Simple and clean java solution
\n\tpublic String kthLargestNumber(String[] nums, int k) {\n\t\t   Arrays.sort(nums, (left, right) -> {\n\t\t\t  if (left.length() != right.length())\n\t\t\t\t 
\n\tpublic String kthLargestNumber(String[] nums, int k) {\n\t\t   Arrays.sort(nums, (left, right) -> {\n\t\t\t  if (left.length() != right.length())\n\t\t\t\t  return left.length() - right.length();\n\t\t\t  return left.compareTo(right);\n\t\t  });\n\t\t\treturn nums[nums.length - k];\n\t\t}
['Java']