MySQL Solution for Nth Highest Salary Problem
Intuition\n Describe your first thoughts on how to solve this problem. \nThe goal of this MySQL function is to retrieve the Nth highest salary from the Employee
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThe goal of this MySQL function is to retrieve the Nth highest salary from the Employee table.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n1. Declare a variable M and set it to N - 1. This is because the LIMIT clause uses a zero-based index, so the Nth highest salary corresponds to the (N-1)th row in the result set.\n2. Use a subquery to select the distinct salaries from the Employee table, ordered in descending order.\n3. Use the LIMIT clause to limit the result set to one row, starting from the (N-1)th row (i.e., offset M).\n4. Return the result of the subquery as the output of the function.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\nThe time complexity of this function depends on the size of the Employee table and the value of the input parameter N. In general, the time complexity of a subquery with an ORDER BY clause is O(n * log n), where n is the number of rows in the table. The LIMIT clause reduces the number of rows returned by the subquery, so the actual time complexity may be less than O(n * log n). However, the function must be called once for each value of N, so the overall time complexity is O(k * n * log n), where k is the number of times the function is called.\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\nThe space complexity of this function depends on the size of the result set and the size of the columns being selected. In this case, the result set will have at most one row and one column (Salary). Therefore, the space complexity is O(1). The space used by the variable M is also constant, so it does not affect the overall space complexity\n\n# Code\n```\nCREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT\nBEGIN\n    declare M INT;\n    set M = N - 1;\n  RETURN (\n      # Write your MySQL query statement below.\n      select distinct Salary from Employee order by Salary desc limit 1 offset M\n      \n  );\nEND\n```
['MySQL']