Hi guys I am writing my P exam for the second time and I remembered two question that confused me when writing the exam. I asked my prof. but it confused him as well. For simplicity I will ask one question here and post the other one after.

So if you could please help me I would really be greatful.

Question:

You have four die in a urn. 2 regular die, 1 die with faces $(2,2,6,6,6,5)$, and 1 die with all 6.

You throw 2 die. What is the probability of getting 6 on both.

My attempt:
I labelled the dies A,B,C,D respectively as in the question. Then i thought to my self there are total of 9 ways for these to occur. but without repetition like AB is the same as BA. so I got the choices $AB, AC, AD, BC, BD, CD$ and the probability of these respectively is $(\frac{1}{36}, \frac{1}{12}, \frac{1}{6}, \frac{1}{12}, \frac{1}{6}, \frac{1}{2})$

I dont know what to do after. do I add them all.

Really confused please help out.

Thank you