ucla stats 10
ucla stats 10 (b) if you were to include humans in your chosen graph, where would the data point be in your selected graph? ” what does this statement mean?
stats10(2) roberts, erica 404400827 1/15/15 q1. there is a strong, positive, correlation between weight and desired weight. q2. q3. wdiff is a descrete variable. if wdiff=0 then the person’s weight and desired weight are the same. if wdiff is positive, then the person’s desired weight is more than their weight. the opposite is true for a negative wdiff; the person’s weight is more than their desired weight. q4. the histogram of wdiff is unimodal and skewed left. it is centered around the median, which is -10. the range is found
the graph of this equation is a line.  we know that because each term is either a constant (1.5) or the product of a constant and the first power of a variable (d, 0.8t).
since we have two variables (d and t), the line sits in a two-dimensional plane, with a vertical axis and a horizontal axis.  d stands alone in the equation, so its value depends on the value oft.  therefore, the vertical--or dependent--axis will represent values of d, and the horizontal--or independent--axis will represent values of t.
at this point, then, we can set up a coordinate plane with a vertical axis labeled d and a horizontal axis labeled t.  all of the points on our plane have a coordinate (t, d).
to graph a line, we need two points.  since the question asks for the axial intercepts anyway, we can use those.
we'll start with the d-intercept, where the line crosses the d-axis.  all of the points on the d-axis have a t-coordinate of zero, so to find where the line crosses the axis, we substitute zero for t in our equation and solve.
d = 1.5 + 0.8 × t
d = 1.5 + 0.8 × (0)
d = 1.5 + 0
d = 1.5
so our d-intercept has the coordinates (0, 1.5), and we have our first point and our first intercept.
similarly, to find the t-intercept, we note that all of the points on the t-axis have a d-coordinate of zero, so we set d equal to zero and solve.
d = 1.5 + 0.8 × t
0 = 1.5 + 0.8 × t
0 - 1.5 = 1.5 - 1.5 + 0.8 × t
-1.5 = 0.8 × t
-1.5 ÷ 0.8 = (0.8 ÷ 0.8) × t
-1.875 = 1 × t
-1.875 = t
and the d-intercept is (-1.875, 0).
now we have both axial intercepts, so that part of the question is complete.  we can plot those two points and draw the line that passing through them (extending on, at either side, to infinity).
all that remains is to find the turning points.  a turning point, also called a local maximum or local minimum, is where the value of a function goes from decreasing to increasing or from increasing to decreasing.  (the graph shown at http://en.wikipedia.org/wiki/file:parabola\_with\_focus\_and\_directrix.svg has a minimum at the origin, for example.)
a line has a constant slope.  to say that differently, the angle between any two points on a line is the same as the angle between any two other points on the line.  if a line is increasing in one location (like our line), it is increasing everywhere, and it is increasing everywhere at the same rate.  therefore, a line has no turning points. given statement is true. what does these graphs tell us? nothing. just that the proportion of races were mostly maintained. asians might have deserved 100% of the seats and yet, are kept within proportion. they might have deserved no seats and yet kept within the proportion. there is no really useful info there. you seem to be missing some information about e.if e is the midpoint between d and f, thene is (1,1) take half of (4-2) = 1 and half of (5-3) = 1e alphabetically does come between d and f.just average the x values and average the y values of the two points d and for plot them graphically, carefully, maybe on some graph paper, and you'llvisually see the midpoint is at (1,1) if i get this right you are trying to sweep1 circle and have the sweeps come to a point.

if that be the case, you either need to have the sweep paths cross and go far enough past each other to come to a point (at right) or you can place the cross section on the inside of the sweep path rather than … 1) p(x) = 1/x2 + 1 if x ≤ 3 it is clear that x= 3 is included, so you have to use this function.2) loo k at table d, and compare the given information with the data written inside the table. yes, select add a site…

[screen shot 2021-09-14 at 3.28.06 pm] hi stuti, 
index can be used with lists, not tables. 
if a variable is used as an index, it is put in the square brackets without the dollar sign and curly brackets, i.e. ${data\_list[item\_index]}. 
you can read more about using indexes with lists in the knowledge base: [https://kb.workfusion.com/disp…](https://kb.workfusion.com/display/rpae/recorder+variables#recordervariables-usingindexeswithlists) Thanks for your reply, I feared it would not be trivail, as I coudnt find any scripts. Idealy the text from the databse is place in a table witht the last column beeing the barcodes path, the images are to replace the text path and be place inside the cell, fitting within the cells width and/or height. i thought facebook allowed you to select the team of your choice?