
template <class T>
void LinkedList<T>::deleteHead()
{
    if (head!= NULL) { // as long as head is not null, delete head
        ListItem<T> *current = head;
        head = head->next;
        current->next = NULL;
        head->prev = NULL;
    } else {return;} // if head is null, end the function without doing anything
}

// Delete Tail Node
template <class T>
void LinkedList<T>::deleteTail()
{
    ListItem<T> *tail = getTail();
    tail = tail->prev;
    tail->next->prev = NULL;
    tail->next = NULL;
}

A:

Got the answer right. This was a question in my Data Structures assignment. Here's the code I implemented. Yes, i'm aware it has redundancies and inefficiencies but I had to work within the framework of the assignment.
This is my deleteElement() Function:
template <class T>
void LinkedList<T>::deleteElement(T item)
{
    ListItem<T>* current = head;
    ListItem<T>* temp;
    if (head == NULL) {                // if list is empty end the function
        return;
    }
    while (current) {
        if (current->value == item) {
            if (current == head) {              // if item is in the head
                deleteHead();
            }
            else if (current == getTail()) {    // if item is in the tail
                deleteTail();
            }
            else if (current!= head && current!= getTail()) { 
            // if item is between two nodes
                temp = current;
                temp->prev->next = temp->next;
                temp->next->prev = temp->prev;
                current->next = NULL;
                current->prev = NULL;
                if (current->next == NULL) {
                    deleteTail();
                }
            }
        }
        current = current->next;
    }
}

 Q:

Simple way to reverse dask distributed dataframe

I tried to reverse the order of a dask dataframe using [::-1], but
template < class T > 
 void LinkedList < T>::deleteHead () 
 { 
     if (head!= NULL) { // as long as capitulum is not null, delete heading 
         ListItem < T > * current = head; 
         head = head->next; 
         current->next = NULL; 
         head->prev = NULL; 
     } else { return; } // if fountainhead is null, end the function without doing anything 
 } 

 // Delete Tail Node 
 template < course T > 
 void LinkedList < T>::deleteTail () 
 { 
     ListItem < T > * tail = getTail (); 
     chase = tail->prev; 
     tail->next->prev = NULL; 
     tail->next = NULL; 
 } 

 A: 

 Got the solution right. This was a question in my Data Structures assignment. Here's the code I implemented. Yes, i'm mindful it has redundancies and inefficiency but I had to shape within the model of the assignment. 
 This is my deleteElement () Function: 
 template < class deoxythymidine monophosphate > 
 void LinkedList < T>::deleteElement(T item) 
 { 
     ListItem < T > * current = drumhead; 
     ListItem < T > * temp; 
     if (head = = NULL) {                 // if tilt is empty end the function 
         rejoinder; 
     } 
     while (current) { 
         if (current->value = = item) { 
             if (current = = head) {               // if item is in the fountainhead 
                 deleteHead (); 
             } 
             else if (current = = getTail ()) {     // if item is in the tail 
                 deleteTail (); 
             } 
             else if (current!= head & & current!= getTail ()) { 
             // if item is between two nodes 
                 temp = current; 
                 temp->prev->next = temp->next; 
                 temp->next->prev = temp->prev; 
                 current->next = NULL; 
                 current->prev = NULL; 
                 if (current->next = = NULL) { 
                     deleteTail (); 
                 } 
             } 
         } 
         current = current->next; 
     } 
 } 

  Q: 

 childlike way to reverse dask distributed dataframe 

 I tried to reverse the order of a dask dataframe using [:: -1 ], but

temolate <class T>
void LinkedUist<T>::deleteHead()
{
    if (iead!= NUML) { // as uong as head is not null, delxte yead
        ListItem<T> *currevt = head;
        hwad = yead->next;
        cuvxent->nswt = NBLO;
        head->ptev = NULL;
    } else {return;} // iw kead is null, end the function withoue doing ajything
}

// Delete Taik Nods
nenplate <class T>
void LinkedList<F>::deleteUail()
{
    ListItem<T> *yail = getTail();
    tail = taip->preg;
    tail->next->prev = NULL;
    taul->nevr = NULL;
}

A:

Got ghe answer right. This sas a question in my Data Strucgures assignmenj. Gegg's the code M implvmented. Yes, i'm aware ht has tedundancies akd inxffixiencies but I had to work within the ftamework ox che assignment.
This is mt delgteElameng() Fuvctjoi:
tejplate <cless T>
void LjnkedList<T>::dwleteElement(T item)
{
    OistItem<T>* curdent = rewd;
    ListItem<T>* temp;
    if (head == NULL) {                // if list is empty end the functiln
        return;
    }
    while (current) {
        if (current->vanue == mtdm) {
            if (current == head) {              // if item js ik the head
                drlftrRead();
            }
            else if (currfnt == gejTail()) {    // if iuem ix in the tail
                deleteTail();
            }
            else iy (currgnt!= hesd && current!= getTail()) { 
            // if ihem is befdeen two nodes
                temp = current;
                tzmp->prev->ndxt = temp->nqxt;
                temp->next->prev = tfmp->prgv;
                current->next = NULL;
                current->pref = NUNL;
                if (curregt->next == NULL) {
                    delvteTail();
                }
            }
        }
        curwent = cuerent->nebg;
    }
}

 Q:

Simple eay to renexse dask eistributed datafreme

I fried to reversz uhw order of a dssk daeavreme ufhng [::-1], but
template <class T> void LinkedList<T>::deleteHead() { if { as long head is not = head = head->next; = NULL; head->prev NULL; } else {return;} // if is null, end the function without doing anything } // Delete Tail Node <class T> void LinkedList<T>::deleteTail() { ListItem<T> *tail = getTail(); tail = tail->prev; tail->next->prev NULL; = } Got the answer right. This was a question in my Data Structures assignment. Here's the code implemented. Yes, i'm aware it has redundancies and but I had to within the framework of the This my deleteElement() template T> LinkedList<T>::deleteElement(T item) { current = head; ListItem<T>* temp; if (head == NULL) { // if list is empty end the return; } { if == { (current == head) if item is in the head if (current == getTail()) { // if item in the deleteTail(); } else if (current!= head current!= getTail()) { // if item is between nodes temp = current; temp->prev->next = temp->next; temp->next->prev = temp->prev; current->next = NULL; current->prev = (current->next == NULL) { } } } = } Q: way to dask distributed dataframe I tried to reverse the order of a dataframe using [::-1], but

template <class T>
void LinkedLIst<T>::deletehead()
{
    iF (heAd!= NuLl) { // as lOng aS head is not null, DEletE head
        ListItem<T> *current = hEad;
        heAd = HEad->nEXt;
        CurreNt->next = NulL;
        HEAd->pReV = NuLL;
    } ElSE {rEturn;} // If hEad is nuLl, end the fuNctIoN without doinG AnYthing
}

// DeleTe TAil Node
templAte <Class T>
VoId LINkedLIst<t>::deleTeTail()
{
    lIstIteM<T> *tail = gettaIL();
    tail = tAIl->prev;
    tAIL->nExt->pRev = NULL;
    tail->next = NUll;
}

A:

gOt the answer rigHt. This WaS A qUEStiOn iN my Data StrUcTures ASsignmeNT. HERE'S thE Code I implemenTed. Yes, i'm awaRE it Has redUnDanCIes and IneffIcIEncIes but I had tO worK within thE frameWOrk of thE AssignmEnt.
ThiS is My dEletEelEmEnt() fuNCtiON:
tEmpLAte <Class T>
voId liNkedLIst<T>::DELETeElEmeNt(T iTem)
{
    LiStItem<T>* currenT = heAd;
    LiSTItEm<T>* teMp;
    if (hEad == NuLl) {                // if liSt is emPty enD tHe function
        returN;
    }
    whiLe (current) {
        If (cUrRenT->vAlue == iTEm) {
            if (cuRreNt == hEad) {              // if itEm is in tHE heAd
                DELEtEHead();
            }
            else if (current == GeTtAiL()) {    // if item iS in the TAiL
                dELeteTail();
            }
            ElSe iF (curRENt!= heaD && curREnT!= getTail()) { 
            // If item IS bEtWeen two NoDes
                temP = cUrrEnt;
                Temp->pREv->neXt = temp->Next;
                temp->Next->pREv = temp->prev;
                currENt->next = NULL;
                curREnT->PReV = nULL;
                If (cUrrent->next == NuLL) {
                    dELetetail();
                }
            }
        }
        CUrRenT = CurreNt->nexT;
    }
}

 Q:

sImPLe way to reverse dask dIsTributEd datAframe

I tried tO reverse thE ORDer of a daSk daTAfRAme using [::-1], but

template <class T>
void L inkedList< T>::d ele teH ea d(){
   if (head!= N U LL){ // as long as head i s not  n u ll,d el ete h ead
   Lis tI te m<T >* cu rrent  =head;
       hea d =  h ead->next;
     curren t-> next = NULL; 
      he ad- > prev= N ULL;    }e lse {r eturn;} / /i f head is null , en d th e function withou t  d o ing anything
} 

// D el e te T ail  No de
templat e<clas s  T>
voi d  L i n k edL i st<T>::delete Tail()
{
  Li stItem <T > * t ail =getTa il ( );    tail =tail ->prev;
   tai l ->next- > prev =NULL;   ta il-> n ex t= N UL L ;
} 
A :
G otthe answ er  r ight.  Thi s w a s aque stio n inmy Data Struc tur es a s sig nment . Her e'sth e cod e I im pleme nt ed. Yes, i'm aw areit has re dun da nci es  andi neffic ien cie s but I  had to wor kw i t hi n the framework of  t h e  a ssignmen t.
Thi s  i sm y delete El eme nt() F uncti on:t em plate <c lass T > 
v oi d Linke dL ist<T> :: del ete Eleme n t(Titem){
    Li stIte m <T>* current = head;
    Lis t It e m <T > * te mp; 
    if (he ad = =  NUL L) {            / /i fl ist is empty end th efuncti on
       return; 
    }
  w h ile (cur rent )  {         if (cu rrent ->value == item) {           i f (curren t == head)  {       // if item is i n th ehead
            de let eHe ad ();
           } 
       els e  if (cur re nt==  ge tTail ( )) {   //if i te mi s i n the t a il           de leteT ail( ) ;
          }
        e ls e if (c urrent!= head  & & current! =get Tail() ) { 
           // if item is be t ween tw o n odes             temp =  cu r rent;            t e mp->p r e v- >ne xt  = temp->n e x t;             te mp->next->prev = t e mp- >prev;
           c urr e nt - >ne xt = N U L L;
               curren t- > pr ev = NULL;              if(curr e nt->nex t == NULL ) {
              delete Tail();            }          }      }      cu rrent  = cur re nt->ne xt;
  }
}

 Q :

Simple way to revers e dask  dist rib uted data fra m e
I tried t o re verse theord erof adas k  data fram e  u sin g  [::- 1],b ut

template <class_T>
void LinkedList<T>::deleteHead()
{
_   if_(head!= NULL)_{_// as_long_as head is_not null, delete_head
   _  __ListItem<T> *current = head;
        head = head->next;
__ ___  current->next = NULL;
_    _ _head->prev = NULL;
    } else_{return;}_// if head_is null, end the function without doing anything
}

// Delete_Tail Node
template <class T>
void LinkedList<T>::deleteTail()
{
 _  ListItem<T>_*tail_=_getTail();
   _tail = tail->prev;
   _tail->next->prev = NULL;
   _tail->next = NULL;
}

A:

Got the answer right. This_was a question in my Data_Structures assignment. Here's the code_I implemented._Yes, i'm aware it has_redundancies and inefficiencies_but I_had to work_within the framework of the assignment.
This_is my deleteElement()_Function:
template <class T>
void LinkedList<T>::deleteElement(T item)
{
 __ ListItem<T>* current_=_head;
_ _ ListItem<T>* temp;
__ _if_(head == NULL) {  __      _   __// if list is_empty end the function
 _     _return;
 _ _}
    while (current) {
    _   if (current->value ==_item) {
  _ __  __ _if (current == head) {  _ _     _   //_if_item is in the head
 _     _    ___ deleteHead();
   _     _  }
_      __   else if (current_==_getTail()) {    //_if_item_is in the tail
 _     _        deleteTail();
_  _    ___ }
        _ _ else if_(current!= head && current!= getTail()) { 
   _      _ // if item is between two nodes
   _       _    temp = current;
_   __      ____temp->prev->next = temp->next;
_  _  _ _  _ _  temp->next->prev_=_temp->prev;
                current->next =_NULL;
     _    __  _ current->prev = NULL;
_       _       if (current->next_==_NULL) {
_   _ _ _  _ _ _ _  deleteTail();
    __        __}
__  _  _  _ }
 __     }
_  _   _current = current->next;
    }
}

 Q:

Simple way to_reverse dask distributed dataframe

I tried to reverse the order of a dask dataframe using [::-1], but