🔥 1 LINE Solution🔥
Approach\nMaking list of lists were list[i]=[diagonal_len,  area_size] and then sorting it with lamda.\n\n\u2B07\uFE0FUpvote please\n# Code for easy anderstandi
# Approach\nMaking list of lists were list[i]=[diagonal_len,  area_size] and then sorting it with lamda.\n\n**\u2B07\uFE0FUpvote please**\n# Code for easy anderstanding\n```python3 []\nclass Solution:\n    def areaOfMaxDiagonal(self, dimensions: List[List[int]]) -> int:\n        x = [[sqrt(i[0] ** 2 + i[1] ** 2), i[0]*i[1]] for i in dimensions]\n        x = sorted(x, key=lambda x : (x[0], x[1]), reverse=True)\n        return x[0][1]\n```\n# 1 LINE Code\n```\nclass Solution:\n    def areaOfMaxDiagonal(self, dimensions: List[List[int]]) -> int:\n        return sorted([[sqrt(i[0] ** 2 + i[1] ** 2), i[0]*i[1]] for i in dimensions], key=lambda x : (x[0], x[1]), reverse=True)[0][1]\n```
['Python3']