Beats 100%.
IntuitionThe problem asks us to calculate the "reverse degree" of a string, where the reverse degree is determined by the position of each character in the reve
# Intuition
The problem asks us to calculate the "reverse degree" of a string, where the reverse degree is determined by the position of each character in the reversed alphabet (i.e., 'a' = 26, 'b' = 25, ..., 'z' = 1). We need to multiply each character's reverse alphabet value with its position in the string (1-indexed) and then sum up these products to get the final result.
# Approach
1. Reverse Alphabet Mapping: First, we need to map each character to its reverse alphabetical value. 
This can be done by calculating:
    - `reverse_val(c) = 26 - (c - 'a')` For example, for 'a', `reverse_val('a') = 26 - (0) = 26`, for 'b', `reverse_val('b') = 26 - (1) = 25`, and so on.

1. Iterating Over String: We then iterate over the string, taking each character and its corresponding position in the string. For each character:
    - Calculate its reverse value as described.
    - Multiply this reverse value by its 1-indexed position in the string.
    - Add the result to a running sum.
1. Return the Sum: After iterating over all characters in the string, we return the accumulated sum as the reverse degree.

# Complexity
- Time complexity:
The algorithm iterates over each character in the string exactly once, so the time complexity is 𝑂(𝑛), where 𝑛 is the length of the string.

- Space complexity:
Space Complexity: The algorithm uses a constant amount of extra space, so the space complexity is O(1).

# Code
```java []
class Solution {
    public int reverseDegree(String s) {
        int sum = 0;
        int flag = 1;
        for (char c : s.toCharArray()) {
            int a = (26 + 'a' - c) * flag;
            sum += a;
            flag++;
        }
        return sum;
    }
}
```
['Java']