Easy C++ Solution - Faster than 100% with simplest logic
\nclass Solution {\npublic:\n    string breakPalindrome(string palindrome) {\n        if(palindrome.length() == 1) return "";\n        \n        for(int i =0; i
```\nclass Solution {\npublic:\n    string breakPalindrome(string palindrome) {\n        if(palindrome.length() == 1) return "";\n        \n        for(int i =0; i < palindrome.length() / 2 ; i++){\n            if (palindrome[i] != \'a\') {\n                palindrome[i] = \'a\';\n                return palindrome;\n            }\n        }\n        palindrome[palindrome.length()-1] = \'b\';\n        return palindrome;\n    }\n};\n```
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