a tank contains a mixture of 52.5 g oxygen gas and...
a tank contains a mixture of 52.5 g oxygen gas and 65.1 g carbon dioxide gas at 27°c. the total pressure in the tank is 9.21 atm. calculate the partial pressures of each gas in the container.
recall: dalton’s law of partial pressures states that the total pressure of a mixture of unreacting gases is the sum of the partial pressures of the individual gases.the partial pressure of a gas in the mixture is the product of the total pressure of the mixture and the mole fraction, χ, of the gas:we first need to calculate the mole fraction of the gases before calculating their partial pressures. the molar mass of o2 is 2(16.00 g/mol o) = 32.00 g/mol and the molar mass of co2 is 12.01 g/mol c + 2(16.00 g/mol o) = 44.01 g/mol.[readmore]the moles of o2 and co2 in the tank are:the total moles of gas is 1.6406 mol + 1.4792 mol = 3.1198 mol.the mole fraction of o2 and co2 are:the total pressure in the tank is 9.21 atm. the partial pressures of o2 and co2 are:
1. according to kinetic theory of ideal gases, molecules of a gas are in incessant random motion, colliding against each other and with the walls of the container. all these collisions are perfectly elastic collision.2. in perfectly elastic collision, total kinetic energy of gas is conserved.3. here, we have a mixture of oxygen and hydrogen gas. thereforek.e of oxygen + k.e of hydrogen=constant4. so, if kinetic energy of oxygen molecules increases, then kinetic energy of hydrogen molecules decreases or vice-versa so that, sum of both kinetic energies remains constant.5. therefore, both option (c) and (d) are correct. answer: the molecular mass of an element is defined as the sum of the masses of the elements present in the molecule. molecular mass is obtained by multiplying the atomic mass of an element with the number of atoms in the molecule and then adding the masses of all the elements in the molecule. o2 is a diatomic molecule. the mass of an oxygen atom = 16 amu. ∴ mass of o2 molecule = 2 × 16 = 32 amu. mass of one molecule of oxygen → 32/ avogadro constant ( 6.023 × 1023) → 5.31 × 10-23g. oxygen in answer: oxygen gas is responsible for combustion. combustion is characterized as a rapid exothermic reaction that releases a significant amount of energy in the form of heat and flames as combustion reactions that can spread through a suitable medium. combustion is the outcome of dynamic or time-dependent activities between atoms, molecules, radicals, and solid boundaries at the molecular level. for combustion to occur, three conditions must be met, which are there should be a combustible material. there should be a supporter of combustion. the combustible material is heated to the ignition temperature. the presence of fuel has a significant effect. the existence of oxygen or air. the ignition temperature is kept constant. hydrogen gas in its natural state consists of molecules of h2, where two hydrogen atoms are bound together by a 100% covalent bond.

the h2 molecules are attracted to each other by london dispersion forces. london dispersion forces result from the formation of temporary dipoles. AgNO3(aq) + NaCl(s) = AgCl(s) + NaNO3  
n(AgCl) = 0.765 g / M(AgCl)  
M(AgCl) = 108 + 35.5 = 143.5 g/mol  
n(AgCl) = 0.765 g /143.5 g/mol = 0.00533 mol  
n(AgCl) = chloride ions = 0.00533 mol  
C(chloride ions) = n/V  
C(chloride ions) = 0.00533 mol/1l = 0.00533 mol/ L (a)  
m(NaCl)=n(NaCl)*M(NaCl)  
n(NaCl) = 0.00533 mol  
M(NaCl) = 23 + 35.5 = 58.5 g/mol  
m(NaCl) = 0.00533 mol * 58.5 g/mol = 0.3115 g (b)  
  
**Answer:**  
**a) 0.00533 mol/ L**  
**b) 0.3115 g** **Pure substance – ethyl alcohol, oxygen, carbon, distilled water mixture – blood, steel** First, you want to convert grams of Iron Hydroxide into moles like this: (55.0g/89.85 g mol^-1) which is 0.6121313 moles.   

  

For each mole of Iron Hydroxide there are 2 moles of oxygen, so you multiply 0.6121313 by 2 to get 1.2242626.   

  

Then, you can use Avogadro's number to convert to number of atoms by multiplying 1.2242626 by 6.0221415x10^23 to get your final answer.   

  

Good luck. <p>concepts and reason</p>
<p>the concept used to solve this problem is the formal charge calculation of the oxygen atoms present in the ozone molecule.</p>
<p>fundamentals</p>
<p>a charge that is assigned to an atom, which is present in the molecule, is represented as a formal charge. in two bonded atoms, a formal charge assumes that the electrons are equally shared between them. the formal charge is calculated using the following formula:</p>
<p>formal charge \(=\mathrm{v}-\mathrm{n}-\frac{\mathrm{b}}{2}\)</p>
<p>here, \(\mathrm{v}\) is the number of valence electrons, \(\mathrm{n}\) is the number of non-bonding electrons and \(\mathrm{b}\) is the number of bonding electrons.</p>
<p> </p>
<p>the structure is as follows:</p>
<p>calculate the formal charge for the circled oxygen in ozone molecule as follows:</p>
<p><img src="https://img.wizedu.com/images/5af6d1f54822b4dfb8fe89d91ef2011c5fe3020815aa4.png" alt="" width="88" /></p>
<p>formal charge \(=\mathrm{v}-\mathrm{n}-\frac{\mathrm{b}}{2}\)</p>
<p>\(\begin{aligned}=& 6-6-\frac{2}{2} \\ &=-1 \end{aligned}\)</p>
<p>explanation | common mistakes | hint for next step</p>
<p>the marked oxygen atom has 6 valence electrons. it contains 6 non-bonding electrons. the marked oxygen atom is bonded with one oxygen atom. therefore, the bonding electron of oxygen is \(2 .\) substitute the values in a formal charge formula to determine the formal charge of oxygen (marked).</p>
<p> </p>
<p>the structure is as follows:</p>
<p><img src="https://img.wizedu.com/images/39493056a8515708b79350d1976e17b35fe30216f0473.png" alt="" width="88" /></p>
<p>calculate the formal charge for the circled oxygen in ozone molecule as follows:</p>
<p>formal charge \(=\mathrm{v}-\mathrm{n}-\frac{\mathrm{b}}{2}\)</p>
<p>\(=6-2-\frac{6}{2}\)</p>
<p>\(=+1\)</p>
<p>explanation | common mistakes | hint for next step</p>
<p>the oxygen atom in the middle has 6 valence electrons and has 2 non-bonding electrons. the central oxygen atom is bonded with 1 double bond and 1 single bond. so, there is a total of 3 bonds containing 6 electrons (bonding electrons). the formal charge of the middle oxygen atom can be determined by substituting the values in a formal charge formula.</p>
<p> </p>
<p>the structure is as follows:</p>
<p><img src="https://img.wizedu.com/images/b1122ce7723aa4ab1f9ae5c9e457299e5fe3022ca77a5.png" alt="" width="88" /></p>
<p>calculate the formal charge for the circled oxygen in ozone molecule as follows:</p>
<p>formal charge \(=\mathrm{v}-\mathrm{n}-\frac{\mathrm{b}}{2}\)</p>
<p>\(=6-4-\frac{4}{2}\)</p>
<p>\(=0\)</p>
<p>the formal charge of each oxygen atom in \(\mathrm{o}\_{3}\) molecule are labeled as follows:</p>
<p><img src="https://img.wizedu.com/images/1de5ee227194f6d8c7fb9fb0e76160f25fe3024117fde.png" alt="" width="120" /></p>
<p>the oxygen atom present on the right side contains 6 valence electrons which have 2 non-bonded electrons. the marked oxygen is bonded with 1 double bond with a central oxygen atom. so, the number of bonding electrons is \(4 .\) the formal charge of the corner oxygen atom (right corner) can be determined by substituting the values in the formal charge formula.</p>
<p>the formal charge of each oxygen atom in \(\mathrm{o}\_{3}\) molecule are labeled as follows:</p>
<p><img src="https://img.wizedu.com/images/1de5ee227194f6d8c7fb9fb0e76160f25fe3024117fde.png" alt="" width="120" /></p> ?solution:
step 1 of 2:
the intermediate pressure in a compressor is given by . the relative uncertainty of and the relative uncertainty of is 2% . we have to find the relative uncertainty in .


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step 2 of 2:


the intermediate pressure in a compressor is = ((


it is given that the relative uncertainty in , = 0.05
 
 relative uncertainty in , = 0.02


so the relative uncertainty in the intermediate presser 




 = 


 = 
 
 = 0.0269


 therefore the relative uncertainty in the intermediate presser is 0.0269 mpa.
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