Java 3 line solution
\npublic String kthLargestNumber(String[] a, int k) {\n        int n=a.length;\n        BigInteger[] b=new BigInteger[n];\n        for(int i=0;i<n;i++)b[i]=new 
```\npublic String kthLargestNumber(String[] a, int k) {\n        int n=a.length;\n        BigInteger[] b=new BigInteger[n];\n        for(int i=0;i<n;i++)b[i]=new BigInteger(a[i]);\n        Arrays.sort(b);\n        return b[n-k].toString();\n    }\n```
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