JAVA FASTEST🚀 AND SIMPLEST CODE😉 || STEP BY STEP EXPLAINED😲
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->O(N^2)\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->O(N)\n\n![Screenshot_20230205_171246.png](https://assets.leetcode.com/users/images/8981a4f4-f542-42ad-b73c-df828f0ec3b7_1689620724.9739566.png)\n\n# Code\n```\nclass Solution {\n    public int findCircleNum(int[][] isConnected) {\n\n        int numProvinces = isConnected.length; // Number of provinces\n        boolean[] visited = new boolean[numProvinces]; // Array to track visited provinces\n        int numCircles = 0; // Counter for the number of provinces in a circle\n        \n        for (int i = 0; i < numProvinces; i++) {\n            if (!visited[i]) {\n                numCircles++;\n                dfs(isConnected, i, visited); // Perform DFS traversal to find provinces in the current circle\n            }\n        }\n        \n        return numCircles;\n    }\n    \n    // Recursive function for DFS traversal to find provinces in a circle\n    private void dfs(int[][] isConnected, int province, boolean[] visited) {\n        \n        visited[province] = true; // Mark the current province as visited\n        \n        // Iterate through the neighboring provinces of the current province\n        for (int neighbor = 0; neighbor < isConnected[province].length; neighbor++) {\n            // If the neighbor province is not visited and there is a connection, mark as visited and explore further\n            if (!visited[neighbor] && isConnected[province][neighbor] == 1) {\n                dfs(isConnected, neighbor, visited); // Recursive call for unvisited provinces in the current circle\n            }\n        }\n    }\n}\n\n```
['Depth-First Search', 'Graph', 'Java']