Travelling Salesman Problem (TSP)
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```python3 []\nfrom typing import List\nimport itertools\nimport functools\n\nclass Solution:\n    def shortestSuperstring(self, words: List[str]) -> str:\n\n        # Function to calculate the overlap between two strings\n        @functools.lru_cache(None)\n        def overlap(a: str, b: str) -> int:\n            max_overlap = 0\n            for i in range(1, min(len(a), len(b)) + 1):\n                if a[-i:] == b[:i]:\n                    max_overlap = i\n            return max_overlap\n\n        # Precompute the overlap between all pairs of words\n        n = len(words)\n        overlaps = [[0] * n for _ in range(n)]\n        for i, j in itertools.product(range(n), repeat=2):\n            if i != j:\n                overlaps[i][j] = overlap(words[i], words[j])\n\n        # dp[mask][i] will be the length of the shortest superstring that contains\n        # all words corresponding to the bits in mask, ending with words[i]\n        dp = [[float(\'inf\')] * n for _ in range(1 << n)]\n        parent = [[None] * n for _ in range(1 << n)]\n        for i in range(n):\n            dp[1 << i][i] = len(words[i])\n\n        # Iterate over all subsets of words\n        for mask in range(1 << n):\n            for i in range(n):\n                if not (mask & (1 << i)):\n                    continue\n                for j in range(n):\n                    if mask & (1 << j):\n                        continue\n                    new_mask = mask | (1 << j)\n                    new_len = dp[mask][i] + len(words[j]) - overlaps[i][j]\n                    if new_len < dp[new_mask][j]:\n                        dp[new_mask][j] = new_len\n                        parent[new_mask][j] = i\n\n        # Reconstruct the shortest superstring\n        mask = (1 << n) - 1\n        min_len = float(\'inf\')\n        last = -1\n        for i in range(n):\n            if dp[mask][i] < min_len:\n                min_len = dp[mask][i]\n                last = i\n\n        result = []\n        while mask:\n            result.append(words[last])\n            next_last = parent[mask][last]\n            mask ^= (1 << last)\n            last = next_last\n\n        result.reverse()\n        superstring = result[0]\n        for i in range(1, len(result)):\n            overlap_len = overlap(result[i - 1], result[i])\n            superstring += result[i][overlap_len:]\n\n        return superstring\n\n```
['Python3']