There must be a simpler, more pythonic way of doing this. 

Given this list of pairs:

```
pp = [('a',1),('b',1),('c',1),('d',2),('e',2)]

```

How do I most easily find the first item in adjacent pairs where the second item changes (here, from 1 to 2). Thus I'm looking for ['c','d']. Assume there will only be one change in pair[1] for the entire list, but that it may be a string.

This code works but seems excruciatingly long and cumbersome.

```
for i, pair in enumerate(pp):
    if i == 0: 
        pInitial = pair[0] 
        sgInitial = pair[1]
    pNext = pair[0]
    sgNext = pair[1]
    if sgInitial == sgNext:
        sgInitial = sgNext
        pInitial = pNext
    else:
        pOne = pInitial
        pTwo = pNext
        x = [pOne, pTwo]
        print x
        break

```

Thanks
Tim