Trying to download data from URL with CSV File
Question: I'm slightly new to Python and have a question as to why the following code
doesn't produce any output in the `csv` file. The code is as follows:

    
    
    import csv
    import urllib2
    
    url = 'http://www.rba.gov.au/statistics/tables/csv/f17-yields.csv'
    response = urllib2.urlopen(url)
    cr = csv.reader(response)
    
    for row in cr:
        with open("AusCentralbank.csv", "wb") as f:
            writer = csv.writer(f)
            writer.writerows(row)
    

Cheers.

**Edit** :

Brien and Albert solved the initial issue I had. However, I now have one
further question. When I download the CSV File which I have listed above which
is in "<http://www.rba.gov.au/statistics/tables/#interest-rates>" under Zero-
coupon "Interest Rates - Analytical Series - 2009 to Current - F17" and is the
F-17 Yields CSV I see that it has 5 workbooks and I actually just want to
gather the data in the 5th Workbook. Is there a way I could do this? Cheers.


Answer: I could only test my code using Python 3. However, the only diffence should be
[`urllib2`](https://docs.python.org/2/library/urllib2.html#urllib2.urlopen),
hence I am using
[`urllib.respose`](https://docs.python.org/3.4/library/urllib.request.html#urllib.request.urlopen)
for opening the desired url.

The variable `html` is type `bytes` and can generally be written to a file in
binary mode. Additionally, your source is a csv-file already, so there should
be no need to convert it somehow:

    
    
    #!/usr/bin/env python3
    # coding: utf-8
    
    import urllib
    
    url = 'http://www.rba.gov.au/statistics/tables/csv/f17-yields.csv'
    
    response = urllib.request.urlopen(url)
    html = response.read()
    
    with open('output.csv', 'wb') as f:
            f.write(html)
    

