Python Solution | EASY 100%
Explanation of the Solution\n\nThe problem we are solving is to find the difference between the product of the digits and the sum of the digits of a given integ
## Explanation of the Solution\n\nThe problem we are solving is to find the difference between the product of the digits and the sum of the digits of a given integer `n`. Let\'s break down the approach used in the code step by step.\n\n### Approach:\n1. **Convert the Number to a List of Digits**:\n   - The input `n` is first converted into a string, and then into a list of characters (`arr`). Each character represents a digit of `n`.\n\n2. **Initialize Variables**:\n   - `prod` is initialized to `1` to store the product of the digits.\n   - `Sum` is initialized to `0` to store the sum of the digits.\n\n3. **Iterate Over Each Digit**:\n   - For each digit `i` in the list `arr`:\n     - Convert the character to an integer and multiply it with `prod` to calculate the running product.\n     - Convert the character to an integer and add it to `Sum` to calculate the running sum.\n\n4. **Return the Result**:\n   - Return the difference between `prod` and `Sum`.\n\n### Time and Space Complexity:\n- **Time Complexity**: \\( O(d) \\), where \\( d \\) is the number of digits in the integer `n`. This is because we iterate over each digit once.\n- **Space Complexity**: \\( O(d) \\) due to the conversion of the integer to a string and then a list. This is not significant for most input sizes as Python handles integers and their conversions efficiently.\n\n### Example Walkthrough:\nFor `n = 234`:\n- Convert `234` to a list: `[\'2\', \'3\', \'4\']`\n- Initialize `prod = 1`, `Sum = 0`\n- Iterate through the list:\n  - For `i = \'2\'`: `prod = 1 * 2 = 2`, `Sum = 0 + 2 = 2`\n  - For `i = \'3\'`: `prod = 2 * 3 = 6`, `Sum = 2 + 3 = 5`\n  - For `i = \'4\'`: `prod = 6 * 4 = 24`, `Sum = 5 + 4 = 9`\n- Return `24 - 9 = 15`\n\n### Code:\n```python\nclass Solution:\n    def subtractProductAndSum(self, n: int) -> int:\n        arr = list(str(n))\n        \n        prod = 1\n        Sum = 0\n        \n        for i in arr:\n            prod *= int(i)\n            Sum += int(i)\n        \n        return prod - Sum\n```\n![image](https://assets.leetcode.com/users/images/b4300d66-7f42-4a6f-89fc-8a062c891451_1733509203.099548.gif)\n
['Python', 'Python3']