query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
sequencelengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
6,600 | train_station | [
"station"
] | Show the names and main services for train stations that have the top three total number of passengers. | SELECT name , main_services FROM station ORDER BY total_passengers DESC LIMIT 3 | medium |
6,601 | train_station | [
"station"
] | What is the average and maximum number of total passengers for train stations in London or Glasgow? | SELECT avg(total_passengers) , max(total_passengers) FROM station WHERE LOCATION = 'London' OR LOCATION = 'Glasgow' | hard |
6,602 | train_station | [
"station"
] | Show all locations and the total number of platforms and passengers for all train stations in each location. | SELECT LOCATION , sum(number_of_platforms) , sum(total_passengers) FROM station GROUP BY LOCATION | medium |
6,603 | train_station | [
"station"
] | Show all locations that have train stations with at least 15 platforms and train stations with more than 25 total passengers. | SELECT DISTINCT LOCATION FROM station WHERE number_of_platforms >= 15 AND total_passengers > 25 | medium |
6,604 | train_station | [
"station"
] | Show all locations which don't have a train station with at least 15 platforms. | SELECT LOCATION FROM station EXCEPT SELECT LOCATION FROM station WHERE number_of_platforms >= 15 | hard |
6,605 | train_station | [
"station"
] | Show the location with most number of train stations. | SELECT LOCATION FROM station GROUP BY LOCATION ORDER BY count(*) DESC LIMIT 1 | hard |
6,606 | train_station | [
"train"
] | Show the name, time, and service for all trains. | SELECT name , TIME , service FROM train | medium |
6,607 | train_station | [
"train"
] | Show the number of trains | SELECT count(*) FROM train | easy |
6,608 | train_station | [
"train"
] | Show the name and service for all trains in order by time. | SELECT name , service FROM train ORDER BY TIME | medium |
6,609 | train_station | [
"station",
"train_station"
] | Show the station name and number of trains in each station. | SELECT T2.name , count(*) FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id | medium |
6,610 | train_station | [
"train",
"station",
"train_station"
] | show the train name and station name for each train. | SELECT T2.name , T3.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id | medium |
6,611 | train_station | [
"train",
"station",
"train_station"
] | Show all train names and times in stations in London in descending order by train time. | SELECT T3.name , T3.time FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T2.location = 'London' ORDER BY T3.time DESC | extra |
6,612 | train_station | [
"station",
"train_station"
] | Show the station name with greatest number of trains. | SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id ORDER BY count(*) DESC LIMIT 1 | extra |
6,613 | train_station | [
"station",
"train_station"
] | Show the station name with at least two trains. | SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id HAVING count(*) >= 2 | medium |
6,614 | train_station | [
"station"
] | Show all locations with only 1 station. | SELECT LOCATION FROM station GROUP BY LOCATION HAVING count(*) = 1 | easy |
6,615 | train_station | [
"station",
"train_station"
] | Show station names without any trains. | SELECT name FROM station WHERE station_id NOT IN (SELECT station_id FROM train_station) | hard |
6,616 | train_station | [
"train",
"station",
"train_station"
] | What are the names of the stations which serve both "Ananthapuri Express" and "Guruvayur Express" trains? | SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Ananthapuri Express" INTERSECT SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Guruvayur Express" | extra |
6,617 | train_station | [
"train",
"station",
"train_station"
] | Find the names of the trains that do not pass any station located in London. | SELECT T2.name FROM train_station AS T1 JOIN train AS T2 ON T1.train_id = T2.train_id WHERE T1.station_id NOT IN (SELECT T4.station_id FROM train_station AS T3 JOIN station AS T4 ON T3.station_id = T4.station_id WHERE t4.location = "London") | extra |
6,618 | train_station | [
"station"
] | List the names and locations of all stations ordered by their yearly entry exit and interchange amounts. | SELECT name , LOCATION FROM station ORDER BY Annual_entry_exit , Annual_interchanges | medium |
6,619 | driving_school | [
"Vehicles"
] | List all vehicle id | SELECT vehicle_id FROM Vehicles; | easy |
6,620 | driving_school | [
"Vehicles"
] | What are the ids of all vehicles? | SELECT vehicle_id FROM Vehicles; | easy |
6,621 | driving_school | [
"Vehicles"
] | How many vehicle in total? | SELECT count(*) FROM Vehicles; | easy |
6,622 | driving_school | [
"Vehicles"
] | How many vehicles exist? | SELECT count(*) FROM Vehicles; | easy |
6,623 | driving_school | [
"Vehicles"
] | Show the detail of vehicle with id 1. | SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1; | easy |
6,624 | driving_school | [
"Vehicles"
] | What are the details of the car with id 1? | SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1; | easy |
6,625 | driving_school | [
"Staff"
] | List the first name middle name and last name of all staff. | SELECT first_name , middle_name , last_name FROM Staff; | medium |
6,626 | driving_school | [
"Staff"
] | What are the first, middle, and last names of all staff? | SELECT first_name , middle_name , last_name FROM Staff; | medium |
6,627 | driving_school | [
"Staff"
] | What is the birthday of the staff member with first name as Janessa and last name as Sawayn? | SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"; | medium |
6,628 | driving_school | [
"Staff"
] | What is the date of birth for the staff member named Janessa Sawayn? | SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"; | medium |
6,629 | driving_school | [
"Staff"
] | When did the staff member with first name as Janessa and last name as Sawayn join the company? | SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"; | medium |
6,630 | driving_school | [
"Staff"
] | When did the staff member named Janessa Sawayn join the company? | SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"; | medium |
6,631 | driving_school | [
"Staff"
] | When did the staff member with first name as Janessa and last name as Sawayn leave the company? | SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"; | medium |
6,632 | driving_school | [
"Staff"
] | When did the staff member Janessa Sawayn leave the company? | SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"; | medium |
6,633 | driving_school | [
"Staff"
] | How many staff have the first name Ludie? | SELECT count(*) FROM Staff WHERE first_name = "Ludie"; | easy |
6,634 | driving_school | [
"Staff"
] | How many employees have a first name of Ludie? | SELECT count(*) FROM Staff WHERE first_name = "Ludie"; | easy |
6,635 | driving_school | [
"Staff"
] | What is the nickname of staff with first name as Janessa and last name as Sawayn? | SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"; | medium |
6,636 | driving_school | [
"Staff"
] | What is the nickname of the employee named Janessa Sawayn? | SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn"; | medium |
6,637 | driving_school | [
"Staff"
] | How many staff in total? | SELECT count(*) FROM Staff; | easy |
6,638 | driving_school | [
"Staff"
] | How many employees are there? | SELECT count(*) FROM Staff; | easy |
6,639 | driving_school | [
"Addresses",
"Staff"
] | Which city does staff with first name as Janessa and last name as Sawayn live? | SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"; | medium |
6,640 | driving_school | [
"Addresses",
"Staff"
] | In what city does Janessa Sawayn live? | SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"; | medium |
6,641 | driving_school | [
"Addresses",
"Staff"
] | Which country and state does staff with first name as Janessa and last name as Sawayn lived? | SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"; | extra |
6,642 | driving_school | [
"Addresses",
"Staff"
] | In which country and state does Janessa Sawayn live? | SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"; | extra |
6,643 | driving_school | [
"Lessons",
"Customers"
] | How long is the total lesson time took by customer with first name as Rylan and last name as Goodwin? | SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin"; | medium |
6,644 | driving_school | [
"Lessons",
"Customers"
] | How long is the total lesson time took by the customer named Rylan Goodwin? | SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin"; | medium |
6,645 | driving_school | [
"Addresses",
"Staff"
] | What is the zip code of staff with first name as Janessa and last name as Sawayn lived? | SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"; | medium |
6,646 | driving_school | [
"Addresses",
"Staff"
] | What is the zip code of the hosue of the employee named Janessa Sawayn? | SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn"; | medium |
6,647 | driving_school | [
"Addresses"
] | How many staff live in state Georgia? | SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia"; | easy |
6,648 | driving_school | [
"Addresses"
] | How many employees live in Georgia? | SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia"; | easy |
6,649 | driving_school | [
"Addresses",
"Staff"
] | Find out the first name and last name of staff lived in city Damianfort. | SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort"; | medium |
6,650 | driving_school | [
"Addresses",
"Staff"
] | What is the first and last name of all employees who live in the city Damianfort? | SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort"; | medium |
6,651 | driving_school | [
"Addresses",
"Staff"
] | Which city lives most of staffs? List the city name and number of staffs. | SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1; | extra |
6,652 | driving_school | [
"Addresses",
"Staff"
] | In which city do the most employees live and how many of them live there? | SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1; | extra |
6,653 | driving_school | [
"Addresses",
"Staff"
] | List the states which have between 2 to 4 staffs living there. | SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4; | medium |
6,654 | driving_school | [
"Addresses",
"Staff"
] | What are the names of the states that have 2 to 4 employees living there? | SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4; | medium |
6,655 | driving_school | [
"Customers"
] | List the first name and last name of all customers. | SELECT first_name , last_name FROM Customers; | medium |
6,656 | driving_school | [
"Customers"
] | What are the first and last names for all customers? | SELECT first_name , last_name FROM Customers; | medium |
6,657 | driving_school | [
"Customers"
] | List email address and birthday of customer whose first name as Carole. | SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole" | medium |
6,658 | driving_school | [
"Customers"
] | What are the email addresses and date of births for all customers who have a first name of Carole? | SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole" | medium |
6,659 | driving_school | [
"Customers"
] | List phone number and email address of customer with more than 2000 outstanding balance. | SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000; | medium |
6,660 | driving_school | [
"Customers"
] | What are the phone numbers and email addresses of all customers who have an outstanding balance of more than 2000? | SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000; | medium |
6,661 | driving_school | [
"Customers"
] | What is the status code, mobile phone number and email address of customer with last name as Kohler or first name as Marina? | SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler" | extra |
6,662 | driving_school | [
"Customers"
] | What is the status code, phone number, and email address of the customer whose last name is Kohler or whose first name is Marina? | SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler" | extra |
6,663 | driving_school | [
"Customers"
] | When are the birthdays of customer who are classified as 'Good Customer' status? | SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer' | easy |
6,664 | driving_school | [
"Customers"
] | What is the date of birth of every customer whose status code is 'Good Customer'? | SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer' | easy |
6,665 | driving_school | [
"Customers"
] | When did customer with first name as Carole and last name as Bernhard became a customer? | SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard"; | medium |
6,666 | driving_school | [
"Customers"
] | When did Carole Bernhard first become a customer? | SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard"; | medium |
6,667 | driving_school | [
"Customers"
] | How many customers in total? | SELECT count(*) FROM Customers; | easy |
6,668 | driving_school | [
"Customers"
] | How many customers are there? | SELECT count(*) FROM Customers; | easy |
6,669 | driving_school | [
"Customers"
] | List all customer status codes and the number of customers having each status code. | SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code; | medium |
6,670 | driving_school | [
"Customers"
] | For each customer status code, how many customers are classified that way? | SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code; | medium |
6,671 | driving_school | [
"Customers"
] | Which customer status code has least number of customers? | SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1; | hard |
6,672 | driving_school | [
"Customers"
] | What is the status code with the least number of customers? | SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1; | hard |
6,673 | driving_school | [
"Lessons",
"Customers"
] | How many lessons taken by customer with first name as Rylan and last name as Goodwin were completed? | SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed"; | medium |
6,674 | driving_school | [
"Lessons",
"Customers"
] | How many lessons did the customer Ryan Goodwin complete? | SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed"; | medium |
6,675 | driving_school | [
"Customers"
] | What is maximum, minimum and average amount of outstanding of customer? | SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers; | medium |
6,676 | driving_school | [
"Customers"
] | What is the maximum, minimum, and average amount of money outsanding for all customers? | SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers; | medium |
6,677 | driving_school | [
"Customers"
] | List the first name and last name of customers have the amount of outstanding between 1000 and 3000. | SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000; | medium |
6,678 | driving_school | [
"Customers"
] | What are the first and last names of all customers with between 1000 and 3000 dollars outstanding? | SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000; | medium |
6,679 | driving_school | [
"Addresses",
"Customers"
] | List first name and last name of customers lived in city Lockmanfurt. | SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt"; | medium |
6,680 | driving_school | [
"Addresses",
"Customers"
] | What are the first and last names of all customers who lived in Lockmanfurt? | SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt"; | medium |
6,681 | driving_school | [
"Addresses",
"Customers"
] | Which country does customer with first name as Carole and last name as Bernhard lived in? | SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard" | medium |
6,682 | driving_school | [
"Addresses",
"Customers"
] | What is the country in which the customer Carole Bernhard lived? | SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard" | medium |
6,683 | driving_school | [
"Addresses",
"Customers"
] | What is zip code of customer with first name as Carole and last name as Bernhard? | SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard" | medium |
6,684 | driving_school | [
"Addresses",
"Customers"
] | What is the zip code of the customer Carole Bernhard? | SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard" | medium |
6,685 | driving_school | [
"Addresses",
"Customers"
] | Which city does has most number of customers? | SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1; | extra |
6,686 | driving_school | [
"Addresses",
"Customers"
] | What is the city with the most customers? | SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1; | extra |
6,687 | driving_school | [
"Customer_Payments",
"Customers"
] | How much in total does customer with first name as Carole and last name as Bernhard paid? | SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard" | medium |
6,688 | driving_school | [
"Customer_Payments",
"Customers"
] | What is the total amount of moeny paid by the customer Carole Bernhard? | SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard" | medium |
6,689 | driving_school | [
"Customer_Payments",
"Customers"
] | List the number of customers that did not have any payment history. | SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments ); | extra |
6,690 | driving_school | [
"Customer_Payments",
"Customers"
] | How many customers have no payment histories? | SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments ); | extra |
6,691 | driving_school | [
"Customer_Payments",
"Customers"
] | List first name and last name of customers that have more than 2 payments. | SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2; | medium |
6,692 | driving_school | [
"Customer_Payments",
"Customers"
] | What are the first and last names of all customers with more than 2 payments? | SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2; | medium |
6,693 | driving_school | [
"Customer_Payments"
] | List all payment methods and number of payments using each payment methods. | SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code; | medium |
6,694 | driving_school | [
"Customer_Payments"
] | For each payment method, how many payments were made? | SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code; | medium |
6,695 | driving_school | [
"Lessons"
] | How many lessons were in cancelled state? | SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled"; | easy |
6,696 | driving_school | [
"Lessons"
] | How many lessons have been cancelled? | SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled"; | easy |
6,697 | driving_school | [
"Staff",
"Lessons"
] | List lesson id of all lessons taught by staff with first name as Janessa, last name as Sawayn and nickname containing letter 's'. | SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%"; | hard |
6,698 | driving_school | [
"Staff",
"Lessons"
] | What are the the lesson ids of all staff taught by Janessa Sawayn whose nickname has the letter s? | SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%"; | hard |
6,699 | driving_school | [
"Staff",
"Lessons"
] | How many lessons taught by staff whose first name has letter 'a' in it? | SELECT count(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%a%" | hard |
Subsets and Splits