4 Line Code
Intuition\nThe goal is to determine the minimum number of elements we need to add or subtract to transform the sum of the array nums into the goal. We can adjus
# Intuition\nThe goal is to determine the minimum number of elements we need to add or subtract to transform the sum of the array `nums` into the `goal`. We can adjust the sum using values limited by a specific maximum (`limit`). The problem can be approached by first calculating the current sum and then figuring out how far we need to adjust it.\n\n# Approach\n1. **Calculate the Current Sum**: Iterate through the `nums` array to calculate the total sum of its elements.\n2. **Determine the Difference**: Compute the absolute difference between the current sum and the desired `goal`. This difference represents how much we need to adjust the sum.\n3. **Calculate Minimum Elements Needed**: To achieve the adjustment, determine how many times we can utilize the `limit` value. This can be done using the formula `(sum + limit - 1) / limit`, which gives the ceiling of the division of `sum` by `limit`. This formula effectively counts how many full increments of `limit` are required to cover the difference.\n\n# Complexity\n- **Time complexity**: $$O(n)$$, where `n` is the number of elements in the `nums` array, as we iterate through the array once to calculate the sum.\n- **Space complexity**: $$O(1)$$, since we are using a constant amount of extra space regardless of the input size.\n\n# Code\n```cpp\nclass Solution {\npublic:\n    int minElements(vector<int>& nums, int limit, int goal) {\n        long long sum = 0;\n        for (auto i : nums) sum += i;\n        sum = abs(goal - sum);\n        return (sum + limit - 1) / limit;\n    }\n};\n```
['C++']