Rotate Array
Intuition\nThe problem requires rotating an array nums to the right by k steps. One intuitive approach is to understand that rotating by k steps is equivalent t
# Intuition\nThe problem requires rotating an array nums to the right by k steps. One intuitive approach is to understand that rotating by k steps is equivalent to moving the last k elements to the front of the array.\n\n# Approach\n1.Take modulo k with the length of the array to handle cases where k is larger than the length of the array, as rotating by the length of the array or its multiples will result in the same array.\n2.Slice the array by taking the last k elements and concatenate them with the remaining elements of the array.\n\n# Complexity\n- Time complexity:\nTime complexity: O(n) wheren is the length of the array nums. Slicing and concatenation operations take O(n) time.\n\n- Space complexity:\nSpace complexity: O(n) for the space used by the sliced portion of the array\n\n# Code\n```\nclass Solution:\n    def rotate(self, nums: List[int], k: int) -> None:\n        """\n        Do not return anything, modify nums in-place instead.\n        """\n        a=k%len(nums)\n        nums[:]=nums[-a:]+nums[:-a]\n        return nums\n        \n```
['Python3']