which base, ch3nh2 or (ch3)2nh, is the stronger ba...
which base, ch3nh2 or (ch3)2nh, is the stronger base? which conjugate acid, (ch3)2 nh2 + or (ch3)2 nh3 + , is the stronger acid?
ch3nh2 will appear as a stronger base since n for (ch3)2nh has bulkier substituents that will block n from accepting extra h (bl base = proton acceptor)[readmore]since ch3nh2  is the stronger base than (ch3)2nh, its c.acid will be weaker compared to (ch3)2nhstronger base → ch3nh2 stronger c.acid → (ch3)2nh3+
a) 3ag + 4hn03 > 3agno3 + no + 2h2o

b) mno2 + 4hcl > 2h2o + mncl2 + cl2 it is best to see doc for proper evaluation and treatment. there are otc med and rx med but work differently for different pts. one may respond better to you may not respond good with other pts.doctor can help you to find the causes of your chronic acidity such as stress, diet etc.. see more... reno, please don't answer organic chemistry questions if you don't know the subject matter.
 
mixing acetic acid with sodium bicarbonate doesn't yield "gaseous water." also, you didn't actually answer the question and decided instead to list the first thing you found in wikipedia about a dangerous reaction that has nothing to do with the fact that acetic acid and hcl react the same way because they are both stronger acids than the conjugate acid of bicarbonate. * the strongest antibiotic is probably vancomycin. the highest division of an antibiotic is between a bactericidal antibiotic and a bacteriostatic antibiotic. NaBr   

  

SO3   

  

CaCl2   

  

Mg3N2 according to ncert answer would be option (1)and

but according to general chemistry answer would be (3)andoption 1)and





option 2)andoption 3)andoption 4)and cao solid + liquid mixture : sand and water, charcoal and water. a) ans. concentration = no. of moles of solute * 1000/ vol. in m;

no. of moles of solute = concentration * vol / 1000 = 1.4 * 270 / 1000 = 0.378 = 0.378 mol.



b)

molality = 1.65

molality = moles of solute / mass of solvent in kg

1.65 = moles of solute / 5.5 x 10^-5 kg

moles of solute = 9.075 x 10^-5

c)

mass of sucrose = 75 x 1.4 / 100 = 1.05g

moles = 1.05 / 342 = 3.07 x 10^-3 c5h10 can have a double bond because it satisfies the general formula for alkenes i.e., cnh2n. here, there are 5 carbon atoms; hence, n is 5. substituting n in the formula cnh2n, we get, `c\_5h\_(2xx5)=c\_5h\_10` use the ka equation: 
take the acid as ha
this will dissociate : 
ha ↔ h+ + a- 
ka = [h+] [a-] /[ha] 
because dissociation is very small we can use 0.1m for [ha] 
[h+] = 2/50*0.1 = 0.0004m 
[a-] = 0.0004m 
 ka 0.0004 * 0.0004 / 0.1 
ka = 1.6*10^-5 * 0.1 
ka = 1.6*10^-4