I am using Keysight MSOX3102T oscilloscope which has 1 GHz bandwidth. At these frequencies, \$1~M\Omega\$ input impedance is not suitable due to reflections. Therefore, it has the possibility to select \$50 \Omega\$ input port.

![schematic](https://i.stack.imgur.com/1aio9.png)

[simulate this circuit](/plugins/schematics?image=http%3a%2f%2fi.stack.imgur.com%2f1aio9.png) – Schematic created using [CircuitLab](https://www.circuitlab.com/)

Assuming the configuration shown in the figure in which I measure a RMS voltage of \$V\_{rms} = 2.2V\$ on the oscilloscope, is it correct to compute the power provided by the signal generator as:
$$ P = \frac{V^2\_{rms}}{R}= \frac{2.2^2}{50}= 0.0968 W$$
where \$V\_{rms}\$ is the RMS voltage measured on the oscilloscope and R the input port impedance?

UPDATE: Thank you everyone for the replies. Maybe I have not been clear enough explaining my doubt. It can be summarized as, setting the input impedance at \$50 \Omega\$, can I take the load impedance as just \$50 \Omega\$ or does it not work that way in an oscilloscope?