In the Large Hadron Collider (LHC) the particles move close to the speed of light.

> 
> The LHC accelerates beams of particles, usually protons, around and
> around a 17-mile ring until they reach 99.9999991 percent the speed of
> light.
> 
> 
> 

([Source](https://www.symmetrymagazine.org/article/inside-the-large-hadron-collider))

Mass of proton: $1.6726219 \times 10^{-27}$.  

At $99.9999991 \%$ speed of light, the total energy (kinetic energy plus rest energy) for a proton is:

$$
E=\frac{m c^{2}}{\sqrt[2]{1-\frac{v^{2}}{c^{2}}}}=\frac{1.6726219 \times 10^{-27} \times\left(300000 \times 10^{3}\right)^{2}}{\sqrt[2]{1-\frac{\left(\frac{99.9999991}{100} \times 300000 \times 10^{3}\right)^{2}}{\left(300000 \times 10^{3}\right)^{2}}}}=1.122 \times 10^{-6} J
$$

As a proton is provided with more and more energy, it's energy will tend toward infinite energy. I understand that I've used a proton which is made up of more fundamental particles, i.e. quarks. Anyway, how are we so sure that as the proton gains more and more energy, it wouldn't break into more fundamental particles on its own without colliding into another particle? In other words, is it possible that as energy becomes quite large (or, as its speed tends closer to speed of light) the proton disintegrates into other stuff on its own. Though, electron is considered to be a fundamental particle, as science history is witness, one can never be too sure about it. Have they ever accelerated the proton to such speeds where its energy becomes, say, 2000 kJ?