0ms 100% "My Rows Are Spinning"
In this solution, we  process even and odd rows separately using two distinct loops due to the different shift directions.
Even rows are checked with a left cir

In this solution, we  process even and odd rows separately using two distinct loops due to the different shift directions. 
* Even rows are checked with a left circular shift (shifting elements to the "left"), 
*  odd rows are checked with a right circular shift (shifting elements to the "right").  

The algorithm optimizes for early termination: if any cell within a row fails the similarity test (i.e., its value doesn't match the circularly shifted counterpart), the function immediately returns false.

The time complexity of this algorithm is O(RC),  as it iterates through every cell of the matrix once.

# Code
```cpp []
class Solution {
public:
    bool areSimilar(const vector<vector<int>>& mat, const int k_) {

        const int rows = mat.size();
        const int cols = mat[0].size();

        const int k = k_ % cols;       

        for (int r = 0; r < mat.size(); r += 2) {
            for (int c = 0; c < cols; ++c) {

                if (mat[r][c] != mat[r][((c - k) + cols) % cols]) {
                    return false;
                }
            }
        }

        bool odd_identical = false;
        for (int r = 1; r < mat.size(); r += 2) {
            for (int c = 0; c < cols; ++c) {
                if (mat[r][c] != mat[r][(c + k) % cols]) {
                    return false;
                }
            }
        }

        return true;
    }
};
```
['C++']