I have found a regex on stackoverflow to add a ',' or '.' after every third number depending on your language. 

```
(\d)(?=(\d\d\d)+(?!\d))

```

The problem is that it also happens when we reach the decimal point like with for example:

```
5487445.46878

```

The result of that with the following code (and regex) is:

```
return number.replace(/(\d)(?=(\d\d\d)+(?!\d))/g, "$1,");

```

Which results in:

```
5,487,445.46,878

```

I'm using this regex when I'm converting a number depending on your language. In Dutch for example a comma is used as a seperator, so there I do the following:

```
return number.replace(/(\d)(?=(\d\d\d)+(?!\d))/g, "$1.")

```

Which results in 

```
5.487.445,46.878

```

These of course need to become:

```
5,487,445.46878

```

and 

```
5.487.445,4687

```

*Does anybody know where I need to update the regex to ignore the decimal point?*