Java Solution for Find the Highest Altitude Problem
Intuition\n Describe your first thoughts on how to solve this problem. \nThe intuition behind the solution is to simulate the biker\'s road trip by calculating 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe intuition behind the solution is to simulate the biker\'s road trip by calculating the altitude at each point. We start with an initial altitude of 0 and update it based on the gain between consecutive points. We keep track of the highest altitude reached during the trip.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. Initialize the highest altitude and current altitude variables to 0.\n1. Iterate through the gain array.\n1. For each element in the gain array, update the current altitude by adding the gain.\n1. Use the Math.max function to compare the current altitude with the highest altitude and update the highest altitude if necessary.\n1. After iterating through the entire gain array, return the highest altitude.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nThe time complexity of the solution is O(n), where n is the length of the gain array. This is because we iterate through the gain array once to calculate the altitudes.\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nThe space complexity of the solution is O(1) because we only use a constant amount of extra space to store the highest altitude and current altitude variables. The space usage does not depend on the size of the input.\n\n# Code\n```\nclass Solution {\n    public int largestAltitude(int[] gain) {\n        int highestAltitude = 0;\n        int currentAltitude = 0;\n        \n        for (int i = 0; i < gain.length; i++) \n        {\n            currentAltitude += gain[i];\n            highestAltitude = Math.max(highestAltitude, currentAltitude);\n        }\n        \n        return highestAltitude;\n    }\n}\n```
['Java']