✔️BEST C++ SOLUTION✔️
PLEASE UPVOTE MY SOLUTION IF YOU LIKE IT\n# CONNECT WITH ME\n### https://www.linkedin.com/in/pratay-nandy-9ba57b229/\n#### https://www.instagram.com/pratay_nand
# **PLEASE UPVOTE MY SOLUTION IF YOU LIKE IT**\n# **CONNECT WITH ME**\n### **[https://www.linkedin.com/in/pratay-nandy-9ba57b229/]()**\n#### **[https://www.instagram.com/pratay_nandy/]()**\n\n# Approach\nThe provided C++ code defines a class "Solution" with a public member function "rotate." This function takes a vector of integers `nums` and an integer `k` as input and aims to rotate the elements of the vector to the right by `k` positions.\n\nHere\'s the approach used in this code:\n\n1. Get the size of the input vector `nums` and store it in the variable `n`.\n\n2. Create a new vector `arr` of the same size as `nums` to store the rotated elements. This vector will be used to hold the new arrangement of elements.\n\n3. Start a loop that iterates through the elements of the original `nums` vector using the index `i`.\n\n4. Inside the loop, calculate the new index for each element in `nums` after the rotation using the formula `(i + k) % n`. This index represents the new position for the element in the rotated array.\n\n5. Assign the value of the element at the original index `i` in `nums` to the corresponding position in the `arr` vector using the calculated new index.\n\n6. After the loop has processed all elements, the `arr` vector will contain the elements of `nums` in their rotated order.\n\n7. Finally, assign the values of the `arr` vector back to the `nums` vector, effectively updating `nums` with the rotated elements.\n\nThe code rotates the elements to the right by `k` positions in a new vector and then copies the rotated elements back to the original vector. The time complexity of this algorithm is O(n), where n is the number of elements in the input vector `nums`, as it iterates through the vector once.\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:0(N)\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:0(N)\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n![upvote2.png](https://assets.leetcode.com/users/images/6652571c-e003-461f-a70c-dc396233f580_1699366653.8511074.png)\n\n\n# Code\n```\nclass Solution {\npublic:\n    void rotate(vector<int>& nums, int k) {\n        int n=nums.size();\n        vector<int>temp(nums.size());\n        for(int i=0;i<n;i++){\n            temp[(i+k) % n]=nums[i];\n        }\n        nums=temp;\n    }\n};\n```
['Array', 'Math', 'C++']