Python dictionary converting to json or yaml
Question: I have parsed a string and converted into a dictionary. however I would like
to be able to get more information from my dictionary and I was thinking
creating a son file or yaml file would be more useful. please feel free to
comment on another way of solving this problem.

    
    
    import re
    regex = '(\w+) \[(.*?)\] "(.*?)" (\d+) "(.*?)" "(.*?)"'
    sample2= 'this [condo] "number is" 28 "owned by" "james"'
    patern = '(?P<host>\S+)\s(?P<tipe>\[\w+\])\s(?P<txt>"(.*?))\s(?P<number>\d+)\s(?P<txt1>"\w+\s\w+")\s(?P<owner>"\w+)'
    m =re.match(patern, sample2)
    res = m.groupdict()
    print res
    

and I would get:

    
    
    {'tipe': '[condo]', 'number': '28', 'host': 'this', 'owner': '"james', 'txt': '"number is"', 'txt1': '"owned by"'}
    

I would like to be able to sort by owner name and write out the type of house
and the house number. for example:

James:{ type:condo, number: 28}

or any other suggestions?


Answer: The question of json vs yaml boils down to what are you doing with the data
you are saving? If you are reusing the data in JS or in another python script
then you could use JSON. If you were using it in something that uses YAML then
use YAML. But in terms of your question, unless there is a particular end game
or use case for your data, it doesn't matter the format, you could even just
do a typical TSV/CSV and it'd be the same.

To answer your question about how to make a dict in to a json.

From your example once you have the `res` dictionary made.

    
    
    import json
    with open('someFile.json', 'wb') as outfile:
         json.dump(res, outfile)
    

Your output file `someFile.json` will be your dictionary `res`

