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Cyrus has come across a curious sight — an undirected, weighted graph with \(N*M\) nodes (numbered from \(0\) to \( N*M - 1\)) and \(N*M + N\) edges (numbered from \(0\) to \(N*M + N - 1\)). Each edge initially has a weight of \(1\). |
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What makes this graph so curious is its shape. The nodes are arranged in \(N\) "circles" of \(M\) nodes each. Nodes \(0..(M - 1)\) are in the first circle, nodes \(M..(2*M - 1)\) are in the second, and so on. In each circle, the nodes are arranged in clockwise order (ordered by increasing node number). |
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The first \(N*M\) edges lie within circles, with \(M\) edges per circle. Edges \(0..(M - 1)\) lie within the first circle, edges \(M..(2*M - 1)\) lie within the second, and so on. In each circle, its first (lowest-numbered) edge connects the circle's first and second nodes, its second edge connects its second and third nodes, and so on, with its final edge connecting its final and first nodes. |
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There are \(N\) more edges (edges \((N*M)..(N*M + N - 1)\)) connecting the \(N\) circles into what might be considered an additional circle. Each circle \(i\) has two "connection points", the first of which is its \((X_i+1)\)st node (that is, node \(M*i + X_i\)), and the second of which is its \((Y_i+1)\)st node (node \(M*i + Y_i\)). \(X_i\) and \(Y_i\) are not necessarily distinct. The \(i\)th of the \(N\) final edges connects the second connection point of circle \(i\) and the first connection point of circle \(((i+1)\text{ modulo }N)\). That is, there's an edge between nodes \(M*0 + Y_0\) and \(M*1 + X_1\), another between \(M*1 + Y_1\) and \(M*2 + X_2\), and so on, with the final edge connecting nodes \(M*(N-1) + Y_{N-1}\) and \(M*0 + X_0\). |
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For example, if \(N = 3\), \(M = 3\), \(X = [0, 2, 1]\), and \(Y = [1, 2, 0]\), the graph would look as follows (with the first \(N*M\) edges indicated in blue, and the last \(N\) in red): |
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{{PHOTO_ID:316300889650982}} |
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Cyrus was hoping to practice computing the [minimum spanning tree](https://en.wikipedia.org/wiki/Minimum_spanning_tree) of this graph, but it's starting to change before his very eyes! \(E\) events are about to occur on the graph (numbered from \(0\) to \(E-1\)), one after another. Event \(i\) will cause the weight of edge \(I_i\) to become \(W_i\). When an edge's weight changes, it will remain at its new value for future events (until changed again). |
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Let \(V_i\) be the weight of the graph's minimum spanning tree after the first \(i\) events. Help Cyrus compute the product of \(V_{1..E}\). As this product may be very large, you should only compute its value modulo 1,000,000,007. |
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In order to reduce the size of the input, the above values will not all be provided explicitly. Instead, you'll be given the first \(K\) values \(X_{0..(K-1)}\), \(Y_{0..(K-1)}\), \(I_{0..(K-1)}\), and \(W_{0..(K-1)}\), as well as the four triples of constants \((A_X, B_X, C_X)\), \((A_Y, B_Y, C_Y)\), \((A_I, B_I, C_I)\), and \((A_W, B_W, C_W)\), and must then compute \(X_{K..(N-1)}\), \(Y_{K..(N-1)}\), \(I_{K..(E-1)}\), and \(W_{K..(E-1)}\) as follows: |
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\(X_i = (A_X * X_{i-2} + B_X * X_{i-1} + C_X)\text{ modulo }M\) for \(i \ge K\) |
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\(Y_i = (A_Y * Y_{i-2} + B_Y * Y_{i-1} + C_Y)\text{ modulo }M\) for \(i \ge K\) |
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\(I_i = (A_I * I_{i-2} + B_I * I_{i-1} + C_I)\text{ modulo }(N*M + N)\) for \(i \ge K\) |
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\(W_i = (A_W * W_{i-2} + B_W * W_{i-1} + C_W)\text{ modulo }1,000,000,000\) for \(i \ge K\) |
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# Input |
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Input begins with an integer \(T\), the number of graphs. For each graph, there are 9 lines: |
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The first line contains the 4 space-separated integers \(N\), \(M\), \(E\), and \(K\). |
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The second line contains the \(K\) space-separated integers \(X_{0..K-1}\). |
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The third line contains the 3 space-separated integers \(A_X\), \(B_X\), and \(C_X\). |
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The fourth line contains the \(K\) space-separated integers \(Y_{0..K-1}\). |
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The fifth line contains the 3 space-separated integers \(A_Y\), \(B_Y\), and \(C_Y\). |
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The sixth line contains the \(K\) space-separated integers \(I_{0..K-1}\). |
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The seventh line contains the 3 space-separated integers \(A_I\), \(B_I\), and \(C_I\). |
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The eighth line contains the \(K\) space-separated integers \(W_{0..K-1}\). |
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The ninth line contains the 3 space-separated integers \(A_W\), \(B_W\), and \(C_W\). |
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# Output |
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For the \(i\)th graph, print a line containing *"Case #i: "* followed by a single integer, the product of \(V_{1..E}\) modulo 1,000,000,007. |
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# Constraints |
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\(1 \le T \le 90\) |
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\(3 \le N, M \le 1,000,000\) |
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\(N*M + N \le 1,000,000\) |
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\(2 \le E \le 1,000,000\) |
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\(2 \le K \le min(N, E)\) |
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\(0 \le A_X, B_X, C_X, A_Y, B_Y, C_Y, A_I, B_I, C_I, A_W, B_W, C_W \le 1,000,000,000\) |
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\(0 \le X_i, Y_i < M\) |
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\(0 \le I_i < N*M + N\) |
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\(0 \le W_i < 1,000,000,000\) |
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The sum of \(N*M + E\) across all \(T\) graphs is at most 20,000,000. |
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# Explanation of Sample |
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**For the first graph:** |
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- \(X = [0, 2, 1]\) |
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- \(Y = [1, 2, 0]\) |
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- \(I = [9, 10, 11]\) |
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- \(W = [1, 1, 1]\) |
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Each event causes an edge weight to remain equal to \(1\). Therefore, the graph looks as follows, both initially and after all three events: |
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{{PHOTO_ID:2720312131621256}} |
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A minimum spanning tree on this graph must involve 8 weight-1 edges. Therefore, \(V = [8, 8, 8]\), and the final answer is \((8 * 8 * 8)\text{ modulo 1,000,000,007} = 512\). |
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**For the second graph:** |
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- \(X = [0, 2, 1]\) |
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- \(Y = [1, 2, 0]\) |
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- \(I = [6, 10, 2, 5, 3, 2, 10, 1]\) |
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- \(W = [0, 2, 2, 3, 3, 4, 4, 5]\) |
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After the eighth and final event, the graph looks as follows, with one possible minimum spanning tree highlighted: |
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{{PHOTO_ID:1530362313804065}} |
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For this graph, \(V = [7, 7, 7, 7, 9, 9, 9, 12]\). |
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**For the third graph:** |
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- \(X = [1, 2, 0]\) |
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- \(Y = [1, 1, 0]\) |
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- \(I = [14, 12, 1, 3, 5, 7, 9, 11, 13, 0]\) |
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- \(W = [11, 0, 6, 9, 12, 15, 18, 21, 24, 27]\) |
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For this graph, \(V = [11, 10, 10, 15, 15, 25, 25, 42, 53, 61]\). |
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**For the fourth graph:** |
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- \(X = [4, 1, 3, 4, 0]\) |
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- \(Y = [0, 3, 3, 0, 0]\) |
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