I have written a function that computes pow(a,b) in O(logb).

```
double pow(double a, int b){
  double res=1;
    while(b>0){
        if (b%2==1){
            res=res*a;
        }
      b=b>>1;
      a=a*a;

    }
    return res;
}

```

I have stumbled upon the question if it would be possible to write a function pow(double a, double b) in `O(1)` time. Yet I have not found an answer.