When nonane-2,8-dione is treated with base, the product 1-(2-methylcyclopent-1-en-1-yl)ethan-1-one forms according to the following scheme:[![actual reaction](https://i.stack.imgur.com/XvHML.jpg)](https://i.stack.imgur.com/XvHML.jpg) The arrow denotes the hydrogen that is first attacked by the base. But why does the reaction not take place like this? —[![this does not occur](https://i.stack.imgur.com/XDYMA.jpg)](https://i.stack.imgur.com/XDYMA.jpg)
Why is the arrow-marked hydrogen less acidic than the previous one?