> 
> $I(x)=\int\_0^x \frac{\sin (t)}{t} \, dt$
> 
> 
> Find $I(1)$ correct to 3 decimal places
> 
> 
> 

I thought that we just put $1$ instead of $x$ and we get $\frac{\sin 1}{1} = 0.841 $ but the answer is different.
Any ideas what is the correct way to solve it?