SIMPLE TWO-POINTER C++ SOLUTION
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:o(n)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:o(1)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\npublic:\n    string makeSmallestPalindrome(string s) {\n        int left = 0;\n        int right = s.size() - 1;\n\n        while (left < right) {\n            if (s[left] != s[right]) {\n                // Replace the character at the larger index with the smaller one\n                if (s[left] > s[right]) {\n                    s[left] = s[right]; // Make the change towards the lexicographically smaller character\n                } else {\n                    s[right] = s[left];\n                }\n            }\n            left++;\n            right--;\n        }\n\n        return s;\n    }\n};\n```
['C++']