I know this has been asked before, and I know you can do it via making a seprate page for each image. But thats not ideal for what I want.

I want to do that age old thing of displaying multiple images from a db on the same page:

```
echo "<table>";
echo "<tr class ='tablehead'><td>Name</td><td>Location</td><td>Review</td><td>Image</td><td>Thumb</td></tr>";

while ($row = mysql_fetch_array($query))
{   
    echo "<tr>";
    echo "<td>" . $row['user_fname'] . "</td>";
    echo "<td>" . $row['user_location'] . "</td>";
    echo "<td>" . $row['user_review'] . "</td>";
    echo "<td>" . $row['user_image'] . "</td>";
    echo "<td>" . $row['user_thumb'] . "</td>";
    echo "</tr>";
}

echo "</table>";

```

`user_image` and `user_thumb` are blob images, is there someway of showing them all on that page, perhaps setting them to a php variable and then converting to javascript or something along those lines? Rather than: 

```
  header('Content-type: image/jpg');
  echo $thumb;

```

In a seperate file?