> 
> If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.  
> 
> Find the sum of all the multiples of 3 or 5 below 1000.
> 
> 
> 

```
mult3 = [] #multiples of 3
mult5 = [] #multiples of 5
for i in range(1000):  
    if i % 3 == 0 and i % 5 != 0: #make sure its numbers are divisible by 3 but not 5
        mult3.append(i)
    if i % 5 == 0 and i % 3 != 0: #make sure its numbers are divisible by 5 but not 3
        mult5.append(i)

total3 = sum(mult3) #sum of all elements in mult3
total5 = sum(mult5) #sum of all elements in mult5
print(total3 + total5)

```

I was wrong with the answer of 200003.
Had I misunderstood the question or are there any bugs in my code?

[Link to the original question](https://projecteuler.net/problem=1)