A sequence of whole numbers, check if it is ordered `true` (in ascending or descending order), otherwise it is `false`. If a number has the same value as the number below, it will not break the order. The sequence ends with `0`.

```
Sample Input 1: 9 8 7 6 5 4 3 2 1 0
Sample Output 1:true
--------------------------------
Sample Input 2: 1 2 3 3 9 0
Sample Output 2:true
--------------------------------
Sample Input 3: 1 2 5 5 2 3 0
Sample Output 3: false
--------------------------------

```

I need help, I've been trying for days ... I really appreciate any help ...

```
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner s = new Scanner(System.in);
        int a = 0;
        while (s.hasNextInt()) {
            int i = s.nextInt();
            a = i;
            if (i < a) {
                if (i < a) {
                    System.out.println("true");
                } else if (i > a) {
                    System.out.println("false");
                    break;
                }
            } else if (i > a) {
                if (i > a) {
                    System.out.println("true");
                } else if (i < a) {
                    System.out.println("false");
                    break;
                }
            } else if (i == a) {
            }
        }
    }
}

```