C++ solution with  proper Explaination
Imp to note :\n1. check the given constraints.\n2. figure out the base  cases.\n3. when there is no movement i.e. when k is 0 there can be a probabilty of havin
**Imp to note :**\n1. check the given constraints.\n2. figure out the base  cases.\n3. when there is no movement i.e. when k is 0 there can be a probabilty of having knight at the chess borad is 1\n4. At every step the knight has 8 choices to move some can be in the board and some can be out of it\n5. the ones which are at the out of the board we can simply ignore that or make it a zero.\n6.   These are choices of Knight :\n  ( row-2, column -1)\n                                                 ( row-1, column -2) \n                                                 ( row+2, column +1)\n\t\t\t\t\t\t\t\t\t\t\t\t ( row+1, column +2)\n                                    ( row-2, column +1)\n\t\t                         \t( row+2, column -1) \n                                   ( row-1, column +2)\n\t\t                           ( row+1, column -2)\n\n7. Dry run the code.\n**Please upvote and do comment  if there is any doubt**\n\n```\nclass Solution {\npublic:\ndouble dp[26][26][101];\n    double knight(int n , int k, int row, int column){\n         //base cases\n          if(row <0 || column <0|| row>= n ||column >= n){\n             return 0;\n             }\n          if(k ==0) return 1; // if k ie. no. of steps is 0 than the probabilty to have Knight on borad is 1\n          if(dp[row][column][k]){\n              return dp[row][column][k];\n         }\n          double sum =0; // to find the sum\n        \n         sum = knight(n, k-1, row-2, column -1) + knight(n, k-1, row-1, column -2) + \n            knight(n, k-1, row+2, column +1) + knight(n, k-1, row+1, column +2)+ \n            knight(n, k-1, row-2, column +1)+ knight(n, k-1, row+2, column -1) +\n            knight(n, k-1, row-1, column +2) + knight(n, k-1, row+1, column -2);\n          sum /= 8;\n          return dp[row][column][k] = sum;\n                                                            \n    }\n    double knightProbability(int n, int k, int row, int column) {\n        return knight(n, k, row, column);\n    }\n};\n```
['Dynamic Programming', 'C', 'C++']