by what amount does the intensity level increase w...
by what amount does the intensity level increase when you triple the intensity of a source of sound? (hint: subtract the old from the new!)

a) 9.5 db

b) 4.8 db

c) 6.0 db

d) 3.0 db

e) 12 db
4.8 db
first trimester ob ultrasound findings must be correlated with a quantitative b-hcg level. depending on the level and how it changes over time dramatically changes the interpretation of the ultrasound findings. we can do hearing tests as often as necessary. but usually not. once you have a hearing loss, if can fix it, unless there a determination in hearing, you may not need another one. see more... no minimum, there was a annual review part on tesla channel recently and off the numbers i saw without promotion, increments varied between 2.5 to 10 percent OK I figured it out, I'll put it here to help someone in the future. The key point is the pitch scale change changes the currently PLAYING sound, so it must be used after the play command.


I now have this:



```
soundSamplePlayer.play('success01')
soundSamplePlayer.voice_set_pitch_scale(0,1.2)

```

Basically in `voice_set_pitch_scale(0,1.2)` the first argument (which I have as `0`) is the index of the sound that's playing, so in my case, the first (and only) sound.


The second argument, which I'm testing with `1.2` is the scale change, so 20% higher in this case.


I hope that helps someone in the future. as the distance between the source and the metal is increased, the intensity of light decreases becausealso, the photocurrent is directly proportional to the intensity of light and also to the number of electrons emitted.hence, the curve d is the appropriate curve representing above equation. ?solution 23cq


a) equation for loop abgefa is (35.5)i1 + (6..25 = 21 v
b) equation for loop cbgedc is ( 9.25i2 - ( 6.25i3 = +15 v method a.increment() overlaps in class b.   
 therefore, regardless of the type of the variable obj, will be called the method corresponding to the actual type of the object - that is, b.increment().  
 
this method will use the variable i, declared in the same class b and having an initial value of 10.  
 
the resulting value - 11. a) ans. concentration = no. of moles of solute * 1000/ vol. in m;

no. of moles of solute = concentration * vol / 1000 = 1.4 * 270 / 1000 = 0.378 = 0.378 mol.



b)

molality = 1.65

molality = moles of solute / mass of solvent in kg

1.65 = moles of solute / 5.5 x 10^-5 kg

moles of solute = 9.075 x 10^-5

c)

mass of sucrose = 75 x 1.4 / 100 = 1.05g

moles = 1.05 / 342 = 3.07 x 10^-3 18 sq.units explanation: x2 = 12y ∴ 4b = 12 ∴ b = 3 area of triangle = `1/2 xx "ab" xx "os"` = `1/2 xx 4"a" xx "a"` = `1/2(12)(3)` = 18 sq. units is this a good answer?

when the electrons in the element are excited they jump to higher energy level and as the electrons fall back down it leave the excited state energy which is re-emitted, the wavelength of which is the emission spectrum.