php not executing another script
<p>I have a .php file that looks like this:</p>

<pre><code>foreach($stmt-&gt;fetchAll() as $array)
              {
            echo '&lt;div class="thumb" style="width: '.$array['thumb_width'].'px; height: '.$array['thumb_height'].'px;"&gt;
            &lt;p&gt;&lt;a href="showfile.php?image_id='.$array['image_id'].'"&gt;
            &lt;img src="showthumbs.php?image_id='.$array['image_id'].'" alt="'.$array['image_name'].' /"&gt;
            &lt;/a&gt;&lt;/p&gt;
            &lt;p&gt;'.$array['image_name'].'&lt;/p&gt;&lt;/div&gt;';
            }
</code></pre>

<p>I am following the tutorial <a href="http://www.phpro.org/tutorials/Storing-Images-in-MySQL-with-PHP.html#7" rel="nofollow">here</a> to basically upload and show images. When I view source the page that is loaded (<a href="http://renps.nm3.co/galerry.php" rel="nofollow">which you can test out here</a>), for some reason it's not displaying the image. I have the showthumbs.php on the same location as the location of the gallery.php. What am I missing?</p>
