Lets destructure and find the max diagonal and area
IntuitionIts a 2D array, loop throught the array and find the maximum diagonal.If there are same values for maximum diagonals then find the maximum area for sam
# Intuition
Its a 2D array, loop throught the array and find the maximum diagonal.

If there are same values for maximum diagonals then find the maximum area for same max diagonals.

# Approach
As we have to find the maximum value we initialise two variables with zero  and make comparisons with upcoming values.

For looping we use destructuring (const [w, l] of dimension) which is cleaner code and more efficient.

We have to consider about the areas of same maximum diagonals and that is checked in else if and the maximum area is returned.

# Complexity
- Time complexity:
 O(n) → We loop through the array once.

- Space complexity:
O(1) → We use only a few variables, no extra data structures.

# Code
```javascript []
/**
 * @param {number[][]} dimensions
 * @return {number}
 */
var areaOfMaxDiagonal = function(dimensions) {
    let maxDiagonal = 0;
    let maxArea = 0;

    for (const [w, l] of dimensions) {
        let diagonalLength = Math.sqrt(w * w + l * l);
        let area = w * l;

        if (diagonalLength > maxDiagonal) {
            maxDiagonal = diagonalLength;
            maxArea = area;
        } else if (diagonalLength === maxDiagonal) {
            maxArea = Math.max(maxArea, area);
        }
    }

    return maxArea;
};
```
['JavaScript']