Pure C
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n\n# Complexity\n- Time complexity:\n Add your time complexity here, e.g. 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```c []\n// A simple structure for hash map node (key-value pair)\ntypedef struct HashNode {\n    int key;\n    int value;\n    struct HashNode* next;\n} HashNode;\n\n// Hash map structure\ntypedef struct HashMap {\n    int size;\n    HashNode** table;\n} HashMap;\n\n// Hash function\nunsigned int hash(int key, int size) {\n    return (unsigned int)(key % size);\n}\n\n// Create a hash map with given size\nHashMap* createHashMap(int size) {\n    HashMap* map = (HashMap*)malloc(sizeof(HashMap));\n    map->size = size;\n    map->table = (HashNode**)malloc(size * sizeof(HashNode*));\n    for (int i = 0; i < size; i++) {\n        map->table[i] = NULL;\n    }\n    return map;\n}\n\n// Insert a key-value pair into the hash map\nvoid insertHashMap(HashMap* map, int key, int value) {\n    int index = hash(key, map->size);\n    HashNode* node = (HashNode*)malloc(sizeof(HashNode));\n    node->key = key;\n    node->value = value;\n    node->next = map->table[index];\n    map->table[index] = node;\n}\n\n// Get a value from the hash map by key\nint getHashMap(HashMap* map, int key) {\n    int index = hash(key, map->size);\n    HashNode* node = map->table[index];\n    while (node) {\n        if (node->key == key) {\n            return node->value;\n        }\n        node = node->next;\n    }\n    return -2; // Not found\n}\n\n// Free the hash map memory\nvoid freeHashMap(HashMap* map) {\n    for (int i = 0; i < map->size; i++) {\n        HashNode* node = map->table[i];\n        while (node) {\n            HashNode* temp = node;\n            node = node->next;\n            free(temp);\n        }\n    }\n    free(map->table);\n    free(map);\n}\n\n// Function to find the minimum subarray that can be removed\nint minSubarray(int* nums, int numsSize, int p) {\n    int totalSum = 0;\n    \n    // Calculate total sum mod p\n    for (int i = 0; i < numsSize; i++) {\n        totalSum = (totalSum + nums[i]) % p;\n    }\n    \n    // If total sum is already divisible by p, no need to remove any subarray\n    if (totalSum == 0) {\n        return 0;\n    }\n\n    // Create a hash map for storing (prefix sum mod p) -> index\n    int hashSize = numsSize > 100 ? numsSize : 100; // Use numsSize as initial hash size\n    HashMap* mod_map = createHashMap(hashSize);\n\n    insertHashMap(mod_map, 0, -1);  // Initialize for prefix sum modulo 0\n    int prefixSum = 0;\n    int result = numsSize;\n\n    // Traverse the array and calculate prefix sums\n    for (int i = 0; i < numsSize; i++) {\n        prefixSum = (prefixSum + nums[i]) % p;\n\n        // Calculate the required modulo value to remove a valid subarray\n        int requiredMod = (prefixSum - totalSum + p) % p;\n\n        int requiredIndex = getHashMap(mod_map, requiredMod);\n        if (requiredIndex != -2) {\n            // Found a valid subarray, update result with minimum length\n            result = (i - requiredIndex < result) ? i - requiredIndex : result;\n        }\n\n        // Update the mod_map with the current prefix sum modulo and index\n        insertHashMap(mod_map, prefixSum, i);\n    }\n\n    freeHashMap(mod_map);\n    return result < numsSize ? result : -1;  // Return -1 if no valid subarray found\n}\n```
['C']