☑️ Finding Number of Even and Odd Bits. ☑️
Code
# Code
```dart []
class Solution {
  List<int> evenOddBit(int n) {
    List<String> list = n.toRadixString(2).split("").reversed.toList();
    
    int countE = 0;
    int countO = 0;
    for(int i = 0; i < list.length; i++){
        if(list[i] == "1" && i % 2 == 0){
            countE++;
        }else if(list[i] == "1" && i % 2 != 0){
            countO++;
        }
    }

    return [countE, countO];
  }
}
```
['Bit Manipulation', 'Dart']