How to launch a process which will open a text file in any editor and automatically move cursor to a certain line number?
<p>From c#, I want to launch a process which will open a text file in any editor and automatically move cursor to a certain line number.</p>

<p>I can open a file using</p>

<pre><code>Process.Start(@"c:\myfile.txt");
</code></pre>

<p>but I don't know how to move cursor at specific location in that file.</p>

<hr>

<p>Answer with source code:</p>

<p>yes, I used notepad++ </p>

<pre><code>private void openLog() {
            try {
                // see if notepad++ is installed on user's machine
                var nppDir = (string)Registry.GetValue("HKEY_LOCAL_MACHINE\\SOFTWARE\\Notepad++", null, null);
                if (nppDir != null) {
                    var nppExePath = Path.Combine(nppDir, "Notepad++.exe");
                    var nppReadmePath = Path.Combine(yourDirectory,fileName );
                    var line = 20;
                    var sb = new StringBuilder();
                    sb.AppendFormat("\"{0}\" -n{1}", nppReadmePath, lineNo);
                    Process.Start(nppExePath, sb.ToString());
                } else {
                    string newPath = @"\\mySharedDrive\notpad++\bin\notepad++.exe";
                    Process.Start(newPath, @"\\" + filePath + " -n" + lineNo); // take exe from my shared drive
                }
            } catch (Exception e) {
                Process.Start(@"\\" + FilePath); // open using notepad
            }
        }
</code></pre>
