JavaScript Solution 100% 100%
js\n/**\n * @param {string[][]} paths\n * @return {string}\n */\nvar destCity = function(paths) {\n    const seen = new Set(paths.map(el => el[0]))\n    \n    f
```js\n/**\n * @param {string[][]} paths\n * @return {string}\n */\nvar destCity = function(paths) {\n    const seen = new Set(paths.map(el => el[0]))\n    \n    for(let i of paths) {\n        if(!seen.has(i[1])) \n            return i[1]\n    }\n    \n    return \'\'\n};\n```
['JavaScript']