UNION ALL date on the same row I am unioning multiple tables together in Postgres, where the timestamp is slightly different, but the same if I round to the hour. Is it possible to make each union show on the same row, if the date is the same? Currently I'm getting duplicate rows of each date.

select date_trunc('hour', TO_TIMESTAMP(created / 1000)::timestamp), 
COALESCE(count(*), 0) as "1489",
null as "1616"
from actions
where group_id = 1489
and TO_TIMESTAMP(created / 1000)::timestamp &gt;= current_date-7
group by 1
union all
select date_trunc('hour', TO_TIMESTAMP(created / 1000)::timestamp), 
null as "1489",
COALESCE(count(*), 0) as "1616"
from actions
where group_id = 1616
and TO_TIMESTAMP(created / 1000)::timestamp &gt;= current_date-7
group by 1
order by 1


It returns:
You can use FULL JOIN like this:


SELECT
    COALESCE(a1.t, a2.t) as t,
    a1."1489",
    a2."1616"
FROM
(
    select 
        date_trunc('hour', TO_TIMESTAMP(created / 1000)::timestamp) as t, 
        COALESCE(count(*), 0) as "1489"
    from actions
    where group_id = 1489
        and TO_TIMESTAMP(created / 1000)::timestamp &gt;= current_date-7
    group by 1
) as a1
FULL JOIN
(
    select 
        date_trunc('hour', TO_TIMESTAMP(created / 1000)::timestamp) as t, 
        COALESCE(count(*), 0) as "1616"
    from actions
    where group_id = 1616
        and TO_TIMESTAMP(created / 1000)::timestamp &gt;= current_date-7
    group by 1
) as a2 ON (a1.t=a2.t)
ORDER BY 1;


Or just use CASE:


SELECT
    date_trunc('hour', TO_TIMESTAMP(created / 1000)::timestamp),
    SUM(CASE WHEN group_id=1489 THEN 1 ELSE 0 END) as "1489",
    SUM(CASE WHEN group_id=1616 THEN 1 ELSE 0 END) as "1616"
FROM actions
WHERE 
    group_id in (1489, 1616)
    AND TO_TIMESTAMP(created / 1000)::timestamp &gt;= current_date-7
GROUP BY 1
ORDER BY 1;