Java&JS&TS Solution (JW)
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```java []\npublic int[] circularGameLosers(int n, int k) {\n    // Set to track the friends who have received the ball\n    Set<Integer> received = new HashSet<>();\n    int[] result;\n    \n    int currentFriend = 1;  // The game starts with the 1st friend\n    int steps = 1;  // Initial steps to pass the ball\n    \n    // Continue the game until a friend receives the ball twice\n    while (!received.contains(currentFriend)) {\n        received.add(currentFriend);  // Mark the current friend as having received the ball\n        currentFriend = (currentFriend + steps * k - 1) % n + 1;  // Move to the next friend\n        steps++;  // Increase the steps (i * k for the next friend)\n    }\n\n    // Create a list of friends who did not receive the ball\n    List<Integer> losers = new ArrayList<>();\n    for (int i = 1; i <= n; i++) {\n        if (!received.contains(i)) {\n            losers.add(i);\n        }\n    }\n\n    // Convert the list of losers to an array\n    result = new int[losers.size()];\n    for (int i = 0; i < losers.size(); i++) {\n        result[i] = losers.get(i);\n    }\n\n    return result;\n}\n```\n```javascript []\nvar circularGameLosers = function(n, k) {\n    const received = new Set(); // Set to track friends who have received the ball\n    let currentFriend = 1; // The game starts with the 1st friend\n    let steps = 1; // Initial steps to pass the ball\n    \n    // Continue the game until a friend receives the ball twice\n    while (!received.has(currentFriend)) {\n        received.add(currentFriend); // Mark current friend as having received the ball\n        currentFriend = (currentFriend + steps * k - 1) % n + 1; // Move to the next friend\n        steps++; // Increase the steps (i * k for the next friend)\n    }\n    \n    // Collect friends who did not receive the ball\n    const losers = [];\n    for (let i = 1; i <= n; i++) {\n        if (!received.has(i)) {\n            losers.push(i);\n        }\n    }\n    \n    return losers;\n};\n```\n```typescript []\nfunction circularGameLosers(n: number, k: number): number[] {\n    const received = new Set<number>(); // Set to track friends who have received the ball\n    let currentFriend = 1; // The game starts with the 1st friend\n    let steps = 1; // Initial steps to pass the ball\n    \n    // Continue the game until a friend receives the ball twice\n    while (!received.has(currentFriend)) {\n        received.add(currentFriend); // Mark current friend as having received the ball\n        currentFriend = (currentFriend + steps * k - 1) % n + 1; // Move to the next friend\n        steps++; // Increase the steps (i * k for the next friend)\n    }\n    \n    // Collect friends who did not receive the ball\n    const losers: number[] = [];\n    for (let i = 1; i <= n; i++) {\n        if (!received.has(i)) {\n            losers.push(i);\n        }\n    }\n    \n    return losers;\n};\n```
['Array', 'Java', 'TypeScript', 'JavaScript']