state any two uses of eddy currents? - physics q&a
answer: eddy currents are currents that circulate in conductors like swirling eddies in a stream. they are induced by changing magnetic fields and flow in closed loops, perpendicular to the plane of the magnetic field. they arise when a conductor moves through a magnetic field, or when the magnetic field surrounding a stationary conductor is varying. to summarise, we can say that anything which results in the conductor experiencing a change in the intensity or direction of a magnetic field produces eddy currents. the two uses of eddy current are: it is used in household current meters to measure power consumption. it is used to check whether the material or surface has any discontinuities, fractures, or faults without harming the material. what are the functions of a transformer? what is the working principle of a transformer?
an equivalent current source in parallel with an equivalent impedance dear student,
we know that,after the discovery of electrons, we got to know that
electrons are the particles that flow in a conductor electrons
being the negatively charged particles flow from the negative
terminal to the positive terminal and for current now, electric or
conventional current is the rate of flow of charge so, the
direction of the current should be same as the direction of the
charge, i e positive charge(conventionally), so the direction is
opposite to the flow of the negative charge(flow of electrons)
hence, the direction of the flow of electrons is opposite to the
direction of electric(or conventional) current
regards sum of peak value of load current and capacitor current as the distance between the source and the metal is increased, the intensity of light decreases becausealso, the photocurrent is directly proportional to the intensity of light and also to the number of electrons emitted.hence, the curve d is the appropriate curve representing above equation. The answer to the question is available in the PDF file https://www.assignmentexpert.com/https://www.assignmentexpert.com/homework-answers/physics-answer-3862.pdf (i) here current (i) = 1 a, resistance (r) = 300 ohm, time(t) = 1hwe know thatp = i2r = 12 x 300 = 300 we = p x t = 300 x 1 = 300 wh(ii) here current (i) = 2 a resistance(r) = 100 ohm, time (t) = 1hwe know thatp = i2r = 22 x 100 = 400 we = p x t = 400 x 1 = 400 whhence, in case (ii), the electrical energy consumed per hour is more. All that is needed is some sort of wave-shape that sweeps the oscilloscope beam to and fro. Since the relationship between vertical displacement and horizontal displacement on the oscilloscope’s trace is purely a function of the test component’s characteristic curve, we really don’t care what form of [AC](https://www.allaboutcircuits.com/textbook/alternating-current/chpt-1/what-is-alternating-current-ac/) voltage excites it. Solution


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![image](https://q2a.s3.us-west-1.amazonaws.com/prod/answer-four-long-current-carrying-wires-planeintersect-form-square-side-lengths-1.gif) Don't kno if you'll see this Davey, but have ya been currently testing it? If so, whaddya think? The binding energy in H atom

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If proton and neutron had charge e' each and were governed by the same electrostatic force, then in the above equation we would need to replace electronic mass m by the reduced mass m' of proton-neutron and the electronic charge e by e' .

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