Python 🐍 Solution Easy
Intuition\n Describe your first thoughts on how to solve this problem. \nThis is a Python code for finding the difference between two lists. The function findDi
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nThis is a Python code for finding the difference between two lists. The function findDifference takes in two lists, nums1 and nums2, as its arguments. It first converts these lists into sets using the built-in set() function.\n\nThe set() function creates a set object from the given iterable (lists, tuples, strings, etc.). A set is an unordered collection of unique objects, so if there are any duplicates in either of the input lists, they will be removed during the conversion to sets.\n\nAfter converting the input lists to sets, the function uses the set difference operator (-) to find the difference between them. Specifically, it computes s1 - s2 and s2 - s1, which are the elements that are in s1 but not in s2, and vice versa, respectively. Finally, it returns the results as lists using the built-in list() function.\n\nNote that the returned list contains two sub-lists, one for each direction of the difference. If you only want the difference in one direction, you can simply return either list(s1 - s2) or list(s2 - s1) .\n# Approach\n<!-- Describe your approach to solving the problem. -->\nThe approach used in the findDifference function is to first convert the input lists nums1 and nums2 into sets s1 and s2, respectively. This is done using the built-in set() function in Python.\n\nAfter converting the input lists to sets, the function finds the set difference between the two sets using the set difference operator (-). This operator returns a new set that contains all elements in the left operand set (s1) that are not present in the right operand set (s2). It also returns a new set that contains all elements in the right operand set (s2) that are not present in the left operand set (s1).\n\nFinally, the function converts these two sets back to lists using the built-in list() function and returns them as a list of two sub-lists representing the difference in both directions.\n\nThe advantage of this approach is that it uses the built-in set operations in Python, which are optimized for efficiency. This results in a simple and efficient solution to find the difference between two lists without needing to write complex code for iterating over the lists and comparing their elements.\n# Complexity\n- Time complexity:$$O(n)$$\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:$$O(n)$$\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\nclass Solution(object):\n    def findDifference(self, nums1, nums2):\n        s1, s2 = set(nums1), set(nums2)\n        return [list(s1 - s2), list(s2 - s1)]\n        """\n        :type nums1: List[int]\n        :type nums2: List[int]\n        :rtype: List[List[int]]\n        """\n```\n\n
['Array', 'Hash Table', 'Python', 'Python3']