I created a page with XPages and jquery mobile.
I passed in a link to a page parameter.

The link that is generated is as follows:

```
http://myserver/mydb.nsf/Test.xsp#subpage?parameter=B

```

I tried using different methods to retrieve the data you get is the past, but not able to retrieve the parameter.

```
var exCon = facesContext.getExternalContext();
var request = exCon.getRequest(); // This is the actual HTTP servlet request...
var paramValue = request.getParameter("parameter");
aaa = facesContext.getExternalContext().getRequest().getRequestURL();
bbb = facesContext.getExternalContext().getRequest().getRequestURI();
ccc = facesContext.getExternalContext().getRequest().getContextPath();
ddd = facesContext.getExternalContext().getRequest().getQueryString();
var url:XSPUrl;
url = context.getUrl();
var tagname = url.getParameter('parameter');
prova = ddd.getParameter('parameter');
print("Request: " + request)
print("URL2: " + url);
print("URL: " + aaa);
print("URL3: " + bbb);
print("URL4: " + ccc);
print("URL5: " + ddd);
print("Parametro3 : " + prova);
print("Parametro2 : " + tagname);
print("Parametro: " + paramValue);

```

Doing a bit of debug with the consol I saw that the url that is shown is:

```
http://myserver/mydb.nsf/Test.xsp

```

How do I retrieve the value of the parameter?