I'm interested in calculating

$$\lim\_{x\to\infty}\frac{x^{5}}{2^{\sqrt{x}}}$$

I'm thinking of using L'Hopital's Rule here, which gives:

$$\lim\_{x\to\infty}\frac{5x^{4}\sqrt{x}}{\ln(2)\cdot
2^{\sqrt{x}-1}}$$

But it doesn't look so great, is this the wrong approach?