solution
stringlengths
10
159k
difficulty
int64
0
3.5k
language
stringclasses
2 values
#include <bits/stdc++.h> using namespace std; int main() { long long xr, sm; cin >> xr >> sm; if (xr > sm || xr % 2 != sm % 2) { cout << -1; return 0; } if (xr == 0 && sm == 0) { cout << 0; return 0; } if (xr == 0) { cout << 2 << endl; cout << sm / 2 << " " << sm / 2 << endl; return 0; } if (sm == xr) { cout << 1 << endl; cout << sm; return 0; } long long am = (sm + xr) / 2; long long sc = sm - am; if (sc > 0 && (am ^ sc) == xr) { cout << 2 << endl << am << " " << sc; return 0; } cout << 3 << endl; cout << xr << " " << (sm - xr) / 2 << " " << (sm - xr) / 2; }
1,700
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n, flag; int a[100008]; while (~scanf("%d", &n)) { for (int i = 0; i < n; i++) { scanf("%d", &a[i]); } sort(a, a + n); flag = 0; for (int i = 0; i < n; i++) { if (a[i] % a[0] == 0) { flag = 1; } else { flag = 0; printf("-1\n"); break; } } if (flag == 1) { printf("%d\n", a[0]); } } return 0; }
1,000
CPP
test_cases = int(input()) for _ in range (test_cases): n = int(input()) first_sum = pow(2, n//2) - 2 + pow(2, n) second_sum = pow(2, n) - pow(2, n//2) print( abs(first_sum - second_sum))
800
PYTHON3
ans = 1 for i in range(2, min(map(int, input().split())) + 1): ans *= i print(ans)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int32_t main() { ios_base::sync_with_stdio(0); long long n, m; cin >> n >> m; vector<vector<long long>> colors(n); for (long long i = 0; i < (n); ++i) { long long s; cin >> s; colors[i].resize(s); for (long long j = 0; j < (s); ++j) { cin >> colors[i][j]; colors[i][j]--; } } vector<vector<long long>> graph(n); for (long long i = 0; i < (n - 1); ++i) { long long t1, t2; cin >> t1 >> t2; t1--; t2--; graph[t1].push_back(t2); graph[t2].push_back(t1); } vector<long long> cols(m); vector<bool> vis(n); function<void(long long)> dfs = [&](long long v) { vis[v] = true; long long idx = 1; long long s = colors[v].size(); vector<bool> taken(s + 1); for (long long col : colors[v]) { if (cols[col]) { if (cols[col] < taken.size()) { taken[cols[col]] = true; } } } for (long long col : colors[v]) { if (!cols[col]) { while (taken[idx]) { idx++; } cols[col] = idx; taken[idx] = 1; } } for (long long son : graph[v]) { if (!vis[son]) { dfs(son); } } }; dfs(0); long long res = 1; for (long long i = 0; i < (m); ++i) { cols[i] = max(cols[i], 1LL); res = max(cols[i], res); } cout << res << "\n"; for (long long i = 0; i < (m); ++i) { cout << cols[i] << " "; } return 0; }
2,200
CPP
# Link to problem : https://codeforces.com/problemset/problem/948/A # There is one case in which we cannot save the sheep which is SW # In above case sheep and wolf are adjacent to each other and we cannot place a dog in between them # But in all other case we can place a dog at '.' places r,c = map(int, input().split()) grid = [] for i in range(r): l = list(input()) grid.append(l) def check(i, j, grid): if i > 0: if grid[i][j] == 'S' and grid[i - 1][j] == 'W': return 'NO' if grid[i][j] == 'S' and grid[i - 1][j] == '.': grid[i - 1][j] = 'D' if i < len(grid) - 1: if grid[i][j] == 'S' and grid[i + 1][j] == 'W': return 'NO' if grid[i][j] == 'S' and grid[i + 1][j] == '.': grid[i + 1][j] = 'D' if j > 0: if grid[i][j] == 'S' and grid[i][j - 1] == 'W': return 'NO' if grid[i][j] == 'S' and grid[i][j - 1] == '.': grid[i][j - 1] = 'D' if j < len(grid[0]) - 1: if grid[i][j] == 'S' and grid[i][j + 1] == 'W': return 'NO' if grid[i][j] == 'S' and grid[i][j + 1] == '.': grid[i][j + 1] = 'D' return '' def main(): for i in range(len(grid)): for j in range(len(grid[0])): if check(i, j, grid) == 'NO': print('No') return print('Yes') for i in range(len(grid)): print(''.join(grid[i])) if __name__ == "__main__": main()
900
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int arr[100]; int n; cin >> n; int ans = 0; int ones = 0; for (int i = 0; i < n; i++) { int a; cin >> a; arr[i] = a; ones += a; } for (int i = 0; i < n; i++) { for (int j = i; j < n; j++) { int temp = 0; for (int k = 0; k < j - i + 1; k++) { temp += arr[k + i]; } temp = ones - 2 * temp + j - i + 1; if (temp > ans) { ans = temp; } } } cout << ans; }
1,200
CPP
import io nancy = int(input()) lima = list(map(int, input().split())) counter = 0 last = 0 for i in range(len(lima)-1, -1, -1): if(last == 0): counter += 1 lima[i] = max(lima[i], last-1) last = lima[i] print(counter)
1,200
PYTHON3
nx_str = input() list_str = input() nx_data = list(map(int, nx_str.split())) list_data = list(map(int, list_str.split())) x = nx_data[1] n = nx_data[0] num = 0 for i in range(n): if list_data[i] < x: num = num + 1 if x in list_data: result_num = x - num + 1 else: result_num = x - num print(result_num)
1,000
PYTHON3
for case in range(int(input())): n = int(input()) a = [int(x) for x in input().split()] new_a = [a[0]] for i in range(1, n-1): if (a[i] >= a[i-1] and a[i] > a[i+1]) or (a[i] <= a[i-1] and a[i] < a[i+1]): new_a.append(a[i]) new_a.append(a[-1]) print(len(new_a)) print(*new_a)
1,300
PYTHON3
t = int(input()) while t!=0: n,m,k = map(int,input().split()) list1 = list(map(int,input().split())) mini = pow(10,9)+7 u=0 list2 = list() k = min(k,m-1) for i in range(m-1,-1,-1): p = max(list1[i],list1[len(list1)-1-u]) list2.append(p) u+=1 temp = list() for i in range(k + 1): temp.append(min(list2[i:i + m - k])) print(max(temp)) t-=1
1,600
PYTHON3
def solve(n): ans = 0 temp = n while n != 0: bills = [100, 20, 10, 5, 1] for b in bills: if n >= b: n %= b ans += (temp - n) / b temp = n break return int(ans) n = int(input()) print(solve(n))
800
PYTHON3
n, k = map(int, input().split()) s = input().strip('.#') l = len(s) - 1 print('NO' if l % k or '#' in s[0:l:k] else 'YES')
800
PYTHON3
a = [int(i) for i in input().split()] s = input() r = 0 for c in s: r+=a[int(c)-1] print(r)
800
PYTHON3
import sys inp = sys.stdin.readline ans = "" for _ in range(int(inp())): a, b, n, s = map(int, inp().split()) a_needed = (s//n) if a >= a_needed: ans += ("YES" if b >= (s%n) else "NO")+"\n" else: ans += ("YES" if b >= (s - a*n) else "NO")+"\n" print(ans)
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = 2e5 + 9; int n, ans1 = -1, ans2, par[N]; pair<int, int> m, p[N], tree[N * 2]; vector<pair<int, int> > v[N]; set<pair<int, int> > s; pair<int, int> query(int l, int r) { pair<int, int> res; res.first = res.second = -1; r++; for (l += n, r += n; l < r; l >>= 1, r >>= 1) { if (l & 1) { if (tree[l].first > res.first) res = tree[l]; l++; } if (r & 1) { if (tree[--r].first > res.first) res = tree[r]; } } return res; } void make_tree() { for (int i = n - 1; i >= 1; i--) { pair<int, int> p1 = tree[i * 2], p2 = tree[i * 2 + 1]; if (p1.first > p2.first) tree[i] = p1; else tree[i] = p2; } } int main() { cin >> n; for (long long i = 0; i < n; i++) { scanf("%d%d", &p[i].first, &p[i].second); ; p[i].first--, p[i].second--; v[p[i].first].push_back(make_pair(p[i].second, i)); } for (long long i = 0; i < n; i++) { for (long long j = 0; j < v[i].size(); j++) s.insert(v[i][j]); pair<int, int> u = *s.begin(); s.erase(u); tree[i + n] = u; par[u.second] = i; } make_tree(); for (long long i = 0; i < n; i++) { m = query(p[i].first, par[i] - 1); if (m.first >= par[i]) ans1 = i, ans2 = m.second; } if (ans1 == -1) cout << "YES" << endl; else cout << "NO" << endl; for (long long i = 0; i < n; i++) cout << par[i] + 1 << " "; cout << endl; if (ans1 != -1) { swap(par[ans1], par[ans2]); for (long long i = 0; i < n; i++) cout << par[i] + 1 << " "; } }
2,600
CPP
a = input() a1 = int(a[0:2])*60 + int(a[3:]) b = input() b1 = int(b[0:2])*60 + int(b[3:]) mid = (a1 + b1) >> 1 a2 = mid / 60 b2 = mid % 60 if a2 < 10: str1 = '0' + str(int(a2)) + ':' else: str1 = str(int(a2)) + ':' if b2 < 10: str2 = '0' + str(int(b2)) else: str2 = str(int(b2)) str = str1 + str2 print(str)
1,000
PYTHON3
def test(l): l1=[] l2=[] for i in range(len(l)): if l[i]<0 and l[i] not in l2: l2.append(l[i]) elif l[i]>0 and l[i] not in l1: l1.append(l[i]) if len(l1)==0 or len(l2)==0: return False for x in l1: if (x*(-1)) in l2: return True for x in l2: if (x*(-1)) in l1: return True return False n,m=input().strip().split(' ') n,m=(int(n),int(m)) for t_0 in range(m): list1=list(map(int,input().strip().split(' '))) if test(list1[1:])==False: print("YES") exit() print("NO")
1,300
PYTHON3
#include <bits/stdc++.h> using namespace std; template <class T> T ABS(T x) { return x < 0 ? -x : x; } long long read() { long long s = 0, w = 1; char ch; while ((ch = getchar()) < '0' || ch > '9') if (ch == '-') w = -1; while (ch >= '0' && ch <= '9') s = (s << 3) + (s << 1) + (ch ^ 48), ch = getchar(); return s * w; } const long long maxn = 1e6 + 10; string S[maxn], w; char tmp[maxn]; long long v[maxn], dx[] = {0, 0, +1, -1}, dy[] = {+1, -1, 0, 0}, n, m; bool onl(long long x, long long y) { long long tot = 0; for (long long i = 0; i < 4; i++) { long long nx = x + dx[i], ny = y + dy[i]; if (nx && ny && nx <= n && ny <= m && S[nx][ny] != '#') { if (!v[(nx - 1) * m + ny]) ++tot; } } if (tot > 1) return 0; return 1; } void bfs(long long X, long long Y) { v[(X - 1) * m + Y] = 1; queue<pair<long long, long long> > Q; Q.push(make_pair(X, Y)); while (!Q.empty()) { long long x = Q.front().first, y = Q.front().second; Q.pop(); for (long long i = 0; i < 4; i++) { long long nx = x + dx[i], ny = y + dy[i]; if (nx && ny && nx <= n && ny <= m && !v[(nx - 1) * m + ny] && S[nx][ny] != '#' && onl(nx, ny)) v[(nx - 1) * m + ny] = 1, Q.push(make_pair(nx, ny)); } } } signed main() { long long csa = read(); while (csa--) { n = read(), m = read(); for (long long i = 1; i <= n; i++) scanf("%s", tmp), S[i] = " " + (w = tmp); for (long long i = 1; i <= n; i++) for (long long j = 1; j <= m; j++) if (S[i][j] == 'L') bfs(i, j); for (long long i = 1; i <= n; i++, cout << '\n') for (long long j = 1; j <= m; j++) if (S[i][j] == 'L') cout << 'L'; else if (v[(i - 1) * m + j]) cout << '+'; else cout << S[i][j]; for (long long i = 1; i <= n * m; i++) v[i] = 0; } return 0; }
2,000
CPP
n=int(input()) if (n%2) == 0: if n == 2: print("NO") else: print("YES") else: print("NO")
800
PYTHON3
t = int(input()) ans = [False for i in range(t)] for i in range(t): n = int(input()) a = [int(j) for j in input().split()] a1 = [[0, -1] for j in range(5001)] for j in range(n): a1[a[j]][0] += 1 if a1[a[j]][1] == -1: a1[a[j]][1] = j if a1[a[j]][0] > 1: if j - a1[a[j]][1] > 1: ans[i] = True break for i in ans: if i == True: print('YES') else: print('NO')
1,100
PYTHON3
#Problem E - Special Elements a = int(input()) for _ in range(a): b= int(input()) li = [0]*(b+1) li1= list(map(int, input().split())) for c in li1: li[c] += 1 ans = 0 for i in range(b): sum1= 0 for j in range(i,b): sum1 += li1[j] if i == j: continue elif sum1 <= b: ans += li[sum1] li[sum1] = 0 elif sum1 > b: break print(ans)
1,500
PYTHON3
#include <bits/stdc++.h> using namespace std; const long long INF = 1e9 + 10, MAX = 2e5 + 1e4, MOD = 1e9 + 7, MAXL = 25; void OUT(long double o, int x) { cout << fixed << setprecision(x) << o; return; } int a[MAX], cnt[20], cnt1[20], cnt2[20]; vector<pair<pair<int, int>, pair<int, int> > > v; pair<int, int> f(pair<pair<int, int>, pair<int, int> > x, pair<pair<int, int>, pair<int, int> > y) { int z = 0, w = 0; if (x.first.first == y.first.first) z++; else cnt1[x.first.first]++, cnt2[y.first.first]++; if (x.first.second == y.first.second) z++; else cnt1[x.first.second]++, cnt2[y.first.second]++; if (x.second.first == y.second.first) z++; else cnt1[x.second.first]++, cnt2[y.second.first]++; if (x.second.second == y.second.second) z++; else cnt1[x.second.second]++, cnt2[y.second.second]++; w += min(cnt1[x.first.first], cnt2[x.first.first]); cnt1[x.first.first] = 0; w += min(cnt1[x.first.second], cnt2[x.first.second]); cnt1[x.first.second] = 0; w += min(cnt1[x.second.first], cnt2[x.second.first]); cnt1[x.second.first] = 0; w += min(cnt1[x.second.second], cnt2[x.second.second]); cnt1[x.second.second] = 0; cnt2[y.first.first] = 0; cnt2[y.first.second] = 0; cnt2[y.second.first] = 0; cnt2[y.second.second] = 0; return {z, w}; } int main() { for (int i = 0; i <= 9; i++) { cnt[i]++; for (int j = 0; j <= 9; j++) { cnt[j]++; for (int k = 0; k <= 9; k++) { cnt[k]++; for (int h = 0; h <= 9; h++) { cnt[h]++; if ((cnt[i] == 1 && cnt[j] == 1) && (cnt[k] == 1 && cnt[h] == 1)) v.push_back({{i, j}, {k, h}}); cnt[h]--; } cnt[k]--; } cnt[j]--; } cnt[i]--; } while (v.size() > 1) { pair<int, int> ma = {0, 0}; for (int i = 0; i < min(int(v.size()), 4); i++) { int mi = INF; for (int j = 0; j <= 4; j++) { for (int k = 0; j + k <= 4; k++) { int x = 0; pair<int, int> p = {j, k}; for (pair<pair<int, int>, pair<int, int> > u : v) { if (f(v[i], u) != p) x++; } mi = min(x, mi); } } ma = max(ma, {mi, i}); } cout << v[ma.second].first.first << v[ma.second].first.second << v[ma.second].second.first << v[ma.second].second.second << endl; int x, y; cin >> x >> y; if (x == 4 && y == 0) return 0; vector<pair<pair<int, int>, pair<int, int> > > q; pair<int, int> p = {x, y}; for (pair<pair<int, int>, pair<int, int> > u : v) { if (f(v[ma.second], u) == p) q.push_back(u); } v.clear(); for (pair<pair<int, int>, pair<int, int> > u : q) v.push_back(u); } cout << v[0].first.first << v[0].first.second << v[0].second.first << v[0].second.second; return 0; }
1,600
CPP
#include <bits/stdc++.h> using namespace std; struct node { int v; int id; } e[(int)1e5 + 1000]; bool cmp(node a, node b) { return a.v < b.v; } int main() { int n; cin >> n; for (int i = 1; i <= n; i++) { scanf("%d", &e[i].v); e[i].id = i; } sort(e + 1, e + 1 + n, cmp); vector<int> V1, V2; long long sum1 = 0, sum2 = 0; for (int i = 1; i <= n; i++) { if (sum1 <= sum2) { V1.push_back(e[i].id); sum1 += e[i].v; } else { V2.push_back(e[i].id); sum2 += e[i].v; } } printf("%d\n", V1.size()); for (int i = 0; i <= V1.size() - 1; i++) { printf("%d%c", V1[i], i == V1.size() - 1 ? '\n' : ' '); } printf("%d\n", V2.size()); for (int i = 0; i <= V2.size() - 1; i++) { printf("%d%c", V2[i], i == V2.size() - 1 ? '\n' : ' '); } }
1,500
CPP
import math for ii in range(int(input())): n,m,k=map(int,input().split()) e=n//k if e>=m: print(m) else: x= math.ceil((m-e)/(k-1)) print(e-x)
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; typedef long long ll; //int:2*10**9 typedef long double ld; typedef pair<ll,ll> P; #define REP(i,n) for(ll i = 0; i<(ll)(n); i++) #define FOR(i,a,b) for(ll i=(a);i<=(b);i++) #define FORD(i,a,b) for(ll i=(a);i>=(b);i--) #define pb push_back #define MOD 1000000007 //998244353 #define PI 3.141592653 #define INF 100000000000000 //14 //cin.tie(0);cout.tie(0);ios::sync_with_stdio(false); void solve() { ll n; cin >> n; string s, t; cin >> s >> t; ll ocnt = 0; ll zcnt = 0; vector<ll> lines = {0}; ll last = 0; REP(i,n) { if (s[i]=='1') ocnt++; else zcnt++; if (ocnt==zcnt) { bool jud = true; ll checker = 0; FOR(j,last,i) { if (j==last) { if (s[last]==t[last]) checker=0; else checker=1; } else { if (checker && s[j]==t[j]) jud = false; else if (checker==0 && s[j]!=t[j]) jud = false; } } if (jud==false) { cout << "NO" << endl; return; } last = i+1; } } FOR(i,last,n-1) { if (s[i]!=t[i]) { cout << "NO" << endl; return; } } cout << "YES" << endl; return; } int main(){ ll t; cin >> t; REP(i,t) solve(); return 0; }
1,200
CPP
n=int(input()) u=[int(i) for i in input().split()] cnt=[0 for i in range(10)] ans=0 for i in range(n): cnt[u[i]-1]+=1 cm=max(cnt) c0=cnt.count(0) gen=cm-1 if (cnt.count(gen))==(10-c0-1): ans=i+1 else: temp=[] for x in cnt: if x!=0: temp.append(x) if len(set(temp))==2 and temp.count(1)==1: ans=i+1 elif len(set(temp))==1 and temp.count(1)>0: ans=i+1 print(ans)
1,500
PYTHON3
tc=int(input()) for _ in range(tc): a=input() setp=set() x=y=ans=nx=ny=0 for c in a: if c=='N': nx=x+1 if c=='S': nx=x-1 if c=='E': ny=y+1 if c=='W': ny=y-1 if (x,y,nx,ny) in setp or (nx,ny,x,y) in setp: ans+=1 else: ans+=5 setp.add((x,y,nx,ny)) x=nx y=ny print(ans)
1,400
PYTHON3
n=int(input()) l=list(map(int,input().split())) ma=max(l) mi=min(l) pma=l.index(ma) rma=pma+1 l2=l.copy() l2.reverse() pmi=l2.index(mi) rmi=len(l)-pmi s=pma+pmi if rmi<rma: s-=1 print(s)
800
PYTHON3
#include <bits/stdc++.h> #pragma comment(linker, "/STACK:128777216") using namespace std; bool d[2][200000]; char a[100010]; char b[100010]; struct Pos { int id; int pos; int t; void init(int id, int pos, int t) { this->id = id; this->pos = pos; this->t = t; d[id][pos] = 1; } } st[300000]; int main() { int n, k; scanf("%d %d", &n, &k); scanf("%s", a); scanf("%s", b); for (int i = 0; i < n; i++) { if (a[i] == 'X') { d[0][i] = 1; } if (b[i] == 'X') { d[1][i] = 1; } } st[0].init(0, 0, 0); for (int d = 0, u = 1; d < u; d++) { int id = st[d].id, pos = st[d].pos, t = st[d].t + 1; if (pos < st[d].t) continue; if (pos + k >= n) { printf("YES"); return 0; } if (pos > 0 && !::d[id][pos - 1]) { st[u++].init(id, pos - 1, t); } if (!::d[id][pos + 1]) { st[u++].init(id, pos + 1, t); } if (!::d[id ^ 1][pos + k]) { st[u++].init(id ^ 1, pos + k, t); } } printf("NO"); return 0; }
1,400
CPP
from collections import * n = int(input()) a = list(map(int,input().split())) o,e = 0,0 for i in a: if(i%2 == 0): e += 1 else: o += 1 a.sort(reverse = True) i = 0 ex,ox = min(o,e),min(o,e) if(o > ox): ox += 1 if(e > ex): ex += 1 while(i < n and (ox or ex)): if(ex and a[i]%2 == 0): a[i] = 0 ex -= 1 if(ox and a[i]%2 == 1): a[i] = 0 ox -= 1 i += 1 print(sum(a))
900
PYTHON3
import heapq n = int(input()) d = list(map(int,input().split())) pq = [-d[0]] heapq.heapify(pq) ans = 0 for i in range(1,n): temp = i - d[i] heapq.heappush(pq,temp) if heapq.nsmallest(1,pq)[0] < temp: ans += temp - heapq.nsmallest(1,pq)[0] heapq.heappushpop(pq,temp) print(ans)
2,300
PYTHON3
#include <bits/stdc++.h> using namespace std; const int maxn = 1e5 + 10, mod = 1e9 + 7; int a[maxn], b[maxn], c[maxn], vis[maxn], cur[maxn], x, d, n; int getNextX() { x = (1ll * x * 37 + 10007) % 1000000007; return x; } void initAB() { int i; for (i = 0; i < n; i = i + 1) { a[i] = i + 1; } for (i = 0; i < n; i = i + 1) { swap(a[i], a[getNextX() % (i + 1)]); } for (i = 0; i < n; i = i + 1) { if (i < d) b[i] = 1; else b[i] = 0; } for (i = 0; i < n; i = i + 1) { swap(b[i], b[getNextX() % (i + 1)]); } } struct node { int v, id; node(int x, int y) { v = x, id = y; } bool operator<(const node& t) const { return v < t.v; } }; priority_queue<node> q; int main() { scanf("%d%d%d", &n, &d, &x); initAB(); int cnt = 0; for (int i = 0; i < n; i++) if (b[i]) cur[cnt++] = i; for (int i = 0; i < n; i++) q.push(node(a[i], i)); for (int i = 0; i < min(70, n); i++) { node e = q.top(); q.pop(); for (int j = 0; j < cnt; j++) if (e.id + cur[j] < n && !vis[e.id + cur[j]]) { vis[e.id + cur[j]] = 1; c[e.id + cur[j]] = e.v; } } for (int i = 0; i < n; i++) if (!vis[i]) { for (int j = 0; j < cnt && cur[j] <= i; j++) c[i] = max(c[i], a[i - cur[j]]); } for (int i = 0; i < n; i++) printf("%d\n", c[i]); }
2,300
CPP
t = int(input()) for i in range(t): n = int(input()) A = sorted(list(map(int, input().split()))) for i in range(n//2): print(A[i+1],A[0])
1,000
PYTHON3
n = int(input()) a = list(map(int, input().split())) lastTime = dict() rooms = set(a) for i in range(n): lastTime[a[i]] = i m = rooms.pop() for room in rooms: if lastTime[room] < lastTime[m]: m = room print(m)
1,000
PYTHON3
def findIndex(num, li, lo, hi): while lo<hi: mid = (lo + hi)>>1 if num < li[mid]: hi = mid else : lo = mid + 1 return hi # li = [1,2,3,5,6,7,8,9] # num = 10 # print(findIndex(num,li, 0, len(li)-1)) n = int(input()) prices = sorted(map(int, input().split())) # print(prices) q = int(input()) for _ in range(q): money = int(input()) options = findIndex(money, prices, 0, len(prices)) print(options)
1,100
PYTHON3
#include <bits/stdc++.h> using namespace std; int con[1048578], lg[1048578], f[1048578]; long long a[1048578], sum[1048578]; bool check(int s) { for (int t = (s - 1) & s; (t << 1) >= s && t; t = (t - 1) & s) { long long tmp = abs(sum[t] - sum[s ^ t]); if (tmp < con[s] && ((con[s] - tmp) & 1)) return 1; } return 0; } int main() { int n, i, s, t, all; scanf("%d", &n); for (i = 0; i < n; i++) { scanf("%lld", &a[i]); if (a[i] == 0) i--, n--; } all = (1 << n) - 1; lg[0] = -1; for (i = 1; i <= all; i++) { con[i] = con[i >> 1] + (i & 1); lg[i] = lg[i >> 1] + 1; } for (i = 1; i <= all; i++) sum[i] = sum[i - (i & -i)] + a[lg[i & -i]]; for (s = 1; s <= all; s++) if (!f[s] && check(s)) { int tmp = all ^ s; f[s] = 1; for (t = tmp; t; t = (t - 1) & tmp) f[s | t] = max(f[s | t], f[t] + 1); } printf("%d", n - f[all]); }
3,100
CPP
#include <bits/stdc++.h> using namespace std; const int N = 5010, M = 50010, lpw = 1e9 + 7; inline int max(int x, int y) { return x > y ? x : y; } inline int min(int x, int y) { return x < y ? x : y; } inline void swap(int &x, int &y) { x ^= y ^= x ^= y; } int n, m, ans, f[N][N]; char s[N], t[N]; int main() { scanf("%s%s", s + 1, t + 1); n = strlen(s + 1); m = strlen(t + 1); for (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) { f[i][j] = f[i][j - 1]; if (s[i] == t[j]) f[i][j] = (f[i][j] + f[i - 1][j - 1] + 1) % lpw; } for (int i = 1; i <= n; i++) ans = (ans + f[i][m]) % lpw; printf("%d\n", ans); return 0; }
1,700
CPP
#include <bits/stdc++.h> using namespace std; string S; int l, r, ssiz, chuluk, pos; int chk[26]; int main(void) { cin >> S; ssiz = S.size(); for (; l < ssiz && !chuluk;) { while (r - l + 1 <= 26 && r < ssiz) { if (S[r] == '?') pos++; else chk[S[r] - 65]++; r++; } if (r - l + 1 <= 26) break; vector<char> isnt; int cont = 0; for (int i = 0; i < 26 && !cont; i++) { if (chk[i] > 1) { cont = 1; } if (!chk[i]) isnt.push_back(i + 65); } if (!cont) { if (isnt.size() > pos) cont = 1; else { for (int i = l; i < r; i++) if (S[i] == '?') S[i] = isnt[--pos]; for (int i = 0; i < ssiz; i++) { if (S[i] == '?') printf("A"); else printf("%c", S[i]); } chuluk = 1; } } if (cont) { S[l] == '?' ? pos-- : chk[S[l] - 65]--; l++; continue; } } if (!chuluk) printf("-1"); }
1,300
CPP
#include <bits/stdc++.h> using namespace std; const int N = 1e6 + 5; priority_queue<int> q[N]; int fa[N]; int n; void init() { for (int i = 0; i <= n; i++) { fa[i] = i; while (!q[i].empty()) q[i].pop(); } } int find(int x) { if (fa[x] != x) fa[x] = find(fa[x]); return fa[x]; } void merge(int a, int b) { a = find(a); b = find(b); if (a != b) fa[a] = fa[b]; } int tar[N]; int main() { int m; while (scanf("%d%d", &n, &m) == 2) { init(); memset(tar, 0, sizeof(tar)); for (int i = 1; i <= n; i++) scanf("%d", tar + i); for (int i = 0; i < m; i++) { int u, v; scanf("%d%d", &u, &v); merge(u, v); } for (int i = 1; i <= n; i++) q[find(i)].push(tar[i]); for (int i = 1; i <= n; i++) { int temp = q[find(i)].top(); q[find(i)].pop(); printf("%d", temp); i == n ? printf("\n") : printf(" "); } } return 0; }
1,700
CPP
#include <bits/stdc++.h> using namespace std; void solve() { int t, n, m; cin >> t; for (int i = 0; i < t; i++) { cin >> n >> m; if (n == 1) cout << 0 << '\n'; else if (n == 2) cout << m << '\n'; else cout << 1LL * m * 2 << '\n'; } } int main() { ios::sync_with_stdio(false), cin.tie(0), cout.tie(0); solve(); return 0; }
800
CPP
#include <bits/stdc++.h> using namespace std; int dx[] = {1, 1, 0, -1, -1, -1, 0, 1}; int dy[] = {0, 1, 1, 1, 0, -1, -1, -1}; template <typename T> void printV(vector<T> v) { for (int i = 0; i < v.size(); i++) { cout << v[i] << " "; } cout << endl; } int main() { ios_base::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); int t; cin >> t; while (t--) { int n; cin >> n; int arr[26]{}; int x = n; while (n--) { string s; cin >> s; for (int i = 0; i < s.length(); i++) { arr[s[i] - 'a']++; } } int isPossible = 1; for (int i = 0; i < 26; i++) { if ((arr[i] % x) != 0) { isPossible = 0; break; } } if (isPossible) { cout << "YES" << endl; } else { cout << "NO" << endl; } } return 0; }
800
CPP
#include <bits/stdc++.h> using namespace std; int n, d = 0; pair<int, int> a[110]; void nhap() { cin >> n; for (int i = 1; i <= n; i++) cin >> a[i].first >> a[i].second; } int main() { nhap(); for (int i = 1; i <= n; i++) if (a[i].second - a[i].first >= 2) d++; cout << d; return 0; }
800
CPP
import math t = int(input()) for _ in range(t): n = int(input()) print(math.floor(n/2)+1)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int a[111111], n; int gcd(int a, int b) { if (b == 0) return a; return gcd(b, a % b); } int main() { cin >> n; scanf("%d", &a[1]); int x = a[1]; for (int i = 2; i <= n; i++) { scanf("%d", &a[i]); x = gcd(x, a[i]); } if (x > 1) { cout << "YES\n" << "0" << endl; return 0; } int sum = 0; for (int i = 1; i <= n; i++) { if (a[i] % 2 == 1 && a[i + 1] % 2 == 1) { int t1 = a[i] - a[i + 1]; int t2 = a[i] + a[i + 1]; a[i] = t1; a[i + 1] = t2; sum += 1; } } for (int i = 1; i <= n; i++) if (a[i] % 2 == 1) { if (i == 1) { int t1 = -2 * a[i + 1]; int t2 = 2 * a[i]; a[i] = t1; a[i + 1] = t2; sum += 2; } else { int t1 = -2 * a[i]; int t2 = 2 * a[i - 1]; a[i - 1] = t1; a[i] = t2; sum += 2; } } cout << "YES\n" << sum << endl; return 0; }
1,700
CPP
#include <bits/stdc++.h> using namespace std; template <class T> void re(T& x) { cin >> x; } template <class T1, class T2> void re(pair<T1, T2>& x) { re(x.first); re(x.second); } template <class T> void re(vector<T>& x) { for (long i = 0; i < x.size(); i++) { re(x[i]); } } template <class T> void re(deque<T>& x) { for (long i = 0; i < x.size(); i++) { re(x[i]); } } template <class T1, class T2> pair<T1, T2> mp(T1& x, T2& z) { return make_pair(x, z); } template <class T> T cross(complex<T> x, complex<T> z) { return (conj(x) * z).imag(); } template <class T> T dot(complex<T> x, complex<T> z) { return (conj(x) * z).real(); } vector<long long> x, z; long long right1(long l, long r, long long v) { if (x[l] > v) { return -1; } if (l == r) { return x[l]; } long long z = r - l; while (z & (z - 1)) { z = z & (z - 1); } while (z) { if (l + z <= r && x[l + z] <= v) { l += z; } z /= 2; } return x[l]; } long long right2(long l, long r, long long v) { if (z[l] > v) { return -1; } if (l == r) { return z[l]; } long long x = r - l; while (x & (x - 1)) { x = x & (x - 1); } while (x) { if (l + x <= r && z[l + x] <= v) { l += x; } x /= 2; } return z[l]; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long a, b, c, s, l, r, ans = 1e18; cin >> a >> b; c = a + b; s = sqrt(a); for (long long i = 1; i <= s; i++) { if (a % i == 0) { x.push_back(i); } } s = sqrt(b); for (long long i = 1; i <= s; i++) { if (b % i == 0) { z.push_back(i); } } s = sqrt(c); for (long long i = 1; i <= s; i++) { if (c % i == 0) { l = right1(0, x.size() - 1, i); r = right2(0, z.size() - 1, i); if (l != -1 && min(l, a / l) <= min(i, c / i) && max(l, a / l) <= max(i, c / i)) { ans = min(ans, (i * 2) + ((c / i) * 2)); } if (r != -1 && min(r, b / r) <= min(i, c / i) && max(r, b / r) <= max(i, c / i)) { ans = min(ans, (i * 2) + ((c / i) * 2)); } } } cout << ans << endl; return 0; }
2,000
CPP
s=input() w="hello" index=0 flag=0 for i in range(len(s)): if (s[i]==w[index]): index+=1 if index==5: flag=1 break if flag==1: print("YES") else: print("NO")
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios_base ::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long n, j, i, k, a[311111]; cin >> n; for (i = 0; i < n; i++) cin >> a[i]; sort(a, a + n); i = 0; j = n - 1; long long sum = 0, cnt = 0; while (i < j) { k = a[i++] + a[j--]; sum += (k * k); } cout << sum; }
900
CPP
#include <bits/stdc++.h> using namespace std; const int64_t mod = 1e9 + 7; vector<int64_t> keys; vector<vector<int64_t>> g; map<int64_t, vector<pair<int64_t, int64_t>>> store; vector<int64_t> pow2((int64_t)5e5 + 1); void dfs(int64_t v, map<int64_t, bool> &visited) { visited[v] = true; for (auto el : g[v]) { if (!visited.count(el)) { dfs(el, visited); } } } signed main() { pow2[0] = 1; for (int64_t i = 1; i < 5e5 + 1; i++) { pow2[i] = pow2[i - 1] * 2 % mod; } ios::sync_with_stdio(false); int64_t n, m; int64_t k; cin >> n >> m; cin >> k; keys.resize(n); g.resize(n); for (auto &el : keys) { cin >> el; } for (int64_t i = 0; i < m; ++i) { int64_t a, b; cin >> a >> b; a--, b--; store[(keys[a] ^ keys[b])].push_back({a, b}); } int64_t ans = (pow2[k] - store.size()) * pow2[n] % mod; for (auto forbiddenKey : store) { set<int64_t> vertices; for (auto vertice : forbiddenKey.second) { vertices.insert(vertice.first); vertices.insert(vertice.second); g[vertice.first].push_back(vertice.second); g[vertice.second].push_back(vertice.first); } int64_t countCC = 0; map<int64_t, bool> visited; for (auto vertice : vertices) { if (!visited.count(vertice)) { dfs(vertice, visited); countCC++; } } ans += pow2[n - vertices.size() + countCC]; ans %= mod; for (auto vertice : vertices) { g[vertice].clear(); } } cout << ans; return 0; }
2,200
CPP
#include <bits/stdc++.h> long long read() { long long x = 0, f = 1; char c = getchar(); while (c < '0' || c > '9') { if (c == '-') f = -1; c = getchar(); } while (c >= '0' && c <= '9') { x = x * 10 + c - '0'; c = getchar(); } return x * f; } using namespace std; const long long maxn = 1e5 + 7; const double eps = 1e-10; const long long mod = 1e9 + 7; long long n; long long totA = 0, totB = 0; long long casA[maxn * 2], casB[maxn * 2]; long long tot = 0; struct Node { long long set, score; }; Node node[maxn]; bool cmp(Node a, Node b) { if (a.set < b.set) return 1; if (a.set == b.set && a.score < b.score) return 1; return 0; } int32_t main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); ; cin >> n; for (long long i = 1; i < 2 * maxn; i++) casA[i] = casB[i] = 9223372036854775807; bool flagA = 0, flagB = 0; for (long long i = 1; i <= n; i++) { long long x; cin >> x; if (x == 1) casA[++totA] = i; else casB[++totB] = i; if (i == n) { if (x == 1) flagA = 1; else flagB = 1; } } for (long long i = n; i >= 1; i--) { long long winA = 0, winB = 0, tarA = 0, tarB = 0; long long now = 1; bool flag = 1; while (now <= n) { if (casA[tarA + i] == 9223372036854775807 && casB[tarB + i] == 9223372036854775807) { flag = 0; break; } if (casA[tarA + i] < casB[tarB + i]) { winA++; tarA += i; tarB = casA[tarA] - tarA; now = casA[tarA] + 1; } else { winB++; tarB += i; tarA = casB[tarB] - tarB; now = casB[tarB] + 1; } } if (winA == winB) flag = 0; if (winA > winB && flagB) flag = 0; if (winA < winB && flagA) flag = 0; if (flag) { node[++tot].set = max(winA, winB); node[tot].score = i; } } sort(node, node + tot, cmp); cout << tot << "\n"; if (tot) { for (long long i = 1; i <= tot; i++) cout << node[i].set << ' ' << node[i].score << "\n"; } }
1,900
CPP
#include <bits/stdc++.h> using namespace std; int main() { long long int n, m, hno = 1, time = 0; cin >> n >> m; for (long long int i = 0; i < m; i++) { long long int inp; cin >> inp; if (inp < hno) { time += (n + 1 - hno) + (inp - 1); } else time += (inp - hno); hno = inp; } cout << time; return 0; }
1,000
CPP
n,m,a=map(int,input().split(' ')) x=n//a y=m//a p=f=g=0 if n%a!=0: p=1 g=y if m%a!=0: if p!=0: f=x+1 else: f=x k=x*y+g+f print(k)
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = (int)1e5 + 17; const int MX = (int)1e6 + 17; const int MOD = (int)1e9 + 7; const long long oo = LLONG_MAX; const int INF = INT_MAX; const long double Pi = 3.14159265358979323846264338327950288419716939937510; const int di[4] = {-1, 0, 1, 0}; const int dj[4] = {0, 1, 0, -1}; inline long long IN() { long long x = 0, ch = getchar(), f = 1; while (!isdigit(ch) && (ch != '-') && (ch != EOF)) ch = getchar(); if (ch == '-') { f = -1; ch = getchar(); } while (isdigit(ch)) { x = (x << 1) + (x << 3) + ch - '0'; ch = getchar(); } return x * f; } inline void OUT(long long x) { if (x < 0) putchar('-'), x = -x; if (x >= 10) OUT(x / 10), putchar(x % 10 + '0'); else putchar(x + '0'); } void IOI2017() { freopen( "partition" ".in", "r", stdin); freopen( "partition" ".out", "w", stdout); } string s; int dp2[N], dp3[N]; set<string> ans; int main() { cin >> s; dp2[(int)s.size()] = dp3[(int)s.size()] = 1; for (int i = (int)s.size() - 2; i >= 5; i--) { if (dp2[i + 2] && s.substr(i, 2) != s.substr(i + 2, 2) || dp3[i + 2]) dp2[i] = 1, ans.insert(s.substr(i, 2)); if (dp3[i + 3] && s.substr(i, 3) != s.substr(i + 3, 3) || dp2[i + 3]) dp3[i] = 1, ans.insert(s.substr(i, 3)); } cout << (int)ans.size() << endl; for (auto i : ans) cout << i << endl; return 0; }
1,800
CPP
#include <bits/stdc++.h> using namespace std; const int MAXN = 1005, MAXD = 1e4 + 10; int n, dp[MAXN][MAXD]; long long sum[MAXN][MAXD]; vector<long long> d, p; long long k, a[MAXN]; int prv[MAXN][MAXD]; long long GCD(long long a, long long b) { return !a ? b : GCD(b % a, a); } int getind(long long val) { return lower_bound(d.begin(), d.end(), val) - d.begin(); } int main() { cin >> n >> k; if (k == 1) { int ind = 0; for (int i = 0; i < n; i++) { cin >> a[i]; if (a[i] < a[ind]) ind = i; } cout << 1 << '\n' << ind + 1; return 0; } for (long long i = 1; i * i <= k; i++) { if (k % i == 0) { d.push_back(i); if (k / i != i) d.push_back(k / i); } } long long tmp = k; for (long long i = 2; i * i <= tmp; i++) { if (tmp % i == 0) p.push_back(i); while (tmp % i == 0) tmp /= i; } if (tmp != 1) p.push_back(tmp); sort(d.begin(), d.end()); fill_n(dp[0], MAXD, 1e9); dp[0][0] = 0; for (int i = 1; i <= n; i++) cin >> a[i]; for (int i = 1; i <= n; i++) { long long g = GCD(a[i], k); for (int j = 0; j < d.size(); j++) dp[i][j] = dp[i - 1][j], sum[i][j] = sum[i - 1][j]; for (int j = 0; j < d.size(); j++) { int t = getind(GCD(k / g, d[j]) * g); if (dp[i][t] > dp[i - 1][j] + 1) prv[i][t] = j + 1, dp[i][t] = dp[i - 1][j] + 1, sum[i][t] = sum[i - 1][j] + a[i]; if (dp[i][t] == dp[i - 1][j] + 1 && sum[i - 1][j] + a[i] < sum[i][t]) prv[i][t] = j + 1, sum[i][t] = sum[i - 1][j] + a[i]; } } if (dp[n][d.size() - 1] == 1e9) cout << -1; else { cout << dp[n][d.size() - 1] << '\n'; int t = d.size() - 1, lv = n; while (lv != 0) { if (prv[lv][t] > 0) cout << lv << ' ', t = prv[lv][t] - 1; lv--; } } }
2,600
CPP
n=int(input()) b=input() a=[] p=[] for i in range(n): a.append(b[i]) c=0 h='I' for j in range(n): if j+1==n: if a[j]==h: c+=1 if a[j-1]!='R': a[j]='R' elif a[j-1]!='G': a[j]='G' else: a[j]='B' elif a[j]==h: c+=1 if a[j-1]!='R' and a[j+1]!='R': a[j]='R' elif a[j-1]!='G' and a[j+1]!='G': a[j]='G' else: a[j]='B' h=a[j] print(c) for k in range(n): print(a[k],end='') #c=1 #for j in range(n-1): # if b[j]==b[j+1]: # c+=1 # else: # p.append(c) # c=1 #p.append(c) #sump=0 #for k in range(len(p)): # sump+=p[k]//2
1,400
PYTHON3
def exec(): x=input() if (len(x)>10): print(x[0]+str((len(x)-2))+x[-1]) else: print(x) if __name__ == "__main__": times=int(input()) for i in range(times): exec()
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const long long N = 2 * 1e5 + 100; long long n, m, k, w, a[N], d[N], p[N], fa[N], vi[N]; long long tot, first[N], nxt[N * 2], point[N * 2], len[N * 2]; priority_queue<pair<long long, long long>, vector<pair<long long, long long> >, greater<pair<long long, long long> > > q; struct node { long long u, v, w; } sh[N]; bool cmp(node a, node b) { return a.w < b.w; } long long find(long long x) { return (x == fa[x]) ? fa[x] : fa[x] = find(fa[x]); } inline long long read() { long long f = 1, x = 0; char s = getchar(); while (s < '0' || s > '9') { if (s == '-') f = -1; s = getchar(); } while (s >= '0' && s <= '9') { x = x * 10 + s - '0'; s = getchar(); } return x * f; } inline void add_edge(long long x, long long y, long long z) { nxt[++tot] = first[x]; first[x] = tot; point[tot] = y; len[tot] = z; } inline bool merge(long long a, long long b) { long long fax = find(a), fay = find(b); if (fax == fay) return 0; fa[fax] = fay; return 1; } signed main() { tot = -1; memset(first, -1, sizeof(first)); n = read(); m = read(); for (long long i = 1; i <= m; i++) { long long u = read(), v = read(), w = read(); add_edge(u, v, w); add_edge(v, u, w); } k = read(); for (long long i = 1; i <= k; i++) a[i] = read(); for (long long i = 1; i <= n; i++) d[i] = 1e18; for (long long i = 1; i <= k; i++) p[a[i]] = a[i], d[a[i]] = 0, q.push(make_pair(0, a[i])); while (!q.empty()) { long long x = q.top().second; q.pop(); if (vi[x]) continue; vi[x] = 1; for (long long i = first[x]; i != -1; i = nxt[i]) { long long u = point[i]; if (d[u] > d[x] + len[i]) { d[u] = d[x] + len[i]; p[u] = p[x]; q.push(make_pair(d[u], u)); } } } for (long long i = 0; i <= tot; i += 2) { long long u = point[i], v = point[i ^ 1]; if (p[u] == p[v]) continue; sh[++w] = (node){p[u], p[v], d[u] + d[v] + len[i]}; } sort(sh + 1, sh + 1 + w, cmp); for (long long i = 1; i <= n; i++) fa[i] = i; long long ans = d[1]; for (long long i = 1; i <= w; i++) if (merge(sh[i].u, sh[i].v)) ans += sh[i].w; printf("%lld\n", ans); }
2,600
CPP
w, h = (int(i) for i in input().split()) g = 4 for i in range(1, w): g *= 2 g = g % 998244353 for i in range(1, h): g *= 2 g = g % 998244353 print(g)
1,300
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); const int M = 3e5; int n; cin >> n; vector<int> a(n + 1); for (int i = 1; i <= n; i++) cin >> a[i]; vector<int64_t> fen1(2 * M + 1), fen2(2 * M + 1); int64_t pref = 0, s = 0, t = 0; auto Sum = [](int i, vector<int64_t>& fen) -> int64_t { int64_t r = 0; while (i > 0) { r += fen[i]; i -= i & (-i); } return r; }; auto Upd = [](int i, vector<int64_t>& fen, int d) -> void { while (i < (int)fen.size()) { fen[i] += d; i += i & (-i); } }; for (int i = 1; i <= n; i++) { s += 1LL * a[i] * (i - 1) - Sum(a[i], fen1); t += pref; pref += a[i]; for (int j = 1; j * a[i] <= 300000; j++) { t -= 1LL * (Sum((j + 1) * a[i] - 1, fen2) - Sum(j * a[i] - 1, fen2)) * j * a[i]; Upd(a[i] * j, fen1, j * a[i]); Upd(a[i] * (j + 1), fen1, -j * a[i]); } Upd(a[i], fen2, 1); cout << s + t << " "; } return 0; }
2,300
CPP
n,h = map(int, input().split()) a = list(map(int, input().split())) k = n for i in a: if i > h: k+=1 print(k)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const int maxn = 100000 + 5; const int maxe = maxn; int psz; struct Edge { int u, v; Edge *next; } epool[maxe * 2], *e[maxn]; void add_edge(int u, int v) { Edge *p = epool + psz++; p->u = u; p->v = v; p->next = e[u]; e[u] = p; } int n, m; bool g[10][10]; bool vis[maxn]; int cnt; int head[maxn]; bool ring[maxn]; int id[maxn]; vector<int> vec[maxn]; void init() { psz = 0; memset(e, 0, sizeof(e)); memset(g, false, sizeof(g)); scanf("%d%d", &n, &m); for (int i = 0; i < m; ++i) { int u, v; scanf("%d%d", &u, &v); --u; --v; if (n <= 7) { g[u][v] = g[v][u] = true; } else { add_edge(u, v); add_edge(v, u); } } } bool find(int u, int f) { vis[u] = true; for (Edge *i = e[u]; i; i = i->next) { int v = i->v; if (v == f) continue; if (vis[v]) { head[cnt] = v; ring[cnt] = true; return true; } else { if (find(v, u)) return true; } } head[cnt] = u; ring[cnt] = false; return true; } bool add(int u, int f, int idx) { vis[u] = true; vec[idx].push_back(u); for (Edge *i = e[u]; i; i = i->next) { int v = i->v; if (v == f) continue; if (v == head[idx]) return true; if (add(v, u, idx)) return true; } return false; } void reorder(int i) { vector<int> tmp; for (int j = 0; j < vec[i].size(); j += 2) tmp.push_back(vec[i][j]); for (int j = 1; j < vec[i].size(); j += 2) tmp.push_back(vec[i][j]); if (tmp.size() % 2 == 0) swap(tmp[0], tmp[1]); vec[i].assign(tmp.begin(), tmp.end()); } void solve() { if (n <= 7) { int idx[7]; for (int i = 0; i < n; ++i) idx[i] = i; do { cnt = 0; for (int i = 0; i < n; ++i) { int x = idx[i], y = idx[(i + 1) % n]; cnt += !g[x][y]; } if (cnt >= m) { for (int i = 0; i < n; ++i) { int x = idx[i], y = idx[(i + 1) % n]; if (g[x][y]) continue; printf("%d %d\n", x + 1, y + 1); if (!(--m)) return; } } } while (next_permutation(idx, idx + n)); printf("-1\n"); return; } memset(vis, false, sizeof(vis)); for (int i = 0; i < n; ++i) if (!vis[i]) { find(i, -1); vec[cnt].clear(); add(head[cnt], -1, cnt); ++cnt; } int large = 0; for (int i = 0; i < cnt; ++i) if (vec[i].size() > vec[large].size()) large = i; reorder(large); vector<int> tmp, res; for (int i = 0; i < cnt; ++i) if (i != large) for (int j = 0; j < vec[i].size(); ++j) tmp.push_back(vec[i][j]); for (int j = 0; j < vec[large].size(); ++j) { res.push_back(vec[large][j]); for (int i = j; i < tmp.size(); i += vec[large].size()) res.push_back(tmp[i]); } for (int i = 0; i < m; ++i) { int x = i, y = (i + 1) % n; printf("%d %d\n", res[x] + 1, res[y] + 1); } } int main() { init(); solve(); return 0; }
2,400
CPP
#include <bits/stdc++.h> using namespace std; int num_children[666666]; int pars[666666]; vector<pair<int, int>> edges[666666]; int dfs(int par, int u, int k, int edge_cost, long long* min_sum, long long* max_sum) { pars[u] = par; int ans = 1; for (const pair<int, int>& vc : edges[u]) { if (vc.first == par) continue; ans += dfs(u, vc.first, k, vc.second, min_sum, max_sum); } num_children[u] = ans; if (num_children[u] % 2 == 1) { (*min_sum) += edge_cost; } long long x = min(k, min(ans, 2 * k - ans)); (*max_sum) += x * edge_cost; return ans; } int main() { int T; cin >> T; for (int t = 1; t <= T; t++) { int k; cin >> k; for (int i = 1; i <= 2 * k; i++) edges[i].clear(); for (int i = 1; i <= 2 * k - 1; i++) { int a, b, t; cin >> a >> b >> t; edges[a].push_back({b, t}); edges[b].push_back({a, t}); } long long min_sum = 0; long long max_sum = 0; dfs(-1, 1, k, 0, &min_sum, &max_sum); printf("%lld %lld\n", min_sum, max_sum); } }
2,000
CPP
#include <bits/stdc++.h> using namespace std; string a, b; pair<int, int> process(string& s) { int sum = 0, wildcard = 0; for (auto c : s) { if (c == '+') { sum++; } else if (c == '-') { sum--; } else { wildcard++; } } return {sum, wildcard}; } int main() { cin >> a >> b; pair<int, int> info_a = process(a); pair<int, int> info_b = process(b); int diff = info_a.first - info_b.first; int wild = info_b.second, res = 0; for (int mask = 0; mask < (1 << wild); mask++) { int sum = 0; for (int i = 1; i <= wild; i++) { if (mask & (1 << (i - 1))) { sum++; } else { sum--; } } if (sum == diff) { res++; } } printf("%.9lf\n", (double)res / (1 << wild)); return 0; }
1,300
CPP
#include <bits/stdc++.h> using namespace std; mt19937 rnd(228); struct pt { int x, y; }; pt operator-(const pt &a, const pt &b) { return {a.x - b.x, a.y - b.y}; } pt operator+(const pt &a, const pt &b) { return {a.x + b.x, a.y + b.y}; } long long operator*(const pt &a, const pt &b) { return a.x * (long long)b.y - a.y * (long long)b.x; } long long len(const pt &p) { return p.x * (long long)p.x + p.y * (long long)p.y; } pt s; const int N = 300 + 7; int ok[N][N]; long long dp[N][N]; vector<pt> f; pt mn; bool operator<(const pt &a, const pt &b) { if ((a - s) * (b - s) != 0) { return (a - s) * (b - s) < 0; } else { return len(a - s) < len(b - s); } } long long sq(const pt &a, const pt &b, const pt &c) { return abs((c - a) * (b - a)); } bool in(const pt &who, const pt &a, const pt &b, const pt &c) { return sq(a, b, c) == sq(a, b, who) + sq(a, c, who) + sq(b, c, who); } int main() { int n; cin >> n; vector<pt> e; for (int i = 0; i < n; i++) { int x, y; cin >> x >> y; e.push_back({x, y}); } long long ans = 0; for (int i = 0; i < n; i++) { f.clear(); for (int j = 0; j < n; j++) { if (e[j].x > e[i].x || (e[j].x == e[i].x && e[j].y > e[i].y)) { f.push_back(e[j]); } } s = e[i]; sort(f.begin(), f.end()); int k = f.size(); for (int i = 0; i < k; i++) { for (int j = i + 1; j < k; j++) { ok[i][j] = 0; } } for (int i = 0; i < k; i++) { for (int j = i + 1; j < k; j++) { ok[i][j] = 1; } } vector<pair<int, int> > e; for (int i = 0; i < k; i++) { for (int j = i + 1; j < k; j++) { e.push_back({i, j}); } } mn = {-1, 1000000000}; sort(e.begin(), e.end(), [](pair<int, int> a, pair<int, int> b) { pt x = f[a.second] - f[a.first]; pt y = f[b.second] - f[b.first]; if (x * mn == 0) { if (y * mn == 0) { return len(x) < len(y); } else { return y * mn < 0; } } if (y * mn == 0) { return x * mn > 0; } if (x * mn < 0 && y * mn < 0) { if (x * y == 0) { return len(x) < len(y); } return x * y < 0; } else if (x * mn > 0 && y * mn > 0) { if (x * y == 0) { return len(x) < len(y); } return x * y < 0; } else { return x * mn > 0; } }); for (int i = 0; i < k; i++) { for (int j = 0; j < 4; j++) { dp[i][j] = 0; } } for (int i = 0; i < k; i++) dp[i][0] = 1; vector<vector<int> > was(n); for (auto c : e) { int i = c.first, go = c.second; for (int j = 0; j < 3; j++) { dp[go][j + 1] += dp[i][j] * (long long)ok[i][go]; } } for (int i = 0; i < k; i++) { ans += dp[i][3]; } } cout << ans << '\n'; }
2,900
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n; scanf("%i", &n); int arr[n]; for (int i = 0; i < n; i++) { int a; scanf("%i", &a); arr[i] = a; } string ans = ""; bool flag = true; int s = 0; while (true) { bool done = true; for (int i = 0; i < n && done; i++) { if (arr[i] > 0) done = false; } if (done) break; if (flag) { for (int i = 0; i < n; i++) { if (arr[i] > 0 && (s == 0 || (s > 0 && ans[s - 1] != 'P'))) { arr[i]--; ans += 'P'; s++; } if (i < n - 1) { ans += 'R'; s++; } } flag = false; } else { for (int i = n - 1; i >= 0; i--) { if (arr[i] > 0 && (s == 0 || (s > 0 && ans[s - 1] != 'P'))) { arr[i]--; ans += 'P'; s++; } if (i > 0) { ans += 'L'; s++; } } flag = true; } } cout << ans << endl; }
1,200
CPP
n , x = map(int,input().split()) p = 0 for i in range(1,n+1): if x%i==0 and x//i<=n: p+=1 print(p)
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { long long x; cin >> x; long long i = 0; while (x) { if (x & 1) { i++; } x = x / 2; } cout << i; }
1,000
CPP
#include <bits/stdc++.h> using namespace std; int gcd(int a, int b) { if (!b) return a; return gcd(b, a % b); } int n, k; int a[105], b[105]; int dp[105][200015]; void ck(int &x, int y) { if (x == -1 || x < y) x = y; } int main() { scanf("%d%d", &n, &k); for (int i = (1); i <= (n); ++i) scanf("%d", &a[i]); for (int i = (1); i <= (n); ++i) scanf("%d", &b[i]); memset(dp, -1, sizeof(dp)); dp[0][100000] = 0; for (int i = (1); i <= (n); ++i) { for (int j = (0); j <= (200002); ++j) { if (dp[i - 1][j] == -1) continue; ck(dp[i][j], dp[i - 1][j]); ck(dp[i][j + a[i] - k * b[i]], dp[i - 1][j] + a[i]); } } if (dp[n][100000] != 0) printf("%d\n", dp[n][100000]); else printf("-1\n"); return 0; }
1,900
CPP
testCases= int(input()) for _ in range(testCases): n, k= map(int, input().split()) addition= 0 odd= 1 count= 0 if((n% 2!= 0) and (k% 2== 0)): print('NO') elif((n% 2== 0) and (k% 2!= 0)): print('NO') else: minimumSum= k**2 if((minimumSum<= n) and (minimumSum% 2== n% 2)): print('YES') else: print('NO')
1,100
PYTHON3
i = input().split() n = int(i[0]) m = int(i[1]) k = int(i[2]) res = 'No' if m>=n and k>=n: res = 'Yes' print(res)
800
PYTHON3
n = int(input()) k = 0 while n: n -= int(max(str(n))) k += 1 print(k)
1,100
PYTHON3
n = int(input()) arr = list(map(int,input().split())) # arr = [15, 20, 30, 40, 50, 60, 70, 80, 90] def minMinute(arr): t = 0 for i in range (len(arr)): if arr[i] - t > 15: return min(90,t+15) else: t = arr[i] return min(t+15, 90) print(minMinute(arr))
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int a[101]; int main() { ios_base::sync_with_stdio(0); cin >> a[1] >> a[2] >> a[3]; int ans = 0; for (int i = 1; i <= 1001; i++) { if (i <= a[1] && i + 1 <= a[2] && i + 2 <= a[3]) { ans = max(ans, i + i + i + 3); } } cout << ans; return 0; }
800
CPP
for _ in range(int(input())): ans = "YES" n = int(input()) arr = list(map(int, input().split())) if n&1: for x,y in zip(arr[:-1], arr[1:]): if y <= x: break else: ans = "NO" print(ans)
1,100
PYTHON3
#include <bits/stdc++.h> using namespace std; const int maxn = 3e5 + 5; const int mod = 1e9 + 7; long long qpow(long long a, long long b) { long long ans = 1; a %= mod; assert(b >= 0); for (; b; b >>= 1) { if (b & 1) ans = ans * a % mod; a = a * a % mod; } return ans; } long long gcd(long long a, long long b) { return b > 0 ? gcd(b, a % b) : a; } int n, m, T; int id[maxn]; vector<int> g[maxn]; bool vis[10][10]; int gao() { int x = 0; memset(vis, 0, sizeof vis); for (int i = 1; i <= n; i++) { for (auto v : g[i]) { if (vis[id[i]][id[v]]) continue; vis[id[i]][id[v]] = vis[id[v]][id[i]] = 1; x++; } } return x; } int cal(int t) { int res = 0, num = 0; for (int i = 1; i <= n; i++) { if (i != t) id[i] = ++num; } for (int i = 1; i <= 6; i++) { id[t] = i; res = max(res, gao()); } return res; } int main() { cin >> n >> m; for (int i = 0; i < m; i++) { int x, y; scanf("%d%d", &x, &y); g[x].push_back(y); g[y].push_back(x); } int ans = 0; if (n <= 6) { ans = m; } else { for (int i = 1; i <= n; i++) { ans = max(ans, cal(i)); } } cout << ans << endl; return 0; }
1,700
CPP
a=input() b="hello" k=0 m=0 for i in b: a=a[k::] #print(a) try: k=a.index(i) if(i=='l'): k=k+1 if i in a: pass else: m=1 print('NO') break except: m=1 print('NO') break if(m==0): print('YES')
1,000
PYTHON3
# Author : code_marshal n,m=map(int,input().split());i=j=0 a=list(map(int,input().split())) b=list(map(int,input().split())) while i<n and j<m: if b[j]>=a[i]:i+=1 j+=1 print (n-i)
1,200
PYTHON3
import sys reader = (line.rstrip() for line in sys.stdin) t = int(next(reader)) modulo = 10 ** 9 + 7 for _ in range(t): x = int(next(reader)) s = [int(i) for i in next(reader)] l = 0 total = len(s) while l < x: l += 1 k = s[l-1] if len(s) < x: n = len(s) for _ in range(k - 1): s.extend(s[l:n]) total = len(s) else: total += (k - 1) * (total - l) total %= modulo print(total)
1,700
PYTHON3
input() line = input() wasm = -1 last0 = 0 last1 = -1 curs = 0 err = False for i in range(len(line)): if line[i]=='(': curs+=1 else: curs-=1 if curs == 0: last0=i if curs == 1: last1=i if curs < 0: if wasm == -1: wasm=i if curs < -2: err = True break if err: print(0) elif wasm == -1: if curs != 2: print(0) else: print(int((len(line)-max(last0,last1))/2)) else: if curs != -2: print(0) else: print(int(wasm/2) + 1)
1,900
PYTHON3
for y in range(int(input())): n=int(input()) lst=list(map(int,input().split())) cnt=0 for i in range(n-1): if lst[i]>lst[i+1]: cnt+=(lst[i]-lst[i+1]) if cnt<=lst[0]: print('YES') else: print('NO')
1,800
PYTHON3
#include <bits/stdc++.h> using namespace std; int s, a, b, c, t; int main() { scanf("%d%d%d%d", &s, &a, &b, &c); t = a + b + c; if (t == 0) printf("0.0 0.0 0.0\n"); else printf("%.15f %.15f %.15f\n", (double)s * a / t, (double)s * b / t, (double)s * c / t); return 0; }
1,800
CPP
#include <bits/stdc++.h> using namespace std; bool is_prime(long long a) { for (long long i = 2; i <= (a / i); i++) { if (a % i == 0) { return 0; } } return 1; } long long tonmoy(long long p, long long q, long long a) { long long x = p; long long y = q; if (a == 1) { return 1; } while (p % q == 0) { p /= a; } return p; } int main() { int n; cin >> n; string a; int b; map<string, int> m; map<string, int> m2; vector<pair<string, int> > v; while (n--) { cin >> a >> b; m[a] += b; v.push_back(make_pair(a, b)); } map<string, int>::iterator it; int best = 0; for (it = m.begin(); it != m.end(); it++) { best = max(best, it->second); } for (int i = 0; i < v.size(); i++) { m2[v[i].first] += v[i].second; if (m2[v[i].first] >= best && m[v[i].first] == best) { cout << v[i].first << endl; return 0; } } }
1,500
CPP
t = int(input()) for i in range(t): l = list(map(int, input().split())) l.sort() if l[0] == l[1] and l[1]!=l[2]: print("NO") continue elif l[0]!=l[1] and l[1]!=l[2]: print("NO") continue print("YES") if l[0] == l[1] and l[1] == l[2]: print(l[0], l[0], l[0]) elif l[1] == l[2]: print(l[0], l[0], l[1])
800
PYTHON3
#include <bits/stdc++.h> using namespace std; long long GCD(long long a, long long b) { return b != 0 ? GCD(b, a % b) : a; } long long LCM(long long a, long long b) { return a * (b / GCD(a, b)); } long long Pow(long long n, long long e) { if (e == 0) return 1; if (e == 1) return n; else if (e & 1) { long long t = Pow(n, e / 2); return n * t * t; } else { long long t = Pow(n, e / 2); return t * t; } } long long start[100005], endd[100005], cntS[100005], cntE[100005], res[100005]; int main() { int N, M, K; scanf("%d %d %d", &N, &M, &K); for (int i = 0, max_ = (M); i < max_; ++i) { int a, b, c; scanf("%d %d %d", &a, &b, &c); --a; --b; start[a] += c; endd[b] += c + (b - a); ++cntS[a]; ++cntE[b]; } long long curr = 0; int cnt = 0; for (int i = 0, max_ = (N); i < max_; ++i) { curr += start[i]; cnt += cntS[i]; res[i] = curr; curr -= endd[i]; cnt -= cntE[i]; curr += cnt; } long long sum = 0; for (int i = 0, max_ = (K); i < max_; ++i) { int b; scanf("%d", &b); --b; sum += res[b]; } printf("%I64d\n", sum); return 0; }
1,600
CPP
def CostOfHeating(c, sum): t = sum // c cost = sum % c * (t + 1)**2 + (c - sum % c) * t**2 return cost def main(): outl = [] for i in range(int(input())): inl = input().split() outl.append(CostOfHeating(int(inl[0]), int(inl[1]))) for i in outl: print(i) if __name__ == '__main__': main()
1,000
PYTHON3
n= int(input()) s= str(input()) count=0 x=1 for i in s: if int(i)%2==0: count= count+ s.index(i)+x x= x+ len(s[: s.index(i)])+1 s= s[s.index(i)+1:] print(count)
800
PYTHON3
a, m = map(int, input().split()) s = set() s.add(a) while True: a = (2 * a) % m if a in s: print("No") exit(0) if a == 0: print("Yes") exit(0) s.add(a)
1,400
PYTHON3
#include <bits/stdc++.h> using namespace std; struct edge { int u, v, c, p; } s[501000]; int n, m; int f[501000], ff[501000]; void Union(int a, int b) { int t = f[a] + f[b]; if (f[a] > f[b]) swap(a, b); f[a] = t; f[b] = a; } int root(int u) { if (f[u] < 0) return u; return f[u] = root(f[u]); } int tcase, now[501000]; int root2(int u) { if (now[u] != tcase) now[u] = tcase, ff[u] = f[u]; if (ff[u] < 0) return u; return ff[u] = root2(ff[u]); } void Union2(int a, int b) { int t = ff[a] + ff[b]; if (ff[a] > ff[b]) swap(a, b); ff[a] = t; ff[b] = a; } vector<pair<int, int> > qc[501000]; vector<int> e[501000]; int q; bool query[501000]; void init() { int k, id; cin >> q; for (int i = 0; i < q; ++i) { cin >> k; query[i] = true; while (k--) { cin >> id; qc[s[id].c].push_back(pair<int, int>(i, id)); } } } void solve() { tcase = 0; for (int i = 1; i <= n; ++i) f[i] = -1; for (int cost = 1; cost <= 5e5; ++cost) { sort(qc[cost].begin(), qc[cost].end()); for (int i = 0; i < qc[cost].size(); ++i) { if (!i || qc[cost][i].first != qc[cost][i - 1].first) tcase++; int id = qc[cost][i].second; int a = root2(s[id].u); int b = root2(s[id].v); if (a == b) { query[qc[cost][i].first] = false; } else Union2(a, b); } for (int id : e[cost]) { int a = root(s[id].u); int b = root(s[id].v); if (a != b) Union(a, b); } } for (int i = 0; i < q; ++i) { if (query[i]) cout << "YES\n"; else cout << "NO\n"; } } int main() { ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); ; cin >> n >> m; for (int i = 1; i <= m; ++i) { cin >> s[i].u >> s[i].v >> s[i].c; e[s[i].c].push_back(i); } init(); solve(); }
2,300
CPP
n = int(input()) s = input() max = 0 val = 0 for i in range(n - 1): sub = s[i] + s[i + 1] val=0 for j in range(n - 1): if s[j] + s[j + 1] == sub: val += 1 if val > max: max = val ans = sub print(ans)
900
PYTHON3
a=input().lower() b=input().lower() if(a==b): print(0) elif(a>b): print(1) else: print(-1)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; long long int fact(long long int n) { long long int ans = 1; for (long long int i = 2; i <= n; i++) ans = (ans % 1000000007 * i % 1000000007) % 1000000007; return ans; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long int t; cin >> t; while (t--) { long long int n; cin >> n; cout << (n % 1000000007 * fact(2 * n - 1) % 1000000007) % 1000000007 << endl; } }
800
CPP
#include <bits/stdc++.h> using namespace std; bool f1(pair<int, int> a, pair<int, int> b) { return a.first < b.first; } bool f2(pair<int, int> a, pair<int, int> b) { return a.second < b.second; } int main() { int tmp; int n; cin >> n; pair<int, int> tmp2; pair<int, int> a[300005]; for (int i = 0; i < n; i++) { cin >> tmp; tmp2.first = tmp; tmp2.second = i; a[i] = tmp2; } stable_sort(a, a + n, f1); tmp2 = a[0]; tmp = tmp2.first; for (int i = 1; i < n; i++) { if (a[i].first > tmp) { tmp2 = a[i]; tmp = tmp2.first; continue; } else { a[i].first = ++tmp; } } sort(a, a + n, f2); for (int i = 0; i < n; i++) { cout << a[i].first << ' '; } cout << endl; }
1,400
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n, k; cin >> n >> k; int a[n], b[n], man = 0, sum = 0; for (int i = 0; i < n; i++) { cin >> a[i]; if (a[i] < 0) { b[man] = abs(a[i]); man++; } a[i] = abs(a[i]); sum += a[i]; } sort(a, a + n); if (((k - man) % 2 == 1) && (k > man)) { k--; sum -= 2 * a[0]; } int t = man - k; sort(b, b + man); for (int i = 0; i < t; i++) sum -= 2 * b[i]; cout << sum << endl; }
1,200
CPP
#include <bits/stdc++.h> using namespace std; struct Event { int l, r, ind; Event() : l(), r(), ind() {} Event(int _l, int _r, int _ind) : l(_l), r(_r), ind(_ind) {} }; const int N = 4005; const int T = 33000; const int SIZE = (1 << 15); int n, p, q; int cost[N], happy[N]; int query_money[T]; int query_res[T]; vector<int> queries[T]; struct Knapsack { int dp[N][N]; int size; vector<pair<int *, int>> history; vector<int> snapshots; Knapsack() : dp(), size() {} void change(int *ptr, int val) { history.push_back(make_pair(ptr, *ptr)); *ptr = val; } void undo() { int *ptr = history.back().first; int val = history.back().second; *ptr = val; history.pop_back(); } void snapshot() { snapshots.push_back((int)history.size()); } void recover() { while ((int)history.size() > snapshots.back()) undo(); snapshots.pop_back(); } void add(int ind) { 0; change(&size, size + 1); for (int i = 0; i < N; i++) { int old_sum = i - cost[ind]; int val = max((old_sum < 0 ? 0 : dp[size - 1][old_sum] + happy[ind]), dp[size - 1][i]); change(&dp[size][i], val); } } int get(int money) { return dp[size][money]; } void dump() { 0; for (int i = 0; i <= size; i++) { for (int j = 0; j < 10; j++) 0; 0; } } }; Knapsack knapsack; bool intersects(int a, int b, int c, int d) { int x = max(a, c); int y = min(b, d); return x <= y; } void solve(int l, int r, vector<Event> &events) { knapsack.snapshot(); for (Event e : events) if (e.l <= l && r <= e.r) knapsack.add(e.ind); if (l == r) { for (int query : queries[l]) { query_res[query] = knapsack.get(query_money[query]); } } else { int m = (l + r) / 2; vector<Event> left, right; for (Event e : events) { if (e.l <= l && r <= e.r) continue; if (intersects(l, m, e.l, e.r)) left.push_back(e); if (intersects(m + 1, r, e.l, e.r)) right.push_back(e); } solve(l, m, left); solve(m + 1, r, right); } knapsack.recover(); } void solve() { vector<Event> events; scanf("%d%d", &n, &p); for (int i = 0; i < n; i++) { int time; scanf("%d%d%d", &cost[i], &happy[i], &time); events.push_back(Event(time, time + p - 1, i)); } scanf("%d", &q); for (int i = 0; i < q; i++) { int time; scanf("%d%d", &time, &query_money[i]); queries[time].push_back(i); } solve(0, SIZE - 1, events); for (int i = 0; i < q; i++) printf("%d\n", query_res[i]); } int main() { solve(); 0; return 0; }
2,700
CPP
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); ; string s; getline(cin, s); long long int prev = 0; long long int cnt = 0; for (long long int i = 1; i <= s.length(); i++) { if (s[i - 1] == 'F') { cnt++; long long int a = i - cnt; if (prev == 0 || prev < a) prev = a; else prev++; } } cout << prev << '\n'; return 0; }
2,000
CPP
N = int(input()) for _ in range(N): a = [ord(s) for s in input().strip()] b = [ord(s) for s in input().strip()] na = len(a) nb = len(b) da = [] sa = [] pre = -1 for ai in a: if pre == ai: da[-1] += 1 else: da.append(0) sa.append(ai) pre = ai db = [] sb = [] pre = -1 for bi in b: if pre == bi: db[-1] += 1 else: db.append(0) sb.append(bi) pre = bi #print(da, db, sa, sb) if sa == sb and all(ai <= bi for ai, bi in zip(da, db)): print('YES') else: print('NO')
1,200
PYTHON3
#include <bits/stdc++.h> using namespace std; void GO_FAST() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); } void AMMAR(int n, int b[1000]) { for (int i = 0; i < n * 2 + 1; ++i) b[i] = 0; } int main() { GO_FAST(); int b[1000], t, n, x; cin >> t; for (int i = 0; i < t; ++i) { cin >> n; AMMAR(n, b); for (int j = 0; j < n * 2; ++j) { cin >> x; if (b[x] == 0) { cout << x << " "; b[x] = 1; } else continue; } cout << endl; AMMAR(n, b); } }
800
CPP
n = int(input()) lis = list(map(int, input().split())) taxi = 0 n3 = lis.count(3) n2 = lis.count(2) n1 = lis.count(1) n4 = lis.count(4) taxi += n4 + n3 + n2 // 2 if n3 > n1: if n2 % 2 != 0: taxi += 1 else: n1 -= n3 if n2 % 2 == 0: taxi += n1 // 4 n1 %= 4 if n1 != 0: taxi += 1 else: taxi += n1 // 4 n1 %= 4 if n1 < 3: taxi += 1 else: taxi += 2 print(taxi)
1,100
PYTHON3
#include <bits/stdc++.h> using namespace std; const double PI = 3.141592653589793238462643383279502884197169399375105820974944592307816406286208998628034825342117067982148086513282306647093844609550582231725359408128481117450284102701938521105559644622948954930381964428810975665933446128475648233786783165271201909145648566923460348610454326648213393607260249141273724587006606315588174881520920962829254091715364367892590360011330530548820466521384146951941511609433057270365759591953092186117381932611793105118548074462379962749567351885752724891227938183011949129833673362440656643086021394946395224737190702179860943702770539217176293176752384674818467669405132000568127145263560827785771342757789609173637178721468440901224953430146549585371050792279689258923542019956112129021960864034418159813629774771309960518707211349999998372978049951059731732816096318595024459455346908302642522308253344685035261931188171010003137838752886587533208381420617177669147303598253490428755468731159562863882353787593751957781857780532171226806613001927876611195909216420198938095257201065485863278865936153381827968230301952; const long long INF = 1e18; long long gcd(long long x, long long y) { return (y == 0 ? x : gcd(y, x % y)); } long long lcm(long long a, long long b) { return a * (b / gcd(a, b)); } bool isprime(long long u) { for (long long i = 2; i <= (int)sqrt(u); i++) { if (u % i == 0) return 0; } return 1; } int main() { vector<long long> x; vector<long long> h; int n, i, r, nb = 1; cin >> n; for (i = 0; i < n; i++) { cin >> r; x.push_back(r); cin >> r; h.push_back(r); } x.push_back(INF); for (i = 1; i < n; i++) { if (x[i] - x[i - 1] > h[i]) nb++; else if (x[i + 1] - x[i] > h[i]) { nb++; x[i] += h[i]; } } cout << nb; return 0; }
1,500
CPP
# from queue import Queue n, m = map(int, input().split()) arr = [None]*n for i in range(n): arr[i] = list(input()) r1, c1 = map(lambda x: int(x) - 1, input().split()) r2, c2 = map(lambda x: int(x) - 1, input().split()) def bfs(maze, x, y, r2, c2): q = [(x, y)] path = [[None]*len(maze[0]) for i in range(len(maze))] path[x][y] = (x,y) DIR = [(1, 0), (-1, 0), (0, 1), (0, -1)] while len(q) != 0: nextLevel = [] for x,y in q: for dx, dy in DIR: new_x, new_y = x + dx, y + dy if 0 <= new_x < len(maze) and 0 <= new_y < len(maze[0]) and path[new_x][new_y] == None and maze[new_x][new_y] == '.': path[new_x][new_y] = (x,y) nextLevel.append((new_x, new_y)) # When maze[r2][c2] == 'X' if new_x == r2 and new_y == c2 and path[new_x][new_y] == None: path[new_x][new_y] = (x,y) nextLevel.append((new_x, new_y)) q = nextLevel return path def printPath(arr, path, sx, sy, fx, fy): b = [] while True: b.append((fx, fy)) (fx, fy) = path[fx][fy] if fx == sx and fy == sy: break # Crack the ice that we went through for i in range(len(b)-1, -1, -1): u,v = b[i] arr[u][v] = 'X' path = bfs(arr, r1, c1, r2, c2) directions = [(1, 0), (-1, 0), (0, 1), (0, -1)] # print(path) answer = 'NO' if n == 1 and m == 1: answer = 'NO' elif r1 == r2 and c1 == c2: for dx, dy in directions: new_x, new_y = r2 + dx, c2 + dy if 0 <= new_x < n and 0 <= new_y < m and arr[new_x][new_y] == '.': answer = 'YES' break elif path[r2][c2] != None: if arr[r2][c2] == 'X': answer = 'YES' else: printPath(arr, path, r1, c1, r2, c2) for dx, dy in directions: new_x, new_y = r2 + dx, c2 + dy if 0 <= new_x < n and 0 <= new_y < m and arr[new_x][new_y] == '.': answer = 'YES' break print(answer)
2,000
PYTHON3