674: Solution with step by step explanation
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n1. We handle the base cases where the input list is empty or has only one
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n1. We handle the base cases where the input list is empty or has only one element. In both cases, the length of the longest continuous in1.creasing subsequence is the length of the input list itself, so we simply return that length.\n\n2. We initialize two variables cur_len and max_len to keep track of the length of the current increasing subsequence and the maximum length seen so far, respectively. We set both variables to 1 because the first element of the input list is always part of a subsequence of length 1.\n\n3. We iterate through the input list starting from the second element. For each element, we check if it is greater than the previous element. If it is, then it is part of the current increasing subsequence, so we increase the length of the subsequence by 1 (cur_len += 1). We also update the maximum length seen so far (max_len = max(max_len, cur_len)) if necessary. If the current element is not greater than the previous element, then it is the start of a new increasing subsequence, so we reset the length of the subsequence to 1 (cur_len = 1).\n\n4. After iterating through the entire input list, we return the maximum length of any increasing subsequence seen (return max_len).\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution:\n    def findLengthOfLCIS(self, nums: List[int]) -> int:\n        # Base case: empty list or single element list\n        if len(nums) == 0 or len(nums) == 1:\n            return len(nums)\n        \n        # Initialize variables to keep track of current length and max length\n        cur_len = 1  # current length of increasing subsequence\n        max_len = 1  # maximum length of increasing subsequence\n        \n        # Iterate through the list starting from the second element\n        for i in range(1, len(nums)):\n            # If the current element is greater than the previous element, it is part of the increasing subsequence\n            if nums[i] > nums[i-1]:\n                cur_len += 1  # increase the length of the subsequence\n                max_len = max(max_len, cur_len)  # update the maximum length if necessary\n            else:\n                cur_len = 1  # reset the length of the subsequence if the current element is not greater than the previous element\n        \n        return max_len\n\n```
['Array', 'Python', 'Python3']