This is very easy solution in python
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution:\n    def areaOfMaxDiagonal(self, dimensions: List[List[int]]) -> int:\n        max_diagonal=0\n        max_area=0\n        for length,width in dimensions:\n            diagonal=math.sqrt(length**2+width**2)\n            area=length*width\n\n            if diagonal>max_diagonal:\n                max_area=area\n                max_diagonal=diagonal\n            if diagonal==max_diagonal:\n                max_area=max(max_area,area)\n        return max_area\n\n```
['Python3']