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pythondev
help
better yet: `if not (isinstance(x, list) or isinstance(y, list))`
2017-07-24T15:58:50.886105
Beula
pythondev_help_Beula_2017-07-24T15:58:50.886105
1,500,911,930.886105
87,003
pythondev
help
flipping beween JS and python
2017-07-24T15:58:56.889102
Meg
pythondev_help_Meg_2017-07-24T15:58:56.889102
1,500,911,936.889102
87,004
pythondev
help
`WHAT LANGUAGE AM I IN???`
2017-07-24T15:59:14.898555
Meg
pythondev_help_Meg_2017-07-24T15:59:14.898555
1,500,911,954.898555
87,005
pythondev
help
is how I feel sometimes
2017-07-24T15:59:20.901927
Meg
pythondev_help_Meg_2017-07-24T15:59:20.901927
1,500,911,960.901927
87,006
pythondev
help
but say I have a conditional `if` can I grab which of the conditions caused the if to not go through in a single line?
2017-07-24T15:59:28.905788
Myong
pythondev_help_Myong_2017-07-24T15:59:28.905788
1,500,911,968.905788
87,007
pythondev
help
I can always just chain a bunch of `if`'s
2017-07-24T15:59:48.916855
Myong
pythondev_help_Myong_2017-07-24T15:59:48.916855
1,500,911,988.916855
87,008
pythondev
help
no, there's really no way to evaluate which conditional breaks the entry
2017-07-24T16:00:20.934129
Meg
pythondev_help_Meg_2017-07-24T16:00:20.934129
1,500,912,020.934129
87,009
pythondev
help
same is true for java/c#, I believe
2017-07-24T16:00:38.945187
Meg
pythondev_help_Meg_2017-07-24T16:00:38.945187
1,500,912,038.945187
87,010
pythondev
help
You could do `next(x for x in [x, y] if not isinstance(x, list))`
2017-07-24T16:00:42.946903
Beula
pythondev_help_Beula_2017-07-24T16:00:42.946903
1,500,912,042.946903
87,011
pythondev
help
I'd just do the `if/elif` though myself
2017-07-24T16:01:09.962150
Beula
pythondev_help_Beula_2017-07-24T16:01:09.962150
1,500,912,069.96215
87,012
pythondev
help
yeah
2017-07-24T16:01:18.967108
Myong
pythondev_help_Myong_2017-07-24T16:01:18.967108
1,500,912,078.967108
87,013
pythondev
help
Is there anyone here able to help me out with learning XMPP with sleekxmpp in particular?
2017-07-24T16:04:47.079653
Lynn
pythondev_help_Lynn_2017-07-24T16:04:47.079653
1,500,912,287.079653
87,014
pythondev
help
Essentially just trying to add two lists if they exist, if not, make the output 0, if they both do, sum them, if one does, figure out which one does
2017-07-24T16:06:08.122186
Myong
pythondev_help_Myong_2017-07-24T16:06:08.122186
1,500,912,368.122186
87,015
pythondev
help
<@Lynn> - you usually get better answers if you ask specific questions
2017-07-24T16:11:46.297883
Beula
pythondev_help_Beula_2017-07-24T16:11:46.297883
1,500,912,706.297883
87,016
pythondev
help
<@Beula> noted
2017-07-24T16:12:08.309056
Lynn
pythondev_help_Lynn_2017-07-24T16:12:08.309056
1,500,912,728.309056
87,017
pythondev
help
Is it possible to add a conditional to this sorted statement `sorted_list = sorted(dictionary.keys(), key=lambda x: dictionary[x].get('key1'))`? Sometimes key1 may return a value of `None`.
2017-07-24T16:32:39.952877
Johnetta
pythondev_help_Johnetta_2017-07-24T16:32:39.952877
1,500,913,959.952877
87,018
pythondev
help
<@Johnetta>, if your conditional is simple, you may be able to add as a second arg to `.get('key1', return something here)`
2017-07-24T16:38:58.149183
Winnifred
pythondev_help_Winnifred_2017-07-24T16:38:58.149183
1,500,914,338.149183
87,019
pythondev
help
<@Winnifred> Thanks, I dabbled with returning default values. However it adds an extraneous value to the key. For instance, I'm trying to sort a dictionary based on dates. If the dictionary item does not have a date I'd like for it to be sorted to the end of the list, but not add a date.
2017-07-24T16:42:27.255950
Johnetta
pythondev_help_Johnetta_2017-07-24T16:42:27.255950
1,500,914,547.25595
87,020
pythondev
help
So the default value I would be adding to keys without a date would be an erroneous date. I'd like for them to remain "None". If that makes sense.
2017-07-24T16:43:15.281201
Johnetta
pythondev_help_Johnetta_2017-07-24T16:43:15.281201
1,500,914,595.281201
87,021
pythondev
help
As is I can't sort `TypeError: can't compare datetime.datetime to NoneType`
2017-07-24T16:44:46.328722
Johnetta
pythondev_help_Johnetta_2017-07-24T16:44:46.328722
1,500,914,686.328722
87,022
pythondev
help
im not sure if this is recommended, but can’t you set a really old “dummy” date?
2017-07-24T16:45:24.348134
Winnifred
pythondev_help_Winnifred_2017-07-24T16:45:24.348134
1,500,914,724.348134
87,023
pythondev
help
I can and it works
2017-07-24T16:45:48.360799
Johnetta
pythondev_help_Johnetta_2017-07-24T16:45:48.360799
1,500,914,748.360799
87,024
pythondev
help
But it isn't clean is all.
2017-07-24T16:46:16.375538
Johnetta
pythondev_help_Johnetta_2017-07-24T16:46:16.375538
1,500,914,776.375538
87,025
pythondev
help
yeah :neutral_face:
2017-07-24T16:50:07.497451
Winnifred
pythondev_help_Winnifred_2017-07-24T16:50:07.497451
1,500,915,007.497451
87,026
pythondev
help
PostGIS doesn't return any results for `ST_DWithin`. I'm having a lot of difficulty figuring it out
2017-07-24T21:39:55.788167
Thomasina
pythondev_help_Thomasina_2017-07-24T21:39:55.788167
1,500,932,395.788167
87,027
pythondev
help
Hi, does anyone have time to help me with a simple regex string?
2017-07-24T21:50:16.910884
Christa
pythondev_help_Christa_2017-07-24T21:50:16.910884
1,500,933,016.910884
87,028
pythondev
help
<@Christa> You usually have the best luck just posting the question, someone will usually be along to help out
2017-07-24T21:54:27.960031
Beula
pythondev_help_Beula_2017-07-24T21:54:27.960031
1,500,933,267.960031
87,029
pythondev
help
Ok. So my question is: I have the following folder structure: C:\ -0.82\ I have this line of code: `app.connect(path=r"C:\0.82\file.exe")` Then, the C:\ folder gets updated and I have this: C:\ -0.82\ -0.86\ Now I want to use regex to connect to the folder 0.86\ `app.connect(path=r"C:\0.\d\d\file.exe")` But that wasn't right and I don't understand regex. Can someone please describe how to use regex correctly in this scenario?
2017-07-24T22:00:03.027249
Christa
pythondev_help_Christa_2017-07-24T22:00:03.027249
1,500,933,603.027249
87,030
pythondev
help
Is the file update deterministic? If so - you may not want regex
2017-07-24T22:04:44.083739
Beula
pythondev_help_Beula_2017-07-24T22:04:44.083739
1,500,933,884.083739
87,031
pythondev
help
My guess is one of your issues will be the backslashes from the windows path, which are "escape sequences" in regex, so `C:\0.\d`, `\0.` probably isn't what you want, `\0` is escaping "0" and then `.` is any char, I think a starting point may be: `C:\\0\.\d{2}\\file.exe`
2017-07-24T22:06:13.100620
Beula
pythondev_help_Beula_2017-07-24T22:06:13.100620
1,500,933,973.10062
87,032
pythondev
help
@hi
2017-07-24T22:06:17.101541
Jame
pythondev_help_Jame_2017-07-24T22:06:17.101541
1,500,933,977.101541
87,033
pythondev
help
Can any one suggest the document for managing pcap files for replaying SNMP traps?
2017-07-24T22:07:06.110855
Jame
pythondev_help_Jame_2017-07-24T22:07:06.110855
1,500,934,026.110855
87,034
pythondev
help
The file update is somewhat incremental
2017-07-24T22:11:35.162251
Christa
pythondev_help_Christa_2017-07-24T22:11:35.162251
1,500,934,295.162251
87,035
pythondev
help
I'm not sure what's going on. There is an 'r' prefixed in the string so its a raw string and \\ is not needed to escape the file path \ in this case. Can you update your answer with this in mind?
2017-07-24T22:12:36.173957
Christa
pythondev_help_Christa_2017-07-24T22:12:36.173957
1,500,934,356.173957
87,036
pythondev
help
It actually does need the escapes in the regex string, it gets compiled and `\d` is a "digit", and `\0` isn't anything, so your regex needs to escape
2017-07-24T22:15:42.209059
Beula
pythondev_help_Beula_2017-07-24T22:15:42.209059
1,500,934,542.209059
87,037
pythondev
help
If you read the docs for the `re` package - you'll see the same behavior I describe, all the raw strings still escape the special chars
2017-07-24T22:16:42.220407
Beula
pythondev_help_Beula_2017-07-24T22:16:42.220407
1,500,934,602.220407
87,038
pythondev
help
<@Jame> what google says: <http://pysnmp.sourceforge.net/>
2017-07-24T22:17:48.232771
Collette
pythondev_help_Collette_2017-07-24T22:17:48.232771
1,500,934,668.232771
87,039
pythondev
help
<@Christa> Here is a snippet from the official docs: &gt; Regular expressions use the backslash character ('\') to indicate special forms or to allow special characters to be used without invoking their special meaning. This collides with Python’s usage of the same character for the same purpose in string literals; for example, to match a literal backslash, one might have to write '\\\\' as the pattern string, because the regular expression must be \\, and each backslash must be expressed as \\ inside a regular Python string literal. &gt; &gt; *The solution is to use Python’s raw string notation for regular expression patterns; backslashes are not handled in any special way in a string literal prefixed with 'r'. So r"\n" is a two-character string containing '\' and 'n', while "\n" is a one-character string containing a newline. Usually patterns will be expressed in Python code using this raw string notation.
2017-07-24T22:20:50.266769
Beula
pythondev_help_Beula_2017-07-24T22:20:50.266769
1,500,934,850.266769
87,040
pythondev
help
I'm sort of confused. Do I have to prefix the string with a function re(`C:\\0\.\d{2}\\file.exe`)
2017-07-24T22:22:47.288160
Christa
pythondev_help_Christa_2017-07-24T22:22:47.288160
1,500,934,967.28816
87,041
pythondev
help
re(`"C:\\0\.\d{2}\\file.exe"`)
2017-07-24T22:23:04.291475
Christa
pythondev_help_Christa_2017-07-24T22:23:04.291475
1,500,934,984.291475
87,042
pythondev
help
or re(r`C:\\0\.\d{2}\\file.exe`)
2017-07-24T22:23:10.292681
Christa
pythondev_help_Christa_2017-07-24T22:23:10.292681
1,500,934,990.292681
87,043
pythondev
help
If you are searching for something: `re.search(r'&lt;regex_string&gt;', source_string)`
2017-07-24T22:23:29.296256
Beula
pythondev_help_Beula_2017-07-24T22:23:29.296256
1,500,935,009.296256
87,044
pythondev
help
in this case, its just file directories.. How do I got about choosing?
2017-07-24T22:23:45.298944
Christa
pythondev_help_Christa_2017-07-24T22:23:45.298944
1,500,935,025.298944
87,045
pythondev
help
Choosing between what?
2017-07-24T22:24:03.302712
Beula
pythondev_help_Beula_2017-07-24T22:24:03.302712
1,500,935,043.302712
87,046
pythondev
help
Folder names
2017-07-24T22:24:09.303811
Christa
pythondev_help_Christa_2017-07-24T22:24:09.303811
1,500,935,049.303811
87,047
pythondev
help
As I said before, I believe regex is the wrong approach
2017-07-24T22:24:19.305664
Beula
pythondev_help_Beula_2017-07-24T22:24:19.305664
1,500,935,059.305664
87,048
pythondev
help
Any suggestions to the correct approach?
2017-07-24T22:24:33.308362
Christa
pythondev_help_Christa_2017-07-24T22:24:33.308362
1,500,935,073.308362
87,049
pythondev
help
Or at least a working one
2017-07-24T22:24:41.309871
Christa
pythondev_help_Christa_2017-07-24T22:24:41.309871
1,500,935,081.309871
87,050
pythondev
help
If it's always an incrementing number, the easy solution is list the directory (`os.listdir`), convert them into floats, and take the highest
2017-07-24T22:25:10.315561
Beula
pythondev_help_Beula_2017-07-24T22:25:10.315561
1,500,935,110.315561
87,051
pythondev
help
OMG You're awesome!
2017-07-24T22:25:37.320774
Christa
pythondev_help_Christa_2017-07-24T22:25:37.320774
1,500,935,137.320774
87,052
pythondev
help
:slightly_smiling_face:
2017-07-24T22:25:43.322143
Christa
pythondev_help_Christa_2017-07-24T22:25:43.322143
1,500,935,143.322143
87,053
pythondev
help
I like the old acronym, KISS -&gt; Keep it simple stupid. (not calling you stupid, so please don't misread that!)
2017-07-24T22:26:32.331517
Beula
pythondev_help_Beula_2017-07-24T22:26:32.331517
1,500,935,192.331517
87,054
pythondev
help
<https://en.wikipedia.org/wiki/KISS_principle>
2017-07-24T22:26:47.334247
Beula
pythondev_help_Beula_2017-07-24T22:26:47.334247
1,500,935,207.334247
87,055
pythondev
help
Heard of that! I am not familiar with the os library and I was familiar with regex so I wouldnt have thought of that solution without you!
2017-07-24T22:28:57.358540
Christa
pythondev_help_Christa_2017-07-24T22:28:57.358540
1,500,935,337.35854
87,056
pythondev
help
As a follow up, as a beginner python programmer, how was I supposed to know that os.listdir was a valid path to take without asking someone else for their sage advice
2017-07-24T22:29:33.365407
Christa
pythondev_help_Christa_2017-07-24T22:29:33.365407
1,500,935,373.365407
87,057
pythondev
help
You did the right thing, you asked for help! That's a good way to find other solutions.
2017-07-24T22:30:07.371701
Beula
pythondev_help_Beula_2017-07-24T22:30:07.371701
1,500,935,407.371701
87,058
pythondev
help
What you had is called an X-Y problem, you wanted to get the next file - and thought regex was the answer so you asked how to do the regex
2017-07-24T22:30:30.376383
Beula
pythondev_help_Beula_2017-07-24T22:30:30.376383
1,500,935,430.376383
87,059
pythondev
help
Those of us that have been around the block once or twice try to understand the actual problem, to make sure we answer the right question
2017-07-24T22:30:49.380155
Beula
pythondev_help_Beula_2017-07-24T22:30:49.380155
1,500,935,449.380155
87,060
pythondev
help
You're right. I shouldve just asked how to do it, at first. I still want to learn how to use regex tho :stuck_out_tongue:
2017-07-24T22:33:32.411399
Christa
pythondev_help_Christa_2017-07-24T22:33:32.411399
1,500,935,612.411399
87,061
pythondev
help
Oh well, hopefully another time. Thanks, again!
2017-07-24T22:33:56.416011
Christa
pythondev_help_Christa_2017-07-24T22:33:56.416011
1,500,935,636.416011
87,062
pythondev
help
If you want to do the regex way you'd do something similar, you'd use a "capture group", convert them to floats, then compare. Much more involved and harder to maintain :smile:
2017-07-24T22:34:10.418754
Beula
pythondev_help_Beula_2017-07-24T22:34:10.418754
1,500,935,650.418754
87,063
pythondev
help
it probably still requires listing the dir too
2017-07-24T22:34:34.423464
Beula
pythondev_help_Beula_2017-07-24T22:34:34.423464
1,500,935,674.423464
87,064
pythondev
help
Hi All, I am trying to get apache running on webserver for django application. When trying to query it i am getting 301 and 405 response
2017-07-24T23:35:20.052154
Pearl
pythondev_help_Pearl_2017-07-24T23:35:20.052154
1,500,939,320.052154
87,065
pythondev
help
anything that i am missing?
2017-07-24T23:35:31.053830
Pearl
pythondev_help_Pearl_2017-07-24T23:35:31.053830
1,500,939,331.05383
87,066
pythondev
help
What's the location header of the `301`?
2017-07-24T23:45:28.151430
Beula
pythondev_help_Beula_2017-07-24T23:45:28.151430
1,500,939,928.15143
87,067
pythondev
help
You can check with `curl -i &lt;path&gt;` if you are unfamiliar
2017-07-24T23:45:45.154000
Beula
pythondev_help_Beula_2017-07-24T23:45:45.154000
1,500,939,945.154
87,068
pythondev
help
<@Beula> i am very new to this. what is value to use in &lt;path&gt;
2017-07-24T23:48:17.178454
Pearl
pythondev_help_Pearl_2017-07-24T23:48:17.178454
1,500,940,097.178454
87,069
pythondev
help
The path is the url: `curl -i localhost:8000/admin`, for example
2017-07-24T23:48:52.184234
Beula
pythondev_help_Beula_2017-07-24T23:48:52.184234
1,500,940,132.184234
87,070
pythondev
help
As an example, see this request: ``` $ curl -i <https://google.com> HTTP/1.1 301 Moved Permanently Location: <https://www.google.com/> Content-Type: text/html; charset=UTF-8 Date: Tue, 25 Jul 2017 03:49:15 GMT Expires: Thu, 24 Aug 2017 03:49:15 GMT Cache-Control: public, max-age=2592000 Server: gws Content-Length: 220 X-XSS-Protection: 1; mode=block X-Frame-Options: SAMEORIGIN Alt-Svc: quic=":443"; ma=2592000; v="39,38,37,36,35" ``` The `Location` one may tell you the issue, my guess is you are not including a trailing slash
2017-07-24T23:49:52.193916
Beula
pythondev_help_Beula_2017-07-24T23:49:52.193916
1,500,940,192.193916
87,071
pythondev
help
let me check
2017-07-24T23:50:17.198033
Pearl
pythondev_help_Pearl_2017-07-24T23:50:17.198033
1,500,940,217.198033
87,072
pythondev
help
Sorry, I am also assuming you have `curl` installed, if your OS doesn't have it you can test in a browser and use the inspector to see
2017-07-24T23:52:09.216750
Beula
pythondev_help_Beula_2017-07-24T23:52:09.216750
1,500,940,329.21675
87,073
pythondev
help
spot on. I was able to get rid of that issue. Now i have 500 error which i will try to figure out. Thank you very much. :+1:
2017-07-24T23:52:15.217666
Pearl
pythondev_help_Pearl_2017-07-24T23:52:15.217666
1,500,940,335.217666
87,074
pythondev
help
will keep you posted on my progress :slightly_smiling_face:
2017-07-24T23:52:40.221765
Pearl
pythondev_help_Pearl_2017-07-24T23:52:40.221765
1,500,940,360.221765
87,075
pythondev
help
:thumbsup::skin-tone-4:
2017-07-24T23:53:10.226691
Beula
pythondev_help_Beula_2017-07-24T23:53:10.226691
1,500,940,390.226691
87,076
pythondev
help
`UPDATE stores SET geom = ST_SetSRID(ST_MakePoint(longitude, latitude), 4326);` vs. `UPDATE yourtable SET geom = ST_MakePoint(longitude, latitude);` What's le difference?
2017-07-25T00:27:13.566390
Thomasina
pythondev_help_Thomasina_2017-07-25T00:27:13.566390
1,500,942,433.56639
87,077
pythondev
help
It worked fine. I ran into some permission issue but it is now resolved. Thank you for all the nelp
2017-07-25T01:03:29.920229
Pearl
pythondev_help_Pearl_2017-07-25T01:03:29.920229
1,500,944,609.920229
87,078
pythondev
help
<@Thomasina> the first example sets an SRID of 4386 (WGS84). the second example doesn't set an SRID and should get the default for geometry which is 0
2017-07-25T01:56:04.450205
Willena
pythondev_help_Willena_2017-07-25T01:56:04.450205
1,500,947,764.450205
87,079
pythondev
help
<@Willena> Will that cause a big difference in the resulting values?
2017-07-25T02:02:29.525265
Thomasina
pythondev_help_Thomasina_2017-07-25T02:02:29.525265
1,500,948,149.525265
87,080
pythondev
help
Depends what your doing. When SRID is 0, the data gets treated like it's on a Cartesian plane (flat). Using 4326 allows for a round earth. If you're trying to do things like get the distance between two points, it can make a difference.
2017-07-25T02:12:00.638348
Willena
pythondev_help_Willena_2017-07-25T02:12:00.638348
1,500,948,720.638348
87,081
pythondev
help
<@Willena> That was the best explanation I could have hoped for. I'd looked it up before but none of the explanations made as much sense as what you said right now. Haha
2017-07-25T03:25:04.719888
Thomasina
pythondev_help_Thomasina_2017-07-25T03:25:04.719888
1,500,953,104.719888
87,082
pythondev
help
I'm trying to find all points inside a square
2017-07-25T03:25:26.726232
Thomasina
pythondev_help_Thomasina_2017-07-25T03:25:26.726232
1,500,953,126.726232
87,083
pythondev
help
I also see that PostGIS says on the site `DO NOT INSTALL it in the database called postgres.`... That's exactly what I did though... No idea why they say not to do it
2017-07-25T03:26:04.737957
Thomasina
pythondev_help_Thomasina_2017-07-25T03:26:04.737957
1,500,953,164.737957
87,084
pythondev
help
You have to install it to your database
2017-07-25T03:33:53.878838
Meg
pythondev_help_Meg_2017-07-25T03:33:53.878838
1,500,953,633.878838
87,085
pythondev
help
Eg, the one you created for the project
2017-07-25T03:34:09.883453
Meg
pythondev_help_Meg_2017-07-25T03:34:09.883453
1,500,953,649.883453
87,086
pythondev
help
If you're familiar with mysql, the postgres db name is similar to the mysql db name
2017-07-25T03:35:42.912185
Meg
pythondev_help_Meg_2017-07-25T03:35:42.912185
1,500,953,742.912185
87,087
pythondev
help
<@Meg> Ah ok. Got it.
2017-07-25T04:47:18.424652
Thomasina
pythondev_help_Thomasina_2017-07-25T04:47:18.424652
1,500,958,038.424652
87,088
pythondev
help
People keep telling me that `43.6532, 79.3832` leads to somewhere in Kazakhstan. I don't understand. They're the coordinates of TORONTO. Put them into Google Maps and it drops a pin in the center of Toronto.
2017-07-25T04:49:39.478061
Thomasina
pythondev_help_Thomasina_2017-07-25T04:49:39.478061
1,500,958,179.478061
87,089
pythondev
help
it drop me in kazakhstan
2017-07-25T04:51:09.513190
Ciera
pythondev_help_Ciera_2017-07-25T04:51:09.513190
1,500,958,269.51319
87,090
pythondev
help
`43.6532, -79.3832` is Toronto
2017-07-25T04:51:38.524195
Ciera
pythondev_help_Ciera_2017-07-25T04:51:38.524195
1,500,958,298.524195
87,091
pythondev
help
<https://www.google.ca/search?q=toronto+lat+long&amp;gws_rd=cr&amp;ei=awZ3WbaYOYTHjwSQlIuwCw>
2017-07-25T04:52:10.536427
Thomasina
pythondev_help_Thomasina_2017-07-25T04:52:10.536427
1,500,958,330.536427
87,092
pythondev
help
I don't get it.
2017-07-25T04:52:12.537189
Thomasina
pythondev_help_Thomasina_2017-07-25T04:52:12.537189
1,500,958,332.537189
87,093
pythondev
help
These "coordinates" Google is serving me aren't actually lat/lon
2017-07-25T04:52:29.543671
Thomasina
pythondev_help_Thomasina_2017-07-25T04:52:29.543671
1,500,958,349.543671
87,094
pythondev
help
?
2017-07-25T04:52:30.544197
Thomasina
pythondev_help_Thomasina_2017-07-25T04:52:30.544197
1,500,958,350.544197
87,095
pythondev
help
79.3832° *W*
2017-07-25T04:53:05.557411
Ciera
pythondev_help_Ciera_2017-07-25T04:53:05.557411
1,500,958,385.557411
87,096
pythondev
help
without direction it's EAST by default
2017-07-25T04:53:19.562828
Ciera
pythondev_help_Ciera_2017-07-25T04:53:19.562828
1,500,958,399.562828
87,097
pythondev
help
:facepalm:
2017-07-25T04:53:21.563697
Thomasina
pythondev_help_Thomasina_2017-07-25T04:53:21.563697
1,500,958,401.563697
87,098
pythondev
help
Wow. Two days of development time spent on trying to figure that out.
2017-07-25T04:53:51.574759
Thomasina
pythondev_help_Thomasina_2017-07-25T04:53:51.574759
1,500,958,431.574759
87,099
pythondev
help
Thank you <@Ciera>. May the force be with you.
2017-07-25T04:53:58.577602
Thomasina
pythondev_help_Thomasina_2017-07-25T04:53:58.577602
1,500,958,438.577602
87,100
pythondev
help
Will be fun to explain to my boss. : o )
2017-07-25T04:54:32.590409
Thomasina
pythondev_help_Thomasina_2017-07-25T04:54:32.590409
1,500,958,472.590409
87,101
pythondev
help
good luck :smile:
2017-07-25T04:55:15.606900
Ciera
pythondev_help_Ciera_2017-07-25T04:55:15.606900
1,500,958,515.6069
87,102