Process queries, reverse order, LWW ( last write wins), linear time, linear space, leverage hashmaps
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```python3 []\n\'\'\'\nURL := https://leetcode.com/problems/sum-of-matrix-after-queries/description/\n2718. Sum of Matrix After Queries\n\'\'\'\nclass Solution:\n    def matrixSumQueries(self, n: int, queries: List[List[int]]) -> int:\n        finalSum = 0\n        rowMap = dict()\n        colMap = dict()\n        time = 0\n        numColsAvail = n\n        numRowsAvail = n\n        # for query in queries:\n        seenRows = set()\n        seenCols = set()\n        for idx in range(len(queries) - 1, -1,-1):\n            query = queries[idx]\n            flag = query[0]\n            idx = query[1]\n            val = query[2]\n            # row case\n            if(flag == 0 and idx not in seenRows):\n                finalSum += (val * numColsAvail)\n                numRowsAvail -= 1\n                seenRows.add(idx)\n            # col case\n            elif(flag == 1 and idx not in seenCols):\n                finalSum += (val * numRowsAvail)\n                numColsAvail -= 1\n                seenCols.add(idx)\n            time += 1\n        # for i in range(n):\n        #     for j in range(n):\n        #         if(i in rowMap and j in colMap):\n        #             timeI = rowMap[i][0]\n        #             timeJ = colMap[j][0]\n        #             if(timeI >= timeJ):\n        #                 finalSum += rowMap[i][1]\n        #             else:\n        #                 finalSum += colMap[j][1]\n        #         elif(i not in rowMap and j in colMap):\n        #             finalSum += colMap[j][1]\n        #         elif(i in rowMap and j not in colMap):\n        #             finalSum += rowMap[i][1]\n        return finalSum\n        \n```
['Array', 'Hash Table', 'Python3']