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--- title: Gradle介绍 slug: /tools/gradle/ --- ## 过滤测试 <https://docs.gradle.org/current/userguide/java_testing.html#simple_name_pattern> ```bash # Executes all tests in SomeTestClass gradle test --tests SomeTestClass # Executes a single specified test in SomeTestClass gradle test --tests SomeTestClass.someSpecificMethod gradle test --tests SomeTestClass.*someMethod* ```
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<properties pageTitle="Serdi varasid Azure automatiseerimine | Microsoft Azure'i" description="Sertide saab salvestada turvaliselt Azure automatiseerimine nii, et nad pääsevad juurde tegevusraamatud või DSC konfiguratsioone autentimiseks Azure ja kolmanda osapoole ressursid. Selles artiklis selgitatakse serdid ja kuidas nendega töötada nii teksti kui ka graafilise loome üksikasju." services="automation" documentationCenter="" authors="mgoedtel" manager="stevenka" editor="tysonn" /> <tags ms.service="automation" ms.devlang="na" ms.topic="article" ms.tgt_pltfrm="na" ms.workload="infrastructure-services" ms.date="02/23/2016" ms.author="magoedte;bwren" /> # <a name="certificate-assets-in-azure-automation"></a>Serdi varasid Azure automatiseerimine Sertide saab salvestada turvaliselt Azure automatiseerimine nii, et nad pääsevad juurde tegevusraamatud või DSC konfiguratsioone **Get-AutomationCertificate** tegevuse abil. See võimaldab teil luua tegevusraamatud ja DSC konfiguratsioone kasutavate serdid autentimine või lisatakse Azure'i või muude tootjate ressursid. >[AZURE.NOTE] Turvaline varasid Azure automatiseerimine kaasata mandaat, serdid, ühendused ja krüptitud muutujate. Varade krüptitud ning talletatud Azure'i automaatika kordumatu võti, mis luuakse iga automatiseerimise konto abil. See võti krüptitud juhtslaidi sertifikaadiga ja talletatud Azure automatiseerimine. Kui kavatsete turvaline vara, automatiseerimise konto võti on lahtikrüptitud juhtslaidi serdiga ja seejärel kasutatud vara krüptimiseks. ## <a name="windows-powershell-cmdlets"></a>Windows PowerShelli cmdlet-käsud Järgmises tabelis cmdlet-käskude kasutatakse luua ja hallata serdi automatiseerimine varasid ning Windows PowerShelli abil. Need saata [Azure PowerShelli moodul](../powershell-install-configure.md) , mis on saadaval kasutamiseks automaatika tegevusraamatud ja DSC konfiguratsioone osana. |Cmdlet-käsud|Kirjeldus| |:---|:---| |[Get-AzureAutomationCertificate](http://msdn.microsoft.com/library/dn913765.aspx)|Kuvatakse teave serdi kohta. Saate tuua ainult sertifikaati Get-AutomationCertificate tegevuse.| |[Uue AzureAutomationCertificate](http://msdn.microsoft.com/library/dn913764.aspx)|Impordib uut serti Azure automatiseerimine.| |[Eemalda – AzureAutomationCertificate](http://msdn.microsoft.com/library/dn913773.aspx)|Eemaldab serdi Azure automatiseerimine.| |[Set - AzureAutomationCertificate](http://msdn.microsoft.com/library/dn913763.aspx)|Määrab atribuutide lüüsiarvutis olemasolev sert, sh serdi faili üleslaadimine ja säte on pfx parool.| ## <a name="activities-to-access-certificates"></a>Tegevuste juurde pääseda serdid Järgmises tabelis tegevuste kasutatakse juurdepääsu serdid käitusjuhendi või DSC konfigureerimine. |Tegevuste|Kirjeldus| |:---|:---| |Get-AutomationCertificate|Saab kasutada käitusjuhendi või DSC konfiguratsiooni sert.| >[AZURE.NOTE] Peaks Vältige muutujat – nimi parameetris Get-AutomationCertificate, kuna see raskendada avastanud sõltuvuste tegevusraamatud või DSC konfiguratsioone ja serdi varasid koostamise ajal. ## <a name="creating-a-new-certificate"></a>Uue serdi loomine Kui loote uue sert, mida CER- või pfx faili üleslaadimine Azure automatiseerimine. Kui märgite tunnistust eksporditav, siis saate edastada selle serdi automatiseerimine Azure'i poest välja. Kui see pole eksporditav, siis seda saab kasutada ainult allkirjastamiseks käitusjuhendi või DSC konfigureerimine. ### <a name="to-create-a-new-certificate-with-the-azure-classic-portal"></a>Azure'i klassikaline portaali luua uut serti 1. Klõpsake konto automatiseerimise **varasid** akna ülaosas. 1. Klõpsake akna allosas **Lisada säte**. 1. Klõpsake **Lisa identimisteavet**. 2. **Mandaadi tüüp** ripploendit, valige **sert**. 3. Tippige väljale **nimi** serdi nimi ja klõpsake paremnoolt. 4. Sirvige CER või pfx-faili. Kui valite pfx-fail, määrake parool ja kas see peaks olema lubatud eksportida. 1. Seejärel klõpsake märkeruutu serdi faili üles laadida ja salvestada uut serti vara. ### <a name="to-create-a-new-certificate-with-the-azure-portal"></a>Azure'i portaalis luua uut serti 1. Klõpsake automatiseerimise kontolt **varad** osa **varad** tera avamiseks. 1. Klõpsake nuppu **serdid** osa **serdid** tera avamiseks. 1. Klõpsake nuppu **Lisa serdi** tera ülaosas. 2. Tippige väljale **nimi** nimi serti. 2. Klõpsake jaotises **serdi faili üleslaadimine** CER- või pfx faili otsimiseks nuppu **Faili valimiseks** . Kui valite pfx-fail, määrake parool ja kas see peaks olema lubatud eksportida. 1. Klõpsake nuppu **Loo** uus sert vara salvestamiseks. ### <a name="to-create-a-new-certificate-with-windows-powershell"></a>Uue serdi loomine Windows PowerShelli abil Valimi järgmised käsud näitab, kuidas luua uus serdi automatiseerimine ja see tähistab eksporditav. See impordib olemasoleva pfx-fail. $certName = 'MyCertificate' $certPath = '.\MyCert.pfx' $certPwd = ConvertTo-SecureString -String 'P@$$w0rd' -AsPlainText -Force New-AzureAutomationCertificate -AutomationAccountName "MyAutomationAccount" -Name $certName -Path $certPath –Password $certPwd -Exportable ## <a name="using-a-certificate"></a>Serdi abil Kasutage **Get-AutomationCertificate** tegevuse kasutada sert. [Get-AzureAutomationCertificate](http://msdn.microsoft.com/library/dn913765.aspx) cmdlet-käsk ei saa kasutada, kuna annab teavet serdi varade, kuid mitte sert. ### <a name="textual-runbook-sample"></a>Teksti käitusjuhendi näidis Järgmine proovi kood näitab, kuidas serdi lisamine rakenduses on käitusjuhendi pilveteenusesse. Selles näites tuuakse parool on krüptitud automatiseerimise muutujat. $serviceName = 'MyCloudService' $cert = Get-AutomationCertificate -Name 'MyCertificate' $certPwd = Get-AutomationVariable –Name 'MyCertPassword' Add-AzureCertificate -ServiceName $serviceName -CertToDeploy $cert ### <a name="graphical-runbook-sample"></a>Graafilised käitusjuhendi näidis Saate lisada mõne **Get-AutomationCertificate** graafilise käitusjuhendi serdi teegi paanil pildiredaktor paremklõpsata ja valida käsu **Add lõuend**. ![](media/automation-certificates/certificate-add-canvas.png) Järgmisel pildil on kujutatud serdiga graafiline käitusjuhendi. See on mõeldud serdi lisamine pilveteenus teksti käitusjuhendi sama näite. Selles näites kasutatakse **UseConnectionObject** parameetri **Saada-TwilioSMS** tegevust, mis kasutab autentimiseks teenusega ühenduse objekti seadmine. [Müügivõimaluste link](automation-graphical-authoring-intro.md#links-and-workflow) tuleb kasutada siin Kuna lingi jada tagasi kogumik, mis sisaldab ühte objekti, mis on andmeühenduse parameeter ei oodanud. ![](media/automation-certificates/add-certificate.png) ## <a name="see-also"></a>Vt ka - [Linkide graafiline koostamine](automation-graphical-authoring-intro.md#links-and-workflow)
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--- title: "Data Science Society" date: 2018-11-18T12:33:46+10:00 featured: true weight: 1 --- Our data science society is a student association that tackles business problems at little to no monetary cost. Student teams of 3-6 partner on your business-driven project to deliver your more minor data science needs. ## Details - __Hours:__ The student teams put in 4-8 hours a week and meet on Wednesdays at 6 pm Mountain as project teams. The projects last 10-11 weeks. - __Skill Level:__ Many of the students are in their second or third year of the program. They have experience with Python and R. - __Project Examples:__ Clients have us build [Shiny](), [Streamlit](), or [PowerBI]() dashboards. We also tackle data automation requests (web scraping, API use, data munging). ## Expectations Many of these projects are proof-of-concept projects. Upperclass data science students are project managers and technical experts. A faculty mentor oversees the student leadership team that supports the project managers. ![](../../images/photos/Society_group_in_action.jpg)
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--- ms.openlocfilehash: 393ab601ccf6110739705c46c50486027b59b304 ms.sourcegitcommit: eb6bef1274b9e6390c7a77ff69bf6a3b94e827fc ms.translationtype: HT ms.contentlocale: de-DE ms.lasthandoff: 10/05/2020 ms.locfileid: "88690969" --- Dieser Artikel baut auf in C# geschriebenem[ Beispielcode](https://github.com/Azure-Samples/live-video-analytics-iot-edge-csharp) auf.
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# WJUIRoutable http 请求组件api ### CocoaPods 安装 ``` 'pod WJUIRoutable' or 'pod WJUIRoutable/API' 'pod WJUIRoutable/Core' ``` ### 要求 * ARC支持 * iOS 6.0+ ### 使用方法 * 在WJConfig配置中心: ``` //WJUIRoutable在配置中心名称 WJUIRoutable : { defaultNavigationController:(String)默认导航控制器名称 routerURLformatter:(String)路由链接格式化器 } ```
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Guaranteed to work with [starterkit-rust](https://github.com/icfpcontest2020/starterkit-rust). Base image `icfpcontest2020/rust:latest` built automatically from `Dockerfile.base`.
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# User Module --- ## Todo - [ ] Protect password with hash bcrypt (WIP) - [ ] Improve put method to allow update registers parts
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--- title: Derleyici Uyarısı (düzey 1) CS2023 ms.date: 07/20/2015 f1_keywords: - CS2023 helpviewer_keywords: - CS2023 ms.assetid: 2201fcbc-0eb6-4a1e-baa0-50c5968d1d92 ms.openlocfilehash: e8061feb31532869bdb1f33d38329061ee3b5300 ms.sourcegitcommit: 3d5d33f384eeba41b2dff79d096f47ccc8d8f03d ms.translationtype: MT ms.contentlocale: tr-TR ms.lasthandoff: 05/04/2018 ms.locfileid: "33315548" --- # <a name="compiler-warning-level-1-cs2023"></a>Derleyici Uyarısı (düzey 1) CS2023 Bir yanıt dosyası içinde belirtildiğinden/noconfig seçeneği yoksayılıyor [/Noconfig](../../csharp/language-reference/compiler-options/noconfig-compiler-option.md) derleyici seçeneği verilmez bir yanıt dosyası içinde belirtildi. Bu uyarı tarafından gizlenen olamaz [/nowarn](../../csharp/language-reference/compiler-options/nowarn-compiler-option.md) seçeneği.
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# 静态服务器 为了方便使用,xmlweb 内置了一个简单的静态服务器的节点组件 Static。当然,在搭建 web 应用时,你可以不使用它或者使用自定义的静态服务器的节点组件。 ## 静态接口 为了了解清楚该组件是如何使用的,我们从一个最简单的示例开始: ```xml <!-- 03-01 --> <i:HTTP xmlns:i='//xmlweb'> <i:Static id='static'/> </i:HTTP> ``` 该静态 web 服务器侦听 8080 端口,并以代码所在的文件目录为工作目录。当然,你最好给它设置一个独立的工作目录。该示例尽管简单,但它可以正常工作,下面是一些可以提供的静态接口属性: - `url`: `String` 描述了允许接受的请求路径集,默认为 `/*` - `root`:`String` 工作目录,默认为代码所在的文件目录 ## 内部结构 为了更好的使用该组件,对 Static 组件的内部做些了解是很有必要的。组件 Static 实质上是一个状态机组件,下面是此组件的视图项: ```xml <Flow xmlns:s='static'> <Router id='router'/> <s:Status id='status'/> <s:Cache id='catch'/> <s:Ranges id='ranges'/> <s:Compress id='compress'/> <s:Output id='output'/> <s:Error id='error'/> </Flow> ``` 从此视图项可以看出,该状态机组件包含若干个子节点组件,下面是各子节点组件的基本用途: - Router:过滤掉所有的非 GET 请求 - Status:获取目录文件的状态属性 - Catch:文件缓存处理 - Ranges: 部分资源的范围请求的处理 - Compress:文件压缩处理 - Output:响应请求 - Error: 处理状态码为 304、412、416、500 的响应 ## 自定义 404 页面 Static 组件节点对不存在的 URL 请求会导致停机,从而将后续处理交给 HTTP 组件节点,而 HTTP 组件节点的处理方式是返回一个简单的 404 页面。我们如果想返回不一样的 404 页面,那么可以自己定义一个组件节点并将其作为 Static 组件节点的后继。如下面的示例所示: ```xml <!-- 03-02 --> <i:HTTP xmlns:i='//xmlweb'> <i:Static id='static'/> <NotFound id='notfound'/> </i:HTTP> ``` 此示例中,所有的 404 响应都会由 NotFound 组件节点完成。该组件的具体定义如下: ```js // 03-03 NotFound: { xml: "<h1>This is not the page you are looking for.</h1>", fun: function (sys, items, opts) { this.on("enter", (e, r) => { r.res.statusCode = 404; r.res.setHeader("Content-Type", "text/html"); r.res.end(this.serialize()); }); } } ``` 当然,这个自定义组件返回的 404 页面还是非常简陋的,你可以进一步修改成你想要的样子。
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README.md
PookMook/CityBuilder.js
bbfbbd6c767115568f0a6e9cbfce49578678ccd9
[ "MIT" ]
null
null
null
README.md
PookMook/CityBuilder.js
bbfbbd6c767115568f0a6e9cbfce49578678ccd9
[ "MIT" ]
null
null
null
# CityBuilder.js City Builder à la Sierra (caesar, pharaoh, etc)
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node/tests.md
shershen08/modern_javascript_frameworks
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[ "MIT" ]
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2018-09-24T18:28:09.000Z
2021-09-28T19:20:26.000Z
node/tests.md
shershen08/modern_javascript_frameworks
16f1f7a9d7c491e77336ae3d81cd999701d58c57
[ "MIT" ]
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2020-07-17T11:48:54.000Z
2022-03-02T04:36:52.000Z
node/tests.md
shershen08/modern_javascript_frameworks
16f1f7a9d7c491e77336ae3d81cd999701d58c57
[ "MIT" ]
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2018-11-08T07:18:53.000Z
2021-07-22T10:41:58.000Z
https://www.coursera.org/learn/writing-running-fixing-code/supplement/DmsyN/revisiting-step-4 ``` Test Your Algorithm Once you have generalized your Algorithm, it is time to test it out. To test it out, you should work it on different instances of the problem than the one(s) you used to come up with it. The goal here is to find out if you mis-generalized before you proceed. We have already seen one instance of mis-generalization in our rectangle problem, in which our algorithm was too specific to the examples from which we had built it (always using r1’s bottom, r2’s left, etc…). Testing on these same examples would not have revealed any problems. In doing this testing, you want to strike a balance—enough testing to give you confidence that your algorithm is correct before you proceed, but not an excessive amount of testing. Note that in this testing, you perform your steps by hand, so it may be somewhat slow for a long or complex algorithm. You can do more extensive testing after you translate your algorithm to code. The tradeoff there is that the computer will execute your test cases (which is fast), but if your algorithm is not correct, you have spent time implementing the wrong algorithm. Here are some guidelines to help you devise a good set of test cases to use in Step 4: Try test cases that are qualitatively different from what you used to design your algorithm. In the case of our rectangle example, the two examples we used to build the algorithm were both fairly similar, but the third example (which we used to show the flaw) was noticeably different—the rectangles overlapped in a very different way. Try to find corner cases—inputs where your algorithm behaves differently. If your algorithm takes a list of things as an input, try it with an empty list. If you count from 1 to N (inclusive), try N=0 (you will count no times) and N=1 (you will count only one time). Try to obtain statement coverage—that is, between all of your test cases, each line in the algorithm should be executed at least once. We will discuss various forms of test case coverage later in the course. Examine your algorithm and see if there are any apparent oddities in its behavior (such as it always answers “true”, it never answers “0” even though that seems like a plausible answer), and think about whether or not you can get a test case where the right answer is something that your algorithm cannot give as its answer ```
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tags.md
bryanbraun/tiffany.blog
5f3269485536db89d517c7e012be18caaf62a6fc
[ "MIT" ]
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tags.md
bryanbraun/tiffany.blog
5f3269485536db89d517c7e012be18caaf62a6fc
[ "MIT" ]
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tags.md
bryanbraun/tiffany.blog
5f3269485536db89d517c7e012be18caaf62a6fc
[ "MIT" ]
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--- title: Posts by Tag layout: tags permalink: /tags/ ---
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posts/2008/12/via-thoughtbot.md
atmos/tumblr.atmos.org
1865e6fe271d4c28047ac50fd4ace154be411ff1
[ "MIT" ]
null
null
null
posts/2008/12/via-thoughtbot.md
atmos/tumblr.atmos.org
1865e6fe271d4c28047ac50fd4ace154be411ff1
[ "MIT" ]
null
null
null
posts/2008/12/via-thoughtbot.md
atmos/tumblr.atmos.org
1865e6fe271d4c28047ac50fd4ace154be411ff1
[ "MIT" ]
2
2019-05-06T18:02:23.000Z
2019-05-06T18:27:47.000Z
<!-- id: 64372818 link: http://tumblr.atmos.org/post/64372818/via-thoughtbot slug: via-thoughtbot date: Thu Dec 11 2008 15:19:50 GMT-0800 (PST) publish: 2008-12-011 tags: title: (via thoughtbot) --> (via thoughtbot) ================ ![](http://31.media.tumblr.com/B0VG4OTsMhdjkc1vOtA3K4Ego1_400.jpg)
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README.md
mauriciocoelho/Cibe
4914ce62d65fa0cf30eb6448a0f3acbac3115eaf
[ "MIT" ]
1
2020-02-21T10:19:08.000Z
2020-02-21T10:19:08.000Z
README.md
mauriciocoelho/Cibe
4914ce62d65fa0cf30eb6448a0f3acbac3115eaf
[ "MIT" ]
2
2021-03-10T04:06:32.000Z
2021-05-10T23:55:56.000Z
README.md
mauriciocoelho/Cibe
4914ce62d65fa0cf30eb6448a0f3acbac3115eaf
[ "MIT" ]
null
null
null
## Sobre CibePorto O CibePorto é um gerenciador de cadastro de pessoas (irmãos) simples, onde possui: - Dashboard. - Cadastro de Congregação. - Cadastro de Pessoas. - Cadastro de Eventos. - Relatório de Pessoas Geral. - Relatório de Cadastro da Pessoa. - Relatório de Aniversários. - Relatório de Eventos. ## Expecificações - Linguagem: PHP 7.3.5 . - Framework: Laravel 6.9.0 . - Banco de Dados: Mysql. ## Instalação - git clone https://github.com/mauriciocoelho/Cibe.git - composer install - cd cibeporto - cp .env.example .env - php artisan migrate - php artisan serve ## Vulnerabilidades de segurança Se você descobrir uma vulnerabilidade de segurança no Laravel, envie um e-mail para [[email protected]]. Todas as vulnerabilidades de segurança serão prontamente tratadas. ## Licença A estrutura do Laravel é um software de código aberto licenciado sob o [MIT license](https://opensource.org/licenses/MIT).
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davisdude/Brady
6f8f8d34ddc0fde9f017233caca6e68e00a6a766
[ "MIT" ]
59
2015-04-02T21:41:36.000Z
2021-11-25T16:20:58.000Z
README.md
davisdude/Brady
6f8f8d34ddc0fde9f017233caca6e68e00a6a766
[ "MIT" ]
2
2016-05-27T20:24:39.000Z
2020-06-10T00:08:08.000Z
README.md
davisdude/Brady
6f8f8d34ddc0fde9f017233caca6e68e00a6a766
[ "MIT" ]
6
2015-08-21T09:37:14.000Z
2021-07-15T20:04:58.000Z
Brady === Brady is a camera library for [LOVE] that features parallax scrolling and aspect ratios. Minimal Example --- Below is a minimal example of using the module. In the repository, you will find a more advanced example/demo [here](#demo) ```lua local Camera = require 'Camera' function love.load() -- Create a camera with a 'width' of 400 x 300 on screen at ( 32, 32 ). -- Because the camera has the flags 'resizable' and 'maintainAspectRatio', the default scaling will take over -- So everything drawn will be scaled up to maximize space within the window, with a 32 pixel buffer from each edge. cam = Camera( 400, 300, { x = 32, y = 32, resizable = true, maintainAspectRatio = true } ) end function love.update( dt ) cam:update() -- Needed to appropriately resize the camera end function love.draw() cam:push() -- By default, translation is half camera width, half camera height -- So this draws a rectangle at the center of the screen. love.graphics.rectangle( 'fill', -32, -32, 64, 64 ) cam:pop() end ``` Demo --- Within the repo is a demo to show off some of the capabilities. To run, follow the instructions found [here](https://love2d.org/wiki/Game_Distribution#Create_a_.love-file). In the demo, the left box shows a close-up view, the right box shows an overview. Use the mouse to create squares using either box. With the mousewheel you can zoom in and out and you can move around using the `wasd` keys and rotate with `q` and `e`. To reset the view, press `o` (for origin). To clear the squares, press `c`, and to reset everything, press `r`. Gotchas --- - Every camera has a layer called `'main'` automatically created. This layer has the same scale as the camera and is used simply to distinguish the layers. - Layers can have an attribute known as the "relativeScale". This value is used to control how fast the layer moves, relative to its scale. For instance, if the layer has a scale of 2 and a relativeScale of .5, it will move at the same speed as the main layer, but will appear twice as large. See [cam:addLayer](#camaddlayer) for more. - `cam.scale` is a number, __not__ a function. Use [cam:scaleBy](#camscaleby) instead. Functions --- ### Camera.newCamera Creates a new camera object. __Synopsis__: `cam = Camera.newCamera( w, h, flags )` or `cam = Camera( w, h, flags )` - `cam`: Table. A new camera object. - `w, h`: Numbers. The width/height of the camera. If the flags `resizable` and `maintainAspectRatio` are set, these are used to determine the scaling needed. Otherwise, it sets the camera to this size. - `flags`: Table. These allow you to set some of the options of the camera without using getter/setter methods. Possible flags are: - `x, y`: _Numbers_ (Default to `0, 0`). The position of the camera on the screen. - `translationX, translationY`: _Numbers_ (Defaults to `0, 0`). The translation of the camera. - `offsetX, offsetY`: _Numbers_ (Default to `w / 2, h / 2`). The amount to offset the camera. - `scale`: _Number_ (Defaults to `1`). The scale of the camera. - `rotation`: _Number_ (Defaults to `0`). The rotation of the camera. - `resizable`: _Boolean_ (Defaults to `false`). `true` if the camera can be resized, `false` if it cannot. - `maintainAspectRatio`: _Boolean_ (Defaults to `false`). `true` if the initial aspect ratio should be maintained, false if it shouldn't. - `center`: _Boolean_ (Defaults to `false`). `true` if offsets should be centered on a screen, false if it shouldn't. - `mode`: _String_ (Defaults to `'transform'`). The [StackType] to use for `push`ing and `pop`ing the camera. - `update`: _Function_. The function called every frame used to control scaling and size. By default, if the camera is resizable, the resizing function is called, passing itself and the results of `cam:getContainerDimensions`. - `resizingFunction`: _Function_. Only called if the `resizable` flag is true. Used to set the width and height of the camera, as well as any other changes due to resizing. By default, the function changes the `aspectRatioScale`, `offsetX` and `offsetY`, `w`, and `h` of the camera and takes the parameters `self`, `containerW`, and `containerH`. - `getContainerDimensions`: _Function_. By default, it returns the width and height of the screen. ### cam:push Prepare the draw area. Pseudonym for [layer:push](#layer-push). __Synopsis__: `cam:push( layer )` - `layer`: `nil`, _String_, or _table_ (Defaults to `'main'`, a layer that is automatically created). The name of the layer (as specified in [cam:addLayer](#camaddlayer)) __or__ the layer, as returned by [cam:addLayer](#camaddlayer). ### cam:pop Used to stop the camera scaling, etc. Pseudonym for [layer:pop](#layer-pop). __Synopsis__: `cam:pop( layer )` - `layer`: `nil`, _String_, or _table_. See [cam:push](#campush) for a detailed description of the layer. By default, this is just the same as calling [love.graphics.pop](#https://love2d.org/wiki/love.graphics.pop), so specifying the layer isn't required unless you want to for stylistic reasons. ### cam:getWorldCoordinates Returns the position within the "world," i.e. what the camera is seeing. Translates mouse coordinates to in-game coordinates. __Synopsis__: `worldX, worldY = cam:getWorldCoordinates( screenX, screenY )` - `worldX, worldY`: _Numbers_. The word-coordinates of the mouse. - `screenX, screenY`: _Numbers_. The coordinates on-screen, i.e. the mouse usually. ### cam:getScreenCoordinates Translates in-game coordinates to the screen. The opposite of [cam:getWorldCoordinates](#camtoworldcoordinates). __Synopsis__: `screenX, screenY = cam:getWorldCoordinates( worldX, worldY )` - `screenX, screenY`: _Numbers_. The coordinates on-screen, i.e. the mouse usually. - `worldX, worldY`: _Numbers_. The word-coordinates of the mouse. ### cam:getMouseWorldCoordinates Short for `cam:getScreenCoordinates( love.mouse.getPosition() )`. See [cam:getScreenCoordinates](#camtoscreencoordinates) for more. __Synopsis__: `screenX, screenY = cam:getMouseWorldCoordinates( layer )` - `screenX, screenY`: _Numbers_. The coordinates on-screen, i.e. the mouse usually. - `layer`: `nil`, _String_, or _table_. See [cam:push](#campush) for a detailed description of the layer. If `nil`, the main layer is used. ### cam:setViewportPosition Set the x and y position of the camera's upper-left corner on-screen. Wrapper function for `cam.x, cam.y = -- etc`. __Synopsis__: `cam:setViewportPosition( x, y )` - `x, y`: _Numbers_. The upper-left corner of the camera. ### cam:getViewportPosition Returns the upper-left x and y position of the camera. __Synopsis__: `x, y = cam:getViewportPosition()` - `x, y`: _Numbers_. The upper-left corner of the camera. ### cam:setOffset Sets the camera's offset, which, by default, is `w / 2` and `h / 2`. __Synopsis__: `cam:setOffset( x, y )` - `x, y`: _Numbers_. The x and y offset for the camera. ### cam:setTranslation Gets the camera's offset. __Synopsis__: `x, y = cam:getOffset()` - `x, y`: _Numbers_. The x and y offset of the camera. ### cam:getTranslation ### cam:increaseTranslation Get/set/increase the translation. ### cam:translate Synonymous with [cam:increaseTranslation](#camincreasetranslation) ### cam:setRotation ### cam:getRotation ### cam:increaseRotation Get/set/increase the rotation. ### cam:rotate Synonymous with [cam:increaseRotation](#camincreaseRotation) ### cam:setScale ### cam:getScale ### cam:increaseScale Get/set/increase the scale. ### cam:scaleBy Increase the scale by a factor. __Synopsis__: `cam:scaleBy( factor )` - `factor`: _Number_. Multiply the scale by this amount. e.g. if the scale is .5 and you `scaleBy` 2, the scale is now 1. ### cam:increaseScaleToPoint Increment the scale, while zooming in to a point __Synopsis__: `cam:increaseScaleToPoint( ds, wx, wy )` - `ds`: _Number_. The amount by which to increment the scale. I.e. if `scale` is _1_ and `ds` is _.1_, then new scale is _1.1_. - `wx, wy`: `nil` or _Numbers_. The __world__ coordinates to zoom into. If left `nil`, defaults to [`cam:getMouseWorldCoordinates()`](#camgetmouseworldcoordinates). ### cam:scaleToPoint Increase the scale by a factor, while zooming to a point __Synopsis__: `cam:scaleToPoint( s, wx, wy )` - `s`: _Number_. The factor by which to increase the scale. I.e. if `scale` is _1_ and `s` is _2_, the new scale is _2_. - `wx, wy`: `nil` or _Numbers_. The _world_ coordinates to zoom into. If left `nil`, defaults to [`cam:getMouseWorldCoordinates()`](#camgetmouseworldcoordinates). ### cam:getLayer Get the specified layer. __Synopsis__: `layer = cam:getLayer( target )` - `target`: _Table_ or _String_. Get the specified layer. If a table is passed, the table is returned. If a string is passed, the layer of the specified name is returned. - `layer`: _Table_ or `nil`. The specified layer, or `nil` if the specified layer does not exist. ### cam:addLayer Create a new layer for the camera. __Synopsis__: `layer = cam:addLayer( name, scale, flags )` - `name`: _String_. The name used to identify the layer. - `scale`: _Number_. The scale of the layer. - `flags`: _Table_. These allow you to specify values for the layer. Possible flags are: - `relativeScale`: _Number_ (Defaults to `1`). The relative scale of the layer. This does __not__ affect the scale in any way; this controls how much the layer is translated. For instance, a layer with a scale of 2 and a relative scale of .5 moves at the same speed as the main layer, it is just twice the size. - `mode`: _String_ (Defaults to `cam.mode`). The [StackType] of the layer. ### layer:push Prepare for the layer's translations. __Synopsis__: `layer:push()` ### layer:pop Ends the layer's translations. By default, it's only [love.graphics.pop]. __Synopsis__: `layer:pop()` [LOVE]: https://love2d.org [StackType]: https://love2d.org/wiki/StackType [love.graphcis.pop]: https://love2d.org/wiki/love.graphics.pop License --- This is under the MIT license, which can be found at the top of [camera.lua](/camera.lua)
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docs/extensibility/debugger/reference/idebugcoreserver3-disableautoattach.md
tommorris/visualstudio-docs.tr-tr
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[ "CC-BY-4.0", "MIT" ]
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docs/extensibility/debugger/reference/idebugcoreserver3-disableautoattach.md
tommorris/visualstudio-docs.tr-tr
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[ "CC-BY-4.0", "MIT" ]
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docs/extensibility/debugger/reference/idebugcoreserver3-disableautoattach.md
tommorris/visualstudio-docs.tr-tr
11f1d23025c44a834e451a92828b7078fdc68a7c
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--- title: IDebugCoreServer3::DisableAutoAttach | Microsoft Docs ms.custom: '' ms.date: 11/04/2016 ms.technology: - vs-ide-sdk ms.topic: conceptual f1_keywords: - IDebugCoreServer3::DisableAutoAttach helpviewer_keywords: - IDebugCoreServer3::DisableAutoAttach ms.assetid: 9d860a20-c154-4df4-ba15-636e0fcd42bf author: gregvanl ms.author: gregvanl manager: douge ms.workload: - vssdk ms.openlocfilehash: 5c8a36e867d4ee7c180b96db6dec004ed4d5227e ms.sourcegitcommit: 6a9d5bd75e50947659fd6c837111a6a547884e2a ms.translationtype: MT ms.contentlocale: tr-TR ms.lasthandoff: 04/16/2018 ms.locfileid: "31106334" --- # <a name="idebugcoreserver3disableautoattach"></a>IDebugCoreServer3::DisableAutoAttach Bu sunucu ile ilişkilendirilen tüm hata ayıklama altyapıları için otomatik ekleme devre dışı bırakır. ## <a name="syntax"></a>Sözdizimi ```cpp HRESULT DisableAutoAttach( void ); ``` ```csharp int DisableAutoAttach(); ``` ## <a name="return-value"></a>Dönüş Değeri Başarılı olursa, döndürür `S_OK`; Aksi takdirde, hata kodunu döndürür. ## <a name="see-also"></a>Ayrıca Bkz. [IDebugCoreServer3](../../../extensibility/debugger/reference/idebugcoreserver3.md)
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vunb/kites-typeorm
526b532d2d7ec22c51ac90df599cbd2ea4a3d9ea
[ "MIT" ]
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README.md
vunb/kites-typeorm
526b532d2d7ec22c51ac90df599cbd2ea4a3d9ea
[ "MIT" ]
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README.md
vunb/kites-typeorm
526b532d2d7ec22c51ac90df599cbd2ea4a3d9ea
[ "MIT" ]
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# kites-typeorm TypeORM for Kites Modeling
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_posts/Historical/1999-09-02-canada.md
Confusedfish/confusedfish.github.io
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[ "CC-BY-3.0" ]
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_posts/Historical/1999-09-02-canada.md
Confusedfish/confusedfish.github.io
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2020-12-30T22:59:17.000Z
2022-02-26T03:28:01.000Z
_posts/Historical/1999-09-02-canada.md
Confusedfish/confusedfish.github.io
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--- layout: post last_modified_at: 2017-12-17T19:00:00-00:00 title: Canada & bit of the United States description: Our first year out together, Canada incl Vancouver, Vancouver Island, Whistler, San Francisco, Las Vegas, New Hampshire, New York thumbSquare: https://instagram.flhr4-2.fna.fbcdn.net/t51.2885-19/891379_1503164956579343_15485354_a.jpg image: https://farm5.staticflickr.com/4681/39115709261_78c948d62a_h.jpg thumbSquare: https://farm1.staticflickr.com/417/32481110406_c0cab227be_q.jpg tags: [ winter, skiing, roadtrip ] country: Canada published: true --- Unfortunately predates our entry to digital cameras but it was a massive year out including: * New York * Vancouver * Vancouver Island * Whistler * Many Hot Springs in British Columbia * San Francisco * Las Vegas * Zion National Park * Bryce Canyon * Arches National Park * Jasper National Park * Peyto Lake * Whitehorse * Edmonton * Ottawa * Montreal * Quebec * Ending with a stay with McIntyre relatives in Lyme New Hampshire
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MehrAlsNix/ext-tinyexpr
80b2a2375e442415310f82e8bffe93d049893fe9
[ "MIT" ]
1
2020-03-15T20:48:22.000Z
2020-03-15T20:48:22.000Z
README.md
MehrAlsNix/ext-tinyexpr
80b2a2375e442415310f82e8bffe93d049893fe9
[ "MIT" ]
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null
null
README.md
MehrAlsNix/ext-tinyexpr
80b2a2375e442415310f82e8bffe93d049893fe9
[ "MIT" ]
null
null
null
# PHP TinyExpression Math evaluation for strings. [![Build Status](https://travis-ci.com/MehrAlsNix/ext-tinyexpr.svg?branch=master)](https://travis-ci.com/MehrAlsNix/ext-tinyexpr) [![Build status](https://ci.appveyor.com/api/projects/status/ih0hlmc8dnv3fji9?svg=true)](https://ci.appveyor.com/project/siad007/ext-tinyexpr) ## TinyExpr Binding [TinyExpr](https://github.com/codeplea/tinyexpr) Bindings for PHP > TinyExpr is a very small parser and evaluation library for evaluating math expressions from C ### Installation #### Linux ``` git clone --branch "master" --depth 1 https://github.com/MehrAlsNix/ext-tinyexpr.git /tmp/tinyexpression cd /tmp/tinyexpression phpize ./configure make make install echo "extension=tinyexpression.so" > /usr/local/etc/php/conf.d/tinyexpression.ini ``` #### Windows tbd. <hr> ### Functions #### tinyexpr_interp <hr> (TinyExpression 0.1.0) <br> <br> tinyexpr_interp - Evaluate math expressions from a `string`. ##### Description ``` tinyexpr_interp ( string $expr ) : float ``` ##### Parameters <b>expr</b> `string` ##### Return Values Returns the evaluated math expression as a `float`. ##### Examples ``` docker-compose build docker-compose up -d docker-compose exec php bash ``` ``` php -r "var_dump(tinyexpr_interp('2*9+8-(5/9)'));" float(25.444444444444) ``` ``` php -r "var_dump(tinyexpr_interp('sin(0.6)'));" float(0.56464247339504) ``` Not parsable expressions will return `NAN`: ``` php -r "var_dump(tinyexpr_interp('(1+2'), is_nan(tinyexpr_interp('(1+2')));" float(NAN) bool(true) ```
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docs/parallel/concrt/reference/network-link-registry-class.md
ANKerD/cpp-docs.pt-br
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docs/parallel/concrt/reference/network-link-registry-class.md
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docs/parallel/concrt/reference/network-link-registry-class.md
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--- title: Classe network_link_registry | Microsoft Docs ms.custom: '' ms.date: 11/04/2016 ms.technology: - cpp-concrt ms.topic: reference f1_keywords: - network_link_registry - AGENTS/concurrency::network_link_registry - AGENTS/concurrency::network_link_registry::add - AGENTS/concurrency::network_link_registry::begin - AGENTS/concurrency::network_link_registry::contains - AGENTS/concurrency::network_link_registry::count - AGENTS/concurrency::network_link_registry::remove dev_langs: - C++ helpviewer_keywords: - network_link_registry class ms.assetid: 3e7b4097-09f1-4252-964e-b15b8f7f7fc6 author: mikeblome ms.author: mblome ms.workload: - cplusplus ms.openlocfilehash: 2798c4abe33e49d2ac6199ad6f9a1013805fde7b ms.sourcegitcommit: 799f9b976623a375203ad8b2ad5147bd6a2212f0 ms.translationtype: MT ms.contentlocale: pt-BR ms.lasthandoff: 09/19/2018 ms.locfileid: "46424411" --- # <a name="networklinkregistry-class"></a>Classe network_link_registry O `network_link_registry` gerencia a classe base abstrata os links entre os blocos de origem e destino. ## <a name="syntax"></a>Sintaxe ``` template<class _Block> class network_link_registry; ``` #### <a name="parameters"></a>Parâmetros *Bloco*<br/> O bloco tipo de dados estão sendo armazenadas em do `network_link_registry`. ## <a name="members"></a>Membros ### <a name="public-typedefs"></a>Typedefs públicos |Nome|Descrição| |----------|-----------------| |`const_pointer`|Um tipo que fornece um ponteiro para um `const` elemento em um `network_link_registry` objeto.| |`const_reference`|Um tipo que fornece uma referência a um `const` elemento armazenado em um `network_link_registry` objeto para leitura e execução de operações constantes.| |`iterator`|Um tipo que fornece um iterador que pode ler ou modificar qualquer elemento em um `network_link_registry` objeto.| |`type`|Um tipo que representa o tipo de bloco armazenado em do `network_link_registry` objeto.| ### <a name="public-methods"></a>Métodos públicos |Nome|Descrição| |----------|-----------------| |[add](#add)|Quando substituído em uma classe derivada, adiciona um link para o `network_link_registry` objeto.| |[begin](#begin)|Quando substituído em uma classe derivada, retorna um iterador para o primeiro elemento no `network_link_registry` objeto.| |[Contém](#contains)|Quando substituído em uma classe derivada, pesquisa o `network_link_registry` objeto para um bloco especificado.| |[count](#count)|Quando substituído em uma classe derivada, retorna o número de itens no `network_link_registry` objeto.| |[remove](#remove)|Quando substituído em uma classe derivada, remove um bloco especificado do `network_link_registry` objeto.| ## <a name="remarks"></a>Comentários O `network link registry` não é seguro para o acesso simultâneo. ## <a name="inheritance-hierarchy"></a>Hierarquia de herança `network_link_registry` ## <a name="requirements"></a>Requisitos **Cabeçalho:** Agents. h **Namespace:** simultaneidade ## <a name="add"></a> Adicionar Quando substituído em uma classe derivada, adiciona um link para o `network_link_registry` objeto. ``` virtual void add(_EType _Link) = 0; ``` ### <a name="parameters"></a>Parâmetros *Link*<br/> Um ponteiro para um bloco a ser adicionado. ## <a name="begin"></a> começar Quando substituído em uma classe derivada, retorna um iterador para o primeiro elemento no `network_link_registry` objeto. ``` virtual iterator begin() = 0; ``` ### <a name="return-value"></a>Valor de retorno Um iterador que trata o primeiro elemento no `network_link_registry` objeto. ### <a name="remarks"></a>Comentários O estado final do iterador é indicado por um `NULL` link. ## <a name="contains"></a> Contém Quando substituído em uma classe derivada, pesquisa o `network_link_registry` objeto para um bloco especificado. ``` virtual bool contains(_EType _Link) = 0; ``` ### <a name="parameters"></a>Parâmetros *Link*<br/> Um ponteiro para um bloco que está sendo procurado no `network_link_registry` objeto. ### <a name="return-value"></a>Valor de retorno `true` Se o bloco foi encontrado, `false` caso contrário. ## <a name="count"></a> Contagem Quando substituído em uma classe derivada, retorna o número de itens no `network_link_registry` objeto. ``` virtual size_t count() = 0; ``` ### <a name="return-value"></a>Valor de retorno O número de itens no objeto `network_link_registry`. ## <a name="remove"></a> Remover Quando substituído em uma classe derivada, remove um bloco especificado do `network_link_registry` objeto. ``` virtual bool remove(_EType _Link) = 0; ``` ### <a name="parameters"></a>Parâmetros *Link*<br/> Um ponteiro para um bloco a ser removido, se encontrado. ### <a name="return-value"></a>Valor de retorno `true` Se o link foi encontrado e removido, `false` caso contrário. ## <a name="see-also"></a>Consulte também [Namespace de simultaneidade](concurrency-namespace.md)<br/> [Classe single_link_registry](single-link-registry-class.md)<br/> [Classe multi_link_registry](multi-link-registry-class.md)
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src/data/NCD/Cat1/SerumIronStudies/README.md
mettlesolutions/coverage_determinations
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src/data/NCD/Cat1/SerumIronStudies/README.md
mettlesolutions/coverage_determinations
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mettlesolutions/coverage_determinations
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# Serum Iron Studies https://www.cms.gov/medicare-coverage-database/details/ncd-details.aspx?NCDId=90&ncdver=1&bc=AAAAgAAAAAAA&
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## 0.1.0(2018-4-21) Create Project
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README.md
FairwindsOps/pentagon
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README.md
reactiveops/pentagon
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# Pentagon # *Pentagon has been deprecated and will no longer be maintained.* ## What is Pentagon? **Pentagon is a cli tool to generate repeatable, cloud-based [Kubernetes](https://kubernetes.io/) infrastructure.** It can be used as a “batteries included” default which can: - provide a network with a cluster - Two HA KOPS based Kubernetes clusters - Segregated multiple development / non-production environments - VPN-based access control - A highly-available network, built across multiple Availability Zones ## How does it work? **Pentagon produces a directory.** The directory defines a basic set of configurations for [Ansible](https://www.ansible.com/), [Terraform](https://www.terraform.io/) and [kops](https://github.com/kubernetes/kops)). When those tools are run in a specific order the result is a VPC with a VPN and a Kubernetes Cluster in AWS. GKE Support is built in but not default. It is designed to be customizable while at the same time built with defaults that fit the needs of most web application companies. ## Getting Started The [Getting Started](docs/getting-started.md) has information about installing Pentagon and creating your first project. Table Of Contents ================= * [Requirements](docs/getting-started.md#requirements) * [Installation](docs/getting-started.md#installation) * [Quick Start Guide](docs/getting-started.md) * [VPC](docs/getting-started.md#vpc-setup) * [VPN](docs/getting-started.md#vpn-setup) * [KOPS](docs/getting-started.md#kops) * [Advanced Usage](docs/getting-started.md#advanced-project-initialization) * [Infrastrucure Repository Overview](docs/overview.md) * [Component](docs/components.md) ## AWS Virtual Private Cloud A VPC configuration is provided with Terraform. Details can be found on the [VPC Setup Page](docs/vpc.md). ## Virtual Private Network Configuration is provided for an OpenVPN setup in the VPC. Details can be found on the [VPN Setup Page](docs/vpn.md). [![CLA assistant](https://cla-assistant.io/readme/badge/reactiveops/pentagon)](https://cla-assistant.io/reactiveops/pentagon)
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LeetCode/DaliyProblem.md
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LeetCode/DaliyProblem.md
sxy22/MyLeetCode
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LeetCode/DaliyProblem.md
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# Leetcode每日一题 # 3/2022 ## 3/22/2022 [440. 字典序的第K小数字](https://leetcode-cn.com/problems/k-th-smallest-in-lexicographical-order/) + long ```java class Solution { public int findKthNumber(int n, int k) { int cur = 1; k -= 1; while (k > 0) { int cnt = cnt(cur, n); if (cnt <= k) { k -= cnt; cur += 1; }else { k -= 1; cur = cur * 10; } } return cur; } private int cnt(int cur, long n) { int cnt = 0; long first = cur; long last = cur; while (first <= n) { cnt += Math.min(last, n) - first + 1; first = first * 10; last = last * 10 + 9; } return cnt; } } ``` ## 3/15/2022 [2044. 统计按位或能得到最大值的子集数目](https://leetcode-cn.com/problems/count-number-of-maximum-bitwise-or-subsets/) ```java class Solution { int cnt = 0; int max_or = -1; public int countMaxOrSubsets(int[] nums) { for (int i = 0; i < nums.length; i++) { dfs(nums, i, nums[i]); } return cnt; } private void dfs(int[] nums, int cur_idx, int cur_or) { if (cur_or > max_or) { max_or = cur_or; cnt = 1; }else if (cur_or == max_or) { cnt += 1; } for (int next_idx = cur_idx + 1; next_idx < nums.length; next_idx++) { dfs(nums, next_idx, cur_or | nums[next_idx]); } } } ``` ## 3/12/2022 [590. N 叉树的后序遍历](https://leetcode-cn.com/problems/n-ary-tree-postorder-traversal/) ```java class Solution { List<Integer> ans; public List<Integer> postorder(Node root) { ans = new ArrayList<>(); if (root == null) return ans; dfs(root); return ans; } private void dfs(Node root) { if (root.children != null) { for (Node node : root.children) { dfs(node); } } ans.add(root.val); } } ``` ## 3/11/2022 [2049. 统计最高分的节点数目](https://leetcode-cn.com/problems/count-nodes-with-the-highest-score/) ```python class Solution: def countHighestScoreNodes(self, parents: List[int]) -> int: n = len(parents) parent2child = collections.defaultdict(list) for i in range(1, n): p = parents[i] parent2child[p].append(i) self.cnt = [-1] * n self.dfs(0, parent2child) max_mul = -1 cnt = -1 for i in range(n): mul = self.get_mul(i, parent2child, n) if mul > max_mul: max_mul = mul cnt = 1 elif mul == max_mul: cnt += 1 return cnt def dfs(self, node, parent2child): cnt = 1 for child in parent2child[node]: cnt += self.dfs(child, parent2child) self.cnt[node] = cnt return cnt def get_mul(self, node, parent2child, n): mul = 1 if len(parent2child[node]) == 0: mul *= n - 1 elif len(parent2child[node]) == 1: l_cnt = self.cnt[parent2child[node][0]] mul *= l_cnt mul *= max(1, n - 1 - l_cnt) else: l_cnt = self.cnt[parent2child[node][0]] r_cnt = self.cnt[parent2child[node][1]] mul *= l_cnt * r_cnt mul *= max(1, n - 1 - l_cnt - r_cnt) return mul ``` ## 3/8/2022 [2055. 蜡烛之间的盘子](https://leetcode-cn.com/problems/plates-between-candles/) ```java class Solution { public int[] platesBetweenCandles(String s, int[][] queries) { int n = s.length(); int[] pre_sum = new int[n]; int[] left = new int[n]; int[] right = new int[n]; int sum = 0; int l = -1; for (int i = 0; i < n; i++) { if (s.charAt(i) == '|') { l = i; pre_sum[i] = sum; }else { sum += 1; } left[i] = l; } int r = n; for (int i = n - 1; i >= 0; i--) { if (s.charAt(i) == '|') { r = i; } right[i] = r; } int m = queries.length; int[] ans = new int[m]; for (int i = 0; i < m; i++) { int le = right[queries[i][0]]; int ri = left[queries[i][1]]; int cnt = 0; if (le <= ri) { cnt = pre_sum[ri] - pre_sum[le]; } ans[i] = cnt; } return ans; } } ``` ## 3/6/2022 [2100. 适合打劫银行的日子](https://leetcode-cn.com/problems/find-good-days-to-rob-the-bank/) ```python class Solution: def goodDaysToRobBank(self, security: List[int], time: int) -> List[int]: if time == 0: return [i for i in range(len(security))] n = len(security) left = [1] * n for i in range(1, n): if security[i - 1] >= security[i]: left[i] = 1 + left[i - 1] right = [1] * n for i in range(n - 2, -1, -1): if security[i + 1] >= security[i]: right[i] = 1 + right[i + 1] ans = [] # print(left) # print(right) for i in range(n): if left[i] - 1 >= time and right[i] - 1 >= time: ans.append(i) return ans ``` # 2/2022 ## 2/25/2022 [2016. 增量元素之间的最大差值](https://leetcode-cn.com/problems/maximum-difference-between-increasing-elements/) ```java class Solution { public int maximumDifference(int[] nums) { int ans = -1; int min = Integer.MAX_VALUE; for (int num : nums) { if (num > min) { ans = Math.max(ans, num - min); }else { min = num; } } return ans; } } ``` ## 2/25/2022 [537. 复数乘法](https://leetcode-cn.com/problems/complex-number-multiplication/) ```python class Solution: def complexNumberMultiply(self, num1: str, num2: str) -> str: s1 = num1.split('+') s2 = num2.split('+') a1, b1 = int(s1[0]), int(s1[1][:-1]) a2, b2 = int(s2[0]), int(s2[1][:-1]) c1 = a1 * a2 - b1 * b2 c2 = a1 * b2 + a2 * b1 return '{}+{}i'.format(c1, c2) ``` ## 2/24/2022 ```java class Solution { int m; int n; public int[] findBall(int[][] grid) { m = grid.length; n = grid[0].length; int[] ans = new int[n]; for (int j = 0; j < n; j++) { ans[j] = dfs(grid, 0, j); } return ans; } private int dfs(int[][] grid, int i, int j) { if (i == m) return j; int dirc = grid[i][j]; if (dirc == 1) { if (j + 1 > n - 1 || grid[i][j + 1] == -1) return -1; return dfs(grid, i + 1, j + 1); }else { if (j - 1 < 0 || grid[i][j - 1] == 1) return -1; return dfs(grid, i + 1, j - 1); } } } ``` ## 2/23/2022 ```python class Solution: def reverseOnlyLetters(self, s: str) -> str: ans = [x for x in s] i, j = 0, len(s) - 1 while i < j: while i < j and not s[i].isalpha(): i += 1 while i < j and not s[j].isalpha(): j -= 1 ans[i], ans[j] = ans[j], ans[i] i += 1 j -= 1 return ''.join(ans) ``` ## 2/21/2022 [838. 推多米诺](https://leetcode-cn.com/problems/push-dominoes/) ```java class Solution: def pushDominoes(self, dominoes: str) -> str: n = len(dominoes) ans = [d for d in dominoes] status = dict() deque = collections.deque() for i in range(n): s = dominoes[i] if s == 'L': deque.append((i, -1)) if s == 'R': deque.append((i, 1)) while deque: status.clear() for i in range(len(deque)): idx, dirc = deque.popleft() if dirc == -1 and idx - 1 >= 0 and ans[idx - 1] == '.': if idx - 1 not in status: status[idx - 1] = 0 status[idx - 1] -= 1 if dirc == 1 and idx + 1 < n and ans[idx + 1] == '.': if idx + 1 not in status: status[idx + 1] = 0 status[idx + 1] += 1 # print(status) for idx in status: if status[idx] == -1: ans[idx] = 'L' deque.append((idx, -1)) if status[idx] == 1: ans[idx] = 'R' deque.append((idx, 1)) return ''.join(ans) ``` ## 2/20/2022 [717. 1比特与2比特字符](https://leetcode-cn.com/problems/1-bit-and-2-bit-characters/) ```java class Solution { public boolean isOneBitCharacter(int[] bits) { int n = bits.length; int i = 0; while (i < n - 1) { if (bits[i] == 1) i += 1; i += 1; } return i == n - 1; } } ``` ## 2/19/2022 [969. 煎饼排序](https://leetcode-cn.com/problems/pancake-sorting/) ```java class Solution { public List<Integer> pancakeSort(int[] arr) { List<Integer> ans = new ArrayList<>(); int n = arr.length; for (int last_idx = n - 1; last_idx > 0; last_idx--) { int idx = last_idx; int max = arr[last_idx]; for (int i = 0; i < last_idx; i++) { if (arr[i] > max) { max = arr[i]; idx = i; } } if (idx == last_idx) continue; reverse(arr, idx); reverse(arr, last_idx); ans.add(idx + 1); ans.add(last_idx + 1); } return ans; } private void reverse(int[] arr, int idx) { int i = 0, j = idx; while (i < j) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; i += 1; j -= 1; } } } ``` ## 2/18/2022 ```java class Solution { public int findCenter(int[][] edges) { int cand1 = edges[0][0]; int cand2 = edges[0][1]; int cand3 = edges[1][0]; int cand4 = edges[1][1]; if (cand1 == cand3 || cand1 == cand4) { return cand1; } return cand2; } } ``` ## 2/17/2022 [688. 骑士在棋盘上的概率](https://leetcode-cn.com/problems/knight-probability-in-chessboard/) ```java class Solution { public double knightProbability(int n, int k, int row, int column) { if (k == 0) return 1.0; double prob[][][] = new double[k + 1][n][n]; int[][] dire = {{-1, 2}, {-1, -2}, {1, 2}, {1, -2}, {-2, 1}, {-2, -1}, {2, -1}, {2, 1}}; for (int step = 0; step <= k; step++) { for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (step == 0) { prob[step][i][j] = 1.0; continue; } for (int[] d : dire) { int di = d[0], dj = d[1]; prob[step][i][j] += get(prob, step - 1, i + di, j + dj, n) / 8; } } } } return prob[k][row][column]; } private double get(double prob[][][], int step, int i, int j, int n) { if (i < 0 || j < 0 || i >= n || j >= n) return 0.0; return prob[step][i][j]; } } ``` ## 2/15/2022 [1380. 矩阵中的幸运数](https://leetcode-cn.com/problems/lucky-numbers-in-a-matrix/) ```java class Solution { public List<Integer> luckyNumbers (int[][] matrix) { int m = matrix.length, n = matrix[0].length; List<Integer> ans = new ArrayList<>(); int[] row_min_idx = new int[m]; int[] col_max = new int[n]; for (int i = 0; i < m; i++) { int min_idx = -1; int min = Integer.MAX_VALUE; for (int j = 0; j < n; j++) { if (matrix[i][j] < min) { min_idx = j; min = matrix[i][j]; } } row_min_idx[i] = min_idx; } for (int i = 0; i < m; i++) { int col = row_min_idx[i]; int val = matrix[i][col]; if (col_max[col] == 0) { col_max[col] = getColMax(matrix, col, m); } if (val == col_max[col]) { ans.add(val); } } return ans; } int getColMax(int[][] matrix, int col, int m) { int max = -1; for (int i = 0; i < m; i++) { max = Math.max(max, matrix[i][col]); } return max; } } ``` ## 2/13/2022 [1189. “气球” 的最大数量](https://leetcode-cn.com/problems/maximum-number-of-balloons/) ```python class Solution: def maxNumberOfBalloons(self, text: str) -> int: w2idx = dict() idx = 0 for w in 'abnlo': w2idx[w] = idx idx += 1 cnt = [0] * 5 for w in text: if w in w2idx: cnt[w2idx[w]] += 1 cnt[w2idx['l']] = cnt[w2idx['l']] // 2 cnt[w2idx['o']] = cnt[w2idx['o']] // 2 return min(cnt) ``` ## 2/12/2022 [1020. 飞地的数量](https://leetcode-cn.com/problems/number-of-enclaves/) ```java class Solution { boolean visited[][]; public int numEnclaves(int[][] grid) { int cnt = 0; int m = grid.length; int n = grid[0].length; visited = new boolean[m][n]; for (int j = 0; j < n; j++) { dfs(grid, 0, j, m, n); dfs(grid, m - 1, j, m, n); } for (int i = 1; i < m - 1; i++) { dfs(grid, i, 0, m, n); dfs(grid, i, n - 1, m, n); } for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { if (grid[i][j] == 1 && !visited[i][j]) { cnt += 1; } } } return cnt; } private void dfs(int[][] grid, int i, int j, int m, int n) { if (i < 0 || j < 0 || i >= m || j >= n) { return; } if (visited[i][j] || grid[i][j] == 0) return; visited[i][j] = true; dfs(grid, i - 1, j, m, n); dfs(grid, i + 1, j, m, n); dfs(grid, i, j - 1, m, n); dfs(grid, i, j + 1, m, n); } } ``` ## 2/11/2022 [1984. 学生分数的最小差值](https://leetcode-cn.com/problems/minimum-difference-between-highest-and-lowest-of-k-scores/) ```java class Solution { public int minimumDifference(int[] nums, int k) { Arrays.sort(nums); int i = 0; int j = i + k - 1; int min = Integer.MAX_VALUE; while (j < nums.length) { min = Math.min(min, nums[j] - nums[i]); i += 1; j += 1; } return min; } } ``` ## 2/10/2022 [1447. 最简分数](https://leetcode-cn.com/problems/simplified-fractions/) + 辗转相除法求a b的最大公因数gcd ```java class Solution { public List<String> simplifiedFractions(int n) { List<String> ans = new ArrayList<>(); for (int deno = 2; deno <= n; deno++) { for (int nume = 1; nume < deno; nume++) { if (gcd(deno, nume) == 1) { ans.add(nume + "/" + deno); } } } return ans; } private int gcd(int a, int b) { if (b == 0) return a; int r = a % b; if (r == 0) { return b; } return gcd(b, r); } } ``` ## 2/9/2022 [2006. 差的绝对值为 K 的数对数目](https://leetcode-cn.com/problems/count-number-of-pairs-with-absolute-difference-k/) ```python class Solution: def countKDifference(self, nums: List[int], k: int) -> int: num_cnt = collections.defaultdict(int) cnt = 0 for num in nums: cnt += num_cnt[num - k] cnt += num_cnt[num + k] num_cnt[num] += 1 return cnt ``` ## 2/8/2022 ```python class Solution: def gridIllumination(self, n: int, lamps: List[List[int]], queries: List[List[int]]) -> List[int]: self.dire = ((-1, 0), (1, 0), (0, -1), (0, 1), (-1, -1), (-1, 1), (1, -1), (1, 1)) self.n = n self.row_cnt = collections.defaultdict(int) self.col_cnt = collections.defaultdict(int) self.dia_sum_cnt = collections.defaultdict(int) self.dia_diff_cnt = collections.defaultdict(int) self.lamp_set = set() for i, j in lamps: if (i, j) not in self.lamp_set: self.lamp_set.add((i, j)) self.row_cnt[i] += 1 self.col_cnt[j] += 1 self.dia_sum_cnt[i + j] += 1 self.dia_diff_cnt[i - j] += 1 ans = [0] * len(queries) for idx in range(len(queries)): i, j = queries[idx] if self.is_open(i, j): ans[idx] = 1 self.shut_adj(i, j) return ans def is_open(self, i, j): return self.row_cnt[i] > 0 or self.col_cnt[j] > 0 or self.dia_sum_cnt[i + j] > 0 or self.dia_diff_cnt[i - j] > 0 def shut(self, i, j): if i < 0 or j < 0 or i >= self.n or j >= self.n: return if (i, j) not in self.lamp_set: return self.lamp_set.remove((i, j)) self.row_cnt[i] -= 1 self.col_cnt[j] -= 1 self.dia_sum_cnt[i + j] -= 1 self.dia_diff_cnt[i - j] -= 1 def shut_adj(self, i, j): self.shut(i, j) for di, dj in self.dire: self.shut(i + di, j + dj) ``` ## 2/7/2022 ```python class Solution: def longestDiverseString(self, a: int, b: int, c: int) -> str: cnt = [[a, 'a'], [b, 'b'], [c, 'c']] ans = [] while 1: cnt = sorted(cnt, key=lambda x : -x[0]) if len(ans) == 0 or ans[-1] != cnt[0][1]: c, ch = cnt[0] idx = 0 else: c, ch = cnt[1] idx = 1 if idx == 0: if c == 0: break elif c == 1: ans.append(ch) cnt[idx][0] -= 1 else: ans.append(ch) ans.append(ch) cnt[idx][0] -= 2 else: if c == 0: break else: ans.append(ch) cnt[idx][0] -= 1 return ''.join(ans) ``` # 2/6/2022 [1748. 唯一元素的和](https://leetcode-cn.com/problems/sum-of-unique-elements/) ```python class Solution: def sumOfUnique(self, nums: List[int]) -> int: cnt = collections.defaultdict(int) ans = 0 for num in nums: if cnt[num] == 0: ans += num cnt[num] += 1 elif cnt[num] == 1: ans -= num cnt[num] = -1 return ans ``` ## 2/5/2022 [1219. 黄金矿工](https://leetcode-cn.com/problems/path-with-maximum-gold/) ```java class Solution { // boolean[][] visited; int[][] dire = {{-1, 0}, {1, 0}, {0, -1}, {0, 1}}; public int getMaximumGold(int[][] grid) { int m = grid.length; int n = grid[0].length; // visited = new boolean[m][n]; int max = 0; for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { if (grid[i][j] != 0) { max = Math.max(max, dfs(grid, i, j, m, n)); } } } return max; } private int dfs(int[][] grid, int i, int j, int m, int n) { if (i < 0 || j < 0 || i >= m || j >= n || grid[i][j] == 0) { return 0; } //visited[i][j] = true; int copy = grid[i][j]; grid[i][j] = 0; int max = 0; for (int[] d : dire) { int di = d[0], dj = d[1]; int ni = i + di, nj = j + dj; max = Math.max(max, dfs(grid, ni, nj, m, n)); } //visited[i][j] = false; grid[i][j] = copy; return max + grid[i][j]; } } ``` ## 2/4/2022 [1725. 可以形成最大正方形的矩形数目](https://leetcode-cn.com/problems/number-of-rectangles-that-can-form-the-largest-square/) ```java class Solution { public int countGoodRectangles(int[][] rectangles) { int maxlen = 0; int cnt = 0; for (int[] rec : rectangles) { int len = Math.min(rec[0], rec[1]); if (len == maxlen) { cnt += 1; }else if (len > maxlen) { maxlen = len; cnt = 1; } } return cnt; } } ``` ## 2/3/2022 [1414. 和为 K 的最少斐波那契数字数目](https://leetcode-cn.com/problems/find-the-minimum-number-of-fibonacci-numbers-whose-sum-is-k/) ```python class Solution: def findMinFibonacciNumbers(self, k: int) -> int: arr = [] a, b = 1, 1 while (b <= k): arr.append(b) a, b = b, a + b cnt = 0 i = len(arr) - 1 while k > 0: if arr[i] <= k: k -= arr[i] cnt += 1 else: i -= 1 return cnt ``` ## 2/2/2022 [2000. 反转单词前缀](https://leetcode-cn.com/problems/reverse-prefix-of-word/) ```java class Solution { public String reversePrefix(String word, char ch) { char[] arr = word.toCharArray(); int n = arr.length; int j = 0; while (j < n) { if (arr[j] == ch) { break; } j += 1; } if (j == n) return word; int i = 0; while (i < j) { char temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; i += 1; j -= 1; } return new String(arr); } } ``` # 1/2022 ## 1/31/2022 [1342. 将数字变成 0 的操作次数](https://leetcode-cn.com/problems/number-of-steps-to-reduce-a-number-to-zero/) + 迭代 ```python class Solution: def numberOfSteps(self, num: int) -> int: if num == 0: return 0 if num & 1 == 1: return 1 + self.numberOfSteps(num - 1) else: return 1 + self.numberOfSteps(num // 2) ``` + 遍历 ```java class Solution { public int numberOfSteps(int num) { int step = 0; while (num != 0) { step += 1; if ((num & 1) == 1) { num -= 1; }else { num >>= 1; } } return step; } } ``` ## 1/30/2022 [884. 两句话中的不常见单词](https://leetcode-cn.com/problems/uncommon-words-from-two-sentences/) ```java class Solution { public String[] uncommonFromSentences(String s1, String s2) { Map<String, Integer> map = new HashMap<>(); String[] arr1 = s1.split(" "); String[] arr2 = s2.split(" "); for (String s : arr1) { map.put(s, map.getOrDefault(s, 0) + 1); } for (String s : arr2) { map.put(s, map.getOrDefault(s, 0) + 1); } List<String> ans = new ArrayList<>(); for (String s : map.keySet()) { if (map.get(s) == 1) { ans.add(s); } } return ans.toArray(new String[ans.size()]); } } ``` ## 1/29/2022 [1765. 地图中的最高点](https://leetcode-cn.com/problems/map-of-highest-peak/) ```python class Solution: def highestPeak(self, isWater: List[List[int]]) -> List[List[int]]: self.visited = set() self.deque = collections.deque() m, n = len(isWater), len(isWater[0]) height = [[0] * n for _ in range(m)] # 得从0开始, 把水面点加入 visited 和 deque for i in range(m): for j in range(n): if isWater[i][j] == 1: self.visited.add((i, j)) self.deque.append((i, j, 0)) while self.deque: i, j, val = self.deque.popleft() height[i][j] = val self.addAdj(i, j, m, n, val + 1) return height def addAdj(self, i, j, m, n, val): # 把 i j 相邻位置加入,应该设置的高度为val pair = ((i - 1, j), (i + 1, j), (i, j - 1), (i, j + 1)) for x, y in pair: if (x, y) not in self.visited and 0 <= x < m and 0 <= y < n: self.visited.add((x, y)) self.deque.append((x, y, val)) ``` ## 1/28/2022 [1996. 游戏中弱角色的数量](https://leetcode-cn.com/problems/the-number-of-weak-characters-in-the-game/) + 先按攻击力从小打到,防御力从到到小 + 可以避免相同攻击力,防御力小的被记录为弱角色 + 从后向前遍历,记录最大防御力 ```java class Solution { public int numberOfWeakCharacters(int[][] properties) { Comparator<int[]> cmp = new Comparator<>() { @Override public int compare(int[] p1, int[] p2) { if (p1[0] != p2[0]) { return p1[0] - p2[0]; } return p2[1] - p1[1]; } }; Arrays.sort(properties, cmp); // for (int[] p : properties) { // System.out.println(Arrays.toString(p)); // } int cnt = 0; int maxdef = -1; for (int i = properties.length - 1; i >= 0; i--) { int def = properties[i][1]; if (def < maxdef) { cnt += 1; }else { maxdef = def; } } return cnt; } } ``` + cmp to key会显著的慢 ```python class Solution: def numberOfWeakCharacters(self, properties: List[List[int]]) -> int: # def cmp(p1, p2): # if p1[0] != p2[0]: # return p1[0] - p2[0] # return p2[1] - p1[1] properties = sorted(properties, key=lambda x : (x[0], -x[1])) cnt = 0 maxdef = -1 for _, d in reversed(properties): if d < maxdef: cnt += 1 else: maxdef = d return cnt ``` ## 1/27/2022 [2047. 句子中的有效单词数](https://leetcode-cn.com/problems/number-of-valid-words-in-a-sentence/) ```java class Solution { public int countValidWords(String sentence) { String[] tokens = sentence.split(" "); System.out.println(Arrays.toString(tokens)); int cnt = 0; for (String token : tokens) { cnt += isValid(token); } return cnt; } private int isValid(String token) { if (token.length() == 0) return 0; int j = token.length() - 1; if (isMark(token.charAt(j))) { j -= 1; } if (j < 0) return 1; if (token.charAt(0) == '-' || token.charAt(j) == '-') return 0; int dash = 0; for (int i = 0; i <= j; i++) { char ch = token.charAt(i); if (ch == '-') { dash += 1; if (dash > 1) return 0; } if (Character.isDigit(ch) || isMark(ch)) return 0; } return 1; } private boolean isMark(char s) { if (s == '!' || s == '.' || s == ',') return true; return false; } } ``` ## 1/26/2022 [2013. 检测正方形](https://leetcode-cn.com/problems/detect-squares/) ```java class DetectSquares { Map<Integer, Map<Integer, Integer>> cnt; public DetectSquares() { cnt = new HashMap<>(); } public void add(int[] point) { int x = point[0], y = point[1]; if (!cnt.containsKey(x)) { cnt.put(x, new HashMap<>()); } Map<Integer, Integer> row = cnt.get(x); row.put(y, 1 + row.getOrDefault(y, 0)); } public int count(int[] point) { int ans = 0; int r = point[0], c1 = point[1]; if (!cnt.containsKey(r)) return 0; Set<Integer> colset = cnt.get(r).keySet(); if (colset == null) return 0; for (int c2 : colset) { if (c2 != c1) { int num = getCnt(r, c2); int l = Math.abs(c1 - c2); ans += num * getCnt(r - l, c1) * getCnt(r - l, c2); ans += num * getCnt(r + l, c1) * getCnt(r + l, c2); } } return ans; } int getCnt(int r, int c) { if (!cnt.containsKey(r)) return 0; return cnt.get(r).getOrDefault(c, 0); } // String toString(int x, int y) { // return x + "," + y; // } } ``` ## 1/25/2022 [1688. 比赛中的配对次数](https://leetcode-cn.com/problems/count-of-matches-in-tournament/) ```java class Solution { public int numberOfMatches(int n) { int ans = 0; while (n > 1) { ans += n >> 1; n = (n >> 1) + (n & 1); } return ans; } } ``` ## 1/23/2022 [2034. 股票价格波动](https://leetcode-cn.com/problems/stock-price-fluctuation/) + treemap ```java class StockPrice { int maxtimestap; Map<Integer, Integer> time2price; TreeMap<Integer, Integer> pricecnt; public StockPrice() { maxtimestap = 0; time2price = new HashMap<>(); pricecnt = new TreeMap<>(); } public void update(int timestamp, int price) { maxtimestap = Math.max(maxtimestap, timestamp); int oldprice = time2price.getOrDefault(timestamp, -1); time2price.put(timestamp, price); if (oldprice != -1) { pricecnt.put(oldprice, pricecnt.get(oldprice) - 1); if (pricecnt.get(oldprice) == 0) { pricecnt.remove(oldprice); } } pricecnt.put(price, pricecnt.getOrDefault(price, 0) + 1); } public int current() { return time2price.get(maxtimestap); } public int maximum() { return pricecnt.lastKey(); } public int minimum() { return pricecnt.firstKey(); } } ``` ## 1/22/2022 [1332. 删除回文子序列](https://leetcode-cn.com/problems/remove-palindromic-subsequences/) + 只有 a b + 本身是回文串则删除一次 + 否则所有a组成回文,所有b组成,删除两次 ```java class Solution { public int removePalindromeSub(String s) { int i = 0, j = s.length() - 1; while (i < j) { if (s.charAt(i) != s.charAt(j)) { return 2; } i += 1; j -= 1; } return 1; } } ``` ## 1/21/2022 [1345. 跳跃游戏 IV](https://leetcode-cn.com/problems/jump-game-iv/) ```java class Solution { public int minJumps(int[] arr) { //if (arr.length == 1) return 0; Set<Integer> visited = new HashSet<>(); Map<Integer, List<Integer>> val2idx = new HashMap<>(); Deque<Integer> deque = new LinkedList<>(); deque.add(0); visited.add(0); int n = arr.length; int step = 0; for (int i = 0; i < n; i++) { int val = arr[i]; if (!val2idx.containsKey(val)) { val2idx.put(val, new ArrayList<>()); } val2idx.get(val).add(i); } //System.out.println(val2idx.toString()); while (!deque.isEmpty()) { int l = deque.size(); for (int i = 0; i < l; i++) { int idx = deque.removeFirst(); if (idx == n - 1) return step; if (idx - 1 >= 0 && !visited.contains(idx - 1)) { deque.add(idx - 1); visited.add(idx - 1); } if (idx + 1 < n && !visited.contains(idx + 1)) { deque.add(idx + 1); visited.add(idx + 1); } if (val2idx.containsKey(arr[idx])) { for (int next : val2idx.get(arr[idx])) { if (!visited.contains(next)) { deque.add(next); visited.add(next); } } val2idx.remove(arr[idx]); } } step += 1; } return -1; } } ``` ## 1/19/2022 [219. 存在重复元素 II](https://leetcode-cn.com/problems/contains-duplicate-ii/) ```java class Solution { public boolean containsNearbyDuplicate(int[] nums, int k) { Set<Integer> set = new HashSet<>(); for (int i = 0; i < nums.length; i++) { int num = nums[i]; if (set.contains(num)) return true; set.add(num); if (i - k >= 0) { set.remove(nums[i - k]); } } return false; } } ``` ## 1/18/2022 [539. 最小时间差](https://leetcode-cn.com/problems/minimum-time-difference/) ```java class Solution { public int findMinDifference(List<String> timePoints) { if (timePoints.size() >= 1440) return 0; int min_diff = 1440; List<Integer> minutes = new ArrayList<>(); for (String t : timePoints) { minutes.add(minute(t)); } Collections.sort(minutes); minutes.add(1440 + minutes.get(0)); for (int i = 1; i < minutes.size(); i++) { min_diff = Math.min(min_diff, minutes.get(i) - minutes.get(i - 1)); } return min_diff; } int minute(String t) { int h = Integer.parseInt(t.substring(0, 2)); int m = Integer.parseInt(t.substring(3)); return h * 60 + m; } } ``` ## 1/16/2022 [1220. 统计元音字母序列的数目](https://leetcode-cn.com/problems/count-vowels-permutation/) ```python class Solution: def countVowelPermutation(self, n: int) -> int: M = 1000000007 a, e, i, o, u = 1, 1, 1, 1, 1 for _ in range(n - 1): ta = e + i + u te = a + i ti = e + o to = i tu = i + o a = ta % M e = te % M i = ti % M o = to % M u = tu % M return (a + e + i + o + u) % M ``` ## 1/15/2022 [1716. 计算力扣银行的钱](https://leetcode-cn.com/problems/calculate-money-in-leetcode-bank/) ```python class Solution: def totalMoney(self, n: int) -> int: week = n // 7 day = n % 7 week_sum = (28 + (28 + 7 * (week - 1))) * week // 2 day_sum = day * (day + 1) // 2 + week * day return week_sum + day_sum ``` ## 1/14/2022 [373. 查找和最小的K对数字](https://leetcode-cn.com/problems/find-k-pairs-with-smallest-sums/) ```java class Solution { public List<List<Integer>> kSmallestPairs(int[] nums1, int[] nums2, int k) { List<List<Integer>> ans = new ArrayList<>(); int n = nums1.length, m = nums2.length; PriorityQueue<int[]> pq = new PriorityQueue<>(new Comparator<int[]>() { @Override public int compare(int[] o1, int[] o2) { return nums1[o1[0]] + nums2[o1[1]] - nums1[o2[0]] - nums2[o2[1]]; } }); for (int i = 0; i < n; i++) { pq.add(new int[]{i, 0}); } while (k-- > 0 && !pq.isEmpty()) { int[] first = pq.poll(); int i = first[0], j = first[1]; List<Integer> pair = Arrays.asList(nums1[i], nums2[j]); ans.add(pair); if (j + 1 < m) { pq.add(new int[]{i, j + 1}); } } return ans; } } ``` ## 1/13/2022 [47. 至少是其他数字两倍的最大数](https://leetcode-cn.com/problems/largest-number-at-least-twice-of-others/) ```java class Solution { public int dominantIndex(int[] nums) { if (nums.length == 1) return 0; int fir_idx = 0; int sec_idx = 1; if (nums[0] < nums[1]) { fir_idx = 1; sec_idx = 0; } for (int i = 2; i < nums.length; i++) { if (nums[i] > nums[fir_idx]) { sec_idx = fir_idx; fir_idx = i; }else if (nums[i] > nums[sec_idx]) { sec_idx = i; } } if (nums[fir_idx] >= 2 * nums[sec_idx]) { return fir_idx; } return -1; } } ``` ## 1/12/2022 [334. 递增的三元子序列](https://leetcode-cn.com/problems/increasing-triplet-subsequence/) + 判断当前的数之前以后没有比它更小的数,称为第二大数,需要维护一个min_val + 维护当前最小的第二大数 ```java class Solution { public boolean increasingTriplet(int[] nums) { if (nums.length < 3) return false; int n = nums.length; int min_val = Integer.MAX_VALUE; int min_sec = Integer.MAX_VALUE; for (int val : nums) { // 判断val是否> min_sec if (val > min_sec) return true; // 更新 if (val > min_val && val < min_sec) { min_sec = val; } min_val = Math.min(min_val, val); } return false; } } ``` ## 1/10/2022 [306. 累加数](https://leetcode-cn.com/problems/additive-number/) ```python class Solution: def isAdditiveNumber(self, num: str) -> bool: self.num = num if len(num) < 3: return False for i in range(len(self.num) // 2): fir = int(self.num[:i + 1]) for j in range(i + 1, len(self.num) - 1): sec = int(self.num[i + 1: j + 1]) if self.isValid(fir, sec, j + 1): return True if self.num[i + 1] == "0": break if self.num[0] == "0": break return False def isValid(self, fir: int, sec: int, start): if start == len(self.num): return True third = str(fir + sec) if len(third) > len(self.num) - start: return False for i in range(len(third)): if third[i] != self.num[start]: return False start += 1 return self.isValid(sec, fir + sec, start) ``` ## 1/9/2022 [1629. 按键持续时间最长的键](https://leetcode-cn.com/problems/slowest-key/) ```java class Solution { public char slowestKey(int[] releaseTimes, String keysPressed) { char max_key = keysPressed.charAt(0); int max_time = releaseTimes[0]; for (int i = 1; i < keysPressed.length(); i++) { char key = keysPressed.charAt(i); int time = releaseTimes[i] - releaseTimes[i - 1]; if (time > max_time || (time == max_time && key > max_key)) { max_key = key; max_time = time; } } return max_key; } } ``` ```python class Solution: def slowestKey(self, releaseTimes: List[int], keysPressed: str) -> str: max_key = keysPressed[0] max_time = releaseTimes[0] for i in range(1, len(releaseTimes)): key = keysPressed[i] time = releaseTimes[i] - releaseTimes[i - 1] if time > max_time or (time == max_time and key > max_key): max_key = key max_time = time return max_key ``` ## 1/8/2022 [89. 格雷编码](https://leetcode-cn.com/problems/gray-code/) + 设 n 阶格雷码集合为 G(n),其中数字为n-1位二进制表示 + 将G(n)反转,每个数最前面加上二进制1,放在G(n)后面得到G(n+1) ```java class Solution { public List<Integer> grayCode(int n) { List<Integer> code = new ArrayList<>(); code.add(0); code.add(1); int add = 2; for (int l = 0; l < n - 1; l++) { int i = code.size() - 1; while (i >= 0) { int val = code.get(i); code.add(val + add); i -= 1; } add = add << 1; } return code; } } ``` **Python** ```python class Solution: def grayCode(self, n: int) -> List[int]: code = [0, 1] add = 2 for _ in range(n - 1): for val in reversed(code): code.append(val + add) add = add << 1 return code ``` ## 1/7/2022 [1614. 括号的最大嵌套深度](https://leetcode-cn.com/problems/maximum-nesting-depth-of-the-parentheses/) ```java class Solution { public int maxDepth(String s) { Deque<Integer> stack = new LinkedList<>(); int max_dep = 0; for (int i = 0; i < s.length(); i++) { char ch = s.charAt(i); if (ch == '(') { stack.add(0); } if (ch == ')') { int dep = stack.removeLast() + 1; if (stack.isEmpty()) { max_dep = Math.max(max_dep, dep); }else { stack.add(Math.max(stack.removeLast(), dep)); } } } return max_dep; } } ``` ```java class Solution { public int maxDepth(String s) { int max_dep = 0; int dep = 0; for (int i = 0; i < s.length(); i++) { char ch = s.charAt(i); if (ch == '(') { dep += 1; } if (ch == ')') { dep -= 1; } max_dep = Math.max(max_dep, dep); } return max_dep; } } ``` ## 1/6/2022 [71. 简化路径](https://leetcode-cn.com/problems/simplify-path/) ```java class Solution { public String simplifyPath(String path) { LinkedList<String> stack = new LinkedList<>(); StringBuilder s = new StringBuilder(); path = path + "/"; for (int i = 0; i < path.length(); i++) { char ch = path.charAt(i); if (ch == '/') { if (s.length() == 0) continue; String dirc = s.toString(); s = new StringBuilder(); if (dirc.equals(".")) { //pass }else if (dirc.equals("..")) { if (!stack.isEmpty()) { stack.removeLast(); } }else { stack.add(dirc); } }else { s.append(ch); } } //System.out.println(stack.toString()); return "/" + String.join("/", stack); } } ``` ```python class Solution: def simplifyPath(self, path: str) -> str: step = path.split('/') stack = [] for s in step: if len(s) == 0: continue if s == '.': pass elif s == '..': if stack: stack.pop() else: stack.append(s) return '/' + '/'.join(stack) ``` ## 1/5/2022 [1576. 替换所有的问号](https://leetcode-cn.com/problems/replace-all-s-to-avoid-consecutive-repeating-characters/) ```java class Solution { public String modifyString(String s) { StringBuilder ans = new StringBuilder(s); char left, right; for (int i = 0; i < ans.length(); i++) { if (ans.charAt(i) != '?') { continue; } if (i == 0) { left = '?'; }else { left = ans.charAt(i - 1); } if (i == ans.length() - 1) { right = '?'; }else { right = ans.charAt(i + 1); } ans.setCharAt(i, getchar(left, right)); } return ans.toString(); } char getchar(char left, char right) { char ch = 'a'; for (int i = 0; i < 26; i++) { if (ch != left && ch != right) { return ch; } ch = (char) (ch + 1); } return ' '; } } ``` ## 1/2/2022 [390. 消除游戏](https://leetcode-cn.com/problems/elimination-game/) ```java class Solution { public int lastRemaining(int n) { if (n == 1) return 1; int pre = n / 2; return 2 * (pre - lastRemaining(pre) + 1); } } ``` ```python class Solution: def lastRemaining(self, n: int) -> int: a1 = 1 an = n step = 1 while a1 != an: # print(a1, an) temp = a1 k = (an - a1) // step + 1 if k & 1 == 1: a1 = an - step else: a1 = an an = temp + step step *= -2 return a1 ``` ## 1/1/2022 [2022. 将一维数组转变成二维数组](https://leetcode-cn.com/problems/convert-1d-array-into-2d-array/) + Arrays.copyOfRange ```java class Solution { public int[][] construct2DArray(int[] original, int m, int n) { int L = original.length; if (m * n != L) return new int[0][]; int[][] ans = new int[m][n]; int i = 0; int start = 0; while (i < m) { ans[i] = Arrays.copyOfRange(original, start, start + n); i += 1; start = start + n; } return ans; } } ``` + 直接计算小标i对应的二维下标 ```java class Solution { public int[][] construct2DArray(int[] original, int m, int n) { int L = original.length; if (m * n != L) return new int[0][]; int[][] ans = new int[m][n]; for (int idx = 0; idx < L; idx ++) { int i = idx / n; int j = idx % n; ans[i][j] = original[idx]; } return ans; } } ``` --- # 12/2021 ## 12/31/2021 [507. 完美数](https://leetcode-cn.com/problems/perfect-number/) ```java class Solution { public boolean checkPerfectNumber(int num) { if (num == 1) return false; int sum = 1; int up = (int)Math.sqrt(num + 1); for (int i = 2; i <= up; i++) { int j = num / i; if (i * j == num) { if (i < j) { sum += i; sum += j; } if (i == j) { sum += i; } } } return sum == num; } } ``` ## 12/30/2021 [846. 一手顺子](https://leetcode-cn.com/problems/hand-of-straights/) ```python class Solution: def isNStraightHand(self, hand: List[int], groupSize: int) -> bool: if groupSize == 1: return True if len(hand) % groupSize != 0: return False cnt = collections.defaultdict(int) for x in hand: cnt[x] += 1 hand = [x for x in cnt] hand = sorted(hand) i = 0 while i < len(hand): # 找到起始数字 start = hand[i] if cnt[start] == 0: i += 1 continue # 判断是否能组成顺子 for j in range(start, start + groupSize): if cnt[j] == 0: return False cnt[j] -= 1 return True ``` ## 12/29/2021 [1995. 统计特殊四元组](https://leetcode-cn.com/problems/count-special-quadruplets/) ```python class Solution: def countQuadruplets(self, nums: List[int]) -> int: hmap = collections.defaultdict(int) n = len(nums) ans = 0 for c in range(n - 2, 1, -1): for d in range(c + 1, n): hmap[nums[d] - nums[c]] += 1 b = c - 1 for a in range(b): ans += hmap[nums[a] + nums[b]] return ans ``` ## 12/28/2021 [472. 连接词](https://leetcode-cn.com/problems/concatenated-words/) ```python class Trie: def __init__(self): # 保存子节点,小写字母情况下最多26个,可以用数组模拟 self.children = dict() # 记录该节点 是否作为一个字符串的结束 self.isEnd = False def insert(self, word: str) -> None: """Inserts a word into the trie. """ node = self for ch in word: # 存在则不操作,不存在则设置一个新节点 node.children.setdefault(ch, Trie()) # 继续向下,插入新的字符 node = node.children[ch] node.isEnd = True def DFS(self, word, start): if start == len(word): return True node = self for i in range(start, len(word)): next_node = node.children.get(word[i], None) if next_node is None: return False if next_node.isEnd: if self.DFS(word, i + 1): return True node = next_node return False class Solution: def findAllConcatenatedWordsInADict(self, words: List[str]) -> List[str]: words.sort(key=len) myTrie = Trie() ans = [] for w in words: if w == '': continue if myTrie.DFS(w, 0): ans.append(w) else: myTrie.insert(w) return ans ``` ## 12/27/2021 [825. 适龄的朋友](https://leetcode-cn.com/problems/friends-of-appropriate-ages/) ```python class Solution: def numFriendRequests(self, ages: List[int]) -> int: ages = sorted(ages) ans = 0 for x in ages: left = 0.5 * x + 7 right = x cnt = self.bisec(ages, right) - self.bisec(ages, left) if x > 14: cnt -= 1 ans += max(0, cnt) return ans def bisec(self, arr, x): lo = 0 hi = len(arr) while lo < hi: mid = (lo + hi) // 2 if arr[mid] <= x: lo = mid + 1 else: hi = mid return lo ``` ```python class Solution: def numFriendRequests(self, ages: List[int]) -> int: cnt = [0] * 121 for age in ages: cnt[age] += 1 presum = [0] * 121 for i in range(1, 121): presum[i] = presum[i - 1] + cnt[i] ans = 0 for age in ages: if age <= 14: continue lo = int(0.5 * age + 7) + 1 ans += presum[age] - presum[lo - 1] - 1 return ans ``` ## 12/26/2021 [1078. Bigram 分词](https://leetcode-cn.com/problems/occurrences-after-bigram/) ```python class Solution: def findOcurrences(self, text: str, first: str, second: str) -> List[str]: lst = text.split(' ') n = len(lst) fir_idx = [] sec_idx = [] ans = [] for i, word in enumerate(lst): if word == first: fir_idx.append(i) if word == second: sec_idx.append(i) i = 0 j = 0 while i < len(fir_idx) and j < len(sec_idx): idx1 = fir_idx[i] idx2 = sec_idx[j] if idx1 + 1 == idx2: if idx2 + 1 < n: ans.append(lst[idx2 + 1]) i += 1 j += 1 elif idx1 < idx2: i += 1 elif idx1 >= idx2: j += 1 return ans ``` ## 12/25/2021 [1609. 奇偶树](https://leetcode-cn.com/problems/even-odd-tree/) ```python # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def isEvenOddTree(self, root: Optional[TreeNode]) -> bool: queue = collections.deque() queue.append(root) level = 0 while queue: layer = [] for _ in range(len(queue)): node = queue.popleft() layer.append(node.val) if node.left is not None: queue.append(node.left) if node.right is not None: queue.append(node.right) if not self.is_valid(layer, level): return False level += 1 return True def is_valid(self, layer, level): if level % 2 == 0: sign = 1 resi = 1 else: sign = -1 resi = 0 pre = layer[0] if pre % 2 != resi: return False for i in range(1, len(layer)): cur = layer[i] if cur % 2 != resi: return False if (cur - pre) * sign <= 0: return False pre = cur return True ``` ## 12/24/2021 [1705. 吃苹果的最大数目](https://leetcode-cn.com/problems/maximum-number-of-eaten-apples/) ```python class Solution: def eatenApples(self, apples: List[int], days: List[int]) -> int: apple_cnt = collections.defaultdict(int) pq = [] day = 1 ans = 0 for i in range(len(apples)): # print(apple_cnt) app = apples[i] ds = days[i] while pq and pq[0] <= day: heapq.heappop(pq) if app != 0: apple_cnt[day + ds] += app heapq.heappush(pq, day + ds) if len(pq) > 0: apple_cnt[pq[0]] -= 1 ans += 1 if apple_cnt[pq[0]] == 0: heapq.heappop(pq) day += 1 # print(ans) while pq: while pq and pq[0] <= day: heapq.heappop(pq) if len(pq) > 0: apple_cnt[pq[0]] -= 1 ans += 1 if apple_cnt[pq[0]] == 0: heapq.heappop(pq) day += 1 return ans ``` ## 12/22/2021 [686. 重复叠加字符串匹配](https://leetcode-cn.com/problems/repeated-string-match/) ```python class Solution: def repeatedStringMatch(self, a: str, b: str) -> int: k = len(b) // len(a) if len(b) % len(a) != 0: k += 1 if self.is_sub(a * k, b): return k if self.is_sub(a * (k + 1), b): return k + 1 return -1 def is_sub(self, ss, s): i = 0 j = len(s) - 1 while j < len(ss): if hash(ss[i: j + 1]) == hash(s): return True i += 1 j += 1 return False ``` ## 12/20/2021 [475. 供暖器](https://leetcode-cn.com/problems/heaters/) + 二分查找距离最近的值 **Java** ```java class Solution { public int findRadius(int[] houses, int[] heaters) { int ans = 0; Arrays.sort(heaters); int n = heaters.length; for (int val : houses) { int min_dist; int idx = bisect(heaters, val); if (idx == 0) { min_dist = heaters[0] - val; }else if (idx == n) { min_dist = val - heaters[n - 1]; }else { int l = val - heaters[idx - 1]; int r = heaters[idx] - val; min_dist = Math.min(l, r); } ans = Math.max(ans, min_dist); } return ans; } int bisect(int[] arr, int value) { int le = 0, ri = arr.length; while (le < ri) { int mid = (le + ri) / 2; if (arr[mid] <= value) { le = mid + 1; }else { ri = mid; } } return le; } } ``` **Python** ```python class Solution: def findRadius(self, houses: List[int], heaters: List[int]) -> int: heaters = sorted(heaters) ans = 0 for val in houses: idx = bisect.bisect(heaters, val) if idx == 0: min_dist = heaters[0] - val elif idx == len(heaters): min_dist = val - heaters[-1] else: min_dist = min(val - heaters[idx - 1], heaters[idx] - val) ans = max(ans, min_dist) return ans ``` ## 12/19/2021 [997. 找到小镇的法官](https://leetcode-cn.com/problems/find-the-town-judge/) + JAVA ```java class Solution { public int findJudge(int n, int[][] trust) { int[] trust_others = new int[n + 1]; int[] trusted = new int[n + 1]; for (int i = 0; i < trust.length; i++) { int a = trust[i][0]; int b = trust[i][1]; trust_others[a] = 1; trusted[b] += 1; } for (int i = 1; i < n + 1; i++) { if (trusted[i] == n - 1 && trust_others[i] == 0) { return i; } } return -1; } } ``` + Python ```python class Solution: def findJudge(self, n: int, trust: List[List[int]]) -> int: trust_other = [0] * (n + 1) trusted = [0] * (n + 1) for a, b in trust: trust_other[a] = 1 trusted[b] += 1 for i in range(1, n + 1): if trusted[i] == n - 1 and trust_other[i] == 0: return i return -1 ``` ## 12/18/2021 [419. 甲板上的战舰](https://leetcode-cn.com/problems/battleships-in-a-board/) + python ```python class Solution: def countBattleships(self, board: List[List[str]]) -> int: ans = 0 m, n = len(board), len(board[0]) for i in range(m): for j in range(n): if board[i][j] != 'X': continue if self.get(i - 1, j, board) != 'X' and self.get(i, j - 1, board) != 'X': ans += 1 return ans def get(self, i, j, board): if i < 0 or j < 0: return '.' else: return board[i][j] ``` + JAVA ```java class Solution { char[][] board; public int countBattleships(char[][] board) { this.board = board; int m = board.length; int n = board[0].length; int ans = 0; for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { if (board[i][j] != 'X') { continue; } if (get(i - 1, j) != 'X' && get(i, j - 1) != 'X') { ans += 1; } } } return ans; } char get(int i, int j) { if (i < 0 || j < 0) { return '.'; }else { return board[i][j]; } } } ``` ## 12/17/2021 [1518. 换酒问题](https://leetcode-cn.com/problems/water-bottles/) + Python ```python class Solution: def numWaterBottles(self, numBottles: int, numExchange: int) -> int: ans = 0 empty = 0 while numBottles != 0: ans += numBottles empty += numBottles numBottles = empty // numExchange empty = empty % numExchange return ans ``` + C++ ```c++ class Solution { public: int numWaterBottles(int numBottles, int numExchange) { int ans = numBottles; int empty = numBottles; while (empty >= numExchange) { int temp = empty / numExchange; ans += temp; empty = empty % numExchange + temp; } return ans; } }; ``` ## 12/15/2021 [851. 喧闹和富有](https://leetcode-cn.com/problems/loud-and-rich/) ```python class Solution: def loudAndRich(self, richer: List[List[int]], quiet: List[int]) -> List[int]: n = len(quiet) hmap = dict() for x, y in richer: hmap.setdefault(y, []).append(x) self.ans = [-1] * n for i in range(n): self.DFS(i, hmap, quiet) return self.ans def DFS(self, i, hmap, quiet): if self.ans[i] != -1: return candi = i for idx in hmap.get(i, []): self.DFS(idx, hmap, quiet) if quiet[self.ans[idx]] < quiet[candi]: candi = self.ans[idx] self.ans[i] = candi return ``` ## 12/14/2021 [630. 课程表 III](https://leetcode-cn.com/problems/course-schedule-iii/) ```python class Solution: def scheduleCourse(self, courses: List[List[int]]) -> int: courses = sorted(courses, key=lambda x: x[1]) heap = [] days = 0 ans = 0 for c in courses: d, last = c if days + d <= last: days += d ans += 1 heapq.heappush(heap, -d) else: if len(heap) == 0: continue dmax = -heap[0] if dmax > d: heapq.heappop(heap) heapq.heappush(heap, -d) days += (d - dmax) return ans ``` ## 12/13/2021 [807. 保持城市天际线](https://leetcode-cn.com/problems/max-increase-to-keep-city-skyline/) ```python class Solution: def maxIncreaseKeepingSkyline(self, grid: List[List[int]]) -> int: n = len(grid) ans = 0 row_max = [0] * n col_max = [0] * n for r in range(n): for c in range(n): val = grid[r][c] row_max[r] = max(row_max[r], val) col_max[c] = max(col_max[c], val) for r in range(n): for c in range(n): ans += min(row_max[r], col_max[c]) - grid[r][c] return ans ``` ## 12/12/2021 [709. 转换成小写字母](https://leetcode-cn.com/problems/to-lower-case/) + 大写字母 A - Z的 ASCII 码范围为[65,90] + 小写字母 a - z的 ASCII 码范围为[97,122] + 相差32 ```python class Solution: def toLowerCase(self, s: str) -> str: ans = [] for ch in s: asc = ord(ch) if asc <= 90 and asc >= 65: ch = chr(asc + 32) ans.append(ch) return ''.join(ans) ``` ## 12/11/2021 [911. 在线选举](https://leetcode-cn.com/problems/online-election/) ```python class TopVotedCandidate: def __init__(self, persons: List[int], times: List[int]): votes = {} top = None max_vote = 0 tops = [] for p in persons: votes.setdefault(p, 0) votes[p] += 1 if votes[p] >= max_vote: max_vote = votes[p] top = p tops.append(top) self.times = times self.tops = tops def q(self, t: int) -> int: lo, hi = 0, len(self.times) while lo < hi: mid = (lo + hi) // 2 if t >= self.times[mid]: lo = mid + 1 else: hi = mid return self.tops[lo - 1] # Your TopVotedCandidate object will be instantiated and called as such: # obj = TopVotedCandidate(persons, times) # param_1 = obj.q(t) ``` ## 12/10/2021 [748. 最短补全词](https://leetcode-cn.com/problems/shortest-completing-word/) ```python class Solution: def shortestCompletingWord(self, licensePlate: str, words: List[str]) -> str: cnt_lic = [0] * 26 for s in licensePlate: s = s.lower() idx = ord(s) - ord('a') if idx >= 0 and idx <= 25: cnt_lic[idx] += 1 # print(cnt_lic) ans = '' min_len = 100 for word in words: if len(word) >= min_len: continue if self.is_comp(word, cnt_lic): ans = word min_len = len(ans) return ans def is_comp(self, word, cnt_lic): cnt_word = [0] * 26 for s in word: idx = ord(s) - ord('a') cnt_word[idx] += 1 for i in range(26): if cnt_lic[i] != 0 and cnt_word[i] < cnt_lic[i]: return False return True ``` ## 12/9/2021 [794. 有效的井字游戏](https://leetcode-cn.com/problems/valid-tic-tac-toe-state/) ```python class Solution: def validTicTacToe(self, board: List[str]) -> bool: cnt1, cnt2 = 0, 0 for r in range(3): for c in range(3): if board[r][c] == ' ': continue if board[r][c] == 'O': cnt2 += 1 else: cnt1 += 1 if cnt1 != cnt2 and cnt1 - 1 != cnt2: return False win1, win2 = 0, 0 for i in range(3): if board[i][0] == board[i][1] and board[i][1] == board[i][2]: if board[i][0] == 'X': win1 += 1 if board[i][0] == 'O': win2 += 1 if board[0][i] == board[1][i] and board[1][i] == board[2][i]: # print(board[0][i], board[1][i], board[2][i]) if board[0][i] == 'X': win1 += 1 if board[0][i] == 'O': win2 += 1 # print(win1, win2) if board[0][0] == board[1][1] == board[2][2]: if board[0][0] == 'X': win1 += 1 if board[0][0] == 'O': win2 += 1 if board[0][2] == board[1][1] == board[2][0]: if board[0][2] == 'X': win1 += 1 if board[0][2] == 'O': win2 += 1 # print(win1, win2) if win1 != 0 and win2 != 0: return False if win1 != 0 and cnt1 == cnt2: return False if win2 != 0 and cnt1 != cnt2: return False return True ``` ## 12/6/2021 [1816. 截断句子](https://leetcode-cn.com/problems/truncate-sentence/) ```python class Solution: def truncateSentence(self, s: str, k: int) -> str: s += ' ' ans = [] word = '' for c in s: if k == 0: break if c == ' ': ans.append(word) word = '' k -= 1 else: word += c return ' '.join(ans) ``` + 数空格 ```python class Solution: def truncateSentence(self, s: str, k: int) -> str: # 数空格 s += ' ' for i in range(len(s)): c = s[i] if c == ' ': k -= 1 if k == 0: break return s[:i] ``` ## 12/4/2021 [383. 赎金信](https://leetcode-cn.com/problems/ransom-note/) ```python class Solution: def canConstruct(self, ransomNote: str, magazine: str) -> bool: mag_cnt = collections.defaultdict(int) for s in magazine: mag_cnt[s] += 1 for s in ransomNote: mag_cnt[s] -= 1 if mag_cnt[s] < 0: return False return True ``` ## 12/2/2021 [506. 相对名次](https://leetcode-cn.com/problems/relative-ranks/) ```python class Solution: def findRelativeRanks(self, score: List[int]) -> List[str]: n = len(score) ans = [''] * n idx_sorted = list(range(n)) idx_sorted = sorted(idx_sorted, key=lambda i: score[i], reverse=True) for i in range(n): medal = str(i + 1) if i == 0: medal = 'Gold Medal' elif i == 1: medal = 'Silver Medal' elif i == 2: medal = 'Bronze Medal' ans[idx_sorted[i]] = medal return ans ``` ## 12/1/2021 [1446. 连续字符](https://leetcode-cn.com/problems/consecutive-characters/) ```python class Solution: def maxPower(self, s: str) -> int: s += '#' char = s[0] max_len = 1 i, j = 0, 0 while j < len(s) - 1: j = j + 1 if s[j] != char: max_len = max(max_len, j - i) char = s[j] i = j return max_len ``` # 11/2021 ## 11/30/2021 [400. 第 N 位数字](https://leetcode-cn.com/problems/nth-digit/) ```python class Solution: def findNthDigit(self, n: int) -> int: s = 0 m = 1 while m < 100: if s < n <= s + 9 * (10 ** (m-1)) * m: break else: s += 9 * (10 ** (m-1)) * m m += 1 # 是m位数 #再确定是m位数中的第几个 T = n - s if T % m == 0: number = int(T/m) else: number = int(T/m) + 1 #计算第number个m位数是几 X = 10 ** (m - 1) + number - 1 #是X的第几位 X = str(X) dig = T % m return int(X[dig - 1]) ``` ## 11/29/2021 [786. 第 K 个最小的素数分数](https://leetcode-cn.com/problems/k-th-smallest-prime-fraction/) + 官方方法二:优先队列 ```python class Frac: def __init__(self, idx: int, idy: int, x: int, y: int) -> None: self.idx = idx self.idy = idy self.x = x self.y = y def __lt__(self, other: "Frac") -> bool: return self.x * other.y < self.y * other.x class Solution: def kthSmallestPrimeFraction(self, arr: List[int], k: int) -> List[int]: n = len(arr) q = [Frac(0, i, arr[0], arr[i]) for i in range(1, n)] heapq.heapify(q) for _ in range(k - 1): frac = heapq.heappop(q) i, j = frac.idx, frac.idy if i + 1 < j: heapq.heappush(q, Frac(i + 1, j, arr[i + 1], arr[j])) frac = heapq.heappop(q) return [frac.x, frac.y] ``` ## 11/28/2021 [438. 找到字符串中所有字母异位词](https://leetcode-cn.com/problems/find-all-anagrams-in-a-string/) + 双指针表示范围 + diff维护差异 ```python class Solution: def findAnagrams(self, s: str, p: str) -> List[int]: if len(s) < len(p): return [] ans = [] len_s, len_p = len(s), len(p) cnt = [0] * 26 for i in range(len_p): cnt[ord(p[i]) - ord('a')] += 1 cnt[ord(s[i]) - ord('a')] -= 1 diff = sum([1 for x in cnt if x != 0]) if diff == 0: ans.append(0) i = 0 j = len_p - 1 while j < len_s - 1: # 去掉s[i] i_idx = ord(s[i]) - ord('a') if cnt[i_idx] == -1: diff -= 1 if cnt[i_idx] == 0: diff += 1 cnt[i_idx] += 1 # 增加s[j+1] j_idx = ord(s[j+1]) - ord('a') if cnt[j_idx] == 1: diff -= 1 if cnt[j_idx] == 0: diff += 1 cnt[j_idx] -= 1 i += 1 j += 1 # print(i, j, diff) if diff == 0: ans.append(i) return ans ``` ## 11/26/2021 [700. 二叉搜索树中的搜索](https://leetcode-cn.com/problems/search-in-a-binary-search-tree/) + 递归 ```python # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def searchBST(self, root: TreeNode, val: int) -> TreeNode: if root is None: return None if root.val == val: return root elif root.val > val: return self.searchBST(root.left, val) else: return self.searchBST(root.right, val) ``` + 迭代 ```python # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def searchBST(self, root: TreeNode, val: int) -> TreeNode: while root: if root.val == val: return root elif val < root.val: root = root.left else: root = root.right return None ``` ## 11/23/2021 [859. 亲密字符串](https://leetcode-cn.com/problems/buddy-strings/) **思路** + 长度要相同 + 若两字符串完全相等,则要求有重复字符 + 有两个位置不同,且错位相等 ```python class Solution: def buddyStrings(self, s: str, goal: str) -> bool: if len(s) != len(goal): return False idx = [] cnt = collections.defaultdict(int) twosame = False for i in range(len(s)): if s[i] != goal[i]: if len(idx) == 2: return False idx.append(i) cnt[s[i]] += 1 if twosame is False and cnt[s[i]] >= 2: twosame = True if len(idx) == 1: return False if len(idx) == 0: return twosame i, j = idx if s[i] != goal[j] or s[j] != goal[i]: return False return True ``` ## 11/22/2021 [384. 打乱数组](https://leetcode-cn.com/problems/shuffle-an-array/) **思路** + 从前往后填充 [0,n−1] + 对于下标 x 而言,我们从[x,n−1] 中随机出一个位置与 xxx 进行值交换 ```python class Solution: def __init__(self, nums: List[int]): self.original = nums.copy() self.nums = nums self.n = len(nums) def reset(self) -> List[int]: self.nums = self.original.copy() return self.nums def shuffle(self) -> List[int]: for i in range(self.n - 1): j = random.randint(i, self.n - 1) self.nums[i], self.nums[j] = self.nums[j], self.nums[i] return self.nums ``` ## 11/21/2021 [559. N 叉树的最大深度](https://leetcode-cn.com/problems/maximum-depth-of-n-ary-tree/) **思路**1 + DFS ```python """ # Definition for a Node. class Node: def __init__(self, val=None, children=None): self.val = val self.children = children """ class Solution: def maxDepth(self, root: 'Node') -> int: if root is None: return 0 # if root.children is None: # return 1 child_dep = 0 for child in root.children: child_dep = max(child_dep, self.maxDepth(child)) return 1 + child_dep ``` **思路2**1 + BFS ```python """ # Definition for a Node. class Node: def __init__(self, val=None, children=None): self.val = val self.children = children """ class Solution: def maxDepth(self, root: 'Node') -> int: if root is None: return 0 ans = 0 queue = collections.deque() queue.append(root) while queue: ans += 1 for _ in range(len(queue)): node = queue.popleft() for child in node.children: queue.append(child) return ans ``` ## 11/20/2021 [594. 最长和谐子序列](https://leetcode-cn.com/problems/longest-harmonious-subsequence/) **思路** + 每个子序列中只有两个相邻的数 + 用哈希表记录每个数字出现的次数 ```python class Solution: def findLHS(self, nums: List[int]) -> int: ans = 0 hashmap = dict() for num in nums: if num not in hashmap: hashmap[num] = 0 hashmap[num] += 1 for fir in hashmap.keys(): sec_cnt = hashmap.get(fir + 1, 0) if sec_cnt != 0: ans = max(ans, hashmap[fir] + sec_cnt) return ans ``` ## 11/19/2021 [397. 整数替换](https://leetcode-cn.com/problems/integer-replacement/) **思路1** + 直接递归 + 偶数时, 计算 n // 2 + 奇数时,计算min(n-1, n+1) ```python class Solution: def integerReplacement(self, n: int) -> int: if n == 1: return 0 if n % 2 == 0: return 1 + self.integerReplacement(n // 2) else: return 2 + min(self.integerReplacement(n // 2), self.integerReplacement(n // 2 + 1) return -1 ``` **思路2** + 记忆化减低复杂度 ```python class Solution: def __init__(self): self.memo = dict() def integerReplacement(self, n: int) -> int: if n == 1: return 0 if n in self.memo: return self.memo[n] steps = -1 if n % 2 == 0: steps = 1 + self.integerReplacement(n // 2) else: steps = 2 + min(self.integerReplacement(n // 2), self.integerReplacement(n // 2 + 1)) self.memo[n] = steps return steps ``` ## 11/18/2021 [563. 二叉树的坡度](https://leetcode-cn.com/problems/binary-tree-tilt/) **思路** + DFS递归,返回以该节点为root的所有结点的和,left + right + node.val + 并同时得到该结点的坡度 ```python # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def findTilt(self, root: TreeNode) -> int: self.ans = 0 _ = self.DFS_sum(root) return self.ans # 计算root的结点和 def DFS_sum(self, root): if root is None: return 0 left_sum = self.DFS_sum(root.left) right_sum = self.DFS_sum(root.right) self.ans += abs(left_sum - right_sum) return left_sum + right_sum + root.val ``` ## 11/17/2021 [318. 最大单词长度乘积](https://leetcode-cn.com/problems/maximum-product-of-word-lengths/) **思路** + 先用26位二进制表示每个word + 与为0则没有相同字符串 ```python class Solution: def maxProduct(self, words: List[str]) -> int: n = len(words) bits = [0] * n for i in range(n): word = words[i] for w in word: # 或运算 bits[i] = bits[i] | (1 << (ord(w) - ord('a'))) ans = 0 for i in range(n): for j in range(i+1, n): if (bits[i] & bits[j]) == 0: ans = max(ans, len(words[i]) * len(words[j])) return ans ``` ## 11/15/2021 [319. 灯泡开关](https://leetcode-cn.com/problems/bulb-switcher/) **思路** + 只需要计算1-n有几个平方数! + 非平方数一定是暗的 + 1-n 中平方数的个数为sqrt(n)向下取整 ```python class Solution: def bulbSwitch(self, n: int) -> int: i = 1 ans = 0 while i * i <= n: ans += 1 i += 1 return ans ``` ```python class Solution: def bulbSwitch(self, n: int) -> int: return (int(math.sqrt(n))) ``` ## 11/14/2021 [677. 键值映射](https://leetcode-cn.com/problems/map-sum-pairs/) **思路** + Trie树的思路,每个结点存当前的sum + 如果重复insert,需要挑战该路径上的所有val,addi = val - pre ```python class MapSum: def __init__(self): self.map = dict() self.trie = Trie() def insert(self, key: str, val: int) -> None: pre = self.map.get(key, 0) addi = val - pre self.map[key] = val node = self.trie for ch in key: idx = ord(ch) - ord('a') if node.children[idx] is None: node.children[idx] = Trie() node.children[idx].val += addi node = node.children[idx] def sum(self, prefix: str) -> int: node = self.trie for ch in prefix: idx = ord(ch) - ord('a') if node.children[idx] is None: return 0 node = node.children[idx] return node.val class Trie: def __init__(self): # 保存子节点,小写字母情况下最多26个,可以用数组模拟 self.children = [None] * 26 # 记录该节点 是否作为一个字符串的结束 self.val = 0 # Your MapSum object will be instantiated and called as such: # obj = MapSum() # obj.insert(key,val) # param_2 = obj.sum(prefix) ``` ## 11/13/2021 [520. 检测大写字母](https://leetcode-cn.com/problems/detect-capital/) ```python class Solution: def detectCapitalUse(self, word: str) -> bool: if len(word) == 1: return True fir = self.is_up(word[0]) sec = self.is_up(word[1]) if fir is False and sec is True: return False rest = False if fir is True and sec is True: rest = True for i in range(2, len(word)): if self.is_up(word[i]) is not rest: return False return True def is_up(self, s): if s >= 'A' and s <= 'Z': return True return False ``` ## 11/12/2021 [375. 猜数字大小 II](https://leetcode-cn.com/problems/guess-number-higher-or-lower-ii/) ```python class Solution: def getMoneyAmount(self, n: int) -> int: dp = [[0] * (n + 1) for _ in range(n + 1)] for l in range(2, n + 1): for i in range(1, n + 2 - l): j = i + l - 1 mini = n * n for k in range(i, j + 1): mini = min(mini, k + max(self.get(dp, i, k-1), self.get(dp, k+1, j))) dp[i][j] = mini return dp[1][n] def get(self, arr, i, j): if i > j: return 0 return arr[i][j] ``` ## 11/10/2021 [495. 提莫攻击](https://leetcode-cn.com/problems/teemo-attacking/) ```python class Solution: def findPoisonedDuration(self, timeSeries: List[int], duration: int) -> int: ans = duration for i in range(len(timeSeries) - 1): t1 = timeSeries[i] t2 = timeSeries[i+1] ans += min(t2 - t1, duration) return ans ``` ## 11/8/2021 [299. 猜数字游戏](https://leetcode-cn.com/problems/bulls-and-cows/) **思路** + 相同的直接记录bu;ll + 不相同的用map记录,取min记录cow ```python class Solution: def getHint(self, secret: str, guess: str) -> str: map1 = collections.defaultdict(int) map2 = collections.defaultdict(int) bull, cow = 0, 0 for s1, s2 in zip(secret, guess): if s1 == s2: bull += 1 else: map1[s1] += 1 map2[s2] += 1 for s in map2: cow += min(map1[s], map2[s]) return f'{bull}A{cow}B' ``` ## 11/7/2021 [598. 范围求和 II](https://leetcode-cn.com/problems/range-addition-ii/) ```python class Solution: def maxCount(self, m: int, n: int, ops: List[List[int]]) -> int: min_a = m min_b = n for a, b in ops: min_a = min(min_a, a) min_b = min(min_b, b) return min_a * min_b ``` ## 11/6/2021 [268. 丢失的数字](https://leetcode-cn.com/problems/missing-number/) + 异或 + 先求[1,n] 的异或和 ans,然后用 anss 对各个 nums[i]nums[ii]进行异或 ```python class Solution: def missingNumber(self, nums: List[int]) -> int: xorsum = 0 n = len(nums) for x in nums: xorsum ^= x for x in range(n + 1): xorsum ^= x return xorsum ``` ## 11/5/2021 [1218. 最长定差子序列](https://leetcode-cn.com/problems/longest-arithmetic-subsequence-of-given-difference/) ```python class Solution: def longestSubsequence(self, arr: List[int], difference: int) -> int: num_len = dict() ans = 1 for num in arr: l = num_len.get(num - difference, 0) + 1 ans = max(ans, l) num_len[num] = l return ans ``` ## 11/4/2021 [367. 有效的完全平方数](https://leetcode-cn.com/problems/valid-perfect-square/) ```python class Solution: def isPerfectSquare(self, num: int) -> bool: if num == 1: return True l = 2 r = num // 2 while l <= r: mid = (l + r) // 2 sq = mid * mid if sq == num: return True elif sq > num: r = mid - 1 else: l = mid + 1 return False ``` ## 11/2/2021 [237. 删除链表中的节点](https://leetcode-cn.com/problems/delete-node-in-a-linked-list/) **思路** + 将需要删除的结点值设置为下一个结点的值 + 删除下一个结点 + 效果等同于删除node ```python # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def deleteNode(self, node): """ :type node: ListNode :rtype: void Do not return anything, modify node in-place instead. """ node.val = node.next.val node.next = node.next.next ``` ## 11/1/2021 [575. 分糖果](https://leetcode-cn.com/problems/distribute-candies/) ```python class Solution: def distributeCandies(self, candyType: List[int]) -> int: hset = set() for c in candyType: hset.add(c) max_candy = len(candyType) // 2 return min(max_candy, len(hset)) ``` # 10/2021 ## 10/31/2021 [500. 键盘行](https://leetcode-cn.com/problems/keyboard-row/) ```python class Solution: def findWords(self, words: List[str]) -> List[str]: hashmap = dict() groups = ["qwertyuiop", "asdfghjkl", "zxcvbnm"] lines = [0, 1, 2] for w, l in zip(groups, lines): for s in w: hashmap[s] = l ans = [] for word in words: line = -1 valid = True for s in word: s = s.lower() if line == -1: line = hashmap[s] continue if hashmap[s] != line: valid = False break if valid: ans.append(word) return ans ```
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md
Markdown
README.md
tkrzeminski/sampleVagrantProvisioning
103baa0994b8a9927a964b2073000be9d9b06a6f
[ "Unlicense" ]
null
null
null
README.md
tkrzeminski/sampleVagrantProvisioning
103baa0994b8a9927a964b2073000be9d9b06a6f
[ "Unlicense" ]
null
null
null
README.md
tkrzeminski/sampleVagrantProvisioning
103baa0994b8a9927a964b2073000be9d9b06a6f
[ "Unlicense" ]
null
null
null
# sampleVagrantProvisioning Sample vagrant based provisioning with simple app and monitoring. # Steps * Clone repository ``` git clone https://github.com/tkrzeminski/sampleVagrantProvisioning . ``` * Start vagrant ``` vagrant up ``` * wait * Open browser on page [http://localhost:8080](http://localhost:8080) or [https://localhost:8443/](https://localhost:8443/) * Checkout monitoring on page [http://localhost:8080/munin/](http://localhost:8080/munin/) or [https://localhost:8443/munin/](https://localhost:8443/munin/) * Ping local simple java server requesting page [http://localhost:8080/ping](http://localhost:8080/ping) or [https://localhost:8443/ping](https://localhost:8443/ping) behind proxy * Try to burn vagrant box requesting page [http://localhost:8080/stress](http://localhost:8080/stress) or [https://localhost:8443/stress](https://localhost:8443/stress) or use console ab command: ``` ab -n 100 -c 5 http://localhost:8080/stress ```
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README.md
stefano-onorati/DaCapo
7db9f37ae85ccdf843ec20c9855d315a035b4384
[ "MIT" ]
null
null
null
README.md
stefano-onorati/DaCapo
7db9f37ae85ccdf843ec20c9855d315a035b4384
[ "MIT" ]
null
null
null
README.md
stefano-onorati/DaCapo
7db9f37ae85ccdf843ec20c9855d315a035b4384
[ "MIT" ]
null
null
null
# Da Capo Website designed for Da Capo Music Studio using Bootstrap. For more information, please visit <a href="http://dacapomusicstudio.com/" target="_blank">Da Capo</a> and <a href="http://startbootstrap.com/">Bootstrap</a>.
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_posts/2019-04-20-Download-1995-saturn-s-air-bag-removel.md
Ozie-Ottman/11
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[ "MIT" ]
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_posts/2019-04-20-Download-1995-saturn-s-air-bag-removel.md
Ozie-Ottman/11
1005fa6184c08c4e1a3030e5423d26beae92c3c6
[ "MIT" ]
null
null
null
_posts/2019-04-20-Download-1995-saturn-s-air-bag-removel.md
Ozie-Ottman/11
1005fa6184c08c4e1a3030e5423d26beae92c3c6
[ "MIT" ]
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jvolkman/rules_python_cross
7d6426a9c929c8a789d0edb502f29474ecf8a63c
[ "Apache-2.0" ]
4
2022-03-29T13:58:58.000Z
2022-03-31T11:10:28.000Z
README.md
jvolkman/rules_python_cross
7d6426a9c929c8a789d0edb502f29474ecf8a63c
[ "Apache-2.0" ]
null
null
null
README.md
jvolkman/rules_python_cross
7d6426a9c929c8a789d0edb502f29474ecf8a63c
[ "Apache-2.0" ]
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# `rules_pycross` - Python + cross platform A proof-of-concept ruleset to (hopefully) improve cross-platform Python builds with Bazel. __Note:__ very much still experimental. ### Features: - A single lock file for all target platforms, thanks to Poetry - Builds that happen in build actions, not during WORKSPACE initialization - Standard Bazel `http_file` rules used for fetching dependencies. `pip` is not a build-time dependency. See the [example](example). ### Why? The current Bazel [rules](https://github.com/bazelbuild/rules_python) for working with Python external dependencies have a couple of issues that make cross-platform usage difficult (see https://github.com/bazelbuild/rules_python/issues/260): - they're based on `pip` and `pip-compile` which do not generate cross-platform lock files. For example, IPython depends on `appnope` only on MacOS. Lock files generated by `pip-compile` will differ based on whether they're created on Linux or MacOS. - They use `pip install` during the `WORKSPACE` phase to fetch and possibly build packages (including native libraries). `WORKSPACE` operations lack many of the things that Bazel's build actions provide such as sandboxing and remote execution. ### How? A `pip install` operation can be roughly broken down into these parts: 1. determine the environment (OS and Python version/implementation) 2. resolve the dependencies of the package to install, some of which may be platform-specific (optionally constrained by a pre-compiled lock file) 3. figure out which files to download - either pre-built wheels matching the current platform or sdists to build locally 4. download sdists and wheels 5. build and install sdists; install wheels `rules_pycross` attemps to deconstruct this operation into its constituent parts and glue them together with Bazel: 1. `pycross_target_environment` is used to specify target environments ahead of time provided with ABI, platform, and implementation parameters (similar to pip's `--abi`, `--platform`, and `--implementation` flags). These environments are selected using Bazel's own platform/constraint system. 2. `pycross_lock_file` generates a "lock" `.bzl` file from an input `poetry.lock`. This `.bzl` file contains a mix of `http_file` repositories and `pycross_*` targets. 3. `pycross_wheel_build` builds `sdist.tar.gz` archives into Python wheels. This is a build action, not a `WORKSPACE` operation. 5. `pycross_wheel_library` "installs" (extracts) a Python wheel - either downloaded or built from an sdist - and provides it as a `py_library`. See the [generated docs](docs/rules.md).
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misc/additional-ubuntu-repositories.md
sespaces/streamfarmers-progress
d02d6787933429a44257c78cdedde608fed06c14
[ "MIT" ]
null
null
null
misc/additional-ubuntu-repositories.md
sespaces/streamfarmers-progress
d02d6787933429a44257c78cdedde608fed06c14
[ "MIT" ]
null
null
null
misc/additional-ubuntu-repositories.md
sespaces/streamfarmers-progress
d02d6787933429a44257c78cdedde608fed06c14
[ "MIT" ]
null
null
null
# Additional Ubuntu Repositories Depending on your Ubuntu installation, you may need this to use the "add-apt-repository" command: apt install software-properties-common Certbot (Let's Encrypt) add-apt-repository ppa:certbot/certbot apt update && apt install -y certbot Geth (Go Ethereum) add-apt-repository ppa:ethereum/ethereum apt update && apt install -y ethereum Sublime-Text wget -qO - https://download.sublimetext.com/sublimehq-pub.gpg | sudo apt-key add - apt install apt-transport-https echo "deb https://download.sublimetext.com/ apt/stable/" | sudo tee /etc/apt/sources.list.d/sublime-text.list apt update && apt install -y sublime-text
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README.md
HelveticaScenario/cubbyjs
068b2b169754c68911b2c5db4c9a66f6470e637c
[ "MIT" ]
1
2021-12-17T17:40:17.000Z
2021-12-17T17:40:17.000Z
README.md
HelveticaScenario/cubbyjs
068b2b169754c68911b2c5db4c9a66f6470e637c
[ "MIT" ]
6
2021-05-24T19:07:55.000Z
2021-08-31T23:05:24.000Z
README.md
HelveticaScenario/cubbyjs
068b2b169754c68911b2c5db4c9a66f6470e637c
[ "MIT" ]
1
2021-05-07T06:29:51.000Z
2021-05-07T06:29:51.000Z
# cubbyjs A micro-store library
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codesydney/censusplus_nsw_employmentrate
882e6f0986c6456c16240e5af6f23c3025042710
[ "CC-BY-4.0" ]
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README.md
codesydney/censusplus_nsw_employmentrate
882e6f0986c6456c16240e5af6f23c3025042710
[ "CC-BY-4.0" ]
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README.md
codesydney/censusplus_nsw_employmentrate
882e6f0986c6456c16240e5af6f23c3025042710
[ "CC-BY-4.0" ]
null
null
null
# censusplus_nsw_employmentrate This is censusplus subproject deals with NSW Employment rate from different NSW suburbs. Data was obtained from https://data.nsw.gov.au/ This work is licensed under https://creativecommons.org/licenses/by/4.0/ "# censusplus_nsw_employmentrate" "# NSW-Employment-Rate"
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asannou/docker-docker-api-proxy
7b986725e2bc024cc7e511f78b5cdc2d9100cff0
[ "MIT" ]
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README.md
asannou/docker-docker-api-proxy
7b986725e2bc024cc7e511f78b5cdc2d9100cff0
[ "MIT" ]
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README.md
asannou/docker-docker-api-proxy
7b986725e2bc024cc7e511f78b5cdc2d9100cff0
[ "MIT" ]
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null
# docker-api-proxy Proxy for accessing Docker daemon's remote API. By default, the API proxy blocks all requests that can run containers and commands that are not covered by the stored images and their predefined commands. However, you can easily customize the filter logic by adapting the lib/filter.js file. Tested against Docker Remote API v1.24 and Docker 1.12. ## Start a container $ docker run -d --name docker-api-proxy -P -v /var/run/docker.sock:/docker.sock asannou/docker-api-proxy ## Connect to it using Docker CLI $ docker -H $(docker port docker-api-proxy 2375/tcp) info
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tutorials/backend/hasura-advanced/tutorial-site-es/content/performance/1-caching.md
surendran82/learn-graphql
0260fab2e73f3a04dfe14b5507c2566647b6e267
[ "MIT" ]
2
2022-01-20T08:06:13.000Z
2022-02-23T18:35:18.000Z
tutorials/backend/hasura-advanced/tutorial-site-es/content/performance/1-caching.md
arjunyel/learn-graphql
133352f15ad8b81200df292d606d9f44cb21f244
[ "MIT" ]
null
null
null
tutorials/backend/hasura-advanced/tutorial-site-es/content/performance/1-caching.md
arjunyel/learn-graphql
133352f15ad8b81200df292d606d9f44cb21f244
[ "MIT" ]
1
2022-02-25T15:16:00.000Z
2022-02-25T15:16:00.000Z
--- title: "Caché de respuestas de GraphQL" metaTitle: "Caché de respuestas de GraphQL | Tutorial avanzado de Hasura GraphQL" metaDescription: "El motor Hasura GraphQL (OSS) admite el almacenamiento en caché de consultas, donde se almacenará la representación interna del AST de GraphQL completamente cualificado." --- El motor Hasura GraphQL (OSS) admite el almacenamiento en caché de consultas, donde se almacenará la representación interna del AST de GraphQL completamente cualificado. Cuando se realiza una consulta de GraphQL, el SQL generado es una instrucción preparada con las variables de sesión adecuadas para que estas lleguen a la base de datos. Estas instrucciones preparadas ayudan a realizar consultas rápidamente. Más información sobre [Almacenamiento de consultas en caché](https://hasura.io/docs/latest/graphql/core/databases/postgres/queries/performance/) Ahora bien, algunas consultas son de acceso más frecuente que otras. Normalmente, podría darse una latencia o tiempos de respuesta lentos debido a - El tamaño de la respuesta - La ubicación del servidor - El número de llamadas concurrentes en la API, etc. Hasura Cloud ofrece soporte para el almacenamiento en caché de las respuestas a las consultas. Cuando la consulta se hace con la configuración de la caché, Hasura Cloud garantiza que los datos de respuesta se almacenan en la caché para mejorar los tiempos de respuesta. **Nota**: el almacenamiento en caché de respuestas de GraphQL está habilitado para proyectos Cloud de nivel `Standard` con un tamaño de caché de hasta 100 MB. ## ¿Cómo funciona el almacenamiento en caché? {#how-does-caching-work} Hasura cuenta con metadatos sobre los modelos de datos en todas las fuentes de datos, además de con reglas de autorización a nivel de aplicación. Esto ayuda a Hasura a proporcionar un almacenamiento en caché de aplicaciones de extremo a extremo. La respuesta de una consulta GraphQL solo puede almacenarse en la caché cuando se cumplen las siguientes condiciones: - La consulta no hace uso de esquemas ni uniones remotos - La consulta y los permisos de usuario relacionados no utilizan variables de sesión - La JSON de respuesta tiene un tamaño inferior a 100 KB Las respuestas en caché se almacenan durante un tiempo en una caché LRU (menos utilizada recientemente) y se eliminan de la caché según sea necesario en función de su uso. Por ejemplo, los registros `users` del modelo de slack serán de acceso frecuente. Podemos almacenarlos en la caché mediante la siguiente consulta: ```graphql query slackUsersCached @cached { users { id name display_name bio } } ``` Tenga en cuenta que en la consulta anterior hemos incluido una directiva `@cached` para especificar que esta consulta debe ser almacenada en la caché. Por `default` su respuesta se almacena en la caché durante `60 seconds`. Ahora vamos a verificar si la respuesta ha sido almacenada en caché correctamente. Lo ideal sería que la respuesta HTTP incluyese un encabezado `Cache-Control` para indicar el número máximo de segundos que la respuesta devuelta ha de permanecer en la caché. Pasado ese tiempo se eliminará de la LRU. ![Encabezado de la respuesta de Control de caché](https://graphql-engine-cdn.hasura.io/learn-hasura/assets/graphql-hasura-advanced/cache-control.png) Puede consultar el valor del encabezado de la respuesta de Control de caché que indica cuánto tiempo más en segundos va a almacenarse esta respuesta en la caché. ## Vida útil de la caché {#cache-lifetime} La duración máxima de una entrada en la memoria caché puede controlarse mediante el argumento ttl de la directiva de consulta @cached. El valor es un número entero de segundos: ```graphql query usersCached @cached(ttl: 300) { users { id name display_name bio } } ``` En la consulta anterior, hemos incluido un argumento `ttl` para la directiva @cached. Esto se utiliza para especificar cuánto tiempo debe permanecer la memoria caché en su sitio. El valor máximo permitido es de 300 segundos (5 minutos) y eso es lo que hemos utilizado en la consulta anterior. Ahora, al leer el encabezado `Cache-Control`, sabremos cuánto tiempo permanecerá la consulta en la memoria caché. Los clientes suelen utilizar este encabezado para llevar un registro de las respuestas almacenadas en la caché.
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herju26/learn
c2288a68031d1919c77934eb4ede4e5a54442e54
[ "MIT" ]
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README.md
herju26/learn
c2288a68031d1919c77934eb4ede4e5a54442e54
[ "MIT" ]
null
null
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README.md
herju26/learn
c2288a68031d1919c77934eb4ede4e5a54442e54
[ "MIT" ]
null
null
null
# learn try to learn github
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farrmt/Saunders_etal_2019_Ecol
a5a7a5645a77d704322a327a508481ba23f26eb7
[ "MIT" ]
null
null
null
README.md
farrmt/Saunders_etal_2019_Ecol
a5a7a5645a77d704322a327a508481ba23f26eb7
[ "MIT" ]
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null
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README.md
farrmt/Saunders_etal_2019_Ecol
a5a7a5645a77d704322a327a508481ba23f26eb7
[ "MIT" ]
null
null
null
# Disentangling data discrepancies with integrated population models ### Sarah P. Saunders, Matthew T. Farr, Alexander D. Wright, Christie A. Bahlai, José W. Ribeiro Jr., Sam Rossman, Allison L. Sussman, Todd W. Arnold, & Elise F. Zipkin ### Ecology ### Please contact the first author for questions about the code or data: Sarah P. Saunders ([email protected]) __________________________________________________________________________________________________________________________________________ ## Abstract: A common challenge for studying wildlife populations occurs when different observation methods (e.g. mark-recapture, census, telemetry, occupancy) provide inconsistent or incomplete inference on the trend, dynamics, or viability of a population. A potential solution to the challenge of conflicting or piecemeal data (i.e. dataset discrepancies and deficiencies, respectively) relies on the integration of multiple data types into a unified modeling framework, such as integrated population models (IPMs). IPMs are a powerful approach for species that inhabit spatially and seasonally complex environments. In cases where data come from heterogeneous collection schemes, individual data sources are unlikely to contain all the information necessary to model large-scale population dynamics, and may fail to capture spatial and temporal variability across a species’ range or annual cycle. We review how data discrepancies can be modeled with IPMs and provide guidance on combining multiple data types when there are data deficiencies. We illustrate this issue with analysis of a migratory species, the American woodcock (Scolopax minor), in which individual monitoring programs suggest differing population trends. To address this discrepancy, we synthesized several long-term datasets (1963 – 2015) within an IPM to estimate continental-scale population trends, and link dynamic drivers across the full annual cycle and complete extent of the woodcock’s geographic range in eastern North America. Our analyses reveal the limiting portions of the life cycle by identifying time periods (i.e. seasons) and locations (i.e. population units) where survival rates are lowest and most variable, as well as which demographic parameters constitute the main drivers of population change. We provide recommendations for exploiting the capabilities of IPMs to account for incongruent datasets and discuss how strategies (e.g. data weighting, data thinning) from other disciplines can be incorporated into ecological analyses that combine multiple, disparate data types. ## Code 1. [Data_manip_AMWO_marray_Git.R](https://github.com/zipkinlab/timberdoodle/blob/master/Data_manip_AMWO_marray_Git.R): Data managment and manipulation code of Banding data to create m-arrays for band-recovery model component of the IPM. 2. [AMWO_harvest_Git.R](https://github.com/zipkinlab/timberdoodle/blob/master/AMWO_harvest_Git.R): Data manipulation of harvest data (Duck Stamp Survey, Harvest Information Program, and Parts-collection Surveys) and JAGS model file and R code for estimation of annual woodcock harvest throughought temporal and spatial range of the study. 3. [IPM_AMWO_modelfile_Git.R](https://github.com/zipkinlab/timberdoodle/blob/master/IPM_AMWO_modelfile_Git.R): JAGS model file and R code for bayesian implementation of the Integrated Population model to estimate population dynamics and trends of the Eastern and Central US woodcock populations from 1963-2015. ## Data This project utilizes 3 datasets: 1) Banding-Recovery Data Description: Bird banding is a universal technique for studying the movement, survival and behavior of birds. Recovery data is also useful for estimating survival rates of both young and adult birds. Contact: USGS Bird Banding Lab Website: https://www.pwrc.usgs.gov/bbl/ 2) Hunter Harvest Data Description: The U.S. Harvest Information Program (HIP) measures hunter effort and number of woodcocks harvested by hunters annually (1963-Present). Contact: USFWS Migratory Bird Data Center Website: https://migbirdapps.fws.gov/ 3) Singing Ground Survey Description: Survey of numerous routes throughout the range of woodcocks to survey singing males during the spring. Contact: USFWS Migratory Bird Data Center Website: https://migbirdapps.fws.gov/
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book-club/the-go-programming-language/ch1/capt.1.md
alinebalogh/go-ladies-br
b6c4cb84e719e8f462b9f85c54f339a67229a347
[ "MIT" ]
4
2022-01-31T11:48:08.000Z
2022-02-04T13:53:57.000Z
book-club/the-go-programming-language/ch1/capt.1.md
alinebalogh/go-ladies-br
b6c4cb84e719e8f462b9f85c54f339a67229a347
[ "MIT" ]
1
2022-02-02T21:41:32.000Z
2022-02-02T21:41:32.000Z
book-club/the-go-programming-language/ch1/capt.1.md
alinebalogh/GoLadies
b6c4cb84e719e8f462b9f85c54f339a67229a347
[ "MIT" ]
null
null
null
## O livro base deste grupo de estudos é: A linguagem de programação GO. e o primeiro cap. do livro é um tutorial, link para o source code do tutorial: https://github.com/adonovan/gopl.io/tree/master/ch1 ### link para o livro: http://www.gopl.io/
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README.md
elm-review-bot/elm-bits
7fb5093cf2f2985b1e5e8b893e87ba785b970662
[ "MIT" ]
null
null
null
README.md
elm-review-bot/elm-bits
7fb5093cf2f2985b1e5e8b893e87ba785b970662
[ "MIT" ]
null
null
null
README.md
elm-review-bot/elm-bits
7fb5093cf2f2985b1e5e8b893e87ba785b970662
[ "MIT" ]
null
null
null
## bits Bits are a good way of storing information. The goal of this package is to enable transporting information as bits in elm. ## Example: id Current id packages have different ways of showing the contained information. This is for example how [danyx23's Uuid][danyx23/elm-uuid] does it: ```elm module CurrentUuid exposing (CurrentUuid, toString, fromString) type CurrentUuid = CurrentUuid String toString : CurrentUuid -> String toString (CurrentUuid string) = string fromString : String -> Maybe CurrentUuid fromString string = if Regex.contains (Regex.fromString "^[0-9A-Fa-f]{8,8}-[0-9A-Fa-f]{4,4}-[1-5][0-9A-Fa-f]{3,3}-[8-9A-Ba-b][0-9A-Fa-f]{3,3}-[0-9A-Fa-f]{12,12}$" |> Maybe.withDefault Regex.never ) string then Just (CurrentUuid string) else Nothing generate : Random.Generator CurrentUuid generate = Random.map (\thirtyOneHexDigits -> [ thirtyOneHexDigits |> List.take 8 |> List.map mapToHex |> String.fromList , "-" , thirtyOneHexDigits |> List.drop 8 |> List.take 4 |> List.map mapToHex |> String.fromList , "-" , "4" , thirtyOneHexDigits |> List.drop 12 |> List.take 3 |> List.map mapToHex |> String.fromList , "-" , thirtyOneHexDigits |> List.drop 15 |> List.take 1 |> List.map limitDigitRange8ToB |> List.map mapToHex |> String.fromList , thirtyOneHexDigits |> List.drop 16 |> List.take 3 |> List.map mapToHex |> String.fromList , "-" , thirtyOneHexDigits |> List.drop 19 |> List.take 12 |> List.map mapToHex |> String.fromList ] |> String.concat |> CurrentUuid ) (Random.list 31 (Random.int 0 15)) ``` With bits: ```elm module Uuid exposing (Uuid, random) -- from typesafe-array import Arr -- from bounded-nat import Nats exposing (Nat128) import Nat exposing (Only) -- from typed-value import Typed exposing (tag) type alias Uuid = Typed Tagged UuidTag Public (Arr (Only Nat128) Bit) type UuidTag = UuidTag Never random : Random.Generator Uuid random = Bits.random nat128 |> Random.map tag ``` package links: - **[typesafe-array](https://package.elm-lang.org/packages/lue-bird/elm-typesafe-array/latest/)** - which uses [bounded-nat](https://package.elm-lang.org/packages/lue-bird/elm-bounded-nat/latest/) - just an extra: [typed-value](https://package.elm-lang.org/packages/lue-bird/elm-typed-value/latest/) → type-safety & a cleaner way of storing information Bits, as a universal way of representing information, could then be - represented in a variety of ways (→ [in action](https://lue-bird.github.io/elm-bits/try/)) - different string formats (human readable (for example [michaelglass/proquint](https://package.elm-lang.org/packages/michaelglass/proquint/latest/), less character space, hexadecimal, ...) - colors, shapes, identicons ([coinop-logan/phace][coinop-logan/phace] or forks of [pukkamustard/elm-identicon](pukkamustard/elm-identicon) (e.g. [dividat/elm-identicon][dividat/elm-identicon])), ... - converted from multiple types of data - from bits directly, from characters, from ints... ```elm import Uuid exposing (Uuid) import Lue.Bit exposing (Bit(..)) import Typed exposing (tag, val) viewUuid : Uuid -> Html msg_ viewUuid uuid = val uuid -- our bits in the id |> bitsToReadableString |> Html.text uuidFromAllBits : Uuid uuidFromAllBits = -- raw bits Arr.from16 O I O I I I I O I I I I I O O O |> InArr.append nat16 (Arr.from16 I I I O O O O I O I I I I O I I) -- ... |> tag uuidFromChars : Uuid uuidFromChars = let c char = InArr.append nat20 (charToBits char) in Arr.empty -- the first 120 bits |> c '骖' |> c '򥔤' |> c '򚔤' |> c '򒒔' |> c '񉉉' |> c '𥩒' -- the last 8 bits |> InArr.append nat8 (Arr.from8 O I O I I I I O) |> tag -- from another package charToBits : Char -> Arr (In Nat20 (Nat20Plus a_)) Bit bitsToReadableString : Arr (In min_ max_) Bit -> String ``` Notice how all of these can build `Uuid`s _safely_ from _different sources of information_. → This package currently contains the building blocks in relation to bits. They can be generated, modified, read and serialized. [coinop-logan/phace]: https://package.elm-lang.org/packages/coinop-logan/phace/latest/ [pukkamustard/elm-identicon]: https://github.com/pukkamustard/elm-identicon [dividat/elm-identicon]: https://package.elm-lang.org/packages/dividat/elm-identicon/latest/ [danyx23/elm-uuid]: https://package.elm-lang.org/packages/danyx23/elm-uuid/latest/Uuid
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TestCase_3_Get_Hash.md
anugushravya/broken-hash
d110b8d7d9e449eff19398e20efb842594bc3008
[ "MIT" ]
null
null
null
TestCase_3_Get_Hash.md
anugushravya/broken-hash
d110b8d7d9e449eff19398e20efb842594bc3008
[ "MIT" ]
3
2020-01-19T19:02:24.000Z
2020-01-19T19:48:29.000Z
TestCase_3_Get_Hash.md
anugushravya/broken-hash
d110b8d7d9e449eff19398e20efb842594bc3008
[ "MIT" ]
null
null
null
# [3] : Get Hash Request ## Description A GET to /hash should accept a job identifier. It should return the base64 encoded password hash for the corresponding POST request. ### Precondition 1. The hash application should be listening at PORT 8088 and ready to accept curl requests. 2. A POST submitted to the hash application, and it successfully returned a hash identifier. ### Assumptions Hash application is running on a windows machine. Curl installed on the machine for sending requests. ## Test Steps 1. Open Command Prompt 2. SET PORT=8088 3. Execute broken-hashserve_win.exe 4. Using curl application run the following command curl -H "application/json" http://127.0.0.1:8088/hash/1 ## Expected Result The curl command should return the base64 encoded password has. For example, Password text "angrybirds" will return. NN0PAKtieayiTY8/Qd53AeMzHkbvZDdwYYiDnwtDdv/FIWvcy1sKCb7qi7Nu8Q8Cd/MqjQeyCI0pWKDGp74A1g== ![Get Request](hash-get-retreival.PNG)
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README.md
jdgwartney/meter-plugin-metrics
9d388c79b32eb153033298239f0c8c58ade0a090
[ "Apache-2.0" ]
null
null
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README.md
jdgwartney/meter-plugin-metrics
9d388c79b32eb153033298239f0c8c58ade0a090
[ "Apache-2.0" ]
null
null
null
README.md
jdgwartney/meter-plugin-metrics
9d388c79b32eb153033298239f0c8c58ade0a090
[ "Apache-2.0" ]
null
null
null
# meter-plugin-metrics Sample plugin to test loading of metrics definitions
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sitescore/OfficeDevPnP.Core.Entities.WebPartEntity.ctor1.md
Laul0/PnP-Guidance
81353471222abae26bc6459844bcde148dcf7752
[ "MIT" ]
null
null
null
sitescore/OfficeDevPnP.Core.Entities.WebPartEntity.ctor1.md
Laul0/PnP-Guidance
81353471222abae26bc6459844bcde148dcf7752
[ "MIT" ]
null
null
null
sitescore/OfficeDevPnP.Core.Entities.WebPartEntity.ctor1.md
Laul0/PnP-Guidance
81353471222abae26bc6459844bcde148dcf7752
[ "MIT" ]
null
null
null
# WebPartEntity.WebPartEntity members **Namespace:** [OfficeDevPnP.Core.Entities](OfficeDevPnP.Core.Entities.md) **Assembly:** OfficeDevPnP.Core.dll ## Syntax ```C# public WebPartEntity() ``` ## See also - [WebPartEntity](OfficeDevPnP.Core.Entities.WebPartEntity.md) - [OfficeDevPnP.Core.Entities](OfficeDevPnP.Core.Entities.md)
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_posts/2017-02-10-aws-change-kernel.md
datacabinet/datacabinet-pixyll
78f58fe41c7c659ad5d931e8b0be36099829d51a
[ "MIT" ]
null
null
null
_posts/2017-02-10-aws-change-kernel.md
datacabinet/datacabinet-pixyll
78f58fe41c7c659ad5d931e8b0be36099829d51a
[ "MIT" ]
null
null
null
_posts/2017-02-10-aws-change-kernel.md
datacabinet/datacabinet-pixyll
78f58fe41c7c659ad5d931e8b0be36099829d51a
[ "MIT" ]
null
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--- layout: post title: Changing kernel of a AWS CentOS 7 instance date: 2014-06-09 12:32:18 summary: Notes on C++ categories: jekyll pixyll --- * spawn the base image of Centos 7 HVM : aws ec2 run-instances --image-id ami-d2c924b2 \ --key-name pankaj-ec2-key --instance-type t2.micro\ --block-device-mapping '[{ "DeviceName" : "/dev/sda1","Ebs" : { "DeleteOnTermination": true, "VolumeSize" : 15 }}]'\ --placement AvailabilityZone=us-west-2b\ --security-groups DataCabinetSSHGroup default * login to the VM and download the better kernel from epel repo rpm --import https://www.elrepo.org/RPM-GPG-KEY-elrepo.org rpm -Uvh http://www.elrepo.org/elrepo-release-7.0-2.el7.elrepo.noarch.rpm yum remove kernel-headers kernel-tools kernel-tools-libs yum --enablerepo=elrepo-kernel install kernel-ml grep -P "submenu|^menuentry" /boot/grub2/grub.cfg | cut -d "'" -f2 | grep elrepo | xargs -d "\n" grub2-set-default grub2-mkconfig -o /boot/grub2/grub.cfg #3 Reboot and make sure that the new kernel is getting used [centos@ip-172-31-26-71 ~]$ uname -a Linux ip-172-31-26-71.us-west-2.compute.internal 4.9.8-1.el7.elrepo.x86_64 #1 SMP Sat Feb 4 11:47:44 EST 2017 x86_64 x86_64 x86_64 GNU/Linux #4 Stop the instance aws ec2 stop-instances --instance-ids $instance_id aws ec2 wait instance-stopped --instance-ids $instance_id This step is necessary otherwise aws screws up the grub2 configuration when imaging live instance #5 Take image image_id=`aws ec2 create-image --instance-id $instance_id --name $1 | grep ImageId | sed 's/\".*\"://' | tr -d '[:space:]' | sed -e 's/^"//' -e 's/"$//'` aws ec2 wait image-available --image-id $image_id
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Markdown
2020-03/2020-03-16_short.md
admariner/trending_archive
ffca6522c4fdaa5203c3f18d9a5a7d7da098169c
[ "MIT" ]
80
2015-02-13T16:52:22.000Z
2022-03-10T20:13:08.000Z
2020-03/2020-03-16_short.md
admariner/trending_archive
ffca6522c4fdaa5203c3f18d9a5a7d7da098169c
[ "MIT" ]
65
2021-10-02T05:54:01.000Z
2021-12-28T22:50:23.000Z
2020-03/2020-03-16_short.md
admariner/trending_archive
ffca6522c4fdaa5203c3f18d9a5a7d7da098169c
[ "MIT" ]
16
2015-10-08T11:06:28.000Z
2021-06-30T07:26:49.000Z
### 2020-03-16 diff between today and yesterday #### python * [BlankerL/DXY-COVID-19-Data](https://github.com/BlankerL/DXY-COVID-19-Data): 2019 | COVID-19/2019-nCoV Infection Time Series Data Warehouse * [CTF-MissFeng/bayonet](https://github.com/CTF-MissFeng/bayonet): bayonetsrc * [3b1b/manim](https://github.com/3b1b/manim): Animation engine for explanatory math videos * [sibirbil/IMO2020](https://github.com/sibirbil/IMO2020): stanbul'da Makine renmesi (27 Ocak- 2 ubat, 2020) - Ders malzemeleri * [pi-hole/docker-pi-hole](https://github.com/pi-hole/docker-pi-hole): Pi-hole in a docker container * [keras-team/keras](https://github.com/keras-team/keras): Deep Learning for humans * [xiyouMc/WebHubBot](https://github.com/xiyouMc/WebHubBot): Python + Scrapy + MongoDB . 5 million data per day !!! The world's largest website. * [pikpikcu/Pentest-Tools-Framework](https://github.com/pikpikcu/Pentest-Tools-Framework): Pentest Tools Framework is a database of exploits, Scanners and tools for penetration testing. Pentest is a powerful framework includes a lot of tools for beginners. You can explore kernel vulnerabilities, network vulnerabilities * [cirosantilli/linux-kernel-module-cheat](https://github.com/cirosantilli/linux-kernel-module-cheat): The perfect emulation setup to study and develop the Linux kernel v5.4.3, kernel modules, QEMU, gem5 and x86_64, ARMv7 and ARMv8 userland and baremetal assembly, ANSI C, C++ and POSIX. GDB step debug and KGDB just work. Powered by Buildroot and crosstool-NG. Highly automated. Thoroughly documented. Automated tests. "Tested" in an Ubuntu 19.10 host. * [Unity-Technologies/ml-agents](https://github.com/Unity-Technologies/ml-agents): Unity Machine Learning Agents Toolkit * [gto76/python-cheatsheet](https://github.com/gto76/python-cheatsheet): Comprehensive Python Cheatsheet * [thunil/TecoGAN](https://github.com/thunil/TecoGAN): This repo will contain source code and materials for the TecoGAN project, i.e. code for a TEmporally COherent GAN * [zhukeyi123/Python_Work](https://github.com/zhukeyi123/Python_Work): * [giddyyupp/ganilla](https://github.com/giddyyupp/ganilla): pytorch implementation of GANILLA * [ioncodes/SMBGhost](https://github.com/ioncodes/SMBGhost): Scanner for CVE-2020-0796 - A SMBv3.1.1 + SMB compression RCE * [cosmicpython/book](https://github.com/cosmicpython/book): A Book about Pythonic Application Architecture Patterns for Managing Complexity. Cosmos is the Opposite of Chaos you see. O'R. wouldn't actually let us call it "Cosmic Python" tho. * [TheAlgorithms/Python](https://github.com/TheAlgorithms/Python): All Algorithms implemented in Python * [google/jax](https://github.com/google/jax): Composable transformations of Python+NumPy programs: differentiate, vectorize, JIT to GPU/TPU, and more #### go * [OJ/gobuster](https://github.com/OJ/gobuster): Directory/File, DNS and VHost busting tool written in Go * [aceld/zinx](https://github.com/aceld/zinx): GolangTCP * [quii/learn-go-with-tests](https://github.com/quii/learn-go-with-tests): Learn Go with test-driven development * [similarweb/statusbay](https://github.com/similarweb/statusbay): Kubernetes deployment visibility like a pro * [Dreamacro/clash](https://github.com/Dreamacro/clash): A rule-based tunnel in Go. * [pingcap/chaos-mesh](https://github.com/pingcap/chaos-mesh): A Chaos Engineering Platform for Kubernetes * [hashicorp/consul](https://github.com/hashicorp/consul): Consul is a distributed, highly available, and data center aware solution to connect and configure applications across dynamic, distributed infrastructure. * [monitoror/monitoror](https://github.com/monitoror/monitoror): Unified monitoring wallboard Light, ergonomic and reliable monitoring for anything. * [peterq/pan-light](https://github.com/peterq/pan-light): , golang + qt5, * [gwuhaolin/lightsocks](https://github.com/gwuhaolin/lightsocks): * [wenjianzhang/go-admin](https://github.com/wenjianzhang/go-admin): Gin + Vue + Element UI * [oragono/oragono](https://github.com/oragono/oragono): A modern IRC server (daemon/ircd) written in Go. * [reviewdog/reviewdog](https://github.com/reviewdog/reviewdog): Automated code review tool integrated with any code analysis tools regardless of programming language #### cpp * [google/or-tools](https://github.com/google/or-tools): Google's Operations Research tools: * [flightlessmango/MangoHud](https://github.com/flightlessmango/MangoHud): A Vulkan and OpenGL overlay for monitoring FPS, temperatures, CPU/GPU load and more. Discord: https://discordapp.com/invite/Gj5YmBb * [pisa-engine/pisa](https://github.com/pisa-engine/pisa): PISA: Performant Indexes and Search for Academia * [Aircoookie/WLED](https://github.com/Aircoookie/WLED): Control WS2812B RGB LEDs with an ESP8266 over WiFi! * [luc-github/ESP3D](https://github.com/luc-github/ESP3D): FW for ESP8266/ESP8285/ESP32 used with 3D printer * [mozilla/DeepSpeech](https://github.com/mozilla/DeepSpeech): A TensorFlow implementation of Baidu's DeepSpeech architecture * [yuzu-emu/yuzu](https://github.com/yuzu-emu/yuzu): Nintendo Switch Emulator * [xoseperez/espurna](https://github.com/xoseperez/espurna): Home automation firmware for ESP8266-based devices * [Errichto/youtube](https://github.com/Errichto/youtube): codes for my streams and YT videos * [polybar/polybar](https://github.com/polybar/polybar): A fast and easy-to-use status bar * [dolphin-emu/dolphin](https://github.com/dolphin-emu/dolphin): Dolphin is a GameCube / Wii emulator, allowing you to play games for these two platforms on PC with improvements. * [zxystd/IntelBluetoothFirmware](https://github.com/zxystd/IntelBluetoothFirmware): Intel bluetooth drivers * [google/leveldb](https://github.com/google/leveldb): LevelDB is a fast key-value storage library written at Google that provides an ordered mapping from string keys to string values. * [TrinityCore/TrinityCore](https://github.com/TrinityCore/TrinityCore): TrinityCore Open Source MMO Framework (master = 8.3.0.33528, 3.3.5 = 3.3.5a.12340) * [nRF24/RF24](https://github.com/nRF24/RF24): Optimized fork of nRF24L01 for Arduino & Raspberry Pi/Linux Devices * [RPCS3/rpcs3](https://github.com/RPCS3/rpcs3): PS3 emulator/debugger * [ethereum/solidity](https://github.com/ethereum/solidity): Solidity, the Contract-Oriented Programming Language * [supercollider/supercollider](https://github.com/supercollider/supercollider): An audio server, programming language, and IDE for sound synthesis and algorithmic composition. * [ValveSoftware/Proton](https://github.com/ValveSoftware/Proton): Compatibility tool for Steam Play based on Wine and additional components * [LeelaChessZero/lc0](https://github.com/LeelaChessZero/lc0): The rewritten engine, originally for tensorflow. Now all other backends have been ported here. #### javascript * [opencovid19-fr/data](https://github.com/opencovid19-fr/data): Consolidation des donnes de sources officielles concernant l'pidmie de COVID19 * [Code-Pop/watch-us-build-trello](https://github.com/Code-Pop/watch-us-build-trello): * [vuejs/vuex](https://github.com/vuejs/vuex): Centralized State Management for Vue.js. * [ccxt/ccxt](https://github.com/ccxt/ccxt): A JavaScript / Python / PHP cryptocurrency trading API with support for more than 120 bitcoin/altcoin exchanges * [OHIF/Viewers](https://github.com/OHIF/Viewers): OHIF zero-footprint DICOM viewer and oncology specific Lesion Tracker, plus shared extension packages * [lazd/coronadatascraper](https://github.com/lazd/coronadatascraper): A scraper that pulls coronavirus case data from verified sources. * [lesspass/lesspass](https://github.com/lesspass/lesspass): stateless open source password manager * [lyswhut/lx-music-desktop](https://github.com/lyswhut/lx-music-desktop): electron * [tanaypratap/teamtanay.jobchallenge.dev](https://github.com/tanaypratap/teamtanay.jobchallenge.dev): The web repository for all things #teamtanayjobchallenge * [DIYgod/RSSHub](https://github.com/DIYgod/RSSHub): Everything is RSSible * [nuxt-community/auth-module](https://github.com/nuxt-community/auth-module): Zero-boilerplate authentication support for Nuxt * [haotian-wang/google-access-helper](https://github.com/haotian-wang/google-access-helper): * [SadeghHayeri/GreenTunnel](https://github.com/SadeghHayeri/GreenTunnel): GreenTunnel is an anti-censorship utility designed to bypass the DPI system that is put in place by various ISPs to block access to certain websites. * [2019ncovmemory/nCovMemory](https://github.com/2019ncovmemory/nCovMemory): 2020 Memory of 2020 nCoV: Media Coverage, Non-fiction Writings, and Individual Narratives (Continuously updating) * [MichMich/MagicMirror](https://github.com/MichMich/MagicMirror): MagicMirror is an open source modular smart mirror platform. With a growing list of installable modules, the MagicMirror allows you to convert your hallway or bathroom mirror into your personal assistant. #### coffeescript * [michaelficarra/CoffeeScriptRedux](https://github.com/michaelficarra/CoffeeScriptRedux): rewrite of the CoffeeScript compiler with proper compiler design principles and a focus on robustness and extensibility
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2020/08/09/2020-08-09 13:25.md
zhzhzhy/WeiBoHot_history
32ce4800e63f26384abb17d43e308452c537c902
[ "MIT" ]
3
2020-07-14T14:54:15.000Z
2020-08-21T06:48:24.000Z
2020/08/09/2020-08-09 13:25.md
zhzhzhy/WeiBoHot_history
32ce4800e63f26384abb17d43e308452c537c902
[ "MIT" ]
null
null
null
2020/08/09/2020-08-09 13:25.md
zhzhzhy/WeiBoHot_history
32ce4800e63f26384abb17d43e308452c537c902
[ "MIT" ]
null
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null
2020年08月09日13时数据 Status: 200 1.张雨绮回应伊能静小作文 微博热度:3832293 2.日本研究发现变异新冠病毒 微博热度:3111881 3.打卡大武汉开启新旅程 微博热度:3111110 4.深圳航空ZH9209 微博热度:3034775 5.杨迪 我必须和你杠到底 微博热度:2983402 6.吴磊 微博热度:2558626 7.虽然是精神病但没关系首尾呼应 微博热度:1391811 8.26岁工学女博士获聘湖南大学副教授 微博热度:787010 9.白岩松谈张玉环案 微博热度:735443 10.黎巴嫩首都发生大规模示威活动 微博热度:708159 11.王漫妮最后还是单身 微博热度:684582 12.贾玲吴彤为杨迪发声 微博热度:593619 13.深圳航空一架客机遇紧急情况返航 微博热度:460279 14.以家人之名超长片花 微博热度:460093 15.全美共发现超33.8万名儿童感染新冠 微博热度:454554 16.深圳航空回应航班紧急返航 微博热度:450841 17.朴宰范加盟中国新说唱 微博热度:447399 18.soul崩了 微博热度:444319 19.河南特岗 微博热度:443023 20.35名老兵守护去世战友女儿长大 微博热度:435888 21.木工爷爷为小孙子做螳螂车 微博热度:427528 22.张月发文与林有有道别 微博热度:420256 23.大爷卖鹅违章交警全部买下 微博热度:411870 24.河北科技大学 微博热度:408568 25.美国每66人中就有1人感染新冠病毒 微博热度:406271 26.张公案 微博热度:387717 27.严浩翔粉和李泽言粉 微博热度:361970 28.时代少年团 姐姐真漂亮 微博热度:349703 29.恋与制作人 微博热度:343675 30.黎巴嫩外交部被抗议者占领 微博热度:319887 31.韩国暴雨已造成28人死亡 微博热度:314899 32.张艺兴小绵羊变成老狐狸了 微博热度:301852 33.王嘉尔震惊到说了九个哇 微博热度:291053 34.黄鹤楼免票首日客流量涨3倍 微博热度:243060 35.荷兰驻黎巴嫩大使夫人在爆炸中身亡 微博热度:233715 36.70年代大熊猫街头卖艺 微博热度:227692 37.王一博被迫撒娇 微博热度:223422 38.雪炫 微博热度:215100 39.梅西一条龙 微博热度:200441 40.微软 微博热度:199820 41.粉笔模考 微博热度:197078 42.今天国际猫咪日 微博热度:172305 43.NBA各奖项候选名单 微博热度:160360 44.核电站海底种珊瑚 微博热度:147358 45.恋与制作人声明 微博热度:142013 46.声音玩具淘汰 微博热度:141001 47.权珉娥 我不要委屈地离开 微博热度:138521 48.福建平潭暖夜灯柱 微博热度:136946 49.新疆新增15例本土病例 微博热度:133728 50.粉丝机场送毛不易毛氏场面话 微博热度:132895
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_includes/04-lists.md
writeClearly/markdown-portfolio
f96907d338c70fc5360db3d527beea0ac9e5f338
[ "MIT" ]
null
null
null
_includes/04-lists.md
writeClearly/markdown-portfolio
f96907d338c70fc5360db3d527beea0ac9e5f338
[ "MIT" ]
5
2021-04-08T16:49:41.000Z
2021-04-11T12:24:36.000Z
_includes/04-lists.md
writeClearly/markdown-portfolio
f96907d338c70fc5360db3d527beea0ac9e5f338
[ "MIT" ]
null
null
null
Replace this with a list of your favorite things. # ✔️ \*:MyEmoji\* - [ ] Unchecked require space inside brackets to work - [x] Checked 1. Ordered 2. List 1. Nested 2. Inside 3. To achive 4. Press 5. Tab 6. Twice - Dash is enough for unordered list - Line break \<br\><br> . What if i place a random dot
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_cards/BLYTHE.md
stokeclimsland/stokeclimsland
93ce79c0012842783608410a6823c4bb46b0b466
[ "MIT" ]
null
null
null
_cards/BLYTHE.md
stokeclimsland/stokeclimsland
93ce79c0012842783608410a6823c4bb46b0b466
[ "MIT" ]
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null
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_cards/BLYTHE.md
stokeclimsland/stokeclimsland
93ce79c0012842783608410a6823c4bb46b0b466
[ "MIT" ]
null
null
null
--- title: BLYTHE is_name: true --- BLYTH(E)
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_posts/etc/2020-08-02-add-gist-plugin.markdown
daesungRa/namu
8a6e5b74a20189fb56d498155e81f55daeb03f52
[ "MIT" ]
null
null
null
_posts/etc/2020-08-02-add-gist-plugin.markdown
daesungRa/namu
8a6e5b74a20189fb56d498155e81f55daeb03f52
[ "MIT" ]
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2022-03-27T08:08:46.000Z
_posts/etc/2020-08-02-add-gist-plugin.markdown
daesungRa/namu
8a6e5b74a20189fb56d498155e81f55daeb03f52
[ "MIT" ]
null
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--- title: 지킬 블로그에 플러그인 추가하기(with gist) date: 2020-07-30 22:23:00 +0900 author: namu categories: etc permalink: "/etc/:year/:month/:day/:title" image: https://jekyllrb.com/img/jekyll-og.png image-view: true image-author: jekyllrb image-source: https://jekyllrb.com/img/jekyll-og.png --- --- [목차] 1. [들어가며](#들어가며) 2. [플러그인 추가하기](#플러그인-추가하기) 3. [gist 추가해보기](#gist-추가해보기) --- ### 들어가며 [지킬```jekyll```](https://jekyllrb.com/docs/)은 [```ruby on rails```](https://rubyonrails.org/) 프레임워크 기반 정적 사이트 생성기이다. 지금 이 블로그도 지킬로 빌드되어 [```github.io```](https://pages.github.com/) 에서 자동배포되고 있다. 블로그 구축 과정은 꽤나 복잡하니 다음에 다뤄 보기로 하고.. 오늘은 이 지킬 블로그에 새로운 플러그인을 추가하는 방법을 알아보자. 설치할 플러그인은 [**```jekyll-gist```**](https://github.com/jekyll/jekyll-gist)이다. ### 플러그인 추가하기 각 플러그인들은 [Ruby gem](https://rubygems.org/) 이라는 패키지 라이브러리 관리자를 통해 설치 및 관리가 가능하다. 이것을 활용하면 [rubygems.org](https://rubygems.org/) 아카이브로부터 데이터를 가져온다(yum 이나 apt 와 같은 역할). 또한 이 관리자는 사용자 PC의 환경(CPU, OS 등)에 따라서 구분되어 있으므로, 버전을 확인하는것이 꼭 필요하다. 지킬 패키지 관리도 이를 통해 이루어진다. 이제 내 지킬 프로젝트의 Gemfile 에 설치하고자 하는 플러그인을 추가해보자. ```text $ gem "jekyll-gist" ``` 혹은, 곧바로 설치하기 위해 다음과 같이 하거나, ```text $ gem install jekyll-gist ``` 직접 Gemfile 에 라인을 추가한다. ```text [Gemfile] ... gem "jekyll", "~> 3.7.4" ... # Windows and JRuby does not include zoneinfo files, so bundle the tzinfo-data gem # and associated library. install_if -> { RUBY_PLATFORM =~ %r!mingw|mswin|java! } do ... gem "jekyll-gist", "~> 1.5.0" ... end ``` 세 가지 방법은 모두 Gemfile 에 라인을 추가하는 동일한 작업이다. 방법의 차이일 뿐이다. 그러나 만약 의존성을 기입하지 않았다면 gem 을 다룰 때 [```bundler```](https://ruby-korea.github.io/bundler-site/) 가 필요하다. 이것은 자동으로 패키지 의존성을 관리해주는 도구이다. 위 세 번재 방식에서는 ```jekyll-gist``` 1.5.0 버전이 ```jekyll``` 3.7.4 버전에 의존되도록 정의되어 있으나(3.0.0 이상), 나머지 방식에는 따로 정의되지 않았으므로, bundler 를 활용해야 한다. 사실상 항시 bundler 를 통한다고 생각하면 된다. ```text $ bundler update ``` 현재 프로젝트에서 Gemfile 에 기록된 목록대로 패키지 의존성 업데이트를 시도한다.<br> 이제 프로젝트의 ```_config.yaml``` 에 설치한 ```jekyll-gist``` 를 입력하고, ```text # Build settings # theme: lagrange plugins: ... - jekyll-gist ``` 빌드 및 서비스를 해보자. ```text $ bundle exec jekyll serve ``` 빌드 잘 된다! ![my_blog01](https://daesungra.github.io/namu/assets/img/my_blog01.png) ### gist 추가해보기 gist 는 코드블럭 등을 github 아카이브에 저장해두고 링크를 통해 참조할 수 있는 너무너무 깔끔하고 손쉬운 기능이다. 이제 플러그인 설치와 빌드가 완료되었으므로, 내 post 에 gist 박스를 추가해보자. [gist.github.com](https://gist.github.com/) 에 접속하고 github 계정으로 로그인하면 바로 코드블럭을 만들 수 있다. ![gist_smpl01](https://daesungra.github.io/namu/assets/img/gist_smpl01.png) secret 혹은 public 방식으로 gist 를 create 한 뒤에 생성된 gist 키값을 post 의 원하는 위치에 다음과 같이 추가해주면 된다. ```text {% raw %}{% gist daesungRa/07ea5ccd0c1b7576e1a4421bff35e944 %}{% endraw %} ``` 그럼 gist.github 사이트의 링크로부터 코드블럭을 불러와 삽입해준다! ![gist_smpl02](https://daesungra.github.io/namu/assets/img/gist_smpl02.png) 끝~
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Markdown
_posts/book/2021-03-02-book_1.md
LEESONGHO/GitHubPageMaker
569c04908e48ff42ca8bd5e403fda3d471aa87dd
[ "MIT" ]
1
2021-03-01T13:50:54.000Z
2021-03-01T13:50:54.000Z
_posts/book/2021-03-02-book_1.md
LEESONGHO/GitHubPageMaker
569c04908e48ff42ca8bd5e403fda3d471aa87dd
[ "MIT" ]
1
2021-03-01T16:01:07.000Z
2021-03-01T16:01:07.000Z
_posts/book/2021-03-02-book_1.md
LEESONGHO/GitHubPageMaker
569c04908e48ff42ca8bd5e403fda3d471aa87dd
[ "MIT" ]
null
null
null
--- layout: post current: post cover: assets/built/images/book-logo.png navigation: True title: Book post (1) - 연습용 업로드 1 date: 2021-03-02 00:20:00 tags: [book] class: post-template subclass: 'post tag-book' author: LEESONGHO --- {% include book-table-of-contents.html %} 이 글은 첫번째 Book post 입니다.
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README.md
c1156010/user20demorepo
0b1c9232dd94f262a8403e3634a7e3021c79105d
[ "MIT" ]
null
null
null
README.md
c1156010/user20demorepo
0b1c9232dd94f262a8403e3634a7e3021c79105d
[ "MIT" ]
null
null
null
README.md
c1156010/user20demorepo
0b1c9232dd94f262a8403e3634a7e3021c79105d
[ "MIT" ]
null
null
null
# user19demorepo Demo Repository
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README.md
tombartkowski/Flowy
bbbed69c8e30457deee7e73ef588bf81bc4983d3
[ "MIT" ]
null
null
null
README.md
tombartkowski/Flowy
bbbed69c8e30457deee7e73ef588bf81bc4983d3
[ "MIT" ]
null
null
null
README.md
tombartkowski/Flowy
bbbed69c8e30457deee7e73ef588bf81bc4983d3
[ "MIT" ]
null
null
null
<p align="center"> <a href="https://raw.githubusercontent.com/tombartkowski/Flowy"> <img src="logo.png" alt="Logo" width="150" height="140"> </a> <h2 align="center"><b>Flowy</b></h2> <p align="center"> Reactive & declarative event-driven coordination in Swift. <br /> <br /> <a href="#features">Features </a> • <a href="#quick-example">Example</a> • <a href="#usage">Usage</a> • <a href="#installation">Installation</a> </p> </p> <p align="center"> <a href="https://developer.apple.com/swift/"><img alt="Swift 5.2" src="https://img.shields.io/badge/swift-5.2-orange.svg?style=flat"></a> <a href="https://github.com/tombartkowski/Flowy/LICENSE"><img alt="License" src="https://img.shields.io/github/license/tombartkowski/Flowy"></a> <a href="https://github.com/tombartkowski/Flowy"><img alt="Build Status" src="https://img.shields.io/github/last-commit/tombartkowski/Flowy"></a> </p> <details open="open"> <summary><h2 style="display: inline-block">Table of Contents</h2></summary> <ol> <li> <a href="#features">Features</a> </li> <li> <a href="#quick-example">Quick Example</a> </li> <li> <a href="#installation">Installation</a> </li> <li><a href="#usage">Usage</a></li> <li><a href="#license">License</a></li> <li><a href="#contact">Contact</a></li> <li><a href="#acknowledgements">Acknowledgements</a></li> </ol> </details> ## Features - :white_check_mark: Declarative - declare your Flows behaviour in one place, - :white_check_mark: Reactive - no more imperative coordination thanks to `RxSwift`, - :white_check_mark: Event-driven - emit flow events from anywhere and coordination will follow, - :white_check_mark: Easier decoupling of views, - :white_check_mark: Simple to get started. ## Quick Example ```swift enum MyFlowEvent: FlowEvent { case detailRequired } class DetailFlow: Flow {} class MasterFlow: Flow { func nextFlowType(for event: FlowEvent) -> FlowType? { if case event = MyFlowEvent.detailRequired { return DetailFlow.self } return nil } } let flowy = Flowy(rootFlow: MasterFlow()) flowy.registerFlow(DetailFlow.self) { root -> DetailFlow in DetailFlow( presentableParent: root, presentable: UIViewController() ) } flowy.start() //This will perform a transition MasterFlow -> DetailFlow DefaultEventsSource.shared.events.onNext(MyFlowEvent.detailRequired) ``` ## Installation ### Requirements - Deployment target iOS 10.0+ - Swift 5+ - Xcode 10+ #### CocoaPods Flowy is available through [CocoaPods](https://cocoapods.org). To install it, simply add the following line to your Podfile: ```ruby pod 'Flowy' ``` ## Usage ### Basics Flowy works with `Flows` and `FlowEvents`. You can think of a `Flow` as a `UIViewController`, or rather an object that references it and the `UIViewController` that presented it. Each `Flow` defines a map of `FlowEvents` to `Flows` which specifies which `Flow` to transition to on a given `FlowEvent`. `Flow` also defines a list of `FlowEvents` that dissmis the `Flow` when emitted. ### Defining Flows To create a basic `Flow` simply create a subclass of the `Flow`. ```swift import Flowy class MasterFlow: Flow { override func nextFlowType(for event: FlowEvent) -> FlowType? { if case event = MyFlowEvent.detailRequired { return DetailFlow.self } return nil } override var presentationMode: Flow.PresentationMode { .modal } override var dismissingEvents: [FlowEvent] { [MyFlowEvent.masterDone] } } ``` Example above will transition to `DetailFlow` when `.detailRequired` event gets emitted. It will also dismiss itself when `.masterDone` event is emitted. `presentationMode` specifies that this `Flow` should always be presented modally. Flowy ships with `NavigationFlow` and `TabBarFlow` that handle the `UINavigationController` and `UITabBarController` navigation under the hood. ### Defining FlowEvents To use Flowy you need to define at least one entity that conforms to the `FlowEvent` protocol. In practice that can mean defining a simple `enum`. ```swift import Flowy enum MyFlowEvent: FlowEvent { case detailRequired case detailDone case masterDone } ``` You can create as many `enums` or `structs` as you wish as long they conform to the `FlowEvent` protocol. #### transitionKey `transitionKey: String?` is an optional property that specifies a concrete `Flow` to transition to when multiple `FlowEvents` trigger one `Flow`. ### Creating a FlowEventsSourceable `FlowEventsSourceable` is a `protocol` responsible for delivering `FlowEvents` from your app to Flowy. To create one it's enough to do following. ```swift import Flowy import RxSwift class MyFlowEventsSource: FlowEventsSourceable { let events = PublishSubject<FlowEvent>() } ``` You should always use the same instance of `FlowEventsSourceable` that you passed to the `Flowy` instance. The best way to do it is via _Dependency Incjetion_, but this is out of scope of this document. ### Creating Flowy `Flowy` is the bridge between your app and the Flowy coordination engine. To create one you need a root `Flow` that will begin the coordination and `FlowEventsSourceable` that will drive it. ```swift import Flowy let rootFlow = MyRootFlow() let eventsSource = MyFlowEventsSource() let flowy = Flowy( rootFlow: rootFlow, eventsSource: eventsSource ) ``` You must keep a strong reference to the `flowy` instance. The easiest way to do this is to store it in your `AppDelegate` as a instance property. #### Registering Flows To create the needed `Flow` instances during runtime and avoid overhead of creating all views on startup, Flowy uses factory closures to instantiate your `Flows`. You can think of it as teaching Flowy it should create your `Flows` when the time comes to present them. To register a `Flow`: ```swift let flowy = Flowy(...) flowy.registerFlow(DetailFlow.self) { root -> DetailFlow in DetailFlow( presentableParent: root, presentable: MyViewController() ) } ``` `root` is the `Presentable` of the `Flow` that coordinates to the `DetailFlow`. `Presentable` is an abstraction over things that can be presented, currently only `UIViewControllers`. It is a good idea to use a _Dependency Injection_ along with Flowy to create your `UIViewControllers`. ```swift let container = DependenciesContainer() // Container of registered dependencies, usually provided by a framework like Swinject. let flowy = Flowy(...) flowy.registerFlow(DetailFlow.self) { root -> DetailFlow in DetailFlow( presentableParent: root, presentable: container.resolve(MyViewController.self) ) } ``` ### Starting the coordination After instantiating `Flowy` and registering your `Flows` you just have to call the `start()` method. ```swift let flowy = Flowy(...) flowy.registerFlow(...) flowy.registerFlow(...) flowy.start() ``` ## License Flowy is available under the MIT license. See the LICENSE file for more info. ## Contact Tomasz Bartkowski - [@tombartkowski](https://twitter.com/bartkowskitom) - [email protected] ## Acknowledgements - Icons made by [Freepik](https://www.freepik.com) from [www.flaticon.com](https://www.flaticon.com/)
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docs/technical-details.md
uwec-innovation-labs/parkingNotifier
e59c6138111c1269592cf54c08a661f491b24489
[ "MIT" ]
3
2018-12-16T21:16:02.000Z
2019-03-31T21:29:08.000Z
docs/technical-details.md
clearwater-labs/parkingNotifier
e59c6138111c1269592cf54c08a661f491b24489
[ "MIT" ]
139
2018-12-03T15:39:05.000Z
2019-07-10T13:44:42.000Z
docs/technical-details.md
clearwater-labs/parkingNotifier
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[ "MIT" ]
null
null
null
# Technical Details ## Status Monitoring The status of the roads are monitored by scraping the [city website](http://www.ci.eau-claire.wi.us/home). The `monitor.js` file is the controller for the scraping of the website. The script checks for an alert banner at the top of the website, and if the banner is there, it visits the announcement linked to make sure it's a snow emergency alert. This automated check is performed every 30 minutes. If the announcement is a snow emergency, the script takes the contents of announcement and inserts it into a database. ## SMS alerts SMS alerts are sent out using the database of subscribers. The provider for the messaging is [Twilio](https://www.twilio.com/). This service is the most convenient because it does not require knowledge of carriers and is extremely reliable. ## Development Instructions Instructions for development can be found [here](./configuration.md) ## Versioning Parking Notifier API will be maintained under the [Semantic Versioning guidelines](http://semver.org) guidelines as much as possible. Releases will be numbered with the following format: `<major>.<minor>.<patch>` And constructed with the following guidelines: Breaking backward compatibility bumps the major (and resets the minor and patch). New additions, including new icons, without breaking backward compatibility bumps the minor (and resets the patch). Bug fixes, changes to brand logos, and misc changes bumps the patch. ## Docker Info Docker is used to containerize the project. More info about Docker can be found here: https://docs.docker.com/get-started/#docker-concepts
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numworks/setup-emscripten
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[ "MIT" ]
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2021-12-19T23:26:58.000Z
2021-12-19T23:26:58.000Z
README.md
numworks/setup-emscripten
95db1a77a6201e5fe8fdfccb066da94a9ed14ebf
[ "MIT" ]
null
null
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README.md
numworks/setup-emscripten
95db1a77a6201e5fe8fdfccb066da94a9ed14ebf
[ "MIT" ]
4
2019-11-02T18:33:56.000Z
2022-03-25T06:06:50.000Z
# Setup emscripten This is a GitHub action to setup an emscripten environment. You can optionally specify which sdk you want to install. In actions.yml: ``` steps: - uses: numworks/setup-emscripten@v1 with: sdk: latest-fastcomp - run: emcc --version ``` ## How to update this action - Push a new commit with your changes on the `master` branch - Checkout the `v1` branch - Rebase `v1` on the top of the `master` branch - Remove the `node_modules` directory - Run `npm install` and add the `node_modules` folder to the repository by amending the last commit "Add prod dependencies" - Force push the `v1` branch to GitHub
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sdiehl28/tutorial-website
c542c720f425811b5d4337bae30e92af277cff38
[ "MIT" ]
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content/reviews/special/udemy.md
sdiehl28/tutorial-website
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[ "MIT" ]
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content/reviews/special/udemy.md
sdiehl28/tutorial-website
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+++ title = "Udemy" description = "" weight = 10 lastmod = 2020-02-05 +++ Udemy courses are on sale seemingly half of the time. A $200 course might go for just $12 during a sale. Udemy is now starting to offer interactive quizzes, but their quiz platform is no where near as good as Data Camp's interactive web platform. The best Udemy courses are excellent. In particular, I recommend: * [Complete Python Bootcamp](https://www.udemy.com/complete-python-bootcamp/) for a thorough introduction to Python * [Python for Data Science and Machine Learning Bootcamp](https://www.udemy.com/python-for-data-science-and-machine-learning-bootcamp/learn/v4/overview) for a less thorough, but broader introduction to Python, Data Science and Machine Learning
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100-general/general-concepts/axiom.md
mandober/debrief.math
c6bf21581ccb48a82a74038135bca09c1d0c2a4f
[ "Unlicense" ]
1
2019-01-18T21:56:33.000Z
2019-01-18T21:56:33.000Z
100-general/general-concepts/axiom.md
mandober/debrief.math
c6bf21581ccb48a82a74038135bca09c1d0c2a4f
[ "Unlicense" ]
1
2018-06-11T13:41:09.000Z
2018-06-11T13:41:09.000Z
100-general/general-concepts/axiom.md
mandober/dust-dllci
3afc7936579dfefd7f823d774c4ac17cc6c57666
[ "Unlicense" ]
null
null
null
# Axiom https://en.wikipedia.org/wiki/Axiom https://en.wikipedia.org/wiki/List_of_axioms https://en.wikipedia.org/wiki/Category:Mathematical_axioms An axiom is a statement that serves as a starting point from which other statements can be logically derived. Whether an axiom is meaningful, and, if so, what is its meaning, e.g. what it means for an axiom to be "true" is a subject of debate in philosophy and philosophy of mathematics. Broadly, an axiom is a statement assumed to be true, to serve as a premise for further reasoning and argumentation. The word comes from the Greek `ἀξίωμα` (axíōma) "that which is thought worthy or fit" or "that which commends itself as evident". However, even though some statements may be evident enough to be taken for granted (justifying this acceptance with one's intuition, experience and knowledge), not all statements fall into this category; and even the ones that do, cannot really be proven without succumbing into the *infinite regression* (because defining or proving a term requires defining or proving its constituent terms, and so on, ad infinitum). And as far the truths that are not (easily) found in nature and experience are concerned, the only option is to take them for granted anyway - because all theories must start somewhere, with a certain set of truths, the axioms should be understood to form the hypothesis of a conditional clause: *if you assume this particular set of axioms, then this particular theorem follows*. Therefore, an axiom need not be true at all; the question is not about the truth of axioms per se, but *about the truth of the conditional with those axioms as the hypothesis and some theorem as the conclusion*, with the conclusion logically following from the axioms. In classic philosophy, an axiom is a statement that is so evident or well-established, that it is taken for granted, without controversy. In modern logic, an axiom is a premise or starting point for reasoning. In mathematics, the term "axiom" is used in two related senses: * *Logical axioms* are usually statements, assumed true, within some defining system of logic, denoted symbolically, e.g. `A ∧ B -> A`. * *Non-logical axioms* are independent assertions about the elements of the domain of a specific mathematical theory, e.g. `a + b = b + a` in arithmetic. In this sense the term axiom is synonymous with postulate, assumption, hypothesis. In most cases, a non-logical axiom is simply a formal logical expression used in deduction to build a mathematical theory, and may not even be self-evident in nature (e.g. the "parallel postulate" in Euclidean geometry). To **axiomatize** a system of knowledge is to show that its claims can be derived from a small, well-understood set of sentences i.e. the axioms. There may be multiple ways to axiomatize a given mathematical domain. ## Classic take with Euclid's postulates Among the ancient Greek philosophers an *axiom* was a claim which could be seen to be self-evidently true without any need for proof. The root meaning of the word *postulate* is "to demand" and so it is also used in this sense: an author demands of a reader to acknowledge some fact, that some particular thing can be achieved. For example, Euclid demands that one agrees that any two points can be joined by a straight line. Classically, there was a slight distinction between axioms and postulates: the axioms were common across the sciences, but the postulates were particular to each science. The validity of postulates was to be established by means of real-world experience. The classical approach is well-illustrated in *Euclid's Elements*, where Euclid first introduces a list of postulates (common-sense geometric facts drawn from the common experience), followed by a list of "common notions" (very basic, self-evident assertions, aka axioms). Postulates (geometry-specific notions): 1. It is possible to draw a `straight line` between two points. 2. It is possible to extend a `line` segment continuously in both directions. 3. It is possible to describe a `circle` with any center and any radius. 4. It is true that all `right angles` are equal to one another. 5. `Parallel Postulate`: It is true that, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, intersect on that side on which are the angles less than the two right angles. That is, if a line intersects two lines by making all the interior angles right angles, then the two lines are parallel (never intersect in Euclidean geometry). Common notions (axioms, non-specific common notions): - Things which are equal to the same thing are also equal to one another. transitivity of equality: (a = b ⋀ b = c) -> a = c - If equals are added to equals, the wholes are equal. (a = b ⋀ c = d) -> a + c = b + d - If equals are subtracted from equals, the remainders are equal. (a = b ⋀ c = d) -> a - c = b - d - Things which coincide with one another are equal to one another. symmetry of equality: a = b <-> b = a - The whole is greater than the part. (c = a ⋃ b) ~~> a ⊆ c ## Modern development A lesson learned by mathematics in the last 150 years is that it is useful to strip the meaning from the mathematical definitions and assertions (axioms, postulates, propositions, theorems) and that one must concede the need for primitive notions (undefined terms or concepts) in any study. Such abstraction or formalization makes mathematical knowledge more general, capable of multiple different meanings, and therefore useful in multiple contexts. (and sidesteps the whole issue of truth of initial assumptions). ## Axioms and infinite regression Since a theory must start somewhere to avoid the infinite regression, it is free to make a "cut" and choose the starting point in the form of a term that is central to a particular theory, which is introduced without definition. Such starting term is supposed to be taken for granted by appealing to people's intuition as something that is obviously true. For example, the central notion in set theory is set, introduced without definition, sometimes as a mathematical primitive, other times as an axiom (e.g. "there exists the empty set"). It is usually insisted that axioms are obvious truths that are sufficiently evident to anybody with a human's intuition and perception, but this doesn't seems rigorous enough to withstand every critic. And perhaps it should be; why not just let axioms be whatever the author chooses? This is what they come to anyway. Therefore, in a certain theory, the author comes up with a set of axioms and it is free to choose however ridiculous assumptions as they want. The whole point is this: if you accept this set of axioms as true, then these derived truths follow. I mean, for a number of theories, it already comes down to this. Axioms should be free of obligations and justification. Then, one mathematical matter would have many theories, eash one based on a different set of axiom. The problem is then to rank the competing theorems. An evident way would surely be based on a number of axioms; ceteris paribus, a theory with less axioms would surely subsume the one with more axioms. And if two competing theories have more-less the same number of axioms, perhaps the elegance would play a part, or lobbing, bribe or influencers.
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VladyslavSarbash/hw-fs-35-node-01
c378f9ac52250219e6a3f53828413633e245d277
[ "MIT" ]
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README.md
VladyslavSarbash/hw-fs-35-node-01
c378f9ac52250219e6a3f53828413633e245d277
[ "MIT" ]
null
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null
README.md
VladyslavSarbash/hw-fs-35-node-01
c378f9ac52250219e6a3f53828413633e245d277
[ "MIT" ]
null
null
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# hw-fs-35-node-01 img - https://photos.app.goo.gl/N2sXvdKX3kMWwB887
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samnabi/previewImagesFromSidebar
b38c38e33eab5f7524a4903ef5d186ddbae5e3ce
[ "MIT" ]
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README.md
samnabi/previewImagesFromSidebar
b38c38e33eab5f7524a4903ef5d186ddbae5e3ce
[ "MIT" ]
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null
README.md
samnabi/previewImagesFromSidebar
b38c38e33eab5f7524a4903ef5d186ddbae5e3ce
[ "MIT" ]
null
null
null
# Previews for Sidebar Images This custom field enables (very basic) previews for images in the sidebar. ## Installation Clone or download the contents of this repo to `/site/fields/previewImagesFromSidebar`. Or, install it as a git submodule: `git submodule add https://github.com/dervondenbergen/Kirby-PreviewSidebarImages-Field site/fields/previewImagesFromSidebar` ## Usage To get previews for a blueprint page, add the custom field of type `previewImagesFromSidebar` to the according blueprint: ``` fields: previewImagesFromSidebar: type: previewImagesFromSidebar ```
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tcypyz/tcypyz
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[ "MIT" ]
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README.md
tcypyz/tcypyz
b2fc5720f6f62307fc61e46565664ebf2428e3d2
[ "MIT" ]
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README.md
tcypyz/tcypyz
b2fc5720f6f62307fc61e46565664ebf2428e3d2
[ "MIT" ]
null
null
null
# tcypyz ## 🚀Git 贡献提交规范 - `feat` 增加新功能 - `fix` 修复问题/BUG - `style` 代码风格相关无影响运行结果的 - `perf` 优化/性能提升 - `refactor` 重构 - `revert` 撤销修改 - `test` 测试相关 - `docs` 文档/注释 - `chore` 依赖更新/脚手架配置修改等 - `workflow` 工作流改进 - `ci` 持续集成 - `types` 类型定义文件更改 - `wip` 开发中
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includes/policy/reference/bycat/policies-healthcare-apis.md
beber-msft/azure-docs.de-de
7ce935d32fff8a0709d7a99b04f85cb50d2ead11
[ "CC-BY-4.0", "MIT" ]
63
2017-08-28T07:43:47.000Z
2022-02-24T03:04:04.000Z
includes/policy/reference/bycat/policies-healthcare-apis.md
beber-msft/azure-docs.de-de
7ce935d32fff8a0709d7a99b04f85cb50d2ead11
[ "CC-BY-4.0", "MIT" ]
704
2017-08-04T09:45:07.000Z
2021-12-03T05:49:08.000Z
includes/policy/reference/bycat/policies-healthcare-apis.md
beber-msft/azure-docs.de-de
7ce935d32fff8a0709d7a99b04f85cb50d2ead11
[ "CC-BY-4.0", "MIT" ]
178
2017-07-05T10:56:47.000Z
2022-03-18T12:25:19.000Z
--- author: georgewallace ms.service: azure-policy ms.topic: include ms.date: 10/11/2021 ms.author: gwallace ms.custom: generated ms.openlocfilehash: 6614e9ae7a83e897d1c52d5ccc1f540247b8573a ms.sourcegitcommit: 54e7b2e036f4732276adcace73e6261b02f96343 ms.translationtype: HT ms.contentlocale: de-DE ms.lasthandoff: 10/12/2021 ms.locfileid: "129810564" --- |Name<br /><sub>(Azure-Portal)</sub> |BESCHREIBUNG |Auswirkungen |Version<br /><sub>(GitHub)</sub> | |---|---|---|---| |[Zugriff auf Ihren FHIR-Dienst über CORS nicht allen Domänen gestatten](https://portal.azure.com/#blade/Microsoft_Azure_Policy/PolicyDetailBlade/definitionId/%2Fproviders%2FMicrosoft.Authorization%2FpolicyDefinitions%2Ffe1c9040-c46a-4e81-9aea-c7850fbb3aa6) |Die ursprungsübergreifende Ressourcenfreigabe (Cross-Origin Resource Sharing, CORS) sollte nicht allen Domänen den Zugriff auf Ihren FHIR-Dienst gestatten. Entfernen Sie den Zugriff für alle Domänen zum Schutz Ihres FHIR-Diensts, und definieren Sie explizit diejenigen Domänen, die eine Verbindung herstellen dürfen. |Überprüfung, deaktiviert |[1.0.0](https://github.com/Azure/azure-policy/blob/master/built-in-policies/policyDefinitions/Healthcare%20APIs/HealthcareAPIs_FHIR_Service_RestrictCORSAccess_Audit.json) |
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_posts/2015-9-27-Week5.md
silencewebber/silencewebber.github.io
2e40987174e8e0c44fd7f1e904474ea34422cf5b
[ "MIT" ]
null
null
null
_posts/2015-9-27-Week5.md
silencewebber/silencewebber.github.io
2e40987174e8e0c44fd7f1e904474ea34422cf5b
[ "MIT" ]
null
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null
_posts/2015-9-27-Week5.md
silencewebber/silencewebber.github.io
2e40987174e8e0c44fd7f1e904474ea34422cf5b
[ "MIT" ]
null
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--- layout: post title: Week 5 of OOP (Generics, Iterators, JPL, and Project 2) --- So, it's been a while since my last post, and the reason for that largely boils down to three words. Honors Operating Systems. If taking CS371P concurrently with CS378 Automated Question Answering with Dr. Porter as well as Structure of Modern Geometry and Intro to Ancient Rome wasn't challenging enough, I'm ALSO taking the infamous CS439H with Ahmed Gheith. Gheith is an amazing teacher, but Operating Systems has been incredibly challenging all by itself. I do NOT recommend taking this many classes alongside 439, for anyone who hasn't taken OS yet. However, OS and OOP have complemented each other nicely in the sense that OS involves considerable use of C++, and OOP drills in HOW to use C++, and its many characteristics and features. So I've had a bit of a headstart from my classmates in OS when it comes to C++. Particularly with the understanding of passing variables by reference, which I think Downing did a great job in teaching by emphasizing that the reference should be thought of as an ALIAS as opposed to a pointer, which Gheith still hasn't properly explained (although the students better have figured it out by now, because the project due today requires that understanding). In class we've most recently talked about using generics and iterators to create algorithms that can be used on any data structure with an iterator. Downing has had us write an equals function, a copy function, and a fill function in class, after showing us how to set up a [template](http://www.codeproject.com/Articles/257589/An-Idiots-Guide-to-Cplusplus-Templates-Part). He also talked of the different types of [iterators](http://www.cplusplus.com/reference/iterator/), and how different algorithms require different kinds of iterators. The kind of iterator depends on what actions you need the iterator to support for your algorithm to work. Example: A forward iterator can only iterate in the forward direction, but if you want to implement an in-place reverse() function, you'd need an iterator that can iterate in both directions and swap the values it finds. For that you'd need a bidirectional iterator. This week we had Alex Menzies visit the class from Jet Propulsion Laboratories. It was really cool to see some of the projects they had recently worked on, particularly in their use of gaming technology like Unity3D and Oculus. I've started using Unity for a couple personal projects and it's always cool to see a tool you've started picking up being used by a serious technology company. His discussion of Scrum and Agile practices in their company was good reinforcement of the related papers Downing has assigned to us. Finally we come to [Project 2: Australian Voting](http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=13&page=show_problem&problem=1083). I enjoyed the project, as it was a stimulating problem and got me exposed to the C++ STL, particularly with [lists](http://www.cplusplus.com/reference/list/list/) and [vectors](http://www.cplusplus.com/reference/vector/vector/) and functions like emplace_back() which will add an element to the container and construct it on site, precluding the use of "new," and handling memory management for you. I also figured out that the particularly convenient for each loop that exists in Java also exists in C++11 (but not older versions). This made a lot of my logic much easier to write, although probably led to less efficiency. But the close of Project 2 has been weird. I got an email that there was a problem with my SHA and that I needed to resubmit. The email very helpfully suggested that perhaps I had not pushed the commit in question or that part of the SHA may not have made it into the submission. I went onto github and saw that the commit I intended to submit was indeed pushed to the repo. I checked the SHA on the website right there and the SHA was the same as what was sent in the email. I went to my local repo clone, ran git fetch/pull, and again ran git rev-parse HEAD. The outputted SHA was again the same as the what was sent in the email, as would be expected. I went to Travis CI and pulled up the latest build, which showed a successful build. The SHA displayed on Travis was ALSO the same as the email. At this point I didn't know what the problem could be; I didn't have any issues submitting Project 1. I emailed the graders to this effect, and also went ahead and resubmitted, with the comment that nothing in this resubmission should be different from the original, and with the hope that the submission wouldn't be given the 20% penalty if it suddenly worked this time around. The graders came back with the message that they didn't think I gave them access to my repo... I rechecked github, and I had given them access days ago. I responded that according to my github, they had access, and they responded that indeed that couldn't be the problem, that the problem was with the SHA, and that they'd get back to me. Very confusing. If anyone has any thoughts about what could be the issue, I'd appreciate the help. Also, reflecting on this process, I think the 20% penalty for a submission issue, even if promptly resolved, is ridiculously harsh. In the business world, problems with "submissions" and the transferring of files happen all the time, and no one gets penalized for it; rather the expectation is that everyone involved pays attention, figures out the problem, and gets it resolved promptly and professionally. To that end, I believe that if a student quickly resolves a submission issue, there should be no penalty whatsoever. But in no way should this be equivalent to NOT submitting the assignment AT ALL for 24 hours beyond the deadline. With the current grading scheme, these two offenses are punished equally, which makes no sense to me. Just my two cents. #### Tip of the Week For any of you who would like to interact with a GUI when SSHing into the CS computers, rather than solely using command line, you can use [VNC Viewer](https://www.realvnc.com/download/viewer/) alongside SSH and connect to the CS computers that way. Instructions on how to do so are [here](http://www.science.smith.edu/~ejensen/vncssh.html).
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docs/spiffe.md
niczy/keyhouse
858d366b54dd38c4339f07ffaa6c890a834fa912
[ "Apache-2.0" ]
122
2021-08-10T18:13:43.000Z
2022-03-30T23:29:08.000Z
docs/spiffe.md
niczy/keyhouse
858d366b54dd38c4339f07ffaa6c890a834fa912
[ "Apache-2.0" ]
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2021-09-10T20:38:20.000Z
2022-03-15T22:07:10.000Z
docs/spiffe.md
niczy/keyhouse
858d366b54dd38c4339f07ffaa6c890a834fa912
[ "Apache-2.0" ]
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2021-08-20T03:46:35.000Z
2022-03-22T02:17:21.000Z
# Keyhouse SPIFFE Integration ## Required SPIFFE ID Schema Keyhouse requires all SPIFFE ids to be of the form: ``` spiffe://<trust-domain>(/<key>:<value>)* ``` This is used to support powerful and cheap indexing on SPIFFE ID matchers, and also set a standard for identity matching. ## Outgoing Connections Keyhouse supports outgoing SPIFFE authorized mTLS to: * ETCD/other backend stores * Implementation-defined services (i.e. a master key host) It uses the internal identity for outgoing connections, which *may* or *may not* be the same as the primary identity. ## Incoming connections Keyhouses uses SPIFFE bundles to authenticate and SPIFFE IDs to authorize requests. SPIFFE identity is integral to how Keyhouse represents authorization. The control plane can be configured to use TLS, in which case it accepts clients with a SPIFFE-sourced bundle. The data plane always uses TLS, and will always use a SPIFFE-sourced bundle to accept clients. If an alternate authentication mode is defined, then the client->server certificate requirement is relaxed, and each gRPC call MUST have a string based token to authenticate with, which *may* be a SPIFFE JWT token.
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mtgrosser/DenyLocationConsent
222887b336ec4d22f64a90efd4d075877975c195
[ "MIT" ]
7
2016-01-31T06:09:10.000Z
2018-11-02T02:31:15.000Z
README.md
mtgrosser/DenyLocationConsent
222887b336ec4d22f64a90efd4d075877975c195
[ "MIT" ]
17
2016-01-31T06:15:37.000Z
2019-08-22T19:40:57.000Z
README.md
mtgrosser/DenyLocationConsent
222887b336ec4d22f64a90efd4d075877975c195
[ "MIT" ]
null
null
null
# [DenyLocationConsent](http://repo.xposed.info/module/org.brainkiller.xposed.denylocationconsent) ![Improve location accuracy](https://raw.githubusercontent.com/mtgrosser/DenyLocationConsent/master/gfx/location_accuracy.png) Disable the annoying "Improve location accuracy?" dialog and always disagree. Based on [Xposed-Disable-Location-Consent](https://github.com/MohammadAG/Xposed-Disable-Location-Consent), but doing the opposite. Use the following versions depending on your version of Play Services: | Play Services Version | DenyLocationConsent Version | | ---------------------- | --------------------------- | | 8.x | 0.3 | | 9.x | 0.4 | | >= 12.5.21 | 0.5 | Tested on Lollipop and CM12.1. #### Licensing Copyright &copy; 2016-2018 Matthias Grosser. Licensed under the MIT license.
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brixx21/deployfdsdfs
b2036878f01502b946368a146e4f2a38a0b805ba
[ "MIT" ]
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2020-11-01T03:27:11.000Z
2020-12-14T22:53:41.000Z
README.md
EdTosoy/Furtech-server-deploy
82687f1edb86284aad430eb10a8d182881962157
[ "MIT" ]
null
null
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README.md
EdTosoy/Furtech-server-deploy
82687f1edb86284aad430eb10a8d182881962157
[ "MIT" ]
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# FlashCard-Project-Backend
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content/blog/2013-04-10-project-seishun/index.md
JamesGabby/kurihara
b0cd2f8b02d60e60426b50b14ae951113f8383ed
[ "MIT" ]
5
2019-12-15T08:49:09.000Z
2022-02-15T13:22:42.000Z
content/blog/2013-04-10-project-seishun/index.md
JamesGabby/kurihara
b0cd2f8b02d60e60426b50b14ae951113f8383ed
[ "MIT" ]
725
2019-07-04T21:12:32.000Z
2022-03-28T00:22:02.000Z
content/blog/2013-04-10-project-seishun/index.md
JamesGabby/kurihara
b0cd2f8b02d60e60426b50b14ae951113f8383ed
[ "MIT" ]
1
2022-03-14T00:45:35.000Z
2022-03-14T00:45:35.000Z
--- draft: false post_id: 424 publish_date: '2013-04-10T19:01:48.000+08:00' revise_date: '2013-04-10T19:01:48.000+08:00' tags: - 芦苇荡 title: Project Seishun --- I customized slightly my theme based on the stock theme WP2011. But I'm not feeling enough satisfied and decide to spend some time in building my own theme. The new theme will be  named somewhat like Seishun or Sa Jeunesse. This theme is inspired by the website 粋屋 ([http://www.ikiya.jp/](http://www.ikiya.jp/index.html)), the 物語/monogatari series by 西尾維新/Nishio Ishin whose anime versions come always with a motto beginning with seishun and the lightnovel/anime entitled  やはり俺の青春ラブコメはまちがっている。 which uses a mincho/song type font. I'm not sure if I can complete this new theme in several springs, well, life is being hard, I have to struggle in some other affaires, and maybe several days later I'll have it renamed Manatsu. Nothing is impossible XD.
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README.md
iAmNathanJ/rrun
b0b6e825ec17013d04fd7115cc34eceacb062bf2
[ "MIT" ]
null
null
null
README.md
iAmNathanJ/rrun
b0b6e825ec17013d04fd7115cc34eceacb062bf2
[ "MIT" ]
null
null
null
README.md
iAmNathanJ/rrun
b0b6e825ec17013d04fd7115cc34eceacb062bf2
[ "MIT" ]
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null
null
# rrun This is a small utility to require and run modules from the command line. ## Install `npm i -D rrun` ## Usage ### Command Line: ```bash $ rrun path/to/some-module [arguments ...] ``` `rrun` will require a file and run it's default export with any arguments passed along. It can be useful for running development tasks. This way, tasks can be run directly from npm scripts or the command line, but they can also be required and run from other task files. It's not intended to run anything other than basic node modules that export a single function. ### Example Task Setup: Assume we have a task to compile sass and we want to run it from npm scripts and also from our watch task. ```js // sass-task.js module.exports = () => { // do sassy stuff }; ``` You can use it in your watch task: ```js const chokidar = require('chokidar'); const sass = require('path/to/sass-task'); chokidar.watch('./src/scss/**/*.scss').on('change', sass); ``` And you can `rrun` it from your npm scripts: ```json "scripts": { "sass": "rrun path/to/sass-task" } ``` **PSA:** You can do the same thing without using `rrun`: ```json "scripts": { "any-task": "node -e \"require('path/to/module')()\"" } ``` But ☝️ that is kind of ugly and co-workers may find it confusing.
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Nandem/gaphql-java-experiments
40d4a0c2a2e8c8de0fb7bacc072b95c25d807df7
[ "Apache-2.0" ]
null
null
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README.md
Nandem/gaphql-java-experiments
40d4a0c2a2e8c8de0fb7bacc072b95c25d807df7
[ "Apache-2.0" ]
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README.md
Nandem/gaphql-java-experiments
40d4a0c2a2e8c8de0fb7bacc072b95c25d807df7
[ "Apache-2.0" ]
null
null
null
# gaphql-java-experiments just some experiments about graphql-java
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articles/virtual-machines/scripts/virtual-machines-linux-cli-sample-copy-snapshot-to-storage-account.md
Zwoch/azure-docs.de-de
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[ "CC-BY-4.0", "MIT" ]
null
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articles/virtual-machines/scripts/virtual-machines-linux-cli-sample-copy-snapshot-to-storage-account.md
Zwoch/azure-docs.de-de
c76b1dfefc2541ca6d661c9eaca428b42b34ebc8
[ "CC-BY-4.0", "MIT" ]
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articles/virtual-machines/scripts/virtual-machines-linux-cli-sample-copy-snapshot-to-storage-account.md
Zwoch/azure-docs.de-de
c76b1dfefc2541ca6d661c9eaca428b42b34ebc8
[ "CC-BY-4.0", "MIT" ]
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null
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--- title: "Azure CLI-Beispielskript – Exportieren/Kopieren einer Momentaufnahme als VHD in ein Speicherkonto in einer anderen Region | Microsoft-Dokumentation" description: "Azure CLI-Beispielskript – Exportieren/Kopieren einer Momentaufnahme als VHD in ein Speicherkonto in demselben oder einem anderen Abonnement" services: virtual-machines-linux documentationcenter: storage author: ramankumarlive manager: kavithag editor: tysonn tags: azure-service-management ms.assetid: ms.service: virtual-machines-linux ms.devlang: azurecli ms.topic: sample ms.tgt_pltfrm: vm-linux ms.workload: infrastructure ms.date: 05/19/2017 ms.author: ramankum ms.custom: mvc ms.openlocfilehash: cd555cfea6a84a0bdf0d0c4c9b9b68ae079fbc7b ms.sourcegitcommit: 8c3267c34fc46c681ea476fee87f5fb0bf858f9e ms.translationtype: HT ms.contentlocale: de-DE ms.lasthandoff: 03/09/2018 --- # <a name="exportcopy-managed-snapshots-as-vhd-to-a-storage-account-in-different-region-with-cli"></a>Exportieren/Kopieren verwalteter Momentaufnahmen als VHD in ein Speicherkonto in einer anderen Region mit der Befehlszeilenschnittstelle Dieses Skript exportiert eine verwaltete Momentaufnahme in ein Speicherkonto in einer anderen Region. Zuerst generiert es den SAS-URI der Momentaufnahme, mit dem es diese anschließend in ein Speicherkonto in einer anderen Region kopiert. Verwenden Sie dieses Skript, um Sicherungen Ihrer verwalteten Datenträger für die Notfallwiederherstellung in einer anderen Region zu verwalten. [!INCLUDE [sample-cli-install](../../../includes/sample-cli-install.md)] [!INCLUDE [quickstarts-free-trial-note](../../../includes/quickstarts-free-trial-note.md)] ## <a name="sample-script"></a>Beispielskript [!code-azurecli[main](../../../cli_scripts/virtual-machine/copy-snapshots-to-storage-account/copy-snapshots-to-storage-account.sh "Copy snapshot")] ## <a name="script-explanation"></a>Erläuterung des Skripts Dieses Skript verwendet die folgenden Befehle zum Generieren des SAS-URI für eine verwaltete Momentaufnahme und zum Kopieren der Momentaufnahme in ein Speicherkonto mithilfe dieses SAS-URI. Jeder Befehl in der Tabelle ist mit der zugehörigen Dokumentation verknüpft. | Get-Help | Notizen | |---|---| | [az snapshot grant-access](https://docs.microsoft.com/cli/azure/snapshot#az_snapshot_grant_access) | Generiert eine schreibgeschützte Shared Access Signature (SAS), die verwendet wird, um die zugrunde liegende VHD-Datei in ein Speicherkonto zu kopieren oder lokal herunterzuladen | | [az storage blob copy start](https://docs.microsoft.com/cli/azure/storage/blob/copy#az_storage_blob_copy_start) | Kopiert ein Blob asynchron aus einem Speicherkonto in ein anderes | ## <a name="next-steps"></a>Nächste Schritte [Erstellen verwalteter Datenträger aus einer VHD](virtual-machines-linux-cli-sample-create-managed-disk-from-vhd.md?toc=%2fcli%2fmodule%2ftoc.json) [Erstellen eines virtuellen Computers aus einem verwalteten Datenträger](./virtual-machines-linux-cli-sample-create-vm-from-managed-os-disks.md?toc=%2fcli%2fmodule%2ftoc.json) Weitere Informationen zur Azure CLI finden Sie in der [Azure CLI-Dokumentation](https://docs.microsoft.com/cli/azure). Zusätzliche CLI-Skriptbeispiele für virtuelle Computer und verwaltete Datenträger finden Sie in der [Dokumentation zu Linux-VMs in Azure](../../app-service/app-service-cli-samples.md?toc=%2fazure%2fvirtual-machines%2flinux%2ftoc.json).
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TEDx/Titles_starting_A_to_O/Eradicating_Tuberculosis_Andreas_Kupz_TEDxJCUCairns.md
gt-big-data/TEDVis
328a4c62e3a05c943b2a303817601aebf198c1aa
[ "MIT" ]
91
2018-01-24T12:54:48.000Z
2022-03-07T21:03:43.000Z
cleaned_tedx_data/Titles_starting_A_to_O/Eradicating_Tuberculosis_Andreas_Kupz_TEDxJCUCairns.md
nadaataiyab/TED-Talks-Nutrition-NLP
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[ "MIT" ]
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null
null
cleaned_tedx_data/Titles_starting_A_to_O/Eradicating_Tuberculosis_Andreas_Kupz_TEDxJCUCairns.md
nadaataiyab/TED-Talks-Nutrition-NLP
4d7e8c2155e12cb34ab8da993dee0700a6775ff9
[ "MIT" ]
18
2018-01-24T13:18:51.000Z
2022-01-09T01:06:02.000Z
so let me start by asking you a question can anyone here read that sign on the slide if you can&#39;t I guess most of you probably think it has something to do with cows or his children so let me tell you story the story behind this sign so I&#39;m that little boy in the middle and and I grew up in East Germany and when I grew up I walked past this sign almost every day because it was attached to a door on my family&#39;s farm where we kept our cows it essentially translates to certified tuberculosis free cattle you know being a little boy I didn&#39;t think much of all at all I only knew from my grandfather that tuberculosis is a disease that can make house very sick but apart from this you know as being a little boy I didn&#39;t I didn&#39;t care much about it so now fast-forward 30 odd years and I&#39;m standing here giving a presentation about eradicating tuberculosis so why is that obviously you know a lot of things change in 30 years not just the way I dress but also I&#39;m now a trained microbiologist and I specialize in infectious disease research and particularly on tuberculosis so obviously I now know a lot more and I know that TB how tuberculosis is also known doesn&#39;t just affect cows it actually a major problem in the world so let me start by giving you some facts so TB as I said tuberculosis also known is the biggest killer amongst all infectious diseases on that planet over the last 200 years it is estimated that TB has killed about 1 billion people so this is more than malaria plague smallpox influenza HIV cholera combined that&#39;s all diseases you may have heard about but what about closer to you know 2017 so the latest data we&#39;ve got is from 2015 and even two years ago there was still one point eight million people dying from tuberculosis more than ten million cases and so why is this just to put into context the recent Ebola outbreak in western Africa killed about eleven to twelve thousand people this is about tuberculosis kills more in two days every day every year but not too many people know about it why is this TB is a lung disease it&#39;s caused by a bacterium called microbiome tuberculosis and it really affects mainly to poor people on the planet because it&#39;s a disease of overcrowding and poor hygiene and it all starts when an infected patient that has active tuberculosis coughs up the bacteria and they can infect others around them and we know that about two billion people in other words about a third of the world&#39;s population is infected with tuberculosis luckily only 1.8 million people of those died but it&#39;s still why too many so I said that TB is a disease of the poor people on the planet and you can see here on the world map that it really affects mainly developing countries in sub-saharan Africa Asia Eastern Europe and also South America and unfortunately these are the same regions of the world where other infectious diseases such as hiv/aids is very prevalent and we know that being infected was both disease at the same time is a major risk factor for actually dying when you infected with tuberculosis however probably the most the more relevant problem and also more relevant to people in in the Western world is that it becomes incredibly harder to treat tuberculosis tuberculosis is a treatable disease if you&#39;ve got it you have to take drugs for about six months and then if you strain it in fact you as susceptible to those drugs you will be cured however over the last decade or so more and more of those bacteria have become resistant to the drugs that we use to treat TB and we call that multi drug-resistant tuberculosis or MDR TB the slide you can see here you know it&#39;s not a solar system and I don&#39;t really want you to look at all the details but it&#39;s a very interesting slide from the World Health Organization that shows us how much it costs to treat one case of multi drug-resistant tuberculosis in different countries of the world and without looking at all the details it really tells us that in many countries it is more expensive to treat one case of multi drug-resistant tuberculosis than the GDP per capita in that country so it&#39;s an enormous public health issue and it&#39;s very very expensive and if you think that MDR TB is far away then think twice because here in Far North topical Queensland we&#39;re only a short boat ride away from one of the most severe outbreaks of multi drug-resistant tuberculosis on the planet on some of those islands of the coast of Papua New Guinea we have such a high incidence of MDR TB that there is a major problem and you know that it&#39;s only a short trip from one island to the next from Papua New Guinea to Australia and from one of those islands to the mainland and Bucs don&#39;t respect borders once they&#39;re on the mainland they can go anywhere so what can we do and this is really where scientists like myself come in because we know that instead of treating a disease we can also prevent it or we can even eliminate it and how can we do this we know that the only and the best way to read acade a disease is vaccination because we&#39;ve done it before we have almost eradicated polio which you can see here and we have eradicated smallpox both of these diseases where all are almost eradicated because we have an effective vaccine that was rolled out worldwide by the World Health Organization the WHL Water Association has put out a very ambitious goal to eliminate TB by 2050 this is about 35 years from now the same timeframe utley can see here for polio so we know that if we will have an effective vaccine it is possible to eradicate tuberculosis some of you in the audience may think now oh well there&#39;s a vaccine against TB I&#39;ve probably got it when I was a child and yes that&#39;s right there is a vaccine it&#39;s called BCG it was introduced in 1921 and it&#39;s been given to more than four billion people on the planet unfortunately TB doesn&#39;t DCG does not prevent the real lung tuberculosis in adults it has prevented several millions of kids from dying from childhood versions of tuberculosis but it will never stop the transmission cycle and therefore help us to eliminate a disease and again this is the point where scientists like myself and others can make a difference there are about several dozen different research groups on the planet currently working to make a better TB vaccine I&#39;m one of them and although this slide may look like a bit of a race it is really a global effort where we all come together and try to make a difference to come up with a effective vaccine that works to develop a vaccine is very expensive and long process it takes at least 20 years to move a vaccine from the preclinical studies all the way through to a licensed product you can see here illustrated by those blue bars that some of those vaccine candidates how we call them have already progressed to different parts of these clinical pipeline some are very close to being licensed but unfortunately in very recent years it has become apparent that many of those vaccines are not better than BCG so there may be an option an alternative to BCG but they&#39;ve warmed help us eliminate the disease and that is why we can&#39;t be complacent that we have to continue to work on new concepts new methods and new strategies to develop a vaccine that actually works the little red arrow on the bottom that&#39;s me my vaccine is still in the preclinical stages but I&#39;m trying to work on new concepts that are currently not used by those Iraq vaccines and this is where the science comes in so I&#39;m trying to keep it as simple as possible but there was me so most vaccines target immune cells in your body depicted here by those purple cell when a vaccine is introduced shown here in red it has taken up by those cells and then presented on the surface of these cells that&#39;s how we call this and this leads to the attraction of other immune cells and they then lead to protection against the disease this is quite common for most diseases and most vaccines unfortunately for the vaccines being developed for tuberculosis many of the ones that are currently going through this clinical pipeline targeted cell type that is destroyed by HIV and I&#39;ve told you earlier that HIV is a major risk factor for reactivation of tuberculosis so these vaccines will not work in particular in the context of HIV in these countries so I had a different idea I am a microbiologist so I can work on genetically engineered bacteria and immunology so what I did we still introduced a vaccine we still target these particular immune cells well what we did is we made a vaccine that remains inside the cell and what that does it leads to the secretion of messenger molecules how we call them and these messenger molecules target particular cell types that can also be protective but they do not get destroyed by HIV infection and secondly we are also trying to work on a new approach to deliver the vaccine because currently BCG is given as a needle injection and believe me not many children will look like this and have just been given so but we also know that a needle based vaccination only generates immune cells that are kind of circulating through the body but not really go to the lung where they&#39;re needed when a tuberculosis infection occurs so in our approach we&#39;re also trying to develop a vaccine that can be administered directly into the lung was a puffer and we know that this approach generates a particular type of immune cell that remains in the lung and can act directly when tuberculosis infection occurs and if this approach will be successful this global effort comes to a conclusion then I hope by 2050 when I would be a grandfather I will be able to tell my grandchildren that TB has been eradicated not just from cows in East Germany but from everyone in the whole world thank you [Applause]
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ramakrishna-bitla/MyfirstApp
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[ "MIT" ]
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README.md
ramakrishna-bitla/MyfirstApp
86dc3b06945dd021bc12664f0870fbd36b4cf92e
[ "MIT" ]
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README.md
ramakrishna-bitla/MyfirstApp
86dc3b06945dd021bc12664f0870fbd36b4cf92e
[ "MIT" ]
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null
null
# MyfirstApp Sample App
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cscfa/bartleby
62a00d8710afc9c698d3336649d8da0fcf79f355
[ "MIT" ]
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2015-06-26T04:57:42.000Z
2015-06-26T04:57:42.000Z
README.md
cscfa/bartleby
62a00d8710afc9c698d3336649d8da0fcf79f355
[ "MIT" ]
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README.md
cscfa/bartleby
62a00d8710afc9c698d3336649d8da0fcf79f355
[ "MIT" ]
null
null
null
# bartleby Database manager with fullREST API access
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kokohuang/WarOfResistanceLive
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2020-11-30T18:37:16.000Z
2021-08-16T13:37:02.000Z
site/source/_posts/1932年05月29日.md
kokohuang/WarOfResistanceLive
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site/source/_posts/1932年05月29日.md
kokohuang/WarOfResistanceLive
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[ "MIT" ]
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2020-12-08T06:47:10.000Z
2021-08-16T13:37:18.000Z
--- layout: post title: "1932年05月29日" date: 2021-05-29 categories: 局部抗战(1931-1937) --- <meta name="referrer" content="no-referrer" /> - 1932年5月29日讯:唐柯三在京招待记者报告调解康、藏纠纷经过,称:“康、藏纠纷,发生于大金、白利两方财产之争执,不意甘孜知事措置失当,激成变乱,以致藏番猖獗,迭陷甘瞻。余秉中央意旨,与藏方议订条件,国人不满意,以割地赔款见责,实太冤枉。” - 1932年5月29日讯:上海童子军战地服务团全体复员。 - 1932年5月29日讯:上海引翔港三友实业社总厂日军撤退。 - 1932年5月29日讯:上午5时,日军第十四师团平松支队进攻肇东李海青义勇军,旋占领肇东。 - 1932年5月29日《申报》:鞍山息,今晨三时半,马贼袭击鞍山东面大孤山之日本警察派出所,日警负伤。后并袭击满铁制铁所、大孤山之采矿所,绑去该所主任等要员三人。(28日电通社电) - #抗战影像#可能正在训练中的一支伪满洲国陆军迫击炮部队。 <br/><img src="https://wx3.sinaimg.cn/large/aca367d8ly8gqz45t8zqdj20hs0a0jsf.jpg" /> - 1932年5月29日《申报》:哈尔滨息,昨日正午有人在一面坡与乌吉密河间一零八三公里轨道中发现地雷一枚,即止将抵之日铁甲车前进。后由火车中日兵将地雷移去,复开车前发。一面坡与该站西十五里某地点间敌军甚为活动,故哈尔滨与西比利亚边界五站间之通车,现复停驶。据昨日开抵此间之汽船四艘报称,曾在距哈尔滨北二十里处受反满军来复枪猛烈之射击,但未伤一人。(28日路透社电) - 1932年5月29日《申报》:淞沪之役,我19路军及第5军将士血战匝月,先后阵亡者数千人,政府及民众追念忠烈,昨日上午11时20分,在苏州公共体育场(即五卅公园)举行淞沪抗日阵亡将士追悼大会。中央、国府暨各军政机关各民众团体,多派代表参加,共计到会军民约五万余人。在风雨凄迷中,举行隆重之祭典,与祭人员,在此庄严悲哀之空气中,多有泣下者。<br/><img src="https://wx3.sinaimg.cn/large/aca367d8ly8gqz0p2s0shj20b408oq3l.jpg" /> - 1932年5月29日讯:汪精卫召罗文幹、蒋作宾及外交委员会委员商外交问题,决定外长仍由罗继任;郭泰祺担任驻英公使,日内赴英履任;驻日公使仍由蒋作宾回任。
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arrays_and_pointers/readme.md
jamesjallorina/cpp_exercises
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[ "MIT" ]
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2019-07-08T14:35:57.000Z
2019-07-08T14:35:57.000Z
arrays_and_pointers/readme.md
jamesjallorina/cpp_exercises
0e18511aad163510143dc66523a8111057694bff
[ "MIT" ]
null
null
null
arrays_and_pointers/readme.md
jamesjallorina/cpp_exercises
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[ "MIT" ]
null
null
null
## Arrays And Pointers Exercises 1. Write a program in C to show the basic declaration of pointer. Go to the editor Expected Output : Pointer : Show the basic declaration of pointer : Here is m=10, n and o are two integer variable and *z is an integer z stores the address of m = 0x7ffd40630d44 *z stores the value of m = 10 &m is the address of m = 0x7ffd40630d44 &n stores the address of n = 0x7ffd40630d48 &o stores the address of o = 0x7ffd40630d4c &z stores the address of z = 0x7ffd40630d50 2. Write a program in C to demonstrate how to handle the pointers in the program. Go to the editor Expected Output : Address of m : 0x7ffcc3ad291c Value of m : 29 Now ab is assigned with the address of m. Address of pointer ab : 0x7ffcc3ad291c Content of pointer ab : 29 The value of m assigned to 34 now. Address of pointer ab : 0x7ffcc3ad291c Content of pointer ab : 34 The pointer variable ab is assigned with the value 7 now. Address of m : 0x7ffcc3ad291c Value of m : 7 3. Write a program in C to demonstrate the use of &(address of) and *(value at address) operator. Go to the editor Expected Output : Pointer : Demonstrate the use of & and * operator : m = 300 fx = 300.600006 cht = z Using & operator : address of m = 0x7ffda2eeeec8 address of fx = 0x7ffda2eeeecc address of cht = 0x7ffda2eeeec7 Using & and * operator : value at address of m = 300 value at address of fx = 300.600006 value at address of cht = z Using only pointer variable : address of m = 0x7ffda2eeeec8 address of fx = 0x7ffda2eeeecc address of cht = 0x7ffda2eeeec7 Using only pointer operator : value at address of m = 300 value at address of fx= 300.600006 value at address of cht= z 4. Write a program in C to add two numbers using pointers. Go to the editor Test Data : Input the first number : 5 Input the second number : 6 Expected Output : The sum of the entered numbers is : 11 5. Write a program in C to add numbers using call by reference. Go to the editor Test Data : Input the first number : 5 Input the second number : 6 Expected Output : The sum of 5 and 6 is 11 6. Write a program in C to find the maximum number between two numbers using a pointer. Go to the editor Test Data : Input the first number : 5 Input the second number : 6 Expected Output : 6 is the maximum number. 7. Write a program in C to store n elements in an array and print the elements using pointer. Go to the editor Test Data : Input the number of elements to store in the array :5 Input 5 number of elements in the array : element - 0 : 5 element - 1 : 7 element - 2 : 2 element - 3 : 9 element - 4 : 8 Expected Output : The elements you entered are : element - 0 : 5 element - 1 : 7 element - 2 : 2 element - 3 : 9 element - 4 : 8 8. Write a program in C to print all permutations of a given string using pointers. Go to the editor Expected Output : The permutations of the string are : abcd abdc acbd acdb adcb adbc bacd badc bcad bcda bdca bdac cbad cbda cabd cadb cdab cdba db ca dbac dcba dcab dacb dabc 9. Write a program in C to find the largest element using Dynamic Memory Allocation. Go to the editor Test Data : Input total number of elements(1 to 100): 5 Number 1: 5 Number 2: 7 Number 3: 2 Number 4: 9 Number 5: 8 Expected Output : The Largest element is : 9.00 10. Write a program in C to Calculate the length of the string using a pointer. Go to the editor Test Data : Input a string : w3resource Expected Output : The length of the given string w3resource is : 10 11. Write a program in C to swap elements using call by reference. Go to the editor Test Data : Input the value of 1st element : 5 Input the value of 2nd element : 6 Input the value of 3rd element : 7 Expected Output : The value before swapping are : element 1 = 5 element 2 = 6 element 3 = 7 The value after swapping are : element 1 = 7 element 2 = 5 element 3 = 6 12. Write a program in C to find the factorial of a given number using pointers. Go to the editor Test Data : Input a number : 5 Expected Output : The Factorial of 5 is : 120 13. Write a program in C to count the number of vowels and consonants in a string using a pointer. Go to the editor Test Data : Input a string: string Expected Output : Number of vowels : 1 Number of constant : 5 14. Write a program in C to sort an array using Pointer. Go to the editor Test Data : testdata Expected Output : Test Data : Input the number of elements to store in the array : 5 Input 5 number of elements in the array : element - 1 : 25 element - 2 : 45 element - 3 : 89 element - 4 : 15 element - 5 : 82 Expected Output : The elements in the array after sorting : element - 1 : 15 element - 2 : 25 element - 3 : 45 element - 4 : 82 element - 5 : 89 15. Write a program in C to show how a function returning pointer. Go to the editor Test Data : Input the first number : 5 Input the second number : 6 Expected Output : The number 6 is larger. 16. Write a program in C to compute the sum of all elements in an array using pointers. Go to the editor Test Data : Input the number of elements to store in the array (max 10) : 5 Input 5 number of elements in the array : element - 1 : 2 element - 2 : 3 element - 3 : 4 element - 4 : 5 element - 5 : 6 Expected Output : The sum of array is : 20 17. Write a program in C to print the elements of an array in reverse order. Go to the editor Test Data : Input the number of elements to store in the array (max 15) : 5 Input 5 number of elements in the array : element - 1 : 2 element - 2 : 3 element - 3 : 4 element - 4 : 5 element - 5 : 6 Expected Output : The elements of array in reverse order are : element - 5 : 6 element - 4 : 5 element - 3 : 4 element - 2 : 3 element - 1 : 2 18. Write a program in C to show the usage of pointer to structure. Go to the editor Expected Output : John Alter from Court Street 19. Write a program in C to show a pointer to union. Go to the editor Expected Output : Jhon Mc Jhon Mc 20. Write a program in C to show a pointer to an array which contents are pointer to structure. Go to the editor Expected Output : Exmployee Name : Alex Employee ID : 1002 21. Write a program in C to print all the alphabets using a pointer. Go to the editor Expected Output : The Alphabets are : A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 22. Write a program in C to print a string in reverse using a pointer. Go to the editor Test Data : Input a string : w3resource Expected Output : Pointer : Print a string in reverse order : Input a string : w3resource Reverse of the string is : ecruoser3w
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EricBlack/AElfChain.SDK
0884476eebdaec3720a8d7aa39646441337dec2e
[ "MIT" ]
null
null
null
README.md
EricBlack/AElfChain.SDK
0884476eebdaec3720a8d7aa39646441337dec2e
[ "MIT" ]
null
null
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README.md
EricBlack/AElfChain.SDK
0884476eebdaec3720a8d7aa39646441337dec2e
[ "MIT" ]
null
null
null
# AElfChain.SDK AElfChain sdk
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notes/markdown/How to Take Smart Notes/Break down amorphous tasks into smaller tasks that can be finished in one go.md
juancoquet/personalwebsite
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[ "MIT" ]
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notes/markdown/How to Take Smart Notes/Break down amorphous tasks into smaller tasks that can be finished in one go.md
juancoquet/personalwebsite
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[ "MIT" ]
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null
notes/markdown/How to Take Smart Notes/Break down amorphous tasks into smaller tasks that can be finished in one go.md
juancoquet/personalwebsite
3d9979ed6aa42ed031971a5e3c6e880f5642c33f
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Note type: #litnote Source: [[📖 How to Take Smart Notes]] --- # Break down amorphous tasks into smaller tasks that can be finished in one go In order to be able to focus and organise, large amorphous tasks should be divided into smaller sub-tasks which can be completed in one go. This means that the sub-tasks can be written down and scheduled, freeing up mental resources to focus on actually *doing*. --- See also: - [[A mind like water]] - [[Circumventing and Leveraging the Ziegarnik effect]] - [[The Ziegarnik Effect]]
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src/in/2020-03/05/06.md
PrJared/sabbath-school-lessons
94a27f5bcba987a11a698e5e0d4279b81a68bc9a
[ "MIT" ]
68
2016-10-30T23:17:56.000Z
2022-03-27T11:58:16.000Z
src/in/2020-03/05/06.md
PrJared/sabbath-school-lessons
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[ "MIT" ]
367
2016-10-21T03:50:22.000Z
2022-03-28T23:35:25.000Z
src/in/2020-03/05/06.md
PrJared/sabbath-school-lessons
94a27f5bcba987a11a698e5e0d4279b81a68bc9a
[ "MIT" ]
109
2016-08-02T14:32:13.000Z
2022-03-31T10:18:41.000Z
--- title: Kuasa Roh Kudus Yang Mengubah Hidup date: 30/07/2020 --- Sebuah penelitian yang cermat terhadap kitab Kisah Para Rasul mengunkapkan Allah melalui Roh-Nya mengerjakan mukjizat dalam kehidupan mansia. Kisah Para Rasul adalah sebuah studi kasus tentang kemenangan Injil atas bias budaya, mengubah kebiasaan seumur hidup, kebiasaan yang mendarah daging, dan mengajarkan semua rahmat dan kebenaran Kristus kepada selruh umat manusia. Roh Kudus bertemu dengan orang-orang di tempat mereka berada, tetapi Ia tidak meninggalkan mereka di sana. Di hadirat-Nya, mereka diubahkan. Hidup mereka berubah. `Bacalah Kisah Para Rasul 16: 11–15, 23–34; 17: 33, 34; 18: 8. Ini hnyalah beberapa kisah pertobatan dalam Alkitab. Apakah yang diajakan berbagai kisah ini kepada kita tentang kuasa Allah untuk mengubah kehidupan semua jenis orang dari berbagai latar belakang?` Ada berbagai jenis orang. Lidia adalah seorang pengusaha Yahudi yang makmur, dan kepala penjara Filipi adalah pegawai negeri sipil kelas menengah di Roma. Roh Kudus dapat menjangkau semua spektrum masyarakat. Kekuaannya untuk mengubahkan mencapai baik laki-laki maupun perempuan, kaya dan miskin, berpendidikan dan tidak berpendidikan. Dua karakter terakhir dalam daftar kita sama-sama luar biasa. Kisah Para Rasul 17: 34 merujuk pada pertobatan Dionisius, anggota majelis Aeropagus. Aeropagus di Atena adalah bagian dari penasihat hukum para hakim yang mengadili kasus-kasus pengadilan. Mereka adalah anggota masyarakat Yunani yang terkemuka dan dihormati. Melalui kuasa Roh Kudus, pelayanan Rasul Paulus mencapai bahkan eselon atas masyarakat. Krispus (Kis. 18: 8) adalah penguasa sinagoge Yahudi. Dia adlah seorang pemimpin agama yang mendalami pemikiran Perjanjian Lama Yhudi, dan Roh Kudus menerobos dan mengubah hidupnya. Sejarah kisah-kisah ini mengungkapkan bahwa ketika kita bersaksi untuk Kristus dan membagkan Firman-Nya kepada orang lain, Roh Kudus akan melakukan hal-hal luar biasa dalam kehidupan semua jenis orang dari segala macam latar belakang, budaya, pendidikan, dan kepercayaan. Kita tidak bisa dan tidak boleh mebuat asumsi tentang siapa yang bisa atau tidak bisa dihubungi. Tugas kita adalah untuk bersaksi kepada siapa saja dan semua orang yang dibawa ke dalam hidup kita. Tuhan akan melakukan sisanya. `Kematian Kristus adalah universal; yaitu untuk setiap umat manusia, selamanya. Apakah yang seharusnya diajarkan kebenaran penting ini kepada kita tentang bagaimana kita tidak boleh berasumsi bahwa ada orang yang berada di luar harapan keselamatan?` #### Pembaca Tambahan: Petikan terpilih dari Ellen G. White Siapa yang diampuni Kristus, Dialah yang pertama membuat menyesal, dan tugas Roh Kuduslah menyadarkan orang terhadap dosa. Mereka yang hatinya telah digerakkan oleh Roh Allah yang memberikan keyakinan melihat bahwa tidak ada kebaikan dalam diri mereka. Mereka lihat bahwa semua yang pernah mereka lakukan adalah bercampur dengan diri dan dosa. Seperti pemungut cukai yang malang itu, mereka berdiri jauhjauh, tidak berani menengadah ke langit, dan berseru, “Ya Allah, kasihanilah aku orang berdosa ini” (Lukas 18:13). Dan mereka diberkati. Ada pe-ngampunan bagi orang yang menyesal; karena Kristus adalah Anak Domba Allah yang menghapus dosa dunia” (Yohanes 1:29). Janji Allah adalah: “Sekalipun dosamu merah seperti kirmizi, akan menjadi putih seperti salju; sekalipun berwarna merah seperti kain kesumba, akan menjadi putih seperti bulu domba.” “Akan Kuberikan hati yang baru kepadamu— Roh-Ku akan Kuberikan diam di dalam batinmu” (Yesaya 1:18; Yehezkiel 36:26, 27). {KAB 17.1} Ketika Kristus menjanjikan Roh kepada murid-murid-Nya, Ia sudah mendekati akhir pekerjaan-Nya di dunia ini. Ia sedang berdiri dalam bayang-bayang salib, dengan penuh kesadaran beban yang terletak atas-Nya sebagai Penanggung Dosa. Sebelum mempersembahkan diri-Nya sendiri sebagai korban sembelihan, Ia memberi petunjuk kepada murid-murid-Nya mengenai pemberian yang paling penting dan sempurna yang dikaruniakan-Nya kepada para pengikut-Nya—pemberian yang akan membawa di dalam jangkauan mereka sumber-sumber yang tidak ter-batas akan rahmat-Nya. “Aku akan minta kepada Bapa,” kata-Nya, “dan Ia akan memberikan kepadamu seorang Penolong yang lain, supaya Ia menyertai kamu, yaitu Roh Kebenaran. Dunia tidak dapat menerima Dia, sebab dunia tidak melihat Dia dan tidak mengenal Dia. Tetapi kamu mengenal Dia, sebab Ia menyertai kamu dan akan diam di dalam kamu.” Yohanes 14:16, 17. Juruselamat menunjuk kepada waktu bilamana Roh Kudus harus datang untuk melakukan pekerjaan yang besar sebagai utus-an-Nya. Kejahatan yang sudah tertimbun berabad-abad lamanya harus dikalahkan oleh kuasa Ilahi dari Roh Kudus. {KR 40.1}
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_posts/java/R/ResultSetMetaData/2021-01-01-ResultSetMetaData.md
w3api/w3api
681462ece7265723031a88bec5285209d0e125bf
[ "MIT" ]
1
2021-09-15T20:32:10.000Z
2021-09-15T20:32:10.000Z
_posts/java/R/ResultSetMetaData/2021-01-01-ResultSetMetaData.md
w3api/w3api
681462ece7265723031a88bec5285209d0e125bf
[ "MIT" ]
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2021-01-17T01:13:46.000Z
2021-06-20T21:16:02.000Z
_posts/java/R/ResultSetMetaData/2021-01-01-ResultSetMetaData.md
w3api/w3api
681462ece7265723031a88bec5285209d0e125bf
[ "MIT" ]
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2021-09-15T20:32:08.000Z
2022-02-20T16:57:46.000Z
--- title: ResultSetMetaData permalink: /Java/ResultSetMetaData/ date: 2021-01-11 key: Java.R.ResultSetMetaData category: Java tags: ['java se', 'java.sql', 'java.sql', 'interface java', 'Java 1.1'] sidebar: nav: java --- ## Descripción {{site.data.Java.R.ResultSetMetaData.description }} ## Sintaxis ~~~java public interface ResultSetMetaData extends Wrapper ~~~ ## Campos * [columnNoNulls](/Java/ResultSetMetaData/columnNoNulls) * [columnNullable](/Java/ResultSetMetaData/columnNullable) * [columnNullableUnknown](/Java/ResultSetMetaData/columnNullableUnknown) ## Métodos * [getCatalogName()](/Java/ResultSetMetaData/getCatalogName) * [getColumnClassName()](/Java/ResultSetMetaData/getColumnClassName) * [getColumnCount()](/Java/ResultSetMetaData/getColumnCount) * [getColumnDisplaySize()](/Java/ResultSetMetaData/getColumnDisplaySize) * [getColumnLabel()](/Java/ResultSetMetaData/getColumnLabel) * [getColumnName()](/Java/ResultSetMetaData/getColumnName) * [getColumnType()](/Java/ResultSetMetaData/getColumnType) * [getColumnTypeName()](/Java/ResultSetMetaData/getColumnTypeName) * [getPrecision()](/Java/ResultSetMetaData/getPrecision) * [getScale()](/Java/ResultSetMetaData/getScale) * [getSchemaName()](/Java/ResultSetMetaData/getSchemaName) * [getTableName()](/Java/ResultSetMetaData/getTableName) * [isAutoIncrement()](/Java/ResultSetMetaData/isAutoIncrement) * [isCaseSensitive()](/Java/ResultSetMetaData/isCaseSensitive) * [isCurrency()](/Java/ResultSetMetaData/isCurrency) * [isDefinitelyWritable()](/Java/ResultSetMetaData/isDefinitelyWritable) * [isNullable()](/Java/ResultSetMetaData/isNullable) * [isReadOnly()](/Java/ResultSetMetaData/isReadOnly) * [isSearchable()](/Java/ResultSetMetaData/isSearchable) * [isSigned()](/Java/ResultSetMetaData/isSigned) * [isWritable()](/Java/ResultSetMetaData/isWritable) ## Ejemplo ~~~java {{ site.data.Java.R.ResultSetMetaData.code}} ~~~ ## Líneas de Código <ul> {%- for _ldc in site.data.Java.R.ResultSetMetaData.ldc -%} <li> <a href="{{_ldc['url'] }}">{{ _ldc['nombre'] }}</a> </li> {%- endfor -%} </ul>
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README.md
MykosX/android-send-receive
d032712e96376ced0a041e97734654d487bc1890
[ "MIT" ]
null
null
null
README.md
MykosX/android-send-receive
d032712e96376ced0a041e97734654d487bc1890
[ "MIT" ]
null
null
null
README.md
MykosX/android-send-receive
d032712e96376ced0a041e97734654d487bc1890
[ "MIT" ]
null
null
null
# android-send-receive
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content/authors/gonzalez-n/_index.md
matematicasco/academic-kickstart
6d9e88af1141af56d3365710e650f221adb01057
[ "MIT" ]
null
null
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content/authors/gonzalez-n/_index.md
matematicasco/academic-kickstart
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content/authors/gonzalez-n/_index.md
matematicasco/academic-kickstart
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--- name: Nelsy R. González Gutíerrez authors: - gonzalez-n superuser: false role: Associate Professor organizations: - name: Universidad Pedagógica y Tecnológica de Colombia url: "http://www.uptc.edu.co" # Short bio (displayed in user profile at end of posts) bio: interests: - Commutative algebra - Epistemiology and history of mathematics education: courses: - course: PhD in Education institution: Universidad Pedagógica y Tecnológica de Colombia year: 2017 - course: MSc in Mathematics institution: Universidad Nacional de Colombia year: 2002 - course: Licenciatura en Matemáticas y Física institution: Universidad Pedagógica y Tecnológica de Colombia year: 1997 # Social/Academic Networking social: - icon: cv icon_pack: ai link: https://scienti.minciencias.gov.co/cvlac/visualizador/generarCurriculoCv.do?cod_rh=0000394556 - icon: google-scholar icon_pack: ai link: https://scholar.google.com/citations?user=-o286msAAAAJ&hl=es - icon: orcid icon_pack: ai link: https://orcid.org/0000-0002-5710-6063 - icon: researchgate icon_pack: ai link: https://www.researchgate.net/profile/Nelsy-Gonzalez # Enter email to display Gravatar (if Gravatar enabled in Config) email: "" # Organizational groups that you belong to (for People widget) # Set this to `[]` or comment out if you are not using People widget. user_groups: - "Escuela" - "giaa" ---
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README.md
tpaksu/xdebug-toggle
7d0a4e2583d17fce9fdc3e1a65cd93e785c2e055
[ "MIT" ]
5
2020-07-13T19:32:24.000Z
2020-09-29T23:29:13.000Z
README.md
tpaksu/xdebug-toggle
7d0a4e2583d17fce9fdc3e1a65cd93e785c2e055
[ "MIT" ]
null
null
null
README.md
tpaksu/xdebug-toggle
7d0a4e2583d17fce9fdc3e1a65cd93e785c2e055
[ "MIT" ]
null
null
null
# Laravel Valet XDebug Toggler Artisan Command [![Latest Version on Packagist](https://img.shields.io/packagist/v/tpaksu/xdebug-toggle.svg?style=flat-square)](https://packagist.org/packages/tpaksu/xdebug-toggle) [![Build Status](https://img.shields.io/travis/tpaksu/xdebug-toggle/master.svg?style=flat-square)](https://travis-ci.org/tpaksu/xdebug-toggle) [![Quality Score](https://img.shields.io/scrutinizer/g/tpaksu/xdebug-toggle.svg?style=flat-square)](https://scrutinizer-ci.com/g/tpaksu/xdebug-toggle) [![Total Downloads](https://img.shields.io/packagist/dt/tpaksu/xdebug-toggle.svg?style=flat-square)](https://packagist.org/packages/tpaksu/xdebug-toggle) [![StyleCI](https://github.styleci.io/repos/7548986/shield)](https://github.styleci.io/repos/271391496) This package automates the XDebug extension activation/deactivation process by adding a console command to Laravel's artisan command. It does these things: - Modifying the current INI file used by PHP, located with parsing the "php_info()" output containing the line "Loaded Configuration File: [path/to/php.ini]" - Restarting the valet NGINX server with the command `valet restart nginx` If you use something else than Laravel Valet, and want to automate your stuff, you can change the **XDEBUG_SERVICE_RESTART_COMMAND** in your environment file, or the `xdebugtoggle.service_restart_command` configuration in xdebug-toggle.php configuration file to suit your own. ## Installation You can install the package as a development requirement via composer: ```bash composer require tpaksu/xdebug-toggle --dev ``` ## Usage To enable XDebug in current environment: ``` bash php artisan xdebug on ``` To disable it: ``` bash php artisan xdebug off ``` ### Configuration You can export the configuration file by running the command: ``` bash php artisan vendor:publish --provider="Tpaksu\XdebugToggle\XdebugToggleServiceProvider" ``` which includes: **service_restart_command** : Gives you the option to run a script after you change the *php.ini* line with the new XDebug status. The default is ```bash valet restart nginx ``` which applies the new php.ini configuration on the PHP running on valet's nginx server. I tried and succeded with this command on Windows running Laragon with nginx: ```batch c:/laragon/bin/nginx/nginx-1.12.0/nginx.exe -p c:/laragon/bin/nginx/nginx-1.12.0 -c conf/nginx.conf -s reload ``` which I changed with setting this environment variable on `.env` and ran `php artisan config:cache` to apply the environment changes: ```ini XDEBUG_SERVICE_RESTART_COMMAND="c:/laragon/bin/nginx/nginx-1.12.0/nginx.exe -p c:/laragon/bin/nginx/nginx-1.12.0 -c conf/nginx.conf -s reload" ``` I could change the configuration setting on `config/xdebug-toggle.php` file too. This would also be a valid modification on the path. **Note: Don't forget to run `php artisan config:cache` to apply new settings when you change any `.env` parameter or configuration setting. Not only for this package, for all changes inside Laravel.** ### Testing Any tests written yet. But I suppose I should. ### Changelog Please see [CHANGELOG](CHANGELOG.md) for more information what has changed recently. ## Contributing Please see [CONTRIBUTING](CONTRIBUTING.md) for details. Any contributions are welcome. ### Security If you discover any security related issues, please email [email protected] instead of using the issue tracker. ## Credits - [Taha PAKSU](https://github.com/tpaksu) - [All Contributors](../../contributors) ## License The MIT License (MIT). Please see [License File](LICENSE.md) for more information.
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istio/kubernetes-istio-curso/02_execucao_istio.md
asantos2000/katacoda-scenarios
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[ "Apache-2.0" ]
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istio/kubernetes-istio-curso/02_execucao_istio.md
asantos2000/katacoda-scenarios
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2021-03-22T11:50:44.000Z
istio/kubernetes-istio-curso/02_execucao_istio.md
asantos2000/katacoda-scenarios
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## Acessando o k8s Primeiramente vamos verificar se estamos acessando o cluster de kubernetes. Vamos verificar como estão os nós do nosso cluster: `kubectl get nodes`{{execute}} > [Opcional] Algumas instalações colocam o arquivo de configuração do kubernetes no caminho `~/.kube/config` e pode ser necessário configurar a variável de ambiente KUBECONFIG para apontar para este arquivo. Caso você obteve o arquivo de config de um cluster externo (AKS, EKS, GKE, etc), você deverá configurar esta variável `export KUBECONFIG=~/.kube/config`{{execute}} No katacoda o ambiente já está configurado e não é necessário nenhuma configuração adicional. > [Opcional] Se você tem mais de um cluster na configuração, verifique se está apontando para o correto. `kubectl config get-contexts`{{execute}} ## Instalando o Istio (linux ou mac) Para instalar a última versão do Istio, neste momento 1.9.2, você pode ir até a página [Getting Started](https://istio.io/latest/docs/setup/getting-started/#download) ou seguir as instruções abaixo: `curl -L https://istio.io/downloadIstio | sh -`{{execute}} > Verifique qual foi a versão baixada e ajuste a variável ISTIO_VERSION, caso sejam diferentes. > Se o download não iniciar, interrompa o comando com <kdb>ctrl</kbd>+<kdb>c</kbd> e execute novamente. Para usar o comando `istioctl`, que está no diretório `bin` do download, coloque-o na variável `PATH` ou copie o arquivo `bin/istioctl` para um diretório no seu `PATH` ## Copiando o istioctl para o diretório de binários `ISTIO_VERSION=1.9.2`{{execute}} Verificar onde está o executável do Istio: `ls istio-$ISTIO_VERSION/bin`{{execute}} Copiar o arquivo para o diretório de binários: `cp istio-$ISTIO_VERSION/bin/istioctl /usr/local/bin`{{execute}} Teste `istioctl version`{{execute}} Ok, já temos o utilitário do Istio instalado no nosso sistema operacional, vamos seguir para instalação no cluster. ## Instalando o mínimo do Istio no k8s Desde a versão 1.6 o Istio é composto de uma única entrega chamada `istiod` e ela pode ser instalada com o comando abaixo: Isso deve demorar de 1 a 5 minutos, dependendo da capacidade do cluster. `istioctl install --set profile=minimal --skip-confirmation`{{execute}} Vamos verificar o que foi instalado Obtendo os namespaces: `kubectl get ns`{{execute}} Um novo namespace foi criado, o istio-system, vamos ver o que foi instalado: `kubectl get all -n istio-system`{{execute}} Neste ponto já temos o Istio instalado. ## Istio CRDs O Istio é uma aplicação que é executada no kubernetes e adiciona recursos personalizados ([CRD](https://kubernetes.io/docs/concepts/extend-kubernetes/api-extension/custom-resources/)) para sua configuração. Você pode obter uma lista completa executando o comando abaixo: `kubectl api-resources --api-group=networking.istio.io`{{execute}} `kubectl api-resources --api-group=security.istio.io`{{execute}} > Note que todos as configurações para recursos do Istio são aplicados para um _namespace_ (Namespaced=true), isso significa que a configuração terá efeito apenas em um _namespace_, porém, configurações que poderão ser aplicadas para toda a malha de serviços serão realizadas no _namespace_ do Istio, o `istio-system`. Você verá muito disso no kubernetes, para uma lista completa de recursos e suas abreviações execute o mesmo comando acima, mas sem o filtro. `kubectl api-resources`{{execute}} Esses são os recursos adicionados e na segunda coluna o nome abreviado, você pode utilizar um ou outro, por exemplo: Abreviado: `kubectl get svc`{{execute}} Que é equivalente a: `kubectl get services`{{execute}} ## Ativando o Istio para um namespace Um elemento chave do Istio é o _sidecar_ ou _proxy_, como veremos na discussão sobre arquitetura do Istio. Para que o Istio injete-o nos PODs da aplicação, é necessário marcar o _namespace_ da seguinte forma: `kubectl label namespace default istio-injection=enabled`{{execute}} Vamos verificar como ficou a configuração do namespace `kubectl describe ns/default`{{execute}} O `istiod` irá monitorar todos os _namespaces_ com o rótulo `istio-injection=enabled` e adicionar ao POD um _container_ de proxy, o _sidecar_. Vamos fazer _deploy_ de uma aplicação exemplo para verificar esse comportamento. ## Criando uma aplicação demo Vamos criar uma aplicação simples. `mkdir -p simple-app`{{execute}} Criando o arquivo de deployment: ``` cat <<EOT > simple-app/deployment.yaml apiVersion: apps/v1 kind: Deployment metadata: name: simple-app labels: app: simple-app version: v1 spec: replicas: 1 selector: matchLabels: app: simple-app version: v1 template: metadata: labels: app: simple-app version: v1 spec: containers: - name: simple-app image: "nginx:stable" imagePullPolicy: IfNotPresent ports: - name: http containerPort: 80 protocol: TCP EOT ```{{execute}} E o serviço: ``` cat <<EOT > simple-app/service.yaml apiVersion: v1 kind: Service metadata: name: simple-app labels: app: simple-app version: v1 spec: type: ClusterIP ports: - port: 80 targetPort: http protocol: TCP name: http selector: app: simple-app version: v1 EOT ```{{execute}} Listando os arquivos criados: `ls -la simple-app`{{execute}} Criamos dois arquivos, o `simple-app/deployment.yaml`{{open}} e o `simple-app/service.yaml`{{open}} no diretório `simple-app`, agora vamos instala-la no _namespace_ default (quando omitido é onde os recursos serão criados). Inspecione os arquivos e tente descobrir o que será instalado no cluster, uma dica, procure a pela imagem. `kubectl apply -f simple-app`{{execute}} Verificando a situação do POD. `kubectl get pods`{{execute}} > Repita o comando algumas vezes até que o POD esteja 2/2 _Running_. > Para instalar a aplicação em um _namespace_ diferente adicione `--namesapce` ou `-n`ao comando. Exemplo: `kubectl apply -f assets/exemplos/simple-app -n test-app` Vamos acessar nossa aplicação, ela foi configurada para o tipo de serviço `ClusterIP`, o que significa que o acesso é interno, apenas entre os PODs do cluster, mas podemos acessá-la utilizando o comando `kubectl port-forward`. `kubectl port-forward svc/simple-app 8000:80 --address 0.0.0.0`{{execute T1}} Vamos testar em um segundo terminal `curl localhost:8000`{{execute T2}} Você também pode usar o link Apps na parte superior do terminal. > Se o terminal for aberto pela primeira vez o comando pode ser ignorado, tente novamente com o terminal aberto. Pronto, você tem acesso à sua aplicação como se estivesse sendo executada na sua máquina. Claro que o kubernetes pode estar na sua máquina, mas isso funcionará em qualquer kubernetes, local ou remoto. Para interromper, no terminal tecle <kbd>CTRL</kbd>+<kbd>C</kbd>. Ou click em `echo " Pronto para ir. "`{{Execute interrupt T1}} Verificando o que foi instalado. `kubectl get --show-labels all`{{execute}} Note que o pod/simple-app tem 2/2 na coluna pronto (Ready), isso significa que dois containers de dois estão ok, vamos verificar quem é o segundo container. Usaremos um dos labels do pod para encontra-lo `kubectl describe pod -l app=simple-app`{{execute}} É uma grande quantidade de informação, vamos procurar uma seção chamada `Containers` e nela a nossa aplicação `simple-app`. Como você pode ver, a imagem desse container é `nginx`, com a tag `stable`, mais abaixo tem um segundo container `istio-proxy`, com a imagem `docker.io/istio/proxyv2` e a _tag_ para a versão `1.9.2`. Esse container não faz parte do `simple-app/deployment.yaml`{{open}}, ele foi adicionado ao seu pod pelo `istiod`. Caso você precise saber todos os _namespaces_ que tem a injeção do _envoy_ do Istio ativado, basta executar o comando: `kubectl get ns -l istio-injection=enabled`{{execute}} Até o momento, somente o namespace `default`, onde configuramos a marcação, foi encontrado. ## Conclusão Neste ponto temos o mínimo do Istio em execução no nosso cluster, mas com exceção de um container extra isso não significa muito. Na próxima parte iremos explorar os recursos que esta instalação mínima do Istio pode oferecer.
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--- Title: Vertrag zwischen der Bundesrepublik Deutschland und der Tunesischen Republik über Rechtsschutz und Rechtshilfe, die Anerkennung und Vollstreckung gerichtlicher Entscheidungen in Zivil- und Handelssachen sowie über die Handelsschiedsgerichtsbarkeit jurabk: VollstrVtr TUN layout: default origslug: vollstrvtr_tun slug: vollstrvtr_tun --- # Vertrag zwischen der Bundesrepublik Deutschland und der Tunesischen Republik über Rechtsschutz und Rechtshilfe, die Anerkennung und Vollstreckung gerichtlicher Entscheidungen in Zivil- und Handelssachen sowie über die Handelsschiedsgerichtsbarkeit (VollstrVtr TUN) Ausfertigungsdatum : 1966-07-19 Fundstelle : BGBl II: 1969, 890
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_posts/2018-09-30-Download-oxford-a-z-of-grammar-and-punctuation.md
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itaimal/bz-ng2-webpack
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[ "Apache-2.0" ]
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2019-08-27T09:03:10.000Z
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README.md
itaimal/bz-ng2-webpack
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README.md
itaimal/bz-ng2-webpack
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# generator-bz-ng2-webpack Template to generate a basic project with the necessary structure of folders and code with angular 2 and webpack. ## Available templates: 1. Project template 2. Component template ## Designed for: @angular 2.0.0-rc.4 ## Installing templates generator ### Prerequisites: You need node.js tools to initialize tests and webpack compilation. Make sure you have Node version >= 4.0 and NPM >= 3 You must have node.js and its package manager (npm) installed in your project (You can obtain it from node). ### Instalation: Using a terminal, place yourself on the folder where the project will be hosted and then execute the following commands. ```bash \anyfolder> npm install -g yo \anyfolder> npm install -g generator-bz-ng2-webpack ``` Create projectFolder ```bash \anyfolder> mkdir projectFolder \anyfolder> cd projectFolder ``` ### Using the template project Making use of a terminal, go to the folder where the template project will be hosted and then execute the following commands. ```bash \projectFolder> yo bz-ng2-webpack \projectFolder> cd WebContent ``` ```bash # change directory to our repo cd {projectFolder}/WebContent # Step 1: Add required global libraries npm install typings webpack-dev-server rimraf webpack -g # Step 2: Install the repo with npm npm install # Step 3: Start the server npm start ``` Now that you have the template project installed, you are ready to browse on it http://localhost:3000 ### Creating a component template On the folder where the component template will be installed execute the following line : ```bash \projectFolder\WebContent\app> yo bz-ng2-webpack:component ``` [Ivan Taimal]
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mkachuee/mkachuee.github.io
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--- redirect_to: "https://sites.google.com/view/mkachuee/home" --- --- layout: default --- --- ## About My name is Mohammad Kachuee. I am a PhD student at the [University of California Los Angeles (UCLA)](http://www.ucla.edu/) [Computer Science Department](http://www.cs.ucla.edu/). I have received my BS and MS degrees from [Sharif University of Technology](http://sharif.edu/) in [Electrical Engineering](http://ee.sharif.edu/). My current research interests include mobile health, data mining, health analytics, and designing machine learning algorithms for health-care applications. --- ## Research Interests - Machine Learning - Health Analytics - Wearable and Mobile Computing --- ## Publications * **M. Kachuee**, O. Goldstein, K. Kärkkäinen, S. Darabi, M. Sarrafzadeh, Opportunistic Learning: Budgeted Cost-Sensitive Learning from Data Streams, International Conference on Learning Representations (ICLR), 2019. [Paper](https://openreview.net/forum?id=S1eOHo09KX) * **M. Kachuee**, S. Darabi, B. Moatamed, M. Sarrafzadeh, Dynamic Feature Acquisition Using Denoising Autoencoders, IEEE Transactions on Neural Networks and Learning Systems (TNNLS), 2018. [Paper](https://arxiv.org/pdf/1811.01249.pdf) * **M. Kachuee**, S. Fazeli, M. Sarrafzadeh, ECG Heartbeat Classification: A Deep Transferable Representation, IEEE International Conference on Healthcare Informatics (ICHI), 2018. [IEEExplore](https://doi.org/10.1109/ICHI.2018.00092), [Dataset](https://www.kaggle.com/shayanfazeli/heartbeat) * **M. Kachuee**, A. Hosseini, B. Moatamed, S. Darabi, M. Sarrafzadeh, Context-Aware Feature Query to Improve the Prediction Performance, IEEE GlobalSIP Symposium on Signal and Information Processing (GlobalSIP), 2017. [IEEExplore](https://doi.org/10.1109/GlobalSIP.2017.8309078) * B. Moatamed, S. Darabi, M. Gwak, **M. Kachuee**, C. Metoyer, M. Linn, M. Sarrafzadeh Sport Analytics Platform for Athletic Readiness Assessment, IEEE-NIH 2017 Special Topics Conference on Healthcare Innovations and Point-of-Care Technologies (HI-POCT), 2017. [IEEExplore](https://doi.org/10.1109/HIC.2017.8227608) * A. Esmaili, **M. Kachuee**, M. Shabany, Nonlinear Cuff-less Blood Pressure Estimation of Healthy Subjects Using Pulse Transit Time and Arrival Time, IEEE Transactions on Instrumentation & Measurement (TIM), 2017. [IEEEexplore](https://doi.org/10.1109/TIM.2017.2745081), [Dataset](https://www.kaggle.com/mkachuee/noninvasivebp) * **M. Kachuee**, L. Moore, T. Homsey, H. G. Damavandi, B. Moatamed, A. Hosseini, R. Huang, J. Leiter, D. Lu, M. Sarrafzadeh, An Active Learning Based Prediction of Epidural Stimulation Outcome in Spinal Cord Injury Patients Using Dynamic Sample weighting, IEEE International Conference on Healthcare Informatics (ICHI), 2017. [IEEExplore](https://doi.org/10.1109/ICHI.2017.38), [Poster](https://github.com/mkachuee/mkachuee.github.io/raw/master/papers/Poster_SCI.pdf) * A. Esmaili, **M. Kachuee**, M. Shabany, Non-Invasive Blood Pressure Estimation Using Phonocardiogram, IEEE International Symposium on Circuits and Systems (ISCAS), 2017. [IEEEexplore](https://doi.org/10.1109/ISCAS.2017.8050240) * **M. Kachuee**, M. M. Kiani, H. Mohammadzade, M. Shabany, Cuff-Less Blood Pressure Estimation Algorithms for Continuous Health-Care Monitoring, IEEE Transactions on Biomedical Engineering (TBME), 2016. [IEEEexplore](http://dx.doi.org/10.1109/TBME.2016.2580904), [Paper](https://github.com/mkachuee/mkachuee.github.io/blob/master/papers/Paper_TBME2016.pdf), [Presentation](https://github.com/mkachuee/mkachuee.github.io/blob/master/papers/Presentation_TBME2016.pdf) * S. Latifi, H. Golestani, **M. Kachuee**, H. Mohammadzade, M. Hashemi, GPU-based Acceleration of Deep Convolutional Neural Networks on Mobile Platforms, arXiv:1511.07376, 2015. [arXiv](http://arxiv.org/abs/1511.07376) * **M. Kachuee**, M. M. Kiani, H. Mohammadzade, M. Shabany, Cuff-Less High-Accuracy Calibration-Free Blood Pressure Estimation Using Pulse Transit Time, IEEE International Symposium on Circuits and Systems (ISCAS), 2015. [IEEEexplore](http://dx.doi.org/10.1109/TBME.2016.2580904), [Presentation](https://github.com/mkachuee/mkachuee.github.io/blob/master/papers/Presentation_ISCAS2015.pdf), [Dataset](https://archive.ics.uci.edu/ml/datasets/Cuff-Less+Blood+Pressure+Estimation) --- ## Other Activities * I have served as a reviewer for IEEE Journal of Biomedical Health Informatics (JBHI) and IEEE Transactions on Biomedical Engineering (TBME). * I had the honor to present a lecture about deep learning and neural networks at the UCLA CS161 course: Introduction to Artificial Intelligence by Prof. Adnan Darwiche, Fall 2017. [Presentation](https://github.com/mkachuee/mkachuee.github.io/raw/master/presentations/Lec_161_NN.pdf) * I was teaching assistant for UCLA CS152 (Introductory Digital Design Laboratory) during Winter 2018. * I was teaching assistant for UCLA CS161 (Introduction to Artificial Intelligence) during Fall 2017.
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### RxSwift filterning and conditional operators <br> 上一节了解了一下**[Transforming Operators](https://www.jianshu.com/p/eabc12be8a57)**,现在我们进行看看还有哪些常用的**过滤 Operators** ### filter > 根据条件,过滤掉事件 ```swift example("filter") { let bag = DisposeBag() Observable.of( "🐱", "🐰", "🐶", "🐸", "🐱", "🐰", "🐹", "🐸", "🐱") .filter { $0 == "🐱" } .subscribe(onNext: { print($0) }) .disposed(by: bag) } ``` ![filter](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/filter.png) <br> ### distinctUntilChanged > 当前的事件值不等于上一次的事件值的时候才会发送,可以用来过滤重复请求 ```swift example("distinctUntilChanged") { let bag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .distinctUntilChanged() .subscribe(onNext: { print($0) }) .disposed(by: bag) } ``` ![distinctUntilChanged](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/distinctUntilChanged.png) <br> ### elementAt > 取指定下标的事件,下标从0开始 ```swift example("elementAt") { let bag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .elementAt(3) .subscribe(onNext: { print($0) }) .disposed(by: bag) } ``` ![elementAt](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/elementAt.png) <br> ### single 和 single { 条件 } > 取第一次事件 ```swift example("single") { let bag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .single() .subscribe( onNext: { print($0) }, onError: { print($0) } ).disposed(by: bag) } example("single with conditions") { let bag = DisposeBag() Observable.of("🐱", "🐰", "🐶", "🐸", "🐷", "🐵") .single { $0 == "🐸" } .subscribe { print($0) } .disposed(by: bag) Observable.of("🐱", "🐰", "🐶", "🐱", "🐰", "🐶") .single { $0 == "🐰" } .subscribe { print($0) } .disposed(by: bag) Observable.of("🐱", "🐰", "🐶", "🐸", "🐷", "🐵") .single { $0 == "🔵" } .subscribe { print($0) } .disposed(by: bag) } ``` ![single](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/single.png) <br> ### take > 取前N次的事件,N由用户输入 ```swift example("take") { let bag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .take(3) .subscribe(onNext: { print($0) }) .disposed(by: bag) } ``` ![take](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/take.png) <br> ### takeLast > 取后N次的事件,N由用户输入 ```swift example("takeLast") { let bag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .takeLast(3) .subscribe(onNext: { print($0) }) .disposed(by: bag) } ``` ![takeLast](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/takeLast.png) <br> ### takeWhile > `closure`中编写条件,取满足掉件的值,当遇到不满足的时候,**Observable**会调用`completed`方法结束 ```swift example("takeWhile") { let bag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .takeWhile { $0 < 3 } .subscribe(onNext: { print($0) }, onError: { print($0) }, onCompleted: { print("completed") }) .disposed(by: bag) } ``` ![takeWhile](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/takeWhile.png) <br> ### takeUntil > 参数是一个**Observable**,之后参数中的**Observable**发送了`onNext`事件才会监听到自己的`onNext`事件,如果参数中的**Observable**发生了`onError`事件,则会释放资源`disposed` ```swift example("takeUntil") { let bag = DisposeBag() let sourceSequence = PublishSubject<String>() let referenceSequence = PublishSubject<String>() sourceSequence .takeUntil(referenceSequence) .subscribe { print($0) } .disposed(by: bag) sourceSequence.onNext("1") sourceSequence.onNext("2") sourceSequence.onNext("2") referenceSequence.onNext("3") sourceSequence.onNext("1") sourceSequence.onNext("4") sourceSequence.onNext("2") } ``` ![takeUntil](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/takeUntil.png) <br> ### Skip > 跳过N次事件,N由用户输入 ```swift example("skip") { let bag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .skip(3) .subscribe(onNext: { print($0) }) .disposed(by: bag) } ``` ![skip](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/skip.png) <br> ### skipWhile > 跳过事件,通过`closure`的返回值(`bool`)决定忽略哪些事件 ```swift example("skipWhile") { let disposeBag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .skipWhile { $0 < 3 } .subscribe(onNext: { print($0) }) .disposed(by: disposeBag) } ``` ![skipWhile](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/skipWhile.png) <br> ### skipWhileWithIndex > 和`skipWhile`类似,只是在closure中多了`index`,但是此方法被标记为过期 ```swift example("skipWhileWithIndex") { let bag = DisposeBag() Observable.of(1, 2, 2, 3, 1, 4, 2) .skipWhileWithIndex { element, index in index < 3 } .subscribe(onNext: { print($0) }) .disposed(by: bag) } ``` ![skipWhileWithIndex](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/skipWhileWithIndex.png) <br> ### skipUntil > 和`takeUntil`类似,表示一直忽略,知道参数中的**Observable**发送了`onNext`事件 ```swift example("skipUntil") { let disposeBag = DisposeBag() let sourceSequence = PublishSubject<String>() let referenceSequence = PublishSubject<String>() sourceSequence .skipUntil(referenceSequence) .subscribe(onNext: { print($0) }) .disposed(by: disposeBag) sourceSequence.onNext("1") sourceSequence.onNext("2") sourceSequence.onNext("2") referenceSequence.onNext("3") sourceSequence.onNext("1") sourceSequence.onNext("4") sourceSequence.onNext("2") } ``` ![takeUntil](/Users/panguoquan/Desktop/RxSwift/RxSwiftStudy/006 FilterningAndConditionalOperators/takeUntil.png) ### throttle >当发送很多事件时,每隔多少ms取一次事件值 **使用场景:滑动Slider的时候回产生很多值,当我们并不想处理每次的值,只想在值的变化过程中取一些值** ```swift progressSlider.rx .value.asObservable() .throttle(0.4, scheduler: MainScheduler.instance) .map(progress) .bind(to: progressLabel.rx.text) .disposed(by: bag) ``` ### debounce > 当上一次的值和下一次的值超出时间间隔之后,就把事件的值发送出来 **使用场景:避免用户多次点击按钮导致多次请求等类似情况** ```swift button.rx .tap.asObservable() .debounce(0.3, scheduler:MainScheduler.instance) .map(btnTapCount) .bind(to: btnLabel.rx.text) .disposed(by: bag) ``` ![filter](/Users/panguoquan/Desktop/博客相关部分/Licecap/filter.gif)
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docs/API Reference/Components/Camera/DJICamera_DJICameraMultispectralExposureState.md
ryaa/Mobile-SDK-Android
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docs/API Reference/Components/Camera/DJICamera_DJICameraMultispectralExposureState.md
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docs/API Reference/Components/Camera/DJICamera_DJICameraMultispectralExposureState.md
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<div class="article"><h1 ><font color="#AAA">class </font>MultispectralExposureState</h1></div> ~~~java @EXClassNullAway class MultispectralExposureState ~~~ <html><table class="table-supportedby"><tr valign="top"><td width=15%><font color="#999"><i>Package:</i></td><td width=85%><font color="#999">dji.common.camera</td></tr></table></html> ##### Description: <font color="#666">The exposure state of a single-band sensor on the multispectral camera. The parameters in the state determines the relationship between exposure and sensor data values. When the camera is in different exposure modes, parameters may be changed by the camera automatically to optimize the exposure. ##### Class Members: <div class="api-row" id="djicamera_djicameramultispectralexposurestate_band"><div class="api-col left">Band</div><div class="api-col middle" style="color:#AAA">method</div><div class="api-col right"><a class="trigger" href="#djicamera_djicameramultispectralexposurestate_band_inline">getSpectrumBand</a></div></div><div class="inline-doc" id="djicamera_djicameramultispectralexposurestate_band_inline" ><div class="article"><h6 ><font color="#AAA">method </font>getSpectrumBand</h6></div> ~~~java SettingsDefinitions.SpectrumBand getSpectrumBand() ~~~ <html><table class="table-supportedby"><tr valign="top"><td width=15%><font color="#999"><i>Package:</i></td><td width=85%><font color="#999">dji.common.camera</td></tr></table></html> ##### Description: <font color="#666">The spectrum for which this exposure state is. ##### Return: <html><table class="table-inline-parameters"><tr valign="top"><td><font color="#70BF41"><a href="/Components/Camera/DJICamera_DJICameraSettingsDef.html#djicamera_djicamerasettingsdef">SettingsDefinitions</a>.<a href="/Components/Camera/DJICamera_DJICameraSettingsDef.html#djicamera_spectrumband">SpectrumBand</a></td><td><font color="#666"><i>An enum value of <code><a href="/Components/Camera/DJICamera_DJICameraSettingsDef.html#djicamera_spectrumband">SpectrumBand</a></code>.</i></td></tr></table></html></div> <div class="api-row" id="djicamera_djicameramultispectralexposurestate_shutterspeed"><div class="api-col left">Shutter Speed</div><div class="api-col middle" style="color:#AAA">method</div><div class="api-col right"><a class="trigger" href="#djicamera_djicameramultispectralexposurestate_shutterspeed_inline">getShutterSpeed</a></div></div><div class="inline-doc" id="djicamera_djicameramultispectralexposurestate_shutterspeed_inline" ><div class="article"><h6 ><font color="#AAA">method </font>getShutterSpeed</h6></div> ~~~java SettingsDefinitions.ShutterSpeed getShutterSpeed() ~~~ <html><table class="table-supportedby"><tr valign="top"><td width=15%><font color="#999"><i>Package:</i></td><td width=85%><font color="#999">dji.common.camera</td></tr></table></html> ##### Description: <font color="#666">The shutter speed of the single band sensor. ##### Return: <html><table class="table-inline-parameters"><tr valign="top"><td><font color="#70BF41"><a href="/Components/Camera/DJICamera_DJICameraSettingsDef.html#djicamera_djicamerasettingsdef">SettingsDefinitions</a>.<a href="/Components/Camera/DJICamera_DJICameraSettingsDef.html#djicamera_djicamerashutterspeed">ShutterSpeed</a></td><td><font color="#666"><i>An enum value of <code><a href="/Components/Camera/DJICamera_DJICameraSettingsDef.html#djicamera_djicamerashutterspeed">ShutterSpeed</a></code>.</i></td></tr></table></html></div> <div class="api-row" id="djicamera_djicameramultispectralexposurestate_sensorgain"><div class="api-col left">Sensor Gain</div><div class="api-col middle" style="color:#AAA">method</div><div class="api-col right"><a class="trigger" href="#djicamera_djicameramultispectralexposurestate_sensorgain_inline">getSensorGain</a></div></div><div class="inline-doc" id="djicamera_djicameramultispectralexposurestate_sensorgain_inline" ><div class="article"><h6 ><font color="#AAA">method </font>getSensorGain</h6></div> ~~~java float getSensorGain() ~~~ <html><table class="table-supportedby"><tr valign="top"><td width=15%><font color="#999"><i>Package:</i></td><td width=85%><font color="#999">dji.common.camera</td></tr></table></html> ##### Description: <font color="#666">The gain of the sensor. ##### Return: <html><table class="table-inline-parameters"><tr valign="top"><td><font color="#70BF41">float</td><td><font color="#666"><i>A float value of sensor gain.</i></td></tr></table></html></div> <div class="api-row" id="djicamera_djicameramultispectralexposurestatecallbackinterface"><div class="api-col left">Callback</div><div class="api-col middle" style="color:#AAA">class</div><div class="api-col right"><a href="/Components/Camera/DJICamera_DJICameraMultispectralExposureStateCallbackInterface.html">Callback</a></div></div>
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_posts/0006-01-01-Intro_to_RNAseq_Analysis.md
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_posts/0006-01-01-Intro_to_RNAseq_Analysis.md
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--- feature_text: | ## Precision Medicine Bioinformatics Introduction to bioinformatics for DNA and RNA sequence analysis title: Intro to RNAseq Analysis categories: - Module-06-RNAseq feature_image: "assets/genvis-dna-bg_optimized_v1a.png" date: 0006-01-01 --- ### Key concepts * RNA-seq, library strategies, RNA splicing, genes and transcripts, transcription strand, gene/transcript abundance estimation, FPKM and TPM, differential expression (DE) analysis, normalization, batch effects. ### Learning objectives * Perform alignment of RNA-seq data and a basic QC analysis of the resulting alignments * Obtain gene and transcript abundance estimates * Perform a reference-free alignment and abundance estimation and contrast the results with the reference based approach * Basic differential expression analysis * Perform an expression outlier analysis * Run an RNA fusion detection tool and parse the results for interesting candidates * Assess expression of specific gene markers of relevance (e.g. HER2, ER, PR) * Assess the expression of specific variants identified in previous sections. * Identify an example of allele specific expression ### Lecture * [PMBIO_Module06_RNAseq.pdf](https://github.com/griffithlab/pmbio.org/raw/master/assets/lectures/PMBIO_Module06_RNAseq.pdf)
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_posts/2017-05-28-testing-from-quill.md
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_posts/2017-05-28-testing-from-quill.md
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--- layout: post date: 2017-05-28 20:41 --- Testing from Quill.
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content/blog/Recipes/Other/sprinkles.md
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content/blog/Recipes/Other/sprinkles.md
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content/blog/Recipes/Other/sprinkles.md
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2021-01-23T19:23:39.000Z
2021-01-23T19:23:39.000Z
--- title: Sprinkles date: '2020-01-24T22:12:03.284Z' post-type: 'recipe' thumb-nail: 'thumbnails/sprinkles.png' --- The basis of which all recipes will follow: ![Sprinkles](./sprinkles.png) ## Ingredients - 175 g Icing sugar - 40g cornflour - 0.25 t Salt - 3 T Water - 1 t Vanilla Extract - Food Colouring ## Instructions 1. Kit prep: fit a small piping tip in a piping bag, have more bags ready to go 2. Combine the sugar, cornflour, salt, water & vanilla 3. Separate into bowls, and add colours 4. Add first colour to the piping bag - make lines for sprinkles, dots are also an option 5. Once the colour is complete, remove the piping tip and start with the second, repeat until rainbow is complete. ### Notes You don't really have to use a piping tip, cutting a hole in the end of the bag will suffice. The mixture is thic though so be warned you might blow through the bag if you aren't careful.
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CodeNarc/UnnecessaryReturnKeyword.md
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2019-07-17T18:16:06.000Z
2021-03-28T23:53:10.000Z
CodeNarc/UnnecessaryReturnKeyword.md
r3yn0ld4/docs-for-code-review-tools
a1590fce3b30891679373ec284787b227b21df05
[ "MIT" ]
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CodeNarc/UnnecessaryReturnKeyword.md
r3yn0ld4/docs-for-code-review-tools
a1590fce3b30891679373ec284787b227b21df05
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2018-09-29T17:02:14.000Z
2021-12-26T16:53:04.000Z
Pattern: Unnecessary `return` keyword Issue: - ## Description In Groovy, the `return` keyword is often optional. If a statement is the last line in a method or closure then you do not need to have the `return` keyword. ## Further Reading * [CodeNarc - UnnecessaryReturnKeyword](https://codenarc.github.io/CodeNarc/codenarc-rules-unnecessary.html#unnecessaryreturnkeyword-rule)
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Home Credit Default Risk/README.md
ppisarski/data-science
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null
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Home Credit Default Risk/README.md
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Home Credit Default Risk/README.md
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# Home Credit Default Risk [data](https://www.kaggle.com/c/home-credit-default-risk/data) - [Gentle Introduction](https://www.kaggle.com/willkoehrsen/start-here-a-gentle-introduction/comments) - [Introduction: Manual Feature Engineering](https://www.kaggle.com/willkoehrsen/introduction-to-manual-feature-engineering)
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Trial and Error/Session 3.md
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Trial and Error/Session 3.md
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Trial and Error/Session 3.md
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# Session 3 - Straight back into it. - Hobbin puts the zombies to sleep - Cloak is blue with elven ish writing and probably worth some money. - Slowly reveal a rather fine rug under the rocks. - Rug comes to life - Bonus action shil - Hit the rug - Kill the rug - Open the end door! - It is the kitchen - Close the door again - Open end door - Waterlogged library - Tenticle beast in the water - Use wild shape to enhance the spores - Take it out - Books about diseases and sickness - - Back to the disappear door - Invis, pull leaver, push door - Detect magic, door and writing conjuration magic, linked - Rub the word out - 8 abjuration chests - Simper goes in to open the first chest - 1 = 3 blue bottles - 2 = 3 blue bottles - True of all of them... - Head outside to see the magic thing. Is Mephet - - Looking for his revenge on the gods - Zombie infusion instructions - Other unpleasant elven notes - Head back to the water - Level of exhaustion - Another level of exhaustion - Crabs - Cold, very very cold - 20 small redish liquid vials - use 2 - With draconic script - And a glass eye - Try drinking one of the potions - Warmth springin through the body. - No longer frozen - These should cure the people... - Head out of Saarlsvault - Head back with Orvo - Look for the buyer - See a few plush chairs and a small dragon - Offer to give the antedote to the buyer - Could transport things to Elroe Alditor - Eye would be helpful if you were blind... - An ursart eye - Send 10 and keep 8 in case there are others -
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src/data/blog/2003/05/hello-ontario/index.md
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src/data/blog/2003/05/hello-ontario/index.md
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src/data/blog/2003/05/hello-ontario/index.md
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2021-03-08T22:09:55.000Z
2021-03-08T22:09:55.000Z
--- category: 'blog' title: 'Hello Ontario!' description: '' date: '2003-05-26' tags: ['Canads Bike Trip'] location: 'Longbow Lake, ON' distance: '84.7km' mapSrc: 'https://www.google.com/maps/embed?pb=!1m18!1m12!1m3!1d10316.800837016823!2d-94.34311775692156!3d49.72585712010983!2m3!1f0!2f0!3f0!3m2!1i1024!2i768!4f13.1!3m3!1m2!1s0x52bde38711fb659d%3A0x6c3040137857a6cb!2sLongbow%20Lake%2C%20ON!5e0!3m2!1sen!2sca!4v1609174273559!5m2!1sen!2sca' --- We're finally here! After one month of riding, we have finally crossed into the province of Ontario. We had a great night last night at Falcon Lake, which will just add to the fond memories I have of passing through Manitoba. The only problem was that Dave once again fell asleep without writing his daily journal entry, and thus he woke up at 4am to do his writing. Inevitably, I woke up as well, which led to a fitful night of sleeping. As a result, we were both a bit reluctant in getting out of bed, leading to a late start to the day. Once we began riding, it was immediately evident that we had left the prairies and entered the Canadian Shield as there were trees and rock everywhere. This of course led to hills... nothing major, but when you haven't seen a hill for over a week, they seem pretty significant! It took a little while to get my body back into gear to handle such obstacles, especially since the tail winds across the prairies had left me with very little work to do in regards to riding. ![](./can_bike_trip_157.jpg) It was just a short journey to the Ontario border, and we stopped for a mandatory photo op and trip to the tourism booth to pick up maps and campground info. We then set out for Kenora, which was to be our lunch destination. Unfortunately, as our bodies got reacquainted with the hilly terrain, our riding speed was a bit slower than we were used to. Thus, we arrived in Kenora a bit later than expected. The trek through the city of Kenora was amazing, with gorgeous scenery in every direction. We stopped for numerous pictures, including shots of Husky the Muskie! We then travelled through downtown, making some required stops, and then we went for lunch at Subway. ![](./can_bike_trip_162.jpg) Following lunch, we tried to decide on where to spend the night. Our original destination, Vermillion Bay, was out of the question, and according to the map, there was nothing between Kenora and Vermillion Bay. A quick stop at the travel information hut pointed us towards a campground just outside of Kenora. This was an ideal location as it leaves us a reasonable distance from Dryden, which is the destination for tomorrow. Also, the campground is located right on the lake and has a small beach, making for a great spot to simply relax and enjoy nature! It is cool to actually see Thunder Bay listed on the distance signs. It appears we are about four days from reaching Thunder Bay, depending on weather of course. After that, Sudbury is the next major destination. It will be interesting to track our progress across Ontario, seeing as how it is bigger than a lot of countries. Getting to Ottawa is going to be great feeling! I'm really looking forward to seeing everybody back home again.
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GTVolk/DBAutoShop
ef89bb7fa1ac2c2ab9f3f042af09e368360df4e0
[ "MIT" ]
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README.md
GTVolk/DBAutoShop
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[ "MIT" ]
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README.md
GTVolk/DBAutoShop
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# MSSQL DB Auto Shop ## Description Microsoft SQL Express + C# Test Application ![Screenshot](/Screenshot.PNG?raw=true) ## Requirements - Visual Studio - MSSQL Express ## TODO - Errors in encoding - Connection Wizard - Fixes - i18l - Cool UI
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vikekh/pokver
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README.md
vikekh/pokver
263792cf2ac44e73dc1adabde29a8c07c5704b2a
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README.md
vikekh/pokver
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# Pokver Versioning for the Nintendo generation.
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docs/odbc/microsoft/dbase-indexes.md
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--- description: Índices do dBASE title: Índices do dBASE | Microsoft Docs ms.custom: '' ms.date: 01/19/2017 ms.prod: sql ms.prod_service: connectivity ms.reviewer: '' ms.technology: connectivity ms.topic: conceptual helpviewer_keywords: - DBase indexes [ODBC] - DBase driver [ODBC], indexes ms.assetid: fdfa56f5-e324-4ec2-9267-fdf95ab99373 author: David-Engel ms.author: v-daenge ms.openlocfilehash: 30a6390f0e187cc063b2a650af2da3b9fcc87d57 ms.sourcegitcommit: e700497f962e4c2274df16d9e651059b42ff1a10 ms.translationtype: MT ms.contentlocale: pt-BR ms.lasthandoff: 08/17/2020 ms.locfileid: "88340952" --- # <a name="dbase-indexes"></a>Índices do dBASE O driver do dBASE do ODBC abre e atualiza automaticamente os arquivos de índice do dBASE IV. Você deve usar a caixa de diálogo **selecionar índices** exibida por meio do administrador de fonte de dados ODBC para associar arquivos. ndx do dBASE III a arquivos do dBASE. As seguintes limitações se aplicam à criação de índices do dBASE: - Todos os nomes de coluna devem ser válidos. - Todas as colunas devem estar na mesma ordem crescente ou decrescente. - O comprimento de qualquer coluna de texto individual deve ser menor que 100 bytes. - Se houver mais de uma coluna, todas as colunas deverão ser colunas de texto e a soma dos tamanhos das colunas deverá ser menor que 100 bytes. - Os campos de memorando não podem ser indexados. - Um índice não deve ser especificado para o conjunto atual de campos (ou seja, índices duplicados não são permitidos). - O nome do índice deve corresponder à Convenção de nomenclatura do índice do dBASE. o dBASE III requer que cada índice esteja em um arquivo separado, cada um com uma extensão. ndx. No dBASE IV, os índices são criados como nomes de marca que são armazenados em um único arquivo. MDX. O arquivo. MDX tem o mesmo nome base do arquivo de banco de dados (por exemplo, EMP. MDX é o arquivo de índice para o banco de dados EMP. dbf). - o dBASE define um índice exclusivo como um em que apenas um registro de um conjunto com valores de chave idênticos é adicionado ao índice.
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mpilquist/shapeless
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2018-06-10T16:12:33.000Z
notes/about.markdown
retronym/shapeless
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notes/about.markdown
retronym/shapeless
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[shapeless](https://github.com/milessabin/shapeless) is an exploration of type class and dependent type based generic programming in Scala. A series of articles on the implementation techniques used will appear [here](http://www.chuusai.com/blog) and it also has a [mailing list](https://groups.google.com/group/shapeless-dev).
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_containers/marcjwilliams1-dnds-clonesize-R-container-latest.md
singularityhub/singularityhub-archive
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[ "ECL-2.0", "Apache-2.0" ]
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_containers/marcjwilliams1-dnds-clonesize-R-container-latest.md
singularityhub/singularityhub-archive
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_containers/marcjwilliams1-dnds-clonesize-R-container-latest.md
singularityhub/singularityhub-archive
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--- id: 10729 name: "marcjwilliams1/dnds-clonesize-R-container" branch: "master" tag: "latest" commit: "299ad35d95e8a478dbb27ab92784d247593a23ee" version: "282e13ea3090576c1de36743fc7fa6cf" build_date: "2020-07-28T16:53:53.769Z" size_mb: 3622.0 size: 1521274911 sif: "https://datasets.datalad.org/shub/marcjwilliams1/dnds-clonesize-R-container/latest/2020-07-28-299ad35d-282e13ea/282e13ea3090576c1de36743fc7fa6cf.sif" datalad_url: https://datasets.datalad.org?dir=/shub/marcjwilliams1/dnds-clonesize-R-container/latest/2020-07-28-299ad35d-282e13ea/ recipe: https://datasets.datalad.org/shub/marcjwilliams1/dnds-clonesize-R-container/latest/2020-07-28-299ad35d-282e13ea/Singularity collection: marcjwilliams1/dnds-clonesize-R-container --- # marcjwilliams1/dnds-clonesize-R-container:latest ```bash $ singularity pull shub://marcjwilliams1/dnds-clonesize-R-container:latest ``` ## Singularity Recipe ```singularity BootStrap: docker From: asachet/rocker-stan %labels Maintainer Marc J Williams %help Singularity image for following paper: %post # add R packages from CRAN Rscript -e "install.packages(pkgs = c('devtools', 'cowplot', 'gtools', 'argparse','jcolors', 'ggthemes', 'viridis','Hmisc','ggridges', 'readxl', 'bayesplot', 'modelr', 'ggforce', 'ggfortify', 'bayestestR'), \ repos='https://cran.revolutionanalytics.com/', \ dependencies=TRUE, \ clean = TRUE)" #add R packages from bioconductor Rscript -e "install.packages('BiocManager')" Rscript -e "library(BiocManager); install('GenomicRanges')" Rscript -e "library(BiocManager); install('IRanges')" Rscript -e "library(BiocManager); install('Biostrings')" Rscript -e "library(BiocManager); install('Rsamtools')" Rscript -e "library(BiocManager); install('seqinr')" Rscript -e "library(BiocManager); install('rtracklayer')" # add R packages from github Rscript -e "library(devtools); install_github('marcjwilliams1/dndscv', ref = 'dev')" ``` ## Collection - Name: [marcjwilliams1/dnds-clonesize-R-container](https://github.com/marcjwilliams1/dnds-clonesize-R-container) - License: None
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_posts/2018-01-01-splitting-strings-python.md
taniaka/taniaka.github.io
9dd0ab4baeffff4a3a3650472678452eb9f234c5
[ "MIT" ]
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_posts/2018-01-01-splitting-strings-python.md
taniaka/taniaka.github.io
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_posts/2018-01-01-splitting-strings-python.md
taniaka/taniaka.github.io
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--- layout: post title: Splitting strings in Python categories: python string icon: hand-spock-o --- If you have ever dealt with Python strings, chances are you're already familiar with the `split` method that takes a string and breaks it into a multi-element list. As an optional argument `split` can take a string indicating where exactly the division should occur. In the example below, this delimiter argument is a comma: ``` >>> 'alpa,beta,gamma,delta'.split(',') ['alpa', 'beta', 'gamma', 'delta'] ``` If the delimiter isn't specified, the string is split on whitespace: ``` >>> 'alpha beta gamma delta'.split() ['alpha', 'beta', 'gamma', 'delta'] ``` This might lead you to believe that splitting with no delimiter is equal to splitting on a space character, but have a look at the following examples: ``` >>> ' hi there '.split(' ') ['', '', '', '', 'hi', 'there', ''] >>> ' hi there '.split() ['hi', 'there'] ``` The operations output totally different lists, but why does this happen? The thing is that two distinct algorithms are used by the `split` method: one of them is applied to splits with a delimiter and the other one to those without one. To fully understand how splitting works, it's a good idea to look at each type separately. ### Splitting with a delimiter So, if a delimiter is specified, the string splits each time the delimiter occurs in it. The delimiter can consist of as many characters as you like and it is stripped out from the result. So basically, we use the delimiter to break the string into pieces and then just 'throw it away'. ``` >>> 'rococoesque'.split('o') ['r', 'c', 'c', 'esque'] >>> 'rococoesque'.split('oes') ['rococ', 'que'] ``` `split` also takes an optional second argument called _maxsplit_ which specifies the maximum number of splits to be made. ``` >>> 'rococoesque'.split('o', 2) ['r', 'c', 'coesque'] ``` In the previous example, the string has 3 o's, but since I set _maxsplit_ to 2, only 2 splits were made. By far the most interesting thing about this splitting algorithm is that consecutive delimiters are treated as if they were separating empty strings. In other words, if the string happens to have two delimiters side by side, an empty string appears at the corresponding position of the list generated through splitting. ``` >>> 'cooool'.split('o') ['c', '', '', '', 'l'] ``` In the previous example, my string has 4 o's in a row, so not only is 'c' separated from 'l', but also a split is made for each pair of consecutive o's and three empty strings are inserted as a result. Also, if the delimiter happens to open or close the string, an empty string is inserted as the first or last element of the output list, respectively. ``` >>> 'kayak'.split('k') ['', 'aya', ''] ``` What has been said is also true for splitting at a whitespace character, (but only if it is explicitely passed as an argument). That is, the algorithm applied by `s.split(' ')` is in no way different from the one applied by, say, `s.split('k')`. ``` >>> ' a b c d '.split(' ') ['', 'a', 'b', 'c', '', '', 'd', ''] ``` ### Splitting without a delimiter If the delimiter is not specified or is set to `None`, the string is split on whitespace. The important thing here is that by whitespace we refer not only to a regular space, but also to a bunch of newline and tab characters: - \n line break - \t horizontal tab - \v vertical tab - \r carriage retun - \f formfeed All of those are considered as delimiters by this splitting algorithm. ``` >>> 'a b\nc\td\ve\rf\f'.split() ['a', 'b', 'c', 'd', 'e', 'f'] ``` According to Python [docs](https://docs.python.org/3/library/stdtypes.html#str.split), any combination of consecutive whitespace is regarded as a single delimiter. What this means is that `split` is smart enough to understand that for a sequence of 5 whitespace characters, I would generally prefer to get 1 split instead of 5. Also, if the string has leading or trailing whitespace, no empty string is inserted at the start or end. ``` >>> ' a\t \vb c\n\n \r d\n'.split() ['a', 'b', 'c', 'd'] ``` ### Using regular expressions to split strings (a couple of examples) Python's `split` method is pretty handy, but it may fall short in more complex scenarios. A more powerful `split` method can be found in Python's `re` module which provides regular expression matching operations. This post is not about regular expressions, but let me show you a couple of things that can be easily achieved with `re`. (And, of course, don't forget to do an `import re` first). When you do a split, the delimiter string is not included in the output list by default. While normally this is the desired behavior, sometimes you may not want to get rid of the delimiter, and with regular expressions keeping it is as easy as putting parentheses around it. ``` >>> re.split(r'2', '12321') #no parentheses, the '2' delimiter is stripped out ['1', '3', '1'] >>> re.split(r'(2)', '12321') #he '2' delimiter is inside parentheses and is not stripped out ['1', '2', '3', '2', '1'] ``` Another thing you are likely to need is being able to simultaneously use several delimiters. For instance, you might want to split a string at ',' and at ';' at the same time. With a regular expression, it can be achieved by separating the delimiters with an '&#124;' character: ``` >>> re.split(r',|;', 'a,b;c;d,e') ['a', 'b', 'c', 'd', 'e'] ``` If you're interested in doing more advanced operations with strings, I highly recommend you to have a closer look at the `re` module. There are many online resources, such as [PyMOTW tutorial](https://pymotw.com/2/re/), to help get you started.
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toothless1216/toothless1216.github.io
4b5d547a3671fbd88c28e9f1429ddccbd8f41c15
[ "CC-BY-3.0" ]
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README.md
toothless1216/toothless1216.github.io
4b5d547a3671fbd88c28e9f1429ddccbd8f41c15
[ "CC-BY-3.0" ]
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README.md
toothless1216/toothless1216.github.io
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[ "CC-BY-3.0" ]
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# toothless1216.github.io
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binyellow/source
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README.md
binyellow/source
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README.md
binyellow/source
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# source notes of read source code
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.changeset/popular-kids-run.md
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.changeset/popular-kids-run.md
PH4NTOMiki/kit
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--- 'create-svelte': patch --- [chore] upgrade to Playwright 1.21.0
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