Easy C solution
Intuition\nIdea is to seperate index numbers 11 and 12 and store it in a variable and then find whether the number is greater than 60 or not.\n\n# Approach\n In
# Intuition\nIdea is to seperate index numbers 11 and 12 and store it in a variable and then find whether the number is greater than 60 or not.\n\n# Approach\n* Initialise `count` variable to `0`\n* Iterate through the string one by one, until the `i<detailsSize`\n* Check if the length of the word is above or equal to 13.\n* If Yes, declare a variable `age` of type `char` and size `3`\n* store number at index 11 in `age[0]`, number at index12 in `age[1]` and add a null character at the end of `age[3] = \'\\0\'`\n* Use `atoi()` function which converts ASCII values to Integer, to convert numbers in `age` variable to integer type and store it in a variable `n`\n* now, If `n>60` Increment count by 1.\n* return count at the end  of function.\n\n# Complexity\n- Time complexity: O(n)\n\n- Space complexity: O(n)\n\n# Code\n```\n#include <stdlib.h>\n#include <string.h>\n\nint countSeniors(char **details, int detailsSize) {\n    int count = 0;\n\n    for (int i = 0; i < detailsSize; i++) {\n        if (strlen(details[i]) >= 13) {\n            char age[3];\n            age[0] = details[i][11];\n            age[1] = details[i][12];\n            age[2] = \'\\0\';\n            int n = atoi(age);\n            if (n > 60) {\n                count++;\n            }\n        }\n    }\n\n    return count;\n}\n\n```
['C']