PYTHON | SIMPLE DP WITH CODE EXPLAINATION
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\nDP\n# Complexity\n- Time complexity:\nO(2N)\n- Space complexity:\nO(2N)\n
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\nDP\n# Complexity\n- Time complexity:\nO(2N)\n- Space complexity:\nO(2N)\n\n# Code\nSure! Here\'s an explanation of the code with comments:\n\n```python\nclass Solution:\n    def maxNonDecreasingLength(self, nums1, nums2):\n        n = len(nums1)\n        # Initialize a 2D array to store the maximum non-decreasing subsequence length\n        dp = [[0,0] for _ in range(n)]\n        ans = 0\n\n        for i in range(n):\n            # Set the initial value of dp[i][0] and dp[i][1] to 1\n            dp[i][0] = dp[i][1] = 1\n\n            if i > 0:\n                # If the current element in nums1 is greater than or equal to the previous element in nums1,\n                # update dp[i][0] to be the maximum non-decreasing subsequence length ending at index i in nums1\n                if nums1[i] >= nums1[i - 1]:\n                    dp[i][0] = dp[i - 1][0] + 1\n\n                # If the current element in nums1 is greater than or equal to the previous element in nums2,\n                # update dp[i][0] to be the maximum non-decreasing subsequence length ending at index i in nums1\n                if nums1[i] >= nums2[i - 1]:\n                    dp[i][0] = max(dp[i][0], dp[i - 1][1] + 1)\n\n                # If the current element in nums2 is greater than or equal to the previous element in nums1,\n                # update dp[i][1] to be the maximum non-decreasing subsequence length ending at index i in nums2\n                if nums2[i] >= nums1[i - 1]:\n                    dp[i][1] = dp[i - 1][0] + 1\n\n                # If the current element in nums2 is greater than or equal to the previous element in nums2,\n                # update dp[i][1] to be the maximum non-decreasing subsequence length ending at index i in nums2\n                if nums2[i] >= nums2[i - 1]:\n                    dp[i][1] = max(dp[i][1], dp[i - 1][1] + 1)\n\n            # Update ans to be the maximum value of ans, dp[i][0], and dp[i][1]\n            ans = max(ans, max(dp[i][0], dp[i][1]))\n\n        return ans\n```
['Dynamic Programming', 'Python3']