Python | Pretty Simple and clean solution with comments
\nclass Solution:\n    def breakPalindrome(self, palindrome: str) -> str:\n        lst = list(palindrome)\n        # if there is noway to make it non-palindromi
```\nclass Solution:\n    def breakPalindrome(self, palindrome: str) -> str:\n        lst = list(palindrome)\n        # if there is noway to make it non-palindromic\n        if len(lst) < 2:\n            return \'\'\n        \n        # checking till mid if not a make it a\n        for i in range(len(lst)//2):\n            if lst[i] != \'a\':\n                lst[i] = \'a\'\n                return \'\'.join(lst)\n        \n        # else make the last char \'b\'\n        lst[len(lst) - 1] = \'b\'\n        return \'\'.join(lst)\n            \n```\n***Please do upvote if found helpful!!!***
['String', 'Python', 'Python3']