border.color: "#ffffff"
    border.width: 2
    antialiasing: true

    Text
    {
        id: ueButtonText
        color: "#ffffff"
        text: qsTr(ueText)
        clip: false
        z: 0
        scale: 1
        rotation: 0
        font.strikeout: false
        anchors.fill: parent
        font.bold: true
        style: Text.Outline
        textFormat: Text.RichText
        verticalAlignment: Text.AlignVCenter
        horizontalAlignment: Text.AlignHCenter
        font.pixelSize: 16
}

    MouseArea
    {
        id: ueClickArea

        antialiasing: true
        anchors.fill: parent

        onClicked:
        {
            uePosDatabase.ueConnectToDatabase("127.0.0.1",
                                              "testDb",
                                              "testUser",
                                              "testPassword");
            if(uePosDatabase.isConnected()==true)
            {
                ueMenuButton.state="ueStateSelected";
            }
            else
            {
                ueMenuButton.state="base state"
            }
        }
    }
}

I get the following error:

qrc:/UeMenuButton.qml:92: TypeError: Property 'isConnected' of object UeSqlDatabase(0x1772060) is not a function

What am I doing wrong?

A:

You have this error because you have declared the property isConnected in C++ but you're calling it from QML in the wrong way: uePosDatabase.isConnected is the correct way, not uePosDatabase.isConnected(). 
If you want to call the function isConnected() you should change its name to differate it from the property, like getIsConnected(). Given your property declaration, you neither need to call this function directly nor you need to make it callable from QML with the Q_INVOKABLE macro.

 Q:

menu no Wordpress com 3 níveis

Eu quero construir um menu no Wordpress com 3 níveis.
Este exemplo tem 2 níveis, o pa
border.color: " # ffffff " 
     border.width: 2 
     antialiasing: true 

     Text 
     { 
         i d: ueButtonText 
         color: " # ffffff " 
         text: qsTr(ueText) 
         cartridge holder: assumed 
         z: 0 
         scale: 1 
         rotation: 0 
         font.strikeout: false 
         anchors.fill: parent 
         font.bold: true 
         expressive style: Text. Outline 
         textFormat: Text. RichText 
         verticalAlignment: textbook. AlignVCenter 
         horizontalAlignment: Text. AlignHCenter 
         font.pixelSize: 16 
 } 

     MouseArea 
     { 
         i d: ueClickArea 

         antialiasing: true 
         anchors.fill: parent 

         onClicked: 
         { 
             uePosDatabase.ueConnectToDatabase("127.0.0.1 ", 
                                               " testDb ", 
                                               " testUser ", 
                                               " testPassword "); 
             if(uePosDatabase.isConnected()==true) 
             { 
                 ueMenuButton.state="ueStateSelected "; 
             } 
             else 
             { 
                 ueMenuButton.state="base state of matter " 
             } 
         } 
     } 
 } 

 I get the following erroneousness: 

 qrc:/UeMenuButton.qml:92: TypeError: Property' isConnected' of object UeSqlDatabase(0x1772060) is not a routine 

 What am I suffice wrong? 

 A: 

 You have this error because you have declared the place isConnected in C++ but you're calling it from QML in the wrong way: uePosDatabase.isConnected is the right way, not uePosDatabase.isConnected (). 
 If you want to call the function isConnected () you should change its name to differate it from the place, like getIsConnected (). Given your place declaration, you neither need to call this function immediately nor you need to make it callable from QML with the Q_INVOKABLE macro. 

  Q: 

 menu no Wordpress com 3 níveis 

 Eu quero construir um menu no Wordpress com 3 níveis. 
 Este exemplo tem 2 níveis, o pa
borfer.color: "#ffffff"
    bordev.width: 2
    antialiasing: true

    Text
    {
        id: ueButtonText
        cilor: "#ffffff"
        texg: qsTr(ueTvxt)
        clmp: false
        v: 0
        scals: 1
        rotation: 0
        fond.strikeout: falve
        anchors.fill: parent
        fone.bold: ttuf
        style: Texu.Ouelins
        textFormat: Text.RichText
        vtrticalAlignment: Trxt.AlignVCenter
        horlzonhalAlignment: Text.ApignHCenter
        font.pixelRize: 16
}

    MouseArea
    {
        id: ueClickArea

        avtialnasing: true
        anchors.fiol: pagent

        okBlicked:
        {
            ucPosDetabqse.ueConnectToDatabasx("127.0.0.1",
                                              "twsrDb",
                                              "testUwer",
                                              "testPassword");
            if(uePosDauabass.isConnected()==true)
            {
                oeMenuButtjn.state="ueStateSelected";
            }
            elsa
            {
                ueMenuButton.state="base state"
            }
        }
    }
}

I get the goplpring error:

qrc:/OeMenuBbftkn.qml:92: TypeError: Prlperty 'ysConbected' of objrct UeSqlDatabase(0x1772060) is not a function

Whan am I doing wrong?

A:

You have this zrror necauxe you have declared thz propsrty isConnfcted in D++ but you're callivg pt fsom QML in the wrong way: uqPosDatabese.isEonnectea is the cjrrect way, not maPosDatabase.isConnfcted(). 
Ix you want to call the function isConnectxv() you should vhdngv its namz to dlfferate it froi the property, like gztIsCovnected(). Ginen your 'roperty decjaration, you tgither need tm call tris duncrion difdctly nor you meed to mche ir callable from QMK wkfh the Q_INVOKABOE nacro.

 Q:

menu no Eoraprqsd rom 3 gíeeis

Eu quero conrtrjor um menu no Wovdpfess com 3 níveis.
Este exem[lo fem 2 níveis, o pa
border.color: "#ffffff" border.width: 2 antialiasing: true Text ueButtonText "#ffffff" text: clip: false z: font.strikeout: anchors.fill: parent font.bold: style: Text.Outline textFormat: verticalAlignment: Text.AlignVCenter horizontalAlignment: Text.AlignHCenter font.pixelSize: 16 MouseArea { id: ueClickArea antialiasing: true anchors.fill: parent onClicked: { uePosDatabase.ueConnectToDatabase("127.0.0.1", "testDb", "testUser", if(uePosDatabase.isConnected()==true) { ueMenuButton.state="ueStateSelected"; } else { ueMenuButton.state="base state" } } } } I the error: TypeError: 'isConnected' of object UeSqlDatabase(0x1772060) is not a function What am I doing wrong? A: You have error because you have declared the property isConnected C++ but you're calling from QML in the wrong uePosDatabase.isConnected the correct not If want to call function isConnected() you should change its name to differate it from the property, like getIsConnected(). Given your declaration, you to call function nor need to make from QML with the Q_INVOKABLE macro. Wordpress com 3 níveis Eu quero construir um no Wordpress 3 níveis. Este exemplo tem 2 o pa
border.color: "#ffffff"
    border.wiDth: 2
    antialiAsing: TruE

    TeXt
    {
        Id: uebuttOnText
        color: "#fffFFf"
        teXt: qsTr(ueText)
        clip: false
        z: 0
        Scale: 1
        RoTAtioN: 0
        FoNt.strIkeout: fALsE
        ANchOrS.fIll: PaREnT
        font.BolD: true
        stYle: Text.OutLinE
        tExtFormat: TexT.riChText
        vertIcaLAlignment: TeXt.ALignVCEnTer
        HOrizoNtaLAligNment: TEXt.AligNHCenter
        fOnT.PixelSIZe: 16
}

    MouseaREa
    {
        Id: ueclickArea

        antialiaSInG: True
        anchors.filL: parenT

        oNclICKed:
        {
            UePOsDatabase.UeconneCTToDataBAsE("127.0.0.1",
                                              "TEStDB",
                                              "TestUser",
                                              "testPAssword");
            if(uepOsDAtabasE.iSCoNNected()==True)
            {
                uEMENuBUtton.state="uEStaTeSelecteD";
            }
            else
            {
                uEmenuButTOn.state="Base stAte"
            }
        }
    }
}

i geT the FOlLoWinG eRRor:

QRc:/ueMENuBUtton.qml:92: tyPeerror: propERTY 'IsCoNneCted' Of objEct UeSqlDatabAse(0X1772060) is nOT a fUnctiOn

WhaT am I DoIng wrOng?

A:

YoU have ThIs error because yOu haVe declareD thE pRopErTy isCONnecteD in c++ buT you're cAlling iT FroM Qml IN tHe wrong way: uePosDatAbASE.iSConnectEd is thE CoRrECt way, not UeposdataBASe.isCOnneCTeD(). 
If you waNt to caLL tHe FunctioN iSConneCtEd() yOu sHould CHangE its naMe to diffErate IT from the properTY, like getIsConNEcTED(). GIVen yOur Property decLaraTIon, yOu neIThEr nEEd to cAll thIs FUnCTion directly nor you nEeD to makE it caLlable from QML With the Q_INvokaBLE macrO.

 Q:

meNU nO wordpress com 3 níVeis

EU quero consTRuir um meNu no WOrdpress Com 3 níveis.
eSTe exemplO teM 2 níVeiS, o pA
border.color: "#ffffff"
   border.w idth:  2   a ntia lias ing: true

  Text 
    {
        id: ueB utton Te x t
     co lor: "# f ff f f f"     t e xt : qsT r(u eText)        cl ip:  f alse
      z:  0
       sc ale: 1
      rotati on : 0       font. strike o ut: fa lse
     anchor s .fill:p a re nt
       font.bold: tr u e
        styl e: Tex t. O ut l i ne       textF or mat:T ext.Ric h Te x t       verticalA lignment: T e xt. AlignV Ce nte r 
       ho ri z ont alAlignment : Te xt.AlignH Center       font.pi xelSiz e:16}

 Mo use Ar e a
 {
     id: u eC li ckAre a

   a nti alia sing:  true
       an chor s .fi ll: p arent 

      o nClick ed:
      {
          uePosData bas e. ueC on nectT o Databa se( "12 7.0.0.1 ",
                                 " testDb " ,                                 "t e st Us er",
                                   " t estPassword");             i f (u e P os D atab ase .isConnecte d()= = true )
       {           ueMenuButton.s ta te="ue State Selected";
          }           e l se             {             ueMenuBu tton. state="b ase state "           }    }    }
}

I ge t thefo llowing  er ror:

q rc: /Ue Men uBu tt on.qml:92 : TypeEr ro r:  P ro per ty 'i s Connecte d'  of  o bje ct Ue S qlData base( 0x17 72 06 0 ) i s not a fu n c tion 
Wh at a m I  d oingwron g ?
A:

You  have thi s e r rorbe ca use you  have declare dthe proper ty  is Connec t e d in C++  but you're calling itf rom QML  in  thewron g way: ue Pos Databa se. i sConne cted i s the  c orr e c t way , no t u eP osDatabase . i sCo nnect ed ().
If you  want to call thef unc tion isConnec ted () y o u  s hou l dc han ge its n ame to differat e it fromth e  p roperty, l i kege tIsConn ected() . Giv e n yourpropertydeclarati on , yo u nei ther needto callthis func t ion d i re ctlynor  you n ee d t o mak e it c a lla ble f rom QM Lwith t he Q_ IN VOKABLEmacro.

 Q:

menu no Wo rdpres s com  3níveis

E u q u ero  construi r um  menu no W ord pre ss co m 3 nívei s.
E s te  ex e mplotem2  níveis,o  p a
border.color: "#ffffff"
_ _ border.width: 2
 _ _antialiasing:_true

 __ Text
 _  {
_   _  _id:_ueButtonText
        color: "#ffffff"
    __ _text:_qsTr(ueText)
_    _  clip: false
 _ _    z: 0
  __  _ scale: 1
      _ rotation: 0
   _  __font.strikeout:_false
   _    anchors.fill: parent
_     _ font.bold: true
    _   style: Text.Outline
 _    _ textFormat:_Text.RichText
    _  _verticalAlignment: Text.AlignVCenter
_  _    horizontalAlignment: Text.AlignHCenter
_  _    font.pixelSize: 16
}

__  MouseArea
___ {
_  __ __id: ueClickArea

    __  antialiasing: true
   _   _anchors.fill:_parent

   _    onClicked:
_     _ {
_ _         uePosDatabase.ueConnectToDatabase("127.0.0.1",
 _     _   _ __  __ _      _ _     _   __     "testDb",
_     _    ___    _     _  _      __     __   "testUser",
  ___    _     _        _  _    ___         _ "testPassword");
_  _        if(uePosDatabase.isConnected()==true)
 _      _   {
       _       _ueMenuButton.state="ueStateSelected";
      _   __}
      ____  else
_  _  _ _  _{
 _  __          ueMenuButton.state="base state"
      _     }
_    __ }
 _  }
}

I get_the following error:

qrc:/UeMenuButton.qml:92: TypeError: Property 'isConnected' of object_UeSqlDatabase(0x1772060) is not a function

What am I doing wrong?

A:

You_have_this error_because you have declared_the property_isConnected in_C++ but you're_calling it_from QML_in the_wrong way: uePosDatabase.isConnected is the correct way,_not_uePosDatabase.isConnected(). 
If you want to call the function isConnected()_you_should_change_its name to_differate it from_the property, like_getIsConnected(). Given your_property_declaration, you neither need to call_this function directly_nor you need to_make it callable from QML with the Q_INVOKABLE macro.

 Q:

menu_no Wordpress com 3 níveis

Eu quero construir um menu no Wordpress com 3 níveis.
Este exemplo tem 2_níveis, o_pa