RB's  Very Simple two Pointers Approach in Python
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution:\n    def countVowels(self, word: str) -> int:\n        cnt = 0\n        vowel = \'aeiou\'\n        ln = len(word)\n        for i in range(len(word)-1,-1,-1):\n            if word[i] in vowel:\n                # for left and right and merged calulation \n                left = i - 0\n                right = ln - 1 - i\n                left_to_right = left*right\n                cnt += left + right + left_to_right + 1 # +1 for itself count as substring\n            else:\n                continue  # for consonant char\n        return cnt\n```
['Math', 'Two Pointers', 'String', 'Python3']