refer to exercise 5. assume that the relative uncertainty | studysoup
?problem 30e


refer to exercise 5. assume that the relative uncertainty in p1, is 5% and the relative uncertainty in p2 is 2%. find the relative uncertainty in p3.
?solution:
step 1 of 2:
the intermediate pressure in a compressor is given by . the relative uncertainty of and the relative uncertainty of is 2% . we have to find the relative uncertainty in .


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step 2 of 2:


the intermediate pressure in a compressor is = ((


it is given that the relative uncertainty in , = 0.05
 
 relative uncertainty in , = 0.02


so the relative uncertainty in the intermediate presser 




 = 


 = 
 
 = 0.0269


 therefore the relative uncertainty in the intermediate presser is 0.0269 mpa.
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Total no. of possible outcomes = 30 {1, 2, 3, … 30}  

  

E ⟶ event of getting no. divisible by 3.  

  

No. of favourable outcomes = 10 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30}  

  

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)  

  

P(E) = 10/30 = 1/3  

  

Bar E ⟶ event of getting no. not divisible by 3.  

  

P(Bar E) = 1 – P(E)  

  

= 1 - 1/3 = 2/3 given : let a , b and c be three students whose chances of solving a problem is given i.e , p(a) = , p(b) = and p(c) = . p() = , p() = and p()= to find: the probability that the problem is solved .here , p(the problem is solved) = 1 - p(the problem is not solved)= 1- p( )= 1 – [p( ) p( ) p( )]= 1- []= 1 - = therefore , the probability that the problem is solved is . The answer to the question is available in the PDF file https://www.assignmentexpert.com/homework-answers/mathematics-answer-25293.pdf start with 50 easys. if you solve those quickly, then move into mediums. hards are pretty tricky tbh i just attempt then peek answers/memorize lol several ways to do this, here's one:

to go from (-6,4) to (-2,5) you need to go 4 in the x direction and 1 in the y direction. if you move again 4 in the x direction and 1 in the y direction you end up at (2, 6). that's p2 1.5 kg = 1.5 × 1000 g = 1500 g∴ ratio of 1.5 kg to 2500 g= 1500 g : 2500 g = `1500/2500` = `3/5` = 3 : 5 we know that- - - - - (i)taking 3 as common, we get3; solving only bracket term first,here a = 2a, b = 3b; putting values in eq.i}applying }}ans: - 3}note: must memorize cubes upto 12 [readmore]typed answer2no + o2 → 2no2rate=knomo2n2nd order in no → m = 23rd order overall → m + n = 3so 2 + n = 3n = 1rate=k[no]2[o2] applying and factorization, we get, also changing by reversing n and dnote: - try to factorize that term which help in reducing expression. hi,

lots of great explanations below, but i fear they might be difficult to truly conceptualize. 

let's start with a pie!

if there's a pie in front of us, that is the market. we'll call it 100 units of pie

we cut the pie in half - one piece (50 pie units) for you, and one piece (50 pie units) for me

scenario 1: we do nothing, we both have 50% market share.

scenario 2: i eat half my pie. my pie slice is now 25 units, yours is still 50 units. as a result, you have 67% of the market share and i have 33%. my "revenues" have fallen and my market share has fallen. your revenues haven't changed but you've gained market share

scenario 3: not only do i eat half my pie, but you also eat 20% of yours. still, i ate more, so even though your "revenues" are down, you've still gained market share.

scenario 4: we both get given more pie (yay). but, i get a whole other 50 units, and you only get 5 more. your "revenues" are up, but you've still lost market share!

i've created the below image for you to visualize this better (click on it to blow it up)...hope this helps!