I'm trying to parse some html and I have some problem with this little html code.

*XML:*

```xml
<div>
    <p><span><a href="../url"></a></span></p>
    <h3 class="header"><a href="../url">Other</a></h3>
    <a href="../url">Other</a><br>
    <a class="aaaaa" href="../url">Indice</a>
    <p></p>               
</div>

```

*code:*

```
import urllib
from lxml import etree
import StringIO
resultado=urllib.urlopen('trozo.html')
html = resultado.read()
parser= etree.HTMLParser()
tree=etree.parse(StringIO.StringIO(html),parser)
xpath='/div/h3'
html_filtrado=tree.xpath(xpath)
print html_filtrado

```

When I print the code it appears [], and I suppose that It should be a list with `<h3 class="header"><a href="../url">Other</a></h3>` in it.
If I would have that list I would execute etree.tostring(html\_filtrado) to see `<h3 class="header"><a href="../url">Other</a></h3>`.

So how can get this code?

```
<h3 class="header"><a href="../url">Other</a></h3>

```

Or only `../url` ? which is the part I want!!

Thank you