Question 3
If quantitative accuracy is desired from this curve tracing circuit, the shunt resistor should be *precisely* 1 kΩ in size. Explain how a precise shunt resistance may be built without the use of precision components (i.e. a special 1 kΩ precision resistor).
Hint: there’s a saying in the electronics world that goes something like this: *“Don’t make it precise, make it adjustable!”*
(a) material q with resistivity 2.63×10-8 ohm-m can be used for making electric wires because it has very low resistivity.(b) material r with resistivity 1.0 ×1015 ohm-m can be used for making handle of soldering iron because it has very high resistivity.(c) material p with resistivity 2.3 × 103 ohm-m can be used for making solar cell because it is a semiconductor. v = (4/3)πr³ 

dv/dt = 4πr².dr/dt

so, when the diameter is 20 cm we have:

-4π = 4πr².dr/dt

hence, dr/dt = -1/r²

i.e. dr/dt = -1/10² => -1/100

now, d = 2r

so, d(d)/dt = 2.dr/dt

=> d(d)/dt = -1/50 cm/hour

or, -0.2 mm/hour

:)> d = 21 m
r =![](https://img-nm%20mnimgs%20com/img/study_content/curr/1/7/3/41/1541/chapter%2011_html_96a2a55%20gif)
circumference = 2πr =![](https://img-nm%20mnimgs%20com/img/study_content/curr/1/7/3/41/1541/chapter%2011_html_521eed1b%20gif)= 66 m
length of rope required for fencing = 2 × 66 m = 132 m
cost of 1 m rope = rs 4
cost of 132 m rope = 4 × 132 = rs 528 as the length of the wire increases so does the electrical resistance as electrons experience a smaller pd gradient as wire gets longer. the size of voltage per metre value decreases causing a lower drift velocity and more ions for electrons to collide with (i) here current (i) = 1 a, resistance (r) = 300 ohm, time(t) = 1hwe know thatp = i2r = 12 x 300 = 300 we = p x t = 300 x 1 = 300 wh(ii) here current (i) = 2 a resistance(r) = 100 ohm, time (t) = 1hwe know thatp = i2r = 22 x 100 = 400 we = p x t = 400 x 1 = 400 whhence, in case (ii), the electrical energy consumed per hour is more. you could use kangaroo, but i don’t think it’s needed here.

instead i’d use inverse distance weighting to make a height field like this.

[sharp\_curves.gh](/uploads/short-url/a5wdkm9xiiwabwl6s0jpgf6ry7j.gh) (11.4 kb)

[[image]](https://aws1.discourse-cdn.com/mcneel/uploads/default/original/3x/d/c/dc85a5f42096a341409c4b4727a7d5066bd68745.png "image.png")

the key step here is making a mesh with vertices on the curves you want to keep sharp. one way of doing this is to split a s… Correct answer is 26 mm. Mass of powder is constant. mi=mf  ⇒ ρiVi = ρfVf ρihi = ρf hf ⇒ hi = (ρf hf)/ρi On substitution, (1755×12)/ 810= 26 mm  


Correct answer is 26 mm.


Mass of powder is constant.


mi=mf ⇒ ρiVi= ρfVf


ρihi = ρf hf⇒ hi = (ρf hf)/ρi


On substitution, (1755×12)/ 810= 26 mm


 


[See less](#) given: (i) xy = 4.5cm

(ii) yz = 5 cm

(iii) zx = 6 cm

to construct: a xyz

steps for construction

step 1 : first we will draw a line segment xy of length 4.5cm



step 2 : we have to draw an arc , taking x as center and radius 6cm



step 3 : we have to another arc, with radius 5cm and center at y and mark the intersection of arcs as z.



step 4 : we have to join xz and xy



this is the required triangle total cost of fencing = rs 9600
rate of fencing = rs 24
then, perimeter of field = cost/rate = 9600/24 = 400mts
let the length and breadth of the rectangular field be 5x and
3x
then perimeter= 2(l+b)
= 2(5x+3x)
= 2*8x = 16x
but the perimeter of the given field is 400 m
so, 16x = 400
x = 400/16 = 25
length of the field = 5*25mts = 125mts
breadth of the field = 3*25mts = 75mts if you do not need the "wave" contents for a further use, just drop out (k) from all its entries.
if you need it for a further use, initialize it as 
wave=zeros(3,numel(t));
before the loop and address it as wave(k,:) within the loop.
commands "stem" are definitely incorrect. if you want to see plots of the dependences on t, they should look something like stem(t,combined) or plot(t,combined), etc. however, the t range in the second version (0,3) is much wider than the one of the first version (0,0.01): consequently, such a graph will show much (hugely) more oscillations--you will probably see nothing but a unifromly painted square.
i do not see any need in the "nold on" and "hold off" commands in the both version.