✅ Explained - Simple and Clear Python3 Code✅
The solution utilizes a recursive approach to construct a binary tree from its inorder and postorder traversals. The process begins by selecting the last elemen
The solution utilizes a recursive approach to construct a binary tree from its inorder and postorder traversals. The process begins by selecting the last element of the postorder list as the root value. By finding the index of this root value in the inorder list, we can determine the elements on the left and right sides, representing the left and right subtrees, respectively. Recursively, the right subtree is built first by passing the appropriate partitions of the inorder and postorder lists. Next, the left subtree is constructed in a similar manner. The resulting subtrees are then assigned to the root node accordingly. This process continues until the entire binary tree is constructed, and the root node is returned as the final result.\n\n\n\n\n# Code\n```\nclass Solution:\n    def buildTree(self, inorder: List[int], postorder: List[int]) -> Optional[TreeNode]:\n        def build_tree(inorder, postorder):\n            if not inorder:\n                return None\n            root_val = postorder.pop()\n            root = TreeNode(root_val)\n            index = inorder.index(root_val)\n            root.right = build_tree(inorder[index + 1:], postorder)\n            root.left = build_tree(inorder[:index], postorder)\n            return root\n\n        return build_tree(inorder, postorder)\n\n```
['Python3']