easy C++ solution
Intuition\nThe problem seems to be about buying tickets, where the cost of each ticket might vary, and you want to find out how much time it would take to buy a
# Intuition\nThe problem seems to be about buying tickets, where the cost of each ticket might vary, and you want to find out how much time it would take to buy all the tickets if you start buying from a specific index k.\n# Approach\nThe approach taken in the provided code is to iterate through the array twice:\n\n1)  First, iterate from the beginning of the array up to index k (exclusive) and add the minimum of the cost at index k and the cost at each index encountered.\n2)  Then, iterate from index k+1 to the end of the array and add the minimum of (tickets[k] - 1) and the cost at each index encountered.\n\nThe total time required to buy all the tickets is then returned.\n# Complexity\n- Time complexity:\nThe algorithm iterates through the array twice, once from the beginning to index k and once from index k+1 to the end. Both iterations are linear, so the time complexity is O(n), where n is the number of elements in the tickets array.\n- Space complexity:\nThe space complexity of the algorithm is O(1) because it uses a constant amount of extra space regardless of the size of the input array.\n# Code\n```\nclass Solution {\npublic:\n    int timeRequiredToBuy(vector<int>& tickets, int k) {\n       int n=tickets.size();\n       int total=tickets[k];\n\n        for(int i=0;i<k;i++){\n            total+=min(tickets[k],tickets[i]);\n        }\n        for(int i=k+1;i<n;i++){\n            total+=min(tickets[k]-1,tickets[i]);\n        }\n        return total;\n    }\n};\n```\nUPVOTE IF YOU FIND ITS USEFULL
['C++']