Given a $k$-manifold $M$, such that $\partial M$ is a $(k-1)$-manifold, there is a standard way in which $\partial M$ inherits the orientation of $M$. So if $M$ is oriented by the form field $\omega$, then $\omega\_\partial=\omega(v\_{\text{out}},v\_1,\dots,v\_{k-1})$ orients $\partial M$, where the $v\_1,\dots,v\_{k-1}$ are basis vectors for a tangent space on a point of the boundary, and $v\_\text{out}$ is an outward pointing vector (see here: <http://math.ucsd.edu/~jeggers/math31ch/pieces.pdf>, which follows the exposition of Hubbard & Hubbard).

In practice I find this very difficult to interpret. How can one find this $v\_\text{out}$ in practice? 

For instance, take $M$ to be defined by $z=x^2+y^2$ for $x\ge0$ (technically a manifold with boundary, in fact a half-paraboloid). It's a fact that $\partial M$ is defined by the parabola $z=y^2$. If $M$ is oriented by $dx\wedge dy$, how does this induce an orientation on the boundary (in fact we should obtain a 1-form that induces an orientation on the boundary)? 

Note: I find the whole discussion of boundary orientation to be rather clumsy in its exposition. In the case of surfaces inducing orientations on boundary curves, I was originally taught to imagine that the normal vector that induces the surface orientation is me walking on the surface. This normal should walk along the boundary such that the surface lies to its left. OK - but how does this translate to the $v\_{\text{out}}$ interpretation, so that we can generalize to other dimensions easily?)

Edit: An ideal answer would merge the intuitive approach with the rigorous approach, if possible. I would grateful to anybody who could help order my (at present confused) understanding!