Using the fact that $$\lim\_{h \to 0}\dfrac{\sin(h)}{h} = 1$$ and $$\lim\_{h\to 0}\dfrac{\cos(h)-1}{h}=0\text{,}$$
Compute the following limits: 

* $\lim\_{h\to 0} \dfrac{\sin(x+h)-\sin(x)}{h}$
* $\lim\_{h\to 0}\dfrac{\cos(x+h)-\cos(x)}{h}$