Clean Python | Semaphore Coordination
Clean Python | Semaphore Coordination\n\n\nfrom threading import Semaphore\nclass ZeroEvenOdd:\n    def __init__(self, n):\n        self.n = n\n        self.sem
**Clean Python | Semaphore Coordination**\n\n```\nfrom threading import Semaphore\nclass ZeroEvenOdd:\n    def __init__(self, n):\n        self.n = n\n        self.semOdd  = Semaphore(0) # Permission to write an Odd  Number\n        self.semEven = Semaphore(0) # Permission to write an Even Number\n        self.semZero = Semaphore(1) # Permission to write a  Zero\n\t# printNumber(x) outputs "x", where x is an integer.\n    def zero(self, printNumber):\n        for i in range(1,self.n+1):\n            # A) Request Permission to Write a Zero\n            self.semZero.acquire()\n            printNumber(0)\n            # B) Check if "i" if Odd or Even, and give permission to write the number\n            if i&1:\n                self.semOdd.release()\n            else:\n                self.semEven.release()\n            # C) Permission to write a zero is returned by another Thread ( release triggers a change)\n    def even(self, printNumber):\n        # A) Iterate only through Even numbers\n        for i in range(2,self.n+1,2):\n            # B) Request Permission to Write Current Number\n            self.semEven.acquire()\n            printNumber(i)\n            # C) Return Permission to Write a Zero (if applicable)\n            self.semZero.release()\n    def odd(self, printNumber):\n        # A) Iterate only through Odd numbers\n        for i in range(1,self.n+1,2):\n            # B) Request Permission to Write Current Number\n            self.semOdd.acquire()\n            printNumber(i)\n            # C) Return Permission to Write a Zero (if applicable)\n            self.semZero.release()\n```
['Python', 'Python3']