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Question: a man has $ 10,000 to invest . he invests $ 4000 at 5 % and $ 3500 at 4 % . in order to have a yearly income of $ 500 , he must invest the remainder at :
A.4.6 %.
B.3.6 %.
C.6.4 %.
D.7.8 %.
e ) 8.9 %C.
"c 6.4 % income from $ 4000 at 5 % in one year = $ 4000 of 5 % . = $ 4000 × 5 / 100 . = $ 4000 × 0.05 . = $ 200 . income from $ 3500 at 4 % in one year = $ 3500 of 4 % . = $ 3500 × 4 / 100 . = $ 3500 × 0.04 . = $ 140 . total income from 4000 at 5 % and 3500 at 4 % = $ 200 + $ 140 = $ 340 . remaining income amount in order to have a yearly income of $ 500 = $ 500 - $ 340 . = $ 160 . total invested amount = $ 4000 + $ 3500 = $ 7500 . remaining invest amount = $ 10000 - $ 7500 = $ 2500 . we know that , interest = principal × rate × time interest = $ 160 , principal = $ 2500 , rate = r [ we need to find the value of r ] , time = 1 year . 160 = 2500 × r × 1 . 160 = 2500 r 160 / 2500 = 2500 r / 2500 [ divide both sides by 2500 ] 0.064 = r r = 0.064 change it to a percent by moving the decimal to the right two places r = 6.4 % therefore , he invested the remaining amount $ 2500 at 6.4 % in order to get $ 500 income every year ." | null |
Question: workers decided to raise rs . 3 lacs by equal contribution from each . had they contributed rs . 50 eachextra , the contribution would have been rs . 3.25 lacs . how many workers were they ?
A.350.
B.400.
C.500.
D.550.
e ) 590C.
"n * 50 = ( 325000 - 300000 ) = 25000 n = 25000 / 50 = 500 c" | null |
Question: in the xy - coordinate system , if ( m , n ) and ( m 1 2 , n 1 k ) are two points on the line with the equation x 5 2 y 1 5 , then k 5
A.1 / 2.
B.1.
C.2.
D.5 / 2.
e ) 4B.
step 1 : analyze the question for any question involving the equation of a line , a good place to start is the slope - intercept form of the line , y = mx 1 b . remember that if you have two points on a line , you can derive the entire equation , and if you have an equation of the line , you can calculate any points on that line . step 2 : state the task we are solving for k , which is the amount by which the y - coordinate increases when the x - coordinate increases by 2 . step 3 : approach strategically the slope of a line is the ratio between the change in y and the change in x . in other words , every time the x - coordinate increases by 1 , the y - coordinate increases by the amount of the slope . the equation of the line in the question stem is defined as x = 2 y + 5 . we must isolate y to have slope - intercept form : so the slope of this line is 1 / 2 . this means that for every change of + 1 in the x direction , there is a change of + 1 / 2 in the y direction . then we know that , because there is an increase in 2 units in the x direction when moving from m to m + 2 , there must be a change of 1 unit in the y direction when moving from n to n + k . so k = 1 . since there are variables that eventually cancel ( m and n are not part of the answers ) , we can pick numbers . let ’ s say that you choose the y - coordinate of the point ( m , n ) to be 0 to allow for easier calculations . using the equation we ’ re given to relate x - and y - coordinates , we can calculate the x - coordinate : so ( m , n ) is the point ( 5 , 0 ) . now we ’ ll plug our values of m and n into the next point : ( m + 2 , n + k ) . that yields ( 7 , k ) . all we have to do is plug an x - coordinate of 7 into the equation to solve for k , the y - coordinate : answer is b | null |
Question: if 625 ^ ( - x ) + 25 ^ ( - 2 x ) + 5 ^ ( - 4 x ) = 11 , what is the value of x ?
A.- 4.
B.- 1 / 4.
C.0.
D.1 / 4.
e ) 4D.
we ' re told that 625 ^ ( - x ) + 25 ^ ( - 2 x ) + 5 ^ ( - 4 x ) = 15 . we ' re asked for the value of x . since each of the calculated terms must be positive ( regardless of what the exponent is ) , we can use thebasesto our advantage . . . . . with answer a , we ' d have 625 ^ 4 , which is much bigger than 15 ( and we ' d be adding to that big number ) . eliminate a . with answer e , we ' d have 625 ^ ( - 4 ) , which would create a tiny fraction ( and we ' d add some other fractions to it , so the total would be much too small ) . eliminate e . with answer d , we ' d have 625 ^ ( - 1 / 4 ) , which will also be a fraction ( just not as tiny as the one in answer e ) , but the total would still be too small . eliminate d . with answer c , anything to the ' 0 power ' is 1 , so we ' d have 1 + 1 + 1 = 3 . this is not 15 . eliminate c . d | null |
Question: find √ ? / 13 = 4 ?
A.76.
B.5776.
C.304.
D.2704.
e ) noneD.
"answer let √ n / 13 = 4 then √ n = 13 x 4 = 52 ∴ n = 52 x 52 = 2704 . correct option : d" | null |
Question: an athlete runs 200 metres race in 25 seconds . what is his speed ?
A.23.
B.38.
C.37.
D.30.
e ) 28.8E.
"speed = distance / time = 200 / 25 = 8 m / s = 8 * 18 / 5 = 28.8 km / hr answer : e" | null |
Question: how many odd prime numbers are there less than 125 ?
A.29.
B.34.
C.44.
D.54.
e ) 64A.
odd prime number less than 125 : 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 , 29 , 31 , 37 , 41 , 43 , 47 , 53 , 59 , 61 , 67 , 71 , 73 , 79 , 83 , 89 , 97 , 101 , 103 , 107 , 109 , 113 there is 29 the odd prime number answer is a | null |
Question: the radius of a semi circle is 3.1 cm then its perimeter is ?
A.15.94.
B.12.41.
C.16.1.
D.32.92.
e ) 32.3A.
"36 / 7 r = 6.3 = 15.94 answer : a" | null |
Question: a , band c can do a piece of work in 11 days , 5 days and 55 days respectively , working alone . how soon can the work be done if a is assisted by band c on alternate days ?
A.5 days.
B.8 days.
C.9 days.
D.10 days.
e ) 11 daysA.
( a + b ) ' s 1 day ' s work = 1 / 11 + 1 / 5 = 16 / 55 ( a + c ) ' s 1 day ' s work = 1 / 11 + 1 / 55 = 6 / 55 work done in 2 day ' s = 16 / 55 + 6 / 55 = 2 / 5 2 / 5 th work done in 2 days work done = 5 / 2 * 2 = 5 days answer : a | null |
Question: find the number of shares that can be bought for rs . 8200 if the market value is rs . 20 each with brokerage being 2.5 % .
A.237.
B.270.
C.177.
D.166.
e ) 111C.
"explanation : cost of each share = ( 20 + 2.5 % of 20 ) = rs . 20.5 therefore , number of shares = 8200 / 20.5 = 400 answer : c" | null |
Question: two trains 300 m and 400 m long run at the speed of 36 kmph and 18 kmph in opposite directions in parallel tracks . the time which they take to cross each other is ?
A.5.6 sec.
B.46.67 sec.
C.10.8 sec.
D.12.6 sec.
e ) 15 secB.
"relative speed = 36 + 18 = 54 kmph * 5 / 18 = 15 m / s distance covered in crossing each other = 300 + 400 = 700 m required time = 700 * 1 / 15 = 46.67 sec answer is b" | null |
Question: if 1 / ( x + 2 ) + 1 / ( x - 2 ) = 1 / ( x + 2 ) , what is the value of x ?
A.- 1.
B.2.
C.1.
D.- 2.
e ) 0D.
"if we solve the question , we get x = - 2 . option : d" | null |
Question: find the compound interest on $ 1200 for 1 year at 20 % p . a . if ci is component yearly ?
A.$ 120.
B.$ 150.
C.$ 240.
D.$ 250.
e ) $ 300C.
"a = p ( 1 + r / 100 ) ^ t = 1200 ( 1 + 20 / 100 ) ^ 1 = 1200 * 6 / 5 = $ 1440 ci = a - p = 1440 - 1200 = $ 240 answer is c" | null |
Question: find the perimeter and area of a square of side 12 cm .
A.144.
B.121.
C.169.
D.196.
e ) 100A.
"we know that the perimeter of square = 4 ã — side side = 12 cm therefore , perimeter = 4 ã — 12 cm = 48 cm now , area of the square = ( side ã — side ) sq . units = 12 ã — 12 cm â ² = 144 cm â ² answer : a" | null |
Question: if the sides of a cube are in the ratio 5 : 4 . what is the ratio of their diagonals ?
A.4 : 3.
B.5 : 4.
C.4 : 7.
D.3 : 4.
e ) 4 : 5B.
"explanation : diagonal of a cube = a √ 3 where a is side a 1 : a 2 = 5 : 4 d 1 : d 2 = 5 : 4 where √ 3 cancelled both side answer : b" | null |
Question: bob wants to run a mile in the same time as his sister . if bob ’ s time for a mile is currently 10 minutes 40 seconds and his sister ’ s time is currently 9 minutes 17 seconds , by what percent does bob need to improve his time in order run a mile in the same time as his sister ?
A.3 %.
B.5 %.
C.8 %.
D.10 %.
e ) 13 %E.
bob ' s time = 640 secs . his sis ' time = 557 secs . percent increase needed = ( 640 - 557 / 640 ) * 100 = 83 / 640 * 100 = 13 % . ans ( e ) . | null |
Question: a train sets off at 9 : 00 am at the speed of 70 km / h . another train starts at 10 : 30 am in the same direction at the rate of 80 km / h . at what time will the second train catch the first train ?
A.7 : 00.
B.8 : 00.
C.9 : 00.
D.10 : 00.
e ) 11 : 00C.
in one hour and thirty minutes the first train travels 105 km . the second train catches the first train at a rate of 80 km / h - 70 km / h = 10 km / h . the second train will catch the first train in 105 / 10 = 10.5 hours , so at 9 : 00 pm . the answer is c . | null |
Question: working together , jose and jane can complete an assigned task in 15 days . however , if jose worked alone and complete half the work and then jane takes over the task and completes the second half of the task , the task will be completed in 45 days . how long will jose take to complete the task if he worked alone ? assume that jane is more efficient than jose
A.26 days.
B.31 days.
C.50 days.
D.65 days.
e ) 36 daysC.
"assume : jose does 1 job in x days , so jose does 1 / x job in a day jane does 1 job in y days , so jane does 1 / y job in a day together , they does ( x + y ) / xy job in a day . this is equals to 1 / 20 . so ( x + y ) / xy = 1 / 15 15 ( x + y ) = xy next , we ' re told 1 job takes 45 days to complete if jose and jane each does half the work . so since jose does 1 job in x days , he wil need x / 2 days to do half the job . jane similarly will need y / 2 days to do the other half . x / 2 + y / 2 = 45 x + y = 90 so xy = 1350 the answer choices are : 25 days 30 days 60 days 65 days 36 days from the answer choices , so i ' ll go for 50 days for jose and 27 days for jane . answer : c" | null |
Question: in an electric circuit , two resistors with resistances x and y are connected in parallel . if r is the combined resistance of these two resistors , then the reciprocal of r is equal to the sum of the reciprocals of x and y . what is r if x is 4 ohms and y is 6 ohms ?
A.5 / 12.
B.7 / 12.
C.12 / 5.
D.7 / 5.
e ) 11 / 5C.
"1 / r = 1 / x + 1 / y 1 / r = 1 / 4 + 1 / 6 = 5 / 12 r = 12 / 5 the answer is c ." | null |
Question: the average mark of the students of a class in a particular exam is 80 . if 5 students whose average mark in that exam is 40 are excluded , the average mark of the remaining will be 90 . find the number of students who wrote the exam .
A.87.
B.27.
C.25.
D.26.
e ) 24C.
"let the number of students who wrote the exam be x . total marks of students = 80 x . total marks of ( x - 5 ) students = 90 ( x - 5 ) 80 x - ( 5 * 40 ) = 90 ( x - 5 ) 250 = 10 x = > x = 25 answer : c" | null |
Question: when x is multiplied by 3 , the result is 16 more than the result of subtracting x from 36 . what is the value of x ?
A.- 4.
B.- 2.
C.11.
D.13.
e ) 22D.
"the equation that can be formed is : 3 x - 16 = 36 - x or , 4 x = 52 or , x = 13 . answer : d" | null |
Question: a goods train leaves a station at a certain time and at a fixed speed . after 6 hours , an express train leaves the same station and moves in the same direction at a uniform speed of 90 kmph . this train catches up the goods train in 4 hours . find the speed of the goods train .
A.36 kmph.
B.40 kmph.
C.30 kmph.
D.42 kmph.
e ) none of theseA.
let the speed of the goods train be x kmph . distance covered by goods train in 10 hours = distance covered by express train in 4 hours . ∴ 10 x = 4 × 90 or x = 36 . so , speed of goods train = 36 kmph . answer a | null |
Question: if 3 people can do 3 times of a particular work in 3 days , then how many days would it take 4 people to do 4 times of that particular work ?
A.1.
B.2.
C.3.
D.4.
e ) 7C.
"3 people can do the work one time in one day . 1 person can do 1 / 3 of the work in one day . 4 people can do 4 / 3 of the work in one day . 4 people can do 4 times the work in 3 days . the answer is c ." | null |
Question: 5 ! / ( 5 - 3 ) ! = ?
A.36.
B.46.
C.56.
D.59.
e ) 60E.
5 ! / ( 5 - 3 ) ! = 5 ! / 2 ! = 5 * 4 * 3 = 60 . hence , the correct answer is e . | null |
Question: the manager of a produce market purchased a quantity of tomatoes for $ 0.80 per pound . due to improper handling , 10 percent of the tomatoes , by weight , were ruined and discarded . at what price per pound should the manager sell the remaining tomatoes if she wishes to make a profit on the sale of the tomatoes equal to 12 percent of the cost of the tomatoes .
A.$ 0.94.
B.$ 0.96.
C.$ 0.99.
D.$ 1.00.
e ) $ 1.20C.
assume the manager bought 100 tomatoes . cost price = 80 given : 10 % are damaged - - > available tomatoes to sell = 90 90 * x - 80 = 0.12 * 80 90 x - 80 = 9.6 90 x = 89.6 x = 89.6 / 90 = 0.995 x is slightly under 0.9955 = 0.99 answer : c | null |
Question: what is the remainder when 4 ^ 8707 is divided by 5 ?
A.0.
B.1.
C.2.
D.3.
e ) 4E.
"4 ^ 0 = 1 4 ^ 1 = 4 4 ^ 2 = 16 4 ^ 3 = 64 4 ^ 4 = 256 4 ^ 5 = . . . . . 4 4 ^ 6 = . . . . . . . 6 and so on in a distinct last - digit pattern of 4,6 , 4,6 . . . after ignoring the first last - digit of 1 8707 / 2 = 4353 ( with a remainder of 1 ) so the last number is a 4 . alternatively , 8707 is an odd number and hence the last digit is a 4 when 4 ^ 8707 is divided by 5 the remainder is 4 , ans = e" | null |
Question: if 5 % more is gained by selling an article for rs . 220 than by selling it for rs . 160 , the cost of the article is ?
A.127.
B.1200.
C.1600.
D.1400.
e ) 1202B.
"let c . p . be rs . x . then , 5 % of x = 220 - 160 = 60 x / 20 = 60 = > x = 1200 answer : b" | null |
Question: how many integers between 100 and 170 , inclusive , can not be evenly divided by 3 nor 5 ?
A.36.
B.38.
C.40.
D.42.
e ) 44B.
"the total numbers between 100 and 170 , inclusive , is 71 . 3 * 34 = 102 and 3 * 56 = 168 so the number of multiples of 3 is 23 . 5 * 20 = 100 and 5 * 34 = 170 so the number of multiples of 5 is 15 . however , the multiples of 15 have been counted twice . 15 * 7 = 105 and 15 * 11 = 165 so the number of multiples of 15 is 5 . thus the total number is 71 - 23 - 15 + 5 = 38 . the answer is b ." | null |
Question: two persons a and b can complete a piece of work in 20 days and 40 days respectively . if they work together , what part of the work will be completed in 5 days ?
A.1 / 8.
B.1 / 3.
C.3 / 6.
D.3 / 8.
e ) 5 / 3D.
"a ' s one day ' s work = 1 / 20 b ' s one day ' s work = 1 / 40 ( a + b ) ' s one day ' s work = 1 / 20 + 1 / 40 = 3 / 40 the part of the work completed in 5 days = 5 ( 3 / 40 ) = 3 / 8 . answer : d" | null |
Question: there are x persons and y chocolates . if each person is given 1 chocolate then 1 chocolate is left , if each person is given 2 chocolates then 1 person will be left . so how many persons and chocolates are there ? ?
A.32.
B.33.
C.34.
D.45.
e ) 44C.
x person , y chocolates 1 st equation = = > ( y - 1 ) / x = 1 2 nd equation = = > y / ( x - 1 ) = 2 solving we get x = 3 , y = 4 answer : c | null |
Question: working alone at their respective constant rates , a can complete a task in ‘ a ’ days and b in ‘ b ’ days . they take turns in doing the task with each working 3 days at a time . if a starts they finish the task in exactly 9 days . if b starts , they take a day more . how long does it take to complete the task if they both work together ?
A.8.
B.6.
C.4.
D.5.
e ) 9 / 2E.
"work done by ab in a day = xy respectively . when a starts : no . of days when a works = 6 no . of days when b works = 3 → 6 x + 3 y = 1 when b starts : no . of days when a works = 4 no . of days when a works = 5 → 5 x + 4 y = 1 solving the above two equations for xy x = 1 / 9 y = 1 / 9 → total work done by ab in a day = 1 / 9 + 1 / 9 = 2 / 9 → no . of days to complete the work when both work together = 9 / 2 ; answer : e" | null |
Question: find out the square of a number which when doubled exceeds its one seventh by 13 ?
A.16.
B.49.
C.19.
D.26.
e ) 17B.
"a let the number be p , then the square will be p ^ 2 according to question : 2 p = ( p / 7 ) + 13 = > 14 p = p + 91 = > p = 7 p ^ 2 = 7 ^ 2 = 49 . answer : b" | null |
Question: a type of extra - large suv averages 12.2 miles per gallon ( mpg ) on the highway , but only 7.6 mpg in the city . what is the maximum distance , in miles , that this suv could be driven on 20 gallons of gasoline ?
A.190.
B.284.6.
C.300.
D.244.
e ) 312D.
"so 12.2 * 20 = 244 . . imo option d is correct answer . ." | null |
Question: an engineering student has to secure 36 % marks to pass . he gets 130 marks and fails by 14 marks . the maximum number of marks obtained by him is ?
A.337.
B.400.
C.298.
D.2798.
e ) 271B.
130 14 - - - - - - - 361 - - - - - - 144 100 % - - - - - - ? = > 400 answer : b | null |
Question: united telephone charges a base rate of $ 9.00 for service , plus an additional charge of $ 0.25 per minute . atlantic call charges a base rate of $ 12.00 for service , plus an additional charge of $ 0.20 per minute . for what number of minutes would the bills for each telephone company be the same ?
A.2 minutes.
B.10 minutes.
C.20 minutes.
D.40 minutes.
e ) 60 minutesE.
lets take number of minutesx . given that , 9 + 0.25 x = 12 + 0.2 x - > 0.05 x = 2 - > x = 60 minutes ans e | null |
Question: the cost of carpeting a room 18 m long with a carpet 75 cm wide at 45 paise per meter is rs . 81 . the breadth of the room is :
A.7 m.
B.7.5 m.
C.5.5 m.
D.6.5 m.
e ) 8.5 mB.
"length of the carpet = total cost / rate / m = 8100 / 45 = 180 m area of the carpet = 180 * 75 / 100 = 135 m 2 breadth of the room = ( area / length ) = 135 / 18 = 7.5 m answer : b" | null |
Question: a swimmer can swim in still water at 4 km / h . if the speed of the water current is 2 km / h , how many hours will the swimmer take to swim against the current for 7 km ?
A.3.0.
B.3.25.
C.3.5.
D.3.75.
e ) 4.0C.
"the swimmer can swim against the current at a speed of 4 - 2 = 2 km / h . the time it will take is 7 / 2 = 3.5 hours . the answer is c ." | null |
Question: ratio between 2 numbers is 5 : 7 and their product is 560 . what is the difference between 2 numbers ?
A.6.
B.7.
C.8.
D.9.
e ) 2C.
"explanation : x / y = 5 / 7 x × y = 560 ⇒ x = 560 / y substituting this value in first equation , we get 560 / yy = 57560 / yy = 57 ⇒ 560 y 2 = 57560 y 2 = 57 ⇒ y = 28 x = 20 so difference between the numbers could be x – y = – 8 y – x = 8 answer : c" | null |
Question: the edges of three metal cubes are 1 cm , 2 cm , and 3 cm respectively . a new cube is made by melting these three cubes together . what is the edge of the new cube ( in centimeters ) ?
A.3.3.
B.3.5.
C.3.7.
D.3.9.
e ) 4.1A.
"the total volume is 1 ^ 3 + 2 ^ 3 + 3 ^ 3 = 36 the edge of the new cube is the cube root of 36 which is about 3.3 cm . the answer is a ." | null |
Question: a scale 6 ft . 8 inches long is divided into 2 equal parts . find the length of each part .
A.20 inches.
B.77 inches.
C.66 inches.
D.97 inches.
e ) 40 inchesE.
explanation : total length of scale in inches = ( 6 * 12 ) + 8 = 80 inches length of each of the 2 parts = 80 / 2 = 40 inches answer : e | null |
Question: right now , al and eliot have bank accounts , and al has more money than eliot . the difference between their two accounts is 1 / 11 of the sum of their two accounts . if al ’ s account were to increase by 10 % and eliot ’ s account were to increase by 20 % , then al would have exactly $ 22 more than eliot in his account . how much money does eliot have in his account right now ?
A.$ 110.
B.$ 120.
C.$ 183.3.
D.$ 220.
e ) $ 260C.
"lets assume al have amount a in his bank account and eliot ' s bank account got e amount . we can form an equation from the first condition . a - e = 1 / 11 * ( a + e ) = = > 10 a = 12 e - - - - - - - - - - - - ( 1 ) second condition gives two different amounts , al ' s amount = 1.1 a and eliot ' s amount = 1.2 e 1.1 a = 22 + 1.2 e = = > 11 a = 220 + 12 e - - - - - - - ( 2 ) substituting ( 1 ) in ( 2 ) : 11 a = 220 + 10 a = = > a = 220 ; e = 183.3 c" | null |
Question: if 11 oranges bought 10 r and 10 oranges sold 11 r . what is the profit
A.11 %.
B.20 %.
C.22 %.
D.21 %.
e ) 23 %D.
suppose he bought 110 apples . cp = rs 100 sp = rs 121 % profit = 100 * ( 121 - 100 ) / 100 = 21 % answer : d | null |
Question: the speed at which a man can row a boat in still water is 15 km / hr . if he rows downstream , where the speed of current is 3 km / hr , how many seconds will he take to cover 110 meters ?
A.18.
B.20.
C.22.
D.24.
e ) 28B.
"the speed of the boat downstream = 15 + 3 = 18 km / hr 18 km / hr * 5 / 18 = 5 m / s the time taken to cover 110 meters = 110 / 5 = 22 seconds . the answer is b ." | null |
Question: find the simple interest on rs . 567 for 7 months at 9 paisa per month ?
A.s . 357.21.
B.s . 322.12.
C.s . 400.
D.s . 278.9.
e ) s . 300A.
"explanation : i = ( 567 * 7 * 9 ) / 100 = 357.21 answer : option a" | null |
Question: the least number which when divided by 4 , 6 , 7 and 8 leaves a remainder 6 , but when divided by 9 leaves no remainder , is
A.340.
B.342.
C.523.
D.363.
e ) none of theseB.
"explanation : l . c . m of 4 , 6 , 7 , 8 = 168 therefore required number is of the form 168 k + 6 . least value of k for which ( 168 k + 6 ) is divisible by 9 is k = 2 therefore required number = ( 168 x 2 + 6 ) = 342 . answer : b" | null |
Question: if 0.6 : 1.4 : : 2 : 4 : x , then x = ?
A.56.
B.5.6.
C.0.56.
D.0.056.
e ) none of theseB.
"explanation : 0.6 × x = 2.4 × 1.4 x = ( 2.4 × 1.4 ) / 0.6 = 24 / 10 × 17 / 10 × 1 / ( 6 / 10 ) 24 / 10 × 14 / 10 × 10 / 6 2 / 5 × 14 = 28 / 5 = 5.6 answer : option b" | null |
Question: the tax on a commodity is diminished by 10 % and its consumption increases by 10 % . find the effects on revenue ?
A.1 % decrease.
B.2 % increase.
C.3 % decrease.
D.4 % decrease.
e ) none of theseA.
"since tax consumption = revenue . therefore , net % change in revenue = ( x + y + xy / 100 ) % = [ - 10 + 10 + ( - 10 x 10 ) / 100 ] % or - 1 % . therefore , revenue decreased by 1 % . answer : a" | null |
Question: at 15 : 00 there were 20 students in the computer lab . at 15 : 03 and every three minutes after that , 4 students entered the lab . if at 15 : 10 and every ten minutes after that 8 students left the lab , how many students were in the computer lab at 15 : 44 ?
A.7.
B.14.
C.25.
D.27.
e ) 30D.
"initial no of students + 3 * ( 1 + no of possible 3 minute intervals between 15 : 03 and 15 : 44 ) - 8 * ( 1 + no of possible 10 minute intervals between 15 : 10 and 15 : 44 ) 20 + 3 * 14 - 8 * 4 = 27 d" | null |
Question: ' a ' and ' b ' are positive integers such that their lcm is 20 and their hcf is 1 . what is the difference between the maximum and minimum possible values of ' a + b ' ?
A.0.
B.12.
C.13.
D.9.
e ) 11A.
a = 4 , b = 5 as they have to co - primes ( hcf being 1 and lcm = 20 ) so a + b = 9 is their max and min value hence difference = 0 answer - a | null |
Question: if a , b and c together can finish a piece of work in 4 days . a alone in 6 days and b in 18 days , then c alone can do it in ?
A.1.
B.7.
C.8.
D.9.
e ) 36E.
"c = 1 / 4 - 1 / 6 – 1 / 18 = 1 / 36 = > 36 days ' answer : e" | null |
Question: wo passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively . when they meet , it is found that one train has traveled 60 km more than the other one . the distance between the two stations is ?
A.227.
B.444.
C.277.
D.298.
e ) 212B.
1 h - - - - - 5 ? - - - - - - 60 12 h rs = 16 + 21 = 37 t = 12 d = 37 * 12 = 444 answer : b | null |
Question: the salary of a typist was at first raised by 10 % and then the same was reduced by 5 % . if he presently draws rs . 3135 . what was his original salary ?
A.2277.
B.2999.
C.1000.
D.3000.
e ) 1971D.
"x * ( 110 / 100 ) * ( 95 / 100 ) = 3135 x * ( 11 / 10 ) * ( 1 / 100 ) = 33 x = 3000 answer : d" | null |
Question: a train speeds past a pole in 15 sec and a platform 130 m long in 25 sec , its length is ?
A.195.
B.150.
C.160.
D.170.
e ) 180A.
"let the length of the train be x m and its speed be y m / sec . then , x / y = 15 = > y = x / 15 ( x + 130 ) / 25 = x / 15 = > x = 195 m . answer : option a" | null |
Question: city a and city b are 140 miles apart . train c departs city a , heading towards city b , at 4 : 00 and travels at 40 miles per hour . train d departs city b , heading towards city a , at 4 : 35 and travels at 20 miles per hour . the trains travel on parallel tracks . at what time do the two trains meet ?
A.5 : 00.
B.5 : 30.
C.6 : 00.
D.6 : 35.
e ) 7 : 00D.
"train c has traveled 20 mi in the half hour before train d has started its journey . 140 - 20 = 120 40 + 20 = 60 mph 120 mi / 60 mph = 2 hrs 4 : 35 pm + 2 hrs = 6 : 35 pm answer : d . 6 : 35" | null |
Question: if - 11 a and - 8 b are negative integers , then ( - 11 a ) * ( - 8 b ) + ab is
A.88 ab.
B.- 89 ab.
C.89 ab.
D.- 88 a.
e ) - 88 bC.
answer : c | null |
Question: what is the thousandths digit in the decimal equivalent of 43 / 5000 ?
A.0.
B.1.
C.3.
D.5.
e ) 8E.
"43 / 5000 = 43 / ( 5 * 10 ^ 3 ) = ( 43 / 5 ) * 10 ^ - 3 = 8.6 * 10 ^ - 3 = . 0086 thousandths digit = 8 answer e" | null |
Question: what is the difference between the largest number and the least number written with the digits 5 , 3 , 1 , 4 ?
A.6084.
B.3788.
C.4086.
D.2721.
e ) 1812C.
explanation : 1345 5431 - - - - - - - - - - - - 4086 answer : c | null |
Question: if ( a – b ) is 9 more than ( c + d ) and ( a + b ) is 3 less than ( c – d ) , then ( a – c ) is :
A.6.
B.2.
C.3.
D.4.
e ) 5C.
( a – b ) – ( c + d ) = 9 and ( c – d ) – ( a + b ) = 3 = > ( a – c ) – ( b + d ) = 9 and ( c – a ) – ( b + d ) = 3 = > ( b + d ) = ( a – c ) – 9 and ( b + d ) = ( c – a ) – 3 = > ( a – c ) – 9 = ( c – a ) – 3 = > 2 ( a – c ) = 6 = > ( a – c ) = 3 answer : c | null |
Question: the population of a town increased from 1 , 75,000 to 2 , 10,000 in a decade . the average percent increase of population per year is
A.2 %.
B.5 %.
C.6 %.
D.8.75 %.
e ) noneA.
"solution increase in 10 years = ( 210000 - 175000 ) = 35000 . increase % = ( 35000 / 175000 ã — 100 ) % = 20 % . required average = ( 20 / 10 ) % = 2 % . answer a" | null |
Question: there are 408 boys and 240 girls in a school which are to be divided into equal sections of either boys or girls alone . find the total number of sections thus formed .
A.27.
B.32.
C.35.
D.30.
e ) 45A.
"explanation : hcf ( 408 , 240 ) = 24 the number of boys or girls that can be placed in a section = 24 . thus the total number of sections is given by 408 / 24 + 240 / 24 = 17 + 10 = 27 answer : a" | null |
Question: an alloy weighing 20 ounces is 70 percent gold . how many ounces of pure gold must be added to create an alloy that is 90 percent gold ?
A.6.
B.9.
C.12.
D.76.
e ) 48D.
"in 24 ounces , gold is 20 * ( 70 / 100 ) = 14 ounces . now we add x ounces of pure gold to make it 90 % gold . so 14 + x = ( 24 + x ) * 90 / 100 = > x = 76 . answer is d ." | null |
Question: the cost of the paint is rs . 20 per kg . if 1 kg of paint covers 15 sq . ft , how much will it cost to paint outside of a cube having 5 feet each side
['A.rs . 200', 'B.rs . 672', 'C.rs . 546', 'D.rs . 876', 'e ) none of these']A.
explanation : surface area of a cube = 6 x 5 ^ 2 = 150 sq . ft quantity of paint required = ( 150 / 15 ) = 10 kg cost of painting = 20 x 10 = rs . 200 answer : a | null |
Question: a student committee on academic integrity has 30 ways to select a president and vice president from a group of candidates . the same person can not be both president and vice president . how many candidates are there ?
A.7.
B.8.
C.9.
D.6.
e ) 11D.
"xc 1 * ( x - 1 ) c 1 = 30 x ^ 2 - x - 30 = 0 ( x - 6 ) ( x + 5 ) = 0 x = 6 , - 5 - 5 ca n ' t possible . d" | null |
Question: what is the difference between the largest number and the least number written with the digits 9 , 3 , 5 , 7 ?
A.6084.
B.3788.
C.2077.
D.2721.
e ) 6174E.
"explanation : 3579 9753 - - - - - - - - - - - - 6174 answer : e" | null |
Question: a bag contains 4 red , 3 blue and 2 green balls . if 2 ballsare picked at random , what is the probability that both are red ?
A.1 / 13.
B.2 / 23.
C.1 / 6.
D.4 / 27.
e ) 3 / 23C.
"p ( both are red ) , = 4 c 29 c 2 = 4 c 29 c 2 = 6 / 36 = 1 / 6 c" | null |
Question: what is the value of 8 1 / 3 % of 600 + 37 ½ of 400
A.100.
B.300.
C.150.
D.200.
e ) 250D.
"25 * 600 / 300 + 75 * 400 / 200 = 50 + 150 = 200 answer : d" | null |
Question: there is a 30 % chance jen will visit chile this year , while there is a 50 % chance that she will visit madagascar this year . what is the probability that jen will visit either chile or madagascar this year , but not both ?
A.25.0 %.
B.37.5 %.
C.50.0 %.
D.62.5 %.
e ) 75 %C.
p ( chile and not madagascar ) = 0.3 * 0.5 = 0.15 p ( madagascar and not chile ) = 0.5 * 0.7 = 0.35 total probability = 0.15 + 0.35 = 0.5 = 50 % the answer is c . | null |
Question: how much 45 % of 60 is greater than 35 % of 40 ?
A.18.
B.13.
C.15.
D.17.
e ) 71B.
"( 45 / 100 ) * 60 – ( 35 / 100 ) * 40 27 - 14 = 13 answer : b" | null |
Question: three numbers are in the ratio of 2 : 3 : 4 and their l . c . m . is 180 . what is their h . c . f . ?
A.15.
B.20.
C.40.
D.60.
e ) 70A.
"let the numbers be 2 x , 3 x , and 4 x . lcm of 2 x , 3 x and 4 x is 12 x . 12 x = 180 x = 15 hcf of 2 x , 3 x and 4 x = x = 15 the answer is a ." | null |
Question: the length of minute hand of a clock is 5.4 cm . what is the area covered by this in 5 minutes
A.15.27.
B.16.27.
C.17.27.
D.7.27.
e ) 7.63E.
"area of circle is pi * r ^ 2 but in 5 minutes area covered is ( 5 / 60 ) * 360 = 30 degree so formula is pi * r ^ 2 * ( angle / 360 ) = 3.14 * ( 5.4 ^ 2 ) * ( 30 / 360 ) = 7.63 cm ^ 2 answer : e" | null |
Question: donovan and michael are racing around a circular 600 - meter track . if donovan runs each lap in 45 seconds and michael runs each lap in 40 seconds , how many laps will michael have to complete in order to pass donovan , assuming they start at the same time ?
A.8.
B.7.
C.9.
D.6.
e ) 5C.
one way of approaching this question is by relative speed method 1 . speed / rate of donovan = distance / time = > 600 / 45 = > 40 / 3 2 . speed / rate of michael = distance / time = > 600 / 40 = > 15 relative speed between them = 15 - 40 / 3 = > 5 / 3 ( we subtract the rates if moving in the same direction and add the rates if moving in the opposite direction ) in order to pass donovan - distance to be covered = 600 , relative rate = 5 / 3 total time taken by micheal to surpass donovan = distance / rate = > 600 * 3 / 5 = > 360 no . of laps taken by michael = total time / michael ' s rate = > 360 / 40 = > 9 hence correct answer is 9 laps . c | null |
Question: if the function q is defined by the formula q = 5 w / ( 4 m ( z ^ 2 ) ) , by what factor will q be multiplied if w is quadrupled , m is doubled , and z is tripled ?
A.1 / 9.
B.2 / 9.
C.4 / 9.
D.3 / 9.
e ) 2 / 27B.
we just need to find the factor thats all , w - > quadrupled - > 4 w m - > doubled - > 2 m z - > tripled - > 3 z hence , z ^ 2 = 9 z ^ 2 w is in numerator , and m * z in denominator . hence , additional factor being introduced = 4 / 2 * 9 = 4 / 18 = 2 / 9 = b | null |
Question: carol spends 1 / 4 of her savings on a stereo and 2 / 3 less than she spent on the stereo for a television . what fraction of her savings did she spend on the stereo and television ?
A.1 / 4.
B.2 / 7.
C.5 / 12.
D.1 / 2.
e ) 7 / 12A.
total savings = s amount spent on stereo = ( 1 / 4 ) s amount spent on television = ( 1 - 2 / 3 ) ( 1 / 4 ) s = ( 1 / 3 ) * ( 1 / 4 ) * s = ( 1 / 12 ) s ( stereo + tv ) / total savings = s ( 1 / 4 + 1 / 12 ) / s = 1 / 4 answer : a | null |
Question: one week , a certain truck rental lot had a total of 18 trucks , all of which were on the lot monday morning . if 50 % of the trucks that were rented out during the week were returned to the lot on or before saturday morning of that week , and if there were at least 12 trucks on the lot that saturday morning , what is the greatest number of different trucks that could have been rented out during the week ?
A.18.
B.16.
C.12.
D.8.
e ) 4C.
"n - not rented trucks ; r - rented trucks n + r = 18 n + r / 2 = 12 r = 12 c" | null |
Question: a grocer has 400 pounds of coffee in stock , 25 percent of which is decaffeinated . if the grocer buys another 100 pounds of coffee of which 60 percent is decaffeinated , what percent , by weight , of the grocer ’ s stock of coffee is decaffeinated ?
A.28 %.
B.30 %.
C.32 %.
D.34 %.
e ) 40 %C.
1 . 25 % of 400 = 100 pounds of decaffeinated coffee 2 . 60 % of 100 = 60 pounds of decaffeinated coffee 3 . wt have 160 pounds of decaffeinated out of 500 pounds , that means 160 / 500 * 100 % = 32 % . the correct answer is c . | null |
Question: calculate how much time could be saved if the train would run at its usual speed , given that it ran at 6 / 8 of its own speed and got to its destination in 11 hours ?
A.2.5 hrs.
B.2.9 hrs.
C.4.5 hrs.
D.3.5 hrs.
e ) 1.5 hrsA.
new speed = 6 / 8 of usual speed new time = 6 / 8 of usual time 6 / 8 of usual time = 10 hrs usual time = 10 * 6 / 8 = 7.5 hrs time saved = 10 - 7.5 = 2.5 hrs answer is a | null |
Question: a person spent rs . 7,540 from his salary on food and 5,690 on house rent . after that he was left with 60 % of his monthly salary . what is his monthly salary ?
A.73,075.
B.34,075.
C.23,075.
D.33,075.
e ) 32,075D.
"total money spent on food and house rent = 7,540 + 5,690 = 13,230 which is 100 - 60 = 40 % of his monthly salary ∴ his salary = 13230 x 100 / 40 = 33075 answer : d" | null |
Question: a survey was sent to 80 customers , 9 of whom responded . then the survey was redesigned and sent to another 63 customers , 12 of whom responded . by approximately what percent did the response rate increase from the original survey to the redesigned survey ?
A.2 %.
B.5 %.
C.14 %.
D.28 %.
e ) 69 %E.
"rate of first survey = 9 / 80 rate of second survey = 12 / 63 % response rate increase ( 12 / 63 - 9 / 80 ) / ( 9 / 80 ) = 69 % answer is e = 69 %" | null |
Question: the speed of a boat in still water is 15 km / hr and the rate of current is 3 km / hr . the distance travelled downstream in 12 minutes is
A.1.2 km.
B.1.8 km.
C.2.4 km.
D.3.6 km.
e ) 1.6 kmD.
"b = 15 km / hr , s = 3 km / hr , downstream b + s = 15 + 3 = 18 km / hr down stream time t = 12 min , we have to change it to hours so t = 12 / 60 = 1 / 5 hrs . distance = speed * time = 18 * 1 / 5 = 3.6 km . answer : d" | null |
Question: a sum of rs . 395 was divided among a , b , and c in such a way that b gets 25 % more than a and 20 % more than c . what is the share of a ?
A.rs . 195.
B.rs . 180.
C.rs . 98.
D.rs . 120.
e ) rs . 130D.
let each one ’ s share is a , b and c respectively , then b = 125 a / 100 = 120 c / 100 a = 100 b / 125 = 4 / 5 b , c = 100 b / 120 = 5 / 6 b 4 / 5 b + b + 5 / 6 b = 395 , 79 b / 30 = 395 , b = 395 * 30 / 79 = 150 a = 4 * 150 / 5 = 120 answer : d | null |
Question: the ratio 5 : 4 expressed as a percent equals
A.12.5 %.
B.40 %.
C.80 %.
D.125 %.
e ) noneD.
"solution 5 : 4 = 5 / 4 = ( 5 / 4 x 100 ) % . = 125 % . answer d" | null |
Question: the current birth rate per certain number of people is 52 , whereas corresponding death rate is 16 per same number of people . if the net growth rate in terms of population increase is 1.2 percent , find number of persons . ( initally )
A.4000.
B.2000.
C.3000.
D.5000.
e ) 1000C.
"sol . net growth on x = ( 52 - 16 ) = 36 . net growth on 100 = ( 36 / x ã — 100 ) % = 1.2 % . then x = 3000 answer : c" | null |
Question: 14 , 28 , 20 , 40 , 32 , 64 , . . . ?
A.10.
B.25.
C.56.
D.21.
e ) 36C.
"first , multiply by 2 and then subtract 8 . 14 14 * 2 = 28 28 - 8 = 20 20 * 2 = 40 40 - 8 = 32 32 * 2 = 64 64 - 8 = 56 answer : c" | null |
Question: the average of runs of a cricket player of 20 innings was 32 . how many runs must he make in his next innings so as to increase his average of runs by 6 ?
A.96.
B.106.
C.158.
D.116.
e ) 122C.
"average = total runs / no . of innings = 32 so , total = average x no . of innings = 32 * 20 = 640 now increase in avg = 4 runs . so , new avg = 32 + 6 = 38 runs total runs = new avg x new no . of innings = 38 * 21 = 798 runs made in the 11 th inning = 798 - 640 = 158 answer : c" | null |
Question: a is half good a work man as b and together they finish a job in 26 days . in how many days working alone b finish the job ?
A.98 days.
B.21 days.
C.17 days.
D.39 days.
e ) 19 daysD.
"wc = 1 : 2 2 x + x = 1 / 26 = > x = 1 / 78 2 x = 1 / 78 = > 39 days answer : d" | null |
Question: jane and ashley take 20 days and 10 days respectively to complete a project when they work on it alone . they thought if they worked on the project together , they would take fewer days to complete it . during the period that they were working together , jane took an eight day leave from work . this led to jane ' s working for four extra days on her own to complete the project . how long did it take to finish the project ?
A.12 days.
B.15 days.
C.16 days.
D.18 days.
e ) 20 daysA.
"let us assume that the work is laying 40 bricks . jane = 2 bricks per day ashley = 4 brick per day together = 6 bricks per day let ' s say first 8 days ashley works alone , no of bricks = 32 last 4 days jane works alone , no . of bricks = 8 remaining bricks = 40 - 40 = 0 so together , they would take 0 / 6 = 0 total no . of days = 8 + 4 + 0 = 12 answer is a" | null |
Question: if john runs in the speed of 9 km / hr from his house , in what time will he reach the park which is 300 m long from his house ?
A.2.
B.4.
C.5.
D.3.
e ) 6A.
speed = 9 * 5 / 18 = 2.5 m / sec time taken = 300 / 2.5 = 120 sec ie . 2 mins . answer : a | null |
Question: a dishonest person wants to make a profit on the selling of milk . he would like to mix water ( costing nothing ) with milk costing 33 $ per litre so as to make a profit of 40 % on cost when he sells the resulting milk and water mixture for 36 $ . in what ratio should he mix the water and milk ?
A.1 : 20.
B.1 : 10.
C.17 : 8.
D.17 : 4.
e ) 17 : 60E.
first of all , let ' s consider 1 liter of the stuff he is going to sell - - - naive customers think it ' s pure milk , but we know it ' s some milk - water mixture . he is going to sell this liter of milk - water for $ 36 . this $ 36 should be a 40 % increase over cost . here , we need to think about percentage increases as multipliers . using multipliers ( cost ) * 1.40 = $ 36 cost = 36 / 1.4 = 360 / 12 = $ 25.71 if he wants a 40 % increase over cost on the sale of one liter of his milk - water , the cost has to be $ 25.71 . well , a liter of milk costs $ 33 , so if he is going to use just $ 30 of milk in his mixture , that ' s 25.71 / 33 = 60 / 77 of a liter . if milk is 60 / 77 of the liter , then water is 17 / 77 of the liter , and the ratio of water to milk is 17 : 60 . answer choice ( e ) | null |
Question: if the sides of a triangle are 26 cm , 18 cm and 10 cm , what is its area ?
['A.90', 'B.110', 'C.130', 'D.140', 'e ) 150']A.
the triangle with sides 26 cm , 18 cm and 10 cm is right angled , where the hypotenuse is 26 cm . area of the triangle = 1 / 2 * 18 * 10 = 90 cm 2 answer : option a | null |
Question: if x is the sum of first 100 positive even integers and y is the sum of first 100 positive odd integers , what is the value of x - y ? please try to explain your answers
A.0.
B.25.
C.50.
D.75.
e ) 100E.
first even minus first odd = 2 - 1 = 1 ; the sum of first 2 even integers minus the sum of first 2 odd integers = ( 2 + 4 ) - ( 1 + 3 ) = 2 ; the sum of first 3 even integers minus the sum of first 3 odd integers = ( 2 + 4 + 6 ) - ( 1 + 3 + 5 ) = 3 ; we can see the patterns here , so the sum of first 100 positive even integers minus the sum of first 100 positive odd integers will be 100 . answer : e . | null |
Question: the ratio of the amount of the oil bill for the month of february to the amount of the oil bill for the month of january was 3 : 2 . if the oil bill for february had been $ 30 more , the corresponding ratio would have been 5 : 3 . how much was the oil bill for january ?
A.$ 120.
B.$ 150.
C.$ 180.
D.$ 210.
e ) $ 240C.
"3 : 2 = 9 : 6 and 5 : 3 = 10 : 6 . an increase in $ 30 increases the ratio by 1 : 6 . therefore , january ' s bill was 6 ( $ 30 ) = $ 180 . the answer is c ." | null |
Question: if x - y - z = 03 x + 4 y + 3 z = 45 x + 2 y + 7 z = 22 , what is the value of z ?
A.3.
B.4.
C.5.
D.2.
e ) 1A.
explanation : 4 x + 2 y - 5 z = - 21 â € “ - - - - - - - i 2 x - 2 y + z = 7 â € “ - - - - - - ii 4 x + 3 y - z = - 1 - - - - - - - - iii solve the first equation for x . x - y - z = 0 x = y + z substitute the solution for x into the second and third equations . ii - - - > 3 * ( y + z ) + 4 y + 3 z = 4 3 y + 3 z + 4 y + 3 z = 4 7 y + 6 z = 4 iii - - - - > 5 * ( y + z ) + 2 y + 7 z = 22 5 y + 5 z + 2 y + 7 z = 22 7 y + 12 z = 22 subtract the new second equation from the new third equation and solve for z . 7 y + 12 z = 22 - ( 7 y + 6 z = 4 ) 6 z = 18 z = 3 answer is a | null |
Question: a call center has two teams . each member of team a was able to process 1 / 5 calls as compared to each member of team b . if team a has 5 / 8 as many number of call center agents as team b , what fraction of the total calls was processed by team b ?
A.3 / 2.
B.3 / 4.
C.8 / 9.
D.1 / 2.
e ) 1 / 5C.
"let team b has 8 agents , so team a has 5 agents let each agent of team b picked up 5 calls , so total calls by team b = 40 so , each agent in team a picked up 1 calls , so total calls for team a = 5 fraction for team b = 40 / ( 40 + 5 ) = 8 / 9 = answer = c" | null |
Question: how much space , in cubic units , is left vacant when maximum number of 3 x 3 x 3 cubes are fitted in a rectangular box measuring 6 x 9 x 11 ?
A.112.
B.111.
C.110.
D.109.
e ) 108E.
"no of cubes that can be accommodated in box = ( 6 * 9 * 11 ) / ( 3 * 3 * 3 ) 6 * 9 in numerator can be perfectly divided by 3 * 3 in denominator . side with length 11 ca n ' t be perfectly divided by 3 and hence is the limiting factor . closet multiple of 3 less that 11 is 9 . so vacant area in cube = = 6 * 9 * ( 11 - 9 ) = 6 * 9 * 2 = 108 ans - e" | null |
Question: the jogging track in a sports complex is 1000 meters in circumference . deepak and his wife start from the same point and walk in opposite directions at 20 km / hr and 17 km / hr respectively . they will meet for the first time in ?
A.50 min.
B.40 min.
C.35 min.
D.37 min.
e ) 20 minD.
"clearly , the two will meet when they are 1000 m apart to be 20 + 17 = 37 km apart , they take 1 hour to be 1000 m apart , they take 37 * 1000 / 1000 = 37 min . answer is d" | null |
Question: if the sum of two numbers is 18 and the sum of their squares is 180 , then the product of the numbers is
A.72.
B.44.
C.80.
D.88.
e ) 48A.
"according to the given conditions x + y = 18 and x ^ 2 + y ^ 2 = 180 now ( x + y ) ^ 2 = x ^ 2 + y ^ 2 + 2 xy so 18 ^ 2 = 180 + 2 xy so xy = 144 / 2 = 72 answer : a" | null |
Question: sam invested rs . 15000 @ 10 % per annum for one year . if the interest is compounded half - yearly , then the amount received by sam at the end of the year will be ?
A.rs . 16,500.
B.rs . 16.
525.50.
C.rs . 16.
537.50.
D.rs . 18,150.
e ) rs . 19,150C.
"p = rs . 15000 ; r = 10 % p . a . = 5 % per half - year ; t = 1 year = 2 half - year amount = [ 15000 * ( 1 + 5 / 100 ) 2 ] = ( 15000 * 21 / 20 * 21 / 20 ) = rs . 16537.50 answer : c" | null |
Question: if the area of a square with sides of length 3 centimeters is equal to the area of a rectangle with a width of 3 centimeters , what is the length of the rectangle , in centimeters ?
A.3.
B.8.
C.12.
D.16.
e ) 18A.
"let length of rectangle = l 3 ^ 2 = l * 3 = > l = 9 / 3 = 3 answer a" | null |
Question: a is 1.5 times as fast as b . a alone can do the work in 30 days . if a and b work on alternative days , beginning with a , in how many days will the work be completed ?
A.23.
B.22.
C.21.
D.36.
e ) 25D.
"a can finish 1 work in 30 days b can finish 1 / 1.5 work in 30 days - since a is 1.5 faster than b this means b can finish 1 work in 30 * 1.5 days = 45 days now using the awesome gmat formula when two machines work together they can finish the job in = ab / ( a + b ) = 45 * 30 / ( 45 + 30 ) = 20 * 30 / 50 = 18 days since they alternate on days , it will take them double this time so total time = 18 * 2 = 36 days so answer is d" | null |
Question: 5355 x 51 = ?
A.273105.
B.273243.
C.273247.
D.273250.
e ) 273258A.
"5355 x 51 = 5355 x ( 50 + 1 ) = 5355 x 50 + 5355 x 1 = 267750 + 5355 = 273105 a" | null |
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