python program for fetching link from a page
Question: I am trying to download an entire play list for Android development tutorial
from Youtube. So I used [savefrom](http://en.savefrom.net/) for generating
playlist for download. But the problem is that I have so many videos in that
playlist. So, I decided to write a python script for making this work simpler.
But the problem is it uses Java Script to generate the link so I cant able to
fetch generated link using javascript()

Example: <http://ssyoutube.com/watch?v=AfleuRtrJoA> It takes 5 sec to generate
download links.

I want to get page source only after 5 sec **from the browse**.

For this kind of work I found a good package named
[selenium](https://pypi.python.org/pypi/selenium).

    
    
    import time
    from selenium import webdriver
    
    def savefromnotnet(url):
        browser = webdriver.Firefox() # Get local session of firefox
        browser.get(url) # Load page
        time.sleep(5) # Let the page load, will be added to the API
        return browser.page_source()
    
    source = savefromnotnet("http://ssyoutube.com/watch?v=AfleuRtrJoA")
    

The `savefromnotnet` function open's Firefox and it will request the url, up
to this every thing works fine. But when I want to get page source
`browser.page_source()` it shows the following error.

    
    
    Traceback (most recent call last):
      File "<stdin>", line 1, in <module>
      File "C:\Python27\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 523, in runfile
        execfile(filename, namespace)
      File "C:\Users\BK\Desktop\Working Folder\Python Temp\temp.py", line 10, in <module>
        source = savefromnotnet("http://ssyoutube.com/watch?v=AfleuRtrJoA")
      File "C:\Users\BK\Desktop\Working Folder\Python Temp\temp.py", line 8, in savefromnotnet
        return browser.page_source()
    TypeError: 'unicode' object is not callable
    


Answer: Error occured on following line.

    
    
    return browser.page_source()
    

I think brackets did not need.

    
    
    return browser.page_source
    

