in this question, study the sequence of letters, numbers or words carefully to work out the pattern on which it is based, and therefore what the next item in the sequence must be. - alphabet and numeric test
in this question, study the sequence of letters, numbers or words carefully to work out the pattern on which it is based, and therefore what the next item in the sequence must be. for example, a, c, e, g, \_\_\_, has odd-numbered letters of the alphabet; therefore, the next item must be 'i'. the meanings of the words are irrelevant. z, x, t, n, \_\_ what is the next alphabet in this sequence'?
f
a - ii, b - iv, c - i, d - iii direction: a word and number arrangement machine when given an input line of word and numbers rearranges them following a particular rule in each step. the following is an illustration of input and rearrangement. input: politics 61 policy 116 partner 93 role 45 clear 27 38 point step i: role politics policy 116 partner 93 45 clear 27 38 point 61 step ii: role clear politics policy partner 93 45 27 38 point 116 61 step iii: role clear partner politics policy 93 45 38 point 27 116 61 step iv: role clear partner politics policy 93 38 point 45 27 116 61 step v: role clear partner politics point policy 93 38 45 27 116 61 step v, is the last step of the above arrangement as the intended arrangement is obtained. as per the rule followed in the given steps find out the appropriate steps for the given input. input: energy 54 78 place 23 issue 211 145 flat rent taxi 17in step iii, what is the difference between fifth element from left and second element from right? hello, 

this code checks to see if the diagonal elements of a given matrix a (assuming n x n) are larger in magnitude than the sum of the magnitude of the non-diagonal elements in its row.

line by line explanation:

the first line loops through all the rows of a.

 for i = 1:n

the second line is defining j = [1 2 3 ... n], so a vector containing 1..n,
 
 j = 1:n;

the third line is removing the diagonal element, aka, the ith row and this removes the ith column, so the i,i th element,
 
 j(i) = [];

the fourth line takes the absolute value of all the elements in the ith row of a, excluding the diagonal element: a(i,j) = a(ith row, elements 1,2,...,i-1,i+1,...,n) since we removed the ith element from j previously.
 
 b = abs(a(i,j));

the fifth line computes the absolute value of the diagonal element minus the sum of the absolute value of all the other elements in the row. if check is positive, we know the magnitude of the diagonal element was greater than the sum of all the magnitudes of the other elements in its row.
 
 check(i) = abs(a(i,i)) - sum(b);

the sixth line checks if it's less than zero, in which case the diagonal elements magnitude is not greater than or equal to the sum of the magnitudes of the other elements.
 
 if check(i) < 0

if this is the case, the matrix is not strictly diagonally dominant, which the seventh line prints.
 
 fprintf('the matrix is not strictly diagonally dominant at row %2i

',i)

the eighth and ninth lines end the cycle.
 
 end
 end

sorry if this was too much detail,

hope this helps! 10.1 sequences polynomials: easy to evaluate, integrate, diﬀerentiate general functions: -a sequence is a list of #s -sequences are written as: -many series correspond to functions formally, the sequence converges to l if for every positive number , there corresponds an integer n such that for all dear student
red is coded as 2076
which means
r=20
e=7
d=6
now lets us number the alphabets as follows
a=1
b=2
c= 3
d= 4
e= 5




r=18


y=25
z=26

now according to the question
r=20=18+2
e=7=5+2
d=6=4+2

therefore we can say that
g = 7+2 =9
a=1+2=3


gag will be coded as 939


regards
â€‹â€‹â€‹â€‹â€‹â€‹â€‹ HM ok, another day, another try, but I gotta say: The seemingly endless lessons about numbers and numbers on top of numbers and more numbers are really disencouraging me a lot. It's been a lot of fun up to this point, but I really don't see the point in filling out so much about numbers for the sake of numbers o\_o Could you, like, do a little less of that? All whitespace: `/\s/g`  

All non-alphanumerics: `/[^a-zA-Z0-9]/g` ?solution:

step 1
in this problem we need to clarify why shaker sort is efficient for sorting lists that are already in close to the correct order.
step 2
shaker sort is a sorting algorithm which compares pairs of adjacent elements, interchanging them if they are not in order. it moves one element at a time till it has reached its proper place in the ordered list by comparing element adjacent to it and also it sorts elements in both directions as it passes through the list. 
for a list that is already close to the correct order, shaker sort will only find the elements that are not in correct place and then put these elements in its correct position. since there are going to be a few elements which are not in their correct position therefore it will take less time for shaker sort to correct the order of the elements. histogram  divide data o equal width o no overlapping  bar chart o skew­ pulls direction of mean o symmetric numeric summary center, spread, and location  greek letters for population  roman letters for statistics 1. mean  µ= population mean  x bar= sanple mean o ∑ xi  all over n= sample mean  k=0 2. mean vs. median a. mean used the most b. n is small when outliers occur c. use median, mean is too affected spread 1. range (max­min) a. sensitive to outliers 2. iqr a. not sensitive to outliers variability­ xi­x bar I'm not going to go through all of your code because I'm in a hurry, but this should simplify it quite a bit. At a minimum it will make it easier to read.



```
alphabet = ['A','B','C','D'....etc]
count = 0
infile = open('infile.txt','r')
for character in infile.readlines():
    if character in alphabet:
        count += 1

print count
```