Write a function isAllLettersUsed(word, required) that takes in a word as the first argument and returns True if the word contains all the letters found in the second argument.

**Examples**

```
>>> isAllLettersUsed('apple', 'apple')
True
>>> isAllLettersUsed('apple', 'google')
False
>>> isAllLettersUsed('learning python', 'google')
True
>>> isAllLettersUsed('learning python', 'apple')
True

```

**What i'm Doing is**

```
def isAllLettersUsed(word, required):
    if all(required in word for required in word):
        return True
    else: 
        return False

```

**And Result returning is**

```
True
True
True
True

```

**Where as it should return as**

```
True
False
True
True

```

i don't understand what should i do at this point i have tried many things but failed. any suggestion??