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Question: of the 20,210 employees of the anvil factory , 2 / 7 are journeymen . if half of the journeymen were laid off , what percentage of the total remaining employees would be journeymen ? A.14.3 %. B.16.67 %. C.33 %. D.28.6 %. e ) 49.67 %E. the exam gives us a number that is easily divisible by 7 to pique our curiosity and tempt us into calculating actual numbers ( also because otherwise the ratio would be incorrect ) . since the question is about percentages , the actual numbers will be meaningless , as only the ratio of that number versus others will be meaningful . nonetheless , for those who are curious , each 1 / 7 portion represents ( 14210 / 7 ) 2,030 employees . this in turn means that 4,060 employees are journeymen and the remaining 10,150 are full time workers . if half the journeymen were laid off , that would mean 1 / 7 of the total current workforce would be removed . this statistic is what leads many students to think that since half the journeymen are left , the remaining journeymen would represent half of what they used to be , which means 1 / 7 of the total workforce . if 1 / 7 of the workforce is journeymen , and 1 / 7 is roughly 14.3 % , then answer choice a should be the right answer . in this case , though , it is merely the tempting trap answer choice . what changed between the initial statement and the final tally ? well , you let go of 1 / 7 of the workforce , so the total number of workers went down . the remaining workers are still 1 / 7 of the initial workers , but the group has changed . the new workforce is smaller than the original group , specifically 6 / 7 of it because 1 / 7 was eliminated . the remaining workers now account for 1 / 7 out of 6 / 7 of the force , which if we multiply by 7 gives us 1 out of 6 . this number as a percentage is answer choice b , 49.67 % . using the absolute numbers we calculated before , there were 4,060 journeymen employees out of 14,210 total . if 2,030 of them are laid off , then there are 2,030 journeyman employees left , but now out of a total of ( 14,210 - 2,030 ) 12,180 employees . 2,030 / 12,180 is exactly 1 / 6 , or 16.67 % . the answer will work with either percentages or absolute numbers , but the percentage calculation will be significantly faster and applicable to any similar situation . the underlying principle of percentages ( and , on a related note , ratios ) can be summed up in the brainteaser i like to ask my students : if you ’ re running a race and you overtake the 2 nd place runner just before the end , what position do you end up in ? the correct answer is 2 nd place . percentages , like ratios and other concepts of relative math , depend entirely on the context . whether 100 % more of something is better than 50 % more of something else depends on the context much more than the percentages quoted . when it comes to percentages on the gmat , the goal is to understand them enough to instinctively not fall into the traps laid out for you . e
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Question: if jimmy drinks 8 ounces of water each time for 8 times a day . how much gallons of water he would have to prepare ahead to drink for 5 days ? ( 1 ounce = 0.0078125 gallon ) A.1. B.1.5. C.2. D.2.5. e ) 3D. 8 ounces * 8 times / day = 64 ounces of water = 64 * 0.0078125 = 0.5 gallon . 5 days need 0.5 * 5 = 2.5 gallons . correct option : 2.5 answer : d
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Question: 100 people are attending a newspaper conference . 45 of them are writers and more than 36 are editors . of the people at the conference , x are both writers and editors and 2 x are neither . what is the largest possible number of people who are both writers and editors ? A.26. B.24. C.18. D.20. e ) 22C. "{ total } = { writers } + { editors } - { both } + { neither } . { total } = 100 ; { writers } = 45 ; { editors } > 38 ; { both } = x ; { neither } = 2 x ; 100 = 45 + { editors } - x + 2 x - - > x = 55 - { editors } . we want to maximize x , thus we should minimize { editors } , minimum possible value of { editors } is 37 , thus x = { both } = 55 - 37 = 18 . answer : c ."
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Question: two trains , a and b , started simultaneously from opposite ends of a 120 - mile route and traveled toward each other on parallel tracks . train a , traveling at a constant rate , completed the 120 - mile trip in 6 hours ; train b , traveling at a constant rate , completed the 120 - mile trip in 4 hours . how many miles had train a traveled when it met train b ? A.28. B.36. C.48. D.50. e ) 54C. "as the ratio of the rates of a and b is 4 to 6 then the distance covered at the time of the meeting ( so after traveling the same time interval ) would also be in that ratio , which means that x would cover 4 / ( 4 + 6 ) = 4 / 10 of 120 miles : 120 * 4 / 10 = 48 miles . answer : c ."
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Question: if a speaks the truth 55 % of the times , b speaks the truth 60 % of the times . what is the probability that they tell the truth at the same time A.0.29. B.0.33. C.0.41. D.0.482. e ) 0.411B. "explanation : probability that a speaks truth is 55 / 100 = 0.55 probability that b speaks truth is 60 / 100 = 0.6 since both a and b are independent of each other so probability of a intersection b is p ( a ) Γ— p ( b ) = 0.55 Γ— 0.6 = 0.33 answer : b"
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Question: the closest approximation of ( 69.28 Γ— 0.004 ) / 0.03 is A.0.092. B.0.92. C.9.2. D.92. e ) 920C. "( 69.28 Γ— 0.004 ) / 0.03 1 . 0.004 = 4 Γ— 10 ^ ( - 3 ) 2 . 0.03 = 3 Γ— 10 ^ ( - 2 ) 3 . ( a Γ— b ) / c = a Γ— ( b / c ) 4 . 0.004 / 0.03 = 4 Γ— 10 ^ ( - 3 ) / ( 3 Γ— 10 ^ ( - 2 ) ) = 4 Γ— 10 ^ ( - 3 - ( - 2 ) ) / 3 = 4 Γ— 10 ^ ( - 1 ) / 3 = ( 4 / 3 ) Γ— 10 ^ ( - 1 ) = 1.333 Γ— 10 ^ ( - 1 ) therefore , ( 69.28 Γ— 0.004 ) / 0.03 = 69.28 Γ— ( 0.004 / 0.03 ) = 69.28 Γ— 1.33 Γ— 10 ^ ( - 1 ) = 69.28 Γ— 1.33 / 10 = 6.928 * 1.33 now , 7 Γ— 2 = 14 7 Γ— 1 = 7 or better : 6.9 Γ— 1 = 6.9 6.9 Γ— 2 = 13.8 hence , 6.9 < 6.928 Γ— 1.33 < 13.8 9.2 is the only answer that satisfies this condition . answer : c"
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Question: to complete a work a and b takes 8 days , b and c takes 12 days , a , b and c takes 6 days . how much time a and c will take A.24 days. B.16 days. C.12 days. D.8 days. e ) none of theseD. explanation : a + b 1 day work = 1 / 8 b + c 1 day work = 1 / 12 a + b + c 1 day work = 1 / 6 we can get a work by ( a + b + c ) - ( b + c ) and c by ( a + b + c ) - ( a + b ) so a 1 day work = 1 / 6 βˆ’ 1 / 12 = 1 / 12 similarly c 1 day work = 1 / 6 βˆ’ 1 / 8 = 4 βˆ’ 3 / 24 = 1 / 24 so a and c 1 day work = 1 / 12 + 1 / 24 = 3 / 24 = 1 / 8 so a and c can together do this work in 8 days option d
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Question: 16 is divided into two parts in such a way that seventh part of first and ninth part of second are equal . find the smallest part ? A.14. B.12. C.11. D.8. e ) 7E. "x / 7 = y / 9 = > x : y = 7 : 9 7 / 16 * 16 = 7 answer : e"
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Question: maxwell leaves his home and walks toward brad ' s house . one hour later , brad leaves his home and runs toward maxwell ' s house . if the distance between their homes is 34 kilometers , maxwell ' s walking speed is 4 km / h , and brad ' s running speed is 6 km / h . what is the total time it takes maxwell before he meets up with brad ? A.3. B.4. C.5. D.6. e ) 8B. "total distance = 34 kms maxwell speed = 4 kms / hr maxwell travelled for 1 hour before brad started , therefore maxwell traveled for 4 kms in 1 hour . time taken = total distance / relative speed total distance after brad started = 30 kms relative speed ( opposite side ) ( as they are moving towards each other speed would be added ) = 6 + 4 = 10 kms / hr time taken to meet brad after brad started = 30 / 10 = 3 hrs distance traveled by maxwell = maxwell ' s speed * time taken = 4 * 3 = 12 + 4 = 16 kms . . . therefore total time taken by maxwell to meet brad = distance travelled by maxwell / maxwell ' s speed = 16 / 4 = 4 hrs . . . answer b"
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Question: if log 2 x - 5 log x + 6 = 0 , then what would the value / values of x be ? A.5.3296. B.6.3296. C.7.3296. D.8.3296. e ) 9.3296A. log ( 2 x ) - 5 log ( x ) + 6 = 0 ( given ) log ( 2 x ) - log ( x ^ 5 ) = - 6 log ( 2 x / x ^ 5 ) = - 6 [ since log ( a ) - log ( b ) = log ( a / b ) ] apply anti log 2 / ( x ^ 4 ) = e ^ - 6 2 / ( x ^ 4 ) = 2.4788 * 10 ^ - 3 x ^ 4 = 806.85 x = 5.3296 answer : a
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Question: the salary of a person was reduced by 25 % . by what percent should his reduced salary be raised so as to bring it at par with his original salary ? A.10 %. B.33.33 %. C.20 %. D.25 %. e ) 50 %B. "let the original salary be $ 100 new salary = $ 75 increase on 75 = 25 increase on 100 = [ ( 25 / 75 ) 100 ] % = 33.33 % answer is b"
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Question: if a light flashes every 6 seconds , how many times will it flash in 1 / 3 of an hour ? A.101. B.201. C.301. D.401. e ) 501B. "in 1 / 3 of an hour there are 20 * 60 = 1200 seconds the number of 6 - second intervals = 1200 / 6 = 200 after the first flash , there will be 200 more flashes for a total of 201 . the answer is b ."
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Question: if ( x + 1 ) ( x + 3 ) = x ^ 2 + x , what is a possible value of x ? A.2. B.3. C.- 1 / 3. D.- 3. e ) - 1E. rearranging the given expression : ( x + 1 ) ( x + 3 ) = x ^ 2 + x i . e . x ^ 2 + 4 x + 3 = x ^ 2 + x i . e . 3 x = - 3 i . e . x = - 3 / 3 = - 1 answer : option e had it been a difficult expression to solve further , then we could have used options to check which one satisfies the expression after solving it as further as possible .
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Question: a company recently conducted a survey and found that 20,000 of its customers live in rural areas . if the number of customers who live in urban areas is 100 percent greater than the number of customers who live in rural areas , how many customers live in urban areas ? A.40,000. B.45,000. C.50,000. D.55,000. e ) 60,000A. "the number of customers in urban areas is 20,000 + 1 * 20,000 = 40,000 . the answer is a ."
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Question: as a treat for her two children , a mother runs to the freezer in which she has 3 cherry ice pops , 4 orange ice pops , and 4 lemon ice pops . she chooses two at random to bring outside to the children , but realizes as she runs out the door that she can not bring them different flavors without one being jealous of the other and getting even more upset . what is the probability that she has to return to the freezer to make sure that they each receive the same flavor ? A.3 / 5. B.5 / 7. C.8 / 11. D.11 / 15. e ) 13 / 20C. p ( 2 cherry ) = 3 / 11 * 2 / 10 = 6 / 110 p ( 2 orange ) = 4 / 11 * 3 / 10 = 12 / 110 p ( 2 lemon ) = 4 / 11 * 3 / 10 = 12 / 110 p ( 2 of the same flavor ) = 30 / 110 p ( 2 different flavors ) = 1 - 30 / 110 = 80 / 110 = 8 / 11 the answer is c .
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Question: john traveled 80 % of the way from yellow - town to green - fields by train at an average speed of 80 miles per hour . the rest of the way john traveled by car at an average speed of v miles per hour . if the average speed for the entire trip was 70 miles per hour , what is v in miles per hour ? A.30. B.40. C.50. D.55. e ) 60E. "hibunuel the question seems incorrect . it should not be 80 % at the speed of 80 . however if it ' s 20 % at the speed of 80 , answer comes out 55 . the question is correct . here ' s the explanation : let distance be d . we can find the total timeequate it , which comes as : 0.8 d / 80 + 0.2 d / v = d / 70 = > v = 60 ( option e ) ."
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Question: a rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing . if the poles of the fence are kept 10 metres apart , how many poles will be needed ? A.28. B.56. C.57. D.58. e ) none of theseA. "solution perimeter of the plot = 2 ( 90 + 50 ) = 280 m . ∴ number of poles = [ 280 / 10 ] = 28 m answer a"
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Question: if in a race of 80 m , a covers the distance in 20 seconds and b in 25 seconds , then a beats b by : A.16 m. B.18 m. C.15 m. D.14 m. e ) 11 mA. "explanation : the difference in the timing of a and b is 5 seconds . hence , a beats b by 5 seconds . the distance covered by b in 5 seconds = ( 80 * 5 ) / 25 = 16 m hence , a beats b by 16 m . answer : a"
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Question: when two dice are rolled , what is the probability that the sum of the two numbers is 6 ? A.1 / 9. B.5 / 36. C.1 / 3. D.2 / 36. e ) none of the aboveB. we have 5 outcomes that satisfy the question : 1 - 5 2 - 4 3 - 3 4 - 2 5 - 1 the probability is ( 1 / 6 * 1 / 6 ) * 5 = 5 / 36 . i think the answer is b
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Question: two trains start from a & b and travel towards each other at speed of 50 kmph and 60 kmph resp . at the time of the meeting the second train has traveled 100 km more than the first . the distance between them . A.800 km. B.900 km. C.1000 km. D.1100 km. e ) 1200 kmD. let the distance traveled by the first train be x km then distance covered by the second train is x + 100 km x / 50 = x + 100 / 60 x = 500 so the distance between a & b is x + x + 100 = 1100 km answer is d .
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Question: a dog takes 5 leaps for every 7 leaps of a hare . if one leap of the dog is equal to 3 leaps of the hare , the ratio of the speed of the dog to that of the hare is : A.16 : 7. B.15 : 7. C.20 : 7. D.7 : 15. e ) 14 : 7B. explanation : dog : hare = ( 5 * 3 ) leaps of hare : 7 leaps of hare = 15 : 7 answer : b
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Question: if x < y < z and y - x > 5 , where x is an even integer and y and z are odd integers , what is the least possible value a of z - x ? A.6. B.7. C.8. D.9. e ) 10D. "x < y < z to find the least possible value for z - x ; we need to find the values for z and x that can be closest to each other . if x is some even number , then what could be minimum possible odd z . if x is some even number y - x > 5 ; y > x + 5 ; minimum value for y = x + 5 + 2 = x + 7 [ note : x + 5 is as even + odd = odd and nearest odd greater than x + 5 is x + 5 + 2 ] minimum value for z = y + 2 = x + 7 + 2 = x + 9 [ note : z = y + 2 because both z and y are odd . difference between two odd numbers is 2 ] a = z - x = x + 9 - x = 9 ans : d"
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Question: 0.1 + ( 0.1 ) ^ 2 + ( 0.1 ) ^ 3 = A.0.1. B.0.111. C.0.1211. D.0.2341. e ) 0.3B. "explanation : 0.1 + ( 0.1 ) ^ 2 + ( 0.1 ) ^ 3 = 0.1 + 0.01 + 0.001 = 0.111 answer : option b"
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Question: a train 360 m long runs with a speed of 45 km / hr . what time will it take to pass a platform of 140 m long ? A.38 sec. B.35 sec. C.44 sec. D.40 sec. e ) 48 secD. "train length = 360 m platform length = 140 m time = ? length = speed * time total length = 360 + 140 = 500 m speed = 45 km / hr = 45 * ( 5 / 18 ) ( m / sec ) = 12.5 m / sec time = length / speed = 500 / 12.5 = 40 sec answer : d"
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Question: convert the 17 / 36 m / s into kilometers per hour ? A.1.7. B.1.5. C.1.3. D.1.1. e ) 1.2A. "17 / 36 m / s = 17 / 36 * 18 / 5 = 17 / 10 = 1.7 kmph . answer : a"
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Question: two guys a and b leave point a and point b simultaneously and travel towards point b and point a on the same route at their respective constant speeds . they meet along the route and immediately proceed to their respective destinations in 32 minutes and 50 minutes respectively . how long will b take to cover the entire journey between point b and point a ? A.65. B.90. C.70. D.75. e ) 80B. let x per minute be the speed of a and y per minute be the speed of b . after meeting at a point , a travels for 32 mins and b travels for 50 mins . so distance covered by each of them post point of crossing a = 32 x and b = 50 y the distance covered by a and b before they cross each would be distance covered by b and a post crossing respectively . therefore distance covered by b before he meets a = 32 x time taken by b cover 32 x distance = 32 x / y mins therefore total time taken by b = 32 x / y + 50 mins . . . . . . . . . . . . . . . . . i we need to find value of x in terms of y to arrive at final answer . total distance = 32 x + 50 y combined speed of a and b = x + y therefore time taken before a and b meet en - route = ( 32 x + 50 y ) / ( x + y ) time taken by b reach destination after meeting a = 50 mins total travel time for b = [ ( 32 x + 50 y ) / ( x + y ) ] + 50 mins . . . . . . . . . . . . . . . . . . . ii equate i and ii 32 x / y + 50 = [ ( 32 x + 50 y ) / ( x + y ) ] + 50 ( 32 x + 50 y ) / y = ( 82 x + 100 y ) / ( x + y ) 32 x ^ 2 + 50 xy + 32 xy + 50 y ^ 2 = 82 xy + 100 y ^ 2 32 x ^ 2 + 82 xy - 82 xy + 50 y ^ 2 - 100 y ^ 2 = 0 32 x ^ 2 - 50 y ^ 2 = 0 32 x ^ 2 = 50 y ^ 2 16 x ^ 2 = 25 y ^ 2 taking square root . . ( since x and y denote speed , square root ca n ' t be negative ) 4 x = 5 y y = 4 x / 5 . . . . . . . . . . . . iii substitute in i = 32 x / ( 4 x / 5 ) + 50 = 32 x * 5 / 4 x + 50 = 40 + 50 = 90 mins b
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Question: in what time will a train 140 m long cross an electric pole , it its speed be 190 km / hr ? A.2.6 sec. B.2.9 sec. C.2.7 sec. D.8.7 sec. e ) 8.5 secA. "speed = 190 * 5 / 18 = 53 m / sec time taken = 140 / 53 = 2.6 sec . answer : a"
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Question: if 63 percent of a class answered the first question on a certain test correctly , 50 percent answered the second question on the test correctly , and 20 percent answered neither of the questions correctly , what percent answered both correctly ? A.24 %. B.27 %. C.30 %. D.33 %. e ) 36 %D. "63 % answered the first question correctly and 20 % answered neither correctly . then 17 % missed the first question but answered the second question correctly . then the percent who answered both correctly is 50 % - 17 % = 33 % . the answer is d ."
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Question: the area of a square garden is a square feet and the perimeter is p feet . if a = 2 p + 26.25 , what is the perimeter of the garden , in feet ? A.28. B.36. C.40. D.42. e ) 64D. "perimeter of square = p side of square = p / 4 area of square = ( p ^ 2 ) / 16 = a given that a = 2 p + 26.25 ( p ^ 2 ) / 16 = 2 p + 26.25 p ^ 2 = 32 p + 420 p ^ 2 - 32 p - 420 = 0 p ^ 2 - 42 p + 10 p - 420 = 0 p ( p - 42 ) + 10 ( p + 42 ) = 0 ( p - 42 ) ( p + 10 ) = 0 p = 42 or - 10 discarding negative value , p = 42 answer is d"
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Question: for the past n days , the average ( arithmetic mean ) daily production at a company was 50 units . if today ' s production of 95 units raises the average to 55 units per day , what is the value of n ? A.6. B.7. C.8. D.9. e ) 10C. "the average daily production was raised by 5 units for n days , which has a weighting of 5 n . 5 n = 95 - 55 = 40 n = 8 the answer is c ."
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Question: how many seconds will a 300 m long train take to cross a man walking with a speed of 3 km / hr in the direction of the moving train if the speed of the train is 63 km / hr ? A.12 sec. B.30 sec. C.86 sec. D.15 sec. e ) 18 secE. "speed of train relative to man = 63 - 3 = 60 km / hr . = 60 * 5 / 18 = 50 / 3 m / sec . time taken to pass the man = 300 * 3 / 50 = 18 sec . answer : e"
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Question: by investing in 1623 % stock at 64 , one earns rs . 1600 . the investment made is A.s . 9600. B.s . 7500. C.s . 5640. D.s . 6144. e ) s . 6760D. "explanation : market value = rs . 64 face value is not given and hence take it as rs . 100 16 2 / 3 % of the face value = 50 / 3 ie , to earn 50 / 3 , investment = rs . 64 hence , to earn rs . 1600 , investment needed = 64 Γ— 3 Γ— 1600 / 50 = 6144 answer : option d"
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Question: abcd is a parallelogram . bd = 2 . the angles of triangle bcd are all equal . what is the perimeter of the parallelogram ? ['A.12', 'B.9 √ 3', 'C.9', 'D.8', 'e ) 3 √ 3']D. so , bc = bd = cd = ba = ad = 2 the parallelogram has 4 equal sides bc = cd = ba = ad = 2 so the perimeter of the parallelogram will be 2 * 4 = 8 hence answer will be ( d ) 2
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Question: the number 42 can be written as the sum of the squares of 3 different positive integers . what is the sum of these 3 integers ? A.17. B.10. C.15. D.14. e ) 13B. "i think brute force with some common sense should be used to solve this problem . write down all perfect squares less than 42 : 1 , 4 , 9 , 16 , 25 , 36 . now , 42 should be the sum of 3 of those 8 numbers . also to simplify a little bit trial and error , we can notice that as 42 is an odd numbers then either all three numbers must be odd ( odd + odd + odd = odd ) or two must be even and one odd ( even + even + odd = odd ) . we can find that 42 equals to 1 + 16 + 25 = 1 ^ 2 + 4 ^ 2 + 5 ^ 2 = 42 - - > 1 + 5 + 4 = 10 . answer : b ."
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Question: if the price of petrol increases by 40 , by how much must a user cut down his consumption so that his expenditure on petrol remains constant ? A.25 %. B.20 %. C.16.67 %. D.28.6 %. e ) none of theseD. "explanation : let us assume before increase the petrol will be rs . 100 . after increase it will be rs ( 100 + 40 ) i . e 140 . now , his consumption should be reduced to : - = ( 140 βˆ’ 100 ) / 140 βˆ— 100 . hence , the consumption should be reduced to 28.6 % . answer : d"
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Question: how many factors does 36 ^ 2 have ? A.2. B.8. C.24. D.25. e ) 26D. "36 ^ 2 = 2 ^ 4 3 ^ 4 total factors = ( 4 + 1 ) ( 4 + 1 ) = 25 . answer is d ."
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Question: the average of 6 no . ' s is 3.95 . the average of 2 of them is 3.8 , while the average of theother 2 is 3.85 . what is the average of the remaining 2 no ' s ? A.4.2. B.4.4. C.4.6. D.5.6. e ) 5.7A. "sum of the remaining two numbers = ( 3.95 * 6 ) - [ ( 3.8 * 2 ) + ( 3.85 * 2 ) ] = 8.4 . required average = ( 8.4 / 2 ) = 4.2 . a"
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Question: 14 times a number gives 210 . the number is A.11. B.12. C.15. D.none. e ) can not be determinedC. "explanation : let the number be ' n ' 14 Γ— n = 210 β‡’ n = 15 correct option : c"
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Question: the average of 7 numbers is 24 . if each number be multiplied by 5 . find the average of new set of numbers ? A.110. B.122. C.120. D.125. e ) 145C. "explanation : average of new numbers = 24 * 5 = 120 answer : option c"
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Question: a cycle is bought for rs . 900 and sold for rs . 1080 , find the gain percent ? A.27 %. B.20 %. C.25 %. D.40 %. e ) 28 %B. "900 - - - - 180 100 - - - - ? = > 20 % answer : b"
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Question: excluding stoppages , the speed of a train is 45 kmph and including stoppages it is 30 kmph . of how many minutes does the train stop per hour ? A.A.5. B.B.10. C.C.20. D.D.30. e ) e ) 40C. "explanation : t = 15 / 45 * 60 = 20 answer : option c"
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Question: if rs . 544 be divided among a , b , c in such a way that a gets 2 / 3 of what b gets and b gets 1 / 4 of what c gets , then their shares are respectively ? A.s . 300. B.s . 360. C.s . 389. D.s . 384. e ) s . 323D. "( a = 2 / 3 b and b = 1 / 4 c ) = a / b = 2 / 3 and b / c = 1 / 4 a : b = 2 : 3 and b : c = 1 : 4 = 3 : 12 a : b : c = 2 : 3 : 12 a ; s share = 544 * 2 / 17 = rs . 64 b ' s share = 544 * 3 / 17 = rs . 96 c ' s share = 544 * 12 / 17 = rs . 384 . answer : d"
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Question: m = { - 6 , - 5 , - 4 , - 3 , - 2 } t = { - 3 , - 2 , - 1 , 0 , 1 , 2 , 3 , 4 } if an integer is to be randomly selected from set m above and an integer is to be randomly selected from set t above , what is the probability that the product of the two integers will be negative ? A.0. B.1 / 3. C.2 / 5. D.1 / 2. e ) 3 / 5D. we will have a negative product only if 1 , 2 , 3 , or 4 are selected from set t . p ( negative product ) = 4 / 8 = 1 / 2 the answer is d .
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Question: a 300 m long train crosses a platform in 48 sec while it crosses a signal pole in 18 sec . what is the length of the platform ? A.500. B.350. C.828. D.277. e ) 122A. "speed = 300 / 18 = 50 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 489 = 50 / 3 3 x + 900 = 2400 = > x = 500 m . answer : a"
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Question: the average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 22 years . find the average age of the women ? A.87. B.98. C.30. D.29. e ) 37D. "20 + 22 + 8 * 2 = 58 / 2 = 29 answer : d"
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Question: a tank contains 7,000 gallons of a solution that is 5 percent sodium chloride by volume . if 2,500 gallons of water evaporate from the tank , the remaining solution will be approximately what percent sodium chloride ? A.4.77 %. B.5.77 %. C.6.77 %. D.7.77 %. e ) 8.77 %D. "we start with 7,000 gallons of a solution that is 5 % sodium chloride by volume . this means that there are 0.05 x 7,000 = 350 gallons of sodium chloride . when 2,500 gallons of water evaporate we are left with 4,500 gallons of solution . from here we can determine what percent of the 4,500 gallon solution is sodium chloride . ( sodium chloride / total solution ) x 100 = ? ( 350 / 4,500 ) x 100 = ? 0.077 x 100 = ? = 7.7 % answer is d ."
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Question: if 20 % of x is 15 less than 15 % of 1500 , then x is ? A.872. B.738. C.837. D.840. e ) 1050E. "20 % of x = x / 5 ; 15 % of 1500 = 15 / 100 * 1500 = 225 given that , x / 5 = 225 - 15 = > x / 5 = 210 = > x = 1050 . answer : e"
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Question: a certain fraction is equivalent to 2 / 5 . if the numerator of the fraction is increased by 4 and the denominator is doubled , the new fraction is equivalent to 1 / 3 . what is the difference of the numerator and denominator of the original fraction ? A.49. B.9. C.28. D.26. e ) 21B. "x / y = 2 / 5 - > 1 ( x + 4 ) / 2 y = 1 / 3 - > 2 divide 1 by 2 : = > 2 x / ( x + 4 ) = 6 / 5 = > 5 x = 3 x + 12 = > x = 6 = > y = 5 / 2 * 6 = 15 so x - y = 9 the answer is b"
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Question: the average of numbers 0.34204 , 0.34203 , 0.34202 and 0.34201 is ? A.0.34202. B.0.34204. C.0.342022. D.0.342025. e ) noneD. "answer average = ( 0.34204 + 0.34203 + 0.34202 + 0.34201 ) / 4 = 1.3681 / 4 = 0.342025 correct option : d"
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Question: what is the total number of integers between 10 and 100 ( exclusive ) that are divisible by 7 ? A.10. B.13. C.15. D.12. e ) 11B. "14 , 21 , 28 , . . . , 91,98 this is an equally spaced list ; you can use the formula : n = ( largest - smallest ) / ( ' space ' ) + 1 = ( 98 - 14 ) / ( 7 ) + 1 = 12 + 1 = 13 answer is b"
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Question: if the average of 5 positive integers is 70 and the difference between the largest and the smallest of these 5 numbers is 10 , what is the maximum value possible for the largest of these 5 integers ? A.50. B.52. C.69. D.78. e ) 84D. "sum of 5 integer ( a , b , c , d , e ) = 5 * 70 = 350 e - a = 10 i . e . e = a + 10 for e to be maximum remaining 4 must be as small as possible since smallest of 5 numbers is a so to minimize other numbers we can take them equal to the smallest of 5 numbers i . e . a + a + a + a + ( a + 10 ) = 350 i . e . 5 a = 340 i . e . a = 68 i . e . largest e = 68 + 10 = 78 answer : option d"
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Question: a rectangular photograph is surrounded by a border that is 3 inch wide on each side . the total area of the photograph and the border is m square inches . if the border had been 6 inches wide on each side , the total area would have been ( m + 178 ) square inches . what is the perimeter of the photograph , in inches ? A.34. B.36. C.38. D.40. e ) 20E. "let length and breadth of photograph be l and b respectively . perimeter is given by 2 * ( l + b ) - - - - - ( 1 ) according to the question : ( l + 6 ) ( b + 6 ) = m - - - - ( 2 ) and ( l + 12 ) ( b + 12 ) = m + 178 - - - - - - - - - > ( l + 12 ) ( b + 12 ) - 178 = m - - - - - - ( 3 ) equating ( 2 ) and ( 3 ) ( l + 6 ) ( b + 6 ) = ( l + 12 ) ( b + 12 ) - 178 lb + 6 l + 6 b + 36 = lb + 12 l + 12 b + 144 - 168 simplify 6 l + 6 b = 60 - - - - - - > 2 ( l + b ) = 20 ( check eq ( 1 ) ) answer is e"
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Question: the two lines y = x and x = - 4 intersect on the coordinate plane . if z represents the area of the figure formed by the intersecting lines and the x - axis , what is the side length e of a cube whose surface area is equal to 6 z ? A.e = 16. B.e = 8 √ 2. C.e = 8. D.e = 2 √ 2. e ) ( √ 2 ) / 3D. "800 score official solution : the first step to solving this problem is to actually graph the two lines . the lines intersect at the point ( - 4 , - 4 ) and form a right triangle whose base length and height are both equal to 4 . as you know , the area of a triangle is equal to one half the product of its base length and height : a = ( 1 / 2 ) bh = ( 1 / 2 ) ( 4 Γ— 4 ) = 8 ; so z = 8 . the next step requires us to find the length of a side of a cube that has a face area equal to 8 . as you know the 6 faces of a cube are squares . so , we can reduce the problem to finding the length of the side of a square that has an area of 8 . since the area of a square is equal to s Β² , where s is the length of one of its side , we can write and solve the equation s Β² = 8 . clearly s = √ 8 = 2 √ 2 , oranswer choice ( d ) ."
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Question: two numbers are in the ratio 3 : 5 . if 9 be subtracted from each , they are in the ratio of 1 : 2 . the first number is : A.A.27. B.B.98. C.C.34. D.D.35. e ) e ) 62A. "( 3 x - 9 ) : ( 5 x - 9 ) = 9 : 17 x = 9 = > 3 x = 27 answer : a"
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Question: what number times ( 1 ⁄ 6 ) ^ 2 will give the value of 6 ^ 3 ? A.6. B.36. C.216. D.1296. e ) 7776E. "x * ( 1 / 6 ) ^ 2 = 6 ^ 3 x = 6 ^ 2 * 6 ^ 3 = 6 ^ 5 = 7776 the answer is e ."
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Question: a can contains a mixture of liquids a and b is the ratio 7 : 5 . when 18 litres of mixture are drawn off and the can is filled with b , the ratio of a and b becomes 7 : 9 . how many liter of liquid a was contained by the can initially ? A.32. B.52. C.62. D.42. e ) 48D. "ci * vi = cf * vf ( 7 / 12 ) * ( v 1 - 18 ) = ( 7 / 16 ) * v 1 ( v 1 - 18 ) / v 1 = 3 / 4 18 accounts for the difference of 1 on ratio scale so initial volume = v 1 = 4 * 18 = 72 litres . 7 / 12 of the initial mixture was liquid a so liquid a was ( 7 / 12 ) * 72 = 42 litres . answer : d"
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Question: angelo and isabella are both salespersons . in any given week , angelo makes $ 560 in base salary plus 8 percent of the portion of his sales above $ 1,000 for that week . isabella makes 10 percent of her total sales for any given week . for what amount of weekly sales would angelo and isabella earn the same amount of money ? A.23,500. B.24,000. C.25,500. D.26,500. e ) 27,500B. "let the weekly sales of both = x 560 + ( x βˆ’ 1000 ) 8 / 100 = 10 / 100 x x = 24000 answer : b"
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Question: a can do a piece of work in 16 days . when he had worked for 2 days b joins him . if the complete work was finished in 8 days . in how many days b alone can finish the work ? A.18. B.77. C.66. D.55. e ) 12E. "8 / 16 + 6 / x = 1 x = 12 days answer : e"
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Question: what is the normal price of an article sold at $ 72 after two successive discounts of 10 % and 20 % ? A.$ 92. B.$ 96. C.$ 100. D.$ 104. e ) $ 108C. 0.8 * 0.9 * cost price = $ 72 cost price = $ 100 the answer is c .
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Question: during a certain two - week period , 76 percent of the movies rented from a video store were comedies , and of the remaining movies rented , there were 5 times as many dramas as action movies . if no other movies were rented during that two - week period and there were a action movies rented , then how many comedies , in terms of a , were rented during that two - week period ? A.16 a. B.19 a. C.17 a. D.18 a. e ) 20 aB. "total movies = 100 . comedies = 76 . action + drama = 24 . since there were 5 times as many dramas as action movies , then action + 5 * action = 24 - - > action = a = 4 . comedies = 76 = 19 a . answer : b ."
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Question: of the 200 stamps in a collection , 80 are foreign and 50 are more than 10 years old . if 20 stamps are both foreign and more than 10 years old , how many stamps are neither foreign nor more than 10 years old ? A.60. B.90. C.100. D.130. e ) 150B. "20 stamps are both foreign and more than 10 years old . 60 stamps are foreign only . 30 stamps are 10 years old only . the number of remaining stamps is 200 - ( 20 + 60 + 30 ) = 90 the answer is b ."
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Question: running at their respective constant rates , machine x takes 2 days longer to produce w widgets than machine y . at these rates , if the two machines together produce 5 / 4 w widgets in 3 days , how many days would it take machine x alone to produce 3 w widgets ? A.4. B.6. C.18. D.10. e ) 12C. "let y produce w widgets in y days hence , in 1 day y will produce w / y widgets . also , x will produce w widgets in y + 2 days ( given , x takes two more days ) hence , in 1 day x will produce w / y + 2 widgets . hence together x and y in 1 day will produce { w / y + w / y + 2 } widgets . together x and y in 3 days will produce = 3 * [ { w / y + w / y + 2 } ] widgets . it is given that in 3 days together they produce ( 5 / 4 ) w widgets . equating , 3 * [ { w / y + w / y + 2 } ] = ( 5 / 4 ) w take out w common and move 3 to denominator of rhs w { 1 / y + 1 / ( y + 2 ) } = ( 5 / 12 ) w canceling w from both sides { 1 / y + 1 / ( y + 2 ) } = 5 / 12 2 y + 2 / y ( y + 2 ) = 5 / 12 24 y + 24 = 5 y ^ 2 + 10 y 5 y ^ 2 - 14 y - 24 = 0 5 y ^ 2 - 20 y + 6 y - 24 = 0 5 y ( y - 4 ) + 6 ( y - 4 ) = 0 ( 5 y + 6 ) + ( y - 4 ) = 0 y = - 6 / 5 or y = 4 discarding y = - 6 / 5 as no of days can not be negative y = 4 hence it takes y , 4 days to produce w widgets . therefore , it will take x ( 4 + 2 ) = 6 days to produce w widgets . hence it will take x 3 * 6 = 18 days to produce 3 w widgets . answer : c"
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Question: joe needs to paint all the airplane hangars at the airport , so he buys 360 gallons of paint to do the job . during the first week , he uses 1 / 4 of all the paint . during the second week , he uses 1 / 3 of the remaining paint . how many gallons of paint has joe used ? A.18. B.180. C.175. D.216. e ) 250B. "total paint initially = 360 gallons paint used in the first week = ( 1 / 4 ) * 360 = 90 gallons . remaning paint = 270 gallons paint used in the second week = ( 1 / 3 ) * 270 = 90 gallons total paint used = 180 gallons . option b"
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Question: the cost of 2 chairs and 3 tables is rs . 1400 . the cost of 3 chairs and 2 tables is rs . 1200 . the cost of each table is more than that of each chair by ? A.228. B.287. C.277. D.188. e ) 200E. "explanation : 2 c + 3 t = 1400 - - - ( 1 ) 3 c + 2 t = 1200 - - - ( 2 ) subtracting 2 nd from 1 st , we get - c + t = 200 = > t - c = 200 answer : e"
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Question: if a truck is traveling at a constant rate of 108 kilometers per hour , how many seconds will it take the truck to travel a distance of 600 meters ? ( 1 kilometer = 1000 meters ) A.20. B.24. C.30. D.36. e ) 48A. speed = 108 km / hr = > 108,000 m / hr in one minute = > 108000 / 60 = 1800 meters in one sec = > 1800 / 60 = 30 meters time = total distance need to be covered / avg . speed = > 600 / 30 = 20 and hence the answer : a
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Question: if x + y = 4 and x 2 y 3 + y 2 x 3 = 36 , what is the value of xy ? A.1. B.2. C.3. D.4. e ) 5D. "xy = 3 as x + y = 4 x 2 y 3 + y 2 x 3 = 36 x 2 y 2 ( y + x ) = 36 substituting x + y x 2 y 2 = 4 xy = 4 answer : d"
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Question: what is the least number that should be added to 1054 , so the sum of the number is divisible by 23 ? A.1. B.2. C.3. D.4. e ) 5D. "( 1054 / 23 ) gives a remainder 19 so we need to add 4 . the answer is d ."
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Question: two bullet trains of equal lengths take 10 seconds and 12 seconds respectively to cross a telegraph post . if the length of each bullet train be 120 metres , in what time ( in seconds ) will they cross each other travelling in opposite direction ? A.11 sec .. B.15 sec .. C.12 sec .. D.17 sec .. e ) 19 sec .A. "speed of the first bullet train = 120 / 10 m / sec = 12 m / sec . speed of the second bullet train = 120 / 12 m / sec = 10 m / sec . relative speed = ( 12 + 10 ) = 22 m / sec . required time = ( 120 + 120 ) / 22 sec = 11 sec . a"
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Question: if d is the standard deviation a , b , and c , what is the standard deviation of a + 6 , b + 6 , c + 6 ? A.d. B.6 d. C.6 d + 6. D.6 d + 12. e ) 6 d + 18A. "concept : standard deviation is defined as average deviation of terms in the set from the mean value of the set . i . e . 1 ) it depends on the separation between the successive terms of the set 2 ) if a constant value is added / subtracted in every terms of set then the separation between successive terms does not change hence s . d . remains constant e . g . { 1 , 2 , 3 , 4 , 5 } will have same standard deviation as { 1 + 10 , 2 + 10 , 3 + 10 , 4 + 10 , 5 + 10 } 3 ) if a constant value is multiplied in every terms then the separation between succesive terms gets multiplied by the constant hence s . d . remains gets multiplied by same number e . g . { 0.7 , 1.4 , 2.1 , 2.8 , 3.5 } will have standard deviation = 0.7 * standard deviation of set { 1 , 2 , 3 , 4 , 5 } when 6 is added in each term of set { a , b , c } then the new set { a + 6 , b + 6 , c + 6 } will remain same as the previous standard deviation i . e . d answer : a"
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Question: 70 % of x is greater than 1 / 3 rd of x by 110 . what is x ? A.100. B.200. C.300. D.350. e ) 400C. "7 x / 10 - x / 3 = 110 11 x / 30 = 110 x = 300 answer : c"
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Question: eight machines , each working at the same constant rate , together can complete a certain job in 20 days . how many additional machines , each working at the same constant rate , will be needed to complete the job in 16 days ? A.4. B.6. C.8. D.10. e ) 2E. "rate of one machine = 1 job / ( 20 * 8 ) days let x = number of machines needed to complete the job in 16 days 1 / ( 8 * 20 ) * 16 * x = 1 job x = 10 10 - 8 = 2 answer : e"
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Question: in a competitive examination in state a , 6 % candidates got selected from the total appeared candidates . state b had an equal number of candidates appeared and 7 % candidates got selected with 80 more candidates got selected than a . what was the number of candidates appeared from each state ? A.7000. B.8000. C.8800. D.8900. e ) 9000B. "state a and state b had an equal number of candidates appeared . in state a , 6 % candidates got selected from the total appeared candidates in state b , 7 % candidates got selected from the total appeared candidates but in state b , 80 more candidates got selected than state a from these , it is clear that 1 % of the total appeared candidates in state b = 80 = > total appeared candidates in state b = 80 x 100 = 8000 = > total appeared candidates in state a = total appeared candidates in state b = 8000"
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Question: the sector of a circle has perimeter of 144 cm and central angle 180 o . find its radius ? A.25 cm. B.32 cm. C.14 cm. D.28 cm. e ) 21 cmD. "let the radius is x cm perimeter of the sector = length of the arc + 2 ( radius ) 144 = ( 180 / 360 * 2 * 22 / 7 * x ) + 2 ( x ) 144 = 22 x / 7 + 2 x 144 = 36 x / 7 36 x = 1008 x = 28 answer : d"
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Question: the dimensions of a room are 10 m x 7 m x 5 m . there are 2 doors and 3 windows in the room . the dimensions of the doors are 1 m x 3 m . one window is of size 2 m x 1.5 m and the other 2 windows are of size 1 m x 1.5 m . the cost of painting the walls at rs . 3 per sq m is ? A.rs . 229. B.rs . 429. C.rs . 129. D.rs . 474. e ) rs . 111D. "area of 4 walls = 2 ( l + b ) h = 2 ( 10 + 7 ) x 5 = 170 sq m area of 2 doors and 3 windows = 2 ( 1 x 3 ) + ( 2 x 1.5 ) + 2 ( 1 x 1.5 ) = 12 sq m area to be planted = 170 - 12 = 158 sq m cost of painting = rs . 158 x 3 = rs . 474 answer : d"
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Question: ravi and kavi start a business by investing Γ’ β€š ΒΉ 2000 and Γ’ β€š ΒΉ 72000 , respectively . find the ratio of their profits at the end of year . A.2 : 36. B.5 : 36. C.7 : 36. D.1 : 36. e ) 3 : 36D. "ratio of profit = ratio of investments = 2000 : 72000 = 1 : 36 answer : d"
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Question: the owner of a furniture shop charges his customer 25 % more than the cost price . if a customer paid rs . 1000 for a computer table , then what was the cost price of the computer table ? A.620. B.400. C.45. D.500. e ) 800E. "cp = sp * ( 100 / ( 100 + profit % ) ) = 1000 ( 100 / 125 ) = rs . 800 . answer : e"
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Question: a worker earns $ 20 on the first day and spends $ 15 on the second day . the worker earns $ 20 on the third day and spends $ 15 on the fourth day . if this pattern continues , on which day will the worker first reach a net total of $ 100 ? A.30. B.33. C.35. D.38. e ) 40B. "every two days , the net total is $ 5 . after 32 days , the worker will have $ 80 . on day 33 , the worker will receive $ 20 for a net total of $ 100 . the answer is b ."
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Question: john makes $ 60 a week from his job . he earns a raise and now makes $ 100 a week . what is the % increase ? A.16 %. B.66.67 %. C.17 %. D.17.61 %. e ) 17.56 %B. "increase = ( 40 / 60 ) * 100 = ( 4 / 6 ) * 100 = 66.67 % . b"
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Question: 6 men and 8 women can complete a work in 10 days . 26 men and 48 women can finish the same work in 2 days . 15 men and 20 women can do the same work in - days . A.4 days. B.6 days. C.2 days. D.8 days. e ) 10 daysA. "explanation : let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b work done by 6 men and 8 women in 1 day = 1 / 10 = > 6 m + 8 b = 1 / 10 = > 60 m + 80 b = 1 - - - ( 1 ) work done by 26 men and 48 women in 1 day = 1 / 2 = > 26 m + 48 b = Β½ = > 52 m + 96 b = 1 - - - ( 2 ) solving equation 1 and equation 2 . we get m = 1 / 100 and b = 1 / 200 work done by 15 men and 20 women in 1 day = 15 / 100 + 20 / 200 = 1 / 4 = > time taken by 15 men and 20 women in doing the work = 4 days answer : option a"
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Question: a farmer has an apple orchard consisting of fuji and gala apple trees . due to high winds this year 10 % of his trees cross pollinated . the number of his trees that are pure fuji plus the cross - pollinated ones totals 153 , while 3 / 4 of all his trees are pure fuji . how many of his trees are pure gala ? A.22. B.33. C.55. D.27. e ) 88D. "let f = pure fuji , g = pure gala and c - cross pollinated . c = 10 % of x where x is total trees . c = . 1 x also 3 x / 4 = f and c + f = 153 = > . 1 x + 3 / 4 x = 153 = > x = 180 180 - 153 = pure gala = 27 . d"
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Question: how long does a bus 100 m long traveling at 50 kmph takes to cross a bridge of 150 m in length ? A.18. B.16. C.15. D.11. e ) 12A. d = 100 + 150 = 250 m s = 50 * 5 / 18 = 125 / 9 t = 250 * 9 / 125 = 18 sec answer : a
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Question: a cistern 5 m long and 4 m wide contains water up to a depth of 1 m 25 cm . the total area of the wet surface is : A.49 m 2. B.42.5 m 2. C.53.5 m 2. D.55 m 2. e ) 57 m 2B. "area of the wet surface = [ 2 ( lb + bh + lh ) - lb ] = 2 ( bh + lh ) + lb = [ 2 ( 4 x 1.25 + 5 x 1.25 ) + 5 x 4 ] m 2 = 42.5 m 2 . answer : option b"
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Question: a sun is divided among x , y and z in such a way that for each rupee x gets , y gets 45 paisa and z gets 50 paisa . if the share of y is rs . 63 , what is the total amount ? A.115. B.273. C.117. D.118. e ) 119B. "x : y : z = 100 : 45 : 50 20 : 9 : 10 9 - - - 63 39 - - - ? = > 273 answer : b"
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Question: find the value of 1 / ( 3 + 1 / ( 3 + 1 / ( 3 - 1 / 3 ) ) ) A.21 / 29. B.27 / 89. C.89 / 21. D.29 / 21. e ) noneB. 1 / [ 3 + ( 1 / ( 3 + 1 / ( 3 - 1 / 3 ) ) ) ] = > 1 / [ 3 + 1 / ( 3 + 1 / ( 8 / 3 ) ) ] = > 1 / [ 3 + 1 / ( 3 + 3 / 8 ) ] = > 1 / [ 3 + 8 / 27 ] = > 1 / ( 89 / 27 ) = > 27 / 89 b
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Question: if a - b = 5 and a 2 + b 2 = 31 , find the value of ab . A.9. B.2. C.3. D.7. e ) 12C. "2 ab = ( a 2 + b 2 ) - ( a - b ) 2 = 31 - 25 = 6 ab = 3 . answer : c"
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Question: if circles x and y have the same area and circle x has a circumference of 18 Ο€ , half of the radius of circle y is : A.16. B.4.5. C.4. D.2. e ) 1B. "x be radius of circle x y be radius of circle y given : pi * x ^ 2 = pi * y ^ 2 also , 2 * pi * x = 18 * pi x = 9 thus y = 9 y / 2 = 4.5 ans : b"
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Question: the present population of a town is 2000 . population increase rate is 20 % p . a . find the population of town after 1 years ? A.1000. B.2400. C.1500. D.1600. e ) 1250B. "p = 2000 r = 20 % required population of town = p ( 1 + r / 100 ) ^ t = 2000 ( 1 + 20 / 100 ) = 2000 ( 6 / 5 ) = 2400 answer is b"
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Question: the ratio of money with ram and gopal is 7 : 17 and that with gopal and krishan is 7 : 17 . if ram has rs . 490 , krishan has ? A.rs . 2890. B.rs . 2330. C.rs . 1190. D.rs . 1620. e ) rs . 2680A. "ram : gopal = 7 : 17 = 49 : 119 gopal : krishan = 7 : 17 = 119 : 289 ram : gopal : krishan = 49 : 119 : 289 ram : krishan = 49 : 289 thus , 49 : 289 = 490 : n & there n = 289 x 490 / 49 = rs . 2890 answer : a"
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Question: by selling an article for $ 195 , a person gains $ 45 . what is the gain % ? A.25 %. B.30 %. C.50 %. D.20 %. e ) 10 %B. s . p . = $ 195 gain = $ 45 c . p . = 195 - 45 = 150 gain % = 45 / 150 * 100 % = 30 % answer is b
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Question: by selling an article at rs . 600 , a profit of 60 % is made . find its cost price ? A.228. B.267. C.375. D.480. e ) 811C. "sp = 600 cp = ( sp ) * [ 100 / ( 100 + p ) ] = 600 * [ 100 / ( 100 + 60 ) ] = 600 * [ 100 / 160 ] = rs . 375 answer : c"
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Question: ray writes a two digit number . he sees that the number exceeds 4 times the sum of its digits by 3 . if the number is increased by 18 , the result is the same as the number formed by reversing the digits . find the number . A.2. B.5. C.6. D.7. e ) 8B. solution : let the two digit number be xy . 4 ( x + y ) + 3 = 10 x + y . . . . . . . ( 1 ) 10 x + y + 18 = 10 y + x . . . . ( 2 ) solving 1 st equation we get 2 x - y = 1 . . . . . ( 3 ) solving 2 nd equation we get y - x = 2 . . . . . ( 4 ) solving 3 and 4 , we get x = 3 and y = 5 answer : b
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Question: how many 3 - digit integers between 311 and 401 , exclusive , are divisible by 3 when the tens digit and the hundered digit are switched ? A.30. B.19. C.22. D.3. e ) 90A. answer is 30 no of digits between 311 and 401 ( exclusive ) = 401 - 311 - 1 = 89 no intergers divisble by 3 = ~ 89 / 3 ~ 30 divsiblivity rule for 3 is sum of all digits must be divisble by 3 . it does n ' t matter if hundred digit and tens digits are switched . e . g 372 is divisble by 3 ( becae 3 + 7 + 2 = 12 ( divisble by 3 ) ) switch digits 732 also divisble by 3 ( becae 7 + 3 + 2 = 12 ( divisble by 3 ) ) divsiblivity rule for 3 is sum of all digits must be divisble by 3 . it does n ' t matter if hundred digit and tens digits are switched . you have right . so it is enough to proceed like usual to find the numbers in a given range that are divisible by 3 . so 399 - 312 / 3 + 1 = 30 . answer : a
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Question: the length of a rectangle is reduced by 22 % . by what % would the width have to be increased to maintain the original area ? A.14 %. B.15 %. C.28 %. D.30 %. e ) 35 %C. "sol . required change = ( 22 * 100 ) / ( 100 - 22 ) = 28.2 % c"
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Question: a can do a piece of work in 28 days and b alone can do it in 10 days . b works at it for 5 days and then leaves . a alone can finish the remaining work in A.5 days. B.6 days. C.7.5 days. D.14 days. e ) 9 daysD. "explanation : b ' s 5 days work = 1 / 10 βˆ— 5 = 1 / 2 remaining work = 1 βˆ’ 1 / 2 = 1 / 2 a can finish work = 28 βˆ— 1 / 2 = 14 days option d"
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Question: if ( x + 3 ) ^ 2 / ( 3 x + 5 ) = 2 , then the difference between the two possible values of x is : A.2. B.4. C.6. D.8. e ) 10A. "( x + 3 ) ^ 2 / ( 3 x + 5 ) = 2 ( x + 3 ) ^ 2 = 2 ( 3 x + 5 ) x ^ 2 + 6 x + 9 = 6 x + 10 x ^ 2 - 1 = 0 ( x - 1 ) ( x + 1 ) = 0 x = 1 or x = - 1 the answer is a ."
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Question: a train 110 m long is running with a speed of 90 km / h . in how many seconds will the train pass a man who is running at 9 km / h in the direction opposite to that in which the train is going ? A.3. B.4. C.5. D.6. e ) 7B. the speed of the train relative to the man = 90 + 9 = 99 km / h . 99000 m / h * 1 h / 3600 s = ( 990 / 36 ) m / s ( 110 m ) / ( 990 / 36 m / s ) = ( 110 * 36 ) / 990 = 36 / 9 = 4 seconds the answer is b .
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Question: the ratio between the length and the breadth of a rectangular park is 2 : 3 if a man cycling along the boundary of the park at the speed of 10 km / hr completes one round in 18 min , then the area of the park ( in sq . m ) is ? A.3000 m. B.9000 m. C.540000 m. D.10000 m. e ) 54000 mC. "perimeter = distance covered in 8 min . = ( 10000 x 18 ) / 60 m = 3000 m . let length = 2 x metres and breadth = 3 x metres . then , 2 ( 2 x + 3 x ) = 3000 or x = 300 . length = 600 m and breadth = 900 m . area = ( 600 x 900 ) m 2 = 540000 m c"
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Question: a car drives 60 miles on local roads at 20 mph , and 195 miles on the highway at 65 mph , what is the average speed of the entire trip ? A.36 mph. B.40 mph. C.44 mph. D.43 mph. e ) 58 mphD. "so the answer is plainly d . . . . we have a general relation for speed , time and distance : v ( velocity ) * t ( time ) = d ( distance ) for first part we have d = 60 miles , and v = 20 mph so we can obtain time : 20 * t = 60 or t = 60 / 20 = 3 hours the needed time to cover 60 miles in the same way we should divide 195 to 65 to find the needed time to cover 195 miles , so t = 3 hours so the total time for covering total distance would be 3 + 3 = 6 hours and total distance is 60 + 195 = 255 miles final stage : average speed is total distance divide to total time : 255 / 6 = 42.5 miles per hour rounded up to 43 mph . . . ."
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Question: a number x is mistakenly divided by 10 instead of being multiplied by 10 . what is the percentage error in the result ? A.- 99 %. B.- 100 %. C.+ 99 %. D.+ 100 %. e ) noneA. solution : actual result = 10 x by mistake it has been divided by 10 = x / 10 % change = [ 10 x - ( 10 / x ) / 10 x ] * 100 = 99 = - 99 % . since , actual value is greater than the wrong value . alternatively , let , x = 10 actual result = 10 * 10 = 100 wrong result = 10 / 10 = 1 . change = ( 1 - 100 ) = - 99 % change = - 99 % . answer : option a
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Question: if x > 3000 , then the value of ( 1.2 x ) / ( 0.5 x - 406 ) is closest to ? A.1 / 6. B.1 / 3. C.10 / 21. D.1 / 2. e ) 3 / 1E. assume x = 3002 ( 1.2 x ) / ( 0.5 x - 406 ) = 3602.4 / ( 3002 * 0.5 - 406 ) = 3602.4 / 1095 = = 3 / 1 e
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