esay solution in three languages
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```javascript []\n\nvar countSeniors = function(details) {\n    let count=0;\n   for(let i=0;i<details.length;i++){\n        if(details[i][11]>=6 && details[i][12]>=0){\n            if(details[i][11]==6 && details[i][12]==0){\n                continue;\n            }\n            count++;\n        }\n   }\n   return count;\n};\n```\n```python []\n\nclass Solution(object):\n    def countSeniors(self, details):\n        count =int(0)\n        for i in range(len(details)) :\n            if details[i][11]>=\'6\' and details[i][12]>=\'0\' :\n                if details[i][11]==\'6\' and details[i][12]==\'0\' :\n                    continue\n                count = count+1\n        return count\n```\n``` c []\n    int countSeniors(char ** details, int detailsSize){\n    int count=0;\n     for(int i=0;i<detailsSize;i++){\n        if(details[i][11]>=\'6\' && details[i][12]>=\'0\'){\n            if(details[i][11]==\'6\' && details[i][12]==\'0\'){\n                continue;\n            }\n            count++;\n        }\n   }\n   return count;\n}\n\n```\n
['C', 'Python3', 'JavaScript']