Easy Solution beats 99.19 %
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```python3 []\nclass Solution:\n    def smallestValue(self, n: int) -> int:\n        def prime_factors(n):\n            factors = []\n            \n            # Divide by 2 to get rid of all even factors\n            while n % 2 == 0:\n                factors.append(2)\n                n //= 2\n            \n            # Try odd numbers starting from 3\n            for i in range(3, int(n**0.5) + 1, 2):\n                while n % i == 0:\n                    factors.append(i)\n                    n //= i\n            \n            # If n is still greater than 2, it must be a prime\n            if n > 2:\n                factors.append(n)\n            \n            return factors\n        \n        while True:\n            temp = prime_factors(n)      \n            factor_sum = sum(temp)\n            if factor_sum == n:\n                break\n            n = factor_sum\n        \n        return n\n```
['Python3']