How To Capture Output of Curl from Python script
<p>I want to find the info about a webpage using curl, but in Python, so far I have this:</p>

<pre><code>os.system("curl --head www.google.com")
</code></pre>

<p>If I run that, it prints out:</p>

<pre><code>HTTP/1.1 200 OK
Date: Sun, 15 Apr 2012 00:50:13 GMT
Expires: -1
Cache-Control: private, max-age=0
Content-Type: text/html; charset=ISO-8859-1
Set-Cookie: PREF=ID=3e39ad65c9fa03f3:FF=0:TM=1334451013:LM=1334451013:S=IyFnmKZh0Ck4xfJ4; expires=Tue, 15-Apr-2014 00:50:13 GMT; path=/; domain=.google.com
Set-Cookie: NID=58=Giz8e5-6p4cDNmx9j9QLwCbqhRksc907LDDO6WYeeV-hRbugTLTLvyjswf6Vk1xd6FPAGi8VOPaJVXm14TBm-0Seu1_331zS6gPHfFp4u4rRkXtSR9Un0hg-smEqByZO; expires=Mon, 15-Oct-2012 00:50:13 GMT; path=/; domain=.google.com; HttpOnly
P3P: CP="This is not a P3P policy! See http://www.google.com/support/accounts/bin/answer.py?hl=en&amp;answer=151657 for more info."
Server: gws
X-XSS-Protection: 1; mode=block
X-Frame-Options: SAMEORIGIN
Transfer-Encoding: chunked
</code></pre>

<p>What I want to do, is be able to match the 200 in it using a regex (i don't need help with that), but, I can't find a way to convert all the text above into a string. How do I do that? 
I tried: <code>info = os.system("curl --head www.google.com")</code> but <code>info</code> was just <code>0</code>.</p>
