The following details are given:

* Partial Key: `XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX11000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000011`
* Initialization Vector: `E898EF8E91F8C9B201E6E29DF87EE152`
* Ciphertext Block 1: `14B8D1412766A8520BACE4598F8AFAEE`
* Ciphertext Block 2: `7E687A49015FA6F1B914635325A6361B`
* Ciphertext Block 3: `8AD191394EF79CEC4B5A256313632CD4`
* Ciphertext Block 4: `8BB4D49F3FA7A917CDF02ECCAA8C4765`
* CBC Mode No padding
* Character set: `ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz1234567890⌴‛~@#$%^&*(){}[]+=-_<>,.?/!:\;’|"`
* Character set info: range [32,127), ASCII encoded, each character is 8 bits

My thinking is that somehow you will need to decrypt each ciphertext block with each of the known 32 bits of the key and work down. The problem is the first ciphertext block has an unmatched key (XXX ...)  

So as a result you will get a plain text of all known characters except the first 32 bits.