JavaScript | Beats 100% | Simple Solution | Explained
\n# Approach\n Describe your approach to solving the problem. \nThe problem appears to be about adding a number represented by an array (num) to another number 
![image.png](https://assets.leetcode.com/users/images/91e88a4d-5328-4f4c-affb-25ac7f43757a_1703451603.339485.png)\n# Approach\n<!-- Describe your approach to solving the problem. -->\nThe problem appears to be about adding a number represented by an array (num) to another number k. The array represents a non-negative integer, and the goal is to return the result as an array.\n\nThe approach involves simulating the addition process, starting from the least significant digit (rightmost) and moving towards the most significant digit (leftmost). We iterate through the array num and add the corresponding digit from k. If there\'s a carry, it is propagated to the next iteration.\n\n# Complexity\n- Time complexity: $$O(max(N, log(k)))$$, where `N` is the length of the `num` array and `k` is the value of the input parameter `k`. This is because, in the worst case, the algorithm iterates through the entire `num` array, and the number of digits in `k` (log(k)).\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(1)$$\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\n/**\n * @param {number[]} num\n * @param {number} k\n * @return {number[]}\n */\nvar addToArrayForm = function(num = [0], k = 1000) {\n    for (let i = num.length - 1; i >= 0; i--) {\n        let sum = num[i] + k;\n        num[i] = sum % 10;\n        k = Math.floor(sum / 10);\n    }\n\n    // Handle remaining carry\n    while (k > 0) {\n        num.unshift(k % 10);\n        k = Math.floor(k / 10);\n    }\n\n    return num;\n};\n```
['JavaScript']