how many electrons must i rub off a ruler to pick up a piece of paper from 2cm (1 inch) away. show thinking?
obviously f=mg, but how would i determine the force on the paper if the particles are uniformly distributed in the ruler/paper? can i idealize the paper/ruler as point particles? or will i need to use some integration to get the electric fields. also, polarization of the (neutral?) paper comes into the picture... i'm more comfortable with math than physics, mostly unsure about what approximations are reasonable, and there's so much going on in my head with this. please help!
that depends on a lot of things. in particular, you would need to find the electric susceptibility of the paper. the field produced by static charge is inverse-square. the polarization of the paper varies directly with the external field, with a proportionality constant equal to the electric susceptibility. the dipole field created by the polarized paper is inverse-cube. overall, the force between the ruler and the paper will vary with the inverse fifth power of distance. to get any more detailed, you would need to know the geometry of the situation, and the charge distribution.
the straight distance between two place on a map can be measured by a strip of paper and divider.use a ruler to measure the distance between the two places. if the line is quite curved, use a string to determine the distance, and then measure the string. find the scale for the map you're going to use. it might be a ruler bar scale or a written scale, in words or numbers. hi trinity, let's do this one!newton's famous second law states, in math terms: f = ma applying to the first case, we have: 100 = m(4.00) => m = 100/4 = 25 kgnow apply the formula to the second case: f = 25 x 16 = 400 newtons trueexplanation: physical balance is very sensitive and used in labs for measuring. it is similar to beam balance. it can measure small differences in mass up to milligram. physics 101 notes: 8/25 (week 2 continued)  force o defined as a push or a pull, and is a vector quantity, meaning that it has direction depending on which way it is being pushed or pulled o it has amount and direction (how much force is being applied and in which direction it is moving)  newton’s first law o first draft: “an object that is free of forces move in a straight line and covers equal distances in equal time” o final: “an object that is free of external forces moves at a constant velocity”  how does a skater start, stop, or turn? o acceleration: “the rate at which an object’s velocity is changing with time o acceleration, s centripetal force:f=mv2rr is equal to l in this question.1. f = (100)(1602)/2500 = 1024 n2. f = (300)(802)/10000 = 192 n3. f = (400)(802)/2500 = 1024 n[readmore]4. f = (200)(1602)/5000 = 1024 n5. f = (800)(402)/10000 = 128 n6. f = (200)(1202)/5000 = 576 n1 = 3 = 4 > 6 > 2 > 5the order of forces acting on the satelites from the largest to the smallest is 1 = 3 = 4 > 6 > 2 > 5 let a and b be the two given vectorsɵ = 150° is the angle between a and bif c is the resultant vector, then: ...1also, it is given that the resultant is perpendicular to one of the given vectors. let that given vector be anow, …2putting 2 in 1, we get:now, putting c = 10, ɵ = 150° ()so, hence, smaller vector is a = 20 units mass (molar mass) → mol (avogadro's number) → molecules[readmore]3.51×104 g ×1 mol163.94 g×6.022×1023 molecules1 mol = 1.29x1026 moleculesthere are 1.29x1026 molecules in the sample coulomb's law:f=kq1q2r2, where k is the coulomb's constant and r is the separation between the two charges. the magnitude of the net force:fnet=fx2+fy2k = 9 × 109 n·m2/c2the force due to charge q1 is:f1a=kq1qar1a2=(9×109)(21.4×10-6)(13.5×10-6)(80.1×10-2)2[readmore]f1a = 4.05 nthe force due to charge, q2:f2a=kq2qar2a2=(9×109)(30.6×10-6)(13.5×10-6)[(80.1×10-2)2+(80.1×10-2)2]2f2a = 2.9 nforce due to charge, q3:f3a=kq3qar3a2=(9×109)(57.3×10-6)(13.5×10-6)(80.1×10-2)2f3a = 10.9 nthe net force along the x-axis:fx=f1a-f2acos(45°)=4.05-(2.9)cos(45°)fx = 2.0 nthe net force in the y-direction:fy=f3a-f2acos(45°)=10.9-(2.9)cos(45°)fy = 8.85 nthe magnitude of the net force:fnet=fx2+fy2=2.02+8.852fnet = 9.07 nthe magnitude of the net force on the charge at point a is 9.07 n. if you want it cleaner you have to use more particles.

try with the vanilla emitter helppatch whats the particle max for your system.

test it adding one component at a time to find out what causes the particlesystem to not funktion any more. direction: a word and number arrangement machine when given an input line of word and numbers rearranges them following a particular rule in each step. the following is an illustration of input and rearrangement. input: politics 61 policy 116 partner 93 role 45 clear 27 38 point step i: role politics policy 116 partner 93 45 clear 27 38 point 61 step ii: role clear politics policy partner 93 45 27 38 point 116 61 step iii: role clear partner politics policy 93 45 38 point 27 116 61 step iv: role clear partner politics policy 93 38 point 45 27 116 61 step v: role clear partner politics point policy 93 38 45 27 116 61 step v, is the last step of the above arrangement as the intended arrangement is obtained. as per the rule followed in the given steps find out the appropriate steps for the given input. input: energy 54 78 place 23 issue 211 145 flat rent taxi 17in step iii, what is the difference between fifth element from left and second element from right?