assume that p (a) = p (b). show that a = b.
we have to show that: a = b
given: p (a) = p (b)
let x be any element of set a,p(a) is the power set of set a, hence it contains all the subsets of set a. thus set a is contained in set p(a).

now let c be an element of set b
∴ 
now, we have:
c ⊂ b
∴ 
∴ a ⊂ b

similarly, we have:
b ⊂ a
now if a ⊂ b and b ⊂ a
∴ a = b
you are correct.there is a simple mathematical reason why your answer is correct, but wyzant told me that adding it to this answer required review by wyzant.try again:p(a or b) = p(a) + p(b) - p(a and b)p(neither a nor b) = 1 - p(a or b) given to prove 

then taking l.h.s.

we have 

                    





                                  

 

  

=  r.h.s.

hence proved. 2, 0 ( any two integers with one of them as 0). a, b and c if , passing through (1, 2), satisfies the differential equation , then a - ii, b - iv, c - i, d - iii a, b & c if the figure below represents a parabola, identity the physical&nbsp;quantities a)

 

  

 

  


b) the first one.