✔️ Python Easy Way To Find Level Order Traversal | 96% Faster | Fast and Simple Solution
IF YOU FIND THIS POST HELPFUL PLEASE UPVOTE \uD83D\uDC4D\n\n\nclass Solution:\n    def levelOrder(self, root: Optional[TreeNode]) -> List[List[int]]:\n        i
**IF YOU FIND THIS POST HELPFUL PLEASE UPVOTE \uD83D\uDC4D**\n\n```\nclass Solution:\n    def levelOrder(self, root: Optional[TreeNode]) -> List[List[int]]:\n        if not root:\n            return []\n        \n        queue = [root]\n        next_queue = []\n        level = []\n        result = []\n        \n        while queue:\n            for root in queue:\n                level.append(root.val)\n                if root.left:\n                    next_queue.append(root.left)\n                if root.right:\n                    next_queue.append(root.right)\n            result.append(level)\n            level = []\n            queue = next_queue\n            next_queue = []\n        \n        return result\n```\n**Visit this blog to learn Python tips and techniques and to find a Leetcode solution with an explanation:  https://www.python-techs.com/**
['Queue', 'Binary Tree', 'Python', 'Python3']