MySQL Solution for Sales Person Problem
Intuition\n Describe your first thoughts on how to solve this problem. \nThe given SQL query selects the names of salespersons from the "salesperson" table whos
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe given SQL query selects the names of salespersons from the "salesperson" table whose sales IDs are not present in the result of a subquery. The subquery retrieves sales IDs from the "orders" table based on a left join with the "company" table, filtering by the company name \'RED\'.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. The main query starts with the SELECT keyword followed by the column s.name, which represents the name of the salesperson.\n2. It specifies the table name salesperson as s.\n3. The WHERE clause is used to filter the records based on the condition s.sales_id NOT IN (...).\n4. The subquery within the NOT IN condition performs a left join between the "orders" and "company" tables, joining on the com_id column.\n5. It selects the sales IDs from the "orders" table where the associated company\'s name is \'RED\'.\n6. The main query excludes salespersons whose sales IDs are present in the result of the subquery.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nThe time complexity of this query depends on the size of the "salesperson" table, the "orders" table, and the execution efficiency of the join and subquery operations. The subquery performs a left join and filtering operation, which may require scanning the "orders" and "company" tables. The time complexity can vary but is typically linear or close to linear in the size of the "salesperson" table and the result of the subquery.\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nThe space complexity of the query depends on the number of salespersons whose sales IDs are not present in the result of the subquery. The database engine needs to store the intermediate result set of the subquery to perform the exclusion. The space complexity is proportional to the number of salespersons returned in the result set.\n\n# Code\n```\n# Write your MySQL query statement below\nselect s.name from salesperson as s \nwhere s.sales_id not in\n(\n    select sales_id from orders as o left join company as c\n    on o.com_id = c.com_id where c.name = \'RED\'\n)\n```
['MySQL']