Fast and Simple Solution
Intuition\nThe intuition behind this SQL query is to retrieve all rows from the "Patients" table where the "conditions" column contains the substring \'DIAB1\' 
# Intuition\nThe intuition behind this SQL query is to retrieve all rows from the "Patients" table where the "conditions" column contains the substring \'DIAB1\' at the beginning or anywhere in the string.\n\n# Approach\nThe approach involves using the SQL SELECT statement with a WHERE clause. The conditions in the WHERE clause check for rows where the "conditions" column contains the specified substring patterns. The \'%\' symbols are used as wildcards to match any characters before or after \'DIAB1\'.\n\n# Complexity\n- Time complexity:\nThe time complexity of this query is proportional to the number of rows in the "Patients" table that satisfy the specified conditions. In the worst case, it may need to scan the entire table, resulting in a time complexity of O(n), where n is the number of rows in the table.\n\n- Space complexity:\nThe space complexity is minimal as it only involves the retrieval of rows based on a condition. It is generally considered to be O(1), constant space.\n\n# Code\n```\n# Write your MySQL query statement below\nSELECT *\nFROM Patients \nWHERE conditions LIKE (\'% DIAB1%\') OR conditions LIKE (\'DIAB1%\');\n```
['MySQL']