Python, using subprocess.Popen to make linux command line call? I'm getting "[Errno 2] No such file or directory"
Question: I'm trying to follow the info I can find about subprocess.Popen as I want to
make a linux command line call.. I am trying as below but am getting the error
"[Errno 2] No such file or directory". I'm not trying to open a file so I
don't understand this error, and it works fine (although with other issues
relating to waiting for the process to finish when I don't want it to) when I
use a regular os.popen.

I can't seem to figure out how to do this properly, any advice is appreciated.

EDIT: THE COMMAND I AM USING IS COMPLEX AND VARIABLIZED, it would be too out-
of-context to include it here, I think its suffice to say that the code works
when I use `os.popen` and not when I do the new way, so no, the "linux command
line call" is obviously not the call I am using

    
    
    subprocess.Popen([r"linux command line call"])
    >>> [Errno 2] No such file or directory
    


Answer: 
    import subprocess    
    proc=subprocess.Popen(['ls','-l'])  # <-- Change the command here
    proc.communicate()
    

`Popen` expects a list of strings. The first string is typically the program
to be run, followed by its arguments. Sometimes when the command is
complicated, it's convenient to use `shlex.split` to compose the list for you:

    
    
    import shlex
    proc=subprocess.Popen(shlex.split('ls -l'))  
    proc.communicate()
    

