Python3-459 ms Beats 66.48%
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```python3 []\nclass Solution:\n    def shortestSuperstring(self, words: List[str]) -> str:\n        n = len(words)\n        \n        # Calculate the overlap between two words\n        def calculate_overlap(word1, word2):\n            max_overlap = 0\n            for i in range(1, min(len(word1), len(word2)) + 1):\n                if word1.endswith(word2[:i]):\n                    max_overlap = i\n            return max_overlap\n        \n        # Calculate overlap for all pairs of words\n        overlap = [[calculate_overlap(words[i], words[j]) for j in range(n)] for i in range(n)]\n        \n        # Initialize DP table\n        dp = [[\'\'] * n for _ in range(1 << n)]\n        \n        # Fill DP table\n        for mask in range(1, 1 << n):\n            for bit in range(n):\n                if mask & (1 << bit):\n                    prev_mask = mask ^ (1 << bit)\n                    if prev_mask == 0:\n                        dp[mask][bit] = words[bit]\n                    else:\n                        for prev_bit in range(n):\n                            if prev_mask & (1 << prev_bit):\n                                current = dp[prev_mask][prev_bit] + words[bit][overlap[prev_bit][bit]:]\n                                if dp[mask][bit] == \'\' or len(current) < len(dp[mask][bit]):\n                                    dp[mask][bit] = current\n        \n        # Find the shortest superstring\n        full_mask = (1 << n) - 1\n        return min(dp[full_mask], key=len)\n\n```
['Python3']