2 Linear (Solution)+Explanation
The idea here is to sort  the array in descending order based on the size of strings, however if the size is equal then we should compare those two strings to c
The idea here is to sort  the array in descending order based on the size of strings, however if the size is equal then we should compare those two strings to check which comes lexographically first.\n\t\n    string kthLargestNumber(vector<string>& nums, int k) \n    {\n    sort(nums.begin(),nums.end(),[](string &a,string &b){return a.size()!=b.size()?a.size()>b.size():a>b;});   \n    return nums[k-1];\n    }
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