Simple py,JAVA code explained in detail!
Problem understanding
Given a string s and integer k.
They are asking us to find whether it is possible to construct k palindromes.
Approach:Counting+GreedyIntu
# Problem understanding

- Given a string `s` and integer `k`.
- They are asking us to find whether it is possible to construct `k` palindromes.
---

# Approach:Counting+Greedy
<!-- Describe your approach to solving the problem. -->

# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->

- There are only *3 ways* to form a palindrome.
    -   All the characters frequency is ***even***.
    - ***Single*** character.
    - Single ***odd*** and any number of ***even*** characters.
- what we should be focused on here is that if there are more number of *odd frequency* of chars than `k` we can't distribute them within `k` palindromic sequences.
- The above logic is implemented using `hash` to find frequency and `count` to calculate the *odd freq.* 
- If `count`>`k` then we can't form palindromic subsequence within `k`. 

# Complexity
- Time complexity:$O(N)$
<!-- Add your time complexity here, e.g. $$O(n)$$ -->

- Space complexity:$O(N)$
<!-- Add your space complexity here, e.g. $$O(n)$$ -->

# Code
```Python3 []
class Solution:
    def canConstruct(self, s: str, k: int) -> bool:
        if len(s)<k:
            return False
        hash=Counter(s)
        print(hash)
        count=0
        for v in hash.values():
            if v%2==1:
                count+=1
        return True if count<=k else False

```
```java []
class Solution {
    public boolean canConstruct(String s, int k) {
        if(s.length()<k){
            return false;
        }
        Map<Character,Integer> hash=new HashMap<>();
        for(char c:s.toCharArray()){
            hash.put(c,hash.getOrDefault(c,0)+1);
        }
        ArrayList<Integer> val=new ArrayList<>(hash.values());
        int count=0;
        for(int i:val){
            if(i%2==1){
                count++;
            }
        }
        if(count<=k){
            return true;
        }
        else{
            return false;
        }
    }
}
```
['Hash Table', 'String', 'Greedy', 'Counting', 'Python', 'Java']