unexpected integer overflow
with the following model (if you can even call it that):

model {

for(k in 1:10) {

print(k - 10);

}

}

the output represents what appears to be integer overflow. i am using cmdstanr\_0.0.0.9008 with stan 2.23. other relevant sessioninfo:

r version 3.6.1 (2019-07-05)

platform: x86\_64-…
hi,

sorry you are having issues with this. this is a known bug that was fixed in 2.24. the index of the loop is of an unsigned type in the generated c++ in 2.23. and since there are no negative numbers in unsigned types -1 becomes max integer.

issue where we found this: [https://github.com/stan-dev…](https://github.com/stan-dev/stanc3/issues/536)
the compiler will throw the following errors:  


10: error: increment of read-only variable **k**,  


12: error: **lvalue** required as increment operand. Dear Sir,   

I has change the printer cartridge. After changing the printer cartridge above mentation comming. When I am making printer power on the (10.10.00 supply memory error) display. Please tell me how to solve this problem. Best regards,   

  

Thanking   

Ajom Khan Hero  

Mobil No.092 5192797.  

Al Nahr Co.Ltd  

Tripoli - Libya you can use the repmat function here
if you have to print the patter n (here 10) times, use the following code:
a = [5 4 3 2 1 0]';
n = 10;
b =repmat(a, n,1) You need to give the user the option of typing in a value that represents that there are no more values to enter. Perhaps give a prompt like:



```
Please enter a value.  Enter -999999 if you have no more values [B]:[/B]
```

As for the ten (or fewer) values, you should probably have an array and a loop instead of ten separate variable names and ten separate cin statements. So you're looking at something like this:



```
double dValue[10];
    int numEntries = 0;
    double sum = 0;
    
    while (numEntries < 10)
    {
          cout << "Enter number (-999999 to stop) : ";
          cin >> dValue[numEntries];
          // check whether dValue[numEntries] == -999999
          // if so, short-circuit the loop with the "break" command
            
          // increment numEntries
          // adjust sum
    }
```

As a side note, I picked -999999 as the value to represent no more values because



1. It's an integer, so it can be represented exactly as a double (no round-off error using == to compare).
2. It's a number that, chances are, people wouldn't actually want to add, so it's sort of "out of the way". Chances are, few people want to add -999999. If they do, they can't use this program! ```
#!/usr/bin/perl
use strict; 
use warnings; 

my $gia = '12tai';

#Capture sequence of digits into one variable,
#capture sequence of non-digits into another variable
my ($number, $name) = $gia =~ m/(\d+)(\D+)/;

print "$number $name\n";#Two values separated by one space
``` okay, i think i found out what is happening: <https://github.com/drtimothyaldendavis/suitesparse/issues/45> Something like the following code should do the trick, provided you complete it (just plan 'A' is covered') and make it robust.  

  


```
#include<stdio.h>

int get\_description(const char type\_plan[], const char ** description, const char ** claim\_limit )
{
  int result = 0; // 0 is 'success' , non-zero is 'failure' 

  switch (type\_plan[0])
  {
  case 'A':
    *description = "Room Charges 150/day\nIntensive Care Unit (ICU) Charges 300/day\nHospital Supplies and Services : As charged. Subject to approval by EZMediLife. Surgical Fees\n";
    switch(type\_plan[1])
    {
    case '1':
      *claim\_limit = "Annual Claim Limit 100.000\n";
      break;

    case '2':
      *claim\_limit = "Lifetime Claim Limit 500000\n";
      break;

    default:
      result = -1;
      break;
    }

    break;
  case 'B':
    //...

  case 'C':
    //...

  default:
    result = -1;
    break;
  }

 return result;

}


int main()
{
  const char * plane[]  = { "A1", "K3", "A2" }; -- test planes

  for ( size\_t n=0; n<sizeof(plane) / sizeof(plane[0]); ++n)
  {
    const char * description, * claim\_limit;
    if ( get\_description( plane[n], &description, &claim\_limit) == 0)
    {
      printf("plane %s: %s%s", plane[n], claim\_limit, description);
    }
    else
    {
      printf("unknown plane %s\n", plane[n]);
    }
    printf("\n");
  }
  return 0;
}
``` It' just standard c++ ifstream and ofstream. When the program starts, try to open the file, if it success then read it. >printf("%c", len\_char); //<this does not print anything too!!  

What did you expect it to print? You realize that the %c format modifier takes the integer value you supply and prints the character representation of that integer, right? In other words, it's not going to print '3'...ever. As long as the lengths are single digits, you can say len\_char + '0' and get the correct representation, but once the length exceeds 9, you're SOL with this method. sometimes one or both of these patches help, especially if the system is showing high ram and/or cpu usage when checking updates:
https://support.microsoft.com/en-us/kb/3050265




https://support.microsoft.com/en-us/kb/3102810﻿﻿
﻿