BEATS 99% || EASY with Eg|| In Depth Commented CODE.
This provided code defines a function getSmallestString(n, k) that generates a lexicographically smallest string with the following properties:\n\n- Length: The
This provided code defines a function `getSmallestString(n, k)` that generates a lexicographically smallest string with the following properties:\n\n- **Length:** The string has a length of `n` characters.\n- **Maximum Zs:** The string can contain at most `k` characters \'z\'.\n\n**Functionality Breakdown:**\n\n1. **Character Array:**\n   - `char[] ans = new char[n];`: This line creates a character array named `ans` of size `n`. This array will hold the characters of the resulting string.\n\n2. **Distributing Zs:**\n   - `k -= n;`: This line subtracts `n` from `k`. The intuition behind this is that initially, we can consider all characters in the string as \'a\'. Since each \'a\' has a value of 1 (in the lexicographic order), subtracting `n` from `k` effectively represents the remaining value (number of \'z\'s) we can distribute in the string.\n\n3. **Filling the String (Loop):**\n   - `for (int i = n - 1; i >= 0; i--) { ... }`: This loop iterates from the end of the `ans` array (`n - 1`) down to the beginning (`i >= 0`). Here\'s what happens inside the loop:\n     - `if (k >= 25) { ... }`: This condition checks if the remaining value `k` is greater than or equal to 25 (the value of \'z\' in the lexicographic order).\n       - If true:\n         - `ans[i] = \'z\';`: A \'z\' is assigned to the current character (`ans[i]`) in the array.\n         - `k -= 25;`: The value `k` is decremented by 25, accounting for the added \'z\'.\n     - `else { ... }`: If the condition is false (meaning `k` is less than 25):\n       - `ans[i] = (char) (\'a\' + k);`: This line calculates the character to be assigned based on the remaining value `k`. It adds `k` to the ASCII value of \'a\' (97) and casts the result to a character. This ensures we assign characters from \'a\' to \'z\' (based on their order) depending on the remaining value.\n       - `k = 0;`: Since all the remaining value (`k`) has been used to assign a character, we set `k` to 0.\n\n4. **Returning the Result:**\n   - `return new String(ans);`: This line creates a new String object from the `ans` character array and returns it.\n\n**Output:**\n\nThis function generates the lexicographically smallest string possible considering the constraints of length `n` and maximum `k` \'z\' characters.\n\n**Example:**\n\nFor `n = 3` and `k = 2`, the code would return "aa`". Here\'s the explanation:\n\n- Initially, `k` is 2 (maximum \'z\'s).\n- Since `k` is less than 25, the loop assigns characters from \'a\' to \'z\'.\n- In the first two iterations (`i = 1` and `i = 0`), `k` is sufficient to assign \'a\' (remaining value 2 is enough for two \'a\'s).\n- In the third iteration (`i = 2`), `k` becomes 0, and the loop terminates.\n- The resulting string is "aa`".\n\n**Key Points:**\n\n- The code prioritizes using \'a\' as much as possible since it has the lowest lexicographic value.\n- It strategically distributes \'z\'s only when the remaining value (`k`) allows it.\n- This approach ensures the generated string is lexicographically the smallest possible.\n\n# Code\n```\nclass Solution {\n    public String getSmallestString(int n, int k) {\n        // Initialize an array to hold the characters of the resulting string\n        char[] ans = new char[n];\n        \n        // Adjust k to account for the minimum possible sum of n \'a\'s (i.e., n)\n        k -= n;\n        \n        // Fill the array from the end to the beginning\n        for (int i = n - 1; i >= 0; i--) {\n            // Determine the value to place at the current position\n            if (k >= 25) {\n                // Place \'z\' at the current position if k allows\n                ans[i] = \'z\';\n                k -= 25;\n            } else {\n                // Place the appropriate character to match the remaining k\n                ans[i] = (char) (\'a\' + k);\n                k = 0;\n            }\n        }\n        \n        // Convert the character array to a string and return it\n        return new String(ans);\n    }\n}\n\n```
['String', 'Greedy', 'Java']