Short python solution
\ndef numOfBurgers(self, ts: int, cs: int) -> List[int]:\n        small = cs \n        ts = ts - cs * 2\n        \n        if ts < 0 or ts % 2 == 1 or ts > cs *
```\ndef numOfBurgers(self, ts: int, cs: int) -> List[int]:\n        small = cs \n        ts = ts - cs * 2\n        \n        if ts < 0 or ts % 2 == 1 or ts > cs * 2: return []\n        \n        jumbo = ts // 2\n        small = small - jumbo\n        \n        return [jumbo, small]\n```
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