$(4x-5)/(3x+5) ≥ 3$

I multiply both sides by (3x+5), getting me:

$(4x-5) ≥ 3(3x+5)$

which simplifies to

$(4x-5) ≥ 9x + 15$

after solving for x, I get

$x ≤ -4$

But after testing through Wolframalpha, I am given:

$-4 ≤ x ≤ -5/3$

Which I don't really understand how they got. I tried multiplying the top side of the fraction by the denominator and then expanding the factored form, and then I rearranged everything once I had a quadratic equation, and I got $-5/3$ and $-2$ as answers, but still not what Wolframalpha got. 

Would appreciate some help and insight into this.

Thanks.