Python3 check next palindrome - Prime Palindrome
\nclass Solution:\n    def primePalindrome(self, N: int) -> int:\n        def isPrime(N):\n            return N > 1 and all(N % d for d in range(2, int(N**0.5)+
```\nclass Solution:\n    def primePalindrome(self, N: int) -> int:\n        def isPrime(N):\n            return N > 1 and all(N % d for d in range(2, int(N**0.5)+1))\n        \n        # N must be a palindrome with odd number of digits.\n        # The return value will have odd number of digits too.\n        def nextPalindrome(N):\n            if N in [999, 99999, 9999999]:\n                return (N + 1) * 10 + 1\n            n = str(N // 10 ** (len(str(N))//2) + 1)\n            return int(n + n[-2::-1])\n        \n        if N <= 11: \n            while not isPrime(N):\n                N += 1\n            return N\n        \n        if (digits := len(str(N))) % 2 == 0:\n            N = 10 ** digits + 1\n        else:\n            n = str(N // 10 ** (len(str(N))//2))\n            if (p := int(n + n[-2::-1])) >= N:\n                N = p\n            else:\n                N = nextPalindrome(p)\n                \n        while not isPrime(N):\n            N = nextPalindrome(N)\n        return N\n```
['Math', 'Python', 'Python3']