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Write SQL query to solve given problem: Give the student staff ratio of university ID 35.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT student_staff_ratio FROM university_year WHERE university_id = 35 |
Write SQL query to solve given problem: Provide the score of the most populated university in 2011.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T2.score FROM university_year AS T1 INNER JOIN university_ranking_year AS T2 ON T1.university_id = T2.university_id WHERE T1.year = 2011 ORDER BY T1.num_students DESC LIMIT 1 |
Write SQL query to solve given problem: Give the criteria name where Harvard University scored 100.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT DISTINCT T3.criteria_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN ranking_criteria AS T3 ON T3.id = T2.ranking_criteria_id WHERE T1.university_name = 'Harvard University' AND T2.score = 100 |
Write SQL query to solve given problem: Provide the university name and ID of the university found in Turkey.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T1.university_name, T1.id FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Turkey' |
Write SQL query to solve given problem: What is the total number of ranking criteria under the ranking system called Shanghai Ranking?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT COUNT(*) FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T1.system_name = 'Shanghai Ranking' |
Write SQL query to solve given problem: Give the name and score of the university ID 124.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T2.university_name, T1.score FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.id = 124 |
Write SQL query to solve given problem: How many female students are there in University of Pennsylvania in 2011?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT CAST(T1.num_students * T1.pct_female_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'University of Pennsylvania' |
Write SQL query to solve given problem: List down all universities that scored below 50.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT DISTINCT T2.university_name FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.score < 50 |
Write SQL query to solve given problem: How many universities are located in Japan?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT COUNT(*) FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Japan' |
Write SQL query to solve given problem: Provide the name of the university with the highest number of male students.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id ORDER BY T1.num_students * T1.pct_female_students / 100 - T1.num_students DESC LIMIT 1 |
Write SQL query to solve given problem: List the countries of universities that scored 70 and below in 2016.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT DISTINCT T3.country_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.score < 70 AND T2.year = 2016 |
Write SQL query to solve given problem: Calculate number of male students in Emory University in 2011.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT CAST((T1.num_students - (T1.num_students * T1.pct_female_students)) AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Emory University' AND T1.year = 2011 |
Write SQL query to solve given problem: In which country does Johns Hopkins University located?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'Johns Hopkins University' |
Write SQL query to solve given problem: Give the names of universities with number of students ranges from 400 to 1000.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT DISTINCT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.num_students BETWEEN 400 AND 1000 |
Write SQL query to solve given problem: In what year does the Brown University score the highest?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T1.year FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Brown University' ORDER BY T1.score DESC LIMIT 1 |
Write SQL query to solve given problem: Calculate the average score of Emory University from 2011 to 2016.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT AVG(T1.score) FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Emory University' AND T1.year BETWEEN 2011 AND 2016 |
Write SQL query to solve given problem: Give the name of the university with the most number of students in 2015.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2015 ORDER BY T1.num_students DESC LIMIT 1 |
Write SQL query to solve given problem: What is the location and number of female students in university ID 23 in 2011?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T3.country_name, CAST(T2.num_students * T2.pct_female_students AS REAL) / 100 FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.year = 2011 AND T1.id = 23 |
Write SQL query to solve given problem: How many universities scored 40 in teaching criteria?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT COUNT(*) FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id WHERE T2.score = 40 AND T1.criteria_name = 'Teaching' AND T2.score = 40 |
Write SQL query to solve given problem: Among the universities in United States of America, what is the percentage of female students in year 2016?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT SUM(CAST(T2.pct_female_students * T2.num_students AS REAL) / 100) * 100 / SUM(T2.num_students) FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'United States of America' AND T2.year = 2016 |
Write SQL query to solve given problem: Calculate the difference between the total number of students and the number of international international students in Univeristy of Tokyo from 2011 to 2014.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT SUM(T1.num_students) - SUM(CAST(T1.num_students * T1.pct_international_students AS REAL) / 100) FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year BETWEEN 2011 AND 2014 AND T2.university_name = 'University of Tokyo' |
Write SQL query to solve given problem: List the names of universities with a score less than 28% of the average score of all universities in 2015.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | university | SELECT T2.university_name FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2015 AND T1.score * 100 < ( SELECT AVG(score) * 28 FROM university_ranking_year WHERE year = 2015 ) |
Write SQL query to solve given problem: How many units of item no.9 were sold in store no.1 on 2012/1/1?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT units FROM sales_in_weather WHERE `date` = '2012-01-01' AND store_nbr = 1 AND item_nbr = 9 |
Write SQL query to solve given problem: How many units of item no.9 were sold in store no.1 in total in January, 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(units) FROM sales_in_weather WHERE SUBSTR(`date`, 6, 2) = '01' AND SUBSTR(`date`, 1, 4) = '2012' AND item_nbr = 9 AND store_nbr = 1 |
Write SQL query to solve given problem: What is the ID of the item that sold the best on 2012/1/1 in store no.1?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT item_nbr FROM sales_in_weather WHERE `date` = '2012-01-01' AND store_nbr = 1 ORDER BY units DESC LIMIT 1 |
Write SQL query to solve given problem: What was the temperature range of station no.1 on 2012/1/1?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT tmax - tmin AS temrange FROM weather WHERE station_nbr = 1 AND `date` = '2012-01-01' |
Write SQL query to solve given problem: Please list the dates on which the temperature of station no.2 was above the 30-year normal.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT `date` FROM weather WHERE station_nbr = 2 AND depart > 0 |
Write SQL query to solve given problem: On which day was the weather more windy in station no.1, 2012/1/1 or 2012/1/2?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT CASE WHEN (SUM(CASE WHEN `date` = '2012-01-01' THEN avgspeed ELSE 0 END) - SUM(CASE WHEN `date` = '2012-01-02' THEN avgspeed ELSE 0 END)) > 0 THEN '2012-01-01' ELSE '2012-01-02' END FROM weather WHERE station_nbr = 1 |
Write SQL query to solve given problem: What is the total number of units of item no.5 sold in store no.3 in 2012 on days when the temperature was below the 30-year normal?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(CASE WHEN T3.depart < 0 THEN units ELSE 0 END) AS sum FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND SUBSTR(T1.`date`, 1, 4) = '2012' AND T1.item_nbr = 5 |
Write SQL query to solve given problem: How many units of item no.5 were sold in store no.3 on the day in 2012 when the max temperature was the highest?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.units FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND SUBSTR(T1.`date`, 1, 4) = '2012' AND T1.item_nbr = 5 ORDER BY tmax DESC LIMIT 1 |
Write SQL query to solve given problem: What was the dew point on the day the most units of item no.5 were sold in store no.3 in 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT dewpoint FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND SUBSTR(T1.`date`, 1, 4) = '2012' AND T1.item_nbr = 5 ORDER BY units DESC LIMIT 1 |
Write SQL query to solve given problem: On how many days with the max temperature over 90 did the sale of item no.5 in store no.3 exceed 100?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(CASE WHEN units > 100 THEN 1 ELSE 0 END) AS count FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND SUBSTR(T1.`date`, 1, 4) = '2012' AND T1.item_nbr = 5 AND tmax > 90 |
Write SQL query to solve given problem: How many units of item no.5 were sold in store no.3 on the day the temperature range was the biggest?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT t2.units FROM relation AS T1 INNER JOIN sales_in_weather AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T1.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND T2.item_nbr = 5 ORDER BY t3.tmax - t3.tmin DESC LIMIT 1 |
Write SQL query to solve given problem: Among the days on which over 100 units of item no.5 were sold in store no.3, on which date was the temperature range the biggest?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T2.`date` FROM relation AS T1 INNER JOIN sales_in_weather AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T1.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND T2.item_nbr = 5 AND T2.units > 100 ORDER BY tmax - tmin DESC LIMIT 1 |
Write SQL query to solve given problem: How many units of item no.5 were sold in store no.3 in total on days with a total precipitation of over 0.05?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(CASE WHEN T3.preciptotal > 0.05 THEN units ELSE 0 END) AS sum FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND T1.item_nbr = 5 |
Write SQL query to solve given problem: Please list the dates on which the sale of item no.5 in store no.3 exceeded 100 and the average wind speed exceeded 10.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.`date` FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND T1.item_nbr = 5 AND T1.units > 100 AND T3.avgspeed > 10 |
Write SQL query to solve given problem: What is the total units of products sold on the day with the highest max temperature in store no.3 in 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(units) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T2.store_nbr = 3 AND T1.`date` LIKE '%2012%' GROUP BY T3.tmax ORDER BY T3.tmax DESC LIMIT 1 |
Write SQL query to solve given problem: How many more units of item no.16 were sold on the day with the highest max temperature in 2012 in store no.5 than in store no.10?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT ( SELECT SUM(units) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T1.item_nbr = 16 AND T1.`date` LIKE '%2012%' AND T1.store_nbr = 5 GROUP BY tmax ORDER BY T3.tmax DESC LIMIT 1 ) - ( SELECT SUM(units) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T1.item_nbr = 16 AND T1.`date` LIKE '%2012%' AND T1.store_nbr = 6 GROUP BY tmax ORDER BY T3.tmax DESC LIMIT 1 ) |
Write SQL query to solve given problem: What is the ID of the item that sold the best on the day with the highest max temperature in store no.3 in 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.item_nbr FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T1.store_nbr = 3 AND T1.`date` LIKE '%2012%' AND tmax = ( SELECT MAX(tmax) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T1.store_nbr = 3 AND T1.`date` LIKE '%2012%' ) GROUP BY T1.item_nbr ORDER BY SUM(units) DESC LIMIT 1 |
Write SQL query to solve given problem: On the day with the highest max temperature in 2012, how many items in store no.3 had no sales?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(DISTINCT T1.item_nbr) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr AND T1.store_nbr = 3 AND SUBSTR(T1.`date`, 1, 4) = '2012' AND T1.units = 0 GROUP BY T3.tmax ORDER BY T3.tmax DESC LIMIT 1 |
Write SQL query to solve given problem: How many units of item no.5 were sold in store no.3 on average on the days when the max temperature exceeded 90?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT CAST(SUM(T1.units) AS REAL) / COUNT(T1.`date`) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T1.store_nbr = 3 AND T1.item_nbr = 5 AND T3.tmax > 90 |
Write SQL query to solve given problem: What is the percentage of the units of item no.5 sold among all units of items sold in store no.3 on the day with the highest max temperature in 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT CAST(SUM(CASE WHEN T1.item_nbr = 5 THEN units * 1 ELSE 0 END) AS REAL) * 100 / SUM(units) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T1.store_nbr = 3 AND T1.`date` LIKE '%2012%' AND T3.tmax = ( SELECT MAX(T3.tmax) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T1.store_nbr = 3 AND T1.`date` LIKE '%2012%' ) |
Write SQL query to solve given problem: Give the id of the bestsellers of store no.1 on 2012/1/1.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT item_nbr FROM sales_in_weather WHERE `date` = '2012-01-01' AND store_nbr = 1 ORDER BY units DESC LIMIT 1 |
Write SQL query to solve given problem: How many no.9 items from store no.11 were sold on 2012/12/7?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT units FROM sales_in_weather WHERE `date` = '2012-12-07' AND store_nbr = 11 AND item_nbr = 9 |
Write SQL query to solve given problem: Give the average temperature of station no.20 on 2014/10/17.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT tavg FROM weather WHERE `date` = '2014-10-17' AND station_nbr = 20 |
Write SQL query to solve given problem: Tell the resultant wind speed of station no.9 on 2014/1/15.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT resultspeed FROM weather WHERE `date` = '2014-01-15' AND station_nbr = 9 |
Write SQL query to solve given problem: Give the id of the weather station with most stores.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT station_nbr FROM relation GROUP BY station_nbr ORDER BY COUNT(station_nbr) DESC LIMIT 1 |
Write SQL query to solve given problem: Which weather station does store no.20 belong to?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT station_nbr FROM relation WHERE store_nbr = 20 |
Write SQL query to solve given problem: Tell the temperature range of the home weather station of store no.7 on 2014/4/28.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.tmax - T1.tmin AS temprange FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 7 AND T1.`date` = '2014-04-28' |
Write SQL query to solve given problem: For the weather station which recorded the highest temperature above the 30-year normal, how many stores does it have?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT store_nbr FROM relation WHERE station_nbr = ( SELECT station_nbr FROM weather ORDER BY depart DESC LIMIT 1 ) |
Write SQL query to solve given problem: For the home weather station of store no.15, what was the dew point on 2012/2/18?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.dewpoint FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 15 AND T1.`date` = '2012-02-18' |
Write SQL query to solve given problem: Tell the wet-bulb temperature of the weather station which contained store no.6 on 2012/2/15.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.wetbulb FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 14 AND T1.`date` = '2012-02-15' |
Write SQL query to solve given problem: Give the number of stores which opened on the weather station that recorded the fastest average wind speed.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(T.store_nbr) FROM ( SELECT DISTINCT store_nbr FROM relation WHERE station_nbr = ( SELECT station_nbr FROM weather ORDER BY avgspeed DESC LIMIT 1 ) ) T |
Write SQL query to solve given problem: State the max temperature of the weather station which has the no.21 store on 2012/11/9.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT tmax FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 21 AND T1.`date` = '2012-11-09' |
Write SQL query to solve given problem: Provide the sunrise time recorded by the home weather station of store no.30 on 2014/2/21.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.sunrise FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T1.`date` = '2014-02-21' AND store_nbr = 30 |
Write SQL query to solve given problem: State the number of stores that belongs to the weather station which recorded the deepest snowfall.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T2.store_nbr FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr ORDER BY snowfall DESC LIMIT 1 |
Write SQL query to solve given problem: Provide the code summarization for the weather recorded by the weather station which contained the no.2 store on 2013/2/12.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.codesum FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T1.`date` = '2013-02-12' AND T2.store_nbr = 2 |
Write SQL query to solve given problem: Show the sea level status recorded by the weather station of store no.19 on 2013/2/24.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.sealevel FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T1.`date` = '2013-02-24' AND T2.store_nbr = 19 |
Write SQL query to solve given problem: How many inches of total precipitation was recorded by the weather station of store no.2 on 2012/12/25?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.preciptotal FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T1.`date` = '2012-12-25' AND T2.store_nbr = 2 |
Write SQL query to solve given problem: Give the station pressure status recorded by the weather station which contained no.12 store on 2012/5/15.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.stnpressure FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T1.`date` = '2012-05-15' AND T2.store_nbr = 12 |
Write SQL query to solve given problem: What percentage was the total unit sales of store no.10 to the total sales of its weather station on 2014/10/31?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT CAST(SUM(CASE WHEN T2.store_nbr = 10 THEN units * 1 ELSE 0 END) AS REAL) * 100 / SUM(units) FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr WHERE T1.`date` = '2014-10-31' |
Write SQL query to solve given problem: For the weather station has store no.9, what was the increased percentage of the average temperature from 2012/2/2 to 2012/2/3?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT CAST((SUM(CASE WHEN T1.`date` = '2012-02-03' THEN T1.tavg * 1 ELSE 0 END) - SUM(CASE WHEN T1.`date` = '2012-02-02' THEN T1.tavg * 1 ELSE 0 END)) AS REAL) * 100 / SUM(CASE WHEN T1.`date` = '2012-02-02' THEN T1.tavg * 1 ELSE 0 END) FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 9 |
Write SQL query to solve given problem: What is the item number of the product with the highest number of units sold in store number 1 on 1/1/2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT item_nbr FROM sales_in_weather WHERE `date` = '2012-01-01' AND store_nbr = 1 ORDER BY units DESC LIMIT 1 |
Write SQL query to solve given problem: How many stores are in weather station 12?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(store_nbr) FROM relation WHERE station_nbr = 12 |
Write SQL query to solve given problem: How many items weren't sold in store 2 on 1/1/2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(item_nbr) FROM sales_in_weather WHERE store_nbr = 2 AND units = 0 AND `date` = '2012-01-01' |
Write SQL query to solve given problem: Between 1/1/2012 to 12/31/2014, which date recorded the hottest temperature in weather station 1?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT `date` FROM weather WHERE station_nbr = 1 AND CAST(SUBSTR(`date`, 1, 4) AS int) BETWEEN 2012 AND 2014 ORDER BY tmax DESC LIMIT 1 |
Write SQL query to solve given problem: Which weather station has the highest number of stores?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT station_nbr FROM relation GROUP BY station_nbr ORDER BY COUNT(store_nbr) DESC LIMIT 1 |
Write SQL query to solve given problem: In March 2014, which weather stations recorded the highest number of days whose temperature is below the 30-year normal?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT station_nbr FROM weather WHERE SUBSTR(`date`, 1, 4) = '2014' AND SUBSTR(`date`, 6, 2) = '03' AND depart < 0 GROUP BY station_nbr HAVING COUNT(DISTINCT `date`) = ( SELECT COUNT(DISTINCT `date`) FROM weather WHERE SUBSTR(`date`, 1, 4) = '2014' AND SUBSTR(`date`, 6, 2) = '03' AND depart < 0 GROUP BY station_nbr ORDER BY COUNT(`date`) DESC LIMIT 1 ) |
Write SQL query to solve given problem: Which weather station does the store that sold the highest quantity of item 9 belongs to?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT station_nbr FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr WHERE T1.item_nbr = 9 GROUP BY T2.station_nbr ORDER BY SUM(T1.units) DESC LIMIT 1 |
Write SQL query to solve given problem: How many stores belong to the most windy station?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(store_nbr) FROM relation WHERE station_nbr = ( SELECT station_nbr FROM weather ORDER BY avgspeed DESC LIMIT 1 ) |
Write SQL query to solve given problem: Among the stores in weather station 14 in February 2014, which store had sold no less than 300 quantities for item number 44 in a single day?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.store_nbr FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr WHERE T2.station_nbr = 14 AND T1.`date` LIKE '%2014-02%' AND T1.item_nbr = 44 AND units >= 300 |
Write SQL query to solve given problem: What is the most purchased products during the rainy days in June 2013 in weather station 9?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.item_nbr FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN weather AS T3 ON T2.station_nbr = T3.station_nbr WHERE T3.station_nbr = 9 AND T1.`date` LIKE '%2013-06%' AND codesum = 'RA' ORDER BY T1.units DESC LIMIT 1 |
Write SQL query to solve given problem: Which station sold the highest quantity of item number 5 overall?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T2.station_nbr FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr WHERE T1.item_nbr = 5 GROUP BY T2.station_nbr ORDER BY SUM(T1.units) DESC LIMIT 1 |
Write SQL query to solve given problem: What is the earliest sunrise recorded in the stations with no more than 1 store in February 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.station_nbr FROM relation AS T1 INNER JOIN weather AS T2 ON T1.station_nbr = T2.station_nbr WHERE sunrise IS NOT NULL AND T2.`date` LIKE '%2012-02%' AND T1.station_nbr IN ( SELECT station_nbr FROM relation GROUP BY station_nbr HAVING COUNT(store_nbr) = 1 ) ORDER BY sunrise LIMIT 1 |
Write SQL query to solve given problem: In weather station 17, which store sold the highest quantity of item 45 in October 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.store_nbr FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr WHERE T1.item_nbr = 45 AND T2.station_nbr = 17 AND T1.`date` LIKE '%2012-10%' GROUP BY T1.store_nbr ORDER BY SUM(T1.units) DESC LIMIT 1 |
Write SQL query to solve given problem: What are the items sold by the store during the day whose station recorded the thickest snowfall?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.item_nbr FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr INNER JOIN ( SELECT station_nbr, `date` FROM weather ORDER BY snowfall DESC LIMIT 1 ) AS T3 ON T2.station_nbr = T3.station_nbr |
Write SQL query to solve given problem: What are the top 3 stations that have sold the highest quantities for an item in a single day?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T2.station_nbr FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr ORDER BY T1.units DESC LIMIT 3 |
Write SQL query to solve given problem: How many stores belong to the station with the highest recorded heat of all time?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(T2.store_nbr) FROM ( SELECT station_nbr FROM weather ORDER BY heat DESC LIMIT 1 ) AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr |
Write SQL query to solve given problem: On February 8, 2014, what is the minimum temperature in the station where store 29 belongs?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT tmin FROM relation AS T1 INNER JOIN weather AS T2 ON T1.station_nbr = T2.station_nbr WHERE T1.store_nbr = 29 AND T2.`date` = '2014-02-08' |
Write SQL query to solve given problem: Among the stations with 3 stores, how many stations have a station pressure of no more than 30 on February 18, 2014?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(station_nbr) FROM weather WHERE `date` = '2014-02-18' AND stnpressure < 30 AND station_nbr IN ( SELECT station_nbr FROM relation GROUP BY station_nbr HAVING COUNT(store_nbr) = 3 ) |
Write SQL query to solve given problem: Which station has the highest number of stores? Calculate the said station's average maximum temperature in February 2012.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT CAST(SUM(T2.tmax) AS REAL) / 29 FROM ( SELECT station_nbr FROM relation GROUP BY station_nbr ORDER BY COUNT(store_nbr) DESC LIMIT 1 ) AS T1 INNER JOIN weather AS T2 ON T1.station_nbr = T2.station_nbr WHERE SUBSTR(T2.`date`, 1, 7) = '2012-02' |
Write SQL query to solve given problem: Between the stores under weather station 12, what is the percentage of item 5 sold in store 10 in 2014?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT CAST(SUM(CASE WHEN T2.store_nbr = 10 THEN units * 1 ELSE 0 END) AS REAL) * 100 / SUM(units) FROM relation AS T1 INNER JOIN sales_in_weather AS T2 ON T1.store_nbr = T2.store_nbr WHERE station_nbr = 12 AND item_nbr = 5 AND T2.`date` LIKE '%2014%' |
Write SQL query to solve given problem: What is the maximum average speed?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT MAX(avgspeed) FROM weather |
Write SQL query to solve given problem: How many days did the show fell more than 5 inches?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(DISTINCT `date`) FROM weather WHERE snowfall > 5 |
Write SQL query to solve given problem: How many days did the sun rise before 5 AM?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(DISTINCT `date`) AS days FROM weather WHERE sunrise < time('05:00:00') |
Write SQL query to solve given problem: What is the minimum dew point?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT MIN(dewpoint) FROM weather |
Write SQL query to solve given problem: What is the maximum and minimum temperature for station number 1 on 15 January 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT tmax, tmin FROM weather WHERE station_nbr = 1 AND `date` = '2012-01-15' |
Write SQL query to solve given problem: How many stations were able to sell item 5 on January 2014?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(DISTINCT T2.station_nbr) AS number FROM sales_in_weather AS T1 INNER JOIN relation AS T2 ON T1.store_nbr = T2.store_nbr WHERE SUBSTR(`date`, 1, 7) = '2014-01' AND item_nbr = 5 |
Write SQL query to solve given problem: What is the lowest minimum temperature recorded in store 16 on January 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT MIN(tmin) FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 16 AND T1.`date` LIKE '%2012-01%' |
Write SQL query to solve given problem: How many units of item 7 have been sold by store 7 when the snow is less than 5 inches?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(units) FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr INNER JOIN sales_in_weather AS T3 ON T2.store_nbr = T3.store_nbr WHERE T2.store_nbr = 7 AND T3.item_nbr = 7 AND T1.snowfall < 5 |
Write SQL query to solve given problem: How many items were sold by store 9 during a snowy day?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT COUNT(DISTINCT item_nbr) FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr INNER JOIN sales_in_weather AS T3 ON T2.store_nbr = T3.store_nbr WHERE T3.store_nbr = 9 AND T1.snowfall <> 0 AND T1.snowfall IS NOT NULL |
Write SQL query to solve given problem: List out stations number and items sold by store 17.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.station_nbr, T2.item_nbr FROM relation AS T1 INNER JOIN sales_in_weather AS T2 ON T1.store_nbr = T2.store_nbr WHERE T1.store_nbr = 17 GROUP BY T1.station_nbr, T2.item_nbr |
Write SQL query to solve given problem: List out dates when haze is recorded in store 35.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.`date` FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 35 AND T1.codesum LIKE '%' OR 'HZ' OR '%' |
Write SQL query to solve given problem: What is the sea level and average speed for store number 3 and store number 4?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T1.sealevel, T1.avgspeed FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 3 OR T2.store_nbr = 4 |
Write SQL query to solve given problem: Which items from store 1 have the highest units sold during rainy day?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT T2.item_nbr FROM weather AS T1 INNER JOIN sales_in_weather AS T2 ON T1.`date` = T2.`date` INNER JOIN relation AS T3 ON T2.store_nbr = T3.store_nbr AND T1.station_nbr = T3.station_nbr WHERE T2.store_nbr = 1 AND T1.codesum LIKE '%' OR 'RA' OR '%' GROUP BY T2.item_nbr ORDER BY T2.units DESC LIMIT 1 |
Write SQL query to solve given problem: What is the ratio of the highest and lowest temperature in store 11?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT CAST((MAX(T1.tmax) - MIN(T1.tmin)) AS REAL) / MIN(T1.tmin) FROM weather AS T1 INNER JOIN relation AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.store_nbr = 11 |
Write SQL query to solve given problem: What was the difference of number of units sold in station number 1 and number 2 on year 2012?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(CASE WHEN T1.station_nbr = 1 THEN units ELSE 0 END) - SUM(CASE WHEN T1.station_nbr = 2 THEN units ELSE 0 END) FROM relation AS T1 INNER JOIN sales_in_weather AS T2 ON T1.store_nbr = T2.store_nbr WHERE T2.`date` LIKE '%2012%' |
Write SQL query to solve given problem: What was the average temperature difference between store number 18 and 19 on 16 September 2022?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(CASE WHEN T1.store_nbr = 18 THEN T2.tavg ELSE 0 END) - SUM(CASE WHEN T1.store_nbr = 19 THEN T2.tavg ELSE 0 END) FROM relation AS T1 INNER JOIN weather AS T2 ON T1.station_nbr = T2.station_nbr WHERE T2.`date` = '2012-09-16' |
Write SQL query to solve given problem: How many units are being sold for item 1 when the average temperature is 83?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT SUM(units) FROM weather AS T1 INNER JOIN sales_in_weather AS T2 ON T1.`date` = T2.`date` INNER JOIN relation AS T3 ON T2.store_nbr = T3.store_nbr WHERE T2.item_nbr = 1 AND T1.tavg = 83 |
Write SQL query to solve given problem: What is the difference between the units sold for item 1 when the sunset was the earliest and the latest?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | sales_in_weather | SELECT ( SELECT SUM(T2.units) AS sumunit FROM weather AS T1 INNER JOIN sales_in_weather AS T2 ON T1.`date` = T2.`date` INNER JOIN relation AS T3 ON T2.store_nbr = T3.store_nbr WHERE T2.item_nbr = 5 AND sunset IS NOT NULL GROUP BY T1.sunset ORDER BY T1.sunset LIMIT 1 ) - ( SELECT SUM(T2.units) AS sumunit FROM weather AS T1 INNER JOIN sales_in_weather AS T2 ON T1.`date` = T2.`date` INNER JOIN relation AS T3 ON T2.store_nbr = T3.store_nbr WHERE T2.item_nbr = 5 AND sunset IS NOT NULL GROUP BY T1.sunset ORDER BY T1.sunset DESC LIMIT 1 ) |
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