The script matches private IP in file and prints the 3rd column.

The value in the 3rd column can be either IPv4 or IPv6. The IPv4 address is trailed by a ":PORT". I can run `sed 's/:.*//g'` but this will also impact the IPv6 address if printed. Likewise if I use mutiple FS [,:] it will print the IPv4 but only the first octet of the IPv6 address.

My solution is to strip the ":PORT" from the end of the IPv4 address

```
$ cat openvpn-status.log
10.13.0.27,ijegunbead-4,74.201.72.222:49911,2022-06-26 02:55:26
10.13.0.23,biddy-h-1,2803:4600:1111:17ec:a821:1a8:53ca:760d,2022-06-26 02:55:28

```

I have this running in a while loop, one cycle dst will `== 10.13.0.27`, the next `== 10.13.0.23`

```
dst1=$(egrep -w ^$dst /etc/openvpn/openvpn-status.log | awk -F'[,:]' '{print $3}')

```

Result:

```
74.201.72.222
2803

```

Desired Result:

```
74.201.72.222
2803:4600:1111:17ec:a821:1a8:53ca:760d

```

I tried this but no luck

```
dst1=$(egrep -w ^$dst /etc/openvpn/openvpn-status.log | awk -F',' '{print $3}') | sed 's/[0-9]+\.[0-9]+\.[0-9]+\.[0-9]+:*//g'

```