text
stringlengths 45
2.98k
| __index_level_0__
float64 0
11.7k
β |
|---|---|
Question: the length and breadth of a rectangle is increased by 5 % and 15 % respectively . what is the increase in the area ?
A.21.25.
B.22.75.
C.19.25.
D.20.75.
e ) 22.25D.
"100 * 100 = 10000 105 * 115 = 12075 - - - - - - - - - - - 2075 10000 - - - - - - 2075 100 - - - - - ? = > 20.75 answer d" | null |
Question: a train running at the speed of 40 km / hr crosses a pole in 9 seconds . what is the length of the train ?
A.120 metres.
B.180 metres.
C.324 metres.
D.150 metres.
e ) 100 metersE.
"speed = 40 x 5 / 18 m / sec = 100 / 9 m / sec . length of the train = ( speed x time ) . length of the train = 100 / 9 x 9 m = 100 m . answer : e" | null |
Question: a chemical supply company has 60 liters of a 35 % hno 3 solution . how many liters of pure undiluted hno 3 must the chemists add so that the resultant solution is a 50 % solution ?
A.18.
B.15.
C.20.
D.24.
e ) 30A.
"60 liters of a 35 % hno 3 solution means hno 3 = 21 liters in 60 liters of the solution . now , let x be the pure hno 3 added . as per question , 21 + x = 50 % of ( 60 + x ) or x = 18 hence , a" | null |
Question: in how many no . between 10 and 30 exactly two of the digits is 2 ?
A.25.
B.1.
C.35.
D.45.
e ) 50B.
"it ' s simple can be solved by elimination of answer choices . option a and c are too large , not possible . even de are large to have correct choice . ans : b" | null |
Question: the batting average of a particular batsman is 60 runs in 46 innings . if the difference in his highest and lowest score is 140 runs and his average excluding these two innings is 58 runs , find his highest score .
A.179.
B.367.
C.269.
D.177.
e ) 174E.
"explanation : total runs scored by the batsman = 60 * 46 = 2760 runs now excluding the two innings the runs scored = 58 * 44 = 2552 runs hence the runs scored in the two innings = 2760 Γ’ β¬ β 2552 = 208 runs . let the highest score be x , hence the lowest score = x Γ’ β¬ β 140 x + ( x - 140 ) = 208 2 x = 348 x = 174 runs answer : e" | null |
Question: if m ^ 2 - 8 m + 1 = 0 , then m ^ 3 + m ^ ( - 3 ) = ?
A.487.
B.488.
C.489.
D.457.
e ) 495B.
here from equation 1 we will get m ^ 2 - 8 m + 1 = 0 m ^ 2 = 8 m - 1 m = ( 8 m - 1 ) / m . . . . . . . . . ( 1 ) m = 8 - 1 / m so m + 1 / m = 8 now in equation 2 m ^ 3 + 1 / m ^ 3 ( m + 1 / m ) ( m ^ 2 - m * 1 / m + 1 / m ^ 2 ) ( m + 1 / m ) ( m ^ 2 - 1 + 1 / m ^ 2 ) ( m + 1 / m ) ( m ^ 2 + 1 / m ^ 2 - 1 ) ( m + 1 / m ) { ( m + 1 / m ) ^ 2 - 2 m * 1 / m - 1 } { since a ^ 2 + b ^ 2 = ( a + b ) ^ 2 - 2 ab } ( m + 1 / m ) { ( m + 1 / m ) ^ 2 - 2 - 1 } now putting the value of m from equation 1 8 ( 8 ^ 2 - 2 - 1 ) 8 ( 64 - 3 ) = 488 answer : b | null |
Question: if 3 a β 3 b β 2 c = 32 and β 3 a - β ( 2 b + 2 c ) = 4 , what is the value of a + b + c ?
A.3.
B.9.
C.10.
D.12.
e ) 14C.
when we look at the two equations , we can relize some similarity , so lets work on it . . 3 a β 2 b β 2 c = 32 can be written as β 3 a ^ 2 - β ( 2 b + 2 c ) ^ 2 = 32 { β 3 a - β ( 2 b + 2 c ) } { β 3 a + β ( 2 b + 2 c ) } = 32 . . or 4 * β 3 a + β ( 2 b + 2 c ) = 32 . . or β 3 a + β ( 2 b + 2 c ) = 8 . . now lets work on these two equations 1 ) β 3 a - β ( 2 b + 2 c ) = 4 . . 2 ) β 3 a + β ( 2 b + 2 c ) = 8 . . a ) add the two eq . . β 3 a + β ( 2 b + 2 c ) + β 3 a - β ( 2 b + 2 c ) = 12 . . 2 β 3 a = 12 . . or β 3 a = 6 . . 3 a = 36 . . a = 12 . b ) subtract 1 from 2 . . β 3 a + β ( 2 b + 2 c ) - β 3 a + β ( 2 b + 2 c ) = 4 . . 2 β ( 2 b + 2 c ) = 4 . . β ( 2 b + 2 c ) = 2 . . 2 b + 2 c = 4 . . or b + c = 2 . . from a and b a + b + c = 12 + 2 = 14 . . c | null |
Question: a farmer with 1,350 acres of land had planted his fields with corn , sugar cane , and tobacco in the ratio of 5 : 2 : 2 , respectively , but he wanted to make more money , so he shifted the ratio to 2 : 3 : 4 , respectively . how many more acres of land were planted with tobacco under the new system ?
A.75.
B.150.
C.300.
D.450.
e ) 600C.
"originally ( 2 / 9 ) * 1350 = 300 acres were planted with tobacco . in the new system ( 4 / 9 ) * 1350 = 600 acres were planted with tobacco . thus 600 - 300 = 300 more acres were planted with tobacco . the answer is c ." | null |
Question: in a group of 100 cars , 47 cars do not have air conditioning . if at least 55 cars have racing stripes , what is the greatest number of cars that could have air conditioning but not racing stripes ?
A.45.
B.47.
C.49.
D.51.
e ) 53A.
"lets assume ac = 53 ( includesonly ac carsandcars with ac and racing stripes ) lets assume rs ( racing stripes ) > = 55 ( includescars with ac and racing stripesandonly racing stripes ) . now since we want to maximize ( only ac ) we have to see to it thatcars with ac and racing stripesis minimal ( assume 0 ) but since rs > = 55 . . we have to assign atleast 8 tocars with ac and racing stripes . hence ac = 53 - 8 = 45 . the answer is a" | null |
Question: at a certain conference , 78 % of the attendees registered at least two weeks in advance and paid their conference fee in full . if 10 % of the attendees who paid their conference fee in full did not register at least two weeks in advance , what percent of conference attendees registered at least two weeks in advance ?
A.18.0 %.
B.62.0 %.
C.79.2 %.
D.86.67 %.
e ) 82.0 %D.
i do not think that venn will be helpful here . a table will make more sense . but here is my approach . 78 % regestered at least 2 weeks and paid full fee . 10 % paid full fee and did not registered at least 2 weeks in advance . then 90 % paid full fee and registered at least 2 weeks before . 90 % * x = 78 % where x is the number of people who registerd 2 weeks in advance and paid full fee . ( answer d ) | null |
Question: a can do a piece of work in 22 days and b alone can do it in 10 days . b works at it for 5 days and then leaves . a alone can finish the remaining work in
A.5 days.
B.6 days.
C.11 days.
D.8.5 days.
e ) 9 daysC.
"explanation : b ' s 5 days work = 1 / 10 β 5 = 1 / 2 remaining work = 1 β 1 / 2 = 1 / 2 a can finish work = 22 β 1 / 2 = 11 days option c" | null |
Question: if the volume of two cubes are in the ratio 8 : 1 , the ratio of their edges is :
['A.2 : 1', 'B.3 : 2', 'C.3 : 5', 'D.3 : 7', 'e ) none of these']A.
explanation : let the edges be a and b of two cubes , then a 3 / b 3 = 8 / 1 = > ( a / b ) 3 = ( 2 / 1 ) 3 a / b = 2 / 1 = > a : b = 2 : 1 option a | null |
Question: what is the dividend . divisor 15 , the quotient is 8 and the remainder is 5
A.A.145.
B.B.148.
C.C.150.
D.D.125.
e ) e ) 158D.
"d = d * q + r d = 15 * 8 + 5 d = 120 + 5 d = 125 answer : d" | null |
Question: x can do a piece of work in 40 days . he works at it for 8 days and then y finished it in 20 days . how long will y take to complete the work ?
A.10.
B.12.
C.25.
D.18.
e ) 20C.
"work done by x in 8 days = 8 * 1 / 40 = 1 / 5 remaining work = 1 - 1 / 5 = 4 / 5 4 / 5 work is done by y in 20 days whole work will be done by y in 20 * 5 / 4 = 25 days answer is c" | null |
Question: the population of a town is 10000 . it increases annually at the rate of 20 % p . a . what will be its population after 5 years ?
A.14300.
B.24883.
C.14500.
D.14600.
e ) 15400B.
"formula : ( after = 100 denominator ago = 100 numerator ) 10000 Γ 120 / 100 ^ 5 = 24883 b )" | null |
Question: by selling an article at rs . 500 , a profit of 25 % is made . find its cost price ?
A.400.
B.267.
C.287.
D.480.
e ) 811A.
"sp = 500 cp = ( sp ) * [ 100 / ( 100 + p ) ] = 500 * [ 100 / ( 100 + 25 ) ] = 500 * [ 100 / 125 ] = rs . 400 answer : a" | null |
Question: in a class of 32 students , 12 enrolled for both english and german . 22 enrolled for german . if the students of the class enrolled for at least one of the two subjects , then how many students enrolled for only english and not german ?
A.30.
B.10.
C.18.
D.28.
e ) 32B.
"total = english + german - both + neither - - > 40 = english + 22 - 12 + 0 - - > english = 22 - - > only english = english - both = 22 - 12 = 10 . answer : b ." | null |
Question: the ratio of radius of a circle and the side of a square is 2 : 5 . find the ratio of their areas :
A.2 : 1.
B.4 : 25.
C.8 : 77.
D.4 : 121.
e ) noneB.
"radius / side = 2 / 5 Γ’ β‘ β area of circle / area of square = 4 / 25 answer : b" | null |
Question: a lion chases a pony 7 hours after the pony runs . lion takes 8 hours to reach the pony . if the average speed of the lion is 49 kmph , what s the average speed of the pony ?
A.28.3 kmph.
B.29.8 kmph.
C.28.4 kmph.
D.29.5 kmph.
e ) 29.4 kmphE.
pony take 15 hours and lion take 8 hours . . . then distance chased by them is 49 * 8 . so speed of pony is ( 49 * 8 ) / 15 = 29.4 kmph . answer is e | null |
Question: on the independence day , bananas were be equally distributed among the children in a school so that each child would get two bananas . on the particular day 360 children were absent and as a result each child got two extra bananas . find the actual number of children in the school ?
A.237.
B.287.
C.197.
D.287.
e ) 720E.
"explanation : let the number of children in the school be x . since each child gets 2 bananas , total number of bananas = 2 x . 2 x / ( x - 360 ) = 2 + 2 ( extra ) = > 2 x - 720 = x = > x = 720 . answer : e" | null |
Question: the cash realised on selling a 14 % stock is rs . 106.25 , brokerage being 1 / 4 % is ?
A.366.
B.106.
C.102.
D.192.
e ) 122B.
"cash realised = rs . ( 106.25 - 0.25 ) = rs . 106 . answer : b" | null |
Question: a reduction of 25 % in the price of oil enables a house wife to obtain 5 kgs more for rs . 900 , what is the reduced price for kg ?
A.45.
B.60.
C.70.
D.80.
e ) 20A.
"a 900 * ( 25 / 100 ) = 225 - - - - 5 ? - - - - 1 = > rs . 45" | null |
Question: rectangular tile each of size 80 cm by 55 cm must be laid horizontally on a rectangular floor of size 210 cm by 330 cm , such that the tiles do not overlap and they are placed with edges jutting against each other on all edges . a tile can be placed in any orientation so long as its edges are parallel to the edges of floor . no tile should overshoot any edge of the floor . the maximum number of tiles that can be accommodated on the floor is :
A.26.
B.16.
C.18.
D.19.
e ) 20B.
"area of tile = 80 * 55 = 4400 area of floor = 210 * 330 = 72600 no of tiles = 72600 / 4400 = 16.5 so , the no of tile = 16 answer : b" | null |
Question: sowdharya had 90 currency notes in all , some of which are of rs 95 denomination and the remaining of rs 45 denomination . the total amount of all these currency notes was rs . 5000 . how much amount ( in rs ) did she have in the denomination of rs 45 ?
A.75.
B.72.
C.71.
D.76.
e ) 73C.
let the number of 45 - rupee notes = x then , the number of 95 - rupee notes = ( 90 β x ) 45 x + 95 ( 90 β x ) = 5000 : x = 71 answer : c | null |
Question: if an investor puts $ 700 in a savings account that earns 10 percent annual interest compounded semiannually , how much money will be in the account after one year ?
A.$ 769.75.
B.$ 771.75.
C.$ 773.75.
D.$ 775.75.
e ) $ 777.75B.
"1.05 * 1.05 * 700 = $ 771.75 the answer is b ." | null |
Question: a salesman β s terms were changed from a flat commission of 5 % on all his sales to a fixed salary of rs . 1000 plus 2.5 % commission on all sales exceeding rs . 4,000 . if his remuneration as per new scheme was rs . 600 more than that by the previous schema , his sales were worth ?
A.12002.
B.12000.
C.12028.
D.12020.
e ) 12013B.
"[ 1000 + ( x - 4000 ) * ( 2.5 / 100 ) ] - x * ( 5 / 100 ) = 600 x = 12000 answer : b" | null |
Question: to deliver an order on time , a company has to make 25 parts a day . after making 25 parts per day for 3 days , the company started to produce 5 more parts per day , and by the last day of work 100 more parts than planned were produced . find how many parts the company made and how many days this took .
A.600.
B.500.
C.575.
D.655.
e ) 675E.
let x be the number of days the company worked . then 25 x is the number of parts they planned to make . at the new production rate they made : 3 β
25 + ( x β 3 ) β
30 = 75 + 30 ( x β 3 ) therefore : 25 x = 75 + 30 ( x β 3 ) β 100 25 x = 75 + 30 x β 90 β 100 190 β 75 = 30 x β 25 115 = 5 x x = 23 so the company worked 23 days and they made 23 β
25 + 100 = 675 pieces . so answer is e . | null |
Question: how many positive integers less than 100 have a reminder 5 when divided by 7 ?
A.11.
B.12.
C.13.
D.14.
e ) 15D.
"take the multiples of 7 and add 5 0 x 7 + 5 = 5 . . . . 13 x 7 + 5 = 96 there are 14 numbers answer d" | null |
Question: what is the 10 th digit of ( 5 ! * 4 ! * 4 ! - 5 ! * 4 ! * 3 ! ) / 2880 ?
A.4.
B.1.
C.6.
D.7.
e ) 8B.
"( 5 ! * 4 ! * 4 ! - 5 ! * 4 ! * 3 ! ) / 2880 ? = 5 ! * 4 ! ( 4 ! - 3 ! ) / 4 ! * 5 ! = 4 ! - 3 ! = 18 sum of digits = 1 answer b" | null |
Question: a hollow iron pipe is 21 cm long and its external diameter is 8 cm . if the thickness of the pipe is 1 cm and iron weights 8 g / cm cube , then find the weight of the pipe .
['A.3.696 kg', 'B.3.686 kg', 'C.2.696 kg', 'D.2.686 kg', 'e ) none of these']A.
explanation : in this type of question , we need to subtract external radius and internal radius to get the answer using the volume formula as the pipe is hollow . oh ! line become a bit complicated , sorry for that , lets solve it . external radius = 4 cm internal radius = 3 cm [ because thickness of pipe is 1 cm ] volume of iron = Ο r 2 h = 22 / 7 β [ 42 β 32 ] β 21 cm 3 = 22 / 7 β 1 β 21 cm 3 = 462 cm 3 weight of iron = 462 * 8 = 3696 gm = 3.696 kg option a | null |
Question: village x has a population of 72000 , which is decreasing at the rate of 1200 per year . village y has a population of 42000 , which is increasing at the rate of 800 per year . in how many years will the population of the two villages be equal ?
A.15.
B.19.
C.11.
D.18.
e ) 13A.
"let the population of two villages be equal after p years then , 72000 - 1200 p = 42000 + 800 p 2000 p = 30000 p = 15 answer is a ." | null |
Question: what is the probability of getting a sum of 8 or 14 when rolling 3 dice simultaneously ?
A.1 / 6.
B.1 / 4.
C.1 / 2.
D.21 / 216.
e ) 32 / 216A.
"the other way would be to list out each option . the options for a sum of 8 : ( 6 , 1,1 ) has 3 options ie ( 6 , 1,1 ) , ( 1 , 6,1 ) , ( 1 , 1,6 ) ; ( 5 , 2,1 ) has 6 options , ( 4 , 3,1 ) has 6 options , ( 4 , 2,2 ) has 3 options , ( 3 , 3,2 ) has 3 options . we have 21 options to get 8 . the options for a sum of 14 : ( 6 , 4,4 ) has 3 options , ( 6 , 5,3 ) has 6 options , ( 6 , 6,2 ) has 3 options , ( 5 , 5,4 ) has 3 options . we have 15 options to get 14 . total : 21 + 15 = 36 / 216 = 1 / 6 . answer a ." | null |
Question: a person purchases 90 clocks and sells 40 clocks at a gain of 10 % and 50 clocks at a gain of 20 % . if he sold all of them at a uniform profit of 15 % , then he would have got rs . 40 less . the cost price of each clock is :
A.50.
B.90.
C.80.
D.28.
e ) 93C.
let c . p . of clock be rs . x . then , c . p . of 90 clocks = rs . 90 x . [ ( 110 % of 40 x ) + ( 120 % of 50 x ) ] - ( 115 % of 90 x ) = 40 44 x + 60 x - 103.5 x = 40 0.5 x = 40 = > x = 80 answer : option c | null |
Question: what is the cost of leveling the field in the form of parallelogram at the rate of rs . 60 / 10 sq . metre , whose base & perpendicular distance from the other side being 34 m & 34 m respectively ?
A.s . 1156.
B.s . 1300.
C.s . 1400.
D.s . 2480.
e ) s . 3600A.
"area of the parallelogram = length of the base * perpendicular height = 34 * 34 = 1156 total cost of levelling = rs . 1156 a" | null |
Question: find the remainder of the division ( 3 ^ 33 ) / 7 .
A.2.
B.3.
C.4.
D.5.
e ) 6E.
find the pattern of the remainders after each power : ( 3 ^ 1 ) / 7 remainder 3 ( 3 ^ 2 ) / 7 remainder 2 ( 3 ^ 3 ) / 7 remainder 6 ( 3 ^ 4 ) / 7 remainder 4 ( 3 ^ 5 ) / 7 remainder 5 ( 3 ^ 6 ) / 7 remainder 1 - - > this is where the cycle ends ( 3 ^ 7 ) / 7 remainder 3 - - > this is where the cycle begins again ( 3 ^ 8 ) / 7 remainder 2 continuing the pattern to ( 3 ^ 33 ) / 7 gives us a remainder of 6 final answer : e ) 6 | null |
Question: an inspector rejects 0.05 % of the meters as defective . how many will he examine to reject 4 ?
A.4000.
B.8000.
C.5000.
D.4500.
e ) 6000B.
"let the number of meters to be examined be x then , 0.05 % of x = 4 ( 5 / 100 ) * ( ( 1 / 100 ) * x = 4 x = 8000 answer is b" | null |
Question: a train passes a platform in 34 seconds . the same train passes a man standing on the platform in 20 seconds . if the speed of the train is 54 km / hr , the length of the platform is
A.280 meter.
B.240 meter.
C.210 meter.
D.200 meter.
e ) none of theseC.
"explanation : speed of the train = 54 km / hr = ( 54 Γ 10 ) / 34 m / s = 15 m / s length of the train = speed Γ time taken to cross the man = 15 Γ 20 = 300 m let the length of the platform = l time taken to cross the platform = ( 300 + l ) / 15 = > ( 300 + l ) / 15 = 34 = > 300 + l = 15 Γ 34 = 510 = > l = 510 - 300 = 210 meter answer : option c" | null |
Question: the average age of 15 students of a class is 15 years . out of these , the average age of 3 students is 14 years and that of the other 11 students is 16 years . the age of the 15 th student is
A.9 years.
B.11 years.
C.14 years.
D.7 years.
e ) 25 yearsD.
"solution age of the 15 th student = [ 15 x 15 - ( 14 x 3 + 16 x 11 ) ] = ( 225 - 218 ) = 7 years . answer d" | null |
Question: a number x is 6 times another number y . the percentage that y is less than x is
A.12.5 %.
B.83.3 %.
C.80 %.
D.11 %.
e ) 1 %B.
say y = 1 and x = 6 . then y = 1 is less than x = 6 by ( 6 - 1 ) / 6 * 100 = 5 / 6 * 100 = 83.3 % . answer : b . | null |
Question: liam is pulled over for speeding just as he is arriving at work . he explains to the police officer that he could not afford to be late today , and has arrived at work only four minutes before he is to start . the officer explains that if liam had driven 5 mph slower for his whole commute , he would have arrived at work exactly on time . if liam ' s commute is 10 miles long , how fast was he actually driving ? ( assume that liam drove at a constant speed for the duration of his commute . )
A.50 mph.
B.45 mph.
C.48 mph.
D.30 mph.
e ) 60 mphD.
"let t be the number of hours he would need to reach office on time . when he is driving with over speed , he reached office 4 min earlier ! so the equation for this is s ( t - 4 / 60 ) = 30 where s is the speed and 30 is the distance . if he decreases his speed by 5 mph then he would have reached his office on time : ( s - 5 ) t = 30 if you solve above equations , you will arrive at t = 2 / 3 hr and s = 30 mph therefore answer is d" | null |
Question: what is the compound interest paid on a sum of rs . 3000 for the period of 2 years at 10 % per annum .
A.630.
B.620.
C.610.
D.600.
e ) none of theseA.
"solution = interest % for 1 st year = 10 interest % for 2 nd year = 10 + 10 % of 10 = 10 + 10 * 10 / 100 = 11 total % of interest = 10 + 11 = 21 total interest = 21 % 3000 = 3000 * ( 21 / 100 ) = 630 answer a" | null |
Question: what is the least integer greater than β 2 + 0.5 ?
A.β 2.
B.β 1.
C.0.
D.1.
e ) 2B.
irst , let ' s take care of the arithmetic : ( - 2 ) + ( 0.5 ) = - 1.5 on a number line , since we ' re adding + . 5 to a number , the total moves to the right ( so we ' re moving from - 2 to - 1.5 ) . next , the question asks for the least integer that is greater than - 1.5 again , we can use a number line . numbers become greater as you move to the right . the first integer to the right of - 1.5 is - 1 . final answer : b | null |
Question: if 5 x + y = 15 , 5 y + z = 25 and 2 z + x = 2 , what is the value of x ?
A.2.
B.5.
C.6.
D.7.
e ) 1A.
"explanation : 5 x + y = 15 β - - - - - - - i * 5 5 y + z = 25 β - - - - - - ii 2 z + x = 2 - - - - - - - - iii subtract ( i ) and ( ii ) 25 x + 5 y + 0 = 75 - 0 + 5 y + z = 25 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - 25 x + 0 β z = 50 β¦ . . . . . . . . . . iv multiply ( iv ) * 2 , we get 50 x β 2 z = 100 adding ( iii ) and ( iv ) we get , 50 x β 2 z = 100 + x + 2 z = 2 - - - - - - - - - - - - - - - - - - - - - - - - 51 x = 102 x = 2 the value of x = 2 answer : a" | null |
Question: a boy perform 5 times a reaction and his reading are 2 , 2.1 , 2 , 2.2 but unfortunately 5 th reading clearly not visible because a drop of chemical fall onto it . but luckily he have mean of all reading which is 2 . please help him in finding 5 th reading .
A.2.
B.1.7.
C.1.9.
D.1.8.
e ) 2.1B.
solution let 5 th reading be x ( 2 + 2.1 + 2 + 2.2 + x ) / 5 = 2 8.3 + x = 10 x = 1.7 answer b | null |
Question: thirty percent of the members of a swim club have passed the lifesaving test . among the members who have not passed the test , 12 have taken the preparatory course and 30 have not taken the course . how many members are there in the swim club ?
A.60.
B.80.
C.100.
D.120.
e ) 140A.
30 % of the members have passed the test , thus 70 % have not passed the test . we also know that 30 + 12 = 42 members have not passed the test , thus 0.7 * total = 42 - - > total = 60 . answer : a . | null |
Question: a certain rectangular window is ( 1 / 3 ) times as long as it is wide . if its perimeter is 28 feet , what are its dimensions in terms of length by width ?
['A.12 by 2', 'B.11 by 3', 'C.10.5 by 3.5', 'D.10 by 4', 'e ) 9 by 3']C.
2 x + 2 y = 28 x + y = 14 x + ( 1 / 3 ) x = 14 4 x = 14 * 3 x = 10.5 answer c | null |
Question: there are 8 teams in a certain league and each team plays each of the other teams exactly once . if each game is played by 2 teams , what is the total number of games played ?
A.15.
B.16.
C.28.
D.56.
e ) 64C.
"number of ways 2 teams can be selected out of 8 teams : c 8 / 2 = 8 β 7 / 2 = 28 ans : ' ' c ' '" | null |
Question: 3 candidates in an election and received 1136 , 7636 and 11628 votes respectively . what % of the total votes did the winning candidate gotin that election ?
A.40 %.
B.55 %.
C.57 %.
D.60 %.
e ) 62 %C.
"total number of votes polled = ( 1136 + 7636 + 11628 ) = 20400 so , required percentage = 11628 / 20400 * 100 = 57 % c" | null |
Question: if p is the product of the integers from 1 to 36 , inclusive , what is the greatest integer k for which 3 ^ k is a factor of p ?
A.13.
B.15.
C.17.
D.19.
e ) 21C.
"36 ! has 3 , 6 , 9 , . . . . 30 , 33 , 36 as factors , which are 12 multiples of 3 . we need to add 5 more to these 12 because of 9 , 18 , 27 , and 36 . the greatest integer of k is 17 . the answer is c ." | null |
Question: at what rate percent on simple interest will rs . 1750 amount to rs . 2000 in 3 years ?
A.4 %.
B.3 6 / 7 %.
C.4.76 %.
D.5 %.
e ) 6 %C.
"explanation : 250 = ( 1750 x 3 xr ) / 100 r = 4.76 % answer : option c" | null |
Question: what is the total surface area in square meters of a rectangular solid whose length is 8 meters , width is 7 meters , and depth is 4 meters ?
A.132 m 2.
B.145 m 2.
C.165 m 2.
D.152 m 2.
e ) 120 m 2A.
"surface area of a cuboid = 2 ( lb + bh + lh ) = 2 ( 8 * 7 + 7 * 4 + 8 * 4 ) = 2 ( 56 + 28 + 32 ) = 2 * 116 = 132 m 2 answer : a" | null |
Question: the perimeter of a square is equal to the perimeter of a rectangle of length 19 cm and breadth 14 cm . find the circumference of a semicircle whose diameter is equal to the side of the square . ( round off your answer to two decimal places )
A.22.78.
B.23.54.
C.23.5.
D.24.55.
e ) 25.93E.
"let the side of the square be a cm . perimeter of the rectangle = 2 ( 19 + 14 ) = 66 cm perimeter of the square = 66 cm i . e . 4 a = 66 a = 16.5 diameter of the semicircle = 16.5 cm circumference of the semicircle = 1 / 2 ( β ) ( 16.5 ) = 1 / 2 ( 22 / 7 ) ( 16.5 ) = 25.93 cm to two decimal places answer : e" | null |
Question: john and steve are speed walkers in a race . john is 15 meters behind steve when he begins his final push . john blazes to the finish at a pace of 4.2 m / s , while steve maintains a blistering 3.7 m / s speed . if john finishes the race 2 meters ahead of steve , how long was john β s final push ?
A.13 seconds.
B.17 seconds.
C.26 seconds.
D.34 seconds.
e ) 51 secondsD.
"let t be the time that john spent for his final push . thus , per the question , 4.2 t = 3.7 t + 15 + 2 - - - > 0.5 t = 17 - - - > t = 34 seconds . d is the correct answer ." | null |
Question: a ratio between two numbers is 3 : 4 and their l . c . m . is 84 . the first number is
A.60.
B.45.
C.21.
D.15.
e ) noneC.
"sol . let the required numbers be 3 x and 4 x . then , their l . c . m . is 12 x . β΄ 12 x = 84 β x = 7 . hence , the first number is 21 . answer c" | null |
Question: the principal that amounts to rs . 4813 in 3 years at 6 1 / 4 % per annum c . i . compounded annually , is ?
A.s . 3096.
B.s . 4036.
C.s . 4085.
D.s . 4096.
e ) s . 5096B.
"principal = [ 4913 / ( 1 + 25 / ( 4 * 100 ) ) 3 ] = 4813 * 16 / 17 * 16 / 17 * 16 / 17 = rs . 4036 . answer : b" | null |
Question: the area of a rectangular plot is 18 times its breadth . if the difference between the length and the breadth is 10 metres , what is its breadth ?
A.10 metres.
B.8 metres.
C.7.5 metres.
D.data inadequate.
e ) none of theseB.
"l Γ b = 18 Γ b β΄ l = 18 m and l β b = 10 β΄ b = 18 β 10 = 8 m answer b" | null |
Question: in a certain archery competition , points were awarded as follows : the first place winner receives 11 points , the second place winner receives 7 points , the third place winner receives 5 points and the fourth place winner receives 2 points . no other points are awarded . john participated several times in the competition and finished first , second , third , or fourth each time . the product of all the points he received was 38500 . how many times did he participate in the competition ?
A.6.
B.7.
C.8.
D.9.
e ) 10B.
38500 = 2 * 2 * 5 * 5 * 5 * 7 * 11 john participated 7 times . the answer is b . | null |
Question: the first flight out of phoenix airport had a late departure . if the next 3 flights departed on - time , how many subsequent flights need to depart from phoenix on - time , for the airport ' s on - time departure rate to be higher than 40 % ?
A.4.
B.6.
C.5.
D.2.
e ) 8D.
we need on - time departure rate to be higher than 4 / 10 , so it should be at least 5 / 11 , which means that 5 out of 11 flights must depart on time . since for now 3 out of 4 flights departed on time then 5 - 3 = 2 subsequent flights need to depart on - time . answer : d | null |
Question: a rainstorm increased the amount of water stored in state j reservoirs from 160 billion gallons to 200 billion gallons . if the storm increased the amount of water in the reservoirs to 40 percent of total capacity , approximately how many billion gallons of water were the reservoirs short of total capacity prior to the storm ?
A.260.
B.280.
C.325.
D.340.
e ) 355D.
"let total capacity be x we know 200 = 0.40 x x = 200 / 0.40 = 500 prior to storm , we had 160 bn gallons 500 - 160 = 340 answer : d" | null |
Question: a number when divided by a divisor leaves a remainder of 23 . when twice the original number is divided by the same divisor , the remainder is 11 . what is the value of the divisor ?
A.12.
B.13.
C.35.
D.36.
e ) 59D.
"let the number is n , the divisor = d , i will make the two equations - n = xd + 23 2 n = yd + 11 where x and y are integers solving them : d ( y - 2 x ) = 36 as d is also integer and 36 is a prime number , the d should be 36 to satisfy the above equation . hence answer is ' d '" | null |
Question: two years ago , ram put $ 500 into a savings account . at the end of the first year , his account had accrued $ 100 in interest bringing his total balance to $ 600 . the next year , his account balance increased by 10 % . at the end of the two years , by what percent has ram ' s account balance increased from his initial deposit of $ 500 ?
A.19 %.
B.28 %.
C.30 %.
D.32 %.
e ) 25 %D.
investment 500 dollars 1 st year total gained = 100 total amount end of first year = 600 second year account increased by 10 % = 600 * 0.1 = 60 therefore total amount by second year end = 660 so total percentage increase in money = ( 660 - 500 ) * 100 / 500 = 32 % correct answer d = 32 % | null |
Question: population of a city in 20004 was 1000000 . if in 2005 there isan increment of 10 % , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 45 % , then find the population of city atthe end of the year 2007
A.976374.
B.979923.
C.980241.
D.1036750.
e ) 1083875D.
"required population = p ( 1 + r 1 / 100 ) ( 1 - r 2 / 100 ) ( 1 + r 3 / 100 ) = p ( 1 + 10 / 100 ) ( 1 - 35 / 100 ) ( 1 + 45 / 100 ) = 1036750 d" | null |
Question: if the sum of two numbers is 45 and the h . c . f and l . c . m of these numbers are 3 and 100 respectively , then the sum of the reciprocal of the numbers is equal to :
A.103 / 300.
B.103 / 200.
C.112 / 300.
D.154 / 140.
e ) 100 / 300A.
let the numbers be a and b . then , a + b = 45 and ab = 3 * 100 = 300 . required sum = 1 / a + 1 / b = ( a + b ) / ab = 103 / 300 answer : a | null |
Question: what is the value of ( 2 ) ^ - 3 ?
A.1 / 6.
B.1 / 5.
C.1 / 8.
D.1 / 9.
e ) 1 / 7C.
"2 ^ - 3 = 1 / ( 2 ) ^ 3 = 1 / 8 answer : c" | null |
Question: mr . kramer , the losing candidate in a two - candidate election , received 942,568 votes , which was exactly 45 percent of all votes cast . approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast ?
A.9 %.
B.12 %.
C.15 %.
D.17 %.
e ) 20 %A.
"let me try a simpler one . lets assume that candidate got 45 % votes and total votes is 100 . candidate won = 45 remaining = 55 to get 50 % , candidate requires 5 votes from 100 which is 5 % and 5 votes from 55 . 5 / 55 = 1 / 11 = . 09 = 9 % which is approx 9 % . hence the answer is a ." | null |
Question: pipe a can fill a tank in 6 hours . due to a leak at the bottom , it takes 12 hours for the pipe a to fill the tank . in what time can the leak alone empty the full tank ?
A.13.
B.17.
C.18.
D.19.
e ) 12E.
"let the leak can empty the full tank in x hours 1 / 6 - 1 / x = 1 / 12 = > 1 / x = 1 / 6 - 1 / 12 = ( 2 - 1 ) / 12 = 1 / 12 = > x = 12 . answer : e" | null |
Question: w and x start a business with rs . 5000 and rs . 20000 respectively . hoe should they share their profits at the end of one year ?
A.4 : 1.
B.1 : 3.
C.1 : 4.
D.1 : 5.
e ) 2 : 1C.
they should share the profits in the ratio of their investments . the ratio of the investments made by w and x = 5000 : 20000 = > 1 : 4 . answer : c | null |
Question: in an examination , a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer . if he attempts all 80 questions and secures 130 marks , the no of questions he attempts correctly is :
A.A.35.
B.B.38.
C.C.90.
D.D.88.
e ) e ) 42E.
"let the number of correct answers be x . number of incorrect answers = ( 60 β x ) . 4 x β ( 80 β x ) = 130 = > 5 x = 210 = > x = 42 answer : e" | null |
Question: what is the least number should be added to 1056 , so the sum of the number is completely divisible by 29 ?
A.17.
B.27.
C.37.
D.47.
e ) 57A.
( 1056 / 29 ) gives remainder 12 17 + 12 = 29 , so we need to add 17 a | null |
Question: an optometrist charges $ 150 per pair for soft contact lenses and $ 85 per pair for hard contact lenses . last week she sold 5 more pairs of soft lenses than hard lenses . if her total sales for pairs of contact lenses last week were $ 1455 , what was the total number of pairs of contact lenses that she sold ?
A.11.
B.13.
C.15.
D.17.
e ) 19A.
( x + 5 ) * 150 + x * 85 = 1455 = > x = 3 total lens = 3 + ( 3 + 5 ) = 11 answer a | null |
Question: if the price of an article went up by 30 % , then by what percent should it be brought down to bring it back to its original price ?
A.25 %.
B.23 1 / 13 %.
C.16 7 / 3 %.
D.16 6 / 3 %.
e ) 16 2 / 3 %B.
"let the price of the article be rs . 100 . 30 % of 100 = 30 . new price = 100 + 30 = rs . 130 required percentage = ( 130 - 100 ) / 130 * 100 = 30 / 130 * 100 = 23 1 / 13 % answer : b" | null |
Question: if n is the product of all the integers from 5 to 20 , inclusive , what is the greatest integer k for which 2 ^ k is a factor of n ?
A.11.
B.12.
C.13.
D.14.
e ) 15E.
20 / 2 = 10 10 / 2 = 5 ans : 10 + 5 = 15 answer : e | null |
Question: the perimeter of an isosceles right triangle is 14 + 14 sq rt 2 . what is the length of the hypotenuse of the triangle ?
A.5.
B.6.
C.7.
D.8.
e ) 9.899E.
"side of triangle is a then perimeter = a + a + a . sqrt 2 ( right angle and pythagorus ) = 2 a + a . sqrt 2 = 14 + 14 sqrt 2 or , a . ( 2 + sqrt 2 ) = 14 ( 1 + sqrt 2 ) , a = 14 * ( 1 + sqrt 2 ) / 2 + sqrt 2 = 14 * 2.414 / 3.414 = then hypotenuse = 9.899 e" | null |
Question: sushil got thrice as many marks in english as in science . his total marks in english , science and maths are 180 . if the ratio of his marks in english and maths is 1 : 2 , find his marks in science ?
A.19.
B.77.
C.66.
D.55.
e ) 31A.
"s : e = 1 : 3 e : m = 1 : 2 - - - - - - - - - - - - s : e : m = 1 : 3 : 6 1 / 10 * 190 = 19 answer : a" | null |
Question: what is 82 % of 3 / 5 ?
A.6.9.
B.0.492.
C.0.6845.
D.0.6859.
e ) 0.69B.
"82 % * ( 3 / 5 ) = 0.82 * 0.6 = 0.492 answer : b" | null |
Question: country c imposes a two - tiered tax on imported cars : the first tier imposes a tax of 12 % of the car ' s price up to a certain price level . if the car ' s price is higher than the first tier ' s level , the tax on the portion of the price that exceeds this value is 9 % . if ron imported a $ 18000 imported car and ended up paying $ 1950 in taxes , what is the first tier ' s price level ?
A.$ 11500.
B.$ 11000.
C.$ 12000.
D.$ 12100.
e ) $ 12500B.
let t be the tier price , p be total price = 18000 per the given conditions : 0.12 t + 0.09 ( p - t ) = 1950 0.12 t + 0.09 * 18000 - 0.09 t = 1950 0.03 t + 1620 = 1950 0.03 t = 1950 - 1620 = 330 t = 330 / 0.03 = 11000 answer b | null |
Question: a 90 cm long wire is to be cut into two pieces so that one piece will be 2 / 7 th of the other , how many centimeters will the shorter piece be ?
A.A.73.
B.B.20.
C.C.83.
D.D.21.
e ) e ) 52B.
"explanation : 1 : 2 / 7 = 7 : 2 2 / 9 * 90 = 20 answer : option b" | null |
Question: the sum of 3 integers is 33 . the largest integer is 3 times the middle integer , and the smallest integer is 23 less than the largest integer . what is the product of the 3 integers ?
A.192.
B.203.
C.214.
D.225.
e ) 236A.
let x be the middle integer . then the largest is 3 x and the smallest is 3 x - 23 . 3 x - 23 + x + 3 x = 33 x = 8 the three integers are 1 , 8 , and 24 . the product is 1 * 8 * 24 = 192 the answer is a . | null |
Question: how many integers between 1 and 10 ^ 19 are such that the sum of their digits is 2 ?
A.190.
B.210.
C.211.
D.230.
e ) 231A.
"the integers with a sum of 2 are : 2 , 20 , 200 , . . . , 2 * 10 ^ 18 and there are 19 integers in this list . also , these integers have a sum of 2 : 11 101 , 110 1001 , 1010 , 1100 etc . . . the number of integers in this list is 1 + 2 + . . . + 18 thus , the total number of integers is 1 + 2 + . . . + 18 + 19 = 20 * 19 / 2 = 190 the answer is a ." | null |
Question: joe β s average ( arithmetic mean ) test score across 4 equally weighted tests was 70 . he was allowed to drop his lowest score . after doing so , his average test score improved to 75 . what is the lowest test score that was dropped ?
A.20.
B.25.
C.55.
D.65.
e ) 80C.
"the arithmetic mean of 4 equally weighted tests was 70 . so what we can assume is that we have 4 test scores , each 70 . he dropped his lowest score and the avg went to 75 . this means that the lowest score was not 70 and other three scores had given the lowest score 5 each to make it up to 70 too . when the lowest score was removed , the other 3 scores got their 5 back . so the lowest score was 3 * 5 = 15 less than 70 . so the lowest score = 70 - 15 = 55 answer ( c )" | null |
Question: an error 2 % in excess is made while measuring the sideofa square . the % of error in the calculated area of the square is ?
A.4 %.
B.4.04 %.
C.4.15 %.
D.5 %.
e ) 5.24 %B.
"100 cm is read as 102 cm . a 1 = ( 100 x 100 ) cm 2 and a 2 ( 102 x 102 ) cm 2 . ( a 2 - a 1 ) = [ ( 102 ) 2 - ( 100 ) 2 ] = ( 102 + 100 ) x ( 102 - 100 ) = 404 cm 2 . percentage error = 404 x 100 % = 4.04 % 100 x 100 b" | null |
Question: what is the normal price of an article sold at $ 144 after two successive discounts of 10 % and 20 % ?
A.$ 184.
B.$ 192.
C.$ 200.
D.$ 208.
e ) $ 216C.
"0.8 * 0.9 * cost price = $ 144 cost price = $ 200 the answer is c ." | null |
Question: the length of a room is 6.5 m and width is 2.75 m . what is the cost of paying the floor by slabs at the rate of rs . 600 per sq . metre .
A.rs . 18725.
B.rs . 16725.
C.rs . 30725.
D.rs . 10725.
e ) rs . 20725D.
"area = 6.5 * 2.75 sq . metre . cost for sq . metre . = rs . 600 hence , total cost = 6.5 * 2.75 * 600 = rs . 10725 answer : d" | null |
Question: the number of diagonals of a polygon of n sides is given by the formula v = n ( n - 3 ) / 2 . if a polygon has twice as many diagonals as sides , how many sides does it have ?
A.3.
B.5.
C.6.
D.7.
e ) 8B.
"v = n ( n - 3 ) v = 2 * n 2 n = n ( n - 3 ) = > 2 = n - 3 = > n = 5 answer b" | null |
Question: what is the least common multiple of 12,27 and 40
A.8521.
B.1080.
C.368.
D.8979.
e ) 6584B.
"factors of 12 = 2 * 2 * 3 factors of 27 = 3 * 3 * 3 factors of 40 = 2 * 2 * 2 * 5 thus the l . c . m is 2 ^ 3 * 3 ^ 3 * 5 = 1080 the answer is b" | null |
Question: saturn travels around the sun at an approximate speed of 5.82 miles per second . this speed is how many kilometers per hour ? ( 1 km = 0.6 miles )
A.30,560.
B.31,650.
C.32,740.
D.33,830.
e ) 34,920E.
the speed is 5.82 miles / s . then 5.82 / 0.6 = 9.7 km / s 9.7 * 3600 = 34,920 kph the answer is e . | null |
Question: total 30 cows 10 cow gives each 2 liter milk 10 cow gives each 3 / 4 liter milk 10 cow gives each 1 / 4 liter milk this is split into 3 son per each 10 cows & 10 liter milk how ?
A.10.
B.12.
C.15.
D.16.
e ) 18A.
"10 cow 2 liter each = 20 liter 10 cow 3 / 4 liter each = 3 / 4 = 0.758 * 10 = 7.5 10 cow 1 / 4 liter each = 1 / 4 = 0.25 * 10 = 2.5 add 20 + 7.5 + 2.5 = 30 milk split into 3 son each 10 liter then 30 / 3 = 10 answer : a" | null |
Question: if 15 % of 30 % of 50 % of a number is 108 , then what is the number ?
A.4000.
B.3050.
C.4400.
D.4800.
e ) none of theseD.
"let the number be a given , 15 / 100 * 30 / 100 * 50 / 100 * a = 108 = > 3 / 20 * 3 / 10 * 1 / 2 * a = 108 = > a = 10 * 20 * 10 * 2 = 4800 . answer : d" | null |
Question: andy solves problems 75 to 125 inclusive in a math exercise . how many problems does he solve ?
A.53.
B.52.
C.51.
D.50.
e ) 49C.
"125 - 75 + 1 = 51 ' c ' is the answer" | null |
Question: if a boat goes 7 km upstream in 42 minutes and the speed of the stream is 6 kmph , then the speed of the boat in still water is
A.12 kmph.
B.13 kmph.
C.14 kmph.
D.15 kmph.
e ) none of theseE.
explanation : rate upstream = ( 7 / 42 ) * 60 kmh = 10 kmph . speed of stream = 6 kmph . let speed in still water is x km / hr then , speed upstream = ( x Γ― ΒΏ Β½ 6 ) km / hr . x - 6 = 10 or x = 16 kmph answer : e | null |
Question: a worker earns $ 20 on the first day and spends $ 15 on the second day . the worker earns $ 20 on the third day and spends $ 15 on the fourth day . if this pattern continues , on which day will the worker first reach a net total of $ 80 ?
A.24.
B.25.
C.27.
D.30.
e ) 32B.
"every two days , the net total is $ 5 . after 24 days , the worker will have $ 60 . on day 25 , the worker will receive $ 20 for a net total of $ 80 . the answer is b ." | null |
Question: 6 ) a marketing firm determined that , of 260 households surveyed , 80 used neither brand a nor brand b soap . 60 used only brand a soap and for every household that used both brands of soap , 3 used only brand b soap . how many of the 200 household surveyed used both brands of soap ?
A.A.15.
B.B.20.
C.C.30.
D.D.40.
e ) e ) 45C.
"180 = at least one of soap a or b both brands = x brand b = 3 x = > 60 + x + 3 x = 180 = > 4 x = 120 = > x = 30 answer - c" | null |
Question: 26 buckets of water fill a tank when the capacity of each bucket is 13.5 litres . how many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres ?
A.30.
B.39.
C.60.
D.data inadequate.
e ) none of theseB.
"capacity of the tank = 26 Γ£ β 13.5 = 351 litres when the capacity of each bucket = 9 litres , then the required no . of buckets = 351 Γ’ Β β 9 = 39 answer b" | null |
Question: a train is running at a speed of 40 km / hr and it crosses a post in 22.5 seconds . what is the length of the train ?
A.190 metres.
B.160 metres.
C.200 metres.
D.120 metres.
e ) 250 metresE.
"speed of the train , v = 40 km / hr = 40000 / 3600 m / s = 400 / 36 m / s time taken to cross , t = 22.5 s distance covered , d = vt = ( 400 / 36 ) Γ£ β 22.5 = 250 m distance covered is equal to the length of the train = 250 m correct answer is 250 metres e" | null |
Question: at a florist shop on a certain day , all corsages sold for either $ 20 or $ 30 . if 10 of the corsages that sold for $ 30 had instead sold for $ 20 , then the store ' s revenue from corsages that day would have been reduced by 20 percent . what was the store ' s actual revenue from corsages that day ?
A.$ 200.
B.$ 400.
C.$ 500.
D.$ 800.
e ) $ 1000C.
"let , no . of corsages @ $ 20 = x , no . of corsages @ $ 30 = y and revenue = r so , 20 x + 30 y = r . . . . . . . . . ( 1 ) now , given the situation , 20 ( x + 10 ) + 30 ( y - 10 ) = r - . 2 r = > 20 x + 200 + 30 y - 300 = . 8 r = > 20 x + 30 y = . 8 r + 100 . . . . . . . . . . . . ( 2 ) so , r = . 8 r + 100 = > r = 500 the answer is c ." | null |
Question: it is currently 8 : 12 pm . at what time in the morning was it exactly 205,106 minutes ago ?
A.9 : 14.
B.9 : 16.
C.9 : 42.
D.9 : 44.
e ) 9 : 46E.
convert 205,106 minutes to hours by dividing by 60 : 205,106 / 60 = 3,418 r 26 . that is 3,418 hours and 26 minutes . convert 3,418 hours to days by dividing by 24 : 3,418 / 24 = 142 r 10 . that is 142 days and 10 hours . now , 142 days previous was 8 : 12 pm . another 10 hours previous was 10 : 12 am . another 26 minutes previous was 9 : 46 am ( subtract the 12 minutes of 10 : 12 from 26 to get 14 . then subtract 14 from 60 to get 46 ) . e | null |
Question: a circular ground whose diameter is 70 metres , has a 2.8 metre - broad garden around it . what is the area of the garden in square metres ?
A.540.72.
B.740.64.
C.640.64.
D.620.45.
e ) 725.26C.
"req . area = Γ― β¬ [ ( 37.8 ) 2 Γ’ β¬ β ( 35 ) 2 ] = 22 Γ’ Β β 7 Γ£ β ( 72.8 Γ£ β 2.8 ) [ since a 2 - b 2 = ( a + b ) ( a - b ) ] = 22 Γ£ β 72.8 Γ£ β 0.4 = 640.64 sq m answer c" | null |
Question: a 70 kg metal bar made of alloy of tin and silver lost 7 kg of its weight in the water . 10 kg of tin loses 1.375 kg in the water ; 5 kg of silver loses 0.375 kg . what is the ratio of tin to silver in the bar ?
A.1 / 4.
B.2 / 5.
C.1 / 2.
D.3 / 5.
e ) 2 / 3E.
"you can simply use this formula to avoid confusion : w 1 / w 2 = ( a 2 - aavg ) / ( avg - a 1 ) here is how you will find the values of a 1 an a 2 . we have an overall loss ( average loss ) . the average loss is 7 kg when 70 kg alloy is immersed . this is a loss of ( 7 / 70 ) * 100 = 10 % . this is aavg the loss of tin is 1.375 kg for every 10 kg . this means it loses ( 1.375 / 10 ) * 100 = 13.75 % of its weight in water . this is a 1 . the loss of silver is . 375 kg for every 5 kg . this means it loses ( . 375 / 5 ) * 100 = 7.5 % of its weight in water . this is a 2 . weight of tin / weight of silver = ( silver ' s loss - avg loss ) / ( avg loss - tin ' s loss ) x / y = ( 7.5 - 10 ) / ( 10 - 13.75 ) = 2 / 3 e" | null |
Question: what is the rate percent when the simple interest on rs . 720 amount to rs . 180 in 4 years ?
A.6.25.
B.7.25.
C.8.25.
D.9.25.
e ) 10.25A.
"180 = ( 720 * 4 * r ) / 100 r = 6.25 % answer : a" | null |
Question: when 242 is divided by a certain divisor the remainder obtained is 15 . when 698 is divided by the same divisor the remainder obtained is 27 . however , when the sum of the two numbers 242 and 698 is divided by the divisor , the remainder obtained is 5 . what is the value of the divisor ?
A.11.
B.17.
C.13.
D.23.
e ) 37E.
let that divisor be x since remainder is 15 or 27 it means divisor is greater than 27 . now 242 - 15 = 227 = kx ( k is an integer and 234 is divisble by x ) similarly 698 - 27 = 671 = lx ( l is an integer and 689 is divisible by x ) adding both 698 and 242 = ( 227 + 671 ) + 15 + 27 = x ( k + l ) + 42 when we divide this number by x then remainder will be equal to remainder of ( 42 divided by x ) = 5 hence x = 42 - 5 = 37 hence e | null |
Subsets and Splits
No saved queries yet
Save your SQL queries to embed, download, and access them later. Queries will appear here once saved.