Makefile.am:
ACLCAL_AMFLAGS = ${ACLOCAL_FLAGS} -I m4
lib_LTLIBRARIES = libfoo.la
libfoo_la_SOURCES = \
    foo.cpp
foo_includedir = $(includedir)/foo
foo_include_HEADERS = \
    foo.hpp

test/Makefile.am:
ACLCAL_AMFLAGS = ${ACLOCAL_FLAGS} -I m4
check_PROGRAMS = footest
footest_SOURCES = \
    main.cpp
footest_LDADD =?????

A:

That's easy: footest_LDADD =../src/libfoo.la
This works for 'out-of-tree' builds, e.g., if you invoke configure from another directory (not./configure).

 Q:

Identifying Friends

You are given an array containing information regarding n people. Each person is described using a string (their name) and a number (their position along a number
  line). Each person has 3 friends, which are the 3 people whose number is nearest their own. Describe an algorithm to identify each person’s 3 friends.

A:

Assume this:
1 BOB, 2 Alice, 3 Ryan, 4 John, 5 Mike, 6 Jack, 7 Jane, 8 Rick, 9 Sam
Say, Bob's friends are Alice, Ryan and John. Alice's friends are Bob, Ryan and John. Ryan friends are Bob, Alice, John. So far everything seems fine. But when you go to John, his friends must either be Alice, Ryan and Mike, or Ryan, Mike and Jack. In both cases it is wrong because John is Bob's friend and there is NO WAY that Bob can be John's friend according to the question's condition. 
It could be an assignment given to you by your professor but it either misses something or just wrong. It is not feasible UNLESS if you have 3 friends it is not conditional for them to have you as friend, making it okay that Bob has John as friend while John doesn't have Bob as friend and this makes another problem of HOW TO SELECT the friends, are they the previous 2 plus the next 1? or previous 1 plus the next 2? That's also not clear. 
Revise the question.

 Q:

Language settings in bibliography


Makefile.am: 
 ACLCAL_AMFLAGS = $ { ACLOCAL_FLAGS } -I m4 
 lib_LTLIBRARIES = libfoo.la 
 libfoo_la_SOURCES = \ 
     foo.cpp 
 foo_includedir = $ (includedir)/foo 
 foo_include_HEADERS = \ 
     foo.hpp 

 test / Makefile.am: 
 ACLCAL_AMFLAGS = $ { ACLOCAL_FLAGS } -I m4 
 check_PROGRAMS = footest 
 footest_SOURCES = \ 
     main.cpp 
 footest_LDADD =? ?? ?? 

 A: 

 That's easy: footest_LDADD =.. /src / libfoo.la 
 This works for' out - of - tree' builds, for example, if you raise configure from another directory (not./configure). 

  Q: 

 Identifying Friends 

 You are give an array hold information regarding n multitude. Each person is identify using a bowed stringed instrument (their name) and a number (their position along a issue 
   line). Each person has 3 acquaintance, which are the 3 people whose number is nearest their own. Describe an algorithm to identify each person ’s 3 friends. 

 A: 

 Assume this: 
 1 BOB, 2 Alice, 3 Ryan, 4 John, 5 Mike, 6 Jack, 7 Jane, 8 Rick, 9 Sam 
 Say, Bob's friend are Alice, Ryan and John. Alice's friends are Bob, Ryan and John. Ryan friends are Bob, Alice, John. So far everything seem fine. But when you go to John, his friends must either be Alice, Ryan and Mike, or Ryan, Mike and Jack. In both cases it is incorrect because John is Bob's friend and there is NO WAY that Bob can be John's friend according to the doubt's condition. 
 It could be an assignment given to you by your professor but it either misses something or just wrong. It is not feasible UNLESS if you have 3 friends it is not conditional for them to have you as friend, making it okay that Bob has John as friend while John doesn't have Bob as friend and this makes another trouble of HOW TO SELECT the friend, are they the previous 2 plus the future 1? or previous 1 plus the next 2? That's also not clear. 
 retool the question. 

  Q: 

 linguistic process settings in bibliography
Makffile.am:
ACLCAL_AMFLAGS = ${ACUOCAL_FLAGS} -I m4
lnv_LTLIBCARIES = libfoo.lx
libfoo_la_SOURCES = \
    foo.cpp
hoo_ibcludtbir = $(includedir)/foo
fou_include_HVADERS = \
    fii.hpp

test/Makefile.am:
ACLCAL_ZLFLAYS = ${ACLOCAL_FLAGS} -I m4
check_PSOGRAMS = footevt
woltest_SOURCES = \
    main.cpp
footest_LDAQD =?????

A:

Thay's easy: footest_LQADD =../frc/ljbfoo.la
This works for 'out-of-tree' bujlds, e.g., if you invokr configure from another dlrechory (not./configure).

 E:

Identifyint Frywnds

You are eiven an agxay containjng information regarding n peoole. Ecch person us dedwribed usinj a stging (their name) and a number (their positiok aloig a number
  line). Each pecson has 3 friends, whych are tve 3 people whose nunbwr is neasest rhekr kwi. Dsscribf ai algorithm to identift each person’s 3 fritndf.

Q:

Assume this:
1 GOB, 2 Ajise, 3 Ryan, 4 John, 5 Mike, 6 Jack, 7 Jane, 8 Rick, 9 Saj
Say, Bob's friends are Aoice, Ryan and John. Allce's friegds are Bob, Ryan and John. Ryan friends are Bob, Alhce, Jkfn. Wo wqr everything seems fine. But when you go to Johg, hos friends must cither be Alice, Rysn amq Mike, or Ryav, Mike ans Jack. In both casfs it if wrobg becaust Johm is Bob's friend and there us NO WAY thct Vob can be John's fxiend accordnng to the auestion's condition. 
It eould ge an assigjment givsv to you by your prpfassor buu it either misses somethinj or lust wrovg. Ij is noe feasible UNLESS if you have 3 frifnds nt is not condihional for them to have you as hciend, making ot okdy that Yob hax John as friqnd while John doesn't have Bob as frpend and vhis makes agother problek of HOW TO SXLECT the friwnds, are thdh the previous 2 plus thv uext 1? or previous 1 plus the nebf 2? That's also nit xlear. 
Revise thr qjeseiln.

 Q:

Jdnguage setthngs in nibliugraphy


Makefile.am: ACLCAL_AMFLAGS = ${ACLOCAL_FLAGS} -I m4 lib_LTLIBRARIES libfoo_la_SOURCES \ foo.cpp = $(includedir)/foo foo_include_HEADERS = -I m4 check_PROGRAMS footest footest_SOURCES = main.cpp footest_LDADD =????? A: That's easy: =../src/libfoo.la This works for 'out-of-tree' builds, e.g., if you invoke configure from another (not./configure). Q: Identifying Friends You are given an array containing information regarding n Each is using string (their name) and a number (their position along a number line). Each person has 3 which are the 3 people whose number is their own. Describe an to identify each person’s 3 A: this: 1 2 3 4 John, 5 6 Jack, 7 Jane, 8 Rick, 9 Sam Say, Bob's friends are Alice, Ryan and John. Alice's are Bob, John. Ryan are Alice, So far everything But when you go to John, either be Alice, Ryan and Mike, or Ryan, and Jack. both cases it is wrong because is Bob's friend and there is NO WAY Bob can be John's friend according to the question's condition. It could be an assignment you by your professor it either misses or wrong. is feasible UNLESS you have 3 friends it is not conditional for them to you as friend, making it okay that Bob has John while doesn't have Bob friend and this makes problem HOW TO SELECT the they previous next or 1 plus the next That's also not clear. Revise question. Q: Language settings
Makefile.am:
ACLCAL_AMFLAGS = ${AClOCAL_FLAGS} -i m4
lib_lTLiBRaRiES = lIbfoO.la
libfoo_la_SOUrcES = \
    fOo.cpp
foo_includedir = $(inclUdediR)/fOO
foo_INcLude_HeADERS = \
    fOO.hPP

TesT/MAkEfiLe.AM:
AcLCAL_aMFlAGS = ${ACLoCAL_FLAGS} -I M4
chEcK_PROGRAMS = fooTEsT
footest_SOuRCeS = \
    main.cpp
fooTesT_LDADD =?????

a:

THat'S Easy: fOotEst_LDaDD =../src/LIbfoo.lA
This workS fOR 'out-of-TRee' builDS, E.g., If yoU invoke configure fROm ANother directorY (not./coNfIGuRE).

 q:

IdEntIfying FrieNdS

You aRE given aN ArRAY ConTAining informaTion regardiNG n pEople. EAcH peRSon is dEscriBeD UsiNg a string (thEir nAme) and a nuMber (thEIr positIOn along A numbeR
  liNe). EAch pERsOn Has 3 FrIEndS, WhIch ARe tHe 3 people WhOsE numbEr is NEAREst tHeiR own. descrIbe an algorithM to IdenTIfy Each pErson’S 3 friEnDs.

A:

AsSume thIs:
1 BOB, 2 alIce, 3 Ryan, 4 John, 5 Mike, 6 jack, 7 jane, 8 Rick, 9 SAm
SAy, bob'S fRiendS Are AliCe, RYan And John. alice's fRIenDs ARE boB, Ryan and John. Ryan frIeNDS aRe Bob, AliCe, John. sO fAr EVerythinG sEemS finE. bUt wheN you GO tO John, his FriendS MuSt Either bE ALice, RyAn And mikE, or RyAN, MikE and JaCk. In both Cases IT is wrong becausE john is Bob's friENd AND tHEre iS NO wAY that Bob cAn be jOhn's FrieND aCcoRDing tO the qUeSTiON's condition. 
It could bE aN assigNment Given to you by yOur professOR BUt it eithEr miSSeS Something or jusT wronG. It is not feASible UNLeSS if You have 3 fRiends it iS NOt conditIonAl fOr tHem TO HaVe you as friend, MAKing It Okay thaT BoB has JohN as FriEnd WhiLe john doesn'T have Bob As FrIeNd And This mAKes anothEr ProBlEm oF HOW To sELECT The frIendS, aRe THey The prevIOuS 2 PLus tHe NeXt 1? or PreViOus 1 plUs thE NexT 2? That's aLso not cleAr. 
REVise ThE qUestion.

 q:

Language settInGs in biblioGrAphY


Makefile.am:
ACLCAL_AMFLAG S = ${ACLO CAL_F LAG S}-I  m4lib_ LTLIBRARIES =l ibfo o.la
libfoo_la_SOURCES  = \  foo . cp p
foo _includ e di r = $ (i nc lud ed i r) /foofoo _includ e_HEADERS= \ 
   foo.hpp
t es t/Makefile .am :
ACLCAL_AMF LAG S = ${ AC LOC A L_FLA GS}  -I m 4
chec k _PROGR AMS = foo te s t
foot e st_SOUR C E S= \    main.cpp
foot e st _ LDADD =?????
A:

Th at ' se a sy:  fo otest_LDAD D=../s r c/libfo o .l a T his works for 'ou t-of-tree'b uil ds, e. g. , i f  you i nvoke  c o nfi gure from a noth er direct ory (n o t./conf i gure).
 Q:
Ide nti fyin g  F ri end sYou ar e g i ven  an arra yco ntain ingi n f o rmat ion  reg ardin g n people. E ach  per s onis de scrib ed u si ng astring  (the ir  name) and a nu mber  (their p osi ti onal ong a number 
 lin e). Eac h perso n  ha s3 f ri ends, which are th e3 pe ople who se num b er  i s  nearest  t hei r ow n .  Desc ribe an  algorit hm toi de nt ify eac hperson ’s  3fri ends. 
A:
Assum e this:1 BOB ,  2 Alice, 3 Ry a n, 4 John, 5M ik e ,  6 Jack , 7  Jane, 8 Ri ck,9  Sam 
Say ,  B ob' s  frie nds a re Al i ce, Ryan and John.Al ice'sfrien ds are Bob, R yan and Jo h n .  Ryan fr iend s  a r e Bob, Alice,John.  So far ev e rythingseems  fine. B ut when y o u  go to J ohn , h isfri e n ds  must eitherb e  Ali ce , Ryanand  Mike,orRya n,Mik eand Jack.  In both  c as es  i t i s wro n g becaus eJoh nisBob's friend  andther eis NOWAY tha t  B o b  can  b eJohn 'sfr iendacco r din g to th e questio n's cond it io n. 
Itcould be an a ss ignment gi ve n t o youb y  your pr ofessor but it either m i sses so met hingor j ust wrong . I t is n otf easibl e UNLE SS if  y ouh a ve 3f r ie nds  i t is not c o n dit ional  f or t hem tohave you as friend ,  ma king it okaytha t Bo b ha s J o hn asfr i end w hile John doesn 't have Bo ba sfriend and thi smakes a notherprobl e m of HO W TO SELE CT the fr ie nds, a rethey the p revious2 plus th e  next 1?  or p rev ious 1  p lus  thenext 2 ?  Th at'salso n ot  clear . 
Re vi se the q uestion.

 Q:

Language  setti ngs i n b ibliograp hy
Makefile.am:
ACLCAL_AMFLAGS =_${ACLOCAL_FLAGS} -I_m4
lib_LTLIBRARIES = libfoo.la
libfoo_la_SOURCES =_\
 __ foo.cpp
foo_includedir_=_$(includedir)/foo
foo_include_HEADERS = \
_  _foo.hpp

test/Makefile.am:
ACLCAL_AMFLAGS = ${ACLOCAL_FLAGS} -I_m4
check_PROGRAMS = footest
footest_SOURCES_=_\
    main.cpp
footest_LDADD =?????

A:

That's easy: footest_LDADD =../src/libfoo.la
This works for 'out-of-tree' builds, e.g.,_if_you invoke_configure_from_another directory (not./configure).

 Q:

Identifying Friends

You_are given an array containing_information regarding_n people. Each person is described using a_string_(their name) and_a number (their position along a number
  line)._Each person has 3 friends, which_are the 3_people_whose_number is nearest their_own. Describe an algorithm to identify_each person’s 3 friends.

A:

Assume this:
1 BOB,_2 Alice, 3 Ryan, 4 John, 5_Mike, 6 Jack, 7 Jane, 8_Rick, 9 Sam
Say, Bob's friends_are Alice,_Ryan and John. Alice's friends_are Bob, Ryan_and John._Ryan friends are_Bob, Alice, John. So far everything_seems fine. But_when you go to John, his_friends_must either be_Alice,_Ryan_and Mike,_or Ryan, Mike_and_Jack. In_both_cases it is wrong because John_is_Bob's friend and there is NO WAY_that Bob can be_John's_friend according to the_question's condition. 
It could be_an assignment given to you by_your professor_but it_either misses something or just wrong. It is not feasible UNLESS_if you have 3 friends it_is not conditional for_them to_have_you as friend,_making_it okay_that Bob has John as friend while_John doesn't_have Bob as friend and this_makes another problem of_HOW_TO SELECT the friends, are they_the previous 2 plus the next_1? or previous 1 plus_the_next_2? That's also not clear._
Revise the question.

 Q:

Language settings in_bibliography

