Get the value that comes after the ? operator in the URL
<p>I want to get the value that will come after the '?' operator, for example:</p>

<pre><code>www.blabla.com/any.php?h r u 
</code></pre>

<p>I want to get this value "h r u", and to search this key in my database. I've already tried this: </p>

<pre><code>$_SERVER["QUERY_STRING"]
</code></pre>

<p>This function is working fine but when I searched these values it prints like this "h%20r%20u" in my database from this query:</p>

<pre><code>$query="SELECT * FROM databasename WHERE colum LIKE'%$link%'";
</code></pre>

<p>It will print link this " h%20r%20u no record found " and my database can't find 
this value. How can i solve my problem?</p>
