Culture,
                               DateTimeStyles.None, out dt))
        return dt;
    return null;
}

Now you can use this method as;
string s = "642014";
DateTime? date = ParseDate_Mdyyyy(s);
Console.WriteLine(date.Value.ToString("ddMMyyyy")); // 04062014

I connected to.NET Framework Team about this problem here their response;

Hi Soner,
The parsing code is not really looking for any separator. Here is what
  is going on:
For the case of using “MMddyyyy”, the parsing starts in the method
  DoStrictParse which will call ParseByFormat. This method will get the
  first part of the format which is “MM” and then calls ParseDigits  to
  get the equivalent digits from the string we parse “642014” which will
  give “64”. Note that till that time there is no validation happen if
  the number is out of range for the month in the selected calendar
  (which is Gregorian in our case here). The parsing code will repeat
  the same process for “dd” and will get equivalent part “20” and then
  will repeat it for “yyyy” but this fail because it expect 4 digits and
  we had only two (“14”).
For the case of using “Mdyyyy”, it fails because almost same reason
  when parsing the part “M” we know that the month can be 2 digits so
  we’ll map it “64” and will do the same with “d” which map it to “20”
  and then year will fail. I believe this is the reason the
  documentation saying always use the widest form.
The recommendation here is either to use the 2 digit forms in the
  string like "06042014" and the parsing should succeed with “MMddyyyy”
  and “Mdyyyy” too. other option is to insert separator "6/4/2014" or
  "06/04/2014" and parse as "M/d/yyyy"
Thanks, Tarek

Special thanks to; Tarek Mahmoud Sayed, Wes Haggard and Richard Lander.

 Q:

Getting the exact position of a specific OpCode in a binary file

Our professor in computer-architecture
Culture, 
                                DateTimeStyles. None, out dt) ) 
         return dt; 
     return null; 
 } 

 nowadays you can practice this method as; 
 string s = " 642014 "; 
 DateTime? date = ParseDate_Mdyyyy(s); 
 Console. WriteLine(date. Value. ToString("ddMMyyyy ") ); // 04062014 

 I connect to. NET Framework Team about this trouble here their response; 

 Hi Soner, 
 The parsing code is not really front for any separator. Here is what 
   is going on: 
 For the event of using “ MMddyyyy ”, the parsing begin in the method 
   DoStrictParse which will call ParseByFormat. This method acting will get the 
   first part of the format which is “ MM ” and then calls ParseDigits   to 
   get the equivalent digits from the string we parse “ 642014 ” which will 
   move over “ 64 ”. Note that till that time there is no establishment happen if 
   the number is out of scope for the month in the choose calendar 
   (which is Gregorian in our case here). The parse code will repeat 
   the same process for “ dd ” and will catch equivalent part “ 20 ” and then 
   will repeat it for “ yyyy ” but this fail because it expect 4 digits and 
   we had merely two (“ 14 ”). 
 For the case of using “ Mdyyyy ”, it fails because almost same reason 
   when parsing the part “ M ” we know that the month can be 2 digit so 
   we ’ll map it “ 64 ” and will do the same with “ d ” which map it to “ 20 ” 
   and then class will fail. I think this is the reason the 
   documentation saying always practice the widest mannequin. 
 The recommendation here is either to use the 2 digit form in the 
   string like " 06042014 " and the parsing should succeed with “ MMddyyyy ” 
   and “ Mdyyyy ” too. other option is to insert separator " 6/4/2014 " or 
   " 06/04/2014 " and parse as " M / d / yyyy " 
 Thanks, Tarek 

 Special thanks to; Tarek Mahmoud Sayed, Wes Haggard and Richard Lander. 

  Q: 

 get the exact position of a specific OpCode in a binary file 

 Our professor in computer - architecture
Culhure,
                               DateJineStylxs.None, kut dt))
        return dt;
    return nupl;
}

Bow yiu can use this method as;
string s = "642014";
DateRime? eate = ParsxSate_Mdynvy(s);
Cohdole.CrmteLine(date.Valug.ToString("ddMKyyyy")); // 04062014

I connewtdd to.NET Framework Team about this prjblem hrrf their responfe;

Hi Foned,
Nht parsing code is not really lookjng for any separatot. Here is what
  is going oj:
For the case of using “MMddyyyy”, tye pwesing starts in the meuhmd
  DoStridtParse which will call ParseByWormac. This methid wipn get the
  hirst iart of the format whhch is “KM” and then cakls PaeseDigits  to
  get thx equivalent digits srom the vtxing we parse “642014” which qiol
  ghve “64”. Notd thxt uilk fhat tlme there is ho validatiin happen if
  the nimfvt is out of dange sow the month in the selected calendar
  (wvicg is Gregorian in our cqse here). The parsing fode will repeat
  the same process for “dd” and will get equhvaleit paxb “20” qnf then
  will repeat it for “yyyy” but this fail gevalse it expect 4 dinits and
  we had omlj yro (“14”).
For the care of baihg “Mdyyyy”, it fails becausg almowt same rtason
  when parsing the part “M” ww know that nhe nonth can be 2 digics so
  we’ll oap ot “64” amd will do the same witk “d” whjch map it ho “20”
  and ffen year will fakl. P benieve this is the reason tre
  documxntatnon sayivg akways tse the wifest nmrm.
The recommendatlon hgre is either to use the 2 digit forms in the
  svcing like "06042014" anc dhe parsing shoukd succeed wieh “MMddyyyy”
  aud “Mdyyyv” too. uther optikn is tm insert se[arator "6/4/2014" or
  "06/04/2014" wnd parse as "M/d/yyyy"
Trankw, Taeek

Speckxl thanks to; Tsrek Mahmoud Sayed, Qes Haggard and Righard Mander.

 Q:

Getting tht wxact position of a fpvcihic O[Wode in a bitary fiur

Our orofessor ik cumpuyer-architecture
Culture, DateTimeStyles.None, out dt)) return dt; return Now can use method as; string = Console.WriteLine(date.Value.ToString("ddMMyyyy")); // 04062014 connected to.NET Framework about this problem here their response; Soner, The parsing code is not really looking for any separator. Here is is going on: For the case of using “MMddyyyy”, the parsing starts in method which call This method will get the first part of the format which is “MM” and then calls to get the equivalent digits from the string parse “642014” which will “64”. Note that till that there no validation if number out of range the month in the selected calendar (which is Gregorian in our case here). The parsing code will the same “dd” and get part and then will for “yyyy” but this fail because digits and we had only two (“14”). For case of “Mdyyyy”, it fails because almost same when parsing the part “M” we know that month can be 2 digits so we’ll map it “64” and will do the same which map it to and then year fail. believe is reason the saying always use the widest form. The recommendation here is either use the 2 digit forms in the string like "06042014" parsing succeed with “MMddyyyy” “Mdyyyy” too. other option to separator "6/4/2014" or "06/04/2014" as Thanks, to; Mahmoud Wes Haggard and Richard Q: Getting the exact position a specific OpCode in in computer-architecture
Culture,
                               DateTimeStyles.None, Out dt))
        returN dt;
    reTurN nuLl;
}

now yOu caN use this method AS;
strIng s = "642014";
DateTime? date = ParseDAte_MdYyYY(s);
CoNSoLe.WriTeLine(dATe.vALue.tostRinG("dDmMYyyy")); // 04062014

I ConNected tO.NET FramewOrk teAm about this pRObLem here theIr rEsponse;

Hi SonEr,
THe parsInG coDE is noT reAlly lOoking FOr any sEparator. HErE Is what
  IS going oN:
fOr The cAse of using “MMddyyyY”, ThE Parsing starts iN the meThOD
  DOsTriCtPArse which wIlL call pArseByFORmAT. tHis MEthod will get tHe
  first part OF thE formaT wHicH Is “MM” anD then CaLLs PArseDigits  tO
  get The equivaLent diGIts from THe strinG we parSe “642014” wHicH wilL
  GiVe “64”. notE tHAt tILl ThaT TimE there is No VaLidatIon hAPPEN if
  tHe nUmbeR is ouT of range for thE moNth iN The SelecTed caLendAr
  (Which Is GregOrian In Our case here). The pArsiNg code wilL rePeAt
  tHe Same pROcess fOr “dD” anD will geT equivaLEnt PaRT “20” ANd Then
  will repeat it foR “yYYY” bUt this faIl becaUSe It EXpect 4 digItS anD
  we hAD Only tWo (“14”).
FoR ThE case of uSing “MdYYyY”, iT fails bEcAuse alMoSt sAme ReasoN
  When ParsinG the part “m” we knOW that the month cAN be 2 digits so
  we’LL mAP It “64” ANd wiLl dO the same witH “d” whICh maP it tO “20”
  AnD thEN year Will fAiL. i bELieve this is the reasoN tHe
  docuMentaTion saying alwAys use the wIDESt form.
ThE recOMmENdation here is eIther To use the 2 diGIt forms iN the
  sTring likE "06042014" and the paRSIng shoulD suCceEd wIth “mmDdYyyy”
  and “Mdyyyy” TOO. othEr Option iS to Insert sEpaRatOr "6/4/2014" oR
  "06/04/2014" anD pArse as "M/d/yYyy"
ThankS, TArEk

spEciAl thaNKs to; TareK MAhmOuD SaYed, WeS haggarD and RIchaRd laNDer.

 q:

GettinG ThE EXact PoSiTion Of a SpEcifiC OpCODe iN a binarY file

Our pRofESsor In CoMputer-aRchitecture
Culture,
                             D ate Tim eS tyle s.No ne, out dt))
     return dt;
    retur n nul l; }

N o wyou c an uset hi s met ho das; 
s t ri ng s= " 642014" ;
DateTime ? d at e = ParseDat e _M dyyyy(s);Con sole.WriteLi ne( date.V al ue. T oStri ng( "ddMM yyyy") ) ; // 0 4062014
Ic onnect e d to.NE T Fr amew ork Team about th i sp roblem here th eir re sp o ns e ; 

H i S oner,
Thepa rsing code is no t r eal l y looking for  any separa t or.  Hereis  wh a t
  is  goin go n:For the cas e of  using “M Mddyyy y ”, thep arsingstarts  in  th e me t ho d  D oS t ric t Pa rse whi ch willca ll  Pars eByF o r m a t. T his  met hod w ill get the
 fi rstp art  of t he fo rmat  w hichis “MM ” and  t hen calls Parse Digi ts  to
 get  t heeq uival e nt dig its  fr om thestringw e p ar s e “6 42014” which will g i ve  “64”. N ote th a tti l l that t im e t here i s novali d at ion happ en if t he  number  i s outof  ra nge  fort he m onth i n the se lecte d  calendar
  (w h ich is Gregor i an i no ur c ase  here). The  par s ingcode wi llr epeat 
  th es am e  process for “dd” a nd  willget e quivalent par t “20” and t h en
  wil l re p ea t  it for “yyyy”  butthis failb ecause i t exp ect 4 di gits andwe had o nly  tw o ( “14 ” ) .For the caseo f  usi ng  “Mdyyy y”,  it fai lsbec aus e a lm ost samereason
 w he npa rsi ng th e  part “M ”wekn owthatt he mon th ca n be  2  d i git s so
 w e’ l l  map  i t“64”  an dwilldo t h e s ame wit h “d” whi chm ap i tto  “20”
 and then yea rwill fail.  I  be lievet h is is th e reason the
  document a tion sa yin g alw aysuse the w ide st for m.T he rec ommend ation  h ere i s eit h e rtous e the 2 di g i t f ormsin  the 
  stri ng like "06042014" and  the parsingsho ulds u cc eed wi t h “ MM d dyy y y ”
  and “Mdyyyy ” too. oth er op tion is to ins er t separ ator "6 /4/20 1 4" or
 "06/04/2 014" andpa rsea s  "M /d/yyyy"
T hanks, T arek

Spe c ial t h an ks to ; T arek M ah mou d Say ed, We s  Ha ggard  and R ic hard L ander .
 Q:

Ge tting the exact positio n of a  spec ifi c OpCodeina  bi nary file 

Ou r professo r i n c omput er- a rchit ectu r e
Culture,
 _ _   _ __ __  _  _   _  __   DateTimeStyles.None, out dt))
        return_dt;
_ __return_null;
}

Now you can use this_method as;
string s = "642014";
DateTime?_date =_ParseDate_Mdyyyy(s);
Console.WriteLine(date.Value.ToString("ddMMyyyy")); // 04062014

I connected to.NET Framework Team about_this_problem here their_response;

Hi Soner,
The parsing code is not really looking for_any separator. Here is what
 _is going on:
For_the_case_of using “MMddyyyy”, the_parsing starts in the method
 _DoStrictParse which will call ParseByFormat. This_method will get the
  first part_of the format which is “MM”_and then calls ParseDigits _to
 _get the equivalent digits from_the string we_parse “642014”_which will
 _give “64”. Note that till that_time there is_no validation happen if
  the_number_is out of_range_for_the month_in the selected_calendar
_ (which_is_Gregorian in our case here). The_parsing_code will repeat
  the same process_for “dd” and will_get_equivalent part “20” and_then
  will repeat it_for “yyyy” but this fail because_it expect_4 digits_and
  we had only two (“14”).
For the case of using_“Mdyyyy”, it fails because almost same_reason
  when parsing_the part_“M”_we know that_the_month can_be 2 digits so
  we’ll map_it “64”_and will do the same with_“d” which map it_to_“20”
  and then year will_fail. I believe this is the_reason the
  documentation saying_always_use_the widest form.
The recommendation here_is either to use the 2_digit forms in_the
  string like "06042014" and the_parsing_should succeed with “MMddyyyy”
  and_“Mdyyyy”_too. other option is to insert_separator_"6/4/2014"_or
  "06/04/2014" and parse_as "M/d/yyyy"
Thanks, Tarek

Special thanks to; Tarek_Mahmoud Sayed, Wes Haggard and Richard Lander.

 Q:

Getting the_exact position of_a specific OpCode in a_binary_file

Our_professor in computer-architecture