✨🚀 Effortlessly 💯 Dominate 100% with Beginner C++ , Java and Python Solution! 🚀✨
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```C++ []\nclass Solution {\npublic:\n    int winningPlayerCount(int n, vector<vector<int>>& pick) {\n        // Create a vector of unordered maps to keep track of picks for each player\n        vector<unordered_map<int, int>> vec(n);\n        // Populate the vector with the pick data\n        for (auto p : pick) {\n            vec[p[0]][p[1]]++; // Increment the count for the pick by player p[0] for number p[1]\n        }\n        int x = 0; // Initialize the count of winning players\n        // Iterate through each player\n        for (int i = 0; i < n; ++i) {\n            // Check each picked number for the current player\n            for (auto k : vec[i]) {\n                // If the count of picks for a number is greater than the player\'s index, they are a winning player\n                if (k.second > i) {\n                    x++; // Increment the count of winning players\n                    break; // Exit the loop as we found the player is winning\n                }\n            }\n        }\n        return x; // Return the total count of winning players\n    }\n};\n```\n```Java []\nclass Solution {\n    public int winningPlayerCount(int n, int[][] pick) {\n        // Create a list of HashMaps to keep track of picks for each player\n        List<Map<Integer, Integer>> vec = new ArrayList<>(n);\n        for (int i = 0; i < n; i++) {\n            vec.add(new HashMap<>());\n        }\n        // Populate the list with the pick data\n        for (int[] p : pick) {\n            vec.get(p[0]).put(p[1], vec.get(p[0]).getOrDefault(p[1], 0) + 1);\n        }\n        int x = 0; // Initialize the count of winning players\n        // Iterate through each player\n        for (int i = 0; i < n; ++i) {\n            // Check each picked number for the current player\n            for (Map.Entry<Integer, Integer> entry : vec.get(i).entrySet()) {\n                // If the count of picks for a number is greater than the player\'s index, they are a winning player\n                if (entry.getValue() > i) {\n                    x++; // Increment the count of winning players\n                    break; // Exit the loop as we found the player is winning\n                }\n            }\n        }\n        return x; // Return the total count of winning players\n    }\n}\n```\n```Python []\nclass Solution:\n    def winningPlayerCount(self, n: int, pick: List[List[int]]) -> int:\n        # Create a list of dictionaries to keep track of picks for each player\n        vec = [defaultdict(int) for _ in range(n)]\n        # Populate the list with the pick data\n        for p in pick:\n            vec[p[0]][p[1]] += 1\n        x = 0 # Initialize the count of winning players\n        # Iterate through each player\n        for i in range(n):\n            # Check each picked number for the current player\n            for k, v in vec[i].items():\n                # If the count of picks for a number is greater than the player\'s index, they are a winning player\n                if v > i:\n                    x += 1 # Increment the count of winning players\n                    break # Exit the loop as we found the player is winning\n        return x # Return the total count of winning players\n```\n
['C++', 'Java', 'Python3']