Easy to Understand Memoization!!!
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```cpp []\nclass Solution {\npublic:\n    int f(int i,int j,vector<vector<int>>&v,vector<vector<int>>&dp)\n    {\n        int n=v.size();\n        int m=v[0].size();\n        if(i>=n || j>=m)\n        {\n            return 0;\n        }\n        if(dp[i][j]!=-1)\n        {\n            return dp[i][j];\n        }\n        int up=0,down=0,right=0;\n        if(i-1>=0 && j+1<m && v[i][j]<v[i-1][j+1])\n        {\n            up=1+f(i-1,j+1,v,dp);\n        }\n        if(i+1<n && j+1<m && v[i][j]<v[i+1][j+1])\n        {\n            down=1+f(i+1,j+1,v,dp);\n        }\n        if(j+1<m && v[i][j]<v[i][j+1])\n        {\n            right=1+f(i,j+1,v,dp);\n        }\n        return dp[i][j]=max({up,down,right});\n    }\n    int maxMoves(vector<vector<int>>& grid) \n    {\n        int n=grid.size();\n        int m=grid[0].size();\n        vector<vector<int>>dp(n,vector<int>(m,-1));\n        int ans=0;\n        for(int i=0;i<n;i++)\n        {\n            ans=max(ans,f(i,0,grid,dp));\n        }\n        return ans;\n    }\n};\n```
['C++']