Java 1ms Easy Solution
\t\tint n=nums.length;\n        int c=0;\n        int maxx=0;\n        for(int i=0;inums[i]){\n                c++;\n                maxx=Math.max(maxx,c);\n   
\t\tint n=nums.length;\n        int c=0;\n        int maxx=0;\n        for(int i=0;i<n-1;i++){\n            if(nums[i+1]>nums[i]){\n                c++;\n                maxx=Math.max(maxx,c);\n            }else{\n                c=0;\n            }\n        }\n        return maxx+1;\n
['Iterator']