plz answer asap 33 a man travels 600km partly by train and partly by car if he covers - maths - simultaneous linear equations
plz answer asap
33 a man travels 600km partly by train and partly by car if he
covers 120km by train and the next by car, it takes him 8 hours
but, if he travels 200km by train and the rest by car he takes 20
minutes longer find the speed of the car and that of the
train
let the speed of train = x km /hlet the speed of car = y km/hcase 1 : 120 km by train and 480 by cartime taken to travel 120 km by train = 120x hrstime taken to travel 120 km by car = 480x hrsaccording to first condition :120x + 480y = 8⇒1x + 4y = 115     
1case 2 : 200 km by train and 400 by cartime taken to travel 200 km by train = 200x hrstime taken to travel 400 km by car = 400x hrsaccording to second condition :    200x + 400y = 82060 = 813 = 253         as, 20 min = 2060 hr = 13 hr⇒1x + 2y = 124     
2subtracting 2 from 1, we get      2y = 115 - 124⇒2y = 8-5120⇒y = 80now, from 1, we get    1x + 480 = 115⇒1x = 11 - 120 = 160⇒x = 60so, speed of train = 60 km/hspeed of car = 80 km/h
hint: here, we will proceed by finding out the relative speed between the two cars and then using the formula i.e., time taken$ = \dfrac{{{\text{distance travelled}}}}{{{\text{speed}}}}$ to determine after how many hours these cars will meet each other.complete step-by-step answer:given, distance between the two cars d=160 kmstarting time for both the cars when they left their respective initial positions a and b is 8:10 amspeed of the first car, x=50 km per hourspeed of the second car, y=30 km per hourin order to obtain the relative speed between these two cars which are moving towards each other (i.e., in opposite directions), the individual speeds of these cars will be added.so, the relative speed between the two given cars, r= x+y=50+30=80 km per houras we know that, time taken$ = \dfrac{{{\text{distance travelled}}}}{{{\text{speed}}}}$so, time when both the cars will meet=$\dfrac{{{\text{initial distance between both the cars}}}}{{{\text{relative speed between the cars}}}} = \dfrac{{\text{d}}}{{\text{r}}} = \dfrac{{160}}{{80}} = 2$ hours.after 8:10 am, both the cars which are initially at different places a and b will meet each other in the next 2 hours.therefore, time when they will meet each = 8:10 am + 2 hours = 10:10 amhence, option a is correct.note: in this particular problem, since the given two cars are moving in opposite directions (or moving towards each other) that’s why the individual speed of the cars are added in order to determine the relative speed between them but if they were moving in the same direction then the relative speed between these cars would have been obtained by subtracting the individual speed of these cars. karan facing towards south moved straight 2 km and from there, turned to his right 90&ordm; and travelled 2 km. then, he took a 45&ordm; turn to his left and travelled 1 km. where would he be now with respect to the starting point? amy takes an hour so she does
1/60 of yhe job per minute
father takes 30 mins so he does
1/30 of the job per minute
 
together they complete
1/60 + 1/30 per minute 
or 3/60 of the job per minute
 
(3/60)x = 1
x = 60/3
x = 20 minutes this depends upon the type of trekking and which route your are going for trekking, but usually not more than seven hours per day. once you reach to 3000m you will walk for six hours. u (initial velocity) = 18 km/hr 
t ( time )= 2.5 sec
v( final velocity) = 0 m/s
from, the first equation of motionv = u +  a×t0 = 5 +  a×2.5a = - 2 m/s2 miles/hour is just that.
 
(3/4)/(1/12) = (3/4)(12) = 9 mph a) Let's find z - score:  
z = (x-mu)/sigma = (40,000-47,000)/4,000 = - 1.75  
p-value for z = 1.75 is 0.0401, for estimating the percent of the tires which last for at least 40,000 miles we have to consider right side of the distribution:  
P(x > 40,000) = (1-P(x < 40,000))*100% = 95.99 %  
  
  
b) the percent of the tires which are not last for at least 40,000 miles would be equal to P (x < 40,000) = 0.0401*100% = 4.01 %;  
c) for more than 50,000 miles   
z = (50,000-40,000)/4,000 = 2.5  
the probability would be  
P(x>50,000) = 00.62 % the straight distance between two place on a map can be measured by a strip of paper and divider.use a ruler to measure the distance between the two places. if the line is quite curved, use a string to determine the distance, and then measure the string. find the scale for the map you're going to use. it might be a ruler bar scale or a written scale, in words or numbers. (a) to my eye, they never have a common speed. that would require the two curves to have the same slope at the same time, which doesn't appear to me to be true.

(b) b is ahead of a but is slowing down and being passed by a, which has been moving at constant speed.

(c) b has an acceleration with greater magnitude. (in fact, the curve for a doesn't show any acceleration at all.)

(d) a has a constant slope, and therefore a constant velocity (and therefore displays no acceleration at all). b starts ahead of a initially with a velocity greater, but then decelerates as it nears t = 4 s. at around t = 3.7 s, b's velocity (slope) has nearly dropped to zero, and it gets passed by a.

if you find this helpful, please select favorite answer! (i) here current (i) = 1 a, resistance (r) = 300 ohm, time(t) = 1hwe know thatp = i2r = 12 x 300 = 300 we = p x t = 300 x 1 = 300 wh(ii) here current (i) = 2 a resistance(r) = 100 ohm, time (t) = 1hwe know thatp = i2r = 22 x 100 = 400 we = p x t = 400 x 1 = 400 whhence, in case (ii), the electrical energy consumed per hour is more.