Faster then 100 %
\nclass Solution {\npublic:\n    string breakPalindrome(string p) {\n    if(p.size()==1)return "";\n     for(int i=0;i<p.size()/2;i++){\n         if(p[i]!=\'a\'
```\nclass Solution {\npublic:\n    string breakPalindrome(string p) {\n    if(p.size()==1)return "";\n     for(int i=0;i<p.size()/2;i++){\n         if(p[i]!=\'a\'){\n             p[i]=\'a\';\n             return p;\n         }\n        }\n        p[p.size()-1]=\'b\';\n        return p;\n    }\n};\n```
['C', 'C++']