Solution Find Kth Largest XOR Coordinate Value
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution {\n  int kthLargestValue(List<List<int>> matrix, int k) {\n    int rows = matrix.length;\n    int cols = matrix[0].length;\n    List<int> temp = [];\n\n    for (int i = 0; i < rows; i++) {\n      for (int j = 0; j < cols; j++) {\n        if (i > 0) matrix[i][j] ^= matrix[i - 1][j];\n        if (j > 0) matrix[i][j] ^= matrix[i][j - 1];\n        if (i > 0 && j > 0) matrix[i][j] ^= matrix[i - 1][j - 1];\n        temp.add(matrix[i][j]);\n      }\n    }\n\n    temp.sort((a, b) => b.compareTo(a)); // Sort in descending order\n    return temp[k - 1];\n  }\n}\n\n```
['Dart']