I'm currently writing a bash script to get the first value among the many comma separated strings.
I have a file that looks like this -

```
name

things: "water bottle","40","new phone cover",10

place

```

I just need to return the value in first double quotes.

```
water bottle

```

The value in first double quotes can be one word/two words. That is, `water bottle` can be sometimes replaced with `pen`.
I tried -

```
awk '/:/ {print $2}'

```

But this just gives

```
water

```

I wanted to comma separate it, but there's `colon(:)` after `things`. So, I'm not sure how to separate it.
How do i get the value present in first double quotes?

**EDIT:**

SOLUTION:
I used the below code since I particularly wanted to use awk -

```
awk '/:/' test.txt | cut -d\" -f2

```