Java&JS&TS Solution (JW)
IntuitionApproachComplexity
Time complexity:

Space complexity:
Code
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->

# Approach
<!-- Describe your approach to solving the problem. -->

# Complexity
- Time complexity:
<!-- Add your time complexity here, e.g. $$O(n)$$ -->

- Space complexity:
<!-- Add your space complexity here, e.g. $$O(n)$$ -->

# Code
```java []
public int winningPlayerCount(int n, int[][] pick) {
    // Map to store player -> (color -> count) mapping
    Map<Integer, Map<Integer, Integer>> playerMap = new HashMap<>();

    // Count the number of balls of each color picked by each player
    for (int[] p : pick) {
        int player = p[0], color = p[1];
        playerMap.putIfAbsent(player, new HashMap<>());
        playerMap.get(player).put(color, playerMap.get(player).getOrDefault(color, 0) + 1);
    }

    int count = 0;

    // Check which players meet the winning condition
    for (Map.Entry<Integer, Map<Integer, Integer>> entry : playerMap.entrySet()) {
        int player = entry.getKey();
        for (int ballCount : entry.getValue().values()) {
            if (ballCount > player) {
                count++;
                break; // No need to check further colors for this player
            }
        }
    }

    return count;
}
```
```javascript []
var winningPlayerCount = function(n, pick) {
    let playerMap = new Map();

    // Count the number of balls of each color picked by each player
    for (let [player, color] of pick) {
        if (!playerMap.has(player)) {
            playerMap.set(player, new Map());
        }
        let colorMap = playerMap.get(player);
        colorMap.set(color, (colorMap.get(color) || 0) + 1);
    }

    let count = 0;

    // Check which players meet the winning condition
    for (let [player, colorMap] of playerMap) {
        for (let ballCount of colorMap.values()) {
            if (ballCount > player) {
                count++;
                break; // No need to check further colors for this player
            }
        }
    }

    return count;
};
```
```typescript []
function winningPlayerCount(n: number, pick: number[][]): number {
    let playerMap = new Map<number, Map<number, number>>();

    // Count the number of balls of each color picked by each player
    for (let [player, color] of pick) {
        if (!playerMap.has(player)) {
            playerMap.set(player, new Map<number, number>());
        }
        let colorMap = playerMap.get(player)!;
        colorMap.set(color, (colorMap.get(color) || 0) + 1);
    }

    let count = 0;

    // Check which players meet the winning condition
    for (let [player, colorMap] of playerMap) {
        for (let ballCount of colorMap.values()) {
            if (ballCount > player) {
                count++;
                break; // No need to check further colors for this player
            }
        }
    }

    return count;
};
```
['Array', 'Hash Table', 'Counting', 'Java', 'TypeScript', 'JavaScript']