[Java] Clean code with comments and very Easy to understand
IntuitionThe basic idea is to:1 - Calculate the number of 1s in the array. This will be the size of our sliding window.
2 - Slide a window of this size through
# Intuition
The basic idea is to:

1 - Calculate the number of 1s in the array. This will be the size of our sliding window.
2 - Slide a window of this size through the array with Circluar Approach, counting the number of 0s inside the window.
3 - The minimum number of 0s encountered in any window will give us the minimum swaps required.

# Approach
1 - Count the number of 1s.
2 - Count zeros in the initial window
3 - Slide the window with circular Approach
4 - Track the minimum zeros
5 - Return the result

# Complexity
- Time complexity:
O(n)

- Space complexity:
O(1)

# Code
```java []
class Solution {
    public int minSwaps(int[] data) {
        int windowSize = 0;
        int minSwaps = Integer.MAX_VALUE;
        int zerosInWindow = 0;
        int n = data.length;
        // Step 1: Calculate the number of 1's in the array, which will be the window size
        for(int i = 0; i < n; i++){
            if(data[i] == 1){
                windowSize++;  
            }
        }
        // Step 2: Count the number of zeros in the initial window (first `windowSize` elements)
        for(int i = 0; i < windowSize; i++){
            if(data[i] == 0){
                zerosInWindow++;
            }
        }
        minSwaps = Math.min(minSwaps, zerosInWindow);
        // Step 3: Slide the window through the array in circular Way
        for(int i = windowSize; i < n + windowSize - 1; i++){
            // Add the new element coming into the window with circular logic
            if(data[i % n] == 0){
                zerosInWindow++;
            }
            // Remove the element that is sliding out of the window
            if(data[i - windowSize] == 0){
                zerosInWindow--;  // If it's zero, decrement the zeros count
            }
            // Update the minimum number of zeros found in the window
            minSwaps = Math.min(minSwaps, zerosInWindow);
        }
        return minSwaps;
    }
}
```
['Java']