Python: UUID in a list
Question: I have a list with a uuid4 in it. I also have a string. For example:

    
    
    list = [UUID('79d8f4b7-06a0-41d1-99d6-dd8c5308875f'), 'example1', 'example2']
    string = 79d8f4b7-06a0-41d1-99d6-dd8c5308875f
    

But when I try:

    
    
    if string in list:
        print("It's in!")
    else:
        print("It's not!")
    

The output is always "it's not".

I know there is probably a data type error going on but i cant seem to find it
myself. Any help is appreciated, i'm sure something this simple will be fixed
within seconds, thanks in advance.

_When I type print list[0] this is what is output:
79d8f4b7-06a0-41d1-99d6-dd8c5308875f. But even when i try say "..in list[0]",
it still doesn't work._


Answer: You need to convert
[`uuid`](https://docs.python.org/2/library/uuid.html#uuid.UUID) to string with
`str()` function .

    
    
    >>> import uuid
    >>> x=uuid.uuid4()
    >>> str(x)
    '924db46b-5c51-4330-861c-363570ea9ef6'
    

and for check you need to convert string to uuid ,with `uuid.UUID` but as this
function accept bytes you need to pass the bytes of your string to it :

    
    
    >>> my_list = [x, 'example1', 'example2']
    >>> uuid.UUID(bytes=x.bytes) in my_list
    True
    

