if the ratio of e
dihybrid crossratio in f2 generation of a dihybrid cross is always 9:3:3:1
if e is any event associated with an experiment, then Total no. of possible outcomes = 30 {1, 2, 3, … 30}  

  

E ⟶ event of getting no. divisible by 3.  

  

No. of favourable outcomes = 10 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30}  

  

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)  

  

P(E) = 10/30 = 1/3  

  

Bar E ⟶ event of getting no. not divisible by 3.  

  

P(Bar E) = 1 – P(E)  

  

= 1 - 1/3 = 2/3 The binding energy in H atom

![](https://www.sarthaks.com/?qa=blob&qa_blobid=791640890598547334)

If proton and neutron had charge e' each and were governed by the same electrostatic force, then in the above equation we would need to replace electronic mass m by the reduced mass m' of proton-neutron and the electronic charge e by e' .

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![](https://www.sarthaks.com/?qa=blob&qa_blobid=8859059287291380947) f you seem to be missing some information about e.if e is the midpoint between d and f, thene is (1,1) take half of (4-2) = 1 and half of (5-3) = 1e alphabetically does come between d and f.just average the x values and average the y values of the two points d and for plot them graphically, carefully, maybe on some graph paper, and you'llvisually see the midpoint is at (1,1) if , passing through (1, 2), satisfies the differential equation , then correct option is a) right electrode will increase answer: k=7 the right option is d) pure i = ke/r
30 = 120k/16
k=4
now you can answer the question when you have fixed the typos.