Simple Solution || Why Overcomplicate
IntuitionWe need to find valid email addresses based on certain criteria:
Exactly one @ symbol.
Ends with .com.
The part before the @ symbol contains only alpha
# Intuition
We need to find valid email addresses based on certain criteria:

1. Exactly one @ symbol.
2. Ends with .com.
3. The part before the @ symbol contains only alphanumeric characters and underscores.
4. The domain part (between @ and .com) contains only letters.
# Approach
1. Use REGEXP: To match the email pattern using regular expressions.
^[a-zA-Z0-9_]+@[a-zA-Z]+\.com$ ensures the local part has only alphanumeric characters and underscores, the domain has only letters, and it ends with .com.
2. Return valid emails and order by user_id.


# Code
```mysql []
# Write your MySQL query statement below
SELECT *
FROM Users
WHERE REGEXP_LIKE(email, '^[a-zA-Z0-9_]+@[a-zA-Z]+\.com)
```
# PLEASE UPVOTE FOR MORE SUCH SOLUTIONS...
['MySQL']