Fast and Simple Solution
Intuition\nThe intuition behind this SQL query is to retrieve the product names and the total units sold for each product in the month of February 2020, conside
# Intuition\nThe intuition behind this SQL query is to retrieve the product names and the total units sold for each product in the month of February 2020, considering data from the "Products" and "Orders" tables. It filters the results to include only those products with a total unit count greater than or equal to 100.\n\n# Approach\nThe approach involves using a JOIN operation between the "Products" and "Orders" tables on the "product_id" column. The WHERE clause filters the results to include only those rows where the order date is in February 2020. The SELECT statement retrieves the product names and calculates the total units sold using the SUM() aggregation function. The GROUP BY clause groups the results by product name, and the HAVING clause filters out products with a total unit count less than 100.\n\n# Complexity\n- Time complexity:\nThe time complexity of this query depends on the efficiency of the underlying database engine in handling JOIN operations, aggregations, and filtering. In general, it can be considered as O(n), where n is the size of the combined result set after the JOIN operation and filtering.\n\n- Space complexity:\nThe space complexity is determined by the storage required for the intermediate result set during the JOIN operation and the aggregated result set. It is typically O(n), where n is the size of the result set.\n\n# Code\n```\n# Write your MySQL query statement below\nSELECT product_name, SUM(unit) AS unit\nFROM Products JOIN Orders USING(product_id)\nWHERE MONTH(order_date) = 2 AND YEAR(order_date) = 2020\nGROUP BY product_name\nHAVING unit >= 100;\n```
['MySQL']