I was wondering, is there a way in MongoDB to get all the documents from one collection excluding those that exists in another, without using aggregation.

Let me explain myself more;

I have a collection of "Users", and another collection where there is an array of objects.
Something like this:

**User**

```
  }
    "_id": "61e6bbe49d7efc57f895ab50",
    "name": "User 1"
  },
  {
    "_id": "61e6b9239d7efc57f895ab02",
    "name": "User 2"
  },
  {
    "_id": "61cae6176d0d9a36efd8f190",
    "name": "User 3"
  },
  {
    "_id": "61cade886d0d9a36efd8f11a",
    "name": "User 4"
  },

```

The other collection looks like this:

```
{
    users: [
        {
           user: {
              "_id": "61e6b9239d7efc57f895ab02",
              "name": "User 2",
           },
           ...

        },
        {
           user: {
              "_id": "61cae6176d0d9a36efd8f190",
              "name": "User 3",
           },
           ...
        },
    ],
},

```

I would like to get all the users in "array 1" excluding those in "array 2".
So the result should be:

```
    [
        {
           "_id": "61e6b9239d7efc57f895ab02",
           "name": "User 1"
        },
        {
           "_id": "61cae6176d0d9a36efd8f190",
           "name": "User 4"
        },
    ],

```

So, is there a way to do that without the need to do aggregation.