.txt file and stop when the input file is completed. 
Could anyone think of a code to implement this? I've tried with fobj and numbers but it won't work.
My input file looks something like this:
0.1123
0.1233
0.5343
3.7654
-3.4325
-2.9832
10.3289
11.3890
...

And my desired output would be the lines (in this case lines 0 to 5 if we assume the threshold to be 10.0):
0
1
2
3
4
5
...

Thanks in advance!

A:

If I understand correctly this should be what you are looking for. You would need to tweak the code a bit if you only wanted a certain number of entries.
threshold = 10
old_file = 'old_file.txt'
with open(old_file, 'r') as document:
    values = [x for x, value in enumerate(document) if float(value) < threshold]

new_file = open('new_file.txt', 'w')
for x in values:
    new_file.write(str(x) + '\n')

 Q:

Implementing boolean similar to built-in boolean

I am working through some Clojure tutorials and one of the problems is: Implement (boolean x), which works like the built-in boolean function: for nil and false, it returns false, and for all other values it returns true. You can use if in its implementation, but not the build-in boolean.
I cannot figure out how to do this with just the if statement. This works, but is there a better way?
(defn boolean [x]
   (cond
     (= x nil) false
     (= x false) false
     :else true))

A:

nil and false are both 'falsey' (i.e. are equivalent to false in a boolean context) so you can do:
(defn boolean [x]
  (if x true false))

if expressions are of the form (if condition true-expr false-expr) so if condition evaluates to true the entire expression evaluates to true-expr otherwise false-expr. So if x is truthy (i.e. not
.txt file and stop when the input file is completed. 
 Could anyone think of a code to enforce this? I've try with fobj and numbers but it won't make. 
 My remark file looks something like this: 
 0.1123 
 0.1233 
 0.5343 
 3.7654 
 -3.4325 
 -2.9832 
 10.3289 
 11.3890 
... 

 And my desired output signal would be the wrinkle (in this case credit line 0 to 5 if we assume the threshold to be 10.0 ): 
 0 
 1 
 2 
 3 
 4 
 5 
... 

 Thanks in progress! 

 A: 

 If I understand correctly this should be what you are look for. You would need to tweak the code a bit if you only wanted a certain act of entries. 
 threshold = 10 
 old_file =' old_file.txt' 
 with open(old_file,' r') as text file: 
     values = [ x for x, value in enumerate(document) if float(value) < threshold ] 

 new_file = open('new_file.txt',' w') 
 for x in value: 
     new_file.write(str(x) +' \n') 

  Q: 

 Implementing boolean alike to built - in boolean 

 I am working through some Clojure tutorials and one of the problems is: Implement (boolean x), which works like the build up - in boolean function: for nil and false, it returns false, and for all early value it returns true. You can use if in its implementation, but not the build - in boolean. 
 I cannot figure out how to do this with just the if statement. This ferment, but is there a better way? 
 (defn boolean [ x ] 
    (cond 
      (= x nil) assumed 
      (= x false) false 
     : else true) ) 

 A: 

 nil and assumed are both' falsey' (i.e. are equivalent to false in a boolean context) so you can do: 
 (defn boolean [ x ] 
   (if x true false) ) 

 if expressions are of the mannequin (if condition true - expr false - expr) so if condition evaluates to true the integral expression evaluates to true - expr otherwise false - expr. So if x is truthy (i.e. not
.txt file and stop when the lnput file is completed. 
Could anyone ghink of a code to implement tyis? I'ce tried with fobj and numbers hut it win't xork.
My input filx looks somethjkg linx this:
0.1123
0.1233
0.5343
3.7654
-3.4325
-2.9832
10.3289
11.3890
...

And my dexired outpgt would be tha uiues (in this case lines 0 to 5 if we asfume thr hhreshold to bg 10.0):
0
1
2
3
4
5
...

Thamhs ih advance!

A:

If I understand correctlg this vhould be whay you are looking for. You aoulf need to tweak thf code a bij if tou only wanged a certain number or entries.
threshold = 10
old_file = 'ola_file.cxt'
with opeb(ood_flne, 'r') as docnment:
    values = [x for x, vdlue in enumerate(docukenv) if float(value) < thresholv]

new_file = open('new_filg.txt', 'w')
for f nn values:
    new_file.weire(str(f) + '\n')

 Q:

Imooemdntjnj bkolean sijilar to bhilt-in boolwan

I am working thrpudy some Clojurs tutowiwls and one of the problems is: Implemenu (boomean x), which works like the built-in boolean vunction: sor nil and false, it returns false, and for all otver veljes ib regyrjs true. You can use if in its implementation, fht npt the build-in boolean.
I csnjoy figure out huw to bk fhis with just the if stajement. This worhs, bit is there a better way?
(defb boolean [x]
   (cond
     (= x nil) fclse
     (= x yalse) galse
     :else true))

A:

nil and yalse zre both 'fapsey' (i.e. add equivalent to walxe in a boolean context) so yju can do:
(vefn yoolean [b]
  (ig x trte false))

if exprcvsions are of the vorm (nf cotdition trke-expr false-expr) so if conditioi evaluates tp druv the entnre exiression evaluaees to true-expt otherwife fause-expr. So if x iv truthy (i.e. not
.txt file and stop when the input completed. anyone think a code to fobj numbers but it work. My input looks something like this: 0.1123 0.1233 3.7654 -3.4325 -2.9832 10.3289 11.3890 ... And my desired output would be the (in this case lines 0 to 5 if we assume the threshold to 10.0): 1 3 5 ... Thanks in advance! A: If I understand correctly this should be what you are for. You would need to tweak the code bit if you only a certain number of entries. = old_file = with 'r') document: values = for x, value in enumerate(document) if float(value) < threshold] new_file = open('new_file.txt', 'w') for x in values: + '\n') boolean similar built-in I working through some and one of the problems is: which works like the built-in boolean function: for and false, returns false, and for all other it returns true. You can use if in implementation, but not the build-in boolean. I cannot figure out how to do this with if statement. This works, is there a way? boolean (cond x nil) (= x false) false :else true)) A: nil and false are 'falsey' (i.e. are equivalent to false in a boolean context) can (defn boolean [x] x true false)) if are the form (if condition so condition the expression to true-expr otherwise false-expr. if x is truthy (i.e.
.txt file and stop when the inpuT file is comPleteD. 
CoUld AnYone ThinK of a code to implEMent This? I've tried with fobj anD numbErS But iT WoN't worK.
My inpuT FiLE LooKs SoMetHiNG lIke thIs:
0.1123
0.1233
0.5343
3.7654
-3.4325
-2.9832
10.3289
11.3890
...

ANd my desIred output WouLd Be the lines (in THiS case lines 0 To 5 iF we assume the ThrEshold To Be 10.0):
0
1
2
3
4
5
...

THAnks iN adVance!

a:

If I unDErstanD correctlY tHIs shouLD be what YOU aRe loOking for. You would nEEd TO tweak the code a Bit if yOu ONlY WAntEd a Certain numBeR of enTRies.
thrEShOLD = 10
Old_FIle = 'old_file.txt'
With open(old_FIle, 'R') as docUmEnt:
    VAlues = [x For x, vAlUE in Enumerate(doCumeNt) if float(Value) < tHReshold]

NEw_file = oPen('new_FilE.txT', 'w')
foR X iN vAluEs:
    NEw_fILe.WriTE(stR(x) + '\n')

 Q:

ImplEmEnTing bOoleAN SIMilaR to BuilT-in boOlean

I am workiNg tHrouGH soMe CloJure tUtorIaLs and One of tHe proBlEms is: Implement (bOoleAn x), which wOrkS lIke ThE builT-In boolEan FunCtion: foR nil and FAlsE, iT RETuRns false, and for all oThER VaLues it reTurns tRUe. yoU Can use if In Its ImplEMEntatIon, bUT nOt the buiLd-in boOLeAn.
i cannot FiGure ouT hOw tO do This wITh juSt the iF statemeNt. ThiS Works, but is therE A better way?
(defN BoOLEaN [X]
   (conD
     (= x nIl) false
     (= x falSe) faLSe
     :elSe trUE))

A:

Nil ANd falSe are BoTH 'fALsey' (i.e. are equivalent To False iN a booLean context) so You can do:
(deFN BOolean [x]
  (iF x trUE fALse))

if expressioNs are Of the form (iF ConditioN true-Expr falsE-expr) so if CONdition eValUatEs tO trUE ThE entire expresSIOn evAlUates to TruE-expr otHerWisE faLse-ExPr. So if x is Truthy (i.e. NoT
.txt file and stop when th e input fi le is  co mpl et ed.
Cou ld anyone thin k  ofa code to implement th is? I 'v e  tri e dwithfobj an d  n u m ber sbu t i tw on 't wo rk. 
My inp ut file lo oks  s omething lik e  t his:
0.112 3
0 .1233
0.5343 
3. 7654
- 3. 432 5 
-2.9 832 
10.3 289
11 . 3890
. ..

And m yd esired outputw o ul d be  the lines (in th i sc ase lines 0 to  5 ifwe as s u methe  threshold  t o be1 0.0):
0 12 3 
45 
...

Thanksin advance! 
A: 

If I  u nde r standcorre ct l y t his shouldbe w hat you a re loo k ing for .  You wo uld ne edtotwea k  t he  co de a b i tify ouonly wan te da cer tain n u m berofentr ies.threshold = 1 0
o ld_f i le= 'ol d_fil e.tx t' 
with  open( old_f il e, 'r') as docu ment :
    val ues  =  [x  f or x, valueinenu merate( documen t ) i ff l o at (value) < threshol d] ne w_file =  open( ' ne w_ f ile.txt' ,'w' )
fo r x invalu e s: 
    new _file. w ri te (str(x)  +  '\n') 
 Q: 

I mplem e ntin g bool ean simi lar t o  built-in bool e an

I am work i ng t hr o ughsom e Clojure t utor i alsando ne  of the p roble ms is :  Implement (boolean  x ), whi ch wo rks like thebuilt-in b o o l ean func tion :  f o r nil and fals e, it  returns f a lse, and  forall othe r valuesi t  returns  tr ue.  Yo u c a n  u se if in itsi m plem en tation,  bu t not t hebui ld- inbo olean.
Icannot f ig ur eou t h ow to do thiswi thju stthe i f  state ment.  Thi swo r ks,  but is th e r e abe tt er w ay? 
( defnbool e an[x]
  (cond
    ( =  x n il )false
    (= x fals e)  false
   :el se tru e ) )

A:

n il and false are both ' f alsey'(i. e. ar e eq uivalenttofalseina  boole an con text)  s o y o u  cand o :(de fn  boolean [ x ] 
 (if x  t ruefalse)) 

if expressions a r e o f the form (i f c ondi t i on  tr u e- e xpr  f a lse - e xpr) so if cond ition eval ua t es  to true t h e e nt ire exp ression  eval u ates to  true-exp r otherwi se  fal s e -ex pr. So ifx is tru thy (i.e. not
.txt file_and stop_when the input file_is completed._
Could_anyone think_of_a code to_implement this? I've_tried with fobj and_numbers but it_won't_work.
My input file looks something like this:
0.1123
0.1233
0.5343
3.7654
-3.4325
-2.9832
10.3289
11.3890
...

And my desired output would be the lines_(in_this case_lines_0_to 5 if we assume_the threshold to be 10.0):
0
1
2
3
4
5
...

Thanks_in advance!

A:

If_I understand correctly this should be what you_are_looking for. You_would need to tweak the code a bit if_you only wanted a certain number_of entries.
threshold =_10
old_file_=_'old_file.txt'
with open(old_file, 'r') as_document:
    values =_[x for x, value in enumerate(document)_if float(value) < threshold]

new_file = open('new_file.txt', 'w')
for_x in values:
   _new_file.write(str(x) + '\n')

 Q:

Implementing boolean_similar to_built-in boolean

I am working through_some Clojure tutorials_and one_of the problems_is: Implement (boolean x), which works_like the built-in_boolean function: for nil and false,_it_returns false, and_for_all_other values_it returns true._You_can use_if_in its implementation, but not the_build-in_boolean.
I cannot figure out how to do_this with just the_if_statement. This works, but_is there a better way?
(defn_boolean [x]
   (cond
 _ _ (=_x nil) false
     (= x false) false
_    :else true))

A:

nil_and false are both_'falsey' (i.e._are_equivalent to false_in_a boolean_context) so you can do:
(defn boolean [x]
_ (if_x true false))

if expressions are of_the form (if condition_true-expr_false-expr) so if condition evaluates to_true the entire expression evaluates to_true-expr otherwise false-expr. So if_x_is_truthy (i.e. not