Count Valid Array Splits Based on Prefix and Suffix Sums
IntuitionThe problem seems to involve checking if the prefix sum of an array up to a certain index is greater than or equal to the sum of the remaining elements
# Intuition
<!-- Describe your first thoughts on how to solve this problem. -->
The problem seems to involve checking if the prefix sum of an array up to a certain index is greater than or equal to the sum of the remaining elements of the array. This makes the problem a good fit for a prefix sum approach.

# Approach
<!-- Describe your approach to solving the problem. -->
- Calculate the Total Sum: First, compute the total sum of the array.
- Iterate Through the Array: Use a loop to calculate the prefix sum (left) and derive the suffix sum (right) by subtracting left from the total sum.
- Check Condition: For each index i, check if the prefix sum (left) is greater than or equal to the suffix sum (right). If true, increment the count.
- Return Count: Return the total count of valid splits.

# Complexity
- Time complexity: O(n)
<!-- Add your time complexity here, e.g. $$O(n)$$ -->

- Space complexity: O(1)
<!-- Add your space complexity here, e.g. $$O(n)$$ -->

# Code
```java []
class Solution {
    public int waysToSplitArray(int[] nums) {
        int n = nums.length;
        long left = 0, right = 0; // Variables to store prefix and suffix sums
        int count = 0; // Variable to count valid splits
        long sum = 0; // Variable to store total sum of the array

        // Calculate the total sum of the array
        for (int num : nums) {
            sum += num;
        }

        // Iterate through the array to check conditions
        for (int i = 0; i < n - 1; i++) {
            left += nums[i]; // Update prefix sum
            right = sum - left; // Derive suffix sum
            if (left >= right) { // Check if prefix sum is >= suffix sum
                count++;
            }
        }

        return count; // Return the number of valid splits
    }
}

```
['Java']