the output voltage of an op amp is 4 v when the | studysoup
the output voltage of an op amp is 4 v when the noninverting input is 1 mv. if the open-loop gain of the op amp is 2  106 , what is the inverting input?
ece 371 microcontroller interfacing paper the description  of   “debouncing” name: haomeng sang date: march 8, 2015 what is debounce and why use it? normally, key switch usually used for mechanical elastic switch, when the mechanical  contact is open or closed, due to the elasticity of the mechanical contacts, a key switch  when closed will not immediately be stably turned on and during disconnection does not suddenly disconnected. thus at the closed and disconnected moment are accompanied by a series of jitter. jitter is determined by the length of time of the mechanical  properties of the keys. key jitter can lead to misread a button repeatedly. to ensure that the cpu is only  closed once
All that is needed is some sort of wave-shape that sweeps the oscilloscope beam to and fro. Since the relationship between vertical displacement and horizontal displacement on the oscilloscope’s trace is purely a function of the test component’s characteristic curve, we really don’t care what form of [AC](https://www.allaboutcircuits.com/textbook/alternating-current/chpt-1/what-is-alternating-current-ac/) voltage excites it. 1/
a/ the x-intersect between 2 graphs , x^2+4x-5=0>x = -5 or 1
v = pi { integral of [(4x)^2 - (5-x^2)^2] dx , from x=-5 to x=1 } solved...
my ram was in ram slot 1 & 3.
switched it to 2&4 - now i can overclock to 4000mhz.


here's the benchmark now


same man... i'm still looking as well lol. i wonder why so many people are having this problem. an increase in the input price will lead to a decrease in the supply and no change in the quantity demanded.the following figure explains how an increase in the input price would affect the equilibrium price and equilibrium quantity.a. the market supply falls with the increase in the input prices.b. this leads to a leftward shift in the supply curve from s2 to s1.c. at the initial price op1, excess demand of q1-q1'.d. this excess demand implies that some consumers will have to pay a higher price to purchase the extra units of output.e. the rise in the market price will continue until it reaches op2.f. at op2, the new supply curve s2 intersects the initial market demand curve d1 at e2.g. e2 if the new equilibrium, op2 is the new equilibrium price, and oq2 is the new equilibrium output.h. at the new equilibrium, the price has increased and the quantity has fallen. v = (4/3)πr³ 

dv/dt = 4πr².dr/dt

so, when the diameter is 20 cm we have:

-4π = 4πr².dr/dt

hence, dr/dt = -1/r²

i.e. dr/dt = -1/10² => -1/100

now, d = 2r

so, d(d)/dt = 2.dr/dt

=> d(d)/dt = -1/50 cm/hour

or, -0.2 mm/hour

:)> hi there!we are asked to determine the process corresponding to the increase in entropy labeled 1 and 2.we can use the heating curve to answer the given questions. recall that entropy is the degree of chaos or disorder of a system. for a given process, entropy (δs) will either increase or decrease. also, phase changes lead to a change in entropy:• we know that the phase at the highest temperature is gas• the plot has 2 process with drastic increase in entropy.• increase in entropy accompanying phase change is from solid → liquid → gas• therefore, the phases in the graph must have been:• phase change from solid to liquid is called fusion or melting• phase change from liquid to gas is called vaporizationprocess 1 represents melting (fusion), and 2 represents vaporization. from the figure:total resistance of the circuit, r = (rab + 15) ω = 20 ωcurrent in the circuit , \[i = \frac{v}{r} = \frac{8}{20} a\] ∴ voltage across ab, vab = i.rab = 2 vthe emf of the cell connected as above is given by: \[e = \frac{l}{l} v\_0\] here:l = 60 cm (balance point)ab = l = 1 m = 100 cm (total length of the wire) \[\therefore e = \frac{60}{100}\left( 2 \right) = 1 . 2 v\] (i) here current (i) = 1 a, resistance (r) = 300 ohm, time(t) = 1hwe know thatp = i2r = 12 x 300 = 300 we = p x t = 300 x 1 = 300 wh(ii) here current (i) = 2 a resistance(r) = 100 ohm, time (t) = 1hwe know thatp = i2r = 22 x 100 = 400 we = p x t = 400 x 1 = 400 whhence, in case (ii), the electrical energy consumed per hour is more. a frequency converter, also known as a frequency changer, is a device that takes incoming power, normally 50 or 60 hz and converts it to 400 hz output power. The additive inverse of 0 is 0.