Golang solution faster than 100%
\nfunc getNoZeroIntegers(n int) []int {\n\tfor i := 1; i < n; i++ {\n\t\tcontainsZero := false\n\t\ta := i\n\t\tb := n - i\n\t\tfor a > 0 { // the first number 
```\nfunc getNoZeroIntegers(n int) []int {\n\tfor i := 1; i < n; i++ {\n\t\tcontainsZero := false\n\t\ta := i\n\t\tb := n - i\n\t\tfor a > 0 { // the first number has no zeros\n\t\t\tif a%10 == 0 {\n\t\t\t\tcontainsZero = true\n\t\t\t\tbreak\n\t\t\t}\n\t\t\ta /= 10\n\t\t}\n\t\tif !containsZero {\n\t\t\tfor b > 0 { // second number has no zeros\n\t\t\t\tif b%10 == 0 {\n\t\t\t\t\tcontainsZero = true\n\t\t\t\t\tbreak\n\t\t\t\t}\n\t\t\t\tb /= 10\n\t\t\t}\n\t\t}\n\t\tif !containsZero { // if none of the numbers have zeros then return \n\t\t\treturn []int{i, n - i}\n\t\t}\n\t}\n\treturn []int{}\n}\n```
['Go']