Select multiple values in LIKE Operator I have a SQL query given below, I want to select multiple value using like operator. 

Is my Query correct?

SELECT top 1 employee_id, employee_ident, utc_dt, rx_dt 
FROM       employee
INNER JOIN employee_mdata_history 
ON         employee.ident=employee_mdata_history.employee_ident 
WHERE      employee_id like 'emp1%' , 'emp3%' 
ORDER BY   rx_dt desc


If not, can anyone correct me?

My table has large amount of data starting with 'emp1' and 'emp3'. 
Can I filter the result by top 3 "emp1" and top 2 "emp3" based on rx_dt?
Alternatively you can try the following method:

SELECT
  x.*
FROM
  (
    VALUES
      ('emp1%', 3),
      ('emp3%', 2)
  ) AS v (pattern, row_count)
  CROSS APPLY
  (  -- your query
    SELECT top (v.row_count)
               employee_id, employee_ident, utc_dt, rx_dt 
    FROM       employee
    INNER JOIN employee_mdata_history
    ON         employee.ident=employee_mdata_history.employee_ident 
    WHERE      employee_id like v.pattern
    ORDER BY   rx_dt desc
  ) AS x
;


The VALUES row constructor represents your pattern list as a table, additionally supplying each pattern with the number of rows to retrieve for that pattern. The CROSS APPLY operator applies your query to every row of the pattern list, i.e. to every pattern, limiting the number of rows for each pattern to the corresponding value from the pattern list.

As a side note, please let me take this opportunity to suggest that you always qualify your columns with the table alias in a query that is reading from two or more tables. That makes your query easier to read/understand. You can always use short aliases to avoid repeating potentially long table names. For instance:

SELECT TOP (1)
  e.employee_id,
  h.employee_ident,
  ...
FROM
  dbo.employee AS e
  INNER JOIN dbo.employee_mdata_history AS h
    ON e.ident = h.employee_ident
WHERE
  e.employee_id LIKE ...
ORDER BY
  ...