I have this question about networking regarding bit stuffing. I am slightly confused about the answer provided. Please help me understand it. 

**QUestion:** When bit stuffing is used, is it possible for the loss, insertion, or modification of a
single bit to cause an error not detected by the checksum? If not, why not? If so, how?
Does the check sum length play a role here?

**Answer:** It is possible. If data is 01111110 -> 011111010 if the second 0 is lost due to
transmission error, 01111110 will received, which can be interpreted as end of frame.
The bits before the end of the frame will then be interpreted as the checksum. 
**If the
checksum is 4 bits, there is 1 chance in 24
that these random bits will be interpreted as a
valid checksum. The longer the checksum, the less likely that this mistake will happen**

I did not understand the bolded part. What does it mean that there is 1 in 24 chance that it will be interpreted as a valid checksum? I will be happy if someone could clarify it for me please.