How to prove that $(A \vee B) + (A \wedge B) \equiv A + B$?

Here $\vee$ and $\wedge$ are bitwise OR and bitwise AND operators, respectively. "$+$" is the arithmetic operator.

Example :- $(5 \vee 6) + (5 \wedge 6) \equiv 5 + 6 = 11$.

Any hints would be appreciated.