Python simple brute force | 95% memory and time
\nclass Solution:\n    def countConsistentStrings(self, allowed: str, words: List[str]) -> int:\n        count = 0\n        allowed = set(allowed)\n        for 
```\nclass Solution:\n    def countConsistentStrings(self, allowed: str, words: List[str]) -> int:\n        count = 0\n        allowed = set(allowed)\n        for i in words:\n            for letter in i:\n                if letter not in allowed: \n                    count += 1\n                    break\n        return len(words) - count\n```\nFor more questions: https://github.com/vanigupta20024/Programming-Challenges
['Python', 'Python3']