Circular Game Losers Identification Algorithm
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\nI approached the problem by first initializing an array with values from 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\nI approached the problem by first initializing an array with values from 1 to n, representing the players in the circular game. I then simulated the game by keeping track of the receivers of the pass and the current start position. I used a while loop to continue the game until a player receives the pass for the second time. I stored the receivers in an array and then mapped it to get the actual player numbers. Finally, I filtered the initial array to get the players who did not receive the pass twice, thus identifying the losers.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nfunction circularGameLosers(n: number, k: number): number[] {\n    let valus = Array.from({ length: n }, (v, i) => i + 1);\n    let receivers: number[] = [0];\n    let start = 0;\n    let count = 1;\n\n    while (receivers.filter((el) => el === start).length !== 2) {\n      start = (start + (count * k)) % n;\n      receivers.push(start);\n      count++;\n    }\n\n    let receivers2 = receivers.map((el) => el + 1);\n\n    return valus.filter((el) => !receivers2.includes(el));\n};\n```
['TypeScript']