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TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
#
#
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Coin sums Problem 31: https://projecteuler.net/problem=31 In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation: 1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p). It is possible to make £2 in the following way: 1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p How many different ways can £2 be made using any number of coins? """ def one_pence() -> int: return 1 def two_pence(x: int) -> int: return 0 if x < 0 else two_pence(x - 2) + one_pence() def five_pence(x: int) -> int: return 0 if x < 0 else five_pence(x - 5) + two_pence(x) def ten_pence(x: int) -> int: return 0 if x < 0 else ten_pence(x - 10) + five_pence(x) def twenty_pence(x: int) -> int: return 0 if x < 0 else twenty_pence(x - 20) + ten_pence(x) def fifty_pence(x: int) -> int: return 0 if x < 0 else fifty_pence(x - 50) + twenty_pence(x) def one_pound(x: int) -> int: return 0 if x < 0 else one_pound(x - 100) + fifty_pence(x) def two_pound(x: int) -> int: return 0 if x < 0 else two_pound(x - 200) + one_pound(x) def solution(n: int = 200) -> int: """Returns the number of different ways can n pence be made using any number of coins? >>> solution(500) 6295434 >>> solution(200) 73682 >>> solution(50) 451 >>> solution(10) 11 """ return two_pound(n) if __name__ == "__main__": print(solution(int(input().strip())))
""" Coin sums Problem 31: https://projecteuler.net/problem=31 In England the currency is made up of pound, £, and pence, p, and there are eight coins in general circulation: 1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p). It is possible to make £2 in the following way: 1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p How many different ways can £2 be made using any number of coins? """ def one_pence() -> int: return 1 def two_pence(x: int) -> int: return 0 if x < 0 else two_pence(x - 2) + one_pence() def five_pence(x: int) -> int: return 0 if x < 0 else five_pence(x - 5) + two_pence(x) def ten_pence(x: int) -> int: return 0 if x < 0 else ten_pence(x - 10) + five_pence(x) def twenty_pence(x: int) -> int: return 0 if x < 0 else twenty_pence(x - 20) + ten_pence(x) def fifty_pence(x: int) -> int: return 0 if x < 0 else fifty_pence(x - 50) + twenty_pence(x) def one_pound(x: int) -> int: return 0 if x < 0 else one_pound(x - 100) + fifty_pence(x) def two_pound(x: int) -> int: return 0 if x < 0 else two_pound(x - 200) + one_pound(x) def solution(n: int = 200) -> int: """Returns the number of different ways can n pence be made using any number of coins? >>> solution(500) 6295434 >>> solution(200) 73682 >>> solution(50) 451 >>> solution(10) 11 """ return two_pound(n) if __name__ == "__main__": print(solution(int(input().strip())))
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" This script demonstrates the implementation of the ReLU function. It's a kind of activation function defined as the positive part of its argument in the context of neural network. The function takes a vector of K real numbers as input and then argmax(x, 0). After through ReLU, the element of the vector always 0 or real number. Script inspired from its corresponding Wikipedia article https://en.wikipedia.org/wiki/Rectifier_(neural_networks) """ from __future__ import annotations import numpy as np def relu(vector: list[float]): """ Implements the relu function Parameters: vector (np.array,list,tuple): A numpy array of shape (1,n) consisting of real values or a similar list,tuple Returns: relu_vec (np.array): The input numpy array, after applying relu. >>> vec = np.array([-1, 0, 5]) >>> relu(vec) array([0, 0, 5]) """ # compare two arrays and then return element-wise maxima. return np.maximum(0, vector) if __name__ == "__main__": print(np.array(relu([-1, 0, 5]))) # --> [0, 0, 5]
""" This script demonstrates the implementation of the ReLU function. It's a kind of activation function defined as the positive part of its argument in the context of neural network. The function takes a vector of K real numbers as input and then argmax(x, 0). After through ReLU, the element of the vector always 0 or real number. Script inspired from its corresponding Wikipedia article https://en.wikipedia.org/wiki/Rectifier_(neural_networks) """ from __future__ import annotations import numpy as np def relu(vector: list[float]): """ Implements the relu function Parameters: vector (np.array,list,tuple): A numpy array of shape (1,n) consisting of real values or a similar list,tuple Returns: relu_vec (np.array): The input numpy array, after applying relu. >>> vec = np.array([-1, 0, 5]) >>> relu(vec) array([0, 0, 5]) """ # compare two arrays and then return element-wise maxima. return np.maximum(0, vector) if __name__ == "__main__": print(np.array(relu([-1, 0, 5]))) # --> [0, 0, 5]
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" This is pure Python implementation of fibonacci search. Resources used: https://en.wikipedia.org/wiki/Fibonacci_search_technique For doctests run following command: python3 -m doctest -v fibonacci_search.py For manual testing run: python3 fibonacci_search.py """ from functools import lru_cache @lru_cache def fibonacci(k: int) -> int: """Finds fibonacci number in index k. Parameters ---------- k : Index of fibonacci. Returns ------- int Fibonacci number in position k. >>> fibonacci(0) 0 >>> fibonacci(2) 1 >>> fibonacci(5) 5 >>> fibonacci(15) 610 >>> fibonacci('a') Traceback (most recent call last): TypeError: k must be an integer. >>> fibonacci(-5) Traceback (most recent call last): ValueError: k integer must be greater or equal to zero. """ if not isinstance(k, int): raise TypeError("k must be an integer.") if k < 0: raise ValueError("k integer must be greater or equal to zero.") if k == 0: return 0 elif k == 1: return 1 else: return fibonacci(k - 1) + fibonacci(k - 2) def fibonacci_search(arr: list, val: int) -> int: """A pure Python implementation of a fibonacci search algorithm. Parameters ---------- arr List of sorted elements. val Element to search in list. Returns ------- int The index of the element in the array. -1 if the element is not found. >>> fibonacci_search([4, 5, 6, 7], 4) 0 >>> fibonacci_search([4, 5, 6, 7], -10) -1 >>> fibonacci_search([-18, 2], -18) 0 >>> fibonacci_search([5], 5) 0 >>> fibonacci_search(['a', 'c', 'd'], 'c') 1 >>> fibonacci_search(['a', 'c', 'd'], 'f') -1 >>> fibonacci_search([], 1) -1 >>> fibonacci_search([.1, .4 , 7], .4) 1 >>> fibonacci_search([], 9) -1 >>> fibonacci_search(list(range(100)), 63) 63 >>> fibonacci_search(list(range(100)), 99) 99 >>> fibonacci_search(list(range(-100, 100, 3)), -97) 1 >>> fibonacci_search(list(range(-100, 100, 3)), 0) -1 >>> fibonacci_search(list(range(-100, 100, 5)), 0) 20 >>> fibonacci_search(list(range(-100, 100, 5)), 95) 39 """ len_list = len(arr) # Find m such that F_m >= n where F_i is the i_th fibonacci number. i = 0 while True: if fibonacci(i) >= len_list: fibb_k = i break i += 1 offset = 0 while fibb_k > 0: index_k = min( offset + fibonacci(fibb_k - 1), len_list - 1 ) # Prevent out of range item_k_1 = arr[index_k] if item_k_1 == val: return index_k elif val < item_k_1: fibb_k -= 1 elif val > item_k_1: offset += fibonacci(fibb_k - 1) fibb_k -= 2 else: return -1 if __name__ == "__main__": import doctest doctest.testmod()
""" This is pure Python implementation of fibonacci search. Resources used: https://en.wikipedia.org/wiki/Fibonacci_search_technique For doctests run following command: python3 -m doctest -v fibonacci_search.py For manual testing run: python3 fibonacci_search.py """ from functools import lru_cache @lru_cache def fibonacci(k: int) -> int: """Finds fibonacci number in index k. Parameters ---------- k : Index of fibonacci. Returns ------- int Fibonacci number in position k. >>> fibonacci(0) 0 >>> fibonacci(2) 1 >>> fibonacci(5) 5 >>> fibonacci(15) 610 >>> fibonacci('a') Traceback (most recent call last): TypeError: k must be an integer. >>> fibonacci(-5) Traceback (most recent call last): ValueError: k integer must be greater or equal to zero. """ if not isinstance(k, int): raise TypeError("k must be an integer.") if k < 0: raise ValueError("k integer must be greater or equal to zero.") if k == 0: return 0 elif k == 1: return 1 else: return fibonacci(k - 1) + fibonacci(k - 2) def fibonacci_search(arr: list, val: int) -> int: """A pure Python implementation of a fibonacci search algorithm. Parameters ---------- arr List of sorted elements. val Element to search in list. Returns ------- int The index of the element in the array. -1 if the element is not found. >>> fibonacci_search([4, 5, 6, 7], 4) 0 >>> fibonacci_search([4, 5, 6, 7], -10) -1 >>> fibonacci_search([-18, 2], -18) 0 >>> fibonacci_search([5], 5) 0 >>> fibonacci_search(['a', 'c', 'd'], 'c') 1 >>> fibonacci_search(['a', 'c', 'd'], 'f') -1 >>> fibonacci_search([], 1) -1 >>> fibonacci_search([.1, .4 , 7], .4) 1 >>> fibonacci_search([], 9) -1 >>> fibonacci_search(list(range(100)), 63) 63 >>> fibonacci_search(list(range(100)), 99) 99 >>> fibonacci_search(list(range(-100, 100, 3)), -97) 1 >>> fibonacci_search(list(range(-100, 100, 3)), 0) -1 >>> fibonacci_search(list(range(-100, 100, 5)), 0) 20 >>> fibonacci_search(list(range(-100, 100, 5)), 95) 39 """ len_list = len(arr) # Find m such that F_m >= n where F_i is the i_th fibonacci number. i = 0 while True: if fibonacci(i) >= len_list: fibb_k = i break i += 1 offset = 0 while fibb_k > 0: index_k = min( offset + fibonacci(fibb_k - 1), len_list - 1 ) # Prevent out of range item_k_1 = arr[index_k] if item_k_1 == val: return index_k elif val < item_k_1: fibb_k -= 1 elif val > item_k_1: offset += fibonacci(fibb_k - 1) fibb_k -= 2 else: return -1 if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
import random from .binary_exp_mod import bin_exp_mod # This is a probabilistic check to test primality, useful for big numbers! # if it's a prime, it will return true # if it's not a prime, the chance of it returning true is at most 1/4**prec def is_prime_big(n, prec=1000): """ >>> from maths.prime_check import is_prime >>> # all(is_prime_big(i) == is_prime(i) for i in range(1000)) # 3.45s >>> all(is_prime_big(i) == is_prime(i) for i in range(256)) True """ if n < 2: return False if n % 2 == 0: return n == 2 # this means n is odd d = n - 1 exp = 0 while d % 2 == 0: d /= 2 exp += 1 # n - 1=d*(2**exp) count = 0 while count < prec: a = random.randint(2, n - 1) b = bin_exp_mod(a, d, n) if b != 1: flag = True for _ in range(exp): if b == n - 1: flag = False break b = b * b b %= n if flag: return False count += 1 return True if __name__ == "__main__": n = abs(int(input("Enter bound : ").strip())) print("Here's the list of primes:") print(", ".join(str(i) for i in range(n + 1) if is_prime_big(i)))
import random from .binary_exp_mod import bin_exp_mod # This is a probabilistic check to test primality, useful for big numbers! # if it's a prime, it will return true # if it's not a prime, the chance of it returning true is at most 1/4**prec def is_prime_big(n, prec=1000): """ >>> from maths.prime_check import is_prime >>> # all(is_prime_big(i) == is_prime(i) for i in range(1000)) # 3.45s >>> all(is_prime_big(i) == is_prime(i) for i in range(256)) True """ if n < 2: return False if n % 2 == 0: return n == 2 # this means n is odd d = n - 1 exp = 0 while d % 2 == 0: d /= 2 exp += 1 # n - 1=d*(2**exp) count = 0 while count < prec: a = random.randint(2, n - 1) b = bin_exp_mod(a, d, n) if b != 1: flag = True for _ in range(exp): if b == n - 1: flag = False break b = b * b b %= n if flag: return False count += 1 return True if __name__ == "__main__": n = abs(int(input("Enter bound : ").strip())) print("Here's the list of primes:") print(", ".join(str(i) for i in range(n + 1) if is_prime_big(i)))
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
#
#
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Information on 2's complement: https://en.wikipedia.org/wiki/Two%27s_complement def twos_complement(number: int) -> str: """ Take in a negative integer 'number'. Return the two's complement representation of 'number'. >>> twos_complement(0) '0b0' >>> twos_complement(-1) '0b11' >>> twos_complement(-5) '0b1011' >>> twos_complement(-17) '0b101111' >>> twos_complement(-207) '0b100110001' >>> twos_complement(1) Traceback (most recent call last): ... ValueError: input must be a negative integer """ if number > 0: raise ValueError("input must be a negative integer") binary_number_length = len(bin(number)[3:]) twos_complement_number = bin(abs(number) - (1 << binary_number_length))[3:] twos_complement_number = ( ( "1" + "0" * (binary_number_length - len(twos_complement_number)) + twos_complement_number ) if number < 0 else "0" ) return "0b" + twos_complement_number if __name__ == "__main__": import doctest doctest.testmod()
# Information on 2's complement: https://en.wikipedia.org/wiki/Two%27s_complement def twos_complement(number: int) -> str: """ Take in a negative integer 'number'. Return the two's complement representation of 'number'. >>> twos_complement(0) '0b0' >>> twos_complement(-1) '0b11' >>> twos_complement(-5) '0b1011' >>> twos_complement(-17) '0b101111' >>> twos_complement(-207) '0b100110001' >>> twos_complement(1) Traceback (most recent call last): ... ValueError: input must be a negative integer """ if number > 0: raise ValueError("input must be a negative integer") binary_number_length = len(bin(number)[3:]) twos_complement_number = bin(abs(number) - (1 << binary_number_length))[3:] twos_complement_number = ( ( "1" + "0" * (binary_number_length - len(twos_complement_number)) + twos_complement_number ) if number < 0 else "0" ) return "0b" + twos_complement_number if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" https://cp-algorithms.com/string/prefix-function.html Prefix function Knuth–Morris–Pratt algorithm Different algorithm than Knuth-Morris-Pratt pattern finding E.x. Finding longest prefix which is also suffix Time Complexity: O(n) - where n is the length of the string """ def prefix_function(input_string: str) -> list: """ For the given string this function computes value for each index(i), which represents the longest coincidence of prefix and suffix for given substring (input_str[0...i]) For the value of the first element the algorithm always returns 0 >>> prefix_function("aabcdaabc") [0, 1, 0, 0, 0, 1, 2, 3, 4] >>> prefix_function("asdasdad") [0, 0, 0, 1, 2, 3, 4, 0] """ # list for the result values prefix_result = [0] * len(input_string) for i in range(1, len(input_string)): # use last results for better performance - dynamic programming j = prefix_result[i - 1] while j > 0 and input_string[i] != input_string[j]: j = prefix_result[j - 1] if input_string[i] == input_string[j]: j += 1 prefix_result[i] = j return prefix_result def longest_prefix(input_str: str) -> int: """ Prefix-function use case Finding longest prefix which is suffix as well >>> longest_prefix("aabcdaabc") 4 >>> longest_prefix("asdasdad") 4 >>> longest_prefix("abcab") 2 """ # just returning maximum value of the array gives us answer return max(prefix_function(input_str)) if __name__ == "__main__": import doctest doctest.testmod()
""" https://cp-algorithms.com/string/prefix-function.html Prefix function Knuth–Morris–Pratt algorithm Different algorithm than Knuth-Morris-Pratt pattern finding E.x. Finding longest prefix which is also suffix Time Complexity: O(n) - where n is the length of the string """ def prefix_function(input_string: str) -> list: """ For the given string this function computes value for each index(i), which represents the longest coincidence of prefix and suffix for given substring (input_str[0...i]) For the value of the first element the algorithm always returns 0 >>> prefix_function("aabcdaabc") [0, 1, 0, 0, 0, 1, 2, 3, 4] >>> prefix_function("asdasdad") [0, 0, 0, 1, 2, 3, 4, 0] """ # list for the result values prefix_result = [0] * len(input_string) for i in range(1, len(input_string)): # use last results for better performance - dynamic programming j = prefix_result[i - 1] while j > 0 and input_string[i] != input_string[j]: j = prefix_result[j - 1] if input_string[i] == input_string[j]: j += 1 prefix_result[i] = j return prefix_result def longest_prefix(input_str: str) -> int: """ Prefix-function use case Finding longest prefix which is suffix as well >>> longest_prefix("aabcdaabc") 4 >>> longest_prefix("asdasdad") 4 >>> longest_prefix("abcab") 2 """ # just returning maximum value of the array gives us answer return max(prefix_function(input_str)) if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Implementing Newton Raphson method in Python # Author: Syed Haseeb Shah (github.com/QuantumNovice) # The Newton-Raphson method (also known as Newton's method) is a way to # quickly find a good approximation for the root of a real-valued function from __future__ import annotations from decimal import Decimal from math import * # noqa: F401, F403 from sympy import diff def newton_raphson( func: str, a: float | Decimal, precision: float = 10**-10 ) -> float: """Finds root from the point 'a' onwards by Newton-Raphson method >>> newton_raphson("sin(x)", 2) 3.1415926536808043 >>> newton_raphson("x**2 - 5*x +2", 0.4) 0.4384471871911695 >>> newton_raphson("x**2 - 5", 0.1) 2.23606797749979 >>> newton_raphson("log(x)- 1", 2) 2.718281828458938 """ x = a while True: x = Decimal(x) - (Decimal(eval(func)) / Decimal(eval(str(diff(func))))) # This number dictates the accuracy of the answer if abs(eval(func)) < precision: return float(x) # Let's Execute if __name__ == "__main__": # Find root of trigonometric function # Find value of pi print(f"The root of sin(x) = 0 is {newton_raphson('sin(x)', 2)}") # Find root of polynomial print(f"The root of x**2 - 5*x + 2 = 0 is {newton_raphson('x**2 - 5*x + 2', 0.4)}") # Find Square Root of 5 print(f"The root of log(x) - 1 = 0 is {newton_raphson('log(x) - 1', 2)}") # Exponential Roots print(f"The root of exp(x) - 1 = 0 is {newton_raphson('exp(x) - 1', 0)}")
# Implementing Newton Raphson method in Python # Author: Syed Haseeb Shah (github.com/QuantumNovice) # The Newton-Raphson method (also known as Newton's method) is a way to # quickly find a good approximation for the root of a real-valued function from __future__ import annotations from decimal import Decimal from math import * # noqa: F401, F403 from sympy import diff def newton_raphson( func: str, a: float | Decimal, precision: float = 10**-10 ) -> float: """Finds root from the point 'a' onwards by Newton-Raphson method >>> newton_raphson("sin(x)", 2) 3.1415926536808043 >>> newton_raphson("x**2 - 5*x +2", 0.4) 0.4384471871911695 >>> newton_raphson("x**2 - 5", 0.1) 2.23606797749979 >>> newton_raphson("log(x)- 1", 2) 2.718281828458938 """ x = a while True: x = Decimal(x) - (Decimal(eval(func)) / Decimal(eval(str(diff(func))))) # This number dictates the accuracy of the answer if abs(eval(func)) < precision: return float(x) # Let's Execute if __name__ == "__main__": # Find root of trigonometric function # Find value of pi print(f"The root of sin(x) = 0 is {newton_raphson('sin(x)', 2)}") # Find root of polynomial print(f"The root of x**2 - 5*x + 2 = 0 is {newton_raphson('x**2 - 5*x + 2', 0.4)}") # Find Square Root of 5 print(f"The root of log(x) - 1 = 0 is {newton_raphson('log(x) - 1', 2)}") # Exponential Roots print(f"The root of exp(x) - 1 = 0 is {newton_raphson('exp(x) - 1', 0)}")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 1: https://projecteuler.net/problem=1 Multiples of 3 and 5 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. """ def solution(n: int = 1000) -> int: """ Returns the sum of all the multiples of 3 or 5 below n. >>> solution(3) 0 >>> solution(4) 3 >>> solution(10) 23 >>> solution(600) 83700 """ result = 0 for i in range(n): if i % 3 == 0 or i % 5 == 0: result += i return result if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 1: https://projecteuler.net/problem=1 Multiples of 3 and 5 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. """ def solution(n: int = 1000) -> int: """ Returns the sum of all the multiples of 3 or 5 below n. >>> solution(3) 0 >>> solution(4) 3 >>> solution(10) 23 >>> solution(600) 83700 """ result = 0 for i in range(n): if i % 3 == 0 or i % 5 == 0: result += i return result if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 8: https://projecteuler.net/problem=8 Largest product in a series The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832. 73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450 Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product? """ from functools import reduce N = ( "73167176531330624919225119674426574742355349194934" "96983520312774506326239578318016984801869478851843" "85861560789112949495459501737958331952853208805511" "12540698747158523863050715693290963295227443043557" "66896648950445244523161731856403098711121722383113" "62229893423380308135336276614282806444486645238749" "30358907296290491560440772390713810515859307960866" "70172427121883998797908792274921901699720888093776" "65727333001053367881220235421809751254540594752243" "52584907711670556013604839586446706324415722155397" "53697817977846174064955149290862569321978468622482" "83972241375657056057490261407972968652414535100474" "82166370484403199890008895243450658541227588666881" "16427171479924442928230863465674813919123162824586" "17866458359124566529476545682848912883142607690042" "24219022671055626321111109370544217506941658960408" "07198403850962455444362981230987879927244284909188" "84580156166097919133875499200524063689912560717606" "05886116467109405077541002256983155200055935729725" "71636269561882670428252483600823257530420752963450" ) def solution(n: str = N) -> int: """ Find the thirteen adjacent digits in the 1000-digit number n that have the greatest product and returns it. >>> solution("13978431290823798458352374") 609638400 >>> solution("13978431295823798458352374") 2612736000 >>> solution("1397843129582379841238352374") 209018880 """ return max( # mypy cannot properly interpret reduce int(reduce(lambda x, y: str(int(x) * int(y)), n[i : i + 13])) for i in range(len(n) - 12) ) if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 8: https://projecteuler.net/problem=8 Largest product in a series The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832. 73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450 Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product? """ from functools import reduce N = ( "73167176531330624919225119674426574742355349194934" "96983520312774506326239578318016984801869478851843" "85861560789112949495459501737958331952853208805511" "12540698747158523863050715693290963295227443043557" "66896648950445244523161731856403098711121722383113" "62229893423380308135336276614282806444486645238749" "30358907296290491560440772390713810515859307960866" "70172427121883998797908792274921901699720888093776" "65727333001053367881220235421809751254540594752243" "52584907711670556013604839586446706324415722155397" "53697817977846174064955149290862569321978468622482" "83972241375657056057490261407972968652414535100474" "82166370484403199890008895243450658541227588666881" "16427171479924442928230863465674813919123162824586" "17866458359124566529476545682848912883142607690042" "24219022671055626321111109370544217506941658960408" "07198403850962455444362981230987879927244284909188" "84580156166097919133875499200524063689912560717606" "05886116467109405077541002256983155200055935729725" "71636269561882670428252483600823257530420752963450" ) def solution(n: str = N) -> int: """ Find the thirteen adjacent digits in the 1000-digit number n that have the greatest product and returns it. >>> solution("13978431290823798458352374") 609638400 >>> solution("13978431295823798458352374") 2612736000 >>> solution("1397843129582379841238352374") 209018880 """ return max( # mypy cannot properly interpret reduce int(reduce(lambda x, y: str(int(x) * int(y)), n[i : i + 13])) for i in range(len(n) - 12) ) if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" The following undirected network consists of seven vertices and twelve edges with a total weight of 243.  The same network can be represented by the matrix below. A B C D E F G A - 16 12 21 - - - B 16 - - 17 20 - - C 12 - - 28 - 31 - D 21 17 28 - 18 19 23 E - 20 - 18 - - 11 F - - 31 19 - - 27 G - - - 23 11 27 - However, it is possible to optimise the network by removing some edges and still ensure that all points on the network remain connected. The network which achieves the maximum saving is shown below. It has a weight of 93, representing a saving of 243 - 93 = 150 from the original network. Using network.txt (right click and 'Save Link/Target As...'), a 6K text file containing a network with forty vertices, and given in matrix form, find the maximum saving which can be achieved by removing redundant edges whilst ensuring that the network remains connected. Solution: We use Prim's algorithm to find a Minimum Spanning Tree. Reference: https://en.wikipedia.org/wiki/Prim%27s_algorithm """ from __future__ import annotations import os from collections.abc import Mapping EdgeT = tuple[int, int] class Graph: """ A class representing an undirected weighted graph. """ def __init__(self, vertices: set[int], edges: Mapping[EdgeT, int]) -> None: self.vertices: set[int] = vertices self.edges: dict[EdgeT, int] = { (min(edge), max(edge)): weight for edge, weight in edges.items() } def add_edge(self, edge: EdgeT, weight: int) -> None: """ Add a new edge to the graph. >>> graph = Graph({1, 2}, {(2, 1): 4}) >>> graph.add_edge((3, 1), 5) >>> sorted(graph.vertices) [1, 2, 3] >>> sorted([(v,k) for k,v in graph.edges.items()]) [(4, (1, 2)), (5, (1, 3))] """ self.vertices.add(edge[0]) self.vertices.add(edge[1]) self.edges[(min(edge), max(edge))] = weight def prims_algorithm(self) -> Graph: """ Run Prim's algorithm to find the minimum spanning tree. Reference: https://en.wikipedia.org/wiki/Prim%27s_algorithm >>> graph = Graph({1,2,3,4},{(1,2):5, (1,3):10, (1,4):20, (2,4):30, (3,4):1}) >>> mst = graph.prims_algorithm() >>> sorted(mst.vertices) [1, 2, 3, 4] >>> sorted(mst.edges) [(1, 2), (1, 3), (3, 4)] """ subgraph: Graph = Graph({min(self.vertices)}, {}) min_edge: EdgeT min_weight: int edge: EdgeT weight: int while len(subgraph.vertices) < len(self.vertices): min_weight = max(self.edges.values()) + 1 for edge, weight in self.edges.items(): if (edge[0] in subgraph.vertices) ^ (edge[1] in subgraph.vertices): if weight < min_weight: min_edge = edge min_weight = weight subgraph.add_edge(min_edge, min_weight) return subgraph def solution(filename: str = "p107_network.txt") -> int: """ Find the maximum saving which can be achieved by removing redundant edges whilst ensuring that the network remains connected. >>> solution("test_network.txt") 150 """ script_dir: str = os.path.abspath(os.path.dirname(__file__)) network_file: str = os.path.join(script_dir, filename) adjacency_matrix: list[list[str]] edges: dict[EdgeT, int] = {} data: list[str] edge1: int edge2: int with open(network_file) as f: data = f.read().strip().split("\n") adjaceny_matrix = [line.split(",") for line in data] for edge1 in range(1, len(adjaceny_matrix)): for edge2 in range(edge1): if adjaceny_matrix[edge1][edge2] != "-": edges[(edge2, edge1)] = int(adjaceny_matrix[edge1][edge2]) graph: Graph = Graph(set(range(len(adjaceny_matrix))), edges) subgraph: Graph = graph.prims_algorithm() initial_total: int = sum(graph.edges.values()) optimal_total: int = sum(subgraph.edges.values()) return initial_total - optimal_total if __name__ == "__main__": print(f"{solution() = }")
""" The following undirected network consists of seven vertices and twelve edges with a total weight of 243.  The same network can be represented by the matrix below. A B C D E F G A - 16 12 21 - - - B 16 - - 17 20 - - C 12 - - 28 - 31 - D 21 17 28 - 18 19 23 E - 20 - 18 - - 11 F - - 31 19 - - 27 G - - - 23 11 27 - However, it is possible to optimise the network by removing some edges and still ensure that all points on the network remain connected. The network which achieves the maximum saving is shown below. It has a weight of 93, representing a saving of 243 - 93 = 150 from the original network. Using network.txt (right click and 'Save Link/Target As...'), a 6K text file containing a network with forty vertices, and given in matrix form, find the maximum saving which can be achieved by removing redundant edges whilst ensuring that the network remains connected. Solution: We use Prim's algorithm to find a Minimum Spanning Tree. Reference: https://en.wikipedia.org/wiki/Prim%27s_algorithm """ from __future__ import annotations import os from collections.abc import Mapping EdgeT = tuple[int, int] class Graph: """ A class representing an undirected weighted graph. """ def __init__(self, vertices: set[int], edges: Mapping[EdgeT, int]) -> None: self.vertices: set[int] = vertices self.edges: dict[EdgeT, int] = { (min(edge), max(edge)): weight for edge, weight in edges.items() } def add_edge(self, edge: EdgeT, weight: int) -> None: """ Add a new edge to the graph. >>> graph = Graph({1, 2}, {(2, 1): 4}) >>> graph.add_edge((3, 1), 5) >>> sorted(graph.vertices) [1, 2, 3] >>> sorted([(v,k) for k,v in graph.edges.items()]) [(4, (1, 2)), (5, (1, 3))] """ self.vertices.add(edge[0]) self.vertices.add(edge[1]) self.edges[(min(edge), max(edge))] = weight def prims_algorithm(self) -> Graph: """ Run Prim's algorithm to find the minimum spanning tree. Reference: https://en.wikipedia.org/wiki/Prim%27s_algorithm >>> graph = Graph({1,2,3,4},{(1,2):5, (1,3):10, (1,4):20, (2,4):30, (3,4):1}) >>> mst = graph.prims_algorithm() >>> sorted(mst.vertices) [1, 2, 3, 4] >>> sorted(mst.edges) [(1, 2), (1, 3), (3, 4)] """ subgraph: Graph = Graph({min(self.vertices)}, {}) min_edge: EdgeT min_weight: int edge: EdgeT weight: int while len(subgraph.vertices) < len(self.vertices): min_weight = max(self.edges.values()) + 1 for edge, weight in self.edges.items(): if (edge[0] in subgraph.vertices) ^ (edge[1] in subgraph.vertices): if weight < min_weight: min_edge = edge min_weight = weight subgraph.add_edge(min_edge, min_weight) return subgraph def solution(filename: str = "p107_network.txt") -> int: """ Find the maximum saving which can be achieved by removing redundant edges whilst ensuring that the network remains connected. >>> solution("test_network.txt") 150 """ script_dir: str = os.path.abspath(os.path.dirname(__file__)) network_file: str = os.path.join(script_dir, filename) adjacency_matrix: list[list[str]] edges: dict[EdgeT, int] = {} data: list[str] edge1: int edge2: int with open(network_file) as f: data = f.read().strip().split("\n") adjaceny_matrix = [line.split(",") for line in data] for edge1 in range(1, len(adjaceny_matrix)): for edge2 in range(edge1): if adjaceny_matrix[edge1][edge2] != "-": edges[(edge2, edge1)] = int(adjaceny_matrix[edge1][edge2]) graph: Graph = Graph(set(range(len(adjaceny_matrix))), edges) subgraph: Graph = graph.prims_algorithm() initial_total: int = sum(graph.edges.values()) optimal_total: int = sum(subgraph.edges.values()) return initial_total - optimal_total if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
import os import sys from . import rsa_key_generator as rkg DEFAULT_BLOCK_SIZE = 128 BYTE_SIZE = 256 def get_blocks_from_text( message: str, block_size: int = DEFAULT_BLOCK_SIZE ) -> list[int]: message_bytes = message.encode("ascii") block_ints = [] for block_start in range(0, len(message_bytes), block_size): block_int = 0 for i in range(block_start, min(block_start + block_size, len(message_bytes))): block_int += message_bytes[i] * (BYTE_SIZE ** (i % block_size)) block_ints.append(block_int) return block_ints def get_text_from_blocks( block_ints: list[int], message_length: int, block_size: int = DEFAULT_BLOCK_SIZE ) -> str: message: list[str] = [] for block_int in block_ints: block_message: list[str] = [] for i in range(block_size - 1, -1, -1): if len(message) + i < message_length: ascii_number = block_int // (BYTE_SIZE**i) block_int = block_int % (BYTE_SIZE**i) block_message.insert(0, chr(ascii_number)) message.extend(block_message) return "".join(message) def encrypt_message( message: str, key: tuple[int, int], block_size: int = DEFAULT_BLOCK_SIZE ) -> list[int]: encrypted_blocks = [] n, e = key for block in get_blocks_from_text(message, block_size): encrypted_blocks.append(pow(block, e, n)) return encrypted_blocks def decrypt_message( encrypted_blocks: list[int], message_length: int, key: tuple[int, int], block_size: int = DEFAULT_BLOCK_SIZE, ) -> str: decrypted_blocks = [] n, d = key for block in encrypted_blocks: decrypted_blocks.append(pow(block, d, n)) return get_text_from_blocks(decrypted_blocks, message_length, block_size) def read_key_file(key_filename: str) -> tuple[int, int, int]: with open(key_filename) as fo: content = fo.read() key_size, n, eor_d = content.split(",") return (int(key_size), int(n), int(eor_d)) def encrypt_and_write_to_file( message_filename: str, key_filename: str, message: str, block_size: int = DEFAULT_BLOCK_SIZE, ) -> str: key_size, n, e = read_key_file(key_filename) if key_size < block_size * 8: sys.exit( "ERROR: Block size is %s bits and key size is %s bits. The RSA cipher " "requires the block size to be equal to or greater than the key size. " "Either decrease the block size or use different keys." % (block_size * 8, key_size) ) encrypted_blocks = [str(i) for i in encrypt_message(message, (n, e), block_size)] encrypted_content = ",".join(encrypted_blocks) encrypted_content = f"{len(message)}_{block_size}_{encrypted_content}" with open(message_filename, "w") as fo: fo.write(encrypted_content) return encrypted_content def read_from_file_and_decrypt(message_filename: str, key_filename: str) -> str: key_size, n, d = read_key_file(key_filename) with open(message_filename) as fo: content = fo.read() message_length_str, block_size_str, encrypted_message = content.split("_") message_length = int(message_length_str) block_size = int(block_size_str) if key_size < block_size * 8: sys.exit( "ERROR: Block size is %s bits and key size is %s bits. The RSA cipher " "requires the block size to be equal to or greater than the key size. " "Did you specify the correct key file and encrypted file?" % (block_size * 8, key_size) ) encrypted_blocks = [] for block in encrypted_message.split(","): encrypted_blocks.append(int(block)) return decrypt_message(encrypted_blocks, message_length, (n, d), block_size) def main() -> None: filename = "encrypted_file.txt" response = input(r"Encrypt\Decrypt [e\d]: ") if response.lower().startswith("e"): mode = "encrypt" elif response.lower().startswith("d"): mode = "decrypt" if mode == "encrypt": if not os.path.exists("rsa_pubkey.txt"): rkg.make_key_files("rsa", 1024) message = input("\nEnter message: ") pubkey_filename = "rsa_pubkey.txt" print(f"Encrypting and writing to {filename}...") encrypted_text = encrypt_and_write_to_file(filename, pubkey_filename, message) print("\nEncrypted text:") print(encrypted_text) elif mode == "decrypt": privkey_filename = "rsa_privkey.txt" print(f"Reading from {filename} and decrypting...") decrypted_text = read_from_file_and_decrypt(filename, privkey_filename) print("writing decryption to rsa_decryption.txt...") with open("rsa_decryption.txt", "w") as dec: dec.write(decrypted_text) print("\nDecryption:") print(decrypted_text) if __name__ == "__main__": main()
import os import sys from . import rsa_key_generator as rkg DEFAULT_BLOCK_SIZE = 128 BYTE_SIZE = 256 def get_blocks_from_text( message: str, block_size: int = DEFAULT_BLOCK_SIZE ) -> list[int]: message_bytes = message.encode("ascii") block_ints = [] for block_start in range(0, len(message_bytes), block_size): block_int = 0 for i in range(block_start, min(block_start + block_size, len(message_bytes))): block_int += message_bytes[i] * (BYTE_SIZE ** (i % block_size)) block_ints.append(block_int) return block_ints def get_text_from_blocks( block_ints: list[int], message_length: int, block_size: int = DEFAULT_BLOCK_SIZE ) -> str: message: list[str] = [] for block_int in block_ints: block_message: list[str] = [] for i in range(block_size - 1, -1, -1): if len(message) + i < message_length: ascii_number = block_int // (BYTE_SIZE**i) block_int = block_int % (BYTE_SIZE**i) block_message.insert(0, chr(ascii_number)) message.extend(block_message) return "".join(message) def encrypt_message( message: str, key: tuple[int, int], block_size: int = DEFAULT_BLOCK_SIZE ) -> list[int]: encrypted_blocks = [] n, e = key for block in get_blocks_from_text(message, block_size): encrypted_blocks.append(pow(block, e, n)) return encrypted_blocks def decrypt_message( encrypted_blocks: list[int], message_length: int, key: tuple[int, int], block_size: int = DEFAULT_BLOCK_SIZE, ) -> str: decrypted_blocks = [] n, d = key for block in encrypted_blocks: decrypted_blocks.append(pow(block, d, n)) return get_text_from_blocks(decrypted_blocks, message_length, block_size) def read_key_file(key_filename: str) -> tuple[int, int, int]: with open(key_filename) as fo: content = fo.read() key_size, n, eor_d = content.split(",") return (int(key_size), int(n), int(eor_d)) def encrypt_and_write_to_file( message_filename: str, key_filename: str, message: str, block_size: int = DEFAULT_BLOCK_SIZE, ) -> str: key_size, n, e = read_key_file(key_filename) if key_size < block_size * 8: sys.exit( "ERROR: Block size is %s bits and key size is %s bits. The RSA cipher " "requires the block size to be equal to or greater than the key size. " "Either decrease the block size or use different keys." % (block_size * 8, key_size) ) encrypted_blocks = [str(i) for i in encrypt_message(message, (n, e), block_size)] encrypted_content = ",".join(encrypted_blocks) encrypted_content = f"{len(message)}_{block_size}_{encrypted_content}" with open(message_filename, "w") as fo: fo.write(encrypted_content) return encrypted_content def read_from_file_and_decrypt(message_filename: str, key_filename: str) -> str: key_size, n, d = read_key_file(key_filename) with open(message_filename) as fo: content = fo.read() message_length_str, block_size_str, encrypted_message = content.split("_") message_length = int(message_length_str) block_size = int(block_size_str) if key_size < block_size * 8: sys.exit( "ERROR: Block size is %s bits and key size is %s bits. The RSA cipher " "requires the block size to be equal to or greater than the key size. " "Did you specify the correct key file and encrypted file?" % (block_size * 8, key_size) ) encrypted_blocks = [] for block in encrypted_message.split(","): encrypted_blocks.append(int(block)) return decrypt_message(encrypted_blocks, message_length, (n, d), block_size) def main() -> None: filename = "encrypted_file.txt" response = input(r"Encrypt\Decrypt [e\d]: ") if response.lower().startswith("e"): mode = "encrypt" elif response.lower().startswith("d"): mode = "decrypt" if mode == "encrypt": if not os.path.exists("rsa_pubkey.txt"): rkg.make_key_files("rsa", 1024) message = input("\nEnter message: ") pubkey_filename = "rsa_pubkey.txt" print(f"Encrypting and writing to {filename}...") encrypted_text = encrypt_and_write_to_file(filename, pubkey_filename, message) print("\nEncrypted text:") print(encrypted_text) elif mode == "decrypt": privkey_filename = "rsa_privkey.txt" print(f"Reading from {filename} and decrypting...") decrypted_text = read_from_file_and_decrypt(filename, privkey_filename) print("writing decryption to rsa_decryption.txt...") with open("rsa_decryption.txt", "w") as dec: dec.write(decrypted_text) print("\nDecryption:") print(decrypted_text) if __name__ == "__main__": main()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Number letter counts Problem 17: https://projecteuler.net/problem=17 If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total. If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used? NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters. The use of "and" when writing out numbers is in compliance withBritish usage. """ def solution(n: int = 1000) -> int: """Returns the number of letters used to write all numbers from 1 to n. where n is lower or equals to 1000. >>> solution(1000) 21124 >>> solution(5) 19 """ # number of letters in zero, one, two, ..., nineteen (0 for zero since it's # never said aloud) ones_counts = [0, 3, 3, 5, 4, 4, 3, 5, 5, 4, 3, 6, 6, 8, 8, 7, 7, 9, 8, 8] # number of letters in twenty, thirty, ..., ninety (0 for numbers less than # 20 due to inconsistency in teens) tens_counts = [0, 0, 6, 6, 5, 5, 5, 7, 6, 6] count = 0 for i in range(1, n + 1): if i < 1000: if i >= 100: # add number of letters for "n hundred" count += ones_counts[i // 100] + 7 if i % 100 != 0: # add number of letters for "and" if number is not multiple # of 100 count += 3 if 0 < i % 100 < 20: # add number of letters for one, two, three, ..., nineteen # (could be combined with below if not for inconsistency in # teens) count += ones_counts[i % 100] else: # add number of letters for twenty, twenty one, ..., ninety # nine count += ones_counts[i % 10] count += tens_counts[(i % 100 - i % 10) // 10] else: count += ones_counts[i // 1000] + 8 return count if __name__ == "__main__": print(solution(int(input().strip())))
""" Number letter counts Problem 17: https://projecteuler.net/problem=17 If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total. If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used? NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters. The use of "and" when writing out numbers is in compliance withBritish usage. """ def solution(n: int = 1000) -> int: """Returns the number of letters used to write all numbers from 1 to n. where n is lower or equals to 1000. >>> solution(1000) 21124 >>> solution(5) 19 """ # number of letters in zero, one, two, ..., nineteen (0 for zero since it's # never said aloud) ones_counts = [0, 3, 3, 5, 4, 4, 3, 5, 5, 4, 3, 6, 6, 8, 8, 7, 7, 9, 8, 8] # number of letters in twenty, thirty, ..., ninety (0 for numbers less than # 20 due to inconsistency in teens) tens_counts = [0, 0, 6, 6, 5, 5, 5, 7, 6, 6] count = 0 for i in range(1, n + 1): if i < 1000: if i >= 100: # add number of letters for "n hundred" count += ones_counts[i // 100] + 7 if i % 100 != 0: # add number of letters for "and" if number is not multiple # of 100 count += 3 if 0 < i % 100 < 20: # add number of letters for one, two, three, ..., nineteen # (could be combined with below if not for inconsistency in # teens) count += ones_counts[i % 100] else: # add number of letters for twenty, twenty one, ..., ninety # nine count += ones_counts[i % 10] count += tens_counts[(i % 100 - i % 10) // 10] else: count += ones_counts[i // 1000] + 8 return count if __name__ == "__main__": print(solution(int(input().strip())))
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 074: https://projecteuler.net/problem=74 The number 145 is well known for the property that the sum of the factorial of its digits is equal to 145: 1! + 4! + 5! = 1 + 24 + 120 = 145 Perhaps less well known is 169, in that it produces the longest chain of numbers that link back to 169; it turns out that there are only three such loops that exist: 169 → 363601 → 1454 → 169 871 → 45361 → 871 872 → 45362 → 872 It is not difficult to prove that EVERY starting number will eventually get stuck in a loop. For example, 69 → 363600 → 1454 → 169 → 363601 (→ 1454) 78 → 45360 → 871 → 45361 (→ 871) 540 → 145 (→ 145) Starting with 69 produces a chain of five non-repeating terms, but the longest non-repeating chain with a starting number below one million is sixty terms. How many chains, with a starting number below one million, contain exactly sixty non-repeating terms? Solution approach: This solution simply consists in a loop that generates the chains of non repeating items using the cached sizes of the previous chains. The generation of the chain stops before a repeating item or if the size of the chain is greater then the desired one. After generating each chain, the length is checked and the counter increases. """ from math import factorial DIGIT_FACTORIAL: dict[str, int] = {str(digit): factorial(digit) for digit in range(10)} def digit_factorial_sum(number: int) -> int: """ Function to perform the sum of the factorial of all the digits in number >>> digit_factorial_sum(69.0) Traceback (most recent call last): ... TypeError: Parameter number must be int >>> digit_factorial_sum(-1) Traceback (most recent call last): ... ValueError: Parameter number must be greater than or equal to 0 >>> digit_factorial_sum(0) 1 >>> digit_factorial_sum(69) 363600 """ if not isinstance(number, int): raise TypeError("Parameter number must be int") if number < 0: raise ValueError("Parameter number must be greater than or equal to 0") # Converts number in string to iterate on its digits and adds its factorial. return sum(DIGIT_FACTORIAL[digit] for digit in str(number)) def solution(chain_length: int = 60, number_limit: int = 1000000) -> int: """ Returns the number of numbers below number_limit that produce chains with exactly chain_length non repeating elements. >>> solution(10.0, 1000) Traceback (most recent call last): ... TypeError: Parameters chain_length and number_limit must be int >>> solution(10, 1000.0) Traceback (most recent call last): ... TypeError: Parameters chain_length and number_limit must be int >>> solution(0, 1000) Traceback (most recent call last): ... ValueError: Parameters chain_length and number_limit must be greater than 0 >>> solution(10, 0) Traceback (most recent call last): ... ValueError: Parameters chain_length and number_limit must be greater than 0 >>> solution(10, 1000) 26 """ if not isinstance(chain_length, int) or not isinstance(number_limit, int): raise TypeError("Parameters chain_length and number_limit must be int") if chain_length <= 0 or number_limit <= 0: raise ValueError( "Parameters chain_length and number_limit must be greater than 0" ) # the counter for the chains with the exact desired length chains_counter = 0 # the cached sizes of the previous chains chain_sets_lengths: dict[int, int] = {} for start_chain_element in range(1, number_limit): # The temporary set will contain the elements of the chain chain_set = set() chain_set_length = 0 # Stop computing the chain when you find a cached size, a repeating item or the # length is greater then the desired one. chain_element = start_chain_element while ( chain_element not in chain_sets_lengths and chain_element not in chain_set and chain_set_length <= chain_length ): chain_set.add(chain_element) chain_set_length += 1 chain_element = digit_factorial_sum(chain_element) if chain_element in chain_sets_lengths: chain_set_length += chain_sets_lengths[chain_element] chain_sets_lengths[start_chain_element] = chain_set_length # If chain contains the exact amount of elements increase the counter if chain_set_length == chain_length: chains_counter += 1 return chains_counter if __name__ == "__main__": import doctest doctest.testmod() print(f"{solution()}")
""" Project Euler Problem 074: https://projecteuler.net/problem=74 The number 145 is well known for the property that the sum of the factorial of its digits is equal to 145: 1! + 4! + 5! = 1 + 24 + 120 = 145 Perhaps less well known is 169, in that it produces the longest chain of numbers that link back to 169; it turns out that there are only three such loops that exist: 169 → 363601 → 1454 → 169 871 → 45361 → 871 872 → 45362 → 872 It is not difficult to prove that EVERY starting number will eventually get stuck in a loop. For example, 69 → 363600 → 1454 → 169 → 363601 (→ 1454) 78 → 45360 → 871 → 45361 (→ 871) 540 → 145 (→ 145) Starting with 69 produces a chain of five non-repeating terms, but the longest non-repeating chain with a starting number below one million is sixty terms. How many chains, with a starting number below one million, contain exactly sixty non-repeating terms? Solution approach: This solution simply consists in a loop that generates the chains of non repeating items using the cached sizes of the previous chains. The generation of the chain stops before a repeating item or if the size of the chain is greater then the desired one. After generating each chain, the length is checked and the counter increases. """ from math import factorial DIGIT_FACTORIAL: dict[str, int] = {str(digit): factorial(digit) for digit in range(10)} def digit_factorial_sum(number: int) -> int: """ Function to perform the sum of the factorial of all the digits in number >>> digit_factorial_sum(69.0) Traceback (most recent call last): ... TypeError: Parameter number must be int >>> digit_factorial_sum(-1) Traceback (most recent call last): ... ValueError: Parameter number must be greater than or equal to 0 >>> digit_factorial_sum(0) 1 >>> digit_factorial_sum(69) 363600 """ if not isinstance(number, int): raise TypeError("Parameter number must be int") if number < 0: raise ValueError("Parameter number must be greater than or equal to 0") # Converts number in string to iterate on its digits and adds its factorial. return sum(DIGIT_FACTORIAL[digit] for digit in str(number)) def solution(chain_length: int = 60, number_limit: int = 1000000) -> int: """ Returns the number of numbers below number_limit that produce chains with exactly chain_length non repeating elements. >>> solution(10.0, 1000) Traceback (most recent call last): ... TypeError: Parameters chain_length and number_limit must be int >>> solution(10, 1000.0) Traceback (most recent call last): ... TypeError: Parameters chain_length and number_limit must be int >>> solution(0, 1000) Traceback (most recent call last): ... ValueError: Parameters chain_length and number_limit must be greater than 0 >>> solution(10, 0) Traceback (most recent call last): ... ValueError: Parameters chain_length and number_limit must be greater than 0 >>> solution(10, 1000) 26 """ if not isinstance(chain_length, int) or not isinstance(number_limit, int): raise TypeError("Parameters chain_length and number_limit must be int") if chain_length <= 0 or number_limit <= 0: raise ValueError( "Parameters chain_length and number_limit must be greater than 0" ) # the counter for the chains with the exact desired length chains_counter = 0 # the cached sizes of the previous chains chain_sets_lengths: dict[int, int] = {} for start_chain_element in range(1, number_limit): # The temporary set will contain the elements of the chain chain_set = set() chain_set_length = 0 # Stop computing the chain when you find a cached size, a repeating item or the # length is greater then the desired one. chain_element = start_chain_element while ( chain_element not in chain_sets_lengths and chain_element not in chain_set and chain_set_length <= chain_length ): chain_set.add(chain_element) chain_set_length += 1 chain_element = digit_factorial_sum(chain_element) if chain_element in chain_sets_lengths: chain_set_length += chain_sets_lengths[chain_element] chain_sets_lengths[start_chain_element] = chain_set_length # If chain contains the exact amount of elements increase the counter if chain_set_length == chain_length: chains_counter += 1 return chains_counter if __name__ == "__main__": import doctest doctest.testmod() print(f"{solution()}")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" The sum-of-subsetsproblem states that a set of non-negative integers, and a value M, determine all possible subsets of the given set whose summation sum equal to given M. Summation of the chosen numbers must be equal to given number M and one number can be used only once. """ from __future__ import annotations def generate_sum_of_subsets_soln(nums: list[int], max_sum: int) -> list[list[int]]: result: list[list[int]] = [] path: list[int] = [] num_index = 0 remaining_nums_sum = sum(nums) create_state_space_tree(nums, max_sum, num_index, path, result, remaining_nums_sum) return result def create_state_space_tree( nums: list[int], max_sum: int, num_index: int, path: list[int], result: list[list[int]], remaining_nums_sum: int, ) -> None: """ Creates a state space tree to iterate through each branch using DFS. It terminates the branching of a node when any of the two conditions given below satisfy. This algorithm follows depth-fist-search and backtracks when the node is not branchable. """ if sum(path) > max_sum or (remaining_nums_sum + sum(path)) < max_sum: return if sum(path) == max_sum: result.append(path) return for index in range(num_index, len(nums)): create_state_space_tree( nums, max_sum, index + 1, path + [nums[index]], result, remaining_nums_sum - nums[index], ) """ remove the comment to take an input from the user print("Enter the elements") nums = list(map(int, input().split())) print("Enter max_sum sum") max_sum = int(input()) """ nums = [3, 34, 4, 12, 5, 2] max_sum = 9 result = generate_sum_of_subsets_soln(nums, max_sum) print(*result)
""" The sum-of-subsetsproblem states that a set of non-negative integers, and a value M, determine all possible subsets of the given set whose summation sum equal to given M. Summation of the chosen numbers must be equal to given number M and one number can be used only once. """ from __future__ import annotations def generate_sum_of_subsets_soln(nums: list[int], max_sum: int) -> list[list[int]]: result: list[list[int]] = [] path: list[int] = [] num_index = 0 remaining_nums_sum = sum(nums) create_state_space_tree(nums, max_sum, num_index, path, result, remaining_nums_sum) return result def create_state_space_tree( nums: list[int], max_sum: int, num_index: int, path: list[int], result: list[list[int]], remaining_nums_sum: int, ) -> None: """ Creates a state space tree to iterate through each branch using DFS. It terminates the branching of a node when any of the two conditions given below satisfy. This algorithm follows depth-fist-search and backtracks when the node is not branchable. """ if sum(path) > max_sum or (remaining_nums_sum + sum(path)) < max_sum: return if sum(path) == max_sum: result.append(path) return for index in range(num_index, len(nums)): create_state_space_tree( nums, max_sum, index + 1, path + [nums[index]], result, remaining_nums_sum - nums[index], ) """ remove the comment to take an input from the user print("Enter the elements") nums = list(map(int, input().split())) print("Enter max_sum sum") max_sum = int(input()) """ nums = [3, 34, 4, 12, 5, 2] max_sum = 9 result = generate_sum_of_subsets_soln(nums, max_sum) print(*result)
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
from __future__ import annotations def find_primitive(n: int) -> int | None: for r in range(1, n): li = [] for x in range(n - 1): val = pow(r, x, n) if val in li: break li.append(val) else: return r return None if __name__ == "__main__": q = int(input("Enter a prime number q: ")) a = find_primitive(q) if a is None: print(f"Cannot find the primitive for the value: {a!r}") else: a_private = int(input("Enter private key of A: ")) a_public = pow(a, a_private, q) b_private = int(input("Enter private key of B: ")) b_public = pow(a, b_private, q) a_secret = pow(b_public, a_private, q) b_secret = pow(a_public, b_private, q) print("The key value generated by A is: ", a_secret) print("The key value generated by B is: ", b_secret)
from __future__ import annotations def find_primitive(n: int) -> int | None: for r in range(1, n): li = [] for x in range(n - 1): val = pow(r, x, n) if val in li: break li.append(val) else: return r return None if __name__ == "__main__": q = int(input("Enter a prime number q: ")) a = find_primitive(q) if a is None: print(f"Cannot find the primitive for the value: {a!r}") else: a_private = int(input("Enter private key of A: ")) a_public = pow(a, a_private, q) b_private = int(input("Enter private key of B: ")) b_public = pow(a, b_private, q) a_secret = pow(b_public, a_private, q) b_secret = pow(a_public, b_private, q) print("The key value generated by A is: ", a_secret) print("The key value generated by B is: ", b_secret)
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# @Author : lightXu # @File : convolve.py # @Time : 2019/7/8 0008 下午 16:13 from cv2 import COLOR_BGR2GRAY, cvtColor, imread, imshow, waitKey from numpy import array, dot, pad, ravel, uint8, zeros def im2col(image, block_size): rows, cols = image.shape dst_height = cols - block_size[1] + 1 dst_width = rows - block_size[0] + 1 image_array = zeros((dst_height * dst_width, block_size[1] * block_size[0])) row = 0 for i in range(0, dst_height): for j in range(0, dst_width): window = ravel(image[i : i + block_size[0], j : j + block_size[1]]) image_array[row, :] = window row += 1 return image_array def img_convolve(image, filter_kernel): height, width = image.shape[0], image.shape[1] k_size = filter_kernel.shape[0] pad_size = k_size // 2 # Pads image with the edge values of array. image_tmp = pad(image, pad_size, mode="edge") # im2col, turn the k_size*k_size pixels into a row and np.vstack all rows image_array = im2col(image_tmp, (k_size, k_size)) # turn the kernel into shape(k*k, 1) kernel_array = ravel(filter_kernel) # reshape and get the dst image dst = dot(image_array, kernel_array).reshape(height, width) return dst if __name__ == "__main__": # read original image img = imread(r"../image_data/lena.jpg") # turn image in gray scale value gray = cvtColor(img, COLOR_BGR2GRAY) # Laplace operator Laplace_kernel = array([[0, 1, 0], [1, -4, 1], [0, 1, 0]]) out = img_convolve(gray, Laplace_kernel).astype(uint8) imshow("Laplacian", out) waitKey(0)
# @Author : lightXu # @File : convolve.py # @Time : 2019/7/8 0008 下午 16:13 from cv2 import COLOR_BGR2GRAY, cvtColor, imread, imshow, waitKey from numpy import array, dot, pad, ravel, uint8, zeros def im2col(image, block_size): rows, cols = image.shape dst_height = cols - block_size[1] + 1 dst_width = rows - block_size[0] + 1 image_array = zeros((dst_height * dst_width, block_size[1] * block_size[0])) row = 0 for i in range(0, dst_height): for j in range(0, dst_width): window = ravel(image[i : i + block_size[0], j : j + block_size[1]]) image_array[row, :] = window row += 1 return image_array def img_convolve(image, filter_kernel): height, width = image.shape[0], image.shape[1] k_size = filter_kernel.shape[0] pad_size = k_size // 2 # Pads image with the edge values of array. image_tmp = pad(image, pad_size, mode="edge") # im2col, turn the k_size*k_size pixels into a row and np.vstack all rows image_array = im2col(image_tmp, (k_size, k_size)) # turn the kernel into shape(k*k, 1) kernel_array = ravel(filter_kernel) # reshape and get the dst image dst = dot(image_array, kernel_array).reshape(height, width) return dst if __name__ == "__main__": # read original image img = imread(r"../image_data/lena.jpg") # turn image in gray scale value gray = cvtColor(img, COLOR_BGR2GRAY) # Laplace operator Laplace_kernel = array([[0, 1, 0], [1, -4, 1], [0, 1, 0]]) out = img_convolve(gray, Laplace_kernel).astype(uint8) imshow("Laplacian", out) waitKey(0)
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Approximates the area under the curve using the trapezoidal rule """ from __future__ import annotations from collections.abc import Callable def trapezoidal_area( fnc: Callable[[int | float], int | float], x_start: int | float, x_end: int | float, steps: int = 100, ) -> float: """ Treats curve as a collection of linear lines and sums the area of the trapezium shape they form :param fnc: a function which defines a curve :param x_start: left end point to indicate the start of line segment :param x_end: right end point to indicate end of line segment :param steps: an accuracy gauge; more steps increases the accuracy :return: a float representing the length of the curve >>> def f(x): ... return 5 >>> f"{trapezoidal_area(f, 12.0, 14.0, 1000):.3f}" '10.000' >>> def f(x): ... return 9*x**2 >>> f"{trapezoidal_area(f, -4.0, 0, 10000):.4f}" '192.0000' >>> f"{trapezoidal_area(f, -4.0, 4.0, 10000):.4f}" '384.0000' """ x1 = x_start fx1 = fnc(x_start) area = 0.0 for _ in range(steps): # Approximates small segments of curve as linear and solve # for trapezoidal area x2 = (x_end - x_start) / steps + x1 fx2 = fnc(x2) area += abs(fx2 + fx1) * (x2 - x1) / 2 # Increment step x1 = x2 fx1 = fx2 return area if __name__ == "__main__": def f(x): return x**3 + x**2 print("f(x) = x^3 + x^2") print("The area between the curve, x = -5, x = 5 and the x axis is:") i = 10 while i <= 100000: print(f"with {i} steps: {trapezoidal_area(f, -5, 5, i)}") i *= 10
""" Approximates the area under the curve using the trapezoidal rule """ from __future__ import annotations from collections.abc import Callable def trapezoidal_area( fnc: Callable[[int | float], int | float], x_start: int | float, x_end: int | float, steps: int = 100, ) -> float: """ Treats curve as a collection of linear lines and sums the area of the trapezium shape they form :param fnc: a function which defines a curve :param x_start: left end point to indicate the start of line segment :param x_end: right end point to indicate end of line segment :param steps: an accuracy gauge; more steps increases the accuracy :return: a float representing the length of the curve >>> def f(x): ... return 5 >>> f"{trapezoidal_area(f, 12.0, 14.0, 1000):.3f}" '10.000' >>> def f(x): ... return 9*x**2 >>> f"{trapezoidal_area(f, -4.0, 0, 10000):.4f}" '192.0000' >>> f"{trapezoidal_area(f, -4.0, 4.0, 10000):.4f}" '384.0000' """ x1 = x_start fx1 = fnc(x_start) area = 0.0 for _ in range(steps): # Approximates small segments of curve as linear and solve # for trapezoidal area x2 = (x_end - x_start) / steps + x1 fx2 = fnc(x2) area += abs(fx2 + fx1) * (x2 - x1) / 2 # Increment step x1 = x2 fx1 = fx2 return area if __name__ == "__main__": def f(x): return x**3 + x**2 print("f(x) = x^3 + x^2") print("The area between the curve, x = -5, x = 5 and the x axis is:") i = 10 while i <= 100000: print(f"with {i} steps: {trapezoidal_area(f, -5, 5, i)}") i *= 10
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Wiggle Sort. Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... For example: if input numbers = [3, 5, 2, 1, 6, 4] one possible Wiggle Sorted answer is [3, 5, 1, 6, 2, 4]. """ def wiggle_sort(nums: list) -> list: """ Python implementation of wiggle. Example: >>> wiggle_sort([0, 5, 3, 2, 2]) [0, 5, 2, 3, 2] >>> wiggle_sort([]) [] >>> wiggle_sort([-2, -5, -45]) [-45, -2, -5] >>> wiggle_sort([-2.1, -5.68, -45.11]) [-45.11, -2.1, -5.68] """ for i, _ in enumerate(nums): if (i % 2 == 1) == (nums[i - 1] > nums[i]): nums[i - 1], nums[i] = nums[i], nums[i - 1] return nums if __name__ == "__main__": print("Enter the array elements:") array = list(map(int, input().split())) print("The unsorted array is:") print(array) print("Array after Wiggle sort:") print(wiggle_sort(array))
""" Wiggle Sort. Given an unsorted array nums, reorder it such that nums[0] < nums[1] > nums[2] < nums[3].... For example: if input numbers = [3, 5, 2, 1, 6, 4] one possible Wiggle Sorted answer is [3, 5, 1, 6, 2, 4]. """ def wiggle_sort(nums: list) -> list: """ Python implementation of wiggle. Example: >>> wiggle_sort([0, 5, 3, 2, 2]) [0, 5, 2, 3, 2] >>> wiggle_sort([]) [] >>> wiggle_sort([-2, -5, -45]) [-45, -2, -5] >>> wiggle_sort([-2.1, -5.68, -45.11]) [-45.11, -2.1, -5.68] """ for i, _ in enumerate(nums): if (i % 2 == 1) == (nums[i - 1] > nums[i]): nums[i - 1], nums[i] = nums[i], nums[i - 1] return nums if __name__ == "__main__": print("Enter the array elements:") array = list(map(int, input().split())) print("The unsorted array is:") print(array) print("Array after Wiggle sort:") print(wiggle_sort(array))
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# https://en.m.wikipedia.org/wiki/Electric_power from __future__ import annotations from collections import namedtuple def electric_power(voltage: float, current: float, power: float) -> tuple: """ This function can calculate any one of the three (voltage, current, power), fundamental value of electrical system. examples are below: >>> electric_power(voltage=0, current=2, power=5) result(name='voltage', value=2.5) >>> electric_power(voltage=2, current=2, power=0) result(name='power', value=4.0) >>> electric_power(voltage=-2, current=3, power=0) result(name='power', value=6.0) >>> electric_power(voltage=2, current=4, power=2) Traceback (most recent call last): File "<stdin>", line 15, in <module> ValueError: Only one argument must be 0 >>> electric_power(voltage=0, current=0, power=2) Traceback (most recent call last): File "<stdin>", line 19, in <module> ValueError: Only one argument must be 0 >>> electric_power(voltage=0, current=2, power=-4) Traceback (most recent call last): File "<stdin>", line 23, in <modulei ValueError: Power cannot be negative in any electrical/electronics system >>> electric_power(voltage=2.2, current=2.2, power=0) result(name='power', value=4.84) """ result = namedtuple("result", "name value") if (voltage, current, power).count(0) != 1: raise ValueError("Only one argument must be 0") elif power < 0: raise ValueError( "Power cannot be negative in any electrical/electronics system" ) elif voltage == 0: return result("voltage", power / current) elif current == 0: return result("current", power / voltage) elif power == 0: return result("power", float(round(abs(voltage * current), 2))) else: raise ValueError("Exactly one argument must be 0") if __name__ == "__main__": import doctest doctest.testmod()
# https://en.m.wikipedia.org/wiki/Electric_power from __future__ import annotations from collections import namedtuple def electric_power(voltage: float, current: float, power: float) -> tuple: """ This function can calculate any one of the three (voltage, current, power), fundamental value of electrical system. examples are below: >>> electric_power(voltage=0, current=2, power=5) result(name='voltage', value=2.5) >>> electric_power(voltage=2, current=2, power=0) result(name='power', value=4.0) >>> electric_power(voltage=-2, current=3, power=0) result(name='power', value=6.0) >>> electric_power(voltage=2, current=4, power=2) Traceback (most recent call last): File "<stdin>", line 15, in <module> ValueError: Only one argument must be 0 >>> electric_power(voltage=0, current=0, power=2) Traceback (most recent call last): File "<stdin>", line 19, in <module> ValueError: Only one argument must be 0 >>> electric_power(voltage=0, current=2, power=-4) Traceback (most recent call last): File "<stdin>", line 23, in <modulei ValueError: Power cannot be negative in any electrical/electronics system >>> electric_power(voltage=2.2, current=2.2, power=0) result(name='power', value=4.84) """ result = namedtuple("result", "name value") if (voltage, current, power).count(0) != 1: raise ValueError("Only one argument must be 0") elif power < 0: raise ValueError( "Power cannot be negative in any electrical/electronics system" ) elif voltage == 0: return result("voltage", power / current) elif current == 0: return result("current", power / voltage) elif power == 0: return result("power", float(round(abs(voltage * current), 2))) else: raise ValueError("Exactly one argument must be 0") if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Jacobi Iteration Method - https://en.wikipedia.org/wiki/Jacobi_method """ from __future__ import annotations import numpy as np from numpy import float64 from numpy.typing import NDArray # Method to find solution of system of linear equations def jacobi_iteration_method( coefficient_matrix: NDArray[float64], constant_matrix: NDArray[float64], init_val: list[int], iterations: int, ) -> list[float]: """ Jacobi Iteration Method: An iterative algorithm to determine the solutions of strictly diagonally dominant system of linear equations 4x1 + x2 + x3 = 2 x1 + 5x2 + 2x3 = -6 x1 + 2x2 + 4x3 = -4 x_init = [0.5, -0.5 , -0.5] Examples: >>> coefficient = np.array([[4, 1, 1], [1, 5, 2], [1, 2, 4]]) >>> constant = np.array([[2], [-6], [-4]]) >>> init_val = [0.5, -0.5, -0.5] >>> iterations = 3 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) [0.909375, -1.14375, -0.7484375] >>> coefficient = np.array([[4, 1, 1], [1, 5, 2]]) >>> constant = np.array([[2], [-6], [-4]]) >>> init_val = [0.5, -0.5, -0.5] >>> iterations = 3 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) Traceback (most recent call last): ... ValueError: Coefficient matrix dimensions must be nxn but received 2x3 >>> coefficient = np.array([[4, 1, 1], [1, 5, 2], [1, 2, 4]]) >>> constant = np.array([[2], [-6]]) >>> init_val = [0.5, -0.5, -0.5] >>> iterations = 3 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) Traceback (most recent call last): ... ValueError: Coefficient and constant matrices dimensions must be nxn and nx1 but received 3x3 and 2x1 >>> coefficient = np.array([[4, 1, 1], [1, 5, 2], [1, 2, 4]]) >>> constant = np.array([[2], [-6], [-4]]) >>> init_val = [0.5, -0.5] >>> iterations = 3 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) Traceback (most recent call last): ... ValueError: Number of initial values must be equal to number of rows in coefficient matrix but received 2 and 3 >>> coefficient = np.array([[4, 1, 1], [1, 5, 2], [1, 2, 4]]) >>> constant = np.array([[2], [-6], [-4]]) >>> init_val = [0.5, -0.5, -0.5] >>> iterations = 0 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) Traceback (most recent call last): ... ValueError: Iterations must be at least 1 """ rows1, cols1 = coefficient_matrix.shape rows2, cols2 = constant_matrix.shape if rows1 != cols1: raise ValueError( f"Coefficient matrix dimensions must be nxn but received {rows1}x{cols1}" ) if cols2 != 1: raise ValueError(f"Constant matrix must be nx1 but received {rows2}x{cols2}") if rows1 != rows2: raise ValueError( f"""Coefficient and constant matrices dimensions must be nxn and nx1 but received {rows1}x{cols1} and {rows2}x{cols2}""" ) if len(init_val) != rows1: raise ValueError( f"""Number of initial values must be equal to number of rows in coefficient matrix but received {len(init_val)} and {rows1}""" ) if iterations <= 0: raise ValueError("Iterations must be at least 1") table: NDArray[float64] = np.concatenate( (coefficient_matrix, constant_matrix), axis=1 ) rows, cols = table.shape strictly_diagonally_dominant(table) # Iterates the whole matrix for given number of times for _ in range(iterations): new_val = [] for row in range(rows): temp = 0 for col in range(cols): if col == row: denom = table[row][col] elif col == cols - 1: val = table[row][col] else: temp += (-1) * table[row][col] * init_val[col] temp = (temp + val) / denom new_val.append(temp) init_val = new_val return [float(i) for i in new_val] # Checks if the given matrix is strictly diagonally dominant def strictly_diagonally_dominant(table: NDArray[float64]) -> bool: """ >>> table = np.array([[4, 1, 1, 2], [1, 5, 2, -6], [1, 2, 4, -4]]) >>> strictly_diagonally_dominant(table) True >>> table = np.array([[4, 1, 1, 2], [1, 5, 2, -6], [1, 2, 3, -4]]) >>> strictly_diagonally_dominant(table) Traceback (most recent call last): ... ValueError: Coefficient matrix is not strictly diagonally dominant """ rows, cols = table.shape is_diagonally_dominant = True for i in range(0, rows): total = 0 for j in range(0, cols - 1): if i == j: continue else: total += table[i][j] if table[i][i] <= total: raise ValueError("Coefficient matrix is not strictly diagonally dominant") return is_diagonally_dominant # Test Cases if __name__ == "__main__": import doctest doctest.testmod()
""" Jacobi Iteration Method - https://en.wikipedia.org/wiki/Jacobi_method """ from __future__ import annotations import numpy as np from numpy import float64 from numpy.typing import NDArray # Method to find solution of system of linear equations def jacobi_iteration_method( coefficient_matrix: NDArray[float64], constant_matrix: NDArray[float64], init_val: list[int], iterations: int, ) -> list[float]: """ Jacobi Iteration Method: An iterative algorithm to determine the solutions of strictly diagonally dominant system of linear equations 4x1 + x2 + x3 = 2 x1 + 5x2 + 2x3 = -6 x1 + 2x2 + 4x3 = -4 x_init = [0.5, -0.5 , -0.5] Examples: >>> coefficient = np.array([[4, 1, 1], [1, 5, 2], [1, 2, 4]]) >>> constant = np.array([[2], [-6], [-4]]) >>> init_val = [0.5, -0.5, -0.5] >>> iterations = 3 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) [0.909375, -1.14375, -0.7484375] >>> coefficient = np.array([[4, 1, 1], [1, 5, 2]]) >>> constant = np.array([[2], [-6], [-4]]) >>> init_val = [0.5, -0.5, -0.5] >>> iterations = 3 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) Traceback (most recent call last): ... ValueError: Coefficient matrix dimensions must be nxn but received 2x3 >>> coefficient = np.array([[4, 1, 1], [1, 5, 2], [1, 2, 4]]) >>> constant = np.array([[2], [-6]]) >>> init_val = [0.5, -0.5, -0.5] >>> iterations = 3 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) Traceback (most recent call last): ... ValueError: Coefficient and constant matrices dimensions must be nxn and nx1 but received 3x3 and 2x1 >>> coefficient = np.array([[4, 1, 1], [1, 5, 2], [1, 2, 4]]) >>> constant = np.array([[2], [-6], [-4]]) >>> init_val = [0.5, -0.5] >>> iterations = 3 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) Traceback (most recent call last): ... ValueError: Number of initial values must be equal to number of rows in coefficient matrix but received 2 and 3 >>> coefficient = np.array([[4, 1, 1], [1, 5, 2], [1, 2, 4]]) >>> constant = np.array([[2], [-6], [-4]]) >>> init_val = [0.5, -0.5, -0.5] >>> iterations = 0 >>> jacobi_iteration_method(coefficient, constant, init_val, iterations) Traceback (most recent call last): ... ValueError: Iterations must be at least 1 """ rows1, cols1 = coefficient_matrix.shape rows2, cols2 = constant_matrix.shape if rows1 != cols1: raise ValueError( f"Coefficient matrix dimensions must be nxn but received {rows1}x{cols1}" ) if cols2 != 1: raise ValueError(f"Constant matrix must be nx1 but received {rows2}x{cols2}") if rows1 != rows2: raise ValueError( f"""Coefficient and constant matrices dimensions must be nxn and nx1 but received {rows1}x{cols1} and {rows2}x{cols2}""" ) if len(init_val) != rows1: raise ValueError( f"""Number of initial values must be equal to number of rows in coefficient matrix but received {len(init_val)} and {rows1}""" ) if iterations <= 0: raise ValueError("Iterations must be at least 1") table: NDArray[float64] = np.concatenate( (coefficient_matrix, constant_matrix), axis=1 ) rows, cols = table.shape strictly_diagonally_dominant(table) # Iterates the whole matrix for given number of times for _ in range(iterations): new_val = [] for row in range(rows): temp = 0 for col in range(cols): if col == row: denom = table[row][col] elif col == cols - 1: val = table[row][col] else: temp += (-1) * table[row][col] * init_val[col] temp = (temp + val) / denom new_val.append(temp) init_val = new_val return [float(i) for i in new_val] # Checks if the given matrix is strictly diagonally dominant def strictly_diagonally_dominant(table: NDArray[float64]) -> bool: """ >>> table = np.array([[4, 1, 1, 2], [1, 5, 2, -6], [1, 2, 4, -4]]) >>> strictly_diagonally_dominant(table) True >>> table = np.array([[4, 1, 1, 2], [1, 5, 2, -6], [1, 2, 3, -4]]) >>> strictly_diagonally_dominant(table) Traceback (most recent call last): ... ValueError: Coefficient matrix is not strictly diagonally dominant """ rows, cols = table.shape is_diagonally_dominant = True for i in range(0, rows): total = 0 for j in range(0, cols - 1): if i == j: continue else: total += table[i][j] if table[i][i] <= total: raise ValueError("Coefficient matrix is not strictly diagonally dominant") return is_diagonally_dominant # Test Cases if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 6: https://projecteuler.net/problem=6 Sum square difference The sum of the squares of the first ten natural numbers is, 1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640. Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum. """ def solution(n: int = 100) -> int: """ Returns the difference between the sum of the squares of the first n natural numbers and the square of the sum. >>> solution(10) 2640 >>> solution(15) 13160 >>> solution(20) 41230 >>> solution(50) 1582700 """ sum_of_squares = 0 sum_of_ints = 0 for i in range(1, n + 1): sum_of_squares += i**2 sum_of_ints += i return sum_of_ints**2 - sum_of_squares if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 6: https://projecteuler.net/problem=6 Sum square difference The sum of the squares of the first ten natural numbers is, 1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640. Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum. """ def solution(n: int = 100) -> int: """ Returns the difference between the sum of the squares of the first n natural numbers and the square of the sum. >>> solution(10) 2640 >>> solution(15) 13160 >>> solution(20) 41230 >>> solution(50) 1582700 """ sum_of_squares = 0 sum_of_ints = 0 for i in range(1, n + 1): sum_of_squares += i**2 sum_of_ints += i return sum_of_ints**2 - sum_of_squares if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
import os from itertools import chain from random import randrange, shuffle import pytest from .sol1 import PokerHand SORTED_HANDS = ( "4S 3H 2C 7S 5H", "9D 8H 2C 6S 7H", "2D 6D 9D TH 7D", "TC 8C 2S JH 6C", "JH 8S TH AH QH", "TS KS 5S 9S AC", "KD 6S 9D TH AD", "KS 8D 4D 9S 4S", # pair "8C 4S KH JS 4D", # pair "QH 8H KD JH 8S", # pair "KC 4H KS 2H 8D", # pair "KD 4S KC 3H 8S", # pair "AH 8S AS KC JH", # pair "3H 4C 4H 3S 2H", # 2 pairs "5S 5D 2C KH KH", # 2 pairs "3C KH 5D 5S KH", # 2 pairs "AS 3C KH AD KH", # 2 pairs "7C 7S 3S 7H 5S", # 3 of a kind "7C 7S KH 2H 7H", # 3 of a kind "AC KH QH AH AS", # 3 of a kind "2H 4D 3C AS 5S", # straight (low ace) "3C 5C 4C 2C 6H", # straight "6S 8S 7S 5H 9H", # straight "JS QS 9H TS KH", # straight "QC KH TS JS AH", # straight (high ace) "8C 9C 5C 3C TC", # flush "3S 8S 9S 5S KS", # flush "4C 5C 9C 8C KC", # flush "JH 8H AH KH QH", # flush "3D 2H 3H 2C 2D", # full house "2H 2C 3S 3H 3D", # full house "KH KC 3S 3H 3D", # full house "JC 6H JS JD JH", # 4 of a kind "JC 7H JS JD JH", # 4 of a kind "JC KH JS JD JH", # 4 of a kind "2S AS 4S 5S 3S", # straight flush (low ace) "2D 6D 3D 4D 5D", # straight flush "5C 6C 3C 7C 4C", # straight flush "JH 9H TH KH QH", # straight flush "JH AH TH KH QH", # royal flush (high ace straight flush) ) TEST_COMPARE = ( ("2H 3H 4H 5H 6H", "KS AS TS QS JS", "Loss"), ("2H 3H 4H 5H 6H", "AS AD AC AH JD", "Win"), ("AS AH 2H AD AC", "JS JD JC JH 3D", "Win"), ("2S AH 2H AS AC", "JS JD JC JH AD", "Loss"), ("2S AH 2H AS AC", "2H 3H 5H 6H 7H", "Win"), ("AS 3S 4S 8S 2S", "2H 3H 5H 6H 7H", "Win"), ("2H 3H 5H 6H 7H", "2S 3H 4H 5S 6C", "Win"), ("2S 3H 4H 5S 6C", "3D 4C 5H 6H 2S", "Tie"), ("2S 3H 4H 5S 6C", "AH AC 5H 6H AS", "Win"), ("2S 2H 4H 5S 4C", "AH AC 5H 6H AS", "Loss"), ("2S 2H 4H 5S 4C", "AH AC 5H 6H 7S", "Win"), ("6S AD 7H 4S AS", "AH AC 5H 6H 7S", "Loss"), ("2S AH 4H 5S KC", "AH AC 5H 6H 7S", "Loss"), ("2S 3H 6H 7S 9C", "7H 3C TH 6H 9S", "Loss"), ("4S 5H 6H TS AC", "3S 5H 6H TS AC", "Win"), ("2S AH 4H 5S 6C", "AD 4C 5H 6H 2C", "Tie"), ("AS AH 3H AD AC", "AS AH 2H AD AC", "Win"), ("AH AC 5H 5C QS", "AH AC 5H 5C KS", "Loss"), ("AH AC 5H 5C QS", "KH KC 5H 5C QS", "Win"), ("7C 7S KH 2H 7H", "3C 3S AH 2H 3H", "Win"), ("3C 3S AH 2H 3H", "7C 7S KH 2H 7H", "Loss"), ("6H 5H 4H 3H 2H", "5H 4H 3H 2H AH", "Win"), ("5H 4H 3H 2H AH", "5H 4H 3H 2H AH", "Tie"), ("5H 4H 3H 2H AH", "6H 5H 4H 3H 2H", "Loss"), ("AH AD KS KC AC", "AH KD KH AC KC", "Win"), ("2H 4D 3C AS 5S", "2H 4D 3C 6S 5S", "Loss"), ("2H 3S 3C 3H 2S", "3S 3C 2S 2H 2D", "Win"), ("4D 6D 5D 2D JH", "3S 8S 3H TC KH", "Loss"), ("4S 6C 8S 3S 7S", "AD KS 2D 7D 7C", "Loss"), ("6S 4C 7H 8C 3H", "5H JC AH 9D 9C", "Loss"), ("9D 9H JH TC QH", "3C 2S JS 5C 7H", "Win"), ("2H TC 8S AD 9S", "4H TS 7H 2C 5C", "Win"), ("9D 3S 2C 7S 7C", "JC TD 3C TC 9H", "Loss"), ) TEST_FLUSH = ( ("2H 3H 4H 5H 6H", True), ("AS AH 2H AD AC", False), ("2H 3H 5H 6H 7H", True), ("KS AS TS QS JS", True), ("8H 9H QS JS TH", False), ("AS 3S 4S 8S 2S", True), ) TEST_STRAIGHT = ( ("2H 3H 4H 5H 6H", True), ("AS AH 2H AD AC", False), ("2H 3H 5H 6H 7H", False), ("KS AS TS QS JS", True), ("8H 9H QS JS TH", True), ) TEST_FIVE_HIGH_STRAIGHT = ( ("2H 4D 3C AS 5S", True, [5, 4, 3, 2, 14]), ("2H 5D 3C AS 5S", False, [14, 5, 5, 3, 2]), ("JH QD KC AS TS", False, [14, 13, 12, 11, 10]), ("9D 3S 2C 7S 7C", False, [9, 7, 7, 3, 2]), ) TEST_KIND = ( ("JH AH TH KH QH", 0), ("JH 9H TH KH QH", 0), ("JC KH JS JD JH", 7), ("KH KC 3S 3H 3D", 6), ("8C 9C 5C 3C TC", 0), ("JS QS 9H TS KH", 0), ("7C 7S KH 2H 7H", 3), ("3C KH 5D 5S KH", 2), ("QH 8H KD JH 8S", 1), ("2D 6D 9D TH 7D", 0), ) TEST_TYPES = ( ("JH AH TH KH QH", 23), ("JH 9H TH KH QH", 22), ("JC KH JS JD JH", 21), ("KH KC 3S 3H 3D", 20), ("8C 9C 5C 3C TC", 19), ("JS QS 9H TS KH", 18), ("7C 7S KH 2H 7H", 17), ("3C KH 5D 5S KH", 16), ("QH 8H KD JH 8S", 15), ("2D 6D 9D TH 7D", 14), ) def generate_random_hand(): play, oppo = randrange(len(SORTED_HANDS)), randrange(len(SORTED_HANDS)) expected = ["Loss", "Tie", "Win"][(play >= oppo) + (play > oppo)] hand, other = SORTED_HANDS[play], SORTED_HANDS[oppo] return hand, other, expected def generate_random_hands(number_of_hands: int = 100): return (generate_random_hand() for _ in range(number_of_hands)) @pytest.mark.parametrize("hand, expected", TEST_FLUSH) def test_hand_is_flush(hand, expected): assert PokerHand(hand)._is_flush() == expected @pytest.mark.parametrize("hand, expected", TEST_STRAIGHT) def test_hand_is_straight(hand, expected): assert PokerHand(hand)._is_straight() == expected @pytest.mark.parametrize("hand, expected, card_values", TEST_FIVE_HIGH_STRAIGHT) def test_hand_is_five_high_straight(hand, expected, card_values): player = PokerHand(hand) assert player._is_five_high_straight() == expected assert player._card_values == card_values @pytest.mark.parametrize("hand, expected", TEST_KIND) def test_hand_is_same_kind(hand, expected): assert PokerHand(hand)._is_same_kind() == expected @pytest.mark.parametrize("hand, expected", TEST_TYPES) def test_hand_values(hand, expected): assert PokerHand(hand)._hand_type == expected @pytest.mark.parametrize("hand, other, expected", TEST_COMPARE) def test_compare_simple(hand, other, expected): assert PokerHand(hand).compare_with(PokerHand(other)) == expected @pytest.mark.parametrize("hand, other, expected", generate_random_hands()) def test_compare_random(hand, other, expected): assert PokerHand(hand).compare_with(PokerHand(other)) == expected def test_hand_sorted(): poker_hands = [PokerHand(hand) for hand in SORTED_HANDS] list_copy = poker_hands.copy() shuffle(list_copy) user_sorted = chain(sorted(list_copy)) for index, hand in enumerate(user_sorted): assert hand == poker_hands[index] def test_custom_sort_five_high_straight(): # Test that five high straights are compared correctly. pokerhands = [PokerHand("2D AC 3H 4H 5S"), PokerHand("2S 3H 4H 5S 6C")] pokerhands.sort(reverse=True) assert pokerhands[0].__str__() == "2S 3H 4H 5S 6C" def test_multiple_calls_five_high_straight(): # Multiple calls to five_high_straight function should still return True # and shouldn't mutate the list in every call other than the first. pokerhand = PokerHand("2C 4S AS 3D 5C") expected = True expected_card_values = [5, 4, 3, 2, 14] for _ in range(10): assert pokerhand._is_five_high_straight() == expected assert pokerhand._card_values == expected_card_values def test_euler_project(): # Problem number 54 from Project Euler # Testing from poker_hands.txt file answer = 0 script_dir = os.path.abspath(os.path.dirname(__file__)) poker_hands = os.path.join(script_dir, "poker_hands.txt") with open(poker_hands) as file_hand: for line in file_hand: player_hand = line[:14].strip() opponent_hand = line[15:].strip() player, opponent = PokerHand(player_hand), PokerHand(opponent_hand) output = player.compare_with(opponent) if output == "Win": answer += 1 assert answer == 376
import os from itertools import chain from random import randrange, shuffle import pytest from .sol1 import PokerHand SORTED_HANDS = ( "4S 3H 2C 7S 5H", "9D 8H 2C 6S 7H", "2D 6D 9D TH 7D", "TC 8C 2S JH 6C", "JH 8S TH AH QH", "TS KS 5S 9S AC", "KD 6S 9D TH AD", "KS 8D 4D 9S 4S", # pair "8C 4S KH JS 4D", # pair "QH 8H KD JH 8S", # pair "KC 4H KS 2H 8D", # pair "KD 4S KC 3H 8S", # pair "AH 8S AS KC JH", # pair "3H 4C 4H 3S 2H", # 2 pairs "5S 5D 2C KH KH", # 2 pairs "3C KH 5D 5S KH", # 2 pairs "AS 3C KH AD KH", # 2 pairs "7C 7S 3S 7H 5S", # 3 of a kind "7C 7S KH 2H 7H", # 3 of a kind "AC KH QH AH AS", # 3 of a kind "2H 4D 3C AS 5S", # straight (low ace) "3C 5C 4C 2C 6H", # straight "6S 8S 7S 5H 9H", # straight "JS QS 9H TS KH", # straight "QC KH TS JS AH", # straight (high ace) "8C 9C 5C 3C TC", # flush "3S 8S 9S 5S KS", # flush "4C 5C 9C 8C KC", # flush "JH 8H AH KH QH", # flush "3D 2H 3H 2C 2D", # full house "2H 2C 3S 3H 3D", # full house "KH KC 3S 3H 3D", # full house "JC 6H JS JD JH", # 4 of a kind "JC 7H JS JD JH", # 4 of a kind "JC KH JS JD JH", # 4 of a kind "2S AS 4S 5S 3S", # straight flush (low ace) "2D 6D 3D 4D 5D", # straight flush "5C 6C 3C 7C 4C", # straight flush "JH 9H TH KH QH", # straight flush "JH AH TH KH QH", # royal flush (high ace straight flush) ) TEST_COMPARE = ( ("2H 3H 4H 5H 6H", "KS AS TS QS JS", "Loss"), ("2H 3H 4H 5H 6H", "AS AD AC AH JD", "Win"), ("AS AH 2H AD AC", "JS JD JC JH 3D", "Win"), ("2S AH 2H AS AC", "JS JD JC JH AD", "Loss"), ("2S AH 2H AS AC", "2H 3H 5H 6H 7H", "Win"), ("AS 3S 4S 8S 2S", "2H 3H 5H 6H 7H", "Win"), ("2H 3H 5H 6H 7H", "2S 3H 4H 5S 6C", "Win"), ("2S 3H 4H 5S 6C", "3D 4C 5H 6H 2S", "Tie"), ("2S 3H 4H 5S 6C", "AH AC 5H 6H AS", "Win"), ("2S 2H 4H 5S 4C", "AH AC 5H 6H AS", "Loss"), ("2S 2H 4H 5S 4C", "AH AC 5H 6H 7S", "Win"), ("6S AD 7H 4S AS", "AH AC 5H 6H 7S", "Loss"), ("2S AH 4H 5S KC", "AH AC 5H 6H 7S", "Loss"), ("2S 3H 6H 7S 9C", "7H 3C TH 6H 9S", "Loss"), ("4S 5H 6H TS AC", "3S 5H 6H TS AC", "Win"), ("2S AH 4H 5S 6C", "AD 4C 5H 6H 2C", "Tie"), ("AS AH 3H AD AC", "AS AH 2H AD AC", "Win"), ("AH AC 5H 5C QS", "AH AC 5H 5C KS", "Loss"), ("AH AC 5H 5C QS", "KH KC 5H 5C QS", "Win"), ("7C 7S KH 2H 7H", "3C 3S AH 2H 3H", "Win"), ("3C 3S AH 2H 3H", "7C 7S KH 2H 7H", "Loss"), ("6H 5H 4H 3H 2H", "5H 4H 3H 2H AH", "Win"), ("5H 4H 3H 2H AH", "5H 4H 3H 2H AH", "Tie"), ("5H 4H 3H 2H AH", "6H 5H 4H 3H 2H", "Loss"), ("AH AD KS KC AC", "AH KD KH AC KC", "Win"), ("2H 4D 3C AS 5S", "2H 4D 3C 6S 5S", "Loss"), ("2H 3S 3C 3H 2S", "3S 3C 2S 2H 2D", "Win"), ("4D 6D 5D 2D JH", "3S 8S 3H TC KH", "Loss"), ("4S 6C 8S 3S 7S", "AD KS 2D 7D 7C", "Loss"), ("6S 4C 7H 8C 3H", "5H JC AH 9D 9C", "Loss"), ("9D 9H JH TC QH", "3C 2S JS 5C 7H", "Win"), ("2H TC 8S AD 9S", "4H TS 7H 2C 5C", "Win"), ("9D 3S 2C 7S 7C", "JC TD 3C TC 9H", "Loss"), ) TEST_FLUSH = ( ("2H 3H 4H 5H 6H", True), ("AS AH 2H AD AC", False), ("2H 3H 5H 6H 7H", True), ("KS AS TS QS JS", True), ("8H 9H QS JS TH", False), ("AS 3S 4S 8S 2S", True), ) TEST_STRAIGHT = ( ("2H 3H 4H 5H 6H", True), ("AS AH 2H AD AC", False), ("2H 3H 5H 6H 7H", False), ("KS AS TS QS JS", True), ("8H 9H QS JS TH", True), ) TEST_FIVE_HIGH_STRAIGHT = ( ("2H 4D 3C AS 5S", True, [5, 4, 3, 2, 14]), ("2H 5D 3C AS 5S", False, [14, 5, 5, 3, 2]), ("JH QD KC AS TS", False, [14, 13, 12, 11, 10]), ("9D 3S 2C 7S 7C", False, [9, 7, 7, 3, 2]), ) TEST_KIND = ( ("JH AH TH KH QH", 0), ("JH 9H TH KH QH", 0), ("JC KH JS JD JH", 7), ("KH KC 3S 3H 3D", 6), ("8C 9C 5C 3C TC", 0), ("JS QS 9H TS KH", 0), ("7C 7S KH 2H 7H", 3), ("3C KH 5D 5S KH", 2), ("QH 8H KD JH 8S", 1), ("2D 6D 9D TH 7D", 0), ) TEST_TYPES = ( ("JH AH TH KH QH", 23), ("JH 9H TH KH QH", 22), ("JC KH JS JD JH", 21), ("KH KC 3S 3H 3D", 20), ("8C 9C 5C 3C TC", 19), ("JS QS 9H TS KH", 18), ("7C 7S KH 2H 7H", 17), ("3C KH 5D 5S KH", 16), ("QH 8H KD JH 8S", 15), ("2D 6D 9D TH 7D", 14), ) def generate_random_hand(): play, oppo = randrange(len(SORTED_HANDS)), randrange(len(SORTED_HANDS)) expected = ["Loss", "Tie", "Win"][(play >= oppo) + (play > oppo)] hand, other = SORTED_HANDS[play], SORTED_HANDS[oppo] return hand, other, expected def generate_random_hands(number_of_hands: int = 100): return (generate_random_hand() for _ in range(number_of_hands)) @pytest.mark.parametrize("hand, expected", TEST_FLUSH) def test_hand_is_flush(hand, expected): assert PokerHand(hand)._is_flush() == expected @pytest.mark.parametrize("hand, expected", TEST_STRAIGHT) def test_hand_is_straight(hand, expected): assert PokerHand(hand)._is_straight() == expected @pytest.mark.parametrize("hand, expected, card_values", TEST_FIVE_HIGH_STRAIGHT) def test_hand_is_five_high_straight(hand, expected, card_values): player = PokerHand(hand) assert player._is_five_high_straight() == expected assert player._card_values == card_values @pytest.mark.parametrize("hand, expected", TEST_KIND) def test_hand_is_same_kind(hand, expected): assert PokerHand(hand)._is_same_kind() == expected @pytest.mark.parametrize("hand, expected", TEST_TYPES) def test_hand_values(hand, expected): assert PokerHand(hand)._hand_type == expected @pytest.mark.parametrize("hand, other, expected", TEST_COMPARE) def test_compare_simple(hand, other, expected): assert PokerHand(hand).compare_with(PokerHand(other)) == expected @pytest.mark.parametrize("hand, other, expected", generate_random_hands()) def test_compare_random(hand, other, expected): assert PokerHand(hand).compare_with(PokerHand(other)) == expected def test_hand_sorted(): poker_hands = [PokerHand(hand) for hand in SORTED_HANDS] list_copy = poker_hands.copy() shuffle(list_copy) user_sorted = chain(sorted(list_copy)) for index, hand in enumerate(user_sorted): assert hand == poker_hands[index] def test_custom_sort_five_high_straight(): # Test that five high straights are compared correctly. pokerhands = [PokerHand("2D AC 3H 4H 5S"), PokerHand("2S 3H 4H 5S 6C")] pokerhands.sort(reverse=True) assert pokerhands[0].__str__() == "2S 3H 4H 5S 6C" def test_multiple_calls_five_high_straight(): # Multiple calls to five_high_straight function should still return True # and shouldn't mutate the list in every call other than the first. pokerhand = PokerHand("2C 4S AS 3D 5C") expected = True expected_card_values = [5, 4, 3, 2, 14] for _ in range(10): assert pokerhand._is_five_high_straight() == expected assert pokerhand._card_values == expected_card_values def test_euler_project(): # Problem number 54 from Project Euler # Testing from poker_hands.txt file answer = 0 script_dir = os.path.abspath(os.path.dirname(__file__)) poker_hands = os.path.join(script_dir, "poker_hands.txt") with open(poker_hands) as file_hand: for line in file_hand: player_hand = line[:14].strip() opponent_hand = line[15:].strip() player, opponent = PokerHand(player_hand), PokerHand(opponent_hand) output = player.compare_with(opponent) if output == "Win": answer += 1 assert answer == 376
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
"""Matrix Exponentiation""" import timeit """ Matrix Exponentiation is a technique to solve linear recurrences in logarithmic time. You read more about it here: https://zobayer.blogspot.com/2010/11/matrix-exponentiation.html https://www.hackerearth.com/practice/notes/matrix-exponentiation-1/ """ class Matrix: def __init__(self, arg): if isinstance(arg, list): # Initializes a matrix identical to the one provided. self.t = arg self.n = len(arg) else: # Initializes a square matrix of the given size and set values to zero. self.n = arg self.t = [[0 for _ in range(self.n)] for _ in range(self.n)] def __mul__(self, b): matrix = Matrix(self.n) for i in range(self.n): for j in range(self.n): for k in range(self.n): matrix.t[i][j] += self.t[i][k] * b.t[k][j] return matrix def modular_exponentiation(a, b): matrix = Matrix([[1, 0], [0, 1]]) while b > 0: if b & 1: matrix *= a a *= a b >>= 1 return matrix def fibonacci_with_matrix_exponentiation(n, f1, f2): # Trivial Cases if n == 1: return f1 elif n == 2: return f2 matrix = Matrix([[1, 1], [1, 0]]) matrix = modular_exponentiation(matrix, n - 2) return f2 * matrix.t[0][0] + f1 * matrix.t[0][1] def simple_fibonacci(n, f1, f2): # Trivial Cases if n == 1: return f1 elif n == 2: return f2 fn_1 = f1 fn_2 = f2 n -= 2 while n > 0: fn_1, fn_2 = fn_1 + fn_2, fn_1 n -= 1 return fn_1 def matrix_exponentiation_time(): setup = """ from random import randint from __main__ import fibonacci_with_matrix_exponentiation """ code = "fibonacci_with_matrix_exponentiation(randint(1,70000), 1, 1)" exec_time = timeit.timeit(setup=setup, stmt=code, number=100) print("With matrix exponentiation the average execution time is ", exec_time / 100) return exec_time def simple_fibonacci_time(): setup = """ from random import randint from __main__ import simple_fibonacci """ code = "simple_fibonacci(randint(1,70000), 1, 1)" exec_time = timeit.timeit(setup=setup, stmt=code, number=100) print( "Without matrix exponentiation the average execution time is ", exec_time / 100 ) return exec_time def main(): matrix_exponentiation_time() simple_fibonacci_time() if __name__ == "__main__": main()
"""Matrix Exponentiation""" import timeit """ Matrix Exponentiation is a technique to solve linear recurrences in logarithmic time. You read more about it here: https://zobayer.blogspot.com/2010/11/matrix-exponentiation.html https://www.hackerearth.com/practice/notes/matrix-exponentiation-1/ """ class Matrix: def __init__(self, arg): if isinstance(arg, list): # Initializes a matrix identical to the one provided. self.t = arg self.n = len(arg) else: # Initializes a square matrix of the given size and set values to zero. self.n = arg self.t = [[0 for _ in range(self.n)] for _ in range(self.n)] def __mul__(self, b): matrix = Matrix(self.n) for i in range(self.n): for j in range(self.n): for k in range(self.n): matrix.t[i][j] += self.t[i][k] * b.t[k][j] return matrix def modular_exponentiation(a, b): matrix = Matrix([[1, 0], [0, 1]]) while b > 0: if b & 1: matrix *= a a *= a b >>= 1 return matrix def fibonacci_with_matrix_exponentiation(n, f1, f2): # Trivial Cases if n == 1: return f1 elif n == 2: return f2 matrix = Matrix([[1, 1], [1, 0]]) matrix = modular_exponentiation(matrix, n - 2) return f2 * matrix.t[0][0] + f1 * matrix.t[0][1] def simple_fibonacci(n, f1, f2): # Trivial Cases if n == 1: return f1 elif n == 2: return f2 fn_1 = f1 fn_2 = f2 n -= 2 while n > 0: fn_1, fn_2 = fn_1 + fn_2, fn_1 n -= 1 return fn_1 def matrix_exponentiation_time(): setup = """ from random import randint from __main__ import fibonacci_with_matrix_exponentiation """ code = "fibonacci_with_matrix_exponentiation(randint(1,70000), 1, 1)" exec_time = timeit.timeit(setup=setup, stmt=code, number=100) print("With matrix exponentiation the average execution time is ", exec_time / 100) return exec_time def simple_fibonacci_time(): setup = """ from random import randint from __main__ import simple_fibonacci """ code = "simple_fibonacci(randint(1,70000), 1, 1)" exec_time = timeit.timeit(setup=setup, stmt=code, number=100) print( "Without matrix exponentiation the average execution time is ", exec_time / 100 ) return exec_time def main(): matrix_exponentiation_time() simple_fibonacci_time() if __name__ == "__main__": main()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 1: https://projecteuler.net/problem=1 Multiples of 3 and 5 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. """ def solution(n: int = 1000) -> int: """ Returns the sum of all the multiples of 3 or 5 below n. >>> solution(3) 0 >>> solution(4) 3 >>> solution(10) 23 >>> solution(600) 83700 >>> solution(-7) 0 """ return sum(e for e in range(3, n) if e % 3 == 0 or e % 5 == 0) if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 1: https://projecteuler.net/problem=1 Multiples of 3 and 5 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. """ def solution(n: int = 1000) -> int: """ Returns the sum of all the multiples of 3 or 5 below n. >>> solution(3) 0 >>> solution(4) 3 >>> solution(10) 23 >>> solution(600) 83700 >>> solution(-7) 0 """ return sum(e for e in range(3, n) if e % 3 == 0 or e % 5 == 0) if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
def alternative_string_arrange(first_str: str, second_str: str) -> str: """ Return the alternative arrangements of the two strings. :param first_str: :param second_str: :return: String >>> alternative_string_arrange("ABCD", "XY") 'AXBYCD' >>> alternative_string_arrange("XY", "ABCD") 'XAYBCD' >>> alternative_string_arrange("AB", "XYZ") 'AXBYZ' >>> alternative_string_arrange("ABC", "") 'ABC' """ first_str_length: int = len(first_str) second_str_length: int = len(second_str) abs_length: int = ( first_str_length if first_str_length > second_str_length else second_str_length ) output_list: list = [] for char_count in range(abs_length): if char_count < first_str_length: output_list.append(first_str[char_count]) if char_count < second_str_length: output_list.append(second_str[char_count]) return "".join(output_list) if __name__ == "__main__": print(alternative_string_arrange("AB", "XYZ"), end=" ")
def alternative_string_arrange(first_str: str, second_str: str) -> str: """ Return the alternative arrangements of the two strings. :param first_str: :param second_str: :return: String >>> alternative_string_arrange("ABCD", "XY") 'AXBYCD' >>> alternative_string_arrange("XY", "ABCD") 'XAYBCD' >>> alternative_string_arrange("AB", "XYZ") 'AXBYZ' >>> alternative_string_arrange("ABC", "") 'ABC' """ first_str_length: int = len(first_str) second_str_length: int = len(second_str) abs_length: int = ( first_str_length if first_str_length > second_str_length else second_str_length ) output_list: list = [] for char_count in range(abs_length): if char_count < first_str_length: output_list.append(first_str[char_count]) if char_count < second_str_length: output_list.append(second_str[char_count]) return "".join(output_list) if __name__ == "__main__": print(alternative_string_arrange("AB", "XYZ"), end=" ")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" The Fibonacci sequence is defined by the recurrence relation: Fn = Fn−1 + Fn−2, where F1 = 1 and F2 = 1. Hence the first 12 terms will be: F1 = 1 F2 = 1 F3 = 2 F4 = 3 F5 = 5 F6 = 8 F7 = 13 F8 = 21 F9 = 34 F10 = 55 F11 = 89 F12 = 144 The 12th term, F12, is the first term to contain three digits. What is the index of the first term in the Fibonacci sequence to contain 1000 digits? """ def solution(n: int = 1000) -> int: """Returns the index of the first term in the Fibonacci sequence to contain n digits. >>> solution(1000) 4782 >>> solution(100) 476 >>> solution(50) 237 >>> solution(3) 12 """ f1, f2 = 1, 1 index = 2 while True: i = 0 f = f1 + f2 f1, f2 = f2, f index += 1 for _ in str(f): i += 1 if i == n: break return index if __name__ == "__main__": print(solution(int(str(input()).strip())))
""" The Fibonacci sequence is defined by the recurrence relation: Fn = Fn−1 + Fn−2, where F1 = 1 and F2 = 1. Hence the first 12 terms will be: F1 = 1 F2 = 1 F3 = 2 F4 = 3 F5 = 5 F6 = 8 F7 = 13 F8 = 21 F9 = 34 F10 = 55 F11 = 89 F12 = 144 The 12th term, F12, is the first term to contain three digits. What is the index of the first term in the Fibonacci sequence to contain 1000 digits? """ def solution(n: int = 1000) -> int: """Returns the index of the first term in the Fibonacci sequence to contain n digits. >>> solution(1000) 4782 >>> solution(100) 476 >>> solution(50) 237 >>> solution(3) 12 """ f1, f2 = 1, 1 index = 2 while True: i = 0 f = f1 + f2 f1, f2 = f2, f index += 1 for _ in str(f): i += 1 if i == n: break return index if __name__ == "__main__": print(solution(int(str(input()).strip())))
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
from collections import Counter def sock_merchant(colors: list[int]) -> int: """ >>> sock_merchant([10, 20, 20, 10, 10, 30, 50, 10, 20]) 3 >>> sock_merchant([1, 1, 3, 3]) 2 """ return sum(socks_by_color // 2 for socks_by_color in Counter(colors).values()) if __name__ == "__main__": import doctest doctest.testmod() colors = [int(x) for x in input("Enter socks by color :").rstrip().split()] print(f"sock_merchant({colors}) = {sock_merchant(colors)}")
from collections import Counter def sock_merchant(colors: list[int]) -> int: """ >>> sock_merchant([10, 20, 20, 10, 10, 30, 50, 10, 20]) 3 >>> sock_merchant([1, 1, 3, 3]) 2 """ return sum(socks_by_color // 2 for socks_by_color in Counter(colors).values()) if __name__ == "__main__": import doctest doctest.testmod() colors = [int(x) for x in input("Enter socks by color :").rstrip().split()] print(f"sock_merchant({colors}) = {sock_merchant(colors)}")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 203: https://projecteuler.net/problem=203 The binomial coefficients (n k) can be arranged in triangular form, Pascal's triangle, like this: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 1 6 15 20 15 6 1 1 7 21 35 35 21 7 1 ......... It can be seen that the first eight rows of Pascal's triangle contain twelve distinct numbers: 1, 2, 3, 4, 5, 6, 7, 10, 15, 20, 21 and 35. A positive integer n is called squarefree if no square of a prime divides n. Of the twelve distinct numbers in the first eight rows of Pascal's triangle, all except 4 and 20 are squarefree. The sum of the distinct squarefree numbers in the first eight rows is 105. Find the sum of the distinct squarefree numbers in the first 51 rows of Pascal's triangle. References: - https://en.wikipedia.org/wiki/Pascal%27s_triangle """ from __future__ import annotations def get_pascal_triangle_unique_coefficients(depth: int) -> set[int]: """ Returns the unique coefficients of a Pascal's triangle of depth "depth". The coefficients of this triangle are symmetric. A further improvement to this method could be to calculate the coefficients once per level. Nonetheless, the current implementation is fast enough for the original problem. >>> get_pascal_triangle_unique_coefficients(1) {1} >>> get_pascal_triangle_unique_coefficients(2) {1} >>> get_pascal_triangle_unique_coefficients(3) {1, 2} >>> get_pascal_triangle_unique_coefficients(8) {1, 2, 3, 4, 5, 6, 7, 35, 10, 15, 20, 21} """ coefficients = {1} previous_coefficients = [1] for _ in range(2, depth + 1): coefficients_begins_one = previous_coefficients + [0] coefficients_ends_one = [0] + previous_coefficients previous_coefficients = [] for x, y in zip(coefficients_begins_one, coefficients_ends_one): coefficients.add(x + y) previous_coefficients.append(x + y) return coefficients def get_squarefrees(unique_coefficients: set[int]) -> set[int]: """ Calculates the squarefree numbers inside unique_coefficients. Based on the definition of a non-squarefree number, then any non-squarefree n can be decomposed as n = p*p*r, where p is positive prime number and r is a positive integer. Under the previous formula, any coefficient that is lower than p*p is squarefree as r cannot be negative. On the contrary, if any r exists such that n = p*p*r, then the number is non-squarefree. >>> get_squarefrees({1}) {1} >>> get_squarefrees({1, 2}) {1, 2} >>> get_squarefrees({1, 2, 3, 4, 5, 6, 7, 35, 10, 15, 20, 21}) {1, 2, 3, 5, 6, 7, 35, 10, 15, 21} """ non_squarefrees = set() for number in unique_coefficients: divisor = 2 copy_number = number while divisor**2 <= copy_number: multiplicity = 0 while copy_number % divisor == 0: copy_number //= divisor multiplicity += 1 if multiplicity >= 2: non_squarefrees.add(number) break divisor += 1 return unique_coefficients.difference(non_squarefrees) def solution(n: int = 51) -> int: """ Returns the sum of squarefrees for a given Pascal's Triangle of depth n. >>> solution(1) 1 >>> solution(8) 105 >>> solution(9) 175 """ unique_coefficients = get_pascal_triangle_unique_coefficients(n) squarefrees = get_squarefrees(unique_coefficients) return sum(squarefrees) if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 203: https://projecteuler.net/problem=203 The binomial coefficients (n k) can be arranged in triangular form, Pascal's triangle, like this: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 1 6 15 20 15 6 1 1 7 21 35 35 21 7 1 ......... It can be seen that the first eight rows of Pascal's triangle contain twelve distinct numbers: 1, 2, 3, 4, 5, 6, 7, 10, 15, 20, 21 and 35. A positive integer n is called squarefree if no square of a prime divides n. Of the twelve distinct numbers in the first eight rows of Pascal's triangle, all except 4 and 20 are squarefree. The sum of the distinct squarefree numbers in the first eight rows is 105. Find the sum of the distinct squarefree numbers in the first 51 rows of Pascal's triangle. References: - https://en.wikipedia.org/wiki/Pascal%27s_triangle """ from __future__ import annotations def get_pascal_triangle_unique_coefficients(depth: int) -> set[int]: """ Returns the unique coefficients of a Pascal's triangle of depth "depth". The coefficients of this triangle are symmetric. A further improvement to this method could be to calculate the coefficients once per level. Nonetheless, the current implementation is fast enough for the original problem. >>> get_pascal_triangle_unique_coefficients(1) {1} >>> get_pascal_triangle_unique_coefficients(2) {1} >>> get_pascal_triangle_unique_coefficients(3) {1, 2} >>> get_pascal_triangle_unique_coefficients(8) {1, 2, 3, 4, 5, 6, 7, 35, 10, 15, 20, 21} """ coefficients = {1} previous_coefficients = [1] for _ in range(2, depth + 1): coefficients_begins_one = previous_coefficients + [0] coefficients_ends_one = [0] + previous_coefficients previous_coefficients = [] for x, y in zip(coefficients_begins_one, coefficients_ends_one): coefficients.add(x + y) previous_coefficients.append(x + y) return coefficients def get_squarefrees(unique_coefficients: set[int]) -> set[int]: """ Calculates the squarefree numbers inside unique_coefficients. Based on the definition of a non-squarefree number, then any non-squarefree n can be decomposed as n = p*p*r, where p is positive prime number and r is a positive integer. Under the previous formula, any coefficient that is lower than p*p is squarefree as r cannot be negative. On the contrary, if any r exists such that n = p*p*r, then the number is non-squarefree. >>> get_squarefrees({1}) {1} >>> get_squarefrees({1, 2}) {1, 2} >>> get_squarefrees({1, 2, 3, 4, 5, 6, 7, 35, 10, 15, 20, 21}) {1, 2, 3, 5, 6, 7, 35, 10, 15, 21} """ non_squarefrees = set() for number in unique_coefficients: divisor = 2 copy_number = number while divisor**2 <= copy_number: multiplicity = 0 while copy_number % divisor == 0: copy_number //= divisor multiplicity += 1 if multiplicity >= 2: non_squarefrees.add(number) break divisor += 1 return unique_coefficients.difference(non_squarefrees) def solution(n: int = 51) -> int: """ Returns the sum of squarefrees for a given Pascal's Triangle of depth n. >>> solution(1) 1 >>> solution(8) 105 >>> solution(9) 175 """ unique_coefficients = get_pascal_triangle_unique_coefficients(n) squarefrees = get_squarefrees(unique_coefficients) return sum(squarefrees) if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Convolutional Neural Network Objective : To train a CNN model detect if TB is present in Lung X-ray or not. Resources CNN Theory : https://en.wikipedia.org/wiki/Convolutional_neural_network Resources Tensorflow : https://www.tensorflow.org/tutorials/images/cnn Download dataset from : https://lhncbc.nlm.nih.gov/LHC-publications/pubs/TuberculosisChestXrayImageDataSets.html 1. Download the dataset folder and create two folder training set and test set in the parent dataste folder 2. Move 30-40 image from both TB positive and TB Negative folder in the test set folder 3. The labels of the iamges will be extracted from the folder name the image is present in. """ # Part 1 - Building the CNN import numpy as np # Importing the Keras libraries and packages import tensorflow as tf from tensorflow.keras import layers, models if __name__ == "__main__": # Initialising the CNN classifier = models.Sequential() # Step 1 - Convolution classifier.add( layers.Conv2D(32, (3, 3), input_shape=(64, 64, 3), activation="relu") ) # Step 2 - Pooling classifier.add(layers.MaxPooling2D(pool_size=(2, 2))) # Adding a second convolutional layer classifier.add(layers.Conv2D(32, (3, 3), activation="relu")) classifier.add(layers.MaxPooling2D(pool_size=(2, 2))) # Step 3 - Flattening classifier.add(layers.Flatten()) # Step 4 - Full connection classifier.add(layers.Dense(units=128, activation="relu")) classifier.add(layers.Dense(units=1, activation="sigmoid")) # Compiling the CNN classifier.compile( optimizer="adam", loss="binary_crossentropy", metrics=["accuracy"] ) # Part 2 - Fitting the CNN to the images # Load Trained model weights # from keras.models import load_model # regressor=load_model('cnn.h5') train_datagen = tf.keras.preprocessing.image.ImageDataGenerator( rescale=1.0 / 255, shear_range=0.2, zoom_range=0.2, horizontal_flip=True ) test_datagen = tf.keras.preprocessing.image.ImageDataGenerator(rescale=1.0 / 255) training_set = train_datagen.flow_from_directory( "dataset/training_set", target_size=(64, 64), batch_size=32, class_mode="binary" ) test_set = test_datagen.flow_from_directory( "dataset/test_set", target_size=(64, 64), batch_size=32, class_mode="binary" ) classifier.fit_generator( training_set, steps_per_epoch=5, epochs=30, validation_data=test_set ) classifier.save("cnn.h5") # Part 3 - Making new predictions test_image = tf.keras.preprocessing.image.load_img( "dataset/single_prediction/image.png", target_size=(64, 64) ) test_image = tf.keras.preprocessing.image.img_to_array(test_image) test_image = np.expand_dims(test_image, axis=0) result = classifier.predict(test_image) training_set.class_indices if result[0][0] == 0: prediction = "Normal" if result[0][0] == 1: prediction = "Abnormality detected"
""" Convolutional Neural Network Objective : To train a CNN model detect if TB is present in Lung X-ray or not. Resources CNN Theory : https://en.wikipedia.org/wiki/Convolutional_neural_network Resources Tensorflow : https://www.tensorflow.org/tutorials/images/cnn Download dataset from : https://lhncbc.nlm.nih.gov/LHC-publications/pubs/TuberculosisChestXrayImageDataSets.html 1. Download the dataset folder and create two folder training set and test set in the parent dataste folder 2. Move 30-40 image from both TB positive and TB Negative folder in the test set folder 3. The labels of the iamges will be extracted from the folder name the image is present in. """ # Part 1 - Building the CNN import numpy as np # Importing the Keras libraries and packages import tensorflow as tf from tensorflow.keras import layers, models if __name__ == "__main__": # Initialising the CNN classifier = models.Sequential() # Step 1 - Convolution classifier.add( layers.Conv2D(32, (3, 3), input_shape=(64, 64, 3), activation="relu") ) # Step 2 - Pooling classifier.add(layers.MaxPooling2D(pool_size=(2, 2))) # Adding a second convolutional layer classifier.add(layers.Conv2D(32, (3, 3), activation="relu")) classifier.add(layers.MaxPooling2D(pool_size=(2, 2))) # Step 3 - Flattening classifier.add(layers.Flatten()) # Step 4 - Full connection classifier.add(layers.Dense(units=128, activation="relu")) classifier.add(layers.Dense(units=1, activation="sigmoid")) # Compiling the CNN classifier.compile( optimizer="adam", loss="binary_crossentropy", metrics=["accuracy"] ) # Part 2 - Fitting the CNN to the images # Load Trained model weights # from keras.models import load_model # regressor=load_model('cnn.h5') train_datagen = tf.keras.preprocessing.image.ImageDataGenerator( rescale=1.0 / 255, shear_range=0.2, zoom_range=0.2, horizontal_flip=True ) test_datagen = tf.keras.preprocessing.image.ImageDataGenerator(rescale=1.0 / 255) training_set = train_datagen.flow_from_directory( "dataset/training_set", target_size=(64, 64), batch_size=32, class_mode="binary" ) test_set = test_datagen.flow_from_directory( "dataset/test_set", target_size=(64, 64), batch_size=32, class_mode="binary" ) classifier.fit_generator( training_set, steps_per_epoch=5, epochs=30, validation_data=test_set ) classifier.save("cnn.h5") # Part 3 - Making new predictions test_image = tf.keras.preprocessing.image.load_img( "dataset/single_prediction/image.png", target_size=(64, 64) ) test_image = tf.keras.preprocessing.image.img_to_array(test_image) test_image = np.expand_dims(test_image, axis=0) result = classifier.predict(test_image) training_set.class_indices if result[0][0] == 0: prediction = "Normal" if result[0][0] == 1: prediction = "Abnormality detected"
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Problem 81: https://projecteuler.net/problem=81 In the 5 by 5 matrix below, the minimal path sum from the top left to the bottom right, by only moving to the right and down, is indicated in bold red and is equal to 2427. [131] 673 234 103 18 [201] [96] [342] 965 150 630 803 [746] [422] 111 537 699 497 [121] 956 805 732 524 [37] [331] Find the minimal path sum from the top left to the bottom right by only moving right and down in matrix.txt (https://projecteuler.net/project/resources/p081_matrix.txt), a 31K text file containing an 80 by 80 matrix. """ import os def solution(filename: str = "matrix.txt") -> int: """ Returns the minimal path sum from the top left to the bottom right of the matrix. >>> solution() 427337 """ with open(os.path.join(os.path.dirname(__file__), filename)) as in_file: data = in_file.read() grid = [[int(cell) for cell in row.split(",")] for row in data.strip().splitlines()] dp = [[0 for cell in row] for row in grid] n = len(grid[0]) dp = [[0 for i in range(n)] for j in range(n)] dp[0][0] = grid[0][0] for i in range(1, n): dp[0][i] = grid[0][i] + dp[0][i - 1] for i in range(1, n): dp[i][0] = grid[i][0] + dp[i - 1][0] for i in range(1, n): for j in range(1, n): dp[i][j] = grid[i][j] + min(dp[i - 1][j], dp[i][j - 1]) return dp[-1][-1] if __name__ == "__main__": print(f"{solution() = }")
""" Problem 81: https://projecteuler.net/problem=81 In the 5 by 5 matrix below, the minimal path sum from the top left to the bottom right, by only moving to the right and down, is indicated in bold red and is equal to 2427. [131] 673 234 103 18 [201] [96] [342] 965 150 630 803 [746] [422] 111 537 699 497 [121] 956 805 732 524 [37] [331] Find the minimal path sum from the top left to the bottom right by only moving right and down in matrix.txt (https://projecteuler.net/project/resources/p081_matrix.txt), a 31K text file containing an 80 by 80 matrix. """ import os def solution(filename: str = "matrix.txt") -> int: """ Returns the minimal path sum from the top left to the bottom right of the matrix. >>> solution() 427337 """ with open(os.path.join(os.path.dirname(__file__), filename)) as in_file: data = in_file.read() grid = [[int(cell) for cell in row.split(",")] for row in data.strip().splitlines()] dp = [[0 for cell in row] for row in grid] n = len(grid[0]) dp = [[0 for i in range(n)] for j in range(n)] dp[0][0] = grid[0][0] for i in range(1, n): dp[0][i] = grid[0][i] + dp[0][i - 1] for i in range(1, n): dp[i][0] = grid[i][0] + dp[i - 1][0] for i in range(1, n): for j in range(1, n): dp[i][j] = grid[i][j] + min(dp[i - 1][j], dp[i][j - 1]) return dp[-1][-1] if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Factorial of a number using memoization from functools import lru_cache @lru_cache def factorial(num: int) -> int: """ >>> factorial(7) 5040 >>> factorial(-1) Traceback (most recent call last): ... ValueError: Number should not be negative. >>> [factorial(i) for i in range(10)] [1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362880] """ if num < 0: raise ValueError("Number should not be negative.") return 1 if num in (0, 1) else num * factorial(num - 1) if __name__ == "__main__": import doctest doctest.testmod()
# Factorial of a number using memoization from functools import lru_cache @lru_cache def factorial(num: int) -> int: """ >>> factorial(7) 5040 >>> factorial(-1) Traceback (most recent call last): ... ValueError: Number should not be negative. >>> [factorial(i) for i in range(10)] [1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362880] """ if num < 0: raise ValueError("Number should not be negative.") return 1 if num in (0, 1) else num * factorial(num - 1) if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" A Queue using a linked list like structure """ from __future__ import annotations from collections.abc import Iterator from typing import Any class Node: def __init__(self, data: Any) -> None: self.data: Any = data self.next: Node | None = None def __str__(self) -> str: return f"{self.data}" class LinkedQueue: """ >>> queue = LinkedQueue() >>> queue.is_empty() True >>> queue.put(5) >>> queue.put(9) >>> queue.put('python') >>> queue.is_empty() False >>> queue.get() 5 >>> queue.put('algorithms') >>> queue.get() 9 >>> queue.get() 'python' >>> queue.get() 'algorithms' >>> queue.is_empty() True >>> queue.get() Traceback (most recent call last): ... IndexError: dequeue from empty queue """ def __init__(self) -> None: self.front: Node | None = None self.rear: Node | None = None def __iter__(self) -> Iterator[Any]: node = self.front while node: yield node.data node = node.next def __len__(self) -> int: """ >>> queue = LinkedQueue() >>> for i in range(1, 6): ... queue.put(i) >>> len(queue) 5 >>> for i in range(1, 6): ... assert len(queue) == 6 - i ... _ = queue.get() >>> len(queue) 0 """ return len(tuple(iter(self))) def __str__(self) -> str: """ >>> queue = LinkedQueue() >>> for i in range(1, 4): ... queue.put(i) >>> queue.put("Python") >>> queue.put(3.14) >>> queue.put(True) >>> str(queue) '1 <- 2 <- 3 <- Python <- 3.14 <- True' """ return " <- ".join(str(item) for item in self) def is_empty(self) -> bool: """ >>> queue = LinkedQueue() >>> queue.is_empty() True >>> for i in range(1, 6): ... queue.put(i) >>> queue.is_empty() False """ return len(self) == 0 def put(self, item: Any) -> None: """ >>> queue = LinkedQueue() >>> queue.get() Traceback (most recent call last): ... IndexError: dequeue from empty queue >>> for i in range(1, 6): ... queue.put(i) >>> str(queue) '1 <- 2 <- 3 <- 4 <- 5' """ node = Node(item) if self.is_empty(): self.front = self.rear = node else: assert isinstance(self.rear, Node) self.rear.next = node self.rear = node def get(self) -> Any: """ >>> queue = LinkedQueue() >>> queue.get() Traceback (most recent call last): ... IndexError: dequeue from empty queue >>> queue = LinkedQueue() >>> for i in range(1, 6): ... queue.put(i) >>> for i in range(1, 6): ... assert queue.get() == i >>> len(queue) 0 """ if self.is_empty(): raise IndexError("dequeue from empty queue") assert isinstance(self.front, Node) node = self.front self.front = self.front.next if self.front is None: self.rear = None return node.data def clear(self) -> None: """ >>> queue = LinkedQueue() >>> for i in range(1, 6): ... queue.put(i) >>> queue.clear() >>> len(queue) 0 >>> str(queue) '' """ self.front = self.rear = None if __name__ == "__main__": from doctest import testmod testmod()
""" A Queue using a linked list like structure """ from __future__ import annotations from collections.abc import Iterator from typing import Any class Node: def __init__(self, data: Any) -> None: self.data: Any = data self.next: Node | None = None def __str__(self) -> str: return f"{self.data}" class LinkedQueue: """ >>> queue = LinkedQueue() >>> queue.is_empty() True >>> queue.put(5) >>> queue.put(9) >>> queue.put('python') >>> queue.is_empty() False >>> queue.get() 5 >>> queue.put('algorithms') >>> queue.get() 9 >>> queue.get() 'python' >>> queue.get() 'algorithms' >>> queue.is_empty() True >>> queue.get() Traceback (most recent call last): ... IndexError: dequeue from empty queue """ def __init__(self) -> None: self.front: Node | None = None self.rear: Node | None = None def __iter__(self) -> Iterator[Any]: node = self.front while node: yield node.data node = node.next def __len__(self) -> int: """ >>> queue = LinkedQueue() >>> for i in range(1, 6): ... queue.put(i) >>> len(queue) 5 >>> for i in range(1, 6): ... assert len(queue) == 6 - i ... _ = queue.get() >>> len(queue) 0 """ return len(tuple(iter(self))) def __str__(self) -> str: """ >>> queue = LinkedQueue() >>> for i in range(1, 4): ... queue.put(i) >>> queue.put("Python") >>> queue.put(3.14) >>> queue.put(True) >>> str(queue) '1 <- 2 <- 3 <- Python <- 3.14 <- True' """ return " <- ".join(str(item) for item in self) def is_empty(self) -> bool: """ >>> queue = LinkedQueue() >>> queue.is_empty() True >>> for i in range(1, 6): ... queue.put(i) >>> queue.is_empty() False """ return len(self) == 0 def put(self, item: Any) -> None: """ >>> queue = LinkedQueue() >>> queue.get() Traceback (most recent call last): ... IndexError: dequeue from empty queue >>> for i in range(1, 6): ... queue.put(i) >>> str(queue) '1 <- 2 <- 3 <- 4 <- 5' """ node = Node(item) if self.is_empty(): self.front = self.rear = node else: assert isinstance(self.rear, Node) self.rear.next = node self.rear = node def get(self) -> Any: """ >>> queue = LinkedQueue() >>> queue.get() Traceback (most recent call last): ... IndexError: dequeue from empty queue >>> queue = LinkedQueue() >>> for i in range(1, 6): ... queue.put(i) >>> for i in range(1, 6): ... assert queue.get() == i >>> len(queue) 0 """ if self.is_empty(): raise IndexError("dequeue from empty queue") assert isinstance(self.front, Node) node = self.front self.front = self.front.next if self.front is None: self.rear = None return node.data def clear(self) -> None: """ >>> queue = LinkedQueue() >>> for i in range(1, 6): ... queue.put(i) >>> queue.clear() >>> len(queue) 0 >>> str(queue) '' """ self.front = self.rear = None if __name__ == "__main__": from doctest import testmod testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Calculate the nth Proth number Source: https://handwiki.org/wiki/Proth_number """ import math def proth(number: int) -> int: """ :param number: nth number to calculate in the sequence :return: the nth number in Proth number Note: indexing starts at 1 i.e. proth(1) gives the first Proth number of 3 >>> proth(6) 25 >>> proth(0) Traceback (most recent call last): ... ValueError: Input value of [number=0] must be > 0 >>> proth(-1) Traceback (most recent call last): ... ValueError: Input value of [number=-1] must be > 0 >>> proth(6.0) Traceback (most recent call last): ... TypeError: Input value of [number=6.0] must be an integer """ if not isinstance(number, int): raise TypeError(f"Input value of [number={number}] must be an integer") if number < 1: raise ValueError(f"Input value of [number={number}] must be > 0") elif number == 1: return 3 elif number == 2: return 5 else: """ +1 for binary starting at 0 i.e. 2^0, 2^1, etc. +1 to start the sequence at the 3rd Proth number Hence, we have a +2 in the below statement """ block_index = int(math.log(number // 3, 2)) + 2 proth_list = [3, 5] proth_index = 2 increment = 3 for block in range(1, block_index): for _ in range(increment): proth_list.append(2 ** (block + 1) + proth_list[proth_index - 1]) proth_index += 1 increment *= 2 return proth_list[number - 1] if __name__ == "__main__": import doctest doctest.testmod() for number in range(11): value = 0 try: value = proth(number) except ValueError: print(f"ValueError: there is no {number}th Proth number") continue print(f"The {number}th Proth number: {value}")
""" Calculate the nth Proth number Source: https://handwiki.org/wiki/Proth_number """ import math def proth(number: int) -> int: """ :param number: nth number to calculate in the sequence :return: the nth number in Proth number Note: indexing starts at 1 i.e. proth(1) gives the first Proth number of 3 >>> proth(6) 25 >>> proth(0) Traceback (most recent call last): ... ValueError: Input value of [number=0] must be > 0 >>> proth(-1) Traceback (most recent call last): ... ValueError: Input value of [number=-1] must be > 0 >>> proth(6.0) Traceback (most recent call last): ... TypeError: Input value of [number=6.0] must be an integer """ if not isinstance(number, int): raise TypeError(f"Input value of [number={number}] must be an integer") if number < 1: raise ValueError(f"Input value of [number={number}] must be > 0") elif number == 1: return 3 elif number == 2: return 5 else: """ +1 for binary starting at 0 i.e. 2^0, 2^1, etc. +1 to start the sequence at the 3rd Proth number Hence, we have a +2 in the below statement """ block_index = int(math.log(number // 3, 2)) + 2 proth_list = [3, 5] proth_index = 2 increment = 3 for block in range(1, block_index): for _ in range(increment): proth_list.append(2 ** (block + 1) + proth_list[proth_index - 1]) proth_index += 1 increment *= 2 return proth_list[number - 1] if __name__ == "__main__": import doctest doctest.testmod() for number in range(11): value = 0 try: value = proth(number) except ValueError: print(f"ValueError: there is no {number}th Proth number") continue print(f"The {number}th Proth number: {value}")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Program to calculate the amortization amount per month, given - Principal borrowed - Rate of interest per annum - Years to repay the loan Wikipedia Reference: https://en.wikipedia.org/wiki/Equated_monthly_installment """ def equated_monthly_installments( principal: float, rate_per_annum: float, years_to_repay: int ) -> float: """ Formula for amortization amount per month: A = p * r * (1 + r)^n / ((1 + r)^n - 1) where p is the principal, r is the rate of interest per month and n is the number of payments >>> equated_monthly_installments(25000, 0.12, 3) 830.3577453212793 >>> equated_monthly_installments(25000, 0.12, 10) 358.67737100646826 >>> equated_monthly_installments(0, 0.12, 3) Traceback (most recent call last): ... Exception: Principal borrowed must be > 0 >>> equated_monthly_installments(25000, -1, 3) Traceback (most recent call last): ... Exception: Rate of interest must be >= 0 >>> equated_monthly_installments(25000, 0.12, 0) Traceback (most recent call last): ... Exception: Years to repay must be an integer > 0 """ if principal <= 0: raise Exception("Principal borrowed must be > 0") if rate_per_annum < 0: raise Exception("Rate of interest must be >= 0") if years_to_repay <= 0 or not isinstance(years_to_repay, int): raise Exception("Years to repay must be an integer > 0") # Yearly rate is divided by 12 to get monthly rate rate_per_month = rate_per_annum / 12 # Years to repay is multiplied by 12 to get number of payments as payment is monthly number_of_payments = years_to_repay * 12 return ( principal * rate_per_month * (1 + rate_per_month) ** number_of_payments / ((1 + rate_per_month) ** number_of_payments - 1) ) if __name__ == "__main__": import doctest doctest.testmod()
""" Program to calculate the amortization amount per month, given - Principal borrowed - Rate of interest per annum - Years to repay the loan Wikipedia Reference: https://en.wikipedia.org/wiki/Equated_monthly_installment """ def equated_monthly_installments( principal: float, rate_per_annum: float, years_to_repay: int ) -> float: """ Formula for amortization amount per month: A = p * r * (1 + r)^n / ((1 + r)^n - 1) where p is the principal, r is the rate of interest per month and n is the number of payments >>> equated_monthly_installments(25000, 0.12, 3) 830.3577453212793 >>> equated_monthly_installments(25000, 0.12, 10) 358.67737100646826 >>> equated_monthly_installments(0, 0.12, 3) Traceback (most recent call last): ... Exception: Principal borrowed must be > 0 >>> equated_monthly_installments(25000, -1, 3) Traceback (most recent call last): ... Exception: Rate of interest must be >= 0 >>> equated_monthly_installments(25000, 0.12, 0) Traceback (most recent call last): ... Exception: Years to repay must be an integer > 0 """ if principal <= 0: raise Exception("Principal borrowed must be > 0") if rate_per_annum < 0: raise Exception("Rate of interest must be >= 0") if years_to_repay <= 0 or not isinstance(years_to_repay, int): raise Exception("Years to repay must be an integer > 0") # Yearly rate is divided by 12 to get monthly rate rate_per_month = rate_per_annum / 12 # Years to repay is multiplied by 12 to get number of payments as payment is monthly number_of_payments = years_to_repay * 12 return ( principal * rate_per_month * (1 + rate_per_month) ** number_of_payments / ((1 + rate_per_month) ** number_of_payments - 1) ) if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
from __future__ import annotations from collections.abc import Iterator from typing import Any class Node: def __init__(self, data: Any): self.data: Any = data self.next: Node | None = None class CircularLinkedList: def __init__(self): self.head = None self.tail = None def __iter__(self) -> Iterator[Any]: node = self.head while self.head: yield node.data node = node.next if node == self.head: break def __len__(self) -> int: return len(tuple(iter(self))) def __repr__(self): return "->".join(str(item) for item in iter(self)) def insert_tail(self, data: Any) -> None: self.insert_nth(len(self), data) def insert_head(self, data: Any) -> None: self.insert_nth(0, data) def insert_nth(self, index: int, data: Any) -> None: if index < 0 or index > len(self): raise IndexError("list index out of range.") new_node = Node(data) if self.head is None: new_node.next = new_node # first node points itself self.tail = self.head = new_node elif index == 0: # insert at head new_node.next = self.head self.head = self.tail.next = new_node else: temp = self.head for _ in range(index - 1): temp = temp.next new_node.next = temp.next temp.next = new_node if index == len(self) - 1: # insert at tail self.tail = new_node def delete_front(self): return self.delete_nth(0) def delete_tail(self) -> Any: return self.delete_nth(len(self) - 1) def delete_nth(self, index: int = 0) -> Any: if not 0 <= index < len(self): raise IndexError("list index out of range.") delete_node = self.head if self.head == self.tail: # just one node self.head = self.tail = None elif index == 0: # delete head node self.tail.next = self.tail.next.next self.head = self.head.next else: temp = self.head for _ in range(index - 1): temp = temp.next delete_node = temp.next temp.next = temp.next.next if index == len(self) - 1: # delete at tail self.tail = temp return delete_node.data def is_empty(self) -> bool: return len(self) == 0 def test_circular_linked_list() -> None: """ >>> test_circular_linked_list() """ circular_linked_list = CircularLinkedList() assert len(circular_linked_list) == 0 assert circular_linked_list.is_empty() is True assert str(circular_linked_list) == "" try: circular_linked_list.delete_front() raise AssertionError() # This should not happen except IndexError: assert True # This should happen try: circular_linked_list.delete_tail() raise AssertionError() # This should not happen except IndexError: assert True # This should happen try: circular_linked_list.delete_nth(-1) raise AssertionError() except IndexError: assert True try: circular_linked_list.delete_nth(0) raise AssertionError() except IndexError: assert True assert circular_linked_list.is_empty() is True for i in range(5): assert len(circular_linked_list) == i circular_linked_list.insert_nth(i, i + 1) assert str(circular_linked_list) == "->".join(str(i) for i in range(1, 6)) circular_linked_list.insert_tail(6) assert str(circular_linked_list) == "->".join(str(i) for i in range(1, 7)) circular_linked_list.insert_head(0) assert str(circular_linked_list) == "->".join(str(i) for i in range(0, 7)) assert circular_linked_list.delete_front() == 0 assert circular_linked_list.delete_tail() == 6 assert str(circular_linked_list) == "->".join(str(i) for i in range(1, 6)) assert circular_linked_list.delete_nth(2) == 3 circular_linked_list.insert_nth(2, 3) assert str(circular_linked_list) == "->".join(str(i) for i in range(1, 6)) assert circular_linked_list.is_empty() is False if __name__ == "__main__": import doctest doctest.testmod()
from __future__ import annotations from collections.abc import Iterator from typing import Any class Node: def __init__(self, data: Any): self.data: Any = data self.next: Node | None = None class CircularLinkedList: def __init__(self): self.head = None self.tail = None def __iter__(self) -> Iterator[Any]: node = self.head while self.head: yield node.data node = node.next if node == self.head: break def __len__(self) -> int: return len(tuple(iter(self))) def __repr__(self): return "->".join(str(item) for item in iter(self)) def insert_tail(self, data: Any) -> None: self.insert_nth(len(self), data) def insert_head(self, data: Any) -> None: self.insert_nth(0, data) def insert_nth(self, index: int, data: Any) -> None: if index < 0 or index > len(self): raise IndexError("list index out of range.") new_node = Node(data) if self.head is None: new_node.next = new_node # first node points itself self.tail = self.head = new_node elif index == 0: # insert at head new_node.next = self.head self.head = self.tail.next = new_node else: temp = self.head for _ in range(index - 1): temp = temp.next new_node.next = temp.next temp.next = new_node if index == len(self) - 1: # insert at tail self.tail = new_node def delete_front(self): return self.delete_nth(0) def delete_tail(self) -> Any: return self.delete_nth(len(self) - 1) def delete_nth(self, index: int = 0) -> Any: if not 0 <= index < len(self): raise IndexError("list index out of range.") delete_node = self.head if self.head == self.tail: # just one node self.head = self.tail = None elif index == 0: # delete head node self.tail.next = self.tail.next.next self.head = self.head.next else: temp = self.head for _ in range(index - 1): temp = temp.next delete_node = temp.next temp.next = temp.next.next if index == len(self) - 1: # delete at tail self.tail = temp return delete_node.data def is_empty(self) -> bool: return len(self) == 0 def test_circular_linked_list() -> None: """ >>> test_circular_linked_list() """ circular_linked_list = CircularLinkedList() assert len(circular_linked_list) == 0 assert circular_linked_list.is_empty() is True assert str(circular_linked_list) == "" try: circular_linked_list.delete_front() raise AssertionError() # This should not happen except IndexError: assert True # This should happen try: circular_linked_list.delete_tail() raise AssertionError() # This should not happen except IndexError: assert True # This should happen try: circular_linked_list.delete_nth(-1) raise AssertionError() except IndexError: assert True try: circular_linked_list.delete_nth(0) raise AssertionError() except IndexError: assert True assert circular_linked_list.is_empty() is True for i in range(5): assert len(circular_linked_list) == i circular_linked_list.insert_nth(i, i + 1) assert str(circular_linked_list) == "->".join(str(i) for i in range(1, 6)) circular_linked_list.insert_tail(6) assert str(circular_linked_list) == "->".join(str(i) for i in range(1, 7)) circular_linked_list.insert_head(0) assert str(circular_linked_list) == "->".join(str(i) for i in range(0, 7)) assert circular_linked_list.delete_front() == 0 assert circular_linked_list.delete_tail() == 6 assert str(circular_linked_list) == "->".join(str(i) for i in range(1, 6)) assert circular_linked_list.delete_nth(2) == 3 circular_linked_list.insert_nth(2, 3) assert str(circular_linked_list) == "->".join(str(i) for i in range(1, 6)) assert circular_linked_list.is_empty() is False if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# https://github.com/rupansh/QuantumComputing/blob/master/rippleadd.py # https://en.wikipedia.org/wiki/Adder_(electronics)#Full_adder # https://en.wikipedia.org/wiki/Controlled_NOT_gate from qiskit import Aer, QuantumCircuit, execute from qiskit.providers import Backend def store_two_classics(val1: int, val2: int) -> tuple[QuantumCircuit, str, str]: """ Generates a Quantum Circuit which stores two classical integers Returns the circuit and binary representation of the integers """ x, y = bin(val1)[2:], bin(val2)[2:] # Remove leading '0b' # Ensure that both strings are of the same length if len(x) > len(y): y = y.zfill(len(x)) else: x = x.zfill(len(y)) # We need (3 * number of bits in the larger number)+1 qBits # The second parameter is the number of classical registers, to measure the result circuit = QuantumCircuit((len(x) * 3) + 1, len(x) + 1) # We are essentially "not-ing" the bits that are 1 # Reversed because its easier to perform ops on more significant bits for i in range(len(x)): if x[::-1][i] == "1": circuit.x(i) for j in range(len(y)): if y[::-1][j] == "1": circuit.x(len(x) + j) return circuit, x, y def full_adder( circuit: QuantumCircuit, input1_loc: int, input2_loc: int, carry_in: int, carry_out: int, ): """ Quantum Equivalent of a Full Adder Circuit CX/CCX is like 2-way/3-way XOR """ circuit.ccx(input1_loc, input2_loc, carry_out) circuit.cx(input1_loc, input2_loc) circuit.ccx(input2_loc, carry_in, carry_out) circuit.cx(input2_loc, carry_in) circuit.cx(input1_loc, input2_loc) # The default value for **backend** is the result of a function call which is not # normally recommended and causes flake8-bugbear to raise a B008 error. However, # in this case, this is accptable because `Aer.get_backend()` is called when the # function is defined and that same backend is then reused for all function calls. def ripple_adder( val1: int, val2: int, backend: Backend = Aer.get_backend("qasm_simulator"), # noqa: B008 ) -> int: """ Quantum Equivalent of a Ripple Adder Circuit Uses qasm_simulator backend by default Currently only adds 'emulated' Classical Bits but nothing prevents us from doing this with hadamard'd bits :) Only supports adding positive integers >>> ripple_adder(3, 4) 7 >>> ripple_adder(10, 4) 14 >>> ripple_adder(-1, 10) Traceback (most recent call last): ... ValueError: Both Integers must be positive! """ if val1 < 0 or val2 < 0: raise ValueError("Both Integers must be positive!") # Store the Integers circuit, x, y = store_two_classics(val1, val2) """ We are essentially using each bit of x & y respectively as full_adder's input the carry_input is used from the previous circuit (for circuit num > 1) the carry_out is just below carry_input because it will be essentially the carry_input for the next full_adder """ for i in range(len(x)): full_adder(circuit, i, len(x) + i, len(x) + len(y) + i, len(x) + len(y) + i + 1) circuit.barrier() # Optional, just for aesthetics # Measure the resultant qBits for i in range(len(x) + 1): circuit.measure([(len(x) * 2) + i], [i]) res = execute(circuit, backend, shots=1).result() # The result is in binary. Convert it back to int return int(list(res.get_counts())[0], 2) if __name__ == "__main__": import doctest doctest.testmod()
# https://github.com/rupansh/QuantumComputing/blob/master/rippleadd.py # https://en.wikipedia.org/wiki/Adder_(electronics)#Full_adder # https://en.wikipedia.org/wiki/Controlled_NOT_gate from qiskit import Aer, QuantumCircuit, execute from qiskit.providers import Backend def store_two_classics(val1: int, val2: int) -> tuple[QuantumCircuit, str, str]: """ Generates a Quantum Circuit which stores two classical integers Returns the circuit and binary representation of the integers """ x, y = bin(val1)[2:], bin(val2)[2:] # Remove leading '0b' # Ensure that both strings are of the same length if len(x) > len(y): y = y.zfill(len(x)) else: x = x.zfill(len(y)) # We need (3 * number of bits in the larger number)+1 qBits # The second parameter is the number of classical registers, to measure the result circuit = QuantumCircuit((len(x) * 3) + 1, len(x) + 1) # We are essentially "not-ing" the bits that are 1 # Reversed because its easier to perform ops on more significant bits for i in range(len(x)): if x[::-1][i] == "1": circuit.x(i) for j in range(len(y)): if y[::-1][j] == "1": circuit.x(len(x) + j) return circuit, x, y def full_adder( circuit: QuantumCircuit, input1_loc: int, input2_loc: int, carry_in: int, carry_out: int, ): """ Quantum Equivalent of a Full Adder Circuit CX/CCX is like 2-way/3-way XOR """ circuit.ccx(input1_loc, input2_loc, carry_out) circuit.cx(input1_loc, input2_loc) circuit.ccx(input2_loc, carry_in, carry_out) circuit.cx(input2_loc, carry_in) circuit.cx(input1_loc, input2_loc) # The default value for **backend** is the result of a function call which is not # normally recommended and causes flake8-bugbear to raise a B008 error. However, # in this case, this is accptable because `Aer.get_backend()` is called when the # function is defined and that same backend is then reused for all function calls. def ripple_adder( val1: int, val2: int, backend: Backend = Aer.get_backend("qasm_simulator"), # noqa: B008 ) -> int: """ Quantum Equivalent of a Ripple Adder Circuit Uses qasm_simulator backend by default Currently only adds 'emulated' Classical Bits but nothing prevents us from doing this with hadamard'd bits :) Only supports adding positive integers >>> ripple_adder(3, 4) 7 >>> ripple_adder(10, 4) 14 >>> ripple_adder(-1, 10) Traceback (most recent call last): ... ValueError: Both Integers must be positive! """ if val1 < 0 or val2 < 0: raise ValueError("Both Integers must be positive!") # Store the Integers circuit, x, y = store_two_classics(val1, val2) """ We are essentially using each bit of x & y respectively as full_adder's input the carry_input is used from the previous circuit (for circuit num > 1) the carry_out is just below carry_input because it will be essentially the carry_input for the next full_adder """ for i in range(len(x)): full_adder(circuit, i, len(x) + i, len(x) + len(y) + i, len(x) + len(y) + i + 1) circuit.barrier() # Optional, just for aesthetics # Measure the resultant qBits for i in range(len(x) + 1): circuit.measure([(len(x) * 2) + i], [i]) res = execute(circuit, backend, shots=1).result() # The result is in binary. Convert it back to int return int(list(res.get_counts())[0], 2) if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
#
#
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Problem 34: https://projecteuler.net/problem=34 145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145. Find the sum of all numbers which are equal to the sum of the factorial of their digits. Note: As 1! = 1 and 2! = 2 are not sums they are not included. """ from math import factorial DIGIT_FACTORIAL = {str(d): factorial(d) for d in range(10)} def sum_of_digit_factorial(n: int) -> int: """ Returns the sum of the factorial of digits in n >>> sum_of_digit_factorial(15) 121 >>> sum_of_digit_factorial(0) 1 """ return sum(DIGIT_FACTORIAL[d] for d in str(n)) def solution() -> int: """ Returns the sum of all numbers whose sum of the factorials of all digits add up to the number itself. >>> solution() 40730 """ limit = 7 * factorial(9) + 1 return sum(i for i in range(3, limit) if sum_of_digit_factorial(i) == i) if __name__ == "__main__": print(f"{solution() = }")
""" Problem 34: https://projecteuler.net/problem=34 145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145. Find the sum of all numbers which are equal to the sum of the factorial of their digits. Note: As 1! = 1 and 2! = 2 are not sums they are not included. """ from math import factorial DIGIT_FACTORIAL = {str(d): factorial(d) for d in range(10)} def sum_of_digit_factorial(n: int) -> int: """ Returns the sum of the factorial of digits in n >>> sum_of_digit_factorial(15) 121 >>> sum_of_digit_factorial(0) 1 """ return sum(DIGIT_FACTORIAL[d] for d in str(n)) def solution() -> int: """ Returns the sum of all numbers whose sum of the factorials of all digits add up to the number itself. >>> solution() 40730 """ limit = 7 * factorial(9) + 1 return sum(i for i in range(3, limit) if sum_of_digit_factorial(i) == i) if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" author: Christian Bender date: 21.12.2017 class: XORCipher This class implements the XOR-cipher algorithm and provides some useful methods for encrypting and decrypting strings and files. Overview about methods - encrypt : list of char - decrypt : list of char - encrypt_string : str - decrypt_string : str - encrypt_file : boolean - decrypt_file : boolean """ from __future__ import annotations class XORCipher: def __init__(self, key: int = 0): """ simple constructor that receives a key or uses default key = 0 """ # private field self.__key = key def encrypt(self, content: str, key: int) -> list[str]: """ input: 'content' of type string and 'key' of type int output: encrypted string 'content' as a list of chars if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(key, int) and isinstance(content, str) key = key or self.__key or 1 # make sure key is an appropriate size key %= 255 return [chr(ord(ch) ^ key) for ch in content] def decrypt(self, content: str, key: int) -> list[str]: """ input: 'content' of type list and 'key' of type int output: decrypted string 'content' as a list of chars if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(key, int) and isinstance(content, list) key = key or self.__key or 1 # make sure key is an appropriate size key %= 255 return [chr(ord(ch) ^ key) for ch in content] def encrypt_string(self, content: str, key: int = 0) -> str: """ input: 'content' of type string and 'key' of type int output: encrypted string 'content' if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(key, int) and isinstance(content, str) key = key or self.__key or 1 # make sure key can be any size while key > 255: key -= 255 # This will be returned ans = "" for ch in content: ans += chr(ord(ch) ^ key) return ans def decrypt_string(self, content: str, key: int = 0) -> str: """ input: 'content' of type string and 'key' of type int output: decrypted string 'content' if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(key, int) and isinstance(content, str) key = key or self.__key or 1 # make sure key can be any size while key > 255: key -= 255 # This will be returned ans = "" for ch in content: ans += chr(ord(ch) ^ key) return ans def encrypt_file(self, file: str, key: int = 0) -> bool: """ input: filename (str) and a key (int) output: returns true if encrypt process was successful otherwise false if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(file, str) and isinstance(key, int) try: with open(file) as fin: with open("encrypt.out", "w+") as fout: # actual encrypt-process for line in fin: fout.write(self.encrypt_string(line, key)) except OSError: return False return True def decrypt_file(self, file: str, key: int) -> bool: """ input: filename (str) and a key (int) output: returns true if decrypt process was successful otherwise false if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(file, str) and isinstance(key, int) try: with open(file) as fin: with open("decrypt.out", "w+") as fout: # actual encrypt-process for line in fin: fout.write(self.decrypt_string(line, key)) except OSError: return False return True # Tests # crypt = XORCipher() # key = 67 # # test encrypt # print(crypt.encrypt("hallo welt",key)) # # test decrypt # print(crypt.decrypt(crypt.encrypt("hallo welt",key), key)) # # test encrypt_string # print(crypt.encrypt_string("hallo welt",key)) # # test decrypt_string # print(crypt.decrypt_string(crypt.encrypt_string("hallo welt",key),key)) # if (crypt.encrypt_file("test.txt",key)): # print("encrypt successful") # else: # print("encrypt unsuccessful") # if (crypt.decrypt_file("encrypt.out",key)): # print("decrypt successful") # else: # print("decrypt unsuccessful")
""" author: Christian Bender date: 21.12.2017 class: XORCipher This class implements the XOR-cipher algorithm and provides some useful methods for encrypting and decrypting strings and files. Overview about methods - encrypt : list of char - decrypt : list of char - encrypt_string : str - decrypt_string : str - encrypt_file : boolean - decrypt_file : boolean """ from __future__ import annotations class XORCipher: def __init__(self, key: int = 0): """ simple constructor that receives a key or uses default key = 0 """ # private field self.__key = key def encrypt(self, content: str, key: int) -> list[str]: """ input: 'content' of type string and 'key' of type int output: encrypted string 'content' as a list of chars if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(key, int) and isinstance(content, str) key = key or self.__key or 1 # make sure key is an appropriate size key %= 255 return [chr(ord(ch) ^ key) for ch in content] def decrypt(self, content: str, key: int) -> list[str]: """ input: 'content' of type list and 'key' of type int output: decrypted string 'content' as a list of chars if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(key, int) and isinstance(content, list) key = key or self.__key or 1 # make sure key is an appropriate size key %= 255 return [chr(ord(ch) ^ key) for ch in content] def encrypt_string(self, content: str, key: int = 0) -> str: """ input: 'content' of type string and 'key' of type int output: encrypted string 'content' if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(key, int) and isinstance(content, str) key = key or self.__key or 1 # make sure key can be any size while key > 255: key -= 255 # This will be returned ans = "" for ch in content: ans += chr(ord(ch) ^ key) return ans def decrypt_string(self, content: str, key: int = 0) -> str: """ input: 'content' of type string and 'key' of type int output: decrypted string 'content' if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(key, int) and isinstance(content, str) key = key or self.__key or 1 # make sure key can be any size while key > 255: key -= 255 # This will be returned ans = "" for ch in content: ans += chr(ord(ch) ^ key) return ans def encrypt_file(self, file: str, key: int = 0) -> bool: """ input: filename (str) and a key (int) output: returns true if encrypt process was successful otherwise false if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(file, str) and isinstance(key, int) try: with open(file) as fin: with open("encrypt.out", "w+") as fout: # actual encrypt-process for line in fin: fout.write(self.encrypt_string(line, key)) except OSError: return False return True def decrypt_file(self, file: str, key: int) -> bool: """ input: filename (str) and a key (int) output: returns true if decrypt process was successful otherwise false if key not passed the method uses the key by the constructor. otherwise key = 1 """ # precondition assert isinstance(file, str) and isinstance(key, int) try: with open(file) as fin: with open("decrypt.out", "w+") as fout: # actual encrypt-process for line in fin: fout.write(self.decrypt_string(line, key)) except OSError: return False return True # Tests # crypt = XORCipher() # key = 67 # # test encrypt # print(crypt.encrypt("hallo welt",key)) # # test decrypt # print(crypt.decrypt(crypt.encrypt("hallo welt",key), key)) # # test encrypt_string # print(crypt.encrypt_string("hallo welt",key)) # # test decrypt_string # print(crypt.decrypt_string(crypt.encrypt_string("hallo welt",key),key)) # if (crypt.encrypt_file("test.txt",key)): # print("encrypt successful") # else: # print("encrypt unsuccessful") # if (crypt.decrypt_file("encrypt.out",key)): # print("decrypt successful") # else: # print("decrypt unsuccessful")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" This algorithm (k=33) was first reported by Dan Bernstein many years ago in comp.lang.c Another version of this algorithm (now favored by Bernstein) uses xor: hash(i) = hash(i - 1) * 33 ^ str[i]; First Magic constant 33: It has never been adequately explained. It's magic because it works better than many other constants, prime or not. Second Magic Constant 5381: 1. odd number 2. prime number 3. deficient number 4. 001/010/100/000/101 b source: http://www.cse.yorku.ca/~oz/hash.html """ def djb2(s: str) -> int: """ Implementation of djb2 hash algorithm that is popular because of it's magic constants. >>> djb2('Algorithms') 3782405311 >>> djb2('scramble bits') 1609059040 """ hash_value = 5381 for x in s: hash_value = ((hash_value << 5) + hash_value) + ord(x) return hash_value & 0xFFFFFFFF
""" This algorithm (k=33) was first reported by Dan Bernstein many years ago in comp.lang.c Another version of this algorithm (now favored by Bernstein) uses xor: hash(i) = hash(i - 1) * 33 ^ str[i]; First Magic constant 33: It has never been adequately explained. It's magic because it works better than many other constants, prime or not. Second Magic Constant 5381: 1. odd number 2. prime number 3. deficient number 4. 001/010/100/000/101 b source: http://www.cse.yorku.ca/~oz/hash.html """ def djb2(s: str) -> int: """ Implementation of djb2 hash algorithm that is popular because of it's magic constants. >>> djb2('Algorithms') 3782405311 >>> djb2('scramble bits') 1609059040 """ hash_value = 5381 for x in s: hash_value = ((hash_value << 5) + hash_value) + ord(x) return hash_value & 0xFFFFFFFF
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
import numpy as np from numpy import ndarray from scipy.optimize import Bounds, LinearConstraint, minimize def norm_squared(vector: ndarray) -> float: """ Return the squared second norm of vector norm_squared(v) = sum(x * x for x in v) Args: vector (ndarray): input vector Returns: float: squared second norm of vector >>> norm_squared([1, 2]) 5 >>> norm_squared(np.asarray([1, 2])) 5 >>> norm_squared([0, 0]) 0 """ return np.dot(vector, vector) class SVC: """ Support Vector Classifier Args: kernel (str): kernel to use. Default: linear Possible choices: - linear regularization: constraint for soft margin (data not linearly separable) Default: unbound >>> SVC(kernel="asdf") Traceback (most recent call last): ... ValueError: Unknown kernel: asdf >>> SVC(kernel="rbf") Traceback (most recent call last): ... ValueError: rbf kernel requires gamma >>> SVC(kernel="rbf", gamma=-1) Traceback (most recent call last): ... ValueError: gamma must be > 0 """ def __init__( self, *, regularization: float = np.inf, kernel: str = "linear", gamma: float = 0, ) -> None: self.regularization = regularization self.gamma = gamma if kernel == "linear": self.kernel = self.__linear elif kernel == "rbf": if self.gamma == 0: raise ValueError("rbf kernel requires gamma") if not (isinstance(self.gamma, float) or isinstance(self.gamma, int)): raise ValueError("gamma must be float or int") if not self.gamma > 0: raise ValueError("gamma must be > 0") self.kernel = self.__rbf # in the future, there could be a default value like in sklearn # sklear: def_gamma = 1/(n_features * X.var()) (wiki) # previously it was 1/(n_features) else: raise ValueError(f"Unknown kernel: {kernel}") # kernels def __linear(self, vector1: ndarray, vector2: ndarray) -> float: """Linear kernel (as if no kernel used at all)""" return np.dot(vector1, vector2) def __rbf(self, vector1: ndarray, vector2: ndarray) -> float: """ RBF: Radial Basis Function Kernel Note: for more information see: https://en.wikipedia.org/wiki/Radial_basis_function_kernel Args: vector1 (ndarray): first vector vector2 (ndarray): second vector) Returns: float: exp(-(gamma * norm_squared(vector1 - vector2))) """ return np.exp(-(self.gamma * norm_squared(vector1 - vector2))) def fit(self, observations: list[ndarray], classes: ndarray) -> None: """ Fits the SVC with a set of observations. Args: observations (list[ndarray]): list of observations classes (ndarray): classification of each observation (in {1, -1}) """ self.observations = observations self.classes = classes # using Wolfe's Dual to calculate w. # Primal problem: minimize 1/2*norm_squared(w) # constraint: yn(w . xn + b) >= 1 # # With l a vector # Dual problem: maximize sum_n(ln) - # 1/2 * sum_n(sum_m(ln*lm*yn*ym*xn . xm)) # constraint: self.C >= ln >= 0 # and sum_n(ln*yn) = 0 # Then we get w using w = sum_n(ln*yn*xn) # At the end we can get b ~= mean(yn - w . xn) # # Since we use kernels, we only need l_star to calculate b # and to classify observations (n,) = np.shape(classes) def to_minimize(candidate: ndarray) -> float: """ Opposite of the function to maximize Args: candidate (ndarray): candidate array to test Return: float: Wolfe's Dual result to minimize """ s = 0 (n,) = np.shape(candidate) for i in range(n): for j in range(n): s += ( candidate[i] * candidate[j] * classes[i] * classes[j] * self.kernel(observations[i], observations[j]) ) return 1 / 2 * s - sum(candidate) ly_contraint = LinearConstraint(classes, 0, 0) l_bounds = Bounds(0, self.regularization) l_star = minimize( to_minimize, np.ones(n), bounds=l_bounds, constraints=[ly_contraint] ).x self.optimum = l_star # calculating mean offset of separation plane to points s = 0 for i in range(n): for j in range(n): s += classes[i] - classes[i] * self.optimum[i] * self.kernel( observations[i], observations[j] ) self.offset = s / n def predict(self, observation: ndarray) -> int: """ Get the expected class of an observation Args: observation (Vector): observation Returns: int {1, -1}: expected class >>> xs = [ ... np.asarray([0, 1]), np.asarray([0, 2]), ... np.asarray([1, 1]), np.asarray([1, 2]) ... ] >>> y = np.asarray([1, 1, -1, -1]) >>> s = SVC() >>> s.fit(xs, y) >>> s.predict(np.asarray([0, 1])) 1 >>> s.predict(np.asarray([1, 1])) -1 >>> s.predict(np.asarray([2, 2])) -1 """ s = sum( self.optimum[n] * self.classes[n] * self.kernel(self.observations[n], observation) for n in range(len(self.classes)) ) return 1 if s + self.offset >= 0 else -1 if __name__ == "__main__": import doctest doctest.testmod()
import numpy as np from numpy import ndarray from scipy.optimize import Bounds, LinearConstraint, minimize def norm_squared(vector: ndarray) -> float: """ Return the squared second norm of vector norm_squared(v) = sum(x * x for x in v) Args: vector (ndarray): input vector Returns: float: squared second norm of vector >>> norm_squared([1, 2]) 5 >>> norm_squared(np.asarray([1, 2])) 5 >>> norm_squared([0, 0]) 0 """ return np.dot(vector, vector) class SVC: """ Support Vector Classifier Args: kernel (str): kernel to use. Default: linear Possible choices: - linear regularization: constraint for soft margin (data not linearly separable) Default: unbound >>> SVC(kernel="asdf") Traceback (most recent call last): ... ValueError: Unknown kernel: asdf >>> SVC(kernel="rbf") Traceback (most recent call last): ... ValueError: rbf kernel requires gamma >>> SVC(kernel="rbf", gamma=-1) Traceback (most recent call last): ... ValueError: gamma must be > 0 """ def __init__( self, *, regularization: float = np.inf, kernel: str = "linear", gamma: float = 0, ) -> None: self.regularization = regularization self.gamma = gamma if kernel == "linear": self.kernel = self.__linear elif kernel == "rbf": if self.gamma == 0: raise ValueError("rbf kernel requires gamma") if not (isinstance(self.gamma, float) or isinstance(self.gamma, int)): raise ValueError("gamma must be float or int") if not self.gamma > 0: raise ValueError("gamma must be > 0") self.kernel = self.__rbf # in the future, there could be a default value like in sklearn # sklear: def_gamma = 1/(n_features * X.var()) (wiki) # previously it was 1/(n_features) else: raise ValueError(f"Unknown kernel: {kernel}") # kernels def __linear(self, vector1: ndarray, vector2: ndarray) -> float: """Linear kernel (as if no kernel used at all)""" return np.dot(vector1, vector2) def __rbf(self, vector1: ndarray, vector2: ndarray) -> float: """ RBF: Radial Basis Function Kernel Note: for more information see: https://en.wikipedia.org/wiki/Radial_basis_function_kernel Args: vector1 (ndarray): first vector vector2 (ndarray): second vector) Returns: float: exp(-(gamma * norm_squared(vector1 - vector2))) """ return np.exp(-(self.gamma * norm_squared(vector1 - vector2))) def fit(self, observations: list[ndarray], classes: ndarray) -> None: """ Fits the SVC with a set of observations. Args: observations (list[ndarray]): list of observations classes (ndarray): classification of each observation (in {1, -1}) """ self.observations = observations self.classes = classes # using Wolfe's Dual to calculate w. # Primal problem: minimize 1/2*norm_squared(w) # constraint: yn(w . xn + b) >= 1 # # With l a vector # Dual problem: maximize sum_n(ln) - # 1/2 * sum_n(sum_m(ln*lm*yn*ym*xn . xm)) # constraint: self.C >= ln >= 0 # and sum_n(ln*yn) = 0 # Then we get w using w = sum_n(ln*yn*xn) # At the end we can get b ~= mean(yn - w . xn) # # Since we use kernels, we only need l_star to calculate b # and to classify observations (n,) = np.shape(classes) def to_minimize(candidate: ndarray) -> float: """ Opposite of the function to maximize Args: candidate (ndarray): candidate array to test Return: float: Wolfe's Dual result to minimize """ s = 0 (n,) = np.shape(candidate) for i in range(n): for j in range(n): s += ( candidate[i] * candidate[j] * classes[i] * classes[j] * self.kernel(observations[i], observations[j]) ) return 1 / 2 * s - sum(candidate) ly_contraint = LinearConstraint(classes, 0, 0) l_bounds = Bounds(0, self.regularization) l_star = minimize( to_minimize, np.ones(n), bounds=l_bounds, constraints=[ly_contraint] ).x self.optimum = l_star # calculating mean offset of separation plane to points s = 0 for i in range(n): for j in range(n): s += classes[i] - classes[i] * self.optimum[i] * self.kernel( observations[i], observations[j] ) self.offset = s / n def predict(self, observation: ndarray) -> int: """ Get the expected class of an observation Args: observation (Vector): observation Returns: int {1, -1}: expected class >>> xs = [ ... np.asarray([0, 1]), np.asarray([0, 2]), ... np.asarray([1, 1]), np.asarray([1, 2]) ... ] >>> y = np.asarray([1, 1, -1, -1]) >>> s = SVC() >>> s.fit(xs, y) >>> s.predict(np.asarray([0, 1])) 1 >>> s.predict(np.asarray([1, 1])) -1 >>> s.predict(np.asarray([2, 2])) -1 """ s = sum( self.optimum[n] * self.classes[n] * self.kernel(self.observations[n], observation) for n in range(len(self.classes)) ) return 1 if s + self.offset >= 0 else -1 if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Given a array of length n, max_subarray_sum() finds the maximum of sum of contiguous sub-array using divide and conquer method. Time complexity : O(n log n) Ref : INTRODUCTION TO ALGORITHMS THIRD EDITION (section : 4, sub-section : 4.1, page : 70) """ def max_sum_from_start(array): """This function finds the maximum contiguous sum of array from 0 index Parameters : array (list[int]) : given array Returns : max_sum (int) : maximum contiguous sum of array from 0 index """ array_sum = 0 max_sum = float("-inf") for num in array: array_sum += num if array_sum > max_sum: max_sum = array_sum return max_sum def max_cross_array_sum(array, left, mid, right): """This function finds the maximum contiguous sum of left and right arrays Parameters : array, left, mid, right (list[int], int, int, int) Returns : (int) : maximum of sum of contiguous sum of left and right arrays """ max_sum_of_left = max_sum_from_start(array[left : mid + 1][::-1]) max_sum_of_right = max_sum_from_start(array[mid + 1 : right + 1]) return max_sum_of_left + max_sum_of_right def max_subarray_sum(array, left, right): """Maximum contiguous sub-array sum, using divide and conquer method Parameters : array, left, right (list[int], int, int) : given array, current left index and current right index Returns : int : maximum of sum of contiguous sub-array """ # base case: array has only one element if left == right: return array[right] # Recursion mid = (left + right) // 2 left_half_sum = max_subarray_sum(array, left, mid) right_half_sum = max_subarray_sum(array, mid + 1, right) cross_sum = max_cross_array_sum(array, left, mid, right) return max(left_half_sum, right_half_sum, cross_sum) array = [-2, -5, 6, -2, -3, 1, 5, -6] array_length = len(array) print( "Maximum sum of contiguous subarray:", max_subarray_sum(array, 0, array_length - 1) )
""" Given a array of length n, max_subarray_sum() finds the maximum of sum of contiguous sub-array using divide and conquer method. Time complexity : O(n log n) Ref : INTRODUCTION TO ALGORITHMS THIRD EDITION (section : 4, sub-section : 4.1, page : 70) """ def max_sum_from_start(array): """This function finds the maximum contiguous sum of array from 0 index Parameters : array (list[int]) : given array Returns : max_sum (int) : maximum contiguous sum of array from 0 index """ array_sum = 0 max_sum = float("-inf") for num in array: array_sum += num if array_sum > max_sum: max_sum = array_sum return max_sum def max_cross_array_sum(array, left, mid, right): """This function finds the maximum contiguous sum of left and right arrays Parameters : array, left, mid, right (list[int], int, int, int) Returns : (int) : maximum of sum of contiguous sum of left and right arrays """ max_sum_of_left = max_sum_from_start(array[left : mid + 1][::-1]) max_sum_of_right = max_sum_from_start(array[mid + 1 : right + 1]) return max_sum_of_left + max_sum_of_right def max_subarray_sum(array, left, right): """Maximum contiguous sub-array sum, using divide and conquer method Parameters : array, left, right (list[int], int, int) : given array, current left index and current right index Returns : int : maximum of sum of contiguous sub-array """ # base case: array has only one element if left == right: return array[right] # Recursion mid = (left + right) // 2 left_half_sum = max_subarray_sum(array, left, mid) right_half_sum = max_subarray_sum(array, mid + 1, right) cross_sum = max_cross_array_sum(array, left, mid, right) return max(left_half_sum, right_half_sum, cross_sum) array = [-2, -5, 6, -2, -3, 1, 5, -6] array_length = len(array) print( "Maximum sum of contiguous subarray:", max_subarray_sum(array, 0, array_length - 1) )
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
from collections.abc import Sequence def evaluate_poly(poly: Sequence[float], x: float) -> float: """Evaluate a polynomial f(x) at specified point x and return the value. Arguments: poly -- the coefficients of a polynomial as an iterable in order of ascending degree x -- the point at which to evaluate the polynomial >>> evaluate_poly((0.0, 0.0, 5.0, 9.3, 7.0), 10.0) 79800.0 """ return sum(c * (x**i) for i, c in enumerate(poly)) def horner(poly: Sequence[float], x: float) -> float: """Evaluate a polynomial at specified point using Horner's method. In terms of computational complexity, Horner's method is an efficient method of evaluating a polynomial. It avoids the use of expensive exponentiation, and instead uses only multiplication and addition to evaluate the polynomial in O(n), where n is the degree of the polynomial. https://en.wikipedia.org/wiki/Horner's_method Arguments: poly -- the coefficients of a polynomial as an iterable in order of ascending degree x -- the point at which to evaluate the polynomial >>> horner((0.0, 0.0, 5.0, 9.3, 7.0), 10.0) 79800.0 """ result = 0.0 for coeff in reversed(poly): result = result * x + coeff return result if __name__ == "__main__": """ Example: >>> poly = (0.0, 0.0, 5.0, 9.3, 7.0) # f(x) = 7.0x^4 + 9.3x^3 + 5.0x^2 >>> x = -13.0 >>> # f(-13) = 7.0(-13)^4 + 9.3(-13)^3 + 5.0(-13)^2 = 180339.9 >>> print(evaluate_poly(poly, x)) 180339.9 """ poly = (0.0, 0.0, 5.0, 9.3, 7.0) x = 10.0 print(evaluate_poly(poly, x)) print(horner(poly, x))
from collections.abc import Sequence def evaluate_poly(poly: Sequence[float], x: float) -> float: """Evaluate a polynomial f(x) at specified point x and return the value. Arguments: poly -- the coefficients of a polynomial as an iterable in order of ascending degree x -- the point at which to evaluate the polynomial >>> evaluate_poly((0.0, 0.0, 5.0, 9.3, 7.0), 10.0) 79800.0 """ return sum(c * (x**i) for i, c in enumerate(poly)) def horner(poly: Sequence[float], x: float) -> float: """Evaluate a polynomial at specified point using Horner's method. In terms of computational complexity, Horner's method is an efficient method of evaluating a polynomial. It avoids the use of expensive exponentiation, and instead uses only multiplication and addition to evaluate the polynomial in O(n), where n is the degree of the polynomial. https://en.wikipedia.org/wiki/Horner's_method Arguments: poly -- the coefficients of a polynomial as an iterable in order of ascending degree x -- the point at which to evaluate the polynomial >>> horner((0.0, 0.0, 5.0, 9.3, 7.0), 10.0) 79800.0 """ result = 0.0 for coeff in reversed(poly): result = result * x + coeff return result if __name__ == "__main__": """ Example: >>> poly = (0.0, 0.0, 5.0, 9.3, 7.0) # f(x) = 7.0x^4 + 9.3x^3 + 5.0x^2 >>> x = -13.0 >>> # f(-13) = 7.0(-13)^4 + 9.3(-13)^3 + 5.0(-13)^2 = 180339.9 >>> print(evaluate_poly(poly, x)) 180339.9 """ poly = (0.0, 0.0, 5.0, 9.3, 7.0) x = 10.0 print(evaluate_poly(poly, x)) print(horner(poly, x))
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Hey, we are going to find an exciting number called Catalan number which is use to find the number of possible binary search trees from tree of a given number of nodes. We will use the formula: t(n) = SUMMATION(i = 1 to n)t(i-1)t(n-i) Further details at Wikipedia: https://en.wikipedia.org/wiki/Catalan_number """ """ Our Contribution: Basically we Create the 2 function: 1. catalan_number(node_count: int) -> int Returns the number of possible binary search trees for n nodes. 2. binary_tree_count(node_count: int) -> int Returns the number of possible binary trees for n nodes. """ def binomial_coefficient(n: int, k: int) -> int: """ Since Here we Find the Binomial Coefficient: https://en.wikipedia.org/wiki/Binomial_coefficient C(n,k) = n! / k!(n-k)! :param n: 2 times of Number of nodes :param k: Number of nodes :return: Integer Value >>> binomial_coefficient(4, 2) 6 """ result = 1 # To kept the Calculated Value # Since C(n, k) = C(n, n-k) if k > (n - k): k = n - k # Calculate C(n,k) for i in range(k): result *= n - i result //= i + 1 return result def catalan_number(node_count: int) -> int: """ We can find Catalan number many ways but here we use Binomial Coefficient because it does the job in O(n) return the Catalan number of n using 2nCn/(n+1). :param n: number of nodes :return: Catalan number of n nodes >>> catalan_number(5) 42 >>> catalan_number(6) 132 """ return binomial_coefficient(2 * node_count, node_count) // (node_count + 1) def factorial(n: int) -> int: """ Return the factorial of a number. :param n: Number to find the Factorial of. :return: Factorial of n. >>> import math >>> all(factorial(i) == math.factorial(i) for i in range(10)) True >>> factorial(-5) # doctest: +ELLIPSIS Traceback (most recent call last): ... ValueError: factorial() not defined for negative values """ if n < 0: raise ValueError("factorial() not defined for negative values") result = 1 for i in range(1, n + 1): result *= i return result def binary_tree_count(node_count: int) -> int: """ Return the number of possible of binary trees. :param n: number of nodes :return: Number of possible binary trees >>> binary_tree_count(5) 5040 >>> binary_tree_count(6) 95040 """ return catalan_number(node_count) * factorial(node_count) if __name__ == "__main__": node_count = int(input("Enter the number of nodes: ").strip() or 0) if node_count <= 0: raise ValueError("We need some nodes to work with.") print( f"Given {node_count} nodes, there are {binary_tree_count(node_count)} " f"binary trees and {catalan_number(node_count)} binary search trees." )
""" Hey, we are going to find an exciting number called Catalan number which is use to find the number of possible binary search trees from tree of a given number of nodes. We will use the formula: t(n) = SUMMATION(i = 1 to n)t(i-1)t(n-i) Further details at Wikipedia: https://en.wikipedia.org/wiki/Catalan_number """ """ Our Contribution: Basically we Create the 2 function: 1. catalan_number(node_count: int) -> int Returns the number of possible binary search trees for n nodes. 2. binary_tree_count(node_count: int) -> int Returns the number of possible binary trees for n nodes. """ def binomial_coefficient(n: int, k: int) -> int: """ Since Here we Find the Binomial Coefficient: https://en.wikipedia.org/wiki/Binomial_coefficient C(n,k) = n! / k!(n-k)! :param n: 2 times of Number of nodes :param k: Number of nodes :return: Integer Value >>> binomial_coefficient(4, 2) 6 """ result = 1 # To kept the Calculated Value # Since C(n, k) = C(n, n-k) if k > (n - k): k = n - k # Calculate C(n,k) for i in range(k): result *= n - i result //= i + 1 return result def catalan_number(node_count: int) -> int: """ We can find Catalan number many ways but here we use Binomial Coefficient because it does the job in O(n) return the Catalan number of n using 2nCn/(n+1). :param n: number of nodes :return: Catalan number of n nodes >>> catalan_number(5) 42 >>> catalan_number(6) 132 """ return binomial_coefficient(2 * node_count, node_count) // (node_count + 1) def factorial(n: int) -> int: """ Return the factorial of a number. :param n: Number to find the Factorial of. :return: Factorial of n. >>> import math >>> all(factorial(i) == math.factorial(i) for i in range(10)) True >>> factorial(-5) # doctest: +ELLIPSIS Traceback (most recent call last): ... ValueError: factorial() not defined for negative values """ if n < 0: raise ValueError("factorial() not defined for negative values") result = 1 for i in range(1, n + 1): result *= i return result def binary_tree_count(node_count: int) -> int: """ Return the number of possible of binary trees. :param n: number of nodes :return: Number of possible binary trees >>> binary_tree_count(5) 5040 >>> binary_tree_count(6) 95040 """ return catalan_number(node_count) * factorial(node_count) if __name__ == "__main__": node_count = int(input("Enter the number of nodes: ").strip() or 0) if node_count <= 0: raise ValueError("We need some nodes to work with.") print( f"Given {node_count} nodes, there are {binary_tree_count(node_count)} " f"binary trees and {catalan_number(node_count)} binary search trees." )
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Horizontal Projectile Motion problem in physics. This algorithm solves a specific problem in which the motion starts from the ground as can be seen below: (v = 0) ** * * * * * * * * * * GROUND GROUND For more info: https://en.wikipedia.org/wiki/Projectile_motion """ # Importing packages from math import radians as angle_to_radians from math import sin # Acceleration Constant on Earth (unit m/s^2) g = 9.80665 def check_args(init_velocity: float, angle: float) -> None: """ Check that the arguments are valid """ # Ensure valid instance if not isinstance(init_velocity, (int, float)): raise TypeError("Invalid velocity. Should be a positive number.") if not isinstance(angle, (int, float)): raise TypeError("Invalid angle. Range is 1-90 degrees.") # Ensure valid angle if angle > 90 or angle < 1: raise ValueError("Invalid angle. Range is 1-90 degrees.") # Ensure valid velocity if init_velocity < 0: raise ValueError("Invalid velocity. Should be a positive number.") def horizontal_distance(init_velocity: float, angle: float) -> float: """ Returns the horizontal distance that the object cover Formula: v_0^2 * sin(2 * alpha) --------------------- g v_0 - initial velocity alpha - angle >>> horizontal_distance(30, 45) 91.77 >>> horizontal_distance(100, 78) 414.76 >>> horizontal_distance(-1, 20) Traceback (most recent call last): ... ValueError: Invalid velocity. Should be a positive number. >>> horizontal_distance(30, -20) Traceback (most recent call last): ... ValueError: Invalid angle. Range is 1-90 degrees. """ check_args(init_velocity, angle) radians = angle_to_radians(2 * angle) return round(init_velocity**2 * sin(radians) / g, 2) def max_height(init_velocity: float, angle: float) -> float: """ Returns the maximum height that the object reach Formula: v_0^2 * sin^2(alpha) -------------------- 2g v_0 - initial velocity alpha - angle >>> max_height(30, 45) 22.94 >>> max_height(100, 78) 487.82 >>> max_height("a", 20) Traceback (most recent call last): ... TypeError: Invalid velocity. Should be a positive number. >>> horizontal_distance(30, "b") Traceback (most recent call last): ... TypeError: Invalid angle. Range is 1-90 degrees. """ check_args(init_velocity, angle) radians = angle_to_radians(angle) return round(init_velocity**2 * sin(radians) ** 2 / (2 * g), 2) def total_time(init_velocity: float, angle: float) -> float: """ Returns total time of the motion Formula: 2 * v_0 * sin(alpha) -------------------- g v_0 - initial velocity alpha - angle >>> total_time(30, 45) 4.33 >>> total_time(100, 78) 19.95 >>> total_time(-10, 40) Traceback (most recent call last): ... ValueError: Invalid velocity. Should be a positive number. >>> total_time(30, "b") Traceback (most recent call last): ... TypeError: Invalid angle. Range is 1-90 degrees. """ check_args(init_velocity, angle) radians = angle_to_radians(angle) return round(2 * init_velocity * sin(radians) / g, 2) def test_motion() -> None: """ >>> test_motion() """ v0, angle = 25, 20 assert horizontal_distance(v0, angle) == 40.97 assert max_height(v0, angle) == 3.73 assert total_time(v0, angle) == 1.74 if __name__ == "__main__": from doctest import testmod testmod() # Get input from user init_vel = float(input("Initial Velocity: ").strip()) # Get input from user angle = float(input("angle: ").strip()) # Print results print() print("Results: ") print(f"Horizontal Distance: {str(horizontal_distance(init_vel, angle))} [m]") print(f"Maximum Height: {str(max_height(init_vel, angle))} [m]") print(f"Total Time: {str(total_time(init_vel, angle))} [s]")
""" Horizontal Projectile Motion problem in physics. This algorithm solves a specific problem in which the motion starts from the ground as can be seen below: (v = 0) ** * * * * * * * * * * GROUND GROUND For more info: https://en.wikipedia.org/wiki/Projectile_motion """ # Importing packages from math import radians as angle_to_radians from math import sin # Acceleration Constant on Earth (unit m/s^2) g = 9.80665 def check_args(init_velocity: float, angle: float) -> None: """ Check that the arguments are valid """ # Ensure valid instance if not isinstance(init_velocity, (int, float)): raise TypeError("Invalid velocity. Should be a positive number.") if not isinstance(angle, (int, float)): raise TypeError("Invalid angle. Range is 1-90 degrees.") # Ensure valid angle if angle > 90 or angle < 1: raise ValueError("Invalid angle. Range is 1-90 degrees.") # Ensure valid velocity if init_velocity < 0: raise ValueError("Invalid velocity. Should be a positive number.") def horizontal_distance(init_velocity: float, angle: float) -> float: """ Returns the horizontal distance that the object cover Formula: v_0^2 * sin(2 * alpha) --------------------- g v_0 - initial velocity alpha - angle >>> horizontal_distance(30, 45) 91.77 >>> horizontal_distance(100, 78) 414.76 >>> horizontal_distance(-1, 20) Traceback (most recent call last): ... ValueError: Invalid velocity. Should be a positive number. >>> horizontal_distance(30, -20) Traceback (most recent call last): ... ValueError: Invalid angle. Range is 1-90 degrees. """ check_args(init_velocity, angle) radians = angle_to_radians(2 * angle) return round(init_velocity**2 * sin(radians) / g, 2) def max_height(init_velocity: float, angle: float) -> float: """ Returns the maximum height that the object reach Formula: v_0^2 * sin^2(alpha) -------------------- 2g v_0 - initial velocity alpha - angle >>> max_height(30, 45) 22.94 >>> max_height(100, 78) 487.82 >>> max_height("a", 20) Traceback (most recent call last): ... TypeError: Invalid velocity. Should be a positive number. >>> horizontal_distance(30, "b") Traceback (most recent call last): ... TypeError: Invalid angle. Range is 1-90 degrees. """ check_args(init_velocity, angle) radians = angle_to_radians(angle) return round(init_velocity**2 * sin(radians) ** 2 / (2 * g), 2) def total_time(init_velocity: float, angle: float) -> float: """ Returns total time of the motion Formula: 2 * v_0 * sin(alpha) -------------------- g v_0 - initial velocity alpha - angle >>> total_time(30, 45) 4.33 >>> total_time(100, 78) 19.95 >>> total_time(-10, 40) Traceback (most recent call last): ... ValueError: Invalid velocity. Should be a positive number. >>> total_time(30, "b") Traceback (most recent call last): ... TypeError: Invalid angle. Range is 1-90 degrees. """ check_args(init_velocity, angle) radians = angle_to_radians(angle) return round(2 * init_velocity * sin(radians) / g, 2) def test_motion() -> None: """ >>> test_motion() """ v0, angle = 25, 20 assert horizontal_distance(v0, angle) == 40.97 assert max_height(v0, angle) == 3.73 assert total_time(v0, angle) == 1.74 if __name__ == "__main__": from doctest import testmod testmod() # Get input from user init_vel = float(input("Initial Velocity: ").strip()) # Get input from user angle = float(input("angle: ").strip()) # Print results print() print("Results: ") print(f"Horizontal Distance: {str(horizontal_distance(init_vel, angle))} [m]") print(f"Maximum Height: {str(max_height(init_vel, angle))} [m]") print(f"Total Time: {str(total_time(init_vel, angle))} [s]")
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# flake8: noqa """ This is pure Python implementation of tree traversal algorithms """ from __future__ import annotations import queue class TreeNode: def __init__(self, data): self.data = data self.right = None self.left = None def build_tree(): print("\n********Press N to stop entering at any point of time********\n") check = input("Enter the value of the root node: ").strip().lower() or "n" if check == "n": return None q: queue.Queue = queue.Queue() tree_node = TreeNode(int(check)) q.put(tree_node) while not q.empty(): node_found = q.get() msg = f"Enter the left node of {node_found.data}: " check = input(msg).strip().lower() or "n" if check == "n": return tree_node left_node = TreeNode(int(check)) node_found.left = left_node q.put(left_node) msg = f"Enter the right node of {node_found.data}: " check = input(msg).strip().lower() or "n" if check == "n": return tree_node right_node = TreeNode(int(check)) node_found.right = right_node q.put(right_node) def pre_order(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> pre_order(root) 1,2,4,5,3,6,7, """ if not isinstance(node, TreeNode) or not node: return print(node.data, end=",") pre_order(node.left) pre_order(node.right) def in_order(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> in_order(root) 4,2,5,1,6,3,7, """ if not isinstance(node, TreeNode) or not node: return in_order(node.left) print(node.data, end=",") in_order(node.right) def post_order(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> post_order(root) 4,5,2,6,7,3,1, """ if not isinstance(node, TreeNode) or not node: return post_order(node.left) post_order(node.right) print(node.data, end=",") def level_order(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> level_order(root) 1,2,3,4,5,6,7, """ if not isinstance(node, TreeNode) or not node: return q: queue.Queue = queue.Queue() q.put(node) while not q.empty(): node_dequeued = q.get() print(node_dequeued.data, end=",") if node_dequeued.left: q.put(node_dequeued.left) if node_dequeued.right: q.put(node_dequeued.right) def level_order_actual(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> level_order_actual(root) 1, 2,3, 4,5,6,7, """ if not isinstance(node, TreeNode) or not node: return q: queue.Queue = queue.Queue() q.put(node) while not q.empty(): list = [] while not q.empty(): node_dequeued = q.get() print(node_dequeued.data, end=",") if node_dequeued.left: list.append(node_dequeued.left) if node_dequeued.right: list.append(node_dequeued.right) print() for node in list: q.put(node) # iteration version def pre_order_iter(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> pre_order_iter(root) 1,2,4,5,3,6,7, """ if not isinstance(node, TreeNode) or not node: return stack: list[TreeNode] = [] n = node while n or stack: while n: # start from root node, find its left child print(n.data, end=",") stack.append(n) n = n.left # end of while means current node doesn't have left child n = stack.pop() # start to traverse its right child n = n.right def in_order_iter(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> in_order_iter(root) 4,2,5,1,6,3,7, """ if not isinstance(node, TreeNode) or not node: return stack: list[TreeNode] = [] n = node while n or stack: while n: stack.append(n) n = n.left n = stack.pop() print(n.data, end=",") n = n.right def post_order_iter(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> post_order_iter(root) 4,5,2,6,7,3,1, """ if not isinstance(node, TreeNode) or not node: return stack1, stack2 = [], [] n = node stack1.append(n) while stack1: # to find the reversed order of post order, store it in stack2 n = stack1.pop() if n.left: stack1.append(n.left) if n.right: stack1.append(n.right) stack2.append(n) while stack2: # pop up from stack2 will be the post order print(stack2.pop().data, end=",") def prompt(s: str = "", width=50, char="*") -> str: if not s: return "\n" + width * char left, extra = divmod(width - len(s) - 2, 2) return f"{left * char} {s} {(left + extra) * char}" if __name__ == "__main__": import doctest doctest.testmod() print(prompt("Binary Tree Traversals")) node = build_tree() print(prompt("Pre Order Traversal")) pre_order(node) print(prompt() + "\n") print(prompt("In Order Traversal")) in_order(node) print(prompt() + "\n") print(prompt("Post Order Traversal")) post_order(node) print(prompt() + "\n") print(prompt("Level Order Traversal")) level_order(node) print(prompt() + "\n") print(prompt("Actual Level Order Traversal")) level_order_actual(node) print("*" * 50 + "\n") print(prompt("Pre Order Traversal - Iteration Version")) pre_order_iter(node) print(prompt() + "\n") print(prompt("In Order Traversal - Iteration Version")) in_order_iter(node) print(prompt() + "\n") print(prompt("Post Order Traversal - Iteration Version")) post_order_iter(node) print(prompt())
# flake8: noqa """ This is pure Python implementation of tree traversal algorithms """ from __future__ import annotations import queue class TreeNode: def __init__(self, data): self.data = data self.right = None self.left = None def build_tree(): print("\n********Press N to stop entering at any point of time********\n") check = input("Enter the value of the root node: ").strip().lower() or "n" if check == "n": return None q: queue.Queue = queue.Queue() tree_node = TreeNode(int(check)) q.put(tree_node) while not q.empty(): node_found = q.get() msg = f"Enter the left node of {node_found.data}: " check = input(msg).strip().lower() or "n" if check == "n": return tree_node left_node = TreeNode(int(check)) node_found.left = left_node q.put(left_node) msg = f"Enter the right node of {node_found.data}: " check = input(msg).strip().lower() or "n" if check == "n": return tree_node right_node = TreeNode(int(check)) node_found.right = right_node q.put(right_node) def pre_order(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> pre_order(root) 1,2,4,5,3,6,7, """ if not isinstance(node, TreeNode) or not node: return print(node.data, end=",") pre_order(node.left) pre_order(node.right) def in_order(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> in_order(root) 4,2,5,1,6,3,7, """ if not isinstance(node, TreeNode) or not node: return in_order(node.left) print(node.data, end=",") in_order(node.right) def post_order(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> post_order(root) 4,5,2,6,7,3,1, """ if not isinstance(node, TreeNode) or not node: return post_order(node.left) post_order(node.right) print(node.data, end=",") def level_order(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> level_order(root) 1,2,3,4,5,6,7, """ if not isinstance(node, TreeNode) or not node: return q: queue.Queue = queue.Queue() q.put(node) while not q.empty(): node_dequeued = q.get() print(node_dequeued.data, end=",") if node_dequeued.left: q.put(node_dequeued.left) if node_dequeued.right: q.put(node_dequeued.right) def level_order_actual(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> level_order_actual(root) 1, 2,3, 4,5,6,7, """ if not isinstance(node, TreeNode) or not node: return q: queue.Queue = queue.Queue() q.put(node) while not q.empty(): list = [] while not q.empty(): node_dequeued = q.get() print(node_dequeued.data, end=",") if node_dequeued.left: list.append(node_dequeued.left) if node_dequeued.right: list.append(node_dequeued.right) print() for node in list: q.put(node) # iteration version def pre_order_iter(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> pre_order_iter(root) 1,2,4,5,3,6,7, """ if not isinstance(node, TreeNode) or not node: return stack: list[TreeNode] = [] n = node while n or stack: while n: # start from root node, find its left child print(n.data, end=",") stack.append(n) n = n.left # end of while means current node doesn't have left child n = stack.pop() # start to traverse its right child n = n.right def in_order_iter(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> in_order_iter(root) 4,2,5,1,6,3,7, """ if not isinstance(node, TreeNode) or not node: return stack: list[TreeNode] = [] n = node while n or stack: while n: stack.append(n) n = n.left n = stack.pop() print(n.data, end=",") n = n.right def post_order_iter(node: TreeNode) -> None: """ >>> root = TreeNode(1) >>> tree_node2 = TreeNode(2) >>> tree_node3 = TreeNode(3) >>> tree_node4 = TreeNode(4) >>> tree_node5 = TreeNode(5) >>> tree_node6 = TreeNode(6) >>> tree_node7 = TreeNode(7) >>> root.left, root.right = tree_node2, tree_node3 >>> tree_node2.left, tree_node2.right = tree_node4 , tree_node5 >>> tree_node3.left, tree_node3.right = tree_node6 , tree_node7 >>> post_order_iter(root) 4,5,2,6,7,3,1, """ if not isinstance(node, TreeNode) or not node: return stack1, stack2 = [], [] n = node stack1.append(n) while stack1: # to find the reversed order of post order, store it in stack2 n = stack1.pop() if n.left: stack1.append(n.left) if n.right: stack1.append(n.right) stack2.append(n) while stack2: # pop up from stack2 will be the post order print(stack2.pop().data, end=",") def prompt(s: str = "", width=50, char="*") -> str: if not s: return "\n" + width * char left, extra = divmod(width - len(s) - 2, 2) return f"{left * char} {s} {(left + extra) * char}" if __name__ == "__main__": import doctest doctest.testmod() print(prompt("Binary Tree Traversals")) node = build_tree() print(prompt("Pre Order Traversal")) pre_order(node) print(prompt() + "\n") print(prompt("In Order Traversal")) in_order(node) print(prompt() + "\n") print(prompt("Post Order Traversal")) post_order(node) print(prompt() + "\n") print(prompt("Level Order Traversal")) level_order(node) print(prompt() + "\n") print(prompt("Actual Level Order Traversal")) level_order_actual(node) print("*" * 50 + "\n") print(prompt("Pre Order Traversal - Iteration Version")) pre_order_iter(node) print(prompt() + "\n") print(prompt("In Order Traversal - Iteration Version")) in_order_iter(node) print(prompt() + "\n") print(prompt("Post Order Traversal - Iteration Version")) post_order_iter(node) print(prompt())
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Audio Filter Audio filters work on the frequency of an audio signal to attenuate unwanted frequency and amplify wanted ones. They are used within anything related to sound, whether it is radio communication or a hi-fi system. * <https://www.masteringbox.com/filter-types/> * <http://ethanwiner.com/filters.html> * <https://en.wikipedia.org/wiki/Audio_filter> * <https://en.wikipedia.org/wiki/Electronic_filter>
# Audio Filter Audio filters work on the frequency of an audio signal to attenuate unwanted frequency and amplify wanted ones. They are used within anything related to sound, whether it is radio communication or a hi-fi system. * <https://www.masteringbox.com/filter-types/> * <http://ethanwiner.com/filters.html> * <https://en.wikipedia.org/wiki/Audio_filter> * <https://en.wikipedia.org/wiki/Electronic_filter>
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
MIT License Copyright (c) 2016-2022 TheAlgorithms and contributors Permission is hereby granted, free of charge, to any person obtaining a copy of this software and associated documentation files (the "Software"), to deal in the Software without restriction, including without limitation the rights to use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies of the Software, and to permit persons to whom the Software is furnished to do so, subject to the following conditions: The above copyright notice and this permission notice shall be included in all copies or substantial portions of the Software. THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
MIT License Copyright (c) 2016-2022 TheAlgorithms and contributors Permission is hereby granted, free of charge, to any person obtaining a copy of this software and associated documentation files (the "Software"), to deal in the Software without restriction, including without limitation the rights to use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies of the Software, and to permit persons to whom the Software is furnished to do so, subject to the following conditions: The above copyright notice and this permission notice shall be included in all copies or substantial portions of the Software. THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Gaussian Naive Bayes Example from matplotlib import pyplot as plt from sklearn.datasets import load_iris from sklearn.metrics import plot_confusion_matrix from sklearn.model_selection import train_test_split from sklearn.naive_bayes import GaussianNB def main(): """ Gaussian Naive Bayes Example using sklearn function. Iris type dataset is used to demonstrate algorithm. """ # Load Iris dataset iris = load_iris() # Split dataset into train and test data x = iris["data"] # features y = iris["target"] x_train, x_test, y_train, y_test = train_test_split( x, y, test_size=0.3, random_state=1 ) # Gaussian Naive Bayes nb_model = GaussianNB() nb_model.fit(x_train, y_train) # Display Confusion Matrix plot_confusion_matrix( nb_model, x_test, y_test, display_labels=iris["target_names"], cmap="Blues", normalize="true", ) plt.title("Normalized Confusion Matrix - IRIS Dataset") plt.show() if __name__ == "__main__": main()
# Gaussian Naive Bayes Example from matplotlib import pyplot as plt from sklearn.datasets import load_iris from sklearn.metrics import plot_confusion_matrix from sklearn.model_selection import train_test_split from sklearn.naive_bayes import GaussianNB def main(): """ Gaussian Naive Bayes Example using sklearn function. Iris type dataset is used to demonstrate algorithm. """ # Load Iris dataset iris = load_iris() # Split dataset into train and test data x = iris["data"] # features y = iris["target"] x_train, x_test, y_train, y_test = train_test_split( x, y, test_size=0.3, random_state=1 ) # Gaussian Naive Bayes nb_model = GaussianNB() nb_model.fit(x_train, y_train) # Display Confusion Matrix plot_confusion_matrix( nb_model, x_test, y_test, display_labels=iris["target_names"], cmap="Blues", normalize="true", ) plt.title("Normalized Confusion Matrix - IRIS Dataset") plt.show() if __name__ == "__main__": main()
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
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DCCCXVIII MLXVII DLXXXX MMDXXI MMMMDLXXXXVIII MXXII LXI DCCCCXLIII MMMMDV MMMMXXXIV MDCCCLVIII MMMCCLXXII MMMMDCCXXXVI MMMMLXXXIX MDCCCLXXXI MMMMDCCCXV MMMMCCCCXI MMMMCCCLIII MDCCCLXXI MMCCCCXI MLXV MMCDLXII MMMMDXXXXII MMMMDCCCXL MMMMCMLVI CCLXXXIV MMMDCCLXXXVI MMCLII MMMCCCCXV MMLXXXIII MMMV MMMV DCCLXII MMDCCCCXVI MMDCXLVIII CCLIIII CCCXXV MMDCCLXXXVIIII MMMMDCLXXVIII MMMMDCCCXCI MMMMCCCXX MMCCXLV MMMDCCCLXIX MMCCLXIIII MMMDCCCXLIX MMMMCCCLXIX CMLXXXXI MCMLXXXIX MMCDLXI MMDCLXXVIII MMMMDCCLXI MCDXXV DL CCCLXXII MXVIIII MCCCCLXVIII CIII MMMDCCLXXIIII MMMDVIII MMMMCCCLXXXXVII MMDXXVII MMDCCLXXXXV MMMMCXLVI MMMDCCLXXXII MMMDXXXVI MCXXII CLI DCLXXXIX MMMCLI MDCLXIII MMMMDCCXCVII MMCCCLXXXV MMMDCXXVIII MMMCDLX MMMCMLII MMMIV MMMMDCCCLVIII MMMDLXXXVIII MCXXIV MMMMLXXVI CLXXIX MMMCCCCXXVIIII DCCLXXXV MMMDCCCVI LI CLXXXVI MMMMCCCLXXVI MCCCLXVI CCXXXIX MMDXXXXI MMDCCCXLI DCCCLXXXVIII MMMMDCCCIV MDCCCCXV MMCMVI MMMMCMLXXXXV MMDCCLVI MMMMCCXLVIII DCCCCIIII MMCCCCIII MMMDCCLXXXVIIII MDCCCLXXXXV DVII MMMV DCXXV MMDCCCXCV DCVIII MMCDLXVI MCXXVIII MDCCXCVIII MMDCLX MMMDCCLXIV MMCDLXXVII MMDLXXXIIII MMMMCCCXXII MMMDCCCXLIIII DCCCCLXVII MMMCLXXXXIII MCCXV MMMMDCXI MMMMDCLXXXXV MMMCCCLII MMCMIX MMDCCXXV MMDLXXXVI MMMMDCXXVIIII DCCCCXXXVIIII MMCCXXXIIII MMDCCLXXVIII MDCCLXVIIII MMCCLXXXV MMMMDCCCLXXXVIII MMCMXCI MDXLII MMMMDCCXIV MMMMLI DXXXXIII MMDCCXI MMMMCCLXXXIII MMMDCCCLXXIII MDCLVII MMCD MCCCXXVII MMMMDCCIIII MMMDCCXLVI MMMCLXXXVII MMMCCVIIII MCCCCLXXIX DL DCCCLXXVI MMDXCI MMMMDCCCCXXXVI MMCII MMMDCCCXXXXV MMMCDXLV MMDCXXXXIV MMD MDCCCLXXXX MMDCXLIII MMCCXXXII MMDCXXXXVIIII DCCCLXXI MDXCVIIII MMMMCCLXXVIII MDCLVIIII MMMCCCLXXXIX MDCLXXXV MDLVIII MMMMCCVII MMMMDCXIV MMMCCCLXIIII MMIIII MMMMCCCLXXIII CCIII MMMCCLV MMMDXIII MMMCCCXC MMMDCCCXXI MMMMCCCCXXXII CCCLVI MMMCCCLXXXVI MXVIIII MMMCCCCXIIII CLXVII MMMCCLXX CCCCLXIV MMXXXXII MMMMCCLXXXX MXL CCXVI CCCCLVIIII MMCCCII MCCCLVIII MMMMCCCX MCDLXXXXIV MDCCCXIII MMDCCCXL MMMMCCCXXIII DXXXIV CVI MMMMDCLXXX DCCCVII MMCMLXIIII MMMDCCCXXXIII DCCC MDIII MMCCCLXVI MMMCCCCLXXI MMDCCCCXVIII CCXXXVII CCCXXV MDCCCXII MMMCMV MMMMCMXV MMMMDCXCI DXXI MMCCXLVIIII MMMMCMLII MDLXXX MMDCLXVI CXXI MMMDCCCLIIII MMMCXXI MCCIII MMDCXXXXI CCXCII MMMMDXXXV MMMCCCLXV MMMMDLXV MMMCCCCXXXII MMMCCCVIII DCCCCLXXXXII MMCLXIV MMMMCXI MLXXXXVII MMMCDXXXVIII MDXXII MLV MMMMDLXVI MMMCXII XXXIII MMMMDCCCXXVI MMMLXVIIII MMMLX MMMCDLXVII MDCCCLVII MMCXXXVII MDCCCCXXX MMDCCCLXIII MMMMDCXLIX MMMMCMXLVIII DCCCLXXVIIII MDCCCLIII MMMCMLXI MMMMCCLXI MMDCCCLIII MMMDCCCVI MMDXXXXIX MMCLXXXXV MMDXXX MMMXIII DCLXXIX DCCLXII MMMMDCCLXVIII MDCCXXXXIII CCXXXII MMMMDCXXV MMMCCCXXVIII MDCVIII MMMCLXXXXIIII CLXXXI MDCCCCXXXIII MMMMDCXXX MMMDCXXIV MMMCCXXXVII MCCCXXXXIIII CXVIII MMDCCCCIV MMMMCDLXXV MMMDLXIV MDXCIII MCCLXXXI MMMDCCCXXIV MCXLIII MMMDCCCI MCCLXXX CCXV MMDCCLXXI MMDLXXXIII MMMMDCXVII MMMCMLXV MCLXVIII MMMMCCLXXVI MMMDCCLXVIIII MMMMDCCCIX DLXXXXIX DCCCXXII MMMMIII MMMMCCCLXXVI DCCCXCIII DXXXI MXXXIIII CCXII MMMDCCLXXXIIII MMMCXX MMMCMXXVII DCCCXXXX MMCDXXXVIIII MMMMDCCXVIII LV MMMDCCCCVI MCCCII MMCMLXVIIII MDCCXI MMMMDLXVII MMCCCCLXI MMDCCV MMMCCCXXXIIII MMMMDI MMMDCCCXCV MMDCCLXXXXI MMMDXXVI MMMDCCCLVI MMDCXXX MCCCVII MMMMCCCLXII MMMMXXV MMCMXXV MMLVI MMDXXX MMMMCVII MDC MCCIII MMMMDCC MMCCLXXV MMDCCCXXXXVI MMMMCCCLXV CDXIIII MLXIIII CCV MMMCMXXXI CCCCLXVI MDXXXII MMMMCCCLVIII MMV MMMCLII MCMLI MMDCCXX MMMMCCCCXXXVI MCCLXXXI MMMCMVI DCCXXX MMMMCCCLXV DCCCXI MMMMDCCCXIV CCCXXI MMDLXXV CCCCLXXXX MCCCLXXXXII MMDCIX DCCXLIIII DXIV MMMMCLII CDLXI MMMCXXVII MMMMDCCCCLXIII MMMDCLIIII MCCCCXXXXII MMCCCLX CCCCLIII MDCCLXXVI MCMXXIII MMMMDLXXVIII MMDCCCCLX MMMCCCLXXXX MMMCDXXVI MMMDLVIII CCCLXI MMMMDCXXII MMDCCCXXI MMDCCXIII MMMMCLXXXVI MDCCCCXXVI MDV MMDCCCCLXXVI MMMMCCXXXVII MMMDCCLXXVIIII MMMCCCCLXVII DCCXLI MMCLXXXVIII MCCXXXVI MMDCXLVIII MMMMCXXXII MMMMDCCLXVI MMMMCMLI MMMMCLXV MMMMDCCCXCIV MCCLXXVII LXXVIIII DCCLII MMMCCCXCVI MMMCLV MMDCCCXXXXVIII DCCCXV MXC MMDCCLXXXXVII MMMMCML MMDCCCLXXVIII DXXI MCCCXLI DCLXXXXI MMCCCLXXXXVIII MDCCCCLXXVIII MMMMDXXV MMMDCXXXVI MMMCMXCVII MMXVIIII MMMDCCLXXIV MMMCXXV DXXXVIII MMMMCLXVI MDXII MMCCCLXX CCLXXI DXIV MMMCLIII DLII MMMCCCXLIX MMCCCCXXVI MMDCXLIII MXXXXII CCCLXXXV MDCLXXVI MDCXII MMMCCCLXXXIII MMDCCCCLXXXII MMMMCCCLXXXV MMDCXXI DCCCXXX MMMDCCCCLII MMMDCCXXII MMMMCDXCVIII MMMCCLXVIIII MMXXV MMMMCDXIX MMMMCCCX MMMCCCCLXVI MMMMDCLXXVIIII MMMMDCXXXXIV MMMCMXII MMMMXXXIII MMMMDLXXXII DCCCLIV MDXVIIII MMMCLXXXXV CCCCXX MMDIX MMCMLXXXVIII DCCXLIII DCCLX D MCCCVII MMMMCCCLXXXIII MDCCCLXXIIII MMMDCCCCLXXXVII MMMMCCCVII MMMDCCLXXXXVI CDXXXIV MCCLXVIII MMMMDLX MMMMDXII MMMMCCCCLIIII MCMLXXXXIII MMMMDCCCIII MMDCLXXXIII MDCCCXXXXIV XXXXVII MMMDCCCXXXII MMMDCCCXLII MCXXXV MDCXXVIIII MMMCXXXXIIII MMMMCDXVII MMMDXXIII MMMMCCCCLXI DCLXXXXVIIII LXXXXI CXXXIII MCDX MCCLVII MDCXXXXII MMMCXXIV MMMMLXXXX MMDCCCCXLV MLXXX MMDCCCCLX MCDLIII MMMCCCLXVII MMMMCCCLXXIV MMMDCVIII DCCCCXXIII MMXCI MMDCCIV MMMMDCCCXXXIV CCCLXXI MCCLXXXII MCMIII CCXXXI DCCXXXVIII MMMMDCCXLVIIII MMMMCMXXXV DCCCLXXV DCCXCI MMMMDVII MMMMDCCCLXVIIII CCCXCV MMMMDCCXX MCCCCII MMMCCCXC MMMCCCII MMDCCLXXVII MMDCLIIII CCXLIII MMMDCXVIII MMMCCCIX MCXV MMCCXXV MLXXIIII MDCCXXVI MMMCCCXX MMDLXX MMCCCCVI MMDCCXX MMMMDCCCCXCV MDCCCXXXII MMMMDCCCCXXXX XCIV MMCCCCLX MMXVII MLXXI MMMDXXVIII MDCCCCII MMMCMLVII MMCLXXXXVIII MDCCCCLV MCCCCLXXIIII MCCCLII MCDXLVI MMMMDXVIII DCCLXXXIX MMMDCCLXIV MDCCCCXLIII CLXXXXV MMMMCCXXXVI MMMDCCCXXI MMMMCDLXXVII MCDLIII MMCCXLVI DCCCLV MCDLXX DCLXXVIII MMDCXXXIX MMMMDCLX MMDCCLI MMCXXXV MMMCCXII MMMMCMLXII MMMMCCV MCCCCLXIX MMMMCCIII CLXVII MCCCLXXXXIIII MMMMDCVIII MMDCCCLXI MMLXXIX CMLXIX MMDCCCXLVIIII DCLXII MMMCCCXLVII MDCCCXXXV MMMMDCCXCVI DCXXX XXVI MMLXIX MMCXI DCXXXVII MMMMCCCXXXXVIII MMMMDCLXI MMMMDCLXXIIII MMMMVIII MMMMDCCCLXII MDCXCI MMCCCXXIIII CCCCXXXXV MMDCCCXXI MCVI MMDCCLXVIII MMMMCXL MLXVIII CMXXVII CCCLV MDCCLXXXIX MMMCCCCLXV MMDCCLXII MDLXVI MMMCCCXVIII MMMMCCLXXXI MMCXXVII MMDCCCLXVIII MMMCXCII MMMMDCLVIII MMMMDCCCXXXXII MMDCCCCLXXXXVI MDCCXL MDCCLVII MMMMDCCCLXXXVI DCCXXXIII MMMMDCCCCLXXXV MMCCXXXXVIII MMMCCLXXVIII MMMDCLXXVIII DCCCI MMMMLXXXXVIIII MMMCCCCLXXII MMCLXXXVII CCLXVI MCDXLIII MMCXXVIII MDXIV CCCXCVIII CLXXVIII MMCXXXXVIIII MMMDCLXXXIV CMLVIII MCDLIX MMMMDCCCXXXII MMMMDCXXXIIII MDCXXI MMMDCXLV MCLXXVIII MCDXXII IV MCDLXXXXIII MMMMDCCLXV CCLI MMMMDCCCXXXVIII DCLXII MCCCLXVII MMMMDCCCXXXVI MMDCCXLI MLXI MMMCDLXVIII MCCCCXCIII XXXIII MMMDCLXIII MMMMDCL DCCCXXXXIIII MMDLVII DXXXVII MCCCCXXIIII MCVII MMMMDCCXL MMMMCXXXXIIII MCCCCXXIV MMCLXVIII MMXCIII MDCCLXXX MCCCLIIII MMDCLXXI MXI MCMLIV MMMCCIIII DCCLXXXVIIII MDCLIV MMMDCXIX CMLXXXI DCCLXXXVII XXV MMMXXXVI MDVIIII CLXIII MMMCDLVIIII MMCCCCVII MMMLXX MXXXXII MMMMCCCLXVIII MMDCCCXXVIII MMMMDCXXXXI MMMMDCCCXXXXV MMMXV MMMMCCXVIIII MMDCCXIIII MMMXXVII MDCCLVIIII MMCXXIIII MCCCLXXIV DCLVIII MMMLVII MMMCXLV MMXCVII MMMCCCLXXXVII MMMMCCXXII DXII MMMDLV MCCCLXXVIII MMMCLIIII MMMMCLXXXX MMMCLXXXIIII MDCXXIII MMMMCCXVI MMMMDLXXXIII MMMDXXXXIII MMMMCCCCLV MMMDLXXXI MMMCCLXXVI MMMMXX MMMMDLVI MCCCCLXXX MMMXXII MMXXII MMDCCCCXXXI MMMDXXV MMMDCLXXXVIIII MMMDLXXXXVII MDLXIIII CMXC MMMXXXVIII MDLXXXVIII MCCCLXXVI MMCDLIX MMDCCCXVIII MDCCCXXXXVI MMMMCMIV MMMMDCIIII MMCCXXXV XXXXVI MMMMCCXVII MMCCXXIV MCMLVIIII MLXXXIX MMMMLXXXIX CLXXXXIX MMMDCCCCLVIII MMMMCCLXXIII MCCCC DCCCLIX MMMCCCLXXXII MMMCCLXVIIII MCLXXXV CDLXXXVII DCVI MMX MMCCXIII MMMMDCXX MMMMXXVIII DCCCLXII MMMMCCCXLIII MMMMCLXV DXCI MMMMCLXXX MMMDCCXXXXI MMMMXXXXVI DCLX MMMCCCXI MCCLXXX MMCDLXXII DCCLXXI MMMCCCXXXVI MCCCCLXXXVIIII CDLVIII DCCLVI MMMMDCXXXVIII MMCCCLXXXIII MMMMDCCLXXV MMMXXXVI CCCLXXXXIX CV CCCCXIII CCCCXVI MDCCCLXXXIIII MMDCCLXXXII MMMMCCCCLXXXI MXXV MMCCCLXXVIIII MMMCCXII MMMMCCXXXIII MMCCCLXXXVI MMMDCCCLVIIII MCCXXXVII MDCLXXV XXXV MMDLI MMMCCXXX MMMMCXXXXV CCCCLIX MMMMDCCCLXXIII MMCCCXVII DCCCXVI MMMCCCXXXXV MDCCCCXCV CLXXXI MMMMDCCLXX MMMDCCCIII MMCLXXVII MMMDCCXXIX MMDCCCXCIIII MMMCDXXIIII MMMMXXVIII MMMMDCCCCLXVIII MDCCCXX MMMMCDXXI MMMMDLXXXIX CCXVI MDVIII MMCCLXXI MMMDCCCLXXI MMMCCCLXXVI MMCCLXI MMMMDCCCXXXIV DLXXXVI MMMMDXXXII MMMXXIIII MMMMCDIV MMMMCCCXLVIII MMMMCXXXVIII MMMCCCLXVI MDCCXVIII MMCXX CCCLIX MMMMDCCLXXII MDCCCLXXV MMMMDCCCXXIV DCCCXXXXVIII MMMDCCCCXXXVIIII MMMMCCXXXV MDCLXXXIII MMCCLXXXIV MCLXXXXIIII DXXXXIII MCCCXXXXVIII MMCLXXIX MMMMCCLXIV MXXII MMMCXIX MDCXXXVII MMDCCVI MCLXXXXVIII MMMCXVI MCCCLX MMMCDX CCLXVIIII MMMCCLX MCXXVIII LXXXII MCCCCLXXXI MMMI MMMCCCLXIV MMMCCCXXVIIII CXXXVIII MMCCCXX MMMCCXXVIIII MCCLXVI MMMCCCCXXXXVI MMDCCXCIX MCMLXXI MMCCLXVIII CDLXXXXIII MMMMDCCXXII MMMMDCCLXXXVII MMMDCCLIV MMCCLXIII MDXXXVII DCCXXXIIII MCII MMMDCCCLXXI MMMLXXIII MDCCCLIII MMXXXVIII MDCCXVIIII MDCCCCXXXVII MMCCCXVI MCMXXII MMMCCCLVIII MMMMDCCCXX MCXXIII MMMDLXI MMMMDXXII MDCCCX MMDXCVIIII MMMDCCCCVIII MMMMDCCCCXXXXVI MMDCCCXXXV MMCXCIV MCMLXXXXIII MMMCCCLXXVI MMMMDCLXXXV CMLXIX DCXCII MMXXVIII MMMMCCCXXX XXXXVIIII
-1
TheAlgorithms/Python
7,339
Follow Flake8 pep3101 and remove modulo formatting
### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T20:16:16Z"
"2022-10-16T20:50:11Z"
7f6e0b656f6362e452b11d06acde50b8b81cb31a
f15cc2f01c2a4124ff6dc0843c728a546f9d9f79
Follow Flake8 pep3101 and remove modulo formatting. ### Describe your change: Follow Flake8 pep3101 and remove modulo formatting (replace with f-strings) For example ```py "Hello %s" % name ``` goes to ```py f"Hello {name}" ``` * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Three distinct points are plotted at random on a Cartesian plane, for which -1000 ≤ x, y ≤ 1000, such that a triangle is formed. Consider the following two triangles: A(-340,495), B(-153,-910), C(835,-947) X(-175,41), Y(-421,-714), Z(574,-645) It can be verified that triangle ABC contains the origin, whereas triangle XYZ does not. Using triangles.txt (right click and 'Save Link/Target As...'), a 27K text file containing the coordinates of one thousand "random" triangles, find the number of triangles for which the interior contains the origin. NOTE: The first two examples in the file represent the triangles in the example given above. """ from __future__ import annotations from pathlib import Path def vector_product(point1: tuple[int, int], point2: tuple[int, int]) -> int: """ Return the 2-d vector product of two vectors. >>> vector_product((1, 2), (-5, 0)) 10 >>> vector_product((3, 1), (6, 10)) 24 """ return point1[0] * point2[1] - point1[1] * point2[0] def contains_origin(x1: int, y1: int, x2: int, y2: int, x3: int, y3: int) -> bool: """ Check if the triangle given by the points A(x1, y1), B(x2, y2), C(x3, y3) contains the origin. >>> contains_origin(-340, 495, -153, -910, 835, -947) True >>> contains_origin(-175, 41, -421, -714, 574, -645) False """ point_a: tuple[int, int] = (x1, y1) point_a_to_b: tuple[int, int] = (x2 - x1, y2 - y1) point_a_to_c: tuple[int, int] = (x3 - x1, y3 - y1) a: float = -vector_product(point_a, point_a_to_b) / vector_product( point_a_to_c, point_a_to_b ) b: float = +vector_product(point_a, point_a_to_c) / vector_product( point_a_to_c, point_a_to_b ) return a > 0 and b > 0 and a + b < 1 def solution(filename: str = "p102_triangles.txt") -> int: """ Find the number of triangles whose interior contains the origin. >>> solution("test_triangles.txt") 1 """ data: str = Path(__file__).parent.joinpath(filename).read_text(encoding="utf-8") triangles: list[list[int]] = [] for line in data.strip().split("\n"): triangles.append([int(number) for number in line.split(",")]) ret: int = 0 triangle: list[int] for triangle in triangles: ret += contains_origin(*triangle) return ret if __name__ == "__main__": print(f"{solution() = }")
""" Three distinct points are plotted at random on a Cartesian plane, for which -1000 ≤ x, y ≤ 1000, such that a triangle is formed. Consider the following two triangles: A(-340,495), B(-153,-910), C(835,-947) X(-175,41), Y(-421,-714), Z(574,-645) It can be verified that triangle ABC contains the origin, whereas triangle XYZ does not. Using triangles.txt (right click and 'Save Link/Target As...'), a 27K text file containing the coordinates of one thousand "random" triangles, find the number of triangles for which the interior contains the origin. NOTE: The first two examples in the file represent the triangles in the example given above. """ from __future__ import annotations from pathlib import Path def vector_product(point1: tuple[int, int], point2: tuple[int, int]) -> int: """ Return the 2-d vector product of two vectors. >>> vector_product((1, 2), (-5, 0)) 10 >>> vector_product((3, 1), (6, 10)) 24 """ return point1[0] * point2[1] - point1[1] * point2[0] def contains_origin(x1: int, y1: int, x2: int, y2: int, x3: int, y3: int) -> bool: """ Check if the triangle given by the points A(x1, y1), B(x2, y2), C(x3, y3) contains the origin. >>> contains_origin(-340, 495, -153, -910, 835, -947) True >>> contains_origin(-175, 41, -421, -714, 574, -645) False """ point_a: tuple[int, int] = (x1, y1) point_a_to_b: tuple[int, int] = (x2 - x1, y2 - y1) point_a_to_c: tuple[int, int] = (x3 - x1, y3 - y1) a: float = -vector_product(point_a, point_a_to_b) / vector_product( point_a_to_c, point_a_to_b ) b: float = +vector_product(point_a, point_a_to_c) / vector_product( point_a_to_c, point_a_to_b ) return a > 0 and b > 0 and a + b < 1 def solution(filename: str = "p102_triangles.txt") -> int: """ Find the number of triangles whose interior contains the origin. >>> solution("test_triangles.txt") 1 """ data: str = Path(__file__).parent.joinpath(filename).read_text(encoding="utf-8") triangles: list[list[int]] = [] for line in data.strip().split("\n"): triangles.append([int(number) for number in line.split(",")]) ret: int = 0 triangle: list[int] for triangle in triangles: ret += contains_origin(*triangle) return ret if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
repos: - repo: https://github.com/pre-commit/pre-commit-hooks rev: v4.3.0 hooks: - id: check-executables-have-shebangs - id: check-yaml - id: end-of-file-fixer types: [python] - id: trailing-whitespace exclude: | (?x)^( data_structures/heap/binomial_heap.py )$ - id: requirements-txt-fixer - repo: https://github.com/psf/black rev: 22.10.0 hooks: - id: black - repo: https://github.com/PyCQA/isort rev: 5.10.1 hooks: - id: isort args: - --profile=black - repo: https://github.com/asottile/pyupgrade rev: v3.0.0 hooks: - id: pyupgrade args: - --py310-plus - repo: https://github.com/PyCQA/flake8 rev: 5.0.4 hooks: - id: flake8 # See .flake8 for args additional_dependencies: - flake8-bugbear - flake8-builtins - flake8-comprehensions - pep8-naming - repo: https://github.com/pre-commit/mirrors-mypy rev: v0.982 hooks: - id: mypy args: - --ignore-missing-imports - --install-types # See mirrors-mypy README.md - --non-interactive additional_dependencies: [types-requests] - repo: https://github.com/codespell-project/codespell rev: v2.2.1 hooks: - id: codespell args: - --ignore-words-list=ans,crate,damon,fo,followings,hist,iff,mater,secant,som,sur,tim,zar - --skip="./.*,./strings/dictionary.txt,./strings/words.txt,./project_euler/problem_022/p022_names.txt" exclude: | (?x)^( strings/dictionary.txt | strings/words.txt | project_euler/problem_022/p022_names.txt )$ - repo: local hooks: - id: validate-filenames name: Validate filenames entry: ./scripts/validate_filenames.py language: script pass_filenames: false
repos: - repo: https://github.com/pre-commit/pre-commit-hooks rev: v4.3.0 hooks: - id: check-executables-have-shebangs - id: check-yaml - id: end-of-file-fixer types: [python] - id: trailing-whitespace exclude: | (?x)^( data_structures/heap/binomial_heap.py )$ - id: requirements-txt-fixer - repo: https://github.com/psf/black rev: 22.10.0 hooks: - id: black - repo: https://github.com/PyCQA/isort rev: 5.10.1 hooks: - id: isort args: - --profile=black - repo: https://github.com/asottile/pyupgrade rev: v3.0.0 hooks: - id: pyupgrade args: - --py310-plus - repo: https://github.com/PyCQA/flake8 rev: 5.0.4 hooks: - id: flake8 # See .flake8 for args additional_dependencies: - flake8-bugbear - flake8-builtins - flake8-broken-line - flake8-comprehensions - pep8-naming - repo: https://github.com/pre-commit/mirrors-mypy rev: v0.982 hooks: - id: mypy args: - --ignore-missing-imports - --install-types # See mirrors-mypy README.md - --non-interactive additional_dependencies: [types-requests] - repo: https://github.com/codespell-project/codespell rev: v2.2.1 hooks: - id: codespell args: - --ignore-words-list=ans,crate,damon,fo,followings,hist,iff,mater,secant,som,sur,tim,zar - --skip="./.*,./strings/dictionary.txt,./strings/words.txt,./project_euler/problem_022/p022_names.txt" exclude: | (?x)^( strings/dictionary.txt | strings/words.txt | project_euler/problem_022/p022_names.txt )$ - repo: local hooks: - id: validate-filenames name: Validate filenames entry: ./scripts/validate_filenames.py language: script pass_filenames: false
1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 8: https://projecteuler.net/problem=8 Largest product in a series The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832. 73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450 Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product? """ import sys N = """73167176531330624919225119674426574742355349194934\ 96983520312774506326239578318016984801869478851843\ 85861560789112949495459501737958331952853208805511\ 12540698747158523863050715693290963295227443043557\ 66896648950445244523161731856403098711121722383113\ 62229893423380308135336276614282806444486645238749\ 30358907296290491560440772390713810515859307960866\ 70172427121883998797908792274921901699720888093776\ 65727333001053367881220235421809751254540594752243\ 52584907711670556013604839586446706324415722155397\ 53697817977846174064955149290862569321978468622482\ 83972241375657056057490261407972968652414535100474\ 82166370484403199890008895243450658541227588666881\ 16427171479924442928230863465674813919123162824586\ 17866458359124566529476545682848912883142607690042\ 24219022671055626321111109370544217506941658960408\ 07198403850962455444362981230987879927244284909188\ 84580156166097919133875499200524063689912560717606\ 05886116467109405077541002256983155200055935729725\ 71636269561882670428252483600823257530420752963450""" def solution(n: str = N) -> int: """ Find the thirteen adjacent digits in the 1000-digit number n that have the greatest product and returns it. >>> solution("13978431290823798458352374") 609638400 >>> solution("13978431295823798458352374") 2612736000 >>> solution("1397843129582379841238352374") 209018880 """ largest_product = -sys.maxsize - 1 for i in range(len(n) - 12): product = 1 for j in range(13): product *= int(n[i + j]) if product > largest_product: largest_product = product return largest_product if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 8: https://projecteuler.net/problem=8 Largest product in a series The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832. 73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450 Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product? """ import sys N = ( "73167176531330624919225119674426574742355349194934" "96983520312774506326239578318016984801869478851843" "85861560789112949495459501737958331952853208805511" "12540698747158523863050715693290963295227443043557" "66896648950445244523161731856403098711121722383113" "62229893423380308135336276614282806444486645238749" "30358907296290491560440772390713810515859307960866" "70172427121883998797908792274921901699720888093776" "65727333001053367881220235421809751254540594752243" "52584907711670556013604839586446706324415722155397" "53697817977846174064955149290862569321978468622482" "83972241375657056057490261407972968652414535100474" "82166370484403199890008895243450658541227588666881" "16427171479924442928230863465674813919123162824586" "17866458359124566529476545682848912883142607690042" "24219022671055626321111109370544217506941658960408" "07198403850962455444362981230987879927244284909188" "84580156166097919133875499200524063689912560717606" "05886116467109405077541002256983155200055935729725" "71636269561882670428252483600823257530420752963450" ) def solution(n: str = N) -> int: """ Find the thirteen adjacent digits in the 1000-digit number n that have the greatest product and returns it. >>> solution("13978431290823798458352374") 609638400 >>> solution("13978431295823798458352374") 2612736000 >>> solution("1397843129582379841238352374") 209018880 """ largest_product = -sys.maxsize - 1 for i in range(len(n) - 12): product = 1 for j in range(13): product *= int(n[i + j]) if product > largest_product: largest_product = product return largest_product if __name__ == "__main__": print(f"{solution() = }")
1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 8: https://projecteuler.net/problem=8 Largest product in a series The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832. 73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450 Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product? """ import sys N = """73167176531330624919225119674426574742355349194934\ 96983520312774506326239578318016984801869478851843\ 85861560789112949495459501737958331952853208805511\ 12540698747158523863050715693290963295227443043557\ 66896648950445244523161731856403098711121722383113\ 62229893423380308135336276614282806444486645238749\ 30358907296290491560440772390713810515859307960866\ 70172427121883998797908792274921901699720888093776\ 65727333001053367881220235421809751254540594752243\ 52584907711670556013604839586446706324415722155397\ 53697817977846174064955149290862569321978468622482\ 83972241375657056057490261407972968652414535100474\ 82166370484403199890008895243450658541227588666881\ 16427171479924442928230863465674813919123162824586\ 17866458359124566529476545682848912883142607690042\ 24219022671055626321111109370544217506941658960408\ 07198403850962455444362981230987879927244284909188\ 84580156166097919133875499200524063689912560717606\ 05886116467109405077541002256983155200055935729725\ 71636269561882670428252483600823257530420752963450""" def str_eval(s: str) -> int: """ Returns product of digits in given string n >>> str_eval("987654321") 362880 >>> str_eval("22222222") 256 """ product = 1 for digit in s: product *= int(digit) return product def solution(n: str = N) -> int: """ Find the thirteen adjacent digits in the 1000-digit number n that have the greatest product and returns it. """ largest_product = -sys.maxsize - 1 substr = n[:13] cur_index = 13 while cur_index < len(n) - 13: if int(n[cur_index]) >= int(substr[0]): substr = substr[1:] + n[cur_index] cur_index += 1 else: largest_product = max(largest_product, str_eval(substr)) substr = n[cur_index : cur_index + 13] cur_index += 13 return largest_product if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 8: https://projecteuler.net/problem=8 Largest product in a series The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832. 73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450 Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product? """ import sys N = ( "73167176531330624919225119674426574742355349194934" "96983520312774506326239578318016984801869478851843" "85861560789112949495459501737958331952853208805511" "12540698747158523863050715693290963295227443043557" "66896648950445244523161731856403098711121722383113" "62229893423380308135336276614282806444486645238749" "30358907296290491560440772390713810515859307960866" "70172427121883998797908792274921901699720888093776" "65727333001053367881220235421809751254540594752243" "52584907711670556013604839586446706324415722155397" "53697817977846174064955149290862569321978468622482" "83972241375657056057490261407972968652414535100474" "82166370484403199890008895243450658541227588666881" "16427171479924442928230863465674813919123162824586" "17866458359124566529476545682848912883142607690042" "24219022671055626321111109370544217506941658960408" "07198403850962455444362981230987879927244284909188" "84580156166097919133875499200524063689912560717606" "05886116467109405077541002256983155200055935729725" "71636269561882670428252483600823257530420752963450" ) def str_eval(s: str) -> int: """ Returns product of digits in given string n >>> str_eval("987654321") 362880 >>> str_eval("22222222") 256 """ product = 1 for digit in s: product *= int(digit) return product def solution(n: str = N) -> int: """ Find the thirteen adjacent digits in the 1000-digit number n that have the greatest product and returns it. """ largest_product = -sys.maxsize - 1 substr = n[:13] cur_index = 13 while cur_index < len(n) - 13: if int(n[cur_index]) >= int(substr[0]): substr = substr[1:] + n[cur_index] cur_index += 1 else: largest_product = max(largest_product, str_eval(substr)) substr = n[cur_index : cur_index + 13] cur_index += 13 return largest_product if __name__ == "__main__": print(f"{solution() = }")
1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Information on binary shifts: # https://docs.python.org/3/library/stdtypes.html#bitwise-operations-on-integer-types # https://www.interviewcake.com/concept/java/bit-shift def logical_left_shift(number: int, shift_amount: int) -> str: """ Take in 2 positive integers. 'number' is the integer to be logically left shifted 'shift_amount' times. i.e. (number << shift_amount) Return the shifted binary representation. >>> logical_left_shift(0, 1) '0b00' >>> logical_left_shift(1, 1) '0b10' >>> logical_left_shift(1, 5) '0b100000' >>> logical_left_shift(17, 2) '0b1000100' >>> logical_left_shift(1983, 4) '0b111101111110000' >>> logical_left_shift(1, -1) Traceback (most recent call last): ... ValueError: both inputs must be positive integers """ if number < 0 or shift_amount < 0: raise ValueError("both inputs must be positive integers") binary_number = str(bin(number)) binary_number += "0" * shift_amount return binary_number def logical_right_shift(number: int, shift_amount: int) -> str: """ Take in positive 2 integers. 'number' is the integer to be logically right shifted 'shift_amount' times. i.e. (number >>> shift_amount) Return the shifted binary representation. >>> logical_right_shift(0, 1) '0b0' >>> logical_right_shift(1, 1) '0b0' >>> logical_right_shift(1, 5) '0b0' >>> logical_right_shift(17, 2) '0b100' >>> logical_right_shift(1983, 4) '0b1111011' >>> logical_right_shift(1, -1) Traceback (most recent call last): ... ValueError: both inputs must be positive integers """ if number < 0 or shift_amount < 0: raise ValueError("both inputs must be positive integers") binary_number = str(bin(number))[2:] if shift_amount >= len(binary_number): return "0b0" shifted_binary_number = binary_number[: len(binary_number) - shift_amount] return "0b" + shifted_binary_number def arithmetic_right_shift(number: int, shift_amount: int) -> str: """ Take in 2 integers. 'number' is the integer to be arithmetically right shifted 'shift_amount' times. i.e. (number >> shift_amount) Return the shifted binary representation. >>> arithmetic_right_shift(0, 1) '0b00' >>> arithmetic_right_shift(1, 1) '0b00' >>> arithmetic_right_shift(-1, 1) '0b11' >>> arithmetic_right_shift(17, 2) '0b000100' >>> arithmetic_right_shift(-17, 2) '0b111011' >>> arithmetic_right_shift(-1983, 4) '0b111110000100' """ if number >= 0: # Get binary representation of positive number binary_number = "0" + str(bin(number)).strip("-")[2:] else: # Get binary (2's complement) representation of negative number binary_number_length = len(bin(number)[3:]) # Find 2's complement of number binary_number = bin(abs(number) - (1 << binary_number_length))[3:] binary_number = ( "1" + "0" * (binary_number_length - len(binary_number)) + binary_number ) if shift_amount >= len(binary_number): return "0b" + binary_number[0] * len(binary_number) return ( "0b" + binary_number[0] * shift_amount + binary_number[: len(binary_number) - shift_amount] ) if __name__ == "__main__": import doctest doctest.testmod()
# Information on binary shifts: # https://docs.python.org/3/library/stdtypes.html#bitwise-operations-on-integer-types # https://www.interviewcake.com/concept/java/bit-shift def logical_left_shift(number: int, shift_amount: int) -> str: """ Take in 2 positive integers. 'number' is the integer to be logically left shifted 'shift_amount' times. i.e. (number << shift_amount) Return the shifted binary representation. >>> logical_left_shift(0, 1) '0b00' >>> logical_left_shift(1, 1) '0b10' >>> logical_left_shift(1, 5) '0b100000' >>> logical_left_shift(17, 2) '0b1000100' >>> logical_left_shift(1983, 4) '0b111101111110000' >>> logical_left_shift(1, -1) Traceback (most recent call last): ... ValueError: both inputs must be positive integers """ if number < 0 or shift_amount < 0: raise ValueError("both inputs must be positive integers") binary_number = str(bin(number)) binary_number += "0" * shift_amount return binary_number def logical_right_shift(number: int, shift_amount: int) -> str: """ Take in positive 2 integers. 'number' is the integer to be logically right shifted 'shift_amount' times. i.e. (number >>> shift_amount) Return the shifted binary representation. >>> logical_right_shift(0, 1) '0b0' >>> logical_right_shift(1, 1) '0b0' >>> logical_right_shift(1, 5) '0b0' >>> logical_right_shift(17, 2) '0b100' >>> logical_right_shift(1983, 4) '0b1111011' >>> logical_right_shift(1, -1) Traceback (most recent call last): ... ValueError: both inputs must be positive integers """ if number < 0 or shift_amount < 0: raise ValueError("both inputs must be positive integers") binary_number = str(bin(number))[2:] if shift_amount >= len(binary_number): return "0b0" shifted_binary_number = binary_number[: len(binary_number) - shift_amount] return "0b" + shifted_binary_number def arithmetic_right_shift(number: int, shift_amount: int) -> str: """ Take in 2 integers. 'number' is the integer to be arithmetically right shifted 'shift_amount' times. i.e. (number >> shift_amount) Return the shifted binary representation. >>> arithmetic_right_shift(0, 1) '0b00' >>> arithmetic_right_shift(1, 1) '0b00' >>> arithmetic_right_shift(-1, 1) '0b11' >>> arithmetic_right_shift(17, 2) '0b000100' >>> arithmetic_right_shift(-17, 2) '0b111011' >>> arithmetic_right_shift(-1983, 4) '0b111110000100' """ if number >= 0: # Get binary representation of positive number binary_number = "0" + str(bin(number)).strip("-")[2:] else: # Get binary (2's complement) representation of negative number binary_number_length = len(bin(number)[3:]) # Find 2's complement of number binary_number = bin(abs(number) - (1 << binary_number_length))[3:] binary_number = ( "1" + "0" * (binary_number_length - len(binary_number)) + binary_number ) if shift_amount >= len(binary_number): return "0b" + binary_number[0] * len(binary_number) return ( "0b" + binary_number[0] * shift_amount + binary_number[: len(binary_number) - shift_amount] ) if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
def multiplicative_persistence(num: int) -> int: """ Return the persistence of a given number. https://en.wikipedia.org/wiki/Persistence_of_a_number >>> multiplicative_persistence(217) 2 >>> multiplicative_persistence(-1) Traceback (most recent call last): ... ValueError: multiplicative_persistence() does not accept negative values >>> multiplicative_persistence("long number") Traceback (most recent call last): ... ValueError: multiplicative_persistence() only accepts integral values """ if not isinstance(num, int): raise ValueError("multiplicative_persistence() only accepts integral values") if num < 0: raise ValueError("multiplicative_persistence() does not accept negative values") steps = 0 num_string = str(num) while len(num_string) != 1: numbers = [int(i) for i in num_string] total = 1 for i in range(0, len(numbers)): total *= numbers[i] num_string = str(total) steps += 1 return steps def additive_persistence(num: int) -> int: """ Return the persistence of a given number. https://en.wikipedia.org/wiki/Persistence_of_a_number >>> additive_persistence(199) 3 >>> additive_persistence(-1) Traceback (most recent call last): ... ValueError: additive_persistence() does not accept negative values >>> additive_persistence("long number") Traceback (most recent call last): ... ValueError: additive_persistence() only accepts integral values """ if not isinstance(num, int): raise ValueError("additive_persistence() only accepts integral values") if num < 0: raise ValueError("additive_persistence() does not accept negative values") steps = 0 num_string = str(num) while len(num_string) != 1: numbers = [int(i) for i in num_string] total = 0 for i in range(0, len(numbers)): total += numbers[i] num_string = str(total) steps += 1 return steps if __name__ == "__main__": import doctest doctest.testmod()
def multiplicative_persistence(num: int) -> int: """ Return the persistence of a given number. https://en.wikipedia.org/wiki/Persistence_of_a_number >>> multiplicative_persistence(217) 2 >>> multiplicative_persistence(-1) Traceback (most recent call last): ... ValueError: multiplicative_persistence() does not accept negative values >>> multiplicative_persistence("long number") Traceback (most recent call last): ... ValueError: multiplicative_persistence() only accepts integral values """ if not isinstance(num, int): raise ValueError("multiplicative_persistence() only accepts integral values") if num < 0: raise ValueError("multiplicative_persistence() does not accept negative values") steps = 0 num_string = str(num) while len(num_string) != 1: numbers = [int(i) for i in num_string] total = 1 for i in range(0, len(numbers)): total *= numbers[i] num_string = str(total) steps += 1 return steps def additive_persistence(num: int) -> int: """ Return the persistence of a given number. https://en.wikipedia.org/wiki/Persistence_of_a_number >>> additive_persistence(199) 3 >>> additive_persistence(-1) Traceback (most recent call last): ... ValueError: additive_persistence() does not accept negative values >>> additive_persistence("long number") Traceback (most recent call last): ... ValueError: additive_persistence() only accepts integral values """ if not isinstance(num, int): raise ValueError("additive_persistence() only accepts integral values") if num < 0: raise ValueError("additive_persistence() does not accept negative values") steps = 0 num_string = str(num) while len(num_string) != 1: numbers = [int(i) for i in num_string] total = 0 for i in range(0, len(numbers)): total += numbers[i] num_string = str(total) steps += 1 return steps if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
from json import loads from pathlib import Path import numpy as np from yulewalker import yulewalk from audio_filters.butterworth_filter import make_highpass from audio_filters.iir_filter import IIRFilter data = loads((Path(__file__).resolve().parent / "loudness_curve.json").read_text()) class EqualLoudnessFilter: r""" An equal-loudness filter which compensates for the human ear's non-linear response to sound. This filter corrects this by cascading a yulewalk filter and a butterworth filter. Designed for use with samplerate of 44.1kHz and above. If you're using a lower samplerate, use with caution. Code based on matlab implementation at https://bit.ly/3eqh2HU (url shortened for flake8) Target curve: https://i.imgur.com/3g2VfaM.png Yulewalk response: https://i.imgur.com/J9LnJ4C.png Butterworth and overall response: https://i.imgur.com/3g2VfaM.png Images and original matlab implementation by David Robinson, 2001 """ def __init__(self, samplerate: int = 44100) -> None: self.yulewalk_filter = IIRFilter(10) self.butterworth_filter = make_highpass(150, samplerate) # pad the data to nyquist curve_freqs = np.array(data["frequencies"] + [max(20000.0, samplerate / 2)]) curve_gains = np.array(data["gains"] + [140]) # Convert to angular frequency freqs_normalized = curve_freqs / samplerate * 2 # Invert the curve and normalize to 0dB gains_normalized = np.power(10, (np.min(curve_gains) - curve_gains) / 20) # Scipy's `yulewalk` function is a stub, so we're using the # `yulewalker` library instead. # This function computes the coefficients using a least-squares # fit to the specified curve. ya, yb = yulewalk(10, freqs_normalized, gains_normalized) self.yulewalk_filter.set_coefficients(ya, yb) def process(self, sample: float) -> float: """ Process a single sample through both filters >>> filt = EqualLoudnessFilter() >>> filt.process(0.0) 0.0 """ tmp = self.yulewalk_filter.process(sample) return self.butterworth_filter.process(tmp)
from json import loads from pathlib import Path import numpy as np from yulewalker import yulewalk from audio_filters.butterworth_filter import make_highpass from audio_filters.iir_filter import IIRFilter data = loads((Path(__file__).resolve().parent / "loudness_curve.json").read_text()) class EqualLoudnessFilter: r""" An equal-loudness filter which compensates for the human ear's non-linear response to sound. This filter corrects this by cascading a yulewalk filter and a butterworth filter. Designed for use with samplerate of 44.1kHz and above. If you're using a lower samplerate, use with caution. Code based on matlab implementation at https://bit.ly/3eqh2HU (url shortened for flake8) Target curve: https://i.imgur.com/3g2VfaM.png Yulewalk response: https://i.imgur.com/J9LnJ4C.png Butterworth and overall response: https://i.imgur.com/3g2VfaM.png Images and original matlab implementation by David Robinson, 2001 """ def __init__(self, samplerate: int = 44100) -> None: self.yulewalk_filter = IIRFilter(10) self.butterworth_filter = make_highpass(150, samplerate) # pad the data to nyquist curve_freqs = np.array(data["frequencies"] + [max(20000.0, samplerate / 2)]) curve_gains = np.array(data["gains"] + [140]) # Convert to angular frequency freqs_normalized = curve_freqs / samplerate * 2 # Invert the curve and normalize to 0dB gains_normalized = np.power(10, (np.min(curve_gains) - curve_gains) / 20) # Scipy's `yulewalk` function is a stub, so we're using the # `yulewalker` library instead. # This function computes the coefficients using a least-squares # fit to the specified curve. ya, yb = yulewalk(10, freqs_normalized, gains_normalized) self.yulewalk_filter.set_coefficients(ya, yb) def process(self, sample: float) -> float: """ Process a single sample through both filters >>> filt = EqualLoudnessFilter() >>> filt.process(0.0) 0.0 """ tmp = self.yulewalk_filter.process(sample) return self.butterworth_filter.process(tmp)
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Youtube Explanation: https://www.youtube.com/watch?v=lBRtnuxg-gU from __future__ import annotations def minimum_cost_path(matrix: list[list[int]]) -> int: """ Find the minimum cost traced by all possible paths from top left to bottom right in a given matrix >>> minimum_cost_path([[2, 1], [3, 1], [4, 2]]) 6 >>> minimum_cost_path([[2, 1, 4], [2, 1, 3], [3, 2, 1]]) 7 """ # preprocessing the first row for i in range(1, len(matrix[0])): matrix[0][i] += matrix[0][i - 1] # preprocessing the first column for i in range(1, len(matrix)): matrix[i][0] += matrix[i - 1][0] # updating the path cost for current position for i in range(1, len(matrix)): for j in range(1, len(matrix[0])): matrix[i][j] += min(matrix[i - 1][j], matrix[i][j - 1]) return matrix[-1][-1] if __name__ == "__main__": import doctest doctest.testmod()
# Youtube Explanation: https://www.youtube.com/watch?v=lBRtnuxg-gU from __future__ import annotations def minimum_cost_path(matrix: list[list[int]]) -> int: """ Find the minimum cost traced by all possible paths from top left to bottom right in a given matrix >>> minimum_cost_path([[2, 1], [3, 1], [4, 2]]) 6 >>> minimum_cost_path([[2, 1, 4], [2, 1, 3], [3, 2, 1]]) 7 """ # preprocessing the first row for i in range(1, len(matrix[0])): matrix[0][i] += matrix[0][i - 1] # preprocessing the first column for i in range(1, len(matrix)): matrix[i][0] += matrix[i - 1][0] # updating the path cost for current position for i in range(1, len(matrix)): for j in range(1, len(matrix[0])): matrix[i][j] += min(matrix[i - 1][j], matrix[i][j - 1]) return matrix[-1][-1] if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Name scores Problem 22 Using names.txt (right click and 'Save Link/Target As...'), a 46K text file containing over five-thousand first names, begin by sorting it into alphabetical order. Then working out the alphabetical value for each name, multiply this value by its alphabetical position in the list to obtain a name score. For example, when the list is sorted into alphabetical order, COLIN, which is worth 3 + 15 + 12 + 9 + 14 = 53, is the 938th name in the list. So, COLIN would obtain a score of 938 × 53 = 49714. What is the total of all the name scores in the file? """ import os def solution(): """Returns the total of all the name scores in the file. >>> solution() 871198282 """ total_sum = 0 temp_sum = 0 with open(os.path.dirname(__file__) + "/p022_names.txt") as file: name = str(file.readlines()[0]) name = name.replace('"', "").split(",") name.sort() for i in range(len(name)): for j in name[i]: temp_sum += ord(j) - ord("A") + 1 total_sum += (i + 1) * temp_sum temp_sum = 0 return total_sum if __name__ == "__main__": print(solution())
""" Name scores Problem 22 Using names.txt (right click and 'Save Link/Target As...'), a 46K text file containing over five-thousand first names, begin by sorting it into alphabetical order. Then working out the alphabetical value for each name, multiply this value by its alphabetical position in the list to obtain a name score. For example, when the list is sorted into alphabetical order, COLIN, which is worth 3 + 15 + 12 + 9 + 14 = 53, is the 938th name in the list. So, COLIN would obtain a score of 938 × 53 = 49714. What is the total of all the name scores in the file? """ import os def solution(): """Returns the total of all the name scores in the file. >>> solution() 871198282 """ total_sum = 0 temp_sum = 0 with open(os.path.dirname(__file__) + "/p022_names.txt") as file: name = str(file.readlines()[0]) name = name.replace('"', "").split(",") name.sort() for i in range(len(name)): for j in name[i]: temp_sum += ord(j) - ord("A") + 1 total_sum += (i + 1) * temp_sum temp_sum = 0 return total_sum if __name__ == "__main__": print(solution())
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
from sys import maxsize def max_sub_array_sum(a: list, size: int = 0): """ >>> max_sub_array_sum([-13, -3, -25, -20, -3, -16, -23, -12, -5, -22, -15, -4, -7]) -3 """ size = size or len(a) max_so_far = -maxsize - 1 max_ending_here = 0 for i in range(0, size): max_ending_here = max_ending_here + a[i] if max_so_far < max_ending_here: max_so_far = max_ending_here if max_ending_here < 0: max_ending_here = 0 return max_so_far if __name__ == "__main__": a = [-13, -3, -25, -20, 1, -16, -23, -12, -5, -22, -15, -4, -7] print(("Maximum contiguous sum is", max_sub_array_sum(a, len(a))))
from sys import maxsize def max_sub_array_sum(a: list, size: int = 0): """ >>> max_sub_array_sum([-13, -3, -25, -20, -3, -16, -23, -12, -5, -22, -15, -4, -7]) -3 """ size = size or len(a) max_so_far = -maxsize - 1 max_ending_here = 0 for i in range(0, size): max_ending_here = max_ending_here + a[i] if max_so_far < max_ending_here: max_so_far = max_ending_here if max_ending_here < 0: max_ending_here = 0 return max_so_far if __name__ == "__main__": a = [-13, -3, -25, -20, 1, -16, -23, -12, -5, -22, -15, -4, -7] print(("Maximum contiguous sum is", max_sub_array_sum(a, len(a))))
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 10: https://projecteuler.net/problem=10 Summation of primes The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two million. References: - https://en.wikipedia.org/wiki/Prime_number """ import math def is_prime(number: int) -> bool: """Checks to see if a number is a prime in O(sqrt(n)). A number is prime if it has exactly two factors: 1 and itself. Returns boolean representing primality of given number num (i.e., if the result is true, then the number is indeed prime else it is not). >>> is_prime(2) True >>> is_prime(3) True >>> is_prime(27) False >>> is_prime(2999) True >>> is_prime(0) False >>> is_prime(1) False """ if 1 < number < 4: # 2 and 3 are primes return True elif number < 2 or number % 2 == 0 or number % 3 == 0: # Negatives, 0, 1, all even numbers, all multiples of 3 are not primes return False # All primes number are in format of 6k +/- 1 for i in range(5, int(math.sqrt(number) + 1), 6): if number % i == 0 or number % (i + 2) == 0: return False return True def solution(n: int = 2000000) -> int: """ Returns the sum of all the primes below n. >>> solution(1000) 76127 >>> solution(5000) 1548136 >>> solution(10000) 5736396 >>> solution(7) 10 """ return sum(num for num in range(3, n, 2) if is_prime(num)) + 2 if n > 2 else 0 if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 10: https://projecteuler.net/problem=10 Summation of primes The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two million. References: - https://en.wikipedia.org/wiki/Prime_number """ import math def is_prime(number: int) -> bool: """Checks to see if a number is a prime in O(sqrt(n)). A number is prime if it has exactly two factors: 1 and itself. Returns boolean representing primality of given number num (i.e., if the result is true, then the number is indeed prime else it is not). >>> is_prime(2) True >>> is_prime(3) True >>> is_prime(27) False >>> is_prime(2999) True >>> is_prime(0) False >>> is_prime(1) False """ if 1 < number < 4: # 2 and 3 are primes return True elif number < 2 or number % 2 == 0 or number % 3 == 0: # Negatives, 0, 1, all even numbers, all multiples of 3 are not primes return False # All primes number are in format of 6k +/- 1 for i in range(5, int(math.sqrt(number) + 1), 6): if number % i == 0 or number % (i + 2) == 0: return False return True def solution(n: int = 2000000) -> int: """ Returns the sum of all the primes below n. >>> solution(1000) 76127 >>> solution(5000) 1548136 >>> solution(10000) 5736396 >>> solution(7) 10 """ return sum(num for num in range(3, n, 2) if is_prime(num)) + 2 if n > 2 else 0 if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Fast Polynomial Multiplication using radix-2 fast Fourier Transform. """ import mpmath # for roots of unity import numpy as np class FFT: """ Fast Polynomial Multiplication using radix-2 fast Fourier Transform. Reference: https://en.wikipedia.org/wiki/Cooley%E2%80%93Tukey_FFT_algorithm#The_radix-2_DIT_case For polynomials of degree m and n the algorithms has complexity O(n*logn + m*logm) The main part of the algorithm is split in two parts: 1) __DFT: We compute the discrete fourier transform (DFT) of A and B using a bottom-up dynamic approach - 2) __multiply: Once we obtain the DFT of A*B, we can similarly invert it to obtain A*B The class FFT takes two polynomials A and B with complex coefficients as arguments; The two polynomials should be represented as a sequence of coefficients starting from the free term. Thus, for instance x + 2*x^3 could be represented as [0,1,0,2] or (0,1,0,2). The constructor adds some zeros at the end so that the polynomials have the same length which is a power of 2 at least the length of their product. Example: Create two polynomials as sequences >>> A = [0, 1, 0, 2] # x+2x^3 >>> B = (2, 3, 4, 0) # 2+3x+4x^2 Create an FFT object with them >>> x = FFT(A, B) Print product >>> print(x.product) # 2x + 3x^2 + 8x^3 + 4x^4 + 6x^5 [(-0+0j), (2+0j), (3+0j), (8+0j), (6+0j), (8+0j)] __str__ test >>> print(x) A = 0*x^0 + 1*x^1 + 2*x^0 + 3*x^2 B = 0*x^2 + 1*x^3 + 2*x^4 A*B = 0*x^(-0+0j) + 1*x^(2+0j) + 2*x^(3+0j) + 3*x^(8+0j) + 4*x^(6+0j) + 5*x^(8+0j) """ def __init__(self, poly_a=None, poly_b=None): # Input as list self.polyA = list(poly_a or [0])[:] self.polyB = list(poly_b or [0])[:] # Remove leading zero coefficients while self.polyA[-1] == 0: self.polyA.pop() self.len_A = len(self.polyA) while self.polyB[-1] == 0: self.polyB.pop() self.len_B = len(self.polyB) # Add 0 to make lengths equal a power of 2 self.c_max_length = int( 2 ** np.ceil(np.log2(len(self.polyA) + len(self.polyB) - 1)) ) while len(self.polyA) < self.c_max_length: self.polyA.append(0) while len(self.polyB) < self.c_max_length: self.polyB.append(0) # A complex root used for the fourier transform self.root = complex(mpmath.root(x=1, n=self.c_max_length, k=1)) # The product self.product = self.__multiply() # Discrete fourier transform of A and B def __dft(self, which): if which == "A": dft = [[x] for x in self.polyA] else: dft = [[x] for x in self.polyB] # Corner case if len(dft) <= 1: return dft[0] # next_ncol = self.c_max_length // 2 while next_ncol > 0: new_dft = [[] for i in range(next_ncol)] root = self.root**next_ncol # First half of next step current_root = 1 for j in range(self.c_max_length // (next_ncol * 2)): for i in range(next_ncol): new_dft[i].append(dft[i][j] + current_root * dft[i + next_ncol][j]) current_root *= root # Second half of next step current_root = 1 for j in range(self.c_max_length // (next_ncol * 2)): for i in range(next_ncol): new_dft[i].append(dft[i][j] - current_root * dft[i + next_ncol][j]) current_root *= root # Update dft = new_dft next_ncol = next_ncol // 2 return dft[0] # multiply the DFTs of A and B and find A*B def __multiply(self): dft_a = self.__dft("A") dft_b = self.__dft("B") inverce_c = [[dft_a[i] * dft_b[i] for i in range(self.c_max_length)]] del dft_a del dft_b # Corner Case if len(inverce_c[0]) <= 1: return inverce_c[0] # Inverse DFT next_ncol = 2 while next_ncol <= self.c_max_length: new_inverse_c = [[] for i in range(next_ncol)] root = self.root ** (next_ncol // 2) current_root = 1 # First half of next step for j in range(self.c_max_length // next_ncol): for i in range(next_ncol // 2): # Even positions new_inverse_c[i].append( ( inverce_c[i][j] + inverce_c[i][j + self.c_max_length // next_ncol] ) / 2 ) # Odd positions new_inverse_c[i + next_ncol // 2].append( ( inverce_c[i][j] - inverce_c[i][j + self.c_max_length // next_ncol] ) / (2 * current_root) ) current_root *= root # Update inverce_c = new_inverse_c next_ncol *= 2 # Unpack inverce_c = [round(x[0].real, 8) + round(x[0].imag, 8) * 1j for x in inverce_c] # Remove leading 0's while inverce_c[-1] == 0: inverce_c.pop() return inverce_c # Overwrite __str__ for print(); Shows A, B and A*B def __str__(self): a = "A = " + " + ".join( f"{coef}*x^{i}" for coef, i in enumerate(self.polyA[: self.len_A]) ) b = "B = " + " + ".join( f"{coef}*x^{i}" for coef, i in enumerate(self.polyB[: self.len_B]) ) c = "A*B = " + " + ".join( f"{coef}*x^{i}" for coef, i in enumerate(self.product) ) return "\n".join((a, b, c)) # Unit tests if __name__ == "__main__": import doctest doctest.testmod()
""" Fast Polynomial Multiplication using radix-2 fast Fourier Transform. """ import mpmath # for roots of unity import numpy as np class FFT: """ Fast Polynomial Multiplication using radix-2 fast Fourier Transform. Reference: https://en.wikipedia.org/wiki/Cooley%E2%80%93Tukey_FFT_algorithm#The_radix-2_DIT_case For polynomials of degree m and n the algorithms has complexity O(n*logn + m*logm) The main part of the algorithm is split in two parts: 1) __DFT: We compute the discrete fourier transform (DFT) of A and B using a bottom-up dynamic approach - 2) __multiply: Once we obtain the DFT of A*B, we can similarly invert it to obtain A*B The class FFT takes two polynomials A and B with complex coefficients as arguments; The two polynomials should be represented as a sequence of coefficients starting from the free term. Thus, for instance x + 2*x^3 could be represented as [0,1,0,2] or (0,1,0,2). The constructor adds some zeros at the end so that the polynomials have the same length which is a power of 2 at least the length of their product. Example: Create two polynomials as sequences >>> A = [0, 1, 0, 2] # x+2x^3 >>> B = (2, 3, 4, 0) # 2+3x+4x^2 Create an FFT object with them >>> x = FFT(A, B) Print product >>> print(x.product) # 2x + 3x^2 + 8x^3 + 4x^4 + 6x^5 [(-0+0j), (2+0j), (3+0j), (8+0j), (6+0j), (8+0j)] __str__ test >>> print(x) A = 0*x^0 + 1*x^1 + 2*x^0 + 3*x^2 B = 0*x^2 + 1*x^3 + 2*x^4 A*B = 0*x^(-0+0j) + 1*x^(2+0j) + 2*x^(3+0j) + 3*x^(8+0j) + 4*x^(6+0j) + 5*x^(8+0j) """ def __init__(self, poly_a=None, poly_b=None): # Input as list self.polyA = list(poly_a or [0])[:] self.polyB = list(poly_b or [0])[:] # Remove leading zero coefficients while self.polyA[-1] == 0: self.polyA.pop() self.len_A = len(self.polyA) while self.polyB[-1] == 0: self.polyB.pop() self.len_B = len(self.polyB) # Add 0 to make lengths equal a power of 2 self.c_max_length = int( 2 ** np.ceil(np.log2(len(self.polyA) + len(self.polyB) - 1)) ) while len(self.polyA) < self.c_max_length: self.polyA.append(0) while len(self.polyB) < self.c_max_length: self.polyB.append(0) # A complex root used for the fourier transform self.root = complex(mpmath.root(x=1, n=self.c_max_length, k=1)) # The product self.product = self.__multiply() # Discrete fourier transform of A and B def __dft(self, which): if which == "A": dft = [[x] for x in self.polyA] else: dft = [[x] for x in self.polyB] # Corner case if len(dft) <= 1: return dft[0] # next_ncol = self.c_max_length // 2 while next_ncol > 0: new_dft = [[] for i in range(next_ncol)] root = self.root**next_ncol # First half of next step current_root = 1 for j in range(self.c_max_length // (next_ncol * 2)): for i in range(next_ncol): new_dft[i].append(dft[i][j] + current_root * dft[i + next_ncol][j]) current_root *= root # Second half of next step current_root = 1 for j in range(self.c_max_length // (next_ncol * 2)): for i in range(next_ncol): new_dft[i].append(dft[i][j] - current_root * dft[i + next_ncol][j]) current_root *= root # Update dft = new_dft next_ncol = next_ncol // 2 return dft[0] # multiply the DFTs of A and B and find A*B def __multiply(self): dft_a = self.__dft("A") dft_b = self.__dft("B") inverce_c = [[dft_a[i] * dft_b[i] for i in range(self.c_max_length)]] del dft_a del dft_b # Corner Case if len(inverce_c[0]) <= 1: return inverce_c[0] # Inverse DFT next_ncol = 2 while next_ncol <= self.c_max_length: new_inverse_c = [[] for i in range(next_ncol)] root = self.root ** (next_ncol // 2) current_root = 1 # First half of next step for j in range(self.c_max_length // next_ncol): for i in range(next_ncol // 2): # Even positions new_inverse_c[i].append( ( inverce_c[i][j] + inverce_c[i][j + self.c_max_length // next_ncol] ) / 2 ) # Odd positions new_inverse_c[i + next_ncol // 2].append( ( inverce_c[i][j] - inverce_c[i][j + self.c_max_length // next_ncol] ) / (2 * current_root) ) current_root *= root # Update inverce_c = new_inverse_c next_ncol *= 2 # Unpack inverce_c = [round(x[0].real, 8) + round(x[0].imag, 8) * 1j for x in inverce_c] # Remove leading 0's while inverce_c[-1] == 0: inverce_c.pop() return inverce_c # Overwrite __str__ for print(); Shows A, B and A*B def __str__(self): a = "A = " + " + ".join( f"{coef}*x^{i}" for coef, i in enumerate(self.polyA[: self.len_A]) ) b = "B = " + " + ".join( f"{coef}*x^{i}" for coef, i in enumerate(self.polyB[: self.len_B]) ) c = "A*B = " + " + ".join( f"{coef}*x^{i}" for coef, i in enumerate(self.product) ) return "\n".join((a, b, c)) # Unit tests if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
"""Queue represented by a Python list""" class Queue: def __init__(self): self.entries = [] self.length = 0 self.front = 0 def __str__(self): printed = "<" + str(self.entries)[1:-1] + ">" return printed """Enqueues {@code item} @param item item to enqueue""" def put(self, item): self.entries.append(item) self.length = self.length + 1 """Dequeues {@code item} @requirement: |self.length| > 0 @return dequeued item that was dequeued""" def get(self): self.length = self.length - 1 dequeued = self.entries[self.front] # self.front-=1 # self.entries = self.entries[self.front:] self.entries = self.entries[1:] return dequeued """Rotates the queue {@code rotation} times @param rotation number of times to rotate queue""" def rotate(self, rotation): for _ in range(rotation): self.put(self.get()) """Enqueues {@code item} @return item at front of self.entries""" def get_front(self): return self.entries[0] """Returns the length of this.entries""" def size(self): return self.length
"""Queue represented by a Python list""" class Queue: def __init__(self): self.entries = [] self.length = 0 self.front = 0 def __str__(self): printed = "<" + str(self.entries)[1:-1] + ">" return printed """Enqueues {@code item} @param item item to enqueue""" def put(self, item): self.entries.append(item) self.length = self.length + 1 """Dequeues {@code item} @requirement: |self.length| > 0 @return dequeued item that was dequeued""" def get(self): self.length = self.length - 1 dequeued = self.entries[self.front] # self.front-=1 # self.entries = self.entries[self.front:] self.entries = self.entries[1:] return dequeued """Rotates the queue {@code rotation} times @param rotation number of times to rotate queue""" def rotate(self, rotation): for _ in range(rotation): self.put(self.get()) """Enqueues {@code item} @return item at front of self.entries""" def get_front(self): return self.entries[0] """Returns the length of this.entries""" def size(self): return self.length
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
def hamming_distance(string1: str, string2: str) -> int: """Calculate the Hamming distance between two equal length strings In information theory, the Hamming distance between two strings of equal length is the number of positions at which the corresponding symbols are different. https://en.wikipedia.org/wiki/Hamming_distance Args: string1 (str): Sequence 1 string2 (str): Sequence 2 Returns: int: Hamming distance >>> hamming_distance("python", "python") 0 >>> hamming_distance("karolin", "kathrin") 3 >>> hamming_distance("00000", "11111") 5 >>> hamming_distance("karolin", "kath") Traceback (most recent call last): ... ValueError: String lengths must match! """ if len(string1) != len(string2): raise ValueError("String lengths must match!") count = 0 for char1, char2 in zip(string1, string2): if char1 != char2: count += 1 return count if __name__ == "__main__": import doctest doctest.testmod()
def hamming_distance(string1: str, string2: str) -> int: """Calculate the Hamming distance between two equal length strings In information theory, the Hamming distance between two strings of equal length is the number of positions at which the corresponding symbols are different. https://en.wikipedia.org/wiki/Hamming_distance Args: string1 (str): Sequence 1 string2 (str): Sequence 2 Returns: int: Hamming distance >>> hamming_distance("python", "python") 0 >>> hamming_distance("karolin", "kathrin") 3 >>> hamming_distance("00000", "11111") 5 >>> hamming_distance("karolin", "kath") Traceback (most recent call last): ... ValueError: String lengths must match! """ if len(string1) != len(string2): raise ValueError("String lengths must match!") count = 0 for char1, char2 in zip(string1, string2): if char1 != char2: count += 1 return count if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Convert speed units https://en.wikipedia.org/wiki/Kilometres_per_hour https://en.wikipedia.org/wiki/Miles_per_hour https://en.wikipedia.org/wiki/Knot_(unit) https://en.wikipedia.org/wiki/Metre_per_second """ speed_chart: dict[str, float] = { "km/h": 1.0, "m/s": 3.6, "mph": 1.609344, "knot": 1.852, } speed_chart_inverse: dict[str, float] = { "km/h": 1.0, "m/s": 0.277777778, "mph": 0.621371192, "knot": 0.539956803, } def convert_speed(speed: float, unit_from: str, unit_to: str) -> float: """ Convert speed from one unit to another using the speed_chart above. "km/h": 1.0, "m/s": 3.6, "mph": 1.609344, "knot": 1.852, >>> convert_speed(100, "km/h", "m/s") 27.778 >>> convert_speed(100, "km/h", "mph") 62.137 >>> convert_speed(100, "km/h", "knot") 53.996 >>> convert_speed(100, "m/s", "km/h") 360.0 >>> convert_speed(100, "m/s", "mph") 223.694 >>> convert_speed(100, "m/s", "knot") 194.384 >>> convert_speed(100, "mph", "km/h") 160.934 >>> convert_speed(100, "mph", "m/s") 44.704 >>> convert_speed(100, "mph", "knot") 86.898 >>> convert_speed(100, "knot", "km/h") 185.2 >>> convert_speed(100, "knot", "m/s") 51.444 >>> convert_speed(100, "knot", "mph") 115.078 """ if unit_to not in speed_chart or unit_from not in speed_chart_inverse: raise ValueError( f"Incorrect 'from_type' or 'to_type' value: {unit_from!r}, {unit_to!r}\n" f"Valid values are: {', '.join(speed_chart_inverse)}" ) return round(speed * speed_chart[unit_from] * speed_chart_inverse[unit_to], 3) if __name__ == "__main__": import doctest doctest.testmod()
""" Convert speed units https://en.wikipedia.org/wiki/Kilometres_per_hour https://en.wikipedia.org/wiki/Miles_per_hour https://en.wikipedia.org/wiki/Knot_(unit) https://en.wikipedia.org/wiki/Metre_per_second """ speed_chart: dict[str, float] = { "km/h": 1.0, "m/s": 3.6, "mph": 1.609344, "knot": 1.852, } speed_chart_inverse: dict[str, float] = { "km/h": 1.0, "m/s": 0.277777778, "mph": 0.621371192, "knot": 0.539956803, } def convert_speed(speed: float, unit_from: str, unit_to: str) -> float: """ Convert speed from one unit to another using the speed_chart above. "km/h": 1.0, "m/s": 3.6, "mph": 1.609344, "knot": 1.852, >>> convert_speed(100, "km/h", "m/s") 27.778 >>> convert_speed(100, "km/h", "mph") 62.137 >>> convert_speed(100, "km/h", "knot") 53.996 >>> convert_speed(100, "m/s", "km/h") 360.0 >>> convert_speed(100, "m/s", "mph") 223.694 >>> convert_speed(100, "m/s", "knot") 194.384 >>> convert_speed(100, "mph", "km/h") 160.934 >>> convert_speed(100, "mph", "m/s") 44.704 >>> convert_speed(100, "mph", "knot") 86.898 >>> convert_speed(100, "knot", "km/h") 185.2 >>> convert_speed(100, "knot", "m/s") 51.444 >>> convert_speed(100, "knot", "mph") 115.078 """ if unit_to not in speed_chart or unit_from not in speed_chart_inverse: raise ValueError( f"Incorrect 'from_type' or 'to_type' value: {unit_from!r}, {unit_to!r}\n" f"Valid values are: {', '.join(speed_chart_inverse)}" ) return round(speed * speed_chart[unit_from] * speed_chart_inverse[unit_to], 3) if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Knight Tour Intro: https://www.youtube.com/watch?v=ab_dY3dZFHM from __future__ import annotations def get_valid_pos(position: tuple[int, int], n: int) -> list[tuple[int, int]]: """ Find all the valid positions a knight can move to from the current position. >>> get_valid_pos((1, 3), 4) [(2, 1), (0, 1), (3, 2)] """ y, x = position positions = [ (y + 1, x + 2), (y - 1, x + 2), (y + 1, x - 2), (y - 1, x - 2), (y + 2, x + 1), (y + 2, x - 1), (y - 2, x + 1), (y - 2, x - 1), ] permissible_positions = [] for position in positions: y_test, x_test = position if 0 <= y_test < n and 0 <= x_test < n: permissible_positions.append(position) return permissible_positions def is_complete(board: list[list[int]]) -> bool: """ Check if the board (matrix) has been completely filled with non-zero values. >>> is_complete([[1]]) True >>> is_complete([[1, 2], [3, 0]]) False """ return not any(elem == 0 for row in board for elem in row) def open_knight_tour_helper( board: list[list[int]], pos: tuple[int, int], curr: int ) -> bool: """ Helper function to solve knight tour problem. """ if is_complete(board): return True for position in get_valid_pos(pos, len(board)): y, x = position if board[y][x] == 0: board[y][x] = curr + 1 if open_knight_tour_helper(board, position, curr + 1): return True board[y][x] = 0 return False def open_knight_tour(n: int) -> list[list[int]]: """ Find the solution for the knight tour problem for a board of size n. Raises ValueError if the tour cannot be performed for the given size. >>> open_knight_tour(1) [[1]] >>> open_knight_tour(2) Traceback (most recent call last): ... ValueError: Open Kight Tour cannot be performed on a board of size 2 """ board = [[0 for i in range(n)] for j in range(n)] for i in range(n): for j in range(n): board[i][j] = 1 if open_knight_tour_helper(board, (i, j), 1): return board board[i][j] = 0 raise ValueError(f"Open Kight Tour cannot be performed on a board of size {n}") if __name__ == "__main__": import doctest doctest.testmod()
# Knight Tour Intro: https://www.youtube.com/watch?v=ab_dY3dZFHM from __future__ import annotations def get_valid_pos(position: tuple[int, int], n: int) -> list[tuple[int, int]]: """ Find all the valid positions a knight can move to from the current position. >>> get_valid_pos((1, 3), 4) [(2, 1), (0, 1), (3, 2)] """ y, x = position positions = [ (y + 1, x + 2), (y - 1, x + 2), (y + 1, x - 2), (y - 1, x - 2), (y + 2, x + 1), (y + 2, x - 1), (y - 2, x + 1), (y - 2, x - 1), ] permissible_positions = [] for position in positions: y_test, x_test = position if 0 <= y_test < n and 0 <= x_test < n: permissible_positions.append(position) return permissible_positions def is_complete(board: list[list[int]]) -> bool: """ Check if the board (matrix) has been completely filled with non-zero values. >>> is_complete([[1]]) True >>> is_complete([[1, 2], [3, 0]]) False """ return not any(elem == 0 for row in board for elem in row) def open_knight_tour_helper( board: list[list[int]], pos: tuple[int, int], curr: int ) -> bool: """ Helper function to solve knight tour problem. """ if is_complete(board): return True for position in get_valid_pos(pos, len(board)): y, x = position if board[y][x] == 0: board[y][x] = curr + 1 if open_knight_tour_helper(board, position, curr + 1): return True board[y][x] = 0 return False def open_knight_tour(n: int) -> list[list[int]]: """ Find the solution for the knight tour problem for a board of size n. Raises ValueError if the tour cannot be performed for the given size. >>> open_knight_tour(1) [[1]] >>> open_knight_tour(2) Traceback (most recent call last): ... ValueError: Open Kight Tour cannot be performed on a board of size 2 """ board = [[0 for i in range(n)] for j in range(n)] for i in range(n): for j in range(n): board[i][j] = 1 if open_knight_tour_helper(board, (i, j), 1): return board board[i][j] = 0 raise ValueError(f"Open Kight Tour cannot be performed on a board of size {n}") if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Description The Koch snowflake is a fractal curve and one of the earliest fractals to have been described. The Koch snowflake can be built up iteratively, in a sequence of stages. The first stage is an equilateral triangle, and each successive stage is formed by adding outward bends to each side of the previous stage, making smaller equilateral triangles. This can be achieved through the following steps for each line: 1. divide the line segment into three segments of equal length. 2. draw an equilateral triangle that has the middle segment from step 1 as its base and points outward. 3. remove the line segment that is the base of the triangle from step 2. (description adapted from https://en.wikipedia.org/wiki/Koch_snowflake ) (for a more detailed explanation and an implementation in the Processing language, see https://natureofcode.com/book/chapter-8-fractals/ #84-the-koch-curve-and-the-arraylist-technique ) Requirements (pip): - matplotlib - numpy """ from __future__ import annotations import matplotlib.pyplot as plt # type: ignore import numpy # initial triangle of Koch snowflake VECTOR_1 = numpy.array([0, 0]) VECTOR_2 = numpy.array([0.5, 0.8660254]) VECTOR_3 = numpy.array([1, 0]) INITIAL_VECTORS = [VECTOR_1, VECTOR_2, VECTOR_3, VECTOR_1] # uncomment for simple Koch curve instead of Koch snowflake # INITIAL_VECTORS = [VECTOR_1, VECTOR_3] def iterate(initial_vectors: list[numpy.ndarray], steps: int) -> list[numpy.ndarray]: """ Go through the number of iterations determined by the argument "steps". Be careful with high values (above 5) since the time to calculate increases exponentially. >>> iterate([numpy.array([0, 0]), numpy.array([1, 0])], 1) [array([0, 0]), array([0.33333333, 0. ]), array([0.5 , \ 0.28867513]), array([0.66666667, 0. ]), array([1, 0])] """ vectors = initial_vectors for _ in range(steps): vectors = iteration_step(vectors) return vectors def iteration_step(vectors: list[numpy.ndarray]) -> list[numpy.ndarray]: """ Loops through each pair of adjacent vectors. Each line between two adjacent vectors is divided into 4 segments by adding 3 additional vectors in-between the original two vectors. The vector in the middle is constructed through a 60 degree rotation so it is bent outwards. >>> iteration_step([numpy.array([0, 0]), numpy.array([1, 0])]) [array([0, 0]), array([0.33333333, 0. ]), array([0.5 , \ 0.28867513]), array([0.66666667, 0. ]), array([1, 0])] """ new_vectors = [] for i, start_vector in enumerate(vectors[:-1]): end_vector = vectors[i + 1] new_vectors.append(start_vector) difference_vector = end_vector - start_vector new_vectors.append(start_vector + difference_vector / 3) new_vectors.append( start_vector + difference_vector / 3 + rotate(difference_vector / 3, 60) ) new_vectors.append(start_vector + difference_vector * 2 / 3) new_vectors.append(vectors[-1]) return new_vectors def rotate(vector: numpy.ndarray, angle_in_degrees: float) -> numpy.ndarray: """ Standard rotation of a 2D vector with a rotation matrix (see https://en.wikipedia.org/wiki/Rotation_matrix ) >>> rotate(numpy.array([1, 0]), 60) array([0.5 , 0.8660254]) >>> rotate(numpy.array([1, 0]), 90) array([6.123234e-17, 1.000000e+00]) """ theta = numpy.radians(angle_in_degrees) c, s = numpy.cos(theta), numpy.sin(theta) rotation_matrix = numpy.array(((c, -s), (s, c))) return numpy.dot(rotation_matrix, vector) def plot(vectors: list[numpy.ndarray]) -> None: """ Utility function to plot the vectors using matplotlib.pyplot No doctest was implemented since this function does not have a return value """ # avoid stretched display of graph axes = plt.gca() axes.set_aspect("equal") # matplotlib.pyplot.plot takes a list of all x-coordinates and a list of all # y-coordinates as inputs, which are constructed from the vector-list using # zip() x_coordinates, y_coordinates = zip(*vectors) plt.plot(x_coordinates, y_coordinates) plt.show() if __name__ == "__main__": import doctest doctest.testmod() processed_vectors = iterate(INITIAL_VECTORS, 5) plot(processed_vectors)
""" Description The Koch snowflake is a fractal curve and one of the earliest fractals to have been described. The Koch snowflake can be built up iteratively, in a sequence of stages. The first stage is an equilateral triangle, and each successive stage is formed by adding outward bends to each side of the previous stage, making smaller equilateral triangles. This can be achieved through the following steps for each line: 1. divide the line segment into three segments of equal length. 2. draw an equilateral triangle that has the middle segment from step 1 as its base and points outward. 3. remove the line segment that is the base of the triangle from step 2. (description adapted from https://en.wikipedia.org/wiki/Koch_snowflake ) (for a more detailed explanation and an implementation in the Processing language, see https://natureofcode.com/book/chapter-8-fractals/ #84-the-koch-curve-and-the-arraylist-technique ) Requirements (pip): - matplotlib - numpy """ from __future__ import annotations import matplotlib.pyplot as plt # type: ignore import numpy # initial triangle of Koch snowflake VECTOR_1 = numpy.array([0, 0]) VECTOR_2 = numpy.array([0.5, 0.8660254]) VECTOR_3 = numpy.array([1, 0]) INITIAL_VECTORS = [VECTOR_1, VECTOR_2, VECTOR_3, VECTOR_1] # uncomment for simple Koch curve instead of Koch snowflake # INITIAL_VECTORS = [VECTOR_1, VECTOR_3] def iterate(initial_vectors: list[numpy.ndarray], steps: int) -> list[numpy.ndarray]: """ Go through the number of iterations determined by the argument "steps". Be careful with high values (above 5) since the time to calculate increases exponentially. >>> iterate([numpy.array([0, 0]), numpy.array([1, 0])], 1) [array([0, 0]), array([0.33333333, 0. ]), array([0.5 , \ 0.28867513]), array([0.66666667, 0. ]), array([1, 0])] """ vectors = initial_vectors for _ in range(steps): vectors = iteration_step(vectors) return vectors def iteration_step(vectors: list[numpy.ndarray]) -> list[numpy.ndarray]: """ Loops through each pair of adjacent vectors. Each line between two adjacent vectors is divided into 4 segments by adding 3 additional vectors in-between the original two vectors. The vector in the middle is constructed through a 60 degree rotation so it is bent outwards. >>> iteration_step([numpy.array([0, 0]), numpy.array([1, 0])]) [array([0, 0]), array([0.33333333, 0. ]), array([0.5 , \ 0.28867513]), array([0.66666667, 0. ]), array([1, 0])] """ new_vectors = [] for i, start_vector in enumerate(vectors[:-1]): end_vector = vectors[i + 1] new_vectors.append(start_vector) difference_vector = end_vector - start_vector new_vectors.append(start_vector + difference_vector / 3) new_vectors.append( start_vector + difference_vector / 3 + rotate(difference_vector / 3, 60) ) new_vectors.append(start_vector + difference_vector * 2 / 3) new_vectors.append(vectors[-1]) return new_vectors def rotate(vector: numpy.ndarray, angle_in_degrees: float) -> numpy.ndarray: """ Standard rotation of a 2D vector with a rotation matrix (see https://en.wikipedia.org/wiki/Rotation_matrix ) >>> rotate(numpy.array([1, 0]), 60) array([0.5 , 0.8660254]) >>> rotate(numpy.array([1, 0]), 90) array([6.123234e-17, 1.000000e+00]) """ theta = numpy.radians(angle_in_degrees) c, s = numpy.cos(theta), numpy.sin(theta) rotation_matrix = numpy.array(((c, -s), (s, c))) return numpy.dot(rotation_matrix, vector) def plot(vectors: list[numpy.ndarray]) -> None: """ Utility function to plot the vectors using matplotlib.pyplot No doctest was implemented since this function does not have a return value """ # avoid stretched display of graph axes = plt.gca() axes.set_aspect("equal") # matplotlib.pyplot.plot takes a list of all x-coordinates and a list of all # y-coordinates as inputs, which are constructed from the vector-list using # zip() x_coordinates, y_coordinates = zip(*vectors) plt.plot(x_coordinates, y_coordinates) plt.show() if __name__ == "__main__": import doctest doctest.testmod() processed_vectors = iterate(INITIAL_VECTORS, 5) plot(processed_vectors)
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Problem 28 Url: https://projecteuler.net/problem=28 Statement: Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is formed as follows: 21 22 23 24 25 20 7 8 9 10 19 6 1 2 11 18 5 4 3 12 17 16 15 14 13 It can be verified that the sum of the numbers on the diagonals is 101. What is the sum of the numbers on the diagonals in a 1001 by 1001 spiral formed in the same way? """ from math import ceil def solution(n: int = 1001) -> int: """Returns the sum of the numbers on the diagonals in a n by n spiral formed in the same way. >>> solution(1001) 669171001 >>> solution(500) 82959497 >>> solution(100) 651897 >>> solution(50) 79697 >>> solution(10) 537 """ total = 1 for i in range(1, int(ceil(n / 2.0))): odd = 2 * i + 1 even = 2 * i total = total + 4 * odd**2 - 6 * even return total if __name__ == "__main__": import sys if len(sys.argv) == 1: print(solution()) else: try: n = int(sys.argv[1]) print(solution(n)) except ValueError: print("Invalid entry - please enter a number")
""" Problem 28 Url: https://projecteuler.net/problem=28 Statement: Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is formed as follows: 21 22 23 24 25 20 7 8 9 10 19 6 1 2 11 18 5 4 3 12 17 16 15 14 13 It can be verified that the sum of the numbers on the diagonals is 101. What is the sum of the numbers on the diagonals in a 1001 by 1001 spiral formed in the same way? """ from math import ceil def solution(n: int = 1001) -> int: """Returns the sum of the numbers on the diagonals in a n by n spiral formed in the same way. >>> solution(1001) 669171001 >>> solution(500) 82959497 >>> solution(100) 651897 >>> solution(50) 79697 >>> solution(10) 537 """ total = 1 for i in range(1, int(ceil(n / 2.0))): odd = 2 * i + 1 even = 2 * i total = total + 4 * odd**2 - 6 * even return total if __name__ == "__main__": import sys if len(sys.argv) == 1: print(solution()) else: try: n = int(sys.argv[1]) print(solution(n)) except ValueError: print("Invalid entry - please enter a number")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
from collections.abc import Callable class Heap: """ A generic Heap class, can be used as min or max by passing the key function accordingly. """ def __init__(self, key: Callable | None = None) -> None: # Stores actual heap items. self.arr: list = [] # Stores indexes of each item for supporting updates and deletion. self.pos_map: dict = {} # Stores current size of heap. self.size = 0 # Stores function used to evaluate the score of an item on which basis ordering # will be done. self.key = key or (lambda x: x) def _parent(self, i: int) -> int | None: """Returns parent index of given index if exists else None""" return int((i - 1) / 2) if i > 0 else None def _left(self, i: int) -> int | None: """Returns left-child-index of given index if exists else None""" left = int(2 * i + 1) return left if 0 < left < self.size else None def _right(self, i: int) -> int | None: """Returns right-child-index of given index if exists else None""" right = int(2 * i + 2) return right if 0 < right < self.size else None def _swap(self, i: int, j: int) -> None: """Performs changes required for swapping two elements in the heap""" # First update the indexes of the items in index map. self.pos_map[self.arr[i][0]], self.pos_map[self.arr[j][0]] = ( self.pos_map[self.arr[j][0]], self.pos_map[self.arr[i][0]], ) # Then swap the items in the list. self.arr[i], self.arr[j] = self.arr[j], self.arr[i] def _cmp(self, i: int, j: int) -> bool: """Compares the two items using default comparison""" return self.arr[i][1] < self.arr[j][1] def _get_valid_parent(self, i: int) -> int: """ Returns index of valid parent as per desired ordering among given index and both it's children """ left = self._left(i) right = self._right(i) valid_parent = i if left is not None and not self._cmp(left, valid_parent): valid_parent = left if right is not None and not self._cmp(right, valid_parent): valid_parent = right return valid_parent def _heapify_up(self, index: int) -> None: """Fixes the heap in upward direction of given index""" parent = self._parent(index) while parent is not None and not self._cmp(index, parent): self._swap(index, parent) index, parent = parent, self._parent(parent) def _heapify_down(self, index: int) -> None: """Fixes the heap in downward direction of given index""" valid_parent = self._get_valid_parent(index) while valid_parent != index: self._swap(index, valid_parent) index, valid_parent = valid_parent, self._get_valid_parent(valid_parent) def update_item(self, item: int, item_value: int) -> None: """Updates given item value in heap if present""" if item not in self.pos_map: return index = self.pos_map[item] self.arr[index] = [item, self.key(item_value)] # Make sure heap is right in both up and down direction. # Ideally only one of them will make any change. self._heapify_up(index) self._heapify_down(index) def delete_item(self, item: int) -> None: """Deletes given item from heap if present""" if item not in self.pos_map: return index = self.pos_map[item] del self.pos_map[item] self.arr[index] = self.arr[self.size - 1] self.pos_map[self.arr[self.size - 1][0]] = index self.size -= 1 # Make sure heap is right in both up and down direction. Ideally only one # of them will make any change- so no performance loss in calling both. if self.size > index: self._heapify_up(index) self._heapify_down(index) def insert_item(self, item: int, item_value: int) -> None: """Inserts given item with given value in heap""" arr_len = len(self.arr) if arr_len == self.size: self.arr.append([item, self.key(item_value)]) else: self.arr[self.size] = [item, self.key(item_value)] self.pos_map[item] = self.size self.size += 1 self._heapify_up(self.size - 1) def get_top(self) -> tuple | None: """Returns top item tuple (Calculated value, item) from heap if present""" return self.arr[0] if self.size else None def extract_top(self) -> tuple | None: """ Return top item tuple (Calculated value, item) from heap and removes it as well if present """ top_item_tuple = self.get_top() if top_item_tuple: self.delete_item(top_item_tuple[0]) return top_item_tuple def test_heap() -> None: """ >>> h = Heap() # Max-heap >>> h.insert_item(5, 34) >>> h.insert_item(6, 31) >>> h.insert_item(7, 37) >>> h.get_top() [7, 37] >>> h.extract_top() [7, 37] >>> h.extract_top() [5, 34] >>> h.extract_top() [6, 31] >>> h = Heap(key=lambda x: -x) # Min heap >>> h.insert_item(5, 34) >>> h.insert_item(6, 31) >>> h.insert_item(7, 37) >>> h.get_top() [6, -31] >>> h.extract_top() [6, -31] >>> h.extract_top() [5, -34] >>> h.extract_top() [7, -37] >>> h.insert_item(8, 45) >>> h.insert_item(9, 40) >>> h.insert_item(10, 50) >>> h.get_top() [9, -40] >>> h.update_item(10, 30) >>> h.get_top() [10, -30] >>> h.delete_item(10) >>> h.get_top() [9, -40] """ pass if __name__ == "__main__": import doctest doctest.testmod()
from collections.abc import Callable class Heap: """ A generic Heap class, can be used as min or max by passing the key function accordingly. """ def __init__(self, key: Callable | None = None) -> None: # Stores actual heap items. self.arr: list = [] # Stores indexes of each item for supporting updates and deletion. self.pos_map: dict = {} # Stores current size of heap. self.size = 0 # Stores function used to evaluate the score of an item on which basis ordering # will be done. self.key = key or (lambda x: x) def _parent(self, i: int) -> int | None: """Returns parent index of given index if exists else None""" return int((i - 1) / 2) if i > 0 else None def _left(self, i: int) -> int | None: """Returns left-child-index of given index if exists else None""" left = int(2 * i + 1) return left if 0 < left < self.size else None def _right(self, i: int) -> int | None: """Returns right-child-index of given index if exists else None""" right = int(2 * i + 2) return right if 0 < right < self.size else None def _swap(self, i: int, j: int) -> None: """Performs changes required for swapping two elements in the heap""" # First update the indexes of the items in index map. self.pos_map[self.arr[i][0]], self.pos_map[self.arr[j][0]] = ( self.pos_map[self.arr[j][0]], self.pos_map[self.arr[i][0]], ) # Then swap the items in the list. self.arr[i], self.arr[j] = self.arr[j], self.arr[i] def _cmp(self, i: int, j: int) -> bool: """Compares the two items using default comparison""" return self.arr[i][1] < self.arr[j][1] def _get_valid_parent(self, i: int) -> int: """ Returns index of valid parent as per desired ordering among given index and both it's children """ left = self._left(i) right = self._right(i) valid_parent = i if left is not None and not self._cmp(left, valid_parent): valid_parent = left if right is not None and not self._cmp(right, valid_parent): valid_parent = right return valid_parent def _heapify_up(self, index: int) -> None: """Fixes the heap in upward direction of given index""" parent = self._parent(index) while parent is not None and not self._cmp(index, parent): self._swap(index, parent) index, parent = parent, self._parent(parent) def _heapify_down(self, index: int) -> None: """Fixes the heap in downward direction of given index""" valid_parent = self._get_valid_parent(index) while valid_parent != index: self._swap(index, valid_parent) index, valid_parent = valid_parent, self._get_valid_parent(valid_parent) def update_item(self, item: int, item_value: int) -> None: """Updates given item value in heap if present""" if item not in self.pos_map: return index = self.pos_map[item] self.arr[index] = [item, self.key(item_value)] # Make sure heap is right in both up and down direction. # Ideally only one of them will make any change. self._heapify_up(index) self._heapify_down(index) def delete_item(self, item: int) -> None: """Deletes given item from heap if present""" if item not in self.pos_map: return index = self.pos_map[item] del self.pos_map[item] self.arr[index] = self.arr[self.size - 1] self.pos_map[self.arr[self.size - 1][0]] = index self.size -= 1 # Make sure heap is right in both up and down direction. Ideally only one # of them will make any change- so no performance loss in calling both. if self.size > index: self._heapify_up(index) self._heapify_down(index) def insert_item(self, item: int, item_value: int) -> None: """Inserts given item with given value in heap""" arr_len = len(self.arr) if arr_len == self.size: self.arr.append([item, self.key(item_value)]) else: self.arr[self.size] = [item, self.key(item_value)] self.pos_map[item] = self.size self.size += 1 self._heapify_up(self.size - 1) def get_top(self) -> tuple | None: """Returns top item tuple (Calculated value, item) from heap if present""" return self.arr[0] if self.size else None def extract_top(self) -> tuple | None: """ Return top item tuple (Calculated value, item) from heap and removes it as well if present """ top_item_tuple = self.get_top() if top_item_tuple: self.delete_item(top_item_tuple[0]) return top_item_tuple def test_heap() -> None: """ >>> h = Heap() # Max-heap >>> h.insert_item(5, 34) >>> h.insert_item(6, 31) >>> h.insert_item(7, 37) >>> h.get_top() [7, 37] >>> h.extract_top() [7, 37] >>> h.extract_top() [5, 34] >>> h.extract_top() [6, 31] >>> h = Heap(key=lambda x: -x) # Min heap >>> h.insert_item(5, 34) >>> h.insert_item(6, 31) >>> h.insert_item(7, 37) >>> h.get_top() [6, -31] >>> h.extract_top() [6, -31] >>> h.extract_top() [5, -34] >>> h.extract_top() [7, -37] >>> h.insert_item(8, 45) >>> h.insert_item(9, 40) >>> h.insert_item(10, 50) >>> h.get_top() [9, -40] >>> h.update_item(10, 30) >>> h.get_top() [10, -30] >>> h.delete_item(10) >>> h.get_top() [9, -40] """ pass if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Author: Abhijeeth S import math def res(x, y): if 0 not in (x, y): # We use the relation x^y = y*log10(x), where 10 is the base. return y * math.log10(x) else: if x == 0: # 0 raised to any number is 0 return 0 elif y == 0: return 1 # any number raised to 0 is 1 if __name__ == "__main__": # Main function # Read two numbers from input and typecast them to int using map function. # Here x is the base and y is the power. prompt = "Enter the base and the power separated by a comma: " x1, y1 = map(int, input(prompt).split(",")) x2, y2 = map(int, input(prompt).split(",")) # We find the log of each number, using the function res(), which takes two # arguments. res1 = res(x1, y1) res2 = res(x2, y2) # We check for the largest number if res1 > res2: print("Largest number is", x1, "^", y1) elif res2 > res1: print("Largest number is", x2, "^", y2) else: print("Both are equal")
# Author: Abhijeeth S import math def res(x, y): if 0 not in (x, y): # We use the relation x^y = y*log10(x), where 10 is the base. return y * math.log10(x) else: if x == 0: # 0 raised to any number is 0 return 0 elif y == 0: return 1 # any number raised to 0 is 1 if __name__ == "__main__": # Main function # Read two numbers from input and typecast them to int using map function. # Here x is the base and y is the power. prompt = "Enter the base and the power separated by a comma: " x1, y1 = map(int, input(prompt).split(",")) x2, y2 = map(int, input(prompt).split(",")) # We find the log of each number, using the function res(), which takes two # arguments. res1 = res(x1, y1) res2 = res(x2, y2) # We check for the largest number if res1 > res2: print("Largest number is", x1, "^", y1) elif res2 > res1: print("Largest number is", x2, "^", y2) else: print("Both are equal")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
from __future__ import annotations def modular_division(a: int, b: int, n: int) -> int: """ Modular Division : An efficient algorithm for dividing b by a modulo n. GCD ( Greatest Common Divisor ) or HCF ( Highest Common Factor ) Given three integers a, b, and n, such that gcd(a,n)=1 and n>1, the algorithm should return an integer x such that 0≤x≤n−1, and b/a=x(modn) (that is, b=ax(modn)). Theorem: a has a multiplicative inverse modulo n iff gcd(a,n) = 1 This find x = b*a^(-1) mod n Uses ExtendedEuclid to find the inverse of a >>> modular_division(4,8,5) 2 >>> modular_division(3,8,5) 1 >>> modular_division(4, 11, 5) 4 """ assert n > 1 and a > 0 and greatest_common_divisor(a, n) == 1 (d, t, s) = extended_gcd(n, a) # Implemented below x = (b * s) % n return x def invert_modulo(a: int, n: int) -> int: """ This function find the inverses of a i.e., a^(-1) >>> invert_modulo(2, 5) 3 >>> invert_modulo(8,7) 1 """ (b, x) = extended_euclid(a, n) # Implemented below if b < 0: b = (b % n + n) % n return b # ------------------ Finding Modular division using invert_modulo ------------------- def modular_division2(a: int, b: int, n: int) -> int: """ This function used the above inversion of a to find x = (b*a^(-1))mod n >>> modular_division2(4,8,5) 2 >>> modular_division2(3,8,5) 1 >>> modular_division2(4, 11, 5) 4 """ s = invert_modulo(a, n) x = (b * s) % n return x def extended_gcd(a: int, b: int) -> tuple[int, int, int]: """ Extended Euclid's Algorithm : If d divides a and b and d = a*x + b*y for integers x and y, then d = gcd(a,b) >>> extended_gcd(10, 6) (2, -1, 2) >>> extended_gcd(7, 5) (1, -2, 3) ** extended_gcd function is used when d = gcd(a,b) is required in output """ assert a >= 0 and b >= 0 if b == 0: d, x, y = a, 1, 0 else: (d, p, q) = extended_gcd(b, a % b) x = q y = p - q * (a // b) assert a % d == 0 and b % d == 0 assert d == a * x + b * y return (d, x, y) def extended_euclid(a: int, b: int) -> tuple[int, int]: """ Extended Euclid >>> extended_euclid(10, 6) (-1, 2) >>> extended_euclid(7, 5) (-2, 3) """ if b == 0: return (1, 0) (x, y) = extended_euclid(b, a % b) k = a // b return (y, x - k * y) def greatest_common_divisor(a: int, b: int) -> int: """ Euclid's Lemma : d divides a and b, if and only if d divides a-b and b Euclid's Algorithm >>> greatest_common_divisor(7,5) 1 Note : In number theory, two integers a and b are said to be relatively prime, mutually prime, or co-prime if the only positive integer (factor) that divides both of them is 1 i.e., gcd(a,b) = 1. >>> greatest_common_divisor(121, 11) 11 """ if a < b: a, b = b, a while a % b != 0: a, b = b, a % b return b if __name__ == "__main__": from doctest import testmod testmod(name="modular_division", verbose=True) testmod(name="modular_division2", verbose=True) testmod(name="invert_modulo", verbose=True) testmod(name="extended_gcd", verbose=True) testmod(name="extended_euclid", verbose=True) testmod(name="greatest_common_divisor", verbose=True)
from __future__ import annotations def modular_division(a: int, b: int, n: int) -> int: """ Modular Division : An efficient algorithm for dividing b by a modulo n. GCD ( Greatest Common Divisor ) or HCF ( Highest Common Factor ) Given three integers a, b, and n, such that gcd(a,n)=1 and n>1, the algorithm should return an integer x such that 0≤x≤n−1, and b/a=x(modn) (that is, b=ax(modn)). Theorem: a has a multiplicative inverse modulo n iff gcd(a,n) = 1 This find x = b*a^(-1) mod n Uses ExtendedEuclid to find the inverse of a >>> modular_division(4,8,5) 2 >>> modular_division(3,8,5) 1 >>> modular_division(4, 11, 5) 4 """ assert n > 1 and a > 0 and greatest_common_divisor(a, n) == 1 (d, t, s) = extended_gcd(n, a) # Implemented below x = (b * s) % n return x def invert_modulo(a: int, n: int) -> int: """ This function find the inverses of a i.e., a^(-1) >>> invert_modulo(2, 5) 3 >>> invert_modulo(8,7) 1 """ (b, x) = extended_euclid(a, n) # Implemented below if b < 0: b = (b % n + n) % n return b # ------------------ Finding Modular division using invert_modulo ------------------- def modular_division2(a: int, b: int, n: int) -> int: """ This function used the above inversion of a to find x = (b*a^(-1))mod n >>> modular_division2(4,8,5) 2 >>> modular_division2(3,8,5) 1 >>> modular_division2(4, 11, 5) 4 """ s = invert_modulo(a, n) x = (b * s) % n return x def extended_gcd(a: int, b: int) -> tuple[int, int, int]: """ Extended Euclid's Algorithm : If d divides a and b and d = a*x + b*y for integers x and y, then d = gcd(a,b) >>> extended_gcd(10, 6) (2, -1, 2) >>> extended_gcd(7, 5) (1, -2, 3) ** extended_gcd function is used when d = gcd(a,b) is required in output """ assert a >= 0 and b >= 0 if b == 0: d, x, y = a, 1, 0 else: (d, p, q) = extended_gcd(b, a % b) x = q y = p - q * (a // b) assert a % d == 0 and b % d == 0 assert d == a * x + b * y return (d, x, y) def extended_euclid(a: int, b: int) -> tuple[int, int]: """ Extended Euclid >>> extended_euclid(10, 6) (-1, 2) >>> extended_euclid(7, 5) (-2, 3) """ if b == 0: return (1, 0) (x, y) = extended_euclid(b, a % b) k = a // b return (y, x - k * y) def greatest_common_divisor(a: int, b: int) -> int: """ Euclid's Lemma : d divides a and b, if and only if d divides a-b and b Euclid's Algorithm >>> greatest_common_divisor(7,5) 1 Note : In number theory, two integers a and b are said to be relatively prime, mutually prime, or co-prime if the only positive integer (factor) that divides both of them is 1 i.e., gcd(a,b) = 1. >>> greatest_common_divisor(121, 11) 11 """ if a < b: a, b = b, a while a % b != 0: a, b = b, a % b return b if __name__ == "__main__": from doctest import testmod testmod(name="modular_division", verbose=True) testmod(name="modular_division2", verbose=True) testmod(name="invert_modulo", verbose=True) testmod(name="extended_gcd", verbose=True) testmod(name="extended_euclid", verbose=True) testmod(name="greatest_common_divisor", verbose=True)
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
import cv2 import numpy as np """ Harris Corner Detector https://en.wikipedia.org/wiki/Harris_Corner_Detector """ class HarrisCorner: def __init__(self, k: float, window_size: int): """ k : is an empirically determined constant in [0.04,0.06] window_size : neighbourhoods considered """ if k in (0.04, 0.06): self.k = k self.window_size = window_size else: raise ValueError("invalid k value") def __str__(self) -> str: return f"Harris Corner detection with k : {self.k}" def detect(self, img_path: str) -> tuple[cv2.Mat, list[list[int]]]: """ Returns the image with corners identified img_path : path of the image output : list of the corner positions, image """ img = cv2.imread(img_path, 0) h, w = img.shape corner_list: list[list[int]] = [] color_img = img.copy() color_img = cv2.cvtColor(color_img, cv2.COLOR_GRAY2RGB) dy, dx = np.gradient(img) ixx = dx**2 iyy = dy**2 ixy = dx * dy k = 0.04 offset = self.window_size // 2 for y in range(offset, h - offset): for x in range(offset, w - offset): wxx = ixx[ y - offset : y + offset + 1, x - offset : x + offset + 1 ].sum() wyy = iyy[ y - offset : y + offset + 1, x - offset : x + offset + 1 ].sum() wxy = ixy[ y - offset : y + offset + 1, x - offset : x + offset + 1 ].sum() det = (wxx * wyy) - (wxy**2) trace = wxx + wyy r = det - k * (trace**2) # Can change the value if r > 0.5: corner_list.append([x, y, r]) color_img.itemset((y, x, 0), 0) color_img.itemset((y, x, 1), 0) color_img.itemset((y, x, 2), 255) return color_img, corner_list if __name__ == "__main__": edge_detect = HarrisCorner(0.04, 3) color_img, _ = edge_detect.detect("path_to_image") cv2.imwrite("detect.png", color_img)
import cv2 import numpy as np """ Harris Corner Detector https://en.wikipedia.org/wiki/Harris_Corner_Detector """ class HarrisCorner: def __init__(self, k: float, window_size: int): """ k : is an empirically determined constant in [0.04,0.06] window_size : neighbourhoods considered """ if k in (0.04, 0.06): self.k = k self.window_size = window_size else: raise ValueError("invalid k value") def __str__(self) -> str: return f"Harris Corner detection with k : {self.k}" def detect(self, img_path: str) -> tuple[cv2.Mat, list[list[int]]]: """ Returns the image with corners identified img_path : path of the image output : list of the corner positions, image """ img = cv2.imread(img_path, 0) h, w = img.shape corner_list: list[list[int]] = [] color_img = img.copy() color_img = cv2.cvtColor(color_img, cv2.COLOR_GRAY2RGB) dy, dx = np.gradient(img) ixx = dx**2 iyy = dy**2 ixy = dx * dy k = 0.04 offset = self.window_size // 2 for y in range(offset, h - offset): for x in range(offset, w - offset): wxx = ixx[ y - offset : y + offset + 1, x - offset : x + offset + 1 ].sum() wyy = iyy[ y - offset : y + offset + 1, x - offset : x + offset + 1 ].sum() wxy = ixy[ y - offset : y + offset + 1, x - offset : x + offset + 1 ].sum() det = (wxx * wyy) - (wxy**2) trace = wxx + wyy r = det - k * (trace**2) # Can change the value if r > 0.5: corner_list.append([x, y, r]) color_img.itemset((y, x, 0), 0) color_img.itemset((y, x, 1), 0) color_img.itemset((y, x, 2), 255) return color_img, corner_list if __name__ == "__main__": edge_detect = HarrisCorner(0.04, 3) color_img, _ = edge_detect.detect("path_to_image") cv2.imwrite("detect.png", color_img)
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Compression Data compression is everywhere, you need it to store data without taking too much space. Either the compression lose some data (then we talk about lossy compression, such as .jpg) or it does not (and then it is lossless compression, such as .png) Lossless compression is mainly used for archive purpose as it allow storing data without losing information about the file archived. On the other hand, lossy compression is used for transfer of file where quality isn't necessarily what is required (i.e: images on Twitter). * <https://www.sciencedirect.com/topics/computer-science/compression-algorithm> * <https://en.wikipedia.org/wiki/Data_compression> * <https://en.wikipedia.org/wiki/Pigeonhole_principle>
# Compression Data compression is everywhere, you need it to store data without taking too much space. Either the compression lose some data (then we talk about lossy compression, such as .jpg) or it does not (and then it is lossless compression, such as .png) Lossless compression is mainly used for archive purpose as it allow storing data without losing information about the file archived. On the other hand, lossy compression is used for transfer of file where quality isn't necessarily what is required (i.e: images on Twitter). * <https://www.sciencedirect.com/topics/computer-science/compression-algorithm> * <https://en.wikipedia.org/wiki/Data_compression> * <https://en.wikipedia.org/wiki/Pigeonhole_principle>
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 2: https://projecteuler.net/problem=2 Even Fibonacci Numbers Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-valued terms. References: - https://en.wikipedia.org/wiki/Fibonacci_number """ import math from decimal import Decimal, getcontext def solution(n: int = 4000000) -> int: """ Returns the sum of all even fibonacci sequence elements that are lower or equal to n. >>> solution(10) 10 >>> solution(15) 10 >>> solution(2) 2 >>> solution(1) 0 >>> solution(34) 44 >>> solution(3.4) 2 >>> solution(0) Traceback (most recent call last): ... ValueError: Parameter n must be greater than or equal to one. >>> solution(-17) Traceback (most recent call last): ... ValueError: Parameter n must be greater than or equal to one. >>> solution([]) Traceback (most recent call last): ... TypeError: Parameter n must be int or castable to int. >>> solution("asd") Traceback (most recent call last): ... TypeError: Parameter n must be int or castable to int. """ try: n = int(n) except (TypeError, ValueError): raise TypeError("Parameter n must be int or castable to int.") if n <= 0: raise ValueError("Parameter n must be greater than or equal to one.") getcontext().prec = 100 phi = (Decimal(5) ** Decimal(0.5) + 1) / Decimal(2) index = (math.floor(math.log(n * (phi + 2), phi) - 1) // 3) * 3 + 2 num = Decimal(round(phi ** Decimal(index + 1))) / (phi + 2) total = num // 2 return int(total) if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 2: https://projecteuler.net/problem=2 Even Fibonacci Numbers Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-valued terms. References: - https://en.wikipedia.org/wiki/Fibonacci_number """ import math from decimal import Decimal, getcontext def solution(n: int = 4000000) -> int: """ Returns the sum of all even fibonacci sequence elements that are lower or equal to n. >>> solution(10) 10 >>> solution(15) 10 >>> solution(2) 2 >>> solution(1) 0 >>> solution(34) 44 >>> solution(3.4) 2 >>> solution(0) Traceback (most recent call last): ... ValueError: Parameter n must be greater than or equal to one. >>> solution(-17) Traceback (most recent call last): ... ValueError: Parameter n must be greater than or equal to one. >>> solution([]) Traceback (most recent call last): ... TypeError: Parameter n must be int or castable to int. >>> solution("asd") Traceback (most recent call last): ... TypeError: Parameter n must be int or castable to int. """ try: n = int(n) except (TypeError, ValueError): raise TypeError("Parameter n must be int or castable to int.") if n <= 0: raise ValueError("Parameter n must be greater than or equal to one.") getcontext().prec = 100 phi = (Decimal(5) ** Decimal(0.5) + 1) / Decimal(2) index = (math.floor(math.log(n * (phi + 2), phi) - 1) // 3) * 3 + 2 num = Decimal(round(phi ** Decimal(index + 1))) / (phi + 2) total = num // 2 return int(total) if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Problem 78 Url: https://projecteuler.net/problem=78 Statement: Let p(n) represent the number of different ways in which n coins can be separated into piles. For example, five coins can be separated into piles in exactly seven different ways, so p(5)=7. OOOOO OOOO O OOO OO OOO O O OO OO O OO O O O O O O O O Find the least value of n for which p(n) is divisible by one million. """ import itertools def solution(number: int = 1000000) -> int: """ >>> solution(1) 1 >>> solution(9) 14 >>> solution() 55374 """ partitions = [1] for i in itertools.count(len(partitions)): item = 0 for j in itertools.count(1): sign = -1 if j % 2 == 0 else +1 index = (j * j * 3 - j) // 2 if index > i: break item += partitions[i - index] * sign item %= number index += j if index > i: break item += partitions[i - index] * sign item %= number if item == 0: return i partitions.append(item) return 0 if __name__ == "__main__": import doctest doctest.testmod() print(f"{solution() = }")
""" Problem 78 Url: https://projecteuler.net/problem=78 Statement: Let p(n) represent the number of different ways in which n coins can be separated into piles. For example, five coins can be separated into piles in exactly seven different ways, so p(5)=7. OOOOO OOOO O OOO OO OOO O O OO OO O OO O O O O O O O O Find the least value of n for which p(n) is divisible by one million. """ import itertools def solution(number: int = 1000000) -> int: """ >>> solution(1) 1 >>> solution(9) 14 >>> solution() 55374 """ partitions = [1] for i in itertools.count(len(partitions)): item = 0 for j in itertools.count(1): sign = -1 if j % 2 == 0 else +1 index = (j * j * 3 - j) // 2 if index > i: break item += partitions[i - index] * sign item %= number index += j if index > i: break item += partitions[i - index] * sign item %= number if item == 0: return i partitions.append(item) return 0 if __name__ == "__main__": import doctest doctest.testmod() print(f"{solution() = }")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Description : Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased. Source: https://www.physicsclassroom.com/class/newtlaws/Lesson-3/Newton-s-Second-Law Formulation: Fnet = m • a Diagrammatic Explanation: Forces are unbalanced | | | V There is acceleration /\ / \ / \ / \ / \ / \ / \ __________________ ____ ________________ |The acceleration | |The acceleration | |depends directly | |depends inversely | |on the net Force | |upon the object's | |_________________| |mass_______________| Units: 1 Newton = 1 kg X meters / (seconds^2) How to use? Inputs: ___________________________________________________ |Name | Units | Type | |-------------|-------------------------|-----------| |mass | (in kgs) | float | |-------------|-------------------------|-----------| |acceleration | (in meters/(seconds^2)) | float | |_____________|_________________________|___________| Output: ___________________________________________________ |Name | Units | Type | |-------------|-------------------------|-----------| |force | (in Newtons) | float | |_____________|_________________________|___________| """ def newtons_second_law_of_motion(mass: float, acceleration: float) -> float: """ >>> newtons_second_law_of_motion(10, 10) 100 >>> newtons_second_law_of_motion(2.0, 1) 2.0 """ force = float() try: force = mass * acceleration except Exception: return -0.0 return force if __name__ == "__main__": import doctest # run doctest doctest.testmod() # demo mass = 12.5 acceleration = 10 force = newtons_second_law_of_motion(mass, acceleration) print("The force is ", force, "N")
""" Description : Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased. Source: https://www.physicsclassroom.com/class/newtlaws/Lesson-3/Newton-s-Second-Law Formulation: Fnet = m • a Diagrammatic Explanation: Forces are unbalanced | | | V There is acceleration /\ / \ / \ / \ / \ / \ / \ __________________ ____ ________________ |The acceleration | |The acceleration | |depends directly | |depends inversely | |on the net Force | |upon the object's | |_________________| |mass_______________| Units: 1 Newton = 1 kg X meters / (seconds^2) How to use? Inputs: ___________________________________________________ |Name | Units | Type | |-------------|-------------------------|-----------| |mass | (in kgs) | float | |-------------|-------------------------|-----------| |acceleration | (in meters/(seconds^2)) | float | |_____________|_________________________|___________| Output: ___________________________________________________ |Name | Units | Type | |-------------|-------------------------|-----------| |force | (in Newtons) | float | |_____________|_________________________|___________| """ def newtons_second_law_of_motion(mass: float, acceleration: float) -> float: """ >>> newtons_second_law_of_motion(10, 10) 100 >>> newtons_second_law_of_motion(2.0, 1) 2.0 """ force = float() try: force = mass * acceleration except Exception: return -0.0 return force if __name__ == "__main__": import doctest # run doctest doctest.testmod() # demo mass = 12.5 acceleration = 10 force = newtons_second_law_of_motion(mass, acceleration) print("The force is ", force, "N")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 129: https://projecteuler.net/problem=129 A number consisting entirely of ones is called a repunit. We shall define R(k) to be a repunit of length k; for example, R(6) = 111111. Given that n is a positive integer and GCD(n, 10) = 1, it can be shown that there always exists a value, k, for which R(k) is divisible by n, and let A(n) be the least such value of k; for example, A(7) = 6 and A(41) = 5. The least value of n for which A(n) first exceeds ten is 17. Find the least value of n for which A(n) first exceeds one-million. """ def least_divisible_repunit(divisor: int) -> int: """ Return the least value k such that the Repunit of length k is divisible by divisor. >>> least_divisible_repunit(7) 6 >>> least_divisible_repunit(41) 5 >>> least_divisible_repunit(1234567) 34020 """ if divisor % 5 == 0 or divisor % 2 == 0: return 0 repunit = 1 repunit_index = 1 while repunit: repunit = (10 * repunit + 1) % divisor repunit_index += 1 return repunit_index def solution(limit: int = 1000000) -> int: """ Return the least value of n for which least_divisible_repunit(n) first exceeds limit. >>> solution(10) 17 >>> solution(100) 109 >>> solution(1000) 1017 """ divisor = limit - 1 if divisor % 2 == 0: divisor += 1 while least_divisible_repunit(divisor) <= limit: divisor += 2 return divisor if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 129: https://projecteuler.net/problem=129 A number consisting entirely of ones is called a repunit. We shall define R(k) to be a repunit of length k; for example, R(6) = 111111. Given that n is a positive integer and GCD(n, 10) = 1, it can be shown that there always exists a value, k, for which R(k) is divisible by n, and let A(n) be the least such value of k; for example, A(7) = 6 and A(41) = 5. The least value of n for which A(n) first exceeds ten is 17. Find the least value of n for which A(n) first exceeds one-million. """ def least_divisible_repunit(divisor: int) -> int: """ Return the least value k such that the Repunit of length k is divisible by divisor. >>> least_divisible_repunit(7) 6 >>> least_divisible_repunit(41) 5 >>> least_divisible_repunit(1234567) 34020 """ if divisor % 5 == 0 or divisor % 2 == 0: return 0 repunit = 1 repunit_index = 1 while repunit: repunit = (10 * repunit + 1) % divisor repunit_index += 1 return repunit_index def solution(limit: int = 1000000) -> int: """ Return the least value of n for which least_divisible_repunit(n) first exceeds limit. >>> solution(10) 17 >>> solution(100) 109 >>> solution(1000) 1017 """ divisor = limit - 1 if divisor % 2 == 0: divisor += 1 while least_divisible_repunit(divisor) <= limit: divisor += 2 return divisor if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" * Author: Manuel Di Lullo (https://github.com/manueldilullo) * Description: Random graphs generator. Uses graphs represented with an adjacency list. URL: https://en.wikipedia.org/wiki/Random_graph """ import random def random_graph( vertices_number: int, probability: float, directed: bool = False ) -> dict: """ Generate a random graph @input: vertices_number (number of vertices), probability (probability that a generic edge (u,v) exists), directed (if True: graph will be a directed graph, otherwise it will be an undirected graph) @examples: >>> random.seed(1) >>> random_graph(4, 0.5) {0: [1], 1: [0, 2, 3], 2: [1, 3], 3: [1, 2]} >>> random.seed(1) >>> random_graph(4, 0.5, True) {0: [1], 1: [2, 3], 2: [3], 3: []} """ graph: dict = {i: [] for i in range(vertices_number)} # if probability is greater or equal than 1, then generate a complete graph if probability >= 1: return complete_graph(vertices_number) # if probability is lower or equal than 0, then return a graph without edges if probability <= 0: return graph # for each couple of nodes, add an edge from u to v # if the number randomly generated is greater than probability probability for i in range(vertices_number): for j in range(i + 1, vertices_number): if random.random() < probability: graph[i].append(j) if not directed: # if the graph is undirected, add an edge in from j to i, either graph[j].append(i) return graph def complete_graph(vertices_number: int) -> dict: """ Generate a complete graph with vertices_number vertices. @input: vertices_number (number of vertices), directed (False if the graph is undirected, True otherwise) @example: >>> print(complete_graph(3)) {0: [1, 2], 1: [0, 2], 2: [0, 1]} """ return { i: [j for j in range(vertices_number) if i != j] for i in range(vertices_number) } if __name__ == "__main__": import doctest doctest.testmod()
""" * Author: Manuel Di Lullo (https://github.com/manueldilullo) * Description: Random graphs generator. Uses graphs represented with an adjacency list. URL: https://en.wikipedia.org/wiki/Random_graph """ import random def random_graph( vertices_number: int, probability: float, directed: bool = False ) -> dict: """ Generate a random graph @input: vertices_number (number of vertices), probability (probability that a generic edge (u,v) exists), directed (if True: graph will be a directed graph, otherwise it will be an undirected graph) @examples: >>> random.seed(1) >>> random_graph(4, 0.5) {0: [1], 1: [0, 2, 3], 2: [1, 3], 3: [1, 2]} >>> random.seed(1) >>> random_graph(4, 0.5, True) {0: [1], 1: [2, 3], 2: [3], 3: []} """ graph: dict = {i: [] for i in range(vertices_number)} # if probability is greater or equal than 1, then generate a complete graph if probability >= 1: return complete_graph(vertices_number) # if probability is lower or equal than 0, then return a graph without edges if probability <= 0: return graph # for each couple of nodes, add an edge from u to v # if the number randomly generated is greater than probability probability for i in range(vertices_number): for j in range(i + 1, vertices_number): if random.random() < probability: graph[i].append(j) if not directed: # if the graph is undirected, add an edge in from j to i, either graph[j].append(i) return graph def complete_graph(vertices_number: int) -> dict: """ Generate a complete graph with vertices_number vertices. @input: vertices_number (number of vertices), directed (False if the graph is undirected, True otherwise) @example: >>> print(complete_graph(3)) {0: [1, 2], 1: [0, 2], 2: [0, 1]} """ return { i: [j for j in range(vertices_number) if i != j] for i in range(vertices_number) } if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
B64_CHARSET = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/" def base64_encode(data: bytes) -> bytes: """Encodes data according to RFC4648. The data is first transformed to binary and appended with binary digits so that its length becomes a multiple of 6, then each 6 binary digits will match a character in the B64_CHARSET string. The number of appended binary digits would later determine how many "=" signs should be added, the padding. For every 2 binary digits added, a "=" sign is added in the output. We can add any binary digits to make it a multiple of 6, for instance, consider the following example: "AA" -> 0010100100101001 -> 001010 010010 1001 As can be seen above, 2 more binary digits should be added, so there's 4 possibilities here: 00, 01, 10 or 11. That being said, Base64 encoding can be used in Steganography to hide data in these appended digits. >>> from base64 import b64encode >>> a = b"This pull request is part of Hacktoberfest20!" >>> b = b"https://tools.ietf.org/html/rfc4648" >>> c = b"A" >>> base64_encode(a) == b64encode(a) True >>> base64_encode(b) == b64encode(b) True >>> base64_encode(c) == b64encode(c) True >>> base64_encode("abc") Traceback (most recent call last): ... TypeError: a bytes-like object is required, not 'str' """ # Make sure the supplied data is a bytes-like object if not isinstance(data, bytes): raise TypeError( f"a bytes-like object is required, not '{data.__class__.__name__}'" ) binary_stream = "".join(bin(byte)[2:].zfill(8) for byte in data) padding_needed = len(binary_stream) % 6 != 0 if padding_needed: # The padding that will be added later padding = b"=" * ((6 - len(binary_stream) % 6) // 2) # Append binary_stream with arbitrary binary digits (0's by default) to make its # length a multiple of 6. binary_stream += "0" * (6 - len(binary_stream) % 6) else: padding = b"" # Encode every 6 binary digits to their corresponding Base64 character return ( "".join( B64_CHARSET[int(binary_stream[index : index + 6], 2)] for index in range(0, len(binary_stream), 6) ).encode() + padding ) def base64_decode(encoded_data: str) -> bytes: """Decodes data according to RFC4648. This does the reverse operation of base64_encode. We first transform the encoded data back to a binary stream, take off the previously appended binary digits according to the padding, at this point we would have a binary stream whose length is multiple of 8, the last step is to convert every 8 bits to a byte. >>> from base64 import b64decode >>> a = "VGhpcyBwdWxsIHJlcXVlc3QgaXMgcGFydCBvZiBIYWNrdG9iZXJmZXN0MjAh" >>> b = "aHR0cHM6Ly90b29scy5pZXRmLm9yZy9odG1sL3JmYzQ2NDg=" >>> c = "QQ==" >>> base64_decode(a) == b64decode(a) True >>> base64_decode(b) == b64decode(b) True >>> base64_decode(c) == b64decode(c) True >>> base64_decode("abc") Traceback (most recent call last): ... AssertionError: Incorrect padding """ # Make sure encoded_data is either a string or a bytes-like object if not isinstance(encoded_data, bytes) and not isinstance(encoded_data, str): raise TypeError( "argument should be a bytes-like object or ASCII string, not " f"'{encoded_data.__class__.__name__}'" ) # In case encoded_data is a bytes-like object, make sure it contains only # ASCII characters so we convert it to a string object if isinstance(encoded_data, bytes): try: encoded_data = encoded_data.decode("utf-8") except UnicodeDecodeError: raise ValueError("base64 encoded data should only contain ASCII characters") padding = encoded_data.count("=") # Check if the encoded string contains non base64 characters if padding: assert all( char in B64_CHARSET for char in encoded_data[:-padding] ), "Invalid base64 character(s) found." else: assert all( char in B64_CHARSET for char in encoded_data ), "Invalid base64 character(s) found." # Check the padding assert len(encoded_data) % 4 == 0 and padding < 3, "Incorrect padding" if padding: # Remove padding if there is one encoded_data = encoded_data[:-padding] binary_stream = "".join( bin(B64_CHARSET.index(char))[2:].zfill(6) for char in encoded_data )[: -padding * 2] else: binary_stream = "".join( bin(B64_CHARSET.index(char))[2:].zfill(6) for char in encoded_data ) data = [ int(binary_stream[index : index + 8], 2) for index in range(0, len(binary_stream), 8) ] return bytes(data) if __name__ == "__main__": import doctest doctest.testmod()
B64_CHARSET = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/" def base64_encode(data: bytes) -> bytes: """Encodes data according to RFC4648. The data is first transformed to binary and appended with binary digits so that its length becomes a multiple of 6, then each 6 binary digits will match a character in the B64_CHARSET string. The number of appended binary digits would later determine how many "=" signs should be added, the padding. For every 2 binary digits added, a "=" sign is added in the output. We can add any binary digits to make it a multiple of 6, for instance, consider the following example: "AA" -> 0010100100101001 -> 001010 010010 1001 As can be seen above, 2 more binary digits should be added, so there's 4 possibilities here: 00, 01, 10 or 11. That being said, Base64 encoding can be used in Steganography to hide data in these appended digits. >>> from base64 import b64encode >>> a = b"This pull request is part of Hacktoberfest20!" >>> b = b"https://tools.ietf.org/html/rfc4648" >>> c = b"A" >>> base64_encode(a) == b64encode(a) True >>> base64_encode(b) == b64encode(b) True >>> base64_encode(c) == b64encode(c) True >>> base64_encode("abc") Traceback (most recent call last): ... TypeError: a bytes-like object is required, not 'str' """ # Make sure the supplied data is a bytes-like object if not isinstance(data, bytes): raise TypeError( f"a bytes-like object is required, not '{data.__class__.__name__}'" ) binary_stream = "".join(bin(byte)[2:].zfill(8) for byte in data) padding_needed = len(binary_stream) % 6 != 0 if padding_needed: # The padding that will be added later padding = b"=" * ((6 - len(binary_stream) % 6) // 2) # Append binary_stream with arbitrary binary digits (0's by default) to make its # length a multiple of 6. binary_stream += "0" * (6 - len(binary_stream) % 6) else: padding = b"" # Encode every 6 binary digits to their corresponding Base64 character return ( "".join( B64_CHARSET[int(binary_stream[index : index + 6], 2)] for index in range(0, len(binary_stream), 6) ).encode() + padding ) def base64_decode(encoded_data: str) -> bytes: """Decodes data according to RFC4648. This does the reverse operation of base64_encode. We first transform the encoded data back to a binary stream, take off the previously appended binary digits according to the padding, at this point we would have a binary stream whose length is multiple of 8, the last step is to convert every 8 bits to a byte. >>> from base64 import b64decode >>> a = "VGhpcyBwdWxsIHJlcXVlc3QgaXMgcGFydCBvZiBIYWNrdG9iZXJmZXN0MjAh" >>> b = "aHR0cHM6Ly90b29scy5pZXRmLm9yZy9odG1sL3JmYzQ2NDg=" >>> c = "QQ==" >>> base64_decode(a) == b64decode(a) True >>> base64_decode(b) == b64decode(b) True >>> base64_decode(c) == b64decode(c) True >>> base64_decode("abc") Traceback (most recent call last): ... AssertionError: Incorrect padding """ # Make sure encoded_data is either a string or a bytes-like object if not isinstance(encoded_data, bytes) and not isinstance(encoded_data, str): raise TypeError( "argument should be a bytes-like object or ASCII string, not " f"'{encoded_data.__class__.__name__}'" ) # In case encoded_data is a bytes-like object, make sure it contains only # ASCII characters so we convert it to a string object if isinstance(encoded_data, bytes): try: encoded_data = encoded_data.decode("utf-8") except UnicodeDecodeError: raise ValueError("base64 encoded data should only contain ASCII characters") padding = encoded_data.count("=") # Check if the encoded string contains non base64 characters if padding: assert all( char in B64_CHARSET for char in encoded_data[:-padding] ), "Invalid base64 character(s) found." else: assert all( char in B64_CHARSET for char in encoded_data ), "Invalid base64 character(s) found." # Check the padding assert len(encoded_data) % 4 == 0 and padding < 3, "Incorrect padding" if padding: # Remove padding if there is one encoded_data = encoded_data[:-padding] binary_stream = "".join( bin(B64_CHARSET.index(char))[2:].zfill(6) for char in encoded_data )[: -padding * 2] else: binary_stream = "".join( bin(B64_CHARSET.index(char))[2:].zfill(6) for char in encoded_data ) data = [ int(binary_stream[index : index + 8], 2) for index in range(0, len(binary_stream), 8) ] return bytes(data) if __name__ == "__main__": import doctest doctest.testmod()
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
""" Project Euler Problem 1: https://projecteuler.net/problem=1 Multiples of 3 and 5 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. """ def solution(n: int = 1000) -> int: """ This solution is based on the pattern that the successive numbers in the series follow: 0+3,+2,+1,+3,+1,+2,+3. Returns the sum of all the multiples of 3 or 5 below n. >>> solution(3) 0 >>> solution(4) 3 >>> solution(10) 23 >>> solution(600) 83700 """ total = 0 num = 0 while 1: num += 3 if num >= n: break total += num num += 2 if num >= n: break total += num num += 1 if num >= n: break total += num num += 3 if num >= n: break total += num num += 1 if num >= n: break total += num num += 2 if num >= n: break total += num num += 3 if num >= n: break total += num return total if __name__ == "__main__": print(f"{solution() = }")
""" Project Euler Problem 1: https://projecteuler.net/problem=1 Multiples of 3 and 5 If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. """ def solution(n: int = 1000) -> int: """ This solution is based on the pattern that the successive numbers in the series follow: 0+3,+2,+1,+3,+1,+2,+3. Returns the sum of all the multiples of 3 or 5 below n. >>> solution(3) 0 >>> solution(4) 3 >>> solution(10) 23 >>> solution(600) 83700 """ total = 0 num = 0 while 1: num += 3 if num >= n: break total += num num += 2 if num >= n: break total += num num += 1 if num >= n: break total += num num += 3 if num >= n: break total += num num += 1 if num >= n: break total += num num += 2 if num >= n: break total += num num += 3 if num >= n: break total += num return total if __name__ == "__main__": print(f"{solution() = }")
-1
TheAlgorithms/Python
7,338
Add `flake8-broken-line` to `pre-commit`
### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
CaedenPH
"2022-10-16T19:46:34Z"
"2022-10-16T19:50:48Z"
b5b1eb2f00f942955217ef6968fe8016476690ba
6d20e2b750839d978873f6a89ce6d844ba3cc0b8
Add `flake8-broken-line` to `pre-commit`. ### Describe your change: Add `flake8-broken-line` to `pre-commit` and fix errors * [ ] Add an algorithm? * [x] Fix a bug or typo in an existing algorithm? * [ ] Documentation change? ### Checklist: * [x] I have read [CONTRIBUTING.md](https://github.com/TheAlgorithms/Python/blob/master/CONTRIBUTING.md). * [x] This pull request is all my own work -- I have not plagiarized. * [x] I know that pull requests will not be merged if they fail the automated tests. * [x] This PR only changes one algorithm file. To ease review, please open separate PRs for separate algorithms. * [x] All new Python files are placed inside an existing directory. * [x] All filenames are in all lowercase characters with no spaces or dashes. * [x] All functions and variable names follow Python naming conventions. * [x] All function parameters and return values are annotated with Python [type hints](https://docs.python.org/3/library/typing.html). * [x] All functions have [doctests](https://docs.python.org/3/library/doctest.html) that pass the automated testing. * [x] All new algorithms have a URL in its comments that points to Wikipedia or other similar explanation. * [x] If this pull request resolves one or more open issues then the commit message contains `Fixes: #{$ISSUE_NO}`.
# Finding longest distance in Directed Acyclic Graph using KahnsAlgorithm def longest_distance(graph): indegree = [0] * len(graph) queue = [] long_dist = [1] * len(graph) for values in graph.values(): for i in values: indegree[i] += 1 for i in range(len(indegree)): if indegree[i] == 0: queue.append(i) while queue: vertex = queue.pop(0) for x in graph[vertex]: indegree[x] -= 1 if long_dist[vertex] + 1 > long_dist[x]: long_dist[x] = long_dist[vertex] + 1 if indegree[x] == 0: queue.append(x) print(max(long_dist)) # Adjacency list of Graph graph = {0: [2, 3, 4], 1: [2, 7], 2: [5], 3: [5, 7], 4: [7], 5: [6], 6: [7], 7: []} longest_distance(graph)
# Finding longest distance in Directed Acyclic Graph using KahnsAlgorithm def longest_distance(graph): indegree = [0] * len(graph) queue = [] long_dist = [1] * len(graph) for values in graph.values(): for i in values: indegree[i] += 1 for i in range(len(indegree)): if indegree[i] == 0: queue.append(i) while queue: vertex = queue.pop(0) for x in graph[vertex]: indegree[x] -= 1 if long_dist[vertex] + 1 > long_dist[x]: long_dist[x] = long_dist[vertex] + 1 if indegree[x] == 0: queue.append(x) print(max(long_dist)) # Adjacency list of Graph graph = {0: [2, 3, 4], 1: [2, 7], 2: [5], 3: [5, 7], 4: [7], 5: [6], 6: [7], 7: []} longest_distance(graph)
-1