"Undefined Variable" notice
<p>Im new to php so im sure this is an easy one. Im getting this error </p>

<pre><code>Notice: Undefined variable: conn in C:\Dev\Webserver\Apache2.2\htdocs\EclipsePHP\thecock\php\db.php on line 23
</code></pre>

<p>for this code</p>

<pre><code>&lt;?php
$host = "localhost"; $database = "dbname"; $username = "user"; $password = "pass";

$conn = new mysqli($host, $username, $password, $database);

if (! $conn) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit(); 
}else{  
    echo("all ok!"); 
}

function getContent($id) {  
    $sql = "SELECT content FROM blocktext WHERE id=$id";  
    if ($rs = $conn-&gt;query($sql)) {    # line 23
        if ($row = $rs-&gt;fetch_assoc()) {    
            echo stripslashes($row['content']);   
        }
        $rs-&gt;close();  
    } 
} 
?&gt;
</code></pre>

<p>How do I fix the notice?</p>
