[Python3] Brute Force
\nclass Solution:\n    def countConsistentStrings(self, allowed: str, words: List[str]) -> int:\n        count = 0\n        for i in words:\n            f = Tru
```\nclass Solution:\n    def countConsistentStrings(self, allowed: str, words: List[str]) -> int:\n        count = 0\n        for i in words:\n            f = True\n            for j in set(i):\n                if(j not in allowed):\n                    f = False\n                    break\n                    \n            if(f):\n                count += 1\n        \n        return count\n```
['Python3']