in the reaction 

sncl4 + 2cl− → sncl62- 

identif...
in the reaction 

sncl4 + 2cl− → sncl62- 

identify the lewis acid.

1. cl−

2. sncl4

3. sncl62-
sncl4
a) 3ag + 4hn03 > 3agno3 + no + 2h2o

b) mno2 + 4hcl > 2h2o + mncl2 + cl2 i. given:valency of carbon is 4valency of chlorine is 1by applying criss-cross method:formula: ccl4thus, the formula for carbon tetrachloride is ccl4.ii. given:valency of element x is 1valency of oxygen is 2by applying criss-cross method:formula: x2o according to ncert answer would be option (1)and

but according to general chemistry answer would be (3)andoption 1)and





option 2)andoption 3)andoption 4)and cao on sapling its

oxidation:
cu --> cu^2+ + 2e^-

reduction:
o\_2 + 4e^- -->2o^2- nucletic acid `overset("nucelase")rarr` nucleotides `overset"nuceotidase")rarr`nucleosides `overset("nucleosidase")rarr` sugars+bases 
soucrose `overset("sucrase")rarr` glucose + fructose 
fats `overset("lipase")rarr` diglycerides `overset("lipase")rarr` monoglycerides 
proteins, peptones, proteoses `underset("carboxypeptidase")overset("trypsin//chymotrypsin")rarr` dipeptides
answer: c
solution: bile salts of bile bring about emulsification of fat by which fat droplets are broken down into may small droplets this increaes lipase action on fat, by increasing the available surface area. AgNO3(aq) + NaCl(s) = AgCl(s) + NaNO3  
n(AgCl) = 0.765 g / M(AgCl)  
M(AgCl) = 108 + 35.5 = 143.5 g/mol  
n(AgCl) = 0.765 g /143.5 g/mol = 0.00533 mol  
n(AgCl) = chloride ions = 0.00533 mol  
C(chloride ions) = n/V  
C(chloride ions) = 0.00533 mol/1l = 0.00533 mol/ L (a)  
m(NaCl)=n(NaCl)*M(NaCl)  
n(NaCl) = 0.00533 mol  
M(NaCl) = 23 + 35.5 = 58.5 g/mol  
m(NaCl) = 0.00533 mol * 58.5 g/mol = 0.3115 g (b)  
  
**Answer:**  
**a) 0.00533 mol/ L**  
**b) 0.3115 g** reno, please don't answer organic chemistry questions if you don't know the subject matter.
 
mixing acetic acid with sodium bicarbonate doesn't yield "gaseous water." also, you didn't actually answer the question and decided instead to list the first thing you found in wikipedia about a dangerous reaction that has nothing to do with the fact that acetic acid and hcl react the same way because they are both stronger acids than the conjugate acid of bicarbonate. use the ka equation: 
take the acid as ha
this will dissociate : 
ha ↔ h+ + a- 
ka = [h+] [a-] /[ha] 
because dissociation is very small we can use 0.1m for [ha] 
[h+] = 2/50*0.1 = 0.0004m 
[a-] = 0.0004m 
 ka 0.0004 * 0.0004 / 0.1 
ka = 1.6*10^-5 * 0.1 
ka = 1.6*10^-4 tw - st < sw < st + tw

4 < sw < 34 The answer to the question is available in the PDF file https://www.assignmentexpert.com/homework-answers/chemistry-answer-42344.pdf