Running Java from the windows command line
<p>I recently asked a bout a java program I could not find the start point to and was told to look in the bat file which started it but I do not understand what it says.</p>

<p>This program runs on a tomcat server and must be running before the .jsp pages will run so they are not the starting point.</p>

<p>Can anyone explain what this means and where the program starts so I can do a step through.</p>

<pre><code>D:\foo_development\server&gt;java -Xmx256M -Djava.library.path=lib -Djava.rmi.serv
er.hostname=192.168.0.104 -Djava.rmi.server.codebase="file:/D:\foo_development\
server\foo_server.jar http://192.168.0.104:8000/foo_client_stubs/server_keycon
sole_stubs.jar" -Djava.security.policy=conf/java.policy -jar foo_server.jar 109
8 2001
</code></pre>

<p>This is exactly how it appears in the cmd window after I click run.bat</p>
