query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
listlengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
1,700 |
epinions_1
|
[
"item",
"review"
] |
Find the titles of items whose rating is higher than the average review rating of all items.
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > (SELECT avg(rating) FROM review)
|
extra
|
1,701 |
epinions_1
|
[
"item",
"review"
] |
Find the titles of items that received any rating below 5.
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
|
medium
|
1,702 |
epinions_1
|
[
"item",
"review"
] |
Find the titles of items that received both a rating higher than 8 and a rating below 5.
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > 8 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
|
extra
|
1,703 |
epinions_1
|
[
"item",
"review"
] |
Find the names of items whose rank is higher than 3 and whose average rating is above 5.
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rank > 3 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id HAVING avg(T2.rating) > 5
|
extra
|
1,704 |
epinions_1
|
[
"item",
"review"
] |
Find the name of the item with the lowest average rating.
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) LIMIT 1
|
extra
|
1,705 |
epinions_1
|
[
"item"
] |
List the titles of all items in alphabetic order .
|
SELECT title FROM item ORDER BY title
|
easy
|
1,706 |
epinions_1
|
[
"review",
"useracct"
] |
Find the name of the user who gives the most reviews.
|
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
1,707 |
epinions_1
|
[
"item",
"review"
] |
Find the name and id of the item with the highest average rating.
|
SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) DESC LIMIT 1
|
extra
|
1,708 |
epinions_1
|
[
"item",
"review"
] |
Find the name and id of the good with the highest average rank.
|
SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rank) DESC LIMIT 1
|
extra
|
1,709 |
epinions_1
|
[
"review",
"useracct"
] |
For each user, return the name and the average rating of reviews given by them.
|
SELECT T1.name , avg(T2.rating) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
|
medium
|
1,710 |
epinions_1
|
[
"review",
"useracct"
] |
For each user, find their name and the number of reviews written by them.
|
SELECT T1.name , count(*) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
|
medium
|
1,711 |
epinions_1
|
[
"review",
"useracct"
] |
Find the name of the user who gave the highest rating.
|
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id ORDER BY T2.rating DESC LIMIT 1
|
hard
|
1,712 |
epinions_1
|
[
"trust",
"useracct"
] |
Find the name of the source user with the highest average trust score.
|
SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.source_u_id GROUP BY T2.source_u_id ORDER BY avg(trust) DESC LIMIT 1
|
extra
|
1,713 |
epinions_1
|
[
"trust",
"useracct"
] |
Find each target user's name and average trust score.
|
SELECT T1.name , avg(trust) FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id GROUP BY T2.target_u_id
|
medium
|
1,714 |
epinions_1
|
[
"trust",
"useracct"
] |
Find the name of the target user with the lowest trust score.
|
SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id ORDER BY trust LIMIT 1
|
hard
|
1,715 |
epinions_1
|
[
"item",
"review"
] |
Find the names of the items that did not receive any review.
|
SELECT title FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
|
hard
|
1,716 |
epinions_1
|
[
"useracct",
"review"
] |
Find the names of users who did not leave any review.
|
SELECT name FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
|
hard
|
1,717 |
epinions_1
|
[
"useracct",
"review"
] |
Find the number of users who did not write any review.
|
SELECT count(*) FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
|
extra
|
1,718 |
epinions_1
|
[
"item",
"review"
] |
Find the number of items without any review.
|
SELECT count(*) FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
|
extra
|
1,719 |
riding_club
|
[
"player"
] |
How many players are there?
|
SELECT count(*) FROM player
|
easy
|
1,720 |
riding_club
|
[
"player"
] |
List the names of players in ascending order of votes.
|
SELECT Player_name FROM player ORDER BY Votes ASC
|
easy
|
1,721 |
riding_club
|
[
"player"
] |
What are the gender and occupation of players?
|
SELECT Gender , Occupation FROM player
|
medium
|
1,722 |
riding_club
|
[
"player"
] |
List the name and residence for players whose occupation is not "Researcher".
|
SELECT Player_name , residence FROM player WHERE Occupation != "Researcher"
|
medium
|
1,723 |
riding_club
|
[
"player"
] |
Show the names of sponsors of players whose residence is either "Brandon" or "Birtle".
|
SELECT Sponsor_name FROM player WHERE Residence = "Brandon" OR Residence = "Birtle"
|
medium
|
1,724 |
riding_club
|
[
"player"
] |
What is the name of the player with the largest number of votes?
|
SELECT Player_name FROM player ORDER BY Votes DESC LIMIT 1
|
medium
|
1,725 |
riding_club
|
[
"player"
] |
Show different occupations along with the number of players in each occupation.
|
SELECT Occupation , COUNT(*) FROM player GROUP BY Occupation
|
medium
|
1,726 |
riding_club
|
[
"player"
] |
Please show the most common occupation of players.
|
SELECT Occupation FROM player GROUP BY Occupation ORDER BY COUNT(*) DESC LIMIT 1
|
hard
|
1,727 |
riding_club
|
[
"player"
] |
Show the residences that have at least two players.
|
SELECT Residence FROM player GROUP BY Residence HAVING COUNT(*) >= 2
|
easy
|
1,728 |
riding_club
|
[
"player_coach",
"coach",
"player"
] |
Show the names of players and names of their coaches.
|
SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID
|
medium
|
1,729 |
riding_club
|
[
"player_coach",
"coach",
"player"
] |
Show the names of players coached by the rank 1 coach.
|
SELECT T3.Player_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T2.Rank = 1
|
hard
|
1,730 |
riding_club
|
[
"player_coach",
"coach",
"player"
] |
Show the names and genders of players with a coach starting after 2011.
|
SELECT T3.Player_name , T3.gender FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T1.Starting_year > 2011
|
hard
|
1,731 |
riding_club
|
[
"player_coach",
"coach",
"player"
] |
Show the names of players and names of their coaches in descending order of the votes of players.
|
SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID ORDER BY T3.Votes DESC
|
hard
|
1,732 |
riding_club
|
[
"player_coach",
"player"
] |
List the names of players that do not have coaches.
|
SELECT Player_name FROM player WHERE Player_ID NOT IN (SELECT Player_ID FROM player_coach)
|
hard
|
1,733 |
riding_club
|
[
"player"
] |
Show the residences that have both a player of gender "M" and a player of gender "F".
|
SELECT Residence FROM player WHERE gender = "M" INTERSECT SELECT Residence FROM player WHERE gender = "F"
|
hard
|
1,734 |
riding_club
|
[
"coach",
"club"
] |
How many coaches does each club has? List the club id, name and the number of coaches.
|
SELECT T1.club_id , T1.club_name, count(*) FROM club AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id
|
medium
|
1,735 |
riding_club
|
[
"match_result",
"coach"
] |
How many gold medals has the club with the most coaches won?
|
SELECT T1.club_id , T1.gold FROM match_result AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
1,736 |
gymnast
|
[
"gymnast"
] |
How many gymnasts are there?
|
SELECT count(*) FROM gymnast
|
easy
|
1,737 |
gymnast
|
[
"gymnast"
] |
Count the number of gymnasts.
|
SELECT count(*) FROM gymnast
|
easy
|
1,738 |
gymnast
|
[
"gymnast"
] |
List the total points of gymnasts in descending order.
|
SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
|
easy
|
1,739 |
gymnast
|
[
"gymnast"
] |
What are the total points for all gymnasts, ordered by total points descending?
|
SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
|
easy
|
1,740 |
gymnast
|
[
"gymnast"
] |
List the total points of gymnasts in descending order of floor exercise points.
|
SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
|
easy
|
1,741 |
gymnast
|
[
"gymnast"
] |
What are the total points of gymnasts, ordered by their floor exercise points descending?
|
SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
|
easy
|
1,742 |
gymnast
|
[
"gymnast"
] |
What is the average horizontal bar points for all gymnasts?
|
SELECT avg(Horizontal_Bar_Points) FROM gymnast
|
easy
|
1,743 |
gymnast
|
[
"gymnast"
] |
Return the average horizontal bar points across all gymnasts.
|
SELECT avg(Horizontal_Bar_Points) FROM gymnast
|
easy
|
1,744 |
gymnast
|
[
"people"
] |
What are the names of people in ascending alphabetical order?
|
SELECT Name FROM People ORDER BY Name ASC
|
easy
|
1,745 |
gymnast
|
[
"people"
] |
Return the names of people, ordered alphabetically.
|
SELECT Name FROM People ORDER BY Name ASC
|
easy
|
1,746 |
gymnast
|
[
"gymnast",
"people"
] |
What are the names of gymnasts?
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
easy
|
1,747 |
gymnast
|
[
"gymnast",
"people"
] |
Return the names of the gymnasts.
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
easy
|
1,748 |
gymnast
|
[
"gymnast",
"people"
] |
What are the names of gymnasts whose hometown is not "Santo Domingo"?
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "Santo Domingo"
|
medium
|
1,749 |
gymnast
|
[
"gymnast",
"people"
] |
Return the names of gymnasts who did not grow up in Santo Domingo.
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "Santo Domingo"
|
medium
|
1,750 |
gymnast
|
[
"people"
] |
What is the age of the tallest person?
|
SELECT Age FROM people ORDER BY Height DESC LIMIT 1
|
medium
|
1,751 |
gymnast
|
[
"people"
] |
Return the age of the person with the greatest height.
|
SELECT Age FROM people ORDER BY Height DESC LIMIT 1
|
medium
|
1,752 |
gymnast
|
[
"people"
] |
List the names of the top 5 oldest people.
|
SELECT Name FROM People ORDER BY Age DESC LIMIT 5
|
medium
|
1,753 |
gymnast
|
[
"people"
] |
What are the names of the five oldest people?
|
SELECT Name FROM People ORDER BY Age DESC LIMIT 5
|
medium
|
1,754 |
gymnast
|
[
"gymnast",
"people"
] |
What is the total point count of the youngest gymnast?
|
SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1
|
hard
|
1,755 |
gymnast
|
[
"gymnast",
"people"
] |
Return the total points of the gymnast with the lowest age.
|
SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1
|
hard
|
1,756 |
gymnast
|
[
"gymnast",
"people"
] |
What is the average age of all gymnasts?
|
SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
easy
|
1,757 |
gymnast
|
[
"gymnast",
"people"
] |
Return the average age across all gymnasts.
|
SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
easy
|
1,758 |
gymnast
|
[
"gymnast",
"people"
] |
What are the distinct hometowns of gymnasts with total points more than 57.5?
|
SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5
|
medium
|
1,759 |
gymnast
|
[
"gymnast",
"people"
] |
Give the different hometowns of gymnasts that have a total point score of above 57.5.
|
SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5
|
medium
|
1,760 |
gymnast
|
[
"gymnast",
"people"
] |
What are the hometowns of gymnasts and the corresponding number of gymnasts?
|
SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown
|
medium
|
1,761 |
gymnast
|
[
"gymnast",
"people"
] |
How many gymnasts are from each hometown?
|
SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown
|
medium
|
1,762 |
gymnast
|
[
"gymnast",
"people"
] |
What is the most common hometown of gymnasts?
|
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
|
extra
|
1,763 |
gymnast
|
[
"gymnast",
"people"
] |
Return the hometown that is most common among gymnasts.
|
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
|
extra
|
1,764 |
gymnast
|
[
"gymnast",
"people"
] |
What are the hometowns that are shared by at least two gymnasts?
|
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2
|
medium
|
1,765 |
gymnast
|
[
"gymnast",
"people"
] |
Give the hometowns from which two or more gymnasts are from.
|
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2
|
medium
|
1,766 |
gymnast
|
[
"gymnast",
"people"
] |
List the names of gymnasts in ascending order by their heights.
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC
|
medium
|
1,767 |
gymnast
|
[
"gymnast",
"people"
] |
What are the names of gymnasts, ordered by their heights ascending?
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC
|
medium
|
1,768 |
gymnast
|
[
"gymnast",
"people"
] |
List the distinct hometowns that are not associated with any gymnast.
|
SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
hard
|
1,769 |
gymnast
|
[
"gymnast",
"people"
] |
From which hometowns did no gymnasts come from?
|
SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
hard
|
1,770 |
gymnast
|
[
"people"
] |
Show the hometowns shared by people older than 23 and younger than 20.
|
SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20
|
hard
|
1,771 |
gymnast
|
[
"people"
] |
From which hometowns did both people older than 23 and younger than 20 come from?
|
SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20
|
hard
|
1,772 |
gymnast
|
[
"people"
] |
How many distinct hometowns did these people have?
|
SELECT count(DISTINCT Hometown) FROM people
|
easy
|
1,773 |
gymnast
|
[
"people"
] |
Count the number of different hometowns of these people.
|
SELECT count(DISTINCT Hometown) FROM people
|
easy
|
1,774 |
gymnast
|
[
"gymnast",
"people"
] |
Show the ages of gymnasts in descending order of total points.
|
SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC
|
medium
|
1,775 |
gymnast
|
[
"gymnast",
"people"
] |
What are the ages of the gymnasts, ordered descending by their total points?
|
SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC
|
medium
|
1,776 |
small_bank_1
|
[
"savings",
"accounts"
] |
Find the total savings balance of all accounts except the account with name ‘Brown’.
|
SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != 'Brown'
|
medium
|
1,777 |
small_bank_1
|
[
"savings",
"accounts"
] |
What is the total balance of savings accounts not belonging to someone with the name Brown?
|
SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != 'Brown'
|
medium
|
1,778 |
small_bank_1
|
[
"accounts"
] |
How many accounts are there in total?
|
SELECT count(*) FROM accounts
|
easy
|
1,779 |
small_bank_1
|
[
"accounts"
] |
Count the number of accounts.
|
SELECT count(*) FROM accounts
|
easy
|
1,780 |
small_bank_1
|
[
"checking"
] |
What is the total checking balance in all accounts?
|
SELECT sum(balance) FROM checking
|
easy
|
1,781 |
small_bank_1
|
[
"checking"
] |
Find the total balance across checking accounts.
|
SELECT sum(balance) FROM checking
|
easy
|
1,782 |
small_bank_1
|
[
"checking"
] |
Find the average checking balance.
|
SELECT avg(balance) FROM checking
|
easy
|
1,783 |
small_bank_1
|
[
"checking"
] |
What is the average balance in checking accounts?
|
SELECT avg(balance) FROM checking
|
easy
|
1,784 |
small_bank_1
|
[
"savings"
] |
How many accounts have a savings balance above the average savings balance?
|
SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings)
|
hard
|
1,785 |
small_bank_1
|
[
"savings"
] |
Find the number of accounts with a savings balance that is higher than the average savings balance.
|
SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings)
|
hard
|
1,786 |
small_bank_1
|
[
"checking",
"accounts"
] |
Find the name and id of accounts whose checking balance is below the maximum checking balance.
|
SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking)
|
extra
|
1,787 |
small_bank_1
|
[
"checking",
"accounts"
] |
What are the customer id and name corresponding to accounts with a checking balance less than the largest checking balance?
|
SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking)
|
extra
|
1,788 |
small_bank_1
|
[
"checking",
"accounts"
] |
What is the checking balance of the account whose owner’s name contains the substring ‘ee’?
|
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '%ee%'
|
hard
|
1,789 |
small_bank_1
|
[
"checking",
"accounts"
] |
Find the balance of the checking account belonging to an owner whose name contains 'ee'.
|
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '%ee%'
|
hard
|
1,790 |
small_bank_1
|
[
"checking",
"savings",
"accounts"
] |
Find the checking balance and saving balance in the Brown’s account.
|
SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = 'Brown'
|
hard
|
1,791 |
small_bank_1
|
[
"checking",
"savings",
"accounts"
] |
What are the checking and savings balances in accounts belonging to Brown?
|
SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = 'Brown'
|
hard
|
1,792 |
small_bank_1
|
[
"checking",
"savings",
"accounts"
] |
Find the names of accounts whose checking balance is above the average checking balance, but savings balance is below the average savings balance.
|
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings)
|
extra
|
1,793 |
small_bank_1
|
[
"checking",
"savings",
"accounts"
] |
What are the names of accounts with checking balances greater than the average checking balance and savings balances below the average savings balance?
|
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings)
|
extra
|
1,794 |
small_bank_1
|
[
"checking",
"savings",
"accounts"
] |
Find the checking balance of the accounts whose savings balance is higher than the average savings balance.
|
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings))
|
extra
|
1,795 |
small_bank_1
|
[
"checking",
"savings",
"accounts"
] |
What are the balances of checking accounts belonging to people with savings balances greater than the average savings balance?
|
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings))
|
extra
|
1,796 |
small_bank_1
|
[
"accounts"
] |
List all customers’ names in the alphabetical order.
|
SELECT name FROM accounts ORDER BY name
|
easy
|
1,797 |
small_bank_1
|
[
"accounts"
] |
What are the names of all the customers in alphabetical order?
|
SELECT name FROM accounts ORDER BY name
|
easy
|
1,798 |
small_bank_1
|
[
"checking",
"savings",
"accounts"
] |
Find the name of account that has the lowest total checking and saving balance.
|
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1
|
extra
|
1,799 |
small_bank_1
|
[
"checking",
"savings",
"accounts"
] |
What is the name corresponding to the accoung with the lowest sum of checking and savings balances?
|
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1
|
extra
|
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