How would I use a IN table with like? So that I could use % in them? By in I mean: 

```
SELECT fields 
  FROM table 
 WHERE age = "50" 
   AND name IN ("tim", "bob", "nancy", "john");

```

I already tried: 

```
SELECT fields 
  FROM table 
 WHERE age = "50" 
   AND name LIKE ("2010-09-17%", "2010-09-16%")

```

But it gave the error "Operand should contain 1 column(s)"