175: Solution with step by step explanation
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\nThis problem can be solved using a LEFT JOIN to combine the Person and Ad
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\nThis problem can be solved using a LEFT JOIN to combine the Person and Address tables based on their common column personId. The query would look like this:\n```\nSELECT Person.firstName, Person.lastName, Address.city, Address.state\nFROM Person\nLEFT JOIN Address\nON Person.personId = Address.personId;\n\n```\nHere, we select the firstName and lastName columns from the Person table, and the city and state columns from the Address table. We use a LEFT JOIN to combine the tables based on their personId columns. If a personId in the Person table doesn\'t have a corresponding entry in the Address table, the city and state columns will be NULL. We then return the resulting table.\n\nThis query should produce the desired output:\n```\n+-----------+----------+---------------+----------+\n| firstName | lastName | city          | state    |\n+-----------+----------+---------------+----------+\n| Allen     | Wang     | NULL          | NULL     |\n| Bob       | Alice    | New York City | New York |\n+-----------+----------+---------------+----------+\n\n```\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nSELECT Person.firstName, Person.lastName, Address.city, Address.state\nFROM Person\nLEFT JOIN Address\nON Person.personId = Address.personId;\n```
['Database', 'MySQL']