math
help po kong paano ma sasagot po eto the current i varies directly as the electromotive force e and inversely as the resistance r. if a current of 30 amperes flows through a system with 16 ohms resistance and electromotive force a 120 volts,find the current when the current when the system with 20 ohms resistance and electromotive force of 200 volt.the current i varies directly as the electromotive force e and inversely as the resistance r. if a current of 30 amperes flows through a system with 16 ohms resistance and electromotive force a 120 volts,find the current when the current when the system with 20 ohms resistance and electromotive force of 200 volt.
i = ke/r
30 = 120k/16
k=4
now you can answer the question when you have fixed the typos.
(i) here current (i) = 1 a, resistance (r) = 300 ohm, time(t) = 1hwe know thatp = i2r = 12 x 300 = 300 we = p x t = 300 x 1 = 300 wh(ii) here current (i) = 2 a resistance(r) = 100 ohm, time (t) = 1hwe know thatp = i2r = 22 x 100 = 400 we = p x t = 400 x 1 = 400 whhence, in case (ii), the electrical energy consumed per hour is more. from the figure:total resistance of the circuit, r = (rab + 15) ω = 20 ωcurrent in the circuit , \[i = \frac{v}{r} = \frac{8}{20} a\] ∴ voltage across ab, vab = i.rab = 2 vthe emf of the cell connected as above is given by: \[e = \frac{l}{l} v\_0\] here:l = 60 cm (balance point)ab = l = 1 m = 100 cm (total length of the wire) \[\therefore e = \frac{60}{100}\left( 2 \right) = 1 . 2 v\] dear student,
we know that,after the discovery of electrons, we got to know that
electrons are the particles that flow in a conductor electrons
being the negatively charged particles flow from the negative
terminal to the positive terminal and for current now, electric or
conventional current is the rate of flow of charge so, the
direction of the current should be same as the direction of the
charge, i e positive charge(conventionally), so the direction is
opposite to the flow of the negative charge(flow of electrons)
hence, the direction of the flow of electrons is opposite to the
direction of electric(or conventional) current
regards as the length of the wire increases so does the electrical resistance as electrons experience a smaller pd gradient as wire gets longer. the size of voltage per metre value decreases causing a lower drift velocity and more ions for electrons to collide with answer: eddy currents are currents that circulate in conductors like swirling eddies in a stream. they are induced by changing magnetic fields and flow in closed loops, perpendicular to the plane of the magnetic field. they arise when a conductor moves through a magnetic field, or when the magnetic field surrounding a stationary conductor is varying. to summarise, we can say that anything which results in the conductor experiencing a change in the intensity or direction of a magnetic field produces eddy currents. the two uses of eddy current are: it is used in household current meters to measure power consumption. it is used to check whether the material or surface has any discontinuities, fractures, or faults without harming the material. what are the functions of a transformer? what is the working principle of a transformer? that depends on a lot of things. in particular, you would need to find the electric susceptibility of the paper. the field produced by static charge is inverse-square. the polarization of the paper varies directly with the external field, with a proportionality constant equal to the electric susceptibility. the dipole field created by the polarized paper is inverse-cube. overall, the force between the ruler and the paper will vary with the inverse fifth power of distance. to get any more detailed, you would need to know the geometry of the situation, and the charge distribution. the force on the wire due to the interaction of magnetic fields of the bar magnet and current carrying wire can act only in upwards or downwards direction. v = (4/3)πr³ 

dv/dt = 4πr².dr/dt

so, when the diameter is 20 cm we have:

-4π = 4πr².dr/dt

hence, dr/dt = -1/r²

i.e. dr/dt = -1/10² => -1/100

now, d = 2r

so, d(d)/dt = 2.dr/dt

=> d(d)/dt = -1/50 cm/hour

or, -0.2 mm/hour

:)> (a) material q with resistivity 2.63×10-8 ohm-m can be used for making electric wires because it has very low resistivity.(b) material r with resistivity 1.0 ×1015 ohm-m can be used for making handle of soldering iron because it has very high resistivity.(c) material p with resistivity 2.3 × 103 ohm-m can be used for making solar cell because it is a semiconductor. ?solution 23cq


a) equation for loop abgefa is (35.5)i1 + (6..25 = 21 v
b) equation for loop cbgedc is ( 9.25i2 - ( 6.25i3 = +15 v