two cars start towards each other, from two places a and b which are at a distance of 160 km. they start at the same time at 8:10 am. if the speeds of the cars are 50 km per hour and 30 km per hour respectively, they will meet each other at$  {\text{a}}{\text{. 10:10 am}} \\  {\text{b}}{\text{. 10:30 am}} \\  {\text{c}}{\text{. 11:10 am}} \\  {\text{d}}{\text{. 11:20 am}} \\  $
hint: here, we will proceed by finding out the relative speed between the two cars and then using the formula i.e., time taken$ = \dfrac{{{\text{distance travelled}}}}{{{\text{speed}}}}$ to determine after how many hours these cars will meet each other.complete step-by-step answer:given, distance between the two cars d=160 kmstarting time for both the cars when they left their respective initial positions a and b is 8:10 amspeed of the first car, x=50 km per hourspeed of the second car, y=30 km per hourin order to obtain the relative speed between these two cars which are moving towards each other (i.e., in opposite directions), the individual speeds of these cars will be added.so, the relative speed between the two given cars, r= x+y=50+30=80 km per houras we know that, time taken$ = \dfrac{{{\text{distance travelled}}}}{{{\text{speed}}}}$so, time when both the cars will meet=$\dfrac{{{\text{initial distance between both the cars}}}}{{{\text{relative speed between the cars}}}} = \dfrac{{\text{d}}}{{\text{r}}} = \dfrac{{160}}{{80}} = 2$ hours.after 8:10 am, both the cars which are initially at different places a and b will meet each other in the next 2 hours.therefore, time when they will meet each = 8:10 am + 2 hours = 10:10 amhence, option a is correct.note: in this particular problem, since the given two cars are moving in opposite directions (or moving towards each other) that’s why the individual speed of the cars are added in order to determine the relative speed between them but if they were moving in the same direction then the relative speed between these cars would have been obtained by subtracting the individual speed of these cars.
let the speed of train = x km /hlet the speed of car = y km/hcase 1 : 120 km by train and 480 by cartime taken to travel 120 km by train = 120x hrstime taken to travel 120 km by car = 480x hrsaccording to first condition :120x + 480y = 8⇒1x + 4y = 115     
1case 2 : 200 km by train and 400 by cartime taken to travel 200 km by train = 200x hrstime taken to travel 400 km by car = 400x hrsaccording to second condition :    200x + 400y = 82060 = 813 = 253         as, 20 min = 2060 hr = 13 hr⇒1x + 2y = 124     
2subtracting 2 from 1, we get      2y = 115 - 124⇒2y = 8-5120⇒y = 80now, from 1, we get    1x + 480 = 115⇒1x = 11 - 120 = 160⇒x = 60so, speed of train = 60 km/hspeed of car = 80 km/h karan facing towards south moved straight 2 km and from there, turned to his right 90&ordm; and travelled 2 km. then, he took a 45&ordm; turn to his left and travelled 1 km. where would he be now with respect to the starting point? first draw the directions, i recommand you draw them as vectors (like arrows):

- north points to the top
- south points to the bottom
- east points to the right
- west points to the left

now lets draw a line from the center of your "+"-sign at about a 45 degree angle to the top right.

this is the hiker that travels northeast. now the next hiker is simple, you just draw a line from the center to the east. that would be a straight line.

now we assume that the angle between the two hikers is 45 degrees. because that's one piece of the given information.

let's calculate how far the first hiker has traveled: 7,5 x 2 = 15 km.
let's calculate how far the second hiker has traveled: 6 x 2 = 12 km.

now we can use sine to calculate the distance between the two hikers.
note: please set your calculator on degrees. we call hiker's distance: x.

sin(45) = x / 15
15 * sin(45) = x

now we know the distance between the two hikers.

greetx jtk miles/hour is just that.
 
(3/4)/(1/12) = (3/4)(12) = 9 mph answer: `1.00` u (initial velocity) = 18 km/hr 
t ( time )= 2.5 sec
v( final velocity) = 0 m/s
from, the first equation of motionv = u +  a×t0 = 5 +  a×2.5a = - 2 m/s2 (a) to my eye, they never have a common speed. that would require the two curves to have the same slope at the same time, which doesn't appear to me to be true.

(b) b is ahead of a but is slowing down and being passed by a, which has been moving at constant speed.

(c) b has an acceleration with greater magnitude. (in fact, the curve for a doesn't show any acceleration at all.)

(d) a has a constant slope, and therefore a constant velocity (and therefore displays no acceleration at all). b starts ahead of a initially with a velocity greater, but then decelerates as it nears t = 4 s. at around t = 3.7 s, b's velocity (slope) has nearly dropped to zero, and it gets passed by a.

if you find this helpful, please select favorite answer! the distance covered by a car in 5 h if it is moving with a speed of 75 km/h is\_\_\_\_\_\_\_\_? amy takes an hour so she does
1/60 of yhe job per minute
father takes 30 mins so he does
1/30 of the job per minute
 
together they complete
1/60 + 1/30 per minute 
or 3/60 of the job per minute
 
(3/60)x = 1
x = 60/3
x = 20 minutes the straight distance between two place on a map can be measured by a strip of paper and divider.use a ruler to measure the distance between the two places. if the line is quite curved, use a string to determine the distance, and then measure the string. find the scale for the map you're going to use. it might be a ruler bar scale or a written scale, in words or numbers.