EZ python solution
\nclass Solution:\n    def breakPalindrome(self, palindrome: str) -> str:\n        le = len(palindrome)\n        \n        if le == 1:\n            return ""\n 
```\nclass Solution:\n    def breakPalindrome(self, palindrome: str) -> str:\n        le = len(palindrome)\n        \n        if le == 1:\n            return ""\n        \n        for i in range(0, le // 2):\n            if palindrome[i] != \'a\':\n                return palindrome[:i] + \'a\' + palindrome[i+1:]\n        \n        return palindrome[:le-1] + \'b\'\n```
['Python']