consider a collision between an oxygen molecule and a hydrogen molecule in a mixture of oxygen and hydrogen kept at room temperature. which of the following are possible?
1. according to kinetic theory of ideal gases, molecules of a gas are in incessant random motion, colliding against each other and with the walls of the container. all these collisions are perfectly elastic collision.2. in perfectly elastic collision, total kinetic energy of gas is conserved.3. here, we have a mixture of oxygen and hydrogen gas. thereforek.e of oxygen + k.e of hydrogen=constant4. so, if kinetic energy of oxygen molecules increases, then kinetic energy of hydrogen molecules decreases or vice-versa so that, sum of both kinetic energies remains constant.5. therefore, both option (c) and (d) are correct.
oxygen in recall that there are several types of intermolecular forces:1. ion-dipole interaction – occurs between an ion and a polar covalent compound2. hydrogen bonding – occurs in compounds where hydrogen is directly connected to an electronegative element such as n, o, or f3. dipole-dipole interaction – occurs between two polar covalent compounds4. induced-dipole interaction – occurs when a nonpolar compound interacts with a polar compound5. dispersion forces – occurs in all compounds. this is the primary intermolecular force exhibited by nonpolar compounds.[readmore]although hcl is a polar molecule, it still exhibits dispersion forces because it occurs in all compounds **Pure substance – ethyl alcohol, oxygen, carbon, distilled water mixture – blood, steel** <p>concepts and reason</p>
<p>the concept used to solve this problem is the formal charge calculation of the oxygen atoms present in the ozone molecule.</p>
<p>fundamentals</p>
<p>a charge that is assigned to an atom, which is present in the molecule, is represented as a formal charge. in two bonded atoms, a formal charge assumes that the electrons are equally shared between them. the formal charge is calculated using the following formula:</p>
<p>formal charge \(=\mathrm{v}-\mathrm{n}-\frac{\mathrm{b}}{2}\)</p>
<p>here, \(\mathrm{v}\) is the number of valence electrons, \(\mathrm{n}\) is the number of non-bonding electrons and \(\mathrm{b}\) is the number of bonding electrons.</p>
<p> </p>
<p>the structure is as follows:</p>
<p>calculate the formal charge for the circled oxygen in ozone molecule as follows:</p>
<p><img src="https://img.wizedu.com/images/5af6d1f54822b4dfb8fe89d91ef2011c5fe3020815aa4.png" alt="" width="88" /></p>
<p>formal charge \(=\mathrm{v}-\mathrm{n}-\frac{\mathrm{b}}{2}\)</p>
<p>\(\begin{aligned}=& 6-6-\frac{2}{2} \\ &=-1 \end{aligned}\)</p>
<p>explanation | common mistakes | hint for next step</p>
<p>the marked oxygen atom has 6 valence electrons. it contains 6 non-bonding electrons. the marked oxygen atom is bonded with one oxygen atom. therefore, the bonding electron of oxygen is \(2 .\) substitute the values in a formal charge formula to determine the formal charge of oxygen (marked).</p>
<p> </p>
<p>the structure is as follows:</p>
<p><img src="https://img.wizedu.com/images/39493056a8515708b79350d1976e17b35fe30216f0473.png" alt="" width="88" /></p>
<p>calculate the formal charge for the circled oxygen in ozone molecule as follows:</p>
<p>formal charge \(=\mathrm{v}-\mathrm{n}-\frac{\mathrm{b}}{2}\)</p>
<p>\(=6-2-\frac{6}{2}\)</p>
<p>\(=+1\)</p>
<p>explanation | common mistakes | hint for next step</p>
<p>the oxygen atom in the middle has 6 valence electrons and has 2 non-bonding electrons. the central oxygen atom is bonded with 1 double bond and 1 single bond. so, there is a total of 3 bonds containing 6 electrons (bonding electrons). the formal charge of the middle oxygen atom can be determined by substituting the values in a formal charge formula.</p>
<p> </p>
<p>the structure is as follows:</p>
<p><img src="https://img.wizedu.com/images/b1122ce7723aa4ab1f9ae5c9e457299e5fe3022ca77a5.png" alt="" width="88" /></p>
<p>calculate the formal charge for the circled oxygen in ozone molecule as follows:</p>
<p>formal charge \(=\mathrm{v}-\mathrm{n}-\frac{\mathrm{b}}{2}\)</p>
<p>\(=6-4-\frac{4}{2}\)</p>
<p>\(=0\)</p>
<p>the formal charge of each oxygen atom in \(\mathrm{o}\_{3}\) molecule are labeled as follows:</p>
<p><img src="https://img.wizedu.com/images/1de5ee227194f6d8c7fb9fb0e76160f25fe3024117fde.png" alt="" width="120" /></p>
<p>the oxygen atom present on the right side contains 6 valence electrons which have 2 non-bonded electrons. the marked oxygen is bonded with 1 double bond with a central oxygen atom. so, the number of bonding electrons is \(4 .\) the formal charge of the corner oxygen atom (right corner) can be determined by substituting the values in the formal charge formula.</p>
<p>the formal charge of each oxygen atom in \(\mathrm{o}\_{3}\) molecule are labeled as follows:</p>
<p><img src="https://img.wizedu.com/images/1de5ee227194f6d8c7fb9fb0e76160f25fe3024117fde.png" alt="" width="120" /></p> Actually, it could be either hydrogen or methane. Both have been used but both are HIGHLY flammable, and methane even MORE dangerous than hydrogen is.   

  

I quote from the article cited below:   

  

With Helium being expensive and now subject to shortage, many people are looking for more available and inexpensive alternatives.   

  

But it surprises me that party balloons sold anywhere in the USA are even ALLOWED to be filled with ANYTHING BUT Helium! Regardless of being more expensive and there being a shortage, if I were a RETAILER, I would not want the chance of a LAWSUIT from the damages, medical or otherwise, which can be so READILY caused by using hydrogen or methane.   

  

Do you remember the old TV show from the 1970's, "Love Boat?" The actor who played, "Gopher," Fred Grandy, had his hands horribly burned by balloons that were filled with hydrogen, and were popped and exploded. I quote from second article below:   

  

But in 1982, a scary accident occurred in a Turkish taxi: A cigarette ignited some balloons that were inexplicably filled with hydrogen, injuring Tewes, Grandy, and several others; Grandy suffered severe burns on his hands and face.   

  

So, there you have it. If I were you, I would try to find out WHERE he got that balloon, and then AVOID getting any future "supplies" from them AT ALL!!! You don't want to mess with that dangerous stuff!   

  

  

Me… kittyslave23… I know my place. hydrogen gas in its natural state consists of molecules of h2, where two hydrogen atoms are bound together by a 100% covalent bond.

the h2 molecules are attracted to each other by london dispersion forces. london dispersion forces result from the formation of temporary dipoles. reno, please don't answer organic chemistry questions if you don't know the subject matter.
 
mixing acetic acid with sodium bicarbonate doesn't yield "gaseous water." also, you didn't actually answer the question and decided instead to list the first thing you found in wikipedia about a dangerous reaction that has nothing to do with the fact that acetic acid and hcl react the same way because they are both stronger acids than the conjugate acid of bicarbonate. answer: oxygen gas is responsible for combustion. combustion is characterized as a rapid exothermic reaction that releases a significant amount of energy in the form of heat and flames as combustion reactions that can spread through a suitable medium. combustion is the outcome of dynamic or time-dependent activities between atoms, molecules, radicals, and solid boundaries at the molecular level. for combustion to occur, three conditions must be met, which are there should be a combustible material. there should be a supporter of combustion. the combustible material is heated to the ignition temperature. the presence of fuel has a significant effect. the existence of oxygen or air. the ignition temperature is kept constant. be very careful. hydrogen peroxide can damage you ears and cause serious trouble. see more... more like retain oxygen intake /efficiency.