In Gauss Law for Electrostatics, Electric flux term contains Electric field due to charges that are both inside and outside the Gaussian surface. If we use Gauss Law to calculate electric field at a point near the infinite line of charge we make Gaussian cylinder (as Gaussian surface) coaxial with the line of charge in such a way that point is on the cylindrical surface. Now if we place another infinite line of charge outside our Gaussian surface. Will the electric field computed by using our previous Gaussian cylinder gives resultant electric field as Gauss's law contains electric field due to both the charges that are inside and outside the Gaussian Cylinder. Kindly Explain it I am very much confused...