Datasets:
target-benchmark
/
spider-queries

Dataset card Data Studio Files Community
3
query_id
int64
0
7k
database_id
stringclasses
140 values
table_id
listlengths
1
5
query
stringlengths
16
224
answer
stringlengths
18
577
difficulty
stringclasses
4 values
2,600
inn_1
[ "reservations", "rooms" ]
What kind of decor has the least number of reservations?
SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY count(T2.decor) ASC LIMIT 1;
extra
2,601
inn_1
[ "reservations", "rooms" ]
What is the least popular kind of decor?
SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY count(T2.decor) ASC LIMIT 1;
extra
2,602
inn_1
[ "reservations", "rooms" ]
List how many times the number of people in the room reached the maximum occupancy of the room. The number of people include adults and kids.
SELECT count(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids;
medium
2,603
inn_1
[ "reservations", "rooms" ]
How many times the number of adults and kids staying in a room reached the maximum capacity of the room?
SELECT count(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids;
medium
2,604
inn_1
[ "reservations", "rooms" ]
Find the first and last names of people who payed more than the rooms' base prices.
SELECT T1.firstname , T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0
medium
2,605
inn_1
[ "reservations", "rooms" ]
What are the first and last names of people who payed more than the rooms' base prices?
SELECT T1.firstname , T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0
medium
2,606
inn_1
[ "rooms" ]
How many rooms are there?
SELECT count(*) FROM Rooms;
easy
2,607
inn_1
[ "rooms" ]
What is the total number of rooms available in this inn?
SELECT count(*) FROM Rooms;
easy
2,608
inn_1
[ "rooms" ]
Find the number of rooms with a king bed.
SELECT count(*) FROM Rooms WHERE bedType = "King";
easy
2,609
inn_1
[ "rooms" ]
How many rooms have a king bed?
SELECT count(*) FROM Rooms WHERE bedType = "King";
easy
2,610
inn_1
[ "rooms" ]
Find the number of rooms for each bed type.
SELECT bedType , count(*) FROM Rooms GROUP BY bedType;
medium
2,611
inn_1
[ "rooms" ]
What are the number of rooms for each bed type?
SELECT bedType , count(*) FROM Rooms GROUP BY bedType;
medium
2,612
inn_1
[ "rooms" ]
Find the name of the room with the maximum occupancy.
SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1;
medium
2,613
inn_1
[ "rooms" ]
What is the name of the room that can accommodate the most people?
SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1;
medium
2,614
inn_1
[ "rooms" ]
Find the id and name of the most expensive base price room.
SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1;
medium
2,615
inn_1
[ "rooms" ]
Which room has the highest base price?
SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1;
medium
2,616
inn_1
[ "rooms" ]
List the type of bed and name of all traditional rooms.
SELECT roomName , bedType FROM Rooms WHERE decor = "traditional";
medium
2,617
inn_1
[ "rooms" ]
What are the bed type and name of all the rooms with traditional decor?
SELECT roomName , bedType FROM Rooms WHERE decor = "traditional";
medium
2,618
inn_1
[ "rooms" ]
Find the number of rooms with king bed for each decor type.
SELECT decor , count(*) FROM Rooms WHERE bedType = "King" GROUP BY decor;
medium
2,619
inn_1
[ "rooms" ]
How many rooms have king beds? Report the number for each decor type.
SELECT decor , count(*) FROM Rooms WHERE bedType = "King" GROUP BY decor;
medium
2,620
inn_1
[ "rooms" ]
Find the average and minimum price of the rooms in different decor.
SELECT decor , avg(basePrice) , min(basePrice) FROM Rooms GROUP BY decor;
medium
2,621
inn_1
[ "rooms" ]
What is the average minimum and price of the rooms for each different decor.
SELECT decor , avg(basePrice) , min(basePrice) FROM Rooms GROUP BY decor;
medium
2,622
inn_1
[ "rooms" ]
List the name of all rooms sorted by their prices.
SELECT roomName FROM Rooms ORDER BY basePrice;
easy
2,623
inn_1
[ "rooms" ]
Sort all the rooms according to the price. Just report the room names.
SELECT roomName FROM Rooms ORDER BY basePrice;
easy
2,624
inn_1
[ "rooms" ]
Find the number of rooms with price higher than 120 for different decor.
SELECT decor , count(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor;
medium
2,625
inn_1
[ "rooms" ]
How many rooms cost more than 120, for each different decor?
SELECT decor , count(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor;
medium
2,626
inn_1
[ "rooms" ]
For each bed type, find the average room price.
SELECT bedType , avg(basePrice) FROM Rooms GROUP BY bedType;
medium
2,627
inn_1
[ "rooms" ]
What is the average base price of rooms, for each bed type?
SELECT bedType , avg(basePrice) FROM Rooms GROUP BY bedType;
medium
2,628
inn_1
[ "rooms" ]
List the name of rooms with king or queen bed.
SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen";
medium
2,629
inn_1
[ "rooms" ]
What are the names of rooms that have either king or queen bed?
SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen";
medium
2,630
inn_1
[ "rooms" ]
How many different types of beds are there?
SELECT count(DISTINCT bedType) FROM Rooms;
easy
2,631
inn_1
[ "rooms" ]
Find the number of distinct bed types available in this inn.
SELECT count(DISTINCT bedType) FROM Rooms;
easy
2,632
inn_1
[ "rooms" ]
Find the name and id of the top 3 expensive rooms.
SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3;
medium
2,633
inn_1
[ "rooms" ]
What are the name and id of the three highest priced rooms?
SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3;
medium
2,634
inn_1
[ "rooms" ]
Find the name of rooms whose price is higher than the average price.
SELECT roomName FROM Rooms WHERE basePrice > ( SELECT avg(basePrice) FROM Rooms );
hard
2,635
inn_1
[ "rooms" ]
What are the name of rooms that cost more than the average.
SELECT roomName FROM Rooms WHERE basePrice > ( SELECT avg(basePrice) FROM Rooms );
hard
2,636
inn_1
[ "reservations", "rooms" ]
Find the number of rooms that do not have any reservation.
SELECT count(*) FROM rooms WHERE roomid NOT IN (SELECT DISTINCT room FROM reservations)
extra
2,637
inn_1
[ "reservations", "rooms" ]
How many rooms have not had any reservation yet?
SELECT count(*) FROM rooms WHERE roomid NOT IN (SELECT DISTINCT room FROM reservations)
extra
2,638
inn_1
[ "reservations", "rooms" ]
Return the name and number of reservations made for each of the rooms.
SELECT T2.roomName , count(*) , T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room
medium
2,639
inn_1
[ "reservations", "rooms" ]
For each room, find its name and the number of times reservations were made for it.
SELECT T2.roomName , count(*) , T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room
medium
2,640
inn_1
[ "reservations", "rooms" ]
Find the names of rooms that have been reserved for more than 60 times.
SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING count(*) > 60
medium
2,641
inn_1
[ "reservations", "rooms" ]
What are the names of rooms whose reservation frequency exceeds 60 times?
SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING count(*) > 60
medium
2,642
inn_1
[ "rooms" ]
Find the name of rooms whose base price is between 120 and 150.
SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150
easy
2,643
inn_1
[ "rooms" ]
Which rooms cost between 120 and 150? Give me the room names.
SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150
easy
2,644
inn_1
[ "reservations", "rooms" ]
Find the name of rooms booked by some customers whose first name contains ROY.
SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%'
hard
2,645
inn_1
[ "reservations", "rooms" ]
What are the name of rooms booked by customers whose first name has "ROY" in part?
SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%'
hard
2,646
local_govt_mdm
[ "cmi_cross_references", "customer_master_index" ]
what are the details of the cmi masters that have the cross reference code 'Tax'?
SELECT T1.cmi_details FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T2.source_system_code = 'Tax'
medium
2,647
local_govt_mdm
[ "cmi_cross_references", "council_tax" ]
What is the cmi cross reference id that is related to at least one council tax entry? List the cross reference id and source system code.
SELECT T1.cmi_cross_ref_id , T1.source_system_code FROM CMI_Cross_References AS T1 JOIN Council_Tax AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T1.cmi_cross_ref_id HAVING count(*) >= 1
medium
2,648
local_govt_mdm
[ "cmi_cross_references", "business_rates" ]
How many business rates are related to each cmi cross reference? List cross reference id, master customer id and the n
SELECT T2.cmi_cross_ref_id , T2.master_customer_id , count(*) FROM Business_Rates AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T2.cmi_cross_ref_id
medium
2,649
local_govt_mdm
[ "cmi_cross_references", "benefits_overpayments" ]
What is the tax source system code related to the benefits and overpayments? List the code and the benifit id, order by benifit id.
SELECT T1.source_system_code , T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Benefits_Overpayments AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id ORDER BY T2.council_tax_id
medium
2,650
local_govt_mdm
[ "cmi_cross_references", "parking_fines" ]
Wat is the tax source system code and master customer id of the taxes related to each parking fine id?
SELECT T1.source_system_code , T1.master_customer_id , T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Parking_Fines AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id
medium
2,651
local_govt_mdm
[ "cmi_cross_references", "rent_arrears", "customer_master_index" ]
What are the renting arrears tax ids related to the customer master index whose detail is not 'Schmidt, Kertzmann and Lubowitz'?
SELECT T1.council_tax_id FROM Rent_Arrears AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id JOIN Customer_Master_Index AS T3 ON T3.master_customer_id = T2.master_customer_id WHERE T3.cmi_details != 'Schmidt , Kertzmann and Lubowitz'
hard
2,652
local_govt_mdm
[ "cmi_cross_references", "electoral_register" ]
What are the register ids of electoral registries that have the cross reference source system code 'Electoral' or 'Tax'?
SELECT T1.electoral_register_id FROM Electoral_Register AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id WHERE T2.source_system_code = 'Electoral' OR T2.source_system_code = 'Tax'
hard
2,653
local_govt_mdm
[ "cmi_cross_references" ]
How many different source system code for the cmi cross references are there?
SELECT count(DISTINCT source_system_code) FROM CMI_cross_references
easy
2,654
local_govt_mdm
[ "customer_master_index" ]
List all information about customer master index, and sort them by details in descending order.
SELECT * FROM customer_master_index ORDER BY cmi_details DESC
easy
2,655
local_govt_mdm
[ "parking_fines" ]
List the council tax ids and their related cmi cross references of all the parking fines.
SELECT council_tax_id , cmi_cross_ref_id FROM parking_fines
medium
2,656
local_govt_mdm
[ "rent_arrears" ]
How many council taxes are collected for renting arrears ?
SELECT count(*) FROM rent_arrears
easy
2,657
local_govt_mdm
[ "cmi_cross_references", "customer_master_index" ]
What are the distinct cross reference source system codes which are related to the master customer details 'Gottlieb, Becker and Wyman'?
SELECT DISTINCT T2.source_system_code FROM customer_master_index AS T1 JOIN cmi_cross_references AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T1.cmi_details = 'Gottlieb , Becker and Wyman'
medium
2,658
local_govt_mdm
[ "cmi_cross_references", "parking_fines" ]
Which cmi cross reference id is not related to any parking taxes?
SELECT cmi_cross_ref_id FROM cmi_cross_references EXCEPT SELECT cmi_cross_ref_id FROM parking_fines
hard
2,659
local_govt_mdm
[ "cmi_cross_references" ]
Which distinct source system code includes the substring 'en'?
SELECT DISTINCT source_system_code FROM cmi_cross_references WHERE source_system_code LIKE '%en%'
medium
2,660
party_host
[ "party" ]
How many parties are there?
SELECT count(*) FROM party
easy
2,661
party_host
[ "party" ]
Count the number of parties.
SELECT count(*) FROM party
easy
2,662
party_host
[ "party" ]
List the themes of parties in ascending order of number of hosts.
SELECT Party_Theme FROM party ORDER BY Number_of_hosts ASC
easy
2,663
party_host
[ "party" ]
What are the themes of parties ordered by the number of hosts in ascending manner?
SELECT Party_Theme FROM party ORDER BY Number_of_hosts ASC
easy
2,664
party_host
[ "party" ]
What are the themes and locations of parties?
SELECT Party_Theme , LOCATION FROM party
medium
2,665
party_host
[ "party" ]
Give me the theme and location of each party.
SELECT Party_Theme , LOCATION FROM party
medium
2,666
party_host
[ "party" ]
Show the first year and last year of parties with theme "Spring" or "Teqnology".
SELECT First_year , Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology"
extra
2,667
party_host
[ "party" ]
What are the first year and last year of the parties whose theme is "Spring" or "Teqnology"?
SELECT First_year , Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology"
extra
2,668
party_host
[ "party" ]
What is the average number of hosts for parties?
SELECT avg(Number_of_hosts) FROM party
easy
2,669
party_host
[ "party" ]
Compute the average number of hosts for parties.
SELECT avg(Number_of_hosts) FROM party
easy
2,670
party_host
[ "party" ]
What is the location of the party with the most hosts?
SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1
medium
2,671
party_host
[ "party" ]
Which party had the most hosts? Give me the party location.
SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1
medium
2,672
party_host
[ "host" ]
Show different nationalities along with the number of hosts of each nationality.
SELECT Nationality , COUNT(*) FROM HOST GROUP BY Nationality
medium
2,673
party_host
[ "host" ]
How many hosts does each nationality have? List the nationality and the count.
SELECT Nationality , COUNT(*) FROM HOST GROUP BY Nationality
medium
2,674
party_host
[ "host" ]
Show the most common nationality of hosts.
SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1
hard
2,675
party_host
[ "host" ]
Which nationality has the most hosts?
SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1
hard
2,676
party_host
[ "host" ]
Show the nations that have both hosts older than 45 and hosts younger than 35.
SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35
hard
2,677
party_host
[ "host" ]
Which nations have both hosts of age above 45 and hosts of age below 35?
SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35
hard
2,678
party_host
[ "party", "party_host", "host" ]
Show the themes of parties and the names of the party hosts.
SELECT T3.Party_Theme , T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID
medium
2,679
party_host
[ "party", "party_host", "host" ]
For each party, return its theme and the name of its host.
SELECT T3.Party_Theme , T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID
medium
2,680
party_host
[ "party", "party_host", "host" ]
Show the locations of parties and the names of the party hosts in ascending order of the age of the host.
SELECT T3.Location , T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age
hard
2,681
party_host
[ "party", "party_host", "host" ]
For each party, find its location and the name of its host. Sort the result in ascending order of the age of the host.
SELECT T3.Location , T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age
hard
2,682
party_host
[ "party", "party_host", "host" ]
Show the locations of parties with hosts older than 50.
SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50
hard
2,683
party_host
[ "party", "party_host", "host" ]
Which parties have hosts of age above 50? Give me the party locations.
SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50
hard
2,684
party_host
[ "party", "party_host", "host" ]
Show the host names for parties with number of hosts greater than 20.
SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20
hard
2,685
party_host
[ "party", "party_host", "host" ]
Which parties have more than 20 hosts? Give me the host names for these parties.
SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20
hard
2,686
party_host
[ "host" ]
Show the name and the nationality of the oldest host.
SELECT Name , Nationality FROM HOST ORDER BY Age DESC LIMIT 1
medium
2,687
party_host
[ "host" ]
What are the name and the nationality of the host of the highest age?
SELECT Name , Nationality FROM HOST ORDER BY Age DESC LIMIT 1
medium
2,688
party_host
[ "party_host", "host" ]
List the names of hosts who did not serve as a host of any party in our record.
SELECT Name FROM HOST WHERE Host_ID NOT IN (SELECT Host_ID FROM party_host)
hard
2,689
party_host
[ "party_host", "host" ]
What are the names of hosts who did not host any party in our record?
SELECT Name FROM HOST WHERE Host_ID NOT IN (SELECT Host_ID FROM party_host)
hard
2,690
storm_record
[ "region" ]
How many regions do we have?
SELECT count(*) FROM region
easy
2,691
storm_record
[ "region" ]
Count the number of regions.
SELECT count(*) FROM region
easy
2,692
storm_record
[ "region" ]
Show all region code and region name sorted by the codes.
SELECT region_code , region_name FROM region ORDER BY region_code
medium
2,693
storm_record
[ "region" ]
What are the codes and names for all regions, sorted by codes?
SELECT region_code , region_name FROM region ORDER BY region_code
medium
2,694
storm_record
[ "region" ]
List all region names in alphabetical order.
SELECT region_name FROM region ORDER BY region_name
easy
2,695
storm_record
[ "region" ]
What are the names of the regions in alphabetical order?
SELECT region_name FROM region ORDER BY region_name
easy
2,696
storm_record
[ "region" ]
Show names for all regions except for Denmark.
SELECT region_name FROM region WHERE region_name != 'Denmark'
easy
2,697
storm_record
[ "region" ]
Return the names of all regions other than Denmark.
SELECT region_name FROM region WHERE region_name != 'Denmark'
easy
2,698
storm_record
[ "storm" ]
How many storms had death records?
SELECT count(*) FROM storm WHERE Number_Deaths > 0
easy
2,699
storm_record
[ "storm" ]
Count the number of storms in which at least 1 person died.
SELECT count(*) FROM storm WHERE Number_Deaths > 0
easy