Python - Easy 2 Liner | Faster than 93% |
\nclass Solution:\n    def digitCount(self, num: str) -> bool:            \n        for i in range(len(num)):\n            if(num.count(str(i))!=int(num[i])): r
```\nclass Solution:\n    def digitCount(self, num: str) -> bool:            \n        for i in range(len(num)):\n            if(num.count(str(i))!=int(num[i])): return False\n        return True\n```\n***Pls upvote if you find it helpful***
['Python']