Let $A$ be a $3\times3$ matrix such that $$\mathrm{adj}(A) = \begin{pmatrix}3 & -12 & -1 \\ 0 & 3 & 0 \\ -3 & -12 & 2\end{pmatrix}.$$Find the value of $\det(A)$.

I know that the adjoint of A is the transpose of the cofactors of $A$, but how do I find A or $\det(A)$ in reverse for a particular matrix? all I can think of is using the $A^{-1} = \det(A)/\mathrm{adj}(A)$ but I have no idea how to apply this for a direct value question.