a few solutions
Game Plan\n\nOnly the x-axis matters since each rectangle\'s width is contrained by threshold T (and y2 can be arbitrarily large).  Thus, we sort the input arra
# Game Plan\n\nOnly the x-axis matters since each rectangle\'s width is contrained by threshold `T` (and y<sub>2</sub> can be arbitrarily large).  Thus, we sort the input array `A` by x-axis and perform a linear scan to accumulate the total `t` rectangles needed.\n\n# Code\n\n*Kotlin*\n```\nclass Solution {\n    fun minRectanglesToCoverPoints(points: Array<IntArray>, T: Int): Int {\n        var A = points.map{ it[0] }.sorted()\n        var (x, t) = Pair(A[0], 1)\n        for (i in 1..A.lastIndex) {\n            if (x + T < A[i]) {\n                x = A[i]; ++t\n            }\n        }\n        return t\n    }\n}\n```\n\n*Javascript*\n```\nlet minRectanglesToCoverPoints = (A, T) => {\n    A = A.map(([x, _]) => x).sort((a, b) => a - b);\n    let [x, t] = [A[0], 1];\n    for (let i = 1; i < A.length; ++i)\n        if (x + T < A[i])\n            x = A[i], ++t;\n    return t;\n};\n```\n\n*Python3*\n```\nclass Solution:\n    def minRectanglesToCoverPoints(self, A: List[List[int]], T: int) -> int:\n        A = sorted([x for x, _ in A])\n        x, t = A[0], 1\n        for i in range(1, len(A)):\n            if x + T < A[i]:\n                x = A[i]; t += 1\n        return t\n```\n\n*Rust*\n```\ntype VI = Vec<i32>;\ntype VVI = Vec<VI>;\nimpl Solution {\n    pub fn min_rectangles_to_cover_points(points: VVI, T: i32) -> i32 {\n        let mut A = points.into_iter().map(|point| point[0]).collect::<VI>(); A.sort();\n        let (mut x, mut t) = (A[0], 1);\n        for i in 1..A.len() {\n            if x + T < A[i] {\n                x = A[i]; t += 1;\n            }\n        }\n        t\n    }\n}\n```\n\n*C++*\n```\nclass Solution {\npublic:\n    using VI = vector<int>;\n    using VVI = vector<VI>;\n    int minRectanglesToCoverPoints(VVI& points, int T, VI A = {}) {\n        transform(points.begin(), points.end(), back_inserter(A), [](auto& point) { return point[0]; });\n        sort(A.begin(), A.end());\n        auto [x, t] = make_pair(A[0], 1);\n        for (auto i{ 1 }; i < A.size(); ++i)\n            if (x + T < A[i])\n                x = A[i], ++t;\n        return t;\n    }\n};\n```\n\n# "Breadcrumbs" for how we arrived "here"\n\n*Python3*\n```\n# 7:24pm - \n\n# game plan: only x-axis matters since y2 can be arbitrarily large\n# x2 - x1 delta must be less-than-or-equal-to threshold T\n\n# sort point array A by x-axis then "cover" points as intervals\n\n# for each rectangle, we track starting position x and ending position x + T inclusive\n# then move onto next point in A with x-axis strictly greater than x + T\n\n# 7:32am -> AC in ~8 minutes, yay! :)\n\nclass Solution:\n    def minRectanglesToCoverPoints(self, A: List[List[int]], T: int) -> int:\n        A = sorted([x for x, _ in A])\n        x, t = A[0], 1\n        for i in range(1, len(A)):\n            if x + T < A[i]:\n                x = A[i]; t += 1\n        return t\n```
['C++', 'Python3', 'Rust', 'Kotlin', 'JavaScript']