✅💯🔥Simple Code🚀📌|| 🔥✔️Easy to understand🎯 || 🎓🧠Beats 100%🔥|| Beginner friendly💀💯
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\n    public long countAlternatingSubarrays(int[] nums) {\n        long ans = 1;\n        int sub=0;\n        int prev=nums[0];\n        for(int i=1; i<nums.length; i++){\n            if(nums[i]!=prev){\n                ans+=(i-sub);\n            } else{\n                sub=i;\n            }\n            ans+=1;\n            prev=nums[i];\n        }\n        return ans;\n    }\n}\n```\n![7be995b4-0cf4-4fa3-b48b-8086738ea4ba_1699897744.9062278.jpeg](https://assets.leetcode.com/users/images/fe5117c9-43b1-4ec8-8979-20c4c7f78d98_1721303757.4674635.jpeg)
['Array', 'Math', 'C', 'Python', 'C++', 'Java']