I have a file with some data like this:

```
1, 3, 0, 0, 0
0, 4, 5, 0, 5
2, 6, 0, 1, 0

```

I would like to write a shell script to delete all the lines where the 3rd argument is 0 (here line 1 and 2)

I already know that 

```
sed -i '/0/d' file.txt

```

but I don't know how I can select the 3rd arguments whatever the others one.

Do you have an idea?