Simplest Solution in Java for Beginners
Intuition\n Describe your first thoughts on how to solve this problem. \nUsing ArrayList to store and sort the Integers.\n\n# Approach\n Describe your approach 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nUsing ArrayList to store and sort the Integers.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n**Step-1**: Creating a ArrayList to store and sort the values.\n**Step-2**: Converting every string numeric values to Big Integers.\n\n***Note***: *Big Integers is used to handle testcases with large value.*\n\n**Step-3**: Sorting the Array with Big Integers.\n**Step-4**: Return the **k***th* largest value as output.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n    O(nlogn)\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n    O(n)\n\n# Code\n```\nimport java.math.*;\nclass Solution {\n    public String kthLargestNumber(String[] nums, int k) {\n        List<BigInteger> Nums = new ArrayList<>();\n        for(String n:nums){\n            Nums.add(new BigInteger(n));\n        }\n        Collections.sort(Nums);\n        int x = Nums.size()-k;\n        return String.valueOf(Nums.get(x));\n    }\n}\n```
['Java']