EASY PYTHON SOLUTION
Optimized Python SolutionExplanation✅Uses set operations for efficiency
set1 - set2gives elements innums1but not innums2.
set2 - set1gives elements innums2but n
### **Optimized Python Solution**
```python
class Solution(object):
    def findDifference(self, nums1, nums2):
        set1, set2 = set(nums1), set(nums2)  # Convert lists to sets for O(1) lookups
        return [list(set1 - set2), list(set2 - set1)]  # Compute differences and convert back to lists
```

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### **Explanation**
✅ **Uses set operations for efficiency**  
- `set1 - set2` gives elements in `nums1` but not in `nums2`.  
- `set2 - set1` gives elements in `nums2` but not in `nums1`.  

✅ **Time Complexity: `O(n + m)`**  
- `set()` conversion takes `O(n)` and `O(m)`.  
- Subtraction (`set1 - set2`) takes `O(min(n, m))`.  
- Overall, this is highly efficient.  

✅ **Space Complexity: `O(n + m)`**  
- Stores unique elements in sets.

This is the most optimized solution! 🚀

![b108d001-cf15-4ff7-847d-0497b3becd90.webp](https://assets.leetcode.com/users/images/e3987950-94a4-467e-a4aa-34745b3b456b_1740289231.9390483.webp)

['Python']