I'm looking for a way to extract the filename column from the below output. 

```
    2016-02-03 08:22:33     610540 vendor_20160202_67536242.WAV
    2016-02-03 08:19:25     530916 vendor_20160202_67536349.WAV
    2016-02-03 08:17:10    2767824 vendor_20160201_67369072 - cb.mp3
    2016-02-03 08:17:06     368928 vendor_20160201_67369072.mp3

```

One of the files has spaces in the name which is causing issues with my current commmand

```
awk '{print $4}'

```

How would I treat a column with spaces as a single column?