Python 3 count distinct pairs and adding into count variable
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution:\n    def similarPairs(self, words: List[str]) -> int:\n\n        d=Counter()\n        count=0\n        for current_word in words:\n            word="".join(sorted(set(current_word)))\n            count+=d[word]\n            d[word]+=1\n\n        return count    \n\n\n```
['Python3']