c++ 0ms easy solution !!!!
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\n/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     TreeNode *left;\n *     TreeNode *right;\n *     TreeNode() : val(0), left(nullptr), right(nullptr) {}\n *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\n    int length(TreeNode* root){\n        if(root==0)return 0;\n        return 1+length(root->left)+length(root->right);\n    }\n    TreeNode* search(TreeNode* root,int x){\n        if(root==0)return 0;\n        if(root->val==x){\n            return root;\n        }\n        auto left=search(root->left,x);\n        auto right=search(root->right,x);\n        if(left)return left;\n        if(right)return right;\n        return 0;\n    }\npublic:\n    bool btreeGameWinningMove(TreeNode* root, int n, int x) {\n        if(root->val==x){\n            if(length(root->left)==length(root->right))\n            return false;\n            else\n            return true;\n        }\n        auto temp=search(root,x);\n        int y=length(temp);\n        int x1=n-y;\n        if(x1>y)return true;\n        int l1=length(temp->left);\n        int l2=length(temp->right);\n        if(x1+1+l1<l2)return true;\n        if(x1+1+l2<l1)return true;\n        return false;\n    }\n};\n```
['C++']