✅ Explained - Simple and Clear Python3 Code✅
\n# Approach\nThe solution follows the logic of iterating through the intervals to find the correct position to insert the new interval while maintaining the so
\n# Approach\nThe solution follows the logic of iterating through the intervals to find the correct position to insert the new interval while maintaining the sorted order. After insertion, it iterates over the modified array to merge any overlapping intervals by updating the end time of the previous interval if necessary. Finally, it returns the modified array with the new interval inserted and any overlapping intervals merged.\n\n# Code\n```\nclass Solution:\n    def insert(self, inv: List[List[int]], nw: List[int]) -> List[List[int]]:\n        #insert nw\n        test=True\n        for i in range(len(inv)):\n            if inv[i][0]>nw[0]:\n                test=False\n                inv.insert(i,nw)\n        if test:\n            inv.append(nw)\n\n        i=1\n        while i<len(inv):\n            if inv[i-1][1]>=inv[i][0]:\n                inv[i-1][1]=max (inv[i-1][1],inv[i][1])\n                inv.pop(i)\n            else:\n                i+=1\n            \n        return inv\n```
['Python3']