 If you use highly thermally conductive rods (like copper or aluminium), the depth of the ocean (let's say is about the order of 5 km) is so much greater than the radius of the metallic rod that radial heat conduction will dominate over the longitudinal one. It means that you won't be able to carry the "coldness" (or "hotteness" for that matter) of deep underwater temperatures to the surface. What will happen instead is that the temperature of the rod will be roughly the same as the temperature of the water around it. So, at the surface where your Peltier element (or better to say, thermoelectric generator) there is virtually no temperature difference due to the rod (or heat exchanger).  The rod will be essentially entirely useless. And this remains true even if you somehow encapsulate the rod in a vacuum cylinder so that the rod makes no contact with water. In that case the thermal resistance of the rod (which scales linearly with its length) is so big that the difference in temperature between the top of the rod and the bottom of the rod will be vanishingly small compared to the temperature difference between the surface of the ocean and its bottom.
In other words, no matter what you do with the rod, using a rod between the surface of the ocean and its bottom in order to establish a temperature difference across a thermoelectric generator will not work as you expect. The rod will not be able to transfer the heat from the bottom to the top, or viceversa. An analogy with an electrical circuit would be that you have in mind that using a copper wire between two elements will be fine because it conducts electricity well. However the reality is that the wire is such that its resistance is insanely high despite that its conductivity is also very high. For example if the wire has a diameter of a few micrometers and a length of millions of kilometers, you end up having a resistance of mega ohms despite the fact that you used copper. That's roughly equivalent to the case you have in mind.

A:

It's theoretically possible, and working prototypes have been built on an experimental basis to explore the possibilities, but to the best of my knowledge no large scale, semi- commercial projects have yet been undertaken. I say semi-commercial because it is likely that some form of state subsidy would be necessary, at least in the early stages. 

 Q:

AJAX Post on Field Completion?

I have the code below that validates a
If you use highly thermally conductive rods (like copper or aluminium), the astuteness of the ocean (lease's say is about the order of 5 kilometer) is so a lot greater than the radius of the metallic perch that radial heat conduction will dominate over the longitudinal one. It mean that you won't be able to carry the " coldness " (or " hotteness " for that topic) of deep underwater temperatures to the surface. What will find instead is that the temperature of the rod will be approximately the same as the temperature of the urine around it. thus, at the surface where your Peltier element (or better to read, thermoelectric generator) there is virtually no temperature difference due to the rod (or inflame exchanger).   The rod will be basically entirely useless. And this remains true even if you somehow encapsulate the rod in a void cylinder so that the rod makes no contact with water. In that case the thermal resistance of the rod (which scales linearly with its length) is so big that the difference in temperature between the top of the rod and the bottom of the rod will be vanishingly small compare to the temperature difference between the surface of the ocean and its bottomland. 
 In other words, no matter what you do with the rod, use a gat between the surface of the ocean and its bottom in holy order to establish a temperature difference across a thermoelectric generator will not work as you expect. The perch will not be able to transfer the heat from the bottom to the top, or viceversa. An doctrine of analogy with an electrical lap would be that you accept in mind that using a copper telegram between two elements will be fine because it conducts electricity well. However the reality is that the wire is such that its resistance is insanely high despite that its conductivity is besides very high. For example if the wire has a diameter of a few micrometers and a duration of millions of kilometer, you end up having a resistance of mega ohms despite the fact that you used bull. That's roughly equivalent to the case you have in thinker. 

 A: 

 It's theoretically possible, and solve prototypes have been built on an experimental basis to explore the possibilities, but to the best of my knowledge no large plate, semi- commercial projects have yet been undertake. I say semi - commercial because it is likely that some form of state subsidy would be necessary, at least in the early stages. 

  Q: 

 AJAX Post on Field Completion? 

 I have the code below that validate a
 If you use highly thermalln conductive rods (like ropper kr alumivium), the depth of the ocean (per's sat is about the order ow 5 km) is do much treauer than the radina of thc metzplic cod that radial heat condgction will dokivace over the longitudinal one. It meanf that uok won't be able to bawry fhe "coldness" (or "hotteness" for that matter) of deep undetwater temperatures to the survace. What will hapoen instead is eyat the tempdrature of the rod wilm be roughly the same as the teoperacure of the wqteg around it. Wo, at the surface where ymur Pelyier element (ov betver ro say, thermoelectric generator) there if virtualny no temperature dufderenwe dge tu thd rkd (od heat exrhanger).  Ths rod will ve essentially entitejj useless. And this weiains true even if you somehow encapsuldte the rod in a vacuum cyoinder so that the rof makes nj contact with water. In that case the thermal reshstanre of tme rue (ahich scales linearly with its length) is so byf uhan the difference ln temperature beteefn jhe top of the rod aus fhe bottom of the god wilj be canishingjy skall compared to the temperqture differvnce between the surfaee of the oczan anc its bottom.
In other words, nu mafter what ylu do witg the rod, using a roc tetween ufe surface of the ocean anv its bottom in prder eo establidh a bamperature differejce aeross a thermoepectric generator will not work as you expect. Tve god will uot be able to tranffer the heat yrom the bottum to the nop, or vireversa. An agalogy with at electrical rircuit wjuld be rhat yoj have in mind yhat usiny a cipper wire between twu elements will yt fune because it vonauces ekesdricity well. Howdvef the feality is bhag thr wire is such that hts desistance is insamejy high eespite ehat its condictivity is also vtry hijh. For examlle if the wire has a diameter of a few mifroieters and a lennth jf millionx of kilometers, you end up having a resmstance of mega ohms dgspite the fact that iou used coppec. That'f roughly equivalent to the cqse you have in mlnd.

A:

It's theoretically lossibne, anf working prototypes have been built on an experimental basis to explore rhe possibilities, gut yo thv bzst of my knoxlxdge no large scake, semi- commercial projects havx yet been uudertaken. I say semi-commerciak cecause it is likely that some form or state xubsidy would be necessary, at lrast in the early stages. 

 Q:

AJAX Post kn Field Cumpletion?

I have thr code beloq that califates a
If you use highly thermally conductive rods or the depth the ocean (let's of km) is so greater than the of the metallic rod that radial conduction will dominate over the longitudinal one. It means that you won't be to carry the "coldness" (or "hotteness" for that matter) of deep underwater temperatures the What happen is that the temperature of the rod will be roughly the same as the temperature of water around it. So, at the surface where Peltier element (or better say, thermoelectric generator) there is no difference due the (or exchanger). The rod be essentially entirely useless. And this remains true even if you somehow encapsulate the rod in a cylinder so rod makes contact water. that case the of the rod (which scales linearly is so big that the difference in temperature the top the rod and the bottom of rod will be vanishingly small compared to the difference between the surface of the ocean and its bottom. In other words, no matter do with the rod, a rod between surface the and bottom in to establish a temperature difference across a thermoelectric generator will not as you expect. The rod will not be able to heat the bottom to top, or viceversa. An with electrical circuit would be have mind copper between elements will be fine it conducts electricity well. However reality is that the resistance is insanely high despite that its conductivity also very high. For example if the has a diameter of a few micrometers and a length of millions kilometers, you having a resistance of mega ohms despite the that you used copper. roughly equivalent to the case you have in mind. It's possible, and prototypes have been on an experimental to explore the to the of knowledge semi- commercial projects have yet been I semi-commercial because it is likely some state subsidy would be necessary, at least in the early stages. Q: AJAX Post on I have the code that a
 If you use highly thermally coNductive roDs (likE coPpeR oR aluMiniUm), the depth of thE OceaN (let's say is about the ordeR of 5 km) Is SO mucH GrEater Than the RAdIUS of ThE mEtaLlIC rOd thaT raDial heaT conductioN wiLl Dominate over THe LongitudinAl oNe. It means thaT yoU won't bE aBle TO carrY thE "coldNess" (or "HOtteneSs" for that MaTTer) of dEEp underWATeR temPeratures to the surFAcE. what will happen InsteaD iS ThAT The TemPerature of ThE rod wILl be rouGHlY THE saME as the temperaTure of the waTEr aRound iT. SO, at THe surfAce whErE YouR Peltier eleMent (Or better tO say, thERmoelecTRic geneRator) tHerE is VirtUAlLy No tEmPEraTUrE diFFerEnce due tO tHe Rod (or Heat EXCHAngeR).  ThE rod Will bE essentially eNtiRely USelEss. AnD this RemaInS true Even if You soMeHow encapsulate tHe roD in a vacuuM cyLiNdeR sO that THe rod mAkeS no Contact With watER. In ThAT CAsE the thermal resistaNcE OF tHe rod (whiCh scalES lInEArly with ItS leNgth) IS So big That THe DifferenCe in teMPeRaTure betWeEn the tOp Of tHe rOd and THe boTtom of The rod wiLl be vANishingly small COmpared to the tEMpERAtURe diFfeRence betweeN the SUrfaCe of THe OceAN and iTs botToM.
in OTher words, no matter whAt You do wIth thE rod, using a rod Between the SURFace of thE oceAN aND its bottom in orDer to Establish a TEmperatuRe difFerence aCross a theRMOelectriC geNerAtoR wiLL NoT work as you expECT. The RoD will noT be Able to tRanSfeR thE heAt From the boTtom to thE tOp, Or ViCevErsa. AN Analogy wItH an ElEctRical CIrcuit Would Be thAt YoU HavE in mind THaT USing A cOpPer wIre BeTween Two eLEmeNts will Be fine becAusE It coNdUcTs electRicity well. HowEvEr the realiTy Is tHat the WIRe is such That its resistance is insaNEly high DesPite tHat iTs conductIviTy is alSo vERy high. for exaMple iF tHe wIRE has a DIAmEteR oF a few microMETerS and a LeNgth Of milliOns of kilometers, you ENd uP having a resisTanCe of MEGa OhmS DeSPitE tHE faCT That you used coppEr. That's rouGhLY eQuivalent tO The CaSe you haVe in minD.

A:

It's THeoretiCally possIble, and woRkIng pROTotYpes have beEn built oN an experiMEntal BAsIs to eXplOre the PoSsiBilitIes, but TO thE best Of my knOwLedge nO largE sCale, semi- Commercial projects have yEt been UnderTakEn. I say semI-coMMerCial becauSe it Is likely thAt sOme Form oF stATe subSidy WOuLd bE NecesSary, AT least in tHE eArlY STaGes. 

 Q:

AJAX PosT ON fieLd ComPleTIon?

I haVe thE code below that valIDates a
 If you use highly thermal ly conduct ive r ods  (l ik e co pper  or aluminium) ,  the  depth of the ocean (l et'ssa y  isa bo ut th e order of 5  km )is  so  m u ch  grea ter  than t he radiusofth e metallic r o dthat radia l h eat conducti onwill d om ina t e ove r t he lo ngitud i nal on e. It mea ns that y o u won't b eable  to carry the "co l dn e ss" (or "hotte ness"fo r  t h a t m att er) of dee punder w ater te m pe r a t ure s  to the surfa ce. What wi l l h appenin ste a d is t hat t he tem perature of  the  rod will  be ro u ghly th e  same a s thetem per atur e  o fthe  w a ter ar oun d  it . So, at  t he  surf acew h e r e yo urPelt ier e lement (or be tte r to say , the rmoel ectr ic  gene rator)  ther eis virtually no  tem peraturedif fe ren ce  duet o therod  (o r heatexchang e r).  T h e  r od will be essenti al l y  e ntirelyuseles s .An d  this re ma ins  tru e evenif y o usomehowencaps u la te  the ro din a v ac uum  cy linde r  sothat t he rod m akesn o contact with water. In tha t  c a s et he t her mal resista nceo f th e ro d  ( whi c h sca les l in e ar l y with its length)is  so bi g tha t the differe nce in tem p e r ature be twee n  t h e top of the r od an d the bott o m of the  rodwill bevanishing l y  small c omp are d t o t h e  t emperature di f f eren ce  betwee n t he surf ace  of  th e o ce an and it s bottom .In  o th erwords ,  no matt er  wh at  yo u dow ith th e rod , us in ga  ro d betwe e nt h e su rf ac e of  th eocean  and its  bottom  in order  to esta bl is h a tem perature diff er ence acros sa t hermoe l e ctric ge nerator will not work a s  you ex pec t. Th e ro d will no t b e able  to transf er the  heat  f rom t he bo t t om  to  t he top, or v ice versa .An a nalogywith an electrical cir cuit would be  th at y o u  h ave in min dt hat u sing a copper w ire betwee nt wo  elementsw ill  b e finebecause  it c o nductselectrici ty well.Ho weve r the  reality i s that t he wire i s  such th at it s r esista nc e i s ins anelyh igh  desp ite th at  its c onduc ti vity isalso very high. For exa mple i f the  wi re has adia m ete r of a fe w mi crometersand  alengt h o f  mill ions of  ki l omete rs,y ou end up ha vin g aresistanceo f meg a ohm s d e spitethefact that you use d  copper. That' s ro u g hly  eq u ival en t to the caseyou  h a v e in min d. 

A:

It'stheoreti ca l ly po ssible , andworking p ro t otypes  hav e b een built  on  a n  experi me nt a l basi s to  e xplore  the p o ssib i l ities, but to th e bes t of my kno wledg eno larg e  sca le, semi-commercialprojec ts h ave y et been  u nderta ken .I say semi - commercia l bec ause it  i s li kel y that  som e formof s ta tesubsidy w o u ld be  n e ces sary , atle astin the ea r ly stage s.
 Q:

A JA X P o s t on F i el d Completion ?
I hav e the code b e lowt ha t  vali datesa
 If_you use_highly thermally conductive rods_(like copper_or_aluminium), the_depth_of the ocean_(let's say is_about the order of_5 km) is_so_much greater than the radius of the metallic rod that radial heat conduction will_dominate_over the_longitudinal_one._It means that you won't_be able to carry the_"coldness" (or_"hotteness" for that matter) of deep underwater temperatures_to_the surface. What_will happen instead is that the temperature of the_rod will be roughly the same_as the temperature_of_the_water around it. So,_at the surface where your Peltier_element (or better to say, thermoelectric_generator) there is virtually no temperature difference_due to the rod (or heat_exchanger).  The rod will_be essentially_entirely useless. And this remains_true even if_you somehow_encapsulate the rod_in a vacuum cylinder so that_the rod makes_no contact with water. In that_case_the thermal resistance_of_the_rod (which_scales linearly with_its_length) is_so_big that the difference in temperature_between_the top of the rod and the_bottom of the rod_will_be vanishingly small compared_to the temperature difference between_the surface of the ocean and_its bottom.
In_other words,_no matter what you do with the rod, using a rod_between the surface of the ocean_and its bottom in_order to_establish_a temperature difference_across_a thermoelectric_generator will not work as you expect._The rod_will not be able to transfer_the heat from the_bottom_to the top, or viceversa. An_analogy with an electrical circuit would_be that you have in_mind_that_using a copper wire between_two elements will be fine because_it conducts electricity_well. However the reality is that the_wire_is such that its resistance is_insanely_high despite that its conductivity is_also_very_high. For example if the_wire has a diameter of a_few micrometers and a length of millions of kilometers,_you end up_having a resistance of mega_ohms_despite_the fact that you used copper. That's roughly equivalent to_the case_you have in_mind.

A:

It's theoretically possible, and working prototypes have been built on_an experimental basis to explore the possibilities,_but to the best of my knowledge no large scale, semi-_commercial projects have yet been undertaken. I say_semi-commercial because it is likely that some_form of state subsidy_would_be necessary, at least in the early_stages._

_Q:

AJAX_Post on Field_Completion?

I have the_code below that_validates a