text
stringlengths 45
2.98k
| __index_level_0__
float64 0
11.7k
⌀ |
|---|---|
Question: if the l . c . m of two numbers is 560 and their product is 42000 , find the h . c . f of the numbers .
A.50.
B.30.
C.75.
D.25.
e ) none of theseC.
"h . c . f = ( product of the numbers ) / ( their l . c . m ) = 42000 / 560 = 75 . answer : c" | null |
Question: 1,000 ^ 2 + 1,001 ^ 2 + 1,002 ^ 2 + 1,003 ^ 2 + 1,004 ^ 2 =
A.6.
030,053.
B.6.
030,054.
C.6.
030,055.
D.6.
020,030.
e ) 6.
030,057D.
interesting problem . i think key is to notice that all the given answer choices differs in last two digits . therefore , our entire focus should be to figure out how the given terms contribute to last two digits of total . 1000 ^ 2 - > 00 1001 ^ 1 - > 01 . . . 1004 ^ 2 - > 16 total - > * 30 answer d . | null |
Question: in a room filled with 6 people , all 6 people have exactly 1 sibling in the room . if two individuals are selected from the room at random , what is the probability that those two individuals are not siblings ?
A.3 / 5.
B.4 / 5.
C.5 / 6.
D.5 / 12.
e ) 7 / 12B.
the 6 people consist of three sets of 2 siblings . the number of ways to choose 2 people is 6 c 2 = 15 . the number of ways to choose 2 from the first group of siblings is 2 c 2 = 1 . the number of ways to choose 2 from the second group of siblings is 2 c 2 = 1 . the number of ways to choose 2 from the third group of siblings is 2 c 2 = 1 . the number of ways to choose 2 people who are siblings is 1 + 1 + 1 = 3 . the number of ways to choose 2 people who are not siblings is 15 - 3 = 12 . p ( the two people are not siblings ) = 12 / 15 = 4 / 5 the answer is b . | null |
Question: find the least number of complete years in which a sum of money put out at 50 % compound interest will be more than double of itself ?
A.2.
B.3.
C.4.
D.5.
e ) 6A.
2 years answer : a | null |
Question: excluding stoppages , the average speed of a bus is 60 km / hr and including stoppages , the average speed of the bus is 40 km / hr . for how many minutes does the bus stop per hour ?
A.18 min.
B.17 min.
C.19 min.
D.20 min.
e ) 21 minD.
"in 1 hr , the bus covers 60 km without stoppages and 40 km with stoppages . stoppage time = time take to travel ( 60 - 40 ) km i . e 20 km at 60 km / hr . stoppage time = 20 / 60 hrs = 20 min . answer : d" | null |
Question: in an office , 50 percent of the workers have at least 5 years of service , and a total of 16 workers have at least 10 years of service . if 90 percent of the workers have fewer than 10 years of service , how many of the workers have at least 5 but fewer than 10 years of service ?
A.8.
B.64.
C.50.
D.144.
e ) 160A.
( 10 / 100 ) workers = 16 = > number of workers = 160 ( 50 / 100 ) * workers = x + 16 = > x = 8 answer a | null |
Question: a certain roller coaster has 6 cars , and a passenger is equally likely to ride in any 1 of the 6 cars each time that passenger rides the roller coaster . if a certain passenger is to ride the roller coaster 6 times , what is the probability that the passenger will ride in each of the 6 cars ?
A.3 / 1944.
B.1 / 96.
C.2 / 96.
D.1 / 1944.
e ) 1A.
if he is to ride 6 times and since he can choose any of the 6 cars each time , total number of ways is = 6 * 6 * 6 * 6 * 6 * 6 = 46656 now the number of ways if he is to choose a different car each time is = 6 * 5 * 4 * 3 * 2 * 1 = 720 so the probability is = 720 / 46656 = 3 / 1944 answer : a | null |
Question: bruce and anne can clean their house in 4 hours working together at their respective constant rates . if anne ’ s speed were doubled , they could clean their house in 3 hours working at their respective rates . how many d hours does it currently take anne to clean the house on her own ?
A.6.
B.7.
C.8.
D.12.
e ) 14D.
"lets suppose anne and bruce take a and b hrs working separately so in 1 hour they can together finish 1 / a + 1 / b portion of the work which equals 1 / 4 ( as the work is completed in 4 hours ) after anne doubles her rate of work the portion completed by the both is 1 / a + 2 / b which is equal to 1 / 3 ( as the work is completed in d = 3 hours ) solving these 2 equations we can find b as 12 so , d" | null |
Question: the average of runs of a cricket player of 20 innings was 32 . how many runs must he make in his next innings so as to increase his average of runs by 8 ?
A.96.
B.200.
C.128.
D.116.
e ) 122B.
"average = total runs / no . of innings = 32 so , total = average x no . of innings = 32 * 20 = 640 now increase in avg = 4 runs . so , new avg = 32 + 8 = 40 runs total runs = new avg x new no . of innings = 40 * 21 = 840 runs made in the 11 th inning = 840 - 640 = 200 answer : b" | null |
Question: a 9 meter long wire is cut into two pieces . if the longer piece is then used to form a perimeter of a square , what is the probability that the area of the square will be more than 4 if the original wire was cut at an arbitrary point ?
A.1 / 6.
B.1 / 5.
C.2 / 9.
D.1 / 3.
e ) 2 / 5C.
"a square with an area of 4 has a perimeter of 8 . for the area to be > 4 , the longer piece must be > 8 . the wire must be cut within 1 meters from either end . the probability of this is 2 / 9 . the answer is c ." | null |
Question: a is two years older than b who is twice as old as c . if the total of the ages of a , b and c be 17 , the how old is b ? a . 7 b . 8 c . 9 d . 10 explanation :
A.6.
B.7.
C.9.
D.10.
e ) 11A.
let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 17 5 x = 15 x = 3 . hence , b ' s age = 2 x = 6 years . answer : option a | null |
Question: two pipes can fill a tank in 12 minutes and 20 minutes respectively . both pipes are opened together and after some time the first pipe is closed and the tank is full in totally 10 minutes . for how many minutes was first pipe open ?
A.8 minutes.
B.6 minutes.
C.7 minutes.
D.10 minutes.
e ) 9 minutesB.
second pipe is opened for 10 minutes . so , part of tank filled by the second pipe = 10 / 20 = 1 / 2 . so , 1 - 1 / 2 = 1 / 2 tank is filled by first pipe . first pipe can fill 1 / 2 of tank in 1 * 12 / 2 = 6 minutes . so , the first pipe is opened for 6 minutes . answer : b | null |
Question: what is the area inscribed by the lines y = 6 , x = 3 , y = 2 x - 4 on an xy - coordinate plane ?
A.A.1.
B.B.2.
C.C.4.
D.D.8.
e ) e ) 16C.
"first , let ' s graph the lines y = 6 and x = 3 at this point , we need to find the points where the line y = 2 x - 4 intersects the other two lines . for the vertical line , we know that x = 3 , so we ' ll plug x = 3 into the equation y = 2 x - 4 to get y = 2 ( 3 ) - 4 = 2 perfect , when x = 3 , y = 2 , so one point of intersection is ( 3,2 ) for the horizontal line , we know that y = 6 , so we ' ll plug y = 6 into the equation y = 2 x - 4 to get 6 = 2 x - 4 . solve to get : x = 5 so , when y = 6 , x = 5 , so one point of intersection is ( 5,6 ) now add these points to our graph and sketch the line y = 2 x - 4 at this point , we can see that we have the following triangle . the base has length 2 and the height is 4 area = ( 1 / 2 ) ( base ) ( height ) = ( 1 / 2 ) ( 2 ) ( 4 ) = 4 answer : c" | null |
Question: the ratio of males to females in a class is 2 : 3 . the career preferences of the students in the class are represented in a circle graph . if the area of the graph allocated to each career preference is proportional to the number of students who have that career preference , how many degrees of the circle should be used to represent a career that is preferred by one - fourth of the males and three - fourths of the females in the class ?
A.186.
B.192.
C.198.
D.204.
e ) 210C.
"1 / 4 * 2 / 5 + 3 / 4 * 3 / 5 = 2 / 20 + 9 / 20 = 11 / 20 the number of degrees is 11 / 20 * 360 = 198 degrees the answer is c ." | null |
Question: the average of 50 numbers id 20 . if two numbers , namely 45 and 55 are discarded , the average of the remaining numbers is :
A.22.75.
B.33.25.
C.22.25.
D.11.75.
e ) 18.75E.
"explanation : total of 50 numbers = ( 50 × 20 ) = 1000 total of 48 numbers = ( 1000 - ( 45 + 55 ) ] = 900 required average = 900 / 48 = 18.75 answer : e" | null |
Question: the area of a triangle is with base 10 m and height 10 m ?
A.11.
B.10.
C.50.
D.122.
e ) 12C.
"1 / 2 * 10 * 10 = 50 m 2 answer : c" | null |
Question: in what time will a railway train 40 m long moving at the rate of 36 kmph pass a telegraph post on its way ?
A.3 sec.
B.4 sec.
C.5 sec.
D.6 sec.
e ) 7 secB.
"t = 40 / 36 * 18 / 5 = 4 sec answer : b" | null |
Question: find remainder if ( 67 ^ 67 + 67 ) is divided by 68
A.60.
B.62.
C.66.
D.72.
e ) 78C.
= > ( 6767 + 1 ) is divisible by ( 67 + 1 ) = > ( 6767 + 1 ) is divisible by 68 = > ( 6767 + 1 ) ÷ 68 gives a remainder of 0 = > [ ( 6767 + 1 ) + 66 ] ÷ 68 gives a remainder of 66 = > ( 6767 + 67 ) ÷ 68 gives a remainder of 66 c | null |
Question: last year a worker saved 6 % of her annual salary . this year , she made 20 % more money than last year and she saved 5 % of her salary . the amount she saved this year was what percent of the amount she saved last year ?
A.90 %.
B.100 %.
C.110 %.
D.120 %.
e ) 130 %B.
let x be the worker ' s salary last year . last year , she saved 0.06 x . this year , she saved 0.05 ( 1.2 x ) = 0.06 x 0.06 x / 0.06 x = 100 % the answer is b . | null |
Question: a walks at 10 kmph and 4 hours after his start , b cycles after him at 20 kmph . how far from the start does b catch up with a ?
A.100 km.
B.150 km.
C.80 km.
D.120 km.
e ) 200 kmC.
"suppose after x km from the start b catches up with a . then , the difference in the time taken by a to cover x km and that taken by b to cover x km is 4 hours . x / 10 - x / 20 = 4 x = 80 km answer is c" | null |
Question: a and b can do a piece of work in 10 days and 10 days respectively . they work together for 10 days and b leaves . in how many days the whole work is completed ?
A.30 days.
B.40 days.
C.50 days.
D.60 days.
e ) 70 daysA.
"explanation : ( a + b ) ’ s 10 days work = 10 [ 1 / 10 + 1 / 10 ] = 10 [ 1 + 1 / 10 ] = 2 a complete remaining work in 2 * 10 = 20 total work = 10 + 20 = 30 days answer : option a" | null |
Question: one hour before john started walking from p to q , a distance of 33 miles , ann had started walking along the same road from q to p . ann walked at a constant speed of 3 miles per hour and john at 2 miles per hour . how many miles had ann walked when they met ?
A.6 miles.
B.8,4 miles.
C.9 miles.
D.9,6 miles.
e ) 21 milesE.
"ann walks from q to p at a speed of 3 miles / hr for one hour . she covers 3 miles in 1 hour and now distance between john and ann is 33 - 3 = 30 miles . ann walks at 3 mph and john at 2 mph so their relative speed is 3 + 2 = 5 mph . they have to cover 30 miles so it will take them 30 / 5 = 6 hours to meet . in 6 hrs , ann would have covered 6 hrs * 3 miles per hour = 18 miles . adding this to the 3 miles she covered before john , ann covered a total of 3 + 18 = 21 miles . answer ( e )" | null |
Question: kim finds a 2 - meter tree branch and marks it off in thirds and fifths . she then breaks the branch along all the markings and removes one piece of every distinct length . what fraction of the original branch remains ?
A.3 / 5.
B.2 / 5.
C.7 / 5.
D.1 / 2.
e ) 8 / 15A.
"3 pieces of 1 / 5 length and two piece each of 1 / 15 and 2 / 15 lengths . removing one piece each from pieces of each kind of lengths the all that will remain will be 2 pieces of 1 / 5 i . e 2 / 5 , 1 piece of 1 / 15 , and 1 piece of 2 / 15 which gives us 2 / 5 + 1 / 15 + 2 / 15 - - - - - > 3 / 5 answer is a" | null |
Question: two tests had the same maximum mark . the pass percentages in the first and the second test were 40 % and 45 % respectively . a candidate scored 216 marks in the second test and failed by 36 marks in that test . find the pass mark in the first test ?
A.277.
B.266.
C.111.
D.121.
e ) 224E.
"let the maximum mark in each test be m . the candidate failed by 36 marks in the second test . pass mark in the second test = 216 + 36 = 252 45 / 100 m = 252 pass mark in the first test = 40 / 100 m = 40 / 45 * 252 = 224 . answer : e" | null |
Question: a man can swim in still water at 12 km / h , but takes twice as long to swim upstream than downstream . the speed of the stream is ?
A.1.7.
B.2.67.
C.1.2.
D.1.5.
e ) 4E.
"m = 12 s = x ds = 12 + x us = 12 + x 12 + x = ( 12 - x ) 2 12 + x = 24 - 2 x 3 x = 12 x = 4 answer : e" | null |
Question: nitin ranks 24 th in a class of 58 students . what is rank from the last ?
A.33.
B.34.
C.32.
D.28.
e ) 19B.
"explanation : number students behind the nitin in rank = ( 58 - 24 ) = 34 nitin is 34 nd from the last answer : b ) 34" | null |
Question: a certain meter records voltage between 0 and 10 volts inclusive . if the average value of 3 recordings on the meter was 4 volts , what was the smallest possible recording in volts ?
A.2.
B.3.
C.4.
D.5.
e ) 6A.
if average of 3 is 4 so sum of 3 should be 12 3 recording can be from 0 - 10 inclusive to find one smallest other two should be highest so , lets assume three var are a , b , c say a is smallest and give b and c greatest readings say 5 and 5 so a has to be 2 a | null |
Question: 5 drainage pipes , each draining water from a pool at the same constant rate , together can drain a certain pool in 12 days . how many additional pipes q , each draining water at the same constant rate , will be needed to drain the pool in 4 days ?
A.6.
B.9.
C.10.
D.12.
e ) 15C.
this is an inverse proportional problem . . . . . . 5 pipes in 12 days ; so for 4 days , it will be = 12 x 5 / 4 = 15 so , q = 15 - 5 = 10 . c | null |
Question: set a { 3 , 3,3 , 4,5 , 5,5 } has a standard deviation of 1 . what will the standard deviation be if every number in the set is multiplied by 3 ?
A.A.1.
B.B.2.
C.C.4.
D.D.3.
e ) e ) 16D.
"points to remember - 1 . if oneadd / subtractthe same amont from every term in a set , sd does n ' t change . 2 . if onemultiply / divideevery term by the same number in a set , sd changes by same number . hence the answer to the above question is d" | null |
Question: a dress on sale in a shop is marked at $ d . during the discount sale its price is reduced by 45 % . staff are allowed a further 40 % reduction on the discounted price . if a staff member buys the dress what will she have to pay in terms of d ?
A.0.35 d.
B.0.76 d.
C.0.65 d.
D.0.77 d.
e ) 0.33 dE.
effective discount = a + b + ab / 100 = - 45 - 40 + ( - 45 ) ( - 40 ) / 100 = - 67 sale price = d * ( 1 - 67 / 100 ) sale price = . 33 * d answer ( e ) | null |
Question: convert 300 miles into km ?
A.360 km.
B.480 km.
C.510 km.
D.320 km.
e ) 500 kmB.
"1 mile = 1.6 km approximately 300 mile = 300 * 1.6 = 480 km answer is b" | null |
Question: difference of 2 numbers is 100 . if 5 % of one number is 10 % of the other number , find the addition of 2 numbers ?
A.150.
B.300.
C.210.
D.290.
e ) 180B.
"let the numbers be x and y 5 % of x = 10 % of y x = 2 y x - y = 100 2 y - y = 100 y = 100 x = 2 y = 200 x + y = 300 answer is b" | null |
Question: in a room with 6 people , 4 people have exactly 1 friend in the room and 3 people have exactly 2 friends in the room ( assuming that friendship is a mutual relationship , i . e . if jane is paul ' s friend , paul is jane ' s friend ) . if two individuals are selected from the room at random , what is the probability that those two individuals are not friends ?
A.5 / 21.
B.3 / 7.
C.4 / 7.
D.5 / 7.
e ) 16 / 15E.
"( 4 / 6 ) ( 5 / 5 ) + ( 3 / 6 ) ( 4 / 5 ) if you choose one of the 4 with one other friend , then you have a 5 / 5 chance of not picking their friend 2 nd . if you choose one of the 3 with 2 friends , you have a 4 / 5 chance of not picking one of their friends second . add them up . 20 / 30 + 12 / 30 32 / 30 = 16 / 15 e . 16 / 15" | null |
Question: the average weight of 4 person ' s increases by 8.5 kg when a new person comes in place of one of them weighing 95 kg . what might be the weight of the new person ?
A.129 kg.
B.134 kg.
C.180 kg.
D.185 kg.
e ) 190 kgA.
"total weight increased = ( 4 x 8.5 ) kg = 34 kg . weight of new person = ( 95 + 34 ) kg = 129 kg option a" | null |
Question: the s . i . on a certain sum of money for 2 years at 8 % per annum is half the c . i . on rs . 4000 for 2 years at 10 % per annum . the sum placed on s . i . is ?
A.2197.
B.1267.
C.1750.
D.2267.
e ) 2625E.
"explanation : c . i . = [ 4000 * ( 1 + 10 / 100 ) 2 - 4000 ] = ( 4000 * 11 / 10 * 11 / 10 - 4000 ) = rs . 840 . sum = ( 420 * 100 ) / ( 2 * 8 ) = rs . 2625 answer : e" | null |
Question: two trains 120 m and 160 m long run at the speed of 60 km / hr and 40 km / hr respectively in opposite directions on parallel tracks . the time which they take to cross each other is ?
A.10.9.
B.10.7.
C.10.3.
D.10.08.
e ) 10.2D.
relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 120 + 160 = 280 m . required time = 280 * 9 / 250 = 252 / 25 = 10.08 sec . ' answer : d | null |
Question: a , b and c start a business each investing 20,000 . after 6 months a withdrew 5000 , b withdrew 4000 and c invests 6000 more . at the end of the year , a total profit of 67,600 was recorded . find the share of b .
A.20,000.
B.21,200.
C.21,600.
D.20,500.
e ) none of theseC.
"ratio of the capitals of a , b and c = 20000 ã — 6 + 15000 ã — 6 : 20000 ã — 6 + 16000 ã — 6 : 20000 ã — 6 + 26000 ã — 6 = 210000 : 216000 : 250000 = 210 : 216 : 250 b â € ™ s share = ( 67600 ã — 216 â „ 676 ) = 21600 answer c" | null |
Question: in the first 20 overs of a cricket game , the run rate was only 4.6 . what should be the run rate in the remaining 30 overs to reach the target of 396 runs ?
A.10.13.
B.9.13.
C.8.13.
D.11.13.
e ) 13.13A.
required run rate = 396 - ( 4.6 x 20 ) / 30 = 304 / 30 = 10.13 option a | null |
Question: a club wants to mix 10 pounds of candy worth $ 8.00 per pound with candy worth $ 5.00 per pound to reduce the cost of the mixture to $ 6.00 per pound . how many pounds of the $ 5.00 per pound candy should be used ?
A.20.
B.30.
C.40.
D.50.
e ) 60A.
"let number of pounds of 5 $ candy to be used be w 6 = ( 10 * 8 + 5 * w ) / ( 10 + w ) = > 60 + 6 w = 80 + 5 w = > w = 20 answer a" | null |
Question: a ferry can transport 50 tons of vehicles . automobiles range in weight from 1,800 to 3,200 pounds . what is the greatest number of automobiles that can be loaded onto the ferry ?
A.23.
B.55.
C.48.
D.62.
e ) 70B.
"to get maximum vehicles we must take into consideration the minimum weight i . e 1800 pounds here since , 1 ton = 2000 pounds 50 tons will be 100,000 pounds from the answer choices : let max number of vehicles be total weight will be = 55 * 1800 = 99000 pounds , which is lesser than the maximum weight allowed . ans : b" | null |
Question: if the annual increase in the population of a town is 10 % and the present number of people is 15000 , what will the population be in 2 years ?
A.12100.
B.15240.
C.18150.
D.18452.
e ) 19002C.
"the required population is = 15000 ( 1 + 10 / 100 ) ^ 2 = 15000 * 11 / 10 * 11 / 10 = 18150 answer is c" | null |
Question: a plant manager must assign 8 new workers to one of five shifts . she needs a first , second , and third shift , and two alternate shifts . each of the shifts will receive 2 new workers . how many different ways can she assign the new workers ?
A.243.
B.336.
C.350.
D.486.
e ) 540B.
"whatever : my take selecting team of 2 out of 8 to assign to the shifts = 8 c 2 = 28 ways . now 2 out of 8 means total of 4 group possible . so putting them in shifts = counting methode : first , second , third , alt , alt = 4 * 3 * 2 * 1 = 24 here alt and alt are the same : so 24 / 2 = 12 ways . total ways of selecting = ( selecting 2 out of 8 ) * arranging those teams in shifts = 28 * 12 = 336 ans : b" | null |
Question: 1 = 62 = 363 = 3634 = 3645 = 365 , then 36 = ?
A.1.
B.2.
C.345.
D.445.
e ) 235B.
1 = 6,2 = 36,3 = 363,4 = 364,5 = 365 , then 36 = ? 36 = 2 check the second eqn . answer : b | null |
Question: a and b can do a piece of work in 7 days . with the help of c they finish the work in 5 days . c alone can do that piece of work in ?
A.33 days.
B.77 days.
C.30 days.
D.17 days.
e ) 18 daysC.
"c = 1 / 5 – 1 / 6 = 1 / 30 = > 30 days answer : c" | null |
Question: convert the 13 / 36 m / s into kilometers per hour ?
A.2.9.
B.2.2.
C.1.3.
D.1.2.
e ) 1.8C.
13 / 36 m / s = 13 / 36 * 18 / 5 = 13 / 10 = 1.3 kmph . answer : c | null |
Question: a man has some hens and cows . if the number of heads be 100 and the number of feet equals 240 , then the number of cows will be :
A.22.
B.23.
C.24.
D.20.
e ) 28D.
"explanation : let the number of hens be x and the number of cows be y . then , x + y = 100 . . . . ( i ) and 2 x + 4 y = 240 x + 2 y = 120 . . . . ( ii ) solving ( i ) and ( ii ) we get : x = 26 , y = 20 . the required answer = 20 . answer : d" | null |
Question: find large number from below question the difference of two numbers is 1000 . on dividing the larger number by the smaller , we get 10 as quotient and the 10 as remainder
A.1234.
B.1110.
C.1456.
D.1200.
e ) 1600B.
"let the smaller number be x . then larger number = ( x + 1365 ) . x + 1000 = 10 x + 10 9 x = 990 x = 110 large number = 110 + 1000 = 1110 b" | null |
Question: the average height of 30 girls out of a class of 40 is 160 cm . and that of the remaining girls is 156 cm . the average height of the whole class is :
A.158 cms.
B.158.5 cms.
C.159 cms.
D.159.5 cms.
e ) noneC.
explanation : average height of the whole class = ( 36 × 160 + 10 × 156 / 40 ) = 159 cms answer c | null |
Question: what is the units digit of 16 ^ 83 × 13 ^ 82 × 11 ^ 87 ?
A.4.
B.5.
C.6.
D.7.
e ) 8C.
"to find : the units digit of 17 ^ 83 × 13 ^ 82 × 11 ^ 87 let ' s reduce the clutter and simplify the product ( 7 ^ 83 ) ( 3 ^ 82 ) ( 1 ^ 87 ) 7 has a cyclicity of 4 : the last digit of any positive power of 7 repeats itself after every 4 th power so 7 ^ 5 has the same last digit as 7 ^ 1 , 7 ^ 9 , 7 ^ 13 thus , 7 ^ 83 has the same last digit as 7 ^ 3 , 7 ^ 7 , 7 ^ 11 i . e . 3 3 has a cyclicity of 4 : exactly the same routine as above thus , 3 ^ 82 has the same last digit as 3 ^ 2 , 3 ^ 6 , 3 ^ 10 i . e . 9 any power of 1 will result in 1 as the last digit so , product of our last digits = 3 x 9 x 1 = 27 . . . . last digit is 6 correct option : c" | null |
Question: a man owns 1 / 3 of market reserch beauro buzness , and sells 3 / 5 of his shares for 15000 rs , what is the value of buzness ?
A.55000.
B.75000.
C.65000.
D.190000.
e ) 250000B.
"if value of business = x total sell ( 2 x / 3 ) ( 3 / 4 ) = 15000 - > x = 75000 answer : b" | null |
Question: jaylen was planning to save all summer for a pair of jordan 12 s . they cost $ 250 . jaylen figured that he could cut grass to help with the cost of the sneakers . how many yards would jaylen have to cut if he charges $ 2.15 per yard ?
A.116 yards.
B.226 yards.
C.97 yards.
D.115.74 yards.
e ) 1 yardD.
d | null |
Question: what is the total number of integers between 200 and 500 that are divisible by 25 ?
A.20.
B.25.
C.14.
D.15.
e ) 18D.
"125 , 150 , 175 , . . . , 450,475 this is an equally spaced list ; you can use the formula : n = ( largest - smallest ) / ( ' space ' ) + 1 = ( 475 - 125 ) / ( 25 ) + 1 = 350 / 25 + 1 = 14 + 1 = 15 answer is d" | null |
Question: at the end of the month , a certain ocean desalination plant ’ s reservoir contained 30 million gallons of water . this amount is twice the normal level . if this amount represents 75 % of the reservoir ’ s total capacity , how many million gallons short of total capacity is the normal level ?
A.10.
B.15.
C.20.
D.25.
e ) 30C.
"the q talks of total capacity , normal level , present level , shortage etc . . so it is all about not going wrong in these terms 30 mg = 75 % of total . . total = 30 / . 75 = 40 mg . . normal level = 1 / 2 of 40 = 20 mg . . shortage of normal level = 40 - 20 = 20 mg . . c" | null |
Question: matt gets a $ 1000 commission on a big sale . this commission alone raises his average commission by $ 150 . if matt ' s new average commission is $ 250 , how many sales has matt made ?
A.3.
B.4.
C.5.
D.6.
e ) 7D.
let , average commission = x no . of items sold = y total commission = xy new commission = xy + 1000 new average = ( xy + 1000 ) / ( y + 1 ) = 150 + x i . e . ( xy + 1000 ) = ( y + 1 ) * ( 150 + x ) i . e . ( xy + 1000 ) = ( xy + x + 150 y + 150 ) i . e . ( 850 ) = ( x + 150 y ) new commission = 250 = 150 + x i . e . x = 100 i . e . y = 5 new sales = y + 1 = 6 answer : option d | null |
Question: the present worth of $ 169 due in 2 years at 4 % per annum compound interest is ?
A.$ 145.89.
B.$ 138.62.
C.$ 156.25.
D.$ 160.23.
e ) $ 158.95C.
"present worth = 169 / ( 1 + 4 / 100 ) ^ 2 = 169 * 25 / 26 * 25 / 26 = $ 156.25 answer is c" | null |
Question: an urn contains 10 black and 5 white balls . two balls are drawn from the urn one after the other without replacement . what is the probability that both drawn balls are black ?
A.1 / 5.
B.3 / 7.
C.2 / 5.
D.3 / 5.
e ) 2 / 7B.
let e and f denote respectively the events that first and second ball drawn are black . we have to find p ( e n f ) or p ( ef ) . now p ( e ) = p ( black ball in first draw ) = 10 / 15 also given that the first ball drawn is black , i . e . , event e has occurred , now there are 9 black balls and five white balls left in the urn . therefore , the probability that the second ball drawn is black , given that the ball in the first draw is black , is nothing but the conditional probability of f given that e has occurred . that is p ( f | e ) = 9 / 14 by multiplication rule of probability , we have p ( e n f ) = p ( e ) p ( f | e ) = 10 / 15 × 9 / 14 = 3 / 7 b | null |
Question: by selling 11 pencils for a rupee a man loses 10 % . how many for a rupee should he sell in order to gain 20 % ?
A.8.25.
B.9.25.
C.7.25.
D.10.25.
e ) 3.25A.
90 % - - - 11 120 % - - - ? 90 / 120 * 11 = 8.25 answer : a | null |
Question: in the first 10 overs of a cricket game , the run rate was only 4.2 . what should be the run rate in the remaining 40 overs to reach the target of 282 runs ?
A.6.25.
B.6.5.
C.6.75.
D.7.
e ) 6E.
"10 overs - run rate = 4.2 runs scored in first 10 overs = 42 remaining overs 40 total runs to be scored = 282 42 runs already scored 282 - 42 = 240 240 runs to be scored in 40 overs let required runrate be x 40 * x = 240 x = 240 / 40 x = 6.0 the required runrate is 6.0 answer : e" | null |
Question: average between two sets of numbers is closer to the set withmore numbers ?
A.60.
B.80.
C.98.
D.89.
e ) 91B.
if on a test three people answered 90 % of the questions correctly and two people answered 80 % correctly , then the average for the group is not 85 % but rather 3 × 90 + 2 × 805 = 4305 = 86.3 × 90 + 2 × 805 = 4305 = 86 . here , 90 has a weight of 3 = > it occurs 3 times . whereas 80 has a weight of 2 = > it occurs 2 times . so the average is closer to 90 than to 80 as we have just calculated . b | null |
Question: crazy eddie has a key chain factory . eddie managed to decrease the cost of manufacturing his key chains while keeping the same selling price , and thus increased the profit from the sale of each key chain from 50 % of the selling price to 50 % of the selling price . if the manufacturing cost is now $ 50 , what was it before the decrease ?
A.$ 20.
B.$ 40.
C.$ 50.
D.$ 80.
e ) $ 100C.
"deargoodyear 2013 , i ' m happy to help . this is a relatively straightforward problem , not very challenging . btw , crazy eddiewas the actually name of an electronics chain on the east coast of the usa back in the 1970 s . manufacturing now is $ 50 . they now are making a 50 % profit , so the selling price must be $ 100 . they had this same selling price , $ 100 , before they made the change , and had a profit of 50 % , so the manufacturing must have been $ 50 . answer = ( c ) ." | null |
Question: if the simple interest on a certain amount in at 4 % rate 5 years amounted to rs . 2240 less than the principal . what was the principal ?
A.1500.
B.2500.
C.2507.
D.2800.
e ) 11500D.
"p - 2240 = ( p * 5 * 4 ) / 100 p = 2800 answer : d" | null |
Question: a jeep takes 9 hours to cover a distance of 480 km . how much should the speed in kmph be maintained to cover the same direction in 3 / 2 th of the previous time ?
A.48 kmph.
B.52 kmph.
C.35 kmph.
D.63 kmph.
e ) 65 kmphC.
time = 9 distance = 480 3 / 2 of 9 hours = 9 * 3 / 2 = 13.5 hours required speed = 480 / 13.5 = 35 kmph c ) | null |
Question: what is the tens digit of 6 ^ 22 ?
A.1.
B.3.
C.5.
D.7.
e ) 9B.
"the tens digit of 6 in integer power starting from 2 ( 6 ^ 1 has no tens digit ) repeats in a pattern of 5 : { 3 , 1 , 9 , 7 , 5 } : the tens digit of 6 ^ 2 = 36 is 3 . the tens digit of 6 ^ 3 = 216 is 1 . the tens digit of 6 ^ 4 = . . . 96 is 9 . the tens digit of 6 ^ 5 = . . . 76 is 7 . the tens digit of 6 ^ 6 = . . . 56 is 5 . the tens digit of 6 ^ 7 = . . . 36 is 3 again . etc . . . 22 has the form 5 n + 2 , so the tens digit of 6 ^ 22 is 3 . the answer is b ." | null |
Question: in one hour , a boat goes 7 km along the steram and 5 km against the stream . the speed of the boat in still waer ( in km / hr ) is :
A.2.
B.4.
C.6.
D.12.
e ) 15C.
"sol . speed in still water = 1 / 2 ( 7 + 5 ) kmph = 6 kmph . answer c" | null |
Question: a 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 36 sec . what is the length of the platform ?
A.389 m.
B.350 m.
C.289 m.
D.299 m.
e ) 25 mE.
"speed = 300 / 36 = 25 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 25 / 3 = > x = 25 m . answer : e" | null |
Question: a certain sum of money is divided among a , b and c such that a gets one - third of what b and c together get and b gets two - seventh of what a and c together get . if the amount received by a is $ 15 more than that received by b , find the total amount shared by a , b and c .
A.$ 250.
B.$ 340.
C.$ 640.
D.$ 440.
e ) $ 540E.
"a = 1 / 3 ( b + c ) = > c = 3 a - b - - - ( 1 ) b = 2 / 7 ( a + c ) = > c = 3.5 b - a - - ( b ) a - b = $ 15 a = 15 + b ( 1 ) = = = > c = 45 + 3 b - b = 2 b + 45 = = > 2 b - c = - 45 - - - ( 3 ) ( 2 ) = = = > c = 3.5 b - b - 15 = 2.5 b - 15 = = > 2.5 b - c = 15 - - - ( 4 ) from ( 4 ) and ( 3 ) 0.5 b = 60 b = $ 120 a = $ 135 c = 405 - 120 = $ 285 total amount = 135 + 120 + 285 = $ 540 answer : e" | null |
Question: the distance between a & b is 1540 km . a person is traveling from a to b at 100 km / hr started at 6 am and another person is traveling from b to a at 120 km / hr and started at same time . then at what time they meet together .
A.11 am.
B.1 pm.
C.3 pm.
D.10 am.
e ) 9 amB.
"let x hours be they will meet together distance covered by 1 st person + distance covered by 2 nd person = 1540 km 100 x + 120 x = 1540 x = 7 hr they will meet = 6 am + 7 hr = 1 pm answer is b" | null |
Question: williams works at a resort from the beginning of march to the end of september . during the month of august this past year , he made 8 times the average ( arithmetic mean ) of his monthly totals in tips for the other months . his total tips for august were what fraction of his total tips for all of the months he worked ?
A.3 / 7.
B.5 / 7.
C.6 / 7.
D.1 / 7.
e ) 4 / 7E.
first notice the number of months for which he worked - march to sept i . e . 7 months avg of monthly totals in tips for months other than august = x tips in august = 8 x total tips for all months = 6 * x + 8 x = 14 x tips for august / total tips for all months = 8 x / 14 x = 4 / 7 answer : e | null |
Question: ajay can ride 50 km in 1 hour . in how many hours he can ride 1000 km ?
A.10 hrs.
B.15 hrs.
C.20 hrs.
D.25 hrs.
e ) 18 hrsC.
"1 hour he ride 50 km he ride 1000 km in = 1000 / 50 * 1 = 20 hours answer is c" | null |
Question: 0.0008 ? = 0.02
A.40.
B.4.
C.0.4.
D.none of these.
e ) 0.04E.
"explanation : required answer = 0.0008 / 0.02 = 0.08 / 2 = 0.04 . answer : option e" | null |
Question: if each edge of cube increased by 50 % , the percentage increase in
A.100.
B.114.
C.115.
D.125.
e ) 105D.
"100 × ( 150 ) / 100 × ( 150 ) / 100 = 225 = > 125 % answer is d ." | null |
Question: a car started running at a speed of 30 km / hr and the speed of the car was increased by 2 km / hr at the end of every hour . find the total distance covered by the car in the first 11 hours of the journey .
A.342 km.
B.352 km.
C.642 km.
D.440 km.
e ) 382 kmD.
"the total distance covered by the car in the first 11 hours = 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 + 48 + 50 = sum of 11 terms in ap whose first term is 30 and last term is 50 = 11 / 2 [ 30 + 50 ] = 440 km . answer : d" | null |
Question: a ' s speed is 20 / 13 times that of b . if a and b run a race , what part of the length of the race should a give b as a head start , so that b beats a by 80 % of the length of the race ?
A.44 %.
B.48 %.
C.52 %.
D.42 %.
e ) 87 %E.
"first calculate the distance , b has covered with his speed in the time , in which a reached 20 % of the race . then add the remaining distance as head start for b to win the race . its best to apply ratios concept here . since a ' s speed is 20 / 13 of b , therefore , b ' s speed is 13 / 20 of a distance covered by b = speed x time = ( 13 / 20 ) x ( 0.2 ) = 0.13 % ( which means b would have covered 0.13 of the race length during the time in which a has covered 0.2 of the race length . therefore to win , b needs a headstart of ( 1 - 0.13 = ) 0.87 of the race length . so the answer is e" | null |
Question: marginal cost is the cost of increasing the quantity produced ( or purchased ) by one unit . if the fixed cost for n products is $ 12,000 and the marginal cost is $ 200 , and the total cost is $ 16,000 , what is the value of n ?
A.20.
B.50.
C.60.
D.80.
e ) 100A.
total cost for n products = fixed cost for n products + n * marginal cost - - > $ 16,000 = $ 12,000 + n * $ 200 - - > n = 20 . answer : a . | null |
Question: the mark up between ` ` normal plan ' ' price and ` ` premium plan ' ' price is 30 percent of the ` ` normal plan ' ' price . the markup is what percent of the ` ` premium plan ' ' price ? ( markup = difference between normal and premium price plans )
A.8 %.
B.20 %.
C.33 1 / 3 %.
D.45 %.
e ) 56 2 / 3 %C.
a = price for normal plan b = price for premium plan mp = 0.5 a b = a + 0.5 a = 1.5 a hence markup = b - a = 0.5 / 1.5 b = 1 / 3 b . hence mp is 33.33 % of b answer c | null |
Question: 90 students represent x percent of the boys at jones elementary school . if the boys at jones elementary make up 50 % of the total school population of x students , what is x ?
A.134.
B.150.
C.225.
D.250.
e ) 500A.
"90 = x / 100 * 50 / 100 * x = > x ^ 2 = 9 * 10000 / 5 = > x = 134 a" | null |
Question: paul ' s income is 40 % less than rex ' s income , quentin ' s income is 20 % less than paul ' s income , and sam ' s income is 40 % less than paul ' s income . if rex gave 60 % of his income to sam and 40 % of his income to quentin , quentin ' s new income would be what fraction of sam ' s new income ?
A.11 / 12.
B.13 / 17.
C.13 / 19.
D.12 / 19.
e ) 11 / 19A.
"let rex ' s income = 100 , then : rex = 100 paul = 60 quentin = 48 sam = 36 rex gives 60 dollars to sam , so now sam has 96 dollars rex gives 40 dollars to quentin , so now quentin has 88 dollars the fraction q / s = 11 / 12 answer : a" | null |
Question: the average salary of all the workers in a workshop is rs . 8000 . the average salary of 8 technicians is rs . 12000 and the average salary of the rest is rs . 6000 . the total number of workers in the workshop is :
A.22.
B.21.
C.88.
D.37.
e ) 24E.
"explanation : lot the total number of workers be v then , 8 ooov = ( 12000 * 8 ) + 6000 ( v - 8 ) < = > 2000 v = 48000 < = > v = 24 answer : e ) 24" | null |
Question: what is the sum of all 3 digit numbers that leave a remainder of ' 2 ' when divided by 7 ?
A.70,592.
B.64,850.
C.64,749.
D.149,700.
e ) 156,720A.
"find the number , upon sum of 3 digits of a number gives a reminder 2 when it is divided by 7 seeing the options after dividing an finding the reminder of 2 my answer was a" | null |
Question: a tyre has two punctures . the first puncture alone would have made the tyre flat in 9 minutes and the second alone would have done it in 6 minutes . if air leaks out at a constant rate , how long does it take both the punctures together to make it flat ?
A.315 min.
B.325 min.
C.335 min.
D.345 min.
e ) none of theseC.
explanation : do not be confused , take this question same as that of work done question ' s . like work done by 1 st puncture in 1 minute and by second in 1 minute . lets solve it : 1 minute work done by both the punctures = ( 19 + 16 ) = ( 518 ) so both punctures will make the type flat in ( 185 ) mins = 335 mins answer : c | null |
Question: a sum of money is distributed among a , b , c , d in the proportion of 5 : 2 : 4 : 3 . if c gets $ 1000 more than d , what is the b ' s share ?
A.$ 1000.
B.$ 2000.
C.$ 2500.
D.$ 2850.
e ) $ 2950B.
"let the shares of a , b , c , d are 5 x , 2 x , 4 x , 3 x 4 x - 3 x = 1000 x = 1000 b ' s share = 2 x = $ 2000 answer is b" | null |
Question: alex takes a loan of $ 6,000 to buy a used truck at the rate of 8 % simple interest . calculate the annual interest to be paid for the loan amount .
A.680.
B.700.
C.720.
D.480.
e ) 420D.
"from the details given in the problem principle = p = $ 6,000 and r = 8 % or 0.08 expressed as a decimal . as the annual interest is to be calculated , the time period t = 1 . plugging these values in the simple interest formula , i = p x t x r = 6,000 x 1 x 0.08 = 480.00 annual interest to be paid = $ 480 answer : d" | null |
Question: during a certain two - week period , 60 percent of the movies rented from a video store were comedies , and of the remaining movies rented , there were 3 times as many dramas as action movies . if no other movies were rented during that two - week period and there were a action movies rented , then how many comedies , in terms of a , were rented during that two - week period ?
A.5 a.
B.6 a.
C.8 a.
D.14 a.
e ) 20 aB.
"movies : 60 % comedies . 40 % remaining genre . now in this 40 % , there are only 2 categories . action movies and drama movies . if action = x ; drama movies = 3 x . total 4 x . 4 x = 40 ; x = 10 action movies : 10 % drama movies : 30 % we can say that out of 100 z , : comedies : 60 z action : 10 z drama : 30 z now action movies werea this means : a = 10 z . z = ( a / 10 ) comedies : 60 z = 60 * ( a / 10 ) 6 a b is the answer ." | null |
Question: if 15 % of a is the same as 40 % of b , then a : b is :
A.5 : 4.
B.8 : 3.
C.7 : 16.
D.2 : 17.
e ) 3 : 5B.
"expl : 15 % of a i = 40 % of b = 15 a / 100 = 40 b / 100 = 8 / 3 = 8 : 3 answer : b" | null |
Question: after successive discounts of 20 % , 10 % and 5 % a certain good is sold for rs . 6500 . find the actual price of the good .
A.s . 6000.
B.s . 9000.
C.s . 10800.
D.s . 9503.
e ) s . 9980D.
"let actual price was 100 . after three successive discount this will become , 100 = = 20 % discount = > 80 = = 10 % discount = > 72 = = 5 % discount = 68.4 now compare , 68.4 = 6500 1 = 6500 / 68.4 100 = ( 6500 * 100 ) / 68.4 = rs . 9503 . answer : option d" | null |
Question: if a man walks at a rate of 10 kmph , he misses a train by 14 minutes . however , if he walks at the rate of 12 kmph , he reaches the station 10 minutes before the arrival of the train . find the distance covered by him to reach the station .
A.6.
B.15.
C.12.
D.4.
e ) 8A.
"let the required distance x km difference in the times taken at two speeds = 12 min = 1 / 5 hr ( x / 10 ) - ( x / 12 ) = 1 / 10 x = 6 the required distance is 6 km answer is a" | null |
Question: of 32 applicants for a job , 14 had at least 4 years ' experience , 18 had degrees , and 7 had less than 4 years ' experience and did not have a degree . how many of the applicants had at least 4 years ' experience and a degree ?
A.14.
B.13.
C.9.
D.7.
e ) 5D.
"set a : people with more than 4 years exp set b : people with degree aub = total - ( less than 4 exp and no degree ) aub = 32 - 7 = 25 aub = a + b - aib aib = 18 + 14 - 25 = 7 answer d" | null |
Question: a box contains 10 tablets of medicine a and 10 tablets of medicine b . what is the least number of tablets that should be taken from the box to ensure that at least two tablets of each kind are among the extracted .
A.12.
B.15.
C.17.
D.19.
e ) 21A.
"the worst case scenario will be if we remove all 15 tablets of medicine b first . the next 2 tablets we remove have to be of medicine a , so to guarantee that at least two tablets of each kind will be taken we should remove minimum of 10 + 2 = 12 tablets . answer : a ." | null |
Question: express a speed of 63 kmph in meters per second ?
A.10 mps.
B.14 mps.
C.17.5 mps.
D.19.4 mps.
e ) 10.8 mpsC.
"63 * 5 / 18 = 17.5 mps answer : c" | null |
Question: if w / x = 2 / 3 and w / y = 3 / 5 , then ( x + y ) / y =
A.4 / 5.
B.9 / 10.
C.7 / 5.
D.8 / 5.
e ) 9 / 5B.
"w / x = 2 / 3 x = > x = 3 / 2 w and w / y = 3 / 5 = > y = 5 / 3 w ( x + y ) / y = ( 3 / 2 w + 5 / 3 w ) / ( 5 / 3 x ) = 9 / 10 correct option : b" | null |
Question: what least number must be subtracted from 42739 so that remaining no . is divisible by 15
A.3.
B.4.
C.6.
D.8.
e ) 9B.
"explanation : on dividing 42739 by 15 we get the remainder 4 , so 4 should be subtracted option b" | null |
Question: 18 business executives and 7 chairmen meet at a conference . if each business executive shakes the hand of every other business executive and every chairman once , and each chairman shakes the hand of each of the business executives but not the other chairmen , how many handshakes would take place ?
A.144.
B.131.
C.279.
D.90.
e ) 45C.
"there are 18 business exec and in each handshake 2 business execs are involved . hence 18 c 2 = 153 also , each of 18 exec will shake hand with every 7 other chairmen for total of 126 handshake . total = 153 + 126 = 279 ans : c" | null |
Question: for each color copy , print shop x charges $ 1.25 and print shop y charges $ 2.75 . how much greater is the charge for 40 color copies at print shop y than at print shop x ?
A.$ 48.
B.$ 54.
C.$ 60.
D.$ 66.
e ) $ 72C.
"the difference in the two prices is $ 2.75 - $ 1.25 = $ 1.50 for each color copy . each color copy will cost an extra $ 1.50 at print shop y . 40 * $ 1.50 = $ 60 the answer is c ." | null |
Question: the probability of two events a and b are 0.20 and 0.40 respectively . the probability that both a and b occur is 0.15 . the probability that neither a nor b occur is _________
A.0.45.
B.0.4.
C.0.5.
D.0.55.
e ) 0.6D.
"we are apply that formula . . . . . . . . . . . . . . p ( aorb ) = p ( a ) + p ( b ) - p ( a and b ) = . 20 + . 40 - . 15 = . 45 but the probability of neither a nor b = 1 - . 45 = 0.55 answer : d" | null |
Question: of the diplomats who attended a summit conference : 20 spoke japanese , 32 did not speak russian and 20 % of the diplomats spoke neither japanese nor russian . if 10 % of the diplomats spoke both japanese and russian , then how many diplomats attended the conference ?
A.70.
B.96.
C.108.
D.120.
e ) 150D.
2 x 2 matrix will be the easiest way to calculate this . text in black : given statements text in red : calculated values thus d = 120 is the correct answer | null |
Question: if n = 2.0423 and n * is the decimal obtained by rounding n to the nearest hundredth , what is the value of n * – n ?
A.- 0.0053.
B.- 0.0023.
C.0.0007.
D.0.0047.
e ) 0.0153B.
n * = 2.04 n * - n = 2.04 - 2.0423 - 0.0023 answer : b | null |
Question: carl can wash all the windows of his house in 6 hours . his wife maggie can wash all the windows in 6 hours . how many hours will it take for both of them working together to wash all the windows ?
A.2.
B.2 1 / 4.
C.3.
D.4 1 / 2.
e ) 5C.
"work hrs = ab / ( a + b ) = 36 / 12 = 3 answer is c" | null |
Question: car x began traveling at an average speed of 35 miles per hour . after 72 minutes , car y began traveling at an average speed of 49 miles per hour . when both cars had traveled the same distance , both cars stopped . how many miles did car x travel from the time car y began traveling until both cars stopped ?
A.105.
B.120.
C.140.
D.147.
e ) 168A.
"car y began travelling after 72 minutes or 1.2 hours . let t be the time for which car y travelled before it stopped . both cars stop when they have travelled the same distance . so , 35 ( t + 1.2 ) = 49 t or 5 t + 6 = 7 t or t = 3 distance travelled by car x from the time car y began traveling until both cars stopped is 35 x 3 = 105 miles answer : - a" | null |
Question: in a restaurant , the profit is 160 % of the cost . if the cost increases by 12 % but the selling price remains constant , approximately what percentage of the selling price is the profit ?
A.30 %.
B.57 %.
C.90 %.
D.100 %.
e ) none of theseB.
"explanation : let c . p . = rs . 100 . then , profit = rs . 160 , s . p . = rs . 260 . new c . p . = 112 % of rs . 100 = rs . 112 new s . p . = rs . 260 . profit = rs . ( 260 - 112 ) = rs . 148 . required percentage = ( 148 / 260 * 100 ) % = 57 % appox answer : b" | null |
Question: a train 250 m long is running at a speed of 45 km / hr . in what time will it pass a bridge 150 m long ?
A.45 sec.
B.42 sec.
C.32 sec.
D.48 sec.
e ) 25 secC.
"total length = 250 + 150 = 400 speed = 45 km / h = ( 45 * 5 ) / 18 = 25 / 2 m / s time = ( 400 * 2 ) / 25 = 32 sec . answer : c" | null |
Subsets and Splits
No saved queries yet
Save your SQL queries to embed, download, and access them later. Queries will appear here once saved.