python3 explained accumulate solution
\nfrom itertools import accumulate \n\nclass Solution:\n    def largestAltitude(self, gain: List[int]) -> int:\n        return max(accumulate(gain, initial=0))\
```\nfrom itertools import accumulate \n\nclass Solution:\n    def largestAltitude(self, gain: List[int]) -> int:\n        return max(accumulate(gain, initial=0))\n```\n\nIf gain = [-5,1,5,0,-7], accumulate by default construct the following: \n\n```accumulate([-5,1,5,0,-7]) --> [-5, -4, 1, 1, -6]```\n\n(-5) + 1 + 5 + 0 + (-7)\n\nEach element is added to the next, this sum becomes the element of the final list. Could be pictured as a table: \n\n```\n     -5  = -5\n-5 +  1  = -4\n-4 +  5  =  1\n 1 +  0  =  1\n 1 + -7  = -6\n```\n\nThe second column is the original list [-5,1,5,0,-7], the third column is the final list [-5, -4, 1, 1, -6]. The first column is the result of the previous step.\n\nIf the "initial" parameter is not provided, the first element of the result will be the first element of the original iterator. Providing "initial" we set the first element of the result. In case of this problem, the first element should be 0, because a biker always starts from 0:\n\n```accumulate([-5,1,5,0,-7], initial=0) --> [0, -5, -4, 1, 1, -6]```\n\nIn the end just find maximum gain by max()
['Python3']