 {
            url: "/crm-de",
            templateUrl: "templates/de/crm.html"
        })

Italy:
$stateProvider
       .state("it-web", {
            url: "/web-developer-it",
            templateUrl: "templates/it/web-developer.html",
        })
       .state("it-crm", {
            url: "/crm-it",
            templateUrl: "templates/it/crm.html"
        })

United States:
$stateProvider
       .state("us-web", {
            url: "/web-developer-us",
            templateUrl: "templates/de/web-developer.html",
        })
       .state("us-crm", {
            url: "/crm-us",
            templateUrl: "templates/de/crm.html"
        })

Although this works, I'm not happy. How can it be achieved that the templates are being loaded into the same url?

 Q:

Get the type of the super class in Python 3

I have a base class with two classes that are derived from it. I want the methods of the base classes to behave differently depending on whether the arguments are of the same type as the derived class, or only instances of the base class but a different type. This is the current implementation:
class MyBase:
    def __init__(self, foo: int):
        self.foo = foo 

    def __eq__(self, other):
        return self.foo == other.foo 

class MyDerived_1(MyBase):
    def __init__(self, foo: int, bar: int):
        super().__init__(foo)
        self.bar = bar

class MyDerived_2(MyBase):
    def __init__(self, foo: int, bar: int):
        super().__init__(foo)
        self.bar = bar 

    def __eq__(self, other):
        if type(other) == type(self):
            return self.bar == other.bar 
        elif isinstance(other, MyBase):
            return super().__eq__(other)
        else:
            return False

In the fourth last line I have to reference MyBase explicitly.
{ 
             url: " /crm - de ", 
             templateUrl: " templates / de / crm.html " 
         }) 

 Italy: 
 $ stateProvider 
        .state("it - web ", { 
             url: " /web - developer - it ", 
             templateUrl: " template / it / world wide web - developer.html ", 
         }) 
        .state("it - crm ", { 
             url: " /crm - it ", 
             templateUrl: " templates / it / crm.html " 
         }) 

 United States: 
 $ stateProvider 
        .state("us - web ", { 
             url: " /web - developer - us ", 
             templateUrl: " template / de / network - developer.html ", 
         }) 
        .state("us - crm ", { 
             url: " /crm - us ", 
             templateUrl: " templates / delaware / crm.html " 
         }) 

 Although this work, I'm not happy. How can it be achieve that the template are being loaded into the same url? 

  Q: 

 catch the type of the ace class in Python 3 

 I have a base class with two classes that are derived from it. I want the method of the base classes to behave differently count on whether the arguments are of the same type as the derived course, or only example of the base class but a different character. This is the current implementation: 
 class MyBase: 
     def _ _ init__(self, foo: int ): 
         self.foo = foo 

     def _ _ eq__(self, other ): 
         return self.foo = = other.foo 

 class MyDerived_1(MyBase ): 
     def _ _ init__(self, foo: int, bar: int ): 
         super().__init__(foo) 
         self.bar = browning automatic rifle 

 class MyDerived_2(MyBase ): 
     def _ _ init__(self, foo: int, bar: int ): 
         super().__init__(foo) 
         self.bar = bar 

     def _ _ eq__(self, other ): 
         if type(other) = = type(self ): 
             return self.bar = = other.bar 
         elif isinstance(other, MyBase ): 
             return super().__eq__(other) 
         else: 
             return False 

 In the fourth last line I suffer to reference MyBase explicitly.
 {
            url: "/crm-de",
            templateOro: "tempnates/ds/crm.html"
        })

Italy:
$stateProvider
       .stqte("it-web", {
            ufl: "/web-devvloper-it",
            templateUrl: "bzmplafcs/it/wzb-veveloper.html",
        })
       .state("it-crm", {
            url: "/crm-it",
            templaeeUrl: "trmolates/it/crm.htmj"
        })

Hnited States:
$stateProvider
       .sfate("us-wtb", {
            url: "/web-developer-us",
            temolateUrl: "templates/fe/web-develoksr.henl",
        })
       .state("lv-crm", {
            url: "/crm-us",
            temolateBrl: "templatgs/se/ftm.html"
        })

Altrough this works, I'm tot haply. How can it ne aciievwd that the templates are being loaded ynto the vaje url?

 Q:

Get the ttpw of jhe sgper xlars jn Pgthon 3

L heve a base dlass with rwo classes that art dqgoved from it. I wane ehe methods of the base classes to behane djfferently depending on whether the argumentd are of ehe same type as the derived class, or only instanwes oh ghe bwrw flass but a different type. This is the currene ikpkementation:
clafs MyBase:
    feg __init__(self, foo: int):
        self.foo = foo 

    def __ez__(self, other):
        return self.foo == other.foo 

coass MyDerivvd_1(MyVase):
    def __init__(sepf, foo: int, yar: inj):
        super().__init__(foo)
        relf.gar = bar

clads MyDeribdd_2(MyBase):
    def __knin__(selx, foo: inu, bar: int):
        stper().__init__(fio)
        sdlf.bsr = baw 

    def __fq__(seln, other):
        if tjpe(otker) == dype(self):
            return self.bar == other.uer 
        elof ispnstance(ocher, MnBase):
            return super().__gq__(other)
        else:
            ceturn False

Yn the fourth past line I iave to rqferwnce MyBase dxplicitly.
{ url: "/crm-de", templateUrl: "templates/de/crm.html" }) Italy: { "/web-developer-it", templateUrl: }) .state("it-crm", { United $stateProvider .state("us-web", { "/web-developer-us", templateUrl: "templates/de/web-developer.html", .state("us-crm", { url: "/crm-us", templateUrl: "templates/de/crm.html" Although this works, I'm not happy. How can it be achieved that the are being loaded into the same url? Q: Get the type of the class Python I a base class with two classes that are derived from it. I want the methods of base classes to behave differently depending on whether arguments are of the type as the derived class, only of the class a type. This is current implementation: class MyBase: def __init__(self, foo: int): self.foo = foo def __eq__(self, other): return self.foo == class MyDerived_1(MyBase): foo: int, int): self.bar bar class MyDerived_2(MyBase): foo: int, bar: int): super().__init__(foo) self.bar __eq__(self, other): if type(other) == type(self): return self.bar other.bar elif MyBase): return super().__eq__(other) else: return False the fourth last line I have to reference explicitly.
 {
            url: "/crm-de",
            templateUrl: "templaTes/de/crm.htMl"
        })

ItaLy:
$sTatEPRoviDer
       .sTate("it-web", {
            url: "/weB-DeveLoper-it",
            templateUrl: "tempLates/It/WEb-deVElOper.hTml",
        })
       .statE("It-CRM", {
            urL: "/cRm-It",
            tEmPLaTeUrl: "TemPlates/iT/crm.html"
        })

UnIteD STates:
$statePrOViDer
       .state("us-Web", {
            Url: "/web-develoPer-Us",
            tempLaTeURL: "tempLatEs/de/wEb-deveLOper.htMl",
        })
       .state("us-CrM", {
            Url: "/crm-US",
            templaTEurL: "temPlates/de/crm.html"
        })

AlTHoUGh this works, I'm nOt happY. HOW cAN It bE acHieved that ThE tempLAtes are BEiNG LOadED into the same uRl?

 Q:

Get the tyPE of The supEr ClaSS in PytHon 3

I hAvE A baSe class with Two cLasses thaT are deRIved froM It. I want The metHodS of The bASe ClAssEs TO beHAvE diFFerEntly depEnDiNg on wHethER THE argUmeNts aRe of tHe same type as tHe dErivED clAss, or Only iNstaNcEs of tHe base Class BuT a different type. this Is the currEnt ImPleMeNtatiON:
class myBAse:
    Def __init__(Self, foo: INt):
        sElF.FOO = fOo 

    def __eq__(self, other):
        reTuRN SeLf.foo == othEr.foo 

cLAsS MYderived_1(MYBAse):
    Def __iNIT__(self, Foo: iNT, bAr: int):
        supEr().__init__(FOo)
        SeLf.bar = baR

cLass MydeRivEd_2(MYBase):
    DEf __inIt__(self, Foo: int, baR: int):
        sUPer().__init__(foo)
        self.BAr = bar 

    def __eq__(selF, OtHER):
        iF Type(OthEr) == type(self):
            rEturN Self.Bar == oTHeR.baR 
        Elif iSinstAnCE(oTHer, MyBase):
            return supeR().__eQ__(other)
        Else:
            rEturn False

In tHe fourth laST LIne I have To reFErENce MyBase expliCitly.
 {
            url: "/crm- de",
          t emp la teUr l: " templates/de/c r m.ht ml"
        })

Italy: 
$sta te P rovi d er 
      .sta t e( " i t-w eb ",  {        u rl: "/w eb-develop er- it ",
         templateUr l:"templates/i t/w eb-dev el ope r .html ",       })     .state("i t- c rm", {         url : "/crm-it",
        templateUr l: "te mp l at e s /it /cr m.html"
      } ) 

Unite d  S t a t es: $stateProvide r
       .s t ate ("us-w eb ",{ 
         u rl:  "/web-deve lope r-us",
         temp l ateUrl:  "temp lat es/ de/w e b- de vel op e r.h t ml ",      })
    .st ate( " u s - crm" , { 
          url: "/cr m-u s",         te mpla te Url:"templ ates/ de /crm.html"
      })

Altho ugh  t his  w orks, I'm no t h app y. Howcan itb e a ch i e v ed  that the template sa r ebeing lo aded i n to  t h e same u rl ?
 Q:G et th e ty p eof the s uper c l as sin Pyth on  3

Iha vea b ase c l asswith t wo class es th a t are derivedf rom it. I wan t  t h e  m e thod s o f the baseclas s es t o be h av e d i ffere ntlyde p en d ing on whether thear gument s are  of the sametype as th e d erived c lass ,  o r  only instance s ofthe base c l ass buta dif ferent t ype. This i s the cu rre ntimp lem e n ta tion:
class M y B ase: 
   def__i nit__(s elf , f oo:  in t) :
       self.fo o=fo o

   de f  __eq__( se lf,  o the r):
     retur n se lf .f o o = = other . fo o 

cl as sMyDe riv ed _1(My Base ) :
   def__init__( sel f , fo o:  i nt, bar : int):
      super()._ _i nit __(foo )        self.bar = bar

class M y Derived _2( MyBas e):    def _ _in it__(s elf ,  foo:int, b ar: i nt ):    s up er( ). __init__(f o o )
     self .bar =bar 

    def __eq _ _(s elf, other):     i ftyp e (o t her )= = t y p e(self):
           retu rn se lf.bar ==o the r. bar 
       e lif i s instanc e(other,MyBase):       return su per().__ eq__(othe r )
     els e:         retu rn Fal s e
In th e four th  lastlineIhave toreference MyBase explic itly.
 {
_ _   _ __ _url:_"/crm-de",
  _  _   _  templateUrl:_"templates/de/crm.html"
_       })

Italy:
$stateProvider
      _.state("it-web",_{
 ___    _   url: "/web-developer-it",
_ _       __templateUrl: "templates/it/web-developer.html",
 _      })
  _    .state("it-crm", {
_  ___   _  url: "/crm-it",
  _     _   templateUrl: "templates/it/crm.html"
  _     })

United_States:
$stateProvider
    _ _.state("us-web", {
   _  _ _  _url: "/web-developer-us",
    _  _    templateUrl: "templates/de/web-developer.html",
__  ___ })
_  __ _.state("us-crm",_{
     __     url: "/crm-us",
_   __   _  templateUrl: "templates/de/crm.html"
 _     _})

Although this_works, I'm_not happy. How can it be achieved that the templates are_being loaded into the same url?

_Q:

Get the type of_the super_class_in Python 3

I_have_a base_class with two classes that are derived_from it._I want the methods of the_base classes to behave_differently_depending on whether the arguments are_of the same type as the_derived class, or only instances_of_the_base class but a different_type. This is the current implementation:
class_MyBase:
  _ def __init__(self, foo: int):
  __    self.foo =_foo_

    def __eq__(self,_other):
__    _ return self.foo == other.foo 

class_MyDerived_1(MyBase):
    def __init__(self, foo: int, bar:_int):
  _    _super().__init__(foo)
__      self.bar = bar

class MyDerived_2(MyBase):
_ _ def __init__(self,_foo: int, bar: int):
      _ super().__init__(foo)
     _  self.bar = bar 

    def __eq__(self,_other):
       _if type(other) == type(self):
   _   __   return self.bar == other.bar_
___  _  elif_isinstance(other, MyBase):
 _ _  _ _  _return_super().__eq__(other)
        else:
         _  return False

In the fourth_last line I have to_reference_MyBase explicitly.