**How many integers $1, 2,....., 11000$ are invertible modulo $880$?**

$880$ can be rewritten as $2^4\cdot5\cdot11$.

So I am supposed to find the number of integers in this range that have $2$, $5$ or $11$ as a divisor and then subtract that value from $11000$. 

So If I divide $11000$ by each of $2$, $5$ and $11$, I get cardinalities of $5500$, $2200$, and $1000$ respectively. But how exactly am I supposed to find how many integers there are that have both $2$ and $5$ as a divisor, $2$ and $11$ as a divisor, and $5$ and $11$ as a divisor? How am I supposed to find the amount of integers that have all three numbers as a divisor? 

Any help?