100% Efficient Solution
Code

# Code
```python3 []
class Solution:
    def reverseDegree(self, s: str) -> int:
        return sum((26 - (ord(c) - ord('a'))) * (i + 1) for i, c in enumerate(s))

```
```Java []
class Solution {
    public int reverseDegree(String s) {
        int sum = 0;
        for (int i = 0; i < s.length(); i++) {
            int reversePos = 26 - (s.charAt(i) - 'a'); // Reverse alphabet position
            sum += reversePos * (i + 1); // Multiply by 1-indexed position
        }
        return sum;    
    }
}
```
```C []
int reverseDegree(char* s) {
    int sum = 0;
    for (int i = 0; s[i] != '\0'; i++) {
        int reversePos = 26 - (s[i] - 'a');
        sum += reversePos * (i + 1);
    }
    return sum;
}
```
```C++ []
class Solution {
public:
    int reverseDegree(string s) {
        int sum = 0;
        for (int i = 0; s[i] != '\0'; i++) {
            int reversePos = 26 - (s[i] - 'a');
            sum += reversePos * (i + 1);
        }
        return sum;
    }
};
```
['String', 'C', 'Simulation', 'C++', 'Java', 'Python3']