two coins are tossed once. find `p(e//f)`. where   
 e:no tail appears and f: no head appears
answer: 0
no answer engr 3341 probability theory and statistics prof. gelb week 5 homework solutions warm-up problems from textbook: section 3.3 problem 9: in this problem, we would like to show that the geometric random variable is memoryless. let x ▯ geometric(p). show that p(x > m+ljx > m) = p(x > l); for m;l 2 f1;2;3;:::g we can interpret this in the following way: remember that a geometric random variable can be obtained by tossing a coin repeatedly until observing the ﬁrst heads. if we toss the coin several times and do not observe a heads, from now on it is like we start all over again. in other words, the failed coin tosses do not impact the distribution of waiting time from now on. the reason for this i the score has been removed. 2, 0 ( any two integers with one of them as 0). british english pronounces it with an /f/. american english doesn't. none of these wasted question, they can't read. \[\ce{fecl2 +2naoh -> fe(oh)2 + 2naci}\] the first one. the total supply of swap is 0