I have a large CSV file that has some mm/dd/yy dates that need to be converted to mm/dd/yyyy. 

eg. "02/23/19" needs to be "02/23/2019"

My original thought was to just do a find/replace /19 with /2019. The problem is that there are other fields that fit the search criteria such as "WELD STUD 5/8 X 6 9/16" that I don't want to be replaced.

Is there a way to do a regex search that will require a leading /##/ followed by 19 and then only replace the 19 with 2019?