✅🐍 Easy python solution 🐍✅
Code
\n# Code\n```python3 []\nclass Solution:\n    def minChanges(self, n: int, k: int) -> int:\n        if n & k != k: return -1\n        n_b, n_k = bin(n)[2:], bin(k)[2:]\n        return n_b.count(\'1\') - n_k.count(\'1\')\n\n```
['Bit Manipulation', 'Python3']