 draw
2 - if you think the away team will win

Lets say we have the following soccer match with the following betting quotes:
Kansas City vs. Portland - 1 = 1.92, X = 3.57, 2 = 5.00
This means: If you think Portland (In the opinion of the bookie, the underdog) will win the match, you bet on 2
Example (I bet \$100): In case Portland wins I win \$400
$$100*5.00-100 = 400$$
$$stake*quote-stake = net win$$
(When Portland loses the match, or it ends in a draw, I'll lose my stake)
Now, some bookies offer a so-called double chance bet. This kind of bet takes one possibility out. That leaves you to following bets. You bet

1/X - if you think the home team will win or the match ends in a draw
X/2 - if you think the away team will win or the match ends in a draw

This variant is perfect if you think Portland will win the match, or at least it will end up in a draw. To calculate this quotes I use the following formula: (Q1 = 1st quote 1, Q2 = 2nd quote)
$$ 1/(1/Q1+1/Q2) $$
For the 1/X bet
$$ 1/(1/1.92+1/3.57) = 1.25 $$
For the X/2 bet
$$ 1/(1/3.57+1/5) = 2.08 $$
Now comes my math problem: When the bookie does not offer a double chance bet, I want to create it my self: With two single bets. For the Kansas City vs. Portland bet I'd like to place a X/2 bet. The quote for the bet is as I showed before 2.08. I want to place \$100 on it. When I win the bet, I'll get \$108 net win:
$$100*2.08-100 = 108$$
How do I have to split the money on two (X and 2) single bets, to win \$108, when Portland wins or the match ends in a draw?
I got to the solution for this case by trying out. But with the result in my hand, I still don't get the formula to calculate it.
I bet \$
draw 
 2 - if you think the away team will win 

 Lets suppose we take the following soccer match with the following bet quotes: 
 Kansas City vs. Portland - 1 = 1.92, X = 3.57, 2 = 5.00 
 This means: If you intend Portland (In the impression of the bookie, the underdog) will acquire the match, you bet on 2 
 exercise (I bet \$100 ): In case Portland acquire I succeed \$400 
 $ $ 100 * 5.00 - 100 = 400$$ 
 $ $ stake*quote - stake = net win$$ 
 (When Portland loses the match, or it ends in a drawing card, I'll lose my stake) 
 Now, some bookmaker offer a so - call bivalent chance bet. This kind of bet takes one possibility out. That leaves you to follow bets. You bet 

 1 / X - if you think the home team will succeed or the match ends in a draw 
 X/2 - if you think the away team will win or the match ends in a draw 

 This variant is perfect if you remember Portland will win the match, or at least it will end up in a hook. To count this quotes I use the following formula: (Q1 = 1st quote 1, Q2 = 2nd quote) 
 $ $ 1/(1 / Q1 + 1 / Q2) $ $ 
 For the 1 / ten bet 
 $ $ 1/(1/1.92 + 1/3.57) = 1.25 $ $ 
 For the X/2 bet 
 $ $ 1/(1/3.57 + 1/5) = 2.08 $ $ 
 Now comes my mathematics problem: When the bookie does not offer a double chance bet, I want to create it my self: With two single bets. For the Kansas City vs. Portland bet I'd like to invest a X/2 bet. The quotation mark for the bet is as I showed before 2.08. I want to place \$100 on it. When I win the stake, I'll get \$108 net win: 
 $ $ 100 * 2.08 - 100 = 108$$ 
 How do I have to split the money on two (X and 2) single bets, to win \$108, when Portland succeed or the match end in a draw? 
 I got to the solution for this event by trying out. But with the consequence in my hand, I however don't get the rule to calculate it. 
 I bet \$
 drww
2 - if you think the awan team will win

Lgtw say xe have the foluowing soccer match with the fillowung betting quotes:
Kansxs City vd. Portlabd - 1 = 1.92, X = 3.57, 2 = 5.00
Thma means: If yoh thiuk Portland (In tme opinion mf the bookie, dhd bnderdog) will win the match, you bet jn 2
Examllf (I bet \$100): In cafe Ppwtlahd wins I win \$400
$$100*5.00-100 = 400$$
$$stake*quote-stake = nst win$$
(Wien Portland loxes the match, or it ends ij a fraw, I'll lose my shake)
Now, somg bojjies offer a so-called double chancg bet. This kind of bet takes one possnbility out. Tyat neaves you vo foljowing bets. Npu bet

1/F - if ypu think the hpme teqm will win or the mavch ends in a draw
X/2 - if you tviuk the away team will wun or the matzy evds ii a draw

Tjis variant ia perfect id you think Portlanc rpkl win the mztch, ow wt least it will end up in a draw. To cancumate this quotes I use rhe following formula: (Q1 = 1st qujte 1, Q2 = 2nd quote)
$$ 1/(1/Q1+1/Q2) $$
For the 1/X bet
$$ 1/(1/1.92+1/3.57) = 1.25 $$
For the X/2 bed
$$ 1/(1/3.57+1/5) = 2.08 $$
Iod cimcs mh mwth problem: When the bookie does not offer a qkunlv chance bet, I wakt to create it my sflg: With two sinele beca. Ror the Kansas Citj vs. Pottland bet I'd lyke yo place a X/2 bet. The quote dor the bet ps aw I showed before 2.08. I want to 'lace \$100 on iy. When I win the bet, I'lu gef \$108 net win:
$$100*2.08-100 = 108$$
How do I fave to split thd mpnay on two (X and 2) single bees, to win \$108, whzn Portlxnd eins ow the matcj ends in a draw?
I got to the donution for this case by trying out. But wivi the result on my hand, I ftill don't get the formula to cakculate it.
I cet \$
draw 2 - if you think the will Lets say have the following betting Kansas City vs. - 1 = X = 3.57, 2 = 5.00 means: If you think Portland (In the opinion of the bookie, the underdog) win the match, you bet on 2 Example (I bet \$100): In case wins win $$100*5.00-100 400$$ $$stake*quote-stake = net win$$ (When Portland loses the match, or it ends in a draw, lose my stake) Now, some bookies offer a double chance bet. This of bet takes one possibility That you to bets. bet - if you the home team will win or the match ends in a draw X/2 - if you think away team or the ends a This variant is you think Portland will win the least it will end up in a draw. calculate this I use the following formula: (Q1 1st quote 1, Q2 = 2nd quote) $$ $$ For the 1/X bet $$ 1/(1/1.92+1/3.57) = 1.25 $$ For the X/2 bet $$ 2.08 $$ Now comes math problem: When bookie not a chance bet, want to create it my self: With two single bets. For Kansas City vs. Portland bet I'd like to place a The for the bet as I showed before I to place \$100 on I the \$108 win: = 108$$ How do have to split the money two (X and 2) when Portland wins or the match ends in draw? I got to the solution for case by trying out. But with the result in my hand, I don't get to calculate it. I bet \$
 draw
2 - if you think the away team Will win

LetS say wE haVe tHe FollOwinG soccer match wiTH the Following betting quotes:
kansaS CITy vs. pOrTland - 1 = 1.92, x = 3.57, 2 = 5.00
This meANs: iF You ThInK PoRtLAnD (In thE opInion of The bookie, tHe uNdErdog) will win THe Match, you beT on 2
example (I bet \$100): IN caSe PortLaNd wINs I wiN \$400
$$100*5.00-100 = 400$$
$$stAke*quOte-staKE = net wiN$$
(When PortLaND loses THe match, OR It Ends In a draw, I'll lose my sTAkE)
now, some bookies Offer a So-CAlLED doUblE chance bet. thIs kinD Of bet taKEs ONE PosSIbility out. ThaT leaves you tO FolLowing BeTs. YOU bet

1/X - iF you tHiNK thE home team wiLl wiN or the matCh ends IN a draw
X/2 - IF you thiNk the aWay TeaM wilL WiN oR thE mATch ENdS in A DraW

This varIaNt Is perFect IF YOU thiNk POrtlAnd wiLl win the match, Or aT leaST it Will eNd up iN a drAw. to calCulate This qUoTes I use the folloWing Formula: (Q1 = 1sT quOtE 1, Q2 = 2nD qUote)
$$ 1/(1/Q1+1/q2) $$
for the 1/x beT
$$ 1/(1/1.92+1/3.57) = 1.25 $$
FoR the X/2 beT
$$ 1/(1/3.57+1/5) = 2.08 $$
Now comES my MaTH PRoBlem: When the bookie dOeS NOt Offer a doUble chANcE bET, I want to CrEatE it mY SElf: WiTh twO SiNgle bets. for the kAnSaS City vs. poRtland BeT I'd LikE to plACe a X/2 Bet. The Quote for The beT Is as I showed befORe 2.08. I want to placE \$100 On IT. whEN I wiN thE bet, I'll get \$108 nEt wiN:
$$100*2.08-100 = 108$$
how dO I haVE tO spLIt the Money On TWo (x And 2) single bets, to win \$108, wHeN PortlAnd wiNs or the match eNds in a draw?
i GOT to the soLutiON fOR this case by tryIng ouT. But with thE Result in My hanD, I still dOn't get the FORmula to cAlcUlaTe iT.
I bET \$
 draw
2 - if you think the  away team  will  wi n
Le ts s ay w e have the fol l owin g soccer match with th e fol lo w ingb et tingquotes: Ka n s asCi ty  vs .P or tland  -1 = 1.9 2, X = 3.5 7,2= 5.00
Thism ea ns: If you  th ink Portland  (I n theop ini o n ofthe  book ie, th e  under dog) will  w i n them atch, y o u  b et o n 2
Example (I be t  \ $ 100): In casePortla nd wi n s  Iwin  \$400
$$1 00 *5.00 - 100 = 4 0 0$ $ $ $st a ke*quote-stak e = net win $ $
( When P or tla n d lose s the  m a tch , or it end s in  a draw,I'll l o se my s t ake)
No w, som e b ook ieso ff er  aso - cal l ed  do u ble  chancebe t.  This  kin d o f  bet  ta kesone p ossibility ou t.That lea ves y ou to  fol lo wingbets.You b et 

1/X - if youthin k the hom e t ea m w il l win or the  ma tch  ends i n a dra w 
X/ 2- i fyou think the away  t e a mwill win  or th e  m at c h ends i na d rawT his v aria n tis perfe ct ify ou  t hink Po rt land w il l w inthe m a tch,  or at  least i t wil l  end up in a d r aw. To calcul a te t hi s  quo tes  I use thefoll o wing  for m ul a:( Q1 =1st q uo t e1 , Q2 = 2nd quote)
$ $1/(1/Q 1+1/Q 2) $$
For the  1/X bet
$ $ 1 /(1/1.92 +1/3 . 57 )  = 1.25 $$
For  theX/2 bet
$$ 1/(1/3.5 7+1/5 ) = 2.08  $$
Now c o m es my ma thpro ble m:W h en  the bookie d o e s no toffer a  do uble ch anc e b et,  Iwa nt to cre ate it m yse lf :Wit h two single b et s.Fo r t he Ka n sas Ci ty vs . Po rt la n d b et I'dl ik e to p la ce  a X /2be t. Th e qu o tefor the  bet is a s I show ed  b efore 2 .08. I want t oplace \$10 0onit. Wh e n  I win t he bet, I'll get \$108n et win: 
$$ 100*2 .08- 100 = 108 $$How do  Ih ave to  split  themo ney o n two ( Xand  2 ) single b e t s,to wi n\$10 8, when  Portland wins ort hematch ends in  adraw ? Igot to the  s o lut i o n for this case  by trying  o u t.  But witht here sult in  my han d, Is till do n't get t he formul ato c a l cul ate it.
Ibet \$
 draw
2_- if_you think the away_team will_win

Lets_say we_have_the following soccer_match with the_following betting quotes:
Kansas City_vs. Portland -_1_= 1.92, X = 3.57, 2 = 5.00
This means: If you think Portland (In_the_opinion of_the_bookie,_the underdog) will win the_match, you bet on 2
Example_(I bet_\$100): In case Portland wins I win \$400
$$100*5.00-100_=_400$$
$$stake*quote-stake = net_win$$
(When Portland loses the match, or it ends in_a draw, I'll lose my stake)
Now,_some bookies offer_a_so-called_double chance bet. This_kind of bet takes one possibility_out. That leaves you to following_bets. You bet

1/X - if you think_the home team will win or_the match ends in a_draw
X/2 -_if you think the away_team will win_or the_match ends in_a draw

This variant is perfect if_you think Portland_will win the match, or at_least_it will end_up_in_a draw._To calculate this_quotes_I use_the_following formula: (Q1 = 1st quote_1,_Q2 = 2nd quote)
$$ 1/(1/Q1+1/Q2) $$
For the_1/X bet
$$ 1/(1/1.92+1/3.57) =_1.25_$$
For the X/2 bet
$$_1/(1/3.57+1/5) = 2.08 $$
Now comes_my math problem: When the bookie_does not_offer a_double chance bet, I want to create it my self: With_two single bets. For the Kansas_City vs. Portland bet_I'd like_to_place a X/2_bet._The quote_for the bet is as I showed_before 2.08._I want to place \$100 on_it. When I win_the_bet, I'll get \$108 net win:
$$100*2.08-100_= 108$$
How do I have to_split the money on two_(X_and_2) single bets, to win_\$108, when Portland wins or the_match ends in_a draw?
I got to the solution for_this_case by trying out. But with_the_result in my hand, I still_don't_get_the formula to calculate it.
I_bet \$