The `testMyNumber` function seems to think numbers in the second position do not match.

Why do 4 and 10 return the default case?

```js
function testMyNumber(number) {
  switch (number) {
    case 6:
      return number+" is 6";
      break;
    case (3 || 4) :
      return number+" is 3 or 4";
      break;

    case 9 || 10 :
      return number+" is 9 or 10";
      break;

    default:
      return number+" is not in 3,4,6,9,10";
      break;
  }
};
console.log(testMyNumber(6));
console.log(testMyNumber(3));
console.log(testMyNumber(4));
console.log(testMyNumber(9));
console.log(testMyNumber(10));
```

Is there a way to make this work?