simple and easy to understand solution using java and python
Intuition\n Describe your first thoughts on how to solve this problem. \nThe problem involves finding the maximum product difference between pairs of elements i
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe problem involves finding the maximum product difference between pairs of elements in an array. To maximize the product difference, we should select the largest and second-largest elements and the smallest and second-smallest elements. Sorting the array allows us to easily access these elements.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n- Sort the array in ascending order.\n- Calculate the product difference using the two largest elements and the two smallest elements.\n- Return the result.\n\n# Complexity\n- Time complexity: O(nlogn)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: O(1)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n\n``` python3 []\nclass Solution:\n    def maxProductDifference(self, nums: List[int]) -> int:\n        nums.sort()\n        return (nums[-1] * nums[-2]) - (nums[0] * nums[1])\n                \n```\n``` java []\nimport java.util.Arrays;\nclass Solution {\n    public int maxProductDifference(int[] nums) {\n        Arrays.sort(nums);\n        return ((nums[nums.length-2]*nums[nums.length-1])-(nums[0]*nums[1]));\n    }\n}\n```
['Java', 'Python3']