I have a loop where in each iteration I (re)calculate a long vector of values:

```
try:
    while(1):
        long_vec = recalculate( long_vec )
        last_vec = long_vec.copy()
except KeyboardInterrupt:
    print last_vec

```

`long_vec` and `last_vec` are numpy arrays. 

My question is: can I be sure that when I press CTRL+C , it won't break copy() function, and `last_vec` is not broken?