Good Question Bad Description 
IntuitionThe question asks you to connect two trees by adding a single edge between a node from the first tree and a node from the second tree. After the connec
# Intuition
The question asks you to connect two trees by adding a single edge between a node from the first tree and a node from the second tree. After the connection, you need to determine the maximum number of nodes that can be reached from a specific node in the first tree within a distance of k edges. The goal is to maximize this count for each node in the first tree.

# About the k-1 logic in the code
When you connect a node u in the first tree to a node  v in the second tree, the edge between u and  v consumes one distance unit. Hence for the second tree only nodes within k−1 distance from 𝑣 v can be considered.

# Code
```cpp []
class Solution {
    int numberofnodes(unordered_map<int, vector<int>>& graph, int node, int k) {
        if(k == 0) return 1;

        queue<pair<int, int>> q;
        q.push({node, 0});
        vector<bool> visited(graph.size(), false);
        int count = 1;

        while (!q.empty()) {
            auto node = q.front();
            q.pop();
            int curr = node.first;
            int dist = node.second;
            visited[curr] = true;
            for (auto& neighbor : graph[curr]) {
                if (!visited[neighbor]) {
                    if(dist + 1 <= k) {
                        count++;
                        q.push({neighbor, dist + 1});
                    }
                }
            }
        }

        return count;
        
    }
public:
    vector<int> maxTargetNodes(vector<vector<int>>& edges1, vector<vector<int>>& edges2, int k) {
        unordered_map<int, vector<int>> graph1, graph2;
        for (auto& edge : edges1) {
            graph1[edge[0]].push_back(edge[1]);
            graph1[edge[1]].push_back(edge[0]);
        }
        for (auto& edge : edges2) {
            graph2[edge[0]].push_back(edge[1]);
            graph2[edge[1]].push_back(edge[0]);
        }

        vector<int> ans1;
        for (int i = 0; i < graph1.size(); i++) {
            ans1.push_back(numberofnodes(graph1, i, k));
            // cout << ans1[i] << " ";
        }

        if(k == 0) {
            return ans1; // GG testcase 724
        }



        int ans2 = 1;
        for (int i = 0; i < graph2.size(); i++) {
            ans2 = max(ans2, numberofnodes(graph2, i, k-1));


        }

        // cout << ans2 << endl;

        for(int i = 0; i < ans1.size(); i++) {
            ans1[i] =ans1[i]+ ans2;
        }

        return ans1;


        
    }
};
```
['C++']