The question is to prove that $f(x) = 2x$ is continuous at $x = 4$ using the delta-epsilon definition of continuous.

So far, I have that we want a $>0$ such that $|x-4|< $ implies that $|2x - 8| < $.
Given $ > 0$ $|2x-8| = 2|x - 4| < 2$.

I am unsure if I have the right approach/where to go from here. Any help would be much appreciated.