Easiest solution in CPP
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\npublic:\n    int removeAlmostEqualCharacters(string word) {\n        int n=word.length();\n        int ans=0;\n        for(int i=1;i<n;i++){\n            if(abs(word[i-1]-word[i])<=1){\n                word[i]=\'A\';\n                ans++;\n            }\n        }\n        return ans;\n    }\n};\n```
['String', 'Greedy', 'C++']