The task is to transform this text file, output of the utility `fslint`, into a bash script with `rm` command lines for the duplicate file(s) to delete and commented lines for file(s) to keep, according to a set of rules.

The rules basically say: delete duplicate files only in specific directories.

The goal is to cleanup about 1 TB of duplicates accumulated over the years on several OS (Mac OS X, Windows, Linux). All data has been copied to a Linux drive.

```bsh
#3 x 697,612,024        (1,395,236,864) bytes wasted
/path/to/backup-100425/file_a.dat
/another/path/to/backup-disk-name/171023/file_a.dat
/yet/another/path/to/labs data/some/path/file_a.dat
#4 x 97,874,344 (293,634,048)   bytes wasted
/path/to/backup-100425/file b.mov
/another/path/to/backup-140102/file b.mov
/backup-120708/Library/some/path/file b.mov
/some/other/path/to/backup-current/file b.mov
#2 x 198,315,112        (198,316,032)   bytes wasted
/path/to/backup-100425/file_c.out
/another/path/to/backup-disk-name/171023/file_c.out

```

The first line says there are 3 identical copies of `file_a.dat` and the following 3 lines list the paths to them. Ideally 2 copies should be deleted here. Directories with 6-digit numbers (dates in YYMMDD format) are what I call **historical backup directories**.

The rules, to be applied **in this order** to each group of identical files, are:

1. If a file is in a path including a directory `Library`, keep it.
2. If a file is in `labs data` or `backup-current`, keep it, and delete all duplicates in **historical backup directories**.
3. If a file is in a historical backup directory, keep the file in the newest backup directory, and delete older duplicates.
4. Otherwise keep the file(s).

Here is the desired output:

```bsh
#!/bin/bash
#3 x 697,612,024        (1,395,236,864) bytes wasted
rm '/path/to/backup-100425/file_a.dat'
rm '/another/path/to/backup-disk-name/171023/file_a.dat'
#/yet/another/path/to/labs data/some/path/file_a.dat
#4 x 97,874,344 (293,634,048)   bytes wasted
rm '/path/to/backup-100425/file b.mov'
rm '/another/path/to/backup-140102/file b.mov'
#/backup-120708/Library/some/path/file b.mov
#/some/other/path/to/backup-current/file b.mov
#2 x 198,315,112        (198,316,032)   bytes wasted
rm '/path/to/backup-100425/file_c.out'
#/another/path/to/backup-disk-name/171023/file_c.out

```

I'm not very familiar with the shell tools awk, grep and sed, and after reading [this thread](https://unix.stackexchange.com/questions/169716/why-is-using-a-shell-loop-to-process-text-considered-bad-practice?noredirect=1&lq=1) I realized my first draft was conceptually wrong, "a naive translation of what [I] would do in an imperative language like C".

And in fact, we're not dealing here with **files**, but with **one file's content**.

Is it appropriate to use a shell script for this scenario?  

If yes, how an efficient script would look like?

**Edited:** I tried to clarify the task and requirements, after reading the answer and code from @Ed, which perfectly solves the question.