I was given the series $\sum\_{n=2}^\infty \frac{(n+4)}{n^2-1} (x-3)^{n+1}$, where I want to find its limit of convergence by using $R:=\frac{1}{\lim sup\_{n\to\infty}|c\_n|^{(1/n)}}$

However, I am struggling with two problems, first is that the index of the series starts from n=2 instead of n=0, does this affect how my calculation for the radius of convergence?

Secondly, the $(x-3)$ is to the power of $n+1$ instead of $n$. how do I convert it so that it matches the power series form $\sum\_{n=0}^\infty c\_n (x - a )^n$ ? 

Thank you for your answers.