solution
stringlengths
10
159k
difficulty
int64
0
3.5k
language
stringclasses
2 values
#include <bits/stdc++.h> using namespace std; int main() { int n, m, x, b[1000] = {0}; cin >> n >> m; for (int i = 0; i < m; i++) { cin >> x; for (int j = x - 1; j < n; j++) { if (b[j] == 0) { b[j] = x; } } } for (int i = 0; i < n; i++) cout << b[i] << ' '; return 0; }
900
CPP
#include <bits/stdc++.h> #pragma GCC optimize("Ofast,unroll-loops,no-stack-protector") using namespace std; using lli = long long; using ld = long double; using ii = pair<int, int>; using vi = vector<int>; const ld eps = 1e-9; int sgn(ld a) { return (a > eps) - (a < -eps); } struct Pt { ld x, y; explicit Pt(ld x = 0, ld y = 0) : x(x), y(y) {} Pt operator+(Pt p) const { return Pt(x + p.x, y + p.y); } Pt operator-(Pt p) const { return Pt(x - p.x, y - p.y); } Pt operator*(ld k) const { return Pt(x * k, y * k); } Pt operator/(ld k) const { return Pt(x / k, y / k); } ld dot(Pt p) const { return x * p.x + y * p.y; } ld cross(Pt p) const { return x * p.y - y * p.x; } ld norm() const { return x * x + y * y; } ld length() const { return sqrtl(norm()); } ld angle() const { ld ang = atan2(y, x); return ang + (ang < 0 ? 2 * acos(-1) : 0); } Pt perp() const { return Pt(-y, x); } Pt unit() const { return (*this) / length(); } Pt rotate(ld angle) const { return Pt(x * cos(angle) - y * sin(angle), x * sin(angle) + y * cos(angle)); } int dir(Pt a, Pt b) const { return sgn((a - *this).cross(b - *this)); } int cuad() const { if (x > 0 && y >= 0) return 0; if (x <= 0 && y > 0) return 1; if (x < 0 && y <= 0) return 2; if (x >= 0 && y < 0) return 3; return -1; } bool operator==(Pt p) const { return (abs((x) - (p.x)) <= +eps) && (abs((y) - (p.y)) <= +eps); } bool operator!=(Pt p) const { return (!(abs((x) - (p.x)) <= +eps)) || (!(abs((y) - (p.y)) <= +eps)); } }; using Poly = vector<Pt>; Poly a; int n, m; bool contains(const Poly &a, Pt p) { int lo = 1, hi = int(a.size()) - 1; if (a[0].dir(a[lo], a[hi]) > 0) swap(lo, hi); if (p.dir(a[0], a[lo]) >= 0 || p.dir(a[0], a[hi]) <= 0) return false; while (abs(lo - hi) > 1) { int mid = (lo + hi) >> 1; (p.dir(a[0], a[mid]) > 0 ? hi : lo) = mid; } return p.dir(a[lo], a[hi]) < 0; } int main() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); while (cin >> n) { a = Poly(n); for (auto &p : a) cin >> p.x >> p.y; cin >> m; bool inside = true; while (m--) { Pt p; cin >> p.x >> p.y; if (!inside) continue; if (!contains(a, p)) inside = false; } cout << (inside ? "YES" : "NO") << '\n'; } return 0; }
2,100
CPP
input() events = input().strip() nor = 10 # number of rooms alist = [0] * 10 for e in events: if e == 'L': for i in range(nor): if alist[i] == 0: alist[i] = 1 break elif e == 'R': for i in range(nor): if alist[nor - i - 1] == 0: alist[nor - i - 1] = 1 break else: alist[ int(e) ] = 0 ans = '' for x in alist: ans += str(x) print(ans)
800
PYTHON3
# -*- coding: utf-8 -*- """ Created on Wed Feb 12 19:45:42 2020 @author: Lenovo """ #https://codeforces.com/problemset/problem/894/A def Qaq(): text = input() output = 0 for i in range(len(text)): if text[i] == "Q": for j in range(i+1, len(text)): if text[j] == "A": for x in range(j+1, len(text)): if text[x] == "Q": output += 1 print(output) return Qaq()
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int n, m, q; int A[300100]; int e[300100]; int lp[300100]; int dist[300100]; vector<int> G[300100]; vector<int> V; inline void unionS(int x, int y) { A[y] = x; } inline int findS(int x) { return (A[x] < 0) ? x : (A[x] = findS(A[x])); } void elp(int u) { int init = u; dist[u] = 0; V = *new vector<int>(); queue<int> Q; Q.push(u); while (Q.size() > 0) { int x = Q.front(); V.push_back(x); Q.pop(); for (int i = (0); i < (G[x].size()); i++) { if (dist[G[x][i]] > dist[x] + 1) { dist[G[x][i]] = dist[x] + 1; Q.push(G[x][i]); } } } for (int i = (0); i < (V.size()); i++) { if (dist[V[i]] < dist[u]) u = V[i]; dist[V[i]] = 10000000; } dist[u] = 0; Q.push(u); while (Q.size() > 0) { int x = Q.front(); Q.pop(); for (int i = (0); i < (G[x].size()); i++) { if (dist[G[x][i]] > dist[x] + 1) { dist[G[x][i]] = dist[x] + 1; Q.push(G[x][i]); } } } lp[init] = 0; for (int i = (0); i < (V.size()); i++) { lp[init] = (((lp[init]) > (dist[V[i]])) ? (lp[init]) : (dist[V[i]])); } e[init] = (lp[init] + 1) / 2; } int main() { ios::sync_with_stdio(false); for (int i = (1); i < (300100); i++) { A[i] = -1; dist[i] = 10000000; } cin >> n >> m >> q; int u, v; for (int i = (1); i <= (m); i++) { cin >> u >> v; G[u].push_back(v); G[v].push_back(u); if (findS(u) != findS(v)) { unionS(findS(u), findS(v)); } } for (int i = (1); i <= (n); i++) { if (A[i] < 0) { elp(i); } } int op, x, y; for (int qq = (1); qq <= (q); qq++) { cin >> op; if (op == 1) { cin >> x; cout << lp[findS(x)] << endl; } else { cin >> x >> y; if (findS(x) != findS(y)) { x = findS(x); y = findS(y); lp[x] = (((lp[x]) > ((((lp[y]) > (e[x] + e[y] + 1)) ? (lp[y]) : (e[x] + e[y] + 1)))) ? (lp[x]) : ((((lp[y]) > (e[x] + e[y] + 1)) ? (lp[y]) : (e[x] + e[y] + 1)))); e[x] = (lp[x] + 1) / 2; unionS(x, y); } } } return 0; }
2,100
CPP
# cook your dish here for _ in range(int(input())): n,a,b = map(int,input().split()) t = "" g = 97 f = 0 for i in range(n): t+=chr(g+f) f+=1 f = f%b print(t)
900
PYTHON3
#include <bits/stdc++.h> using namespace std; const int maxm = 2e5 + 7; const int maxn = 1e6 + 7; const int inf = 0x3f3f3f3f; const long long INF = 0x3f3f3f3f3f3f3f3f; int n; double a, b, x, y, ans, v; double dis() { return sqrt(pow(a - x, 2) + pow(b - y, 2)); } int main() { cin >> a >> b >> n; ans = INF; for (int i = 1; i <= n; i++) { cin >> x >> y >> v; ans = min(ans, dis() / v); } printf("%lf\n", ans); return 0; }
900
CPP
import sys n=int(input()) for i in range(n): str=input() if(len(str)<=10): print(str) else: t=str[0] p=int(len(str)-2) q=str[len(str)-1] print(t,p,q,end='\n',sep="")
800
PYTHON3
t=int(input()) while(t): t-=1 n=int(input()) if n==0: print(0) if n==1: print(1) else: print(int(n/2)+1)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int n, m, k; vector<int> v; int main() { while (scanf("%d%d%d", &n, &m, &k) != EOF) { v.clear(); for (int i = 0; i < k; i++) v.push_back(1); v.push_back(n); for (int i = 1; i < k; i++) v.push_back(n + 1); int l = 2 * n; if (k == 1) l--; while (l < n + m + 1) { v.push_back(l); if (l + 1 == n + m + 1) break; for (int i = 1; i < k; i++) v.push_back(l + 1); l += n; if (k == 1) l--; } printf("%d\n%d", v.size(), v[0]); for (int i = 1; i < v.size(); i++) printf(" %d", v[i]); puts(""); } return 0; }
1,800
CPP
#include <bits/stdc++.h> using namespace std; struct __timestamper {}; vector<int> t, h; vector<vector<int>> g; vector<long long> dp[3]; long long calc(int v, int p, int out) { long long& ans = dp[out][v]; if (ans != -1) { return ans; } if (p == -1 && out != 1) { return -1; } if (p != -1 && out == 1) { return -1; } if (p != -1 && out == 0 && h[v] < h[p]) { return -1; } if (p != -1 && out == 2 && h[v] > h[p]) { return -1; } ans = numeric_limits<long long>::max(); long long cur = 0; vector<long long> changes; int cnt0 = (out == 0), cnt2 = (out == 2); for (int u : g[v]) { if (u == p) continue; long long ans0 = calc(u, v, 2); long long ans2 = calc(u, v, 0); if (ans0 == -1) { cur += ans2; cnt2++; } else { cur += ans0; cnt0++; if (ans2 != -1) { changes.push_back(ans2 - ans0); } } } sort(changes.begin(), changes.end()); for (int i = 0; i <= (int)changes.size(); i++) { ans = min(ans, cur + max(cnt0, cnt2) * 1LL * t[v]); if (i != (int)changes.size()) { cnt0--; cnt2++; cur += changes[i]; } }; return ans; } int main() { int n; while (scanf("%d", &n) == 1) { t = vector<int>(n); h = vector<int>(n); g = vector<vector<int>>(n); dp[0] = dp[1] = dp[2] = vector<long long>(n, -1); for (int i = 0; i < n; i++) { scanf("%d", &t[i]); } for (int i = 0; i < n; i++) { scanf("%d", &h[i]); } for (int i = 0; i < n - 1; i++) { int a, b; scanf("%d%d", &a, &b); --a, --b; g[a].push_back(b); g[b].push_back(a); } printf("%lld\n", calc(0, -1, 1)); } return 0; }
2,800
CPP
#include <bits/stdc++.h> using namespace std; const int N = 1005; int n, a[N][N]; deque<int> p[N]; int ptr[N], mat[N]; bool vis[N][N]; void upd(int x) { while (!p[x].empty() && vis[x][p[x].front()]) p[x].pop_front(); while (!p[x].empty() && vis[x][p[x].back()]) p[x].pop_back(); } inline void del(int x, int y) { vis[x][y] = vis[y][x] = 1; } void add(int x, int y) { mat[y] = x; while (1) { upd(y); if (p[y].empty()) { cout << -1 << endl; exit(0); } if (p[y].back() != x) del(p[y].back(), y); else break; } } int nxt(int x) { upd(x); int y = p[x].front(); p[x].pop_front(); upd(x); p[x].push_front(y); return mat[p[x][1]]; } int main() { ios::sync_with_stdio(false); cin >> n; if (n & 1) { cout << -1 << endl; return 0; } for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { if (i != j) cin >> a[i][j], p[i].push_back(j); } sort(p[i].begin(), p[i].end(), [&](int x, int y) { return a[i][x] < a[i][y]; }); } queue<int> q; for (int i = 1; i <= n; i++) q.push(i); while (!q.empty()) { int x = q.front(); q.pop(); while (1) { upd(x); int y = p[x].front(), z = mat[y]; if (z && a[y][z] < a[y][x]) assert(0); if (z) { mat[y] = 0; q.push(z); } add(x, y); break; } } int cur = 1; while (1) { while (cur <= n) { upd(cur); if (p[cur].size() > 1) break; else ++cur; } if (cur > n) { for (int i = 1; i <= n; i++) cout << p[i].front() << endl; return 0; } vector<int> c1, c2; int x = cur, y = cur; do x = nxt(x), y = nxt(nxt(y)); while (x != y); do c1.push_back(y), y = nxt(y); while (x != y); for (auto &i : c1) { int y = p[i][0]; c2.push_back(y); mat[y] = 0; del(i, y); } for (int i = 0; i < int(c1.size()); i++) add(c1[i], c2[(i + 1) % c1.size()]); } return 0; }
3,500
CPP
for _ in range(int(input())): n,m=map(int,input().split()) a=list(map(int,input().split())) p=set(map(int,input().split())) mx,hmx=0,0 for i in range(len(a)): ai=a[i] #print(i,mx,hmx) if i+1 in p: hmx=max(hmx,ai) if mx>ai: print('NO')#1',mx,ai,i) break elif i in p: if mx>ai: print('NO')#2',mx,ai,i) break mx=max(mx,hmx,ai) else: mx=max(mx,hmx) if mx>ai: print('NO')#3',mx,ai,i) break mx=ai else: print('YES')
1,200
PYTHON3
#include <bits/stdc++.h> using namespace std; long long add(long long x, long long y) { x += y; while (x >= 998244353) x -= 998244353; while (x < 0) x += 998244353; return x; } long long mul(long long x, long long y) { return (x * 1ll * y) % 998244353; } long long binpow(long long x, long long y) { long long z = 1; while (y > 0) { if (y % 2 == 1) z = mul(z, x); x = mul(x, x); y /= 2; } return z; } long long inv(long long x) { return binpow(x, 998244353 - 2); } long long divide(long long x, long long y) { return mul(x, inv(y)); } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long n, k; cin >> n >> k; vector<long long> a(k); for (long long i = 0; i < (long long)k; ++i) cin >> a[i]; vector<long long> last(n + 1, -1), fst(n + 1, k); for (long long i = 1; i <= k; i++) { last[a[i - 1]] = i; } for (long long i = k; i >= 1; i--) { fst[a[i - 1]] = i; } long long ans = 0; for (long long i = 1; i <= n; i++) { for (long long j = max(1ll, i - 1); j <= min(i + 1, n); j++) { if (j == i) { if (last[i] == -1) ans += 1; } else ans += (last[i] <= fst[j]); } } cout << ans << endl; return 0; }
1,500
CPP
import math def calc(p,r): l = math.radians(180.0 / p) return (math.sin(l) * r) / (1.0 - math.sin(l)) p, r = [float(i) for i in input().split()] print(calc(p,r))
1,200
PYTHON3
import math n = input().split(' ') r = int(n[1]) n = int(n[0]) rad = ((90 - 180/n)*math.pi)/180 R = r/(1/math.cos(rad)-1) print(R)
1,200
PYTHON3
n, m, k = [int(n) for n in input().split()] a = [int(n) for n in input().split()] instructions = [] temp = [] for i in range(n+1): temp.append(0) for i in range(m): instructions.append([int(n) for n in input().split()]) queries = [] for i in range(m+1): queries.append(0) for i in range(k): x, y = [int(n) for n in input().split()] x-=1 y-=1 queries[x]+=1 queries[y+1]-=1 num_queries = 0 for i in range(m): num_queries += queries[i] temp[instructions[i][0]-1] += num_queries*instructions[i][2] temp[instructions[i][1]] -= num_queries*instructions[i][2] #print(temp[0]+a[0], end=" ") x = temp[0] print(x + a[0], end=" ") for i in range(1, n): x += temp[i] print(x + a[i], end=" ") print()
1,400
PYTHON3
#include <bits/stdc++.h> using namespace std; int n, m, kk, dp[1005][1005][12][2]; string s, t; int main() { cin >> n >> m >> kk; cin >> s >> t; s = '#' + s; t = '*' + t; for (int k = 1; k <= kk; ++k) { for (int i = 1; i <= n; ++i) { for (int j = 1; j <= m; ++j) { dp[i][j][k][0] = max(dp[i][j - 1][k][0], dp[i - 1][j][k][0]); if (s[i] == t[j]) { dp[i][j][k][1] = max(dp[i - 1][j - 1][k][1] + 1, dp[i - 1][j - 1][k - 1][0] + 1); } dp[i][j][k][0] = max(dp[i][j][k][0], dp[i][j][k][1]); } } } cout << dp[n][m][kk][0]; return 0; }
1,900
CPP
s=input() t=input() check=1 n=len(t) for i in range(len(s)): if s[i]!=t[n-i-1]: check=0 break print("YES" if check==1 else "NO")
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int a, b, c, n, e[200010]; int tal = 0, bc = 0, ac = 0, ab = 0, a0 = 0, b0 = 0, c0 = 0; int main() { scanf("%d%d%d%d", &n, &a, &b, &c); if (a > b) swap(a, b); if (a > c) swap(a, c); if (b > c) swap(b, c); for (int i = 1; i <= n; i++) { scanf("%d", &e[i]); if (e[i] > a + b + c) { printf("-1\n"); return 0; } if (e[i] > b + c) tal++; else if (e[i] > a + c) bc++; else if (a + b > c) { if (e[i] > a + b) ac++; else if (e[i] > c) ab++; else if (e[i] > b) c0++; else if (e[i] > a) b0++; else a0++; } else { if (e[i] > c) ac++; else if (e[i] > a + b) c0++; else if (e[i] > b) ab++; else if (e[i] > a) b0++; else a0++; } } bool deb = false; if (deb) printf("%d %d %d %d %d %d %d\n", a0, b0, c0, ab, ac, bc, tal); int ans = 0; ans += tal; ans += bc; a0 -= bc; ans += ac; if (b0 < ac) { a0 -= ac - b0; b0 = 0; } else b0 -= ac; if (a0 < 0) a0 = 0; if (a + b > c) { if (deb) printf("%d %d %d %d:%d\n", a0, b0, c0, ab, ans); ans += ab; if (c0 >= ab) c0 -= ab; else { ab -= c0; c0 = 0; if (b0 >= ab) b0 -= ab; else { ab -= b0; b0 = 0; a0 -= ab; } } if (deb) printf("%d %d %d: %d\n", a0, b0, c0, ans); if (a0 < 0) a0 = 0; int tmp = c0; if (b0 >= tmp) ans += c0, b0 -= tmp, a0 -= tmp; else { tmp -= b0; a0 -= b0; b0 = 0; if (a0 < 0) a0 = 0; if (a0 >= 2 * tmp) a0 -= 2 * tmp, ans += c0; else { tmp -= (a0 + 1) / 2; a0 = 0; ans += (c0 - tmp) + (tmp + 1) / 2; } } if (a0 < 0) a0 = 0; if (deb) printf("%d %d %d: %d\n", a0, b0, c0, ans); ans += (b0 + 1) / 2; if (a0 >= (b0 + 1) / 2) a0 -= (b0 + 1) / 2; else a0 = 0; if (b0 & 1) a0--; ans += (a0 + 2) / 3; printf("%d\n", ans); } else { int t1 = b0, tmp = b0; if (c0 > b0) c0 -= b0, a0 -= b0, ans += b0; else { tmp -= c0, a0 -= c0; c0 = 0; if (ab > tmp) ab -= tmp, a0 -= tmp, ans += b0; else { tmp -= ab, a0 -= ab; ab = 0; ans += b0 - tmp + (tmp + 1) / 2; a0 -= (tmp + 1) / 2; if (tmp & 1) a0--; } } if (a0 < 0) a0 = 0; int ntt = (a0 + 1) / 2, nt2 = (c0 + ab); if (nt2 > ntt) { ans += ntt; if (c0 > ntt) c0 -= ntt; else { ntt -= c0; c0 = 0; ab -= ntt; } if (ab < 0) ab = 0; ans += c0; ab -= c0; if (ab < 0) ab = 0; ans += (ab + 1) / 2; } else { ans += nt2; a0 -= nt2 * 2; ans += (a0 + 2) / 3; } printf("%d\n", ans); } return 0; }
2,400
CPP
#include <bits/stdc++.h> using namespace std; bool v[4001][4001]; int per[2][4001]; int sum[4001]; int main() { int c, n, c1, c2; int rmin = 4010; cin >> c >> n; for (int i = 0; i < n; i++) { cin >> per[0][i] >> per[1][i]; v[per[0][i]][per[1][i]] = true; v[per[1][i]][per[0][i]] = true; sum[per[0][i]]++; sum[per[1][i]]++; } for (int i = 0; i < n; i++) { c1 = per[0][i]; c2 = per[1][i]; for (int j = 1; j <= c; j++) { if (v[c1][j] && v[c2][j]) { if (sum[c1] + sum[c2] + sum[j] < rmin) { rmin = sum[c1] + sum[c2] + sum[j]; } } } } if (rmin == 4010) { rmin = 5; } cout << rmin - 6; return 0; }
1,500
CPP
#include <bits/stdc++.h> using namespace std; const int N = 1e5 + 10; int a[N], b[N], c[2 * N]; vector<int> e[2 * N]; void dfs(int v, int p) { c[v] = p; for (auto u : e[v]) { if (!c[u]) dfs(u, 3 - p); } } int main() { int n; scanf("%d", &n); for (int i = 1; i <= n; i++) scanf("%d%d", a + i, b + i); for (int i = 1; i <= n; i++) { e[i * 2].push_back(i * 2 - 1); e[i * 2 - 1].push_back(i * 2); e[a[i]].push_back(b[i]); e[b[i]].push_back(a[i]); } for (int i = 1; i <= 2 * n; i++) if (!c[i]) dfs(i, 1); for (int i = 1; i <= n; i++) printf("%d %d\n", c[a[i]], c[b[i]]); return 0; }
2,600
CPP
t=int(input()) for _ in range(t): n=int(input()) if n==1: print(-1) else: print(int('2'+'3'*(n-1)))
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; long long dp1[100005], dp2[100005]; long long ans1[100005], ans2[100005]; int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); long long n, m; cin >> n >> m; std::vector<long long> a(n + 1), b(m + 1); long long x; for (long long int i = 1; i < n + 1; i++) { cin >> a[i]; dp1[i] = dp1[i - 1] + a[i]; } for (long long int i = 1; i < m + 1; i++) { cin >> b[i]; dp2[i] = dp2[i - 1] + b[i]; } cin >> x; for (long long int i = 1; i < n + 1; i++) { long long cur = 1e18; for (long long int j = i; j < n + 1; j++) { long long z1 = dp1[j] - dp1[j - i]; cur = min(cur, z1); } ans1[i] = cur; } for (long long int i = 1; i < m + 1; i++) { long long cur = 1e18; for (long long int j = i; j < m + 1; j++) { long long z1 = dp2[j] - dp2[j - i]; cur = min(cur, z1); } ans2[i] = cur; } long long ans = -1; for (long long int i = 1; i < n + 1; i++) { for (long long int j = 1; j < m + 1; j++) { if ((ans1[i] * ans2[j]) <= x) { ans = max(ans, i * j); } } } if (ans != -1) cout << ans; else cout << "0"; }
1,600
CPP
#include <bits/stdc++.h> using namespace std; int getFours(int* ones, int* twos, int* fours, int num) { if (*fours >= num) { *fours -= num; num = 0; } else { num -= (*fours); *fours = 0; } if (*twos >= num * 2) { *twos -= num * 2; num = 0; } else { num -= (*twos) / 2; *twos = (*twos) % 2; } if (*ones >= num * 4) { *ones -= num * 4; } else { return 1; } return 0; } int main() { int n, k, a[105]; scanf("%d%d", &n, &k); for (int i = 0; i < k; i++) { scanf("%d", &a[i]); } sort(&a[0], &a[k], greater<int>()); int fours, twos, ones; fours = n; twos = 2 * n; ones = 0; for (int i = 0; i < k; i++) { switch (a[i] % 4) { case 0: if (getFours(&ones, &twos, &fours, a[i] / 4) == 1) { printf("NO\n"); return 0; } break; case 1: if (getFours(&ones, &twos, &fours, a[i] / 4) == 1) { printf("NO\n"); return 0; } if (ones > 0) { ones--; } else { if (fours > 0) { fours--; twos++; } else { if (twos > 0) { twos--; } else { printf("NO\n"); return 0; } } } break; case 2: if (getFours(&ones, &twos, &fours, a[i] / 4) == 1) { printf("NO\n"); return 0; } if (twos > 0) { twos--; } else { if (fours > 0) { fours--; ones++; } else { if (ones > 1) { ones -= 2; } else { printf("NO\n"); return 0; } } } break; case 3: if (getFours(&ones, &twos, &fours, a[i] / 4) == 1) { printf("NO\n"); return 0; } if (ones > 0 && twos > 0) { ones--; twos--; } else { if (ones > 2) { ones -= 3; } else { if (getFours(&ones, &twos, &fours, 1) == 1) { printf("NO\n"); return 0; } } } break; default: break; } } printf("YES\n"); return 0; }
1,900
CPP
#include <bits/stdc++.h> using namespace std; int n, q; long long a[200010], c[200010], k; long long f, s; int ef(int le, int ri, long long va) { if (le >= ri) { return le; } int mid = (le + ri) / 2; if (c[mid] < va) { if (c[mid + 1] > va) return mid; return ef(mid + 1, ri, va); } else if (c[mid] > va) { return ef(le, mid - 1, va); } else { return mid; } } int main() { scanf("%d%d", &n, &q); int i, j; for (i = 1; i <= n; i++) { scanf("%I64d", &a[i]); c[i] = c[i - 1] + a[i]; } for (i = 1; i <= q; i++) { scanf("%I64d", &k); if (s + k >= c[n]) { printf("%d\n", n); s = 0; } else if (s + k < c[1]) { printf("%d\n", n); s = s + k; } else { s = s + k; int pos = ef(1, n, s); printf("%d\n", n - pos); } } return 0; }
1,400
CPP
#include <bits/stdc++.h> using namespace std; const long long int logx = 30; const long long int N = 2e5 + 5; const long long int INF = 1e18 + 5; const long long int mod = 321555123; const double PI = 3.14159265358979323846; inline long long int mul(long long int a, long long int b) { return (a * 1ll * b) % mod; } inline long long int sub(long long int a, long long int b) { long long int c = a - b; if (c < 0) c += mod; return c; } inline long long int add(long long int a, long long int b) { long long int c = a + b; if (c > mod) c -= mod; return c; } template <typename T> T power(T x, T y, long long int m) { T ans = 1; while (y > 0) { if (y & 1LL) ans = (ans * x) % m; y >>= 1ll; x = (x * x) % m; } return ans % m; } vector<long long int> g[N]; long long int n, in[N], uu[N], vv[N], siz[N], a[N]; long long int root(long long int x) { while (x != a[x]) { a[x] = a[a[x]]; x = a[x]; } return x; } void unionx(long long int x, long long int y) { long long int rx = root(x); long long int ry = root(y); if (rx == ry) { return; } else { if (siz[rx] < siz[ry]) { a[rx] = ry; siz[ry] += siz[rx]; siz[rx] = 0; } else { a[ry] = rx; siz[rx] += siz[ry]; siz[ry] = 0; } } } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); ; long long int m; cin >> n >> m; long long int maxi = 0, idx; vector<pair<long long int, long long int> > ans; for (long long int i = 1; i <= n; i++) { a[i] = i; siz[i] = 1; } pair<long long int, pair<long long int, long long int> > p[m]; for (long long int i = 0; i < m; i++) { long long int u, v; cin >> u >> v; uu[i] = u; vv[i] = v; in[u]++; in[v]++; g[u].push_back(v); g[v].push_back(u); maxi = max(maxi, max(in[u], in[v])); } for (long long int i = 1; i <= n; i++) { if (maxi == in[i]) { idx = i; break; } } for (auto i : g[idx]) { if (root(idx) == root(i)) { continue; } unionx(idx, i); ans.push_back(make_pair(idx, i)); } for (long long int i = 0; i < m; i++) { long long int u = uu[i]; long long int v = vv[i]; if (root(u) == root(v)) { continue; } unionx(u, v); ans.push_back(make_pair(u, v)); } for (auto i : ans) { cout << i.first << " " << i.second << endl; } }
1,600
CPP
#include <bits/stdc++.h> using namespace std; int a[2000000]; int main() { int n, d; cin >> n >> d; for (int i = 0; i < n; i++) scanf("%d", a + i); long long res = 0; for (int i = 0, j = 0; i < n; i++) { for (; j + 1 < n && a[j + 1] - a[i] <= d; j++) ; if (j - i > 1) res += 1LL * (j - i) * (j - i - 1) / 2; } cout << res << endl; return 0; }
1,300
CPP
# ataux test import math for _ in range(int(input())): n, k = map(int, input().split()) a = [*map(int, input().split())] x = a[1] - a[0] for i in range(1, n): x = math.gcd(a[i]-a[0], x) k -= a[0] if k % x == 0: print("YES") else: print("NO")
1,800
PYTHON3
#include <bits/stdc++.h> using namespace std; long long int n, sol = 1, acc, t; int C[1003][1003]; int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(); C[0][0] = 1; for (int i = 1; i <= 1000; i++) for (int j = 0; j <= i; j++) C[i][j] = (j == 0 ? 1LL : 1LL * C[i - 1][j - 1] + C[i - 1][j]) % 1000000007; cin >> n; while (n-- && cin >> t) { acc += t; sol = 1LL * sol * C[acc - 1][t - 1] % 1000000007; } cout << sol % 1000000007; return 0; }
1,500
CPP
import sys sys.setrecursionlimit(10**5) int1 = lambda x: int(x)-1 p2D = lambda x: print(*x, sep="\n") def II(): return int(sys.stdin.buffer.readline()) def LI(): return list(map(int, sys.stdin.buffer.readline().split())) def LI1(): return list(map(int1, sys.stdin.buffer.readline().split())) def LLI(rows_number): return [LI() for _ in range(rows_number)] def LLI1(rows_number): return [LI1() for _ in range(rows_number)] def BI(): return sys.stdin.buffer.readline().rstrip() def SI(): return sys.stdin.buffer.readline().rstrip().decode() # dij = [(0, 1), (-1, 0), (0, -1), (1, 0)] dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)] inf = 10**16 md = 998244353 # md = 10**9+7 n = II() aa = [] for _ in range(n): ca = SI().split() if ca[0] == "+": aa.append(int(ca[1])) else: aa.append(-1) def solve(ti): dp = [[0]*(n+1) for _ in range(n)] dp[0][0] = 1 for i in range(n-1): for j in range(i+1): pre = dp[i][j] if pre == 0: continue if i < ti: if aa[i] > 0: if aa[i] <= aa[ti]: dp[i+1][j+1] = (dp[i+1][j+1]+pre)%md else: dp[i+1][j] = (dp[i+1][j]+pre)%md else: nj = max(0, j-1) dp[i+1][nj] = (dp[i+1][nj]+pre)%md dp[i+1][j] = (dp[i+1][j]+pre)%md else: if aa[i+1] > 0: if aa[i+1] < aa[ti]: dp[i+1][j+1] = (dp[i+1][j+1]+pre)%md else: dp[i+1][j] = (dp[i+1][j]+pre)%md elif j: dp[i+1][j-1] = (dp[i+1][j-1]+pre)%md dp[i+1][j] = (dp[i+1][j]+pre)%md # print(ti) # p2D(dp) res = 0 for a in dp[-1]: res += a res %= md return res ans = 0 for i in range(n): if aa[i] < 0: continue ans += solve(i)*aa[i]%md ans %= md print(ans)
2,200
PYTHON3
def count_banana_cost(k, w): """ """ cost = 0 for i in range(1, w + 1): cost += (i * k) return cost def must_borrow(cost): """ Return 0 if must borrow or return borrow number """ if n - banana_cost > 0: return 0 return abs(n - banana_cost) k, n, w = list(map(int, input().split())) banana_cost = count_banana_cost(k, w) print(must_borrow(banana_cost))
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const int mx = 1e6 + 5; const int MOD = 1e9 + 7; long long bigmod(long long x, long long n) { long long res = 1; while (n > 0) { if (n % 2 == 1) res = (res * x) % MOD; x = (x * x) % MOD; n /= 2; } return res; } long long fact[mx], inv[mx]; void prep(int k) { fact[0] = 1; for (int i = 1; i <= k; i++) fact[i] = (fact[i - 1] * i) % MOD; for (int i = 1; i < 2005 && i <= k; i++) { inv[i] = bigmod(fact[i], MOD - 2); int x = k - i; inv[x] = bigmod(fact[x], MOD - 2); } } long long nCr(int n, int r) { if (r > n) return 0; if (r == 0 || r == n) return 1; r = min(r, n - r); long long res = fact[n]; res = (res * inv[r]) % MOD; return (res * inv[n - r]) % MOD; } long long DP[1005][1005]; long long solve(int n, int x) { if (x == 1) return 1; if (n == 1) return 0; if (DP[n][x] != -1) return DP[n][x]; long long res = (solve(n - 1, x) * x) % MOD + (solve(n - 1, x - 1) * x) % MOD; return DP[n][x] = res % MOD; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); int m, n, k; cin >> n >> m >> k; long long ans; if (m == 1) ans = bigmod(k, n); else { memset(DP, -1, sizeof(DP)); prep(k); ans = 0; for (int i = 1; i <= n && i <= k; i++) { for (int j = 0; j <= i; j++) { long long cnt = 1; cnt = (cnt * nCr(k, 2 * i - j)) % MOD; cnt = (cnt * nCr(2 * i - j, i - j)) % MOD; cnt = (cnt * nCr(i, i - j)) % MOD; cnt = (cnt * solve(n, i)) % MOD; cnt = (cnt * solve(n, i)) % MOD; cnt = (cnt * bigmod(j, n * m - 2 * n)) % MOD; ans = (ans + cnt) % MOD; } } } cout << ans << endl; return 0; }
2,300
CPP
#include <bits/stdc++.h> using namespace std; const int maxn = 1009; int n; int nxt[maxn][maxn]; int a[maxn]; bool dp[maxn][1 << 8][8]; bool can(int k) { for (int i = 0; i < maxn; i++) { for (int j = 0; j < (1 << 8); j++) { for (int t = 0; t < 8; t++) { dp[i][j][t] = false; } } } dp[1][0][0] = true; for (int i = 1; i <= n; i++) { for (int m = 0; m < (1 << 8); m++) { for (int t = 0; t < 8; t++) { if (!dp[i][m][t]) continue; dp[i + 1][m][t] = true; if (m & (1 << a[i])) continue; if (nxt[i][k / 8] != -1) dp[nxt[i][k / 8]][m | (1 << a[i])][t] = true; if (t < 7 && nxt[i][k / 8 + 1] != -1) dp[nxt[i][k / 8 + 1]][m | (1 << a[i])][t + 1] = true; } } } return dp[n][(1 << 8) - 1][k % 8]; } int main() { scanf("%d", &n); for (int i = 1; i <= n; i++) { scanf("%d", a + i); a[i]--; } for (int i = n; i >= 1; i--) { nxt[i][1] = i; nxt[i][2] = -1; for (int j = n; j > i; j--) { if (a[j] == a[i]) nxt[i][2] = j; } } for (int i = n; i >= 1; i--) { for (int j = 3; j <= n; j++) { if (nxt[i][2] == -1) { nxt[i][j] = -1; } else { nxt[i][j] = nxt[nxt[i][2]][j - 1]; } } } int ans = 0; for (int x = 0; x < 8; x++) { for (int i = 1; i <= n; i++) { if (a[i] == x) { ans++; break; } } } int low = 8, high = n; while (low <= high) { int mid = (low + high) / 2; if (can(mid)) { ans = mid; low = mid + 1; } else { high = mid - 1; } } printf("%d", ans); }
2,200
CPP
#include<bits/stdc++.h> using namespace std; const int inf=0x3f3f3f3f; const int B=5e7; typedef long long ll; #define N 6233 inline ll read(){ ll x=0,f=1; char c=getchar(); while(c<'0'||c>'9'){ if(c=='-')f=-1; c=getchar(); } while(c>='0'&&c<='9'){ x=(x<<1)+(x<<3)+c-'0'; c=getchar(); } return x*f; } namespace Maxflow{ int head[N],ecnt,S,T,dep[N]; struct Edge{ int nxt,to,val; }edge[N<<2]; void add(int a,int b,int c){ edge[++ecnt]={head[a],b,c}; head[a]=ecnt; } void adde(int a,int b,int c){ add(a,b,c),add(b,a,0); } void init(int _S,int _T){ ecnt=1; memset(head,0,sizeof(head)); S=_S,T=_T; } queue<int> q; bool bfs(){ memset(dep,0,sizeof(dep)); q.push(S); dep[S]=1; while(!q.empty()){ int u=q.front(); q.pop(); for(int i=head[u];i;i=edge[i].nxt){ int v=edge[i].to; if(edge[i].val&&!dep[v]){ dep[v]=dep[u]+1; q.push(v); } } } return dep[T]>0; } int dfs(int u,int limit){ if(u==T)return limit; int flow=0; for(int i=head[u];i&&limit;i=edge[i].nxt){ int v=edge[i].to; if(dep[v]==dep[u]+1&&edge[i].val){ int k=dfs(v,min(limit,edge[i].val)); edge[i].val-=k; edge[i^1].val+=k; flow+=k; limit-=k; } } if(!flow)dep[u]=inf; return flow; } int Dinic(){ int maxflow=0; while(bfs()){ maxflow+=dfs(S,inf); } return maxflow; } } int n,m,val[N]; inline int ID(int x,int y){ return (x-1)*(n+1)+y+1; } int main(){ n=read(),m=read(); Maxflow::init(n*n*n+123,n*n*n+124); for(int i=1;i<=m;++i){ int u=read(),v=read(),w=read(); val[u]+=w,val[v]-=w; for(int j=0;j<n;++j){ Maxflow::adde(ID(v,j),ID(u,j+1),inf); } } for(int i=1;i<=n;++i){ for(int j=0;j<n;++j){ Maxflow::adde(ID(i,j),ID(i,j+1),val[i]*j+B); } } for(int i=1;i<=n;++i){ Maxflow::adde(Maxflow::S,ID(i,0),inf); Maxflow::adde(ID(i,n),Maxflow::T,inf); } Maxflow::Dinic(); Maxflow::bfs(); for(int i=1;i<=n;++i){ for(int j=n;j>=0;--j){ if(Maxflow::dep[ID(i,j)]){ printf("%d ",j); break; } } } return 0; }
2,600
CPP
#include <bits/stdc++.h> using namespace std; int main() { int smallpos, largepos, i, j, n; cin >> n; for (i = 1; i <= n; i++) { cin >> j; if (j == 1) smallpos = i; if (j == n) largepos = i; } if ((smallpos == n && largepos == 1) || (smallpos == 1 && largepos == n)) { cout << n - 1 << endl; } else cout << max(max(smallpos - 1, n - smallpos), max(largepos - 1, n - largepos)) << endl; return 0; }
800
CPP
#include <bits/stdc++.h> using namespace std; #pragma GCC target("popcnt") void MP() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); } const long long MAX = (long long)1e6 + 15; const long long MAX2 = 31; const long double EPS = 1e-8; const long long sigma = 128; const long long delta = (long long)1e6 + 3; const long long MAXB = (1 << 10); inline bool gt(long long a, long long i) { return (a >> i) & 1; } const long long MOD = (long long)1e9 + 7; long long add(long long a, long long b) { if (a + b > MOD) return a + b - MOD; return a + b; } void solve() { long long n; cin >> n; long long dp[2][4]; memset(dp, 0, sizeof(dp)); dp[0][0] = 1; for (long long i = (1); i < n + 1; ++i) { for (long long j = 0; j < 4; ++j) { dp[i % 2][j] = 0; for (long long k = 0; k < 4; ++k) { if (j != k) dp[i % 2][j] = add(dp[i % 2][j], dp[(i + 1) % 2][k]); } } } cout << (dp[n % 2][0]) << '\n'; } signed main() { MP(); solve(); }
1,500
CPP
def valid(s): n = len(s) if n == 1: return True for i in range(1,n): if abs(ord(s[i]) - ord(s[i-1])) == 1: return False return True def solve(): result = [] for _ in range(int(input())): s = sorted(input()) half1 = [] half2 = [] turn = 1 i = 0 while i < len(s): j = i while j < len(s) and s[j] == s[i]: j += 1 if j == i: j += 1 if turn == 1: half1 += s[i:j] turn = 2 else: half2 += s[i:j] turn = 1 i += (j - i) ans = "No answer" if not half2: if valid(half2): ans = ''.join(half1) elif valid(half1) and valid(half2): if abs(ord(half1[-1]) - ord(half2[0])) != 1: ans = ''.join(half1 + half2) elif abs(ord(half1[0]) - ord(half2[-1])) != 1: ans = ''.join(half2 + half1) result.append(ans) print ('\n'.join(result)) if __name__ == "__main__": solve()
1,800
PYTHON3
r=input;n=int(r()); l=lambda:map(int, r().split()) s = set([*l()][1:]).union([*l()][1:]) print(["Oh, my keyboard!","I become the guy."][len(s)==n])
800
PYTHON3
#include <bits/stdc++.h> using namespace std; struct point { point() {} point(point a, point b) : x(b.x - a.x), y(b.y - a.y) {} int x, y; }; int operator*(const point& a, const point& b) { return a.x * b.x + a.y * b.y; } int operator-(const point& a, const point& b) { return ((a.x - b.x) * (a.x - b.x)) + ((a.y - b.y) * (a.y - b.y)); } point p[10]; int r[2][10]; bool used[10]; bool check1(int s) { for (int i = 0, j = 1, k = 2; i < 4; i++) { if (point(p[r[s][j]], p[r[s][i]]) * point(p[r[s][j]], p[r[s][k]]) != 0) return false; j++; if (j == 4) j = 0; k++; if (k == 4) k = 0; } for (int i = 0, j = 1; i < 4; i++) { if ((p[r[s][i]] - p[r[s][j]]) == 0) return false; j++; if (j == 4) j = 0; } return true; } bool check2(int s) { if (!check1(s)) return false; for (int i = 1; i < 4; i++) if ((p[r[s][i - 1]] - p[r[s][i]]) != (p[r[s][0]] - p[r[s][3]])) return false; return true; } void rec(int c, int s) { if (c == 4) { c = 0; s++; } if (s == 2) { if (check2(0) && check1(1)) { cout << "YES"; for (int j = 0; j < 2; j++) { cout << endl; for (int i = 0; i < 4; i++) cout << r[j][i] + 1 << " "; } exit(0); } return; } for (int i = 0; i < 8; i++) if (!used[i]) { used[i] = true; r[s][c] = i; rec(c + 1, s); used[i] = false; } } int main() { for (int i = 0; i < 8; i++) cin >> p[i].x >> p[i].y; rec(0, 0); cout << "NO"; return 0; }
1,600
CPP
#include <bits/stdc++.h> using namespace std; int T, n; int solve() { int sum = 0, f = 0; cin >> n; for (int i = 0; i < n; i++) { cin >> f; sum += f; } int div = sum / n; if (div * n == sum) { cout << 0 << "\n"; } else if (div * n != sum) cout << 1 << "\n"; return 0; } int main() { ios::sync_with_stdio(0), cin.tie(0), cout.tie(0); cin >> T; while (T--) solve(); return 0; }
800
CPP
import sys n = int(sys.stdin.readline()) arr =list(map(int, sys.stdin.readline().split())) ans = [0] * n m = len(arr) for i in range(m - 1, -1, -1): if i == m - 1: ans[i] = arr[i] // 2 ans[n - 1 - i] = arr[i] - ans[i] else: if arr[i + 1] < arr[i]: ans[n - i - 1] = ans[n - i - 2] + abs(arr[i + 1] - arr[i]) ans[i] = arr[i] - ans[n - i - 1] else: ans[n - i - 1] = ans[n - i - 2] ans[i] = arr[i] - ans[n - i - 1] print(' '.join(map(str, ans)))
1,300
PYTHON3
N,S = map(int, input().split()) movable = S-N if movable < N: print("NO") else: print("YES") q, r = divmod(movable, N) array = [q+1]*(N-r) + [q+2]*r print(*array) print(1)
1,400
PYTHON3
#include <bits/stdc++.h> inline void in(int &MAGNUS) { scanf("%d", &MAGNUS); } inline void out(int MAGNUS) { printf("%d\n", MAGNUS); } inline void in(int &MAGNUS, int &CLAR) { scanf("%d%d", &MAGNUS, &CLAR); } inline void out(int MAGNUS, int CLAR) { printf("%d %d\n", MAGNUS, CLAR); } inline void inl(long long &LIV) { scanf("%lld", &LIV); } inline void inl(long long &LIV, long long &MART) { scanf("%lld%lld", &LIV, &MART); } inline void outl(long long LIV) { printf("%lld\n", LIV); } inline void outl(long long LIV, long long MART) { printf("%lld %lld\n", LIV, MART); } using namespace std; int main() { int N; in(N); double ans = 0.00; for (int i = 1; i <= N; i++) { double x, y; cin >> x >> y; ans += y; } ans /= N; printf("%.3lf\n", 5 + ans); return 0; }
2,200
CPP
s=list(input()) for i in range(len(s)): if(s[i].isupper()): s[i]=chr(ord(s[i])+32) i=0 c=len(s) while(i<c): if(s[i]=="a" or s[i]=="e" or s[i]=="i" or s[i]=="o" or s[i]=="u" or s[i]=="y"): del(s[i]) c-=1 i-=1 i+=1 i=0 c=2*len(s) while(i<c): s.insert(i,".") i+=2 q="" for i in s: q+=i print(q)
1,000
PYTHON3
import sys def minp(): return sys.stdin.readline().strip() def mint(): return int(minp()) def mints(): return map(int, minp().split()) def solve(): n = mint() b = [None]*n i = 0 for v in mints(): b[i] = (v, i) i += 1 b.sort() c = [0]*n # how many moves to sort all after i with same value + all below ans = int(1e9) s = None i = 0 while i < n: j = i + 1 v = b[i][0] while j < n and b[j][0] == v: j += 1 if s is None: for z in range(i, j): c[z] = j - z - 1 ans = n - j else: k = s while k < e and b[k][1] < b[i][1]: k += 1 for z in range(i, j - 1): c[z] = j - z - 1 + e if k == e: c[j - 1] = c[e - 1] else: c[j - 1] = s + e - k v = n - i - j for z in range(i, j): while k < e and b[k][1] < b[z][1]: k += 1 ans = min(ans, z + (e if k == s else c[k - 1]) + v) s, e, i = i, j, j print(ans) for i in range(mint()): solve()
2,100
PYTHON3
#include <bits/stdc++.h> using namespace std; const double pi = 2 * acos(0); bool solve(double m, double d, double h, double v, double e) { double r = d / 2.0; double vol = r * r * pi * h; double a = r * r * pi * e * m; return vol + a - m * v <= 0.0; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); double d, h, v, e; cin >> d >> h >> v >> e; double lo = 0.0, hi = 1e4 + 1; for (int i = 0; i < 30; i++) { double mid = lo + (hi - lo) / 2; if (solve(mid, d, h, v, e)) hi = mid; else lo = mid; } if (hi > 1e4) { cout << "NO" << '\n'; return 0; } cout << "YES" << '\n'; cout.precision(12); cout << fixed << hi << '\n'; return 0; }
1,100
CPP
import math n=int(input()) p=int(1) t=int(1) k=int(1) for i in range(2,10000): p+=i k+=p if k>n: print(t) exit(0) t+=1
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const double pi = 3.14159265358979323846264338327950288419716939937510582097494459; int dX[] = {0, 0, 1, -1, 0}; int dY[] = {1, -1, 0, 0, 0}; string alpha = "abcdefghijklmnopqrstuvwxyz"; const int MOD = 1000000007; const int N = 150; int n; double arr[N]; int main() { cin >> n; for (int i = 0; i < n; ++i) cin >> arr[i]; sort(arr, arr + n); reverse(arr, arr + n); double cur = 0, pre = 1, ans = 0; for (int i = 0; i < n; ++i) { double p = arr[i]; cur = cur * (1 - p) + pre * p; pre *= (1 - p); ans = max(cur, ans); } printf("%.12f", ans); return 0; }
1,800
CPP
#include <bits/stdc++.h> #pragma GCC optimize("Ofast") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma") #pragma GCC optimize("unroll-loops") using namespace std; const double eps = 1e-12; const double PI = acos(-1.0); const long long INF = 1e18; const long long MOD = 1e9 + 7; const long long nax = 5e5 + 5; long long int gcd(long long int a, long long int b) { if (a == 0) return b; return gcd(b % a, a); } bool isPowerOfTwo(long long int x) { return x && (!(x & (x - 1))); } void solve() { long long int i, n, ans, k, m, j; cin >> n; m = n / 36; k = n / 36; if (n % 36 != 0) m += 1; if ((m * 36 - n) == 1) { k += 1; } cout << k << " "; n -= k * 36; if (n < 0) cout << "0"; else { ans = n / 3; if (n % 3 == 2) ans += 1; cout << ans; } return; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); ; long long int t = 1, i; while (t--) solve(); return 0; }
1,400
CPP
from sys import stdin,stdout nsum = lambda x:(x*(x+1))>>1 n,x = map(int, stdin.readline().split()) d = list(map(int, stdin.readline().split())) presum_hugs = [nsum(d[0])] presum_days = [d[0]] for i in range(1,n): presum_hugs.append(presum_hugs[-1] + nsum(d[i])) presum_days.append(presum_days[-1] + d[i]) for i in range(n): presum_hugs.append(presum_hugs[-1] + nsum(d[i])) presum_days.append(presum_days[-1] + d[i]) ans=0 for start in range((n<<1)-1, n-1, -1): hi=start lo = hi-n+1 while lo+1<hi: mid = (lo+hi)>>1 if presum_days[start]-presum_days[mid-1] > x: lo = mid if presum_days[start]-presum_days[mid-1] == x: break else: hi = mid-1 if presum_days[start]-presum_days[hi-1]>=x: lo=hi temp = presum_hugs[start] - presum_hugs[lo-1] extra = (presum_days[start]-presum_days[lo-1])-x if extra>0: temp -= nsum(extra) ans=max(ans, temp) stdout.write(str(ans) + "\n")
1,900
PYTHON3
str = input() n = len(str) lst = [] for i in range(int(n/2)+1): lst.append(str[2*i]) lst.sort() print('+'.join(lst))
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const double pi = 2 * acos(0); int n, r, h; long long v[100050], aux[100050], ind[100050], bit[100050]; void update(int x, long long val) { while (x <= n) { bit[x] = max(bit[x], val); x += x & -x; } } long long query(int x) { long long ret = 0; while (x > 0) { ret = max(ret, bit[x]); x -= x & -x; } return ret; } int main(int argc, char const *argv[]) { scanf("%d", &n); for (int i = 0; i < n; ++i) { scanf("%d %d", &r, &h); v[i] = (long long)r * r * h; aux[i] = v[i]; } sort(aux, aux + n); for (int i = 0; i < n; ++i) ind[i] = lower_bound(aux, aux + n, v[i]) - aux + 1; for (int i = 0; i < n; ++i) update(ind[i], query(ind[i] - 1) + v[i]); printf("%.10lf\n", query(n) * pi); return 0; }
2,000
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n1, n2; cin >> n1 >> n2; int k1, k2; cin >> k1 >> k2; cout << ((n1 > n2) ? "First" : "Second") << endl; return 0; }
800
CPP
n = int(input()) m=n n+=1 while '8' not in str(n): n+=1 print(n-m)
1,100
PYTHON3
#include <bits/stdc++.h> using namespace std; int a[200009], pos[200009]; int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); int n; cin >> n; for (int i = 1; i <= n; i++) { cin >> a[i]; pos[a[i]] = i; } int l = 0, r = 0, cur = pos[n], val = n; l = cur - 1, r = cur + 1; bool flag = 0; while (val > 1) { if ((l > 0 && (val - a[l]) == 1)) { val--; l--; continue; } if ((r <= n && (val - a[r]) == 1)) { val--; r++; continue; } flag = 1; break; } if (flag) cout << "NO\n"; else cout << "YES\n"; }
1,000
CPP
n=int(input()) l=[] for i in range(0,n): s=input() k=s[0:2] o=s[3:5] l.append(k) l.append(o) c=0 h=[] d=[] q=["++"] for i in range(0,2*n): if(l[i]=="OO"): h=l[0:i] d=l[(i+1):(2*n)] q=h+q+d break else: c+=1 if(c==2*n): print("NO") else: print("YES") for i in range(0,n): print(q[2*i],end="|") print(q[(2*i)+1])
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const int maxn = 200100; int n, k; int a[maxn], f1[maxn], f2[maxn], l2[maxn]; bool full[maxn], visited[maxn]; vector<int> adj[maxn]; bool dfs(int x, int v) { visited[x] = true; if (a[x] >= v) full[x] = true; int fre = 0, ere = 0, b2[2] = {0, 0}, tmp = 0; for (int i = 0; i < adj[x].size(); i++) if (!visited[adj[x][i]]) { if (dfs(adj[x][i], v)) return true; if (!full[adj[x][i]]) { full[x] = false; if (tmp == 0) tmp = adj[x][i]; else tmp = -1; ere = max(ere, f1[adj[x][i]]); } else fre += f1[adj[x][i]]; if (l2[b2[0]] < l2[adj[x][i]]) { b2[1] = b2[0]; b2[0] = adj[x][i]; } else if (l2[b2[1]] < l2[adj[x][i]]) b2[1] = adj[x][i]; } if (a[x] >= v) { if (full[x] && fre == 0) { f1[x] = 1; f2[x] = 1; l2[x] = 0; } else { f1[x] = fre + ere + 1; if (!full[x]) { l2[x] = l2[b2[0]] + 1; l2[x] = max(l2[x], f1[x]); } f2[x] = l2[b2[0]] + l2[b2[1]] + fre + 1; if (tmp != -1) f2[x] = max(f2[x], fre + f2[tmp] + 1); } } if (f1[x] >= k || f2[x] >= k || l2[x] >= k) return true; else return false; } bool possible(int x) { for (int i = 1; i <= n; i++) { full[i] = false; visited[i] = false; f1[i] = 0; f2[i] = 0; l2[i] = 0; } return dfs(1, x); } int main() { scanf("%d %d", &n, &k); for (int i = 1; i <= n; i++) scanf("%d", &a[i]); for (int i = 1; i < n; i++) { int u, v; scanf("%d %d", &u, &v); adj[u].push_back(v); adj[v].push_back(u); } int l = 1, r = 1e6, mid; while (l <= r) { mid = (l + r) / 2; if (possible(mid)) l = mid + 1; else r = mid - 1; } while (mid > 0 && !possible(mid)) mid--; while (possible(mid + 1)) mid++; printf("%d", mid); return 0; }
2,600
CPP
#include <bits/stdc++.h> using namespace std; int last; bool illegal(int n, int tmp) { if (n < last) return true; if (n < 1000) return true; if (n > 2011) return true; int cnt = 0; if (n / 1000 != tmp / 1000) cnt++; if (n % 1000 / 100 != tmp % 1000 / 100) cnt++; if (n % 100 / 10 != tmp % 100 / 10) cnt++; if (n % 10 != tmp % 10) cnt++; if (cnt > 1) return true; return false; } int v[1200]; int main() { int n; scanf("%d", &n); last = 1000; int t; for (int i = 0; i < n; i++) { scanf("%d", &v[i]); } for (int i = 0; i < n; i++) { for (t = last; t <= 2011; t++) { if (!illegal(t, v[i])) { v[i] = t; last = t; break; } } if (t > 2011) { puts("No solution"); return 0; } } for (int i = 0; i < n; i++) { printf("%d\n", v[i]); } return 0; }
1,700
CPP
def isprime(n): return all(n % i for i in range(2, int(n ** .5) + 1)) n = int(input()) if n == 2: print(1) elif n & 1 == 0: print(2) elif isprime(n): print(1) elif isprime(n - 2): print(2) else: print(3)
1,600
PYTHON3
for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) ma = max(a) mi = min(a) sums = set() for i in range(n): s = a[i] for j in a[i + 1:]: s += j if mi <= s <= ma: sums.add(s) c = 0 for i in a: if i in sums: c += 1 print(c)
1,500
PYTHON3
n = int(input()) a = list(map(str, input().split())) def func(x, y): ln = len(y) s = '' for i in range(ln): s = s + x[i] + y[i] return int(s) num = 0 for i in range(n): # for j in range(n): num += func(a[i], a[i]) print((num * n) % 998244353)
1,500
PYTHON3
n = int(input()) s = list(map(int, input().split())) t = False #even for i in range(n): for j in range(i + 1, n): if s[i] > s[j]: t = not t m = int(input()) a = [] for h in range(m): l, r = map(int, input().split()) if ((r - l + 1) / 2) % 2 == 1 or ((r - l + 1) / 2) % 2 == 1.5: t = not t a.append(['even', 'odd'][t]) print('\n'.join(a))
1,800
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); vector<long long> v; long long x, sum = 0; for (long long i = 0; i < 3; i++) { cin >> x; v.push_back(x); } sort(v.begin(), v.end()); for (long long i = 0; i < 2; i++) { sum += (v[i + 1] - v[i]); } cout << sum; }
800
CPP
def pos(sa, k, l=0, r=None): if r is None: r = len(sa) m = (l + r) // 2 if l == r: return l elif k > sa[m]: return pos(sa, k, m + 1, r) elif k < sa[m]: return pos(sa, k, l, m) else: return m def val(q): inc = 0 slist = [] for i in q: if not slist: slist.append(i) else: p = pos(slist, i) inc += p slist.insert(p, i) return inc t = int(input()) for _ in range(t): n, m = [int(i) for i in input().split()] a = [int(i) for i in input().split()] sights = sorted(list(set(a))) bins = {i:[] for i in sights} for i in range(len(a)): bins[a[i]].append(i) total_inc = 0 row = [] for i in sights: b = bins[i] z = 0 while z < len(b): if len(row) + len(b) - z < m: row += b[z:][::-1] z = len(b) else: fz = z + m - len(row) addition = b[z:fz][::-1] row += addition total_inc += val(row) row = [] z = fz print(total_inc)
1,600
PYTHON3
k,b=list(map(int,input().split())) a=list(map(int,input().split())) c=0 d=1 for i in a: c+=((i-d)%k) d=i print(c)
1,000
PYTHON3
import sys def minp(): return sys.stdin.readline().strip() def mint(): return int(minp()) def mints(): return map(int,minp().split()) def main(): n,k = mints() a = [list(minp()) for i in range(3)] w = [[False]*(n+1) for i in range(3)] for j in range(3): if a[j][0] == 's': a[j][0] = '.' w[j][0] = True for i in range(n): for j in range(3): if w[j][i]: if i*3+1>=n or a[j][i*3+1] == '.': for z in range(max(j-1,0),min(j+2,3)): if (i*3+1>=n or a[z][i*3+1] == '.') and (i*3+2>=n or a[z][i*3+2] == '.') and (i*3+3>=n or a[z][i*3+3] == '.'): w[z][i+1] = True can = w[0][n] or w[1][n] or w[2][n] #print(w) if can: print("YES") else: print("NO") t = mint() for i in range(t): main()
1,700
PYTHON3
#include <bits/stdc++.h> using namespace std; vector<long long> vec[3005]; long long n, m; long long bribe(long long now) { long long ex = now - (long long)vec[1].size(); long long i, j, k, l, ret = 0; priority_queue<long long, vector<long long>, greater<long long> > pq; for (i = 2; i <= m; i++) { l = vec[i].size(); for (j = now - 1; j < l; j++) { ret += vec[i][j]; ex--; if (ex < 0) return 1e17; } for (j = 0; j < now - 1 && j < l; j++) { pq.push(vec[i][j]); } } while (ex && !pq.empty()) { ret += pq.top(); pq.pop(); ex--; } if (ex) return 1e17; return ret; } int main() { long long i, j, k, p; scanf("%lld %lld", &n, &m); for (i = 1; i <= n; i++) { scanf("%lld %lld", &k, &p); vec[k].push_back(p); } for (i = 2; i <= m; i++) { sort(vec[i].begin(), vec[i].end()); reverse(vec[i].begin(), vec[i].end()); } long long res, ans = 1e17; long long s = vec[1].size(); for (i = max(s, 1LL); i <= n; i++) { res = bribe(i); ans = min(ans, res); } printf("%lld\n", ans); return 0; }
1,700
CPP
n = int(input()) a = list(map(int, input().split())) q = int(input()) for i in range(q): x, y = map(int, input().split()) x -= 1 if x > 0: a[x - 1] += y - 1 if x < n - 1: a[x + 1] += a[x] - y a[x] = 0 for i in range(n): print(a[i])
800
PYTHON3
###### ### ####### ####### ## # ##### ### ##### # # # # # # # # # # # # # ### # # # # # # # # # # # # # ### ###### ######### # # # # # # ######### # ###### ######### # # # # # # ######### # # # # # # # # # # # #### # # # # # # # # # # ## # # # # # ###### # # ####### ####### # # ##### # # # # # from __future__ import print_function # for PyPy2 from collections import Counter, OrderedDict from itertools import permutations as perm from fractions import Fraction from collections import deque from sys import stdin from bisect import * from heapq import * from math import * g = lambda : stdin.readline().strip() gl = lambda : g().split() gil = lambda : [int(var) for var in gl()] gfl = lambda : [float(var) for var in gl()] gcl = lambda : list(g()) gbs = lambda : [int(var) for var in g()] mod = int(1e9)+7 inf = float("inf") n, m = gil() cat = [0] + gil() adj = [[] for _ in range(n+1)] for _ in range(n-1): x, y = gil() adj[x].append(y) adj[y].append(x) ans = 0 st = [(1, cat[1], cat[1])] vis = [0]*(n+1) while st: p, cunsec, maxi = st.pop() vis[p] = 1 if len(adj[p]) > 1 or p == 1: for c in adj[p]: if vis[c]:continue newCunsec = (cunsec+1)*cat[c] st.append((c, newCunsec, max(maxi, newCunsec))) elif maxi <= m: ans += 1 print(ans)
1,500
PYTHON3
#Problem Set L: Collaborated with Rudrnash Singh n_k = list(map(int, input().split())) if n_k[0] >= 1 and n_k[0] <= 1000: n = n_k[0] if n_k[1] >= 1 and n_k[1] <= 1000: k = n_k[1] def func1(n,k): for i in range(n): for j in range(k): val = (i+j+1)%n print(i+1, val+1) if n < (2*k+1): print("-1") else: print(n*k) func1(n,k)
1,400
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(0); long long a, b; cin >> a >> b; long long ans = 0; while (a > 0 && b > 0) { ans += (a / b); a %= b; if (a == 0) break; ans += (b / a); b %= a; } cout << ans << endl; return 0; }
1,600
CPP
for _ in range(int(input())): n,m = map(int,input().split()) ar = [int(i) for i in input().split()] if sum(ar)==m: print('YES') else: print('NO')
800
PYTHON3
#include <bits/stdc++.h> using namespace std; struct Vec { long long x, y; int index; Vec(long long x, long long y) : x(x), y(y) {} Vec operator+(const Vec &o) const { return Vec(x + o.x, y + o.y); } Vec operator-(const Vec &o) const { return Vec(x - o.x, y - o.y); } long long operator*(const Vec &o) const { return x * o.x + y * o.y; } long long operator%(const Vec &o) const { return x * o.y - y * o.x; } void println() { cout << "(" << x << ", " << y << ")\n"; } bool operator<(const Vec &o) const { if (x != o.x) return x < o.x; return y < o.y; } }; bool leftOf(Vec a, Vec b, Vec pivot) { return (a - pivot) % (b - pivot) < 0; } bool rightOf(Vec a, Vec b, Vec pivot) { return (a - pivot) % (b - pivot) > 0; } int getIndexOfLeftmost(vector<Vec> points, Vec last) { int best = 0; for (int i = 1; i < points.size(); i++) if (leftOf(points[i], points[best], last)) best = i; return best; } int getIndexOfRightmost(vector<Vec> points, Vec last) { int best = 0; for (int i = 1; i < points.size(); i++) if (rightOf(points[i], points[best], last)) best = i; return best; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n; cin >> n; vector<Vec> points; for (int i = 0; i < n; i++) { int x, y; cin >> x >> y; points.push_back(Vec(x, y)); points[i].index = i; } string targetMoves; cin >> targetMoves; vector<Vec> chosen; sort(points.begin(), points.end()); Vec pivot = points[0]; chosen.push_back(points[0]); points.erase(points.begin()); for (int i = 0; i < targetMoves.size(); i++) { int nextIndex; if (targetMoves[i] == 'L') { nextIndex = getIndexOfRightmost(points, pivot); } else { nextIndex = getIndexOfLeftmost(points, pivot); } chosen.push_back(points[nextIndex]); pivot = points[nextIndex]; points.erase(points.begin() + nextIndex); } chosen.push_back(points[0]); for (int i = 0; i < n; i++) { cout << chosen[i].index + 1 << " \n"[i == n - 1]; } return 0; }
2,600
CPP
n = int(input()) RGB, RBG, GRB, GBR, BRG, BGR = n, n, n, n, n, n s = input() for i in range(n): if i%3==0: if s[i]=="R": RGB -= 1 RBG -= 1 elif s[i]=="G": GRB -= 1 GBR -= 1 else: BRG -= 1 BGR -= 1 elif i%3==1: if s[i]=="R": GRB -= 1 BRG -= 1 elif s[i]=="G": RGB -= 1 BGR -= 1 else: RBG -= 1 GBR -= 1 else: if s[i]=="R": GBR -= 1 BGR -= 1 elif s[i]=="G": RBG -= 1 BRG -= 1 else: RGB -= 1 GRB -= 1 m = min(RBG, RGB, BRG, BGR, GRB, GBR) print(m) if m == RBG: print("RBG"*(n//3)+"RBG"[:n%3]) elif m == RGB: print("RGB"*(n//3)+"RGB"[:n%3]) elif m == BRG: print("BRG"*(n//3)+"BRG"[:n%3]) elif m == BGR: print("BGR"*(n//3)+"BGR"[:n%3]) elif m == GRB: print("GRB"*(n//3)+"GRB"[:n%3]) elif m == GBR: print("GBR"*(n//3)+"GBR"[:n%3])
1,300
PYTHON3
def check(n): arr = [0]*10 for i in n: arr[int(i)]+=1 if arr[4]+ arr[7] == 4 or arr[4]+arr[7] == 7: print("YES") else: print("NO") n = input() check(n)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; using ll = long long; void solve() { int n, ans = 0; scanf("%d", &n); vector<int> w(n); for (int i = 0; i < n; i++) scanf("%d", &w[i]); for (int s = 1; s < 2 * n + 1; s++) { vector<bool> b(n, false); int cnt = 0; for (int i = 0; i < n; i++) { if (b[i]) continue; for (int j = 0; j < n; j++) { if (i == j || b[j] || b[i]) continue; if (w[i] + w[j] == s) { b[i] = true; b[j] = true; cnt++; } } } if (ans < cnt) { ans = cnt; } } printf("%d\n", ans); return; } int main() { int t; scanf("%d", &t); while (t--) { solve(); } }
1,200
CPP
#include <bits/stdc++.h> using namespace std; int main() { long long n, k; cin >> n >> k; long long r = n / k; if (r % 2 == 0) cout << "NO"; else cout << "YES"; return 0; }
800
CPP
x = input().split(" ") count = 0 a = int(x[0]) b = int(x[1]) while a <= b: a *= 3 b *= 2 count += 1 print(count)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const long long mod = 1000000007; long long powmod(long long a, long long b) { long long res = 1; a %= mod; for (; b; b >>= 1) { if (b & 1) res = res * a % mod; a = a * a % mod; } return res; } const int N = 101000; int n, val[N], op[N], my[N], vis[N]; int main() { scanf("%d", &n); if (n % 2 == 1) return puts("-1"), 0; for (int i = n / 2; i < n; i++) val[i] = 1, op[op[i] = i - n / 2] = i; int x = 0; vis[x] = 1; while (1) { if (my[x] || vis[(2 * x + (val[x] ^ 1)) % n]) { x = (2 * x + val[x]) % n; if (x == 0) break; continue; } val[x] ^= 1; val[op[x]] ^= 1; my[x] = my[op[x]] = 1; int y = (2 * x + val[x]) % n; while (!vis[y]) { vis[y] = 1; y = (2 * y + val[y]) % n; } } x = 0; printf("0"); for (int i = 0; i < n; i++) { x = (x * 2 + val[x]) % n; printf(" %d", x); } puts(""); }
2,800
CPP
w = int(input()) if w > 2: if w % 2 == 0: ret = 'YES' else: ret = 'NO' else: ret = 'NO' print(ret)
800
PYTHON3
#include <bits/stdc++.h> int n; char c[89]; int cnt; int main() { scanf("%d%s", &n, &c); for (int i = 0; i < n; i++) if (c[i] == '0') { putchar(cnt + 48); cnt = 0; } else cnt++; putchar(cnt + 48); return 0; }
1,100
CPP
#include <bits/stdc++.h> using namespace std; int n; int w, A[200001]; int main() { scanf("%d %d\n", &n, &w); for (int i = 0; i < 2 * n; i++) { scanf("%d", &A[i]); } sort(A, A + 2 * n); double optimal = ((A[0]) < (A[n] / (double)2) ? (A[0]) : (A[n] / (double)2)) * (double)n; printf("%lf\n", ((optimal + (2.0 * optimal)) < ((double)w) ? (optimal + (2.0 * optimal)) : ((double)w))); }
1,500
CPP
for j in range(int(input())): n,k=tuple(map(int,input().split())) a=list(map(int,input().split())) b=list(map(int,input().split())) a.sort() b.sort() for i in range(k): if a[i]<b[-(i+1)]: a[i]=b[-(i+1)] else: break print(sum(a))
800
PYTHON3
x = int(input()) count=0 for i in range(0,x): inp1 = list(map(int,input().split())) if(inp1.count(1)>1): count= count+1 print(count)
800
PYTHON3
def main(): for _ in range(int(input())): x,y,a,b = map(int,input().split()) if (y-x) %(a+b) == 0: n = abs(y-x) //(a+b) print(n) else: print('-1') main()
800
PYTHON3
for _ in range(int(input())): n = int(input()) d1,d2 = {},{} l = [] for i in range(n): x,y = map(int, input().split()) if x in d1: d1[x]+=1 else: d1[x]=1 if y in d2: d2[y]+=1 else: d2[y]=1 l.append([x,y]) ans = n*(n-1)*(n-2)//6 for i in range(n): ans -= (d1[l[i][0]]-1)*(d2[l[i][1]]-1) print(ans)
1,700
PYTHON3
def calculaResultado(qtdBranco, qtdAdj, valor1, valor2): result1 = qtdBranco*valor1 + qtdAdj*valor2 result2 = qtdBranco*valor1 + qtdAdj*2*valor1 if(result1 <= result2): print(result1) else: print(result2) numeroTestes = int(input()) for count in range(0, numeroTestes): linhas, colunas, valor1, valor2 = [int(i) for i in input().split()] qtdBranco = 0 qtdAdj = 0 for linha in range(0, linhas): linhaInput = input() linhaInput = linhaInput.replace(' ','') indice = 0 while(indice < colunas): if linhaInput[indice] == '.': qtdBranco += 1 if indice+1 < colunas: if linhaInput[indice+1] == '.': qtdAdj += 1 qtdBranco -= 1 indice+=1 indice+=1 calculaResultado(qtdBranco, qtdAdj, valor1, valor2)
1,000
PYTHON3
#include <bits/stdc++.h> char s[5005], t[5005]; int a[5005][5005], i, j, ans; int main(void) { gets(s); gets(t); for (i = 0; s[i]; i++) for (j = 0; t[j]; j++) a[i + 1][j + 1] = (a[i + 1][j] + (t[j] == s[i]) * (a[i][j] + 1)) % 1000000007; for (i = 0; s[i]; i++) ans = (ans + a[i + 1][j]) % 1000000007; printf("%d\n", ans); }
1,700
CPP
def sum_of_all(n: int) -> int: if n % 2 == 0: return (n // 2) * (n + 1) else: return ((n + 1) // 2) * n def sum_of_powers(n: int) -> int: sum = 0 current_power = 1 while current_power <= n: sum += current_power current_power *= 2 return sum if __name__ == "__main__": t = int(input()) for i in range(t): n = int(input()) print(sum_of_all(n) - 2 * sum_of_powers(n))
900
PYTHON3
#include <bits/stdc++.h> using namespace std; const int mod = 1e9 + 7; const int N = 1e6 + 5; long long ans[N]; int a[66]; long long dp[66][1050]; long long dfs(int pos, int state, bool lead, bool limit, int k) { if (pos == -1) return state == 0 && !lead; if (!limit && !lead && dp[pos][state] != -1) return dp[pos][state]; int up = limit ? a[pos] : k - 1; long long ans = 0; for (int i = 0; i <= up; i++) { ans += dfs(pos - 1, lead && i == 0 ? state : state ^ (1 << i), lead && i == 0, limit && i == a[pos], k); } if (!limit && !lead) dp[pos][state] = ans; return ans; } long long solve(int k, long long x) { int pos = 0; while (x) { a[pos++] = x % k; x /= k; } return dfs(pos - 1, 0, true, true, k); } struct Node { long long le, ri; int id; Node() {} Node(long long L, long long R, int ID) { id = ID; le = L; ri = R; } }; vector<Node> b[15]; int main() { int T; cin >> T; int id = 0; while (T--) { id++; long long le, ri; int k; scanf("%d%lld%lld", &k, &le, &ri); b[k].push_back(Node(le, ri, id)); } for (int k = 2; k <= 10; k++) { memset(dp, -1, sizeof(dp)); for (int i = 0; i < (int)b[k].size(); i++) { ans[b[k][i].id] = solve(k, b[k][i].ri) - solve(k, b[k][i].le - 1); } } for (int i = 1; i <= id; i++) { printf("%lld\n", ans[i]); } }
2,200
CPP
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n, m; cin >> n >> m; long long a[n], i; for (i = 0; i < n; i++) cin >> a[i]; if (n > m) cout << 0 << endl; else { int ans = 1; for (i = 0; i < n; i++) for (int j = i + 1; j < n; j++) ans = (ans * abs(a[i] - a[j])) % m; cout << ans << endl; } }
1,600
CPP
#include <bits/stdc++.h> using namespace std; static const int maxn = 100000 + 10; inline int read() { int k = 0, f = 1, c = getchar(); while (c > '9' || c < '0') { if (c == '-') f = -1; c = getchar(); } while (c <= '9' && c >= '0') { k = k * 10 + c - '0'; c = getchar(); } return k * f; } static int root[maxn], tot; struct node { int l, r; int sum; } tree[maxn << 6]; void ins(int &u, int l, int r, int pos) { if (!u) u = ++tot; if (l == r) { ++tree[u].sum; return; } int mid = (l + r) / 2; if (pos <= mid) ins(tree[u].l, l, mid, pos); else ins(tree[u].r, mid + 1, r, pos); tree[u].sum = tree[tree[u].l].sum + tree[tree[u].r].sum; } int ask(int u, int l, int r, int s, int t) { if (!u || l > t || r < s) return 0; if (s <= l && r <= t) return tree[u].sum; int mid = (l + r) / 2; return ask(tree[u].l, l, mid, s, t) + ask(tree[u].r, mid + 1, r, s, t); } struct data { int x, r, f; inline void input() { x = read(), r = read(), f = read(); } } a[maxn]; inline bool cmp(int i, int j) { return a[i].r > a[j].r; } static int n, k, r[maxn]; int main() { n = read(), k = read(); for (int i = 1; i <= n; ++i) a[i].input(), r[i] = i; sort(r + 1, r + 1 + n, cmp); long long ans = 0; for (int u = 1; u <= n; ++u) { int i = r[u]; for (int j = max(a[i].f - k, 1); j <= min(a[i].f + k, 10000); ++j) ans += ask(root[j], 1, 1000000000, max(a[i].x - a[i].r, 1), min(a[i].x + a[i].r, 1000000000)); ins(root[a[i].f], 1, 1000000000, a[i].x); } printf("%I64d", ans); return 0; }
2,200
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n, m; int i; scanf("%d%d", &n, &m); i = 1; while (true) { if (m < i) { break; } m -= i; i++; if (i == n + 1) { i = 1; } } printf("%d", m); return 0; }
800
CPP
#include <bits/stdc++.h> using namespace std; int main() { int y, k, n, x, c = 0; vector<int> v; cin >> y >> k >> n; for (int x = k; x <= n; x += k) { if (x > y) v.push_back(x - y); } if (v.size() == 0) cout << "-1\n"; else { for (int i = 0; i < v.size(); i++) cout << v[i] << " "; } return 0; }
1,200
CPP
#include <bits/stdc++.h> using namespace std; struct Node { int cnt, sum; Node operator+(Node n) const { return {cnt + n.cnt, sum + n.sum}; } }; int N, M, K; vector<pair<int, int> > v[2][2], w; Node seg[33000]; bool vis[200201]; void Update(int idx, int val, int n, int l, int r) { if (r < idx || idx < l) return; if (l == r) { seg[n].cnt += 1 * val; seg[n].sum += r * val; return; } int mid = l + r >> 1; Update(idx, val, n << 1, l, mid); Update(idx, val, n << 1 | 1, mid + 1, r); seg[n].cnt = seg[n << 1].cnt + seg[n << 1 | 1].cnt; seg[n].sum = seg[n << 1].sum + seg[n << 1 | 1].sum; } Node Query(int L, int R, int n, int l, int r) { if (r < L || R < l) return {0, 0}; if (L <= l && r <= R) return seg[n]; int mid = l + r >> 1; return Query(L, R, n << 1, l, mid) + Query(L, R, n << 1 | 1, mid + 1, r); } int Kth(int k, int n, int l, int r) { if (l == r) return r; int mid = l + r >> 1; if (k <= seg[n << 1].cnt) return Kth(k, n << 1, l, mid); return Kth(k - seg[n << 1].cnt, n << 1 | 1, mid + 1, r); } int main() { scanf("%d %d %d", &N, &M, &K); for (int i = 1; i <= N; i++) { int t, a, b; scanf("%d %d %d", &t, &a, &b); v[a][b].push_back({t, i}); w.push_back({t, i}); Update(t, 1, 1, 0, 10000); } if (v[1][1].size() + v[1][0].size() < K || v[1][1].size() + v[0][1].size() < K) { printf("-1\n"); return 0; } for (int i = 0; i < 2; i++) for (int j = 0; j < 2; j++) sort(v[i][j].begin(), v[i][j].end()); sort(w.begin(), w.end()); int S11 = 0, S10 = 0, S01 = 0, j = 0, k = 0; for (int i = 0; i < min(K, (int)v[1][1].size()); i++) { S11 += v[1][1][i].first; Update(v[1][1][i].first, -1, 1, 0, 10000); } int res = 2100000000, idx = -1; for (int i = min(K, (int)v[1][1].size()); i >= 0; i--) { if (v[1][0].size() < K - i || v[0][1].size() < K - i) continue; if (i + K - i + K - i > M) continue; while (j < K - i) { S10 += v[1][0][j].first; Update(v[1][0][j].first, -1, 1, 0, 10000); j++; } while (k < K - i) { S01 += v[0][1][k].first; Update(v[0][1][k].first, -1, 1, 0, 10000); k++; } int cnt, pos, kcnt, add; cnt = M - (i + K - i + K - i); if (cnt > 0) { pos = Kth(cnt, 1, 0, 10000); assert(pos >= 1); kcnt = cnt - Query(0, pos - 1, 1, 0, 10000).cnt; add = Query(0, pos - 1, 1, 0, 10000).sum + kcnt * pos; } else pos = kcnt = add = 0; int val = S11 + S10 + S01 + add; if (res > val) { res = val; idx = i; } if (i) { S11 -= v[1][1][i - 1].first; Update(v[1][1][i - 1].first, 1, 1, 0, 10000); } } if (idx == -1) { printf("-1\n"); return 0; } printf("%d\n", res); vector<int> ans; for (int i = 0; i < idx; i++) { ans.push_back(v[1][1][i].second); vis[v[1][1][i].second] = true; } for (int i = 0; i < K - idx; i++) { ans.push_back(v[1][0][i].second); vis[v[1][0][i].second] = true; } for (int i = 0; i < K - idx; i++) { ans.push_back(v[0][1][i].second); vis[v[0][1][i].second] = true; } int cnt = M - (idx + K - idx + K - idx); for (int i = 0; i < w.size(); i++) { if (vis[w[i].second]) continue; if (cnt > 0) { ans.push_back(w[i].second); vis[w[i].second] = true; cnt--; } } for (int x : ans) printf("%d ", x); return 0; }
2,500
CPP
n=input() line=input().split() list0=[int(i) for i in line] list0.sort() list0=[str(i) for i in list0] print(' '.join(list0))
900
PYTHON3
def find_set(v): if (v == parent[v]): return v parent[v] = find_set(parent[v]) return parent[v] def union_sets(a,b): a=find_set(a) b=find_set(b) if (a!=b): if (size[a]<size[b]): a,b = b,a parent[b] = a size[a] += size[b] return True return False n = int(input()) parent = [0]*n size = [1]*n mustBreak=[] mustConnect=[] for i in range(n): parent[i] = i for i in range(n-1): line=input().split(" ") a = int(line[0])-1 b = int(line[1])-1 result= union_sets(a,b) if not result: mustBreak.append((a,b)) for i in range(n): if parent[i] == i: mustConnect.append(i) lenMustBreak = len(mustBreak) print(lenMustBreak) if (lenMustBreak != 0): for i in range(lenMustBreak): print(str(mustBreak[i][0]+1)+" "+str(mustBreak[i][1]+1)+" "+str(mustConnect[i]+1)+" "+str(mustConnect[i+1]+1))
1,900
PYTHON3
for _ in range(int(input())): s = input() l=[] f=0 c=0 for i in s: if f==0 and i=='1': f=1 c+=1 elif f==0 and i=='0': f,c=0,0 elif f==1 and i=='1': c+=1 elif f==1 and i=='0': l.append(c) c,f=0,0 if c>0: l.append(c) l.sort(reverse=True) s=0 for i in l[::2]: s+=i print(s)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = 200025; const int64_t INF = 1e16; const int MOD = 1000000007, K = 25; int64_t modpow(int64_t e, int64_t p, int64_t m = MOD) { int64_t r = 1; for (e %= m; p; p >>= 1, e = e * e % m) if (p & 1) r = r * e % m; return r; } signed main() { ios_base::sync_with_stdio(0), cin.tie(0); int n, M; cin >> n >> M; vector<int> v(n), ans; queue<int> q; for (int &x : v) cin >> x; int H = 0; for (int x : v) H = (H + modpow(K, x)) % MOD; for (int x : v) q.push(M - x); vector<int> cand = v; for (int &x : cand) x = (x + v[0]) % M; sort(cand.begin(), cand.end()); int nowh = 0; for (int x : v) nowh = (nowh + modpow(K, M - x)) % MOD; for (int x : cand) { while (q.size() && q.front() + x >= M) { int a = q.front(); q.pop(); nowh = (nowh - modpow(K, a) + MOD) % MOD; nowh = (nowh + modpow(K, a) * modpow(modpow(K, M), MOD - 2)) % MOD; } int h = nowh * modpow(K, x) % MOD; if (H == h) ans.emplace_back(x); } sort(ans.begin(), ans.end()); cout << ans.size() << '\n'; for (int x : ans) cout << x << ' '; cout << '\n'; }
2,400
CPP