Fast C++ solution
Intuition\n Describe your first thoughts on how to solve this problem. \nThe problem is to find the minimum number of moves required to move all the stones to c
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe problem is to find the minimum number of moves required to move all the stones to consecutive positions. We need to find the minimum number of moves required to move the stones to their final positions and the maximum number of moves required to move the stones to their final positions.\n# Approach\n<!-- Describe your approach to solving the problem. -->\nThe approach is to first sort the stones, then use two pointers to find the minimum and maximum number of moves required to move the stones to their final positions. The first pointer i is used to keep track of the leftmost stone that can be included in the sliding window, and the second pointer j is used to iterate through the stones. The size of the sliding window is represented by the variable n. The variable low is used to keep track of the minimum number of moves required to move the stones to their final positions, and the variable high is used to keep track of the maximum number of moves required to move the stones to their final positions.\n# Complexity\n- Time complexity: $$O(n log n)$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(1)$$\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\npublic:\n    vector<int> numMovesStonesII(vector<int>& stones) {\n        sort(stones.begin(), stones.end());\n        int n = stones.size(), i = 0, low = n;\n        int high = max(stones[n-1] - n + 2 - stones[1], stones[n-2] - stones[0] - n + 2);\n        for (int j = 0; j < n; ++j) {\n            while (stones[j] - stones[i] >= n) ++i;\n            if (j - i + 1 == n - 1 && stones[j] - stones[i] == n - 2)\n                low = min(low, 2);\n            else\n                low = min(low, n - (j - i + 1));\n        }\n        return {low, high};\n    }\n};\n```
['C++']