Python 5 lines Solution with explanations
\nclass Solution:\n    def reorderLogFiles(self, logs: List[str]) -> List[str]:\n        #categorize digit_logs and letter_logs\n        digit_logs = [log for l
```\nclass Solution:\n    def reorderLogFiles(self, logs: List[str]) -> List[str]:\n        #categorize digit_logs and letter_logs\n        digit_logs = [log for log in logs if log.split()[1][0] in "0123456789"]\n        letter_logs = [log for log in logs if log not in digit_logs]\n        \n        #given that Python sort is stable\n        #first, sort the letter_logs based on the identifiers so that they can remain in order of the identifiers \n        #if the contents are identical\n        #second, sort the letter_logs based on the contents\n        letter_logs.sort(key=lambda x: x.split()[0])\n        letter_logs.sort(key=lambda x: x.split()[1:])\n        \n        #append the digit_logs and return the result\n        return letter_logs + digit_logs\n```
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