Here is my Bash code:

```
echo "Some string/Another string" | grep -o "\/.*"

```

This returns `/Another string`. 

But I do not want the `/` included in the value returned by `echo`. 

How do I change the regex do accomplish this?

EDIT: I want to match everything after the `/`, no matter what is after it. `"Another string"` is not always after the `/`.