I want to check if, for example, the digit '2' is in 4059304593.
My aim is to then check if there are any of the digits 1-9 not in my integer. This is what I have tried:

```
for i in xrange(10):
    for j in xrange(100):
        num = str(i^j)
        one_count = 0
        two_count = 0
        for k in xrange(len(num)):
            if num[k] == 1:
                one_count += 1
            if num[k] == 2:
                two_count += 1                    

```

Then my "counts" would go all the way down to nine\_count, and if any of the counts are 0, then that digit isn't in 'num'. From what I've read on these sites, my script would be inefficient - can someone point out a better way?