In a factory, only two machines, A and B, manufacture washers. Neither machine is perfect: machine A produces defective washers 18% of the time, while machine B produces defectives 14% of the time. Machine B is more efficient than machine A and accounts for 70% of the total output of washers. For purposes of quality control, a sample of washers is taken and examined for defectives. Compute the probability that a randomly chosen washer found to be defective was manufactured by machine A. Round your answer to two decimal places.

P(A)=0.3 P(B)=0.7 D=Defective washers P(A|D)=0.18 P(B|D)=0.14
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P(D)= P(D∩A)+P(D∩B)

```
=P(A)*P(D|A)+P(B)*P(D|B)
=0.3*0.18+0.7*0.14
=0.152

```

P(A|D)=P(A∩D)/P(D)

```
  =0.054/0.152
  =0.36 (Correct to 2 decimal place) 

```

Is the calculation correct?