JAVA Easy to understand solution
Title: Check Matrix Similarity After Shifts (Custom Implementation with Left and Right Shifts)\nProblem Statement:\n\nThe task is to determine if a given matrix
Title: Check Matrix Similarity After Shifts (Custom Implementation with Left and Right Shifts)\nProblem Statement:\n\nThe task is to determine if a given matrix becomes identical to its original state after a series of k shifts, where:\n\n    If the number of columns (n) in the matrix is even, we perform a left shift on each row.\n    If n is odd, we perform a right shift on each row.\n\nWe aim to perform k shifts and compare the resulting matrix with the original.\nApproach:\n*     Deep Copy: To preserve the original matrix, we make a deep copy of it.\nShifting Logic:\n*     If the number of columns is even, we left-shift all rows.\n*     Otherwise, we right-shift all rows.\n*     Equality Check: After performing k shifts, we use Arrays.deepEquals to compare the final matrix with the original deep copy.\n*     Helper Functions: We implement leftshift and rightshift helper methods for shifting the rows efficiently.\n\t\n\tclass Solution {\n    public boolean areSimilar(int[][] mat, int k) {\n        int m = mat.length; // Number of rows\n        int n = mat[0].length; // Number of columns\n        \n        // Create a deep copy of the original matrix\n        int[][] deepCopy = new int[m][];\n        for (int i = 0; i < m; i++) {\n            deepCopy[i] = mat[i].clone();\n        }\n        \n        // Perform k shifts\n        for (int q = 0; q < k; q++) {\n            for (int l = 0; l < m; l++) {\n                if (n % 2 == 0) {\n                    int[] x = leftshift(mat[l]);\n                    mat[l] = x;\n                } else {\n                    int[] x = rightshift(mat[l]);\n                    mat[l] = x;\n                }\n            }\n        }\n        \n        // Check if the matrix after k shifts matches the original\n        return Arrays.deepEquals(mat, deepCopy);\n    }\n    \n    // Helper function to perform a left shift on a row\n    public int[] leftshift(int[] mat) {\n        int n = mat.length;\n        int[] res = new int[n];\n        res[n - 1] = mat[0]; // Move the first element to the end\n        for (int i = 1, j = 0; i < n && j < n - 1; i++, j++) {\n            res[j] = mat[i];\n        }\n        return res;\n    }\n    \n    // Helper function to perform a right shift on a row\n    public int[] rightshift(int[] mat) {\n        int n = mat.length;\n        int[] res = new int[n];\n        res[0] = mat[n - 1]; // Move the last element to the beginning\n        for (int i = 1, j = 0; i < n && j < n - 1; i++, j++) {\n            res[i] = mat[j];\n        }\n        return res;\n    }\n}\n`
['Java']