$a,b$ are positive integers. Let $\frac{a}{b}$ be the fraction with the smallest possible denominator $b$ such that $\frac{386}{2019}$ < $\frac{a}{b}$ < $\frac{35}{183}$. Determine the value of $a+b$.

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I have tried simplifying the inequality, but I am stuck. However, I do know that as $b$ has to be smallest, so does $a$.

Any idea how I should do this question? Thanks for any help.