Very Very Easy Solution
Intuition\nThe problem involves replacing zeros in two arrays nums1 and nums2 with positive integers such that the sums of the two arrays become equal. To achie
# Intuition\nThe problem involves replacing zeros in two arrays nums1 and nums2 with positive integers such that the sums of the two arrays become equal. To achieve this, we need to consider the initial sums of the arrays and the count of zeros in each array. Depending on these values, we can determine if it\'s possible to make the sums equal and what the minimum equal sum would be.\n\n# Approach\n1. Calculate Initial Sums and Zero Counts:\n\n2. Iterate through nums1 and nums2 to calculate their initial sums (sum1 and sum2) and count the number of zeros in each array (cnt1 and cnt2).\nCheck Trivial Cases:\n\n3. If the initial sums and the number of zeros are already equal, return sum1 + cnt1 (or sum2 + cnt2).\nIf sum1 + cnt1 (maximum possible sum for nums1 by replacing all zeros with ones) is still less than sum2, or vice versa, return -1 as it is impossible to make the sums equal.\nDetermine Minimum Equal Sum:\n\n4. If the sums can be made equal by replacing zeros appropriately, return the corresponding sum.\n\n# Complexity\n- Time complexity:\nO(n)\n\n- Space complexity:\nO(1)\n\n# Code\n```\nclass Solution {\npublic:\n    long long minSum(vector<int>& nums1, vector<int>& nums2) {\n        long long sum1 = 0, sum2 = 0;\n        long long cnt1 = 0, cnt2 = 0;\n        for(auto i : nums1)\n        {\n            sum1 += i;\n            if(i == 0) cnt1++;\n        }\n        for(auto i : nums2)\n        {\n            sum2 += i;\n            if(i == 0) cnt2++;\n        }\n\n        if(sum1 == sum2 && cnt1 == cnt2) return sum1 + cnt1;\n        if(sum1 + cnt1 > sum2 && cnt2 == 0) return -1;\n        if(sum1 < sum2 + cnt2 && cnt1 == 0) return -1;\n        long long ans = 0;\n        if(sum1 == sum2)\n        {\n            ans = sum1 + max(cnt1,cnt2);\n        }\n        else if((sum1 + cnt1) == (sum2 + cnt2))\n        {\n            ans = sum1 + cnt1;\n        }\n        else if(sum1 + cnt1 > sum2 + cnt2)\n        {\n            ans = sum1 + cnt1;\n        }\n        else if(sum1 + cnt1 < sum2 + cnt2)\n        {\n            ans = sum2 + cnt2;\n        }\n        else\n        {\n            ans = max(sum1,sum2) + max(cnt1,cnt2);\n        }\n        \n        return ans;\n    }\n};\n```
['C++']