equation for carboxylic acids and their derivatives
write an equation for the reaction of ethanoic acid with sodium carbonate. how does this reaction compare with that of hydrochloric acid with sodium carbonate?
 
they look into: what does this tell you about the chemical properties of carboxylic acids?
reno, please don't answer organic chemistry questions if you don't know the subject matter.
 
mixing acetic acid with sodium bicarbonate doesn't yield "gaseous water." also, you didn't actually answer the question and decided instead to list the first thing you found in wikipedia about a dangerous reaction that has nothing to do with the fact that acetic acid and hcl react the same way because they are both stronger acids than the conjugate acid of bicarbonate.
we are being asked to classify the following reactions based on the following categories:combination/synthesis → multiple reactants combine to form a single productw/o change in oxidation numbersa + b → abdecomposition →reactant splits into multiple products with no change in oxidation numbersab → a + bcombustion reaction: reaction with oxygen that produces carbon dioxide and waterhydrocarbon + o2 → co2 + h2osingle displacement →single element displaces another element in a compoundab + c → ac + b[readmore]let’s analyze the given reactionsa. fe2(co3)2 (s) → fe2o3(s) + 2co2(g) break down of fe2(co3)2(s) to its component ions → decomposition reactionanswer: this is a decomposition reaction.b. 2 c6h11oh(l) + 17 o2(g) → 12co2 (g) + 12h2o(l) reaction with oxygen that produces carbon dioxide and water → combustion reactionanswer: this is a combustion reaction.c. p4o10(s) + 6h2o(l) → 4h3po4(aq) two or more substances combine to form a single compound → combination reactionanswer: this is a combination reaction.d. 2c(s) + mno2(s) → mn(s) + 2co(g) substitute one element for another element in a compound →single-displacement reaction answer: this is a single-displacement reactione. 2naclo3 (s) → 2nacl(s) + 3o2(g)break down of compound into its simpler substances → decomposition reactionanswer: this is a decomposition reaction kclo3(s) — heat→ kcl (s) + o2(g)      reactant        productk        1                   1cl       1                   1o       3                    2[readmore]2 kclo3(s) — heat→ 2 kcl (s) + 3 o2(g)      reactant        productk        2                   2cl       2                   2o       6                    6the balanced equation for the reaction is 2 kclo3(s) — heat→ 2 kcl (s) + 3 o2(g) i. given:valency of carbon is 4valency of chlorine is 1by applying criss-cross method:formula: ccl4thus, the formula for carbon tetrachloride is ccl4.ii. given:valency of element x is 1valency of oxygen is 2by applying criss-cross method:formula: x2o we’re being asked to determine the conjugate acid of o2-.recall that the conjugate acid of a base is simply the compound formed when a base gains a proton (h+). it's considered as an acid because it can lose h+ to reform the base.[readmore]for o2–, simply add a hydronium ion from the formula. note that we also need to add the +1 charge of the proton (h+) to o2–, giving our conjugate acid a net charge = -1.o2– + h+ → oh–  –2    +   1     =       –1this means the conjugate acid of o2– is oh–. hydrocarbons are the compounds of hydrogen and carbon. they are the simplest of all the organic compounds.hydrocarbons are of two types:(i) organic (ii) inorganic use the ka equation: 
take the acid as ha
this will dissociate : 
ha ↔ h+ + a- 
ka = [h+] [a-] /[ha] 
because dissociation is very small we can use 0.1m for [ha] 
[h+] = 2/50*0.1 = 0.0004m 
[a-] = 0.0004m 
 ka 0.0004 * 0.0004 / 0.1 
ka = 1.6*10^-5 * 0.1 
ka = 1.6*10^-4 we are going to do the following steps:step 1: determine the classification of the compoundstep 2: write the formula of the compound[readmore]step 1: determine the classification of the compoundrecall the definition of the following:ionic compound - usually made up of a metal and a non-metalcovalent compound - composed of more than one nonmetal togetheracid - substance whose molecules yield hydrogen ions (h+) when dissolved in waterhydrate - substance that contains water or its constituent elementsfor cobaltic iodidecobaltic – metaliodide – nonmetalmetal + nonmetal = ionicstep 2: write the formula of the compoundthe rules for naming ionic compounds are as follows:1. the metal keeps its name and is named and written first.– for transition metals, we use roman numerals to denote its charge.2. the nonmetal keeps its base name but has its ending changed to –ide.for cobaltic iodidecobaltic  → transition metal → +2 charge → co2+iodide → group 7a → -1 charge → i-criss-cross the charges and make them the subscript of the other ioncobaltic iodide → coi2answer: cobaltic iodide is an ionic compound with a formula of coi2 carbon monoxide combines with the haemoglobin of our blood. it reduces the oxygen carrying capacity of blood. we’re being asked which of the given compounds is a lewis acid and lewis base. let’s first define a lewis acid and a lewis base.based on the lewis definition:lewis acid is an electron pair acceptor.some characteristics of a lewis acid:• when hydrogen is connected to an electronegative element such as p, o, n, s or halogens▪ hydrogen gains a partially positive charge → makes hydrogen act as a lewis acid• positively charged metal ions[readmore]▪ can accept negative electron pairs → can act as lewis acids• central element that has less than 8 valence electrons around it▪ more likely to accept an electron pair to follow the octet rule▪ can accept electron pair → can act as lewis acidlewis base is an electron pair donor.some characteristics of a lewis base:• compounds that have lone pair(s) on a central element can act as lewis bases. • compounds that possess a negative charge can act as lewis bases. let’s draw the lewis structure of each given compound and check which of them can act as a lewis acid and lewis base.step 1: determine the central atom in this molecule.step 2: calculate the total number of valence electrons present.   step 3: draw the lewis structure for the molecule.a) cs2step 1: determine the central atom in this molecule.c is less electronegative than s → c will be the central atomstep 2: calculate the total number of valence electrons present.                group             valence electronsc         4a                   1 x 4 e‑ = 4 e-s         6a                   2 x 6 e‑ = 12 e-              total: 16 valence e- step 3: draw the lewis structure for the molecule• c has a total of 8 e- electrons around it and has a lone pair→ complete octet▪ can act as a lewis acidb) sh−step 1: determine the central atom in this molecule.only two atom → no central atomstep 2: calculate the total number of valence electrons present.                group             valence electronss         6a                   1 x 6 e‑ = 6 e-h        1a                   1 x 1 e‑ = 1 e-from -1 charge:                     +1 e-              total: 8 valence e- step 3: draw the lewis structure for the molecule▪ has a negative charge▪ can act as a lewis baseanswer: sh- is the lewis base and its lewis structure is cs2 is the lewis acid and its lewis structure is hi there!we are asked to determine the reaction order of a and b using the given data.recall that the rate law only focuses on the reactant concentrations and has a general form of:rate= kaxbyk = rate constanta & b = reactantsx & y = reactant ordersreactant ain order to calculate the order of the reaction with respect to a, we must look for the experimental data where the concentration of a changes while the concentration of b remains the same.trial[a] (mol/l)[b] (mol/l)initial rate (m/s)10.1000.100520.3000.1004530.1000.2001040.3000.20090the rate laws are:rate= kaxbytrial 1:5 m/s= k0.100x0.100ytrial 2:45 m/s= k0.300x0.100ysolve for x using the ratio of the two rates:***the larger rate should be on the numeratorrate 2rate 1=45 m/s5 m/s= k0.300x0.100yk0.100x0.100y• for reactions at a constant temperature, the rate constant remains the same. thus, it could be canceled out.• since the reaction order ‘y’ of b is also the same, it could also be canceled out.45 m/s5 m/s= k0.300x0.100yk0.100x0.100y9 = 3xlog 9=x·log3log 9log3=x·log3log3x=2the reaction order, x, with respect to a is 2. reactant bin order to calculate the order of the reaction with respect to a, we must look for the experimental data where the concentration of b changes while the concentration of a remains the same.trial[a] (mol/l)[b] (mol/l)initial rate (m/s)10.1000.100520.3000.1004530.1000.2001040.3000.20090the rate laws are:rate= kaxbytrial 1:5 m/s= k0.100x0.100ytrial 3:10 m/s= k0.100x0.200ysolve for x using the ratio of the two rates:***the larger rate should be on the numeratorrate 3rate 1=10 m/s5 m/s= k0.100x0.200yk0.100x0.100y• for reactions at a constant temperature, the rate constant remains the same. thus, it could be canceled out.• since the reaction order ‘x’ of a is also the same, it could also be canceled out.10 m/s5 m/s= k0.100x0.200yk0.100x0.100y2 = 2ylog 2=y·log2log 2log2=y·log2log2y=1the reaction order, y, with respect to b is 1.