can someone explain why there are trails for the ellipse?
<https://p5js.org/examples/structure-create-graphics.html>
because each time fill() is invoked it is only applying 0.047% opacity over what was previously drawn. draw() runs aprox 60 times per second …
The next shapes in the ‘growing’ pattern are as follows:


![](https://mathsgee.com/?qa=blob&qa_blobid=5951663371716016349) Here's the diagram you requested. All the best!  

Greg  

![I need a serpentine belt routing diagram for a - c528ac5.gif](http://i.fixya.net/uploads/images/c528ac5.gif) [@sunlightworking](/u/sunlightworking) this is only a start but you could have fun using subd to model it, break the shape into 2 repeating ‘arms’ that then join together.

[[viewcapture20210611\_093810]](https://aws1.discourse-cdn.com/mcneel/uploads/default/original/4x/b/9/e/b9ec0eea392ef36150b75631db22d3817573de5b.jpeg "viewcapture20210611_093810") <https://docs.glideapps.com/all/reference/components/lists/inline-list#only-show-a-few-items> one idea can be videos have frames so, vectorize each frame and calculate dtw between two consecutive frames. this will help in gaining the difference in each frame and perhaps help in classification. hope this helps you. Hi Uwe, You can make inside/outside strokes on non-closed paths using custom width profiles. Use thhe width tool (Shift+W) to make a stroke like this (hold alt to edit only one side of the stroke at a time): Then save it as a profile (bottom of the stroke panel). After that I think your path should be easy to make. :roll\_eyes:

[[image]](https://aws1.discourse-cdn.com/business6/uploads/dynamobim/original/3x/6/3/6393f7d9277c8a0ff2b48f07b1e2352f69f463b0.png "image")

t1 = [9, 9, 99, 9, 6, 7, 8];

t9 = dscore.list.chop(t1, 3);

a = t9;

t2 = get.valueatindex(a, 0);

t4 = [3, 2];

t10 = dscore.list.ofrepeateditem(t4, 3);

a1 = t10;

t3 = get.valueatindex(a1, 0);

t11 = t2<1l> + t3<1l>;

a2 = t9;

t5 = get.valueatindex(a2, 1);

a3 = t10;

t6 = get.valuea… okay, i think i found out what is happening: <https://github.com/drtimothyaldendavis/suitesparse/issues/45> not understood actually. plz clarify in detail without a specific situation, you can trivially get paths count by doing:

list length > trim tree > list length …

(se hai tastiera italiana, puoi fare le parentesi graffe premendo alt dx + shift + il tasto delle quadre… )