I want to use a regular expression to detect and substitute some phrases. These phrases follow the
same pattern but deviate at some points. All the phrases are in the same string.

For instance I have this string:

```
/this/is//an example of what I want /to///do

```

I want to catch all the words inside and including the // and substitute them with "".

To solve this, I used the following code:

```
import re
txt = "/this/is//an example of what i want /to///do"
re.search("/.*/",txt1, re.VERBOSE)
pattern1 = r"/.*?/\w+"
a = re.sub(pattern1,"",txt)

```

The result is:

```
' example of what i want '

```

which is what I want, that is, to substitute the phrases within // with "". But when I run the same pattern on the following sentence

```
"/this/is//an example of what i want to /do"

```

I get

```
' example of what i want to /do'

```

How can I use one regex and remove all the phrases and //, irrespective of the number of // in a phrase?