I have a question about an exercise from my electronic circuits class, number a): Find an expression for the large signal V\_out at DC.

Since it is DC, we can ignore the capacitor, it will act as an open circuit. We are dealing with MOSFETs, so now current will flow into the base. That means I0 will flow up into from S to D. Now I am confused. If there was no battery, it would just flow to the right, divide 1:2 through M2 and M3 (since they are identical"), and recombine. Then, I\_L would flow into the load, and I\_0 - I\_L would flow into R\_0, which would give V\_out = (I\_0 - IL) \* R0. Unfortunately, there is the battery V\_bat. Some current will also flow in the battery right? So my way of solving it seems to be incorrect, but how else to I tackle the problem?

Thank you very much! :)

[![Exercise](https://i.stack.imgur.com/47uyJ.png)](https://i.stack.imgur.com/47uyJ.png)