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Write SQL query to solve given problem: What is the total quantity that Cindy Stewart order "Lexmark X 9575 Professional All-in-One Color Printer" in the south superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT SUM(T1.Quantity) FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Cindy Stewart' AND T3.`Product Name` = 'Lexmark X 9575 Professional All-in-One Color Printer' |
Write SQL query to solve given problem: List the name of all the products with order quantities greater than or equal to 10 in the central superstore that has been shipped by the slowest delivery method.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Ship Mode` = 'Standard Class' AND T1.Quantity >= 10 |
Write SQL query to solve given problem: What product category got the least sales in the west superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T2.Category FROM west_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` ORDER BY T1.Sales LIMIT 1 |
Write SQL query to solve given problem: What is the total profit of "Memorex Froggy Flash Drive 8 GB in south superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT SUM(T1.Profit) FROM south_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` GROUP BY T2.`Product Name` = 'Memorix Froggy Flash Drive 8 GB' |
Write SQL query to solve given problem: What is the total sales of furniture products in the east superstore in the year 2016.
. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT SUM(T1.Sales) FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE STRFTIME('%Y', T1.`Order Date`) = '2016' AND T2.Category = 'Furniture' |
Write SQL query to solve given problem: Calculate the average sales of ""Sharp AL-1530CS Digital Copier in the east and the west superstore.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT AVG(T1.Sales) FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T3.`Product Name` = 'Sharp AL-1530CS Digital Copier' |
Write SQL query to solve given problem: Calculate the percentage of ordered office supplies products in the central and the south superstore.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT CAST(SUM(CASE WHEN T3.Category = 'Office Supplies' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T3.Category) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` |
Write SQL query to solve given problem: What is the ratio between customers who live in Texas and customers who live in Indiana?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT CAST(SUM(CASE WHEN State = 'Texas' THEN 1 ELSE 0 END) AS REAL) * 100 / SUM(CASE WHEN State = 'Indiana' THEN 1 ELSE 0 END) FROM people |
Write SQL query to solve given problem: Among the orders in Central superstore, which art product were ordered the most?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Sub-Category` = 'Art' GROUP BY T2.`Product Name` ORDER BY COUNT(T2.`Product ID`) DESC LIMIT 1 |
Write SQL query to solve given problem: Among the customers in South superstore, which customers ordered more than 3 times in 2015? State the name of the customers.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Customer Name` FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE STRFTIME('%Y', T1.`Order Date`) = '2015' GROUP BY T2.`Customer Name` HAVING COUNT(T2.`Customer Name`) > 3 |
Write SQL query to solve given problem: State the highest profit made by Anna Chung's orders in the Central Superstore.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT MAX(T2.Profit) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Anna Chung' |
Write SQL query to solve given problem: How many orders were made by Corey Roper in 2015?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(T2.`Customer ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Corey Roper' AND STRFTIME('%Y', T2.`Ship Date`) = '2015' |
Write SQL query to solve given problem: Calculate the difference between the total sales in the East superstore and the total sales in the West superstore.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT SUM(T1.Sales) - SUM(T2.Sales) AS difference FROM east_superstore AS T1 INNER JOIN west_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` |
Write SQL query to solve given problem: What are the names of the ordered products that have profit deficiency in central superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Region = 'Central' AND T1.Profit < 0 |
Write SQL query to solve given problem: In west superstore, what is the name and the shipping mode of the product that was ordered with the shortest shipment time?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Product Name`, T1.`Ship Mode` FROM west_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Region = 'West' ORDER BY T1.`Ship Date` - T1.`Order Date` LIMIT 1 |
Write SQL query to solve given problem: How many orders of O'Sullivan Plantations 2-Door Library in Landvery Oak in central superstore were shipped through the shipping mode with the fastest delivery speed?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(DISTINCT T1.`Order ID`) FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'O''Sullivan Plantations 2-Door Library in Landvery Oak' AND T2.Region = 'Central' AND T1.`Ship Mode` = 'First Class' |
Write SQL query to solve given problem: What is the name of the corporate customer from Rhode Island who had the highest number of orders in 2016 from the east superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T2.Segment = 'Corporate' AND T2.State = 'Rhode Island' AND T2.Region = 'East' AND STRFTIME('%Y', T1.`Order Date`) = '2016' GROUP BY T2.`Customer Name` ORDER BY COUNT(T2.`Customer Name`) DESC LIMIT 1 |
Write SQL query to solve given problem: Among the orders with sales value of no less than 5,000 in west superstore, how many were bought by the customers in California?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(DISTINCT T1.`Order ID`) FROM west_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` INNER JOIN people AS T3 ON T3.`Customer ID` = T1.`Customer ID` WHERE T1.Sales > 5000 AND T3.State = 'California' AND T2.Region = 'West' |
Write SQL query to solve given problem: In which segment does the customer who purchased the product from the east superstore with the highest original price belong?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T2.Segment FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T1.Region = 'East' ORDER BY (T1.Sales / (1 - T1.Discount)) DESC LIMIT 1 |
Write SQL query to solve given problem: What is the shipment duration for order number CA-2011-134103?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT strftime('%J', `Ship Date`) - strftime('%J', `Order Date`) AS duration FROM central_superstore WHERE `Order ID` = 'CA-2011-134103' |
Write SQL query to solve given problem: How many orders with a quantity greater than 5 have been shipped by the fastest delivery method?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(DISTINCT `Order ID`) FROM central_superstore WHERE Quantity > 5 AND `Ship Mode` = 'First Class' |
Write SQL query to solve given problem: Please list any three orders that caused a loss to the company.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT `Order ID` FROM central_superstore WHERE Profit < 0 LIMIT 3 |
Write SQL query to solve given problem: Which product did Phillina Ober buy?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T3.`Product Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Phillina Ober' |
Write SQL query to solve given problem: Who was the customer in the South Region superstore who bought the most “Hon Multipurpose Stacking Arm Chairs"?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T2.`Customer Name` FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T3.`Product Name` = 'Hon Multipurpose Stacking Arm Chairs' GROUP BY T2.`Customer Name` ORDER BY COUNT(T2.`Customer Name`) DESC LIMIT 1 |
Write SQL query to solve given problem: What is the profit from selling the "O'Sullivan Living Dimensions 2-Shelf Bookcases"?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T1.Profit FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'O''Sullivan Living Dimensions 2-Shelf Bookcases' |
Write SQL query to solve given problem: How many of the "Hon Pagoda Stacking Chairs" have been sold in total in the west superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT SUM(T1.Quantity) FROM west_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Hon Pagoda Stacking Chairs' |
Write SQL query to solve given problem: How many orders purchased by Aaron Bergman have been delivered with the slowest shipping speed?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(*) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aaron Bergman' AND T2.`Ship Mode` = 'Standard Class' |
Write SQL query to solve given problem: What is the original price of the "Black Avery Flip-Chart Easel Binder"?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T1.Sales / (1 - T1.Discount) FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Blackstonian Pencils' |
Write SQL query to solve given problem: What is the name of the product that Aimee Bixby bought?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T3.`Product Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Aimee Bixby' |
Write SQL query to solve given problem: Indicate the profit of product Sauder Camden County Barrister Bookcase, Planked Cherry Finish.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T1.Profit FROM south_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Sauder Camden County Barrister Bookcase, Planked Cherry Finish' |
Write SQL query to solve given problem: How many furniture products had been shipped by standard class in the East superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(T2.Category) FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Ship Mode` = 'Standard Class' |
Write SQL query to solve given problem: What is the highest profit order in the East superstore of customers from Houston, Texas?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T1.`Order ID` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T2.City = 'Houston' AND T2.State = 'Texas' ORDER BY T1.Profit DESC LIMIT 1 |
Write SQL query to solve given problem: How many furniture products were ordered at central superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(*) FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Category = 'Furniture' |
Write SQL query to solve given problem: What are the names of the products that had been shipped in March 2013 at central superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE strftime('%Y-%m', T1.`Ship Date`) = '2013-03' |
Write SQL query to solve given problem: How many orders were made by customers who live in Texas at the Central superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.State = 'Texas' |
Write SQL query to solve given problem: How many orders were made by Alan Barnes in 2015 at the Central superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Alan Barnes' AND STRFTIME('%Y', T2.`Order Date`) = '2015' |
Write SQL query to solve given problem: What is the product name of order CA-2011-115791 in the East superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Product Name` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Order ID` = 'CA-2011-141817' |
Write SQL query to solve given problem: What is the percentage of orders with 0.2 discount in the Central superstore were purchased by customers who live in Texas?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT CAST(SUM(CASE WHEN T2.Discount = 0.2 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.State = 'Texas' |
Write SQL query to solve given problem: What is the percentage of furniture orders that were shipped through first class in 2013 at the Central superstore?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT CAST(SUM(CASE WHEN T1.`Ship Mode` = 'First Class' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Category = 'Furniture' AND STRFTIME('%Y', T1.`Ship Date`) = '2013' |
Write SQL query to solve given problem: Who order from the west region on August 12, 2013, and received a discount of 0.2?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Customer Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Order Date` = '2013-08-12' AND T1.Discount = 0.2 AND T1.Region = 'West' |
Write SQL query to solve given problem: What is the order ID of the security-Tint Envelopes product ordered on June 3, 2013, in the Central region?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T1.`Order ID` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Security-Tint Envelopes' AND T1.`Order Date` = '2013-06-03' |
Write SQL query to solve given problem: List the product's name bought by the customer named Bill Shonely from the Central region.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T3.`Product Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Bill Shonely' AND T2.Region = 'Central' |
Write SQL query to solve given problem: Please give the name of customers from the West region that bought exactly 8 items in their purchase.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Customer Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.Quantity = 8 AND T1.Region = 'West' |
Write SQL query to solve given problem: Among the customers from Houston, Texas, what is the total profit of their orders in the Central region?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT SUM(T2.Profit) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.City = 'Houston' AND T1.State = 'Texas' AND T2.Region = 'Central' |
Write SQL query to solve given problem: Who is the customer with an order shipped on March 5, 2013, in the eastern region?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Ship Date` = '2013-03-05' |
Write SQL query to solve given problem: Among the orders from 2016 in the Central region, what is the product with the lowest profit?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Region = 'Central' AND STRFTIME('%Y', T1.`Order Date`) = '2016' ORDER BY T1.Profit ASC LIMIT 1 |
Write SQL query to solve given problem: Who ordered the order ID CA-2011-118976 from the East region?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Order ID` = 'CA-2011-118976' AND T2.Region = 'East' |
Write SQL query to solve given problem: Provide the product's name of the product with the highest sales in the South region.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T2.`Product Name` FROM south_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Region = 'South' ORDER BY T1.Sales DESC LIMIT 1 |
Write SQL query to solve given problem: List down the sales, profit, and subcategories of the product ordered in the order ID US-2011-126571 in the East region.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T1.Sales, T1.Profit, T2.`Sub-Category` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Order ID` = 'US-2011-126571' AND T2.Region = 'East' |
Write SQL query to solve given problem: What is the product's name in the highest quantity in a single purchase?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT T2.`Product Name` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Region = 'East' ORDER BY T1.Quantity DESC LIMIT 1 |
Write SQL query to solve given problem: List the customer's name from the South region with a standard class ship mode and sales greater than the 88% of the average sales of all orders.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT DISTINCT T2.`Customer Name` FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T2.Region = 'South' AND T1.`Ship Mode` = 'Standard Class' AND 100 * T1.Sales / ( SELECT AVG(Sales) FROM south_superstore ) > 88 |
Write SQL query to solve given problem: Among the customers from Indiana, what is the percentage of their purchased orders in the Central region with no discount?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | superstore | SELECT CAST(SUM(CASE WHEN T2.Discount = 0 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T2.Region = 'Central' AND T1.State = 'Indiana' |
Write SQL query to solve given problem: Among all the male officers, what is the percentage of them are White?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(IIF(race = 'W', 1, 0)) AS REAL) * 100 / COUNT(case_number) FROM officers WHERE gender = 'M' |
Write SQL query to solve given problem: What is the percentage of the cases involved more than 3 officers from year 2010 to 2015?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(IIF(officer_count > 3, 1, 0)) AS REAL) * 100 / COUNT(case_number) FROM incidents WHERE STRFTIME('%Y', date) BETWEEN '2010' AND '2015' |
Write SQL query to solve given problem: In which year has the greatest number of cases where Handgun was used as weapon?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT STRFTIME('%Y', date) FROM incidents WHERE subject_weapon = 'Handgun' GROUP BY STRFTIME('%Y', date) ORDER BY COUNT(case_number) DESC LIMIT 1 |
Write SQL query to solve given problem: Among the cases dismissed by the grand jury disposition, what percentage of cases is where the subject is injured?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(subject_statuses = 'Injured') AS REAL) * 100 / COUNT(case_number) FROM incidents WHERE grand_jury_disposition = 'No Bill' |
Write SQL query to solve given problem: Did the number of cases with Vehicle as subject weapon increase or decrease from year 2007 to 2008. State the difference.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT SUM(IIF(STRFTIME('%Y', date) = '2007', 1, 0)) - SUM(IIF(STRFTIME('%Y', date) = '2008', 1, 0)) FROM incidents WHERE subject_weapon = 'Vehicle' |
Write SQL query to solve given problem: Among the 'Handgun' weapon used by subject, how many percent were 'Shoot and Miss'?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(subject_statuses = 'Shoot and Miss') AS REAL) * 100 / COUNT(case_number) FROM incidents WHERE subject_weapon = 'Handgun' |
Write SQL query to solve given problem: Who are the officers involved in cases that are voted as 'No Bill'. List their last name and gender.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT T2.last_name, T2.gender FROM incidents AS T1 INNER JOIN officers AS T2 ON T1.case_number = T2.case_number WHERE T1.grand_jury_disposition = 'No Bill' |
Write SQL query to solve given problem: Which are the cases where the subject are female. List the case number, subject status and weapon.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT T1.case_number, T1.subject_statuses, T1.subject_weapon FROM incidents AS T1 INNER JOIN subjects AS T2 ON T1.case_number = T2.case_number WHERE T2.gender = 'F' |
Write SQL query to solve given problem: From the cases where the subject are male, list the case number and the location and subject status.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT T1.case_number, T1.location, T1.subject_statuses FROM incidents AS T1 INNER JOIN subjects AS T2 ON T1.case_number = T2.case_number WHERE T2.gender = 'M' |
Write SQL query to solve given problem: For case(s) where officer 'Evenden, George' is in charged, state the case number and the grand jury disposition?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT T1.case_number, T1.grand_jury_disposition FROM incidents AS T1 INNER JOIN officers AS T2 ON T1.case_number = T2.case_number WHERE T2.first_name = 'George' AND T2.last_name = 'Evenden' |
Write SQL query to solve given problem: For case number '134472-2015', list the last name of the officers involved and state the subject statuses.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT T2.last_name, T1.subject_statuses FROM incidents AS T1 INNER JOIN officers AS T2 ON T1.case_number = T2.case_number WHERE T1.case_number = '134472-2015' |
Write SQL query to solve given problem: From the cases where the subject were deceased, list the subject's last name, gender, race and case number.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT T2.last_name, T2.gender, T2.race, T2.case_number FROM incidents AS T1 INNER JOIN subjects AS T2 ON T1.case_number = T2.case_number WHERE T1.subject_statuses = 'Deceased' |
Write SQL query to solve given problem: What is the percentage of subject who are female used the Vehicle as weapon?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(T1.subject_weapon = 'Vehicle') AS REAL) * 100 / COUNT(T1.case_number) FROM incidents T1 INNER JOIN subjects T2 ON T1.case_number = T2.case_number WHERE T2.gender = 'F' |
Write SQL query to solve given problem: From the 'Injured' statuses of the subject, what is the ratio of weapons used are knife against handgun?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(T1.subject_weapon = 'Knife') AS REAL) * 100 / SUM(T1.subject_weapon = 'Handgun') FROM incidents AS T1 INNER JOIN subjects AS T2 ON T1.case_number = T2.case_number WHERE T1.subject_statuses = 'Injured' |
Write SQL query to solve given problem: List all cases from the year 2012 in which the subject was deceased. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT case_number FROM incidents WHERE STRFTIME('%Y', date) > '2011' AND subject_statuses = 'Deceased' |
Write SQL query to solve given problem: Of all male officers, what percentage are black officers?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(race = 'B') AS REAL) * 100 / COUNT(case_number) FROM officers WHERE gender = 'M' |
Write SQL query to solve given problem: How many incidents in which the subject's weapon was a vehicle were investigated by a female officer?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT COUNT(T1.case_number) FROM incidents AS T1 INNER JOIN officers AS T2 ON T1.case_number = T2.case_number WHERE T1.subject_weapon = 'Vehicle' AND T2.gender = 'F' |
Write SQL query to solve given problem: In how many cases where the subject was a female was the subject's status listed as Deceased?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT COUNT(T1.case_number) FROM incidents AS T1 INNER JOIN subjects AS T2 ON T1.case_number = T2.case_number WHERE T2.gender = 'F' AND T1.subject_statuses = 'Deceased' |
Write SQL query to solve given problem: Of the black officers, how many of them investigated cases between the years 2010 and 2015?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT COUNT(T1.case_number) FROM officers AS T1 INNER JOIN incidents AS T2 ON T2.case_number = T1.case_number WHERE T1.race = 'B' AND T2.date BETWEEN '2010-01-01' AND '2015-12-31' |
Write SQL query to solve given problem: How many instances were found in June 2015?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT COUNT(case_number) FROM incidents WHERE date BETWEEN '2015-06-01' AND '2015-06-30' |
Write SQL query to solve given problem: How many people were injured between 2006 and 2014 as a result of a handgun?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT COUNT(location) FROM incidents WHERE subject_weapon = 'Handgun' AND subject_statuses = 'Injured' AND date BETWEEN '2006-01-01' AND '2013-12-31' |
Write SQL query to solve given problem: What is the most common type of weapon that causes death?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT subject_weapon FROM incidents WHERE subject_statuses = 'Deceased' GROUP BY subject_weapon ORDER BY COUNT(case_number) DESC LIMIT 1 |
Write SQL query to solve given problem: What is the proportion of white males and females in the police force?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(gender = 'M') AS REAL) / SUM(gender = 'F') FROM officers WHERE race = 'W' |
Write SQL query to solve given problem: How many more black female victims than white female victims were discovered?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT SUM(race = 'B') - SUM(race = 'W') FROM subjects WHERE gender = 'F' |
Write SQL query to solve given problem: What percentage of deaths were caused by rifles?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(subject_statuses = 'Deceased') AS REAL) * 100 / COUNT(case_number) FROM incidents WHERE subject_weapon = 'Rifle' |
Write SQL query to solve given problem: Which type of weapon was used to attack the victim in the record number 031347-2015? What is the victim's race and gender?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT T1.subject_weapon, T2.race, T2.gender FROM incidents AS T1 INNER JOIN subjects AS T2 ON T1.case_number = T2.case_number WHERE T1.case_number = '031347-2015' |
Write SQL query to solve given problem: Which near-death incident did a policeman by the name of Ruben Fredirick look into? What is the victim in this incident's race and gender?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT T1.case_number, T3.race, T3.gender FROM incidents AS T1 INNER JOIN officers AS T2 ON T1.case_number = T2.case_number INNER JOIN subjects AS T3 ON T1.case_number = T3.case_number WHERE T2.first_name = 'Fredirick' AND T2.last_name = 'Ruben' |
Write SQL query to solve given problem: What proportion of male police officers looked into events where people were injured?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | shooting | SELECT CAST(SUM(T2.gender = 'M') AS REAL) * 100 / COUNT(T1.case_number) FROM incidents T1 INNER JOIN officers T2 ON T1.case_number = T2.case_number WHERE T1.subject_statuses = 'Injured' |
Write SQL query to solve given problem: For the genes that are located in the plasma membrane, please list their number of chromosomes.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT T1.Chromosome FROM Genes AS T1 INNER JOIN Classification AS T2 ON T1.GeneID = T2.GeneID WHERE T2.Localization = 'plasma membrane' |
Write SQL query to solve given problem: How many non-essential genes are located in the nucleus?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT COUNT(T1.GeneID) FROM Genes AS T1 INNER JOIN Classification AS T2 ON T1.GeneID = T2.GeneID WHERE T2.Localization = 'nucleus' AND T1.Essential = 'Non-Essential' |
Write SQL query to solve given problem: Among the genes with nucleic acid metabolism defects, how many of them can be found in the vacuole?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT COUNT(T1.GeneID) FROM Genes AS T1 INNER JOIN Classification AS T2 ON T1.GeneID = T2.GeneID WHERE T2.Localization = 'vacuole' AND T1.Phenotype = 'Nucleic acid metabolism defects' |
Write SQL query to solve given problem: Please list the location of the genes that have the most chromosomes.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT T2.Localization FROM Genes AS T1 INNER JOIN Classification AS T2 ON T1.GeneID = T2.GeneID ORDER BY T1.Chromosome DESC LIMIT 1 |
Write SQL query to solve given problem: Among the pairs of genes that are both located in the nucleus, what is the highest expression correlation score?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT T2.Expression_Corr FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 INNER JOIN Genes AS T3 ON T3.GeneID = T2.GeneID2 WHERE T1.Localization = 'nucleus' AND T3.Localization = 'nucleus' ORDER BY T2.Expression_Corr DESC LIMIT 1 |
Write SQL query to solve given problem: What are the functions of the pair of genes that have the lowest expression correlation score?a. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT T1.Function FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 ORDER BY T2.Expression_Corr ASC LIMIT 1 |
Write SQL query to solve given problem: Among the pairs of genes that are not from the class of motorproteins, how many of them are negatively correlated?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT COUNT(T1.GeneID) FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T2.Expression_Corr < 0 AND T1.Class = 'Motorproteins' |
Write SQL query to solve given problem: For the pairs of genes with one having 8 chromosomes and the other having 6 chromosomes, what is the highest expression correlation score?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT T2.Expression_Corr FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T1.Chromosome = 6 OR T1.Chromosome = 8 ORDER BY T2.Expression_Corr DESC LIMIT 1 |
Write SQL query to solve given problem: Please list the motif of the genes that are located in the cytoplasm and have 7 chromosomes.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT T2.GeneID1, T2.GeneID2 FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T1.Localization = 'cytoplasm' AND T1.Chromosome = 7 |
Write SQL query to solve given problem: For the non-essential genes whose functions are transcription, how many of them are not located in the cytoplasm?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT COUNT(T1.GeneID) FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T1.Localization != 'cytoplasm' AND T1.Function = 'TRANSCRIPTION' AND T1.Essential = 'NON-Essential' |
Write SQL query to solve given problem: How many pairs of positively correlated genes are both non-essential?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT COUNT(T2.GeneID2) FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T2.Expression_Corr > 0 AND T1.Essential = 'Non-Essential' |
Write SQL query to solve given problem: If a pair of genes is positively correlated, what is the possibility of it being composed of two genes both with over 10 chromosomes?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT CAST(SUM(IIF(T1.Chromosome > 10 AND T3.Chromosome > 10, 1, 0)) AS REAL) * 100 / COUNT(T1.GeneID) FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 INNER JOIN Genes AS T3 ON T3.GeneID = T2.GeneID2 WHERE T2.Expression_Corr > 0 |
Write SQL query to solve given problem: Lists all genes by identifier number located in the cytoplasm and whose function is metabolism.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT DISTINCT GeneID FROM Genes WHERE Localization = 'cytoplasm' AND Function = 'METABOLISM' |
Write SQL query to solve given problem: How many different genes do we have if we add those located in the plasma and in the nucleus?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT COUNT(GeneID) FROM Classification WHERE Localization IN ('plasma', 'nucleus') |
Write SQL query to solve given problem: What kind of expression correlation occurs in physical type interacting gene pairs and what percentage of these are negatively correlated?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT Expression_Corr FROM Interactions WHERE Type = 'Physical' UNION ALL SELECT CAST(SUM(Expression_Corr < 0) AS REAL) * 100 / COUNT(*) FROM Interactions WHERE Type = 'Physical' |
Write SQL query to solve given problem: What percentage of genes located in the cytoskeleton are of unknown class? And of these, how many are not conditional phenotypes?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT SUM(Localization = 'cytoskeleton' AND Phenotype = 'Conditional phenotypes') , CAST(SUM(Localization = 'cytoskeleton') AS REAL) * 100 / COUNT(GeneID) FROM Genes; |
Write SQL query to solve given problem: List all genes whose interaction is with genes located in the nucleus in which it is positively correlated.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT T1.GeneID FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T2.Expression_Corr > 0 AND T1.Localization = 'nucleus' |
Write SQL query to solve given problem: Taking all the essential genes of the transcription factors class located in the nucleus as a reference, how many of them carry out a genetic-type interaction with another gene? List them.. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT T2.GeneID1 FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T1.Localization = 'nucleus' AND T1.Class = 'Transcription factors' AND T1.Essential = 'Essential' AND T2.Expression_Corr != 0 |
Write SQL query to solve given problem: Of all the nonessential genes that are not of the motorprotein class and whose phenotype is cell cycle defects, how many do not have a physical type of interaction?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT COUNT(T1.GeneID) FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T2.Type != 'Physical' AND T1.Phenotype = 'Cell cycle defects' AND T1.Class != 'Motorproteins' AND T1.Essential = 'Non-Essential' |
Write SQL query to solve given problem: Of the genes whose phenotype and motif are nucleic acid metabolism defects, PS00107, what percentage perform positive interaction with another gene?. Keep the solution inside sql tag ```sql [SQL-Query] ``` | genes | SELECT CAST(SUM(IIF(T2.Expression_Corr > 0, 1, 0)) AS REAL) * 100 / COUNT(T2.GeneID1) FROM Genes AS T1 INNER JOIN Interactions AS T2 ON T1.GeneID = T2.GeneID1 WHERE T1.Phenotype = 'Nucleic acid metabolism defects' AND T1.Motif = 'PS00107' |
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