\begin{eqnarray\*}
\int \frac{3\sin x+2\cos x}{2\sin x+3\cos x}dx &=& \int \frac{(3\sin x+2\cos x)/\cos x}{(2\sin x+3\cos x)/\cos x}dx\\ \\
&=& \int \frac{3\tan x +2}{2\tan x +3} dx\\
&& u = \tan x \text{ and } du = \sec^2 x \ dx 
\end{eqnarray\*}
Am I going in the right direction with this one? It seems like not.