My Java Solution with my understanding as comments
\nclass Solution {\n    public boolean canTransform(String start, String end) {\n        // if there are no X, then the two string must be equal\n        if (!s
```\nclass Solution {\n    public boolean canTransform(String start, String end) {\n        // if there are no X, then the two string must be equal\n        if (!start.replace("X", "").equals(end.replace("X", "")))\n            return false;\n        int pointer1 = 0;\n        int pointer2 = 0;\n        while (pointer1 < start.length() && pointer2 < end.length()) {\n            // increment p1 and p2 whenever we see X from the position\n            // this is to get the nonX positions\n            while (pointer1 < start.length() && start.charAt(pointer1) == \'X\') {\n                pointer1 += 1;\n            }\n            while (pointer2 < end.length() && end.charAt(pointer2) == \'X\') {\n                pointer2 += 1;\n            }\n            // if both the pointer reaches the end of the strings, then we can return true.\n            // if only one of the pointer reaches the end of the strings, then we can return false\n            if (pointer1 == start.length() && pointer2 == end.length())\n                return true;\n            if (pointer1 == start.length() || pointer2 == end.length())\n                return false;\n            // if the characyer at respective pointer1 and pointer2 of start and end is not equal, then we cannot transform\n            if (start.charAt(pointer1) != end.charAt(pointer2))\n                return false;\n            // if the pointer1 at the start points to the \'L\' and pointer2 > pointer1 return false\n            // this is because L can be only moved to the left and pointer1 must be > pointer2\n            // if the pointer2 at the end points to the \'R\' and pointer1 > pointer2 return false\n            // this is because R can be only moved to the right and pointer2 must be > pointer1\n            if (start.charAt(pointer1) == \'L\' && pointer2 > pointer1)\n                return false;\n            if (end.charAt(pointer2) == \'R\' && pointer1 > pointer2)\n                return false;\n            pointer1 += 1;\n            pointer2 += 1;\n        }\n        return true;\n    }\n}\n```
['String', 'Java']