Redistribute Characters to Make All Strings Equal
Intuition\nThe intuition behind this code is to determine if it\'s possible to make all the strings equal by redistributing characters. If the count of each cha
# Intuition\nThe intuition behind this code is to determine if it\'s possible to make all the strings equal by redistributing characters. If the count of each character across all strings is divisible by the number of strings, it implies that each character can be distributed evenly, making the strings equal.\n\n# Approach\nThe code uses an object `charCount` to store the count of each character. It then iterates through each word and each character in the word, updating the count in the `charCount` object. After counting the occurrences of characters in all words, it checks if the count of each character is divisible by the number of strings. If any character\'s count is not divisible, it returns `false`, indicating that it\'s not possible to make all strings equal. Otherwise, it returns `true`.\n\n# Complexity\n- Time complexity: O(n * m), where n is the number of words and m is the average length of words. The code iterates through each character in each word to count the occurrences.\n- Space complexity: O(c), where c is the total number of unique characters across all words. The code uses an object (`charCount`) to store the count of each character.\n\n# Code\n```javascript\nvar makeEqual = function (words) {\n    let charCount = {};\n\n    // Count the occurrences of each character in all strings\n    for (let word of words) {\n        for (let char of word) {\n            charCount[char] = (charCount[char] || 0) + 1;\n        }\n    }\n\n    // Check if the count of each character is divisible by the number of strings\n    let numStrings = words.length;\n    for (let count of Object.values(charCount)) {\n        if (count % numStrings !== 0) {\n            return false;\n        }\n    }\n\n    return true;\n};\n```
['JavaScript']