> 
> In how many ways can $15$ identical blankets be distributed among $6$
>  beggars such that everyone gets at least one blanket and two
>  particular beggars get equal blankets and another three particular
>  beggars get equal blankets.
> 
> 
> 

**Attempt:**

First, $6$ blankets are given and then $9$ blankets are left. 
After that, according to me there are only two possibilities: 

* Possibility $1$:

First set of *particular* beggars receives: $(3,3)$

Second set of *particular* beggars receives: $(1,1,1)$ 

* Possibility $2$:

First set of *particular* beggars receives: $(0,0)$

Second set of *particular* beggars receives: $(3,3,3)$ 

However answer given is $12$.

Please tell me my mistake.