Wrapping std::cout in a function call
<p>I have a lot of couts and so I would like to be able to make a function that can take just three arguments. The function would print them out to the screen just as cout does like this:</p>

<pre><code>print( 5, " is a ", "number" );

// should do the same thing as

cout &lt;&lt; 5 &lt;&lt; " is a " &lt;&lt; "number" &lt;&lt; endl;
</code></pre>

<p>I'm not asking anyone to do it. I'm just looking for a way to be able to. But if you can provide the code that would be good as well. Does anyone have any advice? Thanks.</p>
