what is the total distance travelled by a steel ball which is dropped on a floor from a 10 m high ce&#8230;.
what is the total distance travelled by a steel ball which is dropped on a floor from a 10 m high ceiling, if it jumps up to half the height of the previous jump after every collision with the floor?
what is the total distance travelled by a steel ball which is dropped on a floor from a 10 m high ceiling, if it jumps up to half the height of the previous jump after every collision with the floor?
Δl =l αΔt =2 •10⁻²•14•10⁻⁶•70=1.96•10⁻⁵m=1.96•10⁻² mm eliminte ?, 1) if x=3 sec ? + 4 tan ? and y=4 sec ?- 3 tan ?. 2) the angles of dipression of the top and bottom of 8 meter tall building from the top of multistoried building are 30â° and 45â° respectively.find the height of multistoried building and the distance between two buildings (?3=1.73) floor lamps should have an overall height of roughly 58”-64” (147-163 cm) based on the standard sitting height of a person on a couch or chair. the bottom of the floor lamp shade should be roughly at or above a person’s sitting eye level and should try to match the edges of similar lighting fixtures within the space. kindly refer the following link for similar query
https://www meritnation
com/ask-answer/question/why-does-a-ball-rolling-on-the-ground-in-a-straight-come/science/8033135 a bob of mass m is suspended by inextensible string of length l from a fixed point. the bob is given a speed of at the bottom point. find the tension in the string when string deflects through an angle 120 degree from vertical. the centimetre (cm) is a unit of length in the metric system, equal to one-hundredth of a meter. the millimetre (mm) is a unit of length in the metric system, equivalent to one-thousandth of a meter and is the si base unit of length. 1 mm = 1/10 cm 1 mm = 0.1 cm to convert the unit of length in millimetres to centimetres follow the below steps: take the value of length in millimetres and multiply it by 0.1 cm the obtained value is the answer in centimetres 25mm x 0.1cm= 2.5 cm answer hence, 25 mm = 2.5cm u (initial velocity) = 18 km/hr 
t ( time )= 2.5 sec
v( final velocity) = 0 m/s
from, the first equation of motionv = u +  a×t0 = 5 +  a×2.5a = - 2 m/s2 a large plastic plate and copper plate is an example of infinite long plates.as we know,the electric field due to infinite long sheet is whereσ is the surface charge density of the thin conducting sheetε0 is the permittivity of the free spacethe electric field due to the plastic plate is 10 vm-1thus, the electric field for the copper would be same as that of the plastic plate.the electric field of the copper plate id 10 vm-1 heat lost by the vessel and water= [150 x 4.2 x (30 - 5) j + 100 x 0.4 x (30-5)] j = (150 x 4.2 x 25 + 100 x 0.4 x 25) j = (15,750 + 1000) j= 16,750 j heat gained by ice to change into water at 0 °c = m x specific latent heat of fusion of ice = {m x 336} heat gained by water to come to final temperature (5 °c) = m x specific heat capacity of water x final temperature = (m x 4.2 x 5) = 21m if there is no loss of heat to the surroundings, according to the principle of calorimetry: heat gained by ice to melt and come to final temperature = heat lost by vessel and water or 336m + 21m= 16,750 or 357m = 16,750 or m = 16750/357 = 46.92 ![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/4110270/2012_11_30_15_28_05/vvnzofse6383734697724592802%20png)


let the length of path be a m


total area ![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/4110270/2012_11_30_15_28_05/ceaxujzx7923478049123545928%20png)


area of lawn = total area â€“ area of
path

![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/1800204/2012_12_04_21_09_56/mathmlequation2002748073868866733%20png)


area of lawn


![](https://s3mn%20mnimgs%20com/img/shared/discuss_editlive/4110270/2012_11_30_15_28_05/dwqusyms3311632565229211681%20png)