<p>I have a binary file that I have to parse and I'm using Python. Is there a way to take 4 bytes and convert it to a single precision floating point number?</p>

[{'answer_id': 73281, 'author': 'tzot', 'author_id': 6899, 'author_profile': 'https://Stackoverflow.com/users/6899', 'pm_score': 8, 'selected': True, 'text': "<pre><code>&gt;&gt;&gt; import struct\n&gt;&gt;&gt; struct.pack('f', 3.141592654)\nb'\\xdb\\x0fI@'\n&gt;&gt;&gt; struct.unpack('f', b'\\xdb\\x0fI@')\n(3.1415927410125732,)\n&gt;&gt;&gt; struct.pack('4f', 1.0, 2.0, 3.0, 4.0)\n'\\x00\\x00\\x80?\\x00\\x00\\x00@\\x00\\x00@@\\x00\\x00\\x80@'\n</code></pre>\n"}, {'answer_id': 54168810, 'author': 'NDM', 'author_id': 6585198, 'author_profile': 'https://Stackoverflow.com/users/6585198', 'pm_score': 4, 'selected': False, 'text': "<p>Just a little addition, if you want a float number as output from the unpack method instead of a tuple just write</p>\n<pre><code>&gt;&gt;&gt; import struct\n&gt;&gt;&gt; [x] = struct.unpack('f', b'\\xdb\\x0fI@')\n&gt;&gt;&gt; x\n3.1415927410125732\n</code></pre>\n<p>If you have more floats then just write</p>\n<pre><code>&gt;&gt;&gt; import struct\n&gt;&gt;&gt; [x,y] = struct.unpack('ff', b'\\xdb\\x0fI@\\x0b\\x01I4')\n&gt;&gt;&gt; x\n3.1415927410125732\n&gt;&gt;&gt; y\n1.8719963179592014e-07\n&gt;&gt;&gt; \n</code></pre>\n"}, {'answer_id': 73420517, 'author': 'Chance Cuddeback', 'author_id': 13674247, 'author_profile': 'https://Stackoverflow.com/users/13674247', 'pm_score': 2, 'selected': False, 'text': "<p>I would add a comment but I don't have enough reputation.</p>\n<p>Just to add some info. If you have a byte buffer containing X amount of floats, the syntax for unpacking would be:</p>\n<pre><code>struct.unpack('Xf', ...)\n</code></pre>\n<p>If the values are doubles the unpacking would be:</p>\n<pre><code>struct.unpack('Xd', ...)\n</code></pre>\n"}]
['https://Stackoverflow.com/questions/5415', 'https://Stackoverflow.com', 'https://Stackoverflow.com/users/680/']