How do I sent data from one page to another with `$.ajax` and go to that other page?
If I try the codes below I only get an error on the second page (`watch-video.php`).

I use this code on the `videos.php` page

```
$.ajax({
            type: "POST",
            url: "watch-video.php",
            data: {video: "test"},

            success: function(msg)
            {
                                $(location).attr('href',"watch-video.php");

            }
        });

```

I use this code on the `watch-video.php` page

```
<?php
$name=$_POST['video'];
?>

<html>
<body>

<?php echo $name; ?>

</body>
</html>

```

---

This gives me the same error on the `watch-video.php page`. The error is about this line: 

```
    <?php
$name=$_POST['video'];
?>

```

The error I get is this: 

```
Notice: Undefined index: video in `C:\wamp\www\website\watch-video.php on line 26`

```

I want to submit something to another page, and go to that page but without a form. It has to be done when I click on a div:

```
 $("#gvidbalk").click(function(){

```

It is for something like youtube, if you click on a video image you will go to another page where you can watch that video.