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> To move charge from one point to another in an electric field, *the force which we must apply is equal and opposite to the force due to the field.* 
>  (Quoted from *Engineering Electromagnetics* by Hayt.)
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Here is my concern:
To move a charge, shouldn't the force that we must apply be just a little higher than the force exrted on the charge by the field? I know that electric field intensity is the amount of 'kick' a test charge feels when placed in that electric field. Now if I apply the SAME amount of force against the force due to E field, the charge, according to my understanding, will just stay there and won't move. If I apply a force just a little higher than force due to E field, only then the charge should move.

Why does the text say that to MOVE charge in E field, we should apply force EQUAL to that of the force experienced by charge because of E field.