✅ [Python/Rust] sort -> accumulate -> binary search
\u2705 IF YOU LIKE THIS SOLUTION, PLEASE UPVOTE.\n*\n\n*Python.\n\nclass Solution:\n    def answerQueries(self, nums: List[int], queries: List[int]) -> List[int
**\u2705 IF YOU LIKE THIS SOLUTION, PLEASE UPVOTE.**\n****\n\n**Python.**\n```\nclass Solution:\n    def answerQueries(self, nums: List[int], queries: List[int]) -> List[int]:\n        \n        nums = list(accumulate(sorted(nums)))\n        return [bisect_right(nums,q) for q in queries]\n```\n\n**Rust.**\n```\nimpl Solution \n{\n    pub fn answer_queries(mut nums: Vec<i32>, queries: Vec<i32>) -> Vec<i32> \n    {\n        // [1] sort input values in place\n        nums.sort_unstable();\n        \n        // [2] compute cumsums in place\n        nums.iter_mut().fold(0, |acc, x| { *x += acc; *x});\n        \n        // [3] for a sorted list of cumsums, we can quickly find the index using binary search\n        queries.iter().map(|x| \n            nums.binary_search(x).unwrap_or_else(|i| i - 1) as i32 + 1\n        ).collect()\n    }\n}\n```
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