> 
> If $$\frac{(3x-4y-1)^2}{100}-\frac{(4x+3y-1)^2}{225}=1$$
>  then find the length of the latus rectum.
> 
> 
> 

If the standard hyperbola $\frac{x^2}{a^2}−\frac{y^2}{b^2}=1$, then the latus rectum is $2b^2/a$, but I am not able to apply the concept to the inclined hyperbola.