"Optimizing Vector Intersection in C++: Leveraging Frequency Maps for Efficiency"
Intuition\n Describe your first thoughts on how to solve this problem. \n\nThe code aims to find the intersection of two vectors, nums1 and nums2, by counting t
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\nThe code aims to find the intersection of two vectors, nums1 and nums2, by counting the occurrences of elements in each vector using maps (m1 and m2). The intuition can be summarized as follows:\n\n**Frequency Counting:** Create frequency maps for each vector to efficiently track the occurrences of elements.\n\n**Intersection Counting:** Iterate through one vector and check if each element is present in the other vector\'s frequency map. Increment counters (ans1 and ans2) accordingly.\n\n**Result Vector:** Store the counts in a vector (ans) and return it.\n\nThe approach focuses on counting common elements by leveraging frequency maps, providing a clear strategy for finding the intersection of the two vectors.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. Create two maps (m1 and m2) to store the frequency of elements in nums1 and nums2 respectively.\n2. Iterate through each vector to populate the frequency maps.\n3. Initialize counters ans1 and ans2 to 0.\n4. Iterate through nums1 and check if the element is present in m2. If yes, increment ans1.\n5. Iterate through nums2 and check if the element is present in m1. If yes, increment ans2.\n6. Create a vector ans and push ans1 and ans2 as the results.\nReturn the vector ans.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nO(n+m), where n is the size of nums1 and m is the size of nums2. The two loops for populating the frequency maps take O(n+m) time.\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nO(n+m) for the frequency maps (m1 and m2), where n is the number of distinct elements in nums1 and m is the number of distinct elements in nums2.\n\n# Code\n```\nclass Solution {\npublic:\n    vector<int> findIntersectionValues(vector<int>& nums1, vector<int>& nums2) {\n        \n        map<int,int>m1;\n        map<int,int>m2;\n        for(int i=0;i<nums1.size();i++)\n        {\n            m1[nums1[i]]++;\n        }\n        for(int i=0;i<nums2.size();i++)\n        {\n            m2[nums2[i]]++;\n        }\n        int ans1 = 0,ans2 = 0;\n        \n        for(int i=0;i<nums1.size();i++)\n        {\n            if(m2.find(nums1[i])!=m2.end())\n            {\n                ans1++;\n            }\n        }\n       for(int i=0;i<nums2.size();i++)\n        {\n            if(m1.find(nums2[i])!=m1.end())\n            {\n                ans2++;\n            }\n        }\n        vector<int>ans;\n        ans.push_back(ans1);\n        ans.push_back(ans2);\n        return ans;\n\n    }\n};\n```
['C++']