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For each test case, output a single integer: the maximum possible size of a deck if you operate optimally.
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In the first test case, you can buy one card with the number $1$, and your cards become $[1, 1, 1, 1, 2, 2, 3, 3]$. You can partition them into the decks $[1, 2], [1, 2], [1, 3], [1, 3]$: they all have size $2$, and they all contain distinct values. You can show that you cannot get a partition with decks of size greater than $2$, so the answer is $2$.
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In the second test case, you can buy two cards with the number $1$ and o
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Mocha likes arrays, so before her departure, Bazoka gave her an array $a$ consisting of $n$ positive integers as a gift.
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Now Mocha wants to know whether array $a$ could become sorted in non- decreasing order after performing the following operation some (possibly, zero) times:
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* Split the array into two parts — a prefix and a suffix, then swap these two parts. In other words, let $a=x+y$. Then, we can set $a:= y+x$. Here $+$ denotes the array concatenation operation.
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For example, if $a=[3,1,4,1,5]$, we can choose $x=[3,1]$ and $y=[4,1,5]$, satisfying $a=x+y$. Then, we can set $a:= y + x = [4,1,5,3,1]$. We can also choose $x=[3,1,4,1,5]$ and $y=[\,]$, satisfying $a=x+y$. Then, we can set $a := y+x = [3,1,4,1,5]$. Note that we are not allowed to choose $x=[3,1,1]$ and $y=[4,5]$, neither are we allowed to choose $x=[1,3]$ and $y=[5,1,4]$, as both these choices do not satisfy $a=x+y$.
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Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1\leq t\leq 1000$). The description of the test cases follows.
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The first line of each test case contains a single integer $n$ ($2\leq n\leq 50$) — the length of the array $a$.
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The second line of each test case contains $n$ integers $a_1,a_2,\ldots,a_n$ ($1\leq a_i \leq 10^6$) — the elements of array $a$.
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For each test case, output "Yes" if $a$ could become non-decreasing after performing the operation any number of times, and output "No" if not.
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You can output "Yes" and "No" in any case (for example, strings "yEs", "yes", "Yes" and "YES" will be recognized as a positive response).
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In the first test case, it can be proven that $a$ cannot become non- decreasing after performing the operation any number of times.
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In the second test case, we can perform the following operations to make $a$ sorted in non-decreasing order:
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* Split the array into two parts: $x=[7]$ and $y=[9,2,2,3]$, then swap these two parts. The array will become $y+x = [9,2,2,3,7]$. * Split the array into two parts: $x=[9]$ and $y=[2,2,3,7]$, then swap the
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[EnV - The Dusty Dragon Tavern](https://soundcloud.com/envyofficial/env-the- dusty-dragon-tavern)
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⠀
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You are given an array $a_1, a_2, \ldots, a_n$ of positive integers.
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You can color some elements of the array red, but there cannot be two adjacent red elements (i.e., for $1 \leq i \leq n-1$, at least one of $a_i$ and $a_{i+1}$ must not be red).
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Your score is the maximum value of a red element, plus the minimum value of a red element, plus the number of red elements. Find the maximum score you can get.
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Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 10^4$). The description of the test cases follows.
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The first line of each test case contains a single integer $n$ ($1 \le n \le 2 \cdot 10^5$) — the length of the array.
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The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^9$) — the given array.
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It is guaranteed that the sum of $n$ over all test cases does not exceed $2 \cdot 10^5$.
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For each test case, output a single integer: the maximum possible score you can get after coloring some elements red according to the statement.
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In the first test case, you can color the array as follows: $[\color{red}{5}, 4, \color{red}{5}]$. Your score is $\max([5, 5]) + \min([5, 5]) + \text{size}([5, 5]) = 5+5+2 = 12$. This is the maximum score you can get.
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In the second test case, you can color the array as follows: $[4, \color{red}{5}, 4]$. Your score is $\max([5]) + \min([5]) + \text{size}([5]) = 5+5+1 = 11$. This is the maximum score you can get.
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In the third test case, you can color the array as follows: $[\color{red}{3}, 3, \color{red}{3}, 3, \color{red}{4}, 1, 2, \color{red}{3}, 5, \color{red}{4}]$. Your score is $\max([3, 3, 4, 3, 4]) + \min([3, 3, 4, 3, 4]) + \text{size}([3, 3, 4, 3, 4]) = 4+3+5 = 12$. This is the maximum score you can get.
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[Ken Arai - COMPLEX](https://soundcloud.com/diatomichail2/complex)
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⠀
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This is the hard version of the problem. In this version, the constraints on $n$ and the time limit are higher. You can make hacks only if both versions of the problem are solved.
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A set of (closed) segments is complex if it can be partitioned into some subsets such that
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* all the subsets have the same size; and * a pair of segments intersects if and only if the two segments are in the same subset.
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You are given $n$ segments $[l_1, r_1], [l_2, r_2], \ldots, [l_n, r_n]$. Find the maximum size of a complex subset of these segments.
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Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 10^3$). The description of the test cases follows.
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The first line of each test case contains a single integer $n$ ($1 \le n \le 3 \cdot 10^5$) — the number of segments.
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The second line of each test case contains $n$ integers $l_1, l_2, \ldots, l_n$ ($1 \le l_i \le 2n$) — the left endpoints of the segments.
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The third line of each test case contains $n$ integers $r_1, r_2, \ldots, r_n$ ($l_i \leq r_i \le 2n$) — the right endpoints of the segments.
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It is guaranteed that the sum of $n$ over all test cases does not exceed $3 \cdot 10^5$.
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For each test case, output a single integer: the maximum size of a complex subset of the given segments.
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In the first test case, all pairs of segments intersect, therefore it is optimal to form a single group containing all of the three segments.
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In the second test case, there is no valid partition for all of the five segments. A valid partition with four segments is the following: $\\{\\{ [1, 5], [2, 4] \\}, \\{ [6, 9], [8, 10] \\}\\}$.
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In the third test case, it is optimal to make a single group containing all the segments except the second.
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[NightHawk22 - Isolation](https://soundcloud.com/vepium/nighthawk22-isolation- official-limbo-remix)
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⠀
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This is the medium version of the problem. In the three versions, the constraints on $n$ and the time limit are different. You can make hacks only if all the versions of the problem are solved.
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This is the statement of Problem D1B:
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* There are $n$ cities in a row, numbered $1, 2, \ldots, n$ left to right. * At time $1$, you conquer exactly one city, called the starting city. * At time $2, 3, \ldots, n$, you can choose a city adjacent to the ones conquered so far and conquer it.
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You win if, for each $i$, you conquer city $i$ at a time no later than $a_i$. A winning strategy may or may not exist, also depending on the starting city. How many starting cities allow you to win?
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For each $0 \leq k \leq n$, count the number of arrays of positive integers $a_1, a_2, \ldots, a_n$ such that
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* $1 \leq a_i \leq n$ for each $1 \leq i \leq n$; * the answer to Problem D1B is $k$.
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The answer can be very large, so you have to calculate it modulo a given prime $p$.
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