Find the most general solution to the non-homogeneous equation:

$$y'' - 16y' + 64y = \frac{e^{-8x}}{1 + x^2}$$

With the given conditions: $y(0) = -10$ and $y'(0) = 9$. I partially solved it, with

$$e^{8x} \int\_0^x \frac{-te^{-16t}}{1+t^2}dt + xe^{8x} \int\_0^x \frac{-e^{-16t}}{1+t^2}dt + Ce^{8x}+Dxe^{8x}$$

I am not sure what the variables C and D are. Can anyone help me find the variables?