The Minimum Swaps Challenge
Intuition\nThe problem requires finding the minimum number of steps to convert a binary string (consisting of \'0\'s and \'1\'s) into a string of all \'1\'s. Th
# Intuition\nThe problem requires finding the minimum number of steps to convert a binary string (consisting of \'0\'s and \'1\'s) into a string of all \'1\'s. The key insight is that every \'0\' encountered can be "turned into" a \'1\' through a \'1\' that comes after it in the string. Thus, for each \'1\' found, we need to count how many \'0\'s have been seen so far, as each of these can be converted in one step.\n\n# Approach\n1. Initialize a counter `c` to count the number of \'0\'s encountered as we traverse the string from right to left.\n2. Initialize a result variable `res` to accumulate the total steps needed.\n3. Loop through the string in reverse order:\n   - If the current character is \'0\', increment the counter `c`.\n   - If it\u2019s \'1\', add the current count of \'0\'s (`c`) to the result (`res`).\n4. At the end of the loop, `res` will hold the minimum number of steps required to convert the string to all \'1\'s.\n\n# Complexity\n- Time complexity: \\(O(n)\\), where \\(n\\) is the length of the string, since we traverse the string once.\n- Space complexity: \\(O(1)\\), as we are using a constant amount of extra space.\n\n# Code\n```python\nclass Solution:\n    def minimumSteps(self, s: str) -> int:\n        n = len(s)\n        c = 0\n        res = 0\n        for i in range(n - 1, -1, -1):\n            if s[i] == "0":\n                c += 1\n            elif s[i] == "1":\n                res += c\n        return res\n```
['Python3']