Chapter
stringclasses 18
values | sentence_range
stringlengths 3
9
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stringlengths 7
7.34k
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|---|---|---|
9
|
3939-3942
|
5 cm |
|
ue (25/6) cm = 4 17 cm The
separation between the objective and the eye-piece should be (7
|
9
|
3940-3943
|
|
|
ue (25/6) cm = 4 17 cm The
separation between the objective and the eye-piece should be (7 5 +
4
|
9
|
3941-3944
|
17 cm The
separation between the objective and the eye-piece should be (7 5 +
4 17) cm = 11
|
9
|
3942-3945
|
The
separation between the objective and the eye-piece should be (7 5 +
4 17) cm = 11 67 cm
|
9
|
3943-3946
|
5 +
4 17) cm = 11 67 cm Further the object should be placed 1
|
9
|
3944-3947
|
17) cm = 11 67 cm Further the object should be placed 1 5 cm from
the objective to obtain the desired magnification
|
9
|
3945-3948
|
67 cm Further the object should be placed 1 5 cm from
the objective to obtain the desired magnification 9
|
9
|
3946-3949
|
Further the object should be placed 1 5 cm from
the objective to obtain the desired magnification 9 27
(a)
m = ( fO/fe) = 28
(b)
m = f
f
f
e
O
O
1
+25
= 33
|
9
|
3947-3950
|
5 cm from
the objective to obtain the desired magnification 9 27
(a)
m = ( fO/fe) = 28
(b)
m = f
f
f
e
O
O
1
+25
= 33 6
Rationalised 2023-24
350
Physics
9
|
9
|
3948-3951
|
9 27
(a)
m = ( fO/fe) = 28
(b)
m = f
f
f
e
O
O
1
+25
= 33 6
Rationalised 2023-24
350
Physics
9 28
(a)
fO + fe = 145 cm
(b)
Angle subtended by the tower = (100/3000) = (1/30) rad
|
9
|
3949-3952
|
27
(a)
m = ( fO/fe) = 28
(b)
m = f
f
f
e
O
O
1
+25
= 33 6
Rationalised 2023-24
350
Physics
9 28
(a)
fO + fe = 145 cm
(b)
Angle subtended by the tower = (100/3000) = (1/30) rad Angle subtended by the image produced by the objective
=
O
140
h
h
f
=
Equating the two, h = 4
|
9
|
3950-3953
|
6
Rationalised 2023-24
350
Physics
9 28
(a)
fO + fe = 145 cm
(b)
Angle subtended by the tower = (100/3000) = (1/30) rad Angle subtended by the image produced by the objective
=
O
140
h
h
f
=
Equating the two, h = 4 7 cm
|
9
|
3951-3954
|
28
(a)
fO + fe = 145 cm
(b)
Angle subtended by the tower = (100/3000) = (1/30) rad Angle subtended by the image produced by the objective
=
O
140
h
h
f
=
Equating the two, h = 4 7 cm (c)
Magnification (magnitude) of the eye-piece = 6
|
9
|
3952-3955
|
Angle subtended by the image produced by the objective
=
O
140
h
h
f
=
Equating the two, h = 4 7 cm (c)
Magnification (magnitude) of the eye-piece = 6 Height of the
final image (magnitude) = 28 cm
|
9
|
3953-3956
|
7 cm (c)
Magnification (magnitude) of the eye-piece = 6 Height of the
final image (magnitude) = 28 cm 9
|
9
|
3954-3957
|
(c)
Magnification (magnitude) of the eye-piece = 6 Height of the
final image (magnitude) = 28 cm 9 29
The image formed by the larger (concave) mirror acts as virtual object
for the smaller (convex) mirror
|
9
|
3955-3958
|
Height of the
final image (magnitude) = 28 cm 9 29
The image formed by the larger (concave) mirror acts as virtual object
for the smaller (convex) mirror Parallel rays coming from the object
at infinity will focus at a distance of 110 mm from the larger mirror
|
9
|
3956-3959
|
9 29
The image formed by the larger (concave) mirror acts as virtual object
for the smaller (convex) mirror Parallel rays coming from the object
at infinity will focus at a distance of 110 mm from the larger mirror The distance of virtual object for the smaller mirror = (110 –20) =
90 mm
|
9
|
3957-3960
|
29
The image formed by the larger (concave) mirror acts as virtual object
for the smaller (convex) mirror Parallel rays coming from the object
at infinity will focus at a distance of 110 mm from the larger mirror The distance of virtual object for the smaller mirror = (110 –20) =
90 mm The focal length of smaller mirror is 70 mm
|
9
|
3958-3961
|
Parallel rays coming from the object
at infinity will focus at a distance of 110 mm from the larger mirror The distance of virtual object for the smaller mirror = (110 –20) =
90 mm The focal length of smaller mirror is 70 mm Using the mirror
formula, image is formed at 315 mm from the smaller mirror
|
9
|
3959-3962
|
The distance of virtual object for the smaller mirror = (110 –20) =
90 mm The focal length of smaller mirror is 70 mm Using the mirror
formula, image is formed at 315 mm from the smaller mirror 9
|
9
|
3960-3963
|
The focal length of smaller mirror is 70 mm Using the mirror
formula, image is formed at 315 mm from the smaller mirror 9 30
The reflected rays get deflected by twice the angle of rotation of the
mirror
|
9
|
3961-3964
|
Using the mirror
formula, image is formed at 315 mm from the smaller mirror 9 30
The reflected rays get deflected by twice the angle of rotation of the
mirror Therefore, d/1
|
9
|
3962-3965
|
9 30
The reflected rays get deflected by twice the angle of rotation of the
mirror Therefore, d/1 5 = tan 7°
|
9
|
3963-3966
|
30
The reflected rays get deflected by twice the angle of rotation of the
mirror Therefore, d/1 5 = tan 7° Hence d = 18
|
9
|
3964-3967
|
Therefore, d/1 5 = tan 7° Hence d = 18 4 cm
|
9
|
3965-3968
|
5 = tan 7° Hence d = 18 4 cm 9
|
9
|
3966-3969
|
Hence d = 18 4 cm 9 31
n = 1
|
9
|
3967-3970
|
4 cm 9 31
n = 1 33
CHAPTER 10
10
|
9
|
3968-3971
|
9 31
n = 1 33
CHAPTER 10
10 1
(a)
Reflected light: (wavelength, frequency, speed same as incident
light)
l = 589 nm, n = 5
|
9
|
3969-3972
|
31
n = 1 33
CHAPTER 10
10 1
(a)
Reflected light: (wavelength, frequency, speed same as incident
light)
l = 589 nm, n = 5 09 ´ 1014 Hz, c = 3
|
9
|
3970-3973
|
33
CHAPTER 10
10 1
(a)
Reflected light: (wavelength, frequency, speed same as incident
light)
l = 589 nm, n = 5 09 ´ 1014 Hz, c = 3 00 ´ 108 m s–1
(b)
Refracted light: (frequency same as the incident frequency)
n = 5
|
9
|
3971-3974
|
1
(a)
Reflected light: (wavelength, frequency, speed same as incident
light)
l = 589 nm, n = 5 09 ´ 1014 Hz, c = 3 00 ´ 108 m s–1
(b)
Refracted light: (frequency same as the incident frequency)
n = 5 09 ´ 1014Hz
v = (c/n) = 2
|
9
|
3972-3975
|
09 ´ 1014 Hz, c = 3 00 ´ 108 m s–1
(b)
Refracted light: (frequency same as the incident frequency)
n = 5 09 ´ 1014Hz
v = (c/n) = 2 26 × 108 m s–1, l = (v/n) = 444 nm
10
|
9
|
3973-3976
|
00 ´ 108 m s–1
(b)
Refracted light: (frequency same as the incident frequency)
n = 5 09 ´ 1014Hz
v = (c/n) = 2 26 × 108 m s–1, l = (v/n) = 444 nm
10 2
(a)
Spherical
(b)
Plane
(c)
Plane (a small area on the surface of a large sphere is nearly
planar)
|
9
|
3974-3977
|
09 ´ 1014Hz
v = (c/n) = 2 26 × 108 m s–1, l = (v/n) = 444 nm
10 2
(a)
Spherical
(b)
Plane
(c)
Plane (a small area on the surface of a large sphere is nearly
planar) 10
|
9
|
3975-3978
|
26 × 108 m s–1, l = (v/n) = 444 nm
10 2
(a)
Spherical
(b)
Plane
(c)
Plane (a small area on the surface of a large sphere is nearly
planar) 10 3
(a)
2
|
9
|
3976-3979
|
2
(a)
Spherical
(b)
Plane
(c)
Plane (a small area on the surface of a large sphere is nearly
planar) 10 3
(a)
2 0 × 108 m s–1
(b)
No
|
9
|
3977-3980
|
10 3
(a)
2 0 × 108 m s–1
(b)
No The refractive index, and hence the speed of light in a
medium, depends on wavelength
|
9
|
3978-3981
|
3
(a)
2 0 × 108 m s–1
(b)
No The refractive index, and hence the speed of light in a
medium, depends on wavelength [When no particular
wavelength or colour of light is specified, we may take the given
refractive index to refer to yellow colour
|
9
|
3979-3982
|
0 × 108 m s–1
(b)
No The refractive index, and hence the speed of light in a
medium, depends on wavelength [When no particular
wavelength or colour of light is specified, we may take the given
refractive index to refer to yellow colour ] Now we know violet
colour deviates more than red in a glass prism, i
|
9
|
3980-3983
|
The refractive index, and hence the speed of light in a
medium, depends on wavelength [When no particular
wavelength or colour of light is specified, we may take the given
refractive index to refer to yellow colour ] Now we know violet
colour deviates more than red in a glass prism, i e
|
9
|
3981-3984
|
[When no particular
wavelength or colour of light is specified, we may take the given
refractive index to refer to yellow colour ] Now we know violet
colour deviates more than red in a glass prism, i e nv > nr
|
9
|
3982-3985
|
] Now we know violet
colour deviates more than red in a glass prism, i e nv > nr Therefore, the violet component of white light travels slower than
the red component
|
9
|
3983-3986
|
e nv > nr Therefore, the violet component of white light travels slower than
the red component 10
|
9
|
3984-3987
|
nv > nr Therefore, the violet component of white light travels slower than
the red component 10 4
1 2 10
0 28 10
4 14
|
9
|
3985-3988
|
Therefore, the violet component of white light travels slower than
the red component 10 4
1 2 10
0 28 10
4 14 – 2
– 3
m = 600 nm
10
|
9
|
3986-3989
|
10 4
1 2 10
0 28 10
4 14 – 2
– 3
m = 600 nm
10 5
K/4
10
|
9
|
3987-3990
|
4
1 2 10
0 28 10
4 14 – 2
– 3
m = 600 nm
10 5
K/4
10 6
(a) 1
|
9
|
3988-3991
|
– 2
– 3
m = 600 nm
10 5
K/4
10 6
(a) 1 17 mm
(b) 1
|
9
|
3989-3992
|
5
K/4
10 6
(a) 1 17 mm
(b) 1 56 mm
10
|
9
|
3990-3993
|
6
(a) 1 17 mm
(b) 1 56 mm
10 7
0
|
9
|
3991-3994
|
17 mm
(b) 1 56 mm
10 7
0 15°
10
|
9
|
3992-3995
|
56 mm
10 7
0 15°
10 8
tan–1(1
|
9
|
3993-3996
|
7
0 15°
10 8
tan–1(1 5) ~ 56
|
9
|
3994-3997
|
15°
10 8
tan–1(1 5) ~ 56 3o
Rationalised 2023-24
351
Answers
10
|
9
|
3995-3998
|
8
tan–1(1 5) ~ 56 3o
Rationalised 2023-24
351
Answers
10 9
5000 Å, 6 × 1014 Hz; 45°
10
|
9
|
3996-3999
|
5) ~ 56 3o
Rationalised 2023-24
351
Answers
10 9
5000 Å, 6 × 1014 Hz; 45°
10 10 40 m
CHAPTER 11
11
|
9
|
3997-4000
|
3o
Rationalised 2023-24
351
Answers
10 9
5000 Å, 6 × 1014 Hz; 45°
10 10 40 m
CHAPTER 11
11 1
(a)
7
|
9
|
3998-4001
|
9
5000 Å, 6 × 1014 Hz; 45°
10 10 40 m
CHAPTER 11
11 1
(a)
7 24 × 1018 Hz (b) 0
|
9
|
3999-4002
|
10 40 m
CHAPTER 11
11 1
(a)
7 24 × 1018 Hz (b) 0 041 nm
11
|
9
|
4000-4003
|
1
(a)
7 24 × 1018 Hz (b) 0 041 nm
11 2
(a)
0
|
9
|
4001-4004
|
24 × 1018 Hz (b) 0 041 nm
11 2
(a)
0 34 eV = 0
|
9
|
4002-4005
|
041 nm
11 2
(a)
0 34 eV = 0 54 × 10–19J (b) 0
|
9
|
4003-4006
|
2
(a)
0 34 eV = 0 54 × 10–19J (b) 0 34 V (c) 344 km/s
11
|
9
|
4004-4007
|
34 eV = 0 54 × 10–19J (b) 0 34 V (c) 344 km/s
11 3
1
|
9
|
4005-4008
|
54 × 10–19J (b) 0 34 V (c) 344 km/s
11 3
1 5 eV = 2
|
9
|
4006-4009
|
34 V (c) 344 km/s
11 3
1 5 eV = 2 4 × 10–19 J
11
|
9
|
4007-4010
|
3
1 5 eV = 2 4 × 10–19 J
11 4
(a)
3
|
9
|
4008-4011
|
5 eV = 2 4 × 10–19 J
11 4
(a)
3 14 × 10–19J, 1
|
9
|
4009-4012
|
4 × 10–19 J
11 4
(a)
3 14 × 10–19J, 1 05 × 10–27 kg m/s (b) 3 × 1016 photons/s
(c) 0
|
9
|
4010-4013
|
4
(a)
3 14 × 10–19J, 1 05 × 10–27 kg m/s (b) 3 × 1016 photons/s
(c) 0 63 m/s
11
|
9
|
4011-4014
|
14 × 10–19J, 1 05 × 10–27 kg m/s (b) 3 × 1016 photons/s
(c) 0 63 m/s
11 5
6
|
9
|
4012-4015
|
05 × 10–27 kg m/s (b) 3 × 1016 photons/s
(c) 0 63 m/s
11 5
6 59 × 10–34 J s
11
|
9
|
4013-4016
|
63 m/s
11 5
6 59 × 10–34 J s
11 6
2
|
9
|
4014-4017
|
5
6 59 × 10–34 J s
11 6
2 0 V
11
|
9
|
4015-4018
|
59 × 10–34 J s
11 6
2 0 V
11 7
No, because n < no
11
|
9
|
4016-4019
|
6
2 0 V
11 7
No, because n < no
11 8
4
|
9
|
4017-4020
|
0 V
11 7
No, because n < no
11 8
4 73 × 1014 Hz
11
|
9
|
4018-4021
|
7
No, because n < no
11 8
4 73 × 1014 Hz
11 9
2
|
9
|
4019-4022
|
8
4 73 × 1014 Hz
11 9
2 16 eV = 3
|
9
|
4020-4023
|
73 × 1014 Hz
11 9
2 16 eV = 3 46 × 10–19J
11
|
9
|
4021-4024
|
9
2 16 eV = 3 46 × 10–19J
11 10 (a)
1
|
9
|
4022-4025
|
16 eV = 3 46 × 10–19J
11 10 (a)
1 7 × 10–35 m (b) 1
|
9
|
4023-4026
|
46 × 10–19J
11 10 (a)
1 7 × 10–35 m (b) 1 1 × 10–32 m (c) 3
|
9
|
4024-4027
|
10 (a)
1 7 × 10–35 m (b) 1 1 × 10–32 m (c) 3 0 × 10–23 m
11
|
9
|
4025-4028
|
7 × 10–35 m (b) 1 1 × 10–32 m (c) 3 0 × 10–23 m
11 11 l = h/p = h/(hn/c) = c/n
CHAPTER 12
12
|
9
|
4026-4029
|
1 × 10–32 m (c) 3 0 × 10–23 m
11 11 l = h/p = h/(hn/c) = c/n
CHAPTER 12
12 1
(a) No different from
(b) Thomson’s model; Rutherford’s model
(c) Rutherford’s model
(d) Thomson’s model; Rutherford’s model
(e) Both the models
12
|
9
|
4027-4030
|
0 × 10–23 m
11 11 l = h/p = h/(hn/c) = c/n
CHAPTER 12
12 1
(a) No different from
(b) Thomson’s model; Rutherford’s model
(c) Rutherford’s model
(d) Thomson’s model; Rutherford’s model
(e) Both the models
12 2
The nucleus of a hydrogen atom is a proton
|
9
|
4028-4031
|
11 l = h/p = h/(hn/c) = c/n
CHAPTER 12
12 1
(a) No different from
(b) Thomson’s model; Rutherford’s model
(c) Rutherford’s model
(d) Thomson’s model; Rutherford’s model
(e) Both the models
12 2
The nucleus of a hydrogen atom is a proton The mass of it is
1
|
9
|
4029-4032
|
1
(a) No different from
(b) Thomson’s model; Rutherford’s model
(c) Rutherford’s model
(d) Thomson’s model; Rutherford’s model
(e) Both the models
12 2
The nucleus of a hydrogen atom is a proton The mass of it is
1 67 × 10–27 kg, whereas the mass of an incident a-particle is
6
|
9
|
4030-4033
|
2
The nucleus of a hydrogen atom is a proton The mass of it is
1 67 × 10–27 kg, whereas the mass of an incident a-particle is
6 64 × 10–27 kg
|
9
|
4031-4034
|
The mass of it is
1 67 × 10–27 kg, whereas the mass of an incident a-particle is
6 64 × 10–27 kg Because the scattering particle is more massive than
the target nuclei (proton), the a-particle won’t bounce back in even
in a head-on collision
|
9
|
4032-4035
|
67 × 10–27 kg, whereas the mass of an incident a-particle is
6 64 × 10–27 kg Because the scattering particle is more massive than
the target nuclei (proton), the a-particle won’t bounce back in even
in a head-on collision It is similar to a football colliding with a tenis
ball at rest
|
9
|
4033-4036
|
64 × 10–27 kg Because the scattering particle is more massive than
the target nuclei (proton), the a-particle won’t bounce back in even
in a head-on collision It is similar to a football colliding with a tenis
ball at rest Thus, there would be no large-angle scattering
|
9
|
4034-4037
|
Because the scattering particle is more massive than
the target nuclei (proton), the a-particle won’t bounce back in even
in a head-on collision It is similar to a football colliding with a tenis
ball at rest Thus, there would be no large-angle scattering 12
|
9
|
4035-4038
|
It is similar to a football colliding with a tenis
ball at rest Thus, there would be no large-angle scattering 12 3
5
|
9
|
4036-4039
|
Thus, there would be no large-angle scattering 12 3
5 6 ´ 1014 Hz
12
|
9
|
4037-4040
|
12 3
5 6 ´ 1014 Hz
12 4
13
|
9
|
4038-4041
|
3
5 6 ´ 1014 Hz
12 4
13 6 eV; –27
|
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