How i can read 4th Value(inside "" i.e "vV0...." using Regex in below condition ?

I am updating a bit this part - Is it possible to first find Word "LaunchFileUploader" and then select the 4th Value, if there are multiple instance of LaunchFileUploader in the file just select 4th Value of first word found ? Attaching screenshot of file where this needs to be searched (In the file word is "LaunchFileUploader")

[![enter image description here](https://i.stack.imgur.com/OY2rv.png)](https://i.stack.imgur.com/OY2rv.png)

I tried this but it gives as - I need 4th value (Group 1 is giving me third value)

```
\bLaunchFileUploader\b(\:?.*?,){3}.*?\)

Match 1
Full match  11030-11428 LaunchFileUploader("ERM-1BLX3D04R10-0001", 1662, "2ecbb644-34fa-4919-9809-a5ff47594c2d", "8dZOPyHKBK...

Group 1.    n/a  "2ecbb644-34fa-4919-9809-a5ff47594c2d",

```

I am still looking for solution for this. Any help is aprreciated.