I have a bash script that does a curl request for a URL. All curl headers and information is contained in a variable, here is a simplified example

```
STRING="'http://www.mydomain.com/url' -H 'mydomain.com'"

```

I originally had the script working by doing echo and xargs to pass it, but I've been reading that it might not be a good way to do things

I ran into issues when just trying `curl $STRING`, and adding double quotes to make it `curl "$STRING"` now gives a curl error stating "curl: (1) Protocol "'http" not supported or disabled in libcurl"

I'm guessing there is some simple thing I am overlooking here possibly relating to the quotes and spaces (I tried escaping single quotes earlier and that just added them literally in the string)

If I echo $STRING it displays it as written with all quotes and single quotes, and doing `echo $STRING | xargs curl` does what I want correctly, it does curl with my string as it's input