The 2019 Hacker Cup Finals have just concluded! There were N participants (numbered 1 to N), including yourself (competing as participant 1), and M problems (numbered 1 to M).
Participant i solved problem j if Si,j = "Y", and otherwise they didn't solve it (if Si,j = "N"). Problem i's point value is 2i, and each participant's score is the sum of the point values of the problems that they solved. No two participants solved exactly the same set of problems, which also means that all participants have distinct scores.
Before the final results get announced, you have an opportunity to rearrange the M columns of the scoreboard S into any permutation of problems 1 to M. For example, if you swap columns 1 and 2, then everybody who had originally solved problem 1 will now be considered to have solved problem 2 (thus earning 4 points for it rather than 2), and vice versa.
Of course, you'd like to use this opportunity to your benefit — it would be irresponsible to just let it pass by! However, it would be too suspicious if you simply made yourself win the whole competition. As such, you'd like to cause yourself to end up in 2nd place, such that you (participant 1) have exactly the second-highest score out of all N participants. Now you just need to determine whether or not this is achievable...
Input
Input begins with an integer T, the number of scoreboards.
For each scoreboard, there is first a line containing the space-separated
integers N and M.
Then, N lines follow, the _i_th of which contains a length-M string,
the characters Si,1 through Si,M.
Output
For the _i_th scoreboard, print a line containing "Case #i: " followed by one character, either "Y" if you can end up in 2nd place, or "N" otherwise.
Constraints
1 ≤ T ≤ 200
2 ≤ N ≤ 400
1 ≤ M ≤ 400
The sum of N * M across all T test cases is no greater than 1,000,000.
Explanation of Sample
In the first case, there's only one possible permutation of problems: [1]. This results in you having a score of 2 and participant 2 having a score of 0, which puts you in 1st place rather than 2nd.
In the second case, if you preserve the original permutation of problems, [1, 2], you'll have a score of 2 while participant 2 has a score of 4, putting you in 2nd place, as required. The permutation [2, 1] would have put you in 1st place instead.
In the third case, if you choose the problem permutation [2, 1], the 4 participants' scores will be 4, 0, 6, and 2, respectively. This puts you in 2nd place, as required. The problem permutation [1, 2] would have put you in 3rd place instead.