Is there a pythonic way to check whether OS is a 64bit Ubuntu?
Question: Is there a pythonic way to check whether OS is a 64bit Ubuntu?

Currently, I've been doing it as such:

    
    
    import os
    
    def check_is_linux(distro, architecture, err_msg):
        try:
            this_os = os.popen('lsb_release -d').read()
            this_arch = os.popen('uname -a').read()
            assert distro in this_os and architecture in this_arch, err_msg
        except:
            print(err_msg)
    
    def check_is_64bit_ubuntu(err_msg):
        check_is_linux('Ubuntu', 'x86_64', err_msg)
    


Answer: You can use the [`platform`
module](https://docs.python.org/2/library/platform.html) to get distribution
and processor information:

    
    
    import platform
    
    def is_linux(distro, architecture):
        if not platform.system() == 'Linux':
            return False
    
        if platform.linux_distribution()[0].lower() != distro:
            return False
    
        return platform.processor() == architecture
    
    def is_64bit_ubuntu():
        return is_linux('ubuntu', 'x86_64')
    
    if not is_64bit_ubuntu():
        print(err_msg)
    

