Strange "Invalid Syntax" error in Python
<p>This is some of the code for my Pygame. I can't figure out what's wrong here:</p>

<pre><code>class Aqua(object):
    def __init__(self):
        self.surf = pygame.image.load("Aqua.png").convert_alpha()
        self.here = True
        self.rect = pygame.Rect(240,55,32,32)

            """skipped some unrelated stuff"""

class Game(object):
    def __init__(self):

            """skipped some unrelated stuff"""

        self.aqua = Aqua()

            """skipped some unrelated stuff"""

    def draw(self):
        self.screen.blit(self.floor.floor_surf, (0,0))
        for wall in self.walls:
            self.screen.blit(wall.surf, wall.rect)
        if self.lead.here:
            self.screen.blit(self.lead.surf, (16,150))
        if self.arsenic.here:
            self.screen.blit(self.arsenic.surf, (304,150))

        self.screen.blit(self.player.surf, self.player.rect, pygame.Rect(self.player.frame*32, self.player.dir*64, 32, 64))
        self.screen.blit(self.table.surf, (0,0))
        self.screen.blit(self.table.surf, (0,64))
        self.screen.blit(self.table.surf, (192,64))
        self.screen.blit(self.table.surf, (256,64))
        self.screen.blit(self.table.surf, (320,64))
        self.screen.blit(self.table.surf, (192,128))
        self.screen.blit(self.table.surf, (00,192))
        self.screen.blit(self.table.surf, (192,192))
        self.screen.blit(self.table.surf, (00,256))
        self.screen.blit(self.table.surf, (576,160))
        self.screen.blit(self.table.surf, (576,224))

        if self.mercury.here:
            self.screen.blit(self.mercury.surf, (336,64))
        if self.sulfur.here:
            self.screen.blit(self.sulfur.surf, (32,289)
        if self.aqua.here:    #this is the line it doesn't like.
            self.screen.blit(self.aqua.surf, (240,55))
</code></pre>

<p>when I try to run it, it refers to that second-to-last line, points to the word "here", and says "invalid syntax". Why?</p>
