Check If Splitting is Possible with Frequency Constraint Using C++
Intuition\nThe first step to determine if the array can be split is to ensure that no element appears more than twice, as this would violate the conditions for 
# Intuition\nThe first step to determine if the array can be split is to ensure that no element appears more than twice, as this would violate the conditions for a valid split.\n\n# Approach\n- Traverse the array and use an unordered map to count the frequency of each element.\n- If any element appears more than twice, return `false`.\n- If all elements meet the condition, return `true`.\n\n# Complexity\n- **Time complexity:** $$O(n)$$, where $$n$$ is the length of the array. We traverse the array once.\n- **Space complexity:** $$O(n)$$, since we use a map to store the frequency of each element.\n\n# Code\n```cpp\nclass Solution {\npublic:\n    bool isPossibleToSplit(vector<int>& nums) {\n        unordered_map<int, int> m; \n        for(auto i = nums.begin(); i != nums.end(); ++i) {\n            m[*i]++; \n            if(m[*i] > 2) {\n                return false; \n            }\n        }\n        return true; \n    }\n};\n```\n
['C++']