I m parsing URLS like this

```
>>> from urllib.parse import urlparse
>>> urlparse('http://foo.bar/path/to/heaven')
ParseResult(scheme='http', netloc='foo.bar', path='/path/to/heaven', params='', query='', fragment='')

```

Suppose I have an URL that has a malformed path with recurrent `/` like this:

```
>>> x = urlparse('http://foo.bar/path/to/////foo///baz//bar'))
ParseResult(scheme='http', netloc='foo.bar', path='/path/to/////foo///baz//bar', params='', query='', fragment='')

```

As you can see, the `x.path` still contain recurrent slashes, I'm trying to remove them so I have tried split and looping and replacing like this:

```
>>> newpath = x.path.split('/')
['', 'path', 'to', '', '', '', '', 'foo', '', '', 'baz', '', 'bar']
>>> for i in newpath:
    if i == '':
        newpath.remove('')
>>> '/'.join(newpath)
'/path/to/foo/baz/bar'

```

Which gives the desired output but i think this solution is inefficient and trash. How can I do it better?