This is a question I made up just trying to practice probability calculations. I searched, but I didn't find any duplicates--most questions want to know probability of getting doubles once, or of getting an exact combination (I.e. snake eyes, or double sixes).

I came up with $.8385$.

My reasoning was: $P(\text{doubles})=6/36=1/6$, so $P(\text{not doubles})=5/6$. We have ten rolls, so the probabilty of not getting doubles more than once is $(5/6)^{10}=.1615$ so $P(\text{doubles more than once})=1-.1615=.8385$.

Is this the right answer, and if not, could someone help me understand where I went wrong?

Thanks!