Heavily Commented code Using DFS
\n# Code\ncpp []\nclass Solution {\nprivate:\n    // Depth-First Search (DFS) function to explore the tree\n    void dfs(int temp, int mom, int dist, int root, 
\n# Code\n```cpp []\nclass Solution {\nprivate:\n    // Depth-First Search (DFS) function to explore the tree\n    void dfs(int temp, int mom, int dist, int root, int maxi, vector<int>& res, vector<vector<int>>& nums) {\n        // If the current distance exceeds or equals the maximum allowed distance, stop\n        if (dist >= maxi) return;\n\n        // Increment the result for the current root node (this tracks the number of nodes\n        // reachable within the distance limit for a given root)\n        res[root]++;\n\n        // Explore all adjacent nodes (neighbors) of the current node\n        for (int adj : nums[temp]) {\n            // Make sure we don\'t revisit the parent node (avoid cycles)\n            if (adj != mom) {\n                // Perform DFS on the adjacent node with the current node as the parent\n                dfs(adj, temp, dist + 1, root, maxi, res, nums);\n            }\n        }\n    }\n\npublic:\n    vector<int> maxTargetNodes(vector<vector<int>>& edg1, vector<vector<int>>& edg2, int k) {\n        // Calculate the number of nodes in each graph\n        int n1 = edg1.size() + 1; // Number of nodes in the first graph\n        int n2 = edg2.size() + 1; // Number of nodes in the second graph\n\n        // Initialize adjacency lists for both graphs\n        vector<vector<int>> nums2(n1), nums1(n2);\n\n        // Populate the adjacency list for the first graph (edges from edg1)\n        for (auto& edge : edg1) {\n            int u = edge[0], v = edge[1];\n            nums2[u].push_back(v); // Add v as a neighbor of u\n            nums2[v].push_back(u); // Add u as a neighbor of v (undirected graph)\n        }\n\n        // Populate the adjacency list for the second graph (edges from edg2)\n        for (auto& edge : edg2) {\n            int u = edge[0], v = edge[1];\n            nums1[u].push_back(v); // Add v as a neighbor of u\n            nums1[v].push_back(u); // Add u as a neighbor of v (undirected graph)\n        }\n\n        // Initialize result vectors for both graphs, set all values to 0\n        vector<int> r1(n1, 0), r2(n2, 0);\n\n        // Perform DFS for each node in the first graph, with a maximum distance of k+1\n        for (int i = 0; i < n1; i++) {\n            dfs(i, -1, 0, i, k + 1, r1, nums2); // DFS starting from node i in nums2\n        }\n\n        // Perform DFS for each node in the second graph, with a maximum distance of k\n        for (int i = 0; i < n2; i++) {\n            dfs(i, -1, 0, i, k, r2, nums1); // DFS starting from node i in nums1\n        }\n\n        // Find the maximum value in the r2 array (the maximum number of nodes reachable from any node in graph 2)\n        int maxi = *max_element(r2.begin(), r2.end());\n\n        // Initialize the result vector for the final answer (to store the result for each node in graph 1)\n        vector<int> res(n1);\n\n        // For each node in graph 1, calculate the total result as the sum of reachable nodes from that node in graph 1\n        // and the maximum reachable nodes from any node in graph 2\n        for (int i = 0; i < n1; i++) {\n            res[i] = r1[i] + maxi;\n        }\n\n        // Return the result vector\n        return res;\n    }\n};\n\n```
['C++']