C++ || 2-d Dp
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\n\n\n\nclass Solution {\n    static final int MOD= 1_000_000_007;\n\n    public static long findMaxNonAdjSum(int[] arr) {\n        long inclCurr = 0, exclCurr = 0;\n        for (int elem : arr) {\n            long newInclCurr = exclCurr + elem;\n            exclCurr = Math.max(exclCurr, inclCurr);\n            inclCurr = newInclCurr;\n        }\n        return Math.max(inclCurr, exclCurr);\n    }\n\n    public static int maximumSumSubsequence(int[] arr, int[][] qs) {\n        long Sum = 0;\n        long maxNonAdjSum = findMaxNonAdjSum(arr);\n\n        for (int[] q : qs) {\n            int index = q[0];\n            int value = q[1];\n\n            arr[index] = value;\n            maxNonAdjSum = findMaxNonAdjSum(arr);\n            Sum = (Sum + maxNonAdjSum) % MOD;\n        }\n\n        return (int) Sum;\n    }\n}\n```
['Java']