How can $(2^{100}-2^{98})(2^{99}-2^{97})$ be written in terms of its prime factors?

I tried to expand it: $2^{199}-4^{197}+2^{195}$  

What do I do next?

The answer choices are:

A. $2^{100}\cdot3 \cdot 5$

B. $2^{195}\cdot 3^{2}$ 

C. $2^{199}\cdot 5^{2}$ 

D. $2^{394}$ 

E. $2^{195}\cdot 7 \cdot 5$