the flow stress  of an alloy varies with strain rate  mpa. when the alloy is hot extruded from 10 cm diameter to 5 cm diameter at a speed of 2 cm/s, the flow stress is
105 mpa
v = (4/3)πr³ 

dv/dt = 4πr².dr/dt

so, when the diameter is 20 cm we have:

-4π = 4πr².dr/dt

hence, dr/dt = -1/r²

i.e. dr/dt = -1/10² => -1/100

now, d = 2r

so, d(d)/dt = 2.dr/dt

=> d(d)/dt = -1/50 cm/hour

or, -0.2 mm/hour

:)> an alloy is combination of a metal and a non metal. so it has partial characteristics of metal and non metal. being analloy the ions it it are randomly arranged. it does not have a specific arrangement of ions. hence the flow of electrons in this is more. the this feature of alloy leads to increase in resistivity due to free crystal lattice. we know that metals have high melting point but an alloy has low melting point beacause the presence of a non metal in it behaves as an impurity and restricts in raising to high melting point. due to high melting point the it takes a lot of current to melt and leads in slow movement of electrons which makes the device less efficient. therefore electronic device requires the metal of low melting point. an alloy plays the best role in the elctronic device like electric iron and heater. ?solution:
step 1 of 2:
the intermediate pressure in a compressor is given by . the relative uncertainty of and the relative uncertainty of is 2% . we have to find the relative uncertainty in .


\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_




step 2 of 2:


the intermediate pressure in a compressor is = ((


it is given that the relative uncertainty in , = 0.05
 
 relative uncertainty in , = 0.02


so the relative uncertainty in the intermediate presser 




 = 


 = 
 
 = 0.0269


 therefore the relative uncertainty in the intermediate presser is 0.0269 mpa.
\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ the value of head loss due to friction using chezy formula with constant c= 60 for a fluid, flowing through a 30 cm diameter and 70 m long pipe. velocity of fluid inside the pipe is 5 m/s. Tungsten, also known as wolfram, is a hard, rare metal that is found naturally only in chemical compounds. The free element is remarkable for its robustness, especially the fact that it has the highest melting point of all the elements.  
Tungsten in pure form has the highest melting point (3422 °C, 6192 °F), lowest vapor pressure (at temperatures above 1650 °C, 3000 °F) and the highest tensile strength. Tungsten has the lowest coefficient of thermal expansion of any pure metal. The low thermal expansion and high melting point and tensile strength of tungsten originate from strong covalent bonds formed between tungsten atoms by the 5d electrons. Alloying small quantities of tungsten with steel greatly increases its toughness. coefficient of friction is defined as the ratio of the force of friction acting between two objects and the force which is pushing them together. the value of the coefficient of friction varies from zero to one. there are two types of the coefficient of friction: static coefficient of friction kinetic (also known as sliding) coefficient of friction. therefore, the coefficient of friction depends on the nature of the surface. u (initial velocity) = 18 km/hr 
t ( time )= 2.5 sec
v( final velocity) = 0 m/s
from, the first equation of motionv = u +  a×t0 = 5 +  a×2.5a = - 2 m/s2 hi there!we are asked to determine the process corresponding to the increase in entropy labeled 1 and 2.we can use the heating curve to answer the given questions. recall that entropy is the degree of chaos or disorder of a system. for a given process, entropy (δs) will either increase or decrease. also, phase changes lead to a change in entropy:• we know that the phase at the highest temperature is gas• the plot has 2 process with drastic increase in entropy.• increase in entropy accompanying phase change is from solid → liquid → gas• therefore, the phases in the graph must have been:• phase change from solid to liquid is called fusion or melting• phase change from liquid to gas is called vaporizationprocess 1 represents melting (fusion), and 2 represents vaporization. (a) f = 1/t = 2.11 hz

(b) 2*pi*f = 13.26 radians/s = sqrt(k/m)
m = 0.296 kg
solve for k
(c) (1/2)ka^2 = 0.150 j
solve for amplitude a, in meters Δl =l αΔt =2 •10⁻²•14•10⁻⁶•70=1.96•10⁻⁵m=1.96•10⁻² mm