Passing in arguments to a called script
Question: I'm running `nosetests` on my project with `--with-snort` for Growl
notifications.

The problem is that I have some lib files that I put on the path, so I have a
custom python script at `bin/python`.

I have no issues running nose via my `bin/python` by doing `which nosetests`
and using that executable - `bin/python /usr/local/bin/nosetests`. But now how
do I pass in flags to `nosetests`? Any flags will go to `bin/python` instead.


Answer: What makes you think that flags will go to `bin/python`? Have you tested this?
If I write a simple program to test this out:

    
    
    import sys
    print sys.argv[1:]
    

I get the following ouput from these example calls (assuming I have saved this
in a file called test.py)

`python test.py` prints `[]`

`python test.py 5` prints `['5']`

`python -i test.py 5` prints `['5']` (and then passes control to the
interpreter because of the `-i` flag).

So flags **before** the script name are passed to Python, flags **after** the
script name are passed to the script. So in your example, just use

    
    
    bin/python /usr/local/bin/nosetests --with-snort
    

Some of this is convered in [Invoking the
Interpreter](http://docs.python.org/tutorial/interpreter.html) in Python's
documentation.

