Easiest C++ solution using single for loop
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\npublic:\n    long long findTheArrayConcVal(vector<int>& nums) {\n        long long n=nums.size(),sum=0;\n        for(int i=0;i<n/2;i++){\n            int a=log10(nums[n-1-i]);\n            int b=(nums[i]*(pow(10,a+1)))+nums[n-1-i];\n            sum=sum+b;\n        }\n        if(n%2==1) return sum+nums[n/2];\n       else return sum;\n        \n    }\n};\nDo UPVOTE if you like\n```
['C++']