The round-robin scheduler


Hi everyone,



Can You please help me with the **Round-Robin scheduler**   
**algorithm (C language)**



  

My program will use as a Datastructure a doubly linked list to hold



processes( I will represent my process as: Id(char*), Priority(int) ( a



process with priority n will have n CPU time slots) and a



contextaddress (char*) (address of space holding information about



the process)



My program will allow the following operation :add/new process



(assuming we want to insert the new process according to its



priority), deleting process,searching a process(by Id,by



priority),starvation (increasing the priority of a process (by one) and



changing its order to the right place-Avoiding starvation (process



waiting for too long))and execution(displaying the existing processes



Ids starting from the head of the list)



I *really need your help guys, sorry for bothering and Thank You* 



*in advance,*
How about in c++?



[http://www.1cplusplusstreet.com/vb/scripts/ShowCode.asp?txtCodeId=6877&lngWId=3](/posts/bad_link/258354?url=http%3A%2F%2Fwww.1cplusplusstreet.com%2Fvb%2Fscripts%2FShowCode.asp%3FtxtCodeId%3D6877%26lngWId%3D3)
method for handling data structures where the first element is processed first and the newest element is processed last. direction: a word and number arrangement machine when given an input line of word and numbers rearranges them following a particular rule in each step. the following is an illustration of input and rearrangement. input: politics 61 policy 116 partner 93 role 45 clear 27 38 point step i: role politics policy 116 partner 93 45 clear 27 38 point 61 step ii: role clear politics policy partner 93 45 27 38 point 116 61 step iii: role clear partner politics policy 93 45 38 point 27 116 61 step iv: role clear partner politics policy 93 38 point 45 27 116 61 step v: role clear partner politics point policy 93 38 45 27 116 61 step v, is the last step of the above arrangement as the intended arrangement is obtained. as per the rule followed in the given steps find out the appropriate steps for the given input. input: energy 54 78 place 23 issue 211 145 flat rent taxi 17in step iii, what is the difference between fifth element from left and second element from right? there is no need for a program to do that. 

here are some simple steps which you can follow:

1.right click on your taskbar and choose start task manager.

2.once task manager is opened go to "processes" tab. 

3.when at the processes tab search for .exe file. (maybe in your case it will look like loop.exe or something) 

4.once you have found it. just right-click on it and hover over to "set priority" option. 

5.here are several options. the default one will be "normal" so just set that to "below normal" or "low". (i would prefer setting it to "below normal" so that it does not act strangely) 

6.it's done now restart your program and check the amount of ram it is using.

i hope this helps you. if not leave a reply and i will figure out another solution. glad to help.:) Please see: [How do I schedule a task to update indexes?](https://qa.mythicsoft.com/14733/how-do-i-schedule-a-task-to-update-indexes?show=14733#q14733) `stream`
  




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of `PriorityBlockingQueue`
  




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follows the order `Iterator`
  




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, which according to the [documentation](https://translate.googleusercontent.com/translate_c?depth=1&pto=aue&rurl=translate.google.com&sl=ru&sp=nmt4&tl=en&u=) :



>  The iterator provided in the iterator () method is not guaranteed to traverse the PriorityBlockingQueue elements in any particular order.
> 
> 
> 


If you want order of precedence, you need `poll`
  




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items from `PriorityBlockingQueue`
  




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.



  




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```
PriorityBlockingQueue<Integer> pq = new PriorityBlockingQueue<>();
pq.add(5);
pq.add(8);
pq.add(3);

System.out.println("-- Try 1 --");
pq.stream().forEach(System.out::println);

System.out.println("-- Try 2 --");
IntStream.range(0, pq.size()).map(i -> pq.poll()).forEach(System.out::println);

        

        
        
        
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```

Conclusion (this may depend on Java implementation):



```
-- Try 1 --
3
8
5
-- Try 2 --
3
5
8

        

        
        
        
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``` as long as you write down the hierarchy manually, there’s certainly the possibility to simplify such transitive from implementations with a macro. [i’ve written one here, feel free to take a look.](https://play.rust-lang.org/?version=stable&mode=debug&edition=2018&gist=337cce675aa28e99ac030ca783c1c155) going even further one could try to use procedural macros with global state that uses annotations on the… never mind, finally solved it. i called this.engine.runrenderloop while it’s already running, therefore causing the speed to run twice, because it added a loop/callback the 2nd time.

all i need to do for the ‘resume’ part of my function is to always call this.engine.stoprenderloop() before i call t… [@najoua.abbaci](/u/najoua.abbaci)

mabye the flow can be adopted to following:

assign:

leftside: drresult (datatype: datarow)

right side:

dt\_datepv.asenumerable.orderby(function ( r ) datetime.parseexact(r(0).tostring.trim, “dd.mm.yyyy”, system.globalization.cultureinfo.currentuiculture.datetimeformat)).last()

so… hey [@fastwayjim](/forum/u/fastwayjim)

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