Simple and Efficient Solution | Fully Explained 💯 | Javascript 🔥💯
Intuition\nIn the "Intuition" section, you would describe your initial thoughts and ideas on how to approach and solve the problem. This is where you share your
# Intuition\nIn the "Intuition" section, you would describe your initial thoughts and ideas on how to approach and solve the problem. This is where you share your initial understanding of the problem, any insights you\'ve gained, and any high-level strategies that come to mind. It\'s a place to express your initial reactions and thoughts before diving into the details of your solution.\n# Approach\n1. The function isAcronym takes two inputs: an array of words (words) and a string (s).\n2. It first checks if the length of the words array is the same as the length of the string s. If they have different lengths, it means there\'s a mismatch in the number of characters, and the function immediately returns false because it\'s not possible to form an acronym.\n3. If the lengths are the same, the code enters a loop that iterates through each index i from 0 to the length of the words array minus 1.\n4. Inside the loop, the code compares the first character of the i-th word in the words array with the i-th character in the string s. This comparison checks whether the first letter of the current word matches the corresponding character in the string.\n5. If any of these comparisons fail (i.e., if the characters don\'t match), it indicates that the acronym formation is incorrect, and the function immediately returns false.\n6. If all comparisons succeed (i.e., the first characters of all words match the corresponding characters in the string), the function concludes that the acronym is formed correctly and returns true after the loop completes.\n# Complexity\n- Time complexity: `O(n)`\n\n    The loop runs for words.length iterations.\n    Each iteration involves a constant-time operation: comparing the first character of words[i] with s[i].\n    Therefore, the time complexity is O(n), where n is the length of the input arrays words and s.\n- Space complexity: `O(1)`\n    The main memory usage comes from the input arrays words and s.\n    There are also a few variables used in the loop (e.g., i).\n    Since the memory usage doesn\'t increase with the input size, the space complexity is O(1), indicating constant space usage.\n# Code\n```\n/**\n * @param {string[]} words\n * @param {string} s\n * @return {boolean}\n */\n\nvar isAcronym = function (words, s) {\n  if (words.length !== s.length ) return false;\n\n  for (let i = 0; i < words.length; i++) {\n    if (words[i][0] !== s[i]) return false;\n  }\n  \n  return true;\n};\n```
['Array', 'String Matching', 'JavaScript']