There is an example in the book 'The art of electronics - 3rd edition' that I can't understand. The issue is: How the voltage 0.6V goes to the diode D2 without a drop across R1.

[![enter image description here](https://i.stack.imgur.com/Bw2KA.png)](https://i.stack.imgur.com/Bw2KA.png)

This question is addressed here: [Compensating the forward voltage drop of a diode signal rectifier](https://electronics.stackexchange.com/questions/68019/compensating-the-forward-voltage-drop-of-a-diode-signal-rectifier).
But my main doubt (how 0.6V goes to the anode of D2) isn't dealt with.

In my opinion there must be some voltage across R1 and because of that the voltage 0.6V don't "flow" to the anode of D2.

Am I missing something here? The sinewave signal injected in 'in' doesn't generate a drop across R1? How the voltage that comes from 'in' can be added with the voltage on top of R1? If 'in' is high, e.g. 10V, what is going to happen?

In mind mind, I cannot figure how a voltage on top of R1 can be added to the voltage coming from 'in'. If 'in' is 10V the anode of D2 is going to be 10V and a voltage drop will appear across R1 (10V - 0.6V).