I'm troubleshooting my alternator and believe I have traced the issue to bad diodes on the diode plate. Here is the schematic of my alternator

[![enter image description here](https://i.stack.imgur.com/R9HGT.png)](https://i.stack.imgur.com/R9HGT.png)

So I've a couple of questions I don't understand.

What is the purpose of the three left diodes? Just for better protection against current flowing the wrong direction? I see the 3 stator wire outputs only go through one diode for each phase.

Secondly, this alternator has 4 posts in the back, as well as a 4 pin connector. In the schematic, N,F,E are on the connector. B is the output post. One pin on the connector is not used. So there are three posts not in use. I'm not sure this schematic matches exactly how the alternator is wired. here is a picture of the actual alternator:

[![enter image description here](https://i.stack.imgur.com/DpRcf.jpg)](https://i.stack.imgur.com/DpRcf.jpg)

The diode plate is actually two separate plates. The stators output to one set of diodes on the left. Then there are jumper wires over to the right plate that go through the other three diodes. All those diodes are failed as far as I can tell, and that plate has B+ on it. 

Edit: added picture of diode plate. It
Looks like you can buy diodes that look similar to these. I'm not sure I can remove mine? The spread pressed in?

[![enter image description here](https://i.stack.imgur.com/vwMqv.jpg)](https://i.stack.imgur.com/vwMqv.jpg)

My questions are:

1. Am i misreading the schematic and it actually represents the real alternator? I just don't get what those left diodes are in the schematic.
2. Looking at the real alternator, it appears the stator outputs are wired in parallel to diodes, one per output plate.
3. I'm thinking instead of using the current B+ post which has no output due to bad diodes, I can just move the wire that currently connects to B+ over to a post on the left plate. Not sure if that is a good idea or what might the ramifications be?

Thanks!