I am using `setspace`, `\spacing`. I have many functions which are making arrays and when i have `\begin{spacing} {1.5}` i am getting spacing in those special functions, w
\documentclass{article}

```
\usepackage{cancel,amsmath}
\usepackage{setspace}
\newcommand{\stackBelowCancel}[2]{\begin{array}[t]{@{}c@{}}\cancel{#1}\\#2\end{array}} % stacking BELOW canceling number(NOT FRACTION)

\begin{document}
    \begin{flushleft}
        \begin{spacing}{1.5}
        1.  $\dfrac{1}{3\cancel{0}}\cdot\dfrac{1\cancel{0}}{\stackBelowCancel{27}{3}}=\dfrac{1}{9}$ (Have spacing)
        \end{spacing}
        2. $\dfrac{1}{3\cancel{0}}\cdot\dfrac{1\cancel{0}}{\stackBelowCancel{27}{3}}=\dfrac{1}{9}$ (Not in spacing)
    \end{flushleft}

\end{document}

```

I want to achieve the look from the second **line(2.)** in the spacing environment. How to ignore this spacing which I have in line 1, in the command? 
[![enter image description here](https://i.stack.imgur.com/oLZ1r.png)](https://i.stack.imgur.com/oLZ1r.png)