How many atoms in the hydrocarbon?
==================================

A hydrocarbon is a chemical compound which consists of only hydrogen and carbon atoms. For this challenge, we will only consider the three simplest kinds of hydrocarbons: **alkanes**, **alkenes**, and **alkynes** with no branches.

An **alkane** with \$n\$ carbon atoms contains \$2n+2\$ hydrogen atoms. An **alkene** with \$n\$ carbon atoms contains \$2n\$ hydrogen atoms. An **alkyne** with \$n\$ carbon atoms contains \$2n-2\$ hydrogen atoms.

Each kind of hydrocarbon is named with a prefix indicating the number of carbon atoms it contains, followed by the suffix `ane`, `ene`, or `yne` if it is an alkane, alkene, or alkyne respectively. The numerical prefixes are as follows:

```
1  <-> meth
2  <-> eth
3  <-> prop
4  <-> but
5  <-> pent
6  <-> hex
7  <-> hept
8  <-> oct
9  <-> non
10 <-> dec

```

For example, we can see `propane` has 3 carbon and 8 hydrogen atoms, and `heptyne` has 7 carbon and 12 hydrogen atoms.

Challenge
---------

Your task is to write a function or program that receives a string or list of characters representing the name of a hydrocarbon, and produces or outputs the number of carbon and hydrogen atoms in a molecule of that hydrocarbon.

For each of the 30 hydrocarbon names, the code must accept at least one possible capitalization of that name. For example, it is fine if your code works for `mEthane` but not `methane`, and `ETHAnE` but not `ETHANE`, and `Propane` but not `propane`. The inputs `methene` and `methyne` may give undefined output since those are not real chemicals.

The input and output can be in any convenient format. You don't need to label which number represents carbon and which represents hydrogen, just keep the order of the numbers consistent.

You may assume the input will correspond to a valid hydrocarbon, and there are at most 10 carbon atoms.

Examples
--------

```
Possible Input -> Possible Output
Methane        -> 1 4
propane        -> 3 8
Heptyne        -> 7 12
Decene         -> 10 20

```

Rules
-----

* No standard loopholes.
* Shortest code in bytes wins.