4 liner, hash map solution
\ncount = {}\nfor i in logs:\n      for v in range(i[0],i[1]):\n        count[v] = count.get(v,0) + 1\n m = max(count.values())\n return min([i for i in count i
```\ncount = {}\nfor i in logs:\n      for v in range(i[0],i[1]):\n        count[v] = count.get(v,0) + 1\n m = max(count.values())\n return min([i for i in count if count[i] == m])\n```
['Python', 'Python3']