Prove by induction that $10^n -1$ is divisible by 11 for every even natural number n. $0 \notin N$

Base Case: n = 2, since it is the first even natural number. $10^2 -1 = 99$ which is divisible by 11. 

Assume $n =k $ is true for some $k \in N$. Now prove $n=k+1$ is true. 

$10^k -1$

I know I have to put k+1 instead of k, but I do not know how to relate the induction hypothesis with k+1.