If $\cot(x)=2$ and $\cot(y)=3$ show that $x+y=\frac{\pi}{4}$.
I was trying to find x and y but is some weird thing. Also note that $x,y\:\in (0,\pi/2)$
Second idea was to write : $\frac{\cos x}{\sin x}=2$ and $\frac{\cos y}{\sin y}=3$ and adding this two I'll get $\frac{\cos(x+y)}{\cos x \cos y}=5$. Than what?