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--- |
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license: apache-2.0 |
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datasets: |
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- qingy2024/PR2-SFT |
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language: |
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- en |
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base_model: |
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- Qwen/Qwen2.5-14B-Instruct |
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--- |
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## PR2 14B Instruct |
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PR2 is an experimental fine tune of Qwen2.5 14B Instruct, incorporating planning and reasoning before outputting a final answer. It is trained for 2 epochs on the verified subset of qingy2024/PR2-SFT. |
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**Example:** |
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Input: |
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``` |
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Find the minimum value of the expression \\(\left(\sqrt{2(1+\cos 2 x)}-\sqrt{36-4 \sqrt{5}} \sin x+2\right) \cdot \left(3+2 \sqrt{10-\sqrt{5}} \cos y-\cos 2 y\right)\\). If the answer is not an integer, round it to the nearest integer. |
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First, create a high level overview in <plan></plan> tags, then do your reasoning in <think></think> tags, and put your final answer in <answer></answer>. |
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``` |
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Output: |
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``` |
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<plan> |
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1. Simplify the expression by breaking it down into manageable parts. |
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2. Use trigonometric identities to simplify terms involving trigonometric functions. |
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3. Analyze the structure of the expression to identify potential optimization strategies. |
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4. Consider the possibility of minimizing each part of the expression separately. |
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5. Calculate the minimum value of the entire expression and round it to the nearest integer if necessary. |
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</plan> |
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<think> |
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Hmm... let me start by simplifying the expression. The expression is: |
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\[ |
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\left(\sqrt{2(1+\cos 2x)} - \sqrt{36-4\sqrt{5}} \sin x + 2\right) \cdot \left(3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y\right) |
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\] |
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First, I notice that \(\sqrt{2(1+\cos 2x)}\) can be simplified using a trigonometric identity. Recall that \(1 + \cos 2x = 2\cos^2 x\), so: |
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\[ |
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\sqrt{2(1+\cos 2x)} = \sqrt{2 \cdot 2\cos^2 x} = \sqrt{4\cos^2 x} = 2|\cos x| |
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\] |
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Since \(\cos x\) can be positive or negative, we'll keep it as \(2|\cos x|\) for now. |
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Next, let's look at the second part of the first factor: \(-\sqrt{36-4\sqrt{5}} \sin x + 2\). This seems a bit complicated, but perhaps we can find a way to simplify or bound it. |
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Now, let's consider the second factor: \(3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y\). Again, we can use trigonometric identities to simplify \(\cos 2y\). Recall that \(\cos 2y = 2\cos^2 y - 1\), so: |
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\[ |
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3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y = 3 + 2\sqrt{10-\sqrt{5}} \cos y - (2\cos^2 y - 1) = 4 + 2\sqrt{10-\sqrt{5}} \cos y - 2\cos^2 y |
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\] |
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This is a quadratic in terms of \(\cos y\), so we might be able to find its minimum value. |
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Wait, perhaps it's better to think about minimizing each factor separately and then multiply the minima together. Let's try that. |
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First, let's find the minimum of the first factor: |
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\[ |
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F_1(x) = 2|\cos x| - \sqrt{36-4\sqrt{5}} \sin x + 2 |
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\] |
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This seems complicated due to the absolute value and the trigonometric functions. Maybe we can express it in terms of a single trigonometric function. |
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Alternatively, perhaps we can use calculus to find the minimum of \(F_1(x)\). Let's try that. |
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Let's consider \(F_1(x) = 2|\cos x| - \sqrt{36-4\sqrt{5}} \sin x + 2\). To find the minimum, we can take the derivative and set it to zero. |
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However, the absolute value makes this tricky. Perhaps we can consider the cases where \(\cos x\) is positive and negative separately. |
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Case 1: \(\cos x \geq 0\) |
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Then \(F_1(x) = 2\cos x - \sqrt{36-4\sqrt{5}} \sin x + 2\). Taking the derivative with respect to \(x\): |
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\[ |
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F_1'(x) = -2\sin x - \sqrt{36-4\sqrt{5}} \cos x |
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\] |
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Setting \(F_1'(x) = 0\): |
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\[ |
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-2\sin x - \sqrt{36-4\sqrt{5}} \cos x = 0 \implies -2\sin x = \sqrt{36-4\sqrt{5}} \cos x \implies \tan x = -\frac{\sqrt{36-4\sqrt{5}}}{2} |
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\] |
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This gives us a critical point, but we need to check if it's a minimum. |
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Alternatively, perhaps we can use trigonometric identities to express \(F_1(x)\) as a single trigonometric function. |
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Recall that \(A\sin x + B\cos x = R\sin(x + \alpha)\), where \(R = \sqrt{A^2 + B^2}\) and \(\tan \alpha = \frac{B}{A}\). |
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In our case, \(A = -\sqrt{36-4\sqrt{5}}\) and \(B = 2\), so: |
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\[ |
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R = \sqrt{(-\sqrt{36-4\sqrt{5}})^2 + 2^2} = \sqrt{36-4\sqrt{5} + 4} = \sqrt{40-4\sqrt{5}} = 2\sqrt{10-\sqrt{5}} |
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\] |
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So, \(F_1(x) = 2\sqrt{10-\sqrt{5}} \sin(x + \alpha) + 2\). |
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The minimum value of \(\sin(x + \alpha)\) is \(-1\), so the minimum of \(F_1(x)\) is: |
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\[ |
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2\sqrt{10-\sqrt{5}} \cdot (-1) + 2 = -2\sqrt{10-\sqrt{5}} + 2 |
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\] |
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Now, let's find the minimum of the second factor: |
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\[ |
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F_2(y) = 4 + 2\sqrt{10-\sqrt{5}} \cos y - 2\cos^2 y |
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\] |
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This is a quadratic in \(\cos y\). Let \(z = \cos y\), then: |
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\[ |
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F_2(y) = -2z^2 + 2\sqrt{10-\sqrt{5}} z + 4 |
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\] |
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This is a quadratic equation in \(z\), and since the coefficient of \(z^2\) is negative, it has a maximum value. However, we need the minimum value of \(F_2(y)\). The minimum will occur at the boundaries of \(z\), i.e., when \(z = 1\) or \(z = -1\). |
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Let's evaluate \(F_2(y)\) at \(z = 1\) and \(z = -1\). |
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At \(z = 1\): |
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\[ |
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F_2(y) = -2(1)^2 + 2\sqrt{10-\sqrt{5}} (1) + 4 = -2 + 2\sqrt{10-\sqrt{5}} + 4 = 2 + 2\sqrt{10-\sqrt{5}} |
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\] |
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At \(z = -1\): |
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\[ |
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F_2(y) = -2(-1)^2 + 2\sqrt{10-\sqrt{5}} (-1) + 4 = -2 - 2\sqrt{10-\sqrt{5}} + 4 = 2 - 2\sqrt{10-\sqrt{5}} |
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\] |
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Since \(\sqrt{10-\sqrt{5}} > 0\), the minimum value of \(F_2(y)\) is \(2 - 2\sqrt{10-\sqrt{5}}\). |
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Now, the minimum value of the entire expression is the product of the minima of \(F_1(x)\) and \(F_2(y)\): |
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\[ |
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(-2\sqrt{10-\sqrt{5}} + 2) \cdot (2 - 2\sqrt{10-\sqrt{5}}) = (-2\sqrt{10-\sqrt{5}} + 2)(2 - 2\sqrt{10-\sqrt{5}}) |
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\] |
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Let's compute this product: |
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\[ |
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(-2\sqrt{10-\sqrt{5}} + 2)(2 - 2\sqrt{10-\sqrt{5}}) = (-2\sqrt{10-\sqrt{5}} \cdot 2) + (-2\sqrt{10-\sqrt{5}} \cdot -2\sqrt{10-\sqrt{5}}) + (2 \cdot 2) + (2 \cdot -2\sqrt{10-\sqrt{5}}) |
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\] |
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Simplifying each term: |
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\[ |
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= -4\sqrt{10-\sqrt{5}} + 4(10-\sqrt{5}) + 4 - 4\sqrt{10-\sqrt{5}} |
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\] |
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Combine like terms: |
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\[ |
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= -4\sqrt{10-\sqrt{5}} - 4\sqrt{10-\sqrt{5}} + 4(10-\sqrt{5}) + 4 = -8\sqrt{10-\sqrt{5}} + 40 - 4\sqrt{5} + 4 = -8\sqrt{10-\sqrt{5}} + 44 - 4\sqrt{5} |
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\] |
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This expression is quite complicated, and calculating its exact value might not be straightforward. However, we can approximate the value. |
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First, let's approximate \(\sqrt{10 - \sqrt{5}}\). Since \(\sqrt{5} \approx 2.236\), we have: |
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\[ |
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\sqrt{10 - 2.236} = \sqrt{7.764} \approx 2.786 |
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\] |
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Similarly, \(\sqrt{5} \approx 2.236\). |
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Now, let's approximate the expression: |
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\[ |
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-8 \cdot 2.786 + 44 - 4 \cdot 2.236 = -22.288 + 44 - 8.944 = 12.768 |
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\] |
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Rounding this to the nearest integer gives us 13. |
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Wait, let's double-check the calculations to ensure accuracy. |
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First, let's compute \(\sqrt{10 - \sqrt{5}}\) more precisely. |
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\(\sqrt{5} \approx 2.2360679775\), so: |
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\[ |
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\sqrt{10 - 2.2360679775} = \sqrt{7.7639320225} \approx 2.786 |
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\] |
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Now, compute the expression: |
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\[ |
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-8 \cdot 2.786 + 44 - 4 \cdot 2.236 = -22.288 + 44 - 8.944 = 12.768 |
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\] |
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Rounding 12.768 to the nearest integer gives us 13. |
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Thus, the minimum value of the expression is approximately 13. |
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</think> |
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<answer> |
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\boxed{13} |
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</answer> |
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``` |