C# solution beats 100%??
Intuition\n Describe your first thoughts on how to solve this problem. \nMy first thought on how to solve this problem is to use dynamic programming (DP) to fin
# Intuition\n<!-- Describe your first thoughts on how to solve this problem. -->\nMy first thought on how to solve this problem is to use dynamic programming (DP) to find the minimum number of white tiles that need to be painted black. The problem seems to be a classic example of a DP problem, where we need to make decisions based on previous states.\n\n# Approach\n<!-- Describe your approach to solving the problem. -->\nMy approach is to create a 2D DP array, where the state dp[i, j] represents the minimum number of white tiles that need to be painted black for the first i tiles and j carpets. We iterate through the floor and carpets, and for each state, we consider two options: either paint the current tile black or use a carpet to cover it. We choose the option that results in the minimum number of white tiles painted black.\n\n# Complexity\n- Time complexity:\n<!-- Add your time complexity here, e.g. $$O(n)$$ -->\n$$O(n\\*numCarpets)$$, where n is the length of the floor and numCarpets is the number of carpets. This is because we iterate through the floor and carpets in a nested manner.\n- Space complexity:\n<!-- Add your space complexity here, e.g. $$O(n)$$ -->\n$$O(n\\*numCarpets)$$, as we need to store the DP array of size n x numCarpets.\n\n# Code\n```\npublic class Solution {\n    public int MinimumWhiteTiles(string floor, int numCarpets, int carpetLen) {\n        int n = floor.Length;\n        int[,] dp = new int[n + 1, numCarpets + 1];\n\n        // Initialize the dp array\n        for (int i = 0; i <= n; i++) {\n            for (int j = 0; j <= numCarpets; j++) {\n                dp[i, j] = int.MaxValue / 2; \n            }\n        }\n        dp[0, 0] = 0;\n\n        // Fill the dp array\n        for (int i = 1; i <= n; i++) {\n            for (int j = 0; j <= numCarpets; j++) {\n                if (j > 0 && i >= carpetLen) {\n                    dp[i, j] = Math.Min(dp[i, j], dp[i - carpetLen, j - 1]);\n                }\n                if (j > 0 && i < carpetLen) {\n                    dp[i, j] = Math.Min(dp[i, j], dp[0, j - 1]);\n                }\n                dp[i, j] = Math.Min(dp[i, j], dp[i - 1, j] + (floor[i - 1] == \'1\' ? 1 : 0));\n            }\n        }\n\n        int minWhiteTiles = int.MaxValue;\n        for (int j = 0; j <= numCarpets; j++) {\n            minWhiteTiles = Math.Min(minWhiteTiles, dp[n, j]);\n        }\n\n        return minWhiteTiles;\n    }\n}\n\n```
['C#']