Javascript - Easy Solution
Intuition\n Describe your first thoughts on how to solve this problem. \n\n# Approach\n Describe your approach to solving the problem. \n\n# Complexity\n- Time 
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n\n# Code\n```\n/**\n * @param {number[]} nums\n * @return {number}\n */\nvar countAlternatingSubarrays = function(nums) {\n    let total = nums.length, count = 0;\n    \n    for(let i = 1; i < nums.length; i++) {\n        if(nums[i - 1] !== nums[i]) count++;\n        else {\n            total = total + count * (count + 1) / 2;\n            count = 0;\n        }\n    }\n    \n    total = total + count * (count + 1) / 2;\n    return total;\n};\n```
['JavaScript']