Hello I am solving inverse Laplace transform using partial fraction. The question is:

$$ X(s) = \frac{10(s+1)}{s(s^2+4s+8)} => \frac{10(s+1)}{s((s+2)^2+4)} $$

$$ \frac {C1} {s} + \frac{C2}{((s+2)+4)} + \frac{C3}{((s+2)^2+4)} $$
for finding C1
$$ \frac{10(s+1)}{s((s+2)^2+4)} = \frac {C1} {s} + \frac{C2}{((s+2)+4)} + \frac{C3}{((s+2)^2+4)} $$
Multiplying both side by $s$ and set $s=0$, we get
$C1=5/4$
for finding C3
$$ \frac{10(s+1)}{s((s+2)^2+4)} = \frac {C1} {s} + \frac{C2}{((s+2)+4)} + \frac{C3}{((s+2)^2+4)} $$
Multiplying both side by $((s+2)^2+4)$ and set $s=-2$, we get
$C3=5$  

For C2 I will take first derivative $X(s)$and Multiplying both side by $((s+2)^2+4)$ 
$$ \frac{d}{ds}[((s+2)^2+4) X(s)] = \frac{d}{ds} \frac{10s}{s}$$
$$ \frac {s(10) - (10s + 10)\*1} {s^2} $$
We set $s=-2$  

I got $C2=-5/2$...

but the solution I have they said $C2 = -5/4$
Please can you tell where I did mistake?