PHP newbie here. I want to save a variable (from jQuery) in PHP/MySQL, but this variable is outside the form. The values from the form elements inside the form is being saved fine though. The variable name in this case is 'mode', and I want the 'mode' to be sent to PHP.

Here's code :

HTML form;

```
<form action="submit.php" method="post" id="myform">
 <textarea id="source1" name="source1"></textarea>
<textarea id="source2" name="source2"></textarea>
 <input type="image" src="images/save.png" name="submit" id="submit" title="Save"  class="save-button"/>    
</form>

```

jQuery / AJAX:

```
mode = 1;  // This value needs to be stored/saved

// AJAX form save
$("form#myform").submit( function () {    
$.post(
'submit.php',
$(this).serialize(),
function(data){
....
}
);

```

PHP:

```
$submit_time = date('Y/m/d H:i:s');
$content1 = $_POST['source1'];
$content2 = $_POST['source2'];
$mode = $_POST['mode'];  // This value needs to be stored/saved

```

Is the solution to create a hidden form field inside the form?