full commented solution py3
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution:\n    def maxNumber(self, nums1: List[int], nums2: List[int], k: int) -> List[int]:\n        # Define a method to get the maximum subsequence of length k from the given nums\n        def get_max_subseq(nums, k):\n            stack = []\n            for i, num in enumerate(nums):\n                # While the stack is not empty, and removing elements from it\n                # can create a larger subsequence, pop elements from the stack\n                while stack and len(nums) - i + len(stack) > k and stack[-1] < num:\n                    stack.pop()\n                # If the stack has fewer than k elements, or it can still accommodate more elements, append num to the stack\n                if len(stack) < k:\n                    stack.append(num)\n            return stack\n\n        # Define a method to merge two lists into one, preserving the order to get the maximum number\n        def merge(nums1, nums2):\n            merged = []\n            i, j = 0, 0\n            # Iterate through both lists, comparing elements and appending the larger one to the merged list\n            while i < len(nums1) or j < len(nums2):\n                if i >= len(nums1):\n                    merged.append(nums2[j])\n                    j += 1\n                elif j >= len(nums2):\n                    merged.append(nums1[i])\n                    i += 1\n                elif nums1[i:] > nums2[j:]:\n                    merged.append(nums1[i])\n                    i += 1\n                else:\n                    merged.append(nums2[j])\n                    j += 1\n            return merged\n\n        ans = []\n        # Iterate through possible lengths of the subsequence from nums1\n        for i in range(max(0, k - len(nums2)), min(len(nums1), k) + 1):\n            j = k - i\n            # Get the maximum subsequence of length i from nums1 and length j from nums2\n            subseq1 = get_max_subseq(nums1, i)\n            subseq2 = get_max_subseq(nums2, j)\n            # Merge the two subsequences to get a single maximum subsequence\n            merged = merge(subseq1, subseq2)\n            # Keep track of the maximum subsequence seen so far\n            ans = max(ans, merged)\n        # Return the final maximum subsequence\n        return ans\n\n```
['Python3']