this is my first time writing an assembly program. I'm supposed to write a basic addition program using $t0, $t1 and $t2 to store the first two user inputs and the sum. I am having trouble understanding why my user input is always stored as 5.

Might there be an issue with my syscalls?

```
.data
prompt1: .asciiz "Give me an integer number: "
debug1: .asciiz "The first number inputted was: "
debug2: .asciiz "The second number inputted was: "
prompt2: .asciiz "\nGive me another integer number: "
result: .asciiz "\nThe sum of the two inputted numbers is: "

.text

li $v0, 4 #System call to print a string
la $a0, prompt1 #load prompt1 into address 0 - Give me an integer
syscall

#store first input in $t0
li $v0, 5 #System call code for Read Integer from input
move $t0, $v0 #Move value from $v0 to $t0
syscall 

#print the First user input for debugging --> Always prints 5

li $v0, 4  #System call code for Print String
la $a0, debug1 #Print debug1 string
syscall

li $v0, 1   #print int
move $a0, $t0   #move value in $t0 to $a0
syscall

#call prompt 2
li $v0, 4 #Print a string
la $a0, prompt2 # Here is the value to print - "Give me another integer"
syscall

#store second input in $t1
li $v0, 5 #System call code for Read Integer from input
move $t1, $v0 # $t1 = value from input
syscall

#print the second int input for debugging --> Always prints 5

li $v0, 4 #System call code for Print String
la $a0, debug2 #Print debug2 string
syscall

li $v0, 1   #System call code for Print Int
move $a0, $t1   #move value in $t1 to $a0
syscall

#add numbers
add $t2, $t1, $t0 # $t2 = $t1+$t0

li $v0, 4 #System call to Print String
la $a0, result #Print the string result 
syscall

li $v0, 1  #System call to Print Int
move $a0, $t2 #Move $t2, which = $t1 + $t0, into $a0
syscall

```

I appreciate the help in advance.