query_id
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1.03k
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stringclasses 20
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sequencelengths 1
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stringlengths 18
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| answer
stringlengths 20
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| difficulty
stringclasses 4
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|---|---|---|---|---|---|
800 | world_1 | [
"country"
] | What are the names and areas of countries with the top 5 largest area? | SELECT Name , SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5 | medium |
801 | world_1 | [
"country"
] | Return the names and surface areas of the 5 largest countries. | SELECT Name , SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5 | medium |
802 | world_1 | [
"country"
] | What are names of countries with the top 3 largest population? | SELECT Name FROM country ORDER BY Population DESC LIMIT 3 | medium |
803 | world_1 | [
"country"
] | Return the names of the 3 most populated countries. | SELECT Name FROM country ORDER BY Population DESC LIMIT 3 | medium |
804 | world_1 | [
"country"
] | What are the names of the nations with the 3 lowest populations? | SELECT Name FROM country ORDER BY Population ASC LIMIT 3 | medium |
805 | world_1 | [
"country"
] | Return the names of the 3 countries with the fewest people. | SELECT Name FROM country ORDER BY Population ASC LIMIT 3 | medium |
806 | world_1 | [
"country"
] | how many countries are in Asia? | SELECT count(*) FROM country WHERE continent = "Asia" | easy |
807 | world_1 | [
"country"
] | Count the number of countries in Asia. | SELECT count(*) FROM country WHERE continent = "Asia" | easy |
808 | world_1 | [
"country"
] | What are the names of the countries that are in the continent of Europe and have a population of 80000? | SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000" | medium |
809 | world_1 | [
"country"
] | Give the names of countries that are in Europe and have a population equal to 80000. | SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000" | medium |
810 | world_1 | [
"country"
] | What is the total population and average area of countries in the continent of North America whose area is bigger than 3000 ? | select sum(population) , avg(surfacearea) from country where continent = "north america" and surfacearea > 3000 | hard |
811 | world_1 | [
"country"
] | Give the total population and average surface area corresponding to countries in North America that have a surface area greater than 3000 . | select sum(population) , avg(surfacearea) from country where continent = "north america" and surfacearea > 3000 | hard |
812 | world_1 | [
"city"
] | What are the cities whose population is between 160000 and 900000? | SELECT name FROM city WHERE Population BETWEEN 160000 AND 900000 | easy |
813 | world_1 | [
"city"
] | Return the names of cities that have a population between 160000 and 900000 . | select name from city where population between 160000 and 900000 | easy |
814 | world_1 | [
"countrylanguage"
] | Which language is spoken by the largest number of countries? | SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY count(*) DESC LIMIT 1 | hard |
815 | world_1 | [
"countrylanguage"
] | Give the language that is spoken in the most countries. | SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY count(*) DESC LIMIT 1 | hard |
816 | world_1 | [
"countrylanguage"
] | What is the language spoken by the largest percentage of people in each country? | SELECT LANGUAGE , CountryCode , max(Percentage) FROM countrylanguage GROUP BY CountryCode | medium |
817 | world_1 | [
"countrylanguage"
] | What are the country codes of the different countries, and what are the languages spoken by the greatest percentage of people for each? | SELECT LANGUAGE , CountryCode , max(Percentage) FROM countrylanguage GROUP BY CountryCode | medium |
818 | world_1 | [
"countrylanguage"
] | What is the total number of countries where Spanish is spoken by the largest percentage of people? | SELECT count(*) , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode | extra |
819 | world_1 | [
"countrylanguage"
] | Count the number of countries for which Spanish is the predominantly spoken language. | SELECT count(*) , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode | extra |
820 | world_1 | [
"countrylanguage"
] | What are the codes of countries where Spanish is spoken by the largest percentage of people? | SELECT CountryCode , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode | medium |
821 | world_1 | [
"countrylanguage"
] | Return the codes of countries for which Spanish is the predominantly spoken language. | SELECT CountryCode , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode | medium |
822 | orchestra | [
"conductor"
] | How many conductors are there? | SELECT count(*) FROM conductor | easy |
823 | orchestra | [
"conductor"
] | Count the number of conductors. | SELECT count(*) FROM conductor | easy |
824 | orchestra | [
"conductor"
] | List the names of conductors in ascending order of age. | SELECT Name FROM conductor ORDER BY Age ASC | easy |
825 | orchestra | [
"conductor"
] | What are the names of conductors, ordered by age? | SELECT Name FROM conductor ORDER BY Age ASC | easy |
826 | orchestra | [
"conductor"
] | What are the names of conductors whose nationalities are not "USA"? | SELECT Name FROM conductor WHERE Nationality != 'USA' | easy |
827 | orchestra | [
"conductor"
] | Return the names of conductors that do not have the nationality "USA". | SELECT Name FROM conductor WHERE Nationality != 'USA' | easy |
828 | orchestra | [
"orchestra"
] | What are the record companies of orchestras in descending order of years in which they were founded? | SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC | easy |
829 | orchestra | [
"orchestra"
] | Return the record companies of orchestras, sorted descending by the years in which they were founded. | SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC | easy |
830 | orchestra | [
"SHOW"
] | What is the average attendance of shows? | SELECT avg(Attendance) FROM SHOW | easy |
831 | orchestra | [
"SHOW"
] | Return the average attendance across all shows. | SELECT avg(Attendance) FROM SHOW | easy |
832 | orchestra | [
"performance"
] | What are the maximum and minimum share of performances whose type is not "Live final". | SELECT max(SHARE) , min(SHARE) FROM performance WHERE TYPE != "Live final" | medium |
833 | orchestra | [
"performance"
] | Return the maximum and minimum shares for performances that do not have the type "Live final". | SELECT max(SHARE) , min(SHARE) FROM performance WHERE TYPE != "Live final" | medium |
834 | orchestra | [
"conductor"
] | How many different nationalities do conductors have? | SELECT count(DISTINCT Nationality) FROM conductor | easy |
835 | orchestra | [
"conductor"
] | Count the number of different nationalities of conductors. | SELECT count(DISTINCT Nationality) FROM conductor | easy |
836 | orchestra | [
"conductor"
] | List names of conductors in descending order of years of work. | SELECT Name FROM conductor ORDER BY Year_of_Work DESC | easy |
837 | orchestra | [
"conductor"
] | What are the names of conductors, sorted descending by the number of years they have worked? | SELECT Name FROM conductor ORDER BY Year_of_Work DESC | easy |
838 | orchestra | [
"conductor"
] | List the name of the conductor with the most years of work. | SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1 | medium |
839 | orchestra | [
"conductor"
] | What is the name of the conductor who has worked the greatest number of years? | SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1 | medium |
840 | orchestra | [
"conductor",
"orchestra"
] | Show the names of conductors and the orchestras they have conducted. | SELECT T1.Name , T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID | medium |
841 | orchestra | [
"conductor",
"orchestra"
] | What are the names of conductors as well as the corresonding orchestras that they have conducted? | SELECT T1.Name , T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID | medium |
842 | orchestra | [
"conductor",
"orchestra"
] | Show the names of conductors that have conducted more than one orchestras. | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1 | medium |
843 | orchestra | [
"conductor",
"orchestra"
] | What are the names of conductors who have conducted at more than one orchestra? | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1 | medium |
844 | orchestra | [
"conductor",
"orchestra"
] | Show the name of the conductor that has conducted the most number of orchestras. | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1 | extra |
845 | orchestra | [
"conductor",
"orchestra"
] | What is the name of the conductor who has conducted the most orchestras? | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1 | extra |
846 | orchestra | [
"conductor",
"orchestra"
] | Please show the name of the conductor that has conducted orchestras founded after 2008. | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008 | medium |
847 | orchestra | [
"conductor",
"orchestra"
] | What are the names of conductors who have conducted orchestras founded after the year 2008? | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008 | medium |
848 | orchestra | [
"orchestra"
] | Please show the different record companies and the corresponding number of orchestras. | SELECT Record_Company , COUNT(*) FROM orchestra GROUP BY Record_Company | medium |
849 | orchestra | [
"orchestra"
] | How many orchestras does each record company manage? | SELECT Record_Company , COUNT(*) FROM orchestra GROUP BY Record_Company | medium |
850 | orchestra | [
"orchestra"
] | Please show the record formats of orchestras in ascending order of count. | SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC | medium |
851 | orchestra | [
"orchestra"
] | What are the major record formats of orchestras, sorted by their frequency? | SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC | medium |
852 | orchestra | [
"orchestra"
] | List the record company shared by the most number of orchestras. | SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1 | hard |
853 | orchestra | [
"orchestra"
] | What is the record company used by the greatest number of orchestras? | SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1 | hard |
854 | orchestra | [
"orchestra",
"performance"
] | List the names of orchestras that have no performance. | SELECT Orchestra FROM orchestra WHERE Orchestra_ID NOT IN (SELECT Orchestra_ID FROM performance) | hard |
855 | orchestra | [
"orchestra",
"performance"
] | What are the orchestras that do not have any performances? | SELECT Orchestra FROM orchestra WHERE Orchestra_ID NOT IN (SELECT Orchestra_ID FROM performance) | hard |
856 | orchestra | [
"orchestra"
] | Show the record companies shared by orchestras founded before 2003 and after 2003. | SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003 | hard |
857 | orchestra | [
"orchestra"
] | What are the record companies that are used by both orchestras founded before 2003 and those founded after 2003? | SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003 | hard |
858 | orchestra | [
"orchestra"
] | Find the number of orchestras whose record format is "CD" or "DVD". | SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD" | medium |
859 | orchestra | [
"orchestra"
] | Count the number of orchestras that have CD or DVD as their record format. | SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD" | medium |
860 | orchestra | [
"orchestra",
"performance"
] | Show the years in which orchestras that have given more than one performance are founded. | SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1 | medium |
861 | orchestra | [
"orchestra",
"performance"
] | What are years of founding for orchestras that have had more than a single performance? | SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1 | medium |
862 | network_1 | [
"Highschooler"
] | How many high schoolers are there? | SELECT count(*) FROM Highschooler | easy |
863 | network_1 | [
"Highschooler"
] | Count the number of high schoolers. | SELECT count(*) FROM Highschooler | easy |
864 | network_1 | [
"Highschooler"
] | Show the names and grades of each high schooler. | SELECT name , grade FROM Highschooler | medium |
865 | network_1 | [
"Highschooler"
] | What are the names and grades for each high schooler? | SELECT name , grade FROM Highschooler | medium |
866 | network_1 | [
"Highschooler"
] | Show all the grades of the high schoolers. | SELECT grade FROM Highschooler | easy |
867 | network_1 | [
"Highschooler"
] | What is the grade of each high schooler? | SELECT grade FROM Highschooler | easy |
868 | network_1 | [
"Highschooler"
] | What grade is Kyle in? | SELECT grade FROM Highschooler WHERE name = "Kyle" | easy |
869 | network_1 | [
"Highschooler"
] | Return the grade for the high schooler named Kyle. | SELECT grade FROM Highschooler WHERE name = "Kyle" | easy |
870 | network_1 | [
"Highschooler"
] | Show the names of all high schoolers in grade 10. | SELECT name FROM Highschooler WHERE grade = 10 | easy |
871 | network_1 | [
"Highschooler"
] | What are the names of all high schoolers in grade 10? | SELECT name FROM Highschooler WHERE grade = 10 | easy |
872 | network_1 | [
"Highschooler"
] | Show the ID of the high schooler named Kyle. | SELECT ID FROM Highschooler WHERE name = "Kyle" | easy |
873 | network_1 | [
"Highschooler"
] | What is Kyle's id? | SELECT ID FROM Highschooler WHERE name = "Kyle" | easy |
874 | network_1 | [
"Highschooler"
] | How many high schoolers are there in grade 9 or 10? | SELECT count(*) FROM Highschooler WHERE grade = 9 OR grade = 10 | medium |
875 | network_1 | [
"Highschooler"
] | Count the number of high schoolers in grades 9 or 10. | SELECT count(*) FROM Highschooler WHERE grade = 9 OR grade = 10 | medium |
876 | network_1 | [
"Highschooler"
] | Show the number of high schoolers for each grade. | SELECT grade , count(*) FROM Highschooler GROUP BY grade | medium |
877 | network_1 | [
"Highschooler"
] | How many high schoolers are in each grade? | SELECT grade , count(*) FROM Highschooler GROUP BY grade | medium |
878 | network_1 | [
"Highschooler"
] | Which grade has the most high schoolers? | SELECT grade FROM Highschooler GROUP BY grade ORDER BY count(*) DESC LIMIT 1 | hard |
879 | network_1 | [
"Highschooler"
] | Return the grade that has the greatest number of high schoolers. | SELECT grade FROM Highschooler GROUP BY grade ORDER BY count(*) DESC LIMIT 1 | hard |
880 | network_1 | [
"Highschooler"
] | Show me all grades that have at least 4 students. | SELECT grade FROM Highschooler GROUP BY grade HAVING count(*) >= 4 | easy |
881 | network_1 | [
"Highschooler"
] | Which grades have 4 or more high schoolers? | SELECT grade FROM Highschooler GROUP BY grade HAVING count(*) >= 4 | easy |
882 | network_1 | [
"Friend"
] | Show the student IDs and numbers of friends corresponding to each. | SELECT student_id , count(*) FROM Friend GROUP BY student_id | medium |
883 | network_1 | [
"Friend"
] | How many friends does each student have? | SELECT student_id , count(*) FROM Friend GROUP BY student_id | medium |
884 | network_1 | [
"Friend",
"Highschooler"
] | Show the names of high school students and their corresponding number of friends. | SELECT T2.name , count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id | medium |
885 | network_1 | [
"Friend",
"Highschooler"
] | What are the names of the high schoolers and how many friends does each have? | SELECT T2.name , count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id | medium |
886 | network_1 | [
"Friend",
"Highschooler"
] | What is the name of the high schooler who has the greatest number of friends? | SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1 | extra |
887 | network_1 | [
"Friend",
"Highschooler"
] | Return the name of the high school student with the most friends. | SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1 | extra |
888 | network_1 | [
"Friend",
"Highschooler"
] | Show the names of high schoolers who have at least 3 friends. | SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 3 | medium |
889 | network_1 | [
"Friend",
"Highschooler"
] | What are the names of high schoolers who have 3 or more friends? | SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 3 | medium |
890 | network_1 | [
"Friend",
"Highschooler"
] | Show the names of all of the high schooler Kyle's friends. | SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle" | hard |
891 | network_1 | [
"Friend",
"Highschooler"
] | Return the names of friends of the high school student Kyle. | SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle" | hard |
892 | network_1 | [
"Friend",
"Highschooler"
] | How many friends does the high school student Kyle have? | SELECT count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" | medium |
893 | network_1 | [
"Friend",
"Highschooler"
] | Count the number of friends Kyle has. | SELECT count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" | medium |
894 | network_1 | [
"Friend",
"Highschooler"
] | Show ids of all students who do not have any friends. | SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend | hard |
895 | network_1 | [
"Friend",
"Highschooler"
] | What are the ids of high school students who do not have friends? | SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend | hard |
896 | network_1 | [
"Friend",
"Highschooler"
] | Show names of all high school students who do not have any friends. | SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id | hard |
897 | network_1 | [
"Friend",
"Highschooler"
] | What are the names of students who have no friends? | SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id | hard |
898 | network_1 | [
"Likes",
"Friend"
] | Show the ids of high schoolers who have friends and are also liked by someone else. | SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes | hard |
899 | network_1 | [
"Likes",
"Friend"
] | What are the ids of students who both have friends and are liked? | SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes | hard |
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