EXPLAINED WELLL
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n1. Compute Differences:
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. **Compute Differences:** Iterate over each character of strings `s` and `t` simultaneously. For each index `i`, calculate the difference between the character codes of `s[i]` and `t[i]`, storing these differences in an array arr.\n2. **Initialize Sliding Window**: Use two pointers,`left` and `right`, to create a sliding window over the array`arr`. Initialize a `count` to keep track of the count of subsets that meet your criteria (define what criteria you are using, e.g., subsets with a sum greater than a certain value). \n3. **Sliding Window Logic:** Move the `right` pointer to expand the window and include more elements. Update the `count` based on whether the current window meets your criteria. If the window becomes invalid (e.g., the sum exceeds a threshold), move the `left` pointer to reduce the window size until it becomes valid again.\n4. **Track Maximum Count:** Throughout the sliding window process, keep track of the maximum value of the `count`. This maximum value represents the result you are seeking.\n5. **Return Result:** After the sliding window has processed the entire array, return the maximum value recorded.\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n$$O(n)$$\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n$$O(n)$$\n# Code\n``` javascript []\nvar equalSubstring = function(s, t, maxCost) {\n    let n = s.length;\n    let arr = new Array(n);\n\n    let left=0, right=0;\n    let count = 0, calc = 0;\n    let res = 0;\n    while(right < n) {\n        arr[right] = Math.abs(t[right].charCodeAt(0) - s[right].charCodeAt(0));\n        count++;\n        calc += arr[right];\n        while(maxCost < calc) {\n            calc -= arr[left];\n            count--;\n            left++;\n        }\n        res = Math.max(res, count);\n        right++;\n    }\n    return res;\n};\n```\n``` cpp []\nclass Solution {\npublic:\n    int equalSubstring(string s, string t, int maxCost) {\n        int n = s.size();\n        int arr[n];\n        int left=0, right=0;\n        int count = 0, calc = 0;\n        int res = 0;\n        while(right < n) {\n            arr[right] = abs(t[right] - s[right]);\n            count++;\n            calc += arr[right];\n            while(maxCost < calc) {\n                calc -= arr[left];\n                count--;\n                left++;\n            }\n            res = max(res, count);\n            right++;\n        }\n        return res;\n    }\n};\n```
['String', 'Sliding Window', 'C++', 'JavaScript']