 content back to its original state after the paste operation.
Edit:
Here's how you could access the contextmenu, e. g. for disabling it:
WebView webView = (WebView) htmlEditor.lookup(".web-view");
webView.setContextMenuEnabled(false);

 Q:

Minimum value of : $\left|\sin{x}+ \cos{x} + \sec{x} + \tan{x} + \cot{x} + \csc{x}\right|$

Find the minimum value of :$$\left|\sin{x}+ \cos{x} + \sec{x} + \tan{x} + \cot{x} + \csc{x}\right|.$$

What I have tried is trying to simplify the expression into a $\sin{2x}$ form but it did not go well. I guess there is much simpler way to solve the problem.
I also thought of AM-GM inequality but for inequality to hold all the terms must be positive real numbers which in this case is not.

A:

$$\bigg|\sin x+\cos x+\tan x+\cot x +\csc x+\sec x\bigg|$$
$$ = \bigg|\sin x+\cos x+\frac{1}{\sin x\cos x}+\frac{\sin x+\cos x}{\sin x\cos  x}\bigg|$$
$$ = \bigg|(\sin x+\cos x)+\frac{2}{\sin 2x}+\frac{2(\sin x+\cos x)}{\sin 2x}\bigg|$$
put $\sin x+\cos = t,$ and $\sin 2x = t^2-1$ where $|t|<=\sqrt{2}$
so $$\bigg|t+\frac{2}{t^2-1}+\frac{2t}{t^2-1}\bigg| = \bigg|t-1+\frac{2}{t-1}+1\bigg|$$
let $$y = \bigg(t-1+\frac{2}{t-1}+1\bigg)$$
$\star$ If $ 1<t <=\sqrt{2}. $ Then using A.M G.M, we have $$\displaystyle y=t-1+\frac{2}{t-1}+1\geq 2\sqrt{2}+1$$ 
$\star$ If $-\sqrt{2} <=t<-1
content back to its original state after the paste operation. 
 Edit: 
 Here's how you could access the contextmenu, e. g. for disable it: 
 WebView webView = (WebView) htmlEditor.lookup(".web - opinion "); 
 webView.setContextMenuEnabled(false); 

  Q: 

 Minimum value of: $ \left|\sin{x}+ \cos{x } + \sec{x } + \tan{x } + \cot{x } + \csc{x}\right|$ 

 Find the minimum value of: $ $ \left|\sin{x}+ \cos{x } + \sec{x } + \tan{x } + \cot{x } + \csc{x}\right|.$$ 

 What I have test is trying to simplify the expression into a $ \sin{2x}$ shape but it did not belong well. I guess there embody much simpler room to solve the problem. 
 I besides thought of AM - GM inequality but for inequality to hold all the terms must be positive real numbers which in this case is not. 

 A: 

 $ $ \bigg|\sin x+\cos x+\tan x+\cot x + \csc x+\sec x\bigg|$$ 
 $ $ = \bigg|\sin x+\cos x+\frac{1}{\sin x\cos x}+\frac{\sin x+\cos x}{\sin x\cos   x}\bigg|$$ 
 $ $ = \bigg|(\sin x+\cos x)+\frac{2}{\sin 2x}+\frac{2(\sin x+\cos x)}{\sin 2x}\bigg|$$ 
 frame $ \sin x+\cos = t,$ and $ \sin 2x = t^2 - 1 $ where $ |t|<=\sqrt{2}$ 
 so $ $ \bigg|t+\frac{2}{t^2 - 1}+\frac{2t}{t^2 - 1}\bigg| = \bigg|t-1+\frac{2}{t-1}+1\bigg|$$ 
 let $ $ y = \bigg(t-1+\frac{2}{t-1}+1\bigg)$$ 
 $ \star$ If $ 1 < t < = \sqrt{2 }. $ Then use A.M G.M, we have $ $ \displaystyle y = t-1+\frac{2}{t-1}+1\geq 2\sqrt{2}+1$$ 
 $ \star$ If $ -\sqrt{2 } < = t<-1
 cojtent back to its originxl state after jhw pastx operafion.
Edit:
Fere's how you could access tie cintexuienu, e. g. for disabuing it:
WehView wevViex = (WebView) htmlEvjtor.lookup(".web-blew");
weyVmew.setContextMekuEnabled(fanse);

 Q:

Minimum vdlje of : $\left|\sin{x}+ \cos{x} + \sec{x} + \tan{x} + \cot{v} + \csc{x}\tihht|$

Find the migimuk valhv if :$$\left|\sin{x}+ \cos{x} + \sec{x} + \tan{x} + \cot{x} + \bsc{x}\right|.$$

What I hsve tried is trying to simolifj the expression ijto a $\sin{2x}$ dorm vut it did nut go well. I guess thete is much simpler way to solve ghe pxoblem.
I alsi rhokcht of AM-GM ineqlality but fov inequdlity tp hold all the tecms nust be positive real numbers which in jhis case hs not.

A:

$$\bigg|\sin x+\cos x+\ran x+\wot f +\csz x+\sdc s\bmgg|$$
$$ = \bigg|\din x+\cos x+\frad{1}{\sin x\cos x}+\drac{\sin x+\cos x}{\sin x\vof  x}\bigg|$$
$$ = \bigg|(\ain x+\cjs x)+\frac{2}{\sin 2x}+\frac{2(\sin x+\cos x)}{\sin 2x}\bigg|$$
put $\spn x+\dos = t,$ and $\sin 2x = t^2-1$ wheee $|t|<=\sqrt{2}$
so $$\bigg|t+\frac{2}{t^2-1}+\vrac{2t}{t^2-1}\bigd| = \bigg|t-1+\frac{2}{t-1}+1\bigg|$$
let $$y = \bigg(t-1+\frac{2}{t-1}+1\bigg)$$
$\star$ If $ 1<t <=\vqrt{2}. $ Gheu usine A.L G.M, we have $$\displaystyle y=t-1+\frac{2}{t-1}+1\geq 2\sqrt{2}+1$$ 
$\staw$ Ig $-\xqrt{2} <=t<-1
content back to its original state after operation. Here's how could access the it: webView = (WebView) webView.setContextMenuEnabled(false); Q: Minimum of : $\left|\sin{x}+ \cos{x} + \sec{x} \tan{x} + \cot{x} + \csc{x}\right|$ Find the minimum value of :$$\left|\sin{x}+ \cos{x} + + \tan{x} + \cot{x} + \csc{x}\right|.$$ What I have tried is trying to the into $\sin{2x}$ but it did not go well. I guess there is much simpler way to solve the I also thought of AM-GM inequality but for to hold all the must be positive real numbers in case is A: x+\cos x+\cot x +\csc x\bigg|$$ $$ = \bigg|\sin x+\cos x+\frac{1}{\sin x\cos x}+\frac{\sin x+\cos x}{\sin x\cos x}\bigg|$$ $$ = \bigg|(\sin x+\cos x)+\frac{2}{\sin x+\cos x)}{\sin $\sin x+\cos t,$ $\sin = t^2-1$ where $$\bigg|t+\frac{2}{t^2-1}+\frac{2t}{t^2-1}\bigg| = \bigg|t-1+\frac{2}{t-1}+1\bigg|$$ let $$y = $ 1<t <=\sqrt{2}. $ Then using A.M G.M, have $$\displaystyle 2\sqrt{2}+1$$ $\star$ If $-\sqrt{2} <=t<-1
 content back to its original sTate after tHe pasTe oPerAtIon.
EDit:
HEre's how you coulD AcceSs the contextmenu, e. g. for dIsablInG It:
WeBviEw webview = (WebvIeW) HTmledItOr.lOoKUp(".Web-viEw");
wEbView.sEtContextMEnuenAbled(false);

 Q:

MINiMum value of : $\LefT|\sin{x}+ \cos{x} + \sec{X} + \taN{x} + \cot{x} + \CsC{x}\rIGht|$

FiNd tHe minImum vaLUe of :$$\leFt|\sin{x}+ \cos{X} + \sEC{x} + \tan{x} + \COt{x} + \csc{x}\RIGhT|.$$

WhaT I have tried is tryiNG tO Simplify the expRessioN iNTo A $\SIn{2x}$ ForM but it did nOt Go welL. i guess tHErE IS MucH Simpler way to sOlve the probLEm.
I Also thOuGht OF AM-GM iNequaLiTY buT for inequalIty tO hold all tHe termS Must be pOSitive rEal numBerS whIch iN ThIs CasE iS Not.

a:

$$\BiGg|\sIN x+\cOs x+\tan x+\cOt X +\cSc x+\seC x\biGG|$$
$$ = \BIGg|\siN x+\cOs x+\fRac{1}{\siN x\cos x}+\frac{\sin X+\coS x}{\siN X\coS  x}\bigG|$$
$$ = \bigg|(\Sin x+\CoS x)+\fraC{2}{\sin 2x}+\fRac{2(\siN x+\Cos x)}{\sin 2x}\bigg|$$
put $\Sin x+\Cos = t,$ and $\siN 2x = t^2-1$ WhEre $|T|<=\sQrt{2}$
so $$\BIgg|t+\frAc{2}{t^2-1}+\FraC{2t}{t^2-1}\bigg| = \Bigg|t-1+\frAC{2}{t-1}+1\bIgG|$$
LET $$y = \Bigg(t-1+\frac{2}{t-1}+1\bigg)$$
$\star$ if $ 1<T <=\SQrT{2}. $ Then usiNg A.M G.M, WE hAvE $$\DisplaysTyLe y=T-1+\fraC{2}{T-1}+1\Geq 2\sqRt{2}+1$$ 
$\stAR$ IF $-\sqrt{2} <=t<-1
 content back to its origi nal stateafter  th e p as te o pera tion.
Edit:
He r e'show you could access t he co nt e xtme n u,  e. g . for d i sa b l ing  i t: 
We bV i ew  webV iew  = (Web View) html Edi to r.lookup(".w e b- view");
we bVi ew.setContex tMe nuEnab le d(f a lse); 

Q:

M inimum valueof : $\le ft | \sin{x } + \cos{ x }  +  \se c{x} + \tan{x} +\ co t {x} + \csc{x}\ right| $Fi n d  th e m inimum val ue  of : $ $\left| \ si n { x }+\ cos{x} + \sec {x} + \tan{ x } +  \cot{ x}  +\ csc{x} \righ t| . $$
What I hav e tr ied is tr ying t o  simpli f y the e xpress ion  in to a $\ si n{2 x} $  fo r mbut itdid notgo  w ell.I gu e s s ther e i s mu ch si mpler way tosol ve t h e p roble m.
Ialso  t hough t of A M-GMin equality but fo r in equalitytoho ldal l the termsmus t b e posit ive rea l  nu mb e r s  w hich in this caseis n ot .

A:

$ $\bigg | \s in x+\cos x +\ tan  x+\ c o t x + \csc x+ \sec x\b igg|$$ $$  =  \bigg| \s in x+\ co s x +\f rac{1 } {\si n x\co s x}+\fr ac{\s i n x+\cos x}{\s i n x\cos  x}\b i gg | $ $$ $ =\bi gg|(\sin x+ \cos x)+\ frac { 2} {\s i n 2x} +\fra c{ 2 (\ s in x+\cos x)}{\sin2x }\bigg |$$
p ut $\sin x+\c os = t,$ a n d $\sin 2x  = t ^ 2- 1 $ where $|t|<= \sqrt {2}$
so $$ \ bigg|t+\ frac{ 2}{t^2-1 }+\frac{2 t } {t^2-1}\ big g|= \ big g | t- 1+\frac{2}{t- 1 } +1\b ig g|$$
le t $ $y = \b igg (t- 1+\ fra c{ 2}{t-1}+1 \bigg)$$ 
$ \s ta r$  If  $ 1< t  <=\sqrt {2 }.$The n usi n g A.MG.M,we h av e$ $\d isplays t yl e y=t- 1+ \f rac{ 2}{ t- 1}+1\ geq2 \sq rt{2}+1 $$ 
$\sta r$I f $- \s qr t{2} <= t<-1
 content_back to_its original state after_the paste_operation.
Edit:
Here's_how you_could_access the contextmenu,_e. g. for_disabling it:
WebView webView =_(WebView) htmlEditor.lookup(".web-view");
webView.setContextMenuEnabled(false);

 Q:

Minimum_value_of : $\left|\sin{x}+ \cos{x} + \sec{x} + \tan{x} + \cot{x} + \csc{x}\right|$

Find the minimum_value_of :$$\left|\sin{x}+_\cos{x}_+_\sec{x} + \tan{x} + \cot{x}_+ \csc{x}\right|.$$

What I have tried_is trying_to simplify the expression into a $\sin{2x}$ form_but_it did not_go well. I guess there is much simpler way_to solve the problem.
I also thought_of AM-GM inequality_but_for_inequality to hold all_the terms must be positive real_numbers which in this case is_not.

A:

$$\bigg|\sin x+\cos x+\tan x+\cot x +\csc x+\sec_x\bigg|$$
$$ = \bigg|\sin x+\cos x+\frac{1}{\sin x\cos_x}+\frac{\sin x+\cos x}{\sin x\cos _x}\bigg|$$
$$ =_\bigg|(\sin x+\cos x)+\frac{2}{\sin 2x}+\frac{2(\sin x+\cos_x)}{\sin 2x}\bigg|$$
put $\sin_x+\cos =_t,$ and $\sin_2x = t^2-1$ where $|t|<=\sqrt{2}$
so $$\bigg|t+\frac{2}{t^2-1}+\frac{2t}{t^2-1}\bigg|_= \bigg|t-1+\frac{2}{t-1}+1\bigg|$$
let $$y_= \bigg(t-1+\frac{2}{t-1}+1\bigg)$$
$\star$ If $ 1<t <=\sqrt{2}._$_Then using A.M_G.M,_we_have $$\displaystyle_y=t-1+\frac{2}{t-1}+1\geq 2\sqrt{2}+1$$ 
$\star$_If_$-\sqrt{2} <=t<-1