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hackercup / 2020 /round2 /capastaty.cpp
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2020 Problems
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// Ca-pasta-ty
// Solution by Jacob Plachta
#include <algorithm>
#include <functional>
#include <numeric>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <complex>
#include <cstdlib>
#include <ctime>
#include <cstring>
#include <cassert>
#include <string>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <unordered_set>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <sstream>
using namespace std;
#define LL long long
#define LD long double
#define PR pair<int,int>
#define Fox(i,n) for (i=0; i<n; i++)
#define Fox1(i,n) for (i=1; i<=n; i++)
#define FoxI(i,a,b) for (i=a; i<=b; i++)
#define FoxR(i,n) for (i=(n)-1; i>=0; i--)
#define FoxR1(i,n) for (i=n; i>0; i--)
#define FoxRI(i,a,b) for (i=b; i>=a; i--)
#define Foxen(i,s) for (i=s.begin(); i!=s.end(); i++)
#define Min(a,b) a=min(a,b)
#define Max(a,b) a=max(a,b)
#define Sz(s) int((s).size())
#define All(s) (s).begin(),(s).end()
#define Fill(s,v) memset(s,v,sizeof(s))
#define pb push_back
#define mp make_pair
#define x first
#define y second
template<typename T> T Abs(T x) { return(x < 0 ? -x : x); }
template<typename T> T Sqr(T x) { return(x * x); }
string plural(string s) { return(Sz(s) && s[Sz(s) - 1] == 'x' ? s + "en" : s + "s"); }
const int INF = (int)1e9;
const LD EPS = 1e-12;
const LD PI = acos(-1.0);
#define GETCHAR getchar_unlocked
bool Read(int& x)
{
char c, r = 0, n = 0;
x = 0;
for (;;)
{
c = GETCHAR();
if ((c < 0) && (!r))
return(0);
if ((c == '-') && (!r))
n = 1;
else
if ((c >= '0') && (c <= '9'))
x = x * 10 + c - '0', r = 1;
else
if (r)
break;
}
if (n)
x = -x;
return(1);
}
#define LIM 1000001
int S[LIM], X[LIM], Y[LIM];
void ReadSeq(int* V, int N, int K)
{
int i, A, B, C, D;
Fox(i, K)
Read(V[i]);
Read(A), Read(B), Read(C), Read(D);
FoxI(i, K, N - 1)
V[i] = ((LL)A * V[i - 2] + (LL)B * V[i - 1] + C) % D;
}
LL ProcessCase()
{
int N, K, i;
// input
Read(N), Read(K);
ReadSeq(S, N, K);
ReadSeq(X, N, K);
ReadSeq(Y, N, K);
// aggregate requirements
pair<LL, LL> P[2];
Fox(i, N)
{
int x = X[i] - S[i], y = X[i] + Y[i] - S[i];
P[0].x += max(0, -y);
P[0].y += max(0, -x);
P[1].x += max(0, x);
P[1].y += max(0, y);
}
// check if satisfiable
Fox(i, 2)
if (P[i].x > P[1 - i].y)
return(-1);
return(max(P[0].x, P[1].x));
}
int main()
{
int T, t;
Read(T);
Fox1(t, T)
printf("Case #%d: %lld\n", t, ProcessCase());
return(0);
}