C++ Solution With Explanation ⭐|| Beats 90.23% ✔||  UPVOTE⬆
Approach\n Describe your approach to solving the problem. \n1. ### Skip Blanks:\n\n- Traverse both start and target strings while skipping all blank spaces (_).
# Approach\n<!-- Describe your approach to solving the problem. -->\n1. ### Skip Blanks:\n\n- Traverse both start and target strings while skipping all blank spaces (_).\n- This allows us to focus only on the positions of \'L\' and \'R\'.\n\n2. ### Early Exit Conditions:\n\n- If one string reaches the end before the other, or if the characters at the current positions in start and target don\'t match, then it\u2019s impossible to transform start into target.\n3. ### Movement Rules:\n\n- \'L\' pieces must move left, so the index of \'L\' in start (i) must be greater than or equal to its index in target (j).\n- \'R\' pieces must move right, so the index of \'R\' in start (i) must be less than or equal to its index in target (j).\n\n4. ### Finish Traversal:\n- If both strings are fully traversed and all conditions are satisfied, return ***true***.\n Otherwise, return ***false***.\n\n# Complexity\n- Time complexity:**\uD835\uDC42(\uD835\uDC5B)**,\nEach character in the strings is processed at most once.\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:**O(1)**,\nNo additional data structures are used\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```cpp []\nclass Solution {\npublic:\n    bool canChange(string start, string target) {\n        int n = start.size();\n        int i = 0, j = 0;\n\n        while (i < n || j < n) {\n            // Skip blank spaces in both strings\n            while (i < n && start[i] == \'_\')\n                i++;\n            while (j < n && target[j] == \'_\')\n                j++;\n\n            // Check if both strings have reached the end\n            if (i == n && j == n)\n                return true;\n\n            // Check if one string ends before the other\n            if (i == n || j == n)\n                return false;\n\n            // Check if the characters at the current positions are different\n            if (start[i] != target[j])\n                return false;\n\n            // Check if \'L\' or \'R\' pieces follow the movement rules\n            if (start[i] == \'L\' && i < j)\n                return false;\n            if (start[i] == \'R\' && i > j)\n                return false;\n\n            // Move to the next character\n            i++;\n            j++;\n        }\n        return true;\n    }\n};\n```
['C++']