Easy solution - beat 95%
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nimport math\n\nclass Solution:\n    def areaOfMaxDiagonal(self, dimensions: List[List[int]]) -> int:\n\n        max_diagonal = 0\n        max_area = 0\n        \n        for length, width in dimensions:\n            diagonal = math.sqrt(length ** 2 + width ** 2)\n            if diagonal > max_diagonal:\n                max_diagonal = diagonal\n                max_area = length * width\n            elif diagonal == max_diagonal:\n                max_area = max(max_area, length * width)\n        \n        return max_area\n```
['Python3']