Python🔥Java🔥C++🔥Simple Solution🔥Easy to Understand
!! BIG ANNOUNCEMENT !!\nI am currently Giving away my premium content well-structured assignments and study materials to clear interviews at top companies relat
# !! BIG ANNOUNCEMENT !!\nI am currently Giving away my premium content well-structured assignments and study materials to clear interviews at top companies related to computer science and data science to my current Subscribers. This is only for the first 10,000 Subscribers. **DON\'T FORGET** to Subscribe.\n\n# Search \uD83D\uDC49 `Tech Wired Leetcode` to Subscribe\n\n# Video Solution\n\n# Search \uD83D\uDC49 `Minimum Flips to Make a OR b Equal to c By Tech Wired` \n\n# or\n\n# Click the Link in my Profile\n\nHappy Learning, Cheers Guys \uD83D\uDE0A\n\n```Python []\nclass Solution:\n    def minFlips(self, a: int, b: int, c: int) -> int:\n        flips = 0\n        while a > 0 or b > 0 or c > 0:\n            bit_a = a & 1\n            bit_b = b & 1\n            bit_c = c & 1\n\n            if bit_c == 0:\n                flips += (bit_a + bit_b)  \n            else:\n                if bit_a == 0 and bit_b == 0:\n                    flips += 1  \n\n            a >>= 1\n            b >>= 1\n            c >>= 1\n\n        return flips\n\n```\n```Java []\nclass Solution {\n    public int minFlips(int a, int b, int c) {\n        int flips = 0;\n        while (a > 0 || b > 0 || c > 0) {\n            int bitA = a & 1;\n            int bitB = b & 1;\n            int bitC = c & 1;\n\n            if (bitC == 0) {\n                flips += (bitA + bitB); \n            } else {\n                if (bitA == 0 && bitB == 0) {\n                    flips += 1; \n                }\n            }\n\n            a >>= 1;\n            b >>= 1;\n            c >>= 1;\n        }\n\n        return flips;\n    }\n}\n\n```\n```C++ []\nclass Solution {\npublic:\n    int minFlips(int a, int b, int c) {\n        int flips = 0;\n        while (a > 0 || b > 0 || c > 0) {\n            int bitA = a & 1;\n            int bitB = b & 1;\n            int bitC = c & 1;\n\n            if (bitC == 0) {\n                flips += (bitA + bitB); \n            } else {\n                if (bitA == 0 && bitB == 0) {\n                    flips += 1; \n                }\n            }\n\n            a >>= 1;\n            b >>= 1;\n            c >>= 1;\n        }\n\n        return flips;\n    }\n};\n\n```\n# An Upvote will be encouraging \uD83D\uDC4D
['Bit Manipulation', 'C++', 'Java', 'Python3']