Lets say I have 5 objects selected. The script will correctly export 5 fbx files, place them at 0-0-0 world space, export an fbx with the object name, and return them to their original position. 

The problem is that each export includes all selected objects instead of 1 at a time. Shouldn't my for loop only grab each selected object 1 at a time? How do I select 5 objects, export them so a single object is inside each fbx with the corresponding name?

```
    def execute(self, context):
        # Get the selected objects.
        selected = bpy.context.selected_objects
        for obj in selected:

            # Store current object's name.
            obj_name = obj.name

        # Get the object's original position.
        obj_loc_x = str(obj.location.x)
        obj_loc_y = str(obj.location.y)
        obj_loc_z = str(obj.location.z)

        # Creates the path for the exported fbx.
        obj_path = os.path.join(context.scene.worth_group_tools.dir_path,
                                obj_name + "." + "fbx")

        # Sends object to zero vectors.
        obj.location.x = 0.0
        obj.location.y = 0.0
        obj.location.z = 0.0

        # Export object as fbx. Works, except all selected objects are
        # exported into single fbx instead of one at a time from the list.
        bpy.ops.export_scene.fbx(filepath=obj_path, use_selection=True)

        # Prints each object in list.  Works.
        print(obj_name)

        # Returns the object to its original position.
        obj.location.x = float(obj_loc_x)
        obj.location.y = float(obj_loc_y)
        obj.location.z = float(obj_loc_z)

    return {'FINISHED'}

```