I have to find the following limit:

$$\lim\_{x \to 0}\frac{\arctan3x}{\ln((1-x)^2)}$$

L’Hôpital’s rule only makes things worse. Transforming the numerator and the denominator in taylor series doesn’t help too. I’ve seen in another question that $\arctan \left(\frac{x}{x}\right) \to 1$, but then I don’t see what to do with 
$x/(\ldots)$.

Thanks for your help!

Edit: I think I made an error while differentiating, l’Hopital’s rule works. Thanks for your help.