I try to solve with spin the task about the farmer, wolf, goat and cabbage.

So, I found the folowing promela description:

```js
#define fin (all_right_side == true)
#define wg  (g_and_w == false)
#define gc  (g_and_c == false)

ltl ltl_0 { <> fin && [] ( wg && gc ) } 

bool all_right_side, g_and_w, g_and_c;
active proctype river()
{
 bit f = 0, 
 w = 0, 
 g = 0, 
 c = 0; 

 all_right_side = false;
 g_and_w = false;
 g_and_c = false;
 printf("MSC: f %c w %c g %c c %c \n", f, w, g, c);

 do
 :: (f==1) && (f == w) && (f ==g) && (f == c) -> 
        all_right_side = true; 
        break;
 :: else ->
        if
            :: (f == w) ->
                    f =  1 - f;
                    w =  1 - w;
            :: (f == c) ->
                    f =  1 - f;
                    w =  1 - c;
            :: (f == g) ->
                    f =  1 - f;
                    w =  1 - g;
            :: (true) ->
                    f =  1 - f;
        fi;

        printf("M f %c w %c g %c c %c \n",  f, w, g, c);

        if
            :: (f != g && g == c) ->
                    g_and_c = true;
            :: (f != g && g == w) ->
                    g_and_w = true;
            ::else ->
                    skip
        fi
 od;

 printf ("MSC: OK!\n")
}

```

I add there an LTL-formula: ltl ltl\_0 { <> fin && [] ( wg && gc ) } 
to verify, than the wolf wouldn't eat a goat, and the goat wouldn't eat the cabbage. I want to get an example, how the farmer can transport all his needs (w-g-c) without loss.

When I run verification, I get the following result:
State-vector 20 byte, depth reached 59, errors: 1
 64 states, stored
 23 states, matched
 87 transitions (= stored+matched)
 0 atomic steps
hash conflicts: 0 (resolved)

This means that the program has generated an example for me. But I cannot interpret it.
The content of \*.pml.trial file is:[enter image description here](https://i.stack.imgur.com/HlTbq.png)

Please, help me to interpret.