I have a plain text file like below:

```
11/03/20 09:42:45 APP Service A stopped.
11/03/20 09:42:46 APP Starting service A.
11/03/20 09:42:46 APP Starting service A.
11/03/20 09:44:01 APP Service A stopped.
11/03/20 09:44:02 APP Starting service A.
11/03/20 09:44:02 APP Starting service A.
11/03/20 09:45:02 APP Service A stopped.

...

```

This file refers only to one service (service A). As you can see, lines that contains the "Starting" substring are duplicated twice each time.

Using a batch file (ms-dos bat file) I want to count the number of lines in the plain text file that contains the substring "Starting" but I do not want to count the duplicate ones.

For example, from below piece of plain text file and ignoring duplicated lines, I want the following output:

```
2

```

instead of (taking into account duplicated lines):

```
4

```

I know how to do this by taking into account the duplicated lines but not the ignoring them. I am performing below:

```
findstr /N "Starting" plain_text_file.txt | find /c ":"

```

Any ideas to not count the duplicated lines?

Maybe, once I have the result (number of lines) I can divide them by 2 but I do not think it is an elegant way to do it.