Python Solution
Intuition\nSort both arrays, then from each of the first three elements of nums1 subtract the first elemnt of nums2. At least one of the three resulting integer
# Intuition\nSort both arrays, then from each of the first three elements of nums1 subtract the first elemnt of nums2. At least one of the three resulting integers should be our answer. So check for each of the three integers if it comply with the condition of nums2 being apart of nums1 (after adding the integer to each element in nums1) and it being the smallest integer. Then return the remaining integer.\n\n# Code\n```\nclass Solution:\n    def minimumAddedInteger(self, nums1: List[int], nums2: List[int]) -> int:\n        nums1.sort()\n        nums2.sort()\n        nums2_dict = Counter(nums2)\n        x = float(\'inf\')\n        for i in range(0, len(nums1)-len(nums2) + 1):\n            potential_int = nums2[0]-nums1[i]\n            if potential_int < x:\n                nums1_dict = Counter([j + potential_int for j in nums1])\n                is_inside = []\n                for num in nums2_dict.keys():\n                    if num in nums1_dict.keys() and nums2_dict[num] <= nums1_dict[num]:\n                        is_inside.append(True)\n                    else:\n                        is_inside.append(False)\n                x = potential_int if all(is_inside) else x\n            else: continue\n        return x\n```
['Python3']