I need to solve this homework problem and don't know how to get the solution in terms of $y$:

$$yy'''+(3y'-2y)y''-2(y')^2+yy'+x-2=2xe^x$$ 

with the help of the substitution: 

$$z=yy'+x$$ and initial conditions:$$y(0)=y'(0)=y''(0)=1$$

Any help would be greatly appreciated!