If $\displaystyle x^2+\frac{1}{x^2}=66$ then what is the value of $\displaystyle\frac{x^2-1+2x}{x}$?

My work: $\displaystyle \bigg(x+\frac{1}{x}\bigg)^2-2=66$

$\displaystyle \bigg(x+\frac{1}{x}\bigg)^2=64$

$\displaystyle x^2+\frac{1}{x^2}+2=64$