Can someone help me with this proof?

Prove that for $n≥1$, $\displaystyle\sum\_{i=1}^n \dfrac 1 {i^2} \le 2 -\dfrac 1 n$.

The Base Case is easy but for my induction step, I get stuck at...

```
          (sum from i=1 to k+1 of 1/i^2) ≤ 2 - 1/(k+1)
(sum from i=1 to k of 1/i^2) + 1/(k+1)^2 ≤ 2 - 1/(k+1)

```