full comented solution py3 ))
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution:\n    def earliestAndLatest(self, n: int, firstPlayer: int, secondPlayer: int) -> List[int]:\n        # Initialize minR and maxR with extreme values\n        minR, maxR = 999999, -122\n        players = \'\'\n        \n        # Generate a string representing all players using uppercase letters\n        for i in range(1, n+1):\n            players += chr(i + 65)\n        fp = chr(firstPlayer + 65)\n        sp = chr(secondPlayer + 65)\n\n        @cache\n        def dfs(s, num_round, winners):\n            nonlocal maxR, minR\n            # Base case: If no players are left, update minR and maxR\n            if len(s) == 0:\n                dfs("".join(sorted(winners)), num_round + 1, \'\')\n                return\n            # Base case: If only one player is left, update winners and continue\n            if len(s) == 1:\n                winners += s[0]\n                dfs("".join(sorted(winners)), num_round + 1, \'\')\n                return\n            # Case: The first and last players are the target players\n            if s[0] == fp and s[-1] == sp:\n                maxR = max(maxR, num_round)\n                minR = min(minR, num_round)\n                return\n            # Case: The first player is one of the target players\n            elif s[0] == fp or s[0] == sp:\n                winners += s[0]\n                s = s[1:-1]\n                dfs(s, num_round, winners)\n            # Case: The last player is one of the target players\n            elif s[-1] == fp or s[-1] == sp:\n                winners += s[-1]\n                s = s[1:-1]\n                dfs(s, num_round, winners)\n            # Case: Both the first and last players are not the target players\n            else:\n                l, r = s[0], s[-1]\n                dfs(s[1:-1], num_round, winners + l)\n                dfs(s[1:-1], num_round, winners + r)\n            return\n        \n        # Start the recursive DFS with initial parameters\n        dfs(players, 1, \'\')\n        # Return the result as a list [minR, maxR]\n        return [minR, maxR]\n\n\n\n            \n```
['Python3']