Python easy solution (DFS)
\n# Definition for a binary tree node.\n# class TreeNode:\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.lef
```\n# Definition for a binary tree node.\n# class TreeNode:\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass Solution:\n    def btreeGameWinningMove(self, root: Optional[TreeNode], n: int, x: int) -> bool:\n        \n        # Do DFS on 3 direction of opponent\n        # if one side is greater than the other 2 direction, you win!\n        \n        opponent = None\n        \n        def DFS(root):\n            if not root:\n                return 0\n            \n            nonlocal x\n            if root.val == x:\n                nonlocal opponent\n                opponent = root\n                return 0\n            \n            return 1 + DFS(root.left) + DFS(root.right)\n        \n        above = DFS(root)\n        left = DFS(opponent.left)\n        right = DFS(opponent.right)\n        \n        if (above > left + right) or (left > above + right) or (right > above + left):\n            return True\n        \n        return False\n        \n        \n        \n```
['Python', 'Python3']