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hackercup / 2021 /round3 /expl-ore-ation_ch3.cpp
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2021 Problems
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#include <algorithm>
#include <cstring>
#include <iostream>
#include <set>
#include <tuple>
#include <utility>
#include <vector>
using namespace std;
const int INF = 1000000000;
const int LIM = 1000002;
const int LIM2 = 2000002;
const int LIM3 = 23;
int R, C, N, K;
int H[LIM], S[LIM];
vector<tuple<int, int, int>> A;
pair<int, int> curr;
int M;
int children[LIM2][2];
int parent[LIM2][LIM3];
int high[LIM2];
struct UnionFind {
int N;
vector<int> root, rank, node;
UnionFind(int _N) : N(_N), root(_N), rank(_N, 0), node(_N) {
for (int i = 0; i < N; i++) {
root[i] = i;
node[i] = M;
children[M][0] = children[M][1] = -1;
high[M++] = INF + 1;
}
}
int find(int i) {
if (root[i] != i) {
root[i] = find(root[i]);
}
return root[i];
}
void merge(int i, int j, int e) {
i = find(i);
j = find(j);
if (i == j) {
return;
}
if (rank[i] > rank[j]) {
swap(i, j);
}
root[i] = j;
if (rank[i] == rank[j]) {
rank[j]++;
}
// Make both components' tree M children of a new node.
children[M][0] = node[i];
children[M][1] = node[j];
high[M] = e;
node[j] = M++;
}
};
struct HeavyLightTree {
int heavy[LIM2];
int root[LIM2], treePos[LIM2], inv[LIM2];
int ind, L[LIM2], R[LIM2];
multiset<int> S, S2;
int dfs(int v) {
L[v] = ind++;
for (int i = 0; i < LIM3 - 1; i++) {
int p = parent[v][i];
if (p < 0) {
break;
}
parent[v][i + 1] = parent[p][i];
}
int size = 1, maxSubtree = 0;
for (int u : children[v]) {
if (u < 0) {
continue;
}
parent[u][0] = v;
int subtree = dfs(u);
if (subtree > maxSubtree) {
heavy[v] = u;
maxSubtree = subtree;
}
size += subtree;
}
R[v] = ind - 1;
return size;
}
void init() {
fill_n(heavy, M, -1);
ind = 0;
dfs(M - 1);
for (int i = 0, currentPos = 0; i < M; i++) {
if (parent[i][0] == -1 || heavy[parent[i][0]] != i) {
for (int j = i; j != -1; j = heavy[j]) {
root[j] = i;
inv[currentPos] = j;
treePos[j] = currentPos++;
}
}
}
S.clear();
S2.clear();
S.insert(-1);
}
void update(int i, bool ins) {
if (ins) {
S.insert(treePos[i]);
S2.insert(L[i]);
} else {
S.erase(S.find(treePos[i]));
S2.erase(S2.find(L[i]));
}
}
int find_closest_ancestor_set(int i) {
while (i >= 0) {
int j = root[i];
int k = *prev(S.lower_bound(treePos[i] + 1));
if (k >= treePos[j]) {
return inv[k];
}
i = parent[j][0];
}
return -1;
}
bool subtree_has_set_M(int i, bool inc) {
auto it = S2.lower_bound(L[i] + (inc ? 0 : 1));
return it != S2.end() && *it <= R[i];
}
};
HeavyLightTree HLT;
void update_cell(int i, bool ins) {
// Sample is irrelevant (impossible to collect)?
int s = S[i];
if (s >= H[i]) {
return;
}
// Register collection.
int d = ins ? 1 : -1;
curr.first += d;
// Find corresponding tree node (highest valid ancestor of leaf node).
for (int j = LIM3 - 1; j >= 0; j--) {
if (parent[i][j] >= 0 && high[parent[i][j]] > s) {
i = parent[i][j];
}
}
// Update HLD (if deleting).
if (!ins) {
HLT.update(i, ins);
}
// Update can only be relevant if no samples in i's subtree.
if (!HLT.subtree_has_set_M(i, true)) {
// Find closest ancestor with sample (if any).
int a = HLT.find_closest_ancestor_set(i);
// Update is relevant if a doesn't exist, or if there are other samples
// amongst a's descendants
if (a < 0 || HLT.subtree_has_set_M(a, false)) {
curr.second += d;
}
}
// Update HLD (if inserting).
if (ins) {
HLT.update(i, ins);
}
}
pair<long long, long long> solve() {
A.clear();
// Input.
cin >> R >> C;
N = R * C;
for (int i = 0, j; i < N; i++) {
cin >> H[i];
if ((j = i - C) >= 0) { // Up.
A.emplace_back(-min(H[i], H[j]), i, j);
}
if (i % C > 0 && (j = i - 1) >= 0) { // Left.
A.emplace_back(-min(H[i], H[j]), i, j);
}
}
for (int i = 0; i < N; i++) {
cin >> S[i];
}
// Process edges in non-increasing order of elevation, and construct tree of
// connected regions.
M = 0;
UnionFind U(N);
sort(A.begin(), A.end());
for (auto t : A) {
U.merge(get<1>(t), get<2>(t), -get<0>(t));
}
memset(parent, -1, sizeof(parent[0]) * M);
HLT.init();
// Insert initial samples.
curr = make_pair(0, 0);
for (int i = 0; i < N; i++) {
update_cell(i, 1);
}
// Process updates.
cin >> K;
pair<long long, long long> ans{0, 0};
int prevY = 0;
while (K--) {
int i, j;
cin >> i >> j;
i = (i ^ prevY) - 1;
j = (j ^ prevY) - 1;
i = i * C + j;
update_cell(i, 0);
cin >> S[i];
S[i] ^= prevY;
update_cell(i, 1);
ans.first += curr.first;
ans.second += curr.second;
prevY = curr.second;
}
return ans;
}
int main() {
int T;
cin >> T;
for (int t = 1; t <= T; t++) {
auto ans = solve();
cout << "Case #" << t << ": " << ans.first << " " << ans.second << endl;
}
return 0;
}