Python: My soultion with comments
\n# Approach\nThis code is a solution to separate the digits of a list of integers. Here\'s how it works:\n\nThe function takes a list of integers as input, rep
\n# Approach\nThis code is a solution to separate the digits of a list of integers. Here\'s how it works:\n\nThe function takes a list of integers as input, represented by the variable nums.\n\nIt first checks if the list is empty, in which case it returns an empty list using an if statement.\n\nIf the list is not empty, it sets the first element of the list as the variable n using n = nums[0].\n\nIt then creates an empty list called result to store the separated digits of n.\n\nThe function enters a while loop, which continues until n is less than 10. In each iteration of the loop:\n\na. It adds the remainder of n divided by 10 to the beginning of the result list using the insert method.\n\nb. It updates n to be the result of n divided by 10, which effectively removes the last digit of n.\n\nAfter the while loop, the function adds the final value of n to the beginning of the result list.\n\nFinally, it returns the concatenation of result and the result of calling self.separateDigits on the remaining elements of the list (nums[1:]), which effectively separates the digits of the rest of the numbers in the list.\n\nThis function uses recursion to handle the separation of all the numbers in the input list.\n\n# Complexity\nThe time complexity of this function depends on the number of digits in the input list of integers. Let\'s assume that the average number of digits in the input list is d, then the time complexity can be estimated as follows:\n\nThe initial setup and base case checking takes O(1) time.\n\nThe while loop takes O(d) time in the worst case, where d is the number of digits in the largest number in the list.\n\nThe recursive call to self.separateDigits takes O(n * d) time, where n is the number of elements in the input list. This is because the function is called once for each element in the list, and each call takes O(d) time to process the digits of the number.\n\nTherefore, the overall time complexity of this function is O(n * d).\n\nThe space complexity of this function is O(n * d), as well. This is because the result list stores the separated digits of all the numbers in the input list, and its size grows with the number of digits in the input list. Additionally, the function makes n recursive calls, each of which adds a new level to the call stack and requires additional memory.\n\n# Code\n```\nclass Solution(object):\n    def separateDigits(self, nums):\n        if len(nums) == 0:\n            return []\n        n = nums[0]\n        result = []\n        while n >= 10:\n            result.insert(0, n % 10)\n            n = n / 10\n        result.insert(0, n)\n        return result + self.separateDigits(nums[1:])\n```
['Python']