If $\sum\_{n=1}^{\infty}\frac{1}{{n}^2} = \frac{{\pi}^2}{6}$ then $\sum\_{n=1}^{\infty}\frac{1}{(2n-1)^2}$ is equal to:

I do not know what to try to find the solution. A hint along with the explanation will be helpful. It might be a trivial problem, but I am facing some problem solving. 

Thanks in advance!