How to show the information from the link without leaving the site? PHP
<p>I got the site fully working and returning the information from the rss feed since the it return with website link how can i display the information from the link instead of redirect the user back to the original site?</p>

<pre><code>&lt;?php

    $query = 'http://query.yahooapis.com/v1/public/yql?q=Select%20*%20from%20rss%20where%20url%3D%22http%3A%2F%2Fnestor.sunderland.ac.uk%2F~bf71wx%2FphpTest%2Fjquery.mobile-1.0.1%2520-%2520%25E8%25A4%2587%25E8%25A3%25BD%2Fjquery.mobile-1.0.1%2Fdemos%2Fdocs%2Frss%2FNews.xml%22%20&amp;diagnostics=true';
    $xml = simplexml_load_file($query);
    //var_dump($xml);

    echo '&lt;h2&gt;World of Tank News&lt;/h2&gt;';

    //iterate over query result set
    $results = $xml-&gt;results;
    foreach ($results-&gt;item as $r){
        echo $r-&gt;title . "&lt;br /&gt;";
        echo "&lt;a href=\"" . $r-&gt;link . "\"&gt;" . $r-&gt;link . "&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;";
        echo 'Publish Date - ';

    }

?&gt;
</code></pre>
