Hello in regex how can i find ONLY first two number that start with "39"?

I tried with

```
^(.*?)39

```

but it deletes the second match also. Example:

```none
393905598787
393400048083

```

I want:

```none
3905598755
3400048099

```

With my code, the result is this:

```
05598755
3400048099

```

The `05598755` is wrong because I have two `39`s at the beginning, but I want to discard only the first `39`.