MOST EASIEST PYTHON SOLUTION🔥🔥🔥 || BEGINNER FRIENDLY APPROACH
Intuition\nThe problem likely involves finding pairs from two arrays nums1 and nums2 such that the elements in the pair satisfy a given condition. Specifically,
# Intuition\nThe problem likely involves finding pairs from two arrays nums1 and nums2 such that the elements in the pair satisfy a given condition. Specifically, for each pair (nums1[i], nums2[j]), you\'re tasked with determining whether nums1[i] is divisible by nums2[j] * k (where k is an integer parameter provided). If the condition holds, the pair is considered valid, and you want to count how many such valid pairs exist.\n\n# Approach\nIterate through each element in nums1: For each element nums1[i], check its divisibility against all elements nums2[j] multiplied by k.\n\nNested loop structure: The outer loop will iterate over each element  i in nums1.\nThe inner loop will iterate over each element j in nums2.\n\nCondition check: For every pair (i, j), check if nums1[i] % (nums2[j] * k) == 0.\nIf the condition is met, increase the count of valid pairs.\n\nReturn the count: After checking all possible pairs, return the total count of valid pairs.\n\n# Complexity\n- Time complexity:\n56 MS\n\n- Space complexity:\n11.67 MB\n\n# Code\n```python []\n# class Solution(object):\n\n#     def __init__(self):\n#         self.map = {}\n#         self.c = 0\n\n#     def checkcondition(nums1, nums2, i, j, k):\n#         if( nums2[j] != 0 and nums1[i] % (nums2[j] * k) == 0):\n#             self.map[i] = j\n#             return True\n#         return False\n        \n#     def numberOfPairs(self, nums1, nums2, k):\n#         for i in range(len(nums1)):\n#             for j in range(len(nums2)):\n#                 if (self.checkcondition(self, nums1, nums2, i, j, k)):\n#                     self.c = self.c + 1\n#         return self.c\n\n#         """\n#         :type nums1: List[int]\n#         :type nums2: List[int]\n#         :type k: int\n#         :rtype: int\n#         """\nclass Solution(object):\n\n    def __init__(self):\n        self.map = {}\n        self.c = 0\n\n    def checkcondition(self, nums1, nums2, i, j, k): \n        if nums2[j] != 0 and nums1[i] % (nums2[j] * k) == 0:\n            self.map[i] = j  \n            return True\n        return False\n        \n    def numberOfPairs(self, nums1, nums2, k):\n        for i in range(len(nums1)):\n            for j in range(len(nums2)):\n                if self.checkcondition(nums1, nums2, i, j, k):  \n                    self.c += 1\n        return self.c  \n\n        """\n        :type nums1: List[int]\n        :type nums2: List[int]\n        :type k: int\n        :rtype: int\n        """\n\n```
['Python']