Is it possible to use long double as an integer? (adding, substracting, multiplying, dividing, perbit operations ...)
<p>As far as I know in C++ standart <code>sizeof(long double)</code> is 10 byte = 80 bit => the variable of this <code>long double</code> type can carry 2^80 different values. So my question is here, is it possible to write some wrapper or I don't know what (using, maybe, perbit operations). To use <code>long double</code> (or it wrapper) as full integer? And if there is possible, then why standart doesn't give as 80bit integer?</p>
