C++    | Using Simple LOOP |
Intuition\n Describe your first thoughts on how to solve this problem. The intuition behind this program is to compare the binary representation of \'a\' and \'
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->The intuition behind this program is to compare the binary representation of \'a\' and \'b\' with the binary representation of \'c\' bit by bit. By performing a bitwise OR operation between \'a\' and \'b\', we can obtain a value that represents the combination of all the corresponding bits in \'a\' and \'b\'. Then, by comparing this value with the corresponding bits in \'c\', we can identify the positions where a bit flip is required.\n\nThe program first converts \'a\', \'b\', and \'c\' to their binary representations using the helper function "decToBinary". This allows us to store the individual bits of each integer in separate arrays.\n\nNext, the program iterates over each bit position (from 0 to 31) in the arrays \'x\', \'y\', and \'z\'. For each position, it calculates the bitwise OR of the corresponding bits in \'x\' and \'y\' and stores the result in the variable \'a_or_b\'. This represents the combined value of \'a\' and \'b\' at that bit position.\n\nThe program then compares \'a_or_b\' with the corresponding bit in \'z\'. If they are not equal, it means a bit flip is required to match the desired result in \'z\'. The program handles two cases:\n\nIf \'a_or_b\' is 1 and \'z\' is 0, it means both \'a\' and \'b\' need to be flipped to 0. In this case, the program checks if both \'x\' and \'y\' are already 1. If they are, it requires two flips (\'s += 2\'). Otherwise, only one flip is needed (\'s++\').\n\nIf \'z\' is not as expected (either 0 or 1), it requires a single flip (\'s++\').\n\nFinally, the program returns the value of \'s\', which represents the minimum number of flips needed to convert \'a\' and \'b\' to \'c\' based on the described rules.\n\nIn summary, the program compares the binary representations of \'a\' and \'b\' with \'c\' bit by bit, identifying the positions where bit flips are required and calculating the minimum number of flips needed to transform \'a\' and \'b\' into \'c\'.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->The approach used in this program involves converting the given integers \'a\', \'b\', and \'c\' into their binary representations. By comparing the bits at each position, the program identifies the positions where a bit flip is required to transform \'a\' and \'b\' into \'c\'.\n\nThe program starts by initializing three arrays, \'x\', \'y\', and \'z\', each of size 32, with zeros. These arrays will be used to store the binary representation of \'a\', \'b\', and \'c\', respectively.\n\nTo convert an integer to its binary representation, the program uses the helper function "decToBinary". This function uses a while loop to perform repeated division by 2 and stores the remainder (0 or 1) in the \'binaryNum\' array. The loop continues until the integer becomes zero. As a result, the \'binaryNum\' array will contain the binary representation of the integer in reverse order.\n\nAfter converting \'a\', \'b\', and \'c\' to their binary representations using the "decToBinary" function, the program proceeds to iterate over each bit position (from 0 to 31) in the arrays \'x\', \'y\', and \'z\'.\n\nFor each position, the program calculates the bitwise OR of the corresponding bits in \'x\' and \'y\' and stores the result in the variable \'a_or_b\'. This represents the combined value of \'a\' and \'b\' at that bit position.\n\nThe program then compares \'a_or_b\' with the corresponding bit in \'z\'. If they are not equal, it means a bit flip is required to match the desired result in \'z\'. The program handles two cases:\n\nIf \'a_or_b\' is 1 and \'z\' is 0, it means both \'a\' and \'b\' need to be flipped to 0. In this case, the program checks if both \'x\' and \'y\' are already 1. If they are, it requires two flips (\'s += 2\'). Otherwise, only one flip is needed (\'s++\').\n\nIf \'z\' is not as expected (either 0 or 1), it requires a single flip (\'s++\').\n\nFinally, the program returns the value of \'s\', which represents the minimum number of flips needed to convert \'a\' and \'b\' to \'c\' based on the described rules.\n\nIn summary, the approach involves converting the integers to their binary representations, comparing the bits at each position, and calculating the minimum number of flips required to transform \'a\' and \'b\' into \'c\'.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->0(1)\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->0(1)\n\n# Code\n```\nclass Solution {\npublic:\n    void decToBinary(int n,int binaryNum[])\n    {\n    int i = 0;\n    while (n > 0)\n    {\n        binaryNum[i] = n % 2;\n        n = n / 2;\n        i++;\n    }\n}\n    int minFlips(int a, int b, int c)\n     {\n        int x[32]={0};\n        int y[32]={0};\n        int z[32]={0};\n        decToBinary(a,x);\n        decToBinary(b,y);\n        decToBinary(c,z);\n        int i,j,k,s=0,m=0;\n        for(i=0;i<32;i++)\n        {\n            int a_or_b=x[i]|y[i];\n            if(a_or_b !=z[i])\n            {\n                if(a_or_b==1 and z[i]==0)\n                {\n                    if(x[i]==1 and y[i]==1)\n                    s+=2;\n                    else\n                    s++;\n                }\n                else\n                {\n                    s++;\n                }\n            }\n        }\n        return s;\n    }\n};\n\n//Must Upvote
['C++']