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Intuition:\nThe SQL query retrieves pairs of actor and director IDs from the ActorDirector table where the same actor has worked with the same director at least
**Intuition:**\nThe SQL query retrieves pairs of actor and director IDs from the `ActorDirector` table where the same actor has worked with the same director at least three times, based on the count of timestamps.\n\n**Approach:**\n1. The query groups the records in the `ActorDirector` table by pairs of `actor_id` and `director_id`.\n2. It then uses the `HAVING` clause to filter the grouped results, considering only those pairs where the count of timestamps (`count(timestamp)`) is greater than or equal to three.\n\n**Complexity:**\n- **Time complexity:** The time complexity is influenced by the grouping operation and the subsequent filtering based on the `HAVING` clause. Assuming appropriate indexing, the time complexity is likely to be O(n log n), where n is the number of rows in the `ActorDirector` table.\n\n- **Space complexity:** The space complexity is determined by the temporary storage required for the grouped results. Assuming m is the number of rows in the result set, the space complexity is O(m).\n\nKeep in mind that the actual performance may vary depending on the database engine, indexing, and the size of the `ActorDirector` table.\n\n# Code\n```\n# Write your MySQL query statement below\nselect actor_id, director_id from ActorDirector \ngroup by actor_id, director_id\nhaving count(timestamp)>=3;\n```
['MySQL']