Python🔥Java🔥C++🔥Simple Solution🔥Easy to Understand
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**!! BIG ANNOUNCEMENT !!**\nI am currently Giving away my premium content well-structured assignments and study materials to clear interviews at top companies related to computer science and data science to my current Subscribers. This is only for first 10,000 Subscribers.  **DON\'T FORGET** to Subscribe\n\n# Search \uD83D\uDC49 `Tech Wired Leetcode` to Subscribe\n\n\n# or\n\n# Click the Link in my Profile\n\n# Approach:\n\n- Initialize a fixed-size array (bucket) to store the elements of the HashSet.\n- Implement a hashing function to map the keys to specific indices in the bucket.\n- Handle collisions (i.e., multiple keys mapping to the same index) by using separate chaining. Each index of the bucket will contain a linked list or a similar data structure to store the elements with the same hash value.\n- For adding an element, calculate the hash value of the key and insert it into the corresponding bucket if it doesn\'t already exist.\n- For removing an element, calculate the hash value of the key, find the corresponding bucket, and remove the element from it if it exists.\n- For checking if an element exists, calculate the hash value of the key, find the corresponding bucket, and check if the element is present in it.\n\n# Intuition:\nThe idea behind the HashSet implementation is to leverage the concept of hashing for efficient insertion, removal, and retrieval operations. By using a hashing function, we can map each key to a specific index in the array, which allows for constant-time operations on average.\n\n- During the addition process, the key\'s hash value is calculated, and if it doesn\'t already exist in the bucket, it is inserted. This ensures uniqueness of elements within the HashSet.\n- When removing an element, we calculate the hash value to determine the corresponding bucket and then remove the element if it exists. By using a linked list or similar data structure at each index, we can handle collisions and remove the element efficiently.\n- For checking if an element exists, the hash value of the key is computed, and the corresponding bucket is searched for the element. - \n- If it is found, we can conclude that the HashSet contains the element.\n\n```Python []\nclass MyHashSet:\n    def __init__(self):\n        self.size = 1000\n        self.buckets = [[] for _ in range(self.size)]\n\n    def add(self, key: int) -> None:\n        index = self._hash(key)\n        if key not in self.buckets[index]:\n            self.buckets[index].append(key)\n\n    def remove(self, key: int) -> None:\n        index = self._hash(key)\n        if key in self.buckets[index]:\n            self.buckets[index].remove(key)\n\n    def contains(self, key: int) -> bool:\n        index = self._hash(key)\n        return key in self.buckets[index]\n\n    def _hash(self, key: int) -> int:\n        return key % self.size\n```\n```Java []\n\nclass MyHashSet {\n    private int size;\n    private List<List<Integer>> buckets;\n\n    public MyHashSet() {\n        size = 1000;\n        buckets = new ArrayList<>(size);\n        for (int i = 0; i < size; i++) {\n            buckets.add(new LinkedList<>());\n        }\n    }\n\n    public void add(int key) {\n        int index = hash(key);\n        List<Integer> bucket = buckets.get(index);\n        if (!bucket.contains(key)) {\n            bucket.add(key);\n        }\n    }\n\n    public void remove(int key) {\n        int index = hash(key);\n        List<Integer> bucket = buckets.get(index);\n        bucket.remove(Integer.valueOf(key));\n    }\n\n    public boolean contains(int key) {\n        int index = hash(key);\n        List<Integer> bucket = buckets.get(index);\n        return bucket.contains(key);\n    }\n\n    private int hash(int key) {\n        return key % size;\n    }\n}\n\n```\n```C++ []\n\nclass MyHashSet {\nprivate:\n    int size;\n    std::vector<std::list<int>> buckets;\n\npublic:\n    MyHashSet() {\n        size = 1000;\n        buckets = std::vector<std::list<int>>(size);\n    }\n\n    void add(int key) {\n        int index = hash(key);\n        std::list<int>& bucket = buckets[index];\n        if (!contains(key, bucket)) {\n            bucket.push_back(key);\n        }\n    }\n\n    void remove(int key) {\n        int index = hash(key);\n        std::list<int>& bucket = buckets[index];\n        bucket.remove(key);\n    }\n\n    bool contains(int key) {\n        int index = hash(key);\n        std::list<int>& bucket = buckets[index];\n        return contains(key, bucket);\n    }\n\nprivate:\n    int hash(int key) {\n        return key % size;\n    }\n\n    bool contains(int key, std::list<int>& bucket) {\n        for (int num : bucket) {\n            if (num == key) {\n                return true;\n            }\n        }\n        return false;\n    }\n};\n\n```\n# An Upvote will be encouraging \uD83D\uDC4D\n\n
['Hash Table', 'Design', 'C++', 'Java', 'Python3']