Simple and easy solution. 100 % working
IntuitionThe problem requires checking whether each row in the matrix remains unchanged after a circular shift of k positions. This suggests a modular arithmeti
# Intuition
The problem requires checking whether each row in the matrix remains unchanged after a circular shift of `k` positions. This suggests a modular arithmetic approach to compare elements at corresponding shifted indices.

# Approach
1. Iterate over each row in the matrix.
2. For each row, iterate through its elements and check if the element at index `i` is equal to the element at index `(i + k) % n`.
3. If any mismatch is found, return `false`; otherwise, return `true` after checking all rows.

# Complexity
- Time complexity:
Since we iterate through all rows and for each row iterate through its elements, the time complexity is $$O(m \cdot n)$$, where `m` is the number of rows and `n` is the number of columns.

- Space complexity:
We use only a few integer variables for indexing, so the space complexity is $$O(1)$$ as no additional data structures are used.

# Code
```dart []
  class Solution {
  bool areSimilar(List<List<int>> mat, int k) {
    for (var row in mat) {
      int n = row.length;
      for (int i = 0; i < n; i++) {
        if (row[i] != row[(i + k) % n]) {
          return false;
        }
      }
    }
    return true;
  }
}
```
['Array', 'Math', 'Matrix', 'Simulation', 'Dart']