simple and easy Python solution
if it\'s help, please up \u2B06 vote! \u2764\uFE0F\n\n###### Let\'s Connect on LinkedIn: www.linkedin.com/in/shishirrsiam\n###### Let\'s Connect on Facebook: ww
# if it\'s help, please up \u2B06 vote! \u2764\uFE0F\n\n###### Let\'s Connect on LinkedIn: www.linkedin.com/in/shishirrsiam\n###### Let\'s Connect on Facebook: www.fb.com/shishirrsiam\n\n# Complexity\n- Time complexity: O(n)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: O(n)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```python []\nclass Solution(object):\n    def uncommonFromSentences(self, s1, s2):\n        all_string = s1.split(\' \')\n        all_string += (s2.split(\' \'))\n        counter = Counter(all_string)\n\n        ans = []\n        for s, cnt in counter.items():\n            if cnt == 1:\n                ans.append(s)\n        return ans\n```
['Hash Table', 'String', 'Counting', 'Python', 'Python3']