Simple, Easy and Fast MySQL Solution using sub-query
Code\n\n# Write your MySQL query statement below\n\nSELECT c.customer_id\nFROM Customer c\ngroup by customer_id \nHAVING count(distinct c.product_key) = (select
# Code\n```\n# Write your MySQL query statement below\n\nSELECT c.customer_id\nFROM Customer c\ngroup by customer_id \nHAVING count(distinct c.product_key) = (select count(distinct p.product_key) FROM Product p);\n\n```
['MySQL']