JAVA 1ms(99.52%) with 1D array, minimizing the calculations
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```java []\nclass Solution {\n    public int lengthAfterTransformations(String s, int t) {\n        final int mod = 1_000_000_007;\n        int[] dp = new int[26];\n        for(char c:s.toCharArray()){\n            dp[c-\'a\']++;\n        }\n        int j=25;\n        for(int i=1; i<=t; i++){\n            dp[(j+1)%26] = (dp[(j+1)%26]+dp[j])%mod;\n            j=(j==0)?25:j-1;\n        }\n        int a=0;\n        for(int i=0; i<26; i++)a = (a+dp[i])%mod;\n        return a;\n    }\n}\n```
['Java']