I'm trying to `write()` hexadecimal representation of `\n` without any success.

The code I have `ft_putstr_non_printable.c`:

```
#include <unistd.h>

void    ft_putstr_non_printable(char *str)
{
    int             i;
    unsigned char   a;
    char            c;

    i = 0;
    a = 0x0;
    while (str[i] != '\0')
    {
        if (str[i] <= 31 || str[i] == 127)
        {
            a = str[i];
            write(1, &a, 1);
        }
        else
        {
            c = str[i];
            write(1, &c, 1);
        }
        i++;
    }
}

```

And `main.c`:

```
#include <stdio.h>
#include <string.h>

#include "ft_putstr_non_printable.c"

int main(void)
{
    char a[] = "\n au revoir\a";
    char b[] = "omellette du fromage\b";
    char c[] = "coeuf@ca6va\e fef";
    char d[] = " Batata \x7F rfg";
    char e[] = "roquefort`[e{forte-e_tem,bolor \n feff";
    char f[] = " we 9are 78familly \x1F rgfenf";

    ft_putstr_non_printable(a);
    ft_putstr_non_printable(b);
    ft_putstr_non_printable(c);
    ft_putstr_non_printable(d);
    ft_putstr_non_printable(e);
    ft_putstr_non_printable(f);
}

```

Am I doing something wrong? How do I get \x0a?

Edit: I can't use `printf()`. I'm limited to `write()`.