SOLVED C++
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```cpp []\nclass Solution {\npublic:\n    int getLargestOutlier(vector<int>& nums) {\n    multiset<int> numSet(nums.begin(), nums.end());  // Insert all elements into the multiset\n        int total = 0;\n        int max1 = INT_MIN;\n\n        // Step 1: Calculate total and find the max value\n        for (int a : nums) {\n            total += a;\n            max1 = max(max1, a);  // Track the largest element\n        }\n\n        int ans = INT_MIN;  // Variable to store the largest outlier\n\n        // Step 2: Check for outliers\n        for (int a : nums) {\n            int remainingSum = total - a; // The sum of the special numbers should be (total - a)\n            \n            // If remaining sum is odd, it can\'t be split into two integer special numbers\n            if (remainingSum % 2 != 0) continue;\n\n            int p = remainingSum / 2;  // The sum of the special numbers\n\n            // Step 3: Check if \'p\' exists in the multiset and if \'p\' != \'a\' (distinct numbers)\n            if (numSet.count(p) > 0) {\n                // If p == a, we need to ensure that there are at least two occurrences of a.\n                if (p == a && numSet.count(a) > 1) {\n                    ans = max(ans, a);  // Update largest outlier\n                }\n                // If p != a, just check the count\n                else if (p != a) {\n                    ans = max(ans, a);  // Update largest outlier\n                }\n            }\n        }\n\n        // Step 4: If no outlier is found, return the largest element in nums\n        return (ans == INT_MIN) ? max1 : ans;\n    }\n};\n```
['C++']