📌 One Line Beats 100%
Intuition 🤔The problem requires concatenating a list with itself to create a new list where the original elements are repeated twice in the same order. This can
# Intuition 🤔
The problem requires concatenating a list with itself to create a new list where the original elements are repeated twice in the same order. This can be achieved easily using Python’s list manipulation features.

# Approach 💡
-	Use Python’s multiplication operator (*) on the input list nums to duplicate its elements.


# Complexities ⏳
- Time complexity: $$O(n$$), where $$n$$ is the length of the list. This is because duplicating and concatenating the list both take linear time.

- Space complexity: $$O(n)$$, as the new list created for the result requires additional space proportional to the input size.

# Code
```python3 []
class Solution:
    def getConcatenation(self, nums: List[int]) -> List[int]:
        return nums*2
```
['Array', 'Python3']