✅ Easiest Solution [C++] with 0ms ✅ || Beats 100% of solutions
Intuition\nSince we are checking it against 2 you can deduce that any even number is divisible by 2 and therefore a multiple.\nAnd when it is odd, the next mult
# Intuition\nSince we are checking it against `2` you can deduce that any even number is divisible by `2` and therefore a multiple.\nAnd when it is odd, the next multiple would need to be double itself.\n\n# Complexity\n- Time complexity:\n$1$\n\n\n# Code\n```\nclass Solution {\npublic:\n    int smallestEvenMultiple(int n) {\n        if(!(n%2)) return n;\n        return n*2;\n    }\n};\n```
['C++']