Golang Solution ||| Explanations
Intuition\nGreedily going from one point to another\n\n# Approach\nFirst, \n let us realize that it is always to our advantage to put the largest possible recta
# Intuition\nGreedily going from one point to another\n\n# Approach\n**First,** \n* let us realize that it is always to our advantage to put the largest possible rectangle. **Its dimensions should be** $$(length = w, height = inf)$$.\n* Then we define that it **is always advantageous to place the origin of the rectangle at (iPointX, 0) (y = 0 by convention), where iPointX is the x-coordinate of point i.**\n\nBy observing these 2 conditions, **we guarantee that our rectangle will cover the maximum number of points with maximum probability, and hence the number of rectangles will be minimized.**\n\n# The algorithm itself\n\nLet\'s have 3 variables \n* counter - responsible for the number of placed rectangles\n* x - denotes on which x-coordinate we are now located\n* index - index of the point we are covering\n\n**Let\'s start the while loop.**\nWe need to cover all points, so the **conditions for exiting the while loop are index != n** (possibly index <= n - 1).\nWhen we enter while, **we immediately mark that we put a rectangle, (counter++)**, and **shift x by w** (since we are putting a rectangle with length w).\n**After that we run the second while, where we mark (shift index) the points that are already covered.** \n```go\n        for index != n && points[index][0] <= x {\n            index++\n        }\n```\nAfter that **index will point either to n** (we exit the first while immediately) or **to the next point that is not covered yet.** So we **put x at the position points[index][0]** to put the next rectangle there.\n\n**return counter**\n\n# Important clarification\n**The algorithm works if our points are sorted**. Therefore, let\'s **remember to sort the points by x coordinate at the beginning of the algorithm.**\n```go\n    sort.Slice(points, func(i, j int) bool {\n        return points[i][0] < points[j][0]\n    })\n```\n\n# If my solution was helpful, don\'t forget to upvote \uD83D\uDDA4\n![Upvote Please.jpeg](https://assets.leetcode.com/users/images/d72ec8db-40ed-4095-bada-b653b8aa5767_1713026856.9157765.jpeg)\n\n# Complexity\n- Time complexity:\n$$O(N)$$    \n\n- Space complexity:\n$$O(1)$$\n\n# Code\n```\nfunc minRectanglesToCoverPoints(points [][]int, w int) int {\n    sort.Slice(points, func(i, j int) bool {\n        return points[i][0] < points[j][0]\n    })\n    \n    counter := 0\n    n := len(points)\n    x := points[0][0]\n    index := 0\n    for index != n {\n        x += w\n        counter++\n        for index != n && points[index][0] <= x {\n            index++\n        }\n        if index == n {\n            break\n        }\n        x = points[index][0]\n    }\n    \n    return counter\n}\n```
['Greedy', 'Sorting', 'Go']