The sum of the squares of the first ten natural numbers is,

```12 + 22 + ... + 102 = 385```

The square of the sum of the first ten natural numbers is,

```(1 + 2 + ... + 10)2 = 552 = 3025```

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

# Benchmarks

### Ruby
```ruby
$ ruby problem_6/solution.rb
user     system      total        real
0.000000   0.000000   0.000000 (  0.000032)
Answer: 25164150
user     system      total        real
0.000000   0.000000   0.000000 (  0.000005)
Answer: 25164150
```

### Python
```python
$ python problem_6/solution.py
=> Result: 25164150
=> Time: 0.000020s
```

The sum of the squares of the first ten natural numbers is,

```12 + 22 + ... + 102 = 385```

The square of the sum of the first ten natural numbers is,

```(1 + 2 + ... + 10)2 = 552 = 3025```

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

# Benchmarks

### Ruby
```ruby
$ ruby problem_6/solution.rb
user     system      total        real
0.000000   0.000000   0.000000 (  0.000032)
Answer: 25164150
user     system      total        real
0.000000   0.000000   0.000000 (  0.000005)
Answer: 25164150
```

### Python
```python
$ python problem_6/solution.py
=> Result: 25164150
=> Time: 0.000020s
```

### C
```c
$ gcc -o p6 problem_6/solution.c
$ ./p6
=> Solution 1
=> Result: 25164150
=> Time: 0.000010s
=> Solution 2
=> Result: 25164150
=> Time: 0.000002s
```

Add benchmark for C solutions of problem 6
Add benchmark for C solutions of problem 6
