I am solving a algorithm problem, and I use both Python and Swift to solve it. In python, I can use a for else syntax solve it easily. But in Swift, I am struggling to find a way that similar to python's for else syntax. 

Here is the algorithm problem, it may help you understand what I am doing.

> 
> Given a string array words, find the maximum value of length(word[i])
>  \* length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no
>  such two words exist, return 0.
> 
> 
> Example 1: Given ["abcw", "baz", "foo", "bar", "xtfn", "abcdef"]
> 
> 
> Return 16
> 
> 
> The two words can be "abcw", "xtfn".
> 
> 
> Example 2: Given ["a", "ab", "abc", "d", "cd", "bcd", "abcd"]
> 
> 
> Return 4 
> 
> 
> The two words can be "ab", "cd".
> 
> 
> Example 3: Given ["a", "aa", "aaa", "aaaa"]
> 
> 
> Return 0
> 
> 
> No such pair of words.
> 
> 
> 

Here are my two sets code. 

The Python code works.

```
class Solution(object):
    def maxProduct(self, words):

        maximum = 0
        while words:
            currentWord = set(words[0])
            current_length = len(words[0])
            words = words[1:]

            for ele in words:
                for char in currentWord:
                    if char in ele:
                        break
                else:
                    maximum = max(maximum,current_length*len(ele))
        return maximum

```

The swift code not works well.

```
class Solution
{
    func maxProduct(words: [String]) -> Int
    {
        var input = words
        let length = input.count
        var maximum = 0
        while input.count != 0
        {
            let cur_word = Set(input[0].characters)
            let cur_length = input[0].characters.count
            input = Array(input[1..<length])

            for item in input
            {
                for char in item.characters
                {
                    if cur_word.contains(char)
                    {
                        break
                    }
                }

                // how add a control follow here? if cur_word does not share same character with item, then does the below max statement

                //else
                //{
                    maximum = max(maximum,cur_length*(item.characters.count))
                //}

            }

        }
        return maximum
    }
}

```