Java Solution: Mastering Minimum Money Required for Transactions
Intuition\n Describe your first thoughts on how to solve this problem. \nThe problem involves a set of transactions, each defined by a cost and cashback. We nee
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe problem involves a set of transactions, each defined by a cost and cashback. We need to determine the minimum amount of money required initially to complete all the transactions regardless of the order.\n- If a transaction\'s cost is greater than the cashback, the transaction results in a loss. These transactions need to be handled carefully because they reduce the available money.\n- If a transaction\'s cost is less than or equal to the cashback, it doesn\'t reduce the money significantly, so it\u2019s less risky.\n**Thus, we need to:**\n- Track the total potential loss across transactions where cost exceeds cashback.\n- Keep track of the largest required cost (either from the "loss" or "non-loss" transactions) to ensure we have enough money to cover any possible transaction order.\n# Approach\n<!-- Describe your approach to solving the problem. -->\n***1. Iterate over each transaction:***\n- If costi > cashbacki, update the totalLoss as the difference between cost and cashback for that transaction. Also, track the maximum cashback for loss-making transactions (maxCashBackIfLoss), which is important when deciding the minimum money requirement.\n- If costi <= cashbacki, track the maximum cost among the profitable transactions (maxCostIfWin) as this indicates the largest upfront cost required for transactions that don\'t result in a loss.\n2. The total minimum money required is the total loss (totalLoss) plus the maximum value between maxCashBackIfLoss and maxCostIfWin to ensure the worst-case scenario is handled.\n# Complexity\n- Time complexity:O(n)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:O(1)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```java []\nclass Solution {\n    public long minimumMoney(int[][] transactions) {\n        long totalLoss = 0, maxCashBackIfLoss = 0, maxCostIfWin = 0;\n        int n = transactions.length;\n        for (int[] a : transactions) {\n            if (a[0] > a[1]) {\n                totalLoss += (a[0] - a[1]);\n                if (a[1] > maxCashBackIfLoss) {\n                    maxCashBackIfLoss = a[1];\n                }\n            } else if (a[0] > maxCostIfWin)\n                maxCostIfWin = a[0];\n\n        }\n        return totalLoss + (maxCashBackIfLoss > maxCostIfWin ? maxCashBackIfLoss : maxCostIfWin);\n    }\n}\n```
['Array', 'Greedy', 'Sorting', 'Java']