query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
sequencelengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
1,700 | epinions_1 | [
"item",
"review"
] | Find the titles of items whose rating is higher than the average review rating of all items. | SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > (SELECT avg(rating) FROM review) | extra |
1,701 | epinions_1 | [
"item",
"review"
] | Find the titles of items that received any rating below 5. | SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5 | medium |
1,702 | epinions_1 | [
"item",
"review"
] | Find the titles of items that received both a rating higher than 8 and a rating below 5. | SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > 8 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5 | extra |
1,703 | epinions_1 | [
"item",
"review"
] | Find the names of items whose rank is higher than 3 and whose average rating is above 5. | SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rank > 3 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id HAVING avg(T2.rating) > 5 | extra |
1,704 | epinions_1 | [
"item",
"review"
] | Find the name of the item with the lowest average rating. | SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) LIMIT 1 | extra |
1,705 | epinions_1 | [
"item"
] | List the titles of all items in alphabetic order . | SELECT title FROM item ORDER BY title | easy |
1,706 | epinions_1 | [
"review",
"useracct"
] | Find the name of the user who gives the most reviews. | SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id ORDER BY count(*) DESC LIMIT 1 | extra |
1,707 | epinions_1 | [
"item",
"review"
] | Find the name and id of the item with the highest average rating. | SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) DESC LIMIT 1 | extra |
1,708 | epinions_1 | [
"item",
"review"
] | Find the name and id of the good with the highest average rank. | SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rank) DESC LIMIT 1 | extra |
1,709 | epinions_1 | [
"review",
"useracct"
] | For each user, return the name and the average rating of reviews given by them. | SELECT T1.name , avg(T2.rating) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id | medium |
1,710 | epinions_1 | [
"review",
"useracct"
] | For each user, find their name and the number of reviews written by them. | SELECT T1.name , count(*) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id | medium |
1,711 | epinions_1 | [
"review",
"useracct"
] | Find the name of the user who gave the highest rating. | SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id ORDER BY T2.rating DESC LIMIT 1 | hard |
1,712 | epinions_1 | [
"trust",
"useracct"
] | Find the name of the source user with the highest average trust score. | SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.source_u_id GROUP BY T2.source_u_id ORDER BY avg(trust) DESC LIMIT 1 | extra |
1,713 | epinions_1 | [
"trust",
"useracct"
] | Find each target user's name and average trust score. | SELECT T1.name , avg(trust) FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id GROUP BY T2.target_u_id | medium |
1,714 | epinions_1 | [
"trust",
"useracct"
] | Find the name of the target user with the lowest trust score. | SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id ORDER BY trust LIMIT 1 | hard |
1,715 | epinions_1 | [
"item",
"review"
] | Find the names of the items that did not receive any review. | SELECT title FROM item WHERE i_id NOT IN (SELECT i_id FROM review) | hard |
1,716 | epinions_1 | [
"useracct",
"review"
] | Find the names of users who did not leave any review. | SELECT name FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review) | hard |
1,717 | epinions_1 | [
"useracct",
"review"
] | Find the number of users who did not write any review. | SELECT count(*) FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review) | extra |
1,718 | epinions_1 | [
"item",
"review"
] | Find the number of items without any review. | SELECT count(*) FROM item WHERE i_id NOT IN (SELECT i_id FROM review) | extra |
1,719 | riding_club | [
"player"
] | How many players are there? | SELECT count(*) FROM player | easy |
1,720 | riding_club | [
"player"
] | List the names of players in ascending order of votes. | SELECT Player_name FROM player ORDER BY Votes ASC | easy |
1,721 | riding_club | [
"player"
] | What are the gender and occupation of players? | SELECT Gender , Occupation FROM player | medium |
1,722 | riding_club | [
"player"
] | List the name and residence for players whose occupation is not "Researcher". | SELECT Player_name , residence FROM player WHERE Occupation != "Researcher" | medium |
1,723 | riding_club | [
"player"
] | Show the names of sponsors of players whose residence is either "Brandon" or "Birtle". | SELECT Sponsor_name FROM player WHERE Residence = "Brandon" OR Residence = "Birtle" | medium |
1,724 | riding_club | [
"player"
] | What is the name of the player with the largest number of votes? | SELECT Player_name FROM player ORDER BY Votes DESC LIMIT 1 | medium |
1,725 | riding_club | [
"player"
] | Show different occupations along with the number of players in each occupation. | SELECT Occupation , COUNT(*) FROM player GROUP BY Occupation | medium |
1,726 | riding_club | [
"player"
] | Please show the most common occupation of players. | SELECT Occupation FROM player GROUP BY Occupation ORDER BY COUNT(*) DESC LIMIT 1 | hard |
1,727 | riding_club | [
"player"
] | Show the residences that have at least two players. | SELECT Residence FROM player GROUP BY Residence HAVING COUNT(*) >= 2 | easy |
1,728 | riding_club | [
"player_coach",
"coach",
"player"
] | Show the names of players and names of their coaches. | SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID | medium |
1,729 | riding_club | [
"player_coach",
"coach",
"player"
] | Show the names of players coached by the rank 1 coach. | SELECT T3.Player_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T2.Rank = 1 | hard |
1,730 | riding_club | [
"player_coach",
"coach",
"player"
] | Show the names and genders of players with a coach starting after 2011. | SELECT T3.Player_name , T3.gender FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T1.Starting_year > 2011 | hard |
1,731 | riding_club | [
"player_coach",
"coach",
"player"
] | Show the names of players and names of their coaches in descending order of the votes of players. | SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID ORDER BY T3.Votes DESC | hard |
1,732 | riding_club | [
"player_coach",
"player"
] | List the names of players that do not have coaches. | SELECT Player_name FROM player WHERE Player_ID NOT IN (SELECT Player_ID FROM player_coach) | hard |
1,733 | riding_club | [
"player"
] | Show the residences that have both a player of gender "M" and a player of gender "F". | SELECT Residence FROM player WHERE gender = "M" INTERSECT SELECT Residence FROM player WHERE gender = "F" | hard |
1,734 | riding_club | [
"coach",
"club"
] | How many coaches does each club has? List the club id, name and the number of coaches. | SELECT T1.club_id , T1.club_name, count(*) FROM club AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id | medium |
1,735 | riding_club | [
"match_result",
"coach"
] | How many gold medals has the club with the most coaches won? | SELECT T1.club_id , T1.gold FROM match_result AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id ORDER BY count(*) DESC LIMIT 1 | extra |
1,736 | gymnast | [
"gymnast"
] | How many gymnasts are there? | SELECT count(*) FROM gymnast | easy |
1,737 | gymnast | [
"gymnast"
] | Count the number of gymnasts. | SELECT count(*) FROM gymnast | easy |
1,738 | gymnast | [
"gymnast"
] | List the total points of gymnasts in descending order. | SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC | easy |
1,739 | gymnast | [
"gymnast"
] | What are the total points for all gymnasts, ordered by total points descending? | SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC | easy |
1,740 | gymnast | [
"gymnast"
] | List the total points of gymnasts in descending order of floor exercise points. | SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC | easy |
1,741 | gymnast | [
"gymnast"
] | What are the total points of gymnasts, ordered by their floor exercise points descending? | SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC | easy |
1,742 | gymnast | [
"gymnast"
] | What is the average horizontal bar points for all gymnasts? | SELECT avg(Horizontal_Bar_Points) FROM gymnast | easy |
1,743 | gymnast | [
"gymnast"
] | Return the average horizontal bar points across all gymnasts. | SELECT avg(Horizontal_Bar_Points) FROM gymnast | easy |
1,744 | gymnast | [
"People"
] | What are the names of people in ascending alphabetical order? | SELECT Name FROM People ORDER BY Name ASC | easy |
1,745 | gymnast | [
"People"
] | Return the names of people, ordered alphabetically. | SELECT Name FROM People ORDER BY Name ASC | easy |
1,746 | gymnast | [
"gymnast",
"people"
] | What are the names of gymnasts? | SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID | easy |
1,747 | gymnast | [
"gymnast",
"people"
] | Return the names of the gymnasts. | SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID | easy |
1,748 | gymnast | [
"gymnast",
"people"
] | What are the names of gymnasts whose hometown is not "Santo Domingo"? | SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "Santo Domingo" | medium |
1,749 | gymnast | [
"gymnast",
"people"
] | Return the names of gymnasts who did not grow up in Santo Domingo. | SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "Santo Domingo" | medium |
1,750 | gymnast | [
"people"
] | What is the age of the tallest person? | SELECT Age FROM people ORDER BY Height DESC LIMIT 1 | medium |
1,751 | gymnast | [
"people"
] | Return the age of the person with the greatest height. | SELECT Age FROM people ORDER BY Height DESC LIMIT 1 | medium |
1,752 | gymnast | [
"People"
] | List the names of the top 5 oldest people. | SELECT Name FROM People ORDER BY Age DESC LIMIT 5 | medium |
1,753 | gymnast | [
"People"
] | What are the names of the five oldest people? | SELECT Name FROM People ORDER BY Age DESC LIMIT 5 | medium |
1,754 | gymnast | [
"gymnast",
"people"
] | What is the total point count of the youngest gymnast? | SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1 | hard |
1,755 | gymnast | [
"gymnast",
"people"
] | Return the total points of the gymnast with the lowest age. | SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1 | hard |
1,756 | gymnast | [
"gymnast",
"people"
] | What is the average age of all gymnasts? | SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID | easy |
1,757 | gymnast | [
"gymnast",
"people"
] | Return the average age across all gymnasts. | SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID | easy |
1,758 | gymnast | [
"gymnast",
"people"
] | What are the distinct hometowns of gymnasts with total points more than 57.5? | SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5 | medium |
1,759 | gymnast | [
"gymnast",
"people"
] | Give the different hometowns of gymnasts that have a total point score of above 57.5. | SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5 | medium |
1,760 | gymnast | [
"gymnast",
"people"
] | What are the hometowns of gymnasts and the corresponding number of gymnasts? | SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown | medium |
1,761 | gymnast | [
"gymnast",
"people"
] | How many gymnasts are from each hometown? | SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown | medium |
1,762 | gymnast | [
"gymnast",
"people"
] | What is the most common hometown of gymnasts? | SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1 | extra |
1,763 | gymnast | [
"gymnast",
"people"
] | Return the hometown that is most common among gymnasts. | SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1 | extra |
1,764 | gymnast | [
"gymnast",
"people"
] | What are the hometowns that are shared by at least two gymnasts? | SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2 | medium |
1,765 | gymnast | [
"gymnast",
"people"
] | Give the hometowns from which two or more gymnasts are from. | SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2 | medium |
1,766 | gymnast | [
"gymnast",
"people"
] | List the names of gymnasts in ascending order by their heights. | SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC | medium |
1,767 | gymnast | [
"gymnast",
"people"
] | What are the names of gymnasts, ordered by their heights ascending? | SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC | medium |
1,768 | gymnast | [
"gymnast",
"people"
] | List the distinct hometowns that are not associated with any gymnast. | SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID | hard |
1,769 | gymnast | [
"gymnast",
"people"
] | From which hometowns did no gymnasts come from? | SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID | hard |
1,770 | gymnast | [
"people"
] | Show the hometowns shared by people older than 23 and younger than 20. | SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20 | hard |
1,771 | gymnast | [
"people"
] | From which hometowns did both people older than 23 and younger than 20 come from? | SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20 | hard |
1,772 | gymnast | [
"people"
] | How many distinct hometowns did these people have? | SELECT count(DISTINCT Hometown) FROM people | easy |
1,773 | gymnast | [
"people"
] | Count the number of different hometowns of these people. | SELECT count(DISTINCT Hometown) FROM people | easy |
1,774 | gymnast | [
"gymnast",
"people"
] | Show the ages of gymnasts in descending order of total points. | SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC | medium |
1,775 | gymnast | [
"gymnast",
"people"
] | What are the ages of the gymnasts, ordered descending by their total points? | SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC | medium |
1,776 | small_bank_1 | [
"savings",
"accounts"
] | Find the total savings balance of all accounts except the account with name ‘Brown’. | SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != 'Brown' | medium |
1,777 | small_bank_1 | [
"savings",
"accounts"
] | What is the total balance of savings accounts not belonging to someone with the name Brown? | SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != 'Brown' | medium |
1,778 | small_bank_1 | [
"accounts"
] | How many accounts are there in total? | SELECT count(*) FROM accounts | easy |
1,779 | small_bank_1 | [
"accounts"
] | Count the number of accounts. | SELECT count(*) FROM accounts | easy |
1,780 | small_bank_1 | [
"checking"
] | What is the total checking balance in all accounts? | SELECT sum(balance) FROM checking | easy |
1,781 | small_bank_1 | [
"checking"
] | Find the total balance across checking accounts. | SELECT sum(balance) FROM checking | easy |
1,782 | small_bank_1 | [
"checking"
] | Find the average checking balance. | SELECT avg(balance) FROM checking | easy |
1,783 | small_bank_1 | [
"checking"
] | What is the average balance in checking accounts? | SELECT avg(balance) FROM checking | easy |
1,784 | small_bank_1 | [
"savings"
] | How many accounts have a savings balance above the average savings balance? | SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings) | hard |
1,785 | small_bank_1 | [
"savings"
] | Find the number of accounts with a savings balance that is higher than the average savings balance. | SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings) | hard |
1,786 | small_bank_1 | [
"checking",
"accounts"
] | Find the name and id of accounts whose checking balance is below the maximum checking balance. | SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking) | extra |
1,787 | small_bank_1 | [
"checking",
"accounts"
] | What are the customer id and name corresponding to accounts with a checking balance less than the largest checking balance? | SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking) | extra |
1,788 | small_bank_1 | [
"checking",
"accounts"
] | What is the checking balance of the account whose owner’s name contains the substring ‘ee’? | SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '%ee%' | hard |
1,789 | small_bank_1 | [
"checking",
"accounts"
] | Find the balance of the checking account belonging to an owner whose name contains 'ee'. | SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '%ee%' | hard |
1,790 | small_bank_1 | [
"checking",
"savings",
"accounts"
] | Find the checking balance and saving balance in the Brown’s account. | SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = 'Brown' | hard |
1,791 | small_bank_1 | [
"checking",
"savings",
"accounts"
] | What are the checking and savings balances in accounts belonging to Brown? | SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = 'Brown' | hard |
1,792 | small_bank_1 | [
"checking",
"savings",
"accounts"
] | Find the names of accounts whose checking balance is above the average checking balance, but savings balance is below the average savings balance. | SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings) | extra |
1,793 | small_bank_1 | [
"checking",
"savings",
"accounts"
] | What are the names of accounts with checking balances greater than the average checking balance and savings balances below the average savings balance? | SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings) | extra |
1,794 | small_bank_1 | [
"checking",
"savings",
"accounts"
] | Find the checking balance of the accounts whose savings balance is higher than the average savings balance. | SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings)) | extra |
1,795 | small_bank_1 | [
"checking",
"savings",
"accounts"
] | What are the balances of checking accounts belonging to people with savings balances greater than the average savings balance? | SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings)) | extra |
1,796 | small_bank_1 | [
"accounts"
] | List all customers’ names in the alphabetical order. | SELECT name FROM accounts ORDER BY name | easy |
1,797 | small_bank_1 | [
"accounts"
] | What are the names of all the customers in alphabetical order? | SELECT name FROM accounts ORDER BY name | easy |
1,798 | small_bank_1 | [
"checking",
"savings",
"accounts"
] | Find the name of account that has the lowest total checking and saving balance. | SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1 | extra |
1,799 | small_bank_1 | [
"checking",
"savings",
"accounts"
] | What is the name corresponding to the accoung with the lowest sum of checking and savings balances? | SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1 | extra |
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