Pythonic Solution for 2138: Divide a String Into Groups of Size k | Clean & Efficient Approach 🚀
ApproachThe task is to divide a given string s into groups of size k. If the last group is smaller than k, fill it with a specified character fill. Here's how I
# Approach
``The task is to divide a given string s into groups of size k. If the last group is smaller than k, fill it with a specified character fill. Here's how I approached the problem in Python 3 with a clean and efficient solution. 🚀``

# Why this approch?

- The use of list comprehension makes the solution concise and Pythonic.
- Only the necessary characters are added to the last group, ensuring efficiency.

# Complexity
- **Time complexity**: O(n), where 𝑛 is the length of the string s, because we traverse the string once to create groups.

- **Space complexity**: O(n), as we store the groups in a list.

# Code
```python3 []
class Solution:
    def divideString(self, s: str, k: int, fill: str) -> List[str]:
        lst = [s[arr:arr+k] for arr in range(0, len(s), k)]

        if len(s) % k == 0:
            return lst

        lst[-1] += fill * (k - len(lst[-1]))
        return lst
```

# Closing Note
```If you found this solution helpful or have any suggestions for improvement, feel free to share your thoughts below. I'd love to hear your feedback! 😊```

['String', 'Python', 'Python3']