I have a query:

```
SELECT 
    count(session_id_open) as opens,
    count(session_id_visit) as visits,
    date_intervals_open,
    group_concat(date_intervals_visit)
FROM
    bla
GROUP BY date_intervals_open

```

I get following table. What I need is to find percentage wise the occurrences of each value appearing in group\_concat. So, basically, I need to count number of values (date\_intervals\_visit) in each group (data\_intervals\_open)

```
opens   visits  date_intervals_open group_concat        
213    5        day (12-16)             evening (17-21),evening (17-21),day (12-16),day (12-16),day (12-16)
113    0        evening (17-21)         NULL
11     0        late evening (22-00)    NULL
396    12       morning (5-11)          morning (5-11),morning (5-11),morning (5-11),morning (5-11),morning (5-11),morning (5-11),morning (5-11),morning (5-11),morning (5-11),morning (5-11),morning (5-11),morning (5-11)
9      0        night (1-4)              NULL

```

That is approximately the table that I need to get. in First record evening has 40 because "evening (17-21)" appears twice and the number of all occurrences is 5. 2/5\*100=40 

```
opens   visits  date_intervals_open evening(17-21)  day(12-16)  morning (5-11)  
213    5        day (12-16)             40          60        0
113    0        evening (17-21)         NULL        NULL      NULL
11     0        late evening (22-00)    NULL        NULL     NULL
396    12       morning (5-11)          0        0     100
9      0        night (1-4)             NULL

```

PS: I used group\_concat just to visualize the value that I have there. I do not have to use it as it will be an additional effort to parse it afterwards.