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#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(0); int n, d; cin >> n >> d; vector<pair<int, int> > fr(n); for (int i = 0; i < n; i++) cin >> fr[i].first >> fr[i].second; sort(fr.begin(), fr.end()); vector<long long> w(n + 1, 0); for (int i = 1; i <= n; i++) w[i] = w[i - 1] + fr[i - 1].second; long long ans = -1; for (int i = 0; i < n; i++) { int mn = max(0, fr[i].first - d + 1); int ln = 0, rn = n - 1; while (fr[ln].first < mn) { int m = (rn + ln) / 2; if (fr[m].first < mn) ln = m + 1; else rn = m; } int mx = mn + d - 1; int lx = 0, rx = n - 1; while (fr[rx].first > mx) { int m = (rx + lx) / 2; if (fr[m].first > mx) rx = m - 1; else lx = m + 1; } ans = max(ans, w[rx + 1] - w[ln]); } cout << ans; return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int main() { long long n, d; cin >> n >> d; vector<pair<long long, long long>> v; long long a, b; for (long long i = 0; i < n; i++) { cin >> a >> b; v.push_back({a, b}); } sort(v.begin(), v.end()); long long i = 0, j = 0, ma = 0, cur = 0; while (j < v.size()) { if (v[j].first - v[i].first < d) { cur += v[j].second; ma = max(cur, ma); j++; } else { cur -= v[i].second; ma = max(cur, ma); i++; if (i > j) { j = i; } } } cout << ma; return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; vector<pair<long long, long long> > a; long long b[100001], c[100001]; int n; long long d; bool gr(pair<int, int> a, pair<int, int> b) { if (a.second < b.second) return false; return true; } int main() { cin >> n >> d; for (int i = 0; i < n; i++) { int x, y; cin >> x >> y; a.push_back(make_pair(x, y)); } sort(a.begin(), a.end()); long long ans = 0; long long sum = 0; int l = 0; for (int i = 0; i < n; i++) { sum += a[i].second; while (a[i].first - a[l].first >= d) { sum -= a[l].second; l++; } if (ans < sum) ans = sum; } cout << ans; return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n, diff; cin >> n >> diff; vector<pair<int, int>> v(n); for (int i = 0; i < n; i++) { int x, y; cin >> x >> y; v[i] = make_pair(x, y); } sort(v.begin(), v.end()); long long l = 0, r = 1, sum = v[0].second, ans = sum; while (r < n) { if (abs(v[r].first - v[l].first) < diff) { sum += v[r].second; ans = max(sum, ans); r++; } else { sum -= v[l].second; l++; } } cout << ans << endl; return 0; }
8
CPP
r = lambda: map(int,input().split()) f,m = r() l = [list(r()) for _ in range(f)] l = sorted(l,key = lambda x: x[0]) last = 0 max_score = 0 current_score = 0 for cash, friend in l: if cash >= (last+m): max_score = max(max_score,current_score) current_score = friend last = cash else: current_score += friend max_score = max(max_score,current_score) print (max_score)
8
PYTHON3
#!/usr/bin/env python3 if __name__ == "__main__": n, d = map(int, input().split()) li = [] for i in range(n): m, s = map(int, input().split()) li.append((m,s)) li = sorted(li) total = li[0][1] maxTotal = li[0][1] p = 0 for i in range(1,n): while li[i][0] >= d + li[p][0]: total -= li[p][1] p += 1 total += li[i][1] maxTotal = max(maxTotal, total) print(maxTotal)
8
PYTHON3
import re import sys exit=sys.exit from bisect import bisect_left as bsl,bisect_right as bsr from collections import Counter,defaultdict as ddict,deque from functools import lru_cache cache=lru_cache(None) from heapq import * from itertools import * from math import inf from pprint import pprint as pp enum=enumerate ri=lambda:int(rln()) ris=lambda:list(map(int,rfs())) rln=sys.stdin.readline rl=lambda:rln().rstrip('\n') rfs=lambda:rln().split() mod=1000000007 d4=[(0,-1),(1,0),(0,1),(-1,0)] d8=[(-1,-1),(0,-1),(1,-1),(-1,0),(1,0),(-1,1),(0,1),(1,1)] ######################################################################## n,d=ris() a=[] for _ in range(n): a.append(ris()) a.sort() ans=s=l=0 for r in range(n): s+=a[r][1] while d<=a[r][0]-a[l][0]: s-=a[l][1] l+=1 ans=max(ans,s) print(ans)
8
PYTHON3
z,zz=input,lambda:list(map(int,z().split())) zzz=lambda:[int(i) for i in stdin.readline().split()] szz,graph,mod,szzz=lambda:sorted(zz()),{},10**9+7,lambda:sorted(zzz()) from string import * from re import * from collections import * from queue import * from sys import * from collections import * from math import * from heapq import * from itertools import * from bisect import * from collections import Counter as cc from math import factorial as f from bisect import bisect as bs from bisect import bisect_left as bsl from itertools import accumulate as ac def lcd(xnum1,xnum2):return (xnum1*xnum2//gcd(xnum1,xnum2)) def prime(x): p=ceil(x**.5)+1 for i in range(2,p): if (x%i==0 and x!=2) or x==0:return 0 return 1 def dfs(u,visit,graph): visit[u]=True for i in graph[u]: if not visit[i]: dfs(i,visit,graph) ###########################---Test-Case---################################# """ """ ###########################---START-CODING---############################## n,m=zz() lst=[] for _ in range(n): lst.append(zz()) lst=sorted(lst) ans=0 l=0 s=0 for i in range(n): for j in range(i+1): if lst[i][0]-lst[l][0]>=m: s-=lst[l][1] l+=1 if l>n: l=n-1 else: break s+=lst[i][1] ans=max(ans,s) print(ans)
8
PYTHON3
#!/usr/bin/python3 # -*- coding: <utf-8> -*- import itertools as ittls from collections import Counter def sqr(x): return x*x def inputarray(func = int): return map(func, input().split()) # ------------------------------- # ------------------------------- N, d = map(int, input().split()) A = [(None, None)]*N for i in range(N): A[i] = tuple(map(int, input().split())) A.sort(key=lambda x: x[0]) prefix = [0] + [None]*len(A) for i, (money, friendship) in enumerate(A): prefix[i + 1] = prefix[i] + friendship res, i, j = 0, 0, 0 while i < len(A): while j < len(A) and A[j][0] < A[i][0] + d: j = j + 1 if prefix[j] - prefix[i] > res: res = prefix[j] - prefix[i] i = i + 1 print(res)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; long long int gcd(long long int a, long long int b) { while (a && b) a > b ? a %= b : b %= a; return a + b; } long long int lcm(long long int a, long long int b) { return (max(a, b) / gcd(a, b)) * min(a, b); } long long int power(long long int a, long long int b) { long long int res = 1; while (b != 0) { if (b % 2 != 0) { res = (res * a) % 1000000007; b--; } else { a = (a * a) % 1000000007; b /= 2; } } return res; } long long int f[100005]; long long int n, d; pair<long long int, long long int> v[100005]; long long int Find(long long int u) { long long int l = 0, r = n; while (l < r) { long long int m = (l + r + 1) / 2; if (v[m].first > u) r = m - 1; else l = m; } return l; } int main() { ios::sync_with_stdio(0); ; long long int i, j, k, c = 0, m, t, l, r, x, y, w, low, high, mid; string s; cin >> n >> d; vector<long long int> a, b; for (i = 1; i <= n; i++) { cin >> v[i].first >> v[i].second; } sort(v + 1, v + n + 1); for (i = 1; i <= n; i++) { f[i] = f[i - 1] + v[i].second; c = max(c, f[i] - f[Find(v[i].first - d)]); } cout << c; return 0; }
8
CPP
n,d = map(int,input().split()) friends = [] for i in range(n): money, factor = map(int,input().split()) friends.append([money,factor]) friends.sort() ans = 0 tmp_ans = friends[0][1] back = 0 front = 1 while front < n: if friends[front][0] - friends[back][0] < d: tmp_ans+=friends[front][1] front+=1 else: if tmp_ans > ans: ans = tmp_ans while friends[front][0] - friends[back][0] >= d: tmp_ans -= friends[back][1] back+=1 if back == front: tmp_ans+=friends[back][1] front+=1 if tmp_ans > ans: ans = tmp_ans print(ans)
8
PYTHON3
if __name__ == '__main__': n, d = map(int, input().split()) line = list() for i in range(n): line.append(list(map(int, input().split()))) line.sort(key=lambda a: a[0]) refer = list() note = line[0][0] flag_a = flag_b = False flag_v = 0 for i in range(n - 1): if flag_a: if flag_v - line[i][0] >= d: continue else: flag_a = False if flag_b: break for j in range(i + 1, n): if line[j][0] - line[i][0] >= d: refer.append(sum([line[k][1] for k in range(i, j)])) flag_a = True flag_v = line[j][0] break if j == n - 1: refer.append(sum([line[k][1] for k in range(i, n)])) flag_b = True break refer.append(line[-1][1]) print(max(refer))
8
PYTHON3
#include <bits/stdc++.h> using namespace std; inline void in(int &n) { n = 0; int ch = getchar(); int sign = 1; while (ch < '0' || ch > '9') { if (ch == '-') sign = -1; ch = getchar(); } while (ch >= '0' && ch <= '9') { n = (n << 3) + (n << 1) + ch - '0', ch = getchar(); } n = n * sign; } pair<int, int> a[100005]; int b[100005]; long long int f[100005]; int main() { int n, d; in(n); in(d); for (int i = 1; i <= n; i++) { in(a[i].first); in(a[i].second); } sort(a + 1, a + 1 + n); for (int i = 1; i <= n; i++) { b[i] = a[i].first; } for (int i = n; i >= 1; i--) { f[i] = f[i + 1] + a[i].second; } long long int ans = 0; for (int i = 1; i <= n; i++) { int up = upper_bound(b + 1, b + 1 + n, a[i].first + d - 1) - (b + 1); ans = max(ans, f[i] - f[up + 1]); } printf("%I64d\n", ans); return 0; }
8
CPP
from sys import stdin, stdout lines = stdin.readlines() n, d = int(lines[0].split()[0]), int(lines[0].split()[1]) a = sorted([[int(x.split()[0]),int(x.split()[1])] for x in lines[1:]]) max_val = 0 start_pointer = 0 cur_val = 0 for end_pointer in range(n): cur_val += a[end_pointer][1] while (a[end_pointer][0] - a[start_pointer][0]) >= d: cur_val -= a[start_pointer][1] start_pointer += 1 if cur_val > max_val: max_val = cur_val print(max_val)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; void solve() { long long n, d; cin >> n >> d; vector<std::pair<int, int> > v; long long m, s; for (int i = 0; i < (n); ++i) { cin >> m >> s; v.push_back(make_pair(m, s)); } sort(v.begin(), v.end()); long long maxm = v[0].second, sum = 0, prev = v[0].first, index = 0; for (int i = 1; i <= (n - 1); ++i) { if (i == 1 && v[i].first - prev < d) { sum += v[i - 1].second; maxm = max(sum, maxm); } if (v[i].first - prev < d) { sum += v[i].second; maxm = max(sum, maxm); } else { sum -= v[index].second; maxm = max(sum, maxm); index++; prev = v[index].first; i--; } } cout << maxm; } int main() { std::ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); int t; t = 1; while (t--) { solve(); } return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; const int MOD = 1000000007; const long long int INF = 1e18; const int MX = 300001; int rownum[] = {-1, 0, 0, 1}; int colnum[] = {0, -1, 1, 0}; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); ; long long int t, x, y, p, q, c, e, i, j, n, m, k; cin >> n >> p; vector<pair<long long int, long long int> > v; vector<long long int> vf; for (i = 0; i < n; i++) { cin >> x >> y; v.push_back(make_pair(x, y)); vf.push_back(x); } sort(v.begin(), v.end()); sort(vf.begin(), vf.end()); for (i = 1; i < n; i++) { v[i].second += v[i - 1].second; } k = 0; for (i = 0; i < n; i++) { q = upper_bound(vf.begin(), vf.end(), vf[i] + p - 1) - vf.begin(); if (i == 0) k = max(k, v[q - 1].second); else k = max(k, v[q - 1].second - v[i - 1].second); } cout << k; }
8
CPP
import bisect n,d=map(int,input().split()) a,b,c,i1,l,s,st,lt=0,0,0,0,[],[],[],[] f=0 for i,j in enumerate(range(n)): m,p=map(int,input().split()) l.append([m,p]) l=sorted(l,key=lambda li:li[0]) for i , j in enumerate(range(n)): s.append(l[i][0]) st.append(l[i][1]) while i1<=n-1: a=bisect.bisect_right(s,(s[i1]+(d-1)))-1 c=bisect.bisect_left(s,(s[a]-(d-1))) f=bisect.bisect_left(s,(s[i1]-(d-1))) lt.append(sum(st[c:a+1])) lt.append(sum(st[f:i1+1])) i1=a+1 print(max(lt))
8
PYTHON3
n,d = list(map(int,input().split())) arr = [] for i in range(n): arr.append(list(map(int,input().split()))) arr.sort() l,r = 0,0 ans = 0 t = 0 # print(arr) while r<n: # print(l,r) if arr[r][0]-arr[l][0]<d: t+=arr[r][1] r+=1 else: ans = max(ans,t) t-=arr[l][1] l+=1 ans = max(ans,t) print(ans)
8
PYTHON3
def binary_search(arr, n, key): l, r = 0, n-1 while (l <= r): mid = l+r >> 1 if (arr[mid][0] <= key): l = mid+1 else: r = mid-1 return l def main(): n, d = map(int, input().split()) arr = [] for _ in range(n): m, s = map(int, input().split()) arr += [(m, s)] arr.sort() arr_acc = [0] * (n+1) for i in range(n): arr_acc[i+1] = arr_acc[i] + arr[i][1] res = 0 for i in range(n): key = arr[i][0]+d-1 j = binary_search(arr, n, key) res = max(res, arr_acc[j] - arr_acc[i]) print(res) main()
8
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); ; long long int i, d, j, k, l, t, n; cin >> n >> d; vector<pair<long long int, long long int>> v; l = -1; for (i = 0; i < n; i++) { cin >> j >> k; v.push_back(make_pair(j, k)); } sort(v.begin(), v.end()); long long int cnt = v[0].first; long long int ci = 0; long long int ans = v[0].second; long long int sum = v[0].second; for (i = 1; i < n; i++) { if (v[i].first - cnt < d) { sum += v[i].second; continue; } else { ans = max(ans, sum); sum += v[i].second; for (j = ci; j < i; j++) { if (v[i].first - v[j].first < d) { cnt = v[j].first; ci = j; break; } else sum -= v[j].second; } if (j == i) { cnt = v[i].first; ci = i; } } } ans = max(ans, sum); cout << ans << endl; }
8
CPP
#include <bits/stdc++.h> using namespace std; void err(istream_iterator<string> it) {} template <typename T, typename... Args> void err(istream_iterator<string> it, T a, Args... args) { cerr << *it << " = " << a << "\n"; err(++it, args...); } struct xx { bool operator()(pair<int, int>& x, pair<int, int>& y) { return y.first > x.first; } }; int main() { ios_base::sync_with_stdio(false), cin.tie(NULL); int n, d; cin >> n >> d; vector<pair<int, int>> arr(n); for (int i = 0; i < n; i++) { int x, y; cin >> x >> y; arr[i] = {x, y}; } sort(arr.begin(), arr.end(), xx()); long long max_factor = INT_MIN; long long maxx = 0; int j = 0; for (int i = 0; i < n && j < n;) { if (abs(arr[j].first - arr[i].first) < d) { maxx += arr[j].second; j++; } else { { string _s = "maxx"; replace(_s.begin(), _s.end(), ',', ' '); stringstream _ss(_s); istream_iterator<string> _it(_ss); err(_it, maxx); }; max_factor = max(maxx, max_factor); maxx -= arr[i].second; i++; } max_factor = max(maxx, max_factor); } cout << max_factor; }
8
CPP
#include <bits/stdc++.h> using namespace std; const int N = 1e5 + 1; pair<int, int> a[N]; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, d; cin >> n >> d; for (int i = 0; i < n; ++i) cin >> a[i].first >> a[i].second; sort(a, a + n); int L = 0, R = 0; long long temp = 0, ans = INT_MIN; while (R < n) { temp += a[R++].second; while (a[R - 1].first - a[L].first >= d) temp -= a[L++].second; ans = max(ans, temp); } cout << ans << '\n'; return 0; }
8
CPP
n, d = map(int, input().split()) p = [] for i in range(n): m, f = map(int, input().split()) p.append([m, f]) p = sorted(p) x2 = 0 max_f = 0 f = 0 for x1 in range(n): x2 = max(x1, x2) while x2 < n and p[x2][0] - p[x1][0] < d: f += p[x2][1] x2 += 1 if f > max_f: max_f = f f -= p[x1][1] print(max_f)
8
PYTHON3
n, d = list(map(int, input().split())) friends = [] max_friendship = 0 tmp_index = 0 tmp_friendship = 0 for k in range(n): m, s = list(map(int, input().split())) friends.append({'m': m, 's': s}) friends = sorted(friends, key=lambda x: x['m']) k = 0 while k < n: if abs(friends[tmp_index]['m'] - friends[k]['m']) >= d: tmp_friendship -= friends[tmp_index]['s'] tmp_index += 1 else: tmp_friendship += friends[k]['s'] max_friendship = max(max_friendship, tmp_friendship) k += 1 print(max_friendship)
8
PYTHON3
[n,d] = list(map(int, input().split())) a = [list(map(int, input().split())) for _ in range(n)] a.sort() ans=a[0][1] res=a[0][1] p1=0 p2=0 while(p2 < n-1): if (a[p2+1][0] - a[p1][0] < d): p2 += 1 ans += a[p2][1] if(ans > res): res=ans else: ans -= a[p1][1] p1 += 1 print(res)
8
PYTHON3
n, d = list(map(int, input().split())) pairs = [] for i in range(n): pairs.append(list(map(int, input().split()))) pairs.sort(key=lambda x: x[0]) i = 0 j = 0 count = 0 numbers = [] while(i < n): if(pairs[i][0] - pairs[j][0] < d): count += pairs[i][1] numbers.append(count) i += 1 else: count -= pairs[j][1] j += 1 print(max(numbers))
8
PYTHON3
n, k = [int(i) for i in input().split()] arr = [] for i in range(n): s = [int(i) for i in input().split()] arr.append(s) lst = [] arr.sort() v = arr[0][1] j = 1 for i in range(len(arr)): if j == n: break while abs(arr[i][0] - arr[j][0]) < k: v += arr[j][1] j += 1 if j > n - 1: break lst.append(v) v -= arr[i][1] lst = lst + [i[1] for i in arr] print(max(lst))
8
PYTHON3
# # Kefa wants to celebrate his first big salary by going to restaurant. However, he needs company. # # Kefa has n friends, each friend will agree to go to the restaurant if Kefa asks. # Each friend is characterized by the amount of money he has and the friendship factor in respect to Kefa. # The parrot doesn't want any friend to feel poor compared to somebody else in the company (Kefa doesn't count). # A friend feels poor if in the company there is someone who has at least d units of money more than he does. # Also, Kefa wants the total friendship factor of the members of the company to be maximum. # Help him invite an optimal company! # # Input # # The first line of the input contains two space-separated integers, n and d (1 ≀ n ≀ 105, ) β€” the number of Kefa's # friends and the minimum difference between the amount of money in order to feel poor, respectively. # # Next n lines contain the descriptions of Kefa's friends, the (i + 1)-th line contains # the description of the i-th friend of type mi, si (0 ≀ mi, si ≀ 109) β€” the amount of money # and the friendship factor, respectively. # # Output # # Print the maximum total friendship factor that can be reached. # # Examples # # Input # # 4 5 # 75 5 # 0 100 # 150 20 # 75 1 # # Output # # 100 # # Input # # 5 100 # 0 7 # 11 32 # 99 10 # 46 8 # 87 54 # # Output # # 111 # # Note # # In the first sample test the most profitable strategy is to form a company from only the second friend. # At all other variants the total degree of friendship will be worse. # # In the second sample test we can take all the friends. # import sys class Solution: def max_friendship_factor(self, money_diff, friends_data): # sort by money amount, so that we could go through all # the intervals where money diff in [0, money_diff] friends_data = sorted(friends_data, key=lambda f: f[0]) # count friendship factors for every prefix factors = [friends_data[0][1]] for i in range(1, len(friends_data)): factors.append(factors[i-1] + friends_data[i][1]) # go through all the intervals where # money diff in [0, money_diff] ff_max, j = 0, len(friends_data) - 1 for i in range(len(friends_data) - 1, -1, -1): # find interval left border, on each step j will either # stay the same or decrease since we're decreasing right border while j > 0 and friends_data[j][0] - friends_data[i][0] >= money_diff: j -= 1 # calculate friendship factor for the interval ff = factors[j] if i > 0: ff -= factors[i - 1] # compare if it's total maximum if ff > ff_max: ff_max = ff return ff_max def main(): inp = sys.stdin.readline() friends, money_diff = list(map(int, inp.split())) friends_data = [] while friends > 0: inp = sys.stdin.readline() friends_data.append(list(map(int, inp.split()))) friends -= 1 print(Solution().max_friendship_factor(money_diff, friends_data)) if __name__ == "__main__": main()
8
PYTHON3
#include <bits/stdc++.h> using namespace std; vector<pair<int, int> > v; int main() { int n, d; scanf("%d%d", &n, &d); v.resize(n); for (int i = 0; i < n; i++) { scanf("%d%d", &v[i].first, &v[i].second); } sort(v.begin(), v.end()); long long sum = 0, ans = 0; int l = 0, r = 0; while (r < n) { if (v[r].first - d < v[l].first) { sum += v[r].second; r++; } else { ans = max(ans, sum); sum -= v[l].second; l++; } } cout << max(ans, sum); return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; pair<int, int> a[100005]; int main() { ios_base::sync_with_stdio(0); cin.tie(NULL); int n, d; cin >> n >> d; for (int i = 0; i < n; i++) { cin >> a[i].first >> a[i].second; } sort(a, a + n); long long int mx = 0, x = 0, l = 0, r = 0; for (; l < n; l++) { while (r < n && a[r].first < a[l].first + d) { x += a[r].second; r++; } mx = max(mx, x); x -= a[l].second; } cout << mx << "\n"; return 0; }
8
CPP
n,m=map(int,input().split()) ls=[list(map(int,input().split())) for i in range(n) ] ls.sort(reverse=True) su,maximum=0,0 su=ls[0][1] maximum=su top=0 i=1 while i<n: while i<n and ls[i][0] +m > ls[top][0] : su+=ls[i][1] i+=1 maximum=max(maximum,su) if i==n: break while i>top and ls[i][0] +m <= ls[top][0]: su-=ls[top][1] top+=1 su+=ls[i][1] maximum=max(maximum,su) i+=1 print(maximum)
8
PYTHON3
#include <bits/stdc++.h> typedef struct Friend { long long m, s; } F; long long n, d, res = 0; F a[100001]; void quicksort(long long d, long long c) { if (d >= c) return; srand(time(NULL)); long long i1 = d, j1 = c, val = a[d + rand() % (c - d + 1)].m; while (i1 <= j1) { while (a[i1].m < val) i1++; while (a[j1].m > val) j1--; if (i1 <= j1) { if (i1 < j1) { F tmp = a[i1]; a[i1] = a[j1]; a[j1] = tmp; } i1++; j1--; } } quicksort(d, j1); quicksort(i1, c); } int main() { scanf("%I64d%I64d", &n, &d); for (long long i = 1; i <= n; i++) scanf("%I64d%I64d", &a[i].m, &a[i].s); quicksort(1, n); a[0].s = 0; for (long long i = 1; i <= n; i++) a[i].s += a[i - 1].s; long long j = 1; for (long long i = 1; i <= n; i++) { while (j < n && a[j + 1].m - a[i].m < d) j++; if (a[j].s - a[i - 1].s > res) res = a[j].s - a[i - 1].s; } printf("%I64d", res); return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int xDir[8] = {0, 0, -1, 1, 1, -1, -1, 1}; int yDir[8] = {1, -1, 0, 0, 1, -1, 1, -1}; int EPS = 1e-10; int dComp(double d1, double d2) { if (abs(d1 - d2) <= EPS) return 0; if (d1 > d2) return 1; else return -1; } bool lucky(int i) { string s = to_string(i); for (int j = 0; j < s.size(); j++) if (s[j] - '0' != 4 && s[j] - '0' != 7) return false; return true; } int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); int n, d; cin >> n >> d; vector<pair<int, int> > vec(100001); for (int i = 0; i < n; i++) { cin >> vec[i].first >> vec[i].second; } sort(vec.begin(), vec.begin() + n); int left = 0, right = 0; long long sum = 0; long long mx = -1; while (left <= right && right < n && left < n) { if (abs(vec[left].first - vec[right].first) < d) { sum += vec[right].second; right++; mx = max(mx, sum); } else { sum -= vec[left].second; left++; } mx = max(mx, sum); } cout << mx << endl; }
8
CPP
def bina(arr,target,i,n): l,h,ans=i,n-1,i while(l<=h): m=(l+h)//2 if arr[m][0]>=target: h=m-1 else: ans=m l=m+1 return ans n,d=list(map(int,input().split())) arr=[tuple(map(int,input().split())) for _ in range(n)] arr.sort(key=lambda x :x[0]) prefix=[0]*n prefix[0]=arr[0][1] for i in range(1,n): prefix[i]=prefix[i-1]+arr[i][1] mx=-1 for i in range(n): target=arr[i][0]+d ind=bina(arr,target,i,n) mx=max(mx,prefix[ind]-prefix[i]+arr[i][1]) print(mx)
8
PYTHON3
import sys from bisect import bisect_right def main(): n, d = map(int, input().split()) friends = sorted(tuple(int(c) for c in line.split()) for line in sys.stdin.readlines()) money = [e[0] for e in friends] friendship_sum = [0] for _, e in friends: friendship_sum.append(friendship_sum[-1] + e) _min = friends[0][0] i = 1 start = 0 ans = friends[0][1] while i < n: cur = money[i] diff = cur - _min _min = min(_min, cur) if diff >= d: start = bisect_right(money, cur - d) _min = money[start] friendship = friendship_sum[i+1] - friendship_sum[start] ans = max(ans, friendship) i += 1 print(ans) if __name__ == "__main__": main()
8
PYTHON3
#include <bits/stdc++.h> using namespace std; bool sortbysec(const pair<long long, long long> &a, const pair<long long, long long> &b) { return (a.second > b.second); } void solve() { long long n, d; cin >> n >> d; vector<pair<long long, long long>> v(n); long long sum1 = 0; for (long long i = 0; i < n; i++) { long long x, y; cin >> v[i].first >> v[i].second; } sort(v.begin(), v.end()); long long l = 0, r = 0; long long ans = 0; long long s = 0; for (; l < n; ++l) { while (r < n && v[r].first < v[l].first + d) { s += v[r].second; ++r; } ans = max(ans, s); s -= v[l].second; } cout << ans << endl; } signed main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); ; solve(); return 0; }
8
CPP
n, d = map(int, input().split()) a = [] for i in range(n): m, s = map(int, input().split()) a.append((m, s)) a.sort() l = 0 r = 0 sm = 0 mx = 0 while l < n: while a[r][0] - a[l][0] < d: sm += a[r][1] r += 1 if r == n: break if sm > mx: mx = sm if r == n: break sm -= a[l][1] l += 1 print(mx)
8
PYTHON3
def key_tri(argument): return argument[0] n,d = map(int, input().split()) L = [list(map(int, input().split())) for _ in range(n)] L.sort(key=key_tri) deb = 0 T = [] s = 0 for k in range(1,n): if L[k][0] - L[deb][0] >= d: s = 0 for i in range(deb,k): s+=L[i][1] T+=[s] s = deb+1 while (L[k][0] - L[s][0]) >= d: s+=1 deb = s s = 0 for k in range(deb,n): s+=L[k][1] T = T + [s] print(max(T))
8
PYTHON3
from functools import cmp_to_key def readnums(): return list(map(lambda x: int(x), input().split(" "))) def mycmp(a, b): if a[0] > b[0]: return 1 elif a[0] < b[0]: return -1 else: if a[1] > b[1]: return 1 elif a[1] < b[1]: return -1 return 0 n, d = readnums() fr = [] for i in range(n): fr.append(tuple(readnums())) fr.sort(key=cmp_to_key(mycmp)) # print(fr) ans = 0 min_money = 0 friendship = 0 i = 0 j = 0 while i < n: min_money = fr[i][0] ans = max(ans, friendship) if (i > j): j = i while (j < n) and (abs(fr[j][0] - min_money) < d): # print(i, j, min_money, (abs(fr[j][0] - min_money))) friendship += fr[j][1] j += 1 # print(j, friendship) ans = max(ans, friendship) # print(ans) friendship -= fr[i][1] i += 1 print(ans)
8
PYTHON3
n,d=map(int,input().split(" ")) sum1=0 maximum=-1 a=[] arr=[] arr.append(0) for x in range(n): a.append(list(map(int,input().split(" ")))) a.sort() for x in range(n): sum1+=a[x][1] arr.append(sum1) y=0 for x in range(n): while(y<n and a[y][0]-a[x][0]<d): y+=1 maximum=max(maximum,arr[y]-arr[x]) print(maximum)
8
PYTHON3
import bisect from collections import Counter,defaultdict from sys import stdin, stdout input = stdin.readline I =lambda:int(input()) M =lambda:map(int,input().split()) LI=lambda:list(map(int,input().split())) n,m=M() d=defaultdict(int) b=[] ans=0 for _ in range(n): a,b=M() d[a]+=b ans=max(ans,d[a]) c=list(d.keys());c.sort() e=[0];val=0 for i in range(len(c)): val+=d[c[i]] e+=[val] for i in range(len(c)): f=c[i]+m ind=bisect.bisect_left(c,f) ans=max(ans,e[ind]-e[i]) print(ans)
8
PYTHON3
from collections import namedtuple Friend = namedtuple("Friend", "money value") n, d = map(int, input().split()) # At first we sort all friends in money ascending order. a = [] for i in range(n): money, value = map(int, input().split()) a.append(Friend(money, value)) a.sort() # Now the answer is some array subsegment. s = ans = a[0].value tail = 0 # Next, we use the method of two pointers for finding the required subsegment. for head in range(1, n): while (a[head].money - a[tail].money >= d): s -= a[tail].value tail += 1 s += a[head].value ans = max(s, ans) print(ans)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; const int MAX = 1e5 + 100; long long sum; long long sumLeft[MAX]; pair<int, int> arr[MAX]; int main() { int n, d; scanf("%d %d", &n, &d); for (int i = 1; i <= n; i++) { scanf("%d %d", &arr[i].first, &arr[i].second); } arr[n + 1].first = INT_MAX; sort(arr, arr + n + 1); for (int i = 1; i <= n; i++) sumLeft[i] = sumLeft[i - 1] + arr[i].second; sum = sumLeft[n]; long long ans = 0; for (int i = 1; i <= n; i++) { int index = distance(arr, upper_bound(arr, arr + n + 1, make_pair(arr[i].first + d - 1, INT_MAX))); ans = max(ans, sumLeft[index - 1] - sumLeft[i - 1]); } cout << ans << endl; }
8
CPP
entrada = list(map(int, input().split())) friends = [] for i in range(entrada[0]): friend = list(map(int, input().split())) friends.append(friend) friends.sort() combinations = [] pivot1 = 0 pivot2 = 0 totalSoma = 0 while(pivot1!=entrada[0]): if (pivot2<entrada[0] and friends[pivot2][0]-friends[pivot1][0]<entrada[1]): totalSoma += friends[pivot2][1] pivot2+=1 else: combinations.append(totalSoma) totalSoma -= friends[pivot1][1] pivot1+=1 combinations.append(totalSoma) combinations.sort() print (combinations[-1])
8
PYTHON3
entrada = list(map(int, input().split(' '))) lista = [] friendship = 0 p = 1 for i in range(entrada[0]): temp = list(map(int, input().split())) lista.append((temp[0],temp[1])) lista.sort() lista2 = [0] for i in range(1, entrada[0]+1): lista2.append(lista2[i-1] + lista[i-1][1]) for i in range(entrada[0]): while ((p < entrada[0]) and (lista[i][0] + entrada[1] > lista[p][0])): p +=1 friendship = max(friendship, lista2[p] - lista2[i]); print(friendship)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; const int maxn = 1e5 + 100; int main() { cin.tie(0); cout.tie(0); ios::sync_with_stdio(false); int n, d; long long sum[maxn]; pair<int, int> a[maxn]; while (cin >> n >> d) { for (int i = 1; i <= n; ++i) { cin >> a[i].first >> a[i].second; } sort(a + 1, a + 1 + n); for (int i = 1; i <= n; ++i) { sum[i] = sum[i - 1] + a[i].second; } int j = 1; long long res = 0; for (int i = 0; i <= n; ++i) { while (a[i].first - a[j].first >= d) { ++j; } res = max(res, sum[i] - sum[j - 1]); } cout << res << endl; } return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; mt19937_64 rang( chrono::high_resolution_clock::now().time_since_epoch().count()); int rng(int lim) { uniform_int_distribution<int> uid(0, lim - 1); return uid(rang); } const int INF = 0x3f3f3f3f; const int mod = 1e9 + 7; void solve() { long long n, d; cin >> n >> d; vector<pair<long long, long long> > v(n); for (long long i = 0; i < n; i++) { cin >> v[i].first >> v[i].second; } sort(v.begin(), v.end()); vector<long long> cs(n, 0); for (long long i = 0; i < n; i++) { cs[i] = v[i].second; if (i) cs[i] += cs[i - 1]; } long long res = 0; for (long long i = 0; i < n; i++) { pair<long long, long long> p = {v[i].first + d, -1}; long long idx = lower_bound(v.begin(), v.end(), p) - v.begin() - 1; long long curr_res = cs[idx]; if (i) curr_res -= cs[i - 1]; res = max(res, curr_res); } cout << res; } int main() { ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr); srand(chrono::high_resolution_clock::now().time_since_epoch().count()); int t = 1; while (t--) { solve(); } return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n, k; scanf("%d %d", &n, &k); vector<pair<int, int> > A; for (int i = 0; i < n; i++) { int x, y; scanf("%d %d", &x, &y); A.push_back(make_pair(x, y)); } sort(A.begin(), A.end()); long long ans = 0; long long co = 0; long long pre; vector<pair<int, int> >::iterator it = A.begin(); vector<pair<int, int> >::iterator fir = A.begin(); co = (*it).second; pre = (*it).first; ans = (*it).second; it++; for (; it != A.end(); it++) { while ((*it).first - ((*fir).first) >= k) { co = co - (*fir).second; fir++; } co += (*it).second; ans = max(ans, co); } printf("%lld", ans); return 0; }
8
CPP
n,d = map(int,input().split()) x = [] for i in range(n): a,b = map(int,input().split()) x.append((a,b)) x.sort() y = [] s = x[0][1] i,j = 0,1 while i<n and j<n: if j<n and x[j][0] - x[i][0] < d: s += x[j][1] j+=1 else: y.append(s) s -= x[i][1] i+=1 y.append(s) print(max(y))
8
PYTHON3
n, d = map(int, input().split()) v = sorted([list(map(int, input().split())) for i in range(n)], key = lambda x: x[0]) b = 0; s = sol = v[0][1] for i in range(1, n): while v[i][0] >= d + v[b][0]: s -= v[b][1] b += 1 s += v[i][1] sol = max(sol, s) print(sol)
8
PYTHON3
def getKey(item): return item[0] n,d = map(int, input().split()) li = [] for _ in range(n): l = [int(x) for x in input().split()] li.append(l) li = sorted(li, key=getKey) mx = -1 sum = [0]*n sum[0] = li[0][1] for i in range(1, n): sum[i] = sum[i-1]+li[i][1] end = 0 for i in range(0, n): tmp = end for j in range(tmp, n): if li[j][0] - li[i][0] < d: end = j else: break cnt = li[i][1] if end > i and i == 0: cnt = sum[end] elif end > i: cnt = sum[end] - sum[i-1] if cnt > mx: mx = cnt print(mx)
8
PYTHON3
user_input=input() first_line=user_input.split(' ') n=int(first_line[0]) d=int(first_line[1]) long_list=[] for i in range(n): extended_list=[] user_input = input() line = user_input.split(' ') extended_list.extend([int(line[0]),int(line[1])]) long_list.append(extended_list) long_list.sort() index=0 maximum=0 for i in range(len(long_list)): if maximum<long_list[i][1]: maximum=long_list[i][1] answer=maximum maximum=0 i=0 count=0 looped="false" while i in range(len(long_list)): if long_list[i][0]-long_list[index][0]>d: if count>0 and looped=="false": i-=count count=0 index=i looped="true" else: index=i maximum=0 if long_list[i][0]-long_list[index][0]<d: count+=1 if maximum==0: maximum=long_list[index][1] else: maximum+=long_list[i][1] answer=max(answer,maximum) i+=1 print(answer)
8
PYTHON3
#include <bits/stdc++.h> int const N = 1e5 + 5; using namespace std; long long n, d, ans; pair<long long, long long> p[N]; int main() { cin >> n >> d; for (int i = 0; i < n; i++) cin >> p[i].first >> p[i].second; sort(p, p + n); for (int i = 1; i < n; i++) p[i].second += p[i - 1].second; for (int i = 0; i < n; i++) { long long low = i, high = n - 1, mid, dif; if (!i) dif = 0; else dif = p[i - 1].second; while (low <= high) { mid = (low + high) / 2; if (p[mid].first - p[i].first < d) low = mid + 1, ans = max(ans, p[mid].second - dif); else high = mid - 1; } } cout << ans; return 0; }
8
CPP
n,d=map(int,input().split()) a=[] for i in range(n): a.append(list(map(int,input().split()))) a.sort() p1=p2=0;ma=0;su=0 while p2<n: if a[p2][0]-a[p1][0]<d: su+=a[p2][1];p2+=1;ma=max(ma,su) else: su-=a[p1][1];p1+=1 print(ma)
8
PYTHON3
""" Codeforces Round #321 (Div. 2) Problem 580 B. Kefa and Company @author yamaton @date 2015-09-22 """ import itertools as it import functools import operator import collections import math import sys import bisect def solve(xs, d): xs.sort() ms, fs = list(zip(*xs)) n = len(ms) fsacc = list(it.accumulate(it.chain((0,), fs))) out = [] for i, money in enumerate(ms): k = bisect.bisect_right(ms, money + d - 1) # print_stderr('----------') # print_stderr('i =', i) # print_stderr('k =', k) # print_stderr('d =', d) # print_stderr('ms=', ms) # print_stderr('ms[i] =', ms[i]) # print_stderr('ms[k-1] =', ms[k-1]) # print_stderr('fs[i] =', fs[i]) # print_stderr('fs[k-1] =', fs[k-1]) # out.append(sum(fs[i:k])) out.append(fsacc[k] - fsacc[i]) if k == n: break return max(out) def print_stderr(*args, **kwargs): print(*args, file=sys.stderr, **kwargs) def main(): # Assume the friendship factors are all positive [n, d] = [int(i) for i in input().strip().split()] money_friend_pairs = [tuple(int(i) for i in input().strip().split()) for _ in range(n)] result = solve(money_friend_pairs, d) print(result) if __name__ == '__main__': main()
8
PYTHON3
n,d=map(int,input().split()) l=sorted(list(map(int,input().split())) for _ in range(n)) j=0 fl=0 m=0 for i in range(n): fl+=l[i][1] while (l[i][0]-l[j][0])>=d: fl-=l[j][1] j+=1 m=max(m,fl) print(m)
8
PYTHON3
''' Created on 3Oct.,2017 @author: thorsten ''' user = input().split(" ") numberFriends = int(user[0]) diffToFeelPoor = int(user[1]) arr = [] maxFac = -1 for _ in range(numberFriends): userIn = input().split(" ") money = int(userIn[0]) frFac = int(userIn[1]) if frFac>maxFac: maxFac = frFac arr.append((money, frFac)) if diffToFeelPoor > 0: arr.sort(key=lambda tup: tup[0]) currFac = arr[0][1] maxFac = arr[0][1] startIn = 0 index = 1 while index < len(arr): if arr[index][0]<(arr[startIn][0]+diffToFeelPoor): currFac += arr[index][1] if currFac > maxFac: maxFac = currFac else: currFac += arr[index][1] for index2 in range(startIn, index+1): if arr[index][0]>=(arr[index2][0]+diffToFeelPoor): currFac -= arr[index2][1] startIn = index2+1 else: break if currFac > maxFac: maxFac = currFac index += 1 if currFac > maxFac: maxFac = currFac print(maxFac)
8
PYTHON3
#include <bits/stdc++.h> int const N = 1e5 + 5; using namespace std; long long n, d, ans, sum; pair<long long, long long> p[N]; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> n >> d; for (int i = 0; i < n; i++) { cin >> p[i].first >> p[i].second; } sort(p, p + n); for (int i = 1; i < n; i++) p[i].second += p[i - 1].second; for (int i = 0; i < n; i++) { long long low = i, high = n - 1, mid, dif; if (!i) dif = 0; else dif = p[i - 1].second; while (low <= high) { mid = (low + high) / 2; bool yes = false; if (p[mid].first - p[i].first < d) { low = mid + 1; ans = max(ans, p[mid].second - dif); } else { high = mid - 1; } } } cout << ans; return 0; }
8
CPP
def arr_2d(n): return [[float(x) for x in stdin.readline().split()] for i in range(n)] def get_col(arr, i): return [row[i] for row in arr] def arr_sum(arr): arr.appendleft(0) return list(accumulate(arr, lambda x, y: x + y)) from bisect import * from sys import stdin from itertools import accumulate from collections import deque n, d = map(int, stdin.readline().split()) a = deque(sorted(arr_2d(n), key=lambda x: x[0])) col, ans, col2 = get_col(a, 0), 0, arr_sum(deque(get_col(a, 1))) for i in range(n): ix = bisect_right(col, a[i][0] + d - 1) if ix == n or a[ix][0] > a[i][0] + d - 1: ix -= 1 ans = max(ans, col2[ix + 1] - col2[i]) print(int(ans))
8
PYTHON3
def solve(n,d,friends): big = float('inf') small = float('-inf') friends.sort() maxer = small # two pointers f = 0 s = 0 ind = 0 curr = 0 while(ind < n): miner = friends[s][0] while(s < n and abs(friends[ind][0] - friends[s][0]) >= d): curr -= friends[s][1] s += 1 miner = friends[s][0] flag = True while(ind < n and abs(friends[ind][0] - miner) < d): curr += friends[ind][1] ind += 1 flag = False maxer = max(maxer,curr) return maxer def main(): # t = int(input()) # for i in range(t): # n = int(input()) d = input() d = [int(i) for i in d.split()] a = d[0] b = d[1] friends = [] for i in range(a): d = input() d = [int(i) for i in d.split()] m = d[0] f = d[1] friends.append((m,f)) # c = d[2] # e = d[4] # e = input() # e = [int(i) for i in e.split()] ans = solve(a,b,friends) print(ans) # for i in ans: # print(i,end = "") # print() main()
8
PYTHON3
#include <bits/stdc++.h> /* #include<boost/multiprecision/cpp_int.hpp> namespace mp=boost::multiprecision; */ using namespace std; #define ll long long int #define lo mp::cpp_int #define pb push_back #define pob pop_back #define mk make_pair #define endl "\n" #define ce(x) cout << x <<"\n" #define fill(s,v) memset(s,v,sizeof(s)) #define speed { ios_base::sync_with_stdio(false); cin.tie(0); } #define deb(x) cout<<#x<<" "<<x<<endl; #define INFINITE 1000000009 #define ull unsigned long long int #define take(a,n) for(ll pp=0;pp<n;pp++) { cin>>a[pp]; } #define take2(a,n) for(ll p=0;p<n;p++) { ll temp;cin>>temp;a.pb(temp); } #define f(i,n) for(ll i=0;i<n;i++) #define f1(i,a,n) for(ll i=a;i<n;i++) #define show(a,n) for(ll p=0;p<n;p++) cout<<a[p]<<" "; #define _ <<" "<< #define nl cout<<endl; #define sq(x) ((x)*(x)) #define call(v) v.begin(),v.end() #define rall(v) v.rbegin(),v.rend() #define ff first #define ss second #define lld long double #define sc(n) scanf("%lld",&n); #define de2(x,y) cout<<#x<<" = "<<(x) <<' '<< #y<<" = "<<y<<endl;typedef pair<int, int> pii; #define copy(b,a,n) for(ll i=0;i<n;i++) b[i]=a[i]; #define clock() clock_out() #define tc(tt) \ ll tt; \ cin >> tt; \ for (int _tt = 0; _tt < tt; _tt++) typedef vector<vector<ll>> matrix ; typedef pair<ll,ll> pii; typedef vector<pii> vii; typedef vector<ll> vi; const ll dx[4] = {-1, 0, 1, 0}; const ll dy[4] = {0, -1, 0, 1}; const ll mod = 1000000007; ll gcd(ll a,ll b){if(!b)return a;return gcd(b,a%b);} ll power_mod(ll x,ll y,ll p){ll res=1;x%=p;while(y>0){if(y&1)res=(res*x)%p;y=y>>1;x=(x*x)%p;}return res;} ll modexpo(ll x,ll n,ll M){if(n==0)return 1;else if(n%2 == 0)return modexpo((x*x)%M,n/2,M);else return(x*modexpo((x*x)%M,(n-1)/2,M))%M;} ll lcm(ll a, ll b){return (a*b)/gcd(a, b);} ll sumofdigits(ll n){ll out=0;while(n){out+=(n%10);n/=10;}return out;} bool isPrime(ll n){if (n <= 1) return false; if (n <= 3) return true; if (n%2 == 0 || n%3 == 0) return false; for (ll i=5; i*i<=n; i=i+6) if (n%i == 0 || n%(i+2) == 0) return false;return true;} // ll power(ll a,ll b){if(b==0)return 1;if(b&1)return a*power(a,b-1);ll res=power(a,b/2);return res*res;} ll bexpo(ll x,ll n){if(n==0)return 1;else if(n%2==0)return bexpo(x*x,n/2);else return x*bexpo(x*x,(n-1)/2);} ll log(ll d){return log2(d);} bool isPower(ll x, ll y){if(x==1) return (y==1); ll pow=1; while(pow<y) pow*=x; return(pow == y);} bool isPerfectSquare(long double x){long double sr = sqrt(x);return ((sr - floor(sr)) == 0);} bool compare(const pair<ll,ll> &a, const pair<ll,ll> &b) { return (a.second < b.second);} ll isPalindrome(string s){ll l=0;ll h=s.size()-1;while(h>l){if(s[l++]!=s[h--])return 0;}return 1;} ll setbits(ll n) { if(n==0)return 0; else return 1+setbits(n&(n-1)); } ll modInverse(ll A,ll M){return modexpo(A,M-2,M);} ll suma(ll *a,ll n){ll sum=0;for(ll i=0;i<n;i++)sum+=a[i];return sum;} // void clock_out(){ // cerr<<"\nTime Elapsed : " << 1.0*clock() / CLOCKS_PER_SEC << " s\n"; // } //------modular inverse by extended euclid-------// // ll d, x, y; // void extendedEuclid(ll A, ll B) { // if(B == 0) { // d = A; // x = 1; // y = 0; // } // else { // extendedEuclid(B, A%B); // ll temp = x; // x = y; // y = temp - (A/B)*y; // } // } // ll modInverse2(ll A, ll M){ // extendedEuclid(A,M); // return (x%M+M)%M; // } //---------------------------------// //---------------matrix exponentiation-------------------// // matrix mul(matrix a,matrix b){ // matrix res(n+1,vector<ll>(n+1)); // f(i,n)f(j,n)f(k,n)res[i][j]=(res[i][j]%mod+((a[i][k]%mod)*(b[k][j]%mod))%mod)%mod; // return res; // } // matrix pow(matrix A,ll p) { // if(p==1) return A; // matrix res=pow(A,p/2) ; // res=mul(res,res); // if(p&1) res=mul(res,A) ; // return res; // } //-------------------------------------------------// vector<ll> factorize(ll n) { vector<ll> res; for (ll i = 2; i * i <= n; ++i) { while (n % i == 0) { res.push_back(i); n /= i; } } if (n != 1) { res.push_back(n); } return res; } vector<ll> divisors(ll n){ vector<ll> res; for (ll i=1; i<=sqrt(n); i++){ if (n%i == 0){ if (n/i == i){ res.pb(i); } else{ res.pb(n/i); res.pb(i); } } } return res; } vector<ll> primeFactors(ll n){ if(n==1) return vector<ll>(1,1); bool idx[1]={false}; vector<ll> res; while (n%2 == 0){ if(!idx[1]){idx[1]=true;res.pb(2);} n = n/2; } for (ll i=3;i*i<=n; i+=2){ bool once=false; while (n%i==0){ if(!once){res.pb(i);once=true;} n=n/i; } } if (n > 2)res.pb(n); return res; } //--------------------------------------------// ll dxx[] = {1, 1, 0, -1, -1, -1, 0, 1}; ll dyy[] = {0, 1, 1, 1, 0, -1, -1, -1}; //----check if a point is in range-----/// ///__builtin_ctz(x) --> get power of 2 dude !!!! bool check(ll x,ll y,ll n,ll m){return(x>=0&&x<n&&y>=0&&y<m);} const int FULL_MASK = (1 << 10) - 1; #define pi 3.1415926535897932 vector<vector<ll>> ed; void bfs(ll s, vector<ll> &d) { d[s] = 0; queue<ll> q; q.push(s); while (!q.empty()) { ll v = q.front(); q.pop(); for (auto to : ed[v]) { if (d[to] == 1e9) { d[to] = d[v] + 1; q.push(to); } } } } // void dfs(int u){ // vis[u]=1; // // temp.push_back(u); // for(int i=0;i<adj[u].size();i++){ // if(!vis[adj[u][i]]) // dfs(adj[u][i]); // } // } // void dfs(ll u){ // if(vis[u]) return; // deg += g[u].size(); // ver++; // vis[u] = 1; // for(auto v: g[u])dfs(v); // } ll maxSubArraySum(ll a[],ll size) { ll max_so_far = a[0]; ll curr_max = a[0]; for (ll i = 1; i < size; i++) { curr_max = max(a[i], curr_max+a[i]); max_so_far = max(max_so_far, curr_max); } return max_so_far; } struct node{ ll a,b,c,d; }; int n,m,fg,k=1; char c; char mmp[70][70]; int mp[70][70]; void dfs(int x,int y,int ex,int ey) { //cout<<k++<<endl; if(fg){ return; } for(int i=0;i<4;i++) { int xx=x+dx[i]; int yy=y+dy[i]; if(xx>=0&&xx<n&&yy>=0&&m>yy&&mmp[xx][yy]==c) { if(xx==ex&&yy==ey) continue; else if(mp[xx][yy]||fg){ fg=1; return; } else if(!mp[xx][yy]) { mp[xx][yy]=1; dfs(xx,yy,x,y); } } } return; } void solve(){ ll n, m; cin >> n >> m; pair < ll, ll > arr[n]; for(ll i = 0; i < n; i ++) cin >> arr[i].ff >> arr[i].ss; sort(arr, arr + n); ll mx = 0, s = 0; ll r = 0; for(ll l = 0; l < n; l ++){ while(r < n && arr[l].ff + m > arr[r].ff){ s += arr[r].ss; r ++; } mx = max(mx , s); s -= arr[l].ss; } cout << mx << endl; } int main(){ // tc(tt){ solve(); // } } /* */
8
CPP
n, diff = map(int, input().split(" ")) m_f = [] for i in range(n): m_f.append(tuple(map(int, input().split(" ")))) m_f.sort(key=lambda x: x[0]) start = 0 end = 1 max_f = m_f[0] cost = m_f[start][1] total = m_f[start][1] while len(m_f) > end >= start: if m_f[end][0] - m_f[start][0] >= diff: total = max(total, cost) cost -= m_f[start][1] start += 1 else: cost += m_f[end][1] end += 1 total = max(total, cost) print(total)
8
PYTHON3
n, m = tuple( int( x ) for x in input().split() ) v = [ ] for i in range( n ): i = input() v.append( tuple( int( x ) for x in i.split() ) ) v.sort( reverse = True ) maxi = val = v[ 0 ][ 1 ] i = j = 0 for j in range( 1, len( v ) ): val += v[ j ][ 1 ] while abs( v[ j ][ 0 ] - v[ i ][ 0 ] ) >= m: val -= v[ i ][ 1 ] i += 1 if val > maxi: maxi = val print( maxi )
8
PYTHON3
n, d = map(int, input().split()) al = [list(map(int, input().split())) for _ in range(n)] al.sort() res = al[0][1] t = al[0][1] idx = 0 for i in range(1, n): if al[i][0] - al[idx][0] < d: t += al[i][1] else: while al[i][0] - al[idx][0] >= d: t -= al[idx][1] idx += 1 t += al[i][1] res = max(res, t); print(res)
8
PYTHON3
first_line = input().split() n = int(first_line[0]) d = int(first_line[1]) friends = [[0, 0] for i in range(n)] for i in range(n): a_friend = input().split() friends[i][0] = int(a_friend[0]) friends[i][1] = int(a_friend[1]) friends = sorted(friends) left = 0 right = 0 result = 0 addition = 0 while(left < n and right < n): while(right < n and ((friends[right][0]-friends[left][0]) < d)): addition += friends[right][1] right += 1 result = max(result, addition) addition -= friends[left][1] left += 1 print(result)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; const int MX = 1000005; int N; int dx[] = {0, 1, 1, 1, 0, -1, -1, -1}; int dy[] = {1, 1, 0, -1, -1, -1, 0, 1}; pair<long long, long long> p[MX]; long long pref[MX]; bool cmp(pair<long long, long long>& p1, pair<long long, long long>& p2) { if (p1.first == p2.first) return p1.second > p2.second; return p1.first < p2.first; } int ch(int x, int aim, int d) { if (abs(p[aim].first - p[x].first) < d) return 2; return 0; } long long Ra(int l, int r) { long long las = min(r, N - 1); if (l < 1) return pref[las]; return pref[las] - pref[l - 1]; } int main() { ios_base::sync_with_stdio(false); cin.tie(0); long long d; cin >> N >> d; for (int i = 0; i < N; i++) cin >> p[i].first >> p[i].second; sort(p, p + N, cmp); for (int i = 0; i < N; i++) { if (i) pref[i] = pref[i - 1]; pref[i] += p[i].second; } long long ans = 0; for (int i = 0; i < N; i++) { long long l = i, m, h = N - 1, res = -1e18; while (l <= h) { m = l + h; m /= 2; if (ch(i, m, d)) { res = max(res, Ra(i, m)); l = m + 1; } else h = m - 1; } ans = max(ans, res); } cout << ans; return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; const long long A = 100000000000000LL, N = 228228; char e[21]; vector<string> ot; pair<int, pair<int, string> > a[N]; long long o, p[3] = {-1, -1, -1}; int i, j, l, r, n, m; int main() { cin >> n >> m; for (i = 0; i < n; ++i) { scanf("%d%d", &a[i].first, &a[i].second.first); a[i].second.second = e; } sort(a, a + n); for (l = 0; l < n; o -= a[l].second.first, ++l) { while (r < n && abs(a[l].first - a[r].first) < m) o += a[r].second.first, ++r; if (o >= p[0]) p[0] = o, p[1] = l, p[2] = r; } for (i = p[1]; i < p[2]; ++i) ot.push_back(a[i].second.second); cout << p[0] << "\n"; }
8
CPP
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); int z = 1; while (z--) { int n, d; cin >> n >> d; vector<pair<int, int>> friends; int arr[n]; for (int i = 0; i < n; i++) { int a, b; cin >> a >> b; arr[i] = a; friends.push_back(make_pair(a, b)); } sort(friends.begin(), friends.end()); sort(arr, arr + n); long long int prefix[n]; prefix[0] = friends[0].second; for (int i = 1; i < n; i++) { prefix[i] = prefix[i - 1] + friends[i].second; } long long int maxx = 0; for (int i = 0; i < n; i++) { int pos = upper_bound(arr + i, arr + n, arr[i] + d - 1) - arr; maxx = max(maxx, prefix[pos - 1] - (i ? prefix[i - 1] : 0)); } cout << maxx << "\n"; } return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; template <class X> class vec { public: X x, y; vec<X>(X a = 0, X b = 0) { x = a, y = b; } X dis(vec a) { return (x - a.x) * (x - a.x) + (y - a.y) * (y - a.y); } vec<X> operator-(vec<X> b) { return vec<X>(x - b.x, y - b.y); } X operator*(vec<X> b) { return x * b.y - y * b.x; } }; void sf(int &x) { scanf("%d", &x); } void sf(long long &x) { scanf("%lld", &x); } void sf(long long &x, long long &y) { scanf("%lld%lld", &x, &y); } void sf(float &x) { scanf("%f", &x); } void sf(double &x) { scanf("%lf", &x); } void sf(int &x, int &y) { scanf("%d%d", &x, &y); } void sf(float &x, float &y) { scanf("%f%f", &x, &y); } void sf(double &x, double &y) { scanf("%lf%lf", &x, &y); } void sf(double &x, double &y, double &z) { scanf("%lf%lf%lf", &x, &y, &z); } void sf(int &x, int &y, int &z) { scanf("%d%d%d", &x, &y, &z); } void sf(long long &x, long long &y, long long &z) { scanf("%lld%lld%lld", &x, &y, &z); } void sf(float &x, float &y, float &z) { scanf("%u%u%u", &x, &y, &z); } void sf(char &x) { x = getchar(); } void sf(char *s) { scanf("%s", s); } void sf(string &s) { cin >> s; } void sf(vec<int> &x) { int a, b; sf(a, b); x = vec<int>(a, b); } void pf(int x) { printf("%d\n", x); } void pf(int x, int y) { printf("%d %d\n", x, y); } void pf(int x, int y, int z) { printf("%d %d %d\n", x, y, z); } void pf(long long x) { printf("%lld\n", x); } void pf(long long x, long long y) { printf("%lld %lld\n", x, y); } void pf(long long x, long long y, long long z) { printf("%lld %lld %lld\n", x, y, z); } void pf(float x) { printf("%u\n", x); } void pf(double x) { printf("%.9lf\n", x); } void pf(double x, double y) { printf("%.5lf %.5lf\n", x, y); } void pf(char x) { printf("%c\n", x); } void pf(char *x) { printf("%s\n", x); } void pf(string x) { cout << x; puts(""); } void pf(vec<int> x) { printf("%d %d\n", x.x, x.y); } long long STN(string s) { long long sm; stringstream ss(s); ss >> sm; return sm; } template <class T> T bigmod(T b, T p, T m) { if (p == 0) return 1 % m; T x = b; T ans = 1; while (p) { if (p & 1) ans = (ans * x) % m; p >>= 1; x = (x * x) % m; } return ans; } template <class T> T gcd(T x, T y) { if (y == 0) return x; return gcd(y, x % y); } template <typename T> T POW(T b, T p) { if (p == 0) return 1; if (p == 1) return b; if (p % 2 == 0) { T s = POW(b, p / 2); return s * s; } return b * POW(b, p - 1); } template <typename T> T modinv(T num, T m) { return bigmod(num, m - 2, m); } template <class T> string NTS(T Number) { stringstream ss; ss << Number; return ss.str(); } long long n, d, c[100009]; vector<pair<long long, long long> > v; int main() { v.push_back(make_pair(-1, -1)); sf(n, d); for (int i = 0; i < n; i++) { long long a, b; sf(a, b); v.push_back(make_pair(a, b)); } sort(v.begin(), v.end()); for (int i = 1; i <= n; i++) { c[i] = c[i - 1] + v[i].second; } long long an = 0; for (int i = 1; i <= n; i++) { long long hi = n, lo = i, a = v[i].first + d; while (hi > lo) { long long mid = (hi + lo + 1) / 2; if (v[mid].first < a) lo = mid; else hi = mid - 1; } long long kk = c[lo] - c[i - 1]; an = max(an, kk); } pf(an); return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int T; double pi = acos(-1.0); long long factorial(long long x) { long long total = 1; for (int i = 2; i <= x; i++) total *= i; return total; } bool isprime(long long x) { vector<bool> prime(x + 1, 1); prime[0] = prime[1] = 0; for (long long i = 2; i * i <= x; i++) if (prime[i]) for (long long j = i * i; j <= x; j += i) prime[j] = 0; return prime[x]; } long long gcd(long long a, long long b) { if (b == 0) return a; else return gcd(b, a % b); } long long lcm(long long a, long long b) { return (a * b) / gcd(a, b); } long long temp = 1; long long fastpow(long long base, long long exponent) { if (exponent == 0) return 1; if (exponent == 1) return (temp * base); if (exponent % 2 == 0) return fastpow(base * base, exponent / 2); else { temp *= base; fastpow(base * base, exponent / 2); } } long fib(long n) { if (n == 0) return 0; if (n == 1) return 1; return fib(n - 2) + fib(n - 1); } void solve() { int n, diff; cin >> n >> diff; vector<pair<int, int>> v(n); for (int i = 0; i < n; i++) { int x, y; cin >> x >> y; v[i] = make_pair(x, y); } sort(v.begin(), v.end()); long long l = 0, r = 1, sum = v[0].second, ans = sum; while (r < n) { if (abs(v[r].first - v[l].first) < diff) { sum += v[r].second; ans = max(sum, ans); r++; } else { sum -= v[l].second; l++; } } cout << ans << endl; } int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); { solve(); } return 0; }
8
CPP
n, d = [int(x) for x in input().split()] prieteni = [] for i in range(n): pr = [int(x) for x in input().split()] prieteni += [pr] prieteni.sort(key=lambda x : x[0]) l = 0 r = 0 final = prieteni[l][1] max = 0 while r < n: if l == r: final = prieteni[l][1] r += 1 if r == n: if final > max: max = final break if prieteni[r][0] - prieteni[l][0] < d: final += prieteni[r][1] r += 1 if r == n: if final > max: max = final else: if final > max: max = final l += 1 final = final - prieteni[l-1][1] print(max)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; bool cmp(int n, pair<int, int> const& p) { return ((p.first < n) && (p.second < n)); } int main() { int n, d; cin >> n >> d; pair<long long, long long> a[n + 1]; long long b[n + 1]; for (int i = 0; i < n; i++) { cin >> a[i].first; b[i] = a[i].first; cin >> a[i].second; } sort(b, b + n); sort(a, a + n); long long c[n + 2]; c[0] = 0; for (int i = 1; i <= n; i++) { c[i] = c[i - 1] + a[i - 1].second; } long long mx = 0; for (long long i = 0; i < n; i++) { long long sum = 0; long long j = upper_bound(b, b + n, a[i].first + d - 1) - b; sum = c[j] - c[i]; mx = max(mx, sum); } cout << mx << '\n'; }
8
CPP
n,d=map(int,input().split()) a=[] for i in range(n): x,y=map(int,input().split()) a.append([x,y]) a.sort() partialsum=[0]*n partialsum[0]=a[0][1] for i in range(1,n): partialsum[i]=partialsum[i-1]+a[i][1] mx=partialsum[0] cnt=0 for i in range(1,n): while cnt<i and a[i][0]-a[cnt][0]>=d: cnt+=1 if cnt>0: mx=max(mx,partialsum[i]-partialsum[cnt-1]) else: mx=max(mx,partialsum[i]) print(mx)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(0); int n, d, a, b; cin >> n >> d; vector<pair<int, int> > V; for (int i = 0; i < n; i++) { cin >> a >> b; V.push_back(pair<int, int>(a, b)); } sort(V.begin(), V.end()); long long int sum = 0, r_sum = 0; for (a = 0, b = 0; a < n; a++) { while (V[a].first + d > V[b].first && b < n) r_sum += V[b].second, b++; sum = max(sum, r_sum); r_sum -= V[a].second; } cout << sum << "\n"; }
8
CPP
#include <bits/stdc++.h> using namespace std; const long long mod = 1000000007; void __print(long long x) { cerr << x; } void __print(float x) { cerr << x; } void __print(double x) { cerr << x; } void __print(long double x) { cerr << x; } void __print(char x) { cerr << '\'' << x << '\''; } void __print(const char *x) { cerr << '\"' << x << '\"'; } void __print(const string &x) { cerr << '\"' << x << '\"'; } void __print(bool x) { cerr << (x ? "true" : "false"); } template <typename T, typename V> void __print(const pair<T, V> &x) { cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}'; } template <typename T> void __print(const T &x) { long long f = 0; cerr << '{'; for (auto &i : x) cerr << (f++ ? "," : ""), __print(i); cerr << "}"; } void _print() { cerr << "]\n"; } template <typename T, typename... V> void _print(T t, V... v) { __print(t); if (sizeof...(v)) cerr << ", "; _print(v...); } void solve() { long long n, d; cin >> n >> d; vector<pair<long long, long long> > a(n + 1); for (long long i = 0; i < (n); i++) { long long m, f; cin >> m >> f; a[i + 1] = {m, f}; } sort(a.begin()++, a.end()++); long long l = 1; long long r = 2; long long ans = a[1].second; long long curr = ans; while (r <= n) { while (r <= n and a[r].first - a[l].first < d) { curr += a[r].second; r++; } ans = max(curr, ans); curr -= a[l].second; l++; } cout << ans << "\n"; } int32_t main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long t = 1; while (t--) { solve(); } }
8
CPP
#include <bits/stdc++.h> using namespace std; ifstream fin("date.in"); ofstream fout("date.out"); struct prieten { int money; int friendship; } v[100001]; int part_Hoare(int s, int d) { int i, j; i = s - 1; j = d + 1; int randpoz, r1, r2, r3; int nr = d - s + 1; r1 = rand() % nr + s; r2 = rand() % nr + s; r3 = rand() % nr + s; int minr, maxr; minr = min(min(r1, r2), min(r2, r3)); maxr = max(max(r1, r2), max(r2, r3)); randpoz = r1 + r2 + r3 - minr - maxr; int pivot = v[randpoz].money; while (true) { do { ++i; } while (v[i].money < pivot); do { --j; } while (v[j].money > pivot); if (i >= j) return j; prieten aux; aux.money = v[i].money; aux.friendship = v[i].friendship; v[i].money = v[j].money; v[i].friendship = v[j].friendship; v[j].money = aux.money; v[j].friendship = aux.friendship; } } void qsort(int i, int j) { if (i < j) { int k = part_Hoare(i, j); qsort(i, k); qsort(k + 1, j); } } int caut_bin(int st, int dr, int x, int dif) { int m = (st + dr) / 2; if (st >= dr) { if ((v[m].money - x) <= dif) return st; else return st - 1; } if ((v[m].money - x) > dif) return caut_bin(st, m - 1, x, dif); else return caut_bin(m + 1, dr, x, dif); } int main() { int n, d, i, j, k; long long smax = 0; cin >> n >> d; for (i = 1; i <= n; i++) cin >> v[i].money >> v[i].friendship; qsort(1, n); if ((v[2].money - v[1].money) < d) { j = caut_bin(2, n, v[i].money, d - 1); for (i = 1; i <= j; i++) smax += v[i].friendship; } else if (v[1].friendship > smax) { smax = v[1].friendship; j = 1; } i = 1; j++; long long spart = smax; while (j < n) { while (((v[j].money - v[i].money) >= d) && (i < j)) { spart -= v[i].friendship; i++; } while (((v[j].money - v[i].money) < d) && (j <= n)) { spart += v[j].friendship; j++; } if (spart > smax) smax = spart; } if (v[n].friendship > smax) smax = v[n].friendship; cout << smax; return 0; }
8
CPP
import sys input = lambda: sys.stdin.readline().strip("\r\n") n, d = map(int, input().split()) ls = [] for _ in range(n): m, s = map(int, input().split()) ls.append((m, s)) ls.sort() alpha = 0 maxi = 0 j = 0 for i in range(n): alpha += ls[i][1] while ls[i][0] - ls[j][0] >= d: alpha -= ls[j][1] j += 1 maxi = max(maxi, alpha) print(maxi)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { long long int n, d; cin >> n >> d; vector<pair<long long int, long long int>> friends(n); vector<long long int> prefix(n); vector<long long int> results; results.reserve(n); for (auto&& _friend : friends) cin >> _friend.first >> _friend.second; sort(friends.begin(), friends.end()); prefix[0] = friends[0].second; for (long long int i = 1; i < n; i++) prefix[i] = prefix[i - 1] + friends[i].second; for (long long int i = 0; i < n; i++) { long long int l_min = i, r_max; long long int l = i, r = n - 1; while (r >= l) { long long int m = (l + r) / 2; if (friends[m].first >= friends[i].first + d) { r = m - 1; } else { l = m + 1; } } r_max = l - 1; if (l_min == 0) results.push_back(prefix[r_max]); else results.push_back(prefix[r_max] - prefix[l_min - 1]); } long long int _max = -1; for (auto&& result : results) if (result > _max) _max = result; cout << _max; return 0; }
8
CPP
n,k=map(int,input().split()) l=[] for i in range(n): l.append(list(map(int,input().split()))) l.sort() su=l[0][1] ma=0 first,last=0,1 while first<n and last<n: if l[last][0]-l[first][0]>=k: if su>ma: ma=su su-=l[first][1] first+=1 else: su+=l[last][1] last+=1 if su>ma: ma=su print(ma)
8
PYTHON3
import sys from bisect import bisect_right def main(): n, d = map(int, input().split()) friends = sorted(tuple(int(c) for c in line.split()) for line in sys.stdin.readlines()) money = [e[0] for e in friends] friendship_sum = [0] for _, e in friends: friendship_sum.append(friendship_sum[-1] + e) start = 0 _min, ans = friends[0] for i in range(1, n): cur = friends[i][0] if cur - _min >= d: start = bisect_right(money, cur - d) _min = friends[start][0] friendship = friendship_sum[i + 1] - friendship_sum[start] ans = max(ans, friendship) print(ans) if __name__ == "__main__": main()
8
PYTHON3
n,d=map(int,input().split()) a=[] for i in range(n): x=list(map(int,input().split())) a.append(x) a.sort() i=0 mx=0 x=a[i][0] s=a[i][1] j=1 while j!=n: if a[j][0]-x<d: s+=a[j][1] mx=max(s,mx) j+=1 else: mx=max(s,mx) s-=a[i][1] i+=1 x=a[i][0] print(max(mx,s))
8
PYTHON3
from collections import namedtuple from operator import itemgetter Friend = namedtuple("Friend", "m s") n, d = map(int, input().split()) f = [ ] for i in range(n): f.append(Friend(*map(int, input().split()))) f.sort(key=itemgetter(0)) left = 0 cur = f[0].s result = cur for i, fr in enumerate(f[1:], 1): while left < i and f[left].m + d <= fr.m: cur -= f[left].s left += 1 cur += fr.s result = max(result, cur) print(result)
8
PYTHON3
import sys import math import collections import bisect from collections import deque as queue def get_ints(): return map(int, sys.stdin.readline().strip().split()) def get_list(): return list(map(int, sys.stdin.readline().strip().split())) def get_string(): return sys.stdin.readline().strip() for t in range(1): n,m=get_ints() ans=[] for i in range(n): ans.append(get_list()) ans.sort() start=0 end=0 maxim=0 val=0 while end<n and start<n: if ans[end][0]-ans[start][0]<m: val+=ans[end][1] end+=1 else: val-=ans[start][1] start+=1 maxim=max(val,maxim) print(maxim)
8
PYTHON3
def get_max_friendship_factor(friends, min_money_dif): friends.sort() max_friendship_factor = 0 right = 0 friendship_factor = 0 for left in range(0, len(friends)): while right < len(friends) and abs(friends[left][0] - friends[right][0]) < min_money_dif: friendship_factor += friends[right][1] right += 1 max_friendship_factor = max(max_friendship_factor, friendship_factor) friendship_factor -= friends[left][1] return max_friendship_factor def solve(): first_line = input() num_friends, min_money_dif = [int(num) for num in first_line.split()] friends = [] for _ in range(0, num_friends): line = input() friend = tuple([int(num) for num in line.split()]) friends.append(friend) max_friendship_factor = get_max_friendship_factor(friends, min_money_dif) print(max_friendship_factor) if __name__ == '__main__': solve()
8
PYTHON3
#include <bits/stdc++.h> using namespace std; long long arr[100009]; template <class T> inline void rd(T &i) { bool minus = false; char c; for (c = getchar(); (c < '0' || c > '9') && (c != '-'); c = getchar()) ; if (c == '-') { minus = true; c = '0'; } for (i = 0; c >= '0' && c <= '9'; c = getchar()) i = (i << 3) + (i << 1) + (c - 48); if (minus) i = (~i) + 1; } bool cmp(const pair<int, int> &l, const pair<int, int> &r) { return l.first < r.first; } int main() { vector<pair<int, int> > v; int n, d, a, b; long long sum; pair<int, int> p; rd(n); rd(d); for (int i = 0; i < n; i++) { rd(a); rd(b); p = make_pair(a, b); v.push_back(p); } sort(v.begin(), v.end()); arr[0] = v[0].second; for (int i = 1; i < n; i++) arr[i] = v[i].second + arr[i - 1]; long long mx = 0; for (int i = 0; i < n; i++) { int ind = lower_bound(v.begin(), v.end(), pair<int, int>(v[i].first + d, 0), cmp) - v.begin() - 1; if (i == 0) sum = arr[ind]; else sum = arr[ind] - arr[i - 1]; if (sum > mx) mx = sum; } cout << mx << endl; return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; void solve() { int n, d; cin >> n >> d; vector<pair<int, int>> v(n); for (int i = 0; i < n; i++) { cin >> v[i].first >> v[i].second; } sort(v.begin(), v.end()); long long mx = 0, val = 0; int low = 0, high = 0; while (high < n) { if ((v[high].first - v[low].first) < d) { val += v[high].second; mx = max(mx, val); high++; } else { val -= v[low].second; low++; } } cout << mx << endl; } int main() { solve(); }
8
CPP
n, d = list(map(int, input().split())) persons = [] for i in range(n): m, s = list(map(int, input().split())) persons.append((m, s)) persons.sort() max_s = 0 cur_s = persons[0][1] good_persons = [persons[0]] for i in range(1, n): if abs(good_persons[0][0] - persons[i][0]) < d: good_persons.append(persons[i]) cur_s += persons[i][1] else: j = 0 rec_s = 0 while (j < len(good_persons)) and (abs((good_persons[j][0] - persons[i][0])) >= d): rec_s += good_persons[j][1] j += 1 if rec_s <= persons[i][1]: cur_s = cur_s - rec_s + persons[i][1] good_persons = good_persons[j:] + [persons[i]] else: max_s = max(max_s, cur_s) cur_s = cur_s - rec_s + persons[i][1] good_persons = good_persons[j:] + [persons[i]] print(max(cur_s, max_s))
8
PYTHON3
#include <bits/stdc++.h> using namespace std; pair<long long, long long> vt[100001]; int main() { int n, d; long long maxy = 0; scanf("%d%d", &n, &d); for (int i = 0; i < n; i++) { long long a, b; scanf("%I64d%I64d", &a, &b); vt[i] = make_pair(a, b); } sort(vt, vt + n); for (int i = 0; i < n; i++) { if (i > 0) vt[i].second += vt[i - 1].second; } for (int i = 0; i < n; i++) { long long sum = 0; int l = i, r = n - 1, ans; while (l <= r) { int mid = (l + r) >> 1; if ((vt[mid].first - vt[i].first) >= d) { r = mid - 1; } else { ans = mid; l = mid + 1; } } if (i > 0) sum = vt[ans].second - vt[i - 1].second; else sum = vt[ans].second; maxy = max(maxy, sum); } cout << maxy << endl; }
8
CPP
def main(): def solve(arr): arr.sort(key = lambda x: x[0]) l = 0 s = 0 max_ = 0 for i in range(len(arr)): s += arr[i][1] while arr[i][0] - arr[l][0] >= d: s -= arr[l][1] l += 1 max_ = max(max_,s) return max_ q = [] n,d = list(map(lambda x: int(x),input().split())) for i in range(n): money,ff = list(map(lambda x: int(x),input().split())) q.append((money,ff)) print(solve(q)) py2 = round(0.5) if py2: from future_builtins import ascii, filter, hex, map, oct, zip range = xrange import os, sys from io import IOBase, BytesIO BUFSIZE = 8192 class FastIO(BytesIO): newlines = 0 def __init__(self, file): self._file = file self._fd = file.fileno() self.writable = "x" in file.mode or "w" in file.mode self.write = super(FastIO, self).write if self.writable else None def _fill(self): s = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.seek((self.tell(), self.seek(0,2), super(FastIO, self).write(s))[0]) return s def read(self): while self._fill(): pass return super(FastIO,self).read() def readline(self): while self.newlines == 0: s = self._fill(); self.newlines = s.count(b"\n") + (not s) self.newlines -= 1 return super(FastIO, self).readline() def flush(self): if self.writable: os.write(self._fd, self.getvalue()) self.truncate(0), self.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable if py2: self.write = self.buffer.write self.read = self.buffer.read self.readline = self.buffer.readline else: self.write = lambda s:self.buffer.write(s.encode('ascii')) self.read = lambda:self.buffer.read().decode('ascii') self.readline = lambda:self.buffer.readline().decode('ascii') sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip('\r\n') # My magical way of doing recursion in python. This # isn't the fastest, but at least it works. from types import GeneratorType def bootstrap(func, stack=[]): def wrapped_function(*args, **kwargs): if stack: return func(*args, **kwargs) else: call = func(*args, **kwargs) while True: if type(call) is GeneratorType: stack.append(call) call = next(call) else: stack.pop() if not stack: break call = stack[-1].send(call) return call return wrapped_function if __name__== "__main__": main()
8
PYTHON3
#include <bits/stdc++.h> using namespace std; struct node { long long m; long long f; }; bool comp(node a, node b) { return a.m < b.m; } int main() { long long n; long long d; cin >> n; cin >> d; int pt1, pt2; node a[n]; for (int i = 0; i < n; i++) { cin >> a[i].m; cin >> a[i].f; } sort(a, a + n, comp); int i = 0, j = 1; long long sum = a[0].f; long long curr = a[0].f; while (j < n) { if (a[j].m - a[i].m < d) { curr += a[j].f; j++; } else { if (curr > sum) sum = curr; curr -= a[i].f; i++; } } if (curr > sum) sum = curr; cout << sum << endl; }
8
CPP
#include <bits/stdc++.h> using namespace std; const long long N = 1e5 + 1; long long ans = -1e18, n, d, pre[N], tmp = 0; vector<pair<long long, long long>> v; int main() { cin >> n >> d; long long x, y; v.push_back({-1, -1}); for (int i = 1; i <= n; i++) { cin >> x >> y; v.push_back({x, y}); } sort(v.begin(), v.end()); pre[0] = 0; for (int i = 1; i <= n; i++) pre[i] = pre[i - 1] + v[i].second; long long i, j = 1; for (i = 1; i <= n; i++) { while (v[i].first - v[j].first >= d) { j++; } tmp = pre[i] - pre[j - 1]; ans = max(ans, tmp); } cout << ans; }
8
CPP
def main(): n,d = [int(x) for x in input().split()] preffac = [0] friends = [] for i in range(n): m,s = [int(x) for x in input().split()] friends.append((m,s)) friends.sort() kon = -1 wyn = 0 ob = 0 for pocz in range(n): if kon < pocz: kon = pocz ob = friends[pocz][1] while kon+1 < n and (friends[kon+1][0] - friends[pocz][0]) < d: ob += friends[kon+1][1] kon += 1 wyn = max(wyn, ob) ob -= friends[pocz][1] print(wyn) main()
8
PYTHON3
n,k=map(int,input().split()) f,v=[],[] d={} for _ in range(n): a,b=map(int,input().split()) if a in d: temp=d[a] temp.append(b) else: d[a]=[b] for i in sorted(d): v.extend([i]*len(d[i])) f.extend(sorted(d[i])) start,end=0,1 m=max(f) pre,temp=[],0 for i in f: temp+=i pre.append(temp) while(start<n and end<n): if v[end]-v[start]>=k: start+=1 else: if start==0: m=max(m,pre[end]) else: m=max(m,pre[end]-pre[start-1]) end+=1 if start==0: m=max(m,pre[end-1]) else: m=max(m,pre[end-1]-pre[start-1]) print(m)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; const long long A = 100000000000000LL, N = 228228; char e[21]; vector<string> ot; pair<int, pair<int, string> > a[N]; long long o, p[3] = {-1, -1, -1}; int i, j, l, r, n, m; int main() { cin >> n >> m; for (i = 0; i < n; ++i) { scanf("%d%d", &a[i].first, &a[i].second.first); a[i].second.second = e; } sort(a, a + n); for (l = 0; l < n; o -= a[l].second.first, ++l) { while (r < n && abs(a[l].first - a[r].first) < m) o += a[r].second.first, ++r; if (o >= p[0]) p[0] = o, p[1] = l, p[2] = r; } for (i = p[1]; i < p[2]; ++i) ot.push_back(a[i].second.second); cout << p[0] << "\n"; }
8
CPP
#!/usr/bin/env python # -*- coding: utf-8 -*- n, d = map(int,input().split()) F = [] for i in range(n): F.append(list(map(int,input().split()))) F = sorted(F, key = lambda x:x[0]) f_factor = 0 j = 0 ans = -1 for i in range(n): if i != 0: f_factor -= F[i-1][1] while j < n: if F[j][0] - F[i][0] >= d: break f_factor += F[j][1] j+=1 ans = max(ans, f_factor) print(ans)
8
PYTHON3
n,d = map(int,input().split()) li = [] for i in range(n): li.append(list(map(int,input().split()))) li = sorted(li) su = [0] * n su[0] = li[0][1] for i in range(1,n): su[i] = su[i - 1] + li[i][1] li = [x[0] for x in li] po = 0 ma = 0 for i in range(n): while((po < n-1) and (li[po+1] - li[i] < d)): po = po + 1 if(i == 0): ma = max(ma,su[po]) else: ma = max(ma,su[po] - su[i-1]) print(ma)
8
PYTHON3
#include <bits/stdc++.h> #pragma GCC optimize("Ofast") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma") #pragma GCC optimize("unroll-loops") using namespace std; long long int MOD = 1000000007; double eps = 1e-12; long long int d; vector<pair<long long int, long long int> > v; vector<long long int> pref_fri(100001, 0); long long int exp(long long int a, long long int b) { if (b == 0) return 1; else if (b == 1) return a; else { long long int x = exp(a, b / 2); long long int ans = ((x % MOD) * (x % MOD)) % MOD; if (b % 2 == 1) { ans *= (a % MOD); ans %= MOD; } return ans; } } long long int bs(int t, int hi) { int lo = 0; while (lo != hi) { int mid = (hi + lo) / 2; if (v[t].first - v[mid].first < d) hi = mid; else lo = mid + 1; } if (v[t].first - v[lo].first < d && lo != 0) { return pref_fri[t] - pref_fri[lo - 1]; } else if (v[t].first - v[lo].first < d && lo == 0) { return pref_fri[t]; } return -1; } void solve() { int n; cin >> n >> d; for (int i = 0; i < n; i++) { long long int a, b; cin >> a >> b; v.push_back(make_pair(a, b)); } sort((v).begin(), (v).end()); pref_fri[0] = v[0].second; for (int i = 1; i < n; i++) pref_fri[i] = v[i].second + pref_fri[i - 1]; long long int ans = v[0].second; for (int i = 1; i < n; i++) { long long int var = bs(i, i); ans = max(ans, var); } cout << ans << "\n"; } int main() { int t = 1; while (t--) { solve(); } }
8
CPP
N, M = map(int, input().split()) values = [] for i in range(N): m, f = input().split() values.append((int(m), int(f))) values.sort() r = 0 l = 0 mx = 0 sum =0 while (r < N): dif = values[r][0] - values[l][0] if dif < M: sum = sum + values[r][1] mx = max(mx, sum) r += 1 else: sum -= values[l][1] l += 1 print(mx)
8
PYTHON3
#include <bits/stdc++.h> const int MAXN = 200001; struct People { long long m, s; bool operator<(const People &p) const { return m < p.m; } } p[MAXN]; int n; long long d, s[MAXN]; int main() { scanf("%d%I64d", &n, &d); d--; for (int i = 1; i <= n; i++) { scanf("%I64d%I64d", &p[i].m, &p[i].s); } std::sort(p + 1, p + n + 1); for (int i = 1; i <= n; i++) { s[i] = s[i - 1] + p[i].s; } long long answer = 0; for (int i = 1; i <= n; i++) { int pos = std::upper_bound(p + 1, p + n + 1, (People){p[i].m + d}) - p - 1; answer = std::max(answer, s[pos] - s[i - 1]); } printf("%I64d\n", answer); return 0; }
8
CPP
#In the name of Allah from sys import stdin, stdout input = stdin.readline n, h = map(int, input().split()) f = sorted([list(map(int, input().split())) for i in range(n)]) ans = 0 fc = f[0][1] start = 0 for i in range(1, n): while f[i][0] - f[start][0] >= h: ans = max(ans, fc) fc -= f[start][1] start += 1 #print(f[start],fc, i) fc += f[i][1] ans = max(ans, fc) #print(fc, ans) stdout.write(str(max(ans, fc)))
8
PYTHON3