I have this string `(2.5+1)*5`

I want to make a NSMutableArray containing each of the elements:
`[(, 2.5, +, 1, ), *, 5]`

This is the code I wrote:

```
+ (NSMutableArray*) convertToList: (NSString *) exp {
    NSRegularExpression * reg = [NSRegularExpression regularExpressionWithPattern: @"(\\d+\\.\\d+)|(\\d+)|([+-/*///^])|([/(/)])" options:0 error:nil];
    NSArray *matches = [ reg matchesInString: exp
                                 options: 0
                                   range:NSMakeRange(0, [exp length])];
    return [matches mutableCopy];
}

int main (int argc, char *argv[]) {
    NSString * exp = @"(2+5)";
    NSMutableArray * array = [ExpressionTexting convertToList:exp];
    NSLog(@"%@", array);
}

```

I get this output:

```
(
"<NSExtendedRegularExpressionCheckingResult: 0x10010d2e0>{0, 1}{<NSRegularExpression: 0x10010abb0> (\\d+\\.\\d+)|(\\d+)|([+-/*///^])|([/(/)]) 0x0}",
"<NSExtendedRegularExpressionCheckingResult: 0x10010d3f0>{1, 1}{<NSRegularExpression: 0x10010abb0> (\\d+\\.\\d+)|(\\d+)|([+-/*///^])|([/(/)]) 0x0}",
"<NSExtendedRegularExpressionCheckingResult: 0x10010d470>{2, 1}{<NSRegularExpression: 0x10010abb0> (\\d+\\.\\d+)|(\\d+)|([+-/*///^])|([/(/)]) 0x0}",
"<NSExtendedRegularExpressionCheckingResult: 0x10010d4f0>{3, 1}{<NSRegularExpression: 0x10010abb0> (\\d+\\.\\d+)|(\\d+)|([+-/*///^])|([/(/)]) 0x0}",
"<NSExtendedRegularExpressionCheckingResult: 0x10010d570>{4, 1}{<NSRegularExpression: 0x10010abb0> (\\d+\\.\\d+)|(\\d+)|([+-/*///^])|([/(/)]) 0x0}"
)

```

In Java I got the answer:

```
public static ArrayList<String> convertToList(String exp){
    String regex = "(\\d+\\.\\d+)|(\\d+)|([+-/*///^])|([/(/)])";
    Matcher m3 = Pattern.compile(regex).matcher(exp);
    ArrayList<String> list = new ArrayList<String>(exp.length());
    while (m3.find()) {
        list.add(m3.group());
    }
    return list;
}

```

Which works, but I can't translate it in Objective-c