grasp if you can
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\n    static final int MOD = 1_000_000_007;\n    public static long maxNonAdjacentSum(int[] nums) {\n        long include = 0, exclude = 0;\n        for (int num : nums) {\n            long newInclude = exclude + num;\n            exclude = Math.max(exclude, include);\n            include = newInclude;\n        }\n        return Math.max(include, exclude);\n    }\n\n    public static int  maximumSumSubsequence(int[] nums, int[][] queries) {\n        long totalSum = 0;\n        long currentSum = maxNonAdjacentSum(nums);\n\n        for (int[] query : queries) {\n            int pos = query[0];\n            int val = query[1];\n\n            // Update the nums array\n            nums[pos] = val;\n\n            // Recompute the max non-adjacent sum\n            currentSum = maxNonAdjacentSum(nums);\n\n            // Add to the total sum with modulo operation\n            totalSum = (totalSum + currentSum) % MOD;\n        }\n\n        return (int) totalSum;\n    \n    }\n}\n```
['Java']