Python easy solution!
Intuition\nThe goal is to modify the string s to create the lexicographically smallest string possible by decrementing the characters until reaching the first \
# Intuition\nThe goal is to modify the string s to create the lexicographically smallest string possible by decrementing the characters until reaching the first \'a\', while skipping consecutive \'a\'s. If no change can be made, and the string ends with \'a\', convert the last \'a\' to \'z\'.\n\n# Approach\nIteration through the string: We loop through the string and decrement characters until we hit an \'a\'. For the first \'a\' or consecutive \'a\'s, we avoid modification.\nStopping condition: As soon as we reach an \'a\', we stop modifying further characters since further changes would increase the lexicographic order of the string.\nHandling edge case: If the modified string is the same as the original and the last character is \'a\', we change the last character to \'z\' to ensure a smaller lexicographic order.\nFinal return: If no modification happened, return an empty string; otherwise, return the modified string.\n# Complexity\nTime complexity: O(n), where n is the length of the string s. We iterate through the string once.\nSpace complexity: O(n), for storing the list s_list which is a mutable version of the input string.\n\n# Code\n```python3 []\nclass Solution:\n    def smallestString(self, s: str) -> str:\n        s_list = list(s)\n        for i in range(len(s_list)):\n            if i != 0 and s[i] == "a" and s[i - 1] == "a":\n                continue\n            \n            if i == 0 and s[i] == "a":\n                continue\n\n            if s[i] == "a":\n                break\n            s_list[i] = chr(ord(s[i]) - 1)\n        answer = "".join(s_list)\n        if answer == s and answer[-1] == "a":\n            s_list[-1] = "z"\n            answer = "".join(s_list)\n        return "" if answer == s else answer\n            \n\n        \n```
['Python3']