def first_is_elsewhere_too(seq_seq):
    '\n    Given a sequence of subsequences:\n      -- Returns True if any element of the first (initial) subsequence\n           appears in any of the other subsequences.\n      -- Returns False otherwise.\n\n    For example, if the given argument is:\n        [(3, 1, 4),\n         (13, 10, 11, 7, 10),\n         [11, 12, 3, 10]]\n    then this function returns True because 3 appears\n    in the first subsequence and also in the third subsequence.\n\n    As another example, if the given argument is:\n        [(3, 1, 4),\n         (13, 10, 11, 7, 10),\n         [11, 2, 13, 14]]\n    then this function returns False because 3 does not appear in\n    any subsequence except the first, 1 does not appear in any\n    subsequence except the first, and 4 does not appear in any\n    subsequence except the first.\n\n    As yet another example, if the given argument is:\n      ([], [1, 2], [1, 2])\n    then this function returns False since no element of the first\n    subsequence appears elsewhere.\n\n    Preconditions:\n      :type seq_seq: (list, tuple)\n    and the given argument is a sequence of sequences.\n    '
    for j in range(len(seq_seq[0])):
        for k in range(1, len(seq_seq)):
            for i in range(len(seq_seq[k])):
                if (seq_seq[k][i] == seq_seq[0][j]):
                    return True
    return False
Given a sequence of subsequences:
  -- Returns True if any element of the first (initial) subsequence
       appears in any of the other subsequences.
  -- Returns False otherwise.

For example, if the given argument is:
    [(3, 1, 4),
     (13, 10, 11, 7, 10),
     [11, 12, 3, 10]]
then this function returns True because 3 appears
in the first subsequence and also in the third subsequence.

As another example, if the given argument is:
    [(3, 1, 4),
     (13, 10, 11, 7, 10),
     [11, 2, 13, 14]]
then this function returns False because 3 does not appear in
any subsequence except the first, 1 does not appear in any
subsequence except the first, and 4 does not appear in any
subsequence except the first.

As yet another example, if the given argument is:
  ([], [1, 2], [1, 2])
then this function returns False since no element of the first
subsequence appears elsewhere.

Preconditions:
  :type seq_seq: (list, tuple)
and the given argument is a sequence of sequences.
def first_is_elsewhere_too(seq_seq):
    '\n    Given a sequence of subsequences:\n      -- Returns True if any element of the first (initial) subsequence\n           appears in any of the other subsequences.\n      -- Returns False otherwise.\n\n    For example, if the given argument is:\n        [(3, 1, 4),\n         (13, 10, 11, 7, 10),\n         [11, 12, 3, 10]]\n    then this function returns True because 3 appears\n    in the first subsequence and also in the third subsequence.\n\n    As another example, if the given argument is:\n        [(3, 1, 4),\n         (13, 10, 11, 7, 10),\n         [11, 2, 13, 14]]\n    then this function returns False because 3 does not appear in\n    any subsequence except the first, 1 does not appear in any\n    subsequence except the first, and 4 does not appear in any\n    subsequence except the first.\n\n    As yet another example, if the given argument is:\n      ([], [1, 2], [1, 2])\n    then this function returns False since no element of the first\n    subsequence appears elsewhere.\n\n    Preconditions:\n      :type seq_seq: (list, tuple)\n    and the given argument is a sequence of sequences.\n    '
    for j in range(len(seq_seq[0])):
        for k in range(1, len(seq_seq)):
            for i in range(len(seq_seq[k])):
                if (seq_seq[k][i] == seq_seq[0][j]):
                    return True
    return False