Solution Using MySQL GROUP BY and HAVING
\nSELECT ACTOR_ID, DIRECTOR_ID\nFROM ActorDirector\nGROUP BY actor_id, director_id\nHAVING COUNT(*) > 2\n
```\nSELECT ACTOR_ID, DIRECTOR_ID\nFROM ActorDirector\nGROUP BY actor_id, director_id\nHAVING COUNT(*) > 2\n```
[]