New regex module fuzzy function error value. Python
Question: im trying out the fuzzy function of the new regex module. in this case, i want
there to find a match for all strings with <= 1 errors, but i'm having trouble
with it

    
    
    import regex
    
    statement = 'eol the dark elf'
    test_1 = 'the dark'
    test_2 = 'the darc' 
    test_3 = 'the black'
    
    print regex.search('{}'.format(test_1),statement).group(0) #works
    
    >>> 'the dark' 
    
    print regex.search('{}'.format(test_1){e<=1},statement).group(0)
    
    >>> print regex.search('{}'.format(test_1){e<=1},statement).group(0) #doesn't work 
                                              ^
    SyntaxError: invalid syntax 
    

i have also tried

    
    
    print regex.search('(?:drk){e<=1}',statement).group(0) #works
    >>> 'dark'
    

but this . . .

    
    
    print regex.search(('(?:{}){e<=1}'.format(test_1)),statement).group(0) #doesn't work
    >>> SyntaxError: invalid syntax
    


Answer: In your first snippet, you forgot to put the `{e<=1}` in a string. In your
final snippet, I think the problem is, that `format` tries to deal with the
`{e<=1}` itself. So either you use concatenation:

    
    
    print regex.search(test_1 + '{e<=1}', statement).group(0)
    

or you escape the literal braces, by doubling them:

    
    
    print regex.search('{}{{e<=1}}'.format(test_1), statement).group(0)
    

This can then easily be extended to

    
    
    print regex.search('{}{{e<={}}}'.format(test_1, num_of_errors), statement).group(0)
    

