js solution.
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n1. Creating a Map to St
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. Creating a Map to Store Word Counts\n- We use a Map called wordsCount to keep track of how many times each word appears in both sentences. A Map in JavaScript allows us to store key-value pairs (in this case, the word as the key and its count as the value).\n\n\n```\nlet wordsCount = new Map();\n```\n2. Helper Function countWords\n- This function takes a sentence, splits it into individual words, and then counts how many times each word appears. We use the .split(\' \') method to break the sentence into an array of words by spaces.\n```\nfunction countWords(sentence) {\n    let words = sentence.split(\' \');\n    for (let word of words) {\n        wordsCount.set(word, (wordsCount.get(word) || 0) + 1);\n    }\n}\n```\n- For each word, we check if it\'s already in the wordsCount map. If it is, we increment its count by 1. If not, we add it with an initial count of 1 using wordsCount.set(word, (wordsCount.get(word) || 0) + 1).\n3. Counting Words from Both Sentences\n- We call the countWords function twice\u2014once for each sentence (s1 and s2). This will fill the wordsCount map with the number of occurrences of every word in both sentences combined.\n```\ncountWords(s1);\ncountWords(s2);\n```\n4. Finding Uncommon Words\n - Next, we loop over the entries in the wordsCount map. We check if the count of each word is exactly 1, which means it appears only once in total (either in one sentence or the other but not both). If so, we add it to the result array.\n```\nlet result = [];\nfor (let [word, count] of wordsCount) {\n    if (count === 1) {\n        result.push(word);\n    }\n}\n```\n5. Return the Result\n- Finally, the function returns the result array containing all the uncommon words.\n\n```\nreturn result;\n```\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```javascript []\n/**\n * @param {string} s1\n * @param {string} s2\n * @return {string[]}\n */\nvar uncommonFromSentences = function(s1, s2) {\n    let wordsCount = new Map();\n    \n    // Helper function to count words from a sentence\n    function countWords(sentence) {\n        let words = sentence.split(\' \');\n        for (let word of words) {\n            wordsCount.set(word, (wordsCount.get(word) || 0) + 1);\n        }\n    }\n    \n    // Count words from both sentences\n    countWords(s1);\n    countWords(s2);\n    \n    // Filter out the uncommon words (words that appear exactly once)\n    let result = [];\n    for (let [word, count] of wordsCount) {\n        if (count === 1) {\n            result.push(word);\n        }\n    }\n    \n    return result;\n};\n```
['JavaScript']