C++ easy solution
\nint maximumPopulation(vector<vector<int>>& logs) {\n        vector<int>v(101,0);\n        for(vector<int>cur :logs){\n            for(int i=cur[0];i<cur[1];i+
```\nint maximumPopulation(vector<vector<int>>& logs) {\n        vector<int>v(101,0);\n        for(vector<int>cur :logs){\n            for(int i=cur[0];i<cur[1];i++){\n                v[i-1950]++;\n            }\n        }\n        int maxi =0,ind;\n        for(int i=0;i<101;i++){\n            if(maxi < v[i]){\n                maxi = v[i];\n                ind = i+1950;\n            }\n        }\n        return ind;\n    }\n```
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