Simple Java Solution 💡
Intuition\n\nThe provided Java function findTheArrayConcVal aims to calculate the concatenation value of an array of integers. The concatenation value is obtain
# Intuition\n\nThe provided Java function findTheArrayConcVal aims to calculate the concatenation value of an array of integers. The concatenation value is obtained by concatenating each pair of integers from the array, where the integers are taken alternately from the beginning and end of the array.\n\n# Approach\n\n1. Initialization:\n\n- Initialize two pointers left and right at the beginning and end of the array, respectively.\n- Initialize a variable total to store the cumulative concatenation value.\n2. Loop:\n\n- Iterate through the array while left pointer is less than right.\nFor each iteration, concatenate the integers at positions left and right.\n- Increment left and decrement right to move towards the center of the array.\n3. Handling Odd Length Array:\n\n- If the length of the array is odd, there will be one element left at the center after the loop ends. Add this element to the total.\n4. Return Concatenation Value: Return the total concatenation value.\n\n# Complexity\n**Time complexity**:\n\n- The loop iterates through half of the array\'s length, so it performs O(n/2) concatenations, where n is the length of the input array.\n- Additionally, converting integers to strings and parsing them back to long integers has a time complexity proportional to the number of digits in the integers, but it doesn\'t significantly affect the overall time complexity.\n- Therefore, the time complexity is O(n) where n is the length of the input array.\n\n**Space complexity**:\n\n- The function uses a constant amount of extra space for variables (left, right, total, conVal), regardless of the size of the input array.\n- Therefore, the space complexity is O(1), constant space complexity.\n\n# Code\n```\nclass Solution {\n    public long findTheArrayConcVal(int[] nums) {\n        int left = 0;\n        int right = nums.length - 1;\n        long total = 0;\n        while(left < right){\n            String conVal = String.valueOf(nums[left]) + String.valueOf(nums[right]);\n            total += Long.parseLong(conVal);\n            left++;\n            right--;\n        }\n        return (nums.length % 2 == 0) ? total : total + Long.valueOf(nums[left]);\n    }\n}\n```
['Java']