So I just got back from a Calculus test and I have some trouble figuring out one of the questions, it states:

"Calculate the inverse of the function $y=\dfrac{2x+1}{3-4x}$."

What first came into my mind was to eliminate the denominator somehow. But I quickly realized that it would be rather difficult science the numerator is also of degree one. I then got desperate and just tried to move the denominator and got this expression witch did not help me at all.
$$y(3-4x) = 2x+1$$
After several more equally stupid moves I gave up. Even now with the help of Wolfram Alpha I can not figure out how to solve it. Can anyone explain?