C++ Solution for Reverse Degree of a String
IntuitionThe problem likely involves transforming a string by calculating a "reverse degree." The goal is to map each character to its reverse position in the E
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
The problem likely involves transforming a string by calculating a "reverse degree." The goal is to map each character to its reverse position in the English alphabet ('a' becomes 26, 'b' becomes 25, etc.) and weight each character's reverse value by its position in the string. This creates an interesting metric for processing the input string.

# Approach
<!-- Describe your approach to solving the problem. -->
1. Traverse the given string character by character.
2. For each character `s[i]`:
   - Calculate the reverse value as `26 - (s[i] - 'a')`.
   - Multiply the reverse value by its 1-based position `i + 1` in the string.
3. Accumulate these weighted reverse values into a result variable (`ans`).
4. Return the accumulated result.

# Complexity
- **Time Complexity:** $$O(n)$$, where $$n$$ is the length of the input string. This is because we traverse the string once and perform constant-time calculations for each character.
- **Space Complexity:** $$O(1)$$, as we use only a fixed amount of extra space regardless of the input size.

# Code
```cpp []
class Solution {
public:
    int reverseDegree(string s) {
       int ans=0;
        for(int i=0;i<s.size();i++){
            int rev=26-(s[i]-'a');
            ans+=rev*(i+1);
        }
        return ans;
    }
};
```
['C++']