I am reading properties file to get a file path as below.

```
    String result = "";
    InputStream inputStream = null;
    try {
        Properties prop = new Properties();
        String propFileName = "config.properties";

        inputStream = GetPropertyValues.class.getClassLoader().getResourceAsStream(propFileName);

        if (inputStream != null) {
            prop.load(inputStream);
        } else {
            throw new FileNotFoundException("property file '" + propFileName + "' not found in the classpath");
        }

```

The properties file has the path specified like below.

```
configSettingsFilePath = C:\\\\ConfigSetting.xml

```

Now I get this below exception when I run my code saying file is not found. 

```
Creating instance of bean 'configSettingHelper'

```

configSettingsFilePath = C:\ConfigSetting.xml
2017-09-18 14:47:00 DEBUG ConfigSettingHelper:42 - ConfigSettingHelper :: ConfigSetting File:configSettingsFilePath = C:\ConfigSetting.xml
javax.xml.bind.UnmarshalException
 - with linked exception:
[java.io.FileNotFoundException: C:\Java\eclipse\eclipse\configSettingsFilePath = C:\ConfigSetting.xml (The filename, directory name, or volume label syntax is incorrect)]
 at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:246)
 at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal(UnmarshallerImpl.java:214)
 at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:157)
 at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:162)
 at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:171)
 at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:189)

Instead of reading the path from properties file, if I directly use "C:\ConfigSetting.xml" in the code, it reads the file.

Can you please suggest what I should use in the properties file to specify the path?