I need to load an excel file into python 2.7 using an interface
Question: in order to do some operations with it but I would like to do it from an
interface in order to select the file instead of just running a script with
the name of the file, as the file name will change every day.


Answer: You can use Tkinter `askopenfilename` :

    
    
    from tkFileDialog import askopenfilename
    
    path = askopenfilename()
    
    f = open(path, 'r') # OR DO WHAT YOU WANT WITH PATH
    

