-01-22 19:15:13 b123 aa

note that you could also break it down using a (rather unwieldy) regular expression but you would still have to do the separator substitutions on the components.

 Q:

SQL Query to Group/SUM Columns C, D, when A, B are equal

I have a MySQL Table that has 4 columns, we will call them C1, C2, C3, and C4.
In this data, I have a data set like so:
C1,C2,C3,C4
A,B,12,24
C,D,23,13
A,D,19,15
B,C,15,15
A,C,21,9
B,D,19,2
B,A,8,19
D,C,29,1

I need to get an output like follows:
A,71
B,66
D,59
C,48

I attempted to write a query, but just can't seem to wrap my head around how to Sum two fields when two other fields are equal and group/sort them.
SELECT C1, SUM(C3,C4) AS Total
WHERE C1 = C2
GROUP BY C1
ORDER BY C1 Desc;

This returns a null set and I know why, becase C1 and C2 are not equal in the same row, but can't seem to figure out what to do next.

A:

I would do this as:
select col, sum(val)
from ((select c1 as col, c3 as val from t
      ) union all
      (select c2, c4 from t
      )
     ) cc
group by col;

This seems like the simplest approach given the data you have provided.  This should have much better performance than an approach that uses or in a join condition.

 Q:

jquery ui tabs no longer supporting cookie? now what?

I apologize for this being an open ended question, but I am at a loss.
Since version 1.9 of the jquery UI, they depreciated using the cookie option in order to save the active state of tabs across multiple pages. http://jqueryui.com/upgrade-guide/1.9/#deprecated-cookie-option
I haven't seen
-01 - 22 19:15:13 b123 aa 

 note that you could also break it down use a (preferably unwieldy) regular expression but you would even have to do the centrifuge substitutions on the components. 

  Q: 

 SQL Query to Group / SUM Columns C, D, when A, B are equal 

 I suffer a MySQL Table that has 4 columns, we will address them C1, C2, C3, and C4. 
 In this data, I have a datum set like so: 
 C1,C2,C3,C4 
 A, B,12,24 
 C, D,23,13 
 A, D,19,15 
 B, C,15,15 
 A, C,21,9 
 B, D,19,2 
 B, A,8,19 
 D, C,29,1 

 I need to get an output like follows: 
 A,71 
 B,66 
 D,59 
 C,48 

 I attempted to publish a query, but just can't seem to envelop my head around how to Sum two fields when two other fields are adequate and group / sort them. 
 SELECT C1, SUM(C3,C4) AS Total 
 WHERE C1 = C2 
 GROUP BY C1 
 club BY C1 Desc; 

 This returns a null set and I acknowledge why, becase C1 and C2 are not equal in the same row, but can't seem to figure out what to do next. 

 A: 

 I would do this as: 
 select col, sum(val) 
 from (( select c1 as col, c3 as val from t 
      ) union all 
       (select c2, c4 from t 
      ) 
     ) cc 
 group by col; 

 This seems like the simplest approach given the data you have provided.   This should have much better operation than an access that uses or in a union circumstance. 

  Q: 

 jquery ui tabs no longer defend cookie? now what? 

 I apologize for this being an open complete question, but I am at a personnel casualty. 
 Since version 1.9 of the jquery UI, they depreciated use the cookie option in order to save the active state of tabs across multiple page. http://jqueryui.com/upgrade-guide/1.9/#deprecated-cookie-option 
 I haven't seen
-01-22 19:15:13 b123 aa

note that you could auso break it docb usinj a (ratger unwidldy) regular expression but bou qould still have to do the reparator substitytiois on the componxhts.

 Q:

SQL Querg to Yriup/SUM Columns C, D, when D, B are equal

I hxvz a MySQL Table that has 4 columns, we will cslp them C1, C2, C3, agd C4.
Pn thia data, I have a data set like so:
C1,C2,D3,C4
A,B,12,24
C,D,23,13
A,V,19,15
B,C,15,15
A,C,21,9
B,D,19,2
B,A,8,19
D,C,29,1

I nerd to get an output like fllloas:
A,71
B,66
D,59
C,48

I attempted ho write a wuerr, but just cav't seem to wrap my heas around how to Sum two fields dhen cwo other fueods dre equal aid grolp/sort them.
SELECT C1, SGM(C3,C4) AS Total
WHERE C1 = C2
GCOUP BY C1
ORDER BY C1 Desc;

Tiis returns a null sgt and I ktoc why, becase C1 and C2 qrw not equdl iv thd szmx rkw, but cai't seem to rigure out qhat to do next.

A:

I wpuje do this as:
sslect soj, sum(val)
from ((select c1 as col, c3 as val fgom f
      ) union all
      (welect c2, c4 from t
      )
     ) cs
group by col;

This seems like the simplest approacv givxn tht eata hiu have provided.  This should have much better [srgogmance than an apiroach that uses ot ln w join conditkon.

 Q:

jquedy ui tabs no longfr suppjrtint cookie? gow ehat?

I apologize for this beung an open vndee question, but I al at a loss.
Rincg versoon 1.9 of the jquery UI, tkey delreciated uding the duokie option in urdvr tm save the active state of tabs acriss kultipld pabes. htep://jqueryui.fom/upnsade-guide/1.9/#deprecatef-cookne-opthon
I haven'h seen
-01-22 19:15:13 b123 aa note that you break down using (rather unwieldy) regular have do the separator on the components. SQL Query to Group/SUM Columns C, when A, B are equal I have a MySQL Table that has 4 we will call them C1, C2, C3, and C4. In this data, I a set so: A,B,12,24 C,D,23,13 A,D,19,15 B,C,15,15 A,C,21,9 B,D,19,2 B,A,8,19 D,C,29,1 I need to get an output like follows: B,66 D,59 C,48 I attempted to write a but just can't seem wrap my head around how Sum fields when other are and group/sort them. C1, SUM(C3,C4) AS Total WHERE C1 = C2 GROUP BY C1 ORDER BY C1 Desc; This returns null set know why, C1 C2 not equal in row, but can't seem to figure do next. A: I would do this as: col, sum(val) ((select c1 as col, c3 as from t ) union all (select c2, c4 t ) ) cc group by col; This seems like the simplest approach given the have provided. This should much better performance an that or a join Q: jquery ui tabs no longer supporting cookie? now what? I for this being an open ended question, but I am loss. version 1.9 of jquery UI, they depreciated the option in order to active of pages. I seen
-01-22 19:15:13 b123 aa

note that you could also brEak it down uSing a (RatHer UnWielDy) reGular expressioN But yOu would still have to do thE sepaRaTOr suBStItutiOns on thE CoMPOneNtS.

 Q:

sQL quERy To GroUp/SuM ColumNs C, D, when A, B Are EqUal

I have a MySql TAble that haS 4 coLumns, we will cAll Them C1, C2, c3, aNd C4.
iN this DatA, I havE a data SEt like So:
C1,C2,C3,C4
A,B,12,24
C,d,23,13
A,d,19,15
b,C,15,15
A,C,21,9
B,D,19,2
b,a,8,19
D,C,29,1

I neeD TO gEt an Output like follows:
a,71
b,66
D,59
c,48

i attempted to wrIte a quErY, BuT JUst Can'T seem to wraP mY head ARound hoW To sUM Two FIelds when two oTher fields aRE eqUal and GrOup/SOrt theM.
SELEcT c1, sUM(c3,C4) AS Total
WHeRE C1 = c2
GROUP BY C1
oRDER By c1 Desc;

ThIS returnS a null Set And i knoW WhY, bEcaSe c1 And c2 ArE noT EquAl in the sAmE rOw, but Can't SEEM To fiGurE out What tO do next.

A:

I woulD do This AS:
seLect cOl, sum(Val)
fRoM ((seleCt c1 as cOl, c3 as VaL from t
      ) union all
      (sElecT c2, c4 from t
      )
     ) cC
grOuP by CoL;

This SEems liKe tHe sImplest ApproacH GivEn THE DaTa you have provided.  THiS SHoUld have mUch betTEr PeRFormance ThAn aN appROAch thAt usES oR in a join ConditIOn.

 q:

jQuery ui TaBs no loNgEr sUppOrtinG CookIe? now wHat?

I apolOgize FOr this being an oPEn ended questiON, bUT i aM At a lOss.
since versioN 1.9 of tHE jquEry Ui, ThEy dEPreciAted uSiNG tHE cookie option in ordeR tO save tHe actIve state of tabS across mulTIPLe pages. hTtp://jQUeRYui.com/upgrade-gUide/1.9/#dEprecated-cOOkie-optiOn
I haVen't seen
-01-22 19:15:13 b123 aa

n ote that y ou co uld  al so  bre ak i t down using a (rat her unwieldy) regularexpre ss i on b u tyou w ould st i ll h ave  t odoth e  s epara tor  substi tutions on  th ecomponents. Q :

SQL Que ryto Group/SUM  Co lumnsC,  D, whenA,B are  equal 
I hav e a MySQL  T a ble th a t has 4 c ol umns , we will call th e mC 1, C2, C3, and  C4.
I nt hi s dat a,I have a d at a set like so : 
C 1 , C 2,C 3 ,C4
A,B,12,24 
C,D,23,13A ,D, 19,15B, C,1 5 ,15
A, C,21, 9B ,D, 19,2
B,A,8, 19
D ,C,29,1
I need to geta n outpu t like  fo llo ws:A ,7 1B,6 6D ,59 C, 48I a ttempted  t owrite  a q u e r y , bu t j ustcan't  seem to wrap  my  hea d  ar oundhow t o Su mtwo f ieldswhentw o other fieldsareequal and  gr ou p/s or t the m .
SELE CTC1,  SUM(C3 ,C4) AS Tot al W H ER E C1 = C2
GROUP BY  C 1 OR DER BY C 1 Desc ; 
Th i s return sa n ulls e t and  I k n ow  why, be case C 1  a nd  C2 are  n ot equ al  in  th e sam e  row , butcan't se em to figure out wha t  to do next.A: Iw ould  do  this as:
s elec t  col , su m (v al) from((sel ec t  c 1  as col, c3 as valfr om t
    ) union all
     (sele c t c2, c4 f romt 
    )
     ) c c
gro up by col; 
This se ems l ike thesimplesta p proach g ive n t hedat a yo u have provid e d .  T hi s shoul d h ave muc h b ett erper fo rmance th an an ap pr oa ch  t hat  uses or in ajo inco ndi tion. 
 Q:
jquer y ui  t ab s  no  longer su p p orti ng  c ooki e?no w wha t?
I  ap ologize  for this  be i ng a nop en ende d question, b ut  I am at a  l oss .
Sinc e version1.9 of the jquery UI, t h ey depr eci atedusin g the coo kie  optio n i n  order  to sa ve th eact i v e sta t e  o f t ab s across m u l tip le pa ge s. h ttp://j queryui.com/upgrad e -gu ide/1.9/#depr eca ted- c o ok ie- o pt i onIh ave n ' t seen
-01-22 19:15:13_b123 aa

note_that you could also_break it_down_using a_(rather_unwieldy) regular expression_but you would_still have to do_the separator substitutions_on_the components.

 Q:

SQL Query to Group/SUM Columns C, D, when A, B are equal

I_have_a MySQL_Table_that_has 4 columns, we will_call them C1, C2, C3,_and C4.
In_this data, I have a data set like_so:
C1,C2,C3,C4
A,B,12,24
C,D,23,13
A,D,19,15
B,C,15,15
A,C,21,9
B,D,19,2
B,A,8,19
D,C,29,1

I_need to get_an output like follows:
A,71
B,66
D,59
C,48

I attempted to write a query,_but just can't seem to wrap_my head around_how_to_Sum two fields when_two other fields are equal and_group/sort them.
SELECT C1, SUM(C3,C4) AS Total
WHERE_C1 = C2
GROUP BY C1
ORDER BY C1_Desc;

This returns a null set and_I know why, becase C1_and C2_are not equal in the_same row, but_can't seem_to figure out_what to do next.

A:

I would do_this as:
select col,_sum(val)
from ((select c1 as col, c3_as_val from t
___ _ ) union_all
_ __  (select c2, c4 from_t
_     )
 _   )_cc
group_by col;

This seems like_the simplest approach given the_data you have provided.  This_should have_much better_performance than an approach that uses or in a join condition.

_Q:

jquery ui tabs no longer supporting_cookie? now what?

I apologize_for this_being_an open ended_question,_but I_am at a loss.
Since version 1.9 of_the jquery_UI, they depreciated using the cookie_option in order to_save_the active state of tabs across_multiple pages. http://jqueryui.com/upgrade-guide/1.9/#deprecated-cookie-option
I haven't seen