C++||Soutions🚀✔||Explained line by line🚀✔✔||Easy to understand🚀||Beginner friendly😊✔✔
Intuition\n Describe your first thoughts on how to solve this problem. \nGiven the arrival time and delayed time of a flight, we need to find the delayed arriva
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nGiven the arrival time and delayed time of a flight, we need to find the delayed arrival time of the flight. If the delayed arrival time exceeds 24 hours, it should be wrapped around to the next day.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nWe can first calculate the delayed arrival time by adding the scheduled arrival time and the delayed time. Then, we check if the delayed arrival time exceeds 24 hours. If it does, we subtract 24 from it to get the actual delayed arrival time.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nThe time complexity of this code is O(1), as we are performing a constant number of operations.\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nThe space complexity of this code is also O(1), as we are not using any extra data structures or variables that depend on the input size.\n\n# Code\n```\nclass Solution {\npublic:\n    int findDelayedArrivalTime(int arrivalTime, int delayedTime) {\n        int scheduledArrivalTime = arrivalTime;\n        int delayedArrivalTime = scheduledArrivalTime + delayedTime;\n        if (delayedArrivalTime >= 24) {\n            delayedArrivalTime = delayedArrivalTime - 24;\n        } else {\n            return delayedArrivalTime;\n        }\n        return delayedArrivalTime;\n    }\n};\n```
['C++']