How could you split a string at index 0 of all sublists into separate elements, and have each of the split elements be contained within a copy of the original sublist? 

For example:

```
Original_List = [['a,b','c','d','e','f'],['1','2','3'],['z,y','1','2']]

```

Desired Result: 

```
Desired_List = [['a','c','d','e','f'],['b','c','d','e','f'],['1','2','3'],['z','1','2'],['y','1','2']]

```

Also, to add further clarity with one more actual example:

```
Original_List = [['Contract_ID1,Contract_ID2','Amount','Date'],['Contract_ID3,Contract_ID4','400','Jan1']]

```

I want every sublist to have only one Contract\_ID, but still have the Amount and Date Associated with it

```
Desired_List =  [['Contract_ID1','Amount','Date'],['Contract_ID2','Amount','Date'],['Contract_ID3','400','Jan1'],['Contract_ID4','400','Jan1']]

```

I can split all strings at index 0 of all sublists with the below, but I can't figure out how I would duplicate the whole list for each split element and then replace the strings that were split with the split element, so that each split element had its own list. 

```
Split_First_Indices_of_Sublists = map(lambda x: x[0].split(","),Original_List)
>>[['a', 'b'], ['1'], ['z', 'y']]
for x in Original_List:
     x.pop(0)
>> [['c', 'd', 'e', 'f'], ['2', '3'], ['1', 2]]

```