🔄📖 Reverse Alphabet Math Madness! 🔢🤯Simple Logic Behind the Code 🤓➡️💡PYTHON
IntuitionThe problem requires calculating a weighted sum where each letter's reverse alphabet value is multiplied by its 1-based index in the string.
Since lett
# Intuition
The problem requires calculating a weighted sum where each letter's **reverse alphabet value** is multiplied by its **1-based index** in the string.  
Since letter values are fixed, we can **precompute** them in a dictionary and efficiently compute the sum in a **single pass**.

# Approach
1. **Create a dictionary** that maps each lowercase letter to its **reverse alphabet value**:
   ```python
   Letter = {chr(97 + i): 26 - i for i in range(26)}


# Code
```python3 []
class Solution:
    def reverseDegree(self, s: str) -> int:
        Letter = {chr(97 + i): 26 - i for i in range(26)} 
        res = 0  # Store the sum of values

        for i, char in enumerate(s, start=1):  # 1-based index
            if char in Letter:
                res += Letter[char] * i  # Multiply by index
        return res
```
![upvote code .webp](https://assets.leetcode.com/users/images/88e70ef4-b473-4db2-b8b5-1ef30e0ebfaa_1743568860.360542.webp)

['Python3']