Beats ✅ 100% runtime || Python solution
\n# Code Analysis\npython3\nclass Solution:\n    def lengthAfterTransformations(self, s: str, t: int) -> int:\n        MOD = 10**9 + 7  # Modulo for large numbe
\n# Code Analysis\n```python3\nclass Solution:\n    def lengthAfterTransformations(self, s: str, t: int) -> int:\n        MOD = 10**9 + 7  # Modulo for large numbers\n        \n        @lru_cache(None)  # Memoization decorator\n        def calculate_paths(t: int, c: str) -> int:\n            # Handle insufficient time\n            if t < 0:\n                return 0\n            \n            # Calculate transformation cost\n            steps_req = 26 - (ord(c) - ord(\'a\'))\n            remaining_t = t - steps_req\n            \n            # Handle transformation cases\n            if remaining_t < 0:\n                return 1  # Can\'t complete transformation\n            if remaining_t == 0:\n                return 2  # Exact transformation\n                \n            # Calculate recursive paths\n            return (calculate_paths(remaining_t, \'a\') + \n                   calculate_paths(remaining_t, \'b\')) % MOD\n        \n        # Process each character independently\n        result = 0\n        for c in s:\n            result = (result + calculate_paths(t, c)) % MOD\n            \n        return result\n```\n
['Python', 'Python3']