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Let **S** be a sequence of **N** natural numbers. We can define an infinite |
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sequence **MS** in the following way: **MS**[k] = **S**[k mod **N**] + **N** * |
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floor(k / **N**). Where k is a zero based index. |
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For example if the sequence **S** is {2, 1, 3} then **MS** would be {2, 1, 3, |
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5, 4, 6, 8, 7, 9, 11, 10, 12...} |
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Now consider a subsequence of **MS** generated by picking two random indices |
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**a**, **b** from the range [**0**..**R**] inclusive, and taking all the |
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elements between them, that is: **MS**[min(**a**, **b**)..max(**a**, **b**)]. |
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If we use the same **MS** as in the example above and **a** = 2, **b** = 5 |
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then our subsequence would be {3, 5, 4, 6}. |
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Your task is to calculate the probability that the selected subsequence has at |
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least **K** distinct elements. **a** and **b** are selected independently and |
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with a uniform distribution. The result should be printed as a fraction. See |
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the "Output" section for clarification. |
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### Input |
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The first line of the input file contains an integer **T**. This is followed |
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by **T** test cases, each of which has two lines. |
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The first line of each test case contains three integers separated by spaces, |
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**N**, **K**, and **R**. |
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The second line contains **N** space separated integers, **S**[0] through |
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**S**[**N**-1]. |
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### Constraints |
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1 ≤ **T** ≤ 20 |
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1 ≤ **N** ≤ 2,000 |
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1 ≤ **K** ≤ **R** ≤ 1,000,000,000 |
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1 ≤ **S**[i] ≤ 100,000 |
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### Output |
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For each of the test cases numbered in order from 1 to **T**, output "Case |
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#**i**: " followed by the probability that the selected subsequence of **MS** |
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has at least **K** distinct elements. The probability should be expressed as a |
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fraction **p**/**q**, where **p** and **q** represent the numerator and |
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denominator respectively and are relatively prime (that is they share no |
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common positive divisors except 1). |
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If the probability is 0 or 1 output 0/1 or 1/1 respectively. |
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### Examples |
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In the first example there are 36 different subsequences to consider. 6 of |
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them have only a single number, and the remaining 30 have at least 2 different |
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numbers, so the answer is 5/6. |
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The second example is similar, but now the sequence looks like {2, 1, 5, 5, 4, |
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8}. There are 8 subsequences with less than 2 distinct numbers: the six single |
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number subsequences plus (a=2, b=3) and (a=3, b=2) which both result in {5,5}. |
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That gives a probability of (36 - 8) / 36 = 7/9. |
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The third example uses the same sequence as the second example, but now we |
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want to have subsequences with at least 4 different numbers. All pairs of |
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indices that have this property are: (0,4), (0, 5), (1, 5), (4, 0), (5, 0), |
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and (5, 1). Six out of thirty six results in a probability of 1/6. |
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