question
what is the iupac name of the following compound

option 1)2-bromo-3-methylpent-3-eneoption 2)3-bromo-1,2-dimethylbut-1-eneoption 3)4-bromo-3-methylpent-2-eneoption 4)3-bromo-3-methyl-1,2dimethylprop-1-ene
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the iupac name for this compound is 1-bromo-2,2-dimethylpropane, we are going to do the following steps:step 1: determine the classification of the compoundstep 2: write the formula of the compound[readmore]step 1: determine the classification of the compoundrecall the definition of the following:ionic compound - usually made up of a metal and a non-metalcovalent compound - composed of more than one nonmetal togetheracid - substance whose molecules yield hydrogen ions (h+) when dissolved in waterhydrate - substance that contains water or its constituent elementsfor cobaltic iodidecobaltic – metaliodide – nonmetalmetal + nonmetal = ionicstep 2: write the formula of the compoundthe rules for naming ionic compounds are as follows:1. the metal keeps its name and is named and written first.– for transition metals, we use roman numerals to denote its charge.2. the nonmetal keeps its base name but has its ending changed to –ide.for cobaltic iodidecobaltic  → transition metal → +2 charge → co2+iodide → group 7a → -1 charge → i-criss-cross the charges and make them the subscript of the other ioncobaltic iodide → coi2answer: cobaltic iodide is an ionic compound with a formula of coi2 the name you are mentioning is the generic name of this medication. the brand names are temovate, (clobetasol) olux, clobex et al. see more... a) 3ag + 4hn03 > 3agno3 + no + 2h2o

b) mno2 + 4hcl > 2h2o + mncl2 + cl2 **Pure substance – ethyl alcohol, oxygen, carbon, distilled water mixture – blood, steel** a) van der waals (present, all molecule/atoms contain it)[readmore](b) dipole-dipole (present, c=o creates a partial charge on c and o)(c) hydrogen bonding (not present, h-bonds are only present in compounds with h attached on o, n or f)(d) ion-ion (not present, only appears on compound with full charges) you should have three choices.

 thanks for the update...i'll check it out. hclo3 > hclo2 > hclo > hbro we are asked to write the chemical formula of hydrates and to use proper symbols, case, and formatting.remember that an ionic hydrate is formed when an ionic compound is bonded to one or more molecules of water. naming ionic hydrates has the same set of rules in naming the ionic compound portion. the water molecule portion is named with a numerical prefix together with the word hydrate.[readmore]step 1: discuss the rules in naming ionic hydrates.step 2: from the naming rules, extract the chemical symbols and the formula for each of the compounds.step 1: discuss the rules in naming ionic hydrates.rules in naming the ionic compound portion:1.a. the metal is named and normally written first.-if the metal is a transition metal we must use a roman numeral to describe its positive charge.1.b. the nonmetal keeps the first part of its name but has its ending changed to -ide.1.c. name the polyatomic as you would normally.rules in naming the h2o portion:1.d. the h2o portion will be called hydrate.1.e. to describe the number of h2o molecules, use the numerical prefixes.note: a dot (•) is written in between the ionic compound and the hydrate.step 2: from the naming rules, extract the chemical symbols and the formula for each of the compounds.a. iridium(iii) bromide tetrahydrate rule 1.a.iridium→transition element → symbol : iriii → describes the transition element's positive charge → symbol: 3+rule 1.b.bromide → nonmetal bromine → bromide ion has a charge of -1 → symbol: brwe write the metal and nonmetal beside each other. recall that the charges will be exchanged, becoming subscripts in the chemical formula.we don't need to write 1 as a subscript, it is understood to be 1 without it.rule 1.d.hydrate → h2orule 1.e.tetra → four → 4therefore the chemical formula is irbr3•4h2o.b. tin(iv) chloride pentahydraterule 1.a.tin(iv)→ sn4+rule 1.b.chloride → cl-we write the metal and nonmetal beside each other. recall that the charges will be exchanged, becoming subscripts in the chemical formula.again, we don't need to write 1 as a subscript.rules 1.d and 1.e.pentahydrate → 5 h2o the chemical formula is sncl4•5h2o.therefore the chemical formula is sncl4•5h2o.c. zinc nitrate hexahydrate rule 1.a.zinc→ zn1+rule 1.c. nitrate → no31-we write the metal and nonmetal beside each other. recall that the charges will be exchanged, becoming subscripts in the chemical formula.note that +1 and -1 charges just cancel out, we just put the atoms together.rules 1.d and 1.e.hexahydrate → 6 h2othe chemical formula is znno3•6h2o.therefore the chemical formula is znno3•6h2o.d. sodium carbonate monohydraterule 1.a.sodium→ na1+rule 1.c. carbonate → co32-we write the metal and nonmetal beside each other. recall that the charges will be exchanged, becoming subscripts in the chemical formula.again, we don't need to write 1 as a subscript.rules 1.d and 1.e.monohydrate → 1 h2o → h2o     (we don't need to write 1 as a coefficient.)the chemical formula is na2co3•h2o.therefore the chemical formula is na2co3•h2o. we are being asked to classify the following reactions based on the following categories:combination/synthesis → multiple reactants combine to form a single productw/o change in oxidation numbersa + b → abdecomposition →reactant splits into multiple products with no change in oxidation numbersab → a + bcombustion reaction: reaction with oxygen that produces carbon dioxide and waterhydrocarbon + o2 → co2 + h2osingle displacement →single element displaces another element in a compoundab + c → ac + b[readmore]let’s analyze the given reactionsa. fe2(co3)2 (s) → fe2o3(s) + 2co2(g) break down of fe2(co3)2(s) to its component ions → decomposition reactionanswer: this is a decomposition reaction.b. 2 c6h11oh(l) + 17 o2(g) → 12co2 (g) + 12h2o(l) reaction with oxygen that produces carbon dioxide and water → combustion reactionanswer: this is a combustion reaction.c. p4o10(s) + 6h2o(l) → 4h3po4(aq) two or more substances combine to form a single compound → combination reactionanswer: this is a combination reaction.d. 2c(s) + mno2(s) → mn(s) + 2co(g) substitute one element for another element in a compound →single-displacement reaction answer: this is a single-displacement reactione. 2naclo3 (s) → 2nacl(s) + 3o2(g)break down of compound into its simpler substances → decomposition reactionanswer: this is a decomposition reaction