Pythonic Mathematical Solution :)
Intuition\n\nThe first intuition that came to mind when solving this problem was to determine the unique contribution of each list to the length of the maximum 
# Intuition\n\nThe first intuition that came to mind when solving this problem was to determine the unique contribution of each list to the length of the maximum set. By finding the intersecting elements among the lists and converting each list into a hash set, we can identify the unique contribution of each list.\n\n# Approach\n\nTo find the unique contribution of two lists:\n\n1. Convert both `nums1` and `nums2` into sets.\n2. Find the intersection of the sets to identify the common elements.\n3. Calculate the lengths of unique elements in each set.\n4. Determine the maximum size of the set considering the unique contributions and the intersection by remembering that the bottleneck/the max bound of the solution could be "n".\n\n# Complexity Analysis\n\n- Time complexity: \\(O(n)\\), where \\(n\\) is the total number of elements in both lists.\n- Space complexity: \\(O(n)\\), where \\(n\\) is the total number of unique elements in both lists.\n\n# Code\n\n```python\nclass Solution(object):\n    def maximumSetSize(self, nums1, nums2):\n        halflength = len(nums1) // 2\n        x1 = set(nums1)\n        x2 = set(nums2)\n        inter = x1.intersection(x2)\n        unix1 = len(x1 - inter)\n        unix2 = len(x2 - inter)\n        intermediate = min(halflength, unix1) + min(halflength, unix2)  \n        if intermediate < 2 * halflength:\n            return min(intermediate + len(inter), 2 * halflength)\n        return intermediate\n
['Math', 'Python']