Easy intuition counting
Intuitioncount L, R, and _ the answer is abs(L - R) + _Code
# Intuition
count L, R, and _ the answer is abs(L - R) + _

# Code
```rust []
use std::collections::HashMap;

impl Solution {
    fn count_char(string: String) -> HashMap<char, i32> {
        let mut count: HashMap<char, i32> = HashMap::new();

        for chr in string.chars() {
            *count.entry(chr).or_insert(0) += 1;
        }

        count
    }

    pub fn furthest_distance_from_origin(moves: String) -> i32 {
        let count: HashMap<char, i32> = Self::count_char(moves);
        
        let ans = count.get(&'L').unwrap_or(&0) - count.get(&'R').unwrap_or(&0);
        
        ans.abs() + count.get(&'_').unwrap_or(&0)
    }
}
```
['Rust']