2437. Number of Valid Clock Times
IntuitionApproachComplexity
Time complexity:

Space complexity:
Code
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->

# Approach
<!-- Describe your approach to solving the problem. -->

# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->

- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->

# Code
```python3 []
class Solution:
    def countTime(self, time: str) -> int:
        hours, minutes = time.split(":")
        
        # Handling the hours part
        hour_count = 1
        if hours[0] == '?' and hours[1] == '?':
            hour_count = 24  # 00-23
        elif hours[0] == '?':
            # If the first digit is ?, the second digit can be anything from 0-9
            # But the first digit must be 0, 1, or 2 based on the second digit
            if hours[1] in "0123":
                hour_count = 3  # 0x, 1x, 2x where x can be any
            else:
                hour_count = 2  # 0x, 1x are the valid options
        elif hours[1] == '?':
            # If the second digit is ?, we can replace it with anything 0-9
            if hours[0] == '2':
                hour_count = 4  # 20, 21, 22, 23
            else:
                hour_count = 10  # 00-09, 10-19, 30-39, etc.

        # Handling the minutes part
        minute_count = 1
        if minutes[0] == '?' and minutes[1] == '?':
            minute_count = 60  # 00-59
        elif minutes[0] == '?':
            minute_count = 6  # 00-09, 10-19, ..., 50-59
        elif minutes[1] == '?':
            minute_count = 10  # 00, 10, 20, ..., 50
        
        return hour_count * minute_count

```
['Python3']