✅EASY MYSQL SOLUTION
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n![upv.png](https://assets.leetcode.com/users/images/6f04b65a-c706-49bc-aa90-e6f9c159e1c9_1724403332.8336077.png)\n\n```mysql []\n# Write your MySQL query statement below\nselect sell_date, count( DISTINCT product ) as num_sold ,\nGROUP_CONCAT( DISTINCT product order by product ASC separator \',\' ) as products\nFROM Activities GROUP BY sell_date order by sell_date ASC;\n```
['MySQL']