[![enter image description here](https://i.stack.imgur.com/SVuXx.png)](https://i.stack.imgur.com/SVuXx.png)

I tried this:

```
\documentclass{standalone}

\usepackage{chemfig}

\begin{document}

    $\chemfig{HO-(-[::+30]*6(-*6(------)-----))=[::-60]O}$

\end{document}

```

It is not 60°, how can you know what angle a substitute has?