MySQL Solution for Average Selling Price Problem
Intuition\n Describe your first thoughts on how to solve this problem. \nThe given SQL query calculates the average price for each product based on the units so
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe given SQL query calculates the average price for each product based on the units sold and the corresponding prices. It joins the "Prices" and "UnitsSold" tables on the product_id and filters the units sold based on the purchase date falling within the price\'s start_date and end_date range. The query then groups the results by product_id and sorts them in ascending order.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. The query starts by selecting the distinct product_id and calculates the average price for each product.\n1. It performs an inner join between the "Prices" and "UnitsSold" tables using the product_id.\n1. The join condition also includes a filter on the purchase_date to ensure it falls within the price\'s start_date and end_date range.\n1. The price * units is summed for each product, as well as the total units sold.\n1. The average price is calculated by dividing the sum of (price * units) by the sum of units.\n1. The result is grouped by product_id and ordered in ascending order.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nThe time complexity of the query depends on the number of rows in the "Prices" and "UnitsSold" tables. It involves joining the tables, performing calculations, grouping, and sorting. The time complexity is typically determined by the size of the result set and can be expressed as O(n log n), where n is the total number of rows in the joined tables.\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nThe space complexity of the query depends on the number of distinct product_ids and the space required to store the result set. The space required for storing the result is proportional to the number of distinct product_ids. The space complexity is typically O(n) due to the size of the result set.\n\n# Code\n```\n# Write your MySQL query statement below\nselect distinct p.product_id, round(sum(price * units) / sum(units), 2) as average_price from\nPrices as p join UnitsSold as U on\np.product_id  = u.product_id and u.purchase_date between p.start_date and p.end_date\ngroup by p.product_id\norder by p.product_id\n```
['MySQL']