Python Solution with Explanation
\nclass Solution:\n    def maxArea(self, h: int, w: int, horizontalCuts: [int], verticalCuts: [int]) -> int:\n        #appending the borders 0 and final horizon
```\nclass Solution:\n    def maxArea(self, h: int, w: int, horizontalCuts: [int], verticalCuts: [int]) -> int:\n        #appending the borders 0 and final horizontal line h height\n        # appending horizontal cuts in sequence order\n        hCuts= [0] + sorted(horizontalCuts) + [h]\n\n        #appending the borders 0 and final vertical line w width\n        # appending horizontal cuts in sequence order\n        vCuts = [0] + sorted(verticalCuts) + [w]\n        \n        #print(hCuts,vCuts)\n        \n        # find the distance between each cut and its previous cut both horizontally and vertically\n        \n        for i in range(0,len(hCuts)-1):\n            hCuts[i] = hCuts[i+1]-hCuts[i]\n        for i in range(0,len(vCuts)-1):\n            vCuts[i] = vCuts[i+1]-vCuts[i]\n            \n        # eliminate the last borders\n        hCuts = hCuts[:-1]\n        vCuts = vCuts[:-1]\n        \n        # Area between the max horizontal cut and max vertical cut is the one of maximum area\n        # return after taking module 10^9+7\n        return (max(hCuts)*max(vCuts))%(10**9+7)\n\n```
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