Is there any way to run three python files sequentially as the output of each file depends on the other
Question: I have three python files `file1.py`, `file2.py`, `file3.py`. Each file will
generate a `.csv` file and will give it to the other file sequentially. To
elaborate `file1.py` will generate `file1.csv` and this `.csv` file will be
the input of `file2.py` and so on.

    
    
     import file1
     import file2
     import file3
    
     file1
     file2
     file3
    
     IOError: File file2.csv does not exist
    

The problem is when I import `file2.py`,there is no `file1.csv` as it is yet
to be executed. Please let me how to call each one sequentially without even
reading the next python file.


Answer: Each of your scripts should be set up as a function or class that generates
the file. The general structure could be something like this:

    
    
    # file1.py
    def generate_csv(filename):
        # put your file generation code here
        # you could easily use Python's csv module, for example
        return csv_filename
    

Then in your main script you can call each of your scripts, like this:

    
    
    # main.py
    import file1, file2, file3
    
    def main(filename):
        fname_one = file1.generate_csv(filename)
        fname_two = file2.generate_csv(fname_one)
        fname_three = file3_generate_csv(fname_two)
    

This keeps your original scripts from being run when imported. Your main
script controls the order of execution and can do whatever needs to be done to
the 3rd file name that is returned.

