soaplib with mod_wsgi without django, cherypy or other framework
Question: I checked soaplib for python on net and i get the example

    
    
    import soaplib
    from soaplib.core.service import rpc, DefinitionBase
    from soaplib.core.model.primitive import String, Integer
    from soaplib.core.server import wsgi
    from soaplib.core.model.clazz import Array
    
    
    class HelloWorldService(DefinitionBase):
        @soap(String,Integer,_returns=Array(String))
        def say_hello(self,name,times):
            results = []
            for i in range(0,times):
                results.append('Hello, %s'%name)
            return results
    
    if __name__=='__main__':
        try:
            from wsgiref.simple_server import make_server
            soap_application = soaplib.core.Application([HelloWorldService], 'tns')
            wsgi_application = wsgi.Application(soap_application)
            server = make_server('localhost', 7789, wsgi_application)
            server.serve_forever()
        except ImportError:
            print "Error: example server code requires Python >= 2.5"
    

this example is working fine. But i want to run this with the mod_wsgi in
apache. I checked net and all come with django, cherrypy or pylone. Is it
possible to run this example without any python web framwork? what are the
steps to follow to run this example under mod_wsgi in apache. I want to run
this in unix.


Answer: Like every other "Integration With" document in the
[wiki](http://code.google.com/p/modwsgi/w/list), except with `application =
wsgi.Application(soap_application)`.

