> 
> Find the area of an equilateral $\triangle ABC$ if $I$ is inside point such that:
> 
> 
> $$IA=8 \qquad IB=10 \qquad IC=6$$
> 
> 
> 

My try:

First we note that: $10^{2}=8^{2}+6^{2}$

Take rotational $R\left(C,\frac{π}{3}\right)$

But I don't know what I get??

I think there other simple method without rotational because I don't understand it.

I have already to see your solution