Display ListPopupWindow on most left of the screen
<p>I could display ListPopupWindow on most left of the screen by following code.</p>

<pre><code>@Override
public View onCreateActionView() {
    LayoutInflater layoutInflater = LayoutInflater.from(mContext);

    final View actionItem = layoutInflater.inflate(R.layout.list_table_view_action_provider, null);

    final ImageButton button = (ImageButton) actionItem.findViewById(R.id.button);
    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            mListPopupWindow = new ListPopupWindow(mContext);
            mListPopupWindow.setAnchorView(actionItem);
            mListPopupWindow.setAdapter(mAdapter);
            mListPopupWindow.setModal(true);
            mListPopupWindow.setContentWidth(150);

            // Display mListPopupWindow on most left of the screen
            mListPopupWindow.setHorizontalOffset(-1000);


            mListPopupWindow.setOnItemClickListener(ListTableViewActionProvider.this);

            mListPopupWindow.show();
            mListPopupWindow.setOnDismissListener(ListTableViewActionProvider.this);
        }
    });

    return actionItem;
}
</code></pre>

<p>"mListPopupWindow.setHorizontalOffset(-1000);" is too bad.
Is there other solutions?</p>
