best solution
IntuitionThis solution determines if a number represented as a string is "balanced" by comparing the sum of digits at even positions with the sum of digits at o
# Intuition
This solution determines if a number represented as a string is "balanced" by comparing the sum of digits at even positions with the sum of digits at odd positions. A number is considered balanced if both sums are equal.

# Approach

- Initialize two counters: even for the sum of digits at even positions and odd for the sum of digits at odd positions
- Iterate through each digit in the string representation of the number
- Add the current digit to either the even or odd sum based on its position
    - If the position is even (0, 2, 4, ...), add to the even sum
    - If the position is odd (1, 3, 5, ...), add to the odd sum
- After processing all digits, compare the two sums
- Return true if the sums are equal, false otherwise

# Complexity

- Time complexity: O(n)
    - We iterate once through the string of length n
    - Each operation inside the loop (conversion, addition) is O(1)


- Space complexity: O(1)
    - We only use two variables (even and odd) regardless of input size
    - No additional data structures are used that scale with input size

# Code
```javascript []
/**
 * @param {string} num
 * @return {boolean}
 */
var isBalanced = function (num) {
    let even = 0;
    let odd = 0;
    for (let i = 0; i < num.length; i++) {
        i % 2 === 0 ? even += Number(num[i]) : odd += Number(num[i])
    }
    return even === odd;
};
```
['JavaScript']