the straight distance between two place on a map can be measured by .
the straight distance between two place on a map can be measured by a strip of paper and divider.use a ruler to measure the distance between the two places. if the line is quite curved, use a string to determine the distance, and then measure the string. find the scale for the map you're going to use. it might be a ruler bar scale or a written scale, in words or numbers.
first draw the directions, i recommand you draw them as vectors (like arrows):

- north points to the top
- south points to the bottom
- east points to the right
- west points to the left

now lets draw a line from the center of your "+"-sign at about a 45 degree angle to the top right.

this is the hiker that travels northeast. now the next hiker is simple, you just draw a line from the center to the east. that would be a straight line.

now we assume that the angle between the two hikers is 45 degrees. because that's one piece of the given information.

let's calculate how far the first hiker has traveled: 7,5 x 2 = 15 km.
let's calculate how far the second hiker has traveled: 6 x 2 = 12 km.

now we can use sine to calculate the distance between the two hikers.
note: please set your calculator on degrees. we call hiker's distance: x.

sin(45) = x / 15
15 * sin(45) = x

now we know the distance between the two hikers.

greetx jtk it depends on what map it is Straight lines google map is detailed enough for you to find ur way. it is the best that is available online especially with sat photos hint: here, we will proceed by finding out the relative speed between the two cars and then using the formula i.e., time taken$ = \dfrac{{{\text{distance travelled}}}}{{{\text{speed}}}}$ to determine after how many hours these cars will meet each other.complete step-by-step answer:given, distance between the two cars d=160 kmstarting time for both the cars when they left their respective initial positions a and b is 8:10 amspeed of the first car, x=50 km per hourspeed of the second car, y=30 km per hourin order to obtain the relative speed between these two cars which are moving towards each other (i.e., in opposite directions), the individual speeds of these cars will be added.so, the relative speed between the two given cars, r= x+y=50+30=80 km per houras we know that, time taken$ = \dfrac{{{\text{distance travelled}}}}{{{\text{speed}}}}$so, time when both the cars will meet=$\dfrac{{{\text{initial distance between both the cars}}}}{{{\text{relative speed between the cars}}}} = \dfrac{{\text{d}}}{{\text{r}}} = \dfrac{{160}}{{80}} = 2$ hours.after 8:10 am, both the cars which are initially at different places a and b will meet each other in the next 2 hours.therefore, time when they will meet each = 8:10 am + 2 hours = 10:10 amhence, option a is correct.note: in this particular problem, since the given two cars are moving in opposite directions (or moving towards each other) that’s why the individual speed of the cars are added in order to determine the relative speed between them but if they were moving in the same direction then the relative speed between these cars would have been obtained by subtracting the individual speed of these cars. given statement is true. you don't say that the area must be a rectangle. the true largest area would be a circle, with the circumference equal to 400m and the area would be 12,732.4 m^2. however, evidently, the area is restricted to a rectangle, in which case the maximum area is a square, and the side of the square will be 
400/4 = 100 m. the area is 100x100 = 10,000 m^2.
algebraically,
let x = one pair of opposite sides
(400-2x)/2 = 200-x = the other pair of opposite sides

area = a(x) = x(200 - x) = -x^2 + 200x
x-coordinate of vertex = -b/2a = 200/2 = 100
a(100) = 10,000

that's it! ;) trueexplanation: physical balance is very sensitive and used in labs for measuring. it is similar to beam balance. it can measure small differences in mass up to milligram. karan facing towards south moved straight 2 km and from there, turned to his right 90&ordm; and travelled 2 km. then, he took a 45&ordm; turn to his left and travelled 1 km. where would he be now with respect to the starting point? 13 km