Efficient Python Trie solution, without traversing all characters (a-z) at each step
\nclass MagicDictionary(object):\n\n    def __init__(self):\n        self.trie = {}\n\n    def buildDict(self, dict):\n        for word in dict: \n            n
```\nclass MagicDictionary(object):\n\n    def __init__(self):\n        self.trie = {}\n\n    def buildDict(self, dict):\n        for word in dict: \n            node = self.trie \n            for letter in word: \n                if letter not in node: \n                    node[letter] = {}\n                node = node[letter] \n            node[None] = None \n\n    def search(self, word):\n        def find(node, i, mistakeAllowed): \n            if i == len(word):\n                if None in node and not mistakeAllowed: \n                    return True\n                return False \n            if word[i] not in node: \n                return any(find(node[letter], i+1, False) for letter in node if letter) if mistakeAllowed else False \n            \n            if mistakeAllowed: \n                return find(node[word[i]], i+1, True) or any(find(node[letter], i+1, False) for letter in node if letter and letter != word[i])\n            return find(node[word[i]], i+1, False)\n            \n        return find(self.trie, 0, True)        \n\n```
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