how to make linkbutton control in gridview open an new ie window
<pre><code>  &lt;asp:TemplateField HeaderText ="ename"&gt;
        &lt;ItemTemplate &gt; &lt;asp:Label ID="lbl2" Text ='&lt;%#Eval("ID") %&gt;' runat ="server" &gt;
        &lt;/asp:Label&gt;
        &lt;/ItemTemplate&gt;
        &lt;EditItemTemplate &gt;
        &lt;asp:TextBox ID ="textbox1" Text='&lt;%#Eval("name")%&gt;'  runat ="server"  &gt;&lt;/asp:TextBox&gt;
&lt;asp:LinkButton ID ="link1" Text='&lt;%#Eval("name")%&gt;'  runat ="server"  &gt;&lt;/asp:LinkButton&gt;


        &lt;/EditItemTemplate&gt;
        &lt;/asp:TemplateField&gt;
</code></pre>

<p>i have an  textbox and link button in <strong>Edit itemtemplate</strong>
based on the condition()</p>

<p>if(Text ='&lt;%#Eval("ID") %>')
id=1 show textbox[edit item temalpate]</p>

<p>id=2 show link button[edit item temalpate]</p>

<p>id=3 show link button[edit item temalpate]</p>

<p>now in link button i have value [Text='&lt;%#Eval("name")%>'] (eg:www.stackoverflow.com ,google.com)
so that one an user clicks on the link button open a new browser window and show that webiste</p>

<p>show  to open an new  browser window on the clcik  of the link button</p>

<p>anyhelp would be great thank you</p>
