Fastest Solution Beats 100%
class Solution {\n\n    public String breakPalindrome(String palindrome) {\n\tint n=palindrome.length();\n        char[] CA=palindrome.toCharArray();\n        i
class Solution {\n\n    public String breakPalindrome(String palindrome) {\n\tint n=palindrome.length();\n        char[] CA=palindrome.toCharArray();\n        if(n==1) return "";\n        for(int i=0;i<n/2;i++){\n              if(CA[i]!=\'a\') {\n                CA[i]=\'a\'; \n                return new String(CA); }}\n        CA[n-1]=\'b\';\n        return new String(CA);}}
['Array', 'String', 'Java']