Python Solution - Stop overcomplicating it! (KISS)
I\'ve seen so many overly complex python solutions here - figured it was time to break it down simply.\n1) If there is only one character, we cannot make it not
I\'ve seen so many overly complex python solutions here - figured it was time to break it down simply.\n1) If there is only one character, we cannot make it not a palindrome, so just return "" (the for loop is skipped since ```1 // 2``` is 0)\n2) Go through the first half of the palindrome and find the first character that is not equal to \'a\'. Using integer division ensures that we don\'t check the middle character of an odd-lengthed palindrome (since replacing the middle character would never change it into a non-palindrome).\n3) If a non-a character is found, replace it with an \'a\' and return the string\n4) Otherwise, the lexicographically smallest correction we can make is to change the last character to a \'b\' (since we already know that all other characters are \'a\'s)\n\n```\ndef breakPalindrome(self, palindrome: str) -> str:\n    for i in range(len(palindrome) // 2):\n        if palindrome[i] != \'a\':\n            return palindrome[:i] + \'a\' + palindrome[i+1:]\n    return "" if len(palindrome) == 1 else palindrome[:-1] + \'b\'\n```
['Greedy', 'Python', 'Python3']