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> Show that $$ \sum\_{n=1}^{\infty} \frac{1}{n^n}$$
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I try to use the D'Alembert theorem bit I think to is not the good strategy, I think to the comparation test is the right way but, this is correct?
$$\frac{1}{n^n} \leq \frac{1}{n^2}$$
Any hint or suggestion I will be very grateful