✅ Explained - Simple and Clear Python3 Code✅
Intuition\nThe problem requires counting the number of items that match a given rule. We are given an array of items, where each item is represented by its type
# Intuition\nThe problem requires counting the number of items that match a given rule. We are given an array of items, where each item is represented by its type, color, and name. The rule is defined by a ruleKey and a ruleValue. We need to determine if the ruleKey matches the corresponding attribute of each item, and if so, check if the ruleValue matches the value of that attribute. By counting the items that satisfy the rule, we can determine the final result.\n\n\n# Approach\nWe can solve the problem by iterating over each item in the items array. For each item, we check if the ruleKey matches the corresponding attribute and if the ruleValue matches the value of that attribute. If both conditions are true, we increment a counter variable by 1. Finally, we return the value of the counter variable, which represents the number of items that match the given rule.\n\n\n# Complexity\n- Time complexity:\nThe time complexity of this approach is O(n), where n is the number of items in the input array. We iterate over each item once to check if it matches the given rule.\n\n\n- Space complexity:\nThe space complexity is O(1) because we only use a constant amount of additional space to store the counter variable and the loop variables. The input array is not modified during the process, so we don\'t need any extra space to store intermediate results.\n\n\n\n# Code\n```\nclass Solution:\n    def countMatches(self, items: List[List[str]], ruleKey: str, ruleValue: str) -> int:\n        res=0\n        for i in items:\n            if ruleKey=="type":\n                if i[0]==ruleValue:\n                    res+=1\n            elif ruleKey=="color":\n                if i[1]==ruleValue:\n                    res+=1\n            elif ruleKey=="name":\n                if i[2]==ruleValue:\n                    res+=1\n        return res\n\n```
['Python3']