scripting gmail bulk fowarding, IMAP not an option
<p>Constraint justifying script: IMAP is not an available option. I am working with Gmail enterprise and the option has been made unavailable.</p>

<p>This script needs to bulk forward gmail by user defined label and include message recipient, sender, subject, and date.  It can successfully forward messages; however, given Gmails list of methods, I am not sure how to get the messages forwarded while maintaining its original above info.</p>

<p>Here is my script:</p>

<pre><code>function forwardMail2() {  
  var data = SpreadsheetApp.getActiveSheet().getRange("A2:B11").getValues();  
  for (i in data) {    
    var row = data[i];   
    var name = row[0].toString();
    var email = row[1].toString();
    var label = GmailApp.getUserLabelByName(name);            
    if (label &amp;&amp; (email != "")) {
      var threads = label.getThreads();   
      for (var x in threads) {      
        var messages = threads[x].getMessages(); 
        for (var y in messages) {
          /* var addressee = messages[y].getTo();
          var mailSender = messages[y].getFrom();
          var date = messages[y].getDate();
          var subject = messages[y].getSubject();*/
          messages[y].forward(email);}
</code></pre>

<p>Here are examples for the Gmail method forward() I have come across so far: 
// forward first message of first inbox thread to recipient1 &amp; recipient2, both @example.com</p>

<pre><code>var firstThread = GmailApp.getInboxThreads(0,1)[0];
var message = firstThread.getMessages()[0];
message.forward("recipient1@example.com,recipient2@example.com");
</code></pre>

<p>and  </p>

<pre><code>var firstThread = GmailApp.getInboxThreads(0,1)[0];
var message = firstThread.getMessages()[0];
message.forward("recipient1@example.com,recipient2@example.com", {
  cc: "myboss@example.com",
  bcc: "mybosses-boss@example.com,vp@example.com");
</code></pre>

<p>The optional advanced arguments for the Gmail forward() method do not pertain to the additional info I am trying to include.</p>
