Lo Kr Lo copy
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\n    \n    // Main function to find the maximum number of operations\n    public int maxOperations(int[] nums) {\n        \n        int maxOps = 0;  // Variable to store the maximum operations\n        int len = nums.length;  // Length of the array\n        int[][] memo = new int[len][len];  // Memoization array to store computed results\n        int left = 0;  // Left pointer\n        int right = len - 1;  // Right pointer\n\n        // Checking operations with different combinations and update maxOps accordingly\n        maxOps = Math.max(maxOps, maxOpsHelper(nums, left + 2, right, nums[left] + nums[left + 1], memo) + 1);\n        maxOps = Math.max(maxOps, maxOpsHelper(nums, left + 1, right - 1, nums[left] + nums[right], memo) + 1);\n        maxOps = Math.max(maxOps, maxOpsHelper(nums, left, right - 2, nums[right] + nums[right - 1], memo) + 1);\n\n        return maxOps;\n    }\n\n    private int maxOpsHelper(int[] nums, int left, int right, int prevSum, int[][] memo) {\n        if (left >= right)\n            return 0;  // Base case : no more elements to consider\n        if (memo[left][right] != 0)\n            return memo[left][right];  // Returning memoized result if available\n\n        int ops = 0;  // Variable to store the maximum operations for the current subproblem\n\n        if (nums[left] + nums[left + 1] == prevSum)\n            ops = Math.max(ops, maxOpsHelper(nums, left + 2, right, prevSum, memo) + 1);\n        if (nums[left] + nums[right] == prevSum)\n            ops = Math.max(ops, maxOpsHelper(nums, left + 1, right - 1, prevSum, memo) + 1);\n        if (nums[right] + nums[right - 1] == prevSum)\n            ops = Math.max(ops, maxOpsHelper(nums, left, right - 2, prevSum, memo) + 1);\n\n        return memo[left][right] = ops;  // Memoizing the result and return\n    }\n}\n```
['Java']