(initialIndex);
return null;
}
// parse '/'
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
switch (c) {
case 0 :
// no '/'
// return num as a fraction
return new Fraction(num.intValue(), 1);
case '/' :
// found '/', continue parsing denominator
break;
default :
// invalid '/'
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse denominator
Number den = getDenominatorFormat().parse(source, pos);
if (den == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
if (den.intValue() < 0) {
// minus signs must be leading, invalid
pos.setIndex(initialIndex);
return null;
}
int w = whole.intValue();
int n = num.intValue();
int d = den.intValue();
return new Fraction(((Math.abs(w) * d) + n) * MathUtils.sign(w), d);
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses a string to produce a {@link Fraction} object. This method
* expects the string to be formatted as a proper fraction.
* <p>
* Minus signs are only allowed in the whole number part - i.e.,
* "-3 1/2" is legitimate and denotes -7/2, but "-3 -1/2" is invalid and
* will result in a <code>ParseException</code>.
*
* @param source the string to parse
* @param pos input/ouput parsing parameter.
* @return the parsed {@link Fraction} object.
*/
public Fraction parse(String source, ParsePosition pos) {
// try to parse improper fraction
Fraction ret = super.parse(source, pos);
if (ret != null) {
return ret;
}
int initialIndex = pos.getIndex();
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse whole
Number whole = getWholeFormat().parse(source, pos);
if (whole == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse numerator
Number num = getNumeratorFormat().parse(source, pos);
if (num == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
if (num.intValue() < 0) {
// minus signs should be leading, invalid expression
pos.setIndex(initialIndex);
return null;
}
// parse '/'
int startIndex = pos.getIndex();
char c = parseNextCharacter(source, pos);
switch (c) {
case 0 :
// no '/'
// return num as a fraction
return new Fraction(num.intValue(), 1);
case '/' :
// found '/', continue parsing denominator
break;
default :
// invalid '/'
// set index back to initial, error index should be the last
// character examined.
pos.setIndex(initialIndex);
pos.setErrorIndex(startIndex);
return null;
}
// parse whitespace
parseAndIgnoreWhitespace(source, pos);
// parse denominator
Number den = getDenominatorFormat().parse(source, pos);
if (den == null) {
// invalid integer number
// set index back to initial, error index should already be set
// character examined.
pos.setIndex(initialIndex);
return null;
}
if (den.intValue() < 0) {
// minus signs must be leading, invalid
pos.setIndex(initialIndex);
return null;
}
int w = whole.intValue();
int n = num.intValue();
int d = den.intValue();
return new Fraction(((Math.abs(w) * d) + n) * MathUtils.sign(w), d);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
23 | 800d4d5b7390ae52c270c3049dbe8401fc7f0dfc005c25683f8608f66fcfb1d4 | private static synchronized String getConvertedId(String id) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Converts an old style id to a new style id.
*
* @param id the old style id
* @return the new style id, null if not found
*/
//-----------------------------------------------------------------------
private static synchronized String getConvertedId(String id) {
Map<String, String> map = cZoneIdConversion;
if (map == null) {
// Backwards compatibility with TimeZone.
map = new HashMap<String, String>();
map.put("GMT", "UTC");
map.put("MIT", "Pacific/Apia");
map.put("HST", "Pacific/Honolulu"); // JDK 1.1 compatible
map.put("AST", "America/Anchorage");
map.put("PST", "America/Los_Angeles");
map.put("MST", "America/Denver"); // JDK 1.1 compatible
map.put("PNT", "America/Phoenix");
map.put("CST", "America/Chicago");
map.put("EST", "America/New_York"); // JDK 1.1 compatible
map.put("IET", "America/Indianapolis");
map.put("PRT", "America/Puerto_Rico");
map.put("CNT", "America/St_Johns");
map.put("AGT", "America/Buenos_Aires");
map.put("BET", "America/Sao_Paulo");
map.put("WET", "Europe/London");
map.put("ECT", "Europe/Paris");
map.put("ART", "Africa/Cairo");
map.put("CAT", "Africa/Harare");
map.put("EET", "Europe/Bucharest");
map.put("EAT", "Africa/Addis_Ababa");
map.put("MET", "Asia/Tehran");
map.put("NET", "Asia/Yerevan");
map.put("PLT", "Asia/Karachi");
map.put("IST", "Asia/Calcutta");
map.put("BST", "Asia/Dhaka");
map.put("VST", "Asia/Saigon");
map.put("CTT", "Asia/Shanghai");
map.put("JST", "Asia/Tokyo");
map.put("ACT", "Australia/Darwin");
map.put("AET", "Australia/Sydney");
map.put("SST", "Pacific/Guadalcanal");
map.put("NST", "Pacific/Auckland");
cZoneIdConversion = map;
}
return map.get(id);
}
```
| private static synchronized String getConvertedId(String id) {
Map<String, String> map = cZoneIdConversion;
if (map == null) {
// Backwards compatibility with TimeZone.
map = new HashMap<String, String>();
map.put("GMT", "UTC");
map.put("MIT", "Pacific/Apia");
map.put("HST", "Pacific/Honolulu"); // JDK 1.1 compatible
map.put("AST", "America/Anchorage");
map.put("PST", "America/Los_Angeles");
map.put("MST", "America/Denver"); // JDK 1.1 compatible
map.put("PNT", "America/Phoenix");
map.put("CST", "America/Chicago");
map.put("EST", "America/New_York"); // JDK 1.1 compatible
map.put("IET", "America/Indianapolis");
map.put("PRT", "America/Puerto_Rico");
map.put("CNT", "America/St_Johns");
map.put("AGT", "America/Buenos_Aires");
map.put("BET", "America/Sao_Paulo");
map.put("WET", "Europe/London");
map.put("ECT", "Europe/Paris");
map.put("ART", "Africa/Cairo");
map.put("CAT", "Africa/Harare");
map.put("EET", "Europe/Bucharest");
map.put("EAT", "Africa/Addis_Ababa");
map.put("MET", "Asia/Tehran");
map.put("NET", "Asia/Yerevan");
map.put("PLT", "Asia/Karachi");
map.put("IST", "Asia/Calcutta");
map.put("BST", "Asia/Dhaka");
map.put("VST", "Asia/Saigon");
map.put("CTT", "Asia/Shanghai");
map.put("JST", "Asia/Tokyo");
map.put("ACT", "Australia/Darwin");
map.put("AET", "Australia/Sydney");
map.put("SST", "Pacific/Guadalcanal");
map.put("NST", "Pacific/Auckland");
cZoneIdConversion = map;
}
return map.get(id);
} | true | Time | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Converts an old style id to a new style id.
*
* @param id the old style id
* @return the new style id, null if not found
*/
//-----------------------------------------------------------------------
private static synchronized String getConvertedId(String id) {
Map<String, String> map = cZoneIdConversion;
if (map == null) {
// Backwards compatibility with TimeZone.
map = new HashMap<String, String>();
map.put("GMT", "UTC");
map.put("MIT", "Pacific/Apia");
map.put("HST", "Pacific/Honolulu"); // JDK 1.1 compatible
map.put("AST", "America/Anchorage");
map.put("PST", "America/Los_Angeles");
map.put("MST", "America/Denver"); // JDK 1.1 compatible
map.put("PNT", "America/Phoenix");
map.put("CST", "America/Chicago");
map.put("EST", "America/New_York"); // JDK 1.1 compatible
map.put("IET", "America/Indianapolis");
map.put("PRT", "America/Puerto_Rico");
map.put("CNT", "America/St_Johns");
map.put("AGT", "America/Buenos_Aires");
map.put("BET", "America/Sao_Paulo");
map.put("WET", "Europe/London");
map.put("ECT", "Europe/Paris");
map.put("ART", "Africa/Cairo");
map.put("CAT", "Africa/Harare");
map.put("EET", "Europe/Bucharest");
map.put("EAT", "Africa/Addis_Ababa");
map.put("MET", "Asia/Tehran");
map.put("NET", "Asia/Yerevan");
map.put("PLT", "Asia/Karachi");
map.put("IST", "Asia/Calcutta");
map.put("BST", "Asia/Dhaka");
map.put("VST", "Asia/Saigon");
map.put("CTT", "Asia/Shanghai");
map.put("JST", "Asia/Tokyo");
map.put("ACT", "Australia/Darwin");
map.put("AET", "Australia/Sydney");
map.put("SST", "Pacific/Guadalcanal");
map.put("NST", "Pacific/Auckland");
cZoneIdConversion = map;
}
return map.get(id);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
130 | 80dacb29e9c292817d93eb559d2213c067078993fe166a09000c53bc2c0425b5 | private void inlineAliases(GlobalNamespace namespace) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* For each qualified name N in the global scope, we check if:
* (a) No ancestor of N is ever aliased or assigned an unknown value type.
* (If N = "a.b.c", "a" and "a.b" are never aliased).
* (b) N has exactly one write, and it lives in the global scope.
* (c) N is aliased in a local scope.
*
* If (a) is true, then GlobalNamespace must know all the writes to N.
* If (a) and (b) are true, then N cannot change during the execution of
* a local scope.
* If (a) and (b) and (c) are true, then the alias can be inlined if the
* alias obeys the usual rules for how we decide whether a variable is
* inlineable.
* @see InlineVariables
*/
private void inlineAliases(GlobalNamespace namespace) {
// Invariant: All the names in the worklist meet condition (a).
Deque<Name> workList = new ArrayDeque<Name>(namespace.getNameForest());
while (!workList.isEmpty()) {
Name name = workList.pop();
// Don't attempt to inline a getter or setter property as a variable.
if (name.type == Name.Type.GET || name.type == Name.Type.SET) {
continue;
}
if (!name.inExterns && name.globalSets == 1 && name.localSets == 0 &&
name.aliasingGets > 0) {
// {@code name} meets condition (b). Find all of its local aliases
// and try to inline them.
List<Ref> refs = Lists.newArrayList(name.getRefs());
for (Ref ref : refs) {
if (ref.type == Type.ALIASING_GET && ref.scope.isLocal()) {
// {@code name} meets condition (c). Try to inline it.
if (inlineAliasIfPossible(ref, namespace)) {
name.removeRef(ref);
}
}
}
}
// Check if {@code name} has any aliases left after the
// local-alias-inlining above.
if ((name.type == Name.Type.OBJECTLIT ||
name.type == Name.Type.FUNCTION) &&
name.aliasingGets == 0 && name.props != null) {
// All of {@code name}'s children meet condition (a), so they can be
// added to the worklist.
workList.addAll(name.props);
}
}
}
```
| private void inlineAliases(GlobalNamespace namespace) {
// Invariant: All the names in the worklist meet condition (a).
Deque<Name> workList = new ArrayDeque<Name>(namespace.getNameForest());
while (!workList.isEmpty()) {
Name name = workList.pop();
// Don't attempt to inline a getter or setter property as a variable.
if (name.type == Name.Type.GET || name.type == Name.Type.SET) {
continue;
}
if (!name.inExterns && name.globalSets == 1 && name.localSets == 0 &&
name.aliasingGets > 0) {
// {@code name} meets condition (b). Find all of its local aliases
// and try to inline them.
List<Ref> refs = Lists.newArrayList(name.getRefs());
for (Ref ref : refs) {
if (ref.type == Type.ALIASING_GET && ref.scope.isLocal()) {
// {@code name} meets condition (c). Try to inline it.
if (inlineAliasIfPossible(ref, namespace)) {
name.removeRef(ref);
}
}
}
}
// Check if {@code name} has any aliases left after the
// local-alias-inlining above.
if ((name.type == Name.Type.OBJECTLIT ||
name.type == Name.Type.FUNCTION) &&
name.aliasingGets == 0 && name.props != null) {
// All of {@code name}'s children meet condition (a), so they can be
// added to the worklist.
workList.addAll(name.props);
}
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* For each qualified name N in the global scope, we check if:
* (a) No ancestor of N is ever aliased or assigned an unknown value type.
* (If N = "a.b.c", "a" and "a.b" are never aliased).
* (b) N has exactly one write, and it lives in the global scope.
* (c) N is aliased in a local scope.
*
* If (a) is true, then GlobalNamespace must know all the writes to N.
* If (a) and (b) are true, then N cannot change during the execution of
* a local scope.
* If (a) and (b) and (c) are true, then the alias can be inlined if the
* alias obeys the usual rules for how we decide whether a variable is
* inlineable.
* @see InlineVariables
*/
private void inlineAliases(GlobalNamespace namespace) {
// Invariant: All the names in the worklist meet condition (a).
Deque<Name> workList = new ArrayDeque<Name>(namespace.getNameForest());
while (!workList.isEmpty()) {
Name name = workList.pop();
// Don't attempt to inline a getter or setter property as a variable.
if (name.type == Name.Type.GET || name.type == Name.Type.SET) {
continue;
}
if (!name.inExterns && name.globalSets == 1 && name.localSets == 0 &&
name.aliasingGets > 0) {
// {@code name} meets condition (b). Find all of its local aliases
// and try to inline them.
List<Ref> refs = Lists.newArrayList(name.getRefs());
for (Ref ref : refs) {
if (ref.type == Type.ALIASING_GET && ref.scope.isLocal()) {
// {@code name} meets condition (c). Try to inline it.
if (inlineAliasIfPossible(ref, namespace)) {
name.removeRef(ref);
}
}
}
}
// Check if {@code name} has any aliases left after the
// local-alias-inlining above.
if ((name.type == Name.Type.OBJECTLIT ||
name.type == Name.Type.FUNCTION) &&
name.aliasingGets == 0 && name.props != null) {
// All of {@code name}'s children meet condition (a), so they can be
// added to the worklist.
workList.addAll(name.props);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
96 | 815653872d11708c3b2023290c77dc0635e3eb3abcff172f63e5f88419339fe5 | protected void _addExplicitAnyCreator(DeserializationContext ctxt,
BeanDescription beanDesc, CreatorCollector creators,
CreatorCandidate candidate)
throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Helper method called when there is the explicit "is-creator", but no mode declaration.
*
* @since 2.9.2
*/
protected void _addExplicitAnyCreator(DeserializationContext ctxt,
BeanDescription beanDesc, CreatorCollector creators,
CreatorCandidate candidate)
throws JsonMappingException
{
// Looks like there's bit of magic regarding 1-parameter creators; others simpler:
if (1 != candidate.paramCount()) {
// Ok: for delegates, we want one and exactly one parameter without
// injection AND without name
int oneNotInjected = candidate.findOnlyParamWithoutInjection();
if (oneNotInjected >= 0) {
// getting close; but most not have name
if (candidate.paramName(oneNotInjected) == null) {
_addExplicitDelegatingCreator(ctxt, beanDesc, creators, candidate);
return;
}
}
_addExplicitPropertyCreator(ctxt, beanDesc, creators, candidate);
return;
}
AnnotatedParameter param = candidate.parameter(0);
JacksonInject.Value injectId = candidate.injection(0);
PropertyName paramName = candidate.explicitParamName(0);
BeanPropertyDefinition paramDef = candidate.propertyDef(0);
// If there's injection or explicit name, should be properties-based
boolean useProps = (paramName != null) || (injectId != null);
if (!useProps && (paramDef != null)) {
// One more thing: if implicit name matches property with a getter
// or field, we'll consider it property-based as well
// 25-May-2018, tatu: as per [databind#2051], looks like we have to get
// not implicit name, but name with possible strategy-based-rename
// paramName = candidate.findImplicitParamName(0);
paramName = candidate.findImplicitParamName(0);
useProps = (paramName != null) && paramDef.couldSerialize();
}
if (useProps) {
SettableBeanProperty[] properties = new SettableBeanProperty[] {
constructCreatorProperty(ctxt, beanDesc, paramName, 0, param, injectId)
};
creators.addPropertyCreator(candidate.creator(), true, properties);
return;
}
_handleSingleArgumentCreator(creators, candidate.creator(), true, true);
// one more thing: sever link to creator property, to avoid possible later
// problems with "unresolved" constructor property
if (paramDef != null) {
((POJOPropertyBuilder) paramDef).removeConstructors();
}
}
```
| protected void _addExplicitAnyCreator(DeserializationContext ctxt,
BeanDescription beanDesc, CreatorCollector creators,
CreatorCandidate candidate)
throws JsonMappingException
{
// Looks like there's bit of magic regarding 1-parameter creators; others simpler:
if (1 != candidate.paramCount()) {
// Ok: for delegates, we want one and exactly one parameter without
// injection AND without name
int oneNotInjected = candidate.findOnlyParamWithoutInjection();
if (oneNotInjected >= 0) {
// getting close; but most not have name
if (candidate.paramName(oneNotInjected) == null) {
_addExplicitDelegatingCreator(ctxt, beanDesc, creators, candidate);
return;
}
}
_addExplicitPropertyCreator(ctxt, beanDesc, creators, candidate);
return;
}
AnnotatedParameter param = candidate.parameter(0);
JacksonInject.Value injectId = candidate.injection(0);
PropertyName paramName = candidate.explicitParamName(0);
BeanPropertyDefinition paramDef = candidate.propertyDef(0);
// If there's injection or explicit name, should be properties-based
boolean useProps = (paramName != null) || (injectId != null);
if (!useProps && (paramDef != null)) {
// One more thing: if implicit name matches property with a getter
// or field, we'll consider it property-based as well
// 25-May-2018, tatu: as per [databind#2051], looks like we have to get
// not implicit name, but name with possible strategy-based-rename
// paramName = candidate.findImplicitParamName(0);
paramName = candidate.findImplicitParamName(0);
useProps = (paramName != null) && paramDef.couldSerialize();
}
if (useProps) {
SettableBeanProperty[] properties = new SettableBeanProperty[] {
constructCreatorProperty(ctxt, beanDesc, paramName, 0, param, injectId)
};
creators.addPropertyCreator(candidate.creator(), true, properties);
return;
}
_handleSingleArgumentCreator(creators, candidate.creator(), true, true);
// one more thing: sever link to creator property, to avoid possible later
// problems with "unresolved" constructor property
if (paramDef != null) {
((POJOPropertyBuilder) paramDef).removeConstructors();
}
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Helper method called when there is the explicit "is-creator", but no mode declaration.
*
* @since 2.9.2
*/
protected void _addExplicitAnyCreator(DeserializationContext ctxt,
BeanDescription beanDesc, CreatorCollector creators,
CreatorCandidate candidate)
throws JsonMappingException
{
// Looks like there's bit of magic regarding 1-parameter creators; others simpler:
if (1 != candidate.paramCount()) {
// Ok: for delegates, we want one and exactly one parameter without
// injection AND without name
int oneNotInjected = candidate.findOnlyParamWithoutInjection();
if (oneNotInjected >= 0) {
// getting close; but most not have name
if (candidate.paramName(oneNotInjected) == null) {
_addExplicitDelegatingCreator(ctxt, beanDesc, creators, candidate);
return;
}
}
_addExplicitPropertyCreator(ctxt, beanDesc, creators, candidate);
return;
}
AnnotatedParameter param = candidate.parameter(0);
JacksonInject.Value injectId = candidate.injection(0);
PropertyName paramName = candidate.explicitParamName(0);
BeanPropertyDefinition paramDef = candidate.propertyDef(0);
// If there's injection or explicit name, should be properties-based
boolean useProps = (paramName != null) || (injectId != null);
if (!useProps && (paramDef != null)) {
// One more thing: if implicit name matches property with a getter
// or field, we'll consider it property-based as well
// 25-May-2018, tatu: as per [databind#2051], looks like we have to get
// not implicit name, but name with possible strategy-based-rename
// paramName = candidate.findImplicitParamName(0);
paramName = candidate.findImplicitParamName(0);
useProps = (paramName != null) && paramDef.couldSerialize();
}
if (useProps) {
SettableBeanProperty[] properties = new SettableBeanProperty[] {
constructCreatorProperty(ctxt, beanDesc, paramName, 0, param, injectId)
};
creators.addPropertyCreator(candidate.creator(), true, properties);
return;
}
_handleSingleArgumentCreator(creators, candidate.creator(), true, true);
// one more thing: sever link to creator property, to avoid possible later
// problems with "unresolved" constructor property
if (paramDef != null) {
((POJOPropertyBuilder) paramDef).removeConstructors();
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
25 | 81adad6f755c1e4b07811fd550b4cbf31261137c51367160d7e8b85d47d1f8ed | protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Render the specified text and return the rendered Options
* in a StringBuffer.
*
* @param sb The StringBuffer to place the rendered text into.
* @param width The number of characters to display per line
* @param nextLineTabStop The position on the next line for the first tab.
* @param text The text to be rendered.
*
* @return the StringBuffer with the rendered Options contents.
*/
protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
if (nextLineTabStop >= width)
{
// stops infinite loop happening
nextLineTabStop = 1;
}
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
}
if ( (text.length() > width) && (pos == nextLineTabStop - 1) )
{
pos = width;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
}
```
| protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
if (nextLineTabStop >= width)
{
// stops infinite loop happening
nextLineTabStop = 1;
}
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
}
if ( (text.length() > width) && (pos == nextLineTabStop - 1) )
{
pos = width;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Render the specified text and return the rendered Options
* in a StringBuffer.
*
* @param sb The StringBuffer to place the rendered text into.
* @param width The number of characters to display per line
* @param nextLineTabStop The position on the next line for the first tab.
* @param text The text to be rendered.
*
* @return the StringBuffer with the rendered Options contents.
*/
protected StringBuffer renderWrappedText(StringBuffer sb, int width,
int nextLineTabStop, String text)
{
int pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(rtrim(text));
return sb;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
if (nextLineTabStop >= width)
{
// stops infinite loop happening
nextLineTabStop = 1;
}
// all following lines must be padded with nextLineTabStop space
// characters
final String padding = createPadding(nextLineTabStop);
while (true)
{
text = padding + text.substring(pos).trim();
pos = findWrapPos(text, width, 0);
if (pos == -1)
{
sb.append(text);
return sb;
}
if ( (text.length() > width) && (pos == nextLineTabStop - 1) )
{
pos = width;
}
sb.append(rtrim(text.substring(0, pos))).append(defaultNewLine);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
10 | 81e4feccf9e7a513426e50e4cc62b2370469fc92e755e19813208da996e18a26 | private static StringBuilder escapeRegex(StringBuilder regex, String value, boolean unquote) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Escape constant fields into regular expression
* @param regex The destination regex
* @param value The source field
* @param unquote If true, replace two success quotes ('') with single quote (')
* @return The <code>StringBuilder</code>
*/
//-----------------------------------------------------------------------
// Support for strategies
private static StringBuilder escapeRegex(StringBuilder regex, String value, boolean unquote) {
boolean wasWhite= false;
for(int i= 0; i<value.length(); ++i) {
char c= value.charAt(i);
if(Character.isWhitespace(c)) {
if(!wasWhite) {
wasWhite= true;
regex.append("\\s*+");
}
continue;
}
wasWhite= false;
switch(c) {
case '\'':
if(unquote) {
if(++i==value.length()) {
return regex;
}
c= value.charAt(i);
}
break;
case '?':
case '[':
case ']':
case '(':
case ')':
case '{':
case '}':
case '\\':
case '|':
case '*':
case '+':
case '^':
case '$':
case '.':
regex.append('\\');
}
regex.append(c);
}
return regex;
}
```
| private static StringBuilder escapeRegex(StringBuilder regex, String value, boolean unquote) {
boolean wasWhite= false;
for(int i= 0; i<value.length(); ++i) {
char c= value.charAt(i);
if(Character.isWhitespace(c)) {
if(!wasWhite) {
wasWhite= true;
regex.append("\\s*+");
}
continue;
}
wasWhite= false;
switch(c) {
case '\'':
if(unquote) {
if(++i==value.length()) {
return regex;
}
c= value.charAt(i);
}
break;
case '?':
case '[':
case ']':
case '(':
case ')':
case '{':
case '}':
case '\\':
case '|':
case '*':
case '+':
case '^':
case '$':
case '.':
regex.append('\\');
}
regex.append(c);
}
return regex;
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Escape constant fields into regular expression
* @param regex The destination regex
* @param value The source field
* @param unquote If true, replace two success quotes ('') with single quote (')
* @return The <code>StringBuilder</code>
*/
//-----------------------------------------------------------------------
// Support for strategies
private static StringBuilder escapeRegex(StringBuilder regex, String value, boolean unquote) {
boolean wasWhite= false;
for(int i= 0; i<value.length(); ++i) {
char c= value.charAt(i);
if(Character.isWhitespace(c)) {
if(!wasWhite) {
wasWhite= true;
regex.append("\\s*+");
}
continue;
}
wasWhite= false;
switch(c) {
case '\'':
if(unquote) {
if(++i==value.length()) {
return regex;
}
c= value.charAt(i);
}
break;
case '?':
case '[':
case ']':
case '(':
case ')':
case '{':
case '}':
case '\\':
case '|':
case '*':
case '+':
case '^':
case '$':
case '.':
regex.append('\\');
}
regex.append(c);
}
return regex;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
51 | 8202ff8fc3a9e2cb207f55032b1ee8e850815269074839640826f85e304de4af | protected final JsonDeserializer<Object> _findDeserializer(DeserializationContext ctxt,
String typeId) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/*
/**********************************************************
/* Helper methods for sub-classes
/**********************************************************
*/
protected final JsonDeserializer<Object> _findDeserializer(DeserializationContext ctxt,
String typeId) throws IOException
{
JsonDeserializer<Object> deser = _deserializers.get(typeId);
if (deser == null) {
/* As per [Databind#305], need to provide contextual info. But for
* backwards compatibility, let's start by only supporting this
* for base class, not via interface. Later on we can add this
* to the interface, assuming deprecation at base class helps.
*/
JavaType type = _idResolver.typeFromId(ctxt, typeId);
if (type == null) {
// As per [JACKSON-614], use the default impl if no type id available:
deser = _findDefaultImplDeserializer(ctxt);
if (deser == null) {
// 10-May-2016, tatu: We may get some help...
JavaType actual = _handleUnknownTypeId(ctxt, typeId, _idResolver, _baseType);
if (actual == null) { // what should this be taken to mean?
// TODO: try to figure out something better
return null;
}
// ... would this actually work?
deser = ctxt.findContextualValueDeserializer(actual, _property);
}
} else {
/* 16-Dec-2010, tatu: Since nominal type we get here has no (generic) type parameters,
* we actually now need to explicitly narrow from base type (which may have parameterization)
* using raw type.
*
* One complication, though; can not change 'type class' (simple type to container); otherwise
* we may try to narrow a SimpleType (Object.class) into MapType (Map.class), losing actual
* type in process (getting SimpleType of Map.class which will not work as expected)
*/
if ((_baseType != null)
&& _baseType.getClass() == type.getClass()) {
/* 09-Aug-2015, tatu: Not sure if the second part of the check makes sense;
* but it appears to check that JavaType impl class is the same which is
* important for some reason?
* Disabling the check will break 2 Enum-related tests.
*/
// 19-Jun-2016, tatu: As per [databind#1270] we may actually get full
// generic type with custom type resolvers. If so, should try to retain them.
// Whether this is sufficient to avoid problems remains to be seen, but for
// now it should improve things.
type = ctxt.getTypeFactory().constructSpecializedType(_baseType, type.getRawClass());
}
deser = ctxt.findContextualValueDeserializer(type, _property);
}
_deserializers.put(typeId, deser);
}
return deser;
}
```
| protected final JsonDeserializer<Object> _findDeserializer(DeserializationContext ctxt,
String typeId) throws IOException
{
JsonDeserializer<Object> deser = _deserializers.get(typeId);
if (deser == null) {
/* As per [Databind#305], need to provide contextual info. But for
* backwards compatibility, let's start by only supporting this
* for base class, not via interface. Later on we can add this
* to the interface, assuming deprecation at base class helps.
*/
JavaType type = _idResolver.typeFromId(ctxt, typeId);
if (type == null) {
// As per [JACKSON-614], use the default impl if no type id available:
deser = _findDefaultImplDeserializer(ctxt);
if (deser == null) {
// 10-May-2016, tatu: We may get some help...
JavaType actual = _handleUnknownTypeId(ctxt, typeId, _idResolver, _baseType);
if (actual == null) { // what should this be taken to mean?
// TODO: try to figure out something better
return null;
}
// ... would this actually work?
deser = ctxt.findContextualValueDeserializer(actual, _property);
}
} else {
/* 16-Dec-2010, tatu: Since nominal type we get here has no (generic) type parameters,
* we actually now need to explicitly narrow from base type (which may have parameterization)
* using raw type.
*
* One complication, though; can not change 'type class' (simple type to container); otherwise
* we may try to narrow a SimpleType (Object.class) into MapType (Map.class), losing actual
* type in process (getting SimpleType of Map.class which will not work as expected)
*/
if ((_baseType != null)
&& _baseType.getClass() == type.getClass()) {
/* 09-Aug-2015, tatu: Not sure if the second part of the check makes sense;
* but it appears to check that JavaType impl class is the same which is
* important for some reason?
* Disabling the check will break 2 Enum-related tests.
*/
// 19-Jun-2016, tatu: As per [databind#1270] we may actually get full
// generic type with custom type resolvers. If so, should try to retain them.
// Whether this is sufficient to avoid problems remains to be seen, but for
// now it should improve things.
type = ctxt.getTypeFactory().constructSpecializedType(_baseType, type.getRawClass());
}
deser = ctxt.findContextualValueDeserializer(type, _property);
}
_deserializers.put(typeId, deser);
}
return deser;
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/*
/**********************************************************
/* Helper methods for sub-classes
/**********************************************************
*/
protected final JsonDeserializer<Object> _findDeserializer(DeserializationContext ctxt,
String typeId) throws IOException
{
JsonDeserializer<Object> deser = _deserializers.get(typeId);
if (deser == null) {
/* As per [Databind#305], need to provide contextual info. But for
* backwards compatibility, let's start by only supporting this
* for base class, not via interface. Later on we can add this
* to the interface, assuming deprecation at base class helps.
*/
JavaType type = _idResolver.typeFromId(ctxt, typeId);
if (type == null) {
// As per [JACKSON-614], use the default impl if no type id available:
deser = _findDefaultImplDeserializer(ctxt);
if (deser == null) {
// 10-May-2016, tatu: We may get some help...
JavaType actual = _handleUnknownTypeId(ctxt, typeId, _idResolver, _baseType);
if (actual == null) { // what should this be taken to mean?
// TODO: try to figure out something better
return null;
}
// ... would this actually work?
deser = ctxt.findContextualValueDeserializer(actual, _property);
}
} else {
/* 16-Dec-2010, tatu: Since nominal type we get here has no (generic) type parameters,
* we actually now need to explicitly narrow from base type (which may have parameterization)
* using raw type.
*
* One complication, though; can not change 'type class' (simple type to container); otherwise
* we may try to narrow a SimpleType (Object.class) into MapType (Map.class), losing actual
* type in process (getting SimpleType of Map.class which will not work as expected)
*/
if ((_baseType != null)
&& _baseType.getClass() == type.getClass()) {
/* 09-Aug-2015, tatu: Not sure if the second part of the check makes sense;
* but it appears to check that JavaType impl class is the same which is
* important for some reason?
* Disabling the check will break 2 Enum-related tests.
*/
// 19-Jun-2016, tatu: As per [databind#1270] we may actually get full
// generic type with custom type resolvers. If so, should try to retain them.
// Whether this is sufficient to avoid problems remains to be seen, but for
// now it should improve things.
type = ctxt.getTypeFactory().constructSpecializedType(_baseType, type.getRawClass());
}
deser = ctxt.findContextualValueDeserializer(type, _property);
}
_deserializers.put(typeId, deser);
}
return deser;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
35 | 82846c0d04e7d13b8159a4a1af0857c4faa0da655eaa2294289223f0383a04bc | public static boolean verifyCheckSum(byte[] header) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Wikipedia <a href="http://en.wikipedia.org/wiki/Tar_(file_format)#File_header">says</a>:
* <blockquote>
* The checksum is calculated by taking the sum of the unsigned byte values
* of the header block with the eight checksum bytes taken to be ascii
* spaces (decimal value 32). It is stored as a six digit octal number with
* leading zeroes followed by a NUL and then a space. Various
* implementations do not adhere to this format. For better compatibility,
* ignore leading and trailing whitespace, and get the first six digits. In
* addition, some historic tar implementations treated bytes as signed.
* Implementations typically calculate the checksum both ways, and treat it
* as good if either the signed or unsigned sum matches the included
* checksum.
* </blockquote>
* <p>
* The return value of this method should be treated as a best-effort
* heuristic rather than an absolute and final truth. The checksum
* verification logic may well evolve over time as more special cases
* are encountered.
*
* @param header tar header
* @return whether the checksum is reasonably good
* @see <a href="https://issues.apache.org/jira/browse/COMPRESS-191">COMPRESS-191</a>
* @since 1.5
*/
public static boolean verifyCheckSum(byte[] header) {
long storedSum = parseOctal(header, CHKSUM_OFFSET, CHKSUMLEN);
long unsignedSum = 0;
long signedSum = 0;
int digits = 0;
for (int i = 0; i < header.length; i++) {
byte b = header[i];
if (CHKSUM_OFFSET <= i && i < CHKSUM_OFFSET + CHKSUMLEN) {
b = ' ';
}
unsignedSum += 0xff & b;
signedSum += b;
}
return storedSum == unsignedSum || storedSum == signedSum;
}
```
| public static boolean verifyCheckSum(byte[] header) {
long storedSum = parseOctal(header, CHKSUM_OFFSET, CHKSUMLEN);
long unsignedSum = 0;
long signedSum = 0;
int digits = 0;
for (int i = 0; i < header.length; i++) {
byte b = header[i];
if (CHKSUM_OFFSET <= i && i < CHKSUM_OFFSET + CHKSUMLEN) {
b = ' ';
}
unsignedSum += 0xff & b;
signedSum += b;
}
return storedSum == unsignedSum || storedSum == signedSum;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Wikipedia <a href="http://en.wikipedia.org/wiki/Tar_(file_format)#File_header">says</a>:
* <blockquote>
* The checksum is calculated by taking the sum of the unsigned byte values
* of the header block with the eight checksum bytes taken to be ascii
* spaces (decimal value 32). It is stored as a six digit octal number with
* leading zeroes followed by a NUL and then a space. Various
* implementations do not adhere to this format. For better compatibility,
* ignore leading and trailing whitespace, and get the first six digits. In
* addition, some historic tar implementations treated bytes as signed.
* Implementations typically calculate the checksum both ways, and treat it
* as good if either the signed or unsigned sum matches the included
* checksum.
* </blockquote>
* <p>
* The return value of this method should be treated as a best-effort
* heuristic rather than an absolute and final truth. The checksum
* verification logic may well evolve over time as more special cases
* are encountered.
*
* @param header tar header
* @return whether the checksum is reasonably good
* @see <a href="https://issues.apache.org/jira/browse/COMPRESS-191">COMPRESS-191</a>
* @since 1.5
*/
public static boolean verifyCheckSum(byte[] header) {
long storedSum = parseOctal(header, CHKSUM_OFFSET, CHKSUMLEN);
long unsignedSum = 0;
long signedSum = 0;
int digits = 0;
for (int i = 0; i < header.length; i++) {
byte b = header[i];
if (CHKSUM_OFFSET <= i && i < CHKSUM_OFFSET + CHKSUMLEN) {
b = ' ';
}
unsignedSum += 0xff & b;
signedSum += b;
}
return storedSum == unsignedSum || storedSum == signedSum;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
16 | 8317510443fcfaf72705e2bf769807145111cdf14a15b52d2b638b50c28316a4 | public static Number createNumber(String str) throws NumberFormatException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code> (lower or upper case), it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos || expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
if (expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
}
}
```
| public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos || expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
if (expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
}
} | true | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Turns a string value into a java.lang.Number.</p>
*
* <p>First, the value is examined for a type qualifier on the end
* (<code>'f','F','d','D','l','L'</code>). If it is found, it starts
* trying to create successively larger types from the type specified
* until one is found that can represent the value.</p>
*
* <p>If a type specifier is not found, it will check for a decimal point
* and then try successively larger types from <code>Integer</code> to
* <code>BigInteger</code> and from <code>Float</code> to
* <code>BigDecimal</code>.</p>
*
* <p>If the string starts with <code>0x</code> or <code>-0x</code> (lower or upper case), it
* will be interpreted as a hexadecimal integer. Values with leading
* <code>0</code>'s will not be interpreted as octal.</p>
*
* <p>Returns <code>null</code> if the string is <code>null</code>.</p>
*
* <p>This method does not trim the input string, i.e., strings with leading
* or trailing spaces will generate NumberFormatExceptions.</p>
*
* @param str String containing a number, may be null
* @return Number created from the string (or null if the input is null)
* @throws NumberFormatException if the value cannot be converted
*/
// plus minus everything. Prolly more. A lot are not separable.
// 45 45.5 45E7 4.5E7 Hex Oct Binary xxxF xxxD xxxf xxxd
// Possible inputs:
// new BigInteger(String,int radix)
// new BigInteger(String)
// new BigDecimal(String)
// Short.valueOf(String)
// Short.valueOf(String,int)
// Short.decode(String)
// Short.valueOf(String)
// Long.valueOf(String)
// Long.valueOf(String,int)
// Long.getLong(String,Integer)
// Long.getLong(String,int)
// Long.getLong(String)
// Long.valueOf(String)
// new Byte(String)
// Double.valueOf(String)
// Integer.valueOf(String)
// Integer.getInteger(String,Integer val)
// Integer.getInteger(String,int val)
// Integer.getInteger(String)
// Integer.decode(String)
// Integer.valueOf(String)
// Integer.valueOf(String,int radix)
// Float.valueOf(String)
// Float.valueOf(String)
// Double.valueOf(String)
// Byte.valueOf(String)
// Byte.valueOf(String,int radix)
// Byte.decode(String)
// useful methods:
// BigDecimal, BigInteger and Byte
// must handle Long, Float, Integer, Float, Short,
//-----------------------------------------------------------------------
public static Number createNumber(String str) throws NumberFormatException {
if (str == null) {
return null;
}
if (StringUtils.isBlank(str)) {
throw new NumberFormatException("A blank string is not a valid number");
}
if (str.startsWith("--")) {
// this is protection for poorness in java.lang.BigDecimal.
// it accepts this as a legal value, but it does not appear
// to be in specification of class. OS X Java parses it to
// a wrong value.
return null;
}
if (str.startsWith("0x") || str.startsWith("-0x")) {
return createInteger(str);
}
char lastChar = str.charAt(str.length() - 1);
String mant;
String dec;
String exp;
int decPos = str.indexOf('.');
int expPos = str.indexOf('e') + str.indexOf('E') + 1;
if (decPos > -1) {
if (expPos > -1) {
if (expPos < decPos || expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
dec = str.substring(decPos + 1, expPos);
} else {
dec = str.substring(decPos + 1);
}
mant = str.substring(0, decPos);
} else {
if (expPos > -1) {
if (expPos > str.length()) {
throw new NumberFormatException(str + " is not a valid number.");
}
mant = str.substring(0, expPos);
} else {
mant = str;
}
dec = null;
}
if (!Character.isDigit(lastChar) && lastChar != '.') {
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length() - 1);
} else {
exp = null;
}
//Requesting a specific type..
String numeric = str.substring(0, str.length() - 1);
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
switch (lastChar) {
case 'l' :
case 'L' :
if (dec == null
&& exp == null
&& (numeric.charAt(0) == '-' && isDigits(numeric.substring(1)) || isDigits(numeric))) {
try {
return createLong(numeric);
} catch (NumberFormatException nfe) { // NOPMD
// Too big for a long
}
return createBigInteger(numeric);
}
throw new NumberFormatException(str + " is not a valid number.");
case 'f' :
case 'F' :
try {
Float f = NumberUtils.createFloat(numeric);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
//If it's too big for a float or the float value = 0 and the string
//has non-zeros in it, then float does not have the precision we want
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
case 'd' :
case 'D' :
try {
Double d = NumberUtils.createDouble(numeric);
if (!(d.isInfinite() || (d.floatValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createBigDecimal(numeric);
} catch (NumberFormatException e) { // NOPMD
// ignore the bad number
}
//$FALL-THROUGH$
default :
throw new NumberFormatException(str + " is not a valid number.");
}
} else {
//User doesn't have a preference on the return type, so let's start
//small and go from there...
if (expPos > -1 && expPos < str.length() - 1) {
exp = str.substring(expPos + 1, str.length());
} else {
exp = null;
}
if (dec == null && exp == null) {
//Must be an int,long,bigint
try {
return createInteger(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
return createLong(str);
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigInteger(str);
} else {
//Must be a float,double,BigDec
boolean allZeros = isAllZeros(mant) && isAllZeros(exp);
try {
Float f = createFloat(str);
if (!(f.isInfinite() || (f.floatValue() == 0.0F && !allZeros))) {
return f;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
try {
Double d = createDouble(str);
if (!(d.isInfinite() || (d.doubleValue() == 0.0D && !allZeros))) {
return d;
}
} catch (NumberFormatException nfe) { // NOPMD
// ignore the bad number
}
return createBigDecimal(str);
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
74 | 832337857b35b237fd925c2e63ec5c51cf0eb1bb7bd5df00fdd916c5f6f3295b | @Override
public double integrate(final FirstOrderDifferentialEquations equations,
final double t0, final double[] y0,
final double t, final double[] y)
throws DerivativeException, IntegratorException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
public double integrate(final FirstOrderDifferentialEquations equations,
final double t0, final double[] y0,
final double t, final double[] y)
throws DerivativeException, IntegratorException {
sanityChecks(equations, t0, y0, t, y);
setEquations(equations);
resetEvaluations();
final boolean forward = t > t0;
// create some internal working arrays
final int stages = c.length + 1;
if (y != y0) {
System.arraycopy(y0, 0, y, 0, y0.length);
}
final double[][] yDotK = new double[stages][y0.length];
final double[] yTmp = new double[y0.length];
// set up an interpolator sharing the integrator arrays
AbstractStepInterpolator interpolator;
if (requiresDenseOutput() || (! eventsHandlersManager.isEmpty())) {
final RungeKuttaStepInterpolator rki = (RungeKuttaStepInterpolator) prototype.copy();
rki.reinitialize(this, yTmp, yDotK, forward);
interpolator = rki;
} else {
interpolator = new DummyStepInterpolator(yTmp, forward);
}
interpolator.storeTime(t0);
// set up integration control objects
stepStart = t0;
double hNew = 0;
boolean firstTime = true;
for (StepHandler handler : stepHandlers) {
handler.reset();
}
CombinedEventsManager manager = addEndTimeChecker(t0, t, eventsHandlersManager);
boolean lastStep = false;
// main integration loop
while (!lastStep) {
interpolator.shift();
double error = 0;
for (boolean loop = true; loop;) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale = new double[y0.length];
if (vecAbsoluteTolerance == null) {
for (int i = 0; i < scale.length; ++i) {
scale[i] = scalAbsoluteTolerance + scalRelativeTolerance * Math.abs(y[i]);
}
} else {
for (int i = 0; i < scale.length; ++i) {
scale[i] = vecAbsoluteTolerance[i] + vecRelativeTolerance[i] * Math.abs(y[i]);
}
}
hNew = initializeStep(equations, forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error <= 1.0) {
// discrete events handling
interpolator.storeTime(stepStart + stepSize);
if (manager.evaluateStep(interpolator)) {
final double dt = manager.getEventTime() - stepStart;
if (Math.abs(dt) <= Math.ulp(stepStart)) {
// rejecting the step would lead to a too small next step, we accept it
loop = false;
} else {
// reject the step to match exactly the next switch time
hNew = dt;
}
} else {
// accept the step
loop = false;
}
} else {
// reject the step and attempt to reduce error by stepsize control
final double factor =
Math.min(maxGrowth,
Math.max(minReduction, safety * Math.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// the step has been accepted
final double nextStep = stepStart + stepSize;
System.arraycopy(yTmp, 0, y, 0, y0.length);
manager.stepAccepted(nextStep, y);
lastStep = manager.stop();
// provide the step data to the step handler
interpolator.storeTime(nextStep);
for (StepHandler handler : stepHandlers) {
handler.handleStep(interpolator, lastStep);
}
stepStart = nextStep;
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotK[stages - 1], 0, yDotK[0], 0, y0.length);
}
if (manager.reset(stepStart, y) && ! lastStep) {
// some event handler has triggered changes that
// invalidate the derivatives, we need to recompute them
computeDerivatives(stepStart, y, yDotK[0]);
}
if (! lastStep) {
// in some rare cases we may get here with stepSize = 0, for example
// when an event occurs at integration start, reducing the first step
// to zero; we have to reset the step to some safe non zero value
stepSize = filterStep(stepSize, forward, true);
// stepsize control for next step
final double factor = Math.min(maxGrowth,
Math.max(minReduction,
safety * Math.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
}
}
final double stopTime = stepStart;
resetInternalState();
return stopTime;
}
```
| @Override
public double integrate(final FirstOrderDifferentialEquations equations,
final double t0, final double[] y0,
final double t, final double[] y)
throws DerivativeException, IntegratorException {
sanityChecks(equations, t0, y0, t, y);
setEquations(equations);
resetEvaluations();
final boolean forward = t > t0;
// create some internal working arrays
final int stages = c.length + 1;
if (y != y0) {
System.arraycopy(y0, 0, y, 0, y0.length);
}
final double[][] yDotK = new double[stages][y0.length];
final double[] yTmp = new double[y0.length];
// set up an interpolator sharing the integrator arrays
AbstractStepInterpolator interpolator;
if (requiresDenseOutput() || (! eventsHandlersManager.isEmpty())) {
final RungeKuttaStepInterpolator rki = (RungeKuttaStepInterpolator) prototype.copy();
rki.reinitialize(this, yTmp, yDotK, forward);
interpolator = rki;
} else {
interpolator = new DummyStepInterpolator(yTmp, forward);
}
interpolator.storeTime(t0);
// set up integration control objects
stepStart = t0;
double hNew = 0;
boolean firstTime = true;
for (StepHandler handler : stepHandlers) {
handler.reset();
}
CombinedEventsManager manager = addEndTimeChecker(t0, t, eventsHandlersManager);
boolean lastStep = false;
// main integration loop
while (!lastStep) {
interpolator.shift();
double error = 0;
for (boolean loop = true; loop;) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale = new double[y0.length];
if (vecAbsoluteTolerance == null) {
for (int i = 0; i < scale.length; ++i) {
scale[i] = scalAbsoluteTolerance + scalRelativeTolerance * Math.abs(y[i]);
}
} else {
for (int i = 0; i < scale.length; ++i) {
scale[i] = vecAbsoluteTolerance[i] + vecRelativeTolerance[i] * Math.abs(y[i]);
}
}
hNew = initializeStep(equations, forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error <= 1.0) {
// discrete events handling
interpolator.storeTime(stepStart + stepSize);
if (manager.evaluateStep(interpolator)) {
final double dt = manager.getEventTime() - stepStart;
if (Math.abs(dt) <= Math.ulp(stepStart)) {
// rejecting the step would lead to a too small next step, we accept it
loop = false;
} else {
// reject the step to match exactly the next switch time
hNew = dt;
}
} else {
// accept the step
loop = false;
}
} else {
// reject the step and attempt to reduce error by stepsize control
final double factor =
Math.min(maxGrowth,
Math.max(minReduction, safety * Math.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// the step has been accepted
final double nextStep = stepStart + stepSize;
System.arraycopy(yTmp, 0, y, 0, y0.length);
manager.stepAccepted(nextStep, y);
lastStep = manager.stop();
// provide the step data to the step handler
interpolator.storeTime(nextStep);
for (StepHandler handler : stepHandlers) {
handler.handleStep(interpolator, lastStep);
}
stepStart = nextStep;
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotK[stages - 1], 0, yDotK[0], 0, y0.length);
}
if (manager.reset(stepStart, y) && ! lastStep) {
// some event handler has triggered changes that
// invalidate the derivatives, we need to recompute them
computeDerivatives(stepStart, y, yDotK[0]);
}
if (! lastStep) {
// in some rare cases we may get here with stepSize = 0, for example
// when an event occurs at integration start, reducing the first step
// to zero; we have to reset the step to some safe non zero value
stepSize = filterStep(stepSize, forward, true);
// stepsize control for next step
final double factor = Math.min(maxGrowth,
Math.max(minReduction,
safety * Math.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
}
}
final double stopTime = stepStart;
resetInternalState();
return stopTime;
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
public double integrate(final FirstOrderDifferentialEquations equations,
final double t0, final double[] y0,
final double t, final double[] y)
throws DerivativeException, IntegratorException {
sanityChecks(equations, t0, y0, t, y);
setEquations(equations);
resetEvaluations();
final boolean forward = t > t0;
// create some internal working arrays
final int stages = c.length + 1;
if (y != y0) {
System.arraycopy(y0, 0, y, 0, y0.length);
}
final double[][] yDotK = new double[stages][y0.length];
final double[] yTmp = new double[y0.length];
// set up an interpolator sharing the integrator arrays
AbstractStepInterpolator interpolator;
if (requiresDenseOutput() || (! eventsHandlersManager.isEmpty())) {
final RungeKuttaStepInterpolator rki = (RungeKuttaStepInterpolator) prototype.copy();
rki.reinitialize(this, yTmp, yDotK, forward);
interpolator = rki;
} else {
interpolator = new DummyStepInterpolator(yTmp, forward);
}
interpolator.storeTime(t0);
// set up integration control objects
stepStart = t0;
double hNew = 0;
boolean firstTime = true;
for (StepHandler handler : stepHandlers) {
handler.reset();
}
CombinedEventsManager manager = addEndTimeChecker(t0, t, eventsHandlersManager);
boolean lastStep = false;
// main integration loop
while (!lastStep) {
interpolator.shift();
double error = 0;
for (boolean loop = true; loop;) {
if (firstTime || !fsal) {
// first stage
computeDerivatives(stepStart, y, yDotK[0]);
}
if (firstTime) {
final double[] scale = new double[y0.length];
if (vecAbsoluteTolerance == null) {
for (int i = 0; i < scale.length; ++i) {
scale[i] = scalAbsoluteTolerance + scalRelativeTolerance * Math.abs(y[i]);
}
} else {
for (int i = 0; i < scale.length; ++i) {
scale[i] = vecAbsoluteTolerance[i] + vecRelativeTolerance[i] * Math.abs(y[i]);
}
}
hNew = initializeStep(equations, forward, getOrder(), scale,
stepStart, y, yDotK[0], yTmp, yDotK[1]);
firstTime = false;
}
stepSize = hNew;
// next stages
for (int k = 1; k < stages; ++k) {
for (int j = 0; j < y0.length; ++j) {
double sum = a[k-1][0] * yDotK[0][j];
for (int l = 1; l < k; ++l) {
sum += a[k-1][l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
computeDerivatives(stepStart + c[k-1] * stepSize, yTmp, yDotK[k]);
}
// estimate the state at the end of the step
for (int j = 0; j < y0.length; ++j) {
double sum = b[0] * yDotK[0][j];
for (int l = 1; l < stages; ++l) {
sum += b[l] * yDotK[l][j];
}
yTmp[j] = y[j] + stepSize * sum;
}
// estimate the error at the end of the step
error = estimateError(yDotK, y, yTmp, stepSize);
if (error <= 1.0) {
// discrete events handling
interpolator.storeTime(stepStart + stepSize);
if (manager.evaluateStep(interpolator)) {
final double dt = manager.getEventTime() - stepStart;
if (Math.abs(dt) <= Math.ulp(stepStart)) {
// rejecting the step would lead to a too small next step, we accept it
loop = false;
} else {
// reject the step to match exactly the next switch time
hNew = dt;
}
} else {
// accept the step
loop = false;
}
} else {
// reject the step and attempt to reduce error by stepsize control
final double factor =
Math.min(maxGrowth,
Math.max(minReduction, safety * Math.pow(error, exp)));
hNew = filterStep(stepSize * factor, forward, false);
}
}
// the step has been accepted
final double nextStep = stepStart + stepSize;
System.arraycopy(yTmp, 0, y, 0, y0.length);
manager.stepAccepted(nextStep, y);
lastStep = manager.stop();
// provide the step data to the step handler
interpolator.storeTime(nextStep);
for (StepHandler handler : stepHandlers) {
handler.handleStep(interpolator, lastStep);
}
stepStart = nextStep;
if (fsal) {
// save the last evaluation for the next step
System.arraycopy(yDotK[stages - 1], 0, yDotK[0], 0, y0.length);
}
if (manager.reset(stepStart, y) && ! lastStep) {
// some event handler has triggered changes that
// invalidate the derivatives, we need to recompute them
computeDerivatives(stepStart, y, yDotK[0]);
}
if (! lastStep) {
// in some rare cases we may get here with stepSize = 0, for example
// when an event occurs at integration start, reducing the first step
// to zero; we have to reset the step to some safe non zero value
stepSize = filterStep(stepSize, forward, true);
// stepsize control for next step
final double factor = Math.min(maxGrowth,
Math.max(minReduction,
safety * Math.pow(error, exp)));
final double scaledH = stepSize * factor;
final double nextT = stepStart + scaledH;
final boolean nextIsLast = forward ? (nextT >= t) : (nextT <= t);
hNew = filterStep(scaledH, forward, nextIsLast);
}
}
final double stopTime = stepStart;
resetInternalState();
return stopTime;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 83539f92cfc83bcebc2da7807b8a9aaa9860b812fddfc5b1a18f8b9f31be826d | protected XmlSerializerProvider(XmlSerializerProvider src) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @since 2.8.9
*/
protected XmlSerializerProvider(XmlSerializerProvider src) {
super(src);
// 21-May-2018, tatu: As per [dataformat-xml#282], should NOT really copy
// root name lookup as that may link back to diff version, configuration
_rootNameLookup = src._rootNameLookup;
}
```
| protected XmlSerializerProvider(XmlSerializerProvider src) {
super(src);
// 21-May-2018, tatu: As per [dataformat-xml#282], should NOT really copy
// root name lookup as that may link back to diff version, configuration
_rootNameLookup = src._rootNameLookup;
} | true | JacksonXml | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @since 2.8.9
*/
protected XmlSerializerProvider(XmlSerializerProvider src) {
super(src);
// 21-May-2018, tatu: As per [dataformat-xml#282], should NOT really copy
// root name lookup as that may link back to diff version, configuration
_rootNameLookup = src._rootNameLookup;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
20 | 839f01a465e6cf6d56c44e6dfd40a4dd153ebb9c39c70992958bac78d2d7794c | protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>An implementation of {@link Parser}'s abstract
* {@link Parser#flatten(Options,String[],boolean) flatten} method.</p>
*
* <p>The following are the rules used by this flatten method.
* <ol>
* <li>if <code>stopAtNonOption</code> is <b>true</b> then do not
* burst anymore of <code>arguments</code> entries, just add each
* successive entry without further processing. Otherwise, ignore
* <code>stopAtNonOption</code>.</li>
* <li>if the current <code>arguments</code> entry is "<b>--</b>"
* just add the entry to the list of processed tokens</li>
* <li>if the current <code>arguments</code> entry is "<b>-</b>"
* just add the entry to the list of processed tokens</li>
* <li>if the current <code>arguments</code> entry is two characters
* in length and the first character is "<b>-</b>" then check if this
* is a valid {@link Option} id. If it is a valid id, then add the
* entry to the list of processed tokens and set the current {@link Option}
* member. If it is not a valid id and <code>stopAtNonOption</code>
* is true, then the remaining entries are copied to the list of
* processed tokens. Otherwise, the current entry is ignored.</li>
* <li>if the current <code>arguments</code> entry is more than two
* characters in length and the first character is "<b>-</b>" then
* we need to burst the entry to determine its constituents. For more
* information on the bursting algorithm see
* {@link PosixParser#burstToken(String, boolean) burstToken}.</li>
* <li>if the current <code>arguments</code> entry is not handled
* by any of the previous rules, then the entry is added to the list
* of processed tokens.</li>
* </ol>
* </p>
*
* @param options The command line {@link Options}
* @param arguments The command line arguments to be parsed
* @param stopAtNonOption Specifies whether to stop flattening
* when an non option is found.
* @return The flattened <code>arguments</code> String array.
*/
protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
init();
this.options = options;
// an iterator for the command line tokens
Iterator iter = Arrays.asList(arguments).iterator();
// process each command line token
while (iter.hasNext())
{
// get the next command line token
String token = (String) iter.next();
// handle long option --foo or --foo=bar
if (token.startsWith("--"))
{
if (token.indexOf('=') != -1)
{
tokens.add(token.substring(0, token.indexOf('=')));
tokens.add(token.substring(token.indexOf('=') + 1, token.length()));
}
else
{
tokens.add(token);
}
}
// single hyphen
else if ("-".equals(token))
{
tokens.add(token);
}
else if (token.startsWith("-"))
{
if (token.length() == 2)
{
processOptionToken(token, stopAtNonOption);
}
else if (options.hasOption(token))
{
tokens.add(token);
}
// requires bursting
else
{
burstToken(token, stopAtNonOption);
}
}
else if (stopAtNonOption)
{
process(token);
}
else
{
tokens.add(token);
}
gobble(iter);
}
return (String[]) tokens.toArray(new String[tokens.size()]);
}
```
| protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
init();
this.options = options;
// an iterator for the command line tokens
Iterator iter = Arrays.asList(arguments).iterator();
// process each command line token
while (iter.hasNext())
{
// get the next command line token
String token = (String) iter.next();
// handle long option --foo or --foo=bar
if (token.startsWith("--"))
{
if (token.indexOf('=') != -1)
{
tokens.add(token.substring(0, token.indexOf('=')));
tokens.add(token.substring(token.indexOf('=') + 1, token.length()));
}
else
{
tokens.add(token);
}
}
// single hyphen
else if ("-".equals(token))
{
tokens.add(token);
}
else if (token.startsWith("-"))
{
if (token.length() == 2)
{
processOptionToken(token, stopAtNonOption);
}
else if (options.hasOption(token))
{
tokens.add(token);
}
// requires bursting
else
{
burstToken(token, stopAtNonOption);
}
}
else if (stopAtNonOption)
{
process(token);
}
else
{
tokens.add(token);
}
gobble(iter);
}
return (String[]) tokens.toArray(new String[tokens.size()]);
} | true | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>An implementation of {@link Parser}'s abstract
* {@link Parser#flatten(Options,String[],boolean) flatten} method.</p>
*
* <p>The following are the rules used by this flatten method.
* <ol>
* <li>if <code>stopAtNonOption</code> is <b>true</b> then do not
* burst anymore of <code>arguments</code> entries, just add each
* successive entry without further processing. Otherwise, ignore
* <code>stopAtNonOption</code>.</li>
* <li>if the current <code>arguments</code> entry is "<b>--</b>"
* just add the entry to the list of processed tokens</li>
* <li>if the current <code>arguments</code> entry is "<b>-</b>"
* just add the entry to the list of processed tokens</li>
* <li>if the current <code>arguments</code> entry is two characters
* in length and the first character is "<b>-</b>" then check if this
* is a valid {@link Option} id. If it is a valid id, then add the
* entry to the list of processed tokens and set the current {@link Option}
* member. If it is not a valid id and <code>stopAtNonOption</code>
* is true, then the remaining entries are copied to the list of
* processed tokens. Otherwise, the current entry is ignored.</li>
* <li>if the current <code>arguments</code> entry is more than two
* characters in length and the first character is "<b>-</b>" then
* we need to burst the entry to determine its constituents. For more
* information on the bursting algorithm see
* {@link PosixParser#burstToken(String, boolean) burstToken}.</li>
* <li>if the current <code>arguments</code> entry is not handled
* by any of the previous rules, then the entry is added to the list
* of processed tokens.</li>
* </ol>
* </p>
*
* @param options The command line {@link Options}
* @param arguments The command line arguments to be parsed
* @param stopAtNonOption Specifies whether to stop flattening
* when an non option is found.
* @return The flattened <code>arguments</code> String array.
*/
protected String[] flatten(Options options, String[] arguments, boolean stopAtNonOption)
{
init();
this.options = options;
// an iterator for the command line tokens
Iterator iter = Arrays.asList(arguments).iterator();
// process each command line token
while (iter.hasNext())
{
// get the next command line token
String token = (String) iter.next();
// handle long option --foo or --foo=bar
if (token.startsWith("--"))
{
if (token.indexOf('=') != -1)
{
tokens.add(token.substring(0, token.indexOf('=')));
tokens.add(token.substring(token.indexOf('=') + 1, token.length()));
}
else
{
tokens.add(token);
}
}
// single hyphen
else if ("-".equals(token))
{
tokens.add(token);
}
else if (token.startsWith("-"))
{
if (token.length() == 2)
{
processOptionToken(token, stopAtNonOption);
}
else if (options.hasOption(token))
{
tokens.add(token);
}
// requires bursting
else
{
burstToken(token, stopAtNonOption);
}
}
else if (stopAtNonOption)
{
process(token);
}
else
{
tokens.add(token);
}
gobble(iter);
}
return (String[]) tokens.toArray(new String[tokens.size()]);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
18 | 83a3d37ac11cbeda65ee9ee11a1a4478611911d4c7eabaeccf4d3846380ae68b | Node parseInputs() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses the externs and main inputs.
*
* @return A synthetic root node whose two children are the externs root
* and the main root
*/
//------------------------------------------------------------------------
// Parsing
//------------------------------------------------------------------------
Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main JS sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
hoistExterns(externsRoot);
// Check if the sources need to be re-ordered.
boolean staleInputs = false;
if (options.dependencyOptions.needsManagement()) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
hoistNoCompileFiles();
if (staleInputs) {
repartitionInputs();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
}
```
| Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main JS sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
hoistExterns(externsRoot);
// Check if the sources need to be re-ordered.
boolean staleInputs = false;
if (options.dependencyOptions.needsManagement()) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
hoistNoCompileFiles();
if (staleInputs) {
repartitionInputs();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses the externs and main inputs.
*
* @return A synthetic root node whose two children are the externs root
* and the main root
*/
//------------------------------------------------------------------------
// Parsing
//------------------------------------------------------------------------
Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main JS sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
hoistExterns(externsRoot);
// Check if the sources need to be re-ordered.
boolean staleInputs = false;
if (options.dependencyOptions.needsManagement()) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
hoistNoCompileFiles();
if (staleInputs) {
repartitionInputs();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
19 | 83c17f668639129245285f517512091db53fb9e4b899c4b0f1dbfdf5c34857d6 | private void processOptionToken(String token, boolean stopAtNonOption)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>If an {@link Option} exists for <code>token</code> then
* set the current option and add the token to the processed
* list.</p>
*
* <p>If an {@link Option} does not exist and <code>stopAtNonOption</code>
* is set then ignore the current token and add the remaining tokens
* to the processed tokens list directly.</p>
*
* @param token The current option token
* @param stopAtNonOption Specifies whether flattening should halt
* at the first non option.
*/
private void processOptionToken(String token, boolean stopAtNonOption)
{
if (options.hasOption(token))
{
currentOption = options.getOption(token);
}
else if (stopAtNonOption)
{
eatTheRest = true;
}
tokens.add(token);
}
```
| private void processOptionToken(String token, boolean stopAtNonOption)
{
if (options.hasOption(token))
{
currentOption = options.getOption(token);
}
else if (stopAtNonOption)
{
eatTheRest = true;
}
tokens.add(token);
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>If an {@link Option} exists for <code>token</code> then
* set the current option and add the token to the processed
* list.</p>
*
* <p>If an {@link Option} does not exist and <code>stopAtNonOption</code>
* is set then ignore the current token and add the remaining tokens
* to the processed tokens list directly.</p>
*
* @param token The current option token
* @param stopAtNonOption Specifies whether flattening should halt
* at the first non option.
*/
private void processOptionToken(String token, boolean stopAtNonOption)
{
if (options.hasOption(token))
{
currentOption = options.getOption(token);
}
else if (stopAtNonOption)
{
eatTheRest = true;
}
tokens.add(token);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
145 | 83f477c97796783b7175d4bffbbcfb1a69dbce44f8ab3e65c7daff0f8abcf2be | private boolean isOneExactlyFunctionOrDo(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @return Whether the Node is a DO or FUNCTION (with or without
* labels).
*/
private boolean isOneExactlyFunctionOrDo(Node n) {
if (n.getType() == Token.LABEL) {
Node labeledStatement = n.getLastChild();
if (labeledStatement.getType() != Token.BLOCK) {
return isOneExactlyFunctionOrDo(labeledStatement);
} else {
// For labels with block children, we need to ensure that a
// labeled FUNCTION or DO isn't generated when extraneous BLOCKs
// are skipped.
if (getNonEmptyChildCount(n, 2) == 1) {
return isOneExactlyFunctionOrDo(getFirstNonEmptyChild(n));
} else {
// Either a empty statement or an block with more than one child,
// way it isn't a FUNCTION or DO.
return false;
}
}
} else {
return (n.getType() == Token.FUNCTION || n.getType() == Token.DO);
}
}
```
| private boolean isOneExactlyFunctionOrDo(Node n) {
if (n.getType() == Token.LABEL) {
Node labeledStatement = n.getLastChild();
if (labeledStatement.getType() != Token.BLOCK) {
return isOneExactlyFunctionOrDo(labeledStatement);
} else {
// For labels with block children, we need to ensure that a
// labeled FUNCTION or DO isn't generated when extraneous BLOCKs
// are skipped.
if (getNonEmptyChildCount(n, 2) == 1) {
return isOneExactlyFunctionOrDo(getFirstNonEmptyChild(n));
} else {
// Either a empty statement or an block with more than one child,
// way it isn't a FUNCTION or DO.
return false;
}
}
} else {
return (n.getType() == Token.FUNCTION || n.getType() == Token.DO);
}
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @return Whether the Node is a DO or FUNCTION (with or without
* labels).
*/
private boolean isOneExactlyFunctionOrDo(Node n) {
if (n.getType() == Token.LABEL) {
Node labeledStatement = n.getLastChild();
if (labeledStatement.getType() != Token.BLOCK) {
return isOneExactlyFunctionOrDo(labeledStatement);
} else {
// For labels with block children, we need to ensure that a
// labeled FUNCTION or DO isn't generated when extraneous BLOCKs
// are skipped.
if (getNonEmptyChildCount(n, 2) == 1) {
return isOneExactlyFunctionOrDo(getFirstNonEmptyChild(n));
} else {
// Either a empty statement or an block with more than one child,
// way it isn't a FUNCTION or DO.
return false;
}
}
} else {
return (n.getType() == Token.FUNCTION || n.getType() == Token.DO);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
31 | 840687592b1c98722e49f3c6c09c6a47ef8feb3b56aec11a9c275fb981e6654c | Node parseInputs() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Parses the externs and main inputs.
*
* @return A synthetic root node whose two children are the externs root
* and the main root
*/
//------------------------------------------------------------------------
// Parsing
//------------------------------------------------------------------------
Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main js sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
// Check if inputs need to be rebuilt from modules.
boolean staleInputs = false;
// Check if the sources need to be re-ordered.
if (options.dependencyOptions.needsManagement() &&
!options.skipAllPasses &&
options.closurePass) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
// Inputs can have a null AST during initial parse.
if (n == null) {
continue;
}
if (n.getJSDocInfo() != null) {
JSDocInfo info = n.getJSDocInfo();
if (info.isExterns()) {
// If the input file is explicitly marked as an externs file, then
// assume the programmer made a mistake and throw it into
// the externs pile anyways.
externsRoot.addChildToBack(n);
input.setIsExtern(true);
input.getModule().remove(input);
externs.add(input);
staleInputs = true;
} else if (info.isNoCompile()) {
input.getModule().remove(input);
staleInputs = true;
}
}
}
if (staleInputs) {
fillEmptyModules(modules);
rebuildInputsFromModules();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
}
```
| Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main js sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
// Check if inputs need to be rebuilt from modules.
boolean staleInputs = false;
// Check if the sources need to be re-ordered.
if (options.dependencyOptions.needsManagement() &&
!options.skipAllPasses &&
options.closurePass) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
// Inputs can have a null AST during initial parse.
if (n == null) {
continue;
}
if (n.getJSDocInfo() != null) {
JSDocInfo info = n.getJSDocInfo();
if (info.isExterns()) {
// If the input file is explicitly marked as an externs file, then
// assume the programmer made a mistake and throw it into
// the externs pile anyways.
externsRoot.addChildToBack(n);
input.setIsExtern(true);
input.getModule().remove(input);
externs.add(input);
staleInputs = true;
} else if (info.isNoCompile()) {
input.getModule().remove(input);
staleInputs = true;
}
}
}
if (staleInputs) {
fillEmptyModules(modules);
rebuildInputsFromModules();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Parses the externs and main inputs.
*
* @return A synthetic root node whose two children are the externs root
* and the main root
*/
//------------------------------------------------------------------------
// Parsing
//------------------------------------------------------------------------
Node parseInputs() {
boolean devMode = options.devMode != DevMode.OFF;
// If old roots exist (we are parsing a second time), detach each of the
// individual file parse trees.
if (externsRoot != null) {
externsRoot.detachChildren();
}
if (jsRoot != null) {
jsRoot.detachChildren();
}
// Parse main js sources.
jsRoot = IR.block();
jsRoot.setIsSyntheticBlock(true);
externsRoot = IR.block();
externsRoot.setIsSyntheticBlock(true);
externAndJsRoot = IR.block(externsRoot, jsRoot);
externAndJsRoot.setIsSyntheticBlock(true);
if (options.tracer.isOn()) {
tracker = new PerformanceTracker(jsRoot, options.tracer);
addChangeHandler(tracker.getCodeChangeHandler());
}
Tracer tracer = newTracer("parseInputs");
try {
// Parse externs sources.
for (CompilerInput input : externs) {
Node n = input.getAstRoot(this);
if (hasErrors()) {
return null;
}
externsRoot.addChildToBack(n);
}
// Modules inferred in ProcessCommonJS pass.
if (options.transformAMDToCJSModules || options.processCommonJSModules) {
processAMDAndCommonJSModules();
}
// Check if inputs need to be rebuilt from modules.
boolean staleInputs = false;
// Check if the sources need to be re-ordered.
if (options.dependencyOptions.needsManagement() &&
!options.skipAllPasses &&
options.closurePass) {
for (CompilerInput input : inputs) {
// Forward-declare all the provided types, so that they
// are not flagged even if they are dropped from the process.
for (String provide : input.getProvides()) {
getTypeRegistry().forwardDeclareType(provide);
}
}
try {
inputs =
(moduleGraph == null ? new JSModuleGraph(modules) : moduleGraph)
.manageDependencies(options.dependencyOptions, inputs);
staleInputs = true;
} catch (CircularDependencyException e) {
report(JSError.make(
JSModule.CIRCULAR_DEPENDENCY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
} catch (MissingProvideException e) {
report(JSError.make(
MISSING_ENTRY_ERROR, e.getMessage()));
// If in IDE mode, we ignore the error and keep going.
if (hasErrors()) {
return null;
}
}
}
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
// Inputs can have a null AST during initial parse.
if (n == null) {
continue;
}
if (n.getJSDocInfo() != null) {
JSDocInfo info = n.getJSDocInfo();
if (info.isExterns()) {
// If the input file is explicitly marked as an externs file, then
// assume the programmer made a mistake and throw it into
// the externs pile anyways.
externsRoot.addChildToBack(n);
input.setIsExtern(true);
input.getModule().remove(input);
externs.add(input);
staleInputs = true;
} else if (info.isNoCompile()) {
input.getModule().remove(input);
staleInputs = true;
}
}
}
if (staleInputs) {
fillEmptyModules(modules);
rebuildInputsFromModules();
}
// Build the AST.
for (CompilerInput input : inputs) {
Node n = input.getAstRoot(this);
if (n == null) {
continue;
}
if (devMode) {
runSanityCheck();
if (hasErrors()) {
return null;
}
}
if (options.sourceMapOutputPath != null ||
options.nameReferenceReportPath != null) {
// Annotate the nodes in the tree with information from the
// input file. This information is used to construct the SourceMap.
SourceInformationAnnotator sia =
new SourceInformationAnnotator(
input.getName(), options.devMode != DevMode.OFF);
NodeTraversal.traverse(this, n, sia);
}
jsRoot.addChildToBack(n);
}
if (hasErrors()) {
return null;
}
return externAndJsRoot;
} finally {
stopTracer(tracer, "parseInputs");
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 8442e2f288c44fe6f2aa6ad57c4f0fc868c4ad9055c3b29586c407cf8a6c4bcb | public static Locale toLocale(final String str) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Converts a String to a Locale.</p>
*
* <p>This method takes the string format of a locale and creates the
* locale object from it.</p>
*
* <pre>
* LocaleUtils.toLocale("en") = new Locale("en", "")
* LocaleUtils.toLocale("en_GB") = new Locale("en", "GB")
* LocaleUtils.toLocale("en_GB_xxx") = new Locale("en", "GB", "xxx") (#)
* </pre>
*
* <p>(#) The behaviour of the JDK variant constructor changed between JDK1.3 and JDK1.4.
* In JDK1.3, the constructor upper cases the variant, in JDK1.4, it doesn't.
* Thus, the result from getVariant() may vary depending on your JDK.</p>
*
* <p>This method validates the input strictly.
* The language code must be lowercase.
* The country code must be uppercase.
* The separator must be an underscore.
* The length must be correct.
* </p>
*
* @param str the locale String to convert, null returns null
* @return a Locale, null if null input
* @throws IllegalArgumentException if the string is an invalid format
*/
//-----------------------------------------------------------------------
public static Locale toLocale(final String str) {
if (str == null) {
return null;
}
final int len = str.length();
if (len < 2) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch0 = str.charAt(0);
if (ch0 == '_') {
if (len < 3) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch1 = str.charAt(1);
final char ch2 = str.charAt(2);
if (!Character.isUpperCase(ch1) || !Character.isUpperCase(ch2)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 3) {
return new Locale("", str.substring(1, 3));
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(3) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale("", str.substring(1, 3), str.substring(4));
} else {
final char ch1 = str.charAt(1);
if (!Character.isLowerCase(ch0) || !Character.isLowerCase(ch1)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str);
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
final char ch4 = str.charAt(4);
if (!Character.isUpperCase(ch3) || !Character.isUpperCase(ch4)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
}
if (len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
}
```
| public static Locale toLocale(final String str) {
if (str == null) {
return null;
}
final int len = str.length();
if (len < 2) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch0 = str.charAt(0);
if (ch0 == '_') {
if (len < 3) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch1 = str.charAt(1);
final char ch2 = str.charAt(2);
if (!Character.isUpperCase(ch1) || !Character.isUpperCase(ch2)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 3) {
return new Locale("", str.substring(1, 3));
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(3) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale("", str.substring(1, 3), str.substring(4));
} else {
final char ch1 = str.charAt(1);
if (!Character.isLowerCase(ch0) || !Character.isLowerCase(ch1)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str);
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
final char ch4 = str.charAt(4);
if (!Character.isUpperCase(ch3) || !Character.isUpperCase(ch4)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
}
if (len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Converts a String to a Locale.</p>
*
* <p>This method takes the string format of a locale and creates the
* locale object from it.</p>
*
* <pre>
* LocaleUtils.toLocale("en") = new Locale("en", "")
* LocaleUtils.toLocale("en_GB") = new Locale("en", "GB")
* LocaleUtils.toLocale("en_GB_xxx") = new Locale("en", "GB", "xxx") (#)
* </pre>
*
* <p>(#) The behaviour of the JDK variant constructor changed between JDK1.3 and JDK1.4.
* In JDK1.3, the constructor upper cases the variant, in JDK1.4, it doesn't.
* Thus, the result from getVariant() may vary depending on your JDK.</p>
*
* <p>This method validates the input strictly.
* The language code must be lowercase.
* The country code must be uppercase.
* The separator must be an underscore.
* The length must be correct.
* </p>
*
* @param str the locale String to convert, null returns null
* @return a Locale, null if null input
* @throws IllegalArgumentException if the string is an invalid format
*/
//-----------------------------------------------------------------------
public static Locale toLocale(final String str) {
if (str == null) {
return null;
}
final int len = str.length();
if (len < 2) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch0 = str.charAt(0);
if (ch0 == '_') {
if (len < 3) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch1 = str.charAt(1);
final char ch2 = str.charAt(2);
if (!Character.isUpperCase(ch1) || !Character.isUpperCase(ch2)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 3) {
return new Locale("", str.substring(1, 3));
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(3) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale("", str.substring(1, 3), str.substring(4));
} else {
final char ch1 = str.charAt(1);
if (!Character.isLowerCase(ch0) || !Character.isLowerCase(ch1)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 2) {
return new Locale(str);
}
if (len < 5) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(2) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
final char ch3 = str.charAt(3);
if (ch3 == '_') {
return new Locale(str.substring(0, 2), "", str.substring(4));
}
final char ch4 = str.charAt(4);
if (!Character.isUpperCase(ch3) || !Character.isUpperCase(ch4)) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (len == 5) {
return new Locale(str.substring(0, 2), str.substring(3, 5));
}
if (len < 7) {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
if (str.charAt(5) != '_') {
throw new IllegalArgumentException("Invalid locale format: " + str);
}
return new Locale(str.substring(0, 2), str.substring(3, 5), str.substring(6));
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 84618fc9a033cc4ef734b2c4f917bcea0a46dbefa77d467080060209798de368 | protected XmlSerializerProvider(XmlSerializerProvider src) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @since 2.8.9
*/
protected XmlSerializerProvider(XmlSerializerProvider src) {
super(src);
// 21-May-2018, tatu: As per [dataformat-xml#282], should NOT really copy
// root name lookup as that may link back to diff version, configuration
_rootNameLookup = new XmlRootNameLookup();
}
```
| protected XmlSerializerProvider(XmlSerializerProvider src) {
super(src);
// 21-May-2018, tatu: As per [dataformat-xml#282], should NOT really copy
// root name lookup as that may link back to diff version, configuration
_rootNameLookup = new XmlRootNameLookup();
} | false | JacksonXml | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @since 2.8.9
*/
protected XmlSerializerProvider(XmlSerializerProvider src) {
super(src);
// 21-May-2018, tatu: As per [dataformat-xml#282], should NOT really copy
// root name lookup as that may link back to diff version, configuration
_rootNameLookup = new XmlRootNameLookup();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
94 | 84a63090fb41a7becb58a0e4f5ff945c3f71d34161c2a81ca47708386b3be8e6 | public static int gcd(int u, int v) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Gets the greatest common divisor of the absolute value of two numbers,
* using the "binary gcd" method which avoids division and modulo
* operations. See Knuth 4.5.2 algorithm B. This algorithm is due to Josef
* Stein (1961).
* </p>
*
* @param u a non-zero number
* @param v a non-zero number
* @return the greatest common divisor, never zero
* @since 1.1
*/
public static int gcd(int u, int v) {
if (u * v == 0) {
return (Math.abs(u) + Math.abs(v));
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
/* assert u!=0 && v!=0; */
if (u > 0) {
u = -u;
} // make u negative
if (v > 0) {
v = -v;
} // make v negative
// B1. [Find power of 2]
int k = 0;
while ((u & 1) == 0 && (v & 1) == 0 && k < 31) { // while u and v are
// both even...
u /= 2;
v /= 2;
k++; // cast out twos.
}
if (k == 31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u & 1) == 1) ? v : -(u / 2)/* B3 */;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t & 1) == 0) { // while t is even..
t /= 2; // cast out twos
}
// B5 [reset max(u,v)]
if (t > 0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u) / 2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t != 0);
return -u * (1 << k); // gcd is u*2^k
}
```
| public static int gcd(int u, int v) {
if (u * v == 0) {
return (Math.abs(u) + Math.abs(v));
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
/* assert u!=0 && v!=0; */
if (u > 0) {
u = -u;
} // make u negative
if (v > 0) {
v = -v;
} // make v negative
// B1. [Find power of 2]
int k = 0;
while ((u & 1) == 0 && (v & 1) == 0 && k < 31) { // while u and v are
// both even...
u /= 2;
v /= 2;
k++; // cast out twos.
}
if (k == 31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u & 1) == 1) ? v : -(u / 2)/* B3 */;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t & 1) == 0) { // while t is even..
t /= 2; // cast out twos
}
// B5 [reset max(u,v)]
if (t > 0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u) / 2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t != 0);
return -u * (1 << k); // gcd is u*2^k
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Gets the greatest common divisor of the absolute value of two numbers,
* using the "binary gcd" method which avoids division and modulo
* operations. See Knuth 4.5.2 algorithm B. This algorithm is due to Josef
* Stein (1961).
* </p>
*
* @param u a non-zero number
* @param v a non-zero number
* @return the greatest common divisor, never zero
* @since 1.1
*/
public static int gcd(int u, int v) {
if (u * v == 0) {
return (Math.abs(u) + Math.abs(v));
}
// keep u and v negative, as negative integers range down to
// -2^31, while positive numbers can only be as large as 2^31-1
// (i.e. we can't necessarily negate a negative number without
// overflow)
/* assert u!=0 && v!=0; */
if (u > 0) {
u = -u;
} // make u negative
if (v > 0) {
v = -v;
} // make v negative
// B1. [Find power of 2]
int k = 0;
while ((u & 1) == 0 && (v & 1) == 0 && k < 31) { // while u and v are
// both even...
u /= 2;
v /= 2;
k++; // cast out twos.
}
if (k == 31) {
throw new ArithmeticException("overflow: gcd is 2^31");
}
// B2. Initialize: u and v have been divided by 2^k and at least
// one is odd.
int t = ((u & 1) == 1) ? v : -(u / 2)/* B3 */;
// t negative: u was odd, v may be even (t replaces v)
// t positive: u was even, v is odd (t replaces u)
do {
/* assert u<0 && v<0; */
// B4/B3: cast out twos from t.
while ((t & 1) == 0) { // while t is even..
t /= 2; // cast out twos
}
// B5 [reset max(u,v)]
if (t > 0) {
u = -t;
} else {
v = t;
}
// B6/B3. at this point both u and v should be odd.
t = (v - u) / 2;
// |u| larger: t positive (replace u)
// |v| larger: t negative (replace v)
} while (t != 0);
return -u * (1 << k); // gcd is u*2^k
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
46 | 8521a50c5d0e85d5605416bb43d8298673b60facf3fc4e67a0f521b4986673e2 | @Override
public StringBuilder getGenericSignature(StringBuilder sb)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
@Override
public StringBuilder getGenericSignature(StringBuilder sb)
{
_classSignature(_class, sb, false);
sb.append('<');
sb = _referencedType.getGenericSignature(sb);
sb.append(">;");
return sb;
}
```
| @Override
public StringBuilder getGenericSignature(StringBuilder sb)
{
_classSignature(_class, sb, false);
sb.append('<');
sb = _referencedType.getGenericSignature(sb);
sb.append(">;");
return sb;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
@Override
public StringBuilder getGenericSignature(StringBuilder sb)
{
_classSignature(_class, sb, false);
sb.append('<');
sb = _referencedType.getGenericSignature(sb);
sb.append(">;");
return sb;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | 85790d40349672c30b8f8aa779196892124ef59efcca492e523093ed10cd24f2 | private RealMatrix squareRoot(RealMatrix m) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Computes the square-root of the weight matrix.
*
* @param m Symmetric, positive-definite (weight) matrix.
* @return the square-root of the weight matrix.
*/
private RealMatrix squareRoot(RealMatrix m) {
final EigenDecomposition dec = new EigenDecomposition(m);
return dec.getSquareRoot();
}
```
| private RealMatrix squareRoot(RealMatrix m) {
final EigenDecomposition dec = new EigenDecomposition(m);
return dec.getSquareRoot();
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Computes the square-root of the weight matrix.
*
* @param m Symmetric, positive-definite (weight) matrix.
* @return the square-root of the weight matrix.
*/
private RealMatrix squareRoot(RealMatrix m) {
final EigenDecomposition dec = new EigenDecomposition(m);
return dec.getSquareRoot();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
13 | 85caf295b48e940df001fb824e9fdf7345ca2c8dbb14ee999ce46a8f8bd377f7 | protected Size2D arrangeFF(BlockContainer container, Graphics2D g2,
RectangleConstraint constraint) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Arranges the items within a container.
*
* @param container the container.
* @param constraint the constraint.
* @param g2 the graphics device.
*
* @return The container size after the arrangement.
*/
protected Size2D arrangeFF(BlockContainer container, Graphics2D g2,
RectangleConstraint constraint) {
double[] w = new double[5];
double[] h = new double[5];
w[0] = constraint.getWidth();
if (this.topBlock != null) {
RectangleConstraint c1 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0,
new Range(0.0, constraint.getHeight()),
LengthConstraintType.RANGE);
Size2D size = this.topBlock.arrange(g2, c1);
h[0] = size.height;
}
w[1] = w[0];
if (this.bottomBlock != null) {
RectangleConstraint c2 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0, new Range(0.0,
constraint.getHeight() - h[0]), LengthConstraintType.RANGE);
Size2D size = this.bottomBlock.arrange(g2, c2);
h[1] = size.height;
}
h[2] = constraint.getHeight() - h[1] - h[0];
if (this.leftBlock != null) {
RectangleConstraint c3 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth()),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.leftBlock.arrange(g2, c3);
w[2] = size.width;
}
h[3] = h[2];
if (this.rightBlock != null) {
RectangleConstraint c4 = new RectangleConstraint(0.0,
new Range(0.0, Math.max(constraint.getWidth() - w[2], 0.0)),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.rightBlock.arrange(g2, c4);
w[3] = size.width;
}
h[4] = h[2];
w[4] = constraint.getWidth() - w[3] - w[2];
RectangleConstraint c5 = new RectangleConstraint(w[4], h[4]);
if (this.centerBlock != null) {
this.centerBlock.arrange(g2, c5);
}
if (this.topBlock != null) {
this.topBlock.setBounds(new Rectangle2D.Double(0.0, 0.0, w[0],
h[0]));
}
if (this.bottomBlock != null) {
this.bottomBlock.setBounds(new Rectangle2D.Double(0.0, h[0] + h[2],
w[1], h[1]));
}
if (this.leftBlock != null) {
this.leftBlock.setBounds(new Rectangle2D.Double(0.0, h[0], w[2],
h[2]));
}
if (this.rightBlock != null) {
this.rightBlock.setBounds(new Rectangle2D.Double(w[2] + w[4], h[0],
w[3], h[3]));
}
if (this.centerBlock != null) {
this.centerBlock.setBounds(new Rectangle2D.Double(w[2], h[0], w[4],
h[4]));
}
return new Size2D(constraint.getWidth(), constraint.getHeight());
}
```
| protected Size2D arrangeFF(BlockContainer container, Graphics2D g2,
RectangleConstraint constraint) {
double[] w = new double[5];
double[] h = new double[5];
w[0] = constraint.getWidth();
if (this.topBlock != null) {
RectangleConstraint c1 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0,
new Range(0.0, constraint.getHeight()),
LengthConstraintType.RANGE);
Size2D size = this.topBlock.arrange(g2, c1);
h[0] = size.height;
}
w[1] = w[0];
if (this.bottomBlock != null) {
RectangleConstraint c2 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0, new Range(0.0,
constraint.getHeight() - h[0]), LengthConstraintType.RANGE);
Size2D size = this.bottomBlock.arrange(g2, c2);
h[1] = size.height;
}
h[2] = constraint.getHeight() - h[1] - h[0];
if (this.leftBlock != null) {
RectangleConstraint c3 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth()),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.leftBlock.arrange(g2, c3);
w[2] = size.width;
}
h[3] = h[2];
if (this.rightBlock != null) {
RectangleConstraint c4 = new RectangleConstraint(0.0,
new Range(0.0, Math.max(constraint.getWidth() - w[2], 0.0)),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.rightBlock.arrange(g2, c4);
w[3] = size.width;
}
h[4] = h[2];
w[4] = constraint.getWidth() - w[3] - w[2];
RectangleConstraint c5 = new RectangleConstraint(w[4], h[4]);
if (this.centerBlock != null) {
this.centerBlock.arrange(g2, c5);
}
if (this.topBlock != null) {
this.topBlock.setBounds(new Rectangle2D.Double(0.0, 0.0, w[0],
h[0]));
}
if (this.bottomBlock != null) {
this.bottomBlock.setBounds(new Rectangle2D.Double(0.0, h[0] + h[2],
w[1], h[1]));
}
if (this.leftBlock != null) {
this.leftBlock.setBounds(new Rectangle2D.Double(0.0, h[0], w[2],
h[2]));
}
if (this.rightBlock != null) {
this.rightBlock.setBounds(new Rectangle2D.Double(w[2] + w[4], h[0],
w[3], h[3]));
}
if (this.centerBlock != null) {
this.centerBlock.setBounds(new Rectangle2D.Double(w[2], h[0], w[4],
h[4]));
}
return new Size2D(constraint.getWidth(), constraint.getHeight());
} | false | Chart | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Arranges the items within a container.
*
* @param container the container.
* @param constraint the constraint.
* @param g2 the graphics device.
*
* @return The container size after the arrangement.
*/
protected Size2D arrangeFF(BlockContainer container, Graphics2D g2,
RectangleConstraint constraint) {
double[] w = new double[5];
double[] h = new double[5];
w[0] = constraint.getWidth();
if (this.topBlock != null) {
RectangleConstraint c1 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0,
new Range(0.0, constraint.getHeight()),
LengthConstraintType.RANGE);
Size2D size = this.topBlock.arrange(g2, c1);
h[0] = size.height;
}
w[1] = w[0];
if (this.bottomBlock != null) {
RectangleConstraint c2 = new RectangleConstraint(w[0], null,
LengthConstraintType.FIXED, 0.0, new Range(0.0,
constraint.getHeight() - h[0]), LengthConstraintType.RANGE);
Size2D size = this.bottomBlock.arrange(g2, c2);
h[1] = size.height;
}
h[2] = constraint.getHeight() - h[1] - h[0];
if (this.leftBlock != null) {
RectangleConstraint c3 = new RectangleConstraint(0.0,
new Range(0.0, constraint.getWidth()),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.leftBlock.arrange(g2, c3);
w[2] = size.width;
}
h[3] = h[2];
if (this.rightBlock != null) {
RectangleConstraint c4 = new RectangleConstraint(0.0,
new Range(0.0, Math.max(constraint.getWidth() - w[2], 0.0)),
LengthConstraintType.RANGE, h[2], null,
LengthConstraintType.FIXED);
Size2D size = this.rightBlock.arrange(g2, c4);
w[3] = size.width;
}
h[4] = h[2];
w[4] = constraint.getWidth() - w[3] - w[2];
RectangleConstraint c5 = new RectangleConstraint(w[4], h[4]);
if (this.centerBlock != null) {
this.centerBlock.arrange(g2, c5);
}
if (this.topBlock != null) {
this.topBlock.setBounds(new Rectangle2D.Double(0.0, 0.0, w[0],
h[0]));
}
if (this.bottomBlock != null) {
this.bottomBlock.setBounds(new Rectangle2D.Double(0.0, h[0] + h[2],
w[1], h[1]));
}
if (this.leftBlock != null) {
this.leftBlock.setBounds(new Rectangle2D.Double(0.0, h[0], w[2],
h[2]));
}
if (this.rightBlock != null) {
this.rightBlock.setBounds(new Rectangle2D.Double(w[2] + w[4], h[0],
w[3], h[3]));
}
if (this.centerBlock != null) {
this.centerBlock.setBounds(new Rectangle2D.Double(w[2], h[0], w[4],
h[4]));
}
return new Size2D(constraint.getWidth(), constraint.getHeight());
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
85 | 85ebd7aef60648d24ef87d0309a41912302feb4adcddd09817e23a0fe1b4b0da | public static double[] bracket(UnivariateRealFunction function,
double initial, double lowerBound, double upperBound,
int maximumIterations) throws ConvergenceException,
FunctionEvaluationException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* This method attempts to find two values a and b satisfying <ul>
* <li> <code> lowerBound <= a < initial < b <= upperBound</code> </li>
* <li> <code> f(a) * f(b) <= 0 </code> </li>
* </ul>
* If f is continuous on <code>[a,b],</code> this means that <code>a</code>
* and <code>b</code> bracket a root of f.
* <p>
* The algorithm starts by setting
* <code>a := initial -1; b := initial +1,</code> examines the value of the
* function at <code>a</code> and <code>b</code> and keeps moving
* the endpoints out by one unit each time through a loop that terminates
* when one of the following happens: <ul>
* <li> <code> f(a) * f(b) <= 0 </code> -- success!</li>
* <li> <code> a = lower </code> and <code> b = upper</code>
* -- ConvergenceException </li>
* <li> <code> maximumIterations</code> iterations elapse
* -- ConvergenceException </li></ul></p>
*
* @param function the function
* @param initial initial midpoint of interval being expanded to
* bracket a root
* @param lowerBound lower bound (a is never lower than this value)
* @param upperBound upper bound (b never is greater than this
* value)
* @param maximumIterations maximum number of iterations to perform
* @return a two element array holding {a, b}.
* @throws ConvergenceException if the algorithm fails to find a and b
* satisfying the desired conditions
* @throws FunctionEvaluationException if an error occurs evaluating the
* function
* @throws IllegalArgumentException if function is null, maximumIterations
* is not positive, or initial is not between lowerBound and upperBound
*/
public static double[] bracket(UnivariateRealFunction function,
double initial, double lowerBound, double upperBound,
int maximumIterations) throws ConvergenceException,
FunctionEvaluationException {
if (function == null) {
throw MathRuntimeException.createIllegalArgumentException("function is null");
}
if (maximumIterations <= 0) {
throw MathRuntimeException.createIllegalArgumentException(
"bad value for maximum iterations number: {0}", maximumIterations);
}
if (initial < lowerBound || initial > upperBound || lowerBound >= upperBound) {
throw MathRuntimeException.createIllegalArgumentException(
"invalid bracketing parameters: lower bound={0}, initial={1}, upper bound={2}",
lowerBound, initial, upperBound);
}
double a = initial;
double b = initial;
double fa;
double fb;
int numIterations = 0 ;
do {
a = Math.max(a - 1.0, lowerBound);
b = Math.min(b + 1.0, upperBound);
fa = function.value(a);
fb = function.value(b);
numIterations++ ;
} while ((fa * fb > 0.0) && (numIterations < maximumIterations) &&
((a > lowerBound) || (b < upperBound)));
if (fa * fb > 0.0 ) {
throw new ConvergenceException(
"number of iterations={0}, maximum iterations={1}, " +
"initial={2}, lower bound={3}, upper bound={4}, final a value={5}, " +
"final b value={6}, f(a)={7}, f(b)={8}",
numIterations, maximumIterations, initial,
lowerBound, upperBound, a, b, fa, fb);
}
return new double[]{a, b};
}
```
| public static double[] bracket(UnivariateRealFunction function,
double initial, double lowerBound, double upperBound,
int maximumIterations) throws ConvergenceException,
FunctionEvaluationException {
if (function == null) {
throw MathRuntimeException.createIllegalArgumentException("function is null");
}
if (maximumIterations <= 0) {
throw MathRuntimeException.createIllegalArgumentException(
"bad value for maximum iterations number: {0}", maximumIterations);
}
if (initial < lowerBound || initial > upperBound || lowerBound >= upperBound) {
throw MathRuntimeException.createIllegalArgumentException(
"invalid bracketing parameters: lower bound={0}, initial={1}, upper bound={2}",
lowerBound, initial, upperBound);
}
double a = initial;
double b = initial;
double fa;
double fb;
int numIterations = 0 ;
do {
a = Math.max(a - 1.0, lowerBound);
b = Math.min(b + 1.0, upperBound);
fa = function.value(a);
fb = function.value(b);
numIterations++ ;
} while ((fa * fb > 0.0) && (numIterations < maximumIterations) &&
((a > lowerBound) || (b < upperBound)));
if (fa * fb > 0.0 ) {
throw new ConvergenceException(
"number of iterations={0}, maximum iterations={1}, " +
"initial={2}, lower bound={3}, upper bound={4}, final a value={5}, " +
"final b value={6}, f(a)={7}, f(b)={8}",
numIterations, maximumIterations, initial,
lowerBound, upperBound, a, b, fa, fb);
}
return new double[]{a, b};
} | false | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* This method attempts to find two values a and b satisfying <ul>
* <li> <code> lowerBound <= a < initial < b <= upperBound</code> </li>
* <li> <code> f(a) * f(b) <= 0 </code> </li>
* </ul>
* If f is continuous on <code>[a,b],</code> this means that <code>a</code>
* and <code>b</code> bracket a root of f.
* <p>
* The algorithm starts by setting
* <code>a := initial -1; b := initial +1,</code> examines the value of the
* function at <code>a</code> and <code>b</code> and keeps moving
* the endpoints out by one unit each time through a loop that terminates
* when one of the following happens: <ul>
* <li> <code> f(a) * f(b) <= 0 </code> -- success!</li>
* <li> <code> a = lower </code> and <code> b = upper</code>
* -- ConvergenceException </li>
* <li> <code> maximumIterations</code> iterations elapse
* -- ConvergenceException </li></ul></p>
*
* @param function the function
* @param initial initial midpoint of interval being expanded to
* bracket a root
* @param lowerBound lower bound (a is never lower than this value)
* @param upperBound upper bound (b never is greater than this
* value)
* @param maximumIterations maximum number of iterations to perform
* @return a two element array holding {a, b}.
* @throws ConvergenceException if the algorithm fails to find a and b
* satisfying the desired conditions
* @throws FunctionEvaluationException if an error occurs evaluating the
* function
* @throws IllegalArgumentException if function is null, maximumIterations
* is not positive, or initial is not between lowerBound and upperBound
*/
public static double[] bracket(UnivariateRealFunction function,
double initial, double lowerBound, double upperBound,
int maximumIterations) throws ConvergenceException,
FunctionEvaluationException {
if (function == null) {
throw MathRuntimeException.createIllegalArgumentException("function is null");
}
if (maximumIterations <= 0) {
throw MathRuntimeException.createIllegalArgumentException(
"bad value for maximum iterations number: {0}", maximumIterations);
}
if (initial < lowerBound || initial > upperBound || lowerBound >= upperBound) {
throw MathRuntimeException.createIllegalArgumentException(
"invalid bracketing parameters: lower bound={0}, initial={1}, upper bound={2}",
lowerBound, initial, upperBound);
}
double a = initial;
double b = initial;
double fa;
double fb;
int numIterations = 0 ;
do {
a = Math.max(a - 1.0, lowerBound);
b = Math.min(b + 1.0, upperBound);
fa = function.value(a);
fb = function.value(b);
numIterations++ ;
} while ((fa * fb > 0.0) && (numIterations < maximumIterations) &&
((a > lowerBound) || (b < upperBound)));
if (fa * fb > 0.0 ) {
throw new ConvergenceException(
"number of iterations={0}, maximum iterations={1}, " +
"initial={2}, lower bound={3}, upper bound={4}, final a value={5}, " +
"final b value={6}, f(a)={7}, f(b)={8}",
numIterations, maximumIterations, initial,
lowerBound, upperBound, a, b, fa, fb);
}
return new double[]{a, b};
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
40 | 863e37823bf60c36f61678df372c515df2b2e01e3995400029088bd6f960d4df | public long readBits(final int count) throws IOException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns at most 63 bits read from the underlying stream.
*
* @param count the number of bits to read, must be a positive
* number not bigger than 63.
* @return the bits concatenated as a long using the stream's byte order.
* -1 if the end of the underlying stream has been reached before reading
* the requested number of bits
* @throws IOException on error
*/
public long readBits(final int count) throws IOException {
if (count < 0 || count > MAXIMUM_CACHE_SIZE) {
throw new IllegalArgumentException("count must not be negative or greater than " + MAXIMUM_CACHE_SIZE);
}
while (bitsCachedSize < count && bitsCachedSize < 57) {
final long nextByte = in.read();
if (nextByte < 0) {
return nextByte;
}
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
bitsCached |= (nextByte << bitsCachedSize);
} else {
bitsCached <<= 8;
bitsCached |= nextByte;
}
bitsCachedSize += 8;
}
int overflowBits = 0;
long overflow = 0l;
if (bitsCachedSize < count) {
// bitsCachedSize >= 57 and left-shifting it 8 bits would cause an overflow
int bitsToAddCount = count - bitsCachedSize;
overflowBits = 8 - bitsToAddCount;
final long nextByte = in.read();
if (nextByte < 0) {
return nextByte;
}
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
long bitsToAdd = nextByte & MASKS[bitsToAddCount];
bitsCached |= (bitsToAdd << bitsCachedSize);
overflow = (nextByte >>> bitsToAddCount) & MASKS[overflowBits];
} else {
bitsCached <<= bitsToAddCount;
long bitsToAdd = (nextByte >>> (overflowBits)) & MASKS[bitsToAddCount];
bitsCached |= bitsToAdd;
overflow = nextByte & MASKS[overflowBits];
}
bitsCachedSize = count;
}
final long bitsOut;
if (overflowBits == 0) {
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
bitsOut = (bitsCached & MASKS[count]);
bitsCached >>>= count;
} else {
bitsOut = (bitsCached >> (bitsCachedSize - count)) & MASKS[count];
}
bitsCachedSize -= count;
} else {
bitsOut = bitsCached & MASKS[count];
bitsCached = overflow;
bitsCachedSize = overflowBits;
}
return bitsOut;
}
```
| public long readBits(final int count) throws IOException {
if (count < 0 || count > MAXIMUM_CACHE_SIZE) {
throw new IllegalArgumentException("count must not be negative or greater than " + MAXIMUM_CACHE_SIZE);
}
while (bitsCachedSize < count && bitsCachedSize < 57) {
final long nextByte = in.read();
if (nextByte < 0) {
return nextByte;
}
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
bitsCached |= (nextByte << bitsCachedSize);
} else {
bitsCached <<= 8;
bitsCached |= nextByte;
}
bitsCachedSize += 8;
}
int overflowBits = 0;
long overflow = 0l;
if (bitsCachedSize < count) {
// bitsCachedSize >= 57 and left-shifting it 8 bits would cause an overflow
int bitsToAddCount = count - bitsCachedSize;
overflowBits = 8 - bitsToAddCount;
final long nextByte = in.read();
if (nextByte < 0) {
return nextByte;
}
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
long bitsToAdd = nextByte & MASKS[bitsToAddCount];
bitsCached |= (bitsToAdd << bitsCachedSize);
overflow = (nextByte >>> bitsToAddCount) & MASKS[overflowBits];
} else {
bitsCached <<= bitsToAddCount;
long bitsToAdd = (nextByte >>> (overflowBits)) & MASKS[bitsToAddCount];
bitsCached |= bitsToAdd;
overflow = nextByte & MASKS[overflowBits];
}
bitsCachedSize = count;
}
final long bitsOut;
if (overflowBits == 0) {
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
bitsOut = (bitsCached & MASKS[count]);
bitsCached >>>= count;
} else {
bitsOut = (bitsCached >> (bitsCachedSize - count)) & MASKS[count];
}
bitsCachedSize -= count;
} else {
bitsOut = bitsCached & MASKS[count];
bitsCached = overflow;
bitsCachedSize = overflowBits;
}
return bitsOut;
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns at most 63 bits read from the underlying stream.
*
* @param count the number of bits to read, must be a positive
* number not bigger than 63.
* @return the bits concatenated as a long using the stream's byte order.
* -1 if the end of the underlying stream has been reached before reading
* the requested number of bits
* @throws IOException on error
*/
public long readBits(final int count) throws IOException {
if (count < 0 || count > MAXIMUM_CACHE_SIZE) {
throw new IllegalArgumentException("count must not be negative or greater than " + MAXIMUM_CACHE_SIZE);
}
while (bitsCachedSize < count && bitsCachedSize < 57) {
final long nextByte = in.read();
if (nextByte < 0) {
return nextByte;
}
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
bitsCached |= (nextByte << bitsCachedSize);
} else {
bitsCached <<= 8;
bitsCached |= nextByte;
}
bitsCachedSize += 8;
}
int overflowBits = 0;
long overflow = 0l;
if (bitsCachedSize < count) {
// bitsCachedSize >= 57 and left-shifting it 8 bits would cause an overflow
int bitsToAddCount = count - bitsCachedSize;
overflowBits = 8 - bitsToAddCount;
final long nextByte = in.read();
if (nextByte < 0) {
return nextByte;
}
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
long bitsToAdd = nextByte & MASKS[bitsToAddCount];
bitsCached |= (bitsToAdd << bitsCachedSize);
overflow = (nextByte >>> bitsToAddCount) & MASKS[overflowBits];
} else {
bitsCached <<= bitsToAddCount;
long bitsToAdd = (nextByte >>> (overflowBits)) & MASKS[bitsToAddCount];
bitsCached |= bitsToAdd;
overflow = nextByte & MASKS[overflowBits];
}
bitsCachedSize = count;
}
final long bitsOut;
if (overflowBits == 0) {
if (byteOrder == ByteOrder.LITTLE_ENDIAN) {
bitsOut = (bitsCached & MASKS[count]);
bitsCached >>>= count;
} else {
bitsOut = (bitsCached >> (bitsCachedSize - count)) & MASKS[count];
}
bitsCachedSize -= count;
} else {
bitsOut = bitsCached & MASKS[count];
bitsCached = overflow;
bitsCachedSize = overflowBits;
}
return bitsOut;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
32 | 8645fa961f601441f69c00f9e7acddf08ea1e37e1205f5021a2344d8f4832ddb | @Override
protected void computeGeometricalProperties() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/** {@inheritDoc} */
@Override
protected void computeGeometricalProperties() {
final Vector2D[][] v = getVertices();
if (v.length == 0) {
final BSPTree<Euclidean2D> tree = getTree(false);
if ((Boolean) tree.getAttribute()) {
// the instance covers the whole space
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(0);
setBarycenter(new Vector2D(0, 0));
}
} else if (v[0][0] == null) {
// there is at least one open-loop: the polygon is infinite
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
// all loops are closed, we compute some integrals around the shape
double sum = 0;
double sumX = 0;
double sumY = 0;
for (Vector2D[] loop : v) {
double x1 = loop[loop.length - 1].getX();
double y1 = loop[loop.length - 1].getY();
for (final Vector2D point : loop) {
final double x0 = x1;
final double y0 = y1;
x1 = point.getX();
y1 = point.getY();
final double factor = x0 * y1 - y0 * x1;
sum += factor;
sumX += factor * (x0 + x1);
sumY += factor * (y0 + y1);
}
}
if (sum < 0) {
// the polygon as a finite outside surrounded by an infinite inside
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(sum / 2);
setBarycenter(new Vector2D(sumX / (3 * sum), sumY / (3 * sum)));
}
}
}
```
| @Override
protected void computeGeometricalProperties() {
final Vector2D[][] v = getVertices();
if (v.length == 0) {
final BSPTree<Euclidean2D> tree = getTree(false);
if ((Boolean) tree.getAttribute()) {
// the instance covers the whole space
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(0);
setBarycenter(new Vector2D(0, 0));
}
} else if (v[0][0] == null) {
// there is at least one open-loop: the polygon is infinite
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
// all loops are closed, we compute some integrals around the shape
double sum = 0;
double sumX = 0;
double sumY = 0;
for (Vector2D[] loop : v) {
double x1 = loop[loop.length - 1].getX();
double y1 = loop[loop.length - 1].getY();
for (final Vector2D point : loop) {
final double x0 = x1;
final double y0 = y1;
x1 = point.getX();
y1 = point.getY();
final double factor = x0 * y1 - y0 * x1;
sum += factor;
sumX += factor * (x0 + x1);
sumY += factor * (y0 + y1);
}
}
if (sum < 0) {
// the polygon as a finite outside surrounded by an infinite inside
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(sum / 2);
setBarycenter(new Vector2D(sumX / (3 * sum), sumY / (3 * sum)));
}
}
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/** {@inheritDoc} */
@Override
protected void computeGeometricalProperties() {
final Vector2D[][] v = getVertices();
if (v.length == 0) {
final BSPTree<Euclidean2D> tree = getTree(false);
if ((Boolean) tree.getAttribute()) {
// the instance covers the whole space
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(0);
setBarycenter(new Vector2D(0, 0));
}
} else if (v[0][0] == null) {
// there is at least one open-loop: the polygon is infinite
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
// all loops are closed, we compute some integrals around the shape
double sum = 0;
double sumX = 0;
double sumY = 0;
for (Vector2D[] loop : v) {
double x1 = loop[loop.length - 1].getX();
double y1 = loop[loop.length - 1].getY();
for (final Vector2D point : loop) {
final double x0 = x1;
final double y0 = y1;
x1 = point.getX();
y1 = point.getY();
final double factor = x0 * y1 - y0 * x1;
sum += factor;
sumX += factor * (x0 + x1);
sumY += factor * (y0 + y1);
}
}
if (sum < 0) {
// the polygon as a finite outside surrounded by an infinite inside
setSize(Double.POSITIVE_INFINITY);
setBarycenter(Vector2D.NaN);
} else {
setSize(sum / 2);
setBarycenter(new Vector2D(sumX / (3 * sum), sumY / (3 * sum)));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 869fea20b888c77961fc360f87fe05e32a46597286458edae1d59af471f8e1b2 | protected JavaType _fromVariable(TypeVariable<?> type, TypeBindings context)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
protected JavaType _fromVariable(TypeVariable<?> type, TypeBindings context)
{
final String name = type.getName();
// 19-Mar-2015: Without context, all we can check are bounds.
if (context == null) {
// And to prevent infinite loops, now need this:
return _unknownType();
} else {
// Ok: here's where context might come in handy!
/* 19-Mar-2015, tatu: As per [databind#609], may need to allow
* unresolved type variables to handle some cases where bounds
* are enough. Let's hope it does not hide real fail cases.
*/
JavaType actualType = context.findType(name);
if (actualType != null) {
return actualType;
}
}
/* 29-Jan-2010, tatu: We used to throw exception here, if type was
* bound: but the problem is that this can occur for generic "base"
* method, overridden by sub-class. If so, we will want to ignore
* current type (for method) since it will be masked.
*/
Type[] bounds = type.getBounds();
// With type variables we must use bound information.
// Theoretically this gets tricky, as there may be multiple
// bounds ("... extends A & B"); and optimally we might
// want to choose the best match. Also, bounds are optional;
// but here we are lucky in that implicit "Object" is
// added as bounds if so.
// Either way let's just use the first bound, for now, and
// worry about better match later on if there is need.
/* 29-Jan-2010, tatu: One more problem are recursive types
* (T extends Comparable<T>). Need to add "placeholder"
* for resolution to catch those.
*/
context._addPlaceholder(name);
return _constructType(bounds[0], context);
}
```
| protected JavaType _fromVariable(TypeVariable<?> type, TypeBindings context)
{
final String name = type.getName();
// 19-Mar-2015: Without context, all we can check are bounds.
if (context == null) {
// And to prevent infinite loops, now need this:
return _unknownType();
} else {
// Ok: here's where context might come in handy!
/* 19-Mar-2015, tatu: As per [databind#609], may need to allow
* unresolved type variables to handle some cases where bounds
* are enough. Let's hope it does not hide real fail cases.
*/
JavaType actualType = context.findType(name);
if (actualType != null) {
return actualType;
}
}
/* 29-Jan-2010, tatu: We used to throw exception here, if type was
* bound: but the problem is that this can occur for generic "base"
* method, overridden by sub-class. If so, we will want to ignore
* current type (for method) since it will be masked.
*/
Type[] bounds = type.getBounds();
// With type variables we must use bound information.
// Theoretically this gets tricky, as there may be multiple
// bounds ("... extends A & B"); and optimally we might
// want to choose the best match. Also, bounds are optional;
// but here we are lucky in that implicit "Object" is
// added as bounds if so.
// Either way let's just use the first bound, for now, and
// worry about better match later on if there is need.
/* 29-Jan-2010, tatu: One more problem are recursive types
* (T extends Comparable<T>). Need to add "placeholder"
* for resolution to catch those.
*/
context._addPlaceholder(name);
return _constructType(bounds[0], context);
} | true | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
protected JavaType _fromVariable(TypeVariable<?> type, TypeBindings context)
{
final String name = type.getName();
// 19-Mar-2015: Without context, all we can check are bounds.
if (context == null) {
// And to prevent infinite loops, now need this:
return _unknownType();
} else {
// Ok: here's where context might come in handy!
/* 19-Mar-2015, tatu: As per [databind#609], may need to allow
* unresolved type variables to handle some cases where bounds
* are enough. Let's hope it does not hide real fail cases.
*/
JavaType actualType = context.findType(name);
if (actualType != null) {
return actualType;
}
}
/* 29-Jan-2010, tatu: We used to throw exception here, if type was
* bound: but the problem is that this can occur for generic "base"
* method, overridden by sub-class. If so, we will want to ignore
* current type (for method) since it will be masked.
*/
Type[] bounds = type.getBounds();
// With type variables we must use bound information.
// Theoretically this gets tricky, as there may be multiple
// bounds ("... extends A & B"); and optimally we might
// want to choose the best match. Also, bounds are optional;
// but here we are lucky in that implicit "Object" is
// added as bounds if so.
// Either way let's just use the first bound, for now, and
// worry about better match later on if there is need.
/* 29-Jan-2010, tatu: One more problem are recursive types
* (T extends Comparable<T>). Need to add "placeholder"
* for resolution to catch those.
*/
context._addPlaceholder(name);
return _constructType(bounds[0], context);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
1 | 872e64645a4491b56b7e165ca2084c18d463993f9d4cc1a30c56e6bb88b9e7b4 | public void captureArgumentsFrom(Invocation invocation) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public void captureArgumentsFrom(Invocation invocation) {
if (invocation.getMethod().isVarArgs()) {
int indexOfVararg = invocation.getRawArguments().length - 1;
throw new UnsupportedOperationException();
} else {
for (int position = 0; position < matchers.size(); position++) {
Matcher m = matchers.get(position);
if (m instanceof CapturesArguments) {
((CapturesArguments) m).captureFrom(invocation.getArgumentAt(position, Object.class));
}
}
}
// for (int position = 0; position < matchers.size(); position++) {
// Matcher m = matchers.get(position);
// if (m instanceof CapturesArguments && invocation.getRawArguments().length > position) {
// //TODO SF - this whole lot can be moved captureFrom implementation
// if(isVariableArgument(invocation, position) && isVarargMatcher(m)) {
// Object array = invocation.getRawArguments()[position];
// for (int i = 0; i < Array.getLength(array); i++) {
// ((CapturesArguments) m).captureFrom(Array.get(array, i));
// }
// //since we've captured all varargs already, it does not make sense to process other matchers.
// return;
// } else {
// ((CapturesArguments) m).captureFrom(invocation.getRawArguments()[position]);
// }
// }
// }
}
```
| public void captureArgumentsFrom(Invocation invocation) {
if (invocation.getMethod().isVarArgs()) {
int indexOfVararg = invocation.getRawArguments().length - 1;
throw new UnsupportedOperationException();
} else {
for (int position = 0; position < matchers.size(); position++) {
Matcher m = matchers.get(position);
if (m instanceof CapturesArguments) {
((CapturesArguments) m).captureFrom(invocation.getArgumentAt(position, Object.class));
}
}
}
// for (int position = 0; position < matchers.size(); position++) {
// Matcher m = matchers.get(position);
// if (m instanceof CapturesArguments && invocation.getRawArguments().length > position) {
// //TODO SF - this whole lot can be moved captureFrom implementation
// if(isVariableArgument(invocation, position) && isVarargMatcher(m)) {
// Object array = invocation.getRawArguments()[position];
// for (int i = 0; i < Array.getLength(array); i++) {
// ((CapturesArguments) m).captureFrom(Array.get(array, i));
// }
// //since we've captured all varargs already, it does not make sense to process other matchers.
// return;
// } else {
// ((CapturesArguments) m).captureFrom(invocation.getRawArguments()[position]);
// }
// }
// }
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public void captureArgumentsFrom(Invocation invocation) {
if (invocation.getMethod().isVarArgs()) {
int indexOfVararg = invocation.getRawArguments().length - 1;
throw new UnsupportedOperationException();
} else {
for (int position = 0; position < matchers.size(); position++) {
Matcher m = matchers.get(position);
if (m instanceof CapturesArguments) {
((CapturesArguments) m).captureFrom(invocation.getArgumentAt(position, Object.class));
}
}
}
// for (int position = 0; position < matchers.size(); position++) {
// Matcher m = matchers.get(position);
// if (m instanceof CapturesArguments && invocation.getRawArguments().length > position) {
// //TODO SF - this whole lot can be moved captureFrom implementation
// if(isVariableArgument(invocation, position) && isVarargMatcher(m)) {
// Object array = invocation.getRawArguments()[position];
// for (int i = 0; i < Array.getLength(array); i++) {
// ((CapturesArguments) m).captureFrom(Array.get(array, i));
// }
// //since we've captured all varargs already, it does not make sense to process other matchers.
// return;
// } else {
// ((CapturesArguments) m).captureFrom(invocation.getRawArguments()[position]);
// }
// }
// }
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
132 | 8739aba136dc35969d73230badadfd0b0ddb53acb29d4d025577c4f5d7db2e6b | private Node tryMinimizeIf(Node n) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Try turning IF nodes into smaller HOOKs
*
* Returns the replacement for n or the original if no replacement was
* necessary.
*/
private Node tryMinimizeIf(Node n) {
Node parent = n.getParent();
Node cond = n.getFirstChild();
/* If the condition is a literal, we'll let other
* optimizations try to remove useless code.
*/
if (NodeUtil.isLiteralValue(cond, true)) {
return n;
}
Node thenBranch = cond.getNext();
Node elseBranch = thenBranch.getNext();
if (elseBranch == null) {
if (isFoldableExpressBlock(thenBranch)) {
Node expr = getBlockExpression(thenBranch);
if (!late && isPropertyAssignmentInExpression(expr)) {
// Keep opportunities for CollapseProperties such as
// a.longIdentifier || a.longIdentifier = ... -> var a = ...;
// until CollapseProperties has been run.
return n;
}
if (cond.isNot()) {
// if(!x)bar(); -> x||bar();
if (isLowerPrecedenceInExpression(cond, OR_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
OR_PRECEDENCE)) {
// It's not okay to add two sets of parentheses.
return n;
}
Node or = IR.or(
cond.removeFirstChild(),
expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(or);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
}
// if(x)foo(); -> x&&foo();
if (isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
AND_PRECEDENCE)) {
// One additional set of parentheses is worth the change even if
// there is no immediate code size win. However, two extra pair of
// {}, we would have to think twice. (unless we know for sure the
// we can further optimize its parent.
return n;
}
n.removeChild(cond);
Node and = IR.and(cond, expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(and);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
} else {
// Try to combine two IF-ELSE
if (NodeUtil.isStatementBlock(thenBranch) &&
thenBranch.hasOneChild()) {
Node innerIf = thenBranch.getFirstChild();
if (innerIf.isIf()) {
Node innerCond = innerIf.getFirstChild();
Node innerThenBranch = innerCond.getNext();
Node innerElseBranch = innerThenBranch.getNext();
if (innerElseBranch == null &&
!(isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(innerCond, AND_PRECEDENCE))) {
n.detachChildren();
n.addChildToBack(
IR.and(
cond,
innerCond.detachFromParent())
.srcref(cond));
n.addChildrenToBack(innerThenBranch.detachFromParent());
reportCodeChange();
// Not worth trying to fold the current IF-ELSE into && because
// the inner IF-ELSE wasn't able to be folded into && anyways.
return n;
}
}
}
}
return n;
}
/* TODO(dcc) This modifies the siblings of n, which is undesirable for a
* peephole optimization. This should probably get moved to another pass.
*/
tryRemoveRepeatedStatements(n);
// if(!x)foo();else bar(); -> if(x)bar();else foo();
// An additional set of curly braces isn't worth it.
if (cond.isNot() && !consumesDanglingElse(elseBranch)) {
n.replaceChild(cond, cond.removeFirstChild());
n.removeChild(thenBranch);
n.addChildToBack(thenBranch);
reportCodeChange();
return n;
}
// if(x)return 1;else return 2; -> return x?1:2;
if (isReturnExpressBlock(thenBranch) && isReturnExpressBlock(elseBranch)) {
Node thenExpr = getBlockReturnExpression(thenBranch);
Node elseExpr = getBlockReturnExpression(elseBranch);
n.removeChild(cond);
thenExpr.detachFromParent();
elseExpr.detachFromParent();
// note - we ignore any cases with "return;", technically this
// can be converted to "return undefined;" or some variant, but
// that does not help code size.
Node returnNode = IR.returnNode(
IR.hook(cond, thenExpr, elseExpr)
.srcref(n));
parent.replaceChild(n, returnNode);
reportCodeChange();
return returnNode;
}
boolean thenBranchIsExpressionBlock = isFoldableExpressBlock(thenBranch);
boolean elseBranchIsExpressionBlock = isFoldableExpressBlock(elseBranch);
if (thenBranchIsExpressionBlock && elseBranchIsExpressionBlock) {
Node thenOp = getBlockExpression(thenBranch).getFirstChild();
Node elseOp = getBlockExpression(elseBranch).getFirstChild();
if (thenOp.getType() == elseOp.getType()) {
// if(x)a=1;else a=2; -> a=x?1:2;
if (NodeUtil.isAssignmentOp(thenOp)) {
Node lhs = thenOp.getFirstChild();
if (areNodesEqualForInlining(lhs, elseOp.getFirstChild()) &&
// if LHS has side effects, don't proceed [since the optimization
// evaluates LHS before cond]
// NOTE - there are some circumstances where we can
// proceed even if there are side effects...
!mayEffectMutableState(lhs)) {
n.removeChild(cond);
Node assignName = thenOp.removeFirstChild();
Node thenExpr = thenOp.removeFirstChild();
Node elseExpr = elseOp.getLastChild();
elseOp.removeChild(elseExpr);
Node hookNode = IR.hook(cond, thenExpr, elseExpr).srcref(n);
Node assign = new Node(thenOp.getType(), assignName, hookNode)
.srcref(thenOp);
Node expr = NodeUtil.newExpr(assign);
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
}
}
// if(x)foo();else bar(); -> x?foo():bar()
n.removeChild(cond);
thenOp.detachFromParent();
elseOp.detachFromParent();
Node expr = IR.exprResult(
IR.hook(cond, thenOp, elseOp).srcref(n));
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
boolean thenBranchIsVar = isVarBlock(thenBranch);
boolean elseBranchIsVar = isVarBlock(elseBranch);
// if(x)var y=1;else y=2 -> var y=x?1:2
if (thenBranchIsVar && elseBranchIsExpressionBlock &&
getBlockExpression(elseBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(thenBranch);
Node elseAssign = getBlockExpression(elseBranch).getFirstChild();
Node name1 = var.getFirstChild();
Node maybeName2 = elseAssign.getFirstChild();
if (name1.hasChildren()
&& maybeName2.isName()
&& name1.getString().equals(maybeName2.getString())) {
Node thenExpr = name1.removeChildren();
Node elseExpr = elseAssign.getLastChild().detachFromParent();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name1.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
// if(x)y=1;else var y=2 -> var y=x?1:2
} else if (elseBranchIsVar && thenBranchIsExpressionBlock &&
getBlockExpression(thenBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(elseBranch);
Node thenAssign = getBlockExpression(thenBranch).getFirstChild();
Node maybeName1 = thenAssign.getFirstChild();
Node name2 = var.getFirstChild();
if (name2.hasChildren()
&& maybeName1.isName()
&& maybeName1.getString().equals(name2.getString())) {
Node thenExpr = thenAssign.getLastChild().detachFromParent();
Node elseExpr = name2.removeChildren();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name2.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
}
return n;
}
```
| private Node tryMinimizeIf(Node n) {
Node parent = n.getParent();
Node cond = n.getFirstChild();
/* If the condition is a literal, we'll let other
* optimizations try to remove useless code.
*/
if (NodeUtil.isLiteralValue(cond, true)) {
return n;
}
Node thenBranch = cond.getNext();
Node elseBranch = thenBranch.getNext();
if (elseBranch == null) {
if (isFoldableExpressBlock(thenBranch)) {
Node expr = getBlockExpression(thenBranch);
if (!late && isPropertyAssignmentInExpression(expr)) {
// Keep opportunities for CollapseProperties such as
// a.longIdentifier || a.longIdentifier = ... -> var a = ...;
// until CollapseProperties has been run.
return n;
}
if (cond.isNot()) {
// if(!x)bar(); -> x||bar();
if (isLowerPrecedenceInExpression(cond, OR_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
OR_PRECEDENCE)) {
// It's not okay to add two sets of parentheses.
return n;
}
Node or = IR.or(
cond.removeFirstChild(),
expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(or);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
}
// if(x)foo(); -> x&&foo();
if (isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
AND_PRECEDENCE)) {
// One additional set of parentheses is worth the change even if
// there is no immediate code size win. However, two extra pair of
// {}, we would have to think twice. (unless we know for sure the
// we can further optimize its parent.
return n;
}
n.removeChild(cond);
Node and = IR.and(cond, expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(and);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
} else {
// Try to combine two IF-ELSE
if (NodeUtil.isStatementBlock(thenBranch) &&
thenBranch.hasOneChild()) {
Node innerIf = thenBranch.getFirstChild();
if (innerIf.isIf()) {
Node innerCond = innerIf.getFirstChild();
Node innerThenBranch = innerCond.getNext();
Node innerElseBranch = innerThenBranch.getNext();
if (innerElseBranch == null &&
!(isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(innerCond, AND_PRECEDENCE))) {
n.detachChildren();
n.addChildToBack(
IR.and(
cond,
innerCond.detachFromParent())
.srcref(cond));
n.addChildrenToBack(innerThenBranch.detachFromParent());
reportCodeChange();
// Not worth trying to fold the current IF-ELSE into && because
// the inner IF-ELSE wasn't able to be folded into && anyways.
return n;
}
}
}
}
return n;
}
/* TODO(dcc) This modifies the siblings of n, which is undesirable for a
* peephole optimization. This should probably get moved to another pass.
*/
tryRemoveRepeatedStatements(n);
// if(!x)foo();else bar(); -> if(x)bar();else foo();
// An additional set of curly braces isn't worth it.
if (cond.isNot() && !consumesDanglingElse(elseBranch)) {
n.replaceChild(cond, cond.removeFirstChild());
n.removeChild(thenBranch);
n.addChildToBack(thenBranch);
reportCodeChange();
return n;
}
// if(x)return 1;else return 2; -> return x?1:2;
if (isReturnExpressBlock(thenBranch) && isReturnExpressBlock(elseBranch)) {
Node thenExpr = getBlockReturnExpression(thenBranch);
Node elseExpr = getBlockReturnExpression(elseBranch);
n.removeChild(cond);
thenExpr.detachFromParent();
elseExpr.detachFromParent();
// note - we ignore any cases with "return;", technically this
// can be converted to "return undefined;" or some variant, but
// that does not help code size.
Node returnNode = IR.returnNode(
IR.hook(cond, thenExpr, elseExpr)
.srcref(n));
parent.replaceChild(n, returnNode);
reportCodeChange();
return returnNode;
}
boolean thenBranchIsExpressionBlock = isFoldableExpressBlock(thenBranch);
boolean elseBranchIsExpressionBlock = isFoldableExpressBlock(elseBranch);
if (thenBranchIsExpressionBlock && elseBranchIsExpressionBlock) {
Node thenOp = getBlockExpression(thenBranch).getFirstChild();
Node elseOp = getBlockExpression(elseBranch).getFirstChild();
if (thenOp.getType() == elseOp.getType()) {
// if(x)a=1;else a=2; -> a=x?1:2;
if (NodeUtil.isAssignmentOp(thenOp)) {
Node lhs = thenOp.getFirstChild();
if (areNodesEqualForInlining(lhs, elseOp.getFirstChild()) &&
// if LHS has side effects, don't proceed [since the optimization
// evaluates LHS before cond]
// NOTE - there are some circumstances where we can
// proceed even if there are side effects...
!mayEffectMutableState(lhs)) {
n.removeChild(cond);
Node assignName = thenOp.removeFirstChild();
Node thenExpr = thenOp.removeFirstChild();
Node elseExpr = elseOp.getLastChild();
elseOp.removeChild(elseExpr);
Node hookNode = IR.hook(cond, thenExpr, elseExpr).srcref(n);
Node assign = new Node(thenOp.getType(), assignName, hookNode)
.srcref(thenOp);
Node expr = NodeUtil.newExpr(assign);
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
}
}
// if(x)foo();else bar(); -> x?foo():bar()
n.removeChild(cond);
thenOp.detachFromParent();
elseOp.detachFromParent();
Node expr = IR.exprResult(
IR.hook(cond, thenOp, elseOp).srcref(n));
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
boolean thenBranchIsVar = isVarBlock(thenBranch);
boolean elseBranchIsVar = isVarBlock(elseBranch);
// if(x)var y=1;else y=2 -> var y=x?1:2
if (thenBranchIsVar && elseBranchIsExpressionBlock &&
getBlockExpression(elseBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(thenBranch);
Node elseAssign = getBlockExpression(elseBranch).getFirstChild();
Node name1 = var.getFirstChild();
Node maybeName2 = elseAssign.getFirstChild();
if (name1.hasChildren()
&& maybeName2.isName()
&& name1.getString().equals(maybeName2.getString())) {
Node thenExpr = name1.removeChildren();
Node elseExpr = elseAssign.getLastChild().detachFromParent();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name1.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
// if(x)y=1;else var y=2 -> var y=x?1:2
} else if (elseBranchIsVar && thenBranchIsExpressionBlock &&
getBlockExpression(thenBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(elseBranch);
Node thenAssign = getBlockExpression(thenBranch).getFirstChild();
Node maybeName1 = thenAssign.getFirstChild();
Node name2 = var.getFirstChild();
if (name2.hasChildren()
&& maybeName1.isName()
&& maybeName1.getString().equals(name2.getString())) {
Node thenExpr = thenAssign.getLastChild().detachFromParent();
Node elseExpr = name2.removeChildren();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name2.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
}
return n;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Try turning IF nodes into smaller HOOKs
*
* Returns the replacement for n or the original if no replacement was
* necessary.
*/
private Node tryMinimizeIf(Node n) {
Node parent = n.getParent();
Node cond = n.getFirstChild();
/* If the condition is a literal, we'll let other
* optimizations try to remove useless code.
*/
if (NodeUtil.isLiteralValue(cond, true)) {
return n;
}
Node thenBranch = cond.getNext();
Node elseBranch = thenBranch.getNext();
if (elseBranch == null) {
if (isFoldableExpressBlock(thenBranch)) {
Node expr = getBlockExpression(thenBranch);
if (!late && isPropertyAssignmentInExpression(expr)) {
// Keep opportunities for CollapseProperties such as
// a.longIdentifier || a.longIdentifier = ... -> var a = ...;
// until CollapseProperties has been run.
return n;
}
if (cond.isNot()) {
// if(!x)bar(); -> x||bar();
if (isLowerPrecedenceInExpression(cond, OR_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
OR_PRECEDENCE)) {
// It's not okay to add two sets of parentheses.
return n;
}
Node or = IR.or(
cond.removeFirstChild(),
expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(or);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
}
// if(x)foo(); -> x&&foo();
if (isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(expr.getFirstChild(),
AND_PRECEDENCE)) {
// One additional set of parentheses is worth the change even if
// there is no immediate code size win. However, two extra pair of
// {}, we would have to think twice. (unless we know for sure the
// we can further optimize its parent.
return n;
}
n.removeChild(cond);
Node and = IR.and(cond, expr.removeFirstChild()).srcref(n);
Node newExpr = NodeUtil.newExpr(and);
parent.replaceChild(n, newExpr);
reportCodeChange();
return newExpr;
} else {
// Try to combine two IF-ELSE
if (NodeUtil.isStatementBlock(thenBranch) &&
thenBranch.hasOneChild()) {
Node innerIf = thenBranch.getFirstChild();
if (innerIf.isIf()) {
Node innerCond = innerIf.getFirstChild();
Node innerThenBranch = innerCond.getNext();
Node innerElseBranch = innerThenBranch.getNext();
if (innerElseBranch == null &&
!(isLowerPrecedenceInExpression(cond, AND_PRECEDENCE) &&
isLowerPrecedenceInExpression(innerCond, AND_PRECEDENCE))) {
n.detachChildren();
n.addChildToBack(
IR.and(
cond,
innerCond.detachFromParent())
.srcref(cond));
n.addChildrenToBack(innerThenBranch.detachFromParent());
reportCodeChange();
// Not worth trying to fold the current IF-ELSE into && because
// the inner IF-ELSE wasn't able to be folded into && anyways.
return n;
}
}
}
}
return n;
}
/* TODO(dcc) This modifies the siblings of n, which is undesirable for a
* peephole optimization. This should probably get moved to another pass.
*/
tryRemoveRepeatedStatements(n);
// if(!x)foo();else bar(); -> if(x)bar();else foo();
// An additional set of curly braces isn't worth it.
if (cond.isNot() && !consumesDanglingElse(elseBranch)) {
n.replaceChild(cond, cond.removeFirstChild());
n.removeChild(thenBranch);
n.addChildToBack(thenBranch);
reportCodeChange();
return n;
}
// if(x)return 1;else return 2; -> return x?1:2;
if (isReturnExpressBlock(thenBranch) && isReturnExpressBlock(elseBranch)) {
Node thenExpr = getBlockReturnExpression(thenBranch);
Node elseExpr = getBlockReturnExpression(elseBranch);
n.removeChild(cond);
thenExpr.detachFromParent();
elseExpr.detachFromParent();
// note - we ignore any cases with "return;", technically this
// can be converted to "return undefined;" or some variant, but
// that does not help code size.
Node returnNode = IR.returnNode(
IR.hook(cond, thenExpr, elseExpr)
.srcref(n));
parent.replaceChild(n, returnNode);
reportCodeChange();
return returnNode;
}
boolean thenBranchIsExpressionBlock = isFoldableExpressBlock(thenBranch);
boolean elseBranchIsExpressionBlock = isFoldableExpressBlock(elseBranch);
if (thenBranchIsExpressionBlock && elseBranchIsExpressionBlock) {
Node thenOp = getBlockExpression(thenBranch).getFirstChild();
Node elseOp = getBlockExpression(elseBranch).getFirstChild();
if (thenOp.getType() == elseOp.getType()) {
// if(x)a=1;else a=2; -> a=x?1:2;
if (NodeUtil.isAssignmentOp(thenOp)) {
Node lhs = thenOp.getFirstChild();
if (areNodesEqualForInlining(lhs, elseOp.getFirstChild()) &&
// if LHS has side effects, don't proceed [since the optimization
// evaluates LHS before cond]
// NOTE - there are some circumstances where we can
// proceed even if there are side effects...
!mayEffectMutableState(lhs)) {
n.removeChild(cond);
Node assignName = thenOp.removeFirstChild();
Node thenExpr = thenOp.removeFirstChild();
Node elseExpr = elseOp.getLastChild();
elseOp.removeChild(elseExpr);
Node hookNode = IR.hook(cond, thenExpr, elseExpr).srcref(n);
Node assign = new Node(thenOp.getType(), assignName, hookNode)
.srcref(thenOp);
Node expr = NodeUtil.newExpr(assign);
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
}
}
// if(x)foo();else bar(); -> x?foo():bar()
n.removeChild(cond);
thenOp.detachFromParent();
elseOp.detachFromParent();
Node expr = IR.exprResult(
IR.hook(cond, thenOp, elseOp).srcref(n));
parent.replaceChild(n, expr);
reportCodeChange();
return expr;
}
boolean thenBranchIsVar = isVarBlock(thenBranch);
boolean elseBranchIsVar = isVarBlock(elseBranch);
// if(x)var y=1;else y=2 -> var y=x?1:2
if (thenBranchIsVar && elseBranchIsExpressionBlock &&
getBlockExpression(elseBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(thenBranch);
Node elseAssign = getBlockExpression(elseBranch).getFirstChild();
Node name1 = var.getFirstChild();
Node maybeName2 = elseAssign.getFirstChild();
if (name1.hasChildren()
&& maybeName2.isName()
&& name1.getString().equals(maybeName2.getString())) {
Node thenExpr = name1.removeChildren();
Node elseExpr = elseAssign.getLastChild().detachFromParent();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name1.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
// if(x)y=1;else var y=2 -> var y=x?1:2
} else if (elseBranchIsVar && thenBranchIsExpressionBlock &&
getBlockExpression(thenBranch).getFirstChild().isAssign()) {
Node var = getBlockVar(elseBranch);
Node thenAssign = getBlockExpression(thenBranch).getFirstChild();
Node maybeName1 = thenAssign.getFirstChild();
Node name2 = var.getFirstChild();
if (name2.hasChildren()
&& maybeName1.isName()
&& maybeName1.getString().equals(name2.getString())) {
Node thenExpr = thenAssign.getLastChild().detachFromParent();
Node elseExpr = name2.removeChildren();
cond.detachFromParent();
Node hookNode = IR.hook(cond, thenExpr, elseExpr)
.srcref(n);
var.detachFromParent();
name2.addChildrenToBack(hookNode);
parent.replaceChild(n, var);
reportCodeChange();
return var;
}
}
return n;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
4 | 873d68c40806c621dec9d27a79fc106aa62ec5746c066c57d8a6dd11efb01d18 | private void checkRequiredOptions()
throws MissingOptionException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Throws a {@link MissingOptionException} if all of the
* required options are no present.</p>
*
* @throws MissingOptionException if any of the required Options
* are not present.
*/
private void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (requiredOptions.size() > 0)
{
Iterator iter = requiredOptions.iterator();
StringBuffer buff = new StringBuffer("Missing required option");
buff.append(requiredOptions.size() == 1 ? "" : "s");
buff.append(": ");
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
}
throw new MissingOptionException(buff.toString());
}
}
```
| private void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (requiredOptions.size() > 0)
{
Iterator iter = requiredOptions.iterator();
StringBuffer buff = new StringBuffer("Missing required option");
buff.append(requiredOptions.size() == 1 ? "" : "s");
buff.append(": ");
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
}
throw new MissingOptionException(buff.toString());
}
} | false | Cli | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Throws a {@link MissingOptionException} if all of the
* required options are no present.</p>
*
* @throws MissingOptionException if any of the required Options
* are not present.
*/
private void checkRequiredOptions()
throws MissingOptionException
{
// if there are required options that have not been
// processsed
if (requiredOptions.size() > 0)
{
Iterator iter = requiredOptions.iterator();
StringBuffer buff = new StringBuffer("Missing required option");
buff.append(requiredOptions.size() == 1 ? "" : "s");
buff.append(": ");
// loop through the required options
while (iter.hasNext())
{
buff.append(iter.next());
}
throw new MissingOptionException(buff.toString());
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
52 | 879749941d5f5e2775ef7982fa06035b336bdd1a6466edb764350813ede3065e | static boolean isSimpleNumber(String s) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
static boolean isSimpleNumber(String s) {
int len = s.length();
for (int index = 0; index < len; index++) {
char c = s.charAt(index);
if (c < '0' || c > '9') {
return false;
}
}
return len > 0;
}
```
| static boolean isSimpleNumber(String s) {
int len = s.length();
for (int index = 0; index < len; index++) {
char c = s.charAt(index);
if (c < '0' || c > '9') {
return false;
}
}
return len > 0;
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
static boolean isSimpleNumber(String s) {
int len = s.length();
for (int index = 0; index < len; index++) {
char c = s.charAt(index);
if (c < '0' || c > '9') {
return false;
}
}
return len > 0;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
18 | 87a46d4ab3cdb120787082e20e8280d6e9ef6a7de7733698fcae9db85d26a928 | static Type getSupertype(Type context, Class<?> contextRawType, Class<?> supertype) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the generic form of {@code supertype}. For example, if this is {@code
* ArrayList<String>}, this returns {@code Iterable<String>} given the input {@code
* Iterable.class}.
*
* @param supertype a superclass of, or interface implemented by, this.
*/
static Type getSupertype(Type context, Class<?> contextRawType, Class<?> supertype) {
if (context instanceof WildcardType) {
// wildcards are useless for resolving supertypes. As the upper bound has the same raw type, use it instead
context = ((WildcardType)context).getUpperBounds()[0];
}
checkArgument(supertype.isAssignableFrom(contextRawType));
return resolve(context, contextRawType,
$Gson$Types.getGenericSupertype(context, contextRawType, supertype));
}
```
| static Type getSupertype(Type context, Class<?> contextRawType, Class<?> supertype) {
if (context instanceof WildcardType) {
// wildcards are useless for resolving supertypes. As the upper bound has the same raw type, use it instead
context = ((WildcardType)context).getUpperBounds()[0];
}
checkArgument(supertype.isAssignableFrom(contextRawType));
return resolve(context, contextRawType,
$Gson$Types.getGenericSupertype(context, contextRawType, supertype));
} | false | Gson | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the generic form of {@code supertype}. For example, if this is {@code
* ArrayList<String>}, this returns {@code Iterable<String>} given the input {@code
* Iterable.class}.
*
* @param supertype a superclass of, or interface implemented by, this.
*/
static Type getSupertype(Type context, Class<?> contextRawType, Class<?> supertype) {
if (context instanceof WildcardType) {
// wildcards are useless for resolving supertypes. As the upper bound has the same raw type, use it instead
context = ((WildcardType)context).getUpperBounds()[0];
}
checkArgument(supertype.isAssignableFrom(contextRawType));
return resolve(context, contextRawType,
$Gson$Types.getGenericSupertype(context, contextRawType, supertype));
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
33 | 882cccbaafb786240a39699117f1f4aafe195573a0da3d46d8c4fcb4b16085b3 | public boolean hasSameMethod(Invocation candidate) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public boolean hasSameMethod(Invocation candidate) {
//not using method.equals() for 1 good reason:
//sometimes java generates forwarding methods when generics are in play see JavaGenericsForwardingMethodsTest
Method m1 = invocation.getMethod();
Method m2 = candidate.getMethod();
/* Avoid unnecessary cloning */
return m1.equals(m2);
}
```
| public boolean hasSameMethod(Invocation candidate) {
//not using method.equals() for 1 good reason:
//sometimes java generates forwarding methods when generics are in play see JavaGenericsForwardingMethodsTest
Method m1 = invocation.getMethod();
Method m2 = candidate.getMethod();
/* Avoid unnecessary cloning */
return m1.equals(m2);
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public boolean hasSameMethod(Invocation candidate) {
//not using method.equals() for 1 good reason:
//sometimes java generates forwarding methods when generics are in play see JavaGenericsForwardingMethodsTest
Method m1 = invocation.getMethod();
Method m2 = candidate.getMethod();
/* Avoid unnecessary cloning */
return m1.equals(m2);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
53 | 88b38a56755aebef00d63aecf80e6b568f5f8c35f110cd48bd0b5ff8589bdee4 | private void replaceAssignmentExpression(Var v, Reference ref,
Map<String, String> varmap) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Replaces an assignment like x = {...} with t1=a,t2=b,t3=c,true.
* Note that the resulting expression will always evaluate to
* true, as would the x = {...} expression.
*/
private void replaceAssignmentExpression(Var v, Reference ref,
Map<String, String> varmap) {
// Compute all of the assignments necessary
List<Node> nodes = Lists.newArrayList();
Node val = ref.getAssignedValue();
blacklistVarReferencesInTree(val, v.scope);
Preconditions.checkState(val.getType() == Token.OBJECTLIT);
Set<String> all = Sets.newLinkedHashSet(varmap.keySet());
for (Node key = val.getFirstChild(); key != null;
key = key.getNext()) {
String var = key.getString();
Node value = key.removeFirstChild();
// TODO(user): Copy type information.
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)), value));
all.remove(var);
}
// TODO(user): Better source information.
for (String var : all) {
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)),
NodeUtil.newUndefinedNode(null)));
}
Node replacement;
// All assignments evaluate to true, so make sure that the
// expr statement evaluates to true in case it matters.
nodes.add(new Node(Token.TRUE));
// Join these using COMMA. A COMMA node must have 2 children, so we
// create a tree. In the tree the first child be the COMMA to match
// the parser, otherwise tree equality tests fail.
nodes = Lists.reverse(nodes);
replacement = new Node(Token.COMMA);
Node cur = replacement;
int i;
for (i = 0; i < nodes.size() - 2; i++) {
cur.addChildToFront(nodes.get(i));
Node t = new Node(Token.COMMA);
cur.addChildToFront(t);
cur = t;
}
cur.addChildToFront(nodes.get(i));
cur.addChildToFront(nodes.get(i + 1));
Node replace = ref.getParent();
replacement.copyInformationFromForTree(replace);
if (replace.getType() == Token.VAR) {
replace.getParent().replaceChild(
replace, NodeUtil.newExpr(replacement));
} else {
replace.getParent().replaceChild(replace, replacement);
}
}
```
| private void replaceAssignmentExpression(Var v, Reference ref,
Map<String, String> varmap) {
// Compute all of the assignments necessary
List<Node> nodes = Lists.newArrayList();
Node val = ref.getAssignedValue();
blacklistVarReferencesInTree(val, v.scope);
Preconditions.checkState(val.getType() == Token.OBJECTLIT);
Set<String> all = Sets.newLinkedHashSet(varmap.keySet());
for (Node key = val.getFirstChild(); key != null;
key = key.getNext()) {
String var = key.getString();
Node value = key.removeFirstChild();
// TODO(user): Copy type information.
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)), value));
all.remove(var);
}
// TODO(user): Better source information.
for (String var : all) {
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)),
NodeUtil.newUndefinedNode(null)));
}
Node replacement;
// All assignments evaluate to true, so make sure that the
// expr statement evaluates to true in case it matters.
nodes.add(new Node(Token.TRUE));
// Join these using COMMA. A COMMA node must have 2 children, so we
// create a tree. In the tree the first child be the COMMA to match
// the parser, otherwise tree equality tests fail.
nodes = Lists.reverse(nodes);
replacement = new Node(Token.COMMA);
Node cur = replacement;
int i;
for (i = 0; i < nodes.size() - 2; i++) {
cur.addChildToFront(nodes.get(i));
Node t = new Node(Token.COMMA);
cur.addChildToFront(t);
cur = t;
}
cur.addChildToFront(nodes.get(i));
cur.addChildToFront(nodes.get(i + 1));
Node replace = ref.getParent();
replacement.copyInformationFromForTree(replace);
if (replace.getType() == Token.VAR) {
replace.getParent().replaceChild(
replace, NodeUtil.newExpr(replacement));
} else {
replace.getParent().replaceChild(replace, replacement);
}
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Replaces an assignment like x = {...} with t1=a,t2=b,t3=c,true.
* Note that the resulting expression will always evaluate to
* true, as would the x = {...} expression.
*/
private void replaceAssignmentExpression(Var v, Reference ref,
Map<String, String> varmap) {
// Compute all of the assignments necessary
List<Node> nodes = Lists.newArrayList();
Node val = ref.getAssignedValue();
blacklistVarReferencesInTree(val, v.scope);
Preconditions.checkState(val.getType() == Token.OBJECTLIT);
Set<String> all = Sets.newLinkedHashSet(varmap.keySet());
for (Node key = val.getFirstChild(); key != null;
key = key.getNext()) {
String var = key.getString();
Node value = key.removeFirstChild();
// TODO(user): Copy type information.
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)), value));
all.remove(var);
}
// TODO(user): Better source information.
for (String var : all) {
nodes.add(
new Node(Token.ASSIGN,
Node.newString(Token.NAME, varmap.get(var)),
NodeUtil.newUndefinedNode(null)));
}
Node replacement;
// All assignments evaluate to true, so make sure that the
// expr statement evaluates to true in case it matters.
nodes.add(new Node(Token.TRUE));
// Join these using COMMA. A COMMA node must have 2 children, so we
// create a tree. In the tree the first child be the COMMA to match
// the parser, otherwise tree equality tests fail.
nodes = Lists.reverse(nodes);
replacement = new Node(Token.COMMA);
Node cur = replacement;
int i;
for (i = 0; i < nodes.size() - 2; i++) {
cur.addChildToFront(nodes.get(i));
Node t = new Node(Token.COMMA);
cur.addChildToFront(t);
cur = t;
}
cur.addChildToFront(nodes.get(i));
cur.addChildToFront(nodes.get(i + 1));
Node replace = ref.getParent();
replacement.copyInformationFromForTree(replace);
if (replace.getType() == Token.VAR) {
replace.getParent().replaceChild(
replace, NodeUtil.newExpr(replacement));
} else {
replace.getParent().replaceChild(replace, replacement);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
11 | 892a2ee030c264892a6f3b37eb0e2e0970dacabb162fdd44d0400fd6aec0bd59 | public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Creates a random string based on a variety of options, using
* supplied source of randomness.</p>
*
* <p>If start and end are both {@code 0}, start and end are set
* to {@code ' '} and {@code 'z'}, the ASCII printable
* characters, will be used, unless letters and numbers are both
* {@code false}, in which case, start and end are set to
* {@code 0} and {@code Integer.MAX_VALUE}.
*
* <p>If set is not {@code null}, characters between start and
* end are chosen.</p>
*
* <p>This method accepts a user-supplied {@link Random}
* instance to use as a source of randomness. By seeding a single
* {@link Random} instance with a fixed seed and using it for each call,
* the same random sequence of strings can be generated repeatedly
* and predictably.</p>
*
* @param count the length of random string to create
* @param start the position in set of chars to start at
* @param end the position in set of chars to end before
* @param letters only allow letters?
* @param numbers only allow numbers?
* @param chars the set of chars to choose randoms from, must not be empty.
* If {@code null}, then it will use the set of all chars.
* @param random a source of randomness.
* @return the random string
* @throws ArrayIndexOutOfBoundsException if there are not
* {@code (end - start) + 1} characters in the set array.
* @throws IllegalArgumentException if {@code count} < 0 or the provided chars array is empty.
* @since 2.0
*/
public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
} else {
if (end <= start) {
throw new IllegalArgumentException("Parameter end (" + end + ") must be greater than start (" + start + ")");
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
}
```
| public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
} else {
if (end <= start) {
throw new IllegalArgumentException("Parameter end (" + end + ") must be greater than start (" + start + ")");
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Creates a random string based on a variety of options, using
* supplied source of randomness.</p>
*
* <p>If start and end are both {@code 0}, start and end are set
* to {@code ' '} and {@code 'z'}, the ASCII printable
* characters, will be used, unless letters and numbers are both
* {@code false}, in which case, start and end are set to
* {@code 0} and {@code Integer.MAX_VALUE}.
*
* <p>If set is not {@code null}, characters between start and
* end are chosen.</p>
*
* <p>This method accepts a user-supplied {@link Random}
* instance to use as a source of randomness. By seeding a single
* {@link Random} instance with a fixed seed and using it for each call,
* the same random sequence of strings can be generated repeatedly
* and predictably.</p>
*
* @param count the length of random string to create
* @param start the position in set of chars to start at
* @param end the position in set of chars to end before
* @param letters only allow letters?
* @param numbers only allow numbers?
* @param chars the set of chars to choose randoms from, must not be empty.
* If {@code null}, then it will use the set of all chars.
* @param random a source of randomness.
* @return the random string
* @throws ArrayIndexOutOfBoundsException if there are not
* {@code (end - start) + 1} characters in the set array.
* @throws IllegalArgumentException if {@code count} < 0 or the provided chars array is empty.
* @since 2.0
*/
public static String random(int count, int start, int end, boolean letters, boolean numbers,
char[] chars, Random random) {
if (count == 0) {
return "";
} else if (count < 0) {
throw new IllegalArgumentException("Requested random string length " + count + " is less than 0.");
}
if (chars != null && chars.length == 0) {
throw new IllegalArgumentException("The chars array must not be empty");
}
if (start == 0 && end == 0) {
if (chars != null) {
end = chars.length;
} else {
if (!letters && !numbers) {
end = Integer.MAX_VALUE;
} else {
end = 'z' + 1;
start = ' ';
}
}
} else {
if (end <= start) {
throw new IllegalArgumentException("Parameter end (" + end + ") must be greater than start (" + start + ")");
}
}
char[] buffer = new char[count];
int gap = end - start;
while (count-- != 0) {
char ch;
if (chars == null) {
ch = (char) (random.nextInt(gap) + start);
} else {
ch = chars[random.nextInt(gap) + start];
}
if (letters && Character.isLetter(ch)
|| numbers && Character.isDigit(ch)
|| !letters && !numbers) {
if(ch >= 56320 && ch <= 57343) {
if(count == 0) {
count++;
} else {
// low surrogate, insert high surrogate after putting it in
buffer[count] = ch;
count--;
buffer[count] = (char) (55296 + random.nextInt(128));
}
} else if(ch >= 55296 && ch <= 56191) {
if(count == 0) {
count++;
} else {
// high surrogate, insert low surrogate before putting it in
buffer[count] = (char) (56320 + random.nextInt(128));
count--;
buffer[count] = ch;
}
} else if(ch >= 56192 && ch <= 56319) {
// private high surrogate, no effing clue, so skip it
count++;
} else {
buffer[count] = ch;
}
} else {
count++;
}
}
return new String(buffer);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
82 | 892c0822caf538a32185cad73d9e7b5d3272bba7dea7789e77b47d588b9a6876 | private Integer getPivotRow(final int col, final SimplexTableau tableau) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns the row with the minimum ratio as given by the minimum ratio test (MRT).
* @param tableau simple tableau for the problem
* @param col the column to test the ratio of. See {@link #getPivotColumn(SimplexTableau)}
* @return row with the minimum ratio
*/
private Integer getPivotRow(final int col, final SimplexTableau tableau) {
double minRatio = Double.MAX_VALUE;
Integer minRatioPos = null;
for (int i = tableau.getNumObjectiveFunctions(); i < tableau.getHeight(); i++) {
final double rhs = tableau.getEntry(i, tableau.getWidth() - 1);
final double entry = tableau.getEntry(i, col);
if (MathUtils.compareTo(entry, 0, epsilon) >= 0) {
final double ratio = rhs / entry;
if (ratio < minRatio) {
minRatio = ratio;
minRatioPos = i;
}
}
}
return minRatioPos;
}
```
| private Integer getPivotRow(final int col, final SimplexTableau tableau) {
double minRatio = Double.MAX_VALUE;
Integer minRatioPos = null;
for (int i = tableau.getNumObjectiveFunctions(); i < tableau.getHeight(); i++) {
final double rhs = tableau.getEntry(i, tableau.getWidth() - 1);
final double entry = tableau.getEntry(i, col);
if (MathUtils.compareTo(entry, 0, epsilon) >= 0) {
final double ratio = rhs / entry;
if (ratio < minRatio) {
minRatio = ratio;
minRatioPos = i;
}
}
}
return minRatioPos;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns the row with the minimum ratio as given by the minimum ratio test (MRT).
* @param tableau simple tableau for the problem
* @param col the column to test the ratio of. See {@link #getPivotColumn(SimplexTableau)}
* @return row with the minimum ratio
*/
private Integer getPivotRow(final int col, final SimplexTableau tableau) {
double minRatio = Double.MAX_VALUE;
Integer minRatioPos = null;
for (int i = tableau.getNumObjectiveFunctions(); i < tableau.getHeight(); i++) {
final double rhs = tableau.getEntry(i, tableau.getWidth() - 1);
final double entry = tableau.getEntry(i, col);
if (MathUtils.compareTo(entry, 0, epsilon) >= 0) {
final double ratio = rhs / entry;
if (ratio < minRatio) {
minRatio = ratio;
minRatioPos = i;
}
}
}
return minRatioPos;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
45 | 89497540798f13b39402e837d3c935bdd31b7c986c898fa324d82230d7c55c50 | void resetInsertionMode() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
void resetInsertionMode() {
boolean last = false;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element node = stack.get(pos);
if (pos == 0) {
last = true;
node = contextElement;
}
String name = node.nodeName();
if ("select".equals(name)) {
transition(HtmlTreeBuilderState.InSelect);
break; // frag
} else if (("td".equals(name) || "td".equals(name) && !last)) {
transition(HtmlTreeBuilderState.InCell);
break;
} else if ("tr".equals(name)) {
transition(HtmlTreeBuilderState.InRow);
break;
} else if ("tbody".equals(name) || "thead".equals(name) || "tfoot".equals(name)) {
transition(HtmlTreeBuilderState.InTableBody);
break;
} else if ("caption".equals(name)) {
transition(HtmlTreeBuilderState.InCaption);
break;
} else if ("colgroup".equals(name)) {
transition(HtmlTreeBuilderState.InColumnGroup);
break; // frag
} else if ("table".equals(name)) {
transition(HtmlTreeBuilderState.InTable);
break;
} else if ("head".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
} else if ("body".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break;
} else if ("frameset".equals(name)) {
transition(HtmlTreeBuilderState.InFrameset);
break; // frag
} else if ("html".equals(name)) {
transition(HtmlTreeBuilderState.BeforeHead);
break; // frag
} else if (last) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
}
}
}
```
| void resetInsertionMode() {
boolean last = false;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element node = stack.get(pos);
if (pos == 0) {
last = true;
node = contextElement;
}
String name = node.nodeName();
if ("select".equals(name)) {
transition(HtmlTreeBuilderState.InSelect);
break; // frag
} else if (("td".equals(name) || "td".equals(name) && !last)) {
transition(HtmlTreeBuilderState.InCell);
break;
} else if ("tr".equals(name)) {
transition(HtmlTreeBuilderState.InRow);
break;
} else if ("tbody".equals(name) || "thead".equals(name) || "tfoot".equals(name)) {
transition(HtmlTreeBuilderState.InTableBody);
break;
} else if ("caption".equals(name)) {
transition(HtmlTreeBuilderState.InCaption);
break;
} else if ("colgroup".equals(name)) {
transition(HtmlTreeBuilderState.InColumnGroup);
break; // frag
} else if ("table".equals(name)) {
transition(HtmlTreeBuilderState.InTable);
break;
} else if ("head".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
} else if ("body".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break;
} else if ("frameset".equals(name)) {
transition(HtmlTreeBuilderState.InFrameset);
break; // frag
} else if ("html".equals(name)) {
transition(HtmlTreeBuilderState.BeforeHead);
break; // frag
} else if (last) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
}
}
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
void resetInsertionMode() {
boolean last = false;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element node = stack.get(pos);
if (pos == 0) {
last = true;
node = contextElement;
}
String name = node.nodeName();
if ("select".equals(name)) {
transition(HtmlTreeBuilderState.InSelect);
break; // frag
} else if (("td".equals(name) || "td".equals(name) && !last)) {
transition(HtmlTreeBuilderState.InCell);
break;
} else if ("tr".equals(name)) {
transition(HtmlTreeBuilderState.InRow);
break;
} else if ("tbody".equals(name) || "thead".equals(name) || "tfoot".equals(name)) {
transition(HtmlTreeBuilderState.InTableBody);
break;
} else if ("caption".equals(name)) {
transition(HtmlTreeBuilderState.InCaption);
break;
} else if ("colgroup".equals(name)) {
transition(HtmlTreeBuilderState.InColumnGroup);
break; // frag
} else if ("table".equals(name)) {
transition(HtmlTreeBuilderState.InTable);
break;
} else if ("head".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
} else if ("body".equals(name)) {
transition(HtmlTreeBuilderState.InBody);
break;
} else if ("frameset".equals(name)) {
transition(HtmlTreeBuilderState.InFrameset);
break; // frag
} else if ("html".equals(name)) {
transition(HtmlTreeBuilderState.BeforeHead);
break; // frag
} else if (last) {
transition(HtmlTreeBuilderState.InBody);
break; // frag
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
32 | 896ad50e86d877ae9081f13637a1037b0d5139149b663b9cb78b046808e59b7d | private void applyPaxHeadersToCurrentEntry(Map<String, String> headers) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private void applyPaxHeadersToCurrentEntry(Map<String, String> headers) {
/*
* The following headers are defined for Pax.
* atime, ctime, charset: cannot use these without changing TarArchiveEntry fields
* mtime
* comment
* gid, gname
* linkpath
* size
* uid,uname
* SCHILY.devminor, SCHILY.devmajor: don't have setters/getters for those
*/
for (Entry<String, String> ent : headers.entrySet()){
String key = ent.getKey();
String val = ent.getValue();
if ("path".equals(key)){
currEntry.setName(val);
} else if ("linkpath".equals(key)){
currEntry.setLinkName(val);
} else if ("gid".equals(key)){
currEntry.setGroupId(Long.parseLong(val));
} else if ("gname".equals(key)){
currEntry.setGroupName(val);
} else if ("uid".equals(key)){
currEntry.setUserId(Long.parseLong(val));
} else if ("uname".equals(key)){
currEntry.setUserName(val);
} else if ("size".equals(key)){
currEntry.setSize(Long.parseLong(val));
} else if ("mtime".equals(key)){
currEntry.setModTime((long) (Double.parseDouble(val) * 1000));
} else if ("SCHILY.devminor".equals(key)){
currEntry.setDevMinor(Integer.parseInt(val));
} else if ("SCHILY.devmajor".equals(key)){
currEntry.setDevMajor(Integer.parseInt(val));
}
}
}
```
| private void applyPaxHeadersToCurrentEntry(Map<String, String> headers) {
/*
* The following headers are defined for Pax.
* atime, ctime, charset: cannot use these without changing TarArchiveEntry fields
* mtime
* comment
* gid, gname
* linkpath
* size
* uid,uname
* SCHILY.devminor, SCHILY.devmajor: don't have setters/getters for those
*/
for (Entry<String, String> ent : headers.entrySet()){
String key = ent.getKey();
String val = ent.getValue();
if ("path".equals(key)){
currEntry.setName(val);
} else if ("linkpath".equals(key)){
currEntry.setLinkName(val);
} else if ("gid".equals(key)){
currEntry.setGroupId(Long.parseLong(val));
} else if ("gname".equals(key)){
currEntry.setGroupName(val);
} else if ("uid".equals(key)){
currEntry.setUserId(Long.parseLong(val));
} else if ("uname".equals(key)){
currEntry.setUserName(val);
} else if ("size".equals(key)){
currEntry.setSize(Long.parseLong(val));
} else if ("mtime".equals(key)){
currEntry.setModTime((long) (Double.parseDouble(val) * 1000));
} else if ("SCHILY.devminor".equals(key)){
currEntry.setDevMinor(Integer.parseInt(val));
} else if ("SCHILY.devmajor".equals(key)){
currEntry.setDevMajor(Integer.parseInt(val));
}
}
} | false | Compress | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private void applyPaxHeadersToCurrentEntry(Map<String, String> headers) {
/*
* The following headers are defined for Pax.
* atime, ctime, charset: cannot use these without changing TarArchiveEntry fields
* mtime
* comment
* gid, gname
* linkpath
* size
* uid,uname
* SCHILY.devminor, SCHILY.devmajor: don't have setters/getters for those
*/
for (Entry<String, String> ent : headers.entrySet()){
String key = ent.getKey();
String val = ent.getValue();
if ("path".equals(key)){
currEntry.setName(val);
} else if ("linkpath".equals(key)){
currEntry.setLinkName(val);
} else if ("gid".equals(key)){
currEntry.setGroupId(Long.parseLong(val));
} else if ("gname".equals(key)){
currEntry.setGroupName(val);
} else if ("uid".equals(key)){
currEntry.setUserId(Long.parseLong(val));
} else if ("uname".equals(key)){
currEntry.setUserName(val);
} else if ("size".equals(key)){
currEntry.setSize(Long.parseLong(val));
} else if ("mtime".equals(key)){
currEntry.setModTime((long) (Double.parseDouble(val) * 1000));
} else if ("SCHILY.devminor".equals(key)){
currEntry.setDevMinor(Integer.parseInt(val));
} else if ("SCHILY.devmajor".equals(key)){
currEntry.setDevMajor(Integer.parseInt(val));
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
39 | 8a05f9993c0d12380a52b3a4c397e4b6670b5a3050718f5e507d6e43bdc5df3b | private static String replaceEach(String text, String[] searchList, String[] replacementList,
boolean repeat, int timeToLive)
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>
* Replaces all occurrences of Strings within another String.
* </p>
*
* <p>
* A <code>null</code> reference passed to this method is a no-op, or if
* any "search string" or "string to replace" is null, that replace will be
* ignored.
* </p>
*
* <pre>
* StringUtils.replaceEach(null, *, *, *) = null
* StringUtils.replaceEach("", *, *, *) = ""
* StringUtils.replaceEach("aba", null, null, *) = "aba"
* StringUtils.replaceEach("aba", new String[0], null, *) = "aba"
* StringUtils.replaceEach("aba", null, new String[0], *) = "aba"
* StringUtils.replaceEach("aba", new String[]{"a"}, null, *) = "aba"
* StringUtils.replaceEach("aba", new String[]{"a"}, new String[]{""}, *) = "b"
* StringUtils.replaceEach("aba", new String[]{null}, new String[]{"a"}, *) = "aba"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"w", "t"}, *) = "wcte"
* (example of how it repeats)
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, false) = "dcte"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, true) = "tcte"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "ab"}, *) = IllegalArgumentException
* </pre>
*
* @param text
* text to search and replace in, no-op if null
* @param searchList
* the Strings to search for, no-op if null
* @param replacementList
* the Strings to replace them with, no-op if null
* @param repeat if true, then replace repeatedly
* until there are no more possible replacements or timeToLive < 0
* @param timeToLive
* if less than 0 then there is a circular reference and endless
* loop
* @return the text with any replacements processed, <code>null</code> if
* null String input
* @throws IllegalArgumentException
* if the search is repeating and there is an endless loop due
* to outputs of one being inputs to another
* @throws IndexOutOfBoundsException
* if the lengths of the arrays are not the same (null is ok,
* and/or size 0)
* @since 2.4
*/
private static String replaceEach(String text, String[] searchList, String[] replacementList,
boolean repeat, int timeToLive)
{
// mchyzer Performance note: This creates very few new objects (one major goal)
// let me know if there are performance requests, we can create a harness to measure
if (text == null || text.length() == 0 || searchList == null ||
searchList.length == 0 || replacementList == null || replacementList.length == 0)
{
return text;
}
// if recursing, this shouldnt be less than 0
if (timeToLive < 0) {
throw new IllegalStateException("TimeToLive of " + timeToLive + " is less than 0: " + text);
}
int searchLength = searchList.length;
int replacementLength = replacementList.length;
// make sure lengths are ok, these need to be equal
if (searchLength != replacementLength) {
throw new IllegalArgumentException("Search and Replace array lengths don't match: "
+ searchLength
+ " vs "
+ replacementLength);
}
// keep track of which still have matches
boolean[] noMoreMatchesForReplIndex = new boolean[searchLength];
// index on index that the match was found
int textIndex = -1;
int replaceIndex = -1;
int tempIndex = -1;
// index of replace array that will replace the search string found
// NOTE: logic duplicated below START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i]);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic mostly below END
// no search strings found, we are done
if (textIndex == -1) {
return text;
}
int start = 0;
// get a good guess on the size of the result buffer so it doesnt have to double if it goes over a bit
int increase = 0;
// count the replacement text elements that are larger than their corresponding text being replaced
for (int i = 0; i < searchList.length; i++) {
if (searchList[i] == null || replacementList[i] == null) {
continue;
}
int greater = replacementList[i].length() - searchList[i].length();
if (greater > 0) {
increase += 3 * greater; // assume 3 matches
}
}
// have upper-bound at 20% increase, then let Java take over
increase = Math.min(increase, text.length() / 5);
StringBuilder buf = new StringBuilder(text.length() + increase);
while (textIndex != -1) {
for (int i = start; i < textIndex; i++) {
buf.append(text.charAt(i));
}
buf.append(replacementList[replaceIndex]);
start = textIndex + searchList[replaceIndex].length();
textIndex = -1;
replaceIndex = -1;
tempIndex = -1;
// find the next earliest match
// NOTE: logic mostly duplicated above START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i], start);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic duplicated above END
}
int textLength = text.length();
for (int i = start; i < textLength; i++) {
buf.append(text.charAt(i));
}
String result = buf.toString();
if (!repeat) {
return result;
}
return replaceEach(result, searchList, replacementList, repeat, timeToLive - 1);
}
```
| private static String replaceEach(String text, String[] searchList, String[] replacementList,
boolean repeat, int timeToLive)
{
// mchyzer Performance note: This creates very few new objects (one major goal)
// let me know if there are performance requests, we can create a harness to measure
if (text == null || text.length() == 0 || searchList == null ||
searchList.length == 0 || replacementList == null || replacementList.length == 0)
{
return text;
}
// if recursing, this shouldnt be less than 0
if (timeToLive < 0) {
throw new IllegalStateException("TimeToLive of " + timeToLive + " is less than 0: " + text);
}
int searchLength = searchList.length;
int replacementLength = replacementList.length;
// make sure lengths are ok, these need to be equal
if (searchLength != replacementLength) {
throw new IllegalArgumentException("Search and Replace array lengths don't match: "
+ searchLength
+ " vs "
+ replacementLength);
}
// keep track of which still have matches
boolean[] noMoreMatchesForReplIndex = new boolean[searchLength];
// index on index that the match was found
int textIndex = -1;
int replaceIndex = -1;
int tempIndex = -1;
// index of replace array that will replace the search string found
// NOTE: logic duplicated below START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i]);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic mostly below END
// no search strings found, we are done
if (textIndex == -1) {
return text;
}
int start = 0;
// get a good guess on the size of the result buffer so it doesnt have to double if it goes over a bit
int increase = 0;
// count the replacement text elements that are larger than their corresponding text being replaced
for (int i = 0; i < searchList.length; i++) {
if (searchList[i] == null || replacementList[i] == null) {
continue;
}
int greater = replacementList[i].length() - searchList[i].length();
if (greater > 0) {
increase += 3 * greater; // assume 3 matches
}
}
// have upper-bound at 20% increase, then let Java take over
increase = Math.min(increase, text.length() / 5);
StringBuilder buf = new StringBuilder(text.length() + increase);
while (textIndex != -1) {
for (int i = start; i < textIndex; i++) {
buf.append(text.charAt(i));
}
buf.append(replacementList[replaceIndex]);
start = textIndex + searchList[replaceIndex].length();
textIndex = -1;
replaceIndex = -1;
tempIndex = -1;
// find the next earliest match
// NOTE: logic mostly duplicated above START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i], start);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic duplicated above END
}
int textLength = text.length();
for (int i = start; i < textLength; i++) {
buf.append(text.charAt(i));
}
String result = buf.toString();
if (!repeat) {
return result;
}
return replaceEach(result, searchList, replacementList, repeat, timeToLive - 1);
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>
* Replaces all occurrences of Strings within another String.
* </p>
*
* <p>
* A <code>null</code> reference passed to this method is a no-op, or if
* any "search string" or "string to replace" is null, that replace will be
* ignored.
* </p>
*
* <pre>
* StringUtils.replaceEach(null, *, *, *) = null
* StringUtils.replaceEach("", *, *, *) = ""
* StringUtils.replaceEach("aba", null, null, *) = "aba"
* StringUtils.replaceEach("aba", new String[0], null, *) = "aba"
* StringUtils.replaceEach("aba", null, new String[0], *) = "aba"
* StringUtils.replaceEach("aba", new String[]{"a"}, null, *) = "aba"
* StringUtils.replaceEach("aba", new String[]{"a"}, new String[]{""}, *) = "b"
* StringUtils.replaceEach("aba", new String[]{null}, new String[]{"a"}, *) = "aba"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"w", "t"}, *) = "wcte"
* (example of how it repeats)
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, false) = "dcte"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, true) = "tcte"
* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "ab"}, *) = IllegalArgumentException
* </pre>
*
* @param text
* text to search and replace in, no-op if null
* @param searchList
* the Strings to search for, no-op if null
* @param replacementList
* the Strings to replace them with, no-op if null
* @param repeat if true, then replace repeatedly
* until there are no more possible replacements or timeToLive < 0
* @param timeToLive
* if less than 0 then there is a circular reference and endless
* loop
* @return the text with any replacements processed, <code>null</code> if
* null String input
* @throws IllegalArgumentException
* if the search is repeating and there is an endless loop due
* to outputs of one being inputs to another
* @throws IndexOutOfBoundsException
* if the lengths of the arrays are not the same (null is ok,
* and/or size 0)
* @since 2.4
*/
private static String replaceEach(String text, String[] searchList, String[] replacementList,
boolean repeat, int timeToLive)
{
// mchyzer Performance note: This creates very few new objects (one major goal)
// let me know if there are performance requests, we can create a harness to measure
if (text == null || text.length() == 0 || searchList == null ||
searchList.length == 0 || replacementList == null || replacementList.length == 0)
{
return text;
}
// if recursing, this shouldnt be less than 0
if (timeToLive < 0) {
throw new IllegalStateException("TimeToLive of " + timeToLive + " is less than 0: " + text);
}
int searchLength = searchList.length;
int replacementLength = replacementList.length;
// make sure lengths are ok, these need to be equal
if (searchLength != replacementLength) {
throw new IllegalArgumentException("Search and Replace array lengths don't match: "
+ searchLength
+ " vs "
+ replacementLength);
}
// keep track of which still have matches
boolean[] noMoreMatchesForReplIndex = new boolean[searchLength];
// index on index that the match was found
int textIndex = -1;
int replaceIndex = -1;
int tempIndex = -1;
// index of replace array that will replace the search string found
// NOTE: logic duplicated below START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i]);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic mostly below END
// no search strings found, we are done
if (textIndex == -1) {
return text;
}
int start = 0;
// get a good guess on the size of the result buffer so it doesnt have to double if it goes over a bit
int increase = 0;
// count the replacement text elements that are larger than their corresponding text being replaced
for (int i = 0; i < searchList.length; i++) {
if (searchList[i] == null || replacementList[i] == null) {
continue;
}
int greater = replacementList[i].length() - searchList[i].length();
if (greater > 0) {
increase += 3 * greater; // assume 3 matches
}
}
// have upper-bound at 20% increase, then let Java take over
increase = Math.min(increase, text.length() / 5);
StringBuilder buf = new StringBuilder(text.length() + increase);
while (textIndex != -1) {
for (int i = start; i < textIndex; i++) {
buf.append(text.charAt(i));
}
buf.append(replacementList[replaceIndex]);
start = textIndex + searchList[replaceIndex].length();
textIndex = -1;
replaceIndex = -1;
tempIndex = -1;
// find the next earliest match
// NOTE: logic mostly duplicated above START
for (int i = 0; i < searchLength; i++) {
if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
searchList[i].length() == 0 || replacementList[i] == null)
{
continue;
}
tempIndex = text.indexOf(searchList[i], start);
// see if we need to keep searching for this
if (tempIndex == -1) {
noMoreMatchesForReplIndex[i] = true;
} else {
if (textIndex == -1 || tempIndex < textIndex) {
textIndex = tempIndex;
replaceIndex = i;
}
}
}
// NOTE: logic duplicated above END
}
int textLength = text.length();
for (int i = start; i < textLength; i++) {
buf.append(text.charAt(i));
}
String result = buf.toString();
if (!repeat) {
return result;
}
return replaceEach(result, searchList, replacementList, repeat, timeToLive - 1);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
93 | 8a0aff371dc80a5194b257af925f8379a609fd822769bc41372c69d87f114908 | public List<Connection.KeyVal> formData() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Get the data that this form submits. The returned list is a copy of the data, and changes to the contents of the
* list will not be reflected in the DOM.
* @return a list of key vals
*/
public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
if (el.hasAttr("disabled")) continue; // skip disabled form inputs
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if (type.equalsIgnoreCase("button")) continue; // browsers don't submit these
if ("select".equals(el.normalName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val().length() > 0 ? el.val() : "on";
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
}
```
| public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
if (el.hasAttr("disabled")) continue; // skip disabled form inputs
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if (type.equalsIgnoreCase("button")) continue; // browsers don't submit these
if ("select".equals(el.normalName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val().length() > 0 ? el.val() : "on";
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Get the data that this form submits. The returned list is a copy of the data, and changes to the contents of the
* list will not be reflected in the DOM.
* @return a list of key vals
*/
public List<Connection.KeyVal> formData() {
ArrayList<Connection.KeyVal> data = new ArrayList<>();
// iterate the form control elements and accumulate their values
for (Element el: elements) {
if (!el.tag().isFormSubmittable()) continue; // contents are form listable, superset of submitable
if (el.hasAttr("disabled")) continue; // skip disabled form inputs
String name = el.attr("name");
if (name.length() == 0) continue;
String type = el.attr("type");
if (type.equalsIgnoreCase("button")) continue; // browsers don't submit these
if ("select".equals(el.normalName())) {
Elements options = el.select("option[selected]");
boolean set = false;
for (Element option: options) {
data.add(HttpConnection.KeyVal.create(name, option.val()));
set = true;
}
if (!set) {
Element option = el.select("option").first();
if (option != null)
data.add(HttpConnection.KeyVal.create(name, option.val()));
}
} else if ("checkbox".equalsIgnoreCase(type) || "radio".equalsIgnoreCase(type)) {
// only add checkbox or radio if they have the checked attribute
if (el.hasAttr("checked")) {
final String val = el.val().length() > 0 ? el.val() : "on";
data.add(HttpConnection.KeyVal.create(name, val));
}
} else {
data.add(HttpConnection.KeyVal.create(name, el.val()));
}
}
return data;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
50 | 8b311344074cc32768deb280c8813250c9374e67953a743c2d6da9d820abd07f | static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// todo - this is getting gnarly. needs a rewrite.
// switching the chartset midstream when a meta http-equiv tag defines the charset.
// reads bytes first into a buffer, then decodes with the appropriate charset. done this way to support
static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
// look for BOM - overrides any other header or input
byteData.mark();
byte[] bom = new byte[4];
byteData.get(bom);
byteData.rewind();
if (bom[0] == 0x00 && bom[1] == 0x00 && bom[2] == (byte) 0xFE && bom[3] == (byte) 0xFF || // BE
bom[0] == (byte) 0xFF && bom[1] == (byte) 0xFE && bom[2] == 0x00 && bom[3] == 0x00) { // LE
charsetName = "UTF-32"; // and I hope it's on your system
} else if (bom[0] == (byte) 0xFE && bom[1] == (byte) 0xFF || // BE
bom[0] == (byte) 0xFF && bom[1] == (byte) 0xFE) {
charsetName = "UTF-16"; // in all Javas
} else if (bom[0] == (byte) 0xEF && bom[1] == (byte) 0xBB && bom[2] == (byte) 0xBF) {
charsetName = "UTF-8"; // in all Javas
byteData.position(3); // 16 and 32 decoders consume the BOM to determine be/le; utf-8 should be consumed
}
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = null;
if (meta.hasAttr("http-equiv")) {
foundCharset = getCharsetFromContentType(meta.attr("content"));
}
if (foundCharset == null && meta.hasAttr("charset")) {
try {
if (Charset.isSupported(meta.attr("charset"))) {
foundCharset = meta.attr("charset");
}
} catch (IllegalCharsetNameException e) {
foundCharset = null;
}
}
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
}
```
| static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
// look for BOM - overrides any other header or input
byteData.mark();
byte[] bom = new byte[4];
byteData.get(bom);
byteData.rewind();
if (bom[0] == 0x00 && bom[1] == 0x00 && bom[2] == (byte) 0xFE && bom[3] == (byte) 0xFF || // BE
bom[0] == (byte) 0xFF && bom[1] == (byte) 0xFE && bom[2] == 0x00 && bom[3] == 0x00) { // LE
charsetName = "UTF-32"; // and I hope it's on your system
} else if (bom[0] == (byte) 0xFE && bom[1] == (byte) 0xFF || // BE
bom[0] == (byte) 0xFF && bom[1] == (byte) 0xFE) {
charsetName = "UTF-16"; // in all Javas
} else if (bom[0] == (byte) 0xEF && bom[1] == (byte) 0xBB && bom[2] == (byte) 0xBF) {
charsetName = "UTF-8"; // in all Javas
byteData.position(3); // 16 and 32 decoders consume the BOM to determine be/le; utf-8 should be consumed
}
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = null;
if (meta.hasAttr("http-equiv")) {
foundCharset = getCharsetFromContentType(meta.attr("content"));
}
if (foundCharset == null && meta.hasAttr("charset")) {
try {
if (Charset.isSupported(meta.attr("charset"))) {
foundCharset = meta.attr("charset");
}
} catch (IllegalCharsetNameException e) {
foundCharset = null;
}
}
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// todo - this is getting gnarly. needs a rewrite.
// switching the chartset midstream when a meta http-equiv tag defines the charset.
// reads bytes first into a buffer, then decodes with the appropriate charset. done this way to support
static Document parseByteData(ByteBuffer byteData, String charsetName, String baseUri, Parser parser) {
String docData;
Document doc = null;
// look for BOM - overrides any other header or input
byteData.mark();
byte[] bom = new byte[4];
byteData.get(bom);
byteData.rewind();
if (bom[0] == 0x00 && bom[1] == 0x00 && bom[2] == (byte) 0xFE && bom[3] == (byte) 0xFF || // BE
bom[0] == (byte) 0xFF && bom[1] == (byte) 0xFE && bom[2] == 0x00 && bom[3] == 0x00) { // LE
charsetName = "UTF-32"; // and I hope it's on your system
} else if (bom[0] == (byte) 0xFE && bom[1] == (byte) 0xFF || // BE
bom[0] == (byte) 0xFF && bom[1] == (byte) 0xFE) {
charsetName = "UTF-16"; // in all Javas
} else if (bom[0] == (byte) 0xEF && bom[1] == (byte) 0xBB && bom[2] == (byte) 0xBF) {
charsetName = "UTF-8"; // in all Javas
byteData.position(3); // 16 and 32 decoders consume the BOM to determine be/le; utf-8 should be consumed
}
if (charsetName == null) { // determine from meta. safe parse as UTF-8
// look for <meta http-equiv="Content-Type" content="text/html;charset=gb2312"> or HTML5 <meta charset="gb2312">
docData = Charset.forName(defaultCharset).decode(byteData).toString();
doc = parser.parseInput(docData, baseUri);
Element meta = doc.select("meta[http-equiv=content-type], meta[charset]").first();
if (meta != null) { // if not found, will keep utf-8 as best attempt
String foundCharset = null;
if (meta.hasAttr("http-equiv")) {
foundCharset = getCharsetFromContentType(meta.attr("content"));
}
if (foundCharset == null && meta.hasAttr("charset")) {
try {
if (Charset.isSupported(meta.attr("charset"))) {
foundCharset = meta.attr("charset");
}
} catch (IllegalCharsetNameException e) {
foundCharset = null;
}
}
if (foundCharset != null && foundCharset.length() != 0 && !foundCharset.equals(defaultCharset)) { // need to re-decode
foundCharset = foundCharset.trim().replaceAll("[\"']", "");
charsetName = foundCharset;
byteData.rewind();
docData = Charset.forName(foundCharset).decode(byteData).toString();
doc = null;
}
}
} else { // specified by content type header (or by user on file load)
Validate.notEmpty(charsetName, "Must set charset arg to character set of file to parse. Set to null to attempt to detect from HTML");
docData = Charset.forName(charsetName).decode(byteData).toString();
}
if (doc == null) {
doc = parser.parseInput(docData, baseUri);
doc.outputSettings().charset(charsetName);
}
return doc;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
5 | 8b45b7366f759524d46cb008f84767796f37e957108372db44fb9d7254a15052 | public void verify(VerificationData data) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Verify the given ongoing verification data, and confirm that it satisfies the delegate verification mode
* before the full duration has passed.
*
* In practice, this polls the delegate verification mode until it is satisfied. If it is not satisfied once
* the full duration has passed, the last error returned by the delegate verification mode will be thrown
* here in turn. This may be thrown early if the delegate is unsatisfied and the verification mode is known
* to never recover from this situation (e.g. {@link AtMost}).
*
* If it is satisfied before the full duration has passed, behaviour is dependent on the returnOnSuccess parameter
* given in the constructor. If true, this verification mode is immediately satisfied once the delegate is. If
* false, this verification mode is not satisfied until the delegate is satisfied and the full time has passed.
*
* @throws MockitoAssertionError if the delegate verification mode does not succeed before the timeout
*/
public void verify(VerificationData data) {
AssertionError error = null;
timer.start();
while (timer.isCounting()) {
try {
delegate.verify(data);
if (returnOnSuccess) {
return;
} else {
error = null;
}
} catch (MockitoAssertionError e) {
error = handleVerifyException(e);
}
catch (org.mockito.exceptions.verification.junit.ArgumentsAreDifferent e) {
error = handleVerifyException(e);
}
}
if (error != null) {
throw error;
}
}
```
| public void verify(VerificationData data) {
AssertionError error = null;
timer.start();
while (timer.isCounting()) {
try {
delegate.verify(data);
if (returnOnSuccess) {
return;
} else {
error = null;
}
} catch (MockitoAssertionError e) {
error = handleVerifyException(e);
}
catch (org.mockito.exceptions.verification.junit.ArgumentsAreDifferent e) {
error = handleVerifyException(e);
}
}
if (error != null) {
throw error;
}
} | true | Mockito | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Verify the given ongoing verification data, and confirm that it satisfies the delegate verification mode
* before the full duration has passed.
*
* In practice, this polls the delegate verification mode until it is satisfied. If it is not satisfied once
* the full duration has passed, the last error returned by the delegate verification mode will be thrown
* here in turn. This may be thrown early if the delegate is unsatisfied and the verification mode is known
* to never recover from this situation (e.g. {@link AtMost}).
*
* If it is satisfied before the full duration has passed, behaviour is dependent on the returnOnSuccess parameter
* given in the constructor. If true, this verification mode is immediately satisfied once the delegate is. If
* false, this verification mode is not satisfied until the delegate is satisfied and the full time has passed.
*
* @throws MockitoAssertionError if the delegate verification mode does not succeed before the timeout
*/
public void verify(VerificationData data) {
AssertionError error = null;
timer.start();
while (timer.isCounting()) {
try {
delegate.verify(data);
if (returnOnSuccess) {
return;
} else {
error = null;
}
} catch (MockitoAssertionError e) {
error = handleVerifyException(e);
}
catch (org.mockito.exceptions.verification.junit.ArgumentsAreDifferent e) {
error = handleVerifyException(e);
}
}
if (error != null) {
throw error;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
58 | 8c0b52160576c0c9279cf5b244a21fd3bc61577f56b5ca3753159b72f59ac5bf | protected SettableBeanProperty constructSettableProperty(DeserializationContext ctxt,
BeanDescription beanDesc, BeanPropertyDefinition propDef,
JavaType propType0)
throws JsonMappingException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Method that will construct a regular bean property setter using
* the given setter method.
*
* @return Property constructed, if any; or null to indicate that
* there should be no property based on given definitions.
*/
protected SettableBeanProperty constructSettableProperty(DeserializationContext ctxt,
BeanDescription beanDesc, BeanPropertyDefinition propDef,
JavaType propType0)
throws JsonMappingException
{
// need to ensure method is callable (for non-public)
AnnotatedMember mutator = propDef.getNonConstructorMutator();
if (ctxt.canOverrideAccessModifiers()) {
// [databind#877]: explicitly prevent forced access to `cause` of `Throwable`;
// never needed and attempts may cause problems on some platforms.
// !!! NOTE: should be handled better for 2.8 and later
if ((mutator instanceof AnnotatedField)
&& "cause".equals(mutator.getName())) {
;
} else {
mutator.fixAccess(ctxt.isEnabled(MapperFeature.OVERRIDE_PUBLIC_ACCESS_MODIFIERS));
}
}
// note: this works since we know there's exactly one argument for methods
BeanProperty.Std property = new BeanProperty.Std(propDef.getFullName(),
propType0, propDef.getWrapperName(),
beanDesc.getClassAnnotations(), mutator, propDef.getMetadata());
JavaType type = resolveType(ctxt, beanDesc, propType0, mutator);
// did type change?
if (type != propType0) {
property = property.withType(type);
}
// First: does the Method specify the deserializer to use? If so, let's use it.
JsonDeserializer<Object> propDeser = findDeserializerFromAnnotation(ctxt, mutator);
type = modifyTypeByAnnotation(ctxt, mutator, type);
TypeDeserializer typeDeser = type.getTypeHandler();
SettableBeanProperty prop;
if (mutator instanceof AnnotatedMethod) {
prop = new MethodProperty(propDef, type, typeDeser,
beanDesc.getClassAnnotations(), (AnnotatedMethod) mutator);
} else {
prop = new FieldProperty(propDef, type, typeDeser,
beanDesc.getClassAnnotations(), (AnnotatedField) mutator);
}
if (propDeser != null) {
prop = prop.withValueDeserializer(propDeser);
}
// need to retain name of managed forward references:
AnnotationIntrospector.ReferenceProperty ref = propDef.findReferenceType();
if (ref != null && ref.isManagedReference()) {
prop.setManagedReferenceName(ref.getName());
}
ObjectIdInfo objectIdInfo = propDef.findObjectIdInfo();
if(objectIdInfo != null){
prop.setObjectIdInfo(objectIdInfo);
}
return prop;
}
```
| protected SettableBeanProperty constructSettableProperty(DeserializationContext ctxt,
BeanDescription beanDesc, BeanPropertyDefinition propDef,
JavaType propType0)
throws JsonMappingException
{
// need to ensure method is callable (for non-public)
AnnotatedMember mutator = propDef.getNonConstructorMutator();
if (ctxt.canOverrideAccessModifiers()) {
// [databind#877]: explicitly prevent forced access to `cause` of `Throwable`;
// never needed and attempts may cause problems on some platforms.
// !!! NOTE: should be handled better for 2.8 and later
if ((mutator instanceof AnnotatedField)
&& "cause".equals(mutator.getName())) {
;
} else {
mutator.fixAccess(ctxt.isEnabled(MapperFeature.OVERRIDE_PUBLIC_ACCESS_MODIFIERS));
}
}
// note: this works since we know there's exactly one argument for methods
BeanProperty.Std property = new BeanProperty.Std(propDef.getFullName(),
propType0, propDef.getWrapperName(),
beanDesc.getClassAnnotations(), mutator, propDef.getMetadata());
JavaType type = resolveType(ctxt, beanDesc, propType0, mutator);
// did type change?
if (type != propType0) {
property = property.withType(type);
}
// First: does the Method specify the deserializer to use? If so, let's use it.
JsonDeserializer<Object> propDeser = findDeserializerFromAnnotation(ctxt, mutator);
type = modifyTypeByAnnotation(ctxt, mutator, type);
TypeDeserializer typeDeser = type.getTypeHandler();
SettableBeanProperty prop;
if (mutator instanceof AnnotatedMethod) {
prop = new MethodProperty(propDef, type, typeDeser,
beanDesc.getClassAnnotations(), (AnnotatedMethod) mutator);
} else {
prop = new FieldProperty(propDef, type, typeDeser,
beanDesc.getClassAnnotations(), (AnnotatedField) mutator);
}
if (propDeser != null) {
prop = prop.withValueDeserializer(propDeser);
}
// need to retain name of managed forward references:
AnnotationIntrospector.ReferenceProperty ref = propDef.findReferenceType();
if (ref != null && ref.isManagedReference()) {
prop.setManagedReferenceName(ref.getName());
}
ObjectIdInfo objectIdInfo = propDef.findObjectIdInfo();
if(objectIdInfo != null){
prop.setObjectIdInfo(objectIdInfo);
}
return prop;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Method that will construct a regular bean property setter using
* the given setter method.
*
* @return Property constructed, if any; or null to indicate that
* there should be no property based on given definitions.
*/
protected SettableBeanProperty constructSettableProperty(DeserializationContext ctxt,
BeanDescription beanDesc, BeanPropertyDefinition propDef,
JavaType propType0)
throws JsonMappingException
{
// need to ensure method is callable (for non-public)
AnnotatedMember mutator = propDef.getNonConstructorMutator();
if (ctxt.canOverrideAccessModifiers()) {
// [databind#877]: explicitly prevent forced access to `cause` of `Throwable`;
// never needed and attempts may cause problems on some platforms.
// !!! NOTE: should be handled better for 2.8 and later
if ((mutator instanceof AnnotatedField)
&& "cause".equals(mutator.getName())) {
;
} else {
mutator.fixAccess(ctxt.isEnabled(MapperFeature.OVERRIDE_PUBLIC_ACCESS_MODIFIERS));
}
}
// note: this works since we know there's exactly one argument for methods
BeanProperty.Std property = new BeanProperty.Std(propDef.getFullName(),
propType0, propDef.getWrapperName(),
beanDesc.getClassAnnotations(), mutator, propDef.getMetadata());
JavaType type = resolveType(ctxt, beanDesc, propType0, mutator);
// did type change?
if (type != propType0) {
property = property.withType(type);
}
// First: does the Method specify the deserializer to use? If so, let's use it.
JsonDeserializer<Object> propDeser = findDeserializerFromAnnotation(ctxt, mutator);
type = modifyTypeByAnnotation(ctxt, mutator, type);
TypeDeserializer typeDeser = type.getTypeHandler();
SettableBeanProperty prop;
if (mutator instanceof AnnotatedMethod) {
prop = new MethodProperty(propDef, type, typeDeser,
beanDesc.getClassAnnotations(), (AnnotatedMethod) mutator);
} else {
prop = new FieldProperty(propDef, type, typeDeser,
beanDesc.getClassAnnotations(), (AnnotatedField) mutator);
}
if (propDeser != null) {
prop = prop.withValueDeserializer(propDeser);
}
// need to retain name of managed forward references:
AnnotationIntrospector.ReferenceProperty ref = propDef.findReferenceType();
if (ref != null && ref.isManagedReference()) {
prop.setManagedReferenceName(ref.getName());
}
ObjectIdInfo objectIdInfo = propDef.findObjectIdInfo();
if(objectIdInfo != null){
prop.setObjectIdInfo(objectIdInfo);
}
return prop;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
69 | 8c76364e3f192b63399e4f4e0556f89fbbc2da12660dff233217b1ea689f4ff5 | public RealMatrix getCorrelationPValues() throws MathException | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Returns a matrix of p-values associated with the (two-sided) null
* hypothesis that the corresponding correlation coefficient is zero.
* <p><code>getCorrelationPValues().getEntry(i,j)</code> is the probability
* that a random variable distributed as <code>t<sub>n-2</sub></code> takes
* a value with absolute value greater than or equal to <br>
* <code>|r|((n - 2) / (1 - r<sup>2</sup>))<sup>1/2</sup></code></p>
* <p>The values in the matrix are sometimes referred to as the
* <i>significance</i> of the corresponding correlation coefficients.</p>
*
* @return matrix of p-values
* @throws MathException if an error occurs estimating probabilities
*/
public RealMatrix getCorrelationPValues() throws MathException {
TDistribution tDistribution = new TDistributionImpl(nObs - 2);
int nVars = correlationMatrix.getColumnDimension();
double[][] out = new double[nVars][nVars];
for (int i = 0; i < nVars; i++) {
for (int j = 0; j < nVars; j++) {
if (i == j) {
out[i][j] = 0d;
} else {
double r = correlationMatrix.getEntry(i, j);
double t = Math.abs(r * Math.sqrt((nObs - 2)/(1 - r * r)));
out[i][j] = 2 * (1 - tDistribution.cumulativeProbability(t));
}
}
}
return new BlockRealMatrix(out);
}
```
| public RealMatrix getCorrelationPValues() throws MathException {
TDistribution tDistribution = new TDistributionImpl(nObs - 2);
int nVars = correlationMatrix.getColumnDimension();
double[][] out = new double[nVars][nVars];
for (int i = 0; i < nVars; i++) {
for (int j = 0; j < nVars; j++) {
if (i == j) {
out[i][j] = 0d;
} else {
double r = correlationMatrix.getEntry(i, j);
double t = Math.abs(r * Math.sqrt((nObs - 2)/(1 - r * r)));
out[i][j] = 2 * (1 - tDistribution.cumulativeProbability(t));
}
}
}
return new BlockRealMatrix(out);
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Returns a matrix of p-values associated with the (two-sided) null
* hypothesis that the corresponding correlation coefficient is zero.
* <p><code>getCorrelationPValues().getEntry(i,j)</code> is the probability
* that a random variable distributed as <code>t<sub>n-2</sub></code> takes
* a value with absolute value greater than or equal to <br>
* <code>|r|((n - 2) / (1 - r<sup>2</sup>))<sup>1/2</sup></code></p>
* <p>The values in the matrix are sometimes referred to as the
* <i>significance</i> of the corresponding correlation coefficients.</p>
*
* @return matrix of p-values
* @throws MathException if an error occurs estimating probabilities
*/
public RealMatrix getCorrelationPValues() throws MathException {
TDistribution tDistribution = new TDistributionImpl(nObs - 2);
int nVars = correlationMatrix.getColumnDimension();
double[][] out = new double[nVars][nVars];
for (int i = 0; i < nVars; i++) {
for (int j = 0; j < nVars; j++) {
if (i == j) {
out[i][j] = 0d;
} else {
double r = correlationMatrix.getEntry(i, j);
double t = Math.abs(r * Math.sqrt((nObs - 2)/(1 - r * r)));
out[i][j] = 2 * (1 - tDistribution.cumulativeProbability(t));
}
}
}
return new BlockRealMatrix(out);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
43 | 8c7a218510f90fee411a3e0d3a8a96633769586caf9afd8c773e360d07895571 | private static <E extends Element> Integer indexInList(Element search, List<E> elements) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
private static <E extends Element> Integer indexInList(Element search, List<E> elements) {
Validate.notNull(search);
Validate.notNull(elements);
for (int i = 0; i < elements.size(); i++) {
E element = elements.get(i);
if (element.equals(search))
return i;
}
return null;
}
```
| private static <E extends Element> Integer indexInList(Element search, List<E> elements) {
Validate.notNull(search);
Validate.notNull(elements);
for (int i = 0; i < elements.size(); i++) {
E element = elements.get(i);
if (element.equals(search))
return i;
}
return null;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
private static <E extends Element> Integer indexInList(Element search, List<E> elements) {
Validate.notNull(search);
Validate.notNull(elements);
for (int i = 0; i < elements.size(); i++) {
E element = elements.get(i);
if (element.equals(search))
return i;
}
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
61 | 8c95f16f9745cfd23d568a3a768c2edcdd69460cbe8c86b7c76a5c2b6b487dbc | public boolean hasClass(String className) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// performance sensitive
/**
* Tests if this element has a class. Case insensitive.
* @param className name of class to check for
* @return true if it does, false if not
*/
public boolean hasClass(String className) {
final String classAttr = attributes.get("class");
final int len = classAttr.length();
final int wantLen = className.length();
if (len == 0 || len < wantLen) {
return false;
}
// if both lengths are equal, only need compare the className with the attribute
if (len == wantLen) {
return className.equalsIgnoreCase(classAttr);
}
// otherwise, scan for whitespace and compare regions (with no string or arraylist allocations)
boolean inClass = false;
int start = 0;
for (int i = 0; i < len; i++) {
if (Character.isWhitespace(classAttr.charAt(i))) {
if (inClass) {
// white space ends a class name, compare it with the requested one, ignore case
if (i - start == wantLen && classAttr.regionMatches(true, start, className, 0, wantLen)) {
return true;
}
inClass = false;
}
} else {
if (!inClass) {
// we're in a class name : keep the start of the substring
inClass = true;
start = i;
}
}
}
// check the last entry
if (inClass && len - start == wantLen) {
return classAttr.regionMatches(true, start, className, 0, wantLen);
}
return false;
}
```
| public boolean hasClass(String className) {
final String classAttr = attributes.get("class");
final int len = classAttr.length();
final int wantLen = className.length();
if (len == 0 || len < wantLen) {
return false;
}
// if both lengths are equal, only need compare the className with the attribute
if (len == wantLen) {
return className.equalsIgnoreCase(classAttr);
}
// otherwise, scan for whitespace and compare regions (with no string or arraylist allocations)
boolean inClass = false;
int start = 0;
for (int i = 0; i < len; i++) {
if (Character.isWhitespace(classAttr.charAt(i))) {
if (inClass) {
// white space ends a class name, compare it with the requested one, ignore case
if (i - start == wantLen && classAttr.regionMatches(true, start, className, 0, wantLen)) {
return true;
}
inClass = false;
}
} else {
if (!inClass) {
// we're in a class name : keep the start of the substring
inClass = true;
start = i;
}
}
}
// check the last entry
if (inClass && len - start == wantLen) {
return classAttr.regionMatches(true, start, className, 0, wantLen);
}
return false;
} | true | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// performance sensitive
/**
* Tests if this element has a class. Case insensitive.
* @param className name of class to check for
* @return true if it does, false if not
*/
public boolean hasClass(String className) {
final String classAttr = attributes.get("class");
final int len = classAttr.length();
final int wantLen = className.length();
if (len == 0 || len < wantLen) {
return false;
}
// if both lengths are equal, only need compare the className with the attribute
if (len == wantLen) {
return className.equalsIgnoreCase(classAttr);
}
// otherwise, scan for whitespace and compare regions (with no string or arraylist allocations)
boolean inClass = false;
int start = 0;
for (int i = 0; i < len; i++) {
if (Character.isWhitespace(classAttr.charAt(i))) {
if (inClass) {
// white space ends a class name, compare it with the requested one, ignore case
if (i - start == wantLen && classAttr.regionMatches(true, start, className, 0, wantLen)) {
return true;
}
inClass = false;
}
} else {
if (!inClass) {
// we're in a class name : keep the start of the substring
inClass = true;
start = i;
}
}
}
// check the last entry
if (inClass && len - start == wantLen) {
return classAttr.regionMatches(true, start, className, 0, wantLen);
}
return false;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
36 | 8c9ef0a146c4126467d4b6139e7cd576563b966395e4b1675546dd6631229b04 | private boolean canInline(
Reference declaration,
Reference initialization,
Reference reference) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* @return true if the provided reference and declaration can be safely
* inlined according to our criteria
*/
private boolean canInline(
Reference declaration,
Reference initialization,
Reference reference) {
if (!isValidDeclaration(declaration)
|| !isValidInitialization(initialization)
|| !isValidReference(reference)) {
return false;
}
// If the value is read more than once, skip it.
// VAR declarations and EXPR_RESULT don't need the value, but other
// ASSIGN expressions parents do.
if (declaration != initialization &&
!initialization.getGrandparent().isExprResult()) {
return false;
}
// Be very conservative and do no cross control structures or
// scope boundaries
if (declaration.getBasicBlock() != initialization.getBasicBlock()
|| declaration.getBasicBlock() != reference.getBasicBlock()) {
return false;
}
// Do not inline into a call node. This would change
// the context in which it was being called. For example,
// var a = b.c;
// a();
// should not be inlined, because it calls a in the context of b
// rather than the context of the window.
// var a = b.c;
// f(a)
// is ok.
Node value = initialization.getAssignedValue();
Preconditions.checkState(value != null);
if (value.isGetProp()
&& reference.getParent().isCall()
&& reference.getParent().getFirstChild() == reference.getNode()) {
return false;
}
if (value.isFunction()) {
Node callNode = reference.getParent();
if (reference.getParent().isCall()) {
CodingConvention convention = compiler.getCodingConvention();
// Bug 2388531: Don't inline subclass definitions into class defining
// calls as this confused class removing logic.
SubclassRelationship relationship =
convention.getClassesDefinedByCall(callNode);
if (relationship != null) {
return false;
}
// issue 668: Don't inline singleton getter methods
// calls as this confused class removing logic.
if (convention.getSingletonGetterClassName(callNode) != null) {
return false;
}
}
}
return canMoveAggressively(value) ||
canMoveModerately(initialization, reference);
}
```
| private boolean canInline(
Reference declaration,
Reference initialization,
Reference reference) {
if (!isValidDeclaration(declaration)
|| !isValidInitialization(initialization)
|| !isValidReference(reference)) {
return false;
}
// If the value is read more than once, skip it.
// VAR declarations and EXPR_RESULT don't need the value, but other
// ASSIGN expressions parents do.
if (declaration != initialization &&
!initialization.getGrandparent().isExprResult()) {
return false;
}
// Be very conservative and do no cross control structures or
// scope boundaries
if (declaration.getBasicBlock() != initialization.getBasicBlock()
|| declaration.getBasicBlock() != reference.getBasicBlock()) {
return false;
}
// Do not inline into a call node. This would change
// the context in which it was being called. For example,
// var a = b.c;
// a();
// should not be inlined, because it calls a in the context of b
// rather than the context of the window.
// var a = b.c;
// f(a)
// is ok.
Node value = initialization.getAssignedValue();
Preconditions.checkState(value != null);
if (value.isGetProp()
&& reference.getParent().isCall()
&& reference.getParent().getFirstChild() == reference.getNode()) {
return false;
}
if (value.isFunction()) {
Node callNode = reference.getParent();
if (reference.getParent().isCall()) {
CodingConvention convention = compiler.getCodingConvention();
// Bug 2388531: Don't inline subclass definitions into class defining
// calls as this confused class removing logic.
SubclassRelationship relationship =
convention.getClassesDefinedByCall(callNode);
if (relationship != null) {
return false;
}
// issue 668: Don't inline singleton getter methods
// calls as this confused class removing logic.
if (convention.getSingletonGetterClassName(callNode) != null) {
return false;
}
}
}
return canMoveAggressively(value) ||
canMoveModerately(initialization, reference);
} | false | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* @return true if the provided reference and declaration can be safely
* inlined according to our criteria
*/
private boolean canInline(
Reference declaration,
Reference initialization,
Reference reference) {
if (!isValidDeclaration(declaration)
|| !isValidInitialization(initialization)
|| !isValidReference(reference)) {
return false;
}
// If the value is read more than once, skip it.
// VAR declarations and EXPR_RESULT don't need the value, but other
// ASSIGN expressions parents do.
if (declaration != initialization &&
!initialization.getGrandparent().isExprResult()) {
return false;
}
// Be very conservative and do no cross control structures or
// scope boundaries
if (declaration.getBasicBlock() != initialization.getBasicBlock()
|| declaration.getBasicBlock() != reference.getBasicBlock()) {
return false;
}
// Do not inline into a call node. This would change
// the context in which it was being called. For example,
// var a = b.c;
// a();
// should not be inlined, because it calls a in the context of b
// rather than the context of the window.
// var a = b.c;
// f(a)
// is ok.
Node value = initialization.getAssignedValue();
Preconditions.checkState(value != null);
if (value.isGetProp()
&& reference.getParent().isCall()
&& reference.getParent().getFirstChild() == reference.getNode()) {
return false;
}
if (value.isFunction()) {
Node callNode = reference.getParent();
if (reference.getParent().isCall()) {
CodingConvention convention = compiler.getCodingConvention();
// Bug 2388531: Don't inline subclass definitions into class defining
// calls as this confused class removing logic.
SubclassRelationship relationship =
convention.getClassesDefinedByCall(callNode);
if (relationship != null) {
return false;
}
// issue 668: Don't inline singleton getter methods
// calls as this confused class removing logic.
if (convention.getSingletonGetterClassName(callNode) != null) {
return false;
}
}
}
return canMoveAggressively(value) ||
canMoveModerately(initialization, reference);
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
33 | 8d44eac26b05ab741ea11a0c559ec04856137aef2bae566530898ddba741017a | protected void dropPhase1Objective() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* Removes the phase 1 objective function, positive cost non-artificial variables,
* and the non-basic artificial variables from this tableau.
*/
protected void dropPhase1Objective() {
if (getNumObjectiveFunctions() == 1) {
return;
}
List<Integer> columnsToDrop = new ArrayList<Integer>();
columnsToDrop.add(0);
// positive cost non-artificial variables
for (int i = getNumObjectiveFunctions(); i < getArtificialVariableOffset(); i++) {
final double entry = tableau.getEntry(0, i);
if (Precision.compareTo(entry, 0d, maxUlps) > 0) {
columnsToDrop.add(i);
}
}
// non-basic artificial variables
for (int i = 0; i < getNumArtificialVariables(); i++) {
int col = i + getArtificialVariableOffset();
if (getBasicRow(col) == null) {
columnsToDrop.add(col);
}
}
double[][] matrix = new double[getHeight() - 1][getWidth() - columnsToDrop.size()];
for (int i = 1; i < getHeight(); i++) {
int col = 0;
for (int j = 0; j < getWidth(); j++) {
if (!columnsToDrop.contains(j)) {
matrix[i - 1][col++] = tableau.getEntry(i, j);
}
}
}
for (int i = columnsToDrop.size() - 1; i >= 0; i--) {
columnLabels.remove((int) columnsToDrop.get(i));
}
this.tableau = new Array2DRowRealMatrix(matrix);
this.numArtificialVariables = 0;
}
```
| protected void dropPhase1Objective() {
if (getNumObjectiveFunctions() == 1) {
return;
}
List<Integer> columnsToDrop = new ArrayList<Integer>();
columnsToDrop.add(0);
// positive cost non-artificial variables
for (int i = getNumObjectiveFunctions(); i < getArtificialVariableOffset(); i++) {
final double entry = tableau.getEntry(0, i);
if (Precision.compareTo(entry, 0d, maxUlps) > 0) {
columnsToDrop.add(i);
}
}
// non-basic artificial variables
for (int i = 0; i < getNumArtificialVariables(); i++) {
int col = i + getArtificialVariableOffset();
if (getBasicRow(col) == null) {
columnsToDrop.add(col);
}
}
double[][] matrix = new double[getHeight() - 1][getWidth() - columnsToDrop.size()];
for (int i = 1; i < getHeight(); i++) {
int col = 0;
for (int j = 0; j < getWidth(); j++) {
if (!columnsToDrop.contains(j)) {
matrix[i - 1][col++] = tableau.getEntry(i, j);
}
}
}
for (int i = columnsToDrop.size() - 1; i >= 0; i--) {
columnLabels.remove((int) columnsToDrop.get(i));
}
this.tableau = new Array2DRowRealMatrix(matrix);
this.numArtificialVariables = 0;
} | true | Math | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Removes the phase 1 objective function, positive cost non-artificial variables,
* and the non-basic artificial variables from this tableau.
*/
protected void dropPhase1Objective() {
if (getNumObjectiveFunctions() == 1) {
return;
}
List<Integer> columnsToDrop = new ArrayList<Integer>();
columnsToDrop.add(0);
// positive cost non-artificial variables
for (int i = getNumObjectiveFunctions(); i < getArtificialVariableOffset(); i++) {
final double entry = tableau.getEntry(0, i);
if (Precision.compareTo(entry, 0d, maxUlps) > 0) {
columnsToDrop.add(i);
}
}
// non-basic artificial variables
for (int i = 0; i < getNumArtificialVariables(); i++) {
int col = i + getArtificialVariableOffset();
if (getBasicRow(col) == null) {
columnsToDrop.add(col);
}
}
double[][] matrix = new double[getHeight() - 1][getWidth() - columnsToDrop.size()];
for (int i = 1; i < getHeight(); i++) {
int col = 0;
for (int j = 0; j < getWidth(); j++) {
if (!columnsToDrop.contains(j)) {
matrix[i - 1][col++] = tableau.getEntry(i, j);
}
}
}
for (int i = columnsToDrop.size() - 1; i >= 0; i--) {
columnLabels.remove((int) columnsToDrop.get(i));
}
this.tableau = new Array2DRowRealMatrix(matrix);
this.numArtificialVariables = 0;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
37 | 8d9cdf07b12706cfcde9913dfd3f59d56a80552c0068b79c54c12e80500acd27 | @SuppressWarnings("unchecked")
public static <T> T[] addAll(T[] array1, T... array2) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* <p>Adds all the elements of the given arrays into a new array.</p>
* <p>The new array contains all of the element of <code>array1</code> followed
* by all of the elements <code>array2</code>. When an array is returned, it is always
* a new array.</p>
*
* <pre>
* ArrayUtils.addAll(null, null) = null
* ArrayUtils.addAll(array1, null) = cloned copy of array1
* ArrayUtils.addAll(null, array2) = cloned copy of array2
* ArrayUtils.addAll([], []) = []
* ArrayUtils.addAll([null], [null]) = [null, null]
* ArrayUtils.addAll(["a", "b", "c"], ["1", "2", "3"]) = ["a", "b", "c", "1", "2", "3"]
* </pre>
*
* @param array1 the first array whose elements are added to the new array, may be <code>null</code>
* @param array2 the second array whose elements are added to the new array, may be <code>null</code>
* @return The new array, <code>null</code> if both arrays are <code>null</code>.
* The type of the new array is the type of the first array,
* unless the first array is null, in which case the type is the same as the second array.
* @since 2.1
*/
@SuppressWarnings("unchecked")
public static <T> T[] addAll(T[] array1, T... array2) {
if (array1 == null) {
return clone(array2);
} else if (array2 == null) {
return clone(array1);
}
final Class<?> type1 = array1.getClass().getComponentType();
T[] joinedArray = (T[]) Array.newInstance(type1, array1.length + array2.length);
System.arraycopy(array1, 0, joinedArray, 0, array1.length);
try {
System.arraycopy(array2, 0, joinedArray, array1.length, array2.length);
} catch (ArrayStoreException ase) {
// Check if problem is incompatible types
final Class<?> type2 = array2.getClass().getComponentType();
if (!type1.isAssignableFrom(type2)){
throw new IllegalArgumentException("Cannot store "+type2.getName()+" in an array of "+type1.getName());
}
throw ase; // No, so rethrow original
}
return joinedArray;
}
```
| @SuppressWarnings("unchecked")
public static <T> T[] addAll(T[] array1, T... array2) {
if (array1 == null) {
return clone(array2);
} else if (array2 == null) {
return clone(array1);
}
final Class<?> type1 = array1.getClass().getComponentType();
T[] joinedArray = (T[]) Array.newInstance(type1, array1.length + array2.length);
System.arraycopy(array1, 0, joinedArray, 0, array1.length);
try {
System.arraycopy(array2, 0, joinedArray, array1.length, array2.length);
} catch (ArrayStoreException ase) {
// Check if problem is incompatible types
final Class<?> type2 = array2.getClass().getComponentType();
if (!type1.isAssignableFrom(type2)){
throw new IllegalArgumentException("Cannot store "+type2.getName()+" in an array of "+type1.getName());
}
throw ase; // No, so rethrow original
}
return joinedArray;
} | false | Lang | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* <p>Adds all the elements of the given arrays into a new array.</p>
* <p>The new array contains all of the element of <code>array1</code> followed
* by all of the elements <code>array2</code>. When an array is returned, it is always
* a new array.</p>
*
* <pre>
* ArrayUtils.addAll(null, null) = null
* ArrayUtils.addAll(array1, null) = cloned copy of array1
* ArrayUtils.addAll(null, array2) = cloned copy of array2
* ArrayUtils.addAll([], []) = []
* ArrayUtils.addAll([null], [null]) = [null, null]
* ArrayUtils.addAll(["a", "b", "c"], ["1", "2", "3"]) = ["a", "b", "c", "1", "2", "3"]
* </pre>
*
* @param array1 the first array whose elements are added to the new array, may be <code>null</code>
* @param array2 the second array whose elements are added to the new array, may be <code>null</code>
* @return The new array, <code>null</code> if both arrays are <code>null</code>.
* The type of the new array is the type of the first array,
* unless the first array is null, in which case the type is the same as the second array.
* @since 2.1
*/
@SuppressWarnings("unchecked")
public static <T> T[] addAll(T[] array1, T... array2) {
if (array1 == null) {
return clone(array2);
} else if (array2 == null) {
return clone(array1);
}
final Class<?> type1 = array1.getClass().getComponentType();
T[] joinedArray = (T[]) Array.newInstance(type1, array1.length + array2.length);
System.arraycopy(array1, 0, joinedArray, 0, array1.length);
try {
System.arraycopy(array2, 0, joinedArray, array1.length, array2.length);
} catch (ArrayStoreException ase) {
// Check if problem is incompatible types
final Class<?> type2 = array2.getClass().getComponentType();
if (!type1.isAssignableFrom(type2)){
throw new IllegalArgumentException("Cannot store "+type2.getName()+" in an array of "+type1.getName());
}
throw ase; // No, so rethrow original
}
return joinedArray;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
77 | 8dd2549eb72c6d6a1b0e2460fb7f949912b94395a64edcb2c1d0d04632fc46ca | private void popStackToClose(Token.EndTag endTag) | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
/**
* If the stack contains an element with this tag's name, pop up the stack to remove the first occurrence. If not
* found, skips.
*
* @param endTag tag to close
*/
private void popStackToClose(Token.EndTag endTag) {
String elName = endTag.normalName();
Element firstFound = null;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
if (next.nodeName().equals(elName)) {
firstFound = next;
break;
}
}
if (firstFound == null)
return; // not found, skip
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
stack.remove(pos);
if (next == firstFound)
break;
}
}
```
| private void popStackToClose(Token.EndTag endTag) {
String elName = endTag.normalName();
Element firstFound = null;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
if (next.nodeName().equals(elName)) {
firstFound = next;
break;
}
}
if (firstFound == null)
return; // not found, skip
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
stack.remove(pos);
if (next == firstFound)
break;
}
} | false | Jsoup | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* If the stack contains an element with this tag's name, pop up the stack to remove the first occurrence. If not
* found, skips.
*
* @param endTag tag to close
*/
private void popStackToClose(Token.EndTag endTag) {
String elName = endTag.normalName();
Element firstFound = null;
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
if (next.nodeName().equals(elName)) {
firstFound = next;
break;
}
}
if (firstFound == null)
return; // not found, skip
for (int pos = stack.size() -1; pos >= 0; pos--) {
Element next = stack.get(pos);
stack.remove(pos);
if (next == firstFound)
break;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
82 | 8dd4153a5f96b39dee49b336e2be622e9ff452c2fc2197b2c897f8164e164fcb | public final boolean isEmptyType() | I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
public final boolean isEmptyType() {
return isNoType() || isNoObjectType() || isNoResolvedType();
}
```
| public final boolean isEmptyType() {
return isNoType() || isNoObjectType() || isNoResolvedType();
} | true | Closure | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
public final boolean isEmptyType() {
return isNoType() || isNoObjectType() || isNoResolvedType();
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
74 | 8e1093eb183b2b27cc495d570f2ea8da690f7d025dc4b0dca69205b6ca92daa2 | @SuppressWarnings("resource")
protected Object _deserializeTypedUsingDefaultImpl(JsonParser p, DeserializationContext ctxt,
TokenBuffer tb) throws IOException
| I want you to act as a code defect detector, where I'll provide you with a Java function and it will be your responsibility to analyze it for potential issues based on the provided function code. Please respond with either "A. Yes, there are defects" or "B. No, there are no defects" based on your assessment. Let's get started with our first potentially flawed Java function:
```java
// off-lined to keep main method lean and mean...
@SuppressWarnings("resource")
protected Object _deserializeTypedUsingDefaultImpl(JsonParser p, DeserializationContext ctxt,
TokenBuffer tb) throws IOException
{
// As per [JACKSON-614], may have default implementation to use
JsonDeserializer<Object> deser = _findDefaultImplDeserializer(ctxt);
if (deser != null) {
if (tb != null) {
tb.writeEndObject();
p = tb.asParser(p);
// must move to point to the first token:
p.nextToken();
}
return deser.deserialize(p, ctxt);
}
// or, perhaps we just bumped into a "natural" value (boolean/int/double/String)?
Object result = TypeDeserializer.deserializeIfNatural(p, ctxt, _baseType);
if (result != null) {
return result;
}
// or, something for which "as-property" won't work, changed into "wrapper-array" type:
if (p.getCurrentToken() == JsonToken.START_ARRAY) {
return super.deserializeTypedFromAny(p, ctxt);
} else if (p.getCurrentToken() == JsonToken.VALUE_STRING) {
if (ctxt.isEnabled(DeserializationFeature.ACCEPT_EMPTY_STRING_AS_NULL_OBJECT)) {
String str = p.getText().trim();
if (str.isEmpty()) {
return null;
}
}
}
ctxt.reportWrongTokenException(p, JsonToken.FIELD_NAME,
"missing property '"+_typePropertyName+"' that is to contain type id (for class "+baseTypeName()+")");
return null;
}
```
| @SuppressWarnings("resource")
protected Object _deserializeTypedUsingDefaultImpl(JsonParser p, DeserializationContext ctxt,
TokenBuffer tb) throws IOException
{
// As per [JACKSON-614], may have default implementation to use
JsonDeserializer<Object> deser = _findDefaultImplDeserializer(ctxt);
if (deser != null) {
if (tb != null) {
tb.writeEndObject();
p = tb.asParser(p);
// must move to point to the first token:
p.nextToken();
}
return deser.deserialize(p, ctxt);
}
// or, perhaps we just bumped into a "natural" value (boolean/int/double/String)?
Object result = TypeDeserializer.deserializeIfNatural(p, ctxt, _baseType);
if (result != null) {
return result;
}
// or, something for which "as-property" won't work, changed into "wrapper-array" type:
if (p.getCurrentToken() == JsonToken.START_ARRAY) {
return super.deserializeTypedFromAny(p, ctxt);
} else if (p.getCurrentToken() == JsonToken.VALUE_STRING) {
if (ctxt.isEnabled(DeserializationFeature.ACCEPT_EMPTY_STRING_AS_NULL_OBJECT)) {
String str = p.getText().trim();
if (str.isEmpty()) {
return null;
}
}
}
ctxt.reportWrongTokenException(p, JsonToken.FIELD_NAME,
"missing property '"+_typePropertyName+"' that is to contain type id (for class "+baseTypeName()+")");
return null;
} | false | JacksonDatabind | /**
* Perform a binary search on a sorted array to find the position of a specified element.
*/
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r + l) / 2;
if (arr[mid] == x)
return mid;
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
return binarySearch(arr, mid + 1, r, x);
}
return -1;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
/**
* Counts the number of set bits in the binary representation of a given integer.
*/
public class BITCOUNT {
public static int bitcount(int n) {
int count = 0;
while (n != 0) {
n = (n & (n - 1));
count++;
}
return count;
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that finds and returns the kth smallest element in an unsorted array.
*/
public class KTH {
public static Integer kth(ArrayList<Integer> arr, int k) {
int pivot = arr.get(0);
ArrayList<Integer> below, above;
below = new ArrayList<Integer>(arr.size());
above = new ArrayList<Integer>(arr.size());
for (Integer x : arr) {
if (x < pivot) {
below.add(x);
} else if (x > pivot) {
above.add(x);
}
}
int num_less = below.size();
int num_lessoreq = arr.size() - above.size();
if (k < num_less) {
return kth(below, k);
} else if (k >= num_lessoreq) {
return kth(above, k-num_lessoreq);
} else {
return pivot;
}
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: B. No, it doesn't have defects
/**
* A method that sorts an ArrayList of integers using the Merge Sort algorithm.
*/
public static ArrayList<Integer> mergesort(ArrayList<Integer> arr) {
if (arr.size() <= 1) { // <= 1 in correct version
return arr;
} else {
int middle = arr.size() / 2;
ArrayList<Integer> left = new ArrayList<Integer>(100);
left.addAll(arr.subList(0,middle));
left = mergesort(left);
ArrayList<Integer> right = new ArrayList<Integer>(100);
right.addAll(arr.subList(middle, arr.size()));
right = mergesort(right);
return merge(left, left);
}
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: A. Yes, it has defects
// off-lined to keep main method lean and mean...
@SuppressWarnings("resource")
protected Object _deserializeTypedUsingDefaultImpl(JsonParser p, DeserializationContext ctxt,
TokenBuffer tb) throws IOException
{
// As per [JACKSON-614], may have default implementation to use
JsonDeserializer<Object> deser = _findDefaultImplDeserializer(ctxt);
if (deser != null) {
if (tb != null) {
tb.writeEndObject();
p = tb.asParser(p);
// must move to point to the first token:
p.nextToken();
}
return deser.deserialize(p, ctxt);
}
// or, perhaps we just bumped into a "natural" value (boolean/int/double/String)?
Object result = TypeDeserializer.deserializeIfNatural(p, ctxt, _baseType);
if (result != null) {
return result;
}
// or, something for which "as-property" won't work, changed into "wrapper-array" type:
if (p.getCurrentToken() == JsonToken.START_ARRAY) {
return super.deserializeTypedFromAny(p, ctxt);
} else if (p.getCurrentToken() == JsonToken.VALUE_STRING) {
if (ctxt.isEnabled(DeserializationFeature.ACCEPT_EMPTY_STRING_AS_NULL_OBJECT)) {
String str = p.getText().trim();
if (str.isEmpty()) {
return null;
}
}
}
ctxt.reportWrongTokenException(p, JsonToken.FIELD_NAME,
"missing property '"+_typePropertyName+"' that is to contain type id (for class "+baseTypeName()+")");
return null;
}
Question: Please determine whether the above-mentioned Java function has any defects?
A. Yes, it has defects
B. No, it doesn't have defects
Answer: |
Subsets and Splits