Straightforward Python
\n\nclass Solution:\n    def breakPalindrome(self, palindrome: str) -> str:\n        n = len(palindrome)\n        if n == 1: return \'\'\n        for i, char in
\n```\nclass Solution:\n    def breakPalindrome(self, palindrome: str) -> str:\n        n = len(palindrome)\n        if n == 1: return \'\'\n        for i, char in enumerate(palindrome):\n            if char != \'a\' and i != n//2:\n                return palindrome[:i] + \'a\' + palindrome[i+1:]\n            elif char == \'a\' and i == n - 1:\n                return palindrome[:-1] + \'b\'\n```
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