Naive solution C#
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \nFind the overlap X and 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nFind the overlap X and overlap Y.\n\n\nFind the min value of X and Y to calculate largest possible square.\n# Complexity\n- Time complexity: $$O(n^2)$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity: $$O(1)$$\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\npublic class Solution {\n    public long LargestSquareArea(int[][] bottomLeft, int[][] topRight) {\n         long maxArea = 0;\n        int n = bottomLeft.Length;\n        \n        for (int i = 0; i < n; i++) {\n            for (int j = i + 1; j < n; j++) {\n                int xOverlap = Math.Max(0, Math.Min(topRight[i][0], topRight[j][0]) - Math.Max(bottomLeft[i][0], bottomLeft[j][0]));\n                int yOverlap = Math.Max(0, Math.Min(topRight[i][1], topRight[j][1]) - Math.Max(bottomLeft[i][1], bottomLeft[j][1]));\n                \n                int side = Math.Min(xOverlap, yOverlap);\n                maxArea = Math.Max(maxArea, (long)side * side);\n            }\n        }\n        \n        return maxArea;\n    }\n}\n```
['C#']