Simple, methodical Go solution, beats 100% time and space
Separate the letter logs from the number logs\n2. Sort the letter logs, first on log content, then on identifier\n3. Append the number logs to the letter logs\n
1. Separate the letter logs from the number logs\n2. Sort the letter logs, first on log content, then on identifier\n3. Append the number logs to the letter logs\n\n```\nfunc reorderLogFiles(logs []string) []string {\n    if len(logs) < 2 {\n        return logs\n    }\n    \n    var sortedStrLogs []string\n    var sortedNumLogs []string\n    for _, log := range logs {\n        i := strings.Index(log, " ")\n        if log[i+1] >= \'a\' && log[i+1] <= \'z\' {\n            sortedStrLogs = append(sortedStrLogs, log)\n        } else {\n            sortedNumLogs = append(sortedNumLogs, log)\n        }\n    }\n    \n    sort.Slice(sortedStrLogs, func (i, j int) bool {\n        iIndex := strings.Index(sortedStrLogs[i], " ")\n        jIndex := strings.Index(sortedStrLogs[j], " ")\n        \n        iLog := sortedStrLogs[i][iIndex+1:]\n        jLog := sortedStrLogs[j][jIndex+1:]\n        if iLog == jLog {\n            return sortedStrLogs[i] < sortedStrLogs[j]\n        }\n        return iLog < jLog\n    })\n    \n    sortedStrLogs = append(sortedStrLogs, sortedNumLogs...)\n    return sortedStrLogs\n}\n```
['Go']