rank each satellite based on the net force acting ...
rank each satellite based on the net force acting on it. rank from largest to smallest.1. m = 100kg, l = 2500m, v= 160 m/s2. m = 300kg l = 10000m, v= 80 m/s3. m = 400kg l = 2500m, v= 80 m/s4. m = 200kg l = 5000m, v= 160 m/s5. m = 800kg l = 10000m, v= 40 m/s6. m = 200kg l = 5000m, v= 120 m/s
centripetal force:f=mv2rr is equal to l in this question.1. f = (100)(1602)/2500 = 1024 n2. f = (300)(802)/10000 = 192 n3. f = (400)(802)/2500 = 1024 n[readmore]4. f = (200)(1602)/5000 = 1024 n5. f = (800)(402)/10000 = 128 n6. f = (200)(1202)/5000 = 576 n1 = 3 = 4 > 6 > 2 > 5the order of forces acting on the satelites from the largest to the smallest is 1 = 3 = 4 > 6 > 2 > 5
hi trinity, let's do this one!newton's famous second law states, in math terms: f = ma applying to the first case, we have: 100 = m(4.00) => m = 100/4 = 25 kgnow apply the formula to the second case: f = 25 x 16 = 400 newtons one pascal is defined as the 1 newton force applied on an area of 1 m2. it is the si unit of pressure. also 1 pa = 1 kg. 1.5 kg = 1.5 × 1000 g = 1500 g∴ ratio of 1.5 kg to 2500 g= 1500 g : 2500 g = `1500/2500` = `3/5` = 3 : 5 (a) f = 1/t = 2.11 hz

(b) 2*pi*f = 13.26 radians/s = sqrt(k/m)
m = 0.296 kg
solve for k
(c) (1/2)ka^2 = 0.150 j
solve for amplitude a, in meters please check below with your carrier

4g bands 
4g fdd-lte: b1(2100),b2(1900),b3(1800),b4(aws),b5(850),b7(2600),b8(900),b12(700),b13(700), b18(800),b19(800),b20(800),b25(1900),b26(850),b28(700) / 
4g tdd-lte: b34(2010),b38(2600),b39(1900),b40(2300),b41(2500... u (initial velocity) = 18 km/hr 
t ( time )= 2.5 sec
v( final velocity) = 0 m/s
from, the first equation of motionv = u +  a×t0 = 5 +  a×2.5a = - 2 m/s2 the centimetre (cm) is a unit of length in the metric system, equal to one-hundredth of a meter. the millimetre (mm) is a unit of length in the metric system, equivalent to one-thousandth of a meter and is the si base unit of length. 1 mm = 1/10 cm 1 mm = 0.1 cm to convert the unit of length in millimetres to centimetres follow the below steps: take the value of length in millimetres and multiply it by 0.1 cm the obtained value is the answer in centimetres 25mm x 0.1cm= 2.5 cm answer hence, 25 mm = 2.5cm excess baggage on your flight home is often the best, most practical, and almost cheapest option, depending on airline. for postal service which is usually the cheapest, there is maximum size / weight restriction. for sea freight, you have to find a freight forwarder, usually located somewhere outside tourist area. you have to pay for pick up, or deliver the bags yourself to the forwarder. there is also the issue of minimum charge, additional packaging, ... for l5 i’ve seen 115 to 120k base and 30-50k rsu from the figure:total resistance of the circuit, r = (rab + 15) ω = 20 ωcurrent in the circuit , \[i = \frac{v}{r} = \frac{8}{20} a\] ∴ voltage across ab, vab = i.rab = 2 vthe emf of the cell connected as above is given by: \[e = \frac{l}{l} v\_0\] here:l = 60 cm (balance point)ab = l = 1 m = 100 cm (total length of the wire) \[\therefore e = \frac{60}{100}\left( 2 \right) = 1 . 2 v\]