what will be the output of the following program?

```

class person {
    public string name;
    public int age;

    public person(string name, int age) {
        this.name = name;
        this.age = age;
    }

    public boolean equals(object obj) {
       return obj instanceof person
               && this.age == ((person)obj).age
               && this.name.equals(((person)obj).name);
   }
}

public class quizful {
    public static void main(string[] args){
        person p1 = new person(null, 10);
        person p2 = new person("alex", 22);
        system.out.println(p1.equals(p2));
    }
}

```
&& is a short circuit operator in java, which means that once it evaluates the left expression as false - it no longer evaluates the right expression.   

in our case, in the equals method evaluates 

```

obj instanceof person 
```
 to **true**; 

```

this.age == ((person)obj).age 
```
 to **false**; the next expression, 
```

this.name.equals(((person)obj).name);
```
 is not evaluated at all, and the method returns **false**.   

changing the && operator to || or & would result in a java.lang.nullpointerexception
The problem is that your pair's closure must return two different types of objects: int if you ask for "con", and the next closure on the line if you ask for "crd".


Here's one possible implementation:


Use a speaker so you can come back.



```
public static Func<string, dynamic> Pair(int x, Func<string, dynamic> y)
{
    Func<string, dynamic> pair =
           (a) =>
           {
               if (a == "con") return x;
               if (a == "crd") return y;
               throw new Exception();
           };

    return pair;
}

public static void Print(Func<string, dynamic> pair)
{
    while (true)
    {
        var next = pair("crd");
        Console.WriteLine((next == null ? "-":"+") +"> " + pair("con"));
        if (next != null)
        {
            Console.WriteLine("|");
            pair = (x) => next(x);
            continue;
        }
        break;
    }
}

        

        
        
        
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```


  




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Test:



```
var pair = Pair(1,
            Pair(2,
                  Pair(3,
                        Pair(4, null))));

Print(pair);

        

        
        
        
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```

output:



```
+> 1
|
+> 2
|
+> 3
|
-> 4

        

        
        
        
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``` c = input()  

t = len(c)  

temp = ""  

for i in range(0,len(c)):  

    if t<3:  

        break  

    else:  

        if i in (0,1,t-2,t-1):  

            temp = temp+c[i]  

        else:  

            continue  

print(temp) let table = base.gettable("table 1")

let record = await input.recordasync("record", table)

await table.updaterecordasync(record.id, {

"single select": null

}) I will preface this by saying that I don't know Java at all. I touched upon it in school 20+ years ago, but I've been doing PHP ever since.


However, on line 27, you say that if the input passed in is a double, execute this code block *blah*.


The user enters -1.


Is -1 not a double? It is a valid double, and therefore the code block executes, setting the priceFromUser to be -1 and adding it to the list.


Then, when the loop starts back up again on line 23, priceFromUser is now -1, so the loop breaks and prints the tally.


Also, note you're definining this constant SENTINEL variable, but you're not actually using it anywhere in your code.


Perhaps do something like this instead, changing the while loop into a do-while loop:



```
System.out.println("Please enter item price to start, since there needs to be at least 1 item:");

do
{

        // Keep asking for a price until the user enters a valid price
        while (!in.hasNextDouble())               
        {
                trash=in.nextLine(); //throw away the input 
                System.out.println("You did not enter a valid price. Please try again:");
        }

        priceFromUser=in.nextDouble(); //read value from user
        list.add(priceFromUser); //add valid price to the list            

          System.out.println("Please enter another item price, or enter -1 to quit.");

} while (priceFromUser != SENTINEL)
```

Note this isn't valid code because I'm not a Java programmer, but hopefully it helps you out a bit. You need to give the user the option of typing in a value that represents that there are no more values to enter. Perhaps give a prompt like:



```
Please enter a value.  Enter -999999 if you have no more values [B]:[/B]
```

As for the ten (or fewer) values, you should probably have an array and a loop instead of ten separate variable names and ten separate cin statements. So you're looking at something like this:



```
double dValue[10];
    int numEntries = 0;
    double sum = 0;
    
    while (numEntries < 10)
    {
          cout << "Enter number (-999999 to stop) : ";
          cin >> dValue[numEntries];
          // check whether dValue[numEntries] == -999999
          // if so, short-circuit the loop with the "break" command
            
          // increment numEntries
          // adjust sum
    }
```

As a side note, I picked -999999 as the value to represent no more values because



1. It's an integer, so it can be represented exactly as a double (no round-off error using == to compare).
2. It's a number that, chances are, people wouldn't actually want to add, so it's sort of "out of the way". Chances are, few people want to add -999999. If they do, they can't use this program! ```
[b]#include[/b] <stdio.h> 

[b]void[/b] [b]foo[/b]([b]int[/b] n)
{
   [b]if[/b] ( n >= 0 )
   {
	  [b]printf[/b]("%d ", n);
	  [b]foo[/b](n - 1);
   }
}

[b]void bar[/b]([b]int[/b] n)
{
   [b]if[/b] ( n >= 0 )
   {
	  [b]bar[/b](n - 1);
	  [b]printf[/b]("%d ", n);
   }
}

[b]int main[/b]() 
{
   [b]int[/b] value = 5;
   [b]foo[/b](value); [b]putchar[/b]('\n');
   [b]bar[/b](value); [b]putchar[/b]('\n');
   [b]return[/b] 0; 
}

/* my output
5 4 3 2 1 0 
0 1 2 3 4 5 
*/
``` ```
#!/usr/bin/perl
use strict; 
use warnings; 

my $gia = '12tai';

#Capture sequence of digits into one variable,
#capture sequence of non-digits into another variable
my ($number, $name) = $gia =~ m/(\d+)(\D+)/;

print "$number $name\n";#Two values separated by one space
``` In C ++ 11, the code is well defined, but may not do what you expect. Exact Effects: 21.4.5 / 2:



>  Returns: `*(begin() + pos)`
>   
> 
> 
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>  
>   
> 
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> 
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> 
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> 
> ; the reference value should not be changed.
> 
> 
> 



  




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So, if the string is not empty, it returns a reference to the beginning of the internal buffer. If empty, it returns a reference `char`
  




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with a value `0`
  




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whose location is implementation information. as per the question:
modal class = 35 -45
l = 35
h = 10
f1 = 23
f0 = 21
f2 = 14

= 

= 36.8
the above given data can be represented in the form of table as below:



= 35.37
the mode of the data shows that maximum number of patients in the age group of 36.8, whereas the average age of all the patients is 35.37. Your function works, but both the IF and the ELSE return an alert message that says its invalid.  

The first part - the IF - should return in the alert box "Valid SSN"  

I am assuming your input should be like this 123-45-1234


but do you need to tell the user the input is valid? Surely the alert should only be displayed if the input is invalid? So the if should return nothing. imho