Python quick search in numpy array
Question: Does Numpy have a function for quick search of element in 2D array and return
its indexes? Mean for example:

    
    
    a=54
    array([[ 0,  1,  2,  3],
          [ 4,  5,  54,  7],
          [ 8,  9, 10, 11]])
    

So equal value will be `array[1][2]`. Of course I can make it using simple
loops- but I want something similar to:

    
    
       if 54 in arr
    


Answer: 
    In [4]: import numpy as np 
    
    In [5]: my_array = np.array([[ 0,  1,  2,  3],
                                 [ 4,  5,  54,  7],
                                 [8, 54, 10, 54]])
    
    In [6]: my_array
    Out[6]: 
    array([[ 0,  1,  2,  3],
           [ 4,  5, 54,  7],
           [ 8, 54, 10, 54]])
    
    In [7]: np.where(my_array == 54) #indices of all elements equal to 54
    Out[7]: (array([1, 2, 2]), array([2, 1, 3])) #(row_indices, col_indices)
    
    In [10]: temp = np.where(my_array == 54)
    
    In [11]: zip(temp[0], temp[1])   # maybe this format is what you want
    Out[11]: [(1, 2), (2, 1), (2, 3)]
    

