Python One Line Solution 🐍🔧 (watch to learn smth new)
Approach

Equality Check:

At first we check if s1 is equal to s2.
If they are already the same, it returns True immediately since no swap is needed.



Collect
# Approach
1. **Equality Check:**  
   - At first we check if `s1` is equal to `s2`.  
   - If they are already the same, it returns `True` immediately since no swap is needed.

2. **Collecting Different Indices:**  
   - If the strings differ, a list comprehension (`[i for i in range(len(s1)) if s1[i] != s2[i]]`) is used to collect all indices where `s1` and `s2` have different characters.

3. **Validating the Swap with a Lambda Function:**  
   - A lambda function is applied to the list of differing indices (stored in variable `d`).
   - It checks two conditions:
     - That there are exactly two indices where the strings differ (`len(d) == 2`).
     - That swapping the characters at these indices in `s1` would make it equal to `s2` (i.e., `s1[d[0]] == s2[d[1]]` and `s1[d[1]] == s2[d[0]]`).



# Code
```python3 []
class Solution:
    def areAlmostEqual(self, s1: str, s2: str) -> bool:
        return s1 == s2 or (lambda d: len(d) == 2 and s1[d[0]] == s2[d[1]] and s1[d[1]] == s2[d[0]])([i for i in range(len(s1)) if s1[i] != s2[i]])

```
['Python3']