I asked a question earlier today ([jquery select2: error in getting data from php-mysql](https://stackoverflow.com/questions/35216302/jquery-select2-error-in-getting-data-from-php-mysql)). However, I am trying to fix it and doing that now I am getting bit strange issue. I am not sure why it is happening like this.

Below is the JavaScript code.

```
<div class="form-group">
   <label class="col-sm-4 control-label">Product Name</label>
   <div class="col-sm-6">       
      <input type="hidden" id="tags" style="width: 300px"/>
   </div>
</div>

<script type="text/javascript">
var lastResults = [];

$("#tags").select2({
    multiple: true,
    placeholder: "Please enter tags",
    tokenSeparators: [","],
    initSelection : function (element, callback) {
        var data = [];
        $(element.val().split(",")).each(function () {
            data.push({id: this, text: this});
        });
        callback(data);
    },
    ajax: {
        multiple: true,
        url: "fetch.php",
        dataType: "json",
        type: "POST",
      data: function(term) {
                        return {q: term};
                    },
                    results: function(data) {
                        return {results: data};
                    }, 

    },
    createSearchChoice: function (term) {
        var text = term + (lastResults.some(function(r) { return r.text == term }) ? "" : " (new)");
        return { id: term, text: text };
    },
});

$('#tags').on("change", function(e){
    if (e.added) {
        if (/ \(new\)$/.test(e.added.text)) {
           var response = confirm("Do you want to add the new tag "+e.added.id+"?");
           if (response == true) {
              alert("Will now send new tag to server: " + e.added.id);
              /*
               $.ajax({
                   type: "POST",
                   url: '/someurl&action=addTag',
                   data: {id: e.added.id, action: add},    
                   error: function () {
                      alert("error");
                   }
                });
               */
           } else {
                console.log("Removing the tag");
                var selectedTags = $("#tags").select2("val");
                var index = selectedTags.indexOf(e.added.id);
                selectedTags.splice(index,1);
                if (selectedTags.length == 0) {
                    $("#tags").select2("val","");
                } else {
                    $("#tags").select2("val",selectedTags);
                }
           }
        }
    }
});
</script>

```

Here is the php code (**fetch.php**)

```
<?php 
// connect to database 
require('db.php');

// strip tags may not be the best method for your project to apply extra layer of security but fits needs for this tutorial 
$search = strip_tags(trim($_GET['q'])); 
//$search='te';
// Do Prepared Query 
$query = $mysqli->prepare("SELECT tid,tag FROM tag WHERE tag LIKE :search LIMIT 4");

// Add a wildcard search to the search variable
$query->execute(array(':search'=>"%".$search."%"));

// Do a quick fetchall on the results
$list = $query->fetchall(PDO::FETCH_ASSOC);

// Make sure we have a result
if(count($list) > 0){
   foreach ($list as $key => $value) {
    $data[] = array('id' => $value['tid'], 'text' => $value['tag']);                
   } 
} else {
   $data[] = array('id' => '0', 'text' => 'No Products Found');
}

// return the result in json
echo json_encode($data);

?>

```

**select2 version is 3.5**

Above code is able to send/receive request from database by using fetch.php. 

Problem is in my database there are two records **test** & **temp** when I tag any one of them it create new tag. 

It should work like this: *if database have value then it won't create the new tag with same name.*

[![enter image description here](https://i.stack.imgur.com/4USw5.png)](https://i.stack.imgur.com/4USw5.png)

Update
------

[![enter image description here](https://i.stack.imgur.com/qgM1R.png)](https://i.stack.imgur.com/qgM1R.png)