676: Solution with step by step explanation
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n1. init method\n    1. Create an empty dictionary to hold the words and t
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n1. __init__ method\n    1. Create an empty dictionary to hold the words and their replacements.\n    2. Store the dictionary in the class attribute self.dict.\n2. buildDict method\n    1. For each word in the dictionary argument:\n        - For each index i in the range 0 to len(word):\n            - Replace the character at index i with *.\n            - Store the new string in a variable named replaced.\n            - If replaced is already a key in the dictionary:\n                - Append the original word to the list of words associated with the replaced key.\n            - Otherwise, create a new key-value pair in the dictionary where the key is replaced and the value is a list containing word.\n    2. Store the updated dictionary in the class attribute self.dict.\n3. search method\n1. For each index i in the range 0 to len(searchWord):\n    1. Replace the character at index i with *.\n    2. Store the new string in a variable named replaced.\n    3. If replaced is a key in the dictionary:\n        - Get the list of words associated with the replaced key.\n        - For each word in the list:\n            - If the word is not equal to searchWord and has the same length as searchWord:\n                - Initialize a variable match to True.\n                - For each index j in the range 0 to len(searchWord):\n                    - If the characters at index j in searchWord and word are not equal and the character at index j in replaced is not *, set match to False and break out of the loop.\n                - If match is still True after the loop, return True.\n2. Return False if no matches were found.\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass MagicDictionary:\n    def __init__(self):\n        self.dict = {}\n\n    def buildDict(self, dictionary: List[str]) -> None:\n        for word in dictionary:\n            for i in range(len(word)):\n                replaced = word[:i] + \'*\' + word[i+1:]\n                if replaced in self.dict:\n                    self.dict[replaced].append(word)\n                else:\n                    self.dict[replaced] = [word]\n\n    def search(self, searchWord: str) -> bool:\n        for i in range(len(searchWord)):\n            replaced = searchWord[:i] + \'*\' + searchWord[i+1:]\n            if replaced in self.dict:\n                words = self.dict[replaced]\n                for word in words:\n                    if word != searchWord and len(word) == len(searchWord):\n                        match = True\n                        for j in range(len(searchWord)):\n                            if searchWord[j] != word[j] and replaced[j] != \'*\':\n                                match = False\n                                break\n                        if match:\n                            return True\n        return False\n\n```
['Hash Table', 'String', 'Trie', 'Python', 'Python3']