get input stream of zipped file?
<p>Is it possible to get a file as InputStream from the zipped file? I only know this one here: <a href="http://stackoverflow.com/questions/3125841/how-to-extract-a-single-file-from-a-remote-archive-file">How to extract a single file from a remote archive file?</a> which gives me just the bytes of the file. </p>

<p>so is there any functionality to have a method like this: <code>InputStream getFile(String path, File zipFile)</code> where the <code>path</code> is the path inside the ziped File?</p>
