Easy and Simple Solution 
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Happy coding! 💻🐱‍🏍Intuition

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# Code
```mysql []
# Write your MySQL query statement below
SELECT Person.firstName, Person.lastName, Address.city, Address.state
FROM Person
LEFT JOIN Address ON Person.personId=Address.personId;
```
**If you found this solution helpful, please give it an upvote! 🌟✨ It really motivates me to share more solutions like this. 😊👍
Happy coding! 💻🐱‍🏍**

<img src="https://assets.leetcode.com/users/images/6e8c623a-1111-4d21-9a5b-54e00e7feabb_1738093236.165277.jpeg" width=300px>

## Intuition
1. **Understand the Data Relationship**:
   - The `Person` table holds information about individuals (`personId`, `firstName`, `lastName`).
   - The `Address` table contains address details for some individuals, linked via the `personId` column.
   - Not all persons in the `Person` table will have an entry in the `Address` table.

2. **Goal**:
   - Retrieve all persons from the `Person` table and include their address details (`city` and `state`) if available.
   - If no matching entry exists in the `Address` table for a person, the `city` and `state` should be `NULL`.

3. **Use a `LEFT JOIN`**:
   - A `LEFT JOIN` is used to include all rows from the `Person` table, even if there are no matching rows in the `Address` table.

## Approach
1. Start with the `Person` table as the base.
2. Perform a `LEFT JOIN` on the `Address` table using the `personId` column as the key.
3. Select the required columns:
   - `firstName` and `lastName` from the `Person` table.
   - `city` and `state` from the `Address` table.
4. Handle cases where no match exists in the `Address` table by allowing `NULL` values for `city` and `state`.

## Complexity Analysis

### Time Complexity
- The complexity of the `LEFT JOIN` operation depends on the number of rows in both tables:
  - Let `n` be the number of rows in the `Person` table.
  - Let `m` be the number of rows in the `Address` table.
- In the worst case, the `LEFT JOIN` operation has a time complexity of **O(n * m)**.
- However, the actual performance depends on database query optimizations and whether an index exists on the `personId` column.

### Space Complexity
- The space complexity is proportional to the size of the result set:
  - This includes all rows from the `Person` table and any matching rows from the `Address` table.
- Additional space may be used for intermediate results during the join operation, which varies based on the database system.

['MySQL']