Perl 6 has a cool feature which allows one to get any [Pod declarator block](https://docs.perl6.org/language/pod#Declarator_blocks) that is attached to a subroutine (or class, role, etc.), using the [`WHY` method](https://docs.perl6.org/routine/WHY):

```
#|(Some enlightening words about myfunc.)
sub myfunc (Int $i) { say "You provided an integer: $i"; };
#=(Some more words about myfunc.)

say &myfunc.WHY;

```

This displays:

```
Some enlightening words about myfunc.
Some more words about myfunc.

```

Unfortunately, when one has multiple candidates for a subroutine, one can't just invoke `.WHY` on the subroutine name:

```
#|(myfunc accepts an integer.)
multi myfunc (Int $i) { say "You provided an integer $i"; };
#|(myfunc accepts a string.)
multi myfunc (Str $s) { say "You provided a string $s"; };

say &myfunc.WHY;

```

The result:

```
No documentation available for type 'Sub'.
Perhaps it can be found at https://docs.perl6.org/type/Sub

```

Is there a way to get the Pod declarator block that is attached to a specific multi sub candidate? Is there a way to do so for all a subroutine's candidates?