Swift (Low Acceptance)
\n# Approach\n1. Update nums array: For each query, update the nums array at the specified position with the new value.\n2. Calculate maximum sum of a subsequen
\n# Approach\n1. Update nums array: For each query, update the nums array at the specified position with the new value.\n2. Calculate maximum sum of a subsequence with no adjacent elements:\n- Use two variables, incl and excl, to keep track of the maximum sum including and excluding the current element, respectively.\n- Iterate through the nums array, updating incl and excl based on whether the current element is included or excluded.\n- The maximum sum at each step is the maximum of incl and excl.\n3. Sum the results of all queries: Sum the results of each query, taking the modulus 10^9 + 7 to prevent overflow.\n\n# Complexity\nThis approach ensures that we efficiently handle each query and calculate the maximum sum of a subsequence with no adjacent elements using dynamic programming, resulting in an overall time complexity of O(n*m), where n is the length of nums and m is the number of queries.\n\n# Code\n```\nclass Solution {\n    func maximumSumSubsequence(_ nums: [Int], _ queries: [[Int]]) -> Int {\n        let MOD = 1_000_000_007\n        var nums = nums\n        var result = 0\n\n        for query in queries {\n            let pos = query[0]\n            let value = query[1]\n            nums[pos] = value\n            \n            result = (result + maxSumNoAdjacent(nums)) % MOD\n        }\n\n        return result\n    }\n    \n    private func maxSumNoAdjacent(_ nums: [Int]) -> Int {\n        var incl = 0\n        var excl = 0\n\n        for num in nums {\n            let newExcl = max(incl, excl)\n            incl = excl + num\n            excl = newExcl\n        }\n\n        return max(incl, excl)\n    }\n}\n\n```
['Swift']