I am trying to do a simple "find-replace" in xslt but having trouble getting it to produce the correct output. I tried to follow other examples but unfortunately I haven't done much with XSLT and haven't been able to locate an example which does what I want to do.

I have the following XML:

```
<metadata>
<Permissions>site:abcdefg-123456-id1::{azeckoski}h,S,r</Permissions>
<Permissions>site:hjklqwe-098765-id2::{person2}h,S,r</Permissions>
<Permissions>playlist:5678::{azeckoski}h,S,r</Permissions>
<Permissions>playlist:7890::{azeckoski}H,s,r</Permissions>
<Permissions>playlist:1234::{person1}H,s,R</Permissions>
</metadata>

```

And the following XSLT:

```
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:package="info:srw/extension/13/package-v1.0" >
<xsl:output omit-xml-declaration="yes" indent="no"/>
 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>
 <xsl:template match="metadata[starts-with(Permissions,'site:abcdefg-123456-id1::')]">
  <xsl:copy>
   <xsl:text>site:abcdefg-123456-id1::{azeckoski}H,S,R</xsl:text>
  </xsl:copy>
 </xsl:template>
</xsl:stylesheet>

```

I would like to end up with the following XML:

```
<metadata>
<Permissions>site:abcdefg-123456-id1::{azeckoski}H,S,R</Permissions>
<Permissions>site:hjklqwe-098765-id2::{person2}h,S,r</Permissions>
<Permissions>playlist:5678::{azeckoski}h,S,r</Permissions>
<Permissions>playlist:7890::{azeckoski}H,s,r</Permissions>
<Permissions>playlist:1234::{person1}H,s,R</Permissions>
</metadata>

```

However I end up with this instead:

```
<metadata>site:abcdefg-123456-id1::{azeckoski}H,S,R</metadata>

```

I don't understand why the rest of the XML document is being wiped out. I thought I was using the identity template to keep everything else as it is.