2967. Minimum Cost to make Array Equalindromic Best Solution
Intuition\nThe problem seems to involve finding the minimum cost to transform an array of integers into a palindrome by adjusting each number. \n\n# Approach\nT
# Intuition\nThe problem seems to involve finding the minimum cost to transform an array of integers into a palindrome by adjusting each number. \n\n# Approach\nThe approach involves first sorting the array and then finding the median element. Then, it calculates the next and previous palindromes based on the median. It calculates the cost for transforming the array into these palindromes and returns the minimum cost.\n\n# Complexity\n- Time complexity: \n  - Sorting the array: $$O(n \\log n)$$\n  - Calculating palindromes: $$O(n)$$\n  - Calculating the cost: $$O(n)$$\n  Overall, the time complexity is $$O(n \\log n)$$ due to sorting.\n- Space complexity: \n  - The space complexity is $$O(1)$$ as the additional space used is constant irrespective of the input size.\n\n# Code\n```\nclass Solution:\n  def minimumCost(self, nums: List[int]) -> int:\n    nums.sort()\n    median = nums[len(nums) // 2]\n    nextPalindrome = self._getPalindrome(median, delta=1)\n    prevPalindrome = self._getPalindrome(median, delta=-1)\n    return min(self._cost(nums, nextPalindrome),\n               self._cost(nums, prevPalindrome))\n\n  def _cost(self, nums: List[int], palindrome: int) -> int:\n    """Returns the cost to change all the numbers to `palindrome`."""\n    return sum(abs(palindrome - num) for num in nums)\n\n  def _getPalindrome(self, num: int, delta: int) -> int:\n    """Returns the palindrome `p`, where p = num + a * delta and a > 0."""\n    while not self._isPalindrome(num):\n      num += delta\n    return num\n\n  def _isPalindrome(self, num: int) -> int:\n    original = str(num)\n    return original == original[::-1]\n```
['Python3']