```
# prints "here" when run in bash
if [[ ((9 > 220)) ]]; then echo "here"; fi

```

I'm confused why the above if statement gets evaluated to true. Wouldn't `((9 > 220))` evaluate to false which would make the if statement false?
The code below behaves as expected. I'm confused why using the double parentheses in a double brackets "if" isn't working above though.

```
# doesn't print anything
if ((9 > 220)); then echo "here"; fi

```