Counter
Since numbers in each array are unique, we can just count all numbers.\n\nNumbers that are present in each array will be counted nums.size() number of times.\n\
Since numbers in each array are unique, we can just count all numbers.\n\nNumbers that are present in each array will be counted `nums.size()` number of times.\n\n**C++**\n```cpp\nvector<int> intersection(vector<vector<int>>& nums) {\n    vector<int> cnt(1001), res;\n    for (auto &arr: nums)\n        for (int n : arr)\n            ++cnt[n];\n    for (int i = 0; i < cnt.size(); ++i)\n        if (cnt[i] == nums.size())\n            res.push_back(i);\n    return res;\n}\n```
['C']