a card is drawn at random from a well-shuffled pack of 52 cards. find the probability that the drawn card is neither a king nor a queen.
total number of cards in a well-shuffled pack =52total number of queens and kings cards =4+4=8therefore, there are 44 cards (52−8) that are neither king nor queen.total number of favorable outcomes  =44  
probability is given by,p(a)=no. of total outcomesno. of possible outcomes​  
required probability =5244​=1311​
given : five defective bulbs are accidently mixed with 20 good ones.to find : probability distribution from this lotformula used :five defective bulbs are accidently mixed with 20 good ones.total number of bulbs = 25x denote the number of defective bulbs drawnx can draw the value 0 , 1 , 2 , 3 , 4.since the number of bulbs drawn is 4, n = 4p(0) = p(getting a no defective bulb) = = = p(1) = p(getting 1 defective bulb and 3 good ones) = = p(1) = = p(2) = p(getting 2 defective bulbs and 2 good one) = p(2) = = = p(3) = p(getting 3 defective bulbs and 1 good one) = p(3) = = p(4) = p(getting all defective bulbs) = = = p(4) = the probability distribution table is as follows, it depends on what map it is It's not a strange coincidence. It's just the nature of the game! the heroes. as powerful as they are, they would be able to run up to him and tear off the gauntlet before he could snap.

bq; it's all random. who lives and who dies is determined just by luck.

please
https://answers.yahoo.com/question/index?qid=20190717180935aakyztb lol bless you no - she most certainly is not. she's no j k rowling. now that woman is famous all over the world. can't be determined not that i am aware of the whole world wants democracy.

notice that none of them want republicacy. Total no. of possible outcomes = 30 {1, 2, 3, … 30}  

  

E ⟶ event of getting no. divisible by 3.  

  

No. of favourable outcomes = 10 {3, 6, 9, 12, 15, 18, 21, 24, 27, 30}  

  

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)  

  

P(E) = 10/30 = 1/3  

  

Bar E ⟶ event of getting no. not divisible by 3.  

  

P(Bar E) = 1 – P(E)  

  

= 1 - 1/3 = 2/3 Um. That gal did not hold an “appointed” position. Nice try.