**Question:**

> 
> Calculate the potential of hydrogen electrode in contact with a solution of pH 10.
> 
> 
> 

**My attempt:**

Cell reaction: $\ce{ H^+ + e^- -> \frac{1}{2}H\_2 }$

I've attempted to solve this myself by using Nernst equation which yielded the answer -0.591 V. But I believe that Nernst equation is used when there are two electrodes, but my friends are saying that 

*"how will you make a cell from one electrode?"*. 

So guys, please rectify the problem.