force symmetry for hexagon pattern
hi everyone!

i have a symmetrical shape (bunch of curves, shaping hexagons) and i managed to make them planar hexagons with the coplanar tool, but in the process it loses symmetry

see difference between red (original) and blue (mirrored) line on the first picture, green is the difference.

just a …
hi [@banati.bodo](/u/banati.bodo)

the key here is to find which points are on the symmetry plane and keep them there with an onplane goal, then for the points ‘above’ the symmetry plane, use a transform goal to lock them to their mirror image below the symmetry plane.

[symmetry\_planarhex.gh](/uploads/short-url/wlxtpug6o3kghsxsd43l0qwa6jy.gh) (17.3 kb)

[symmetry]
(a)The regular octahedron has 3 symmetry planes;  
(b)The regular dodecahedron has 15 symmetry planes;  
(c)The regular icosahedron has 15 symmetry planes; 圖片參考：http://imgcld.yimg.com/8/n/ab00135862/o/161006040753513872668990.jpg
 
首先請先 複習下列公式
 
設扇形的中心角θ弳，半徑為r，弧長為s，面積為a，則
s=rθ；a= r2θ= rs
sol: 設: ∠aob=θ 弳 (弧度) od=x
(x+2.5) θ =6 ……………………………..(1)
求黃色部分面積= (x+5)2 θ - x2θ
= θ ( x2+10x+25-x2 )
= θ (10x+25)
=5θ( x + 2.5)=30



圖片參考：http://imgcld.yimg.com/8/n/ab00135862/o/161006040753513872669011.jpg
 

圖片參考：http://imgcld.yimg.com/8/n/ab00135862/o/161006040753513872669012.jpg
 

圖片參考：http://imgcld.yimg.com/8/n/ab00135862/o/161006040753513872669033.jpg
 



 2010-06-04 23:25:06 補充：
y= |cosx|

恕不再多畫 將以文字說明

1. 當cosx >0 時 y=cosx
2. 當cosx <0 時 y = -cosx

 2010-06-04 23:26:21 補充：
注意

y=3sin2(x-π)+2

之 a , b 步驟為同一圖形

 2010-06-05 13:06:49 補充：
奇怪 1/2 通通不見了

更正

s=rθ；a=0.5 r2θ=0.5 rs

求黃色部分面積=0.5(x+5)2 θ - 0.5x2 θ
=0.5θ ( x2+10x+25-x2 )
=θ (10x+25)
=5θ( x + 2.5)=30

p.s. x2 即為 x平方

 2010-08-28 11:35:07 補充：
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rid of when a ray of light falls on a smooth and shiny surface, the whole of light is sent back in the same direction. it is called reflection. mirrors do not allow even a small amount of light to pass through them. mirrors show regular and complete reflection.when all the parallel rays reflected from a plane are not parallel, the reflection is diffused or irregular. this is not violation of law of reflection, the reason for diffused reflection is due to irregularities in the reflecting surface. thanks everyone for your suggestions. i went with a modified version of [@weekend](/u/weekend)’s:

[[screenshot from 2020-02-22 06-44-57]](https://media.blenderartists.org/uploads/default/original/4x/a/d/6/ad62e605b45c9294a1a33960e705f2a07772113c.jpeg "screenshot from 2020-02-22 06-44-57")

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alan weiss
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<https://www.babylonjs-playground.com/#vkixd8>

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