Python's trigonmetric function return unexpected values
Question: 
    import math
    print "python calculator"
    print "calc or eval"
    while 0 == 0:
        check = raw_input() #(experimental evaluation or traditional calculator)
        if check == "eval":
            a = raw_input("operator\n") #operator
            if a == "+":
                b = input("arg1\n") #inarg1
                c = input("arg2\n") #inarg2
                z = b + c
                print z
            elif a == "-":
                b = input("arg1\n") #inarg1
                c = input("arg2") #inarg2
                z = b - c
                print z
            elif a == "/":
                b = input("arg1\n") #inarg1
                c = input("arg2\n") #inarg2
                z = b / c
                print z
            elif a == "*":
                b = input("arg1\n") #inarg1
                c = input("arg2]n") #inarg2
                z = b * c
                print z
            elif a == "^":
                b = input("arg1\n") #inarg1
                c = input("arg2\n") #inarg2
                z = b ** c
            elif a == "sin":
                b = input("arg1\n") #inarg1
                var = math.degrees(math.sin(b))
                print var
            elif a == "asin":
                b = input("arg1\n") #inarg1
                var = math.degrees(math.asin(b))
                print var
            elif a == "cos":
                b = input("arg1\n") #inarg1
                var = math.degrees(math.cos(b))
                print var
            elif a == "acos":
                b = input("arg1\n") #inarg1
                var = math.degrees(math.acos(b))
                print var
            elif a == "tan":
                b = input("arg1\n") #inarg1
                var = math.degrees(math.tan(b))
                print var
            elif a == "atan":
                b = input("arg1\n") #inarg1
                var = math.degrees(math.atan(b))
                print var
        elif check == "calc" :
            x = input() #takes input as expression
            print x #prints expression's result
    

Isn't the sine of 90 degrees 1? With this it shows up as something around
51.2? Google's calculator does this too? BTW: this is my python calculator

    
    
                b = input("arg1\n") #inarg1
                var = math.degrees(math.sin(b))
                print var
    

This one and other trig functions are the problem. For the most part, this was
just a simple python calculator, but I wanted to add some trig functions.


Answer: You don't want o convert the return value of `sin()` to degrees -- the return
value isn't an angle. You instead want to convert the argument to radians,
since `math.sin()` expects radians:

    
    
    >>> math.sin(math.radians(90))
    1.0
    

