I learned that the destructor is called when an object goes out of scope and also the destructor deletes the objects. Ok fine, but what's happening here?

I'm calling the destructor explicitly, if it deletes the object then why is the destructor implicitly called? Even though there no object now because it's already deleted with the explicitly destructor calling. Sorry may be I'm wrong about explicitly and implicitly But try to understand my problem.

```
#include <iostream>
using namespace std;
class A{
    public:
        A(){
            cout << "Constructor" << endl;
        }
        ~A(){
            cout << "Destructor" << endl;
        }

};
int main(){
    A obj;
    obj.~A();
    cout << "End" << endl;
}

```

Now

```
obj.~A();

```

The above line deletes the object. Then why again is the destructor called? Even though no object is there.

Output:

```
Constructor
Destructor
End
Destructor

```