question
a compound (a) of boron reacts with nme3 to give an adduct (b) which on hydrolysis gives a compound (c) and hydrogen gas. compound (c) is an acid. identify the compounds a, b and c. give the reactions involved
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we are being asked to classify the following reactions based on the following categories:combination/synthesis → multiple reactants combine to form a single productw/o change in oxidation numbersa + b → abdecomposition →reactant splits into multiple products with no change in oxidation numbersab → a + bcombustion reaction: reaction with oxygen that produces carbon dioxide and waterhydrocarbon + o2 → co2 + h2osingle displacement →single element displaces another element in a compoundab + c → ac + b[readmore]let’s analyze the given reactionsa. fe2(co3)2 (s) → fe2o3(s) + 2co2(g) break down of fe2(co3)2(s) to its component ions → decomposition reactionanswer: this is a decomposition reaction.b. 2 c6h11oh(l) + 17 o2(g) → 12co2 (g) + 12h2o(l) reaction with oxygen that produces carbon dioxide and water → combustion reactionanswer: this is a combustion reaction.c. p4o10(s) + 6h2o(l) → 4h3po4(aq) two or more substances combine to form a single compound → combination reactionanswer: this is a combination reaction.d. 2c(s) + mno2(s) → mn(s) + 2co(g) substitute one element for another element in a compound →single-displacement reaction answer: this is a single-displacement reactione. 2naclo3 (s) → 2nacl(s) + 3o2(g)break down of compound into its simpler substances → decomposition reactionanswer: this is a decomposition reaction because of the small size of boron atom and presence of only six electrons in its valence shell, b(oh)3 accepts a pair of electrons from oh- ion of h2o, releasing a proton.the reaction mechanism is: a) van der waals (present, all molecule/atoms contain it)[readmore](b) dipole-dipole (present, c=o creates a partial charge on c and o)(c) hydrogen bonding (not present, h-bonds are only present in compounds with h attached on o, n or f)(d) ion-ion (not present, only appears on compound with full charges) reno, please don't answer organic chemistry questions if you don't know the subject matter.
 
mixing acetic acid with sodium bicarbonate doesn't yield "gaseous water." also, you didn't actually answer the question and decided instead to list the first thing you found in wikipedia about a dangerous reaction that has nothing to do with the fact that acetic acid and hcl react the same way because they are both stronger acids than the conjugate acid of bicarbonate. we are going to do the following steps:step 1: determine the classification of the compoundstep 2: write the formula of the compound[readmore]step 1: determine the classification of the compoundrecall the definition of the following:ionic compound - usually made up of a metal and a non-metalcovalent compound - composed of more than one nonmetal togetheracid - substance whose molecules yield hydrogen ions (h+) when dissolved in waterhydrate - substance that contains water or its constituent elementsfor cobaltic iodidecobaltic – metaliodide – nonmetalmetal + nonmetal = ionicstep 2: write the formula of the compoundthe rules for naming ionic compounds are as follows:1. the metal keeps its name and is named and written first.– for transition metals, we use roman numerals to denote its charge.2. the nonmetal keeps its base name but has its ending changed to –ide.for cobaltic iodidecobaltic  → transition metal → +2 charge → co2+iodide → group 7a → -1 charge → i-criss-cross the charges and make them the subscript of the other ioncobaltic iodide → coi2answer: cobaltic iodide is an ionic compound with a formula of coi2 a) 3ag + 4hn03 > 3agno3 + no + 2h2o

b) mno2 + 4hcl > 2h2o + mncl2 + cl2 we’re being asked which of the given compounds is a lewis acid and lewis base. let’s first define a lewis acid and a lewis base.based on the lewis definition:lewis acid is an electron pair acceptor.some characteristics of a lewis acid:• when hydrogen is connected to an electronegative element such as p, o, n, s or halogens▪ hydrogen gains a partially positive charge → makes hydrogen act as a lewis acid• positively charged metal ions[readmore]▪ can accept negative electron pairs → can act as lewis acids• central element that has less than 8 valence electrons around it▪ more likely to accept an electron pair to follow the octet rule▪ can accept electron pair → can act as lewis acidlewis base is an electron pair donor.some characteristics of a lewis base:• compounds that have lone pair(s) on a central element can act as lewis bases. • compounds that possess a negative charge can act as lewis bases. let’s draw the lewis structure of each given compound and check which of them can act as a lewis acid and lewis base.step 1: determine the central atom in this molecule.step 2: calculate the total number of valence electrons present.   step 3: draw the lewis structure for the molecule.a) cs2step 1: determine the central atom in this molecule.c is less electronegative than s → c will be the central atomstep 2: calculate the total number of valence electrons present.                group             valence electronsc         4a                   1 x 4 e‑ = 4 e-s         6a                   2 x 6 e‑ = 12 e-              total: 16 valence e- step 3: draw the lewis structure for the molecule• c has a total of 8 e- electrons around it and has a lone pair→ complete octet▪ can act as a lewis acidb) sh−step 1: determine the central atom in this molecule.only two atom → no central atomstep 2: calculate the total number of valence electrons present.                group             valence electronss         6a                   1 x 6 e‑ = 6 e-h        1a                   1 x 1 e‑ = 1 e-from -1 charge:                     +1 e-              total: 8 valence e- step 3: draw the lewis structure for the molecule▪ has a negative charge▪ can act as a lewis baseanswer: sh- is the lewis base and its lewis structure is cs2 is the lewis acid and its lewis structure is there are 3 types of hybridisation for carbon in organic compounds, sp, sp2 and sp3 depending on the number of sigma and pi bonds between the carbon atoms. more the ‘s’ character more is the electronegativity of the carbon as ‘s’ orbitals are closer to the nucleus, hence electrons held more closely. hydrocarbons are the compounds of hydrogen and carbon. they are the simplest of all the organic compounds.hydrocarbons are of two types:(i) organic (ii) inorganic we’re being asked to determine the conjugate acid of o2-.recall that the conjugate acid of a base is simply the compound formed when a base gains a proton (h+). it's considered as an acid because it can lose h+ to reform the base.[readmore]for o2–, simply add a hydronium ion from the formula. note that we also need to add the +1 charge of the proton (h+) to o2–, giving our conjugate acid a net charge = -1.o2– + h+ → oh–  –2    +   1     =       –1this means the conjugate acid of o2– is oh–.