💢☠💫Easiest👾Faster✅💯 Lesser🧠 🎯 C++✅Python3🐍✅Java✅C✅Python🐍✅C#✅💥🔥💫Explained☠💥🔥 Beats 100
Intuition\n\n\n\n\n\n\n\n\n---\nI Tried to explain this question in best possible way.. We Just Simply Try to traverse through every chil node for every node. F
# Intuition\n![0ehh83fsnh811.jpg](https://assets.leetcode.com/users/images/8bb4fa37-a47f-4d2d-8d5d-045bed83f7e7_1724647272.5606556.jpeg)\n![Screenshot 2024-08-26 094640.png](https://assets.leetcode.com/users/images/3c678bf5-7f89-4bf8-926c-60b9b079f0b3_1724647282.6749287.png)\n![Screenshot 2024-08-26 095041.png](https://assets.leetcode.com/users/images/6809fa48-72ac-486f-bc5f-64cd95e16a97_1724647289.7707932.png)\n![Screenshot 2024-08-26 095319.png](https://assets.leetcode.com/users/images/0fc5a0f7-202f-46e6-b510-f3b1a258fa4e_1724647296.3484774.png)\n![Screenshot 2024-08-26 095458.png](https://assets.leetcode.com/users/images/c062113b-7968-434c-b31b-a6c76f0de85b_1724647304.3540227.png)\n![Screenshot 2024-08-26 100407.png](https://assets.leetcode.com/users/images/d5286cfb-de89-49b0-9428-283952c42ade_1724647311.9000807.png)\n![Screenshot 2024-08-26 101003.png](https://assets.leetcode.com/users/images/7b7340ef-3c10-4bab-ace4-559339b9d9ef_1724647323.5854948.png)\n\n---\n***I Tried to explain this question in best possible way.. We Just Simply Try to traverse through every chil node for every node. For every languages other than C there is an advantage for having a for-each loop which directly retrievs the child nodes from every node.. Although in every Node type there is a array of nodes with number of array elements in it which is numChildren in C but in all other languages we can retrieve it via arr.length i.e why in all other languages int numChildren is not shown in Node definition.***\n![Screenshot 2024-08-26 130258.png](https://assets.leetcode.com/users/images/30e304f8-df5c-4fa4-a998-329d8b3a43a0_1724657614.5014322.png)\n\n***Also Visit my N-ary PreOrder Tree Traversal helps you to learn better to tackle these types of trees.. Afterwards We can do Level-Order Traversal for N-ary tress***\n\n***Q - 589*** https://leetcode.com/problems/n-ary-tree-preorder-traversal/solutions/5692438/easiest-faster-lesser-c-python3-java-c-python-c-explained-beats-100\n\n***Q - 429*** https://leetcode.com/problems/n-ary-tree-level-order-traversal/solutions/5693741/easiestfaster-lesser-cpython3javacpythoncexplained-beats-100\n---\n\n\n```javascript []\n//JavaScript Code\n/**\n * // Definition for a _Node.\n * function _Node(val,children) {\n *    this.val = val;\n *    this.children = children;\n * };\n */\n\n/**\n * @param {_Node|null} root\n * @return {number[]}\n */\nvar postorder = function(root) {\n    const arr = []\n    const postOrder = ((root) =>{\n        if(root == undefined)\n            return\n        for(let child of root.children)\n            postOrder(child)\n        \n        arr.push(root.val)\n    })\n    \n    postOrder(root)\n    return arr\n};\n```\n```C++ []\n//C++ Code\n/*\n// Definition for a Node.\nclass Node {\npublic:\n    int val;\n    vector<Node*> children;\n\n    Node() {}\n\n    Node(int _val) {\n        val = _val;\n    }\n\n    Node(int _val, vector<Node*> _children) {\n        val = _val;\n        children = _children;\n    }\n};\n*/\n\nclass Solution {\n    vector<int> res;\n    void postOrder(Node* root) {\n        if (!root)\n            return;\n        for (auto child : root->children) {\n            postOrder(child);\n            res.push_back(child->val);\n        }\n    }\n\npublic:\n    vector<int> postorder(Node* root) {\n        if (!root)\n            return {};\n        postOrder(root);\n        res.push_back(root->val);\n        return res;\n    }\n};\n```\n```Python3  []\n#Python3 Code\n"""\n# Definition for a Node.\nclass Node:\n    def __init__(self, val=None, children=None):\n        self.val = val\n        self.children = children\n"""\n\nclass Solution:\n    def postorder(self, root: \'Node\') -> List[int]:\n        res = []\n        \n        def postOrder(root):\n            if not root:\n                return\n            for node in root.children:\n                postOrder(node)\n                res.append(node.val)\n        \n        if not root:\n            return []\n        postOrder(root)\n        res.append(root.val)\n        return res\n```\n```Java []\n//Java Code\n/*\n// Definition for a Node.\nclass Node {\n    public int val;\n    public List<Node> children;\n\n    public Node() {}\n\n    public Node(int _val) {\n        val = _val;\n    }\n\n    public Node(int _val, List<Node> _children) {\n        val = _val;\n        children = _children;\n    }\n};\n*/\n\nclass Solution {\n    List<Integer> res = new ArrayList<>();\n\n    private void postOrder(Node root) {\n        if (root == null)\n            return;\n        for (Node child : root.children) {\n            postOrder(child);\n            res.add(child.val);\n        }\n    }\n\n    public List<Integer> postorder(Node root) {\n        if (root == null)\n            return new ArrayList<>();\n        postOrder(root);\n        res.add(root.val);\n        return res;\n    }\n}\n```\n```C []\n//C Code\n/**\n * Definition for a Node.\n * struct Node {\n *     int val;\n *     int numChildren;\n *     struct Node** children;\n * };\n */\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nvoid postOrder(struct Node* root, int* arr, int* returnSize){\n    if(!root)\n        return;\n    for(int i = 0; i < root->numChildren; i++)\n        postOrder(root->children[i], arr, returnSize);\n\n    arr[(*returnSize)++] = root->val;\n}\n\nint* postorder(struct Node* root, int* returnSize) {\n    int* arr = (int*)calloc(sizeof(int), 10001);\n    *returnSize = 0;\n    \n    if(!root)\n        return arr;\n    \n    postOrder(root, arr, returnSize);\n    return arr;\n}\n```\n```Python []\n#python Code\n"""\n# Definition for a Node.\nclass Node(object):\n    def __init__(self, val=None, children=None):\n        self.val = val\n        self.children = children\n"""\n\nclass Solution(object):\n    def postorder(self, root):\n        """\n        :type root: Node\n        :rtype: List[int]\n        """\n        res = []\n        \n        def postOrder(root):\n            if not root:\n                return\n            for node in root.children:\n                postOrder(node)\n                res.append(node.val)\n        \n        if not root:\n            return []\n        postOrder(root)\n        res.append(root.val)\n        return res\n```\n```C# []\n//C# Code\n/*\n// Definition for a Node.\npublic class Node {\n    public int val;\n    public IList<Node> children;\n\n    public Node() {}\n\n    public Node(int _val) {\n        val = _val;\n    }\n\n    public Node(int _val, IList<Node> _children) {\n        val = _val;\n        children = _children;\n    }\n}\n*/\n\npublic class Solution {\n    List<int> res = new List<int>();\n    \n    void postOrder(Node root){\n        if(root == null)\n            return;\n        foreach(Node child in root.children){\n            postOrder(child);\n            res.Add(child.val);\n        }\n    }\n    \n    public IList<int> Postorder(Node root) {\n        if(root == null)\n            return new List<int>();\n        postOrder(root);\n        res.Add(root.val);\n        return res;\n    }\n}\n```\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n     O(n)\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n     O(n)\n# Code\n![th.jpeg](https://assets.leetcode.com/users/images/7313ef57-2123-4b98-adea-126d6ad274d6_1724647659.9983175.jpeg)\n
['Stack', 'Tree', 'Depth-First Search', 'C', 'Python', 'C++', 'Java', 'Python3', 'JavaScript', 'C#']