draw the structures of esters with the formula \[{c\_3}{h\_6}{o\_2}\].
hint: at first think about the structure of ester so that you are able to draw the structure for a given molecular formula. the structure of ester is $r - co - o - r'$.complete answer:an ester is a chemical compound derived from an acid in which at least one –oh group is replaced by an $ - o - $ alkyl group. esters are generally derived from substitution reactions of a carboxylic acid and an alcohol which is also known as an esterification reaction. from the given molecular formula we can draw only two structures of esters. they are ethyl formate and methyl acetate. their structures are $h - co - o - c{h\_2} - c{h\_3}$ and $c{h\_3} - co - o - c{h\_3}$.additional information:esterification is the process of combining carboxylic acid and alcohol to give at least one ester and water.$r - co - oh + r - oh \rightleftharpoons r - co - o - r' + {h\_2}o$in the above reaction, the forward reaction gives us esterification and the backward reaction gives us hydrolysis of the ester. the hydrolysis of esters in the presence of alkalis such as potassium hydroxide (lye) or sodium, a reaction called saponification which is utilized in the preparation of soaps from fats and oils and is also used for the quantitative estimation of esters.note:esters are common in organic chemistry and biological materials, and often have a pleasant characteristic, fruity odor. this leads to their extensive use in the fragrance and flavor industry. ester bonds are also found in many polymers.
solution: `ch\_(4)(g) + 2o\_(2)(g) to co\_(2)(g) + 2h\_(2)o(g) + "heat. (evolved)"` sin(theta) = d, 
cos(theta) = a, 
tan(theta) = h, 
csc(theta) = f, 
sec(theta) = c, 
cot(theta) = g. in this we are asked to divide it in 2:3 ratioso, 3+2 = 55, number congruent of line segment is formed.i. firstly, we have to draw a line segment ab of length 7 cm. draw a line with an acute angle from point aii. point the compass on a, and cut the new line with some radiusplace the compass along the line and make 5 arcs. since we need 5 congruent parts, and name the last one as “g”iii. take length of bg as radius draw an arc from a just below it.again, take the length of ag as radius and draw an arc which cuts the previous arc from b, name the intersection point as hconnect b and hiv. taking the same length that we used in line ag, draw arcs along bh and name the points.v. connect the points along ag and bh. name the intercepts on the line ab as m, n, o & p.vi. thus we can divide a line segment as ao:ob = 6:4= 3:2 a - ii, b - iv, c - i, d - iii answer: `1.8706 xx 10^(11) " erg", 4477 cal` if the figure below represents a parabola, identity the physical&nbsp;quantities Straight lines The next shapes in the ‘growing’ pattern are as follows:


![](https://mathsgee.com/?qa=blob&qa_blobid=5951663371716016349) \[\ce{fecl2 +2naoh -> fe(oh)2 + 2naci}\] answer: `4+1+(1)/(4)+(1)/(6)+...`
solution: n/a