find the solution of each of the following initial-value problems.yl'+y'+y=h,(t)-hh(t); | studysoup
find the solution of each of the following initial-value problems.yl'+y'+y=h,(t)-hh(t); y(o)=l,y'(o)=o
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solution: `ch\_(4)(g) + 2o\_(2)(g) to co\_(2)(g) + 2h\_(2)o(g) + "heat. (evolved)"` answer: `4+1+(1)/(4)+(1)/(6)+...`
solution: n/a y = 3x

It can be observed that x = −1, y = −3 and x = 1, y = 3 are solutions of the above equation. Therefore, the solution table is as follows.



| x | -1 | 1 |
| y | -3 | 3 |

The graph of the above equation is constructed as follows.

![](https://www.sarthaks.com/?qa=blob&qa_blobid=15681428413536225923) switch x and y, then solve again for y:

x = 3y+12
x-12 = 3y
(x-12)/3 = y

or,

y = x/3 - 4 answer: `(x-1)/(3)=(y+2)/(-4) =(z-3)/(5) , vec( r) =(hat(i) -2hat(j) +3hat(k)) +lambda (3hat(i) -4hat(j) +5hat(k))` a - ii, b - iv, c - i, d - iii start with 50 easys. if you solve those quickly, then move into mediums. hards are pretty tricky tbh i just attempt then peek answers/memorize lol to find: limitsnote: first check the form of imit. used this method if the limit is satisfying any one from 7 indeterminate form.in this case, indeterminate form is formula used: = 1so, by using the above formula, we have = = therefore, = solution: ` x = {:((-4/5,-1),(2/5,1)):}` >> [x,y] = ismember(a,b);
>> [~,z] = sort(y(x));
>> v = find(x);
>> r = reshape(v(z),2,[]).'
r =
 2 9
 4 8
 5 7