189: Solution step by step explanation
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n1. The first step is to calculate the number of steps we actually need to
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n1. The first step is to calculate the number of steps we actually need to take. Since rotating the array by its length has no effect, we can use the modulo operator to reduce the number of steps to be less than the length of the array.\n2. The second step is to reverse the entire array. This has the effect of moving the last k elements to the beginning of the array.\n3. The third step is to reverse the first k elements. This moves them to the end of the array, while leaving the remaining elements in place.\n4. The fourth and final step is to reverse the remaining elements. This moves them to the beginning of the array, completing the rotation.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution:\n    def rotate(self, nums: List[int], k: int) -> None:\n        # Calculate the number of steps we actually need to take\n        k = k % len(nums)\n    \n        # Reverse the entire array\n        nums.reverse()\n    \n        # Reverse the first k elements\n        nums[:k] = reversed(nums[:k])\n    \n        # Reverse the remaining elements\n        nums[k:] = reversed(nums[k:])\n\n```
['Array', 'Math', 'Two Pointers', 'Python', 'Python3']