$x^2 + \sqrt{2}x = \frac{1}{2}$

I need to find the **real solutions** for this equation and write it in this form: 

$$\frac{-\sqrt{A} \pm B}{C}$$

So when I work the problem out with the quadratic equation I get: $x = 0.118121$

I had no idea how to even put that in the form described so I assumed they didn't want me to solve but just put it in that form so I put it as follows:

$A = x^2$

$B = \sqrt{2}x$

$C = \frac{1}{2}$

That was wrong also. I'm not really sure what they're asking me to do. I know the answer is: $x = 0.118121$ but is it even possible to put it in the form described? Any help would be appreciated.