select specific decendants using Jquery
<p>In <a href="http://api.jquery.com/child-selector/" rel="nofollow">JQuery's Documentation</a> the <code>"parent &gt; child"</code> selector selects all direct child elements specified by "child" of elements specified by "parent". "Direct child" is just the element one level down. For example, I have this code:</p>

<pre><code>    ...
    &lt;table class="advanceSearch"&gt;
      &lt;tr&gt;
        &lt;td&gt;
          &lt;ul class="form"&gt;
            &lt;li&gt;
              &lt;label&gt;Document Type:&lt;/label&gt;
              &lt;input type="text" id="cmbDocumentType" name="paramtitle" /&gt;
            &lt;/li&gt;
            &lt;li&gt;
              &lt;label&gt;Title:&lt;/label&gt;
              &lt;input type="text" id="paramtitle" name="paramtitle" /&gt;
            &lt;/li&gt;
            &lt;li&gt;
              &lt;label&gt;Notes:&lt;/label&gt;
              &lt;input type="text" id="paramNotes" name="paramNotes" /&gt;
            &lt;/li&gt;
            &lt;li&gt;
              &lt;label&gt;Revision Number:&lt;/label&gt;
              &lt;input type="text" id="paramRevisionNumber" name="paramRevisionNumber" /&gt;
            &lt;/li&gt;
            &lt;li&gt;
              &lt;label&gt;Draft Number:&lt;/label&gt;
              &lt;input type="text" id="paramDraftNumber" name="paramDraftNumber" /&gt;
            &lt;/li&gt;
            &lt;li&gt;
              &lt;label&gt;Version Number:&lt;/label&gt;
              &lt;input type="text" id="paramVersionNumber" name="paramVersionNumber" /&gt;
            ...
</code></pre>

<p>I want to select the <code>input</code> elements with ids starting with "param", and so I used the <code>find()</code> instead of the <code>parent &gt; child</code> selector:</p>

<pre><code>      $("table.advanceSearch").find("ul.form").find('input[id^="param"]').attr("disabled", "disabled");
</code></pre>

<p>This works well but I find it redundant having two <code>find()</code> selectors. Is there any way to have the shorthand for this?</p>
