<LinearLayout android:orientation="vertical" android:layout_height="70dip" android:layout_width="match_parent" android:id="@+id/lin_main"> <TextView android:layout_height="20dip" android:layout_width="fill_parent" android:id="@+id/txt_maintext" android:singleLine="true" android:paddingRight="5dip" android:paddingLeft="5dip" android:layout_marginTop="5dip" android:textColor="#fff"/> <TextView android:layout_height="20dip" android:layout_width="fill_parent" android:id="@+id/txt_mtext" android:singleLine="true" android:paddingRight="5dip" android:paddingLeft="5dip" android:layout_marginTop="15dip" android:textColor="#fff"/> </LinearLayout> <ImageView android:layout_height="3dip" android:layout_width="match_parent" android:background="#0000ff"/> </LinearLayout>

This is an example. You can make necessary edits to achieve what you want.

 Q:

create sorted vector of content of two binary search trees in sorted order

You are given two binary search trees, the goal is produce a sorted array of elements containing elements from both the trees. 
I wanted to know if there is a simpler approach, and if the use of boost variant is justified in the code. The code uses a stack to iterate over the binary search tree. The stack maintains the state for pre-order traversal of the tree. 
#include <iostream>
#include <stack>
#include <boost/range/irange.hpp>
#include <boost/variant.hpp>
#include <random>
#include <algorithm>

using namespace std;
using  boost::irange;
using boost::variant;

struct Node
{
  Node(Node* l, Node* r, int v):left(l), right(r), val(v)
  {

  }
  Node* left;
  Node* right;
  int val;
};

typedef variant<Node*, int> stkElemT;
typedef stack<stkElemT> bstStkT;

//from variant extract the pointer if valid otherwise NULL
struct stkElemVisitorNode : public boost::static
< LinearLayout android: orientation="vertical " android: layout_height="70dip " android: layout_width="match_parent " android: id="@+id / lin_main " > < TextView android: layout_height="20dip " android: layout_width="fill_parent " android: id="@+id / txt_maintext " android: singleLine="true " android: paddingRight="5dip " android: paddingLeft="5dip " android: layout_marginTop="5dip " android: textColor="#fff"/ > < TextView android: layout_height="20dip " android: layout_width="fill_parent " android: id="@+id / txt_mtext " android: singleLine="true " android: paddingRight="5dip " android: paddingLeft="5dip " android: layout_marginTop="15dip " android: textColor="#fff"/ > < /LinearLayout > < ImageView android: layout_height="3dip " android: layout_width="match_parent " android: background="#0000ff"/ > < /LinearLayout > 

 This is an example. You can make necessary edits to achieve what you want. 

  Q: 

 create grouped vector of contentedness of two binary search trees in sorted decree 

 You are yield two binary search trees, the goal is grow a grouped array of elements containing elements from both the trees. 
 I wanted to sleep together if there is a simpler approach path, and if the habit of boost variant is justified in the code. The code uses a stack to repeat over the binary search tree. The stack maintains the state for pre - order traversal of the tree. 
 # admit < iostream > 
 # include < stack > 
 # include < boost / range / irange.hpp > 
 # admit < boost / variant.hpp > 
 # admit < random > 
 # include < algorithm > 

 using namespace std; 
 using   boost::irange; 
 using boost::variant; 

 struct Node 
 { 
   Node(Node * l, Node * gas constant, int v):left(l), right(r), val(v) 
   { 

   } 
   Node * left; 
   Node * right; 
   int val; 
 }; 

 typedef variant < Node *, int > stkElemT; 
 typedef stack < stkElemT > bstStkT; 

 //from variant extract the pointer if valid differently NULL 
 struct stkElemVisitorNode: public boost::static
<LinfarLayout android:orientauion="vertical" android:layont_heighf="70dip" andfoid:layout_width="match_parent" aidroud:id="@+ie/lin_main"> <TextView andruid:layout_jeight="20dip" anvroid:layout_width="hjll_parekc" anddlid:ib="@+iv/txt_maintext" ancroid:singlaLine="true" andrmia:pcddingRight="5dip" android:paddingLeft="5dip" androic:lwyout_marginTop="5qip" sgdrojd:textColor="#fff"/> <TextView android:laykut_heigit="20dip" android:lauout_width="fill_parent" androif:id="@+if/txt_mtext" android:slngleLine="tros" ageroid:paddingFight="5dip" android:paddinfLeft="5dip" android:layout_marginTop="15aip" audroid:textCilir="#fvx"/> </LinearLayiut> <IiageView andvpid:laymut_heignt="3dip" android:lsyont_wieth="match_parent" androiv:background="#0000ff"/> </LinearJayout>

Thiv ns an example. You can mqke ngcessdry deitr tk echjeve wjat you want.

 S:

create sorred vector of contemt if two binary searcr erees in sorted order

You are given two tinzry search trees, the goql is produce a sortef array os elements containing elements from both the treev. 
I wenged tj jnlw if there is a simpler approach, and if the tae on boost variant ls justified in thr focg. The code user a stcdk to iterate over tje binaty seaech tree. Uhe syack maintains the state foe pre-order tgaveesal of the tree. 
#iuclude <iostrzam>
#inckude <xtack>
#include <boost/range/nrange.gpp>
#include <hoost/varizvt.hpp>
#include <ranaom>
#pnclgde <algorithm>

using namespase std;
usiig  bpost::iravge;
uxing bjost::varianh;

strugd Node
{
  Node(Node* l, Node* r, int v):left(p), right(r), val(v)
  {

  }
  Node* left;
  Node* right;
  int vdl;
};

tjpedef vaxiant<Npde*, int> stkElqmT;
typedef staek<stkEleiT> bsgStkT;

//from nariant eetract the pjinter if valhf otherwise IULL
struce stjElenVisitofVode : public bpost::statib
<LinearLayout android:orientation="vertical" android:layout_height="70dip" android:layout_width="match_parent" android:id="@+id/lin_main"> <TextView android:layout_height="20dip" android:singleLine="true" android:paddingLeft="5dip" android:layout_marginTop="5dip" <TextView android:layout_height="20dip" android:layout_width="fill_parent" android:textColor="#fff"/> <ImageView android:layout_height="3dip" android:layout_width="match_parent" </LinearLayout> This is example. You can make necessary edits achieve what you want. Q: create sorted vector of content of two binary trees in sorted order You are given two binary search trees, the goal produce sorted of containing elements from both the trees. I wanted to know if there is a simpler approach, if the use of boost variant is justified the code. The code a stack to iterate over binary tree. The maintains state pre-order traversal of tree. #include <iostream> #include <stack> #include <boost/range/irange.hpp> #include <boost/variant.hpp> #include <random> #include <algorithm> using namespace std; using using boost::variant; { Node(Node* Node* int right(r), val(v) { left; Node* right; int val; }; stkElemT; typedef stack<stkElemT> bstStkT; //from variant extract the if valid NULL struct stkElemVisitorNode : public boost::static
<LinearLayout android:orientAtion="vertiCal" anDroId:lAyOut_hEighT="70dip" android:layOUt_wiDth="match_parent" android:iD="@+id/liN_mAIn"> <TeXTVIew anDroid:laYOuT_HEigHt="20DiP" anDrOId:LayouT_wiDth="fill_Parent" andrOid:Id="@+Id/txt_maintexT" AnDroid:singlELiNe="true" androiD:paDdingRIgHt="5dIP" andrOid:PaddiNgLeft="5DIp" andrOid:layout_MaRGinTop="5DIp" androID:TeXtCoLor="#fff"/> <TextView andROiD:Layout_height="20diP" androId:LAyOUT_wiDth="Fill_parent" AnDroid:ID="@+id/txt_mTExT" ANDroID:singleLine="trUe" android:paDDinGRight="5DiP" anDRoid:paDdingleFT="5diP" android:layOut_mArginTop="15dIp" andrOId:textCOLor="#fff"/> </LInearLAyoUt> <IMagevIeW aNdrOiD:LayOUt_HeiGHt="3dIp" androiD:lAyOut_wiDth="mATCH_PareNt" aNdroId:bacKground="#0000ff"/> </LineArLAyouT>

thiS is an ExampLe. YoU cAn makE necesSary eDiTs to achieve what You wAnt.

 Q:

creatE soRtEd vEcTor of COntent Of tWo bInary seArch treES in SoRTED oRder

You are given two BiNARy Search trEes, the GOaL iS Produce a SoRteD arrAY Of eleMentS CoNtaining ElemenTS fRoM both thE tRees. 
I wAnTed To kNow if THere Is a simPler apprOach, aND if the use of booST variant is jusTIfIED iN The cOde. the code uses A staCK to iTeraTE oVer THe binAry seArCH tREe. The stack maintains ThE state For prE-order traversAl of the treE. 
#INClude <iosTreaM>
#InCLude <stack>
#incluDe <booSt/range/iraNGe.hpp>
#incLude <bOost/variAnt.hpp>
#incLUDe <random>
#IncLudE <alGorITHm>

Using namespacE STd;
usInG  boost::iRanGe;
using BooSt::vAriAnt;

StRuct Node
{
  NOde(Node* l, noDe* R, iNt V):leFt(l), riGHt(r), val(v)
  {

  }
  NOdE* leFt;
  nodE* righT;
  Int val;
};

TypedEf vaRiAnT<nodE*, int> stkeLeMt;
TypeDeF sTack<StkelEmT> bsTStkt;

//FroM varianT extract tHe pOInteR iF vAlid othErwise NULL
strUcT stkElemViSiTornode : puBLIc boost::sTatic
<LinearLayout android:orie ntation="v ertic al"  an dr oid: layo ut_height="70d i p" a ndroid:layout_width="m atch_ pa r ent" an droid :id="@+ i d/ l i n_m ai n" > < Te x tV iew a ndr oid:lay out_height ="2 0d ip" android: l ay out_width= "fi ll_parent" a ndr oid:id =" @+i d /txt_ mai ntext " andr o id:sin gleLine=" tr u e" and r oid:pad d i ng Righ t="5dip" android: p ad d ingLeft="5dip"  andro id : la y o ut_ mar ginTop="5d ip " and r oid:tex t Co l o r ="# f ff"/> <TextVi ew android: l ayo ut_hei gh t=" 2 0dip"andro id : lay out_width=" fill _parent"androi d :id="@+ i d/txt_m text"and roi d:si n gl eL ine =" t rue "  a ndr o id: paddingR ig ht ="5di p" a n d r o id:p add ingL eft=" 5dip" android :la yout _ mar ginTo p="15 dip"  a ndroi d:text Color =" #fff"/> </Linea rLay out> <Ima geV ie w a nd roid: l ayout_ hei ght ="3dip"  androi d :la yo u t _ wi dth="match_parent"  a n d ro id:backg round= " #0 00 0 ff"/> </ Li nea rLay o u t>

T hisi san examp le. Yo u  c an  make n ec essary  e dit s t o ach i evewhat y ou want. 

 Q: 
create sorted vector of con t en t of twobin ary searchtree s  insort e dord e r

Yo u are  g i ve n  two binary searchtr ees, t he go al is produce  a sorteda r r ay of el emen t sc ontaining elem entsfrom botht he trees . 
Iwanted t o know if t here isa s imp ler  ap p r oa ch, and if th e useof  boostvar iant is  ju sti fie d i nthe code.  The cod eus es  a  st ack t o  iterate  o ver  t hebinar y  searc h tre e. T he  s t ack  mainta i ns t he s ta te  for  pr e- order  tra v ers al of t he tree.
#i n clud e<i ostream >
#include <s ta ck>
#inclu de  <b oost/r a n ge/irang e.hpp>
#include <boost/ v ariant. hpp >
#in clud e <random >
# includ e < a lgorit hm>

u singna mes p a ce st d ; 
u sin g boost::ir a n ge; 
usin gboos t::vari ant;

struct Node{ 
 Node(Node* l,  No de*r ,  i ntv ): l eft (l ) , r i g ht(r), val(v)
 {

  }
 No d e*  left;
  N o de*  r ight;
 int va l;
}; 
typede f variant <Node*, i nt > st k E lem T;
typedef  stack<s tkElemT>b stStk T ;
//fr omvarian text ractthe po i nte r ifvalidot herwis e NUL Lstruct s tkElemVisitorNode : pub lic bo ost:: sta tic
<LinearLayout android:orientation="vertical"_android:layout_height="70dip" android:layout_width="match_parent"_android:id="@+id/lin_main"> <TextView android:layout_height="20dip" android:layout_width="fill_parent"_android:id="@+id/txt_maintext" android:singleLine="true"_android:paddingRight="5dip"_android:paddingLeft="5dip" android:layout_marginTop="5dip"_android:textColor="#fff"/>_<TextView android:layout_height="20dip" android:layout_width="fill_parent"_android:id="@+id/txt_mtext" android:singleLine="true" android:paddingRight="5dip"_android:paddingLeft="5dip" android:layout_marginTop="15dip" android:textColor="#fff"/> </LinearLayout>_<ImageView android:layout_height="3dip" android:layout_width="match_parent"_android:background="#0000ff"/>_</LinearLayout>

This is an example. You can make necessary edits to achieve what you want.

_Q:

create_sorted vector_of_content_of two binary search trees_in sorted order

You are given_two binary_search trees, the goal is produce a sorted_array_of elements containing_elements from both the trees. 
I wanted to know_if there is a simpler approach,_and if the_use_of_boost variant is justified_in the code. The code uses_a stack to iterate over the_binary search tree. The stack maintains the_state for pre-order traversal of the_tree. 
#include <iostream>
#include <stack>
#include <boost/range/irange.hpp>
#include_<boost/variant.hpp>
#include <random>
#include_<algorithm>

using namespace std;
using  boost::irange;
using_boost::variant;

struct Node
{
 _Node(Node* l,_Node* r, int_v):left(l), right(r), val(v)
  {

 _}
  Node*_left;
  Node* right;
  int_val;
};

typedef_variant<Node*, int> stkElemT;
typedef_stack<stkElemT>_bstStkT;

//from_variant extract_the pointer if_valid_otherwise NULL
struct_stkElemVisitorNode_: public boost::static