query_id
int64 0
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| database_id
stringclasses 140
values | table_id
sequencelengths 1
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stringlengths 16
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| answer
stringlengths 18
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| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
3,700 | baseball_1 | [
"home_game",
"team"
] | Which team had the least number of attendances in home games in 1980? | SELECT T2.name FROM home_game AS T1 JOIN team AS T2 ON T1.team_id = T2.team_id_br WHERE T1.year = 1980 ORDER BY T1.attendance ASC LIMIT 1; | extra |
3,701 | baseball_1 | [
"home_game",
"team"
] | Find the team that attended the least number of home games in 1980. | SELECT T2.name FROM home_game AS T1 JOIN team AS T2 ON T1.team_id = T2.team_id_br WHERE T1.year = 1980 ORDER BY T1.attendance ASC LIMIT 1; | extra |
3,702 | baseball_1 | [
"park"
] | List the names of states that have more than 2 parks. | SELECT state FROM park GROUP BY state HAVING count(*) > 2; | easy |
3,703 | baseball_1 | [
"park"
] | Which states have more than 2 parks? | SELECT state FROM park GROUP BY state HAVING count(*) > 2; | easy |
3,704 | baseball_1 | [
"team_franchise"
] | How many team franchises are active, with active value 'Y'? | SELECT count(*) FROM team_franchise WHERE active = 'Y'; | easy |
3,705 | baseball_1 | [
"team_franchise"
] | Find the number of team franchises that are active (have 'Y' as "active" information). | SELECT count(*) FROM team_franchise WHERE active = 'Y'; | easy |
3,706 | baseball_1 | [
"park"
] | Which cities have 2 to 4 parks? | SELECT city FROM park GROUP BY city HAVING count(*) BETWEEN 2 AND 4; | easy |
3,707 | baseball_1 | [
"park"
] | Find all the cities that have 2 to 4 parks. | SELECT city FROM park GROUP BY city HAVING count(*) BETWEEN 2 AND 4; | easy |
3,708 | baseball_1 | [
"home_game",
"park"
] | Which park had most attendances in 2008? | SELECT T2.park_name FROM home_game AS T1 JOIN park AS T2 ON T1.park_id = T2.park_id WHERE T1.year = 2008 ORDER BY T1.attendance DESC LIMIT 1; | extra |
3,709 | baseball_1 | [
"home_game",
"park"
] | Which park did the most people attend in 2008? | SELECT T2.park_name FROM home_game AS T1 JOIN park AS T2 ON T1.park_id = T2.park_id WHERE T1.year = 2008 ORDER BY T1.attendance DESC LIMIT 1; | extra |
3,710 | mountain_photos | [
"camera_lens"
] | How many camera lenses have a focal length longer than 15 mm? | SELECT count(*) FROM camera_lens WHERE focal_length_mm > 15 | easy |
3,711 | mountain_photos | [
"camera_lens"
] | Find the brand and name for each camera lens, and sort in descending order of maximum aperture. | SELECT brand , name FROM camera_lens ORDER BY max_aperture DESC | medium |
3,712 | mountain_photos | [
"photos"
] | List the id, color scheme, and name for all the photos. | SELECT id , color , name FROM photos | medium |
3,713 | mountain_photos | [
"mountain"
] | What are the maximum and average height of the mountains? | SELECT max(height) , avg(height) FROM mountain | medium |
3,714 | mountain_photos | [
"mountain"
] | What are the average prominence of the mountains in country 'Morocco'? | SELECT avg(prominence) FROM mountain WHERE country = 'Morocco' | easy |
3,715 | mountain_photos | [
"mountain"
] | What are the name, height and prominence of mountains which do not belong to the range 'Aberdare Range'? | SELECT name , height , prominence FROM mountain WHERE range != 'Aberdare Range' | medium |
3,716 | mountain_photos | [
"mountain",
"photos"
] | What are the id and name of the photos for mountains? | SELECT T1.id , T1.name FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id WHERE T1.height > 4000 | medium |
3,717 | mountain_photos | [
"mountain",
"photos"
] | What are the id and name of the mountains that have at least 2 photos? | SELECT T1.id , T1.name FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id GROUP BY T1.id HAVING count(*) >= 2 | medium |
3,718 | mountain_photos | [
"photos",
"camera_lens"
] | What are the names of the cameras that have taken picture of the most mountains? | SELECT T2.name FROM photos AS T1 JOIN camera_lens AS T2 ON T1.camera_lens_id = T2.id GROUP BY T2.id ORDER BY count(*) DESC LIMIT 1 | extra |
3,719 | mountain_photos | [
"photos",
"camera_lens"
] | What are the names of photos taken with the lens brand 'Sigma' or 'Olympus'? | SELECT T1.name FROM camera_lens AS T1 JOIN photos AS T2 ON T2.camera_lens_id = T1.id WHERE T1.brand = 'Sigma' OR T1.brand = 'Olympus' | hard |
3,720 | mountain_photos | [
"camera_lens"
] | How many different kinds of lens brands are there? | SELECT count(DISTINCT brand) FROM camera_lens | easy |
3,721 | mountain_photos | [
"photos",
"camera_lens"
] | How many camera lenses are not used in taking any photos? | SELECT count(*) FROM camera_lens WHERE id NOT IN ( SELECT camera_lens_id FROM photos ) | extra |
3,722 | mountain_photos | [
"mountain",
"photos"
] | How many distinct kinds of camera lenses are used to take photos of mountains in the country 'Ethiopia'? | SELECT count(DISTINCT T2.camera_lens_id) FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id WHERE T1.country = 'Ethiopia' | medium |
3,723 | mountain_photos | [
"mountain",
"camera_lens",
"photos"
] | List the brands of lenses that took both a picture of mountains with range 'Toubkal Atlas' and a picture of mountains with range 'Lasta Massif' | SELECT T3.brand FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id JOIN camera_lens AS T3 ON T2.camera_lens_id = T3.id WHERE T1.range = 'Toubkal Atlas' INTERSECT SELECT T3.brand FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id JOIN camera_lens AS T3 ON T2.camera_lens_id = T3.id WHERE T1.range = 'Lasta Massif' | extra |
3,724 | mountain_photos | [
"mountain",
"camera_lens",
"photos"
] | Show the name and prominence of the mountains whose picture is not taken by a lens of brand 'Sigma'. | SELECT name , prominence FROM mountain EXCEPT SELECT T1.name , T1.prominence FROM mountain AS T1 JOIN photos AS T2 ON T1.id = T2.mountain_id JOIN camera_lens AS T3 ON T2.camera_lens_id = T3.id WHERE T3.brand = 'Sigma' | extra |
3,725 | mountain_photos | [
"camera_lens"
] | List the camera lens names containing substring "Digital". | SELECT name FROM camera_lens WHERE name LIKE "%Digital%" | medium |
3,726 | mountain_photos | [
"photos",
"camera_lens"
] | What is the name of each camera lens and the number of photos taken by it? Order the result by the count of photos. | SELECT T1.name , count(*) FROM camera_lens AS T1 JOIN photos AS T2 ON T1.id = T2.camera_lens_id GROUP BY T1.id ORDER BY count(*) | hard |
3,727 | program_share | [
"channel"
] | Find the names of channels that are not owned by CCTV. | SELECT name FROM channel WHERE OWNER != 'CCTV' | easy |
3,728 | program_share | [
"channel"
] | Which channels are not owned by CCTV? Give me the channel names. | SELECT name FROM channel WHERE OWNER != 'CCTV' | easy |
3,729 | program_share | [
"channel"
] | List all channel names ordered by their rating in percent from big to small. | SELECT name FROM channel ORDER BY rating_in_percent DESC | easy |
3,730 | program_share | [
"channel"
] | Give me a list of all the channel names sorted by the channel rating in descending order. | SELECT name FROM channel ORDER BY rating_in_percent DESC | easy |
3,731 | program_share | [
"channel"
] | What is the owner of the channel that has the highest rating ratio? | SELECT OWNER FROM channel ORDER BY rating_in_percent DESC LIMIT 1 | medium |
3,732 | program_share | [
"channel"
] | Show me the owner of the channel with the highest rating. | SELECT OWNER FROM channel ORDER BY rating_in_percent DESC LIMIT 1 | medium |
3,733 | program_share | [
"program"
] | how many programs are there? | SELECT count(*) FROM program | easy |
3,734 | program_share | [
"program"
] | Count the number of programs. | SELECT count(*) FROM program | easy |
3,735 | program_share | [
"program"
] | list all the names of programs, ordering by launch time. | SELECT name FROM program ORDER BY launch | easy |
3,736 | program_share | [
"program"
] | What is the list of program names, sorted by the order of launch date? | SELECT name FROM program ORDER BY launch | easy |
3,737 | program_share | [
"program"
] | List the name, origin and owner of each program. | SELECT name , origin , OWNER FROM program | medium |
3,738 | program_share | [
"program"
] | What are the name, origin and owner of each program? | SELECT name , origin , OWNER FROM program | medium |
3,739 | program_share | [
"program"
] | find the name of the program that was launched most recently. | SELECT name FROM program ORDER BY launch DESC LIMIT 1 | medium |
3,740 | program_share | [
"program"
] | Which program was launched most recently? Return the program name. | SELECT name FROM program ORDER BY launch DESC LIMIT 1 | medium |
3,741 | program_share | [
"channel"
] | find the total percentage share of all channels owned by CCTV. | SELECT sum(Share_in_percent) FROM channel WHERE OWNER = 'CCTV' | easy |
3,742 | program_share | [
"channel"
] | What is the total share (in percent) of all the channels owned by CCTV? | SELECT sum(Share_in_percent) FROM channel WHERE OWNER = 'CCTV' | easy |
3,743 | program_share | [
"channel",
"broadcast"
] | Find the names of the channels that are broadcast in the morning. | SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Morning' | medium |
3,744 | program_share | [
"channel",
"broadcast"
] | Which channels are broadcast in the morning? Give me the channel names. | SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Morning' | medium |
3,745 | program_share | [
"channel",
"broadcast"
] | what are the names of the channels that broadcast in both morning and night? | SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Morning' INTERSECT SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Night' | extra |
3,746 | program_share | [
"channel",
"broadcast"
] | Which channels broadcast both in the morning and at night? Give me the channel names. | SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Morning' INTERSECT SELECT t1.name FROM channel AS t1 JOIN broadcast AS t2 ON t1.channel_id = t2.channel_id WHERE t2.time_of_day = 'Night' | extra |
3,747 | program_share | [
"broadcast"
] | how many programs are broadcast in each time section of the day? | SELECT count(*) , time_of_day FROM broadcast GROUP BY time_of_day | medium |
3,748 | program_share | [
"broadcast"
] | Count the number of programs broadcast for each time section of a day. | SELECT count(*) , time_of_day FROM broadcast GROUP BY time_of_day | medium |
3,749 | program_share | [
"broadcast"
] | find the number of different programs that are broadcast during night time. | SELECT count(DISTINCT program_id) FROM broadcast WHERE time_of_day = 'Night' | easy |
3,750 | program_share | [
"broadcast"
] | How many distinct programs are broadcast at "Night" time? | SELECT count(DISTINCT program_id) FROM broadcast WHERE time_of_day = 'Night' | easy |
3,751 | program_share | [
"program",
"broadcast"
] | Find the names of programs that are never broadcasted in the morning. | SELECT name FROM program EXCEPT SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id WHERE t2.Time_of_day = "Morning" | hard |
3,752 | program_share | [
"program",
"broadcast"
] | Which programs are never broadcasted in the morning? Give me the names of the programs. | SELECT name FROM program EXCEPT SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id WHERE t2.Time_of_day = "Morning" | hard |
3,753 | program_share | [
"program",
"broadcast"
] | find the program owners that have some programs in both morning and night time. | SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id WHERE t2.Time_of_day = "Morning" INTERSECT SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id WHERE t2.Time_of_day = "Night" | extra |
3,754 | program_share | [
"program",
"broadcast"
] | Who are the owners of the programs that broadcast both in the morning and at night? | SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id WHERE t2.Time_of_day = "Morning" INTERSECT SELECT t1.owner FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id WHERE t2.Time_of_day = "Night" | extra |
3,755 | program_share | [
"program"
] | List all program origins in the alphabetical order. | SELECT origin FROM program ORDER BY origin | easy |
3,756 | program_share | [
"program"
] | What is the list of program origins ordered alphabetically? | SELECT origin FROM program ORDER BY origin | easy |
3,757 | program_share | [
"channel"
] | what is the number of different channel owners? | SELECT count(DISTINCT OWNER) FROM channel | easy |
3,758 | program_share | [
"channel"
] | Count the number of distinct channel owners. | SELECT count(DISTINCT OWNER) FROM channel | easy |
3,759 | program_share | [
"program"
] | find the names of programs whose origin is not in Beijing. | SELECT name FROM program WHERE origin != 'Beijing' | easy |
3,760 | program_share | [
"program"
] | Which programs' origins are not "Beijing"? Give me the program names. | SELECT name FROM program WHERE origin != 'Beijing' | easy |
3,761 | program_share | [
"channel"
] | What are the names of the channels owned by CCTV or HBS? | SELECT name FROM channel WHERE OWNER = 'CCTV' OR OWNER = 'HBS' | medium |
3,762 | program_share | [
"channel"
] | List the names of all the channels owned by either CCTV or HBS | SELECT name FROM channel WHERE OWNER = 'CCTV' OR OWNER = 'HBS' | medium |
3,763 | program_share | [
"channel"
] | Find the total rating ratio for each channel owner. | SELECT sum(Rating_in_percent) , OWNER FROM channel GROUP BY OWNER | medium |
3,764 | program_share | [
"channel"
] | What is the total rating of channel for each channel owner? | SELECT sum(Rating_in_percent) , OWNER FROM channel GROUP BY OWNER | medium |
3,765 | program_share | [
"program",
"broadcast"
] | Find the name of the program that is broadcast most frequently. | SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id GROUP BY t2.program_id ORDER BY count(*) DESC LIMIT 1 | extra |
3,766 | program_share | [
"program",
"broadcast"
] | Which program is broadcast most frequently? Give me the program name. | SELECT t1.name FROM program AS t1 JOIN broadcast AS t2 ON t1.program_id = t2.program_id GROUP BY t2.program_id ORDER BY count(*) DESC LIMIT 1 | extra |
3,767 | e_learning | [
"COURSES"
] | How many courses are there in total? | SELECT count(*) FROM COURSES | easy |
3,768 | e_learning | [
"COURSES"
] | Find the total number of courses offered. | SELECT count(*) FROM COURSES | easy |
3,769 | e_learning | [
"COURSES"
] | What are the descriptions of the courses with name "database"? | SELECT course_description FROM COURSES WHERE course_name = "database" | easy |
3,770 | e_learning | [
"COURSES"
] | Return the description for the courses named "database". | SELECT course_description FROM COURSES WHERE course_name = "database" | easy |
3,771 | e_learning | [
"Course_Authors_and_Tutors"
] | What are the addresses of the course authors or tutors with personal name "Cathrine" | SELECT address_line_1 FROM Course_Authors_and_Tutors WHERE personal_name = "Cathrine" | easy |
3,772 | e_learning | [
"Course_Authors_and_Tutors"
] | Return the addresses of the course authors or tutors whose personal name is "Cathrine". | SELECT address_line_1 FROM Course_Authors_and_Tutors WHERE personal_name = "Cathrine" | easy |
3,773 | e_learning | [
"Course_Authors_and_Tutors"
] | List the addresses of all the course authors or tutors. | SELECT address_line_1 FROM Course_Authors_and_Tutors | easy |
3,774 | e_learning | [
"Course_Authors_and_Tutors"
] | What is the address of each course author or tutor? | SELECT address_line_1 FROM Course_Authors_and_Tutors | easy |
3,775 | e_learning | [
"Course_Authors_and_Tutors"
] | List all the login names and family names of course author and tutors. | SELECT login_name , family_name FROM Course_Authors_and_Tutors | medium |
3,776 | e_learning | [
"Course_Authors_and_Tutors"
] | What are the login names and family names of course author and tutors? | SELECT login_name , family_name FROM Course_Authors_and_Tutors | medium |
3,777 | e_learning | [
"Student_Course_Enrolment"
] | List all the dates of enrollment and completion of students. | SELECT date_of_enrolment , date_of_completion FROM Student_Course_Enrolment | medium |
3,778 | e_learning | [
"Student_Course_Enrolment"
] | What are all the dates of enrollment and completion in record? | SELECT date_of_enrolment , date_of_completion FROM Student_Course_Enrolment | medium |
3,779 | e_learning | [
"Student_Course_Enrolment"
] | How many distinct students are enrolled in courses? | SELECT count(DISTINCT student_id) FROM Student_Course_Enrolment | easy |
3,780 | e_learning | [
"Student_Course_Enrolment"
] | Find the number of distinct students enrolled in courses. | SELECT count(DISTINCT student_id) FROM Student_Course_Enrolment | easy |
3,781 | e_learning | [
"Student_Course_Enrolment"
] | How many distinct courses are enrolled in by students? | SELECT count(course_id) FROM Student_Course_Enrolment | easy |
3,782 | e_learning | [
"Student_Course_Enrolment"
] | Find the number of distinct courses that have enrolled students. | SELECT count(course_id) FROM Student_Course_Enrolment | easy |
3,783 | e_learning | [
"Student_Tests_Taken"
] | Find the dates of the tests taken with result "Pass". | SELECT date_test_taken FROM Student_Tests_Taken WHERE test_result = "Pass" | easy |
3,784 | e_learning | [
"Student_Tests_Taken"
] | Which tests have "Pass" results? Return the dates when the tests were taken. | SELECT date_test_taken FROM Student_Tests_Taken WHERE test_result = "Pass" | easy |
3,785 | e_learning | [
"Student_Tests_Taken"
] | How many tests have result "Fail"? | SELECT count(*) FROM Student_Tests_Taken WHERE test_result = "Fail" | easy |
3,786 | e_learning | [
"Student_Tests_Taken"
] | Count the number of tests with "Fail" result. | SELECT count(*) FROM Student_Tests_Taken WHERE test_result = "Fail" | easy |
3,787 | e_learning | [
"Students"
] | What are the login names of the students with family name "Ward"? | SELECT login_name FROM Students WHERE family_name = "Ward" | easy |
3,788 | e_learning | [
"Students"
] | Return the login names of the students whose family name is "Ward". | SELECT login_name FROM Students WHERE family_name = "Ward" | easy |
3,789 | e_learning | [
"Students"
] | What are the dates of the latest logon of the students with family name "Jaskolski" or "Langosh"? | SELECT date_of_latest_logon FROM Students WHERE family_name = "Jaskolski" OR family_name = "Langosh" | medium |
3,790 | e_learning | [
"Students"
] | Find the latest logon date of the students whose family name is "Jaskolski" or "Langosh". | SELECT date_of_latest_logon FROM Students WHERE family_name = "Jaskolski" OR family_name = "Langosh" | medium |
3,791 | e_learning | [
"Students"
] | How many students have personal names that contain the word "son"? | SELECT COUNT(*) FROM Students WHERE personal_name LIKE "%son%" | medium |
3,792 | e_learning | [
"Students"
] | Find the number of students who have the word "son" in their personal names. | SELECT COUNT(*) FROM Students WHERE personal_name LIKE "%son%" | medium |
3,793 | e_learning | [
"SUBJECTS"
] | List all the subject names. | SELECT subject_name FROM SUBJECTS | easy |
3,794 | e_learning | [
"SUBJECTS"
] | What are the names of all the subjects. | SELECT subject_name FROM SUBJECTS | easy |
3,795 | e_learning | [
"Course_Authors_and_Tutors"
] | List all the information about course authors and tutors in alphabetical order of the personal name. | SELECT * FROM Course_Authors_and_Tutors ORDER BY personal_name | easy |
3,796 | e_learning | [
"Course_Authors_and_Tutors"
] | Sort the information about course authors and tutors in alphabetical order of the personal name. | SELECT * FROM Course_Authors_and_Tutors ORDER BY personal_name | easy |
3,797 | e_learning | [
"Students"
] | List the personal names and family names of all the students in alphabetical order of family name. | SELECT personal_name , family_name FROM Students ORDER BY family_name | medium |
3,798 | e_learning | [
"Students"
] | What are the personal names and family names of the students? Sort the result in alphabetical order of the family name. | SELECT personal_name , family_name FROM Students ORDER BY family_name | medium |
3,799 | e_learning | [
"Student_Tests_Taken"
] | List each test result and its count in descending order of count. | SELECT test_result , COUNT(*) FROM Student_Tests_Taken GROUP BY test_result ORDER BY COUNT(*) DESC | extra |
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