Input coming from the standard input and storing as a vector,
<pre><code>Background info:
----------------------------------------------------------------
public class Point {

    protected int x;
    protected int y;

    public Point(){

        this.x = x;
        this.y = y;
    }

    public String toString(){

        return "" + x + " , " + y; 
    }
}
---------------------------------------------------------------
public class PointName extends Point {

    private String name;

    public PointName(String name, int x, int y){

        super();
        this.name = name;
    }

    public PointName() {
        // TODO Auto-generated constructor stub
    }


    public String toString(){

        return name + super.toString();

    }

}
------------------------------------------------------------------------
</code></pre>

<p></p>

<p>I want to create an application called closest point and in this class data is supplied from the standard input(keyboard). Then i want to supply 10 points (name given points) which will be stored in a vector. Then print them out. A bit more after this but im stuck in this stage as i dont know what to do. I welcome all possible solutions!!</p>

<p><br>
    <strong>MY SOLUTION SO FAR:</strong> </p>

<pre><code>public class ClosestPoint {

    public static void main (String[] args){

        Scanner in = new Scanner(System.in);
        System.out.println("Write in the new point starting with name then x, y");

        String name = "";
        Integer x = 0;
        Integer y = 0;

        String nameGivenPoints[] = null; // List of points to create
        String line = in.nextLine(); // info from the board

        while(!line.endsWith("")){
        nameGivenPoints = line.split("\r\n\r");

        name = nameGivenPoints[0];
        x = Integer.parseInt(nameGivenPoints[1]);
        y = Integer.parseInt(nameGivenPoints[2]);

// Maybe a forloop here
        PointName tenDifferentPunkts = new PointName(name, x, y);
        System.out.println(tenDifferentPunkts.toString());
         line = in.nextLine();

                }   
        }
</code></pre>
