So I have this fairly complicated fraction, and I am trying to find its antiderivative.

$$
\int \frac{7xe^{2x}}{(1+2x)^2} dx
$$

I am not sure where to start. I was thinking using integration by parts, but then I tried substituting it with $u$'s:

$$
u = 1+2x, du = 2 dx \to dx=\frac{du}{2} \\
= \int \frac{\frac{7u-7}{2}e^{u-1}}{u^2}\color{red}{\frac{ du}{2} }\\
= \frac{7}{4}\int \frac{e^{u-1}}{u} du - \frac{7}{4}\int \frac{e^{u-1}}{u^2} du
$$

But now I am stuck and I can't go any further. Can someone please guide me through this problematic integration? Thanks!