How to create a loop that shuts down when given answer in python?
Question: what I am wanting to do is randomly generate two numbers that equal a given
number. Yet to allow for this to get the desired answer I want it to be
random. That is the problem.

    
    
    a=(1,2,3,4,5,6,7,8,9,)
    from random import choice
    b=choice(a)
    c=choice(b)
    d= c+b
    if d == 10:
    #then run the rest of the program with the value's c and b in it
    #probably something like sys.exit goes here but I am not sure to end \/
    else:
    # i have tryied a few things here but I am not sure what will loop it around*
    

* * *

(thanks for the help :D)

I have know created a list called 'right' and know trying to append values a
and b to the list yet that is not working. For I am knowing running the
program _'in for trail in range(100)'_ so I get the answer. Yet the values are
not appending into the new list right. Which is the problem. Then what I am
going to do it read values 0 and 1 in the list right and then use them.(sorry
its not that well done for at school) **This is for fractions not adding to a
given variable. This bit second but is.**

    
    
    import sys
    right=(0)
    y=x+x
    from trail in range(y)
    a=(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20)
    from random import choice 
    A=choice(a)
    B=choice(a)
    d=A/B
    if d==1:
        right.append(A)
        right.append(B)
    else:
        x.append(1)
    


Answer: 
     from random import choice
    
     a = range(1, 10)
     b = c = 0
     while b + c != 10:
         b = choice(a)
         c = choice(a)  # You meant choice(a) here, right?
    

But this accomplishes the same thing:

    
    
     b = choice(a)
     c = 10 - b
    

For decimal numbers betweeen 0 and 10:

    
    
    from random import uniform
    
    b = uniform(0, 10)
    c = 10 - b
    

