🚀🚀🚀THREE LiNES OF CODE🚀🚀🚀by PRODONiK (Java, C++, Python, Go, JS, Ruby, C#)
Intuition\nThe intuition behind this solution is to determine if two strings are anagrams by comparing their sorted representations. Anagrams are words or phras
# Intuition\nThe intuition behind this solution is to determine if two strings are anagrams by comparing their sorted representations. Anagrams are words or phrases formed by rearranging the letters of another, and sorting the characters in each string allows us to easily check if they contain the same set of characters.\n\n# Approach\nThe approach involves converting the input strings `s` and `t` into character arrays `ss` and `tt` using the `toCharArray()` method. These arrays are then sorted using `Arrays.sort()` to arrange the characters in ascending order. Finally, the `Arrays.equals()` method is used to check if the sorted arrays are equal, which indicates that the original strings are anagrams.\n\n# Complexity\n- Time complexity: $$O(n \\log n)$$, where $$n$$ is the length of the input strings. The dominant factor is the sorting operation.\n- Space complexity: $$O(n)$$, as additional space is used to store the character arrays.\n\nThe space complexity is determined by the size of the character arrays, and the time complexity is influenced by the sorting operation.\n\n# Code\n```Java []\nclass Solution {\n    public boolean isAnagram(String s, String t) {\n        char [] ss = s.toCharArray(), tt = t.toCharArray();\n        Arrays.sort(ss); Arrays.sort(tt);\n        return Arrays.equals(ss, tt);\n    }\n}\n```\n```C++ []\nclass Solution {\npublic:\n    bool isAnagram(std::string s, std::string t) {\n        // Convert strings to char arrays\n        std::sort(s.begin(), s.end());\n        std::sort(t.begin(), t.end());\n\n        // Check if the sorted char arrays are equal\n        return s == t;\n    }\n};\n```\n```Python []\nclass Solution:\n    def isAnagram(self, s: str, t: str) -> bool:\n        # Convert strings to sorted lists of characters\n        ss = sorted(s)\n        tt = sorted(t)\n\n        # Check if the sorted lists are equal\n        return ss == tt\n```\n```C# []\npublic class Solution {\n    public bool IsAnagram(string s, string t) {\n        // Convert strings to char arrays\n        char[] ss = s.ToCharArray();\n        char[] tt = t.ToCharArray();\n        \n        // Sort the char arrays\n        Array.Sort(ss);\n        Array.Sort(tt);\n        \n        // Check if the sorted char arrays are equal\n        return new string(ss) == new string(tt);\n    }\n}\n```\n```Go []\nfunc (s *Solution) IsAnagram(str1 string, str2 string) bool {\n\t// Convert strings to sorted slices of characters\n\tss := strings.Split(str1, "")\n\ttt := strings.Split(str2, "")\n\tsort.Strings(ss)\n\tsort.Strings(tt)\n\n\t// Check if the sorted slices are equal\n\treturn strings.Join(ss, "") == strings.Join(tt, "")\n}\n```\n```Ruby []\nclass Solution\n  def is_anagram(s, t)\n    # Convert strings to arrays of characters and sort them\n    ss = s.chars.sort\n    tt = t.chars.sort\n\n    # Check if the sorted arrays are equal\n    ss == tt\n  end\nend\n```\n```JavaScript []\nclass Solution {\n    isAnagram(s, t) {\n        // Convert strings to arrays of characters and sort them\n        const ss = s.split(\'\').sort();\n        const tt = t.split(\'\').sort();\n\n        // Check if the sorted arrays are equal\n        return ss.join(\'\') === tt.join(\'\');\n    }\n}\n
['C++', 'Java', 'Go', 'Python3', 'Ruby', 'JavaScript', 'C#']