Python Best Solution
Intuition\n\nThe intuition for this problem is to check if it\'s possible to make two given strings equal by performing swaps on characters at indices with a di
# Intuition\n\nThe intuition for this problem is to check if it\'s possible to make two given strings equal by performing swaps on characters at indices with a difference of 2. To achieve this, you can try all possible swaps and check if any of them result in equal strings.\n\n# Approach\n\n- Iterate through all possible pairs of indices i and j with a difference of 2, where j is calculated as (i + 2) % len(s1).\n\n- Convert s1 to a list of characters so that you can perform swaps. This is necessary because strings are immutable in Python.\n\n- Swap the characters at indices i and j within the list.\n\n- Convert the list back to a string.\n\n- Check if the modified s1 is equal to s2. If they are equal, return True, indicating that the strings can be made equal using the swaps.\n\n- If none of the swaps result in equal strings, return False.\n\n# Complexity\n- Time complexity:: The code iterates through all possible swaps, which is a constant number of swaps (4 in this case, as the problem specifies strings of length 4). Thus, the time complexity is O(1), constant time.\n\n- Space complexity: The code uses additional space to store the modified s1 as a list of characters, which has a space complexity of O(N), where N is the length of the string. However, this additional space usage is temporary, and the list is converted back to a string. Therefore, the overall space complexity is O(N), but it doesn\'t depend on the input size in a significant way since N is small (4 in this problem).\n\n# Code\n```\nclass Solution:\n    def canBeEqual(self, s1: str, s2: str) -> bool:\n        for i in range(len(s1)):\n            j = (i + 2) % len(s1)\n            s1 = list(s1)  # Convert string to list to perform the swap\n            s1[i], s1[j] = s1[j], s1[i]  # Swap characters at indices i and j\n            s1 = "".join(s1)  # Convert the list back to a string\n            if s1 == s2:\n                return True\n        return False\n\n```
['Python3']