count paths per branch
hi, i need to count the paths in a tree, though divided by the upper level category. for the attached image, for instance, the looked-for answer would be:

[0]=7

[1]=7

(used because keyboard doesn’t have the curly ones).

tried tree statistics but it gives me the complete length of all the number…
without a specific situation, you can trivially get paths count by doing:

list length > trim tree > list length …

(se hai tastiera italiana, puoi fare le parentesi graffe premendo alt dx + shift + il tasto delle quadre… )
![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/4110270/2012_11_30_15_28_05/vvnzofse6383734697724592802%20png)


let the length of path be a m


total area ![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/4110270/2012_11_30_15_28_05/ceaxujzx7923478049123545928%20png)


area of lawn = total area â€“ area of
path

![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/1800204/2012_12_04_21_09_56/mathmlequation2002748073868866733%20png)


area of lawn


![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/4110270/2012_11_30_15_28_05/dwqusyms3311632565229211681%20png) `for i in count:` means `for i in 7:`, which won't work. The bit after the `in` should be of an iterable type, not a number. Try this:



```
for i in range(count):

``` I'm not going to go through all of your code because I'm in a hurry, but this should simplify it quite a bit. At a minimum it will make it easier to read.



```
alphabet = ['A','B','C','D'....etc]
count = 0
infile = open('infile.txt','r')
for character in infile.readlines():
    if character in alphabet:
        count += 1

print count
``` Hi Uwe, You can make inside/outside strokes on non-closed paths using custom width profiles. Use thhe width tool (Shift+W) to make a stroke like this (hold alt to edit only one side of the stroke at a time): Then save it as a profile (bottom of the stroke panel). After that I think your path should be easy to make. cli::tree works with a data.frame that describe a full tree. in you example, your missing some lines for each children.

also, in your tree call tree(root = "rcmdcheck"), you are calling a root that does not exist in your data.frame. so it won't work.

you must add the minimal for the processx tree. … Here's the diagram you requested. All the best!  

Greg  

![I need a serpentine belt routing diagram for a - c528ac5.gif](http://i.fixya.net/uploads/images/c528ac5.gif) i counted 54 elements in your ‘locations’ array.

now when i look at the ‘z’ array, i technically find 108 elements.

judging by your syntax, did you meant to use a ‘,’ to separate thousands and hundreds? (but python interprets it as a separation in a list) ?answer :
step 1 of 1 :


in a pareto chart, the bars are always arranged in descending order according to frequencies.
the pareto chart helps us understand data by drawing attention to the more important categories, which have the highest frequencies. Solution:


Hello Gavin,

You have got a nice question. No matter how the question is, don’t forget to ask. Thanks.  
There are a couple of ways to find the number in digits in a number. As you told you just started learning and well-known with the for-loop. I am trying to solve the problem using a simple iteration. Please have a look below program. I hope the program will clarify itself to you as you’ve covered the for-loop topic already.


```
public class DigitsInNumber{
    static int countDigit(long x){ 
        int counter = 0; 
        while (x != 0) { 
            x = x / 10; 
            ++counter; 
        } 
        return counter; 
    }

  	public static void main(String[] args){ 
        long x = 1052809467; 
        System.out.print("Number of digits : " + countDigit(x)); 
    } 
}
```
Thanks again. Good Day! you can pick 1 senior in 5 ways, 1 junior in 4 ways, 1 sophomore in 3 ways and i freshman in 2 ways.
in all you can make these selections i 5 * 4 * 3 * 2 ways = 120 ways.
 
please note: selecting a committee is a "combination" problem, not a "permutation".