Super easy Python Solution| Beginner friendly
Code

# Code
```python []
class Solution(object):
    def numberOfPairs(self, num1, num2, k):
        count=0
        for i in range(len(num1)):
            for j in range(len(num2)):
                if num1[i]%(num2[j]*k)==0:
                    count+=1
        return count
```
['Array', 'Hash Table', 'Python']