5 Lines Solution with good explanation
This C++ solution is designed to find the size of the largest submatrix containing only 1s in a given matrix a. Here\'s a step-by-step explanation:\n\n1. Initia
This C++ solution is designed to find the size of the largest submatrix containing only 1s in a given matrix `a`. Here\'s a step-by-step explanation:\n\n1. **Initialize Variables:**\n   - `n` and `m` store the number of rows and columns in the matrix, respectively.\n   - `ans` is the variable to keep track of the maximum area of a submatrix.\n\n2. **Update Matrix:**\n   - Iterate through each row starting from the second row (`i=1`).\n   - For each element in the row, if it is a 1, add the value of the element in the previous row at the same column. This step essentially accumulates the height of consecutive 1s in each column.\n\n3. **Sort Rows:**\n   - For each row, sort the values in descending order. This step helps in finding the maximum area in the next step efficiently.\n\n4. **Calculate Maximum Area:**\n   - Iterate through each row and each column.\n   - For each element, calculate the area of the submatrix ending at that element by multiplying the width (column index + 1) with the height (value in the sorted row).\n   - Update the `ans` variable with the maximum area encountered so far.\n\n5. **Return Result:**\n   - The final result is stored in the `ans` variable, representing the size of the largest submatrix containing only 1s.\n\nIn summary, this solution efficiently calculates the height of consecutive 1s in each column, sorts the rows based on the height of 1s, and then iterates through each element to find the maximum area of submatrices containing only 1s.\n\n# In 5 line as the title says\n\n```cpp\nclass Solution {\npublic:\n    int largestSubmatrix(vector<vector<int>>& a) {\n        int n=a.size(),m=a[0].size(),ans=0;\n        for(int i=1;i<n;i++) for(int j=0;j<m;j++) if(a[i][j]) a[i][j]+=a[i-1][j];\n        for(int i=0;i<n;i++) sort(a[i].begin(), a[i].end(), greater<int>());\n        for(int i=0;i<n;i++) for(int j=0;j<m;j++) ans = max(ans, (j+1)*a[i][j]);\n        return ans;\n    }\n};\n```\n# More Readable\n```\nclass Solution {\npublic:\n    int largestSubmatrix(vector<vector<int>>& a) {\n        int n=a.size(),m=a[0].size(),ans=0;\n        for(int i=1;i<n;i++)\n            for(int j=0;j<m;j++)\n                if(a[i][j])\n                    a[i][j]+=a[i-1][j];\n\n        for(int i=0;i<n;i++)\n            sort(a[i].begin(), a[i].end(), greater<int>());\n\n        for(int i=0;i<n;i++)\n            for(int j=0;j<m;j++)\n                ans = max(ans, (j+1)*a[i][j]);\n            \n        return ans;\n    }\n};\n```\n\n\n#### The description of code is generated by chat gpt, I\'m too lazy to explain on my own
['C++']