After looking at the `man` page for `ls` on my system and searching Google, I see there **[IS a hack of way to use `awk` or `perl` to show octal permissions](http://www.unix.com/unix-dummies-questions-answers/140509-ls-show-numeric-permission-bit.html)** when using `ls`, but with `bash` is there anything more native?

### Standard output of ls -alh

```
$ ll
total 0
drwxr-xr-x   5 user  group   170B May 20 20:03 .
drwxr-xr-x  17 user  group   578B May 20 20:03 ..
-rw-r--r--   1 user  group     0B May 20 20:03 example
-rw-r--r--   1 user  group     0B May 20 20:03 example-1
-rw-r--r--   1 user  group     0B May 20 20:03 example-3

```

### Desired output including octal representation of permissions

```
$ ll
total 0
drwxr-xr-x 1775  5 user  group   170B May 20 20:03 .
drwxr-xr-x 1775 17 user  group   578B May 20 20:03 ..
-rw-r--r-- 1644  1 user  group     0B May 20 20:03 example
-rw-r--r-- 1644  1 user  group     0B May 20 20:03 example-1
-rw-r--r-- 1644  1 user  group     0B May 20 20:03 example-3

```

(disclaimer: not sure if those octals are *exactly* right)

### Reasoning

I am more familiar with the `drwxr-xr-x` notation for permissions but sometimes when the dashes fall in odd places I might mis-read it at a quick glance. I'd like to see the octal equivalent as well.

### Conversion Ability (question part 2)

I think a long time ago octal permissions might have been limited to `000` - `777` but in recent times there are some things like `set-group-ID` and `sticky` that have given us octals with 4 places like `1775`. Is it possible to represent every possible permission in octal format? If it is not then I'd better understand why bash's `ls` command doesn't seem to have this format.