Split numpy array object into two different size vectors using C
Question: I have

X as input --- this is dtype object this is of following structure
x=[[1,2,3,4...n elements],[1 element],[1,2,...m elements],[1 element]]

To mimic the input...

    
    
    >>> from numpy import *
    >>> x=array([array([1,2,3,4,5]),array([1]),array([1,2,3,4,5,6,7,8]),array([1])],dtype=object)
    >>> x
    array([[1 2 3 4 5], [1], [1 2 3 4 5 6 7 8], [1]], dtype=object)
    

I passing X as an argument to my Python C extension as PyArray_Object

    
    
    static PyObject* samp(PyObject *self, PyObject *args) {
    
        PyArrayObject *array,*p1,*p2;
        int n,j;
    
        if (!PyArg_ParseTuple(args, "O!",&PyArray_Type, &array))
            return NULL;
        n=array->nd;
    
        if(n!=1 || array->descr->type_num!=PyArray_OBJECT) {
            PyErr_SetString(PyExc_ValueError, "array must be one-dimensional and of Object type");
            return NULL;
        }
        j=array->dimensions[0];
        /* ...... */
    }
    

Now I am stuck here as I m not sure how to split this into 4 objects Please
kindly can anyone give me few pointers on this...


Answer: Originally you had an array of four arrays. The following line extracts it
into four array variables:

`a,b,c,d=x[0],x[1],x[2],x[3]`

If you need native Python objects instead of numpy arrays, use list
comprehension:

`objs = [y for y in a]`

