MySQL Solution for Actors and Directors Who Cooperated At Least Three Times Problem
Intuition\n Describe your first thoughts on how to solve this problem. \nThe intuition behind the given solution is to find actor-director pairs that have worke
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe intuition behind the given solution is to find actor-director pairs that have worked together in at least three movies. The approach involves grouping the rows in the ActorDirector table by actor_id and director_id, and then applying a condition in the HAVING clause to count the number of occurrences of each actor-director pair and filter out those with a count of less than three.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. Group the rows in the ActorDirector table by actor_id and director_id.\n1. For each group, count the number of occurrences of the actor-director pair.\n1. Filter out the groups where the count is less than three.\n1. Return the actor_id and director_id values from the remaining groups.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nThe time complexity of this solution depends on the size of the ActorDirector table. The grouping operation requires scanning the ActorDirector table, which has a time complexity of O(n), where n is the number of rows in the ActorDirector table. Additionally, the count operation requires counting the occurrences of each actor-director pair, which also has a time complexity of O(n).\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nThe space complexity of this solution depends on the number of distinct actor_id and director_id pairs that satisfy the condition. The query requires storing the grouped actor_id and director_id values temporarily, so the space complexity is determined by the cardinality of these values.\n\n# Code\n```\n# Write your MySQL query statement below\nselect actor_id, director_id from ActorDirector\ngroup by actor_id, director_id\nhaving count(*) >= 3\n```
['MySQL']