Python | Greedy
see the Successfully Accepted Submission\n\n# Code\n\nimport heapq\nfrom typing import List\n\nclass Solution:\n    def findMaximizedCapital(self, k: int, w: in
[see the Successfully Accepted Submission](https://leetcode.com/problems/ipo/submissions/1288724380/?envType=daily-question&envId=2024-06-15)\n\n# Code\n```\nimport heapq\nfrom typing import List\n\nclass Solution:\n    def findMaximizedCapital(self, k: int, w: int, profits: List[int], capital: List[int]) -> int:\n        # Combine capital and profits into one list of tuples and sort by capital\n        projects = sorted(zip(capital, profits))\n        \n        max_profit_heap = []\n        current_capital = w\n        project_index = 0\n        \n        for _ in range(k):\n            # Push all projects that can be started with current_capital into the max heap\n            while project_index < len(projects) and projects[project_index][0] <= current_capital:\n                heapq.heappush(max_profit_heap, -projects[project_index][1])\n                project_index += 1\n            \n            # If there are no projects that can be started, break\n            if not max_profit_heap:\n                break\n            \n            # Select the project with the maximum profit\n            current_capital += -heapq.heappop(max_profit_heap)\n        \n        return current_capital\n\n```\n# Maximizing Capital for LeetCode IPO\n\n## Understanding the Problem:\n\n- We are given a number of projects, each with a required capital to start and a profit once completed.\n- We start with an initial amount of capital, `w`, and we can choose up to `k` projects to maximize our final capital.\n\n## Greedy Strategy:\n\n- Since we want to maximize the capital, we should prioritize the projects with the highest profits that we can afford with our current capital.\n- To efficiently select these projects, we can use a max-heap (priority queue) to always pick the most profitable project available given our current capital.\n\n## Procedure:\n\n1. Store the projects as pairs of (capital required, profit).\n2. Sort the projects based on the capital required in ascending order.\n3. Use a min-heap to keep track of the smallest capital requirements and a max-heap to select the projects with the highest profits.\n4. Iterate over the projects and push them into the max-heap based on current available capital.\n5. Always pick the project with the highest profit from the max-heap that can be started with the current capital.\n6. Repeat until we have either completed `k` projects or no more projects can be started.\n\n## Algorithm:\n\n1. Sort the projects based on the capital required.\n2. Use a max-heap to store profits of the projects that can be afforded.\n3. Iterate through the projects, add the feasible ones to the max-heap, and pick the most profitable one at each step.\n\n\n![image](https://assets.leetcode.com/users/images/b1e4af48-4da1-486c-bc97-b11ae02febd0_1696186577.992237.jpeg)
['Python3']