query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
sequencelengths 1
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stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
6,300 | city_record | [
"MATCH"
] | What are the venues of all the matches? Sort them in the descending order of match date. | SELECT venue FROM MATCH ORDER BY date DESC | easy |
6,301 | city_record | [
"city"
] | what is the GDP of the city with the largest population. | SELECT gdp FROM city ORDER BY Regional_Population DESC LIMIT 1 | medium |
6,302 | city_record | [
"city"
] | Find the GDP of the city with the largest regional population. | SELECT gdp FROM city ORDER BY Regional_Population DESC LIMIT 1 | medium |
6,303 | city_record | [
"city",
"hosting_city"
] | What are the GDP and population of the city that already served as a host more than once? | SELECT t1.gdp , t1.Regional_Population FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY t2.Host_City HAVING count(*) > 1 | medium |
6,304 | city_record | [
"city",
"hosting_city"
] | Which cities have served as host cities more than once? Return me their GDP and population. | SELECT t1.gdp , t1.Regional_Population FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY t2.Host_City HAVING count(*) > 1 | medium |
6,305 | e_government | [
"individuals"
] | List every individual's first name, middle name and last name in alphabetical order by last name. | SELECT individual_first_name , individual_middle_name , individual_last_name FROM individuals ORDER BY individual_last_name | medium |
6,306 | e_government | [
"individuals"
] | What are the first, middle, and last names of all individuals, ordered by last name? | SELECT individual_first_name , individual_middle_name , individual_last_name FROM individuals ORDER BY individual_last_name | medium |
6,307 | e_government | [
"forms"
] | List all the types of forms. | SELECT DISTINCT form_type_code FROM forms | easy |
6,308 | e_government | [
"forms"
] | What are the different types of forms? | SELECT DISTINCT form_type_code FROM forms | easy |
6,309 | e_government | [
"forms",
"party_forms"
] | Find the name of the most popular party form. | SELECT t1.form_name FROM forms AS t1 JOIN party_forms AS t2 ON t1.form_id = t2.form_id GROUP BY t2.form_id ORDER BY count(*) DESC LIMIT 1 | extra |
6,310 | e_government | [
"forms",
"party_forms"
] | What is the name of the party form that is most common? | SELECT t1.form_name FROM forms AS t1 JOIN party_forms AS t2 ON t1.form_id = t2.form_id GROUP BY t2.form_id ORDER BY count(*) DESC LIMIT 1 | extra |
6,311 | e_government | [
"parties"
] | Find the payment method and phone of the party with email "[email protected]". | SELECT payment_method_code , party_phone FROM parties WHERE party_email = "[email protected]" | medium |
6,312 | e_government | [
"parties"
] | What is the payment method code and party phone of the party with the email '[email protected]'? | SELECT payment_method_code , party_phone FROM parties WHERE party_email = "[email protected]" | medium |
6,313 | e_government | [
"parties",
"party_forms"
] | Find the emails of parties with the most popular party form. | SELECT t1.party_email FROM parties AS t1 JOIN party_forms AS t2 ON t1.party_id = t2.party_id WHERE t2.form_id = (SELECT form_id FROM party_forms GROUP BY form_id ORDER BY count(*) DESC LIMIT 1) | extra |
6,314 | e_government | [
"parties",
"party_forms"
] | What are the party emails associated with parties that used the party form that is the most common? | SELECT t1.party_email FROM parties AS t1 JOIN party_forms AS t2 ON t1.party_id = t2.party_id WHERE t2.form_id = (SELECT form_id FROM party_forms GROUP BY form_id ORDER BY count(*) DESC LIMIT 1) | extra |
6,315 | e_government | [
"organizations"
] | List all the name of organizations in order of the date formed. | SELECT organization_name FROM organizations ORDER BY date_formed ASC | easy |
6,316 | e_government | [
"organizations"
] | What are the names of organizations, ordered by the date they were formed, ascending? | SELECT organization_name FROM organizations ORDER BY date_formed ASC | easy |
6,317 | e_government | [
"organizations"
] | Find the name of the youngest organization. | SELECT organization_name FROM organizations ORDER BY date_formed DESC LIMIT 1 | medium |
6,318 | e_government | [
"organizations"
] | What is the name of the organization that was formed most recently? | SELECT organization_name FROM organizations ORDER BY date_formed DESC LIMIT 1 | medium |
6,319 | e_government | [
"organizations",
"organization_contact_individuals",
"individuals"
] | Find the last name of the latest contact individual of the organization "Labour Party". | SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.organization_name = "Labour Party" ORDER BY t2.date_contact_to DESC LIMIT 1 | extra |
6,320 | e_government | [
"organizations",
"organization_contact_individuals",
"individuals"
] | What is the last name of the contact individual from the Labour party organization who was contacted most recently? | SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.organization_name = "Labour Party" ORDER BY t2.date_contact_to DESC LIMIT 1 | extra |
6,321 | e_government | [
"organizations",
"organization_contact_individuals",
"individuals"
] | Find the last name of the first ever contact person of the organization with the highest UK Vat number. | SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.uk_vat_number = (SELECT max(uk_vat_number) FROM organizations) ORDER BY t2.date_contact_to ASC LIMIT 1 | extra |
6,322 | e_government | [
"organizations",
"organization_contact_individuals",
"individuals"
] | What is the last name of the first individual contacted from the organization with the maximum UK Vat number across all organizations? | SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.uk_vat_number = (SELECT max(uk_vat_number) FROM organizations) ORDER BY t2.date_contact_to ASC LIMIT 1 | extra |
6,323 | e_government | [
"services"
] | How many services are there? | SELECT count(*) FROM services | easy |
6,324 | e_government | [
"services"
] | Count the number of services. | SELECT count(*) FROM services | easy |
6,325 | e_government | [
"party_services",
"services"
] | Find name of the services that has never been used. | SELECT service_name FROM services EXCEPT SELECT t1.service_name FROM services AS t1 JOIN party_services AS t2 ON t1.service_id = t2.service_id | hard |
6,326 | e_government | [
"party_services",
"services"
] | What are the names of the services that have never been used? | SELECT service_name FROM services EXCEPT SELECT t1.service_name FROM services AS t1 JOIN party_services AS t2 ON t1.service_id = t2.service_id | hard |
6,327 | e_government | [
"addresses"
] | Find the name of all the cities and states. | SELECT town_city FROM addresses UNION SELECT state_province_county FROM addresses | hard |
6,328 | e_government | [
"addresses"
] | What are the names of all cities and states? | SELECT town_city FROM addresses UNION SELECT state_province_county FROM addresses | hard |
6,329 | e_government | [
"addresses"
] | How many cities are there in state "Colorado"? | SELECT count(*) FROM addresses WHERE state_province_county = "Colorado" | easy |
6,330 | e_government | [
"addresses"
] | Count the number of cities in the state of Colorado. | SELECT count(*) FROM addresses WHERE state_province_county = "Colorado" | easy |
6,331 | e_government | [
"parties"
] | Find the payment method code used by more than 3 parties. | SELECT payment_method_code FROM parties GROUP BY payment_method_code HAVING count(*) > 3 | easy |
6,332 | e_government | [
"parties"
] | What are the payment method codes that have been used by more than 3 parties? | SELECT payment_method_code FROM parties GROUP BY payment_method_code HAVING count(*) > 3 | easy |
6,333 | e_government | [
"organizations"
] | Find the name of organizations whose names contain "Party". | SELECT organization_name FROM organizations WHERE organization_name LIKE "%Party%" | medium |
6,334 | e_government | [
"organizations"
] | What are the names of organizations that contain the word "Party"? | SELECT organization_name FROM organizations WHERE organization_name LIKE "%Party%" | medium |
6,335 | e_government | [
"parties"
] | How many distinct payment methods are used by parties? | SELECT count(DISTINCT payment_method_code) FROM parties | easy |
6,336 | e_government | [
"parties"
] | Count the number of different payment method codes used by parties. | SELECT count(DISTINCT payment_method_code) FROM parties | easy |
6,337 | e_government | [
"party_services",
"parties"
] | Which is the email of the party that has used the services the most number of times? | SELECT t1.party_email FROM parties AS t1 JOIN party_services AS t2 ON t1.party_id = t2.customer_id GROUP BY t1.party_email ORDER BY count(*) DESC LIMIT 1 | extra |
6,338 | e_government | [
"party_services",
"parties"
] | Return the party email that has used party services the greatest number of times. | SELECT t1.party_email FROM parties AS t1 JOIN party_services AS t2 ON t1.party_id = t2.customer_id GROUP BY t1.party_email ORDER BY count(*) DESC LIMIT 1 | extra |
6,339 | e_government | [
"addresses"
] | Which state can address "6862 Kaitlyn Knolls" possibly be in? | SELECT state_province_county FROM addresses WHERE line_1_number_building LIKE "%6862 Kaitlyn Knolls%" | medium |
6,340 | e_government | [
"addresses"
] | Give the state corresponding to the line number building "6862 Kaitlyn Knolls". | SELECT state_province_county FROM addresses WHERE line_1_number_building LIKE "%6862 Kaitlyn Knolls%" | medium |
6,341 | e_government | [
"organizations",
"organization_contact_individuals"
] | What is the name of organization that has the greatest number of contact individuals? | SELECT t1.organization_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id GROUP BY t1.organization_name ORDER BY count(*) DESC LIMIT 1 | extra |
6,342 | e_government | [
"organizations",
"organization_contact_individuals"
] | Return the name of the organization which has the most contact individuals. | SELECT t1.organization_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id GROUP BY t1.organization_name ORDER BY count(*) DESC LIMIT 1 | extra |
6,343 | e_government | [
"organization_contact_individuals",
"individuals"
] | Find the last name of the individuals that have been contact individuals of an organization. | SELECT DISTINCT t1.individual_last_name FROM individuals AS t1 JOIN organization_contact_individuals AS t2 ON t1.individual_id = t2.individual_id | easy |
6,344 | e_government | [
"organization_contact_individuals",
"individuals"
] | What are the last names of individuals who have been contact individuals for an organization? | SELECT DISTINCT t1.individual_last_name FROM individuals AS t1 JOIN organization_contact_individuals AS t2 ON t1.individual_id = t2.individual_id | easy |
6,345 | school_bus | [
"driver"
] | How many drivers are there? | SELECT count(*) FROM driver | easy |
6,346 | school_bus | [
"driver"
] | Show the name, home city, and age for all drivers. | SELECT name , home_city , age FROM driver | medium |
6,347 | school_bus | [
"driver"
] | Show the party and the number of drivers in each party. | SELECT party , count(*) FROM driver GROUP BY party | medium |
6,348 | school_bus | [
"driver"
] | Show the name of drivers in descending order of age. | SELECT name FROM driver ORDER BY age DESC | easy |
6,349 | school_bus | [
"driver"
] | Show all different home cities. | SELECT DISTINCT home_city FROM driver | easy |
6,350 | school_bus | [
"driver"
] | Show the home city with the most number of drivers. | SELECT home_city FROM driver GROUP BY home_city ORDER BY count(*) DESC LIMIT 1 | hard |
6,351 | school_bus | [
"driver"
] | Show the party with drivers from Hartford and drivers older than 40. | SELECT party FROM driver WHERE home_city = 'Hartford' AND age > 40 | medium |
6,352 | school_bus | [
"driver"
] | Show home city where at least two drivers older than 40 are from. | SELECT home_city FROM driver WHERE age > 40 GROUP BY home_city HAVING count(*) >= 2 | medium |
6,353 | school_bus | [
"driver"
] | Show all home cities except for those having a driver older than 40. | SELECT home_city FROM driver EXCEPT SELECT home_city FROM driver WHERE age > 40 | hard |
6,354 | school_bus | [
"driver",
"school_bus"
] | Show the names of the drivers without a school bus. | SELECT name FROM driver WHERE driver_id NOT IN (SELECT driver_id FROM school_bus) | hard |
6,355 | school_bus | [
"school"
] | Show the types of schools that have two schools. | SELECT TYPE FROM school GROUP BY TYPE HAVING count(*) = 2 | easy |
6,356 | school_bus | [
"school",
"driver",
"school_bus"
] | Show the school name and driver name for all school buses. | SELECT T2.school , T3.name FROM school_bus AS T1 JOIN school AS T2 ON T1.school_id = T2.school_id JOIN driver AS T3 ON T1.driver_id = T3.driver_id | medium |
6,357 | school_bus | [
"school_bus"
] | What is the maximum, minimum and average years spent working on a school bus? | SELECT max(years_working) , min(years_working) , avg(years_working) FROM school_bus | medium |
6,358 | school_bus | [
"school",
"school_bus"
] | Show the school name and type for schools without a school bus. | SELECT school , TYPE FROM school WHERE school_id NOT IN (SELECT school_id FROM school_bus) | extra |
6,359 | school_bus | [
"school",
"school_bus"
] | Show the type of school and the number of buses for each type. | SELECT T2.type , count(*) FROM school_bus AS T1 JOIN school AS T2 ON T1.school_id = T2.school_id GROUP BY T2.type | medium |
6,360 | school_bus | [
"driver"
] | How many drivers are from Hartford city or younger than 40? | SELECT count(*) FROM driver WHERE home_city = 'Hartford' OR age < 40 | medium |
6,361 | school_bus | [
"driver"
] | List names for drivers from Hartford city and younger than 40. | SELECT name FROM driver WHERE home_city = 'Hartford' AND age < 40 | medium |
6,362 | school_bus | [
"driver",
"school_bus"
] | find the name of driver who is driving the school bus with the longest working history. | SELECT t1.name FROM driver AS t1 JOIN school_bus AS t2 ON t1.driver_id = t2.driver_id ORDER BY years_working DESC LIMIT 1 | hard |
6,363 | flight_company | [
"flight"
] | How many flights have a velocity larger than 200? | SELECT count(*) FROM flight WHERE velocity > 200 | easy |
6,364 | flight_company | [
"flight"
] | List the vehicle flight number, date and pilot of all the flights, ordered by altitude. | SELECT vehicle_flight_number , date , pilot FROM flight ORDER BY altitude ASC | medium |
6,365 | flight_company | [
"airport"
] | List the id, country, city and name of the airports ordered alphabetically by the name. | SELECT id , country , city , name FROM airport ORDER BY name | medium |
6,366 | flight_company | [
"operate_company"
] | What is maximum group equity shareholding of the companies? | SELECT max(group_equity_shareholding) FROM operate_company | easy |
6,367 | flight_company | [
"flight"
] | What is the velocity of the pilot named 'Thompson'? | SELECT avg(velocity) FROM flight WHERE pilot = 'Thompson' | easy |
6,368 | flight_company | [
"operate_company",
"flight"
] | What are the names and types of the companies that have ever operated a flight? | SELECT T1.name , T1.type FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id | medium |
6,369 | flight_company | [
"airport"
] | What are the names of the airports which are not in the country 'Iceland'? | SELECT name FROM airport WHERE country != 'Iceland' | easy |
6,370 | flight_company | [
"operate_company",
"flight"
] | What are the distinct types of the companies that have operated any flights with velocity less than 200? | SELECT DISTINCT T1.type FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T2.velocity < 200 | medium |
6,371 | flight_company | [
"operate_company",
"flight"
] | What are the ids and names of the companies that operated more than one flight? | SELECT T1.id , T1.name FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id GROUP BY T1.id HAVING count(*) > 1 | medium |
6,372 | flight_company | [
"flight",
"airport"
] | What is the id, name and IATA code of the airport that had most number of flights? | SELECT T1.id , T1.name , T1.IATA FROM airport AS T1 JOIN flight AS T2 ON T1.id = T2.airport_id GROUP BY T2.id ORDER BY count(*) DESC LIMIT 1 | extra |
6,373 | flight_company | [
"flight",
"airport"
] | What are the different pilot names who had piloted a flight in the country 'United States' or in the airport named 'Billund Airport'? | SELECT DISTINCT T2.pilot FROM airport AS T1 JOIN flight AS T2 ON T1.id = T2.airport_id WHERE T1.country = 'United States' OR T1.name = 'Billund Airport' | hard |
6,374 | flight_company | [
"operate_company"
] | What is the most common company type, and how many are there? | SELECT TYPE , count(*) FROM operate_company GROUP BY TYPE ORDER BY count(*) DESC LIMIT 1 | hard |
6,375 | flight_company | [
"flight",
"airport"
] | How many airports haven't the pilot 'Thompson' driven an aircraft? | SELECT count(*) FROM airport WHERE id NOT IN ( SELECT airport_id FROM flight WHERE pilot = 'Thompson' ); | extra |
6,376 | flight_company | [
"operate_company",
"flight"
] | List the name of the pilots who have flied for both a company that mainly provide 'Cargo' services and a company that runs 'Catering services' activities. | SELECT T2.pilot FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T1.principal_activities = 'Cargo' INTERSECT SELECT T2.pilot FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T1.principal_activities = 'Catering services' | extra |
6,377 | flight_company | [
"airport"
] | Which of the airport names contains the word 'international'? | SELECT name FROM airport WHERE name LIKE '%international%' | medium |
6,378 | flight_company | [
"operate_company",
"flight",
"airport"
] | How many companies operates airlines in each airport? | SELECT T3.id , count(*) FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id JOIN airport AS T3 ON T2.airport_id = T3.id GROUP BY T3.id | hard |
6,379 | flight_company | [
"airport"
] | how many airports are there in each country? | SELECT count(*) , country FROM airport GROUP BY country | medium |
6,380 | flight_company | [
"airport"
] | which countries have more than 2 airports? | SELECT country FROM airport GROUP BY country HAVING count(*) > 2 | easy |
6,381 | flight_company | [
"flight"
] | which pilot is in charge of the most number of flights? | SELECT pilot FROM flight GROUP BY pilot ORDER BY count(*) DESC LIMIT 1 | hard |
6,382 | cre_Docs_and_Epenses | [
"Accounts"
] | How many accounts do we have? | SELECT count(*) FROM Accounts | easy |
6,383 | cre_Docs_and_Epenses | [
"Accounts"
] | Count the number of accounts. | SELECT count(*) FROM Accounts | easy |
6,384 | cre_Docs_and_Epenses | [
"Accounts"
] | Show all account ids and account details. | SELECT account_id , account_details FROM Accounts | medium |
6,385 | cre_Docs_and_Epenses | [
"Accounts"
] | What are the ids and details of all accounts? | SELECT account_id , account_details FROM Accounts | medium |
6,386 | cre_Docs_and_Epenses | [
"Statements"
] | How many statements do we have? | SELECT count(*) FROM Statements | easy |
6,387 | cre_Docs_and_Epenses | [
"Statements"
] | Count the number of statements. | SELECT count(*) FROM Statements | easy |
6,388 | cre_Docs_and_Epenses | [
"Statements"
] | List all statement ids and statement details. | SELECT STATEMENT_ID , statement_details FROM Statements | medium |
6,389 | cre_Docs_and_Epenses | [
"Statements"
] | What are the ids and details of all statements? | SELECT STATEMENT_ID , statement_details FROM Statements | medium |
6,390 | cre_Docs_and_Epenses | [
"Statements",
"Accounts"
] | Show statement id, statement detail, account detail for accounts. | SELECT T1.statement_id , T2.statement_details , T1.account_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id | medium |
6,391 | cre_Docs_and_Epenses | [
"Statements",
"Accounts"
] | What are the statement ids, statement details, and account details, for all accounts? | SELECT T1.statement_id , T2.statement_details , T1.account_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id | medium |
6,392 | cre_Docs_and_Epenses | [
"Accounts"
] | Show all statement id and the number of accounts for each statement. | SELECT STATEMENT_ID , count(*) FROM Accounts GROUP BY STATEMENT_ID | medium |
6,393 | cre_Docs_and_Epenses | [
"Accounts"
] | What are the different statement ids on accounts, and the number of accounts for each? | SELECT STATEMENT_ID , count(*) FROM Accounts GROUP BY STATEMENT_ID | medium |
6,394 | cre_Docs_and_Epenses | [
"Statements",
"Accounts"
] | Show the statement id and the statement detail for the statement with most number of accounts. | SELECT T1.statement_id , T2.statement_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id GROUP BY T1.statement_id ORDER BY count(*) DESC LIMIT 1 | extra |
6,395 | cre_Docs_and_Epenses | [
"Statements",
"Accounts"
] | What are the statement id and statement detail for the statement that has the most corresponding accounts? | SELECT T1.statement_id , T2.statement_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id GROUP BY T1.statement_id ORDER BY count(*) DESC LIMIT 1 | extra |
6,396 | cre_Docs_and_Epenses | [
"Documents"
] | Show the number of documents. | SELECT count(*) FROM Documents | easy |
6,397 | cre_Docs_and_Epenses | [
"Documents"
] | Count the number of documents. | SELECT count(*) FROM Documents | easy |
6,398 | cre_Docs_and_Epenses | [
"Documents"
] | List the document type code, document name, and document description for the document with name 'Noel CV' or name 'King Book'. | SELECT document_type_code , document_name , document_description FROM Documents WHERE document_name = 'Noel CV' OR document_name = 'King Book' | extra |
6,399 | cre_Docs_and_Epenses | [
"Documents"
] | What are the type come, name, and description of the document that has either the name 'Noel CV' or 'King Book'? | SELECT document_type_code , document_name , document_description FROM Documents WHERE document_name = 'Noel CV' OR document_name = 'King Book' | extra |
Subsets and Splits