python regular expression match comma
Question: In the following string,how to match the words including the commas

  1. \--
    
        process_str = "Marry,had ,a,alittle,lamb"
    import re
    
    re.findall(r".*",process_str)
    ['Marry,had ,a,alittle,lamb', '']
    

  2. \--
    
        process_str="192.168.1.43,Marry,had ,a,alittle,lamb11"
    
    import re
    ip_addr = re.findall(r"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}",l)          
    re.findall(ip_addr,process_str1)
    

How to find the words after the ip address excluding the first comma only i.e,
the outout again is expected to be `Marry,had ,a,alittle,lamb11`

  3. In the second example above how to find if the string is ending with a digit.


Answer: In the second example, you just need to capture (using `()`) everything that
follows the ip:

    
    
     import re
    
     s = "192.168.1.43,Marry,had ,a,alittle,lamb11"
     text = re.findall(r"\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3},(.*)", s)[0]
     // text now holds the string Marry,had ,a,alittle,lamb11
    

To find out if the string ends with a digit, you can use the following:

    
    
    re.match(".*\d$", process_str)
    

That is, you match the entire string (`.*`), and then backtrack to test if the
last character (using `$`, which matches the end of the string) is a digit.

