question
write the reactions of f2 with h2o?
write the reactions of f2 with h2o?
we are being asked to classify the following reactions based on the following categories:combination/synthesis → multiple reactants combine to form a single productw/o change in oxidation numbersa + b → abdecomposition →reactant splits into multiple products with no change in oxidation numbersab → a + bcombustion reaction: reaction with oxygen that produces carbon dioxide and waterhydrocarbon + o2 → co2 + h2osingle displacement →single element displaces another element in a compoundab + c → ac + b[readmore]let’s analyze the given reactionsa. fe2(co3)2 (s) → fe2o3(s) + 2co2(g) break down of fe2(co3)2(s) to its component ions → decomposition reactionanswer: this is a decomposition reaction.b. 2 c6h11oh(l) + 17 o2(g) → 12co2 (g) + 12h2o(l) reaction with oxygen that produces carbon dioxide and water → combustion reactionanswer: this is a combustion reaction.c. p4o10(s) + 6h2o(l) → 4h3po4(aq) two or more substances combine to form a single compound → combination reactionanswer: this is a combination reaction.d. 2c(s) + mno2(s) → mn(s) + 2co(g) substitute one element for another element in a compound →single-displacement reaction answer: this is a single-displacement reactione. 2naclo3 (s) → 2nacl(s) + 3o2(g)break down of compound into its simpler substances → decomposition reactionanswer: this is a decomposition reaction \[\ce{fecl2 +2naoh -> fe(oh)2 + 2naci}\] setup the kc expression for the reaction, recall that kc expression will appear as:kc expression for the problem:solving for [n2]:note that ice table is not necessary for this calculation answer is 0.016 m a) 3ag + 4hn03 > 3agno3 + no + 2h2o

b) mno2 + 4hcl > 2h2o + mncl2 + cl2 we are asked to write the chemical formula of hydrates and to use proper symbols, case, and formatting.remember that an ionic hydrate is formed when an ionic compound is bonded to one or more molecules of water. naming ionic hydrates has the same set of rules in naming the ionic compound portion. the water molecule portion is named with a numerical prefix together with the word hydrate.[readmore]step 1: discuss the rules in naming ionic hydrates.step 2: from the naming rules, extract the chemical symbols and the formula for each of the compounds.step 1: discuss the rules in naming ionic hydrates.rules in naming the ionic compound portion:1.a. the metal is named and normally written first.-if the metal is a transition metal we must use a roman numeral to describe its positive charge.1.b. the nonmetal keeps the first part of its name but has its ending changed to -ide.1.c. name the polyatomic as you would normally.rules in naming the h2o portion:1.d. the h2o portion will be called hydrate.1.e. to describe the number of h2o molecules, use the numerical prefixes.note: a dot (•) is written in between the ionic compound and the hydrate.step 2: from the naming rules, extract the chemical symbols and the formula for each of the compounds.a. iridium(iii) bromide tetrahydrate rule 1.a.iridium→transition element → symbol : iriii → describes the transition element's positive charge → symbol: 3+rule 1.b.bromide → nonmetal bromine → bromide ion has a charge of -1 → symbol: brwe write the metal and nonmetal beside each other. recall that the charges will be exchanged, becoming subscripts in the chemical formula.we don't need to write 1 as a subscript, it is understood to be 1 without it.rule 1.d.hydrate → h2orule 1.e.tetra → four → 4therefore the chemical formula is irbr3•4h2o.b. tin(iv) chloride pentahydraterule 1.a.tin(iv)→ sn4+rule 1.b.chloride → cl-we write the metal and nonmetal beside each other. recall that the charges will be exchanged, becoming subscripts in the chemical formula.again, we don't need to write 1 as a subscript.rules 1.d and 1.e.pentahydrate → 5 h2o the chemical formula is sncl4•5h2o.therefore the chemical formula is sncl4•5h2o.c. zinc nitrate hexahydrate rule 1.a.zinc→ zn1+rule 1.c. nitrate → no31-we write the metal and nonmetal beside each other. recall that the charges will be exchanged, becoming subscripts in the chemical formula.note that +1 and -1 charges just cancel out, we just put the atoms together.rules 1.d and 1.e.hexahydrate → 6 h2othe chemical formula is znno3•6h2o.therefore the chemical formula is znno3•6h2o.d. sodium carbonate monohydraterule 1.a.sodium→ na1+rule 1.c. carbonate → co32-we write the metal and nonmetal beside each other. recall that the charges will be exchanged, becoming subscripts in the chemical formula.again, we don't need to write 1 as a subscript.rules 1.d and 1.e.monohydrate → 1 h2o → h2o     (we don't need to write 1 as a coefficient.)the chemical formula is na2co3•h2o.therefore the chemical formula is na2co3•h2o. Can you show the calculate function that you've wrote so far? 0.10m hc2h3o2 and 0.10m lic2h3o2 solution: `ch\_(4)(g) + 2o\_(2)(g) to co\_(2)(g) + 2h\_(2)o(g) + "heat. (evolved)"` a) he helium (he) is an element by itself. he atom can only exhibit dispersion forces.b) hclh          1a                   1 × 1 e– = 1 e–cl         7a                   1 × 7 e– = 7 e–   total: 8 valence e–[readmore]cl is more electronegative than h, so hcl is a polar covalent compound. hcl exhibits dipole-dipole interaction.c) h2oh          1a                   1 × 2 e– = 2 e–o          6a                   1 × 6 e– = 6 e–   total: 8 valence e– since hydrogen is bonded directly to oxygen.h2o exhibits hydrogen bonding.d) cl2cl         7a                   1 × 7 e– = 14 valence e–composed of the same atom. there's no electronegativity difference.cl2 can only exhibit dispersion forces. kclo3(s) — heat→ kcl (s) + o2(g)      reactant        productk        1                   1cl       1                   1o       3                    2[readmore]2 kclo3(s) — heat→ 2 kcl (s) + 3 o2(g)      reactant        productk        2                   2cl       2                   2o       6                    6the balanced equation for the reaction is 2 kclo3(s) — heat→ 2 kcl (s) + 3 o2(g)