✅ Easy Rust Solution
\nimpl Solution {\n    pub fn is_balanced(num: String) -> bool {\n        let mut even = 0;\n        let mut odd = 0;\n\n        for (i, ch) in num.into_bytes()
```\nimpl Solution {\n    pub fn is_balanced(num: String) -> bool {\n        let mut even = 0;\n        let mut odd = 0;\n\n        for (i, ch) in num.into_bytes().into_iter().enumerate() {\n            let ch = ch - b\'0\';\n            if i & 1 == 0 {\n                even += ch as usize;\n            } else {\n                odd += ch as usize;\n            }\n        }\n\n        even == odd\n    }\n}\n```
['Rust']