Solution in 11 Lines of Python
Intuition\n Describe your first thoughts on how to solve this problem. \n        rows = len(mat)\n        evens = rows // 2\n        odds = math.ceil(rows / 2)\
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n        rows = len(mat)\n        evens = rows // 2\n        odds = math.ceil(rows / 2)\n        return evens % k == 0 and odds % k == 0\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\nThe issue is that it doesn\'t handle every case.\n\nSo just check every element and shift it to see if it equals the original value.  If a mismatch is found return False.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nO(n)\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nO(1)\n\n# Code\n```python3 []\nimport math\nclass Solution:\n    def areSimilar(self, mat: List[List[int]], k: int) -> bool:\n        if len(mat[0]) == 1:\n            return True\n        for i in range(len(mat)):\n            for j in range(len(mat[0])):\n                if i % 2 == 0:\n                    if mat[i][j] != mat[i][(j-k)%len(mat[0])]:\n                        return False\n                else:                    \n                    if mat[i][j] != mat[i][(j+k)%len(mat[0])]:\n                        return False\n        return True\n\n\n```
['Python3']