trigonometric grade 11 problem solving?
two hikers leave an intersection at the same time. one walks east at 6 km/h and the other walks northeast at 7.5 km/h. how far are the hikers apart after two hours, to the nearest tenth of a km?

can someone explain how to do this to me please
first draw the directions, i recommand you draw them as vectors (like arrows):

- north points to the top
- south points to the bottom
- east points to the right
- west points to the left

now lets draw a line from the center of your "+"-sign at about a 45 degree angle to the top right.

this is the hiker that travels northeast. now the next hiker is simple, you just draw a line from the center to the east. that would be a straight line.

now we assume that the angle between the two hikers is 45 degrees. because that's one piece of the given information.

let's calculate how far the first hiker has traveled: 7,5 x 2 = 15 km.
let's calculate how far the second hiker has traveled: 6 x 2 = 12 km.

now we can use sine to calculate the distance between the two hikers.
note: please set your calculator on degrees. we call hiker's distance: x.

sin(45) = x / 15
15 * sin(45) = x

now we know the distance between the two hikers.

greetx jtk
hint: here, we will proceed by finding out the relative speed between the two cars and then using the formula i.e., time taken$ = \dfrac{{{\text{distance travelled}}}}{{{\text{speed}}}}$ to determine after how many hours these cars will meet each other.complete step-by-step answer:given, distance between the two cars d=160 kmstarting time for both the cars when they left their respective initial positions a and b is 8:10 amspeed of the first car, x=50 km per hourspeed of the second car, y=30 km per hourin order to obtain the relative speed between these two cars which are moving towards each other (i.e., in opposite directions), the individual speeds of these cars will be added.so, the relative speed between the two given cars, r= x+y=50+30=80 km per houras we know that, time taken$ = \dfrac{{{\text{distance travelled}}}}{{{\text{speed}}}}$so, time when both the cars will meet=$\dfrac{{{\text{initial distance between both the cars}}}}{{{\text{relative speed between the cars}}}} = \dfrac{{\text{d}}}{{\text{r}}} = \dfrac{{160}}{{80}} = 2$ hours.after 8:10 am, both the cars which are initially at different places a and b will meet each other in the next 2 hours.therefore, time when they will meet each = 8:10 am + 2 hours = 10:10 amhence, option a is correct.note: in this particular problem, since the given two cars are moving in opposite directions (or moving towards each other) that’s why the individual speed of the cars are added in order to determine the relative speed between them but if they were moving in the same direction then the relative speed between these cars would have been obtained by subtracting the individual speed of these cars. this depends upon the type of trekking and which route your are going for trekking, but usually not more than seven hours per day. once you reach to 3000m you will walk for six hours. miles/hour is just that.
 
(3/4)/(1/12) = (3/4)(12) = 9 mph the straight distance between two place on a map can be measured by a strip of paper and divider.use a ruler to measure the distance between the two places. if the line is quite curved, use a string to determine the distance, and then measure the string. find the scale for the map you're going to use. it might be a ruler bar scale or a written scale, in words or numbers. karan facing towards south moved straight 2 km and from there, turned to his right 90&ordm; and travelled 2 km. then, he took a 45&ordm; turn to his left and travelled 1 km. where would he be now with respect to the starting point? u (initial velocity) = 18 km/hr 
t ( time )= 2.5 sec
v( final velocity) = 0 m/s
from, the first equation of motionv = u +  a×t0 = 5 +  a×2.5a = - 2 m/s2 hi jean! the jingle jungle 5k is such a fun event! while the family fun 5k's are not timed events, they do require that runners maintain a 16-minute/mile pace. there will be transportation available to the finish line for those that aren't able to keep above that. the pacers will go along at the very back of the race at that pace, so you just want to try to stay ahead of them. you should be able to get your medal at the finish area. (this is subject to change, but in the past, you could) i hope this helps! please let me know if you have any other questions. in the figure below, the angle  is shown in the standard position where the point  is on the terminal side of , and  is the distance from the origin to . 

if  is the distance from the origin to  then the trigonometric function of  are
  
  
     
therefore, the trigonometric functions are , , and . hi kathy! even though the fabulous caribbean beach resort is located near epcot, it's not possible to walk between the two. there are busy roads and no pedestrian sidewalks or crosswalks, so it would be best to drive or use the disney transportation service. you can be sure it will be a very short ride because it's so close! have a magical vacation! you seem to be missing some information about e.if e is the midpoint between d and f, thene is (1,1) take half of (4-2) = 1 and half of (5-3) = 1e alphabetically does come between d and f.just average the x values and average the y values of the two points d and for plot them graphically, carefully, maybe on some graph paper, and you'llvisually see the midpoint is at (1,1)