Beats 100% || Simple Code || Time : O(N) || Space : O(1) || Easy 
IntuitionWe will check only the first letter of each word, and compare the letter with string s.Approach
Check if the length of string s is equal to the size of
# Intuition
We will check only the first letter of each word, and compare the letter with string s.

# Approach
- Check if the length of string s is equal to the size of the array. If not, than return false.
- check the first letter of each word with string s.

# Complexity
- Time complexity: O(N) : Traverse the array once.

- Space complexity: O(1) : traversing the loop doesn't use additional memory.

# Code
```cpp []
class Solution {
public:
    bool isAcronym(vector<string>& words, string s) {
        if (s.length()!=words.size()) return false ;

        for (int i=0 ; i<s.length() ; i++)
            if (words[i][0]!=s[i]) return false ;

        return true ;
    }
};
```
['C++']