Swift💯1liner w/ bits; Fastest: 0ms 
One-Liner using Bits, terse (accepted answer)
Return true if s can be partitioning into at least k sections and the number of odd-count letters is <= k.
**One-Liner using Bits, terse (accepted answer)**
Return `true` if `s` can be partitioning into at least `k` sections and the number of odd-count letters is <= `k`.
```
class Solution {
  func canConstruct(_ s: String, _ k: Int) -> Bool {
    s.count>=k && s.utf8.reduce(0){$0^(1<<($1-97))}.nonzeroBitCount<=k
  }
}
```
['Swift']