✅ Explained - Simple and Clear Python3 Code✅
Intuition\nThe given problem requires separating the digits of positive integers in an array and returning the digits in the same order they appear in the origi
# Intuition\nThe given problem requires separating the digits of positive integers in an array and returning the digits in the same order they appear in the original numbers.\n\n\n# Approach\nThe provided solution uses a function named separateDigits within a class named Solution. The function takes an input parameter nums, which is a list of positive integers. The function returns a list res containing the separated digits.\n\nTo separate the digits of each integer, the solution iterates over each number x in the input array nums. For each number, it initializes an empty list t. It then enters a while loop that continues until the number x becomes zero.\n\nWithin the while loop, the solution calculates the remainder of x divided by 10 using the modulo operator %, which gives the last digit of the number. This digit is then inserted at the beginning of the list t using the insert method with an index of 0.\n\nAfter inserting the digit, the solution updates x by performing an integer division x // 10, which removes the last digit from the number. This process is repeated until all the digits of x are separated.\n\nOnce all the digits of x are separated and stored in the list t, the solution appends the contents of t to the result list res using the += operator. This ensures that the digits of each number are added in the order they appear in the input array.\n\nFinally, when all numbers in the input array have been processed, the function returns the resulting list res.\n\n\n\n# Complexity\n- Time complexity:\nthe time complexity of this solution depends on the total number of digits in all the integers present in the input array. If there are a total of n digits, the solution will iterate over each digit once, resulting in a time complexity of O(n).\n\n- Space complexity:\nThe space complexity of the solution is also dependent on the number of digits. It uses additional space to store the separated digits of each number in the list t and the final result in the list res. Therefore, the space complexity is also O(n), where n represents the total number of digits in the input array.\n\n\n\n\n\n# Code\n```\nclass Solution:\n    def separateDigits(self, nums: List[int]) -> List[int]:\n        res=[]\n        for x in nums:\n            t=[]\n            while x>0:\n                t.insert(0,x%10)\n                x=x//10\n            res+=t\n        return res\n```
['Python3']