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Question: the market value of a certain machine decreased by 10 percent of its purchase price each year . if the machine was purchased in 1982 for its market value of $ 8000 , what was its market value two years later ?
A.$ 8,000.
B.$ 5,600.
C.$ 3,200.
D.$ 6,400.
e ) $ 800D.
d market value in 1982 = $ 8000 market value in 1983 = $ 8000 - ( $ 8000 x 10 / 100 ) = 8000 - 800 = $ 7200 market value in 1984 = market value in 1983 - ( 10 % of $ 8000 ) = 7200 - 800 = $ 6400 | null |
Question: two numbers are less than third number by 60 % and 74 % respectively . how much percent is the second number less than by the first ?
A.18 %.
B.29 %.
C.35 %.
D.41 %.
e ) none of theseC.
"explanation : let the third number is x . then first number = ( 100 - 60 ) % of x = 40 % of x = 4 x / 10 second number is ( 26 x / 100 ) difference = 4 x / 10 - 26 x / 100 = 14 x / 10 so required percentage is , difference is what percent of first number = > ( 14 x / 100 * 10 / 4 x * 100 ) % = 35 % answer : c" | null |
Question: a 1400 m long train crosses a tree in 100 sec , how much time will it take to pass a platform 700 m long ?
A.288.
B.190.
C.150.
D.188.
e ) 12C.
"l = s * t s = 1400 / 100 s = 14 m / sec . total length ( d ) = 2100 m t = d / s t = 2100 / 14 t = 150 sec answer : c" | null |
Question: the product of two positive integers is 675 and their difference is 2 . what is the bigger number ?
A.21.
B.23.
C.25.
D.27.
e ) 29D.
"let ' s use trial and error to find the two numbers . 25 * 23 = 575 ( too low ) 27 * 25 = 675 the answer is d ." | null |
Question: during the last 4 years , a large truck company purchased diesel at rates of $ 1.2 , $ 1.3 , $ 1.8 and $ 2.1 per gallon . what was the mean cost of diesel over the 4 - year period if the company spends the same amount of dollars on diesel each year ?
A.$ 2.5.
B.$ 2.55.
C.$ 1.52.
D.$ 3.25.
e ) $ 3.0C.
finding the harmonic mean here . hm = 4 / ( 1 / 12 + 1 / 13 + 1 / 18 + 1 / 21 ) = 15.18 c | null |
Question: after spending rs . 5000 on rent , rs . 1500 on milk , rs . 4500 on groceries , rs . 2500 on childrens education rs . 2000 on petrol and rs . 5200 on miscellaneous expenses , mr . kishore saved 10 % of his monthly salary . how much did he save in rs . ?
A.2160.
B.2350.
C.2000.
D.2300.
e ) none of theseD.
"explanation : total exp = 5000 + 1500 + 4500 + 2500 + 2000 + 5200 = 20700 exp in % = 100 - 10 = 90 % , 20700 = 90 % saving = 10 % = 20700 x 10 / 90 = rs . 2300 answer : d" | null |
Question: shekar scored 76 , 65 , 82 , 47 and 85 marks in mathematics , science , social studies , english and biology respectively . what are his average marks ?
A.71.
B.69.
C.75.
D.85.
e ) 90A.
"explanation : average = ( 76 + 65 + 82 + 47 + 85 ) / 5 = 355 / 5 = 71 hence average = 71 answer : a" | null |
Question: at an elementary school , 70 % of the faculty members are women and 60 % of the faculty members are married . if 2 ⁄ 3 of the men are single , what fraction of the women are married ?
A.5 ⁄ 7.
B.7 ⁄ 10.
C.1 ⁄ 3.
D.7 ⁄ 30.
e ) 5 ⁄ 70A.
"plugging in numbers for this . assume 100 faculty members . 70 faculty members are women 30 faculty members are men 60 total faculty members are married 1 / 3 of men are married ( 10 ) , which means 20 men are single 10 of the 60 married faculty members are men , which means that 50 women are married . 50 / 70 women are married , reduced to 5 / 7 ans a" | null |
Question: how many multiples of 4 are there between 12 and 104 , inclusive ?
A.21.
B.22.
C.23.
D.24.
e ) 25D.
"the multiples of 4 are from 4 * 3 up to 4 * 26 . 26 - 3 + 1 = 24 . the answer is d ." | null |
Question: a high school has 400 students 1 / 2 attend the airthmetic club , 5 / 8 attend the physics club and 3 / 4 attend the chemistry club . 3 / 8 attend all 3 clubs . if every student attends at least one club how many students attend exactly 2 clubs .
A.80.
B.70.
C.60.
D.50.
e ) 30D.
"a - club has 200 members ( 1 / 2 of 400 ) b - club has 250 members ( 5 / 8 of 400 ) c - club has 300 members ( 3 / 4 of 400 ) we can create an equation to solve this : 200 + 250 + 300 = n + x + 2 y where n is the number of students , x is the number of students in two clubs , and y is the number of students in three clubs . the question provides y for us ( 150 ) . 750 = 400 + x + 300 x = 50 d" | null |
Question: how many kg of rice at rs . 6.60 per kg . be mixed with 56 kg of rice at rs . 9.60 per kg to get a mixture worth rs . 8.20 per kg
A.56 kg.
B.52 kg.
C.44 kg.
D.49 kg.
e ) none of theseD.
explanation : by the rule of alligation , we have cost of 1 kg of 1 st kind rice cost of 1 kg of 2 nd kind rice 6.6 9.6 price of 1 kg of the mixture 8.2 9.6 - 8.2 = 1.4 8.2 - 6.6 = 1.6 quantity of 1 st kind rice : quantity of 2 nd kind rice = 1.4 : 1.6 = 7 : 8 quantity of 1 st kind rice : 56 = 7 : 8 = > quantity of 1 st kind rice = 56 × 78 = 49 answer : option d | null |
Question: a box measuring 36 inches long by 45 inches wide by 18 inches deep is to be filled entirely with identical cubes . no space is to be left unfilled . what is the smallest number of cubes that can accomplish this objective ?
A.32.
B.34.
C.38.
D.40.
e ) 42D.
"least number of cubes will be required when the cubes that could fit in are biggest . 9 is the biggest number that could divide all three , 36 , 45 and 18 . thus side of cube must be 9 , and total number of cubes = 36 / 9 * 45 / 9 * 18 / 9 = 40 ans d ." | null |
Question: the dimensions of a rectangular solid are 4 inches , 5 inches , and 12 inches . if a cube , a side of which is equal to one of the dimensions of the rectangular solid , is placed entirely within thespherejust large enough to hold the cube , what the ratio of the volume of the cube to the volume within thespherethat is not occupied by the cube ?
A.10 : 17.
B.2 : 5.
C.5 : 16.
D.25 : 7.
e ) 10 : 21E.
answer : e . | null |
Question: tanks a and b are each in the shape of a right circular cylinder . the interior of tank a has a height of 10 meters and a circumference of 8 meters , and the interior of tank b has a height of 8 meters and a circumference of 10 meters . the capacity of tank a is what percent of the capacity of tank b ?
A.90 %.
B.50 %.
C.60 %.
D.70 %.
e ) 80 %E.
"circumference of a = 2 ( pie ) r = 8 so r = 4 / pie volume = pie ( 4 / pie ) ^ 2 * 10 = 160 / pie circumference of b = 2 ( pie ) r = 10 so r = 5 / pie volume = pie ( 5 / pie ) ^ 2 * 8 = 200 / pie so ratio of capacities = 160 / 200 = 0.8 so capacity of a will be 80 % of the capacity of b answer : e" | null |
Question: a person ' s present age is two - fifth of the age of his mother . after 8 years , he will be one - half of the age of his mother . how old is the mother at present
A.38.
B.40.
C.42.
D.44.
e ) 45B.
"explanation : let the mother ' s present age be x years . then , the person ' s present age = ( 2 / 5 x ) years . = > ( 2 / 5 x + 8 / 2 ) = 1 ( x + 8 ) = > 2 ( 2 x + 40 ) = 5 ( x + 8 ) = > x = 40 answer : option b" | null |
Question: in town x , 64 percent of the population are employed , and 47 percent of the population are employed males . what percent of the employed people in town x are females ?
A.16 %.
B.46 %.
C.32 %.
D.24 %.
e ) 52 %D.
"answer b male - employed - 64 % female - employed - 17 % total employed 64 % means total unemployed = 36 % therefore d and e are not correct because female unemployed has to be less than 36 % female - unemployed = 32 % male unemployed = 4 % 48 % + 4 % = 52 % 16 % + 32 % = 48 % plug in a and b in place of 32 % and the sum is not 100 % 17 / 64 = 26 d" | null |
Question: when positive integer n is divided by positive integer j , the remainder is 18 . if n / j = 134.03 , what is value of j ?
A.22.
B.56.
C.78.
D.112.
e ) 600E.
"1 ) we know that decimal part of decimal quotient = { remainder / divisor } so 0.03 , the decimal part of the decimal quotient , must equal the remainder , 18 , divided by the divisor j . 0.03 = 18 / j 0.03 * j = 18 j = 18 / 0.03 = 1800 / 3 = 600 so j = 600 , answer = e ." | null |
Question: the present population of a town is 3744 . population increase rate is 20 % p . a . find the population of town before 2 years ?
A.2500.
B.2600.
C.3500.
D.3600.
e ) 2050B.
"p = 3744 r = 20 % required population of town = p / ( 1 + r / 100 ) ^ t = 3744 / ( 1 + 20 / 100 ) ^ 2 = 3744 / ( 6 / 5 ) ^ 2 = 2600 ( approximately ) answer is b" | null |
Question: at joes steakhouse the hourly wage for a chef is 20 % greater than that of a dishwasher , and the hourly wage of a dishwasher is half as much as the hourly wage of a manager . if a managers wage is $ 6.50 per hour , how much less than a manager does a chef earn each hour ?
A.$ 2.6.
B.$ 2.40.
C.$ 3.40.
D.$ 4.40.
e ) $ 5.40A.
manager wages per hour = $ 6.50 dishwasher wages per hour = half of manager ' s wages . = 1 / 2 ( $ 6.50 ) = = > $ 3.25 chef wages per hour = 20 % greater than dishwasher wages - - > 20 % of $ 3.25 = ( 20 * ( $ 3.25 ) ) / 100 - - > ( $ 65 ) / 100 - - > $ 0.65 therefore , chef wages per hour = $ 3.25 + $ 0.65 = = > $ 3.9 difference of wages between manager and chef = $ 6.50 - $ 3.9 = = > $ 2.6 answer : a | null |
Question: the cost of paint is 60 per kilograme . a kilogram paint covers 20 square feet . how much will it cost to paint the outside of a cube having each side 10 feet ?
['A.3000', 'B.900', 'C.1800', 'D.360', 'e ) none of these']C.
area of cube = 6 × ( side ) 2 = 6 × 10 × 10 = 600 square feet . cost to paint outside of the cube = 600 ⁄ 20 × 60 = 1800 answer c | null |
Question: a man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 0.5 kmph , find his average speed for the total journey ?
A.4.
B.3.5.
C.3.
D.3.1.
e ) 2.8D.
"m = 4.5 s = 2.5 ds = 7 us = 2 as = ( 2 * 7 * 2 ) / 9 = 3.1 answer : d" | null |
Question: the original price of a suit is $ 160 . the price increased 25 % , and after this increase , the store published a 25 % off coupon for a one - day sale . given that the consumers who used the coupon on sale day were getting 25 % off the increased price , how much did these consumers pay for the suit ?
A.$ 140.
B.$ 145.
C.$ 150.
D.$ 155.
e ) $ 160C.
0.75 * ( 1.25 * 160 ) = $ 150 the answer is c . | null |
Question: the least perfect square , which is divisible by each of 21 , 36 and 66 is
A.213414.
B.213424.
C.213434.
D.213444.
e ) none of theseD.
"explanation : l . c . m . of 21 , 36 , 66 = 2772 now , 2772 = 2 x 2 x 3 x 3 x 7 x 11 to make it a perfect square , it must be multiplied by 7 x 11 . so , required number = 2 x 2 x 3 x 3 x 7 x 7 x 11 x 11 = 213444 option d" | null |
Question: a merchant sells an item at a 20 % discount , but still makes a gross profit of 40 percent of the cost . what percent of the cost would the gross profit on the item have been if it had been sold without the discount ?
A.20 %.
B.40 %.
C.50 %.
D.60 %.
e ) 75 %E.
"original sp = x cost = c current selling price = . 8 x ( 20 % discount ) . 8 x = 1.4 c ( 40 % profit ) x = 1.4 / . 8 * c x = 7 / 4 c original selling price is 1.75 c which is 75 % profit answer e" | null |
Question: in a throw of dice what is the probability of getting number greater than 5
A.1 / 7.
B.1 / 6.
C.1 / 11.
D.1 / 13.
e ) 2 / 9B.
"number greater than 5 is 6 , so only 1 number total cases of dice = [ 1,2 , 3,4 , 5,6 ] so probability = 1 / 6 b )" | null |
Question: in a village there are 150 men and 90 women in present time . if in next year population will be p = ( a ^ 2 + b ^ 2 ) ^ 1 / 2 , and in every year men are reduces 4 % . what is population of after 2 year .
A.140.
B.141.
C.142.
D.143.
e ) 147E.
"next year total population = [ 150 ^ 2 + 90 ^ 2 ] ^ . 5 = 174.92 = 175 man decreased by 4 % so total man = 150 * . 96 = 144 women will be = 175 - 144 = 31 so population after two years = [ 135 ^ 2 + 31 ^ 2 ] ^ . 5 = 147.30 = 147 so population after two year = 147 answer : e" | null |
Question: if | x + 132 | = 32 what is the sum of all the values of x .
A.- 264.
B.200.
C.- 64.
D.0.
e ) - 328A.
there will be two cases x + 132 = 32 and x + 132 = - 32 solve for x = > x = 32 - 132 = > x = - 100 or x = - 32 - 132 = > x = - 164 the sum of both values will be - 164 + - 100 = - 264 answer is a | null |
Question: of 60 children , 30 are happy , 10 are sad , and 20 are neither happy nor sad . there are 19 boys and 41 girls . if there are 6 happy boys and 4 sad girls , how many boys are neither happy nor sad ?
A.2.
B.7.
C.6.
D.8.
e ) 10B.
"venn diagrams are useful for multiple values of a single variable e . g . state of mind - happy / sad / neither . when you have two or more variables such as here where you have gender - boy / girl too , it becomes unwieldy . in this case , either use the table or logic . table method is shown above ; here is how you will use logic : there are 6 happy boys . there are 4 sad girls but total 10 sad children . so rest 6 sad children must be sad boys . we have 6 happy boys and 6 sad boys . total we have 19 boys . so 19 - 6 - 6 = 7 boys must be neither happy nor sad . answer ( b )" | null |
Question: a store sells chairs and tables . if the price of 2 chairs and 1 table is 60 % of the price of 1 chair and 2 tables , and the price of 1 table and 1 chair is $ 64 , what is the price , in dollars , of 1 table ? ( assume that every chair has the same price and every table has the same price . )
A.48.
B.52.
C.54.
D.58.
e ) 56E.
"let c = chair ; t = table 2 c + 1 t = 0.6 ( 1 c + 2 t ) or c ( 2 - 0.6 ) = 1.2 t - 1 t or 1.4 c = 0.2 t therefore c = 0.2 / 1.4 t = 1 / 7 t ic + 1 t = 64 or 1 / 7 t + 1 t = 64 therefore t = 64 * 7 / 8 = 56 e" | null |
Question: if the radius of a circle that centers at the origin is 5 , how many points q on the circle have integer coordinates ?
A.4.
B.8.
C.12.
D.15.
e ) 20C.
"i understand this might not be required but i used the equation of a circle . since the origin is at 0 , x ^ 2 + y ^ 2 = 5 ^ 2 . x , y could be + / - ( 0,5 or 5,0 ) - 4 possibilities . x , y could be + / - ( 3,4 or 4,3 ) - 8 possibilities . ans : q = c" | null |
Question: the ratio of the radius of two circles is 1 : 5 , and then the ratio of their areas is ?
A.1 : 7.
B.2 : 9.
C.1 : 25.
D.3 : 7.
e ) 3 : 4C.
"r 1 : r 2 = 1 : 5 î r 1 ^ 2 : î r 2 ^ 2 r 1 ^ 2 : r 2 ^ 2 = 1 : 25 answer : c" | null |
Question: the average of 11 numbers is 60 . out of 11 numbers the average of first 6 no . is 98 , and last 6 numbers is 65 then find 6 th number ?
A.A.318.
B.B.65.
C.C.58.
D.D.62.
e ) e ) 48A.
6 th number = sum of 1 st 6 no . s + sum of last 6 no . s - sum of 11 no . s answer = 6 * 98 + 6 * 65 - 11 * 60 = 318 answer is a | null |
Question: a man bought 40 shares of rs . 60 at 8 discount , the rate of dividend being 1212 % the rate of interest obtained is
A.13.64 %.
B.15.5 %.
C.14 %.
D.14.42 %.
e ) 14.95 %D.
"explanation : face value of a share = rs . 60 he bought each share at rs . 60 - rs . 8 = rs . 52 number of shares = 40 dividend = 12 1 / 2 % = 25 / 2 % dividend per share = 60 × 25 / 2 × 100 = rs . 7.5 total dividend = ( 40 × 7.5 ) ie , he got a dividend of ( 40 × 7.5 ) for an investment of rs . ( 40 × 52 ) interest obtained = 40 × 7.5 × 100 / 40 × 52 = 14.42 % answer : option d" | null |
Question: the area of a triangle is 615 m 2 . if one of its sides is 123 metre , find the length of the perpendicular dropped on that side from opposite vertex .
['A.15 metres', 'B.12 metres', 'C.10 metres', 'D.9 metres', 'e ) none of these']C.
in a triangle , area = 1 ⁄ 2 × length of perpendicular × base or 615 = 1 ⁄ 2 × length of perpendicular × 123 ∴ length of perpendicular = 615 × 2 / 123 = 10 m answer c | null |
Question: in an election between the two candidates , the candidates who gets 60 % of votes polled is wined by 280 votes majority . what is the total number of votes polled ?
A.1400.
B.1500.
C.1600.
D.1700.
e ) 1800A.
note : majority ( 20 % ) = difference in votes polled to win ( 60 % ) & defeated candidates ( 40 % ) 20 % = 60 % - 40 % 20 % - - - - - > 280 ( 20 × 14 = 280 ) 100 % - - - - - > 1400 ( 100 × 14 = 1400 ) a | null |
Question: solve the equation for x : 6 x - 47 + 3 x = 4 + 9 - x
A.4.
B.5.
C.7.
D.9.
e ) 6E.
"e 6 9 x + x = 13 + 47 10 x = 60 = > x = 6" | null |
Question: what is the remainder if 7 ^ 12 is divided by 100 ?
A.1.
B.2.
C.3.
D.4.
e ) 5A.
7 ^ 16 can be written as ( 7 ^ 4 ) ^ 3 if we divide 7 ^ 4 by 100 the reminder is 1 so , ( 7 ^ 4 ) ^ 3 by 100 , the reminder is 1 ^ 3 = 1 answer : a | null |
Question: calculate the average of all the numbers between 10 and 86 which are divisible by 9 .
A.49.5.
B.41.5.
C.45.5.
D.40.5.
e ) 47.5A.
"explanation : numbers divisible by 9 are 18,27 , 36,45 , 54,63 , 72,81 , average = ( 18 + 27 + 36 + 45 + 54 + 63 + 72 + 81 , ) / 8 = 396 / 8 = 49.5 answer : a" | null |
Question: what is the length of a bridge ( in meters ) , which a train 156 meters long and travelling at 45 km / h can cross in 30 seconds ?
A.203.
B.211.
C.219.
D.227.
e ) 235C.
speed = 45 km / h = 45000 m / 3600 s = 25 / 2 m / s in 30 seconds , the train can travel 25 / 2 * 30 = 375 meters 375 = length of train + length of bridge length of bridge = 375 - 156 = 219 meters the answer is c . | null |
Question: zachary is helping his younger brother , sterling , learn his multiplication tables . for every question that sterling answers correctly , zachary gives him 3 pieces of candy . for every question that sterling answers incorrectly , zachary takes away two pieces of candy . after 6 questions , if sterling had answered 2 more questions correctly , he would have earned 31 pieces of candy . how many of the 6 questions did zachary answer correctly ?
A.6.
B.7.
C.8.
D.9.
e ) 10B.
"i got two equations : 3 x - 2 y = 25 x + y = 6 3 x - 2 ( 6 - x ) = 25 3 x - 12 + 2 x = 25 5 x = 37 x = 7.4 or between 7 and 8 . ( ans b )" | null |
Question: the average of first 17 even numbers is ?
A.10.
B.11.
C.18.
D.20.
e ) 24C.
"sum of 17 even numbers = 17 * 18 = 306 average = 306 / 17 = 18 answer : c" | null |
Question: the average of all odd numbers up to 200 is
A.50.
B.100.
C.120.
D.75.
e ) 80B.
"the numbers are 1,3 , 5,7 , - - - - - - - - , 197,199 average = ( 199 - 1 ) / 2 + 1 = 100 answer is b" | null |
Question: a and b are two multiples of 14 , and q is the set of consecutive integers between a and b , inclusive . if q contains 11 multiples of 14 , how many multiples of 7 are there in q ?
A.19.
B.20.
C.21.
D.22.
e ) 23C.
"halfway between the multiples of 14 , there will be another multiple of 7 . the total number of multiples of 7 is 11 + 10 = 21 . the answer is c ." | null |
Question: the ratio between the presents of the a and b is 2 : 3 . if b is 5 years older than a , what will be the ratio of the ages of a and b after 5 years ?
A.3 : 4.
B.1 : 2.
C.2 : 3.
D.5 : 6.
e ) 1 : 3A.
"let a and b ages will be 2 x and 3 x 3 x - 2 x = 5 x = 5 required ratio = 2 x + 5 : 3 x + 5 = 15 : 20 = 3 : 4 answer is a" | null |
Question: a man gains 40 % by selling an article for a certain price . if he sells it at double the price , the percentage of profit will be .
A.130 %.
B.180 %.
C.150 %.
D.160 %.
e ) 170 %B.
"explanation : let the c . p . = x , then s . p . = ( 140 / 100 ) x = 7 x / 5 new s . p . = 2 ( 7 x / 5 ) = 14 x / 5 profit = 14 x / 5 - x = 9 x / 5 profit % = ( profit / c . p . ) * 100 = > ( 9 x / 5 ) * ( 1 / x ) * 100 = 180 % option b" | null |
Question: if x * y = xy – 2 ( x + y ) for all integers x and y , then 1 * ( – 3 ) =
A.– 16.
B.– 11.
C.– 4.
D.4.
e ) 1E.
"1 * ( - 3 ) = 1 * ( - 3 ) - 2 ( 1 + ( - 3 ) ) = - 3 + 4 = 1 option ( e )" | null |
Question: on increasing the price of t . v . sets by 40 % , their sale decreases by 20 % . what is the effect on the revenue receipts of the shop ?
A.4.
B.5.
C.56.
D.12.
e ) 7D.
"explanation : let the price be = rs . 100 , and number of units sold = 100 then , sale value = rs . ( 100 × 100 ) = rs . 10000 new sale value = rs . ( 140 × 80 ) = rs . 11200 increase % = 1200 / 10000 × 100 = 12 % answer : d" | null |
Question: 0.002 x 0.5 = ?
A.0.0001.
B.0.001.
C.0.01.
D.0.1.
e ) none of theseB.
"explanation : 2 x 5 = 10 . sum of decimal places = 4 0.002 x 0.5 = 0.001 answer - b" | null |
Question: a 10 % stock yields 8 % . the market value of the stock is :
A.rs . 72.
B.rs . 125.
C.rs . 112.50.
D.rs . 116.50.
e ) none of theseB.
"solution to obtain rs . 8 , investment = rs . 100 . to obtain rs . 10 , investment = rs . ( 100 / 8 x 10 ) = rs . 125 ∴ market value of rs . 100 stock = rs . 125 answer b" | null |
Question: a certain sum is invested at simple interest at 18 % p . a . for two years instead of investing at 12 % p . a . for the same time period . therefore the interest received is more by rs . 300 . find the sum ?
A.7000.
B.2500.
C.2778.
D.2800.
e ) 2791B.
"let the sum be rs . x . ( x * 18 * 2 ) / 100 - ( x * 12 * 2 ) / 100 = 300 = > 36 x / 100 - 24 x / 100 = 300 = > 12 x / 100 = 300 = > x = 2500 . answer : b" | null |
Question: at a monthly meeting , 3 / 5 of the attendees were males and 7 / 8 of the male attendees arrived on time . if 4 / 5 of the female attendees arrived on time , what fraction of the attendees at the monthly meeting did not arrive on time ?
A.47 / 200.
B.31 / 200.
C.17 / 100.
D.11 / 100.
e ) 7 / 50B.
"males who did not arrive on time are 1 / 8 * 3 / 5 = 3 / 40 of the attendees . females who did not arrive on time are 1 / 5 * 2 / 5 = 2 / 25 of the attendees . the fraction of all attendees who did not arrive on time is 3 / 40 + 2 / 25 = 31 / 200 the answer is b ." | null |
Question: how many quarters are equal to 4 dollars ?
A.16.
B.8.
C.12.
D.9.
e ) 7A.
"4 * 4 = 16 quarters answer : a" | null |
Question: 1391 x 1391 = ?
A.A.1951609.
B.B.1951601.
C.C.1951602.
D.D.1951603.
e ) e ) 1934881E.
"1391 x 1391 = ( 1391 ) 2 = ( 1400 - 9 ) 2 = ( 1400 ) 2 + ( 9 ) 2 - ( 2 x 1400 x 9 ) = 1960000 + 81 - 25200 = 1960081 - 25200 = 1934881 . answer : e" | null |
Question: danny and steve are running towards each other , each one from his own house . danny can reach steve ' s house in 33 minutes of running , which is half the time it takes steve to reach danny ' s house . if the two started to run at the same time , how much time longer will it take steve to reach the halfway point between their houses than danny to reach the halfway point between their houses ?
A.16.5 minutes.
B.33 minutes.
C.49.5 minutes.
D.66 minutes.
e ) 99 minutesA.
"danny ' s time is 33 minutes . the time to reach halfway is 16.5 minutes . steve ' s time is 66 minutes . the time to reach halfway is 33 minutes . the time difference is 33 - 16.5 = 16.5 minutes the answer is a ." | null |
Question: the compound interest on $ 30,000 at 7 % p . a is $ . 4347 . find out the period ( in years ) ?
A.1.
B.1.5.
C.2.
D.2.5.
e ) 3C.
"amount = 30,000 + 4347 = 34347 . . . . . . . . . now by using compound interest formula we get , 30,000 * ( 107 / 100 ) ^ n = 34347 = = = = > n = 2 years ans - c" | null |
Question: a fair 2 sided coin is flipped 4 times . what is the probability that tails will be the result at least twice , but not more than 4 times ?
A.1 / 8.
B.2 / 3.
C.5 / 8.
D.4 / 7.
e ) 3 / 7C.
"at least twice , but not more than 4 timesmeans exactly 2 times , 3 times , 4 times the probability of getting exactly k results out of n flips is nck / 2 ^ n 4 c 2 / 2 ^ 4 + 4 c 3 / 2 ^ 4 = 10 / 16 = 5 / 8 option : c" | null |
Question: i have only 1 $ and 2 $ note . i want to give 95 $ to john . how many maximum number of 1 $ note i need ?
A.53.
B.35.
C.47.
D.95.
e ) 62D.
"to give 95 $ we need of 95 1 $ notes so ans is d" | null |
Question: how many multiples of 6 are less than 5000 , and also multiples of 8 ?
A.104.
B.208.
C.625.
D.832.
e ) 833B.
"lcm of 6 & 8 = 24 tried dividing 5000 by 24 got quotient 208.33 ' so b is answer" | null |
Question: audrey 4 hours to complete a certain job . ferris can do the same job in 3 hours . audrey and ferris decided to collaborate on the job , working at their respective rates . while audrey worked continuously , ferris took 5 breaks of equal length . if the two completed the job together in 2 hours , how many minutes long was each of ferris ’ breaks ?
A.5.
B.6.
C.15.
D.20.
e ) 25B.
"audery and ferris collective work rate : 1 / 4 + 1 / 3 = 7 / 12 collective work time = 12 / 7 = 1.7 hrs job was actually done in = 2 ( includes breaks ) breaks = actual time taken - collective work time = 2 - 1.7 = . 3 hrs = 1 / 2 so ferrais took 5 breaks = . 3 / 5 = . 06 hrs = 6 m so answer is b ) 10 mins" | null |
Question: find the sum of divisors of 544 which are perfect squares .
A.32.
B.64.
C.42.
D.21.
e ) none of theseD.
"544 = 25 + 171 = ( 2 ) 0 + ( 2 ) 1 + ( 2 ) 2 + ( 2 ) 3 + ( 2 ) 4 + ( 2 ) 5 x ( 17 ) 0 + ( 17 ) 1 . here 20 = 1 = 11 a perfect square , 22 and 24 = 16 = 44 are perfect squares , hence , 1 + 4 + 16 = 21 . correct answer is : d" | null |
Question: a glass was filled with 10 ounces of water , and 0.03 ounce of the water evaporated each day during a 20 - day period . what percent of the original amount of water evaporated during this period ?
A.0.006 %.
B.0.06 %.
C.0.6 %.
D.6 %.
e ) 60 %D.
"we are given that 0.03 ounces of water evaporated each day . furthermore , we know that this process happened over a 20 - day period . to calculate the total amount of water that evaporated during this time frame we need to multiply 0.01 by 20 . this gives us : 0.03 x 20 = 0.6 ounces finally , we are asked for “ what percent ” of the original amount of water evaporated during this period . to determine this percentage , we have to make sure we translate the expression correctly . we can translate it to : ( amount evaporated / original amount ) x 100 % ( 0.6 / 10 ) x 100 % ( 6 / 100 ) x 100 % = 6 % answer d" | null |
Question: a cistern is normally filled in 6 hours but takes two hours longer to fill because of a leak in its bottom . if the cistern is full , the leak will empty it in ?
A.33.
B.88.
C.24.
D.99.
e ) 11C.
1 / 6 - 1 / x = 1 / 8 x = 24 answer : c | null |
Question: a mobile battery in 1 hour charges to 20 percent . how much time ( in minute ) will it require more to charge to 50 percent .
A.145.
B.150.
C.175.
D.160.
e ) 130B.
1 hr = 20 percent . thus 15 min = 5 percent . now to charge 50 percent 150 min . answer : b | null |
Question: the diagonals of a rhombus are 10 cm and 12 cm . find its area ?
A.158.
B.60.
C.150.
D.123.
e ) 117B.
"1 / 2 * 10 * 12 = 60 answer : b" | null |
Question: a hollow iron pipe is 21 cm long and its external diameter is 8 cm . if the thickness of the pipe is 1 cm and iron weighs 8 g / cm 3 , then the weight of the pipe is :
A.3.6 kg.
B.3.696 kg.
C.36 kg.
D.36.9 kg.
e ) noneB.
"solution external radius = 4 cm , internal radius = 3 cm . volume of iron = ( 22 / 7 × ( 42 ) - ( 32 ) × 21 ) cm 3 = ( 22 / 7 × 7 × 1 × 21 ) cm 3 = 462 cm 3 . weight of iron = ( 462 x 8 ) gm = 3696 gm = 3.696 kg . answer b" | null |
Question: in the forestside summer camp there are 50 children . 90 % of the children are boys and the rest are girls . the camp administrator decided to make the number of girls only 5 % of the total number of children in the camp . how many more boys must she bring to make that happen ?
A.50 ..
B.45 ..
C.40 ..
D.30 ..
e ) 25 .A.
given there are 50 students in the forestside summer camp , 90 % of 50 = 45 boys and remaining 5 girls . now here 90 % are boys and 10 % are girls . now question is asking about how many boys do we need to add , to make the girls percentage to 5 or 5 % . . if we add 50 to existing 45 then the count will be 95 and the girls number will be 5 as it . now boys are 95 % and girls are 5 % . ( out of 100 students = 95 boys + 5 girls ) . imo option a is correct . | null |
Question: on dividing 109 by a number , the quotient is 9 and the remainder is 1 . find the divisor ?
A.10.
B.12.
C.14.
D.16.
e ) 18B.
"d = ( d - r ) / q = ( 109 - 1 ) / 9 = 108 / 9 = 12 b )" | null |
Question: kathleen can paint a room in 4 hours , and anthony can paint an identical room in 5 hours . how many hours would it take kathleen and anthony to paint both rooms if they work together at their respective rates ?
A.8 / 15.
B.40 / 9.
C.15 / 8.
D.9 / 4.
e ) 15 / 4B.
"( 1 / 4 + 1 / 5 ) t = 2 t = 40 / 9 answer : b" | null |
Question: if 0.75 : x : : 10 : 8 , then x is equal to :
A.A.0.6.
B.B.0.8.
C.C.0.85.
D.D.0.5.
e ) e ) noneA.
"( x * 10 ) = ( 0.75 * 8 ) x = 6 / 10 x = 0.6 answer = a" | null |
Question: there are 2 sections a and b in a class , consisting of 36 and 44 students respectively . if the average weight of section a is 40 kg and that of section b is 35 kg , find the average of the whole class ?
A.35.29 kg.
B.37.25 kg.
C.42.45 kg.
D.55.12 kg.
e ) 29.78 kgB.
total weight of 36 + 44 students = 36 * 44 + 44 * 35 = 2980 average weight of the class is = 2980 / 80 = 37.25 kg answer is b | null |
Question: a box contains 100 pairs of shoes ( 200 shoes in total ) . if two shoes are selected at random , what it is the probability that they are matching shoes ?
A.1 / 190.
B.1 / 20.
C.1 / 199.
D.1 / 10.
e ) 1 / 9C.
"the problem with your solution is that we do n ' t choose 1 shoe from 200 , but rather choose the needed one after we just took one and need the second to be the pair of it . so , the probability would simply be : 1 / 1 * 1 / 199 ( as after taking one at random there are 199 shoes left and only one is the pair of the first one ) = 1 / 199 answer : c ." | null |
Question: the nasdaq index has decreased by 70 % since year 2000 . how much should the index increase in order to gain the same value as in year 2000 ?
A.400 %.
B.80 %.
C.233 %.
D.60 %.
e ) none of the aboveC.
let x be the index in the year 2000 . after the decrease it becomes 0.3 x now for 0.3 x to reach 1 x it has to raise by 0.7 x . the increase needs to be 0.7 x / 0.3 x * 100 = 233.3 % answer c | null |
Question: the sum of three consecutive numbers is 102 . the greatest among these three number is :
A.26.
B.35.
C.29.
D.30.
e ) 31B.
"let the numbers be x , x + 1 and x + 2 then , x + ( x + 1 ) + ( x + 2 ) = 102 3 x = 102 x = 33 greatest number , ( x + 2 ) = 35 . answer : b" | null |
Question: a dishonest dealer claims to sell a product at its cost price . he uses a counterfeit weight which is 20 % less than the real weight . further greed overtook him and he added 40 % impurities to the product . find the net profit percentage of the dealer ?
A.94 %.
B.87.5 %.
C.55 %.
D.56.25 %.
e ) 36 %B.
"the dealer uses weight which is 20 % less than the real weight . or ( 1 - 1 / 5 ) or 4 / 5 of real weight . it means that he is selling $ 4 worth of product for $ 5 . the dealer then further added 50 % impurities to the product . it means that he is selling $ 5 worth of product for $ 7.5 . so his profit is $ 7.5 - $ 4 = $ 3.5 and his profit percent is ( 3.5 / 4 ) * 100 = 87.5 % answer : - b" | null |
Question: if the simple interest on a sum of money for 2 years at 5 % per annum is rs . 52 , what is the compound interest on the same sum at the rate and for the same time ?
A.s . 53.30.
B.s . 53.22.
C.s . 51.219.
D.s . 53.18.
e ) s . 51.10A.
explanation : sum = ( 52 * 100 ) / ( 2 * 5 ) = rs . 520 amount = [ 520 * ( 1 + 5 / 100 ) 2 ] = rs . 573.3 c . i . = ( 573.3 - 520 ) = rs . 53.30 . answer : a | null |
Question: 29 persons can repair a road in 16 days , working 5 hours a day . in how many days will 30 persons , working 6 hours a day , complete the work ?
A.12.88.
B.3.88.
C.13.88.
D.15.
e ) 18.8A.
"let the required number of days be x more persons , less days ( indirect proportion ) more hours , less days ( indirect proportion ) hence we can write as ( persons ) 29 : 30 } : : x : 16 ( hours ) 5 : 6 29 * 5 * 16 = 30 * 6 * x x = 12.88 answer : a" | null |
Question: the income tax in country x is 8 % of any income up to $ 5000 . for incomes over $ 5000 , an 8 % tax is imposed on the first $ 5000 , and a 10 % tax is imposed on the portion of the total income in excess of $ 5000 . if perry paid $ 950 in income tax last month , then what was perry ' s income ?
A.$ 10500.
B.$ 11000.
C.$ 13000.
D.$ 13500.
e ) $ 14,000A.
given : for incomes over $ 5,000 , an 8 % tax is imposed on the first $ 5,000 , and a 10 % tax is imposed on the portion of the total income in excess of $ 5000 . if perry paid $ 950 in income tax last month , then what was perry ' s income ? for first 5000 , 8 % tax then we get 400 $ as tax . now perry paid 950 $ tax . . . we need to check which option is going to yield 550 $ on the remaining amount . a . $ 10,500 - 5000 = 5500 , then we get 10 % tax , we get 550 $ . . . ( $ 10,500 - 5000 - here already for 5000 $ we have calculated the tax and we need to tally for the remaining amount ) 550 + 400 = 950 $ . . . hence this is the option . answer : option a . | null |
Question: a shopkeeper sold an book offering a discount of 5 % and earned a profit of 23.5 % . what would have been the percentage of profit earned if no discount was offered ?
A.140.
B.120.
C.130.
D.110.
e ) 150C.
c 130 % let c . p . be $ 100 . then , s . p . = $ 123.50 let marked price be $ x . then , 95 / 100 x = 123.50 x = 12350 / 95 = $ 130 now , s . p . = $ 130 , c . p . = $ 100 profit % = 30 % . | null |
Question: if n = 2 ^ 0.15 and n ^ b = 8 , b must equal
A.3 / 80.
B.3 / 5.
C.20.
D.5 / 3.
e ) 80 / 3C.
"15 / 100 = 3 / 20 n = 2 ^ 3 / 20 n ^ b = 2 ^ 3 ( 2 ^ 3 / 20 ) ^ b = 2 ^ 3 b = 20 answer : c" | null |
Question: last year sandy saved 10 % of her annual salary . this year , she made 10 % more money than last year , and she saved 6 % of her salary . the amount saved this year was what percent of the amount she saved last year ?
A.66 %.
B.80 %.
C.112 %.
D.136 %.
e ) 148 %A.
"let last year ' s salary be x . last year , sandy save 0.1 x this year , sandy saved 0.06 * 1.1 x = 0.066 x 0.066 x / 0.1 x = 0.66 = 66 % the answer is a ." | null |
Question: the value of a scooter depreciates in such a way that its value of the end of each year is 3 / 4 of its value of the beginning of the same year . if the initial value of the scooter is rs . 40000 , what is the value at the end of 2 years ?
A.3277.
B.2977.
C.22500.
D.6077.
e ) 17112C.
explanation : 40,000 * ( 3 / 4 ) ^ 2 answer : c | null |
Question: 5 years ago , paula was 3 times as old as karl . in 6 years , paula will be twice as old as karl . what is the sum of their ages now ?
A.42.
B.46.
C.50.
D.54.
e ) 58D.
p - 5 = 3 ( k - 5 ) and so p = 3 k - 10 p + 6 = 2 ( k + 6 ) ( 3 k - 10 ) + 6 = 2 k + 12 k = 16 p = 38 p + k = 54 the answer is d . | null |
Question: one fourth of a solution that was 8 % sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight . the second solution was what percent sugar by weight ?
A.74 %.
B.52 %.
C.40 %.
D.18 %.
e ) 8.5 %C.
"say the second solution ( which was 1 / 4 th of total ) was x % sugar , then 3 / 4 * 0.08 + 1 / 4 * x = 1 * 0.16 - - > x = 0.4 . alternately you can consider total solution to be 100 liters and in this case you ' ll have : 75 * 0.08 + 25 * x = 100 * 0.16 - - > x = 0.4 . answer : c ." | null |
Question: a and b invests rs . 2000 and rs . 4000 respectively in a business . if a doubles his capital after 6 months . in what ratio should a and b divide that year ' s profit ?
A.3 : 5.
B.3 : 4.
C.9 : 2.
D.9 : 9.
e ) 3 : 1B.
"( 2 * 6 + 4 * 6 ) : ( 4 * 12 ) 36 : 48 = > 3 : 4 answer : b" | null |
Question: two trains of equal lengths take 8 sec and 15 sec respectively to cross a telegraph post . if the length of each train be 120 m , in what time will they cross other travelling in opposite direction ?
A.22.
B.12.
C.77.
D.10.
e ) 21D.
"speed of the first train = 120 / 8 = 15 m / sec . speed of the second train = 120 / 15 = 8 m / sec . relative speed = 15 + 8 = 23 m / sec . required time = ( 120 + 120 ) / 23 = 10 sec . answer : d" | null |
Question: a certain list consists of 21 different numbers . if n is in the list and n is 5 times the average ( arithmetic mean ) of the other 20 numbers in the list , then n is what fraction of the sum of the 21 numbers in the list ?
A.1 / 20.
B.1 / 6.
C.1 / 5.
D.4 / 21.
e ) 5 / 21C.
"series : a 1 , a 2 . . . . a 20 , n sum of a 1 + a 2 + . . . + a 20 = 20 * x ( x = average ) so , n = 5 * x hence , a 1 + a 2 + . . + a 20 + n = 25 x so , the fraction asked = 5 x / 25 x = 1 / 5 answer c" | null |
Question: danny and steve are running towards each other , each one from his own house . danny can reach steve ' s house in 27 minutes of running , which is half the time it takes steve to reach danny ' s house . if the two started to run at the same time , how much time longer will it take steve to reach the halfway point between their houses than danny to reach the halfway point between their houses ?
A.13.5 minutes.
B.27 minutes.
C.35 minutes.
D.54 minutes.
e ) 81 minutesA.
"danny ' s time is 27 minutes . the time to reach halfway is 13.5 minutes . steve ' s time is 54 minutes . the time to reach halfway is 27 minutes . the time difference is 27 - 13.5 = 13.5 minutes the answer is a ." | null |
Question: mr . loyd wants to fence his square shaped land of 120 sqft each side . if a pole is laid every 12 ft how many poles do he need ?
A.20.
B.30.
C.40.
D.50.
e ) 60C.
"if each side is 120 feet . . then total perimeter is 120 * 4 = 480 poles every 12 feet hence no of poles = 480 / 12 = 40 answer : c" | null |
Question: a number exceeds by 40 from its 3 / 8 part . then the number is ?
A.A.32.
B.B.24.
C.C.64.
D.D.40.
e ) e ) 45C.
"x – 3 / 8 x = 40 x = 64 answer : c" | null |
Question: amar takes as much time in running 22 meters as a car takes in covering 58 meters . what will be the distance covered by amar during the time the car covers 2.6 km ?
A.700 m.
B.978 m.
C.970 m.
D.986 m.
e ) 640 mD.
"distance covered by amar = 22 / 58 ( 2.6 km ) = 11 / 29 ( 2600 ) = 986 m answer : d" | null |
Question: a 340 - liter solution of kola is made from 88 % water , 5 % concentrated kola and the rest is made from sugar . if 3.2 liters of sugar , 10 liter of water and 6.8 liters of concentrated kola were added to the solution , what percent of the solution is made from sugar ?
A.6 % ..
B.7.5 % ..
C.9.2 % ..
D.10.5 % ..
e ) 11 % .B.
"denominator : 340 + 10 + 3.2 + 6.8 = 360 numerator : 340 ( 1 - . 88 - . 05 ) + 3.2 340 ( 0.07 ) + 3.2 23.8 + 3.2 27 ratio : 27 / 360 = 3 / 40 answer : b" | null |
Question: the average age of 28 students in a group is 12 years . when teacher â € ™ s age is included to it , the average increases by one . what is the teacher â € ™ s age in years ?
A.31.
B.36.
C.41.
D.51.
e ) noneC.
"sol . age of the teacher = ( 29 ã — 13 â € “ 28 ã — 12 ) years = 41 years . answer c" | null |
Question: a rectangular tiled patio is composed of 60 square tiles . the rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles . after the change in layout , the patio will still have 60 tiles , and it will still be rectangular . how many rows are in the tile patio before the change in layout ?
A.5.
B.6.
C.10.
D.13.
e ) 8E.
"r * c = 60 and ( r + 4 ) ( c - 2 ) = 60 - - > r = 8 and c = 7 . answer : e ." | null |
Question: when the perimeter of a regular polygon is divided by 5 , the length of a side is 25 . what is the name of the polygon ? what is the perimeter ?
['A.125', 'B.126', 'C.127', 'D.128', 'e ) 129']A.
regular polygon . a polygon with equal sides and equal sides . divided by 5 to get the length of a side . it is the pentagon since it has 5 sides . so p = 5 × s to get the perimeter , just multiply a side by 5 . since 25 × 5 = 125 , the perimeter is 125 . answer a | null |
Question: a vessel of capacity 60 litres is fully filled with pure milk . nine litres of milk is removed from the vessel and replaced with water . nine litres of the solution thus formed is removed and replaced with water . find the quantity of pure milk in the final milk solution ?
A.23.89.
B.72.9.
C.38.3.
D.43.35.
e ) 79.3D.
explanation : let the initial quantity of milk in vessel be t litres . let us say y litres of the mixture is taken out and replaced by water for n times , alternatively . quantity of milk finally in the vessel is then given by [ ( t - y ) / t ] ^ n * t for the given problem , t = 60 , y = 9 and n = 2 . hence , quantity of milk finally in the vessel = [ ( 60 - 9 ) / 60 ] ^ 2 ( 60 ) = 43.35 litres . answer : option d | null |
Question: an empty wooden vessel weighs 8 % of its total weight when filled with paint . if the weight of a partially filled vessel is one half that of a completely filled vessel , what fraction of the vessel is filled .
A.3 / 7.
B.5 / 9.
C.1 / 24.
D.4 / 9.
e ) 2 / 5A.
"an empty wooden vessel weighs 8 % of its total weight when filled with paint : vessel = 0.08 ( vessel + paint ) ; 8 v = v + p ( so the weight of completely filled vessel is 8 v ) p = 7 v ( so the weight of the paint when the vessels is completely filled is 7 v ) . the weight of a partially filled vessel is one half that of a completely filled vessel : v + p ' = 1 / 2 * 8 v ; p ' = 3 v ( so the weight of the paint when the vessels is partially filled is 3 v ) . what fraction of the vessel is filled ? so , we need to find the ratio of the weight of the paint when the vessel iscompletely filledto the weight of the paint when the vessel ispartially filled : p ' / p = 3 v / 7 v = 3 / 7 . answer : a ." | null |
Question: in a government institute 20 nos . staffs are employed . in a festival season their boss give festival allowance to all . he says his accountant to calculate for 30 days @ 100 . also he says balance payment will give to driver and cleaning staff and to be adjust from petty cash . he had given rs . 65000 / - to the accountant . how much amount will taken from petty cash ?
A.A.1000.
B.B.3000.
C.C.3500.
D.D.2500.
e ) e ) 2250A.
for 20 staffs : 300 * 100 * 20 = 60000 for driver and cleaning staff : 300 * 100 * 2 = 6000 from petty cash : 1000 answer is a | null |
Question: if $ 5,000 is invested in an account that earns 4 % interest compounded semi - annually , then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8 % simple yearly interest ?
A.$ 4.
B.$ 8.
C.$ 12.
D.$ 16.
e ) $ 432A.
"solution amount ( ci ) = p + ( 1 + r / n ) ^ nt = 5000 + ( 1 + 0.04 / 2 ) ^ 2 = 5404 amount ( si ) = p + ptr / 100 = 5000 + ( 5000 * 1 * 4 / 100 ) = 5400 difference = 5404 - 5400 = 4 $ a" | null |
Question: an amount of money is to be distributed among faruk , vasim and ranjith in the ratio 3 : 5 : 7 . if vasims share is rs . 1500 , what is the difference between faruk ' s and ranjith ' s shares ?
A.rs 1200.
B.rs 1500.
C.rs 1600.
D.rs 1900.
e ) rs 1700A.
"explanation : let p = faruk , q = vasim , r = ranjith let p = 3 x , q = 5 x and r = 7 x . then , 5 x = 1500 ? x = 300 . p = 900 , q = 1500 and r = 2100 . hence , ( r - p ) = ( 2100 - 900 ) = 1200 answer : a" | null |
Question: in a company of 10 employees , 5 employees earn $ 30,000 , 3 employees earn $ 40,000 , and the 2 highest - paid employees earn the same amount . if the average annual salary for the 10 employees is $ 65,000 , what is the annual salary for each of the highest - paid employees ?
A.$ 190,000.
B.$ 170,000.
C.$ 150,000.
D.$ 130,000.
e ) $ 110,000A.
"5 * 30,000 + 3 * 40,000 + 2 x = 10 * 65,000 2 x = 650,000 - 150,000 - 120,000 2 x = 380,000 x = 190,000 the answer is a ." | null |
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