C# Solution for Maximum Product of Two Elements In An Array Problem
Intuition\n Describe your first thoughts on how to solve this problem. \nThe intuition behind the provided solution: find the two largest elements in the array 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe intuition behind the provided solution: find the two largest elements in the array and then calculate their product after subtracting 1 from each, giving the maximum possible value of (nums[i]-1)*(nums[j]-1).\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1.\tInitialize max1 and max2 as the two minimum integer values.\n2.\tIterate through the array.\n3.\tUpdate max1 and max2 accordingly if a larger value is found.\n4.\tReturn the product of (max1 - 1) and (max2 - 1).\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nThe time complexity of this solution is O(n), where \u2018n\u2019 is the length of the input array nums. This is because it iterates through the array only once to find the two maximum elements.\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nThe space complexity is O(1), as the solution uses only a constant amount of extra space to store max1 and max2, irrespective of the input array\u2019s size.\n\n# Code\n```\npublic class Solution {\n    public int MaxProduct(int[] nums) {\n        int max1 = int.MinValue;\n        int max2 = int.MinValue;\n        \n        foreach (int num in nums) {\n            if (num >= max1) {\n                max2 = max1;\n                max1 = num;\n            } else if (num > max2) {\n                max2 = num;\n            }\n        }\n        \n        return (max1 - 1) * (max2 - 1);\n    }\n}\n```
['C#']