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> $$\lim\_{x \to \pi/ 6} \frac{(2\sin x + \cos(6x))^2}{(6x - \pi)\sin(6x)}$$
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I would expand with Maclaurin series but $x \to \frac \pi 6$ so I cannot do that. So I evaluated it with l'Hopital rule (result is $-\frac 1{12}$), but is there a better way? I had to differentiate two times and it gets really big and complicated.