Simplest Solution|| C++||
Intuition\n Describe your first thoughts on how to solve this problem. \nThe intuition behind the solution is to check if the first letter of each word in words
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe intuition behind the solution is to check if the first letter of each word in words is present in s.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nThe approach is to iterate through the words in words and check if the first letter of each word is present in s. If it is, the algorithm appends the letter to str.\n\nThe algorithm returns true if str is equal to s.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nO(n), where n is the length of the list words. This is because the algorithm only needs to iterate through the list once.\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\nO(1), where n is the length of the list words. This is because the algorithm does not need to store any additional data structures.\n\n\n# Code\n```\nclass Solution {\npublic:\n    bool isAcronym(vector<string>& words, string s) {\n       string str = "";\n        for(int i=0;i<words.size();i++){\n            str.push_back(words[i][0]);\n        }\n   return str==s;\n    }\n};\n```
['C++']