ecg electro cardio gram
informative
answer: `1.8706 xx 10^(11) " erg", 4477 cal` from the figure:total resistance of the circuit, r = (rab + 15) ω = 20 ωcurrent in the circuit , \[i = \frac{v}{r} = \frac{8}{20} a\] ∴ voltage across ab, vab = i.rab = 2 vthe emf of the cell connected as above is given by: \[e = \frac{l}{l} v\_0\] here:l = 60 cm (balance point)ab = l = 1 m = 100 cm (total length of the wire) \[\therefore e = \frac{60}{100}\left( 2 \right) = 1 . 2 v\] [readmore]typed answera) δg° = -rtlnksp δg° = -(8.314 jmol-k)(298k)ln(4.6×10-2 )= 7628.72 j = 7.63 kjb) ∆g° = nfe°e° = ∆g°-nfe° = 7.63-(2)(96,000)(11000)e° =-0.0397 v correct option is a) right electrode will increase clean the carbon from the egr passages,check all vacuum lines for splits,cracks,dry rotted. you fixed the evap problem,so now you have insufficient egr flow. error correcting code memory differs from other rams in respect of security. you need ecc ram when working with high-value data as it protects against data corruption by automatically detecting single-bit small errors that may affect what’s your day rate. try doing a compression test cec i'm an engineer so don't know exactly how much an em makes but my gut feeling says it should be around 65-70k sek a month before tax (we don't mesure salary annually here in europe 😁)