JAVA COMMENTED SOLUTION INTUTIVE PRIORITY QUEUE BASED SOLUTION
\n\n\nclass Solution {\n    public int maximumSetSize(int[] nums1, int[] nums2) {\n        // Frequency map for nums1 and nums2\n        HashMap<Integer, Intege
```\n\n\nclass Solution {\n    public int maximumSetSize(int[] nums1, int[] nums2) {\n        // Frequency map for nums1 and nums2\n        HashMap<Integer, Integer> frequencyMap1 = new HashMap<>();\n        HashMap<Integer, Integer> frequencyMap2 = new HashMap<>();\n\n        // Counting frequency for nums1\n        for (int num : nums1) {\n            frequencyMap1.put(num, frequencyMap1.getOrDefault(num, 0) + 1);\n        }\n        \n        // Counting frequency for nums2\n        for (int num : nums2) {\n            frequencyMap2.put(num, frequencyMap2.getOrDefault(num, 0) + 1);\n        }\n\n        // Priority queue for nums1 based on frequency and secondary sorting on nums2 frequency\n        PriorityQueue<Integer> pq1 = new PriorityQueue<>((a, b) -> {\n            if (frequencyMap1.get(a).equals(frequencyMap1.get(b))) {\n                return frequencyMap2.getOrDefault(b, 0) - frequencyMap2.getOrDefault(a, 0);\n            } else {\n                return frequencyMap1.get(b) - frequencyMap1.get(a);\n            }\n        });\n\n        // Adding keys from frequencyMap1 to pq1\n        for (int key : frequencyMap1.keySet()) {\n            pq1.add(key);\n        }\n\n        // Reduce frequencyMap1 to half of its original size\n        int size1 = nums1.length / 2;\n        while (size1-- > 0) {\n            int top = pq1.poll();\n            if (frequencyMap1.get(top) == 1) {\n                frequencyMap1.remove(top);\n            } else {\n                frequencyMap1.put(top, frequencyMap1.get(top) - 1);\n                pq1.add(top);\n            }\n        }\n\n        // Priority queue for nums2 based on frequency and secondary sorting on nums1 frequency\n        PriorityQueue<Integer> pq2 = new PriorityQueue<>((a, b) -> {\n            if (frequencyMap2.get(a).equals(frequencyMap2.get(b))) {\n                return frequencyMap1.getOrDefault(b, 0) - frequencyMap1.getOrDefault(a, 0);\n            } else {\n                return frequencyMap2.get(b) - frequencyMap2.get(a);\n            }\n        });\n\n        // Adding keys from frequencyMap2 to pq2\n        for (int key : frequencyMap2.keySet()) {\n            pq2.add(key);\n        }\n\n        // Reduce frequencyMap2 to half of its original size\n        int size2 = nums1.length / 2;\n        while (size2-- > 0) {\n            int top = pq2.poll();\n            if (frequencyMap2.get(top) == 1) {\n                frequencyMap2.remove(top);\n            } else {\n                frequencyMap2.put(top, frequencyMap2.get(top) - 1);\n                pq2.add(top);\n            }\n        }\n\n        // Combining unique keys from both maps\n        HashSet<Integer> uniqueKeys = new HashSet<>(frequencyMap1.keySet());\n        uniqueKeys.addAll(frequencyMap2.keySet());\n\n        // Returning the size of unique keys\n        return uniqueKeys.size();\n    }\n}\n```\n
['Hash Table', 'Greedy', 'C', 'Heap (Priority Queue)', 'Java']