JS | 99% | With explanation
\n\n\nTo solve this problem, first of all we check if the length of the string is equal to 1, if it is, we return an empty string (" ").\nFor convenience, we tu
![image](https://assets.leetcode.com/users/images/ffb87ca4-b84a-48c7-8998-2d0f35422d26_1665416260.8143685.png)\n\n\nTo solve this problem, first of all we check if the length of the string is equal to **1**, if it is, we return an empty string **(" ")**.\nFor convenience, we turn the string into an **array**.\nNow we do a search on the first half of the array (we add \'**~~**\' to remove the fractional part if the number is not paired), since this is a polyndrom, it makes no sense for us to sort through the second part.\nIn case we find a character that is **greater** than \'**a**\', we change it to \'**a**\'. But if the whole string consists **only** of characters equal to \'**a**\', we take the **last** **one** and change it to \'**b**\'.\nAt the end, it remains only to collect the string from the array again.\n\n```\nlet breakPalindrome = function (palindrome) {\n    if (palindrome.length === 1) return \'\';\n    let arr = Array.from(palindrome);\n\n    for (let i = 0; i < ~~(arr.length / 2 ); i++) {\n        if (arr[i] > \'a\') {\n            arr[i] = \'a\';\n            return arr.join(\'\');\n        }\n    }\n    arr[arr.length - 1] = \'b\';\n    return arr.join(\'\');\n};\n```\n\nI hope I was able to explain clearly.\n **Happy coding!** \uD83D\uDE43
['JavaScript']