I am stuck with calculating the peak current through the inductor in a boost converter. Can you please check if I am right?

Ipeak = (Vmax / R2) = 18 / 1000 = 0.018 A. So, my peak current through the inductor is just 18 mA? Am I doing it correctly?

If this is correct, how will I account for the Vce drop inside the pin1 and pin2 of the IC?

The Darlington transistor inside the IC is just like a normal transistor. I have added two transistors outside the IC instead of using the Darlington switch in the IC for thermal purposes.

Can you please help me with the calculation of Vswce and Ipeak? The calculation of Vswce is not mentioned in the datasheet.

The calculation of Ipeak is mentioned in the datasheet, but is my approach of calculating the peak current through the inductor right?

[![My circuit](https://i.stack.imgur.com/nT523.png)](https://i.stack.imgur.com/nT523.png)