Mouse Move



I have an application which is supposed to move the mouse based on input like that from a keyboard. the code listens for the direction keys to see if they are pressed. the code works but only in 2 direction it can only move to the right and down. is there any way to move it up and left to.  

Here is the code:



```
#include <windows.h>
#include <iostream>
#include <cstdlib>
void MoveMouse(int x, int y);
using namespace std;

int main(){
	bool boo = true;
	int x = 0;
	int y = 0;
	while(boo){
		if(GetKeyState(VK_LEFT)<0){
			x--;
			if(x < 0){
				x = 0;
			}
			MoveMouse(x,NULL);
		}
		if(GetKeyState(VK_RIGHT)<0){
			x++;
			if(x < 0){
				x = 0;
			}
			MoveMouse(x,NULL);
		}
		if(GetKeyState(VK_UP)<0){
			y--;
			if(y < 0){
				y = 0;
			}
			MoveMouse(NULL,y);
		}
		if(GetKeyState(VK_DOWN)<0){
			y++;
			if(y < 0){
				y = 0;
			}
			MoveMouse(NULL,y);
		}
		if(GetKeyState(VK_SPACE)<0){
			boo = false;
			}
		Sleep(30);
		system("cls");
		cout << x << endl;
		cout << y << endl;

	}

	system("cls");
}

void MoveMouse(int x, int y){
	int buffer;
	for(buffer = 0; x >= buffer && y >= buffer; buffer++){
		mouse_event(0x0001,x,y,NULL,NULL);
		Sleep(1);
	}
}
```

also if anyone can help is there any way to control the mouse and clicks with a serial input. if you need more info just ask and is there a way for me to be able to click outside of the console window but still control the mouse with the program
You can use SetCursorPos() to control the position of the cursor. It returns true is it succeeds and false if not. It takes 2 arguments int x and int y. You can use GetCursorPos() to retrieve the position of cursor. it returns the same as Set...() it takes one paramater a pointer to a structure of type POINT, which contains to values long x and long y. Also if you want to send Mouse clicks then you will need to look into the function SendInput() its well documented on msdn but feel free to ask for more information.



Chris
Go to the control panel and check the mouse settings and click on defaults to reset the settings if ever someone changed it! Hello  

  

Please try this Press the 'Input/Source' Button > Press '2, 5, 8, 0' on the keypad of the remote > Scroll down to "Reset All" and press "OK" > Select "Yes" and press "OK". and let us know. Here's an example of one possibility. Just season to taste... 



```
extends Node2D
var x_delta = 0

func _physics_process(delta):
    var input_velocity = Vector2.ZERO

    if Input.is_action_just_pressed("ui_right"):
        x_delta = 1

    if Input.is_action_just_pressed("ui_left"):
        x_delta = -1

    if Input.is_action_just_released("ui_right") && x_delta > 0:
        x_delta = 0

    if Input.is_action_just_released("ui_left") && x_delta < 0:
        x_delta = 0

    input_velocity.x = x_delta

    print(input_velocity.x)

``` The problem is that your pair's closure must return two different types of objects: int if you ask for "con", and the next closure on the line if you ask for "crd".


Here's one possible implementation:


Use a speaker so you can come back.



```
public static Func<string, dynamic> Pair(int x, Func<string, dynamic> y)
{
    Func<string, dynamic> pair =
           (a) =>
           {
               if (a == "con") return x;
               if (a == "crd") return y;
               throw new Exception();
           };

    return pair;
}

public static void Print(Func<string, dynamic> pair)
{
    while (true)
    {
        var next = pair("crd");
        Console.WriteLine((next == null ? "-":"+") +"> " + pair("con"));
        if (next != null)
        {
            Console.WriteLine("|");
            pair = (x) => next(x);
            continue;
        }
        break;
    }
}

        

        
        
        
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```


  




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Test:



```
var pair = Pair(1,
            Pair(2,
                  Pair(3,
                        Pair(4, null))));

Print(pair);

        

        
        
        
 (adsbygoogle = window.adsbygoogle || []).push({});
 
        

    
```

output:



```
+> 1
|
+> 2
|
+> 3
|
-> 4

        

        
        
        
 (adsbygoogle = window.adsbygoogle || []).push({});
 
        

    
``` hi,

unfortunately, this information is not available.

but you can calculate the motion via matched bbox in adjacency frame directly.

thanks. how about this?

fn write\_some\_content(&mut self, hour: u32) -> result<(), std::io::error> {

if self.current\_hour != hour {

if let some(writer) = self.current\_file.as\_mut() {

writer.flush()?;

}

self.current\_file = none;

self.current\_hour = hour;

}

… cheat engine searches through the memory for values that you input, then locates the memory address of them so that you can change that value later on.

for example:

lets say we would cheat in pinball.

in cheat engine you select pinball as the process.

if your score is 10, you search for 10, when cheat engine is done, change the value in the game (get more / less score), then search for that value, after repeating this a few times, it will have found the address to the value of the score. then you can change it to whatever you want, you can do the same for amounts of balls and so on.

i remember i used to cheat in diablo 2 with it, get infinite stat-points and skillpoints, you could even change the experience to instantly get lvl 99, all games uses values for almost everything, (hp, mana, experience, damage) and so on, just gotta find it in ce so you can change it!

there are tutorials on cheat engines webpage.

http://www.cheatengine.org/tutorials.php direction: a word and number arrangement machine when given an input line of word and numbers rearranges them following a particular rule in each step. the following is an illustration of input and rearrangement. input: politics 61 policy 116 partner 93 role 45 clear 27 38 point step i: role politics policy 116 partner 93 45 clear 27 38 point 61 step ii: role clear politics policy partner 93 45 27 38 point 116 61 step iii: role clear partner politics policy 93 45 38 point 27 116 61 step iv: role clear partner politics policy 93 38 point 45 27 116 61 step v: role clear partner politics point policy 93 38 45 27 116 61 step v, is the last step of the above arrangement as the intended arrangement is obtained. as per the rule followed in the given steps find out the appropriate steps for the given input. input: energy 54 78 place 23 issue 211 145 flat rent taxi 17in step iii, what is the difference between fifth element from left and second element from right? to hide files and folders with the same names on left and right:

jscript:

function onclick(clickdata)

{

var cmdsource = clickdata.func.command;

cmdsource.clearfiles();

var cmddest = dopus.create.command;

cmddest.setsourcetab(clickdata.func.desttab);

cmdsource.runcommand("select deselectnomat… hi,

you can use gpi/o to start/pause/stop your program by using field bus.

please see the following setting.

[\_20210611\_134829]