How to parse a list in python using re
Question: I am trying to parse a list to get the individual images returned by the bash
script (stored in the list errors in py script). How can I do this with "re" ?

**bash script**

    
    
    #!/bin/bash
    value(){
    for entry in *
    do
    if expr "$(file -b $entry)" : 'JPEG ' >/dev/null; 
    then
        echo -e "$entry"
    fi  
    done
    }
    value
    

**python code**

    
    
    import subprocess
    errors = [subprocess.check_output(['/black.sh'])]
    print errors
    

**Output**

    
    
    11_37_24.jpeg
    11_38_02.jpeg
    11_39_56.jpeg
    11_40_20.jpeg
    11_40_32.jpeg
    11_45_03.jpeg
    

The list `"errors"` is getting assigned a string of length 1:

    
    
    errors = ["11_37_24.jpeg 11_38_02.jpeg 11_39_56.jpeg 11_40_20.jpeg 11_40_32.jpeg 11_45_03.jpeg"]
    

However, I want to get those images separately to use it in an html page. How
can I do that with "re"? Is there any other alternative?


Answer: I make a few assumptions (based on the example input you give):

  * file names only contain digits and underscores (so I can use `\w` in regex)
  * words in a file name are always concatenated by underscores (no spaces)
  * every file is a jpeg file

The code:

    
    
    import re
    
    errors = ["11_37_24.jpeg 11_38_02.jpeg 11_39_56.jpeg 11_40_20.jpeg 11_40_32.jpeg 11_45_03.jpeg"]
    
    re.findall('\w+\.jpeg', errors[0])
    ['11_37_24.jpeg', '11_38_02.jpeg', '11_39_56.jpeg', '11_40_20.jpeg', '11_40_32.jpeg', '11_45_03.jpeg']
    

If my assumptions are wrong for your project, `re` is probably not the way to
go.

**EDIT**

The OP used the following code (which was given in the comments):

    
    
    errors[0].split('\n')
    

