One liner solution (Beats 100% , 0ms)
IntuitionIf number is even , divisible by both
else if odd number , then minimum is the double of the odd numberApproachTernary operator used .Complexity

Time
# Intuition
If number is even , divisible by both
else if odd number , then minimum is the double of the odd number 

# Approach
Ternary operator used .

# Complexity
- Time complexity:
O(1)

- Space complexity:
O(1)

# Code
```cpp []
class Solution {
public:
    int smallestEvenMultiple(int n) {
        return (n%2==0)?n:2*n;
    }
};
```
['C++']