💯AMAZING SOLUTION💯 || 😨SQL😨 || 💥BEATS 1000.0%💥|| 🫵GROUP BY, HAVING🫵
\n\n# Code\n\n# Write your MySQL query statement below\nselect customer_id \nfrom Customer\ngroup by customer_id \nhaving count(distinct product_key) in (\n  se
\n\n# Code\n```\n# Write your MySQL query statement below\nselect customer_id \nfrom Customer\ngroup by customer_id \nhaving count(distinct product_key) in (\n  select count(distinct product_key)\n  from Product \n)\n```\n![st,small,845x845-pad,1000x1000,f8f8f8.jpg](https://assets.leetcode.com/users/images/ec255417-b7c2-4e1d-a87b-c86d86625cac_1697716140.3746212.jpeg)\n
['MySQL']