Duplicated fromΒ Tonic1/ImageEdit-GOT-OCR
β£1x=1cβ£=β£cβxxcβ£=1β£xβ£β 1β£cβ£β β£xβcβ£\mid\frac{1}{x}=\frac{1}{c}\mid=\mid\frac{c-x}{xc}\mid=\frac{1}{\left\vert x\right\vert}\cdot\frac{1}{\left\vert c\right\vert}\cdot\left\vert x-c\right\vertβ£x1β=c1ββ£=β£xccβxββ£=β£xβ£1ββ β£cβ£1ββ β£xβcβ£
The factor $$\frac{1}{\left\vert x\right\vert}$$ is not good if its near 0.