Go solution with clean code and comments
It takes a long time to figure out the right way to describe the patterns. Comments are inlined. Hope this is helpful.\n\n\nfunc stoneGameIX(stones []int) bool 
It takes a long time to figure out the right way to describe the patterns. Comments are inlined. Hope this is helpful.\n\n```\nfunc stoneGameIX(stones []int) bool {\n\n\tcnt := [3]int{}\n\tfor i, _ := range stones {\n\t\tidx := stones[i] % 3\n\t\tcnt[idx] = cnt[idx] + 1\n\t}\n\t\n\t// Ignoring cnt[0], possible paths without failing the game are:\n\t// 11212121..\n\t//  2212121..\n\t// If the above patterns can be strictly followed, cnt[0] cannot flip the result since all\n\t// numbers can be picked eventually.\n\t// Otherwise, odd number of cnt[0] can flip the result.\n\twin1 := false\n\twin2 := false\n    oddZero := cnt[0] & 1 == 1\n\tx := cnt[1] - cnt[2]\n    // Alice can only start from 1 or 2, check each path respectively.\n\t// Start from 1\n\tif cnt[1] > 0 {\n\t    // x >= 1, 1121 or 112 or 1121111 ....\n\t\twin1 = !(x >= 1)\n        // Do XOR (!= for bool) to flip the result (ignoring x==2 || x==1 since they follow the patterns)\n\t\twin1 = win1 != (oddZero && !(x == 2 || x == 1))\n\t}\n\n\t// Start from 2\n\tif cnt[2] > 0 {\n\t    // x <= -1, 221 or 22121 or 2212 or 2212222....\n\t\twin2 = !(x <= -1)\n        // Do XOR (!= for bool) to flip the result (ignoring x==-1 || x==-2 since they follow the patterns)\n\t\twin2 = win2 != (oddZero && !(x == -1 || x == -2))\n\t}\n    // Alice has the advantage to choose the path, hence she will always pick the winning path\n\treturn win1 || win2\n}\n```
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