Beginner-Friendly Python Solution || Easy - peasy
Intuition\n Describe your first thoughts on how to solve this problem. \nThe problem asks for the maximum product difference between any two pairs of elements i
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe problem asks for the maximum product difference between any two pairs of elements in the given list of integers. To maximize the product difference, you\'d ideally want to select the two largest numbers and the two smallest numbers. This is because multiplying two large numbers and subtracting the product of two small numbers would result in the maximum difference.\n# Approach\n<!-- Describe your approach to solving the problem. -->\n- Sort the array in ascending order.\n- The maximum product difference would be the product of the last two elements (the two largest) minus the product of the first two elements (the two smallest).\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nThe dominant factor in the time complexity is the sorting operation. Sorting an array of length N has a time complexity of O(NlogN). The subsequent operations (accessing elements and performing arithmetic) have a time complexity of O(1).\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nThe space complexity is O(1) since the algorithm uses only a constant amount of extra space for variables, regardless of the size of the input array.\n# Code\n```\nclass Solution:\n    def maxProductDifference(self, nums: List[int]) -> int:\n        # Step 1: Sort the array in ascending order\n        nums.sort()\n\n        # Step 2: Calculate the maximum product difference and return the result\n        # The product of the last two elements (largest) minus the product of the first two elements (smallest)\n        return (nums[-1] * nums[-2]) - (nums[0] * nums[1])\n```\n# Hope you understood the solution. Please do upvote this if you like it\uD83D\uDE0A\uD83D\uDE0A
['Python3']