Python | Easy
see the Successfully Accepted Submission\npython\nclass Solution(object):\n    def makeEqual(self, words):\n        frequency_counter = [0] * 26\n        for wo
[see the Successfully Accepted Submission](https://leetcode.com/submissions/detail/1132050567/)\n```python\nclass Solution(object):\n    def makeEqual(self, words):\n        frequency_counter = [0] * 26\n        for word in words:\n            for c in word:\n                frequency_counter[ord(c) - ord(\'a\')] += 1\n\n        n = len(words)\n        for indx in range(26):\n            if frequency_counter[indx] != 0 and frequency_counter[indx] % n != 0:\n                return False\n\n        return True\n        \n```\n\n![image](https://assets.leetcode.com/users/images/b1e4af48-4da1-486c-bc97-b11ae02febd0_1696186577.992237.jpeg)
['Python']