Imagine I have an arbitrary vector $\mathbf{v}\in\mathbb{R}^n$ and say it can be represented as
$$
\mathbf{v}=(v\_1,...,v\_n)^T
$$
where it's understood that the indexes are in increasing order. Imagine now the vector $\mathbf{u}\in\mathbb{R}^{n-1}$ obtained by simply removing entry with index $i$ of $\mathbf{v}$. What's the best (and most "economic") way to represent such vector? My idea was to simply interpret the vector as a sequence and write
$$
\mathbf{u}=\{v\_j\}\_{j\neq i}^T
$$
but I'm not sure whether this is correct and/or there is a better way of writing it. Any ideas?

**Edit:** I'm aware that
$$
\mathbf{u}=(v\_1,...,v\_{i-1},v\_{i+1},...,v\_n)^T
$$
can be used, but I was wondering whether a more "elegant" representation could be possible. If $i=1$ or $i=n$, in this notation, it is just strange that we included $v\_1$ or $v\_n$ in $\mathbf{u}$ in the first place. Purely an aesthetic preference, I know, but still.