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// Mail Security | |
// Solution by Jacob Plachta | |
using namespace std; | |
template<typename T> T Abs(T x) { return(x < 0 ? -x : x); } | |
template<typename T> T Sqr(T x) { return(x * x); } | |
string plural(string s) { return(Sz(s) && s[Sz(s) - 1] == 'x' ? s + "en" : s + "s"); } | |
const int INF = (int)1e9; | |
const LD EPS = 1e-12; | |
const LD PI = acos(-1.0); | |
bool Read(int& x) | |
{ | |
char c, r = 0, n = 0; | |
x = 0; | |
for (;;) | |
{ | |
c = GETCHAR(); | |
if ((c < 0) && (!r)) | |
return(0); | |
if ((c == '-') && (!r)) | |
n = 1; | |
else | |
if ((c >= '0') && (c <= '9')) | |
x = x * 10 + c - '0', r = 1; | |
else | |
if (r) | |
break; | |
} | |
if (n) | |
x = -x; | |
return(1); | |
} | |
int N, M, K, X; | |
int S[LIM], P[LIM]; | |
void ReadSeq(int* V, int N, int K) | |
{ | |
int i, A, B, C, D; | |
Fox(i, K) | |
Read(V[i]); | |
Read(A), Read(B), Read(C), Read(D); | |
FoxI(i, K, N - 1) | |
V[i] = ((LL)A * V[i - 2] + (LL)B * V[i - 1] + C) % D + 1; | |
} | |
bool Valid(int np) | |
{ | |
int i; | |
// assemble list of relevant objects | |
vector<PR> O; | |
FoxR(i, N) // largest np mailboxes, plus any large enough for a key | |
if (O.size() < np || S[i] >= X) | |
O.pb(mp(S[i], 1)); | |
int nb = Sz(O); | |
Fox(i, np) // smallest np packages | |
O.pb(mp(P[i], 0)); | |
sort(All(O), std::greater<>()); | |
// iterate over objects by non-increasing capacity/size | |
multiset<PR> AC; // available pairs of (capacity % X, capacity) | |
LL nk = 0; | |
for (auto o : O) | |
{ | |
// mailbox? | |
if (o.y) | |
{ | |
nk += o.x / X; | |
AC.insert(mp(o.x % X, o.x)); | |
continue; | |
} | |
// package | |
if (AC.empty()) | |
return(0); | |
auto I = AC.lower_bound(mp(o.x % X, 0)); | |
if (I == AC.end()) | |
I = AC.begin(); | |
int c = I->y; | |
AC.erase(I); | |
nk += (c - o.x) / X - c / X; | |
} | |
return(nk >= nb - 1); | |
} | |
int ProcessCase() | |
{ | |
// input | |
Read(N), Read(M), Read(K), Read(X); | |
ReadSeq(S, N, K); | |
ReadSeq(P, M, K); | |
// sort objects by capacity/size | |
sort(S, S + N); | |
sort(P, P + M); | |
// binary search | |
int r1 = 0, r2 = min(N, M); | |
while (r1 < r2) | |
{ | |
int m = (r1 + r2 + 1) / 2; | |
if (Valid(m)) | |
r1 = m; | |
else | |
r2 = m - 1; | |
} | |
return(r1); | |
} | |
int main() | |
{ | |
int T, t; | |
Read(T); | |
Fox1(t, T) | |
printf("Case #%d: %d\n", t, ProcessCase()); | |
return(0); | |
} |