Solution By Dare2Solve | Detailed Explanation | Clean Code
Explanation []\nauthorslog.com/blog/uwRC8XVTlm\n\n# Code\n\ncpp []\nclass Solution {\npublic:\n    vector<string> uncommonFromSentences(string s1, string s2) {\
```Explanation []\nauthorslog.com/blog/uwRC8XVTlm\n```\n# Code\n\n```cpp []\nclass Solution {\npublic:\n    vector<string> uncommonFromSentences(string s1, string s2) {\n        unordered_map<string, int> wordCount;\n        istringstream iss1(s1), iss2(s2);\n        string word;\n\n        // Count words from s1\n        while (iss1 >> word) {\n            wordCount[word]++;\n        }\n\n        // Count words from s2\n        while (iss2 >> word) {\n            wordCount[word]++;\n        }\n\n        vector<string> result;\n        // Add words that appear only once to the result\n        for (auto& entry : wordCount) {\n            if (entry.second == 1) {\n                result.push_back(entry.first);\n            }\n        }\n        return result;\n    }\n};\n```\n\n```python []\nclass Solution:\n    def uncommonFromSentences(self, s1: str, s2: str) -> List[str]:\n        word_count = {}\n        words = (s1 + " " + s2).split()\n\n        # Count words\n        for word in words:\n            word_count[word] = word_count.get(word, 0) + 1\n\n        # Collect words that appear only once\n        return [word for word, count in word_count.items() if count == 1]\n```\n\n```java []\nclass Solution {\n    public String[] uncommonFromSentences(String s1, String s2) {\n        Map<String, Integer> wordCount = new HashMap<>();\n        String[] words = (s1 + " " + s2).split(" ");\n\n        // Count words\n        for (String word : words) {\n            wordCount.put(word, wordCount.getOrDefault(word, 0) + 1);\n        }\n\n        // Collect words that appear only once\n        List<String> result = new ArrayList<>();\n        for (Map.Entry<String, Integer> entry : wordCount.entrySet()) {\n            if (entry.getValue() == 1) {\n                result.add(entry.getKey());\n            }\n        }\n        return result.toArray(new String[0]);\n    }\n}\n```\n\n```javascript []\nvar uncommonFromSentences = function (s1, s2) {\n\n    const arr = [...s1.split(" "), ...s2.split(" ")];\n    const map = new Map();\n    \n    for (let i = 0; i < arr.length; i++) {\n        if (!map[arr[i]]) map[arr[i]] = 1;\n        else map[arr[i]]++;\n    }\n    let res = [];\n    for (const key of Object.keys(map)) {\n        if (map[key] === 1) res.push(key);\n    }\n    return res;\n};\n```
['Hash Table', 'String', 'Python', 'C++', 'Java', 'Python3', 'JavaScript']