What would the running time be? I got O(n^2)

```
`cin >> n;
 min = 2*n;
 max = (n+3)*10;

for(int i=0; i<1000; i++)
    for(int j =0; j<n; j++)
         for(int k = min; k< max;k++)
            p = f+c+m

```

`