thought of comparison of words and s. if fulfills then split the string and use startsWith method.
IntuitionApproachComplexity
Time complexity:

Space complexity:
Code
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->

# Approach
<!-- Describe your approach to solving the problem. -->

# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->

- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->

# Code
```javascript []
/**
 * @param {string[]} words
 * @param {string} s
 * @return {boolean}
 */
var isAcronym = function(words, s) {
    if(words.length !== s.length) return false;
    for(let i=0; i < words.length; i++){
        let charOfS = s.split("")[i];
        if(!words[i].startsWith(charOfS)) return false;
    }
    return true;
};
```
['JavaScript']