query_id
int64 0
1.53k
| database_id
stringclasses 11
values | table_id
sequencelengths 1
4
| query
stringlengths 23
286
| answer
stringlengths 29
1.45k
| difficulty
stringclasses 3
values | evidence
stringlengths 0
591
|
|---|---|---|---|---|---|---|
700 | codebase_community | [
"votes"
] | Identify the number of posts that offer a bounty amount over 30. | SELECT COUNT(id) FROM votes WHERE BountyAmount >= 30 | simple | bounty amount over 30 refers to BountyAmount > = 30; |
701 | codebase_community | [
"users",
"posts"
] | Among all the posts posted by the most influential user, identify the percentage with a score above 50. | SELECT CAST(SUM(CASE WHEN T2.Score >= 50 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.Id) FROM users T1 INNER JOIN posts T2 ON T1.Id = T2.OwnerUserId INNER JOIN ( SELECT MAX(Reputation) AS max_reputation FROM users ) T3 ON T1.Reputation = T3.max_reputation | challenging | The user with higher reputation has more influence; DIVIDE(COUNT(stats_posts.Id where Score > = 50 and MAX(Reputation))), COUNT(stats_posts.Id where MAX(Reputation)) as percentage; |
702 | codebase_community | [
"posts"
] | How many posts have a score less than 20? | SELECT COUNT(id) FROM posts WHERE Score < 20 | simple | score less than 20 refers to Score < 20; |
703 | codebase_community | [
"tags"
] | Among the tags with tag ID below 15, how many of them have 20 count of posts and below? | SELECT COUNT(id) FROM tags WHERE Count <= 20 AND Id < 15 | simple | ID below 15 refers to Id < 15; have 20 count of posts and below refers to Count < = 20; |
704 | codebase_community | [
"tags"
] | What is the excerpt post ID and wiki post ID of the tag named sample? | SELECT ExcerptPostId, WikiPostId FROM tags WHERE TagName = 'sample' | simple | tag named sample refers to TagName = 'sample'; |
705 | codebase_community | [
"users",
"comments"
] | Give the user's reputation and up vote number of the user that commented "fine, you win :)". | SELECT T2.Reputation, T2.UpVotes FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.Text = 'fine, you win :)' | simple | Text = 'fine, you win :)'; |
706 | codebase_community | [
"comments",
"posts"
] | Give the texts commented on the post about linear regression. | SELECT T1.Text FROM comments AS T1 INNER JOIN posts AS T2 ON T1.PostId = T2.Id WHERE T2.Title LIKE '%linear regression%' | simple | Title = 'How can I adapt ANOVA for binary data?'; |
707 | codebase_community | [
"comments",
"posts"
] | Among the posts with views ranging from 100 to 150, what is the comment with the highest score? | SELECT Text FROM comments WHERE PostId IN ( SELECT Id FROM posts WHERE ViewCount BETWEEN 100 AND 150 ) ORDER BY Score DESC LIMIT 1 | moderate | views ranging from 100 to 150 refers to ViewCount BETWEEN 100 and 150; comment with the highest score refers to Text where MAX(Score); |
708 | codebase_community | [
"users",
"comments"
] | List the creation date and age of the user that commented with webiste. | SELECT T2.CreationDate, T2.Age FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.text LIKE '%http://%' | moderate | commented with webiste refers to the value contains 'http://' |
709 | codebase_community | [
"comments",
"posts"
] | In comments with 0 score, how many of the posts have view count lower than 5? | SELECT COUNT(T1.Id) FROM comments AS T1 INNER JOIN posts AS T2 ON T1.PostId = T2.Id WHERE T2.ViewCount < 5 AND T2.Score = 0 | simple | view count lower than 5 refers to ViewCount < 5; |
710 | codebase_community | [
"comments",
"posts"
] | In posts with 1 comment, how many of the comments have 0 score? | SELECT COUNT(T1.id) FROM comments AS T1 INNER JOIN posts AS T2 ON T1.PostId = T2.Id WHERE T2.CommentCount = 1 AND T2.Score = 0 | simple | in posts with 1 comment refers to CommentCount = 1; |
711 | codebase_community | [
"users",
"comments"
] | Among products comments with 0 score, what is the total number of users ages 40 years old? | SELECT COUNT(T1.id) FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.Score = 0 AND T2.Age = 40 | simple | |
712 | codebase_community | [
"comments",
"posts"
] | What is the post ID and the comments commented in the post titled by "Group differences on a five point Likert item"? | SELECT T2.Id, T1.Text FROM comments AS T1 INNER JOIN posts AS T2 ON T1.PostId = T2.Id WHERE T2.Title = 'Group differences on a five point Likert item' | simple | Title = 'Group differences on a five point Likert item'; |
713 | codebase_community | [
"users",
"comments"
] | What is the up vote number of the user that commented "R is also lazy evaluated."? | SELECT T2.UpVotes FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.Text = 'R is also lazy evaluated.' | simple | commented "R is also lazy evaluated." refers to Text of the comment; |
714 | codebase_community | [
"users",
"comments"
] | List the comments commented by the user with a username of Harvey Motulsky. | SELECT T1.Text FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T2.DisplayName = 'Harvey Motulsky' | simple | comments refer to Text; username of Harvey Motulsky refers to DisplayName = 'Harvey Motulsky'; |
715 | codebase_community | [
"users",
"comments"
] | In comments with score between 1 to 5, list down the display names of the users with 0 down votes. | SELECT T2.DisplayName FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.Score BETWEEN 1 AND 5 AND T2.DownVotes = 0 | simple | DownVotes = 0; Score BETWEEN 1 and 5 |
716 | codebase_community | [
"users",
"comments"
] | Among the comments with scores between 5 to 10, what is the percentage of the users with 0 up votes? | SELECT CAST(SUM(IIF(T1.UpVotes = 0, 1, 0)) AS REAL) / COUNT(T1.Id) AS per FROM users AS T1 INNER JOIN comments AS T2 ON T1.Id = T2.UserId WHERE T2.Score BETWEEN 5 AND 10 | moderate | DIVIDE(COUNT(UserId where UpVotes = 0 and Score BETWEEN 5 and 10)), (COUNT(UserId where Score BETWEEN 5 and 10)) as percentage; |
717 | superhero | [
"superhero",
"superpower",
"hero_power"
] | Please list all the superpowers of 3-D Man. | SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = '3-D Man' | simple | 3-D Man refers to superhero_name = '3-D Man'; superpowers refers to power_name |
718 | superhero | [
"superpower",
"hero_power"
] | How many superheroes have the super power of "Super Strength"? | SELECT COUNT(T1.hero_id) FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T2.power_name = 'Super Strength' | simple | super power of "Super Strength" refers to power_name = 'Super Strength' |
719 | superhero | [
"superhero",
"superpower",
"hero_power"
] | Among the superheroes with the super power of "Super Strength", how many of them have a height of over 200cm? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Super Strength' AND T1.height_cm > 200 | moderate | super power of "Super Strength" refers to power_name = 'Super Strength'; a height of over 200cm refers to height_cm > 200 |
720 | superhero | [
"superhero",
"hero_power"
] | Please list the full names of all the superheroes with over 15 super powers. | SELECT DISTINCT T1.full_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id GROUP BY T1.full_name HAVING COUNT(T2.power_id) > 15 | simple | 15 super powers refers to COUNT(full_name) > 15 |
721 | superhero | [
"superhero",
"colour"
] | How many superheroes have blue eyes? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T2.colour = 'Blue' | simple | blue eyes refers to colour = 'Blue' and eye_colour_id = colour.id; |
722 | superhero | [
"superhero",
"colour"
] | What is the colour of Apocalypse's skin? | SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.skin_colour_id = T2.id WHERE T1.superhero_name = 'Apocalypse' | simple | Apocalypse refers to superhero_name = 'Apocalypse'; colour of skin refers to colour where skin_colour_id = colour.id |
723 | superhero | [
"superhero",
"colour",
"superpower",
"hero_power"
] | Among the superheroes with blue eyes, how many of them have the super power of "Agility"? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id INNER JOIN colour AS T4 ON T1.eye_colour_id = T4.id WHERE T3.power_name = 'Agility' AND T4.colour = 'Blue' | moderate | blue eyes refers to colour = 'Blue' and eye_colour_id = colour.id; super power of "Agility" refers to power_name = 'Agility' |
724 | superhero | [
"superhero",
"colour"
] | Please list the superhero names of all the superheroes that have blue eyes and blond hair. | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T2.colour = 'Blue' AND T3.colour = 'Blond' | challenging | blue eyes refers to colour = 'Blue' and eye_colour_id = colour.id; blond hair refers to colour = 'Blond' and hair_colour_id = colour.id; super power of "Agility" refers to power_name = 'Agility' |
725 | superhero | [
"publisher",
"superhero"
] | How many superheroes are published by Marvel Comics? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'Marvel Comics' | simple | published by Marvel Comics refers to publisher_name = 'Marvel Comics' |
726 | superhero | [
"publisher",
"superhero"
] | Please give the full name of the tallest hero published by Marvel Comics. | SELECT T1.full_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'Marvel Comics' ORDER BY T1.height_cm DESC LIMIT 1 | moderate | the tallest hero refers to MAX(height_cm); published by Marvel Comics refers to publisher_name = 'Marvel Comics' |
727 | superhero | [
"publisher",
"superhero"
] | Who is the publisher of Sauron? | SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.superhero_name = 'Sauron' | simple | the publisher refers to publisher_name; Sauron refers to superhero_name = 'Sauron' |
728 | superhero | [
"publisher",
"superhero",
"colour"
] | Among the superheroes from Marvel Comics, how many of them have blue eyes? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN colour AS T3 ON T1.eye_colour_id = T3.id WHERE T2.publisher_name = 'Marvel Comics' AND T3.colour = 'Blue' | moderate | the superheroes from Marvel Comics refers to publisher_name = 'Marvel Comics'; blue eyes refers to colour = 'Blue' and eye_colour_id = colour.id |
729 | superhero | [
"publisher",
"superhero"
] | What is the average height of the superheroes from Marvel Comics? | SELECT AVG(T1.height_cm) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'Marvel Comics' | simple | superheroes from Marvel Comics refers to publisher_name = 'Marvel Comics'; average height of the superheroes refers to AVG(height_cm) |
730 | superhero | [
"publisher",
"superhero",
"superpower",
"hero_power"
] | Among the superheroes from Marvel Comics, what is the percentage of those who have the super power of "Super Strength"? | SELECT CAST(COUNT(CASE WHEN T3.power_name = 'Super Strength' THEN T1.id ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id INNER JOIN publisher AS T4 ON T1.publisher_id = T4.id WHERE T4.publisher_name = 'Marvel Comics' | challenging | the superheroes from Marvel Comics refers to publisher_name = 'Marvel Comics'; super power of "Super Strength" refers to power_name = 'Super Strength'; Calculation = MULTIPLY(DIVIDE(SUM(power_name = 'Super Strength'), COUNT(id)), 100) |
731 | superhero | [
"publisher",
"superhero"
] | How many superheroes did DC Comics publish? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'DC Comics' | simple | superheroes that DC Comics published refers to publisher_name = 'DC Comics' |
732 | superhero | [
"publisher",
"superhero",
"hero_attribute",
"attribute"
] | Which publisher published the slowest superhero? | SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN hero_attribute AS T3 ON T1.id = T3.hero_id INNER JOIN attribute AS T4 ON T3.attribute_id = T4.id WHERE T4.attribute_name = 'Speed' ORDER BY T3.attribute_value LIMIT 1 | moderate | the slowest superhero refers to attribute_name = 'Speed' where MIN(attribute_value); publisher refers to publisher_name |
733 | superhero | [
"publisher",
"superhero",
"colour"
] | How many gold-eyed superheroes did Marvel Comics publish? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN colour AS T3 ON T1.eye_colour_id = T3.id WHERE T2.publisher_name = 'Marvel Comics' AND T3.colour = 'Gold' | moderate | gold-eyed refers to colour = 'Gold' where eye_colour_id = colour.id; superheroes that Marvel Comics published refers to publisher_name = 'Marvel Comics' |
734 | superhero | [
"publisher",
"superhero"
] | What is the publisher's name of Blue Beetle II? | SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.superhero_name = 'Blue Beetle II' | simple | Blue Beetle II refers to superhero_name = 'Blue Beetle II' |
735 | superhero | [
"superhero",
"colour"
] | How many superheroes with blonde hair are there? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.hair_colour_id = T2.id WHERE T2.colour = 'Blond' | simple | superheroes with blonde hair refers to colour = 'Blond' where hair_colour_id = colour.id |
736 | superhero | [
"attribute",
"superhero",
"hero_attribute"
] | Who is the dumbest superhero? | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Intelligence' ORDER BY T2.attribute_value LIMIT 1 | moderate | the dumbest superhero refers to MIN(attribute_value) where attribute_name = 'Intelligence' |
737 | superhero | [
"superhero",
"race"
] | What is Copycat's race? | SELECT T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.superhero_name = 'Copycat' | simple | Copycat is the superhero_name; |
738 | superhero | [
"attribute",
"hero_attribute"
] | How many superheroes have durability of less than 50? | SELECT COUNT(T1.hero_id) FROM hero_attribute AS T1 INNER JOIN attribute AS T2 ON T1.attribute_id = T2.id WHERE T2.attribute_name = 'Durability' AND T1.attribute_value < 50 | simple | durability of less than 50 refers to attribute_name = 'Durability' AND attribute_value < 50 |
739 | superhero | [
"superhero",
"superpower",
"hero_power"
] | What are the names of the superheroes with the power of death touch? | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Death Touch' | moderate | name of superheroes refers to refers to superhero_name; the power of death touch refers to power_name = 'Death Touch' |
740 | superhero | [
"attribute",
"superhero",
"hero_attribute",
"gender"
] | How many female superheroes have a strength value of 100? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id INNER JOIN gender AS T4 ON T1.gender_id = T4.id WHERE T3.attribute_name = 'Strength' AND T2.attribute_value = 100 AND T4.gender = 'Female' | moderate | female refers to gender = 'Female'; strength value of 100 refers to attribute_name = 'Strength' AND attribute_value = 100 |
741 | superhero | [
"superhero",
"hero_power"
] | What is the name of the superhero that has the most powers? | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id GROUP BY T1.superhero_name ORDER BY COUNT(T2.hero_id) DESC LIMIT 1 | simple | name of the superhero refers to superhero_name; superhero that has the most powers refers to MAX(COUNT(superhero_name)) |
742 | superhero | [
"superhero",
"race"
] | How many vampire superheroes are there? | SELECT COUNT(T1.superhero_name) FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Vampire' | simple | vampire superheroes refers to race = 'Vampire' |
743 | superhero | [
"publisher",
"superhero",
"alignment"
] | What is the percentage of superheroes who act in their own self-interest or make decisions based on their own moral code? Indicate how many of the said superheroes were published by Marvel Comics. | SELECT (CAST(COUNT(*) AS REAL) * 100 / (SELECT COUNT(*) FROM superhero)), CAST(SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) AS REAL) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN alignment AS T3 ON T3.id = T1.alignment_id WHERE T3.alignment = 'Bad' | challenging | published by Marvel Comics refers to publisher_name = 'Marvel Comics'; superheroes who act in their own self-interest or make decisions based on their own moral code refers to alignment = 'Bad'; calculation = MULTIPLY(DIVIDE(SUM(alignment = 'Bad); count(id)), 100) |
744 | superhero | [
"publisher",
"superhero"
] | Between DC and Marvel Comics, which publisher has published more superheroes? Find the difference in the number of superheroes they have published. | SELECT SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.publisher_name = 'DC Comics' THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id | challenging | DC refers to publisher_name = 'DC Comics'; Marvel Comics refers to publisher_name = 'Marvel Comics'; calculation = SUBTRACT(SUM(publisher_name = 'Marvel Comics'), SUM(publisher_name = 'DC Comics')) |
745 | superhero | [
"publisher"
] | Give the publisher ID of Star Trek. | SELECT id FROM publisher WHERE publisher_name = 'Star Trek' | simple | Star Trek is the publisher_name; |
746 | superhero | [
"hero_attribute"
] | Calculate the average attribute value of all superheroes. | SELECT AVG(attribute_value) FROM hero_attribute | simple | average attribute value of all superheroes refers to AVG(attribute_value) |
747 | superhero | [
"superhero"
] | What is the total number of superheroes without full name? | SELECT COUNT(id) FROM superhero WHERE full_name IS NULL | simple | superheroes without full name refers to full_name IS NULL |
748 | superhero | [
"superhero",
"colour"
] | What is the eye colour of superhero with superhero ID 75? | SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.id = 75 | simple | eye colour refers to colour where eye_colour_id = colour.id; |
749 | superhero | [
"superhero",
"superpower",
"hero_power"
] | Provide the superpowers of the superhero called Deathlok. | SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = 'Deathlok' | simple | superpowers refers to power_name; Deathlok refers to superhero_name = 'Deathlok' |
750 | superhero | [
"superhero",
"gender"
] | What is the average weight of all female superheroes? | SELECT AVG(T1.weight_kg) FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id WHERE T2.gender = 'Female' | simple | female refers to gender_id = 2; average weight refers to AVG(weight_kg) |
751 | superhero | [
"superhero",
"superpower",
"gender",
"hero_power"
] | List down at least five superpowers of male superheroes. | SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T3.id = T2.power_id INNER JOIN gender AS T4 ON T4.id = T1.gender_id WHERE T4.gender = 'Male' LIMIT 5 | moderate | male refers to gender = 'Male'; superpowers refers to power_name; |
752 | superhero | [
"superhero",
"race"
] | Give the name of the alien superheroes. | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Alien' | simple | alien superheroes refers to race = 'Alien'; name of superhero refers to superhero_name; |
753 | superhero | [
"superhero",
"colour"
] | Among the superheroes with height from 170 to 190, list the names of the superheroes with no eye color. | SELECT DISTINCT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.height_cm BETWEEN 170 AND 190 AND T2.colour LIKE 'No Colour' | moderate | height from 170 to 190 refers to height_cm BETWEEN 170 AND 190; no eye color refers to eye_colour_id = 1 |
754 | superhero | [
"superpower",
"hero_power"
] | What is the superpower of hero ID 56? | SELECT T2.power_name FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T1.hero_id = 56 | simple | superpower refers to hero_power |
755 | superhero | [
"superhero",
"race"
] | List down at least five full name of Demi-God superheroes. | SELECT T1.full_name FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Demi-God' | simple | Demi-God superheroes refers to race = 'Demi-God' |
756 | superhero | [
"superhero",
"alignment"
] | How many bad superheroes are there? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Bad' | simple | bad superheroes refers to alignment_id = Bad |
757 | superhero | [
"superhero",
"race"
] | Identify the race of the superhero who weighed 169 kg. | SELECT T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.weight_kg = 169 | simple | weighed 169 kg refers to weight_kg = 169 |
758 | superhero | [
"superhero",
"race",
"colour"
] | Provide the hair colour of the human superhero who is 185 cm tall. | SELECT DISTINCT T3.colour FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T1.height_cm = 185 AND T2.race = 'Human' | moderate | 185 cm tall refers to height_cm = 185; human superhero refers to race = 'human'; hair colour refers to colour where hair_colour_id = colour.id; |
759 | superhero | [
"superhero",
"colour"
] | What is the eye clolour of the heaviest superhero? | SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id ORDER BY T1.weight_kg DESC LIMIT 1 | simple | the heaviest superhero refers to MAX(weight_kg); eye colour refers to colour where eye_colour_id = colour.id; |
760 | superhero | [
"publisher",
"superhero"
] | In superheroes with height between 150 to 180, what is the percentage of heroes published by Marvel Comics? | SELECT CAST(COUNT(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.height_cm BETWEEN 150 AND 180 | challenging | height between 150 to 180 refers to height_cm BETWEEN 150 AND 180; heroes published by Marvel Comics refers to publisher_id = 13; calculation = MULTIPLY(DIVIDE(SUM(publisher.id = 13)), COUNT(publisher.id), 100) |
761 | superhero | [
"superhero",
"gender"
] | Among the male superheroes, list the full names of superheroes with weight greater than the 79% average weight of all superheroes. | SELECT T1.full_name FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id WHERE T2.gender = 'Male' AND T1.weight_kg * 100 > ( SELECT AVG(weight_kg) FROM superhero ) * 79 | moderate | Calculation = weight_kg > MULTIPLY(AVG(weight_kg), 0.79) |
762 | superhero | [
"superpower",
"hero_power"
] | Which power do superheroes have the most of? | SELECT T2.power_name FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id GROUP BY T2.power_name ORDER BY COUNT(T1.hero_id) DESC LIMIT 1 | simple | power that superheroes have the most refers to MAX(COUNT(power_name)) |
763 | superhero | [
"superhero",
"hero_attribute"
] | Indicate the attribute value of superhero Abomination. | SELECT T2.attribute_value FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id WHERE T1.superhero_name = 'Abomination' | simple | Abomination refers to superhero_name = 'Abomination'; |
764 | superhero | [
"superpower",
"hero_power"
] | What are the superpowers of heroes with ID 1? | SELECT DISTINCT T2.power_name FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T1.hero_id = 1 | simple | superpowers refers to power_name; heroes with ID 1 refers to hero_id = 1; |
765 | superhero | [
"superpower",
"hero_power"
] | How many heroes have stealth power? | SELECT COUNT(T1.hero_id) FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T2.power_name = 'Stealth' | simple | stealth power refers to power_name = 'stealth'; |
766 | superhero | [
"attribute",
"superhero",
"hero_attribute"
] | What is the hero's full name with the highest attribute in strength? | SELECT T1.full_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Strength' ORDER BY T2.attribute_value DESC LIMIT 1 | moderate | highest attribute in strength refers to MAX(attribute_value) WHERE attribute_name = 'strength'; |
767 | superhero | [
"superhero",
"colour"
] | What is the average of superheroes with no skin colour? | SELECT CAST(COUNT(*) AS REAL) / SUM(CASE WHEN T2.id = 1 THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.skin_colour_id = T2.id | simple | average = DIVIDE(COUNT(superhero.id), SUM(skin_colour_id = 1)); no skin colour refers to skin_colour_id WHERE colour.id = 1; |
768 | superhero | [
"publisher",
"superhero"
] | How many superheroes were published by Dark Horse Comics? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'Dark Horse Comics' | simple | published by Dark Horse Comics refers to publisher_name = 'Dark Horse Comics'; |
769 | superhero | [
"attribute",
"superhero",
"hero_attribute",
"publisher"
] | Which superhero has the most durability published by Dark Horse Comics? | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T3.id = T2.attribute_id INNER JOIN publisher AS T4 ON T4.id = T1.publisher_id WHERE T4.publisher_name = 'Dark Horse Comics' AND T3.attribute_name = 'Durability' ORDER BY T2.attribute_value DESC LIMIT 1 | challenging | which superhero refers to superhero_name; most durability refers to MAX(attribute_value) WHERE attribute_name = 'durability'; published by Dark Horse Comics refers to publisher_name = 'Dark Horse Comics'; |
770 | superhero | [
"superhero",
"colour"
] | What is the eyes colour of Abraham Sapien? | SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.full_name = 'Abraham Sapien' | simple | eye colour refers to colour.colour where eye_colour_id = colour.id; Abraham Sapien is the full name of superhero; |
771 | superhero | [
"superhero",
"superpower",
"hero_power"
] | List the name of superheroes with flight power. | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Flight' | simple | name of superheroes refers to superhero_name; flight power refers to power_name = 'Flight'; |
772 | superhero | [
"publisher",
"superhero",
"gender"
] | List the eyes, hair and skin colour of all female superheroes published by Dark Horse Comics. | SELECT T1.eye_colour_id, T1.hair_colour_id, T1.skin_colour_id FROM superhero AS T1 INNER JOIN publisher AS T2 ON T2.id = T1.publisher_id INNER JOIN gender AS T3 ON T3.id = T1.gender_id WHERE T2.publisher_name = 'Dark Horse Comics' AND T3.gender = 'Female' | challenging | eyes refers to eye_colour_id; hair refers to hair_colour_id; skin colour refers to skin_colour_id; female superheroes refers to gender = 'Female'; published by Dark Horse Comics refers to publisher_name = 'Dark Horse Comics'; |
773 | superhero | [
"publisher",
"superhero"
] | Which superhero has the same eyes, hair and skin colour? Indicate the publisher of the superhero. | SELECT T1.superhero_name, T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.eye_colour_id = T1.hair_colour_id AND T1.eye_colour_id = T1.skin_colour_id | challenging | which superhero refers to superhero_name; the same eyes, hair and skin colour refers to hair_colour_id = skin_colour_id AND hair_colour_id = eye_colour_id; publisher refers to publisher_name; |
774 | superhero | [
"superhero",
"race"
] | Which group does superhero A-Bomb belong to? | SELECT T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.superhero_name = 'A-Bomb' | simple | group refers to race; A-Bomb refers to superhero_name = 'A-Bomb'; |
775 | superhero | [
"superhero",
"gender",
"colour"
] | What is the percentage of blue female superheroes among all female superheroes? | SELECT CAST(COUNT(CASE WHEN T3.colour = 'Blue' THEN T1.id ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id INNER JOIN colour AS T3 ON T1.skin_colour_id = T3.id WHERE T2.gender = 'Female' | challenging | percentage = MULTIPLY(DIVIDE(SUM(colour = 'Blue' WHERE gender = 'Female'), COUNT(gender = 'Female')), 100); blue refers to the color; female refers to gender = 'Female'; |
776 | superhero | [
"superhero",
"race"
] | Provide the hero name and race of Charles Chandler. | SELECT T1.superhero_name, T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.full_name = 'Charles Chandler' | simple | hero name refers to superhero_name; Charles Chandler is the full name of superhero; |
777 | superhero | [
"superhero",
"gender"
] | What is the gender of Agent 13 hero? | SELECT T2.gender FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id WHERE T1.superhero_name = 'Agent 13' | simple | Agent 13 hero refers to superhero_name = 'Agent 13'; |
778 | superhero | [
"superhero",
"superpower",
"hero_power"
] | Provide superheroes' names who have the adaptation power. | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Adaptation' | simple | adaptation power refers to power_name = 'Adaptation'; |
779 | superhero | [
"superhero",
"hero_power"
] | How many powers does Amazo hero have? | SELECT COUNT(T1.power_id) FROM hero_power AS T1 INNER JOIN superhero AS T2 ON T1.hero_id = T2.id WHERE T2.superhero_name = 'Amazo' | simple | Amazo hero refers to superhero_name = 'Amazo'; |
780 | superhero | [
"superhero",
"superpower",
"hero_power"
] | List the powers of Hunter Zolomon. | SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.full_name = 'Hunter Zolomon' | simple | Hunter Zolomon is the full name of superhero; list the powers refers to power_name; |
781 | superhero | [
"superhero",
"colour"
] | Provide the heights of the heroes whose eye colours are amber. | SELECT T1.height_cm FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T2.colour = 'Amber' | simple | heights of the heroes refers to height_cm; eye colours are amber refers to colour.colour = 'Amber' WHERE eye_colour_id = colour.id; |
782 | superhero | [
"superhero",
"colour"
] | List the heroes' names whose eyes and hair colours are both black. | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id AND T1.hair_colour_id = T2.id WHERE T2.colour = 'Black' | moderate | heroes' names refers to superhero_name; eyes and hair colours are both black refers to eye_colour_id AND hair_colour_id WHERE colour.colour = 'Black'; |
783 | superhero | [
"superhero",
"colour"
] | Provide the eye colours of the heroes whose skin colours are gold. | SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id INNER JOIN colour AS T3 ON T1.skin_colour_id = T3.id WHERE T3.colour = 'Gold' | simple | skin colours are gold refers to colour.colour = 'Gold' WHERE skin_colour_id = colour.id; |
784 | superhero | [
"superhero",
"race"
] | Provide the full names of vampire heroes. | SELECT T1.full_name FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Vampire' | simple | vampire heroes refers to race = 'Vampire'; |
785 | superhero | [
"superhero",
"alignment"
] | Describe the names of neutral alignment superheroes. | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Neutral' | simple | names of superheroes refers to superhero_name; neutral alignment refers to alignment = 'Neutral'; |
786 | superhero | [
"attribute",
"hero_attribute"
] | How many heroes have the highest attribute value in strength? | SELECT COUNT(T1.hero_id) FROM hero_attribute AS T1 INNER JOIN attribute AS T2 ON T1.attribute_id = T2.id WHERE T2.attribute_name = 'Strength' AND T1.attribute_value = ( SELECT MAX(attribute_value) FROM hero_attribute ) | moderate | highest attribute value in strength refers to MAX(attribute_value) WHERE attribute_name = 'Strength'; |
787 | superhero | [
"superhero",
"alignment",
"race"
] | What are the race and alignment of Cameron Hicks? | SELECT T2.race, T3.alignment FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id INNER JOIN alignment AS T3 ON T1.alignment_id = T3.id WHERE T1.superhero_name = 'Cameron Hicks' | simple | Cameron Hicks refers to superhero_name = 'Cameron Hicks'; |
788 | superhero | [
"publisher",
"superhero",
"gender"
] | How many percent of female heroes were published by Marvel Comics? | SELECT CAST(COUNT(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T3.gender = 'Female' | challenging | percent = MULTIPLY(DIVIDE(SUM(gender = 'Female' WHERE publisher_name = 'Marvel Comics'), COUNT(publisher_name = 'Marvel Comics')), 100); female heroes refers to gender = 'Female'; Marvel Comics refers to publisher_name = 'Marvel Comics'; |
789 | superhero | [
"superhero",
"race"
] | Find the average weight of the heroes who are aliens. | SELECT CAST(SUM(T1.weight_kg) AS REAL) / COUNT(T1.id) FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Alien' | simple | average = AVG(weight_kg); aliens refers to race = 'Alien'; |
790 | superhero | [
"superhero"
] | Calculate the difference between Emil Blonsky's weight and Charles Chandler's weight. | SELECT ( SELECT weight_kg FROM superhero WHERE full_name LIKE 'Emil Blonsky' ) - ( SELECT weight_kg FROM superhero WHERE full_name LIKE 'Charles Chandler' ) AS CALCULATE | moderate | difference = SUBTRACT(SUM(weight_kg WHERE full_name = 'Emil Blonsky'), SUM(weight_kg WHERE full_name = 'Charles Chandler')); Emil Blonsky is the full name of superhero; Charles Chandler is the full name of superhero; |
791 | superhero | [
"superhero"
] | Calculate the average height for each superhero. | SELECT CAST(SUM(height_cm) AS REAL) / COUNT(id) FROM superhero | simple | average = DIVIDE(SUM(height_cm), COUNT(all heros)); |
792 | superhero | [
"superhero",
"superpower",
"hero_power"
] | What is Abomination's superpower? | SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = 'Abomination' | simple | Abomination refers to superhero_name = 'Abomination'; superpower refers to power_name; |
793 | superhero | [
"superhero",
"gender",
"race"
] | Among the superheroes with the race of god/eternal, how many of them are male | SELECT COUNT(*) FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id INNER JOIN gender AS T3 ON T3.id = T1.gender_id WHERE T1.race_id = 21 AND T1.gender_id = 1 | simple | race "god/eternal" refers to race_id = 21; male refers to gender.id = 1 |
794 | superhero | [
"attribute",
"superhero",
"hero_attribute"
] | Which hero was the fastest? | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Speed' ORDER BY T2.attribute_value DESC LIMIT 1 | moderate | which hero refers to superhero_name; fastest refers to MAX(attribute_value) WHERE attribute_name = 'Speed'; |
795 | superhero | [
"superhero",
"alignment"
] | How many superheroes have a neutral alignment? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Neutral' | simple | neutral alignment refers to alignment_id = 3; |
796 | superhero | [
"attribute",
"superhero",
"hero_attribute"
] | State all of 3-D Man's attributes along with their values. | SELECT T3.attribute_name, T2.attribute_value FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T1.superhero_name = '3-D Man' | moderate | 3-D Man is the superhero_name. attributes refers to attribute_name; values refers to attribute_value; |
797 | superhero | [
"superhero",
"colour"
] | Which superheroes have blue eyes with brown hair? | SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T2.colour = 'Blue' AND T3.colour = 'Brown' | moderate | which superheroes refers to superhero_name; blue eyes refers to eye_colour_id = 7; brown hair refers to hair_colour_id = 9; |
798 | superhero | [
"publisher",
"superhero"
] | What is the publisher for Hawkman, Karate Kid and Speedy? | SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.superhero_name IN ('Hawkman', 'Karate Kid', 'Speedy') | moderate | publisher refers to publisher_name; Hawkman refers to superhero_name = 'Hawkman'; Karate Kid refers to superhero_name = 'Karate Kid'; Speedy refers to superhero_name = 'Speedy'; |
799 | superhero | [
"publisher",
"superhero"
] | How many superheroes didn't have any publisher? | SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.id = 1 | simple | didn't have any publisher refers to publisher.id = 1; |
Subsets and Splits