what is the average displacement over a period of s.h.m - simple harmonic motion (shm)
the average displacement over a period of s.h.m. is .................................... (a = amplitude of s.h.m.) 0 a 2a 4a
d. 4a
u (initial velocity) = 18 km/hr 
t ( time )= 2.5 sec
v( final velocity) = 0 m/s
from, the first equation of motionv = u +  a×t0 = 5 +  a×2.5a = - 2 m/s2 the relationship of wavelength and frequency will appear as:using the wavelength range given, 280-320 nm, frequency range will be calculated using the equation above and by converting the values to the proper units [readmore]each wavelength must be in meters:we need to calculate the frequency for both 280 and 320 nm:range of frequency will appear as 1.07x1015 to 9.38x1014 s-1 (a) f = 1/t = 2.11 hz

(b) 2*pi*f = 13.26 radians/s = sqrt(k/m)
m = 0.296 kg
solve for k
(c) (1/2)ka^2 = 0.150 j
solve for amplitude a, in meters histogram  divide data o equal width o no overlapping  bar chart o skew­ pulls direction of mean o symmetric numeric summary center, spread, and location  greek letters for population  roman letters for statistics 1. mean  µ= population mean  x bar= sanple mean o ∑ xi  all over n= sample mean  k=0 2. mean vs. median a. mean used the most b. n is small when outliers occur c. use median, mean is too affected spread 1. range (max­min) a. sensitive to outliers 2. iqr a. not sensitive to outliers variability­ xi­x bar v = (4/3)πr³ 

dv/dt = 4πr².dr/dt

so, when the diameter is 20 cm we have:

-4π = 4πr².dr/dt

hence, dr/dt = -1/r²

i.e. dr/dt = -1/10² => -1/100

now, d = 2r

so, d(d)/dt = 2.dr/dt

=> d(d)/dt = -1/50 cm/hour

or, -0.2 mm/hour

:)> the centimetre (cm) is a unit of length in the metric system, equal to one-hundredth of a meter. the millimetre (mm) is a unit of length in the metric system, equivalent to one-thousandth of a meter and is the si base unit of length. 1 mm = 1/10 cm 1 mm = 0.1 cm to convert the unit of length in millimetres to centimetres follow the below steps: take the value of length in millimetres and multiply it by 0.1 cm the obtained value is the answer in centimetres 25mm x 0.1cm= 2.5 cm answer hence, 25 mm = 2.5cm Hi,
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Revert. class intervals
frequency
(fi)
xi
di = xi - a
fi di


0 - 20
17
10
-40
-680


20 - 40
28
30
-20
-560


40 - 60
32
50 = a
0
0


60 - 80
p
70
20
20p


80 - 100
19
90
40
760


total
Î£
fi = 96 + p


Î£ fi di = 20p -
480


![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/5130830/2013_07_08_13_01_36/mathmlequation8813644107607516415%20png) area of trapezium = area of trapezium = = therefore = 24 cm [readmore]typed answerh2 + i2 ⇌ 2hi      kc = 4.6i            0.5   0.5     0.5c          -x      -x       +2xe        0.5-x 0.5-x   0.5+2xkc=hi2hii2kc=0.5+2x20.5-x0.5-xkc=0.5+2x20.5-x24.6=0.5+2x0.5-xx=0.138hi=0.5+2x=0.776 m