**Input**

```
array([[10, 11, 12, 13, 26, 28, 11],
       [ 4,  9, 19, 20, 21, 26, 12],
       [ 1,  7, 10, 23, 28, 32, 16],
       [ 4,  6,  7, 10, 13, 25,  3],
       [ 4,  6, 15, 17, 30, 31, 16]])

test = np.array([10, 11, 12, 13, 26, 28, 11])

```

**Trying**

```
def check(test,array):
    for i in array:
        if np.array_equal(i,test):
            print('in')
            break 
    print('not in')

```

Is there any simple method without using `for...in...if...else` structure?