Python 3 solution - O(1) solution
Intuition and Approach\n\nTo solve this problem, We need to find the minimum number of elements that we can add to the array to reach the goal sum while maintai
# Intuition and Approach\n\nTo solve this problem, We need to find the minimum number of elements that we can add to the array to reach the goal sum while maintaining the property that abs(nums[i]) <= limit for all i.\n\nFirst, we calculate the current sum of the array. Then, we calculate the difference between the goal and the current sum. Since we want to add the minimum number of elements, we should try to add elements with the maximum possible absolute value, which is \'limit\'. We can then calculate how many times we need to add \'limit\' to reach the goal sum.\n\n# Complexity\n- Time complexity:\nO(1)\n\n- Space complexity:\nO(1)\n\n# Code\n```\nclass Solution:\n    def minElements(self, nums: List[int], limit: int, goal: int) -> int:\n        current_sum = sum(nums)\n        \n        # Calculate the difference between the goal sum and the current sum\n        diff = abs(goal - current_sum)\n        \n        # Calculate the minimum number of elements required to reach the goal sum\n        min_elements = (diff + limit - 1) // limit\n        \n        return min_elements\n```
['Python3']