easy solution
Intuition\nThe problem asks to replace each element in the array with the sum of its digits and then return the minimum element. To solve this, we need to proce
# Intuition\nThe problem asks to replace each element in the array with the sum of its digits and then return the minimum element. To solve this, we need to process each element by computing the sum of its digits and then find the smallest among the transformed values.\n\n# Approach\n1. **Sum of Digits**: Create a helper function `digitsSum` that takes an integer and returns the sum of its digits by repeatedly extracting the last digit using modulo (`%`) and adding it to a running total.\n2. **Transform Array**: Iterate through each element in the `nums` array and replace it with the sum of its digits.\n3. **Find Minimum**: After transforming the array, iterate through it again to find the minimum value.\n\n# Complexity\n- **Time complexity**:  \n  - Computing the sum of digits for each number takes time proportional to the number of digits, i.e., $$O(d)$$ where $$d$$ is the number of digits.\n  - For an array of size $$n$$, the overall time complexity is $$O(n \\cdot d)$$, where $$d$$ is the average number of digits.\n  \n- **Space complexity**:  \n  $$O(1)$$, since we are modifying the input array in place and only using a constant amount of extra space.\n\n# Code\n```cpp\nclass Solution {\npublic:\n    int minElement(vector<int>& nums) {\n        // Replace each number with the sum of its digits\n        for (int i = 0; i < nums.size(); i++) {\n            nums[i] = digitsSum(nums[i]);\n        }\n        \n        // Find the minimum element in the transformed array\n        int ans = INT_MAX;\n        for (int i = 0; i < nums.size(); i++) {\n            ans = min(ans, nums[i]);\n        }\n        \n        return ans;\n    }\n    \n    // Helper function to compute the sum of digits of a number\n    int digitsSum(int x) {\n        int total = 0;\n        while (x) {\n            total += x % 10; // Add the last digit\n            x /= 10;         // Remove the last digit\n        }\n        return total;\n    }\n};\n```
['C++']