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hackercup / 2021 /round3 /expl-ore-ation_ch2.cpp
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2021 Problems
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#include <algorithm>
#include <iostream>
#include <set>
#include <tuple>
#include <utility>
#include <vector>
using namespace std;
const int INF = 1000000000;
const int LIM = 1000002;
struct UnionFind {
int N;
vector<int> root, rank, sidx;
vector<set<pair<int, int>>> S;
UnionFind(int _N) : N(_N), root(_N), rank(_N, 0), sidx(_N), S(_N) {
for (int i = 0; i < N; i++) {
root[i] = i;
sidx[i] = i;
S[i].emplace(-INF, -INF);
S[i].emplace(INF, INF);
}
}
int find(int i) {
if (root[i] != i) {
root[i] = find(root[i]);
}
return root[i];
}
void merge(int i, int j) {
i = find(i);
j = find(j);
if (i == j) {
return;
}
if (rank[i] > rank[j]) {
swap(i, j);
}
root[i] = j;
if (rank[i] == rank[j]) {
rank[j]++;
}
// Merge robot interval sets (ensuring j gets the larger one, and merging the
// other into it).
if (S[sidx[i]].size() > S[sidx[j]].size()) {
swap(sidx[i], sidx[j]);
}
auto &SA = S[sidx[i]], &SB = S[sidx[j]];
for (auto p : SA) {
if (p.first == -INF || p.first == INF) {
continue;
}
auto it = prev(SB.lower_bound(make_pair(p.first + 1, -1)));
if (it->second < p.first - 1) {
it++;
}
while (it->first <= p.second + 1) {
p.first = min(p.first, it->first);
p.second = max(p.second, it->second);
it = SB.erase(it);
}
SB.insert(p);
}
SA.clear();
}
};
int R, C, N, K;
int H[LIM];
vector<pair<int, int>> children[LIM];
vector<tuple<int, int, int, int>> A;
pair<long long, long long> solve() {
A.clear();
for (int i = 0; i < LIM; i++) {
children[i].clear();
}
// Input.
cin >> R >> C;
N = R * C;
for (int i = 0, j; i < N; i++) {
cin >> H[i];
if ((j = i - C) >= 0) { // Up.
A.emplace_back(-min(H[i], H[j]), INF, i, j);
}
if (i % C > 0 && (j = i - 1) >= 0) { // Left.
A.emplace_back(-min(H[i], H[j]), INF, i, j);
}
}
for (int i = 0; i < N; i++) {
int s;
cin >> s;
children[i].emplace_back(0, s);
}
cin >> K;
for (int i = 0; i < K; i++) {
int a, b, u;
cin >> a >> b >> u;
a--;
b--;
int j = a * C + b;
if (i == 0) {
children[j].clear();
}
children[j].emplace_back(i, u);
}
// Determine interval of situations per original/updated S value.
for (int i = 0; i < N; i++) {
for (int j = 0; j < children[i].size(); j++) {
int a = children[i][j].first;
int b = j < int(children[i].size()) - 1
? children[i][j + 1].first - 1
: K - 1;
A.emplace_back(-children[i][j].second, i, a, b);
}
}
// Process edges/samples in non-increasing order of elevation.
UnionFind U(N);
sort(A.begin(), A.end());
pair<long long, long long> ans{0, 0};
for (const auto &t : A) {
int h = -get<0>(t), i = get<1>(t), a = get<2>(t), b = get<3>(t);
if (i < INF) { // Sample.
if (H[i] <= h) { // Impossible to collect.
continue;
}
ans.first += b - a + 1; // Collect it in each relevant situation.
auto &S = U.S[U.sidx[U.find(i)]];
// Add new robots to relevant situations as necessary.
auto it = prev(S.lower_bound(make_pair(a + 1, -1)));
if (it->second < a - 1) {
it++;
}
while (it->first <= b + 1) {
a = min(a, it->first);
b = max(b, it->second);
ans.second -= it->second - it->first + 1;
it = S.erase(it);
}
S.emplace(a, b);
ans.second += b - a + 1;
continue;
}
U.merge(a, b); // Edge.
}
return ans;
}
int main() {
int T;
cin >> T;
for (int t = 1; t <= T; t++) {
auto ans = solve();
cout << "Case #" << t << ": " << ans.first << " " << ans.second << endl;
}
return 0;
}