Count consecutive null rows from a joined table I have the following tables:

members:
----------------------------------------------
| member_id | member_name | member_join_date |
----------------------------------------------  

events:
-------------------------
| event_id | event_name |
-------------------------

event_dates:
--------------------------------------
| event_id | event_date | event_week |
--------------------------------------

attendance:
------------------------------------------------------------
| member_id | event_id | attendance_date | attendance_week |
------------------------------------------------------------


So I have members who joined the organization at a certain time and they may attend weekly events (the occurrences of which are monitored by the event_dates table)

What I want to do is get all members that have at least 3-consecutive absences

I did all I could and I think I have each part of the query but don't know how to merge them together.

Get all events that they could've attended:

    SELECT
      m.member_id AS id,
      ed.event_id,
      ed.event_week
    FROM
      members AS m
      LEFT JOIN
        event_dates AS ed
        ON
          ed.event_date &gt;= m.member_join_date


Get all the events they actually attended:

    SELECT
      m.member_id AS id,
      a.event_id
    FROM
      members AS m
      LEFT JOIN
        attendance AS a
        ON
          a.member_id = m.member_id


And probably the answer to this question if I manage to merge the two queries into one:

https://stackoverflow.com/questions/1321670/count-of-consecutive-not-null-values

But this time I want to count NULL values
This is essentially a gaps-and-islands problem. And when I have my SQL Server hat on, I often solve this kind of problem with two ROW_NUMBER() calls. Sadly, MySQL, unlike many other major SQL products, does not support ROW_NUMBER(), nor any other ranking function. To make up for that, however, you can use variable assignment in SELECTs, which MySQL does support (unlike many other major SQL products).

Below is a solution followed by an explanation:

SELECT
  member_id,
  member_name,
  event_id,
  COUNT(*) AS consecutive_times_missed,
  MIN(event_date) AS first_date_missed,
  MAX(event_date) AS last_date_missed
FROM (
  SELECT
    member_id,
    member_name,
    event_id,
    event_date,
    is_missed,
    @occ_ranking := (event_id = @last_event) * (member_id = @last_member) * @occ_ranking + 1,
    @att_ranking := (event_id = @last_event) * (member_id = @last_member)
                                             * (is_missed = @last_missed) * @att_ranking + 1,
    @occ_ranking - @att_ranking AS grp,
    @last_member := member_id,
    @last_event  := event_id,
    @last_missed := is_missed
  FROM (
    SELECT
      m.member_id,
      m.member_name,
      e.event_id,
      e.event_date,
      (a.attendance_date IS NULL) AS is_missed
    FROM       members     m
    INNER JOIN event_dates e ON m.member_join_date &lt;= e.event_date
    LEFT  JOIN attendance  a ON m.member_id = a.member_id
                            AND e.event_id = a.event_id
                            AND e.event_date = a.attendance_date,
    (
      SELECT
        @occ_ranking := 0,
        @att_ranking := 0,
        @last_member := 0,
        @last_event  := 0,
        @last_missed := 0
    ) v
    ORDER BY
      m.member_id,
      e.event_date
  ) s
) s
WHERE
  is_missed = 1
GROUP BY
  member_id,
  member_name,
  event_id,
  grp
HAVING
  COUNT(*) &gt;= 3
;


Basically, you start with joining members and event_dates to get all the event occurrences the members could have attended based on their membership dates. Then you throw in the attendance table (via a left join) to flag the missed occurrences. Here's an example of what you get by this time:

member_id  event_id  event_date  is_missed
---------  --------  ----------  ---------
1          1         2012-07-10  0
2          1         2012-07-10  1
1          1         2012-07-14  0
2          1         2012-07-14  1
…          …         …           …


At this point, the resulting set needs to be sorted by member_id, event_id, because that is crucial to the subsequent rankings calculation.

Two different rankings are produced for every row. One is a ranking within the row's partition of (member_id, event_id) (it is reset as soon as a new event or a new member is encountered). The other is a ranking within the specific group of consecutive event occurrences, either attended or missed, that the row belongs to (this ranking, in addition to being reset upon coming across a new member or event, also gets reset whenever the other group is encountered). And so you get something like this:

member_id  event_id  event_date  is_missed  ranking1  ranking2
---------  --------  ----------  ---------  --------  --------
…          …         …           …          …         …
1          1         2012-07-27  0          4         4
1          1         2012-07-28  0          5         5
1          1         2012-07-29  1          6         1
2          1         2012-07-10  1          1         1
2          1         2012-07-14  1          2         2
2          1         2012-07-25  1          3         3
2          1         2012-07-27  0          4         1
…          …         …           …          …         …


As you may have noticed, the difference between the two ranking numbers is constant throughout the particular group of consecutive event occurrences of the same kind ("attended" or "missed") and is also unique for that group within its partition. Therefore, every such group can be identified by member_id, event_id and the just mentioned difference.

And it now remains simply to filter the events leaving just the missed ones, group the rows and get the necessary aggregated data, like the number of rows and, possibly, as in the query above, the dates of the first and the last event occurrence in the group. The number of rows is also used in an additional filter condition to omit groups with fewer rows than required.