Count Pairs Of Similar Strings
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution:\n    def similarPairs(self, words: List[str]) -> int:\n        count = 0\n        for i in range(len(words)):\n            for j in range(i + 1, len(words)):\n                if set(words[i]) == set(words[j]):\n                    count += 1\n        return count\n```
['Array', 'Hash Table', 'String', 'Python3']