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2,700	a9f689b4-6ddd-11ea-be0f-ccda262736ce	https://socratic.org/questions/the-vol-of-co2-released-when-6g-of-carbon-combusrs-completed	11.25 L	start physical_unit 3 3 volume l qc_end physical_unit 9 9 6 7 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume [OF] CO2 [IN] L"}]	[{"type":"physical unit","value":"11.25 L"}]	[{"type":"physical unit","value":"Mass [OF] carbon [=] \\pu{6 g}"},{"type":"other","value":"Combusrs completed."}]	<h1 class="questionTitle" itemprop="name">The vol of CO2 released when 6g of carbon combusrs completed ? </h1>	null	11.25 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here is the equation of reaction (Combustion of Carbon)</p> <p><mathjax>#CO_2 -> C + O_2#</mathjax></p> <p><strong>Mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> <mathjax>#= 6g#</mathjax></p> <p><strong>Molar mass of Carbon</strong> <mathjax>#= 12gmol^-1#</mathjax></p> <p><strong>Recall</strong> <mathjax>#->#</mathjax> <strong>Amount in moles</strong> <mathjax>#= (Mass)/(Molar mass)#</mathjax></p> <p><mathjax>#"Amount in moles" = (Mass of Carbon)/(Molar mass of carbon)#</mathjax></p> <p><mathjax>#"Amount in moles" = 6/12#</mathjax></p> <p><mathjax>#"Amount in moles of C" =0.5 mols#</mathjax></p> <p>From the stoichiometric equation we have <mathjax>#1 : 1 : 1#</mathjax> as the ratio</p> <p>Since <mathjax>#1 mol#</mathjax> of <mathjax>#CO_2#</mathjax> yields <mathjax>#1 mol#</mathjax> of <mathjax>#C#</mathjax></p> <p><mathjax>#:.#</mathjax> <mathjax>#0.5 mol#</mathjax> of <mathjax>#CO_2#</mathjax> yields <mathjax>#0.5mol#</mathjax> of <mathjax>#C#</mathjax></p> <p>Hence <mathjax>#"No of moles of" CO_2 = 0.5 mols#</mathjax></p> <p><strong>Also Recall</strong> <mathjax>#->#</mathjax> <strong>Amount in moles</strong> <mathjax>#= "Volume of solution"/"Molar volume"#</mathjax></p> <p><mathjax>#->#</mathjax> <mathjax>#"Volume of" CO_2 = "Number of moles of" CO_2 xx "Molar Volume"#</mathjax></p> <p><strong>Note that:</strong> <mathjax>#"Molar Volume" = 22.5mol^-1dm^3 "at s.t.p"#</mathjax></p> <p><mathjax>#"Volume of" CO_2 = 0.5cancel(mol) xx 22.5cancel(mol^-1)dm^3#</mathjax></p> <p><mathjax>#"Volume of" CO_2 = (0.5 xx 22.5) dm^3#</mathjax></p> <p><mathjax>#Volume of CO_2 = 11.25 dm^3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Volume of CO_2 = 11.25 dm^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here is the equation of reaction (Combustion of Carbon)</p> <p><mathjax>#CO_2 -> C + O_2#</mathjax></p> <p><strong>Mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> <mathjax>#= 6g#</mathjax></p> <p><strong>Molar mass of Carbon</strong> <mathjax>#= 12gmol^-1#</mathjax></p> <p><strong>Recall</strong> <mathjax>#->#</mathjax> <strong>Amount in moles</strong> <mathjax>#= (Mass)/(Molar mass)#</mathjax></p> <p><mathjax>#"Amount in moles" = (Mass of Carbon)/(Molar mass of carbon)#</mathjax></p> <p><mathjax>#"Amount in moles" = 6/12#</mathjax></p> <p><mathjax>#"Amount in moles of C" =0.5 mols#</mathjax></p> <p>From the stoichiometric equation we have <mathjax>#1 : 1 : 1#</mathjax> as the ratio</p> <p>Since <mathjax>#1 mol#</mathjax> of <mathjax>#CO_2#</mathjax> yields <mathjax>#1 mol#</mathjax> of <mathjax>#C#</mathjax></p> <p><mathjax>#:.#</mathjax> <mathjax>#0.5 mol#</mathjax> of <mathjax>#CO_2#</mathjax> yields <mathjax>#0.5mol#</mathjax> of <mathjax>#C#</mathjax></p> <p>Hence <mathjax>#"No of moles of" CO_2 = 0.5 mols#</mathjax></p> <p><strong>Also Recall</strong> <mathjax>#->#</mathjax> <strong>Amount in moles</strong> <mathjax>#= "Volume of solution"/"Molar volume"#</mathjax></p> <p><mathjax>#->#</mathjax> <mathjax>#"Volume of" CO_2 = "Number of moles of" CO_2 xx "Molar Volume"#</mathjax></p> <p><strong>Note that:</strong> <mathjax>#"Molar Volume" = 22.5mol^-1dm^3 "at s.t.p"#</mathjax></p> <p><mathjax>#"Volume of" CO_2 = 0.5cancel(mol) xx 22.5cancel(mol^-1)dm^3#</mathjax></p> <p><mathjax>#"Volume of" CO_2 = (0.5 xx 22.5) dm^3#</mathjax></p> <p><mathjax>#Volume of CO_2 = 11.25 dm^3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The vol of CO2 released when 6g of carbon combusrs completed ? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="447703" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/endurance-j"><img alt="" class="" src="https://profilepictures.socratic.org/14B4RfloRQGn2gxEFUBU_Endy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/endurance-j"> Jumbotron </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-04T08:23:00" itemprop="dateCreated"> Jul 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Volume of CO_2 = 11.25 dm^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here is the equation of reaction (Combustion of Carbon)</p> <p><mathjax>#CO_2 -> C + O_2#</mathjax></p> <p><strong>Mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> <mathjax>#= 6g#</mathjax></p> <p><strong>Molar mass of Carbon</strong> <mathjax>#= 12gmol^-1#</mathjax></p> <p><strong>Recall</strong> <mathjax>#->#</mathjax> <strong>Amount in moles</strong> <mathjax>#= (Mass)/(Molar mass)#</mathjax></p> <p><mathjax>#"Amount in moles" = (Mass of Carbon)/(Molar mass of carbon)#</mathjax></p> <p><mathjax>#"Amount in moles" = 6/12#</mathjax></p> <p><mathjax>#"Amount in moles of C" =0.5 mols#</mathjax></p> <p>From the stoichiometric equation we have <mathjax>#1 : 1 : 1#</mathjax> as the ratio</p> <p>Since <mathjax>#1 mol#</mathjax> of <mathjax>#CO_2#</mathjax> yields <mathjax>#1 mol#</mathjax> of <mathjax>#C#</mathjax></p> <p><mathjax>#:.#</mathjax> <mathjax>#0.5 mol#</mathjax> of <mathjax>#CO_2#</mathjax> yields <mathjax>#0.5mol#</mathjax> of <mathjax>#C#</mathjax></p> <p>Hence <mathjax>#"No of moles of" CO_2 = 0.5 mols#</mathjax></p> <p><strong>Also Recall</strong> <mathjax>#->#</mathjax> <strong>Amount in moles</strong> <mathjax>#= "Volume of solution"/"Molar volume"#</mathjax></p> <p><mathjax>#->#</mathjax> <mathjax>#"Volume of" CO_2 = "Number of moles of" CO_2 xx "Molar Volume"#</mathjax></p> <p><strong>Note that:</strong> <mathjax>#"Molar Volume" = 22.5mol^-1dm^3 "at s.t.p"#</mathjax></p> <p><mathjax>#"Volume of" CO_2 = 0.5cancel(mol) xx 22.5cancel(mol^-1)dm^3#</mathjax></p> <p><mathjax>#"Volume of" CO_2 = (0.5 xx 22.5) dm^3#</mathjax></p> <p><mathjax>#Volume of CO_2 = 11.25 dm^3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/447703" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1435 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The vol of CO2 released when 6g of carbon combusrs completed ?	null
2,701	ab5a9bc0-6ddd-11ea-b7cf-ccda262736ce	https://socratic.org/questions/a-mass-of-45-0-grams-of-aluminum-will-react-with-how-many-grams-of-zinc-chloride	328.67 grams	start physical_unit 14 15 mass g qc_end physical_unit 6 6 3 4 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] zinc chloride [IN] grams"}]	[{"type":"physical unit","value":"328.67 grams"}]	[{"type":"physical unit","value":"Mass [OF] aluminum [=] \\pu{45.0 grams}"}]	<h1 class="questionTitle" itemprop="name">A mass of 45.0 grams of aluminum will react with how many grams of zinc chloride?</h1>	null	328.67 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we need to begin with a balanced chemical equation.</p> <p>Zinc Chloride <mathjax>#(ZnCl_2 - Zn^+2 and Cl^-1)#</mathjax><br/> Reacts with Aluminum in solution to form <br/> Aluminum Chloride <mathjax>#(AlCl_3 - Al^+3 and Cl^-1)#</mathjax></p> <p><mathjax>#2Al + 3ZnCl_2 -> 2AlCl_3 + 3Zn#</mathjax></p> <p>Now we must use <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> to convert grams of Al to grams of ZnCl_2</p> <p>molar mass of aluminum is <mathjax>#27.99 g/(mol)#</mathjax></p> <p>molar mass of zinc chloride is <mathjax>#136.29 g/(mol)#</mathjax> <br/> Zn <mathjax>#65.39#</mathjax><br/> Cl <mathjax>#2(35.45) = 70.90#</mathjax> <br/> <mathjax>#65.39 +70.90 = 136.329#</mathjax></p> <p><a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of <mathjax>#ZnCl_2#</mathjax> to <mathjax>#Al#</mathjax> is <mathjax>#3:2#</mathjax></p> <p>grams <mathjax>#->#</mathjax> moles <mathjax>#->#</mathjax> moles <mathjax>#->#</mathjax> grams</p> <p><mathjax>#45 g Al#</mathjax> x <mathjax>#(1 cancel(mol Al))/(27.99 cancel(g Al))#</mathjax> x <mathjax>#cancel(3 (mol ZnCl_2))/(2 cancel(mol Al))#</mathjax> x <mathjax>#(136.29 g ZnCl_2)/(1 cancel(mol ZnCl_2))#</mathjax> =</p> <p><mathjax>#(45(3)(136.29))/((27.99)(2))#</mathjax> = <mathjax>#328.6 g/(mol)#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/qa9G9yhG61M?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#328.6 g/(mol)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we need to begin with a balanced chemical equation.</p> <p>Zinc Chloride <mathjax>#(ZnCl_2 - Zn^+2 and Cl^-1)#</mathjax><br/> Reacts with Aluminum in solution to form <br/> Aluminum Chloride <mathjax>#(AlCl_3 - Al^+3 and Cl^-1)#</mathjax></p> <p><mathjax>#2Al + 3ZnCl_2 -> 2AlCl_3 + 3Zn#</mathjax></p> <p>Now we must use <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> to convert grams of Al to grams of ZnCl_2</p> <p>molar mass of aluminum is <mathjax>#27.99 g/(mol)#</mathjax></p> <p>molar mass of zinc chloride is <mathjax>#136.29 g/(mol)#</mathjax> <br/> Zn <mathjax>#65.39#</mathjax><br/> Cl <mathjax>#2(35.45) = 70.90#</mathjax> <br/> <mathjax>#65.39 +70.90 = 136.329#</mathjax></p> <p><a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of <mathjax>#ZnCl_2#</mathjax> to <mathjax>#Al#</mathjax> is <mathjax>#3:2#</mathjax></p> <p>grams <mathjax>#->#</mathjax> moles <mathjax>#->#</mathjax> moles <mathjax>#->#</mathjax> grams</p> <p><mathjax>#45 g Al#</mathjax> x <mathjax>#(1 cancel(mol Al))/(27.99 cancel(g Al))#</mathjax> x <mathjax>#cancel(3 (mol ZnCl_2))/(2 cancel(mol Al))#</mathjax> x <mathjax>#(136.29 g ZnCl_2)/(1 cancel(mol ZnCl_2))#</mathjax> =</p> <p><mathjax>#(45(3)(136.29))/((27.99)(2))#</mathjax> = <mathjax>#328.6 g/(mol)#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/qa9G9yhG61M?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A mass of 45.0 grams of aluminum will react with how many grams of zinc chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="253369" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-12T16:26:02" itemprop="dateCreated"> Apr 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#328.6 g/(mol)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we need to begin with a balanced chemical equation.</p> <p>Zinc Chloride <mathjax>#(ZnCl_2 - Zn^+2 and Cl^-1)#</mathjax><br/> Reacts with Aluminum in solution to form <br/> Aluminum Chloride <mathjax>#(AlCl_3 - Al^+3 and Cl^-1)#</mathjax></p> <p><mathjax>#2Al + 3ZnCl_2 -> 2AlCl_3 + 3Zn#</mathjax></p> <p>Now we must use <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> to convert grams of Al to grams of ZnCl_2</p> <p>molar mass of aluminum is <mathjax>#27.99 g/(mol)#</mathjax></p> <p>molar mass of zinc chloride is <mathjax>#136.29 g/(mol)#</mathjax> <br/> Zn <mathjax>#65.39#</mathjax><br/> Cl <mathjax>#2(35.45) = 70.90#</mathjax> <br/> <mathjax>#65.39 +70.90 = 136.329#</mathjax></p> <p><a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of <mathjax>#ZnCl_2#</mathjax> to <mathjax>#Al#</mathjax> is <mathjax>#3:2#</mathjax></p> <p>grams <mathjax>#->#</mathjax> moles <mathjax>#->#</mathjax> moles <mathjax>#->#</mathjax> grams</p> <p><mathjax>#45 g Al#</mathjax> x <mathjax>#(1 cancel(mol Al))/(27.99 cancel(g Al))#</mathjax> x <mathjax>#cancel(3 (mol ZnCl_2))/(2 cancel(mol Al))#</mathjax> x <mathjax>#(136.29 g ZnCl_2)/(1 cancel(mol ZnCl_2))#</mathjax> =</p> <p><mathjax>#(45(3)(136.29))/((27.99)(2))#</mathjax> = <mathjax>#328.6 g/(mol)#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/qa9G9yhG61M?origin=https://socratic.org&wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/253369" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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2,702	aa898476-6ddd-11ea-87bd-ccda262736ce	https://socratic.org/questions/a-compound-having-an-empirical-formula-of-c-3h-4o-3-has-a-mass-of-180-g-mol-what	C6H8O6	start chemical_formula qc_end physical_unit 1 1 12 13 molar_mass qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"C6H8O6"}]	[{"type":"physical unit","value":"Molar mass [OF] the compound [=] \\pu{180 g/mol}"},{"type":"other","value":"A compound have an empirical formula of C3H4O3."}]	<h1 class="questionTitle" itemprop="name">A compound having an empirical formula of #C_3H_4O_3# has a mass of 180 g/mol. What is the molecular formula?</h1>	null	C6H8O6	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is always a whole number multiple of the empirical formula:</p> <p>i.e. <mathjax>#"Molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"(Empirical formula)"xxn#</mathjax></p> <p>So we need to solve for <mathjax>#n#</mathjax>.</p> <p>Thus <mathjax>#180gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#nxx(3xx12.011+4xx1.0079+3xx15.999)gmol^-1#</mathjax><br/> <mathjax>#=#</mathjax> <mathjax>#nxx(88.0)gmol^-1#</mathjax></p> <p><mathjax>#n~=2#</mathjax>. Thus <mathjax>#"Molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_6H_8O_6#</mathjax>.</p> <p>Of course, the ratio is out a little bit. Such errors are common in the determination of such formulae. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_6H_8O_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is always a whole number multiple of the empirical formula:</p> <p>i.e. <mathjax>#"Molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"(Empirical formula)"xxn#</mathjax></p> <p>So we need to solve for <mathjax>#n#</mathjax>.</p> <p>Thus <mathjax>#180gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#nxx(3xx12.011+4xx1.0079+3xx15.999)gmol^-1#</mathjax><br/> <mathjax>#=#</mathjax> <mathjax>#nxx(88.0)gmol^-1#</mathjax></p> <p><mathjax>#n~=2#</mathjax>. Thus <mathjax>#"Molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_6H_8O_6#</mathjax>.</p> <p>Of course, the ratio is out a little bit. Such errors are common in the determination of such formulae. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A compound having an empirical formula of #C_3H_4O_3# has a mass of 180 g/mol. What is the molecular formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="273678" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-04T08:46:37" itemprop="dateCreated"> Jun 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_6H_8O_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is always a whole number multiple of the empirical formula:</p> <p>i.e. <mathjax>#"Molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"(Empirical formula)"xxn#</mathjax></p> <p>So we need to solve for <mathjax>#n#</mathjax>.</p> <p>Thus <mathjax>#180gmol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#nxx(3xx12.011+4xx1.0079+3xx15.999)gmol^-1#</mathjax><br/> <mathjax>#=#</mathjax> <mathjax>#nxx(88.0)gmol^-1#</mathjax></p> <p><mathjax>#n~=2#</mathjax>. Thus <mathjax>#"Molecular formula"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_6H_8O_6#</mathjax>.</p> <p>Of course, the ratio is out a little bit. Such errors are common in the determination of such formulae. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/273678" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1225 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A compound having an empirical formula of #C_3H_4O_3# has a mass of 180 g/mol. What is the molecular formula?	null
2,703	a940607e-6ddd-11ea-89cf-ccda262736ce	https://socratic.org/questions/what-is-the-oxidation-number-of-oxygen-in-peroxides	-1	start physical_unit 6 8 oxidation_number none qc_end substance 8 8 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] oxygen in peroxides"}]	[{"type":"physical unit","value":"-1"}]	[{"type":"substance name","value":"Peroxides"}]	<h1 class="questionTitle" itemprop="name">What is the oxidation number of oxygen in peroxides? </h1>	null	-1	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxygen almost always has an oxidation number of <mathjax>#-2#</mathjax>, except in peroxides. </p> <p>A peroxide is a molecule which includes <mathjax>#-O-O-#</mathjax>, like hydrogen peroxide, <mathjax>#HOOH#</mathjax>. </p> <p>In hydrogen peroxide, the overall charge is <mathjax>#0#</mathjax>, so all the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> must add up to <mathjax>#0#</mathjax>. The oxidation number for hydrogen is always <mathjax>#+1#</mathjax>, so</p> <p><mathjax>#HOOH = 0 = 1 xx 2 + X xx 2#</mathjax></p> <p>where <mathjax>#X#</mathjax> is the oxidation number for oxygen. </p> <p>From this, we can deduce that <mathjax>#X=-1#</mathjax>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxygen almost always has an oxidation number of <mathjax>#-2#</mathjax>, except in peroxides. </p> <p>A peroxide is a molecule which includes <mathjax>#-O-O-#</mathjax>, like hydrogen peroxide, <mathjax>#HOOH#</mathjax>. </p> <p>In hydrogen peroxide, the overall charge is <mathjax>#0#</mathjax>, so all the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> must add up to <mathjax>#0#</mathjax>. The oxidation number for hydrogen is always <mathjax>#+1#</mathjax>, so</p> <p><mathjax>#HOOH = 0 = 1 xx 2 + X xx 2#</mathjax></p> <p>where <mathjax>#X#</mathjax> is the oxidation number for oxygen. </p> <p>From this, we can deduce that <mathjax>#X=-1#</mathjax>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of oxygen in peroxides? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="385578" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/reudhreghs"><img alt="" class="" src="https://profilepictures.socratic.org/cbvHaqiiRa2eTNL3y20D_Just%20monkeying%20around%20%F0%9F%90%92%F0%9F%98%8D%F0%9F%8C%9E.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/reudhreghs"> reudhreghs </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-02T21:17:40" itemprop="dateCreated"> Mar 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Oxygen almost always has an oxidation number of <mathjax>#-2#</mathjax>, except in peroxides. </p> <p>A peroxide is a molecule which includes <mathjax>#-O-O-#</mathjax>, like hydrogen peroxide, <mathjax>#HOOH#</mathjax>. </p> <p>In hydrogen peroxide, the overall charge is <mathjax>#0#</mathjax>, so all the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> must add up to <mathjax>#0#</mathjax>. The oxidation number for hydrogen is always <mathjax>#+1#</mathjax>, so</p> <p><mathjax>#HOOH = 0 = 1 xx 2 + X xx 2#</mathjax></p> <p>where <mathjax>#X#</mathjax> is the oxidation number for oxygen. </p> <p>From this, we can deduce that <mathjax>#X=-1#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/385578" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electode-reaction-has-dssolved-oxygen-as-a-reactant-is-the-electrode-an-an"> If an electode reaction has dssolved oxygen as a reactant, is the electrode an anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electrode-reaction-has-dissolved-oxygen-as-a-reactant-is-the-electrode-and"> If an electrode reaction has dissolved oxygen as a reactant, is the electrode and anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-balanced-equation-represents-a-redox-reaction-2"> What balanced equation represents a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-redox-reactions-involved-in-electrolysis"> How are redox reactions involved in electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-oxidation-reduction-reactions-coupled"> Why are oxidation reduction reactions coupled? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-oxidation-reduction-reactions-involve"> What do oxidation reduction reactions involve? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-reduction-reactions-used-for"> What are reduction reactions used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-calx-mean-in-oxidation-reduction-reactions"> What does "calx" mean in oxidation reduction reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-reduced-components-in-this-reaction-zn-2h-zn-2-h2"> What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-and-reduction-reactions"> See all questions in Oxidation and Reduction Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13224 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the oxidation number of oxygen in peroxides?	null
2,704	ac90bff4-6ddd-11ea-9c70-ccda262736ce	https://socratic.org/questions/how-many-atoms-are-in-3-5-moles-of-arsenic-atoms	2.11 × 10^24	start physical_unit 8 9 number none qc_end physical_unit 8 9 5 6 mole qc_end end	[{"type":"physical unit","value":"Number [OF] arsenic atoms"}]	[{"type":"physical unit","value":"2.11 × 10^24"}]	[{"type":"physical unit","value":"Mole [OF] arsenic atoms [=] \\pu{3.5 moles}"}]	<h1 class="questionTitle" itemprop="name">How many atoms are in 3.5 moles of arsenic atoms?</h1>	null	2.11 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#3.5 cancel"mol As"* (6.02*10^23 "atoms As")/(1 cancel"mol As")=#</mathjax></p> <p><mathjax>#2.1xx10^24 "atoms As"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>See below<br/> <mathjax>#2.1xx10^24 "atoms As"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#3.5 cancel"mol As"* (6.02*10^23 "atoms As")/(1 cancel"mol As")=#</mathjax></p> <p><mathjax>#2.1xx10^24 "atoms As"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many atoms are in 3.5 moles of arsenic atoms?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="577562" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/hi-85"><img alt="" class="" src="https://profilepictures.socratic.org/6eJhQ7JzSje1IJFq7oZk_hqdefault.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/hi-85"> Hriman </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-20T01:14:12" itemprop="dateCreated"> Mar 20, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>See below<br/> <mathjax>#2.1xx10^24 "atoms As"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#3.5 cancel"mol As"* (6.02*10^23 "atoms As")/(1 cancel"mol As")=#</mathjax></p> <p><mathjax>#2.1xx10^24 "atoms As"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/577562" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="577563" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-20T01:15:49" itemprop="dateCreated"> Mar 20, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.11 × 10^24\ "Arsenic atoms"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <blockquote> <blockquote> <p><mathjax>#"1 mol of atoms" = 6.022 × 10^23\ "atoms"#</mathjax></p> </blockquote> </blockquote> </blockquote> <p><mathjax>#3.5 cancel"mol" × (6.022 × 10^23\ "atoms")/(1 cancel"mol") = 2.11 × 10^24\ "atoms"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/577563" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div 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2,705	acabe093-6ddd-11ea-ac01-ccda262736ce	https://socratic.org/questions/if-the-hydrogen-ion-concentration-in-a-solution-is-7-10-x-10-5-mol-l-what-is-the	4.15	start physical_unit 7 7 ph none qc_end physical_unit 2 3 9 12 concentration qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"4.15"}]	[{"type":"physical unit","value":"Concentration [OF] hydrogen ion [=] \\pu{7.10 × 10^(-5) mol/L}"}]	<h1 class="questionTitle" itemprop="name">If the hydrogen ion concentration in a solution is #7.10 x 10^-5# mol/L, what is the pH?</h1>	null	4.15	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax>.</p> <p>We are given that <mathjax>#[H_3O^+]=7.10xx10^-5molL^-1#</mathjax>.</p> <p>And thus <mathjax>#pH=-log_10(7.10xx10^-5)~=4#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH~=4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax>.</p> <p>We are given that <mathjax>#[H_3O^+]=7.10xx10^-5molL^-1#</mathjax>.</p> <p>And thus <mathjax>#pH=-log_10(7.10xx10^-5)~=4#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the hydrogen ion concentration in a solution is #7.10 x 10^-5# mol/L, what is the pH?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="369236" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-25T18:19:33" itemprop="dateCreated"> Jan 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH~=4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax>.</p> <p>We are given that <mathjax>#[H_3O^+]=7.10xx10^-5molL^-1#</mathjax>.</p> <p>And thus <mathjax>#pH=-log_10(7.10xx10^-5)~=4#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/369236" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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2,706	aa39455e-6ddd-11ea-9139-ccda262736ce	https://socratic.org/questions/5936d13f11ef6b0d253faf67	BaI2.30H2O	start chemical_formula qc_end physical_unit 14 14 12 13 mole qc_end physical_unit 18 18 16 17 mole qc_end end	[{"type":"other","value":"Chemical Formula [OF] barium iodide hydrate [IN] default"}]	[{"type":"chemical equation","value":"BaI2.30H2O"}]	[{"type":"physical unit","value":"Mole [OF] BaCI2 [=] \\pu{0.0243 mol}"},{"type":"physical unit","value":"Mole [OF] water [=] \\pu{0.75 mol}"}]	<h1 class="questionTitle" itemprop="name">What would be the formula of a barium iodide hydrate that contains #0.0243mol# #BaI_2#, and #0.75mol# water?</h1>	null	BaI2.30H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And how did I get this?</p> <p>I took the quotient <mathjax>#"Moles of water"/"Moles of barium iodide"#</mathjax>.</p> <p>And thus we gets........<mathjax>#(0.75molH_2O)/(0.0243molBaI_2)#</mathjax></p> <p>I think that you have quoted the wrong units; barium iodide is typically supplied as the dihydrate, i.e. <mathjax>#BaI_2*2H_2O#</mathjax>; well, that's what the (old!) bottle on the shelf says. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well it would be <mathjax>#BaI_230H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And how did I get this?</p> <p>I took the quotient <mathjax>#"Moles of water"/"Moles of barium iodide"#</mathjax>.</p> <p>And thus we gets........<mathjax>#(0.75molH_2O)/(0.0243molBaI_2)#</mathjax></p> <p>I think that you have quoted the wrong units; barium iodide is typically supplied as the dihydrate, i.e. <mathjax>#BaI_22H_2O#</mathjax>; well, that's what the (old!) bottle on the shelf says. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What would be the formula of a barium iodide hydrate that contains #0.0243mol# #BaI_2#, and #0.75mol# water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437552" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T15:16:57" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well it would be <mathjax>#BaI_230H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And how did I get this?</p> <p>I took the quotient <mathjax>#"Moles of water"/"Moles of barium iodide"#</mathjax>.</p> <p>And thus we gets........<mathjax>#(0.75molH_2O)/(0.0243molBaI_2)#</mathjax></p> <p>I think that you have quoted the wrong units; barium iodide is typically supplied as the dihydrate, i.e. <mathjax>#BaI_22H_2O#</mathjax>; well, that's what the (old!) bottle on the shelf says. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437552" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2192 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What would be the formula of a barium iodide hydrate that contains #0.0243mol# #BaI_2#, and #0.75mol# water?	null
2,707	ac7b605c-6ddd-11ea-9e54-ccda262736ce	https://socratic.org/questions/a-piece-of-iron-was-placed-in-a-silver-nitrate-solution-after-the-reaction-iron-	0.02 moles	start physical_unit 24 24 mole mol qc_end physical_unit 3 3 18 19 mass qc_end substance 8 10 qc_end end	[{"type":"physical unit","value":"Mole [OF] Fe(NO3)2 [IN] moles"}]	[{"type":"physical unit","value":"0.02 moles"}]	[{"type":"physical unit","value":"Increased mass [OF] iron [=] \\pu{3.52 g}"},{"type":"substance name","value":"Silver nitrate solution"}]	<h1 class="questionTitle" itemprop="name">A piece of iron was placed in a silver nitrate solution. After the reaction iron's mass increased by 3.52g. How many moles of #"Fe"("NO"_3)_2# were produced?</h1>	null	0.02 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong><a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong> in which iron, <mathjax>#"Fe"#</mathjax>, <strong>reduces</strong> the silver cations, <mathjax>#"Ag"^(+)#</mathjax>, to silver metal, <mathjax>#"Ag"#</mathjax>, while being <strong>oxidized</strong> to iron(II) cations, <mathjax>#"Fe"^(2+)#</mathjax>. </p> <p>The <strong>net ionic equation</strong> that describes this reaction looks like this </p> <blockquote> <p><mathjax>#"Fe"_ ((s)) + 2"Ag"_ ((aq))^(+) -> "Fe"_ ((aq))^(2+) + color(red)(2)"Ag"_ ((s)) darr#</mathjax></p> </blockquote> <p>The silver metal produced by the reaction will be <strong>deposited</strong> on the piece of iron. As a result, its <em>mass</em> will increase. </p> <p>Now, here's where the tricky part comes in. Keep in mind that some of the iron will be converted to iron(II) cations. This means that if you <em>disregard</em> the deposited silver, the piece of iron will actually have a <strong>smaller mass</strong> once the reaction is completed. </p> <p>Let's take <mathjax>#m_"Fe"#</mathjax> <mathjax>#"g"#</mathjax> to be the <strong>initial mass</strong> of the piece of iron. Let's assume that <mathjax>#x#</mathjax> represents the <strong>number of moles</strong> of iron(II) cations produced by the reaction. Iron has a <strong>molar mass</strong> of <mathjax>#"55.845 g mol"^(-1)#</mathjax>. </p> <p>This means that the mass of iron that was converted to iron(II) cations was </p> <blockquote> <p><mathjax>#x color(red)(cancel(color(black)("moles Fe"^(2+)))) * "55.845 g"/(1color(red)(cancel(color(black)("mole Fe"^(2+))))) = (55.845 * x)" g"#</mathjax></p> </blockquote> <p>The mass of the piece of iron <strong>after</strong> the reaction is completed, once again <em>disregarding</em> the mass of silver deposited, will be </p> <blockquote> <p><mathjax>#m_"Fe" " g" - (x * 55.845)" g" = (m_"Fe" - x * 55.845)" g"#</mathjax></p> </blockquote> <p>Now, notice that <strong>for every mole</strong> of iron(II) cations produced by the reaction, you also get <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of silver metal. It follows that for <mathjax>#x#</mathjax> <strong>moles</strong> of iron(II) cations, the reaction will produce <mathjax>#(color(red)(2)x)#</mathjax> <strong>moles</strong> of silver metal. </p> <p>Use the <strong>molar mass</strong> of silver to find the <em>mass</em> of silver metal produced by the reaction</p> <blockquote> <p><mathjax>#(color(red)(2)x) color(red)(cancel(color(black)("moles Ag"))) * "107.87 g"/(1color(red)(cancel(color(black)("mole Ag")))) = (215.74 * x)" g Ag"#</mathjax></p> </blockquote> <p>This mass is <strong>added</strong> to the mass of <em>iron</em> to get the <strong>total mass</strong> of the piece of iron, i.e. iron + deposited silver</p> <blockquote> <p><mathjax>#overbrace((m_"Fe" - 55.845 * x) " g")^(color(blue)("remaining mass of iron")) + overbrace((215.74 * x)" g")^(color(purple)("mass of silver deposited")) = overbrace((m_"Fe" + 3.52)" g")^(color(darkgreen)("mass of iron + silver"))#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(m_"Fe"))) - 55.845 * x + 215.74 * x = color(red)(cancel(color(black)(m_"Fe"))) + 3.52#</mathjax></p> <p><mathjax>#159.895 * x = 3.52 implies x = 3.52/159.895 = 0.0220#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> represents the <strong>number of moles</strong> of iron(II) cations, which keep in mind is <strong>equal</strong> to the number of moles of iron(II) nitrate, <mathjax>#"Fe"("NO"_3)_2#</mathjax>, produced by the reaction</p> <blockquote> <p><mathjax>#"Fe"("NO"_ 3)_ (2(aq)) -> "Fe"_ ((aq))^(2+) + 2"NO"_ (3(aq))#</mathjax></p> </blockquote> <p>you will have</p> <blockquote> <p><mathjax>#"no. of moles of Fe"^(2+) = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.0220 moles")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.0220 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong><a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong> in which iron, <mathjax>#"Fe"#</mathjax>, <strong>reduces</strong> the silver cations, <mathjax>#"Ag"^(+)#</mathjax>, to silver metal, <mathjax>#"Ag"#</mathjax>, while being <strong>oxidized</strong> to iron(II) cations, <mathjax>#"Fe"^(2+)#</mathjax>. </p> <p>The <strong>net ionic equation</strong> that describes this reaction looks like this </p> <blockquote> <p><mathjax>#"Fe"_ ((s)) + 2"Ag"_ ((aq))^(+) -> "Fe"_ ((aq))^(2+) + color(red)(2)"Ag"_ ((s)) darr#</mathjax></p> </blockquote> <p>The silver metal produced by the reaction will be <strong>deposited</strong> on the piece of iron. As a result, its <em>mass</em> will increase. </p> <p>Now, here's where the tricky part comes in. Keep in mind that some of the iron will be converted to iron(II) cations. This means that if you <em>disregard</em> the deposited silver, the piece of iron will actually have a <strong>smaller mass</strong> once the reaction is completed. </p> <p>Let's take <mathjax>#m_"Fe"#</mathjax> <mathjax>#"g"#</mathjax> to be the <strong>initial mass</strong> of the piece of iron. Let's assume that <mathjax>#x#</mathjax> represents the <strong>number of moles</strong> of iron(II) cations produced by the reaction. Iron has a <strong>molar mass</strong> of <mathjax>#"55.845 g mol"^(-1)#</mathjax>. </p> <p>This means that the mass of iron that was converted to iron(II) cations was </p> <blockquote> <p><mathjax>#x color(red)(cancel(color(black)("moles Fe"^(2+)))) * "55.845 g"/(1color(red)(cancel(color(black)("mole Fe"^(2+))))) = (55.845 * x)" g"#</mathjax></p> </blockquote> <p>The mass of the piece of iron <strong>after</strong> the reaction is completed, once again <em>disregarding</em> the mass of silver deposited, will be </p> <blockquote> <p><mathjax>#m_"Fe" " g" - (x * 55.845)" g" = (m_"Fe" - x * 55.845)" g"#</mathjax></p> </blockquote> <p>Now, notice that <strong>for every mole</strong> of iron(II) cations produced by the reaction, you also get <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of silver metal. It follows that for <mathjax>#x#</mathjax> <strong>moles</strong> of iron(II) cations, the reaction will produce <mathjax>#(color(red)(2)x)#</mathjax> <strong>moles</strong> of silver metal. </p> <p>Use the <strong>molar mass</strong> of silver to find the <em>mass</em> of silver metal produced by the reaction</p> <blockquote> <p><mathjax>#(color(red)(2)x) color(red)(cancel(color(black)("moles Ag"))) * "107.87 g"/(1color(red)(cancel(color(black)("mole Ag")))) = (215.74 * x)" g Ag"#</mathjax></p> </blockquote> <p>This mass is <strong>added</strong> to the mass of <em>iron</em> to get the <strong>total mass</strong> of the piece of iron, i.e. iron + deposited silver</p> <blockquote> <p><mathjax>#overbrace((m_"Fe" - 55.845 * x) " g")^(color(blue)("remaining mass of iron")) + overbrace((215.74 * x)" g")^(color(purple)("mass of silver deposited")) = overbrace((m_"Fe" + 3.52)" g")^(color(darkgreen)("mass of iron + silver"))#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(m_"Fe"))) - 55.845 * x + 215.74 * x = color(red)(cancel(color(black)(m_"Fe"))) + 3.52#</mathjax></p> <p><mathjax>#159.895 * x = 3.52 implies x = 3.52/159.895 = 0.0220#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> represents the <strong>number of moles</strong> of iron(II) cations, which keep in mind is <strong>equal</strong> to the number of moles of iron(II) nitrate, <mathjax>#"Fe"("NO"_3)_2#</mathjax>, produced by the reaction</p> <blockquote> <p><mathjax>#"Fe"("NO"_ 3)_ (2(aq)) -> "Fe"_ ((aq))^(2+) + 2"NO"_ (3(aq))#</mathjax></p> </blockquote> <p>you will have</p> <blockquote> <p><mathjax>#"no. of moles of Fe"^(2+) = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.0220 moles")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A piece of iron was placed in a silver nitrate solution. After the reaction iron's mass increased by 3.52g. How many moles of #"Fe"("NO"_3)_2# were produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="291449" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-24T12:53:49" itemprop="dateCreated"> Jul 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.0220 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong><a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong> in which iron, <mathjax>#"Fe"#</mathjax>, <strong>reduces</strong> the silver cations, <mathjax>#"Ag"^(+)#</mathjax>, to silver metal, <mathjax>#"Ag"#</mathjax>, while being <strong>oxidized</strong> to iron(II) cations, <mathjax>#"Fe"^(2+)#</mathjax>. </p> <p>The <strong>net ionic equation</strong> that describes this reaction looks like this </p> <blockquote> <p><mathjax>#"Fe"_ ((s)) + 2"Ag"_ ((aq))^(+) -> "Fe"_ ((aq))^(2+) + color(red)(2)"Ag"_ ((s)) darr#</mathjax></p> </blockquote> <p>The silver metal produced by the reaction will be <strong>deposited</strong> on the piece of iron. As a result, its <em>mass</em> will increase. </p> <p>Now, here's where the tricky part comes in. Keep in mind that some of the iron will be converted to iron(II) cations. This means that if you <em>disregard</em> the deposited silver, the piece of iron will actually have a <strong>smaller mass</strong> once the reaction is completed. </p> <p>Let's take <mathjax>#m_"Fe"#</mathjax> <mathjax>#"g"#</mathjax> to be the <strong>initial mass</strong> of the piece of iron. Let's assume that <mathjax>#x#</mathjax> represents the <strong>number of moles</strong> of iron(II) cations produced by the reaction. Iron has a <strong>molar mass</strong> of <mathjax>#"55.845 g mol"^(-1)#</mathjax>. </p> <p>This means that the mass of iron that was converted to iron(II) cations was </p> <blockquote> <p><mathjax>#x color(red)(cancel(color(black)("moles Fe"^(2+)))) * "55.845 g"/(1color(red)(cancel(color(black)("mole Fe"^(2+))))) = (55.845 * x)" g"#</mathjax></p> </blockquote> <p>The mass of the piece of iron <strong>after</strong> the reaction is completed, once again <em>disregarding</em> the mass of silver deposited, will be </p> <blockquote> <p><mathjax>#m_"Fe" " g" - (x * 55.845)" g" = (m_"Fe" - x * 55.845)" g"#</mathjax></p> </blockquote> <p>Now, notice that <strong>for every mole</strong> of iron(II) cations produced by the reaction, you also get <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of silver metal. It follows that for <mathjax>#x#</mathjax> <strong>moles</strong> of iron(II) cations, the reaction will produce <mathjax>#(color(red)(2)x)#</mathjax> <strong>moles</strong> of silver metal. </p> <p>Use the <strong>molar mass</strong> of silver to find the <em>mass</em> of silver metal produced by the reaction</p> <blockquote> <p><mathjax>#(color(red)(2)x) color(red)(cancel(color(black)("moles Ag"))) * "107.87 g"/(1color(red)(cancel(color(black)("mole Ag")))) = (215.74 * x)" g Ag"#</mathjax></p> </blockquote> <p>This mass is <strong>added</strong> to the mass of <em>iron</em> to get the <strong>total mass</strong> of the piece of iron, i.e. iron + deposited silver</p> <blockquote> <p><mathjax>#overbrace((m_"Fe" - 55.845 * x) " g")^(color(blue)("remaining mass of iron")) + overbrace((215.74 * x)" g")^(color(purple)("mass of silver deposited")) = overbrace((m_"Fe" + 3.52)" g")^(color(darkgreen)("mass of iron + silver"))#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(m_"Fe"))) - 55.845 * x + 215.74 * x = color(red)(cancel(color(black)(m_"Fe"))) + 3.52#</mathjax></p> <p><mathjax>#159.895 * x = 3.52 implies x = 3.52/159.895 = 0.0220#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> represents the <strong>number of moles</strong> of iron(II) cations, which keep in mind is <strong>equal</strong> to the number of moles of iron(II) nitrate, <mathjax>#"Fe"("NO"_3)_2#</mathjax>, produced by the reaction</p> <blockquote> <p><mathjax>#"Fe"("NO"_ 3)_ (2(aq)) -> "Fe"_ ((aq))^(2+) + 2"NO"_ (3(aq))#</mathjax></p> </blockquote> <p>you will have</p> <blockquote> <p><mathjax>#"no. of moles of Fe"^(2+) = color(green)(\|bar(ul(color(white)(a/a)color(black)("0.0220 moles")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/291449" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -> 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---> 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---> 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---> 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16281 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A piece of iron was placed in a silver nitrate solution. After the reaction iron's mass increased by 3.52g. How many moles of #"Fe"("NO"_3)_2# were produced?	null
2,708	ac0d7e88-6ddd-11ea-b64f-ccda262736ce	https://socratic.org/questions/what-is-the-mass-of-a-sample-of-neon-gas-if-the-volume-is-10-l-at-stp	9 g	start physical_unit 6 9 mass g qc_end physical_unit 6 9 14 15 volume qc_end c_other STP qc_end end	[{"type":"physical unit","value":"Mass [OF] neon gas sample [IN] g"}]	[{"type":"physical unit","value":"9 g"}]	[{"type":"physical unit","value":"Volume [OF] neon gas sample [=] \\pu{10 L}"},{"type":"other","value":"STP"}]	<h1 class="questionTitle" itemprop="name">What is the mass of a sample of neon gas if the volume is 10 L at STP?</h1>	null	9 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we solve for <mathjax>#n_"moles of gas"#</mathjax> in the Ideal Gas equation, and of course we have to fish out an appropriate gas constant...</p> <p><mathjax>#n=(PV)/(RT)=(100kPaxx10L)/(8.314LkPaK^-1mol^-1xx273.15K)#</mathjax></p> <p><mathjax>#=0.440mol#</mathjax></p> <p>And thus a mass of <mathjax>#0.440molxx20.18gmol^-1#</mathjax>...approx. <mathjax>#9g#</mathjax>...</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well <mathjax>#"STP"#</mathjax> specifies <mathjax>#100kPa#</mathjax> and <mathjax>#273.15K#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we solve for <mathjax>#n_"moles of gas"#</mathjax> in the Ideal Gas equation, and of course we have to fish out an appropriate gas constant...</p> <p><mathjax>#n=(PV)/(RT)=(100kPaxx10L)/(8.314LkPaK^-1mol^-1xx273.15K)#</mathjax></p> <p><mathjax>#=0.440mol#</mathjax></p> <p>And thus a mass of <mathjax>#0.440molxx20.18gmol^-1#</mathjax>...approx. <mathjax>#9g#</mathjax>...</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass of a sample of neon gas if the volume is 10 L at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="643292" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-25T08:25:06" itemprop="dateCreated"> Jul 25, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well <mathjax>#"STP"#</mathjax> specifies <mathjax>#100kPa#</mathjax> and <mathjax>#273.15K#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we solve for <mathjax>#n_"moles of gas"#</mathjax> in the Ideal Gas equation, and of course we have to fish out an appropriate gas constant...</p> <p><mathjax>#n=(PV)/(RT)=(100kPaxx10L)/(8.314LkPaK^-1mol^-1xx273.15K)#</mathjax></p> <p><mathjax>#=0.440mol#</mathjax></p> <p>And thus a mass of <mathjax>#0.440molxx20.18gmol^-1#</mathjax>...approx. <mathjax>#9g#</mathjax>...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/643292" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3782 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass of a sample of neon gas if the volume is 10 L at STP?	null
2,709	a8d3d9e2-6ddd-11ea-a73f-ccda262736ce	https://socratic.org/questions/how-do-you-balance-c4h16-o2-co2-h2o-i-have-tried-to-do-balance-them-but-i-can-39	2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O"}]	[{"type":"chemical equation","value":"C4H10 + O2 -> CO2 + H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance _C4H16+_O2--> _CO2+_H2O? I have tried to do balance them but i can&#39;t..this is very tricky... thanks..?</h1>	null	2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydrocarbons (of all stamps) react with oxygen to give <mathjax>#CO_2#</mathjax> and <mathjax>#H_2O#</mathjax>. Sometimes the carbon in hydrocarbons, where oxygen is limited, react to give particulate <mathjax>#C#</mathjax>, and gaseous <mathjax>#CO#</mathjax> (this occurs particularly in diesel engines). Balance the carbons (as <mathjax>#CO_2#</mathjax> for complete combustion), then the hydrogens (as water), and then the oxygen reactant (it doesn't matter if I have a half coefficient, because I could remove it by doubling the entire reaction:</p> <p><mathjax>#2C_4H_10(g) + 13O_2(g) rarr 8CO_2(g) + 10H_2O(g)#</mathjax></p> <p>For every reactant particle is there a corresponding product particle? Hmm, <mathjax>#8C's#</mathjax>, <mathjax>#20H's#</mathjax>, <mathjax>#26O's#</mathjax>. So this equation is indeed stoichiometrically balanced, as required. </p> <p>You should try this routine with other hydrocarbons, <mathjax>#CH_4#</mathjax>, <mathjax>#H_3C-CH_3#</mathjax>, hexane, kerosene, diesel. These questions invariably appear on A level exams, and with a little bit of preparation they are trivial exercises. Good luck!</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Combustion of butane:<br/> <mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydrocarbons (of all stamps) react with oxygen to give <mathjax>#CO_2#</mathjax> and <mathjax>#H_2O#</mathjax>. Sometimes the carbon in hydrocarbons, where oxygen is limited, react to give particulate <mathjax>#C#</mathjax>, and gaseous <mathjax>#CO#</mathjax> (this occurs particularly in diesel engines). Balance the carbons (as <mathjax>#CO_2#</mathjax> for complete combustion), then the hydrogens (as water), and then the oxygen reactant (it doesn't matter if I have a half coefficient, because I could remove it by doubling the entire reaction:</p> <p><mathjax>#2C_4H_10(g) + 13O_2(g) rarr 8CO_2(g) + 10H_2O(g)#</mathjax></p> <p>For every reactant particle is there a corresponding product particle? Hmm, <mathjax>#8C's#</mathjax>, <mathjax>#20H's#</mathjax>, <mathjax>#26O's#</mathjax>. So this equation is indeed stoichiometrically balanced, as required. </p> <p>You should try this routine with other hydrocarbons, <mathjax>#CH_4#</mathjax>, <mathjax>#H_3C-CH_3#</mathjax>, hexane, kerosene, diesel. These questions invariably appear on A level exams, and with a little bit of preparation they are trivial exercises. Good luck!</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance _C4H16+_O2--> _CO2+_H2O? I have tried to do balance them but i can&#39;t..this is very tricky... thanks..?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="178724" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-21T06:38:30" itemprop="dateCreated"> Oct 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Combustion of butane:<br/> <mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Hydrocarbons (of all stamps) react with oxygen to give <mathjax>#CO_2#</mathjax> and <mathjax>#H_2O#</mathjax>. Sometimes the carbon in hydrocarbons, where oxygen is limited, react to give particulate <mathjax>#C#</mathjax>, and gaseous <mathjax>#CO#</mathjax> (this occurs particularly in diesel engines). Balance the carbons (as <mathjax>#CO_2#</mathjax> for complete combustion), then the hydrogens (as water), and then the oxygen reactant (it doesn't matter if I have a half coefficient, because I could remove it by doubling the entire reaction:</p> <p><mathjax>#2C_4H_10(g) + 13O_2(g) rarr 8CO_2(g) + 10H_2O(g)#</mathjax></p> <p>For every reactant particle is there a corresponding product particle? Hmm, <mathjax>#8C's#</mathjax>, <mathjax>#20H's#</mathjax>, <mathjax>#26O's#</mathjax>. So this equation is indeed stoichiometrically balanced, as required. </p> <p>You should try this routine with other hydrocarbons, <mathjax>#CH_4#</mathjax>, <mathjax>#H_3C-CH_3#</mathjax>, hexane, kerosene, diesel. These questions invariably appear on A level exams, and with a little bit of preparation they are trivial exercises. Good luck!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/178724" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1845 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance _C4H16+_O2--> _CO2+_H2O? I have tried to do balance them but i can&#39;t..this is very tricky... thanks..?	null
2,710	a8c92a7e-6ddd-11ea-8cb6-ccda262736ce	https://socratic.org/questions/what-is-the-freezing-point-of-an-a-nonionizing-antifreeze-solution-containing-38	-2.84 ℃	start physical_unit 6 10 freezing_point_temperature °c qc_end physical_unit 16 16 12 13 mass qc_end physical_unit 21 21 18 19 mass qc_end end	[{"type":"physical unit","value":"Freezing point [OF] an a nonionizing antifreeze solution [IN] ℃"}]	[{"type":"physical unit","value":"-2.84 ℃"}]	[{"type":"physical unit","value":"Mass [OF] C2H6O2 [=] \\pu{38.8 g}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{409 g}"}]	<h1 class="questionTitle" itemprop="name">What is the freezing point of an a nonionizing antifreeze solution containing 38.8g ethylene glycol, #C_2H_6O_2#, and 409 g of water?</h1>	null	-2.84 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice for this problem will be the equation for <em>freezing-point depression</em>, which looks like this </p> <blockquote> <p><mathjax>#DeltaT_f = i * K_f * b" "#</mathjax>, where</p> </blockquote> <p><mathjax>#DeltaT_f#</mathjax> - the freezing-point depression;<br/> <mathjax>#i#</mathjax> - the <em>van't Hoff factor</em>, equal to <mathjax>#1#</mathjax> for non-electrolytes;<br/> <mathjax>#K_f#</mathjax> - the <em>cryoscopic constant</em> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>;<br/> <mathjax>#b#</mathjax> - the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution.</p> <p>The cryoscopic constant of water is equal to <mathjax>#1.86 ""^@"C kg mol"^(-1)#</mathjax></p> <p><a href="http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf" rel="nofollow" target="_blank">http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf</a></p> <p>In order to be able to determine the freezing point of this solution, you will first need to find its <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a>, which as you know is defined as the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> divided by the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> - expressed in <strong>kilograms</strong>!</p> <p>Use ethylene glycol's molar mass to determine how many moles you have in that sample</p> <blockquote> <p><mathjax>#38.8color(red)(cancel(color(black)("g"))) * ("1 mole C"_2"H"_6"O"_2)/(62.07color(red)(cancel(color(black)("g")))) = "0.625 moles C"_2"H"_6"O"_2#</mathjax></p> </blockquote> <p>This means that the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(b = n/m)#</mathjax></p> <p><mathjax>#b = "0.625 moles"/(409 * 10^(-3)"kg") = "1.528 molal"#</mathjax></p> </blockquote> <p>This means that the freezing-point depression for this solution will be </p> <blockquote> <p><mathjax>#DeltaT_"f" = 1 * 1.86""^@"C" color(red)(cancel(color(black)("kg"))) color(red)(cancel(color(black)("mol"^(-1)))) * 1.528color(red)(cancel(color(black)("moles"))) color(red)(cancel(color(black)("kg"^(-1)))) = 2.84^@"C"#</mathjax></p> </blockquote> <p>The freezing-point depression is defined as the difference bwteen the freezing point of the <em>pure solvent</em> and the freezing point of the solution</p> <blockquote> <p><mathjax>#color(blue)(DeltaT_"f" = T_"f"^@ - T_"f sol")#</mathjax></p> </blockquote> <p>This means that the freezing point of the solution will be </p> <blockquote> <p><mathjax>#T_"f sol" = T_"f"^@ - DeltaT_"f"#</mathjax></p> <p><mathjax>#T_"f sol" = 0^@"C" - 2.84^@"C" = color(green)(-2.84^@"C")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T_"f sol" = -2.84^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice for this problem will be the equation for <em>freezing-point depression</em>, which looks like this </p> <blockquote> <p><mathjax>#DeltaT_f = i * K_f * b" "#</mathjax>, where</p> </blockquote> <p><mathjax>#DeltaT_f#</mathjax> - the freezing-point depression;<br/> <mathjax>#i#</mathjax> - the <em>van't Hoff factor</em>, equal to <mathjax>#1#</mathjax> for non-electrolytes;<br/> <mathjax>#K_f#</mathjax> - the <em>cryoscopic constant</em> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>;<br/> <mathjax>#b#</mathjax> - the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution.</p> <p>The cryoscopic constant of water is equal to <mathjax>#1.86 ""^@"C kg mol"^(-1)#</mathjax></p> <p><a href="http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf" rel="nofollow" target="_blank">http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf</a></p> <p>In order to be able to determine the freezing point of this solution, you will first need to find its <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a>, which as you know is defined as the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> divided by the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> - expressed in <strong>kilograms</strong>!</p> <p>Use ethylene glycol's molar mass to determine how many moles you have in that sample</p> <blockquote> <p><mathjax>#38.8color(red)(cancel(color(black)("g"))) * ("1 mole C"_2"H"_6"O"_2)/(62.07color(red)(cancel(color(black)("g")))) = "0.625 moles C"_2"H"_6"O"_2#</mathjax></p> </blockquote> <p>This means that the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(b = n/m)#</mathjax></p> <p><mathjax>#b = "0.625 moles"/(409 * 10^(-3)"kg") = "1.528 molal"#</mathjax></p> </blockquote> <p>This means that the freezing-point depression for this solution will be </p> <blockquote> <p><mathjax>#DeltaT_"f" = 1 * 1.86""^@"C" color(red)(cancel(color(black)("kg"))) color(red)(cancel(color(black)("mol"^(-1)))) * 1.528color(red)(cancel(color(black)("moles"))) color(red)(cancel(color(black)("kg"^(-1)))) = 2.84^@"C"#</mathjax></p> </blockquote> <p>The freezing-point depression is defined as the difference bwteen the freezing point of the <em>pure solvent</em> and the freezing point of the solution</p> <blockquote> <p><mathjax>#color(blue)(DeltaT_"f" = T_"f"^@ - T_"f sol")#</mathjax></p> </blockquote> <p>This means that the freezing point of the solution will be </p> <blockquote> <p><mathjax>#T_"f sol" = T_"f"^@ - DeltaT_"f"#</mathjax></p> <p><mathjax>#T_"f sol" = 0^@"C" - 2.84^@"C" = color(green)(-2.84^@"C")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the freezing point of an a nonionizing antifreeze solution containing 38.8g ethylene glycol, #C_2H_6O_2#, and 409 g of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="191044" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-20T13:06:22" itemprop="dateCreated"> Nov 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T_"f sol" = -2.84^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice for this problem will be the equation for <em>freezing-point depression</em>, which looks like this </p> <blockquote> <p><mathjax>#DeltaT_f = i * K_f * b" "#</mathjax>, where</p> </blockquote> <p><mathjax>#DeltaT_f#</mathjax> - the freezing-point depression;<br/> <mathjax>#i#</mathjax> - the <em>van't Hoff factor</em>, equal to <mathjax>#1#</mathjax> for non-electrolytes;<br/> <mathjax>#K_f#</mathjax> - the <em>cryoscopic constant</em> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>;<br/> <mathjax>#b#</mathjax> - the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution.</p> <p>The cryoscopic constant of water is equal to <mathjax>#1.86 ""^@"C kg mol"^(-1)#</mathjax></p> <p><a href="http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf" rel="nofollow" target="_blank">http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf</a></p> <p>In order to be able to determine the freezing point of this solution, you will first need to find its <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a>, which as you know is defined as the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> divided by the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> - expressed in <strong>kilograms</strong>!</p> <p>Use ethylene glycol's molar mass to determine how many moles you have in that sample</p> <blockquote> <p><mathjax>#38.8color(red)(cancel(color(black)("g"))) * ("1 mole C"_2"H"_6"O"_2)/(62.07color(red)(cancel(color(black)("g")))) = "0.625 moles C"_2"H"_6"O"_2#</mathjax></p> </blockquote> <p>This means that the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(b = n/m)#</mathjax></p> <p><mathjax>#b = "0.625 moles"/(409 * 10^(-3)"kg") = "1.528 molal"#</mathjax></p> </blockquote> <p>This means that the freezing-point depression for this solution will be </p> <blockquote> <p><mathjax>#DeltaT_"f" = 1 * 1.86""^@"C" color(red)(cancel(color(black)("kg"))) color(red)(cancel(color(black)("mol"^(-1)))) * 1.528color(red)(cancel(color(black)("moles"))) color(red)(cancel(color(black)("kg"^(-1)))) = 2.84^@"C"#</mathjax></p> </blockquote> <p>The freezing-point depression is defined as the difference bwteen the freezing point of the <em>pure solvent</em> and the freezing point of the solution</p> <blockquote> <p><mathjax>#color(blue)(DeltaT_"f" = T_"f"^@ - T_"f sol")#</mathjax></p> </blockquote> <p>This means that the freezing point of the solution will be </p> <blockquote> <p><mathjax>#T_"f sol" = T_"f"^@ - DeltaT_"f"#</mathjax></p> <p><mathjax>#T_"f sol" = 0^@"C" - 2.84^@"C" = color(green)(-2.84^@"C")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/191044" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-colligative-properties-determined"> How are colligative properties determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-freezing-point-depression"> How do you calculate freezing point depression? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-freezing-point-depression-determine-purity"> How can freezing point depression determine purity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-colligative-properties-affect-boiling-point"> How does the nature of the solute affect boiling point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-colligative-properties-affect-freezing-point"> How do colligative properties affect freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-colligative-property-causes-ice-to-melt"> What colligative property causes ice to melt? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-colligative-properties-depend-on-the-number-of-particles"> Why do colligative properties depend on the number of particles? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionic-bonding-affect-the-boiling-point"> How do ionic solutes affect the boiling point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-vapor-pressure"> Why do solutes lower vapor pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-boiling-point"> How does solubility affect boiling point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/colligative-properties"> See all questions in Colligative Properties </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12523 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the freezing point of an a nonionizing antifreeze solution containing 38.8g ethylene glycol, #C_2H_6O_2#, and 409 g of water?	null
2,711	a8ef3d28-6ddd-11ea-a159-ccda262736ce	https://socratic.org/questions/what-is-the-specific-heat-of-a-material-if-a-6-0-g-sample-absorbs-50-j-when-it-i	0.42 J/(g * ℃)	start physical_unit 7 7 specific_heat j/(°c_·_g) qc_end physical_unit 7 7 10 11 mass qc_end physical_unit 7 7 14 15 heat_energy qc_end physical_unit 7 7 21 22 temperature qc_end physical_unit 7 7 24 25 temperature qc_end end	[{"type":"physical unit","value":"Specific heat [OF] the material sample [IN] J/(g * ℃)"}]	[{"type":"physical unit","value":"0.42 J/(g * ℃)"}]	[{"type":"physical unit","value":"Mass [OF] the material sample [=] \\pu{6.0 g}"},{"type":"physical unit","value":"Absorbed energy [OF] the material sample [=] \\pu{50 J}"},{"type":"physical unit","value":"Temperature1 [OF] the material sample [=] \\pu{30 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the material sample [=] \\pu{50 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the specific heat of a material if a 6.0 g sample absorbs 50 J when it is heated from 30°C to 50°C?</h1>	null	0.42 J/(g * ℃)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation <mathjax>#q=mC_sDeltaT#</mathjax></p> <p>You are given the <mathjax>#q#</mathjax> in the form of J. You are given the mass in grams and also the initial and final temperature. <mathjax>#Delta#</mathjax>T = <mathjax>#T_f#</mathjax>-<mathjax>#T_i#</mathjax>.</p> <p>If you plug in the known variables the equation will look like:<br/> <mathjax>#50J#</mathjax>=<mathjax>#6g#</mathjax><mathjax>#(C_s)#</mathjax><mathjax>#20C#</mathjax></p> <p>At this point you just solve for <mathjax>#C_s#</mathjax> using some algebra.</p> <p><mathjax>#50J#</mathjax>/<mathjax>#(6g)#</mathjax><mathjax>#(20C)#</mathjax></p> <p>It is really helpful to keep units in the equation when solving. Let the units lead the way in solving thermochemistry problems.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cs#</mathjax>= 0.4167<mathjax>#J/(gC)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation <mathjax>#q=mC_sDeltaT#</mathjax></p> <p>You are given the <mathjax>#q#</mathjax> in the form of J. You are given the mass in grams and also the initial and final temperature. <mathjax>#Delta#</mathjax>T = <mathjax>#T_f#</mathjax>-<mathjax>#T_i#</mathjax>.</p> <p>If you plug in the known variables the equation will look like:<br/> <mathjax>#50J#</mathjax>=<mathjax>#6g#</mathjax><mathjax>#(C_s)#</mathjax><mathjax>#20C#</mathjax></p> <p>At this point you just solve for <mathjax>#C_s#</mathjax> using some algebra.</p> <p><mathjax>#50J#</mathjax>/<mathjax>#(6g)#</mathjax><mathjax>#(20C)#</mathjax></p> <p>It is really helpful to keep units in the equation when solving. Let the units lead the way in solving thermochemistry problems.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the specific heat of a material if a 6.0 g sample absorbs 50 J when it is heated from 30°C to 50°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185855" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/slangus"><img alt="" class="" src="https://profilepictures.socratic.org/drkbgwWiTc2nF7Sd9TrX_1103421756345992.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/slangus"> Slangus </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-09T01:30:50" itemprop="dateCreated"> Nov 9, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cs#</mathjax>= 0.4167<mathjax>#J/(gC)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation <mathjax>#q=mC_sDeltaT#</mathjax></p> <p>You are given the <mathjax>#q#</mathjax> in the form of J. You are given the mass in grams and also the initial and final temperature. <mathjax>#Delta#</mathjax>T = <mathjax>#T_f#</mathjax>-<mathjax>#T_i#</mathjax>.</p> <p>If you plug in the known variables the equation will look like:<br/> <mathjax>#50J#</mathjax>=<mathjax>#6g#</mathjax><mathjax>#(C_s)#</mathjax><mathjax>#20C#</mathjax></p> <p>At this point you just solve for <mathjax>#C_s#</mathjax> using some algebra.</p> <p><mathjax>#50J#</mathjax>/<mathjax>#(6g)#</mathjax><mathjax>#(20C)#</mathjax></p> <p>It is really helpful to keep units in the equation when solving. Let the units lead the way in solving thermochemistry problems.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185855" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9640 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the specific heat of a material if a 6.0 g sample absorbs 50 J when it is heated from 30°C to 50°C?	null
2,712	a8bca831-6ddd-11ea-92cf-ccda262736ce	https://socratic.org/questions/what-is-the-molar-mass-of-a-gas-if-a-0-950-gram-sample-of-it-occupies-232-ml-at-	126 g/mol	start physical_unit 7 7 molar_mass g/mol qc_end physical_unit 7 7 10 11 mass qc_end physical_unit 7 7 16 17 volume qc_end physical_unit 7 7 19 20 temperature qc_end physical_unit 7 7 22 23 pressure qc_end end	[{"type":"physical unit","value":"Molar mass [OF] the gas sample [IN] g/mol"}]	[{"type":"physical unit","value":"126 g/mol"}]	[{"type":"physical unit","value":"Mass [OF] the gas sample [=] \\pu{0.950 gram}"},{"type":"physical unit","value":"Volume [OF] the gas sample [=] \\pu{232 mL}"},{"type":"physical unit","value":"Temperature [OF] the gas sample [=] \\pu{95 ℃}"},{"type":"physical unit","value":"Pressure [OF] the gas sample [=] \\pu{0.985 atm}"}]	<h1 class="questionTitle" itemprop="name">What is the molar mass of a gas if a 0.950 gram sample of it occupies 232 mL at 95 °C and 0.985 atm?</h1>	null	126 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First calculate the moles of the gas using the gas law, <mathjax>#PV=nRT#</mathjax>, where <mathjax>#n#</mathjax> is the moles and <mathjax>#R#</mathjax> is the gas constant. Then divide the given mass by the number of moles to get molar mass.</p> <p><strong>Calculate Moles</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#"mass":#</mathjax><mathjax>#"0.950 g"#</mathjax></p> <p><mathjax>#"pressure":#</mathjax><mathjax># P="0.985 atm"#</mathjax></p> <p><mathjax>#"volume":#</mathjax><mathjax># V=232 cancel"mL"xx(1"L")/(1000cancel"mL")="0.232 L"#</mathjax></p> <p><mathjax>#"gas constant":#</mathjax><mathjax>#R="0.082057338 L atm K"^(-1) "mol"^(-1)#</mathjax></p> <p><mathjax>#"temperature":#</mathjax><mathjax>#T=95^"o""C"+273.15="368 K"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#n#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(0.985cancel"atm"xx0.232cancel"L")/(0.082057338 cancel"L "cancel"atm"cancel"K"^(-1)cancel"mol"^(-1)xx368cancel"K")="0.007568 mol"#</mathjax></p> <p>(I'm keeping a couple of guard digits to reduce rounding errors. I'll round to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> at the end.)</p> <p><strong>Molar Mass of Gas</strong></p> <p>Molar mass<mathjax>#=#</mathjax><mathjax>#("grams")/("mol")#</mathjax></p> <p>Molar mass<mathjax>#=#</mathjax><mathjax>#(0.950"g")/(0.007568"mol")="126 g/mol"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of the gas is <mathjax>#"126 g/mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First calculate the moles of the gas using the gas law, <mathjax>#PV=nRT#</mathjax>, where <mathjax>#n#</mathjax> is the moles and <mathjax>#R#</mathjax> is the gas constant. Then divide the given mass by the number of moles to get molar mass.</p> <p><strong>Calculate Moles</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#"mass":#</mathjax><mathjax>#"0.950 g"#</mathjax></p> <p><mathjax>#"pressure":#</mathjax><mathjax># P="0.985 atm"#</mathjax></p> <p><mathjax>#"volume":#</mathjax><mathjax># V=232 cancel"mL"xx(1"L")/(1000cancel"mL")="0.232 L"#</mathjax></p> <p><mathjax>#"gas constant":#</mathjax><mathjax>#R="0.082057338 L atm K"^(-1) "mol"^(-1)#</mathjax></p> <p><mathjax>#"temperature":#</mathjax><mathjax>#T=95^"o""C"+273.15="368 K"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#n#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(0.985cancel"atm"xx0.232cancel"L")/(0.082057338 cancel"L "cancel"atm"cancel"K"^(-1)cancel"mol"^(-1)xx368cancel"K")="0.007568 mol"#</mathjax></p> <p>(I'm keeping a couple of guard digits to reduce rounding errors. I'll round to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> at the end.)</p> <p><strong>Molar Mass of Gas</strong></p> <p>Molar mass<mathjax>#=#</mathjax><mathjax>#("grams")/("mol")#</mathjax></p> <p>Molar mass<mathjax>#=#</mathjax><mathjax>#(0.950"g")/(0.007568"mol")="126 g/mol"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of a gas if a 0.950 gram sample of it occupies 232 mL at 95 °C and 0.985 atm?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="193226" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-26T07:25:20" itemprop="dateCreated"> Nov 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of the gas is <mathjax>#"126 g/mol"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First calculate the moles of the gas using the gas law, <mathjax>#PV=nRT#</mathjax>, where <mathjax>#n#</mathjax> is the moles and <mathjax>#R#</mathjax> is the gas constant. Then divide the given mass by the number of moles to get molar mass.</p> <p><strong>Calculate Moles</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#"mass":#</mathjax><mathjax>#"0.950 g"#</mathjax></p> <p><mathjax>#"pressure":#</mathjax><mathjax># P="0.985 atm"#</mathjax></p> <p><mathjax>#"volume":#</mathjax><mathjax># V=232 cancel"mL"xx(1"L")/(1000cancel"mL")="0.232 L"#</mathjax></p> <p><mathjax>#"gas constant":#</mathjax><mathjax>#R="0.082057338 L atm K"^(-1) "mol"^(-1)#</mathjax></p> <p><mathjax>#"temperature":#</mathjax><mathjax>#T=95^"o""C"+273.15="368 K"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#n#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(0.985cancel"atm"xx0.232cancel"L")/(0.082057338 cancel"L "cancel"atm"cancel"K"^(-1)cancel"mol"^(-1)xx368cancel"K")="0.007568 mol"#</mathjax></p> <p>(I'm keeping a couple of guard digits to reduce rounding errors. I'll round to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> at the end.)</p> <p><strong>Molar Mass of Gas</strong></p> <p>Molar mass<mathjax>#=#</mathjax><mathjax>#("grams")/("mol")#</mathjax></p> <p>Molar mass<mathjax>#=#</mathjax><mathjax>#(0.950"g")/(0.007568"mol")="126 g/mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193226" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 116124 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the molar mass of a gas if a 0.950 gram sample of it occupies 232 mL at 95 °C and 0.985 atm?	null
2,713	a872095a-6ddd-11ea-9570-ccda262736ce	https://socratic.org/questions/how-would-you-determine-the-oxidation-number-of-sulpher-in-so-3-2	+4	start physical_unit 8 10 oxidation_number none qc_end chemical_equation 10 10 qc_end end	[{"type":"physical unit","value":"Oxidation number [OF] Sulpher in SO3^2-"}]	[{"type":"physical unit","value":"+4"}]	[{"type":"chemical equation","value":"SO3^2-"}]	<h1 class="questionTitle" itemprop="name">How would you determine the oxidation number of Sulpher in #SO_3^-2#?</h1>	null	+4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a>/states of the individual <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the species must equal the charge on the ion. <mathjax>#O#</mathjax> normally takes a <mathjax>#-II#</mathjax> oxidation state and it does here.</p> <p>Thus <mathjax>#-2=3xx(-2)+ON_"sulfur"#</mathjax></p> <p>And so <mathjax>#ON_"sulfur"=-2+6=+4,#</mathjax> i.e. <mathjax>#+IV#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation state of sulfur in <mathjax>#SO_3^(2-)#</mathjax> is <mathjax>#+IV#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a>/states of the individual <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the species must equal the charge on the ion. <mathjax>#O#</mathjax> normally takes a <mathjax>#-II#</mathjax> oxidation state and it does here.</p> <p>Thus <mathjax>#-2=3xx(-2)+ON_"sulfur"#</mathjax></p> <p>And so <mathjax>#ON_"sulfur"=-2+6=+4,#</mathjax> i.e. <mathjax>#+IV#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you determine the oxidation number of Sulpher in #SO_3^-2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="280468" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-23T09:54:19" itemprop="dateCreated"> Jun 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation state of sulfur in <mathjax>#SO_3^(2-)#</mathjax> is <mathjax>#+IV#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a>/states of the individual <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the species must equal the charge on the ion. <mathjax>#O#</mathjax> normally takes a <mathjax>#-II#</mathjax> oxidation state and it does here.</p> <p>Thus <mathjax>#-2=3xx(-2)+ON_"sulfur"#</mathjax></p> <p>And so <mathjax>#ON_"sulfur"=-2+6=+4,#</mathjax> i.e. <mathjax>#+IV#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/280468" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1527 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you determine the oxidation number of Sulpher in #SO_3^-2#?	null
2,714	a90be607-6ddd-11ea-9c50-ccda262736ce	https://socratic.org/questions/what-is-molarity-of-a-solution-containing-7-g-of-naoh-in-500-ml-of-naoh-solution	0.35 M	start physical_unit 15 16 molarity mol/l qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 15 16 12 13 volume qc_end end	[{"type":"physical unit","value":"Molarity [OF] NaOH solution [IN] M"}]	[{"type":"physical unit","value":"0.35 M"}]	[{"type":"physical unit","value":"Mass [OF] NaOH [=] \\pu{7 g}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{500 mL}"}]	<h1 class="questionTitle" itemprop="name">What is molarity of a solution containing 7 g of NaOH in 500 mL of NaOH solution? </h1>	null	0.35 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case is sodium hydroxide, <mathjax>#"NaOH"#</mathjax>, divided by <em>liters of solution</em>. </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>Notice that the problem provides you with the volume of the solution, but that the volume is expressed in <em>milliliters</em>, <mathjax>#"mL"#</mathjax>. </p> <p>Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to </p> <ul> <li><em>determine how many moles of sodium hydroxide you have in that many grams</em></li> <li><em>convert the volume of the solution from milliliters to liters</em></li> </ul> <p>So, to get the number of moles of solute, use sodium hydroxide's <strong>molar mass</strong>, which tells you what the mass of <strong>one mole</strong> of sodium hydroxide is. </p> <blockquote> <p><mathjax>#7color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(40.0color(red)(cancel(color(black)("g")))) = "0.175 moles NaOH"#</mathjax></p> </blockquote> <p>The volume of the solution in liters will be </p> <blockquote> <p><mathjax>#500color(red)(cancel(color(black)("mL"))) * "1 L"/(1000color(red)(cancel(color(black)("mL")))) = "0.5 L"#</mathjax></p> </blockquote> <p>Therefore, the molarity of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(c = n/V)#</mathjax></p> <p><mathjax>#c = "0.175 moles"/"0.5 L" = "0.35 M"#</mathjax></p> </blockquote> <p>Rounded to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the answer will be </p> <blockquote> <p><mathjax>#c = color(green)("0.4 M")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.4 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case is sodium hydroxide, <mathjax>#"NaOH"#</mathjax>, divided by <em>liters of solution</em>. </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>Notice that the problem provides you with the volume of the solution, but that the volume is expressed in <em>milliliters</em>, <mathjax>#"mL"#</mathjax>. </p> <p>Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to </p> <ul> <li><em>determine how many moles of sodium hydroxide you have in that many grams</em></li> <li><em>convert the volume of the solution from milliliters to liters</em></li> </ul> <p>So, to get the number of moles of solute, use sodium hydroxide's <strong>molar mass</strong>, which tells you what the mass of <strong>one mole</strong> of sodium hydroxide is. </p> <blockquote> <p><mathjax>#7color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(40.0color(red)(cancel(color(black)("g")))) = "0.175 moles NaOH"#</mathjax></p> </blockquote> <p>The volume of the solution in liters will be </p> <blockquote> <p><mathjax>#500color(red)(cancel(color(black)("mL"))) * "1 L"/(1000color(red)(cancel(color(black)("mL")))) = "0.5 L"#</mathjax></p> </blockquote> <p>Therefore, the molarity of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(c = n/V)#</mathjax></p> <p><mathjax>#c = "0.175 moles"/"0.5 L" = "0.35 M"#</mathjax></p> </blockquote> <p>Rounded to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the answer will be </p> <blockquote> <p><mathjax>#c = color(green)("0.4 M")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is molarity of a solution containing 7 g of NaOH in 500 mL of NaOH solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192695" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-24T19:21:51" itemprop="dateCreated"> Nov 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.4 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is defined as <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em>, which in your case is sodium hydroxide, <mathjax>#"NaOH"#</mathjax>, divided by <em>liters of solution</em>. </p> <blockquote> <p><mathjax>#color(blue)("molarity" = "moles of solute"/"liters of solution")#</mathjax></p> </blockquote> <p>Notice that the problem provides you with the volume of the solution, but that the volume is expressed in <em>milliliters</em>, <mathjax>#"mL"#</mathjax>. </p> <p>Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to </p> <ul> <li><em>determine how many moles of sodium hydroxide you have in that many grams</em></li> <li><em>convert the volume of the solution from milliliters to liters</em></li> </ul> <p>So, to get the number of moles of solute, use sodium hydroxide's <strong>molar mass</strong>, which tells you what the mass of <strong>one mole</strong> of sodium hydroxide is. </p> <blockquote> <p><mathjax>#7color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(40.0color(red)(cancel(color(black)("g")))) = "0.175 moles NaOH"#</mathjax></p> </blockquote> <p>The volume of the solution in liters will be </p> <blockquote> <p><mathjax>#500color(red)(cancel(color(black)("mL"))) * "1 L"/(1000color(red)(cancel(color(black)("mL")))) = "0.5 L"#</mathjax></p> </blockquote> <p>Therefore, the molarity of the solution will be </p> <blockquote> <p><mathjax>#color(blue)(c = n/V)#</mathjax></p> <p><mathjax>#c = "0.175 moles"/"0.5 L" = "0.35 M"#</mathjax></p> </blockquote> <p>Rounded to one <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the answer will be </p> <blockquote> <p><mathjax>#c = color(green)("0.4 M")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192695" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 112631 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is molarity of a solution containing 7 g of NaOH in 500 mL of NaOH solution?	null
2,715	ac490087-6ddd-11ea-9f37-ccda262736ce	https://socratic.org/questions/at-what-temperature-in-celsius-will-19-4-g-of-molecular-ozone-exert-a-pressure-o	96.85 Celsius	start physical_unit 9 10 temperature °c qc_end physical_unit 9 10 6 7 mass qc_end physical_unit 9 10 15 16 pressure qc_end physical_unit 9 10 19 20 volume qc_end end	[{"type":"physical unit","value":"Temperature [OF] molecular Ozone [IN] Celsius"}]	[{"type":"physical unit","value":"96.85 Celsius"}]	[{"type":"physical unit","value":"Mass [OF] molecular Ozone [=] \\pu{19.4 g}"},{"type":"physical unit","value":"Pressure [OF] molecular Ozone [=] \\pu{1820 mmHg}"},{"type":"physical unit","value":"Volume [OF] molecular Ozone [=] \\pu{5.12 L}"}]	<h1 class="questionTitle" itemprop="name">At what temperature in Celsius will 19.4 g of molecular Ozone exert a pressure of 1820 mmHg in a 5.12 L cylinder?</h1>	null	96.85 Celsius	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ozone = <mathjax>#19.4#</mathjax>g<br/> Molar mass = <mathjax>#48#</mathjax> g/mol<br/> No. of moles = <mathjax>#19.4#</mathjax> g/<mathjax>#48#</mathjax>g.mol-1 = <mathjax>#0.4041#</mathjax> moles<br/> Pressure = <mathjax>#1820#</mathjax> mmHg<br/> P = <mathjax>#1820#</mathjax> mmHg/<mathjax>#760#</mathjax> mm Hg = 2.39 atm<br/> Volume = 5.12 L<br/> R = 0.08206 atm.L.K-1.mol-1<br/> According to ideal gas law<br/> <mathjax>#PV#</mathjax> = <mathjax>#nRT#</mathjax><br/> <mathjax>#T#</mathjax> = <mathjax>#PV#</mathjax>/<mathjax>#nR#</mathjax></p> <p><mathjax>#T#</mathjax> = (<mathjax>#2.39 atm#</mathjax> x <mathjax>#5.12L#</mathjax>) / (<mathjax>#0.4041#</mathjax> moles x <mathjax>#0.08206 atm.L.K-1.mol-1#</mathjax>)</p> <p><mathjax>#T#</mathjax> = <mathjax>#369#</mathjax> K</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T#</mathjax> = <mathjax>#369#</mathjax> K</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ozone = <mathjax>#19.4#</mathjax>g<br/> Molar mass = <mathjax>#48#</mathjax> g/mol<br/> No. of moles = <mathjax>#19.4#</mathjax> g/<mathjax>#48#</mathjax>g.mol-1 = <mathjax>#0.4041#</mathjax> moles<br/> Pressure = <mathjax>#1820#</mathjax> mmHg<br/> P = <mathjax>#1820#</mathjax> mmHg/<mathjax>#760#</mathjax> mm Hg = 2.39 atm<br/> Volume = 5.12 L<br/> R = 0.08206 atm.L.K-1.mol-1<br/> According to ideal gas law<br/> <mathjax>#PV#</mathjax> = <mathjax>#nRT#</mathjax><br/> <mathjax>#T#</mathjax> = <mathjax>#PV#</mathjax>/<mathjax>#nR#</mathjax></p> <p><mathjax>#T#</mathjax> = (<mathjax>#2.39 atm#</mathjax> x <mathjax>#5.12L#</mathjax>) / (<mathjax>#0.4041#</mathjax> moles x <mathjax>#0.08206 atm.L.K-1.mol-1#</mathjax>)</p> <p><mathjax>#T#</mathjax> = <mathjax>#369#</mathjax> K</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">At what temperature in Celsius will 19.4 g of molecular Ozone exert a pressure of 1820 mmHg in a 5.12 L cylinder?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="462680" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sarita-rana"><img alt="" class="" src="https://profilepictures.socratic.org/tvT08VaORGyEZTsSaNA4_images.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sarita-rana"> Sarita Rana </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T05:12:52" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T#</mathjax> = <mathjax>#369#</mathjax> K</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ozone = <mathjax>#19.4#</mathjax>g<br/> Molar mass = <mathjax>#48#</mathjax> g/mol<br/> No. of moles = <mathjax>#19.4#</mathjax> g/<mathjax>#48#</mathjax>g.mol-1 = <mathjax>#0.4041#</mathjax> moles<br/> Pressure = <mathjax>#1820#</mathjax> mmHg<br/> P = <mathjax>#1820#</mathjax> mmHg/<mathjax>#760#</mathjax> mm Hg = 2.39 atm<br/> Volume = 5.12 L<br/> R = 0.08206 atm.L.K-1.mol-1<br/> According to ideal gas law<br/> <mathjax>#PV#</mathjax> = <mathjax>#nRT#</mathjax><br/> <mathjax>#T#</mathjax> = <mathjax>#PV#</mathjax>/<mathjax>#nR#</mathjax></p> <p><mathjax>#T#</mathjax> = (<mathjax>#2.39 atm#</mathjax> x <mathjax>#5.12L#</mathjax>) / (<mathjax>#0.4041#</mathjax> moles x <mathjax>#0.08206 atm.L.K-1.mol-1#</mathjax>)</p> <p><mathjax>#T#</mathjax> = <mathjax>#369#</mathjax> K</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462680" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="462686" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T05:55:16" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The temperature in degrees Celsius is <mathjax>#97^@"C"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> in order to answer this question. The formula is:</p> <p><mathjax>#PV=nRT#</mathjax>, </p> <p>where P is pressure, V is volume, n is moles, R is the gas constant, and T is temperature in Kelvins.</p> <p><strong>Determine Moles <mathjax>#"O"_3#</mathjax></strong></p> <p>In order to determine the moles of molecular ozone <mathjax>#("O"_3")#</mathjax>, you need to divide its given mass by its molar mass (g/mol), which is <mathjax>#"47.9997 g/mol O"_3")#</mathjax>. To do this, multiply the given mass by the inverse of the molar mass (mol/g).</p> <p><a href="https://www.ncbi.nlm.nih.gov/pccompound?term=ozone" rel="nofollow" target="_blank">https://www.ncbi.nlm.nih.gov/pccompound?term=ozone</a></p> <p><mathjax>#19.4color(red)cancel(color(black)("g O"_3))xx(1"mol O"_3)/(47.997color(red)cancel(color(black)("g O"_3)))="0.404 mol O"_3#</mathjax> to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a></p> <p><strong>Gas Constant, <mathjax>#R#</mathjax></strong></p> <p>The gas constant is determined by the units used in the question. The pressure is in mmHg, the volume is in liters (L), the quantity is in moles (n), and the temperature is in Kelvins (K).</p> <p><mathjax>#R=62.363577 LmmHgK^(-1)mol^(-1)#</mathjax></p> <p><a href="https://en.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Gas_constant</a> (1 Torr=1 mmHg)</p> <p><strong>Organize the data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#P="1820 mmHg"#</mathjax></p> <p><mathjax>#V="5.12 L"#</mathjax></p> <p><mathjax>#n="0.404 mol"#</mathjax></p> <p><mathjax>#R=62.363577 LmmHgK^(-1)mol^(-1)#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#T#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#T#</mathjax>. Insert the data into the new equation and solve.</p> <p><mathjax>#T=(PV)/(nR)#</mathjax></p> <p><mathjax>#T=((1820color(red)cancel(color(black)("mmHg")))xx(5.12color(red)cancel(color(black)("L"))))/((0.404color(red)cancel(color(black)("mol")))xx(62.363577 color(red)cancel(color(black)(L))color(red)cancel(color(black)(mmHg))K^(-1)*color(red)cancel(color(black)(mol^(-1))))="370. K"#</mathjax> or <mathjax>#3.70xx10^2 "K"#</mathjax> (rounded to three significant figures)</p> <p><strong>Convert Temperature from Kelvins to degrees Celsius</strong></p> <p>Subtract <mathjax>#273.15#</mathjax> from <mathjax>#370^@"C"#</mathjax>.</p> <p><mathjax>#"370 K"-"273.15"=97^@"C"#</mathjax> (rounded to a whole number)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462686" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11600 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	At what temperature in Celsius will 19.4 g of molecular Ozone exert a pressure of 1820 mmHg in a 5.12 L cylinder?	null
2,716	a8bf8d76-6ddd-11ea-bc0e-ccda262736ce	https://socratic.org/questions/how-many-moles-of-solute-particles-are-present-in-1-ml-exact-of-aqueous-0-033-m-	3.3 × 10^(− 5) moles	start physical_unit 4 5 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] solute particles [IN] moles"}]	[{"type":"physical unit","value":"3.3 × 10^(− 5) moles"}]	[{"type":"physical unit","value":"Molarity [OF] C5H5N aqueous [=] \\pu{0.033 M}"},{"type":"physical unit","value":"Volume [OF] C5H5N aqueous [=] \\pu{1 mL}"}]	<h1 class="questionTitle" itemprop="name">How many moles of solute particles are present in 1 mL (exact) of aqueous 0.033 M pyridine #C_5H_5N#?</h1>	null	3.3 × 10^(− 5) moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <blockquote> <p><mathjax>#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#"n = Molarity × Volume"#</mathjax></p> <p><mathjax>#"n = 0.033 M × 1 mL"#</mathjax></p> <p><mathjax>#"n" = 0.033 "mol"/cancel"L" × 10^-3 cancel"L" color(white)(..)[∵ "M = mol/L & 1 mL" = 10^-3\ "L"]#</mathjax></p> <p><mathjax>#"n" = 3.3 × 10^-5\ "mol"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.3 × 10^-5\ "moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <blockquote> <p><mathjax>#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#"n = Molarity × Volume"#</mathjax></p> <p><mathjax>#"n = 0.033 M × 1 mL"#</mathjax></p> <p><mathjax>#"n" = 0.033 "mol"/cancel"L" × 10^-3 cancel"L" color(white)(..)[∵ "M = mol/L & 1 mL" = 10^-3\ "L"]#</mathjax></p> <p><mathjax>#"n" = 3.3 × 10^-5\ "mol"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of solute particles are present in 1 mL (exact) of aqueous 0.033 M pyridine #C_5H_5N#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="584355" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-29T01:00:37" itemprop="dateCreated"> Mar 29, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.3 × 10^-5\ "moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote> <blockquote> <p><mathjax>#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#"n = Molarity × Volume"#</mathjax></p> <p><mathjax>#"n = 0.033 M × 1 mL"#</mathjax></p> <p><mathjax>#"n" = 0.033 "mol"/cancel"L" × 10^-3 cancel"L" color(white)(..)[∵ "M = mol/L & 1 mL" = 10^-3\ "L"]#</mathjax></p> <p><mathjax>#"n" = 3.3 × 10^-5\ "mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/584355" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a 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2,717	acd557c1-6ddd-11ea-a5b5-ccda262736ce	https://socratic.org/questions/how-many-moles-of-n-2-are-formed-by-the-decomposition-of-2-5-moles-of-nan-3	3.75 moles	start physical_unit 4 4 mole mol qc_end physical_unit 14 14 11 12 mole qc_end end	[{"type":"physical unit","value":"Mole [OF] N2 [IN] moles"}]	[{"type":"physical unit","value":"3.75 moles"}]	[{"type":"physical unit","value":"Mole [OF] NaN3 [=] \\pu{2.5 moles}"}]	<h1 class="questionTitle" itemprop="name">How many moles of #N_2# are formed by the decomposition of 2.5 moles of #NaN_3#?</h1>	null	3.75 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The decomposition reaction of sodium azide <mathjax>#NaN_3#</mathjax> is:</p> <p><mathjax>#2NaN_3(s)->2Na(s)+3N_2(g)#</mathjax></p> <p>Using dimensional analysis, we can find the number of mole of <mathjax>#N_2#</mathjax> gas formed:</p> <p><mathjax>#?molN_2(g)=2.5cancel(mol NaN_3)xx(3molN_2)/(2cancel(molNaN_3))=3.75molN_2#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.75molN_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The decomposition reaction of sodium azide <mathjax>#NaN_3#</mathjax> is:</p> <p><mathjax>#2NaN_3(s)->2Na(s)+3N_2(g)#</mathjax></p> <p>Using dimensional analysis, we can find the number of mole of <mathjax>#N_2#</mathjax> gas formed:</p> <p><mathjax>#?molN_2(g)=2.5cancel(mol NaN_3)xx(3molN_2)/(2cancel(molNaN_3))=3.75molN_2#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of #N_2# are formed by the decomposition of 2.5 moles of #NaN_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/decomposition-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Decomposition Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="227229" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-16T19:40:56" itemprop="dateCreated"> Feb 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.75molN_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The decomposition reaction of sodium azide <mathjax>#NaN_3#</mathjax> is:</p> <p><mathjax>#2NaN_3(s)->2Na(s)+3N_2(g)#</mathjax></p> <p>Using dimensional analysis, we can find the number of mole of <mathjax>#N_2#</mathjax> gas formed:</p> <p><mathjax>#?molN_2(g)=2.5cancel(mol NaN_3)xx(3molN_2)/(2cancel(molNaN_3))=3.75molN_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/227229" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="227232" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdul-s-1"><img alt="" class="" src="https://lh6.googleusercontent.com/-W8XMY2yP-hM/AAAAAAAAAAI/AAAAAAAAABg/XwBa66Uif8k/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdul-s-1"> Abdul Sammad </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-16T19:44:03" itemprop="dateCreated"> Feb 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5.8 mols#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>first multiply the mols with the mr <mathjax>#65*2.5=162.5#</mathjax> <br/> then use this to get the mols of <mathjax>#N_2#</mathjax> <br/> <mathjax>#mols=162.5/28#</mathjax><br/> <mathjax>#mols=5.8#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/227232" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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class="relatedQuestionLink" href="/questions/do-chlorates-decompose-when-heated"> Do chlorates decompose when heated? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/decomposition-reactions"> See all questions in Decomposition Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6381 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles of #N_2# are formed by the decomposition of 2.5 moles of #NaN_3#?	null
2,718	a95c3bbb-6ddd-11ea-803e-ccda262736ce	https://socratic.org/questions/57df4659b72cff1623806bd7	3.16 × 10^24	start physical_unit 2 3 number none qc_end physical_unit 2 2 8 9 mass qc_end end	[{"type":"physical unit","value":"Number [OF] silver atoms"}]	[{"type":"physical unit","value":"3.16 × 10^24"}]	[{"type":"physical unit","value":"Mass [OF] silver [=] \\pu{0.566 kg}"}]	<h1 class="questionTitle" itemprop="name">How many silver atoms are there in a #0.566*kg# mass of silver?</h1>	null	3.16 × 10^24	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know (or should know) that the formula mass of silver is <mathjax>#107.87gmol^-1#</mathjax>. How did I know this? Did I know it off the top of my head? How will you know this if you are asked the question in an exam?</p> <p>Now <mathjax>#1#</mathjax> <mathjax>#"mole"#</mathjax> of silver atoms or in a <mathjax>#107.87g#</mathjax> mass, there are, by definition, <mathjax>#6.022xx10^23#</mathjax> <mathjax>#"individual atoms of silver."#</mathjax></p> <p>So all I have to do to get the number of silver atoms, is (i) calculate the molar quantity, and (ii) multiply this molar quantity by <mathjax>#6.022xx10^23mol^-1#</mathjax>, i.e. <mathjax>#"Avogadro's number"#</mathjax>.</p> <p>So.......</p> <p><mathjax>#(0.566xx10^3g)/(107.87gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5.25mol#</mathjax>.</p> <p>And <mathjax>#5.25molxx6.022xx10^23mol^-1#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#30xx10^23" silver atoms"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.566kg#</mathjax> of silver <mathjax>#~=#</mathjax> <mathjax>#30xx10^23" silver atoms"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know (or should know) that the formula mass of silver is <mathjax>#107.87gmol^-1#</mathjax>. How did I know this? Did I know it off the top of my head? How will you know this if you are asked the question in an exam?</p> <p>Now <mathjax>#1#</mathjax> <mathjax>#"mole"#</mathjax> of silver atoms or in a <mathjax>#107.87g#</mathjax> mass, there are, by definition, <mathjax>#6.022xx10^23#</mathjax> <mathjax>#"individual atoms of silver."#</mathjax></p> <p>So all I have to do to get the number of silver atoms, is (i) calculate the molar quantity, and (ii) multiply this molar quantity by <mathjax>#6.022xx10^23mol^-1#</mathjax>, i.e. <mathjax>#"Avogadro's number"#</mathjax>.</p> <p>So.......</p> <p><mathjax>#(0.566xx10^3g)/(107.87gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5.25mol#</mathjax>.</p> <p>And <mathjax>#5.25molxx6.022xx10^23*mol^-1#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#30xx10^23" silver atoms"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many silver atoms are there in a #0.566kg# mass of silver?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="319635" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-09T10:01:38" itemprop="dateCreated"> Oct 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.566kg#</mathjax> of silver <mathjax>#~=#</mathjax> <mathjax>#30xx10^23" silver atoms"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know (or should know) that the formula mass of silver is <mathjax>#107.87gmol^-1#</mathjax>. How did I know this? Did I know it off the top of my head? How will you know this if you are asked the question in an exam?</p> <p>Now <mathjax>#1#</mathjax> <mathjax>#"mole"#</mathjax> of silver atoms or in a <mathjax>#107.87g#</mathjax> mass, there are, by definition, <mathjax>#6.022xx10^23#</mathjax> <mathjax>#"individual atoms of silver."#</mathjax></p> <p>So all I have to do to get the number of silver atoms, is (i) calculate the molar quantity, and (ii) multiply this molar quantity by <mathjax>#6.022xx10^23mol^-1#</mathjax>, i.e. <mathjax>#"Avogadro's number"#</mathjax>.</p> <p>So.......</p> <p><mathjax>#(0.566xx10^3g)/(107.87gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5.25mol#</mathjax>.</p> <p>And <mathjax>#5.25molxx6.022xx10^23mol^-1#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#30xx10^23" silver atoms"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/319635" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5259 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many silver atoms are there in a #0.566*kg# mass of silver?	null
2,719	a9a628f6-6ddd-11ea-801b-ccda262736ce	https://socratic.org/questions/if-the-activation-energy-for-a-given-compound-is-found-to-be-42-0-kj-mol-with-a-	3.48 × 10^3	start physical_unit 29 30 reaction_rate_constant none qc_end physical_unit 5 7 12 13 activation_barrier qc_end physical_unit 29 30 19 22 pre-exponential_factor qc_end physical_unit 29 30 32 33 temperature qc_end end	[{"type":"physical unit","value":"Rate constant [OF] this reaction"}]	[{"type":"physical unit","value":"3.48 × 10^3"}]	[{"type":"physical unit","value":"Activation energy [OF] a given compound [=] \\pu{42.0 kJ/mol}"},{"type":"physical unit","value":"Frequency factor [OF] this reaction [=] \\pu{8.0 × 10^10 s^(−1)}"},{"type":"physical unit","value":"Temperature [OF] this reaction [=] \\pu{298 K}"}]	<h1 class="questionTitle" itemprop="name">If the activation energy for a given compound is found to be 42.0 kJ/mol, with a frequency factor of #8.0 x 10^10 s^(-1)#, what is the rate constant for this reaction at 298 K?</h1>	null	3.48 × 10^3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Rate constant can be calculated from Arrhenius equation</p> <blockquote> <blockquote> <p><mathjax>#k = A xx e^(-E_a/(RT))#</mathjax></p> </blockquote> </blockquote> <p>Where,</p> <blockquote> <p>k = Rate constant</p> <p>A = Frequency factor</p> <p><mathjax>#E_a#</mathjax> = Activation energy</p> <p>R = Gas constant</p> <p>T = Absolute Temperature</p> </blockquote> <p><mathjax>#k = 8.0 xx 10^10 s^-1 × e^-("42.0 kJ/mol × 1000 J/kJ"/("8.314 J/(mol K) × 298 K")) = 3.48 × 10^3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.48 × 10^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Rate constant can be calculated from Arrhenius equation</p> <blockquote> <blockquote> <p><mathjax>#k = A xx e^(-E_a/(RT))#</mathjax></p> </blockquote> </blockquote> <p>Where,</p> <blockquote> <p>k = Rate constant</p> <p>A = Frequency factor</p> <p><mathjax>#E_a#</mathjax> = Activation energy</p> <p>R = Gas constant</p> <p>T = Absolute Temperature</p> </blockquote> <p><mathjax>#k = 8.0 xx 10^10 s^-1 × e^-("42.0 kJ/mol × 1000 J/kJ"/("8.314 J/(mol K) × 298 K")) = 3.48 × 10^3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If the activation energy for a given compound is found to be 42.0 kJ/mol, with a frequency factor of #8.0 x 10^10 s^(-1)#, what is the rate constant for this reaction at 298 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-kinetics" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Kinetics</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-kinetics/rate-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Rate Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="541477" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-26T09:48:40" itemprop="dateCreated"> Jan 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.48 × 10^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Rate constant can be calculated from Arrhenius equation</p> <blockquote> <blockquote> <p><mathjax>#k = A xx e^(-E_a/(RT))#</mathjax></p> </blockquote> </blockquote> <p>Where,</p> <blockquote> <p>k = Rate constant</p> <p>A = Frequency factor</p> <p><mathjax>#E_a#</mathjax> = Activation energy</p> <p>R = Gas constant</p> <p>T = Absolute Temperature</p> </blockquote> <p><mathjax>#k = 8.0 xx 10^10 s^-1 × e^-("42.0 kJ/mol × 1000 J/kJ"/("8.314 J/(mol K) × 298 K")) = 3.48 × 10^3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/541477" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-catalysts-affect-rates-of-reaction"> How do catalysts affect rates of reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-enzymes-speed-up-rates-of-reaction"> How do enzymes speed up rates of 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clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 45968 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If the activation energy for a given compound is found to be 42.0 kJ/mol, with a frequency factor of #8.0 x 10^10 s^(-1)#, what is the rate constant for this reaction at 298 K?	null
2,720	aab8b4fa-6ddd-11ea-8123-ccda262736ce	https://socratic.org/questions/what-is-the-theoretical-yield-of-solid-product-when-25-5-ml-of-0-150-m-lead-ii-n	3.83 × 10^(-3) mol	start physical_unit 6 7 theoretical_yield mol qc_end physical_unit 14 16 12 13 molarity qc_end physical_unit 25 25 23 24 molarity qc_end end	[{"type":"physical unit","value":"Theoretical yield [OF] solid product [IN] mol"}]	[{"type":"physical unit","value":"3.83 × 10^(-3) mol"}]	[{"type":"physical unit","value":"Volume [OF] lead (II) nitrate solution [=] \\pu{25.5 ml}"},{"type":"physical unit","value":"Molarity [OF] lead (II) nitrate solution [=] \\pu{0.150 M}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{30.0 ml}"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.200 M}"}]	<h1 class="questionTitle" itemprop="name">What is the theoretical yield of solid product when 25.5 ml of 0.150 M lead (II) nitrate is mixed with 30.0 ml of 0.200 M NaOH? </h1>	null	3.83 × 10^(-3) mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have the stoichiometric reaction above. I also happen to know that hydroxides are generally insoluble (hence I can predict that the lead hydroxide will precipitate).</p> <p>We can find the molar quantities of each reagent. <mathjax>#Pb(NO_3)_2#</mathjax>: <mathjax>#25.5xx10^(-3)Lxx0.150molL^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>.</p> <p><mathjax>#NaOH#</mathjax>: <mathjax>#30.0xx10^(-3)Lxx0.200molL^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>. Remember that quantitative precipitation of the lead hydroxide requires <mathjax>#2#</mathjax> equivs of hydroxide, as the equation specifies.</p> <p>I could rewrite the solubility reaction as a net ionic equation by removing the aqueous species:</p> <p><mathjax>#Pb^(2+) + 2OH^(-) rarr Pb(OH)_2(s)darr#</mathjax></p> <p>The sodium and nitrate ions will remain in solution, and are just along for the ride.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Pb(NO_3)_2(aq) + 2NaOH rarr Pb(OH)_2(s)darr + 2NaNO_3(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have the stoichiometric reaction above. I also happen to know that hydroxides are generally insoluble (hence I can predict that the lead hydroxide will precipitate).</p> <p>We can find the molar quantities of each reagent. <mathjax>#Pb(NO_3)_2#</mathjax>: <mathjax>#25.5xx10^(-3)Lxx0.150molL^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>.</p> <p><mathjax>#NaOH#</mathjax>: <mathjax>#30.0xx10^(-3)Lxx0.200molL^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>. Remember that quantitative precipitation of the lead hydroxide requires <mathjax>#2#</mathjax> equivs of hydroxide, as the equation specifies.</p> <p>I could rewrite the solubility reaction as a net ionic equation by removing the aqueous species:</p> <p><mathjax>#Pb^(2+) + 2OH^(-) rarr Pb(OH)_2(s)darr#</mathjax></p> <p>The sodium and nitrate ions will remain in solution, and are just along for the ride.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the theoretical yield of solid product when 25.5 ml of 0.150 M lead (II) nitrate is mixed with 30.0 ml of 0.200 M NaOH? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="187576" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-12T20:52:19" itemprop="dateCreated"> Nov 12, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Pb(NO_3)_2(aq) + 2NaOH rarr Pb(OH)_2(s)darr + 2NaNO_3(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have the stoichiometric reaction above. I also happen to know that hydroxides are generally insoluble (hence I can predict that the lead hydroxide will precipitate).</p> <p>We can find the molar quantities of each reagent. <mathjax>#Pb(NO_3)_2#</mathjax>: <mathjax>#25.5xx10^(-3)Lxx0.150molL^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>.</p> <p><mathjax>#NaOH#</mathjax>: <mathjax>#30.0xx10^(-3)Lxx0.200molL^(-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>. Remember that quantitative precipitation of the lead hydroxide requires <mathjax>#2#</mathjax> equivs of hydroxide, as the equation specifies.</p> <p>I could rewrite the solubility reaction as a net ionic equation by removing the aqueous species:</p> <p><mathjax>#Pb^(2+) + 2OH^(-) rarr Pb(OH)_2(s)darr#</mathjax></p> <p>The sodium and nitrate ions will remain in solution, and are just along for the ride.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187576" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1810 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the theoretical yield of solid product when 25.5 ml of 0.150 M lead (II) nitrate is mixed with 30.0 ml of 0.200 M NaOH?	null
2,721	a9a1d95a-6ddd-11ea-8ec4-ccda262736ce	https://socratic.org/questions/the-poh-of-a-solution-is-10-75-what-is-the-concentration-of-oh-ions-in-the-solut	1.78 × 10^(-11) M	start physical_unit 12 13 concentration mol/l qc_end physical_unit 15 16 6 6 poh qc_end end	[{"type":"physical unit","value":"Concentration [OF] OH- ions [IN] M"}]	[{"type":"physical unit","value":"1.78 × 10^(-11) M"}]	[{"type":"physical unit","value":"pOH [OF] the solution [=] \\pu{10.75}"}]	<h1 class="questionTitle" itemprop="name">The pOH of a solution is 10.75. What is the concentration of #OH^-# ions in the solution?</h1>	null	1.78 × 10^(-11) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH#</mathjax> is defined the same way as <mathjax>#pH#</mathjax>, except that here we address hydroxide ion concentration, i.e. <mathjax>#pOH=-log_10[HO^-]#</mathjax>......and thus <mathjax>#[HO^-]=10^(-pOH)=10^(-10.75)#</mathjax>.</p> <p>Remember that since <mathjax>#pK_w=pH+pOH#</mathjax></p> <p><mathjax>#-log_(10)10^-14=-log_(10)[H_3O^+]-log_10[HO^-]#</mathjax></p> <p><mathjax>#-(-14)=pH+ pOH= 14#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]=10^(-10.75)=1.78xx10^-11molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH#</mathjax> is defined the same way as <mathjax>#pH#</mathjax>, except that here we address hydroxide ion concentration, i.e. <mathjax>#pOH=-log_10[HO^-]#</mathjax>......and thus <mathjax>#[HO^-]=10^(-pOH)=10^(-10.75)#</mathjax>.</p> <p>Remember that since <mathjax>#pK_w=pH+pOH#</mathjax></p> <p><mathjax>#-log_(10)10^-14=-log_(10)[H_3O^+]-log_10[HO^-]#</mathjax></p> <p><mathjax>#-(-14)=pH+ pOH= 14#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pOH of a solution is 10.75. What is the concentration of #OH^-# ions in the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="381090" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-21T19:52:31" itemprop="dateCreated"> Feb 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]=10^(-10.75)=1.78xx10^-11molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH#</mathjax> is defined the same way as <mathjax>#pH#</mathjax>, except that here we address hydroxide ion concentration, i.e. <mathjax>#pOH=-log_10[HO^-]#</mathjax>......and thus <mathjax>#[HO^-]=10^(-pOH)=10^(-10.75)#</mathjax>.</p> <p>Remember that since <mathjax>#pK_w=pH+pOH#</mathjax></p> <p><mathjax>#-log_(10)10^-14=-log_(10)[H_3O^+]-log_10[HO^-]#</mathjax></p> <p><mathjax>#-(-14)=pH+ pOH= 14#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/381090" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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What is the concentration of #OH^-# ions in the solution?	null
2,722	aae73c41-6ddd-11ea-9835-ccda262736ce	https://socratic.org/questions/599e428b11ef6b2dead71ac4	332.93 grams	start physical_unit 7 7 mass g qc_end physical_unit 12 13 10 11 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] CaCl2 [IN] grams"}]	[{"type":"physical unit","value":"332.93 grams"}]	[{"type":"physical unit","value":"Molarity [OF] CaCl2 solution [=] \\pu{3 M}"}]	<h1 class="questionTitle" itemprop="name">What is the mass in grams of #"CaCl"_2"# in a #"3 M CaCl"_2"# solution?</h1>	null	332.93 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"=("mol solute")/("liter of solution")#</mathjax></p> <p>A 3 M solution of calcium chloride contains 3 moles of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <mathjax>#"CaCl"_2#</mathjax> in one liter of solution. To convert 3 mol <mathjax>#"CaCl"_2#</mathjax> to mass in grams, multiply the given moles by the molar mass: <mathjax>#"110.978 g/mol"#</mathjax>. </p> <p><mathjax>#3color(red)cancel(color(black)("mol CaCl"_2))xx(110.978"g CaCl"_2)/(1color(red)cancel(color(black)("mol CaCl"_2)))="300 g CaCl"_2"#</mathjax> (rounded to one significant figure due to 3 mol)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"300 g CaCl"_2"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"=("mol solute")/("liter of solution")#</mathjax></p> <p>A 3 M solution of calcium chloride contains 3 moles of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <mathjax>#"CaCl"_2#</mathjax> in one liter of solution. To convert 3 mol <mathjax>#"CaCl"_2#</mathjax> to mass in grams, multiply the given moles by the molar mass: <mathjax>#"110.978 g/mol"#</mathjax>. </p> <p><mathjax>#3color(red)cancel(color(black)("mol CaCl"_2))xx(110.978"g CaCl"_2)/(1color(red)cancel(color(black)("mol CaCl"_2)))="300 g CaCl"_2"#</mathjax> (rounded to one significant figure due to 3 mol)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass in grams of #"CaCl"_2"# in a #"3 M CaCl"_2"# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="467526" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-24T03:22:30" itemprop="dateCreated"> Aug 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"300 g CaCl"_2"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"=("mol solute")/("liter of solution")#</mathjax></p> <p>A 3 M solution of calcium chloride contains 3 moles of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> <mathjax>#"CaCl"_2#</mathjax> in one liter of solution. To convert 3 mol <mathjax>#"CaCl"_2#</mathjax> to mass in grams, multiply the given moles by the molar mass: <mathjax>#"110.978 g/mol"#</mathjax>. </p> <p><mathjax>#3color(red)cancel(color(black)("mol CaCl"_2))xx(110.978"g CaCl"_2)/(1color(red)cancel(color(black)("mol CaCl"_2)))="300 g CaCl"_2"#</mathjax> (rounded to one significant figure due to 3 mol)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/467526" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1315 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass in grams of #"CaCl"_2"# in a #"3 M CaCl"_2"# solution?	null
2,723	acc17614-6ddd-11ea-9cc1-ccda262736ce	https://socratic.org/questions/a-gas-occupies-3-litres-at-0-c-what-volume-will-it-occupy-at-20-c-assuming-press	2.78 L	start physical_unit 1 1 volume l qc_end physical_unit 1 1 3 4 volume qc_end physical_unit 1 1 6 7 temperature qc_end physical_unit 1 1 14 15 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"2.78 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{3 litres}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{-20 ℃}"},{"type":"other","value":"Pressure remaining constant."}]	<h1 class="questionTitle" itemprop="name">A gas occupies 3 litres at 0°C. what volume will it occupy at -20°C, assuming pressure remaining constant?</h1>	null	2.78 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you treat it as an ideal gas, then <mathjax>#PV=nRT#</mathjax> where P is pressure, V is volume, n is number of moles, R is the gas constant and T is temperature in K.</p> <p>If you assume pressure is constant, and we know that the amount of substance will remain constant, and of course the gas constant is a constant, then <mathjax>#V#</mathjax> varies directly with <mathjax>#T#</mathjax>. So for the two temperatures you can say:</p> <p><mathjax>#V_1.T_1 = V_2.T_2#</mathjax><br/> <mathjax>#V_2 = (V_1.T_1)/(T_2)#</mathjax></p> <p><mathjax>#T_2#</mathjax>, the higher of the two temperatures, will be 273 K and <mathjax>#T_1#</mathjax> will be 20 degrees lower, so 253 K.</p> <p>Now plug in the numbers:</p> <p><mathjax>#V_2 = (3 . 253)/(273) = 2.78#</mathjax> litres.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.78 litres</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you treat it as an ideal gas, then <mathjax>#PV=nRT#</mathjax> where P is pressure, V is volume, n is number of moles, R is the gas constant and T is temperature in K.</p> <p>If you assume pressure is constant, and we know that the amount of substance will remain constant, and of course the gas constant is a constant, then <mathjax>#V#</mathjax> varies directly with <mathjax>#T#</mathjax>. So for the two temperatures you can say:</p> <p><mathjax>#V_1.T_1 = V_2.T_2#</mathjax><br/> <mathjax>#V_2 = (V_1.T_1)/(T_2)#</mathjax></p> <p><mathjax>#T_2#</mathjax>, the higher of the two temperatures, will be 273 K and <mathjax>#T_1#</mathjax> will be 20 degrees lower, so 253 K.</p> <p>Now plug in the numbers:</p> <p><mathjax>#V_2 = (3 . 253)/(273) = 2.78#</mathjax> litres.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas occupies 3 litres at 0°C. what volume will it occupy at -20°C, assuming pressure remaining constant?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="509830" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-22T14:28:15" itemprop="dateCreated"> Nov 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2.78 litres</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If you treat it as an ideal gas, then <mathjax>#PV=nRT#</mathjax> where P is pressure, V is volume, n is number of moles, R is the gas constant and T is temperature in K.</p> <p>If you assume pressure is constant, and we know that the amount of substance will remain constant, and of course the gas constant is a constant, then <mathjax>#V#</mathjax> varies directly with <mathjax>#T#</mathjax>. So for the two temperatures you can say:</p> <p><mathjax>#V_1.T_1 = V_2.T_2#</mathjax><br/> <mathjax>#V_2 = (V_1.T_1)/(T_2)#</mathjax></p> <p><mathjax>#T_2#</mathjax>, the higher of the two temperatures, will be 273 K and <mathjax>#T_1#</mathjax> will be 20 degrees lower, so 253 K.</p> <p>Now plug in the numbers:</p> <p><mathjax>#V_2 = (3 . 253)/(273) = 2.78#</mathjax> litres.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/509830" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14586 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas occupies 3 litres at 0°C. what volume will it occupy at -20°C, assuming pressure remaining constant?	null
2,724	a83f6f1f-6ddd-11ea-8670-ccda262736ce	https://socratic.org/questions/a-sample-of-a-compound-contains-259-2-g-f-and-40-8-g-c-how-do-you-find-its-empir	CF4	start chemical_formula qc_end physical_unit 8 8 6 7 mass qc_end physical_unit 12 12 10 11 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound sample [IN] empirical"}]	[{"type":"chemical equation","value":"CF4"}]	[{"type":"physical unit","value":"Mass [OF] F [=] \\pu{259.2 g}"},{"type":"physical unit","value":"Mass [OF] C [=] \\pu{40.8 g}"}]	<h1 class="questionTitle" itemprop="name">A sample of a compound contains 259.2 g #F# and 40.8 g #C#. How do you find its empirical formula?</h1>	null	CF4	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <em>empirical formula</em> of a compound, given the mass of each element present in the compound. </p> <p>To to this, we need to find the <strong>ratio</strong> of mole values for each element, so using the <em>molar mass</em> of each element (from a periodic table), let's find the number of <em>moles</em> of each element present:</p> <ul> <li> <p><mathjax>#259.2cancel("g F")((1color(white)(l)"mol F")/(19.00cancel("g F"))) = color(red)(13.64#</mathjax> <mathjax>#color(red)("mol F"#</mathjax></p> </li> <li> <p><mathjax>#40.8cancel("g C")((1color(white)(l)"mol C")/(12.01cancel("g C"))) = color(blue)(3.397#</mathjax> <mathjax>#color(blue)("mol C"#</mathjax></p> </li> </ul> <p>The ratio of <mathjax>#"F"#</mathjax> atoms to <mathjax>#"C"#</mathjax> atoms is thus</p> <p><mathjax>#(color(red)(13.64))/(color(blue)(3.397)) = 4.02 ~~ color(green)(4#</mathjax></p> <p>Thus, there are <mathjax>#4#</mathjax> <mathjax>#"F"#</mathjax> atoms for each <mathjax>#"C"#</mathjax> atom, so the empirical formula is</p> <p><mathjax>#"CF"_ (color(green)(4))#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"CF"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <em>empirical formula</em> of a compound, given the mass of each element present in the compound. </p> <p>To to this, we need to find the <strong>ratio</strong> of mole values for each element, so using the <em>molar mass</em> of each element (from a periodic table), let's find the number of <em>moles</em> of each element present:</p> <ul> <li> <p><mathjax>#259.2cancel("g F")((1color(white)(l)"mol F")/(19.00cancel("g F"))) = color(red)(13.64#</mathjax> <mathjax>#color(red)("mol F"#</mathjax></p> </li> <li> <p><mathjax>#40.8cancel("g C")((1color(white)(l)"mol C")/(12.01cancel("g C"))) = color(blue)(3.397#</mathjax> <mathjax>#color(blue)("mol C"#</mathjax></p> </li> </ul> <p>The ratio of <mathjax>#"F"#</mathjax> atoms to <mathjax>#"C"#</mathjax> atoms is thus</p> <p><mathjax>#(color(red)(13.64))/(color(blue)(3.397)) = 4.02 ~~ color(green)(4#</mathjax></p> <p>Thus, there are <mathjax>#4#</mathjax> <mathjax>#"F"#</mathjax> atoms for each <mathjax>#"C"#</mathjax> atom, so the empirical formula is</p> <p><mathjax>#"CF"_ (color(green)(4))#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of a compound contains 259.2 g #F# and 40.8 g #C#. How do you find its empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="447225" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-03T01:56:33" itemprop="dateCreated"> Jul 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"CF"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <em>empirical formula</em> of a compound, given the mass of each element present in the compound. </p> <p>To to this, we need to find the <strong>ratio</strong> of mole values for each element, so using the <em>molar mass</em> of each element (from a periodic table), let's find the number of <em>moles</em> of each element present:</p> <ul> <li> <p><mathjax>#259.2cancel("g F")((1color(white)(l)"mol F")/(19.00cancel("g F"))) = color(red)(13.64#</mathjax> <mathjax>#color(red)("mol F"#</mathjax></p> </li> <li> <p><mathjax>#40.8cancel("g C")((1color(white)(l)"mol C")/(12.01cancel("g C"))) = color(blue)(3.397#</mathjax> <mathjax>#color(blue)("mol C"#</mathjax></p> </li> </ul> <p>The ratio of <mathjax>#"F"#</mathjax> atoms to <mathjax>#"C"#</mathjax> atoms is thus</p> <p><mathjax>#(color(red)(13.64))/(color(blue)(3.397)) = 4.02 ~~ color(green)(4#</mathjax></p> <p>Thus, there are <mathjax>#4#</mathjax> <mathjax>#"F"#</mathjax> atoms for each <mathjax>#"C"#</mathjax> atom, so the empirical formula is</p> <p><mathjax>#"CF"_ (color(green)(4))#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/447225" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11977 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of a compound contains 259.2 g #F# and 40.8 g #C#. How do you find its empirical formula?	null
2,725	a8ed32a5-6ddd-11ea-bc86-ccda262736ce	https://socratic.org/questions/59310fd711ef6b0d208353b0	CO2(g) + Ca(OH)2(aq) -> CaCO3(s) + H2O(l)	start chemical_equation qc_end chemical_equation 5 5 qc_end chemical_equation 7 7 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the reaction"}]	[{"type":"chemical equation","value":"CO2(g) + Ca(OH)2(aq) -> CaCO3(s) + H2O(l)"}]	[{"type":"chemical equation","value":"CO2(g)"},{"type":"chemical equation","value":"Ca(OH)2(aq)"}]	<h1 class="questionTitle" itemprop="name">What is the reaction of #"CO"_2(g)# with #"Ca"("OH")_2(aq)#?</h1>	null	CO2(g) + Ca(OH)2(aq) -> CaCO3(s) + H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is NOT so obvious. You generally get a fine precipitate of <mathjax>#CaCO_3(s)#</mathjax>, the which you might not notice. The solution? Get a saturated <mathjax>#CO_2#</mathjax> solution (and this is simply sparkling, i.e. carbonated water that you might otherwise drink), and add this to lime water (which is saturated <mathjax>#Ca(OH)_2(aq)#</mathjax>). You should see a dense white precipitate of <mathjax>#CaCO_3#</mathjax>. This is a control, so that you can appreciate the result of a positive test, </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CO_2(g) + Ca(OH)_2(aq)rarrCaCO_3(s)darr +H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is NOT so obvious. You generally get a fine precipitate of <mathjax>#CaCO_3(s)#</mathjax>, the which you might not notice. The solution? Get a saturated <mathjax>#CO_2#</mathjax> solution (and this is simply sparkling, i.e. carbonated water that you might otherwise drink), and add this to lime water (which is saturated <mathjax>#Ca(OH)_2(aq)#</mathjax>). You should see a dense white precipitate of <mathjax>#CaCO_3#</mathjax>. This is a control, so that you can appreciate the result of a positive test, </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the reaction of #"CO"_2(g)# with #"Ca"("OH")_2(aq)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="433442" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-02T07:37:57" itemprop="dateCreated"> Jun 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CO_2(g) + Ca(OH)_2(aq)rarrCaCO_3(s)darr +H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is NOT so obvious. You generally get a fine precipitate of <mathjax>#CaCO_3(s)#</mathjax>, the which you might not notice. The solution? Get a saturated <mathjax>#CO_2#</mathjax> solution (and this is simply sparkling, i.e. carbonated water that you might otherwise drink), and add this to lime water (which is saturated <mathjax>#Ca(OH)_2(aq)#</mathjax>). You should see a dense white precipitate of <mathjax>#CaCO_3#</mathjax>. This is a control, so that you can appreciate the result of a positive test, </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/433442" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="433638" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-02T16:35:45" itemprop="dateCreated"> Jun 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>See below:</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When <mathjax>#sf(CO_2)#</mathjax> gas is bubbled through limewater you initially get a milky precipitate of insoluble calcium carbonate:</p> <p><img alt="www.sciencephoto.com" src="http://www.sciencephoto.com/image/4216/large/A5000280-Carbon_dioxide_test-SPL.jpg"/></p> <p>This is an acid - base reaction and is used as a qualitative test for <mathjax>#sf(CO_2)#</mathjax>:</p> <p><mathjax>#sf(CO_2(g)+Ca(OH)_(2)(aq)rarrCaCO_3(s)+H_2O(l)#</mathjax></p> <p>If you continue to pass <mathjax>#sf(CO_2)#</mathjax> through the suspension the acidic nature of the gas causes the precipitate to dissolve rendering the solution clear again due to the formation of soluble calcium hydrogen carbonate:</p> <p>Carbonic acid is formed first:</p> <p><mathjax>#sf(CO_(2)+H_2O(l)rightleftharpoonsH_2CO_(3)(aq))#</mathjax></p> <p>This then reacts with the calcium carbonate in an acid / base reaction:</p> <p><mathjax>#sf(H_2CO_(3)(aq)+CaCO_(3)(s)rightleftharpoonsCa(HCO_3)_(2)(aq))#</mathjax></p> <p>This process occurs in nature. Rain water is naturally acidic due to the presence of dissolved <mathjax>#sf(CO_2)#</mathjax>. </p> <p>Minerals such as limestone, which is a form of calcium carbonate, are subjected to chemical weathering. This results in cave formation in limestone areas.</p> <p>You will notice that the reactions are reversible. As the solution naturally evaporates this can lead to a deposit of solid calcium carbonate resulting in the formation of stalagtites and stalagmites:</p> <p><img alt="www.summitpost.org" src="http://www.summitpost.org/images/original/608767.JPG"/></p> <p>Water containing dissolved <mathjax>#sf(Ca^(2+))#</mathjax> and <mathjax>#sf(Mg^(2+))#</mathjax> ions is referred to as "hard water".</p> <p>A downside of this is that it forms an insoluble "scum" with soap - based detergents which is wasteful.</p> <p>On the plus side hard water is good for making beer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/433638" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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2,726	ab4d69c1-6ddd-11ea-8536-ccda262736ce	https://socratic.org/questions/how-do-you-write-a-balanced-equation-for-the-combustion-reaction-with-oxygen-gas	C6H12O6(s) + 6 O2(g) -> 6 CO2(g) + 6 H2O(l)	start chemical_equation qc_end substance 12 13 qc_end chemical_equation 16 16 qc_end substance 19 20 qc_end substance 22 22 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the combustion"}]	[{"type":"chemical equation","value":"C6H12O6(s) + 6 O2(g) -> 6 CO2(g) + 6 H2O(l)"}]	[{"type":"substance name","value":"Oxygen gas"},{"type":"chemical equation","value":"C6H12O6"},{"type":"substance name","value":"Carbon dioxide"},{"type":"substance name","value":"Water"}]	<h1 class="questionTitle" itemprop="name">How do you write a balanced equation for the combustion (reaction with oxygen gas) of glucose, #C_6H_12O_6#, to give carbon dioxide and water?</h1>	null	C6H12O6(s) + 6 O2(g) -> 6 CO2(g) + 6 H2O(l)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Is mass balanced? Do not trust my arithmetic. How would energy transfer in the reaction? Is the reaction endothermic or exothermic?</p> <p>As to how I balanced the equation, I know that products of combustion are carbon dioxide and water. Under conditions of complete combustion, a carbohydrate (or alkane) gives stoichiometric carbon dioxide and water. You can balance the oxygen last. Given this it is a fairly easy exercise to ensure that garbage out equal garbage in. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_12O_6(s) +6O_2(g) rarr 6CO_2(g) +6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Is mass balanced? Do not trust my arithmetic. How would energy transfer in the reaction? Is the reaction endothermic or exothermic?</p> <p>As to how I balanced the equation, I know that products of combustion are carbon dioxide and water. Under conditions of complete combustion, a carbohydrate (or alkane) gives stoichiometric carbon dioxide and water. You can balance the oxygen last. Given this it is a fairly easy exercise to ensure that garbage out equal garbage in. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write a balanced equation for the combustion (reaction with oxygen gas) of glucose, #C_6H_12O_6#, to give carbon dioxide and water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="315931" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-29T17:38:27" itemprop="dateCreated"> Sep 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_12O_6(s) +6O_2(g) rarr 6CO_2(g) +6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Is mass balanced? Do not trust my arithmetic. How would energy transfer in the reaction? Is the reaction endothermic or exothermic?</p> <p>As to how I balanced the equation, I know that products of combustion are carbon dioxide and water. Under conditions of complete combustion, a carbohydrate (or alkane) gives stoichiometric carbon dioxide and water. You can balance the oxygen last. Given this it is a fairly easy exercise to ensure that garbage out equal garbage in. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/315931" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5222 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you write a balanced equation for the combustion (reaction with oxygen gas) of glucose, #C_6H_12O_6#, to give carbon dioxide and water?	null
2,727	a8ca630c-6ddd-11ea-9984-ccda262736ce	https://socratic.org/questions/use-this-balanced-equation-2c-2h-2-5o-2-4co-2-2h2-o-2599-kj-how-much-energy-is-n	-634 kJ	start physical_unit 28 29 energy kj qc_end chemical_equation 4 17 qc_end physical_unit 28 29 25 26 mass qc_end end	[{"type":"physical unit","value":"Needed energy [OF] carbon dioxide [IN] kJ"}]	[{"type":"physical unit","value":" -634 kJ"}]	[{"type":"chemical equation","value":"2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O + 2599 kJ"},{"type":"physical unit","value":"Mass [OF] carbon dioxide [=] \\pu{42.9 grams}"}]	<h1 class="questionTitle" itemprop="name">Use this balanced equation #2C_2H_2 + 5O_2 -> 4CO_2 + 2H2_O + 2599 kJ#. How much energy is needed to produce 42.9 grams of carbon dioxide? </h1>	null	-634 kJ	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As follows...<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/EX3msrz8QvGtkp4nu4ZX_Combustion%20of%20Acetylene_0003.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Heat Needed => - 634 Kj (Exothermic)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As follows...<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/EX3msrz8QvGtkp4nu4ZX_Combustion%20of%20Acetylene_0003.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Use this balanced equation #2C_2H_2 + 5O_2 -> 4CO_2 + 2H2_O + 2599 kJ#. How much energy is needed to produce 42.9 grams of carbon dioxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430810" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-28T04:06:55" itemprop="dateCreated"> May 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Heat Needed => - 634 Kj (Exothermic)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As follows...<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/EX3msrz8QvGtkp4nu4ZX_Combustion%20of%20Acetylene_0003.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430810" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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How much energy is needed to produce 42.9 grams of carbon dioxide?	null
2,728	a837f71c-6ddd-11ea-882e-ccda262736ce	https://socratic.org/questions/586c5aed7c0149578d0f89dd	737 g/mol	start physical_unit 5 5 molecular_weight g/mol qc_end physical_unit 5 5 1 2 mass qc_end physical_unit 5 5 11 12 osmotic_pressure qc_end physical_unit 5 5 17 18 temperature qc_end end	[{"type":"physical unit","value":"Molecular mass [OF] polystyrene [IN] g/mol"}]	[{"type":"physical unit","value":"737 g/mol"}]	[{"type":"physical unit","value":"mass [OF] polystyrene [=] \\pu{5 g}"},{"type":"physical unit","value":"osmotic pressure [OF] polystyrene [=] \\pu{1.21 kPa}"},{"type":"physical unit","value":"temperature [OF] polystyrene [=] \\pu{523 K}"}]	<h1 class="questionTitle" itemprop="name">A #5g# mass of polystyrene exerts an osmotic pressure of #1.21kPa# at a temperature of #523*K#. What is the molecular mass of the polystyrene?</h1>	null	737 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Pi_"the osmotic pressure"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#cRT#</mathjax></p> <p>And thus <mathjax>#Pi/(RT)=c#</mathjax></p> <p><mathjax>#c=(1.21cancel(kPa))/(1.01325cancel(kPaatm^-1))xx1/(0.0821Lcancel(atm)cancel(K^-1)mol^-1xx523cancelK)=0.0278molL^-1#</mathjax>.</p> <p>Note the dimensional consistency. I changed the pressure into units of atmospheres, because this gives us a better idea of dimensionality. Of course, <mathjax>#1atm-=101.3kPa#</mathjax>; such information should be given as supplementary material in any examination. Of course, you have to know how to use it and manipulate it. </p> <p>And thus,<br/> <mathjax>#(2.05g)/("Molecular mass of polystyrene")xx1/(0.100L)=0.0278molL^-1#</mathjax><br/> So, finally, <mathjax>#"Molecular mass of polystyrene"=(2.05g)/(0.0278molL^-1)xx1/(0.100L)=737gmol^-1#</mathjax>.</p> <p>How many formula units of <mathjax>#"styrene, "C_7H_8,#</mathjax> compose this polymer?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molecular mass of polystyrene"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#7.4xx10^2gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Pi_"the osmotic pressure"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#cRT#</mathjax></p> <p>And thus <mathjax>#Pi/(RT)=c#</mathjax></p> <p><mathjax>#c=(1.21cancel(kPa))/(1.01325cancel(kPaatm^-1))xx1/(0.0821Lcancel(atm)cancel(K^-1)mol^-1xx523cancelK)=0.0278molL^-1#</mathjax>.</p> <p>Note the dimensional consistency. I changed the pressure into units of atmospheres, because this gives us a better idea of dimensionality. Of course, <mathjax>#1atm-=101.3kPa#</mathjax>; such information should be given as supplementary material in any examination. Of course, you have to know how to use it and manipulate it. </p> <p>And thus,<br/> <mathjax>#(2.05g)/("Molecular mass of polystyrene")xx1/(0.100L)=0.0278molL^-1#</mathjax><br/> So, finally, <mathjax>#"Molecular mass of polystyrene"=(2.05g)/(0.0278molL^-1)xx1/(0.100L)=737gmol^-1#</mathjax>.</p> <p>How many formula units of <mathjax>#"styrene, "C_7H_8,#</mathjax> compose this polymer?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A #5g# mass of polystyrene exerts an osmotic pressure of #1.21kPa# at a temperature of #523K#. What is the molecular mass of the polystyrene?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/osmolarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Osmolarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="360564" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-05T13:20:10" itemprop="dateCreated"> Jan 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molecular mass of polystyrene"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#7.4xx10^2gmol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Pi_"the osmotic pressure"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#cRT#</mathjax></p> <p>And thus <mathjax>#Pi/(RT)=c#</mathjax></p> <p><mathjax>#c=(1.21cancel(kPa))/(1.01325cancel(kPaatm^-1))xx1/(0.0821Lcancel(atm)cancel(K^-1)mol^-1xx523cancelK)=0.0278molL^-1#</mathjax>.</p> <p>Note the dimensional consistency. I changed the pressure into units of atmospheres, because this gives us a better idea of dimensionality. Of course, <mathjax>#1atm-=101.3kPa#</mathjax>; such information should be given as supplementary material in any examination. Of course, you have to know how to use it and manipulate it. </p> <p>And thus,<br/> <mathjax>#(2.05g)/("Molecular mass of polystyrene")xx1/(0.100L)=0.0278molL^-1#</mathjax><br/> So, finally, <mathjax>#"Molecular mass of polystyrene"=(2.05g)/(0.0278molL^-1)xx1/(0.100L)=737g*mol^-1#</mathjax>.</p> <p>How many formula units of <mathjax>#"styrene, "C_7H_8,#</mathjax> compose this polymer?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/360564" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-osmolarity-of-a-solution"> How do you calculate osmolarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-osmolarity-of-the-blood-maintain-homeostasis"> How does osmolarity of the blood maintain homeostasis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-osmolarity-from-molarity"> How do you calculate osmolarity from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-osmolarity"> What is osmolarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-dehydration-affect-osmolarity"> How does dehydration affect osmolarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-osmolarity-affect-blood-pressure"> How does osmolarity affect blood pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-osmolarity-affect-cells"> How does osmolarity affect cells? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-relative-osmolarities-relate-to-water-movement"> Do relative osmolarities relate to water movement? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-osmolarity-affect-osmosis"> How does osmolarity affect osmosis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-water-affect-osmolarity"> How does water affect osmolarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/osmolarity"> See all questions in Osmolarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2810 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A #5g# mass of polystyrene exerts an osmotic pressure of #1.21kPa# at a temperature of #523*K#. What is the molecular mass of the polystyrene?	null
2,729	a9d9fa2f-6ddd-11ea-bcd2-ccda262736ce	https://socratic.org/questions/57df4a597c014962cf9296f7	8.76 × 10^3 moles	start physical_unit 9 11 mole mol qc_end physical_unit 9 11 7 8 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] block of calcium [IN] moles"}]	[{"type":"physical unit","value":"8.76 × 10^3 moles"}]	[{"type":"physical unit","value":"Mass [OF] block of calcium [=] \\pu{351 kg}"}]	<h1 class="questionTitle" itemprop="name">How many moles are present in a #"351 kg"# block of calcium?</h1>	null	8.76 × 10^3 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the mass of one mole (i.e. molar mass) of calcium. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. </p> <p><strong>The molar mass of calcium is 40.078 g/mol .</strong></p> <p>Next, since molar mass is g/mol, we need to convert 351 kg to g. There are 1000 g in 1 kg.</p> <p><mathjax>#351 cancel"kg Ca"xx(1000 "g Ca")/(1cancel"kg Ca")="351 000 g"#</mathjax></p> <p><mathjax>#"351 kg Ca=351 000 g Ca"#</mathjax></p> <p>Next we'll convert the given mass to moles by dividing the given mass by the molar mass.</p> <p><mathjax>#351 000cancel"g Ca"xx(1"mol Ca")/(40.078cancel"g Ca")=8.76xx10^3 "mol Ca"#</mathjax> (rounded to three significant figures)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The number of moles in <mathjax>#"351 kg Ca"#</mathjax> is <mathjax>#8.76xx10^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the mass of one mole (i.e. molar mass) of calcium. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. </p> <p><strong>The molar mass of calcium is 40.078 g/mol .</strong></p> <p>Next, since molar mass is g/mol, we need to convert 351 kg to g. There are 1000 g in 1 kg.</p> <p><mathjax>#351 cancel"kg Ca"xx(1000 "g Ca")/(1cancel"kg Ca")="351 000 g"#</mathjax></p> <p><mathjax>#"351 kg Ca=351 000 g Ca"#</mathjax></p> <p>Next we'll convert the given mass to moles by dividing the given mass by the molar mass.</p> <p><mathjax>#351 000cancel"g Ca"xx(1"mol Ca")/(40.078cancel"g Ca")=8.76xx10^3 "mol Ca"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are present in a #"351 kg"# block of calcium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="312856" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-21T19:07:25" itemprop="dateCreated"> Sep 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The number of moles in <mathjax>#"351 kg Ca"#</mathjax> is <mathjax>#8.76xx10^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the mass of one mole (i.e. molar mass) of calcium. The molar mass of an element is its atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol. </p> <p><strong>The molar mass of calcium is 40.078 g/mol .</strong></p> <p>Next, since molar mass is g/mol, we need to convert 351 kg to g. There are 1000 g in 1 kg.</p> <p><mathjax>#351 cancel"kg Ca"xx(1000 "g Ca")/(1cancel"kg Ca")="351 000 g"#</mathjax></p> <p><mathjax>#"351 kg Ca=351 000 g Ca"#</mathjax></p> <p>Next we'll convert the given mass to moles by dividing the given mass by the molar mass.</p> <p><mathjax>#351 000cancel"g Ca"xx(1"mol Ca")/(40.078cancel"g Ca")=8.76xx10^3 "mol Ca"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/312856" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="313377" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-23T05:51:51" itemprop="dateCreated"> Sep 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are approx. <mathjax>#9000#</mathjax> moles of calcium metal. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Calcium metal, "Z=20,#</mathjax> has a molar mass of <mathjax>#40.08gmol^-1#</mathjax>. From where did I get this figure? From where will get it if you are asked this on an exam? You will not be expected to remember it.</p> <p>And molar quantity is simply the quotient:</p> <p><mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(351.0xx10^3cancelg)/(40.08cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>Note that this calculation is dimensionally consistent. I wanted an answer in <mathjax>#"moles"#</mathjax>. The mass units cancelled out so I got an answer in <mathjax>#1/(mol^-1)="moles"#</mathjax>. This persuades me that I set up the question right (for once!). Are you happy with this treatment?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/313377" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7690 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are present in a #"351 kg"# block of calcium?	null
2,730	a99cf8f8-6ddd-11ea-95b8-ccda262736ce	https://socratic.org/questions/595d54bc7c014916d2f732f7	0.54 g	start physical_unit 3 3 mass g qc_end physical_unit 10 10 7 8 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] oxygen [IN] g"}]	[{"type":"physical unit","value":"0.54 g"}]	[{"type":"physical unit","value":"Mass [OF] MgO [=] \\pu{1.36 g}"}]	<h1 class="questionTitle" itemprop="name">What mass of oxygen is found in #"1.36 g"# of #"MgO"#?</h1>	null	0.54 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium oxide is composed by atoms of Magnesium and Oxygen in equal quantities because the formula unit is MgO.</p> <p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> we read that the mass of one atom of Magnesium is <mathjax>#24.305#</mathjax> u and the mass of one atom of Oxygen is <mathjax>#15.999#</mathjax> u.</p> <p>This means that one formula unit of MgO has a mass of <mathjax>#24.305+15.999=40.304#</mathjax> u and the fraction of mass that is of Oxygen is </p> <blockquote> <p><mathjax>#15.999/40.304 \approx 0.397#</mathjax>.</p> </blockquote> <p>Then when we have a certain quantity of MgO we know that the <mathjax>#39.7%#</mathjax> of it by mass is Oxygen (and <mathjax>#60.3%#</mathjax> by mass is Magnesium) and in our case the mass of the Oxygen will be </p> <blockquote> <p><mathjax>#1.36\times 0.397\approx 0.54#</mathjax> <mathjax>#"g"#</mathjax>.</p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The Oxygen is <mathjax>#0.54#</mathjax> g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium oxide is composed by atoms of Magnesium and Oxygen in equal quantities because the formula unit is MgO.</p> <p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> we read that the mass of one atom of Magnesium is <mathjax>#24.305#</mathjax> u and the mass of one atom of Oxygen is <mathjax>#15.999#</mathjax> u.</p> <p>This means that one formula unit of MgO has a mass of <mathjax>#24.305+15.999=40.304#</mathjax> u and the fraction of mass that is of Oxygen is </p> <blockquote> <p><mathjax>#15.999/40.304 \approx 0.397#</mathjax>.</p> </blockquote> <p>Then when we have a certain quantity of MgO we know that the <mathjax>#39.7%#</mathjax> of it by mass is Oxygen (and <mathjax>#60.3%#</mathjax> by mass is Magnesium) and in our case the mass of the Oxygen will be </p> <blockquote> <p><mathjax>#1.36\times 0.397\approx 0.54#</mathjax> <mathjax>#"g"#</mathjax>.</p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of oxygen is found in #"1.36 g"# of #"MgO"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448361" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/emanuele-l-1"><img alt="" class="" src="https://profilepictures.socratic.org/8wJGUuEZSaucWOYjIPyl_283186-19.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/emanuele-l-1"> Burglar </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-05T21:22:31" itemprop="dateCreated"> Jul 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The Oxygen is <mathjax>#0.54#</mathjax> g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium oxide is composed by atoms of Magnesium and Oxygen in equal quantities because the formula unit is MgO.</p> <p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> we read that the mass of one atom of Magnesium is <mathjax>#24.305#</mathjax> u and the mass of one atom of Oxygen is <mathjax>#15.999#</mathjax> u.</p> <p>This means that one formula unit of MgO has a mass of <mathjax>#24.305+15.999=40.304#</mathjax> u and the fraction of mass that is of Oxygen is </p> <blockquote> <p><mathjax>#15.999/40.304 \approx 0.397#</mathjax>.</p> </blockquote> <p>Then when we have a certain quantity of MgO we know that the <mathjax>#39.7%#</mathjax> of it by mass is Oxygen (and <mathjax>#60.3%#</mathjax> by mass is Magnesium) and in our case the mass of the Oxygen will be </p> <blockquote> <p><mathjax>#1.36\times 0.397\approx 0.54#</mathjax> <mathjax>#"g"#</mathjax>.</p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448361" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> 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</div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3515 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of oxygen is found in #"1.36 g"# of #"MgO"#?	null
2,731	a861934a-6ddd-11ea-a73c-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-363-8-g-of-ba-oh-2	2.1 moles	start physical_unit 8 8 mole mol qc_end physical_unit 8 8 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] Ba(OH)2 [IN] moles"}]	[{"type":"physical unit","value":"2.1 moles"}]	[{"type":"physical unit","value":"Mass [OF] Ba(OH)2 [=] \\pu{363.8 g}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 363.8 g of #Ba(OH)_2#? </h1>	null	2.1 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the molar mass of the barium hydroxide.</p> <p><mathjax>#Ba=(137.327"g")/"mol"#</mathjax></p> <p><mathjax>#O=(16"g")/"mol"#</mathjax></p> <p><mathjax>#H=(1.008"g")/"mol"#</mathjax></p> <p>molar mass of <mathjax>#Ba(OH)_2=((137.327+2(16)+2(1.008))"g")/"mol"#</mathjax></p> <p><mathjax>#=(171.343"g")/"mol"#</mathjax></p> <p>We know we have <mathjax>#363.8"g"#</mathjax>.</p> <p><mathjax>#(363.8"g")/(x" mol")=(171.343"g")/(1"mol")#</mathjax></p> <p>Solve to find that there are <mathjax>#2.1"mol "Ba(OH)_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.1"mol "Ba(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the molar mass of the barium hydroxide.</p> <p><mathjax>#Ba=(137.327"g")/"mol"#</mathjax></p> <p><mathjax>#O=(16"g")/"mol"#</mathjax></p> <p><mathjax>#H=(1.008"g")/"mol"#</mathjax></p> <p>molar mass of <mathjax>#Ba(OH)_2=((137.327+2(16)+2(1.008))"g")/"mol"#</mathjax></p> <p><mathjax>#=(171.343"g")/"mol"#</mathjax></p> <p>We know we have <mathjax>#363.8"g"#</mathjax>.</p> <p><mathjax>#(363.8"g")/(x" mol")=(171.343"g")/(1"mol")#</mathjax></p> <p>Solve to find that there are <mathjax>#2.1"mol "Ba(OH)_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 363.8 g of #Ba(OH)_2#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="194847" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mason-m"><img alt="" class="" src="https://profilepictures.socratic.org/U70pu8hUTGGkEuy92fsO_IMG_2585.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mason-m"> mason m </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-30T23:47:36" itemprop="dateCreated"> Nov 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.1"mol "Ba(OH)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the molar mass of the barium hydroxide.</p> <p><mathjax>#Ba=(137.327"g")/"mol"#</mathjax></p> <p><mathjax>#O=(16"g")/"mol"#</mathjax></p> <p><mathjax>#H=(1.008"g")/"mol"#</mathjax></p> <p>molar mass of <mathjax>#Ba(OH)_2=((137.327+2(16)+2(1.008))"g")/"mol"#</mathjax></p> <p><mathjax>#=(171.343"g")/"mol"#</mathjax></p> <p>We know we have <mathjax>#363.8"g"#</mathjax>.</p> <p><mathjax>#(363.8"g")/(x" mol")=(171.343"g")/(1"mol")#</mathjax></p> <p>Solve to find that there are <mathjax>#2.1"mol "Ba(OH)_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194847" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,732	a8ecfe3a-6ddd-11ea-bb17-ccda262736ce	https://socratic.org/questions/the-temperature-of-a-balloon-increases-from-25-k-to-50-k-what-will-the-final-vol	2 L	start physical_unit 18 19 volume l qc_end physical_unit 3 4 7 8 temperature qc_end physical_unit 3 4 10 11 temperature qc_end physical_unit 18 19 24 25 volume qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the balloon [IN] L"}]	[{"type":"physical unit","value":"2 L"}]	[{"type":"physical unit","value":"Temperature1 [OF] a balloon [=] \\pu{25 K}"},{"type":"physical unit","value":"Temperature2 [OF] a balloon [=] \\pu{50 K}"},{"type":"physical unit","value":"Volume1 [OF] the balloon [=] \\pu{1 L}"}]	<h1 class="questionTitle" itemprop="name">The temperature of a balloon increases from 25 K to 50 K. What will the final volume of the balloon be if it was 1 L before the temperature change? </h1>	null	2 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Charle’s law</p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#"V ∝ T"#</mathjax></p> </blockquote> <p><mathjax>#"V"_2/"V"_1 = "T"_2/"T"_1#</mathjax></p> </blockquote> </blockquote> </blockquote> <p><mathjax>#"V"_2 = "V"_1 × "T"_2/"T"_1 = "1 L" × (50 cancel"K")/(25 cancel"K") = "2 L"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Charle’s law</p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#"V ∝ T"#</mathjax></p> </blockquote> <p><mathjax>#"V"_2/"V"_1 = "T"_2/"T"_1#</mathjax></p> </blockquote> </blockquote> </blockquote> <p><mathjax>#"V"_2 = "V"_1 × "T"_2/"T"_1 = "1 L" × (50 cancel"K")/(25 cancel"K") = "2 L"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The temperature of a balloon increases from 25 K to 50 K. What will the final volume of the balloon be if it was 1 L before the temperature change? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="577570" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-20T01:26:37" itemprop="dateCreated"> Mar 20, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Charle’s law</p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#"V ∝ T"#</mathjax></p> </blockquote> <p><mathjax>#"V"_2/"V"_1 = "T"_2/"T"_1#</mathjax></p> </blockquote> </blockquote> </blockquote> <p><mathjax>#"V"_2 = "V"_1 × "T"_2/"T"_1 = "1 L" × (50 cancel"K")/(25 cancel"K") = "2 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/577570" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1393 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The temperature of a balloon increases from 25 K to 50 K. What will the final volume of the balloon be if it was 1 L before the temperature change?	null
2,733	aa621fc1-6ddd-11ea-af74-ccda262736ce	https://socratic.org/questions/how-many-ml-of-0-20-m-hydrochloric-acid-is-required-to-neutralize-100-ml-of-0-80	400 mL	start physical_unit 6 7 volume ml qc_end physical_unit 6 7 4 5 molarity qc_end physical_unit 17 18 15 16 molarity qc_end physical_unit 17 18 12 13 volume qc_end end	[{"type":"physical unit","value":"Volume [OF] hydrochloric acid [IN] mL"}]	[{"type":"physical unit","value":"400 mL"}]	[{"type":"physical unit","value":"Molarity [OF] hydrochloric acid [=] \\pu{0.20 M}"},{"type":"physical unit","value":"Molarity [OF] potassium hydroxide [=] \\pu{0.80 M}"},{"type":"physical unit","value":"Volume [OF] potassium hydroxide [=] \\pu{100 mL}"}]	<h1 class="questionTitle" itemprop="name">How many mL of 0.20 M hydrochloric acid is required to neutralize 100 mL of 0.80 M potassium hydroxide?</h1>	null	400 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HCl(aq) + KOH(aq) rarr KCl(aq) + H_2O(l)#</mathjax></p> <p>Now the reaction is trivial here. It is nevertheless good practice to write the stoichiometric equation to show the <mathjax>#1:1#</mathjax> equivalence.</p> <p><mathjax>#"Moles of KOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.80molL^-1xx0.100L#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.080mol#</mathjax>. Note that here I normalized the volumes, <mathjax>#1mL#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^-3L#</mathjax>. </p> <p>Thus <mathjax>#"volume of HCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.080mol)/(0.20molL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.40*L#</mathjax></p> <p>PS Sorry for shouting in the top answer; I still haven't got the hang of this editor.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><h2><mathjax>#"Volume of HCl"=400#</mathjax> <mathjax>#mL#</mathjax>.</h2></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HCl(aq) + KOH(aq) rarr KCl(aq) + H_2O(l)#</mathjax></p> <p>Now the reaction is trivial here. It is nevertheless good practice to write the stoichiometric equation to show the <mathjax>#1:1#</mathjax> equivalence.</p> <p><mathjax>#"Moles of KOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.80molL^-1xx0.100L#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.080mol#</mathjax>. Note that here I normalized the volumes, <mathjax>#1mL#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^-3L#</mathjax>. </p> <p>Thus <mathjax>#"volume of HCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.080mol)/(0.20molL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.40*L#</mathjax></p> <p>PS Sorry for shouting in the top answer; I still haven't got the hang of this editor.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many mL of 0.20 M hydrochloric acid is required to neutralize 100 mL of 0.80 M potassium hydroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="297812" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-11T15:44:30" itemprop="dateCreated"> Aug 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><h2><mathjax>#"Volume of HCl"=400#</mathjax> <mathjax>#mL#</mathjax>.</h2></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HCl(aq) + KOH(aq) rarr KCl(aq) + H_2O(l)#</mathjax></p> <p>Now the reaction is trivial here. It is nevertheless good practice to write the stoichiometric equation to show the <mathjax>#1:1#</mathjax> equivalence.</p> <p><mathjax>#"Moles of KOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.80molL^-1xx0.100L#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.080mol#</mathjax>. Note that here I normalized the volumes, <mathjax>#1mL#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^-3L#</mathjax>. </p> <p>Thus <mathjax>#"volume of HCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.080mol)/(0.20molL^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.40*L#</mathjax></p> <p>PS Sorry for shouting in the top answer; I still haven't got the hang of this editor.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/297812" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16614 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many mL of 0.20 M hydrochloric acid is required to neutralize 100 mL of 0.80 M potassium hydroxide?	null
2,734	ab3ae91a-6ddd-11ea-be9e-ccda262736ce	https://socratic.org/questions/what-is-the-equation-for-this-reaction-barium-nitrate-sodium-carbonate	Ba(NO3)2(aq) + Na2CO3(aq) -> BaCO3(s) + 2 NaNO3(aq)	start chemical_equation qc_end substance 7 8 qc_end substance 10 11 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"Ba(NO3)2(aq) + Na2CO3(aq) -> BaCO3(s) + 2 NaNO3(aq)"}]	[{"type":"substance name","value":"Barium Nitrate"},{"type":"substance name","value":"Sodium Carbonate"}]	<h1 class="questionTitle" itemprop="name">What is the equation for this reaction: Barium Nitrate + Sodium Carbonate?</h1>	null	Ba(NO3)2(aq) + Na2CO3(aq) -> BaCO3(s) + 2 NaNO3(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the net ionic equation is:</p> <p><mathjax>#Ba^2+ + CO_3^(2-) rarr BaCO_3(s)darr #</mathjax></p> <p>Barium carbonate is quite insoluble in aqueous solution, <mathjax>#K_"sp"=2.58xx10^(−9)#</mathjax>, and should precipitate in this <mathjax>#"metathesis (partner exchange) reaction"#</mathjax></p> <p>Would you expect <mathjax>#BaCO_3#</mathjax> to be more soluble in a weakly acidic solution? Why or why not?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ba(NO_3)_2(aq) + Na_2CO_3(aq) rarr BaCO_3(s)darr + 2NaNO_3(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the net ionic equation is:</p> <p><mathjax>#Ba^2+ + CO_3^(2-) rarr BaCO_3(s)darr #</mathjax></p> <p>Barium carbonate is quite insoluble in aqueous solution, <mathjax>#K_"sp"=2.58xx10^(−9)#</mathjax>, and should precipitate in this <mathjax>#"metathesis (partner exchange) reaction"#</mathjax></p> <p>Would you expect <mathjax>#BaCO_3#</mathjax> to be more soluble in a weakly acidic solution? Why or why not?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the equation for this reaction: Barium Nitrate + Sodium Carbonate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="340382" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-22T18:30:12" itemprop="dateCreated"> Nov 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ba(NO_3)_2(aq) + Na_2CO_3(aq) rarr BaCO_3(s)darr + 2NaNO_3(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the net ionic equation is:</p> <p><mathjax>#Ba^2+ + CO_3^(2-) rarr BaCO_3(s)darr #</mathjax></p> <p>Barium carbonate is quite insoluble in aqueous solution, <mathjax>#K_"sp"=2.58xx10^(−9)#</mathjax>, and should precipitate in this <mathjax>#"metathesis (partner exchange) reaction"#</mathjax></p> <p>Would you expect <mathjax>#BaCO_3#</mathjax> to be more soluble in a weakly acidic solution? Why or why not?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/340382" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 46435 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the equation for this reaction: Barium Nitrate + Sodium Carbonate?	null
2,735	ab50cec2-6ddd-11ea-8711-ccda262736ce	https://socratic.org/questions/560a0f2c581e2a6ad766ed69	0.21 mol/g	start physical_unit 10 10 molality mol/g qc_end physical_unit 10 10 6 7 mass qc_end physical_unit 16 16 13 14 mass qc_end end	[{"type":"physical unit","value":"Molality [OF] toluene [IN] mol/g"}]	[{"type":"physical unit","value":"0.21 mol/g"}]	[{"type":"physical unit","value":"Mass [OF] toluene [=] \\pu{5.0 g}"},{"type":"physical unit","value":"Mass [OF] benzene [=] \\pu{255 g}"}]	<h1 class="questionTitle" itemprop="name">What is the #"molality"# of a #5.0g# mass of toluene dissolved in #255g# of benzene? </h1>	null	0.21 mol/g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, you could equally have a solution of benzene in toluene or a solution of toluene in benzene. The advantage of using <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a>, or opposed to <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, is that because we have used mass as the measure of solvent, molality is independent of volume. Temperature would affect the volume of both toluene and benzene, therefore, a measurement of molality is independent of temperature.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Molalilty is (moles of solute)/(kg solvent). You have the mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, and can determine the amount of moles, and you also have the mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. The exercise is arithmetic.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, you could equally have a solution of benzene in toluene or a solution of toluene in benzene. The advantage of using <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a>, or opposed to <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, is that because we have used mass as the measure of solvent, molality is independent of volume. Temperature would affect the volume of both toluene and benzene, therefore, a measurement of molality is independent of temperature.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the #"molality"# of a #5.0g# mass of toluene dissolved in #255g# of benzene? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molality" itemprop="url"> <span class="breadcrumb" itemprop="title">Molality</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="172788" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-29T06:32:46" itemprop="dateCreated"> Sep 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Molalilty is (moles of solute)/(kg solvent). You have the mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, and can determine the amount of moles, and you also have the mass of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. The exercise is arithmetic.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here, you could equally have a solution of benzene in toluene or a solution of toluene in benzene. The advantage of using <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a>, or opposed to <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, is that because we have used mass as the measure of solvent, molality is independent of volume. Temperature would affect the volume of both toluene and benzene, therefore, a measurement of molality is independent of temperature.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/172788" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="172789" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-29T06:35:07" itemprop="dateCreated"> Sep 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#m=(5.4xx10^(-2) mol)/(0.255kg)=0.21 "mol"/g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> is calculated by: <mathjax>#m=(n_"solute")/(mass_"solvent")#</mathjax></p> <p>Where, <mathjax>#(n_"solute")#</mathjax> is the number of mole of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> (Toluene), and <mathjax>#mass_"solvent"#</mathjax> is the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> in kg.</p> <p>For Toluene:<br/> <mathjax>#MM_"Toluene"=92 g/"mol"#</mathjax><br/> <mathjax>#mass_"Toluene"= 5.0g#</mathjax></p> <p>Then, <mathjax>#n_"Toluene"=(5.0cancel(g))/(92 cancel(g)/"mol")=5.4xx10^(-2) mol#</mathjax></p> <p>The molality then: <mathjax>#m=(5.4xx10^(-2) mol)/(0.255kg)=0.21 "mol"/"kg"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/172789" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-molality-and-molarity-differ"> How do molality and molarity differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molality-be"> How high can molality be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molality-from-molarity"> How do you calculate molality from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-used-for-colligative-properties"> Why is molality used for colligative properties? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-independent-of-temperature"> Why is molality independent of temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-molality-when-75-0-grams-of-mgcl2-is-dissolved-in-500-0-"> How can I calculate the molality when 75.0 grams of MgCl2 is dissolved in 500.0 g of solvent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/49-8-grams-of-ki-is-dissolved-in-1-00-kg-of-solvent-what-is-the-molality"> 49.8 grams of KI is dissolved in 1.00 kg of solvent. 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What... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-when-0-75-mol-is-dissolved-in-2-50-l-of-solvent"> What is the molality when 0.75 mol is dissolved in 2.50 L of solvent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-when-48-0-ml-of-6-00-m-h2so4-are-diluted-into-0-250-l"> What is the molality when 48.0 mL of 6.00 M H2SO4 are diluted into 0.250 L? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molality"> See all questions in Molality </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12318 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the #"molality"# of a #5.0g# mass of toluene dissolved in #255g# of benzene?	null
2,736	a8bcf69c-6ddd-11ea-b252-ccda262736ce	https://socratic.org/questions/the-empirical-formula-is-c-5h-4-and-its-molar-mass-is-128-16-g-mol-what-is-the-m	C10H8	start chemical_formula qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]	[{"type":"chemical equation","value":"C10H8"}]	[{"type":"physical unit","value":"Molar mass [OF] it [=] \\pu{128.16 g/mol}"},{"type":"other","value":"The empirical formula is C5H4."}]	<h1 class="questionTitle" itemprop="name">The empirical formula is #C_5H_4# and its molar mass is 128.16 g/mol. What is the molecular formula?</h1>	null	C10H8	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is ALWAYS a mulitple of the empirical formula. Of course, the multiple might be <mathjax>#1#</mathjax>.</p> <p>So <mathjax>#"MF" =(EF)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5xx12.011gmol^-1+ 4xx1.00794gmol^-1)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(64.08)gmol^-1xxn= 128.16g*mol^-1.#</mathjax></p> <p>Clearly, <mathjax>#n=2#</mathjax>, and molecular formula <mathjax>#=#</mathjax> <mathjax>#C_10H_8#</mathjax>, probably napthalene.</p> <p>Capisce?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula is <mathjax>#C_10H_8#</mathjax>. How do we know?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is ALWAYS a mulitple of the empirical formula. Of course, the multiple might be <mathjax>#1#</mathjax>.</p> <p>So <mathjax>#"MF" =(EF)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5xx12.011gmol^-1+ 4xx1.00794gmol^-1)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(64.08)gmol^-1xxn= 128.16g*mol^-1.#</mathjax></p> <p>Clearly, <mathjax>#n=2#</mathjax>, and molecular formula <mathjax>#=#</mathjax> <mathjax>#C_10H_8#</mathjax>, probably napthalene.</p> <p>Capisce?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The empirical formula is #C_5H_4# and its molar mass is 128.16 g/mol. What is the molecular formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="226220" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-14T15:59:17" itemprop="dateCreated"> Feb 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molecular formula is <mathjax>#C_10H_8#</mathjax>. How do we know?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula is ALWAYS a mulitple of the empirical formula. Of course, the multiple might be <mathjax>#1#</mathjax>.</p> <p>So <mathjax>#"MF" =(EF)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5xx12.011gmol^-1+ 4xx1.00794gmol^-1)_n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(64.08)gmol^-1xxn= 128.16g*mol^-1.#</mathjax></p> <p>Clearly, <mathjax>#n=2#</mathjax>, and molecular formula <mathjax>#=#</mathjax> <mathjax>#C_10H_8#</mathjax>, probably napthalene.</p> <p>Capisce?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/226220" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16238 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The empirical formula is #C_5H_4# and its molar mass is 128.16 g/mol. What is the molecular formula?	null
2,737	a8bc8118-6ddd-11ea-b18d-ccda262736ce	https://socratic.org/questions/a-sample-of-hydrogen-at-47-c-exerts-a-pressure-of-329-atm-the-gas-is-heated-to-7	0.36 atm	start physical_unit 13 14 pressure atm qc_end physical_unit 1 3 5 6 temperature qc_end physical_unit 13 14 18 19 temperature qc_end physical_unit 1 3 11 12 pressure qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] atm"}]	[{"type":"physical unit","value":"0.36 atm"}]	[{"type":"physical unit","value":"Temperature1 [OF] the hydrogen sample [=] \\pu{47 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{77 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the hydrogen sample [=] \\pu{0.329 atm}"}]	<h1 class="questionTitle" itemprop="name">A sample of hydrogen at 47°C exerts a pressure of .329 atm. The gas is heated to 77°C at constant volume. What will its new pressure be?</h1>	null	0.36 atm	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming that Hydrogen is behaving ideally, therefore, we can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>:<mathjax>#PV=nRT#</mathjax></p> <p>Since the gas is being heated only and the volume is not changing, therefore, n and V are constant and therefore we can say:</p> <p><mathjax>#P/T=k#</mathjax> where <mathjax>#k=(nR)/V#</mathjax> is a constant value that does not change during the process.</p> <p>Thus, <mathjax>#(P_1)/(T_1)=(P_2)/(T_2)#</mathjax> This is called <strong>Gay-Lussac</strong> law.</p> <p><mathjax>#=>P_2=(P_1)/(T_1)xxT_2#</mathjax></p> <p><mathjax>#=>P_2=(0.329atm)/(320cancel(K))xx350cancel(K)=0.360atm#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_2=0.360atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming that Hydrogen is behaving ideally, therefore, we can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>:<mathjax>#PV=nRT#</mathjax></p> <p>Since the gas is being heated only and the volume is not changing, therefore, n and V are constant and therefore we can say:</p> <p><mathjax>#P/T=k#</mathjax> where <mathjax>#k=(nR)/V#</mathjax> is a constant value that does not change during the process.</p> <p>Thus, <mathjax>#(P_1)/(T_1)=(P_2)/(T_2)#</mathjax> This is called <strong>Gay-Lussac</strong> law.</p> <p><mathjax>#=>P_2=(P_1)/(T_1)xxT_2#</mathjax></p> <p><mathjax>#=>P_2=(0.329atm)/(320cancel(K))xx350cancel(K)=0.360atm#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of hydrogen at 47°C exerts a pressure of .329 atm. The gas is heated to 77°C at constant volume. What will its new pressure be?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="193905" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T08:55:48" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_2=0.360atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming that Hydrogen is behaving ideally, therefore, we can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>:<mathjax>#PV=nRT#</mathjax></p> <p>Since the gas is being heated only and the volume is not changing, therefore, n and V are constant and therefore we can say:</p> <p><mathjax>#P/T=k#</mathjax> where <mathjax>#k=(nR)/V#</mathjax> is a constant value that does not change during the process.</p> <p>Thus, <mathjax>#(P_1)/(T_1)=(P_2)/(T_2)#</mathjax> This is called <strong>Gay-Lussac</strong> law.</p> <p><mathjax>#=>P_2=(P_1)/(T_1)xxT_2#</mathjax></p> <p><mathjax>#=>P_2=(0.329atm)/(320cancel(K))xx350cancel(K)=0.360atm#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193905" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. 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The gas is heated to 77°C at constant volume. What will its new pressure be?	null
2,738	ac0405b8-6ddd-11ea-a35a-ccda262736ce	https://socratic.org/questions/calculate-the-ph-of-a-solution-formed-by-the-addition-of-10-0ml-of-0-050m-hydroc	2.08	start physical_unit 5 5 ph none qc_end physical_unit 5 5 11 12 volume qc_end physical_unit 16 17 14 15 molarity qc_end physical_unit 26 27 20 21 volume qc_end physical_unit 26 27 24 25 molarity qc_end chemical_equation 34 38 qc_end physical_unit 34 34 41 43 ka qc_end end	[{"type":"physical unit","value":"pH [OF] the solution"}]	[{"type":"physical unit","value":"2.08"}]	[{"type":"physical unit","value":"Volume [OF] hydrochloric acid solution [=] \\pu{10.0 mL}"},{"type":"physical unit","value":"Molarity [OF] hydrochloric acid solution [=] \\pu{0.050 M}"},{"type":"physical unit","value":"Volume [OF] acetic acid sample [=] \\pu{50.0 mL}"},{"type":"physical unit","value":"Molarity [OF] acetic acid sample [=] \\pu{0.20 M}"},{"type":"chemical equation","value":"HAc <=> Ac- + H+(aq)"},{"type":"physical unit","value":"Ka [OF] HAc [=] \\pu{1.8 × 10^(-5)}"}]	<h1 class="questionTitle" itemprop="name">Calculate the pH of a solution formed by the addition of 10.0mL of 0.050M hydrochloric acid to a 50.0mL sample of 0.20M acetic acid?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Consider the dissociation of acetic acid<br/> HAc <-> Ac- + H+(aq) Ka=1.8x10-5.</p> <p>Calculate the pH of a solution formed by the addition of 10.0mL of 0.050M<br/> hydrochloric acid to a 50.0mL sample of 0.20M acetic acid?</p></div> </h2> </div> </div>	2.08	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The strong acid <mathjax>#"HCl"#</mathjax> will almost completely suppress the ionization of the weak acid <mathjax>#"HAc"#</mathjax>.</p> <p>Thus, we need to consider only the contribution of <mathjax>#"H"_3"O"^"+"#</mathjax> from the <mathjax>#"HCl"#</mathjax>.</p> <blockquote></blockquote> <p>The equation for the dissociation of <mathjax>#"HCl"#</mathjax> is</p> <p><mathjax>#"HCl + H"_2"O" → "H"_3"O"^"+" + "Cl"^"-"#</mathjax></p> <p><mathjax>#"Moles of HCl" = 0.0100 color(red)(cancel(color(black)("L HCl"))) × "0.050 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.000 50 mol HCl"#</mathjax></p> <blockquote></blockquote> <p>Since <mathjax>#"HCl"#</mathjax> is a strong acid, it will dissociate completely to form 0.0050 mol of <mathjax>#"H"_3"O"^"+"#</mathjax>.</p> <p>The volume of the solution is</p> <p><mathjax>#V= "10.0 mL + 50.0 mL" = "60.0 mL" = "0.060 L"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#["H"_3"O"^"+"] = "moles"/"litres" = "0.000 50 mol"/"0.060 L" = "0.008 33 mol/L"#</mathjax></p> <p><mathjax>#"pH" = -log["H"_3"O"^"+"] = "-"log("0.00 833") = 2.08#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <mathjax>#"pH"#</mathjax> will be 2.08.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The strong acid <mathjax>#"HCl"#</mathjax> will almost completely suppress the ionization of the weak acid <mathjax>#"HAc"#</mathjax>.</p> <p>Thus, we need to consider only the contribution of <mathjax>#"H"_3"O"^"+"#</mathjax> from the <mathjax>#"HCl"#</mathjax>.</p> <blockquote></blockquote> <p>The equation for the dissociation of <mathjax>#"HCl"#</mathjax> is</p> <p><mathjax>#"HCl + H"_2"O" → "H"_3"O"^"+" + "Cl"^"-"#</mathjax></p> <p><mathjax>#"Moles of HCl" = 0.0100 color(red)(cancel(color(black)("L HCl"))) × "0.050 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.000 50 mol HCl"#</mathjax></p> <blockquote></blockquote> <p>Since <mathjax>#"HCl"#</mathjax> is a strong acid, it will dissociate completely to form 0.0050 mol of <mathjax>#"H"_3"O"^"+"#</mathjax>.</p> <p>The volume of the solution is</p> <p><mathjax>#V= "10.0 mL + 50.0 mL" = "60.0 mL" = "0.060 L"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#["H"_3"O"^"+"] = "moles"/"litres" = "0.000 50 mol"/"0.060 L" = "0.008 33 mol/L"#</mathjax></p> <p><mathjax>#"pH" = -log["H"_3"O"^"+"] = "-"log("0.00 833") = 2.08#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the pH of a solution formed by the addition of 10.0mL of 0.050M hydrochloric acid to a 50.0mL sample of 0.20M acetic acid?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Consider the dissociation of acetic acid<br/> HAc <-> Ac- + H+(aq) Ka=1.8x10-5.</p> <p>Calculate the pH of a solution formed by the addition of 10.0mL of 0.050M<br/> hydrochloric acid to a 50.0mL sample of 0.20M acetic acid?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="351453" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-14T02:24:51" itemprop="dateCreated"> Dec 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <mathjax>#"pH"#</mathjax> will be 2.08.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The strong acid <mathjax>#"HCl"#</mathjax> will almost completely suppress the ionization of the weak acid <mathjax>#"HAc"#</mathjax>.</p> <p>Thus, we need to consider only the contribution of <mathjax>#"H"_3"O"^"+"#</mathjax> from the <mathjax>#"HCl"#</mathjax>.</p> <blockquote></blockquote> <p>The equation for the dissociation of <mathjax>#"HCl"#</mathjax> is</p> <p><mathjax>#"HCl + H"_2"O" → "H"_3"O"^"+" + "Cl"^"-"#</mathjax></p> <p><mathjax>#"Moles of HCl" = 0.0100 color(red)(cancel(color(black)("L HCl"))) × "0.050 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.000 50 mol HCl"#</mathjax></p> <blockquote></blockquote> <p>Since <mathjax>#"HCl"#</mathjax> is a strong acid, it will dissociate completely to form 0.0050 mol of <mathjax>#"H"_3"O"^"+"#</mathjax>.</p> <p>The volume of the solution is</p> <p><mathjax>#V= "10.0 mL + 50.0 mL" = "60.0 mL" = "0.060 L"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#["H"_3"O"^"+"] = "moles"/"litres" = "0.000 50 mol"/"0.060 L" = "0.008 33 mol/L"#</mathjax></p> <p><mathjax>#"pH" = -log["H"_3"O"^"+"] = "-"log("0.00 833") = 2.08#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/351453" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How 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src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calculate the pH of a solution formed by the addition of 10.0mL of 0.050M hydrochloric acid to a 50.0mL sample of 0.20M acetic acid?	Consider the dissociation of acetic acid HAc <-> Ac- + H+(aq) Ka=1.8x10-5. Calculate the pH of a solution formed by the addition of 10.0mL of 0.050M hydrochloric acid to a 50.0mL sample of 0.20M acetic acid?
2,739	acda8525-6ddd-11ea-8eac-ccda262736ce	https://socratic.org/questions/58933cea7c0149300b481dbb	120.39 moles	start physical_unit 9 11 mole mol qc_end physical_unit 9 11 6 8 number qc_end end	[{"type":"physical unit","value":"Mole [OF] carbon dioxide molecules [IN] moles"}]	[{"type":"physical unit","value":"120.39 moles"}]	[{"type":"physical unit","value":"Number [OF] carbon dioxide molecules [=] \\pu{7.25 × 10^25}"}]	<h1 class="questionTitle" itemprop="name">How many moles are present in #7.25xx10^25# #"carbon dioxide molecules"#?</h1>	null	120.39 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus we work out the quotient:</p> <p><mathjax>#(7.2xx10^25"carbon dioxide molecules")/(6.022xx10^23"carbon dioxide molecules"mol^-1)#</mathjax></p> <p><mathjax>#~=120mol#</mathjax> <mathjax>#"carbon dioxide"#</mathjax>.</p> <p>This is dimensionally consistent, because we get an answer with units <mathjax>#1/(mol^-1)=1/(1/"mol")=mol#</mathjax> as required. </p> <p>Do you agree?</p> <p>What is the mass of this quantity of carbon dioxide?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well one mole of stuff, any stuff, including carbon dioxide, specifies <mathjax>#6.022xx10^23#</mathjax> individual items of that stuff.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus we work out the quotient:</p> <p><mathjax>#(7.2xx10^25"carbon dioxide molecules")/(6.022xx10^23"carbon dioxide molecules"mol^-1)#</mathjax></p> <p><mathjax>#~=120mol#</mathjax> <mathjax>#"carbon dioxide"#</mathjax>.</p> <p>This is dimensionally consistent, because we get an answer with units <mathjax>#1/(mol^-1)=1/(1/"mol")=mol#</mathjax> as required. </p> <p>Do you agree?</p> <p>What is the mass of this quantity of carbon dioxide?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are present in #7.25xx10^25# #"carbon dioxide molecules"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="372551" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-02T14:31:47" itemprop="dateCreated"> Feb 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well one mole of stuff, any stuff, including carbon dioxide, specifies <mathjax>#6.022xx10^23#</mathjax> individual items of that stuff.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus we work out the quotient:</p> <p><mathjax>#(7.2xx10^25"carbon dioxide molecules")/(6.022xx10^23"carbon dioxide molecules"mol^-1)#</mathjax></p> <p><mathjax>#~=120mol#</mathjax> <mathjax>#"carbon dioxide"#</mathjax>.</p> <p>This is dimensionally consistent, because we get an answer with units <mathjax>#1/(mol^-1)=1/(1/"mol")=mol#</mathjax> as required. </p> <p>Do you agree?</p> <p>What is the mass of this quantity of carbon dioxide?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/372551" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div 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</ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3825 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are present in #7.25xx10^25# #"carbon dioxide molecules"#?	null
2,740	ac0fd628-6ddd-11ea-a3f3-ccda262736ce	https://socratic.org/questions/what-is-the-molality-of-a-water-solution-that-boils-at-101-70-c	3.32 mol/kg	start physical_unit 6 7 molality mol/kg qc_end physical_unit 6 7 11 12 temperature qc_end end	[{"type":"physical unit","value":"Molality [OF] water solution [IN] mol/kg"}]	[{"type":"physical unit","value":"3.32 mol/kg"}]	[{"type":"physical unit","value":"Temperature [OF] water solution [=] \\pu{101.70 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the molality of a water solution that boils at 101.70°C?</h1>	null	3.32 mol/kg	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Water has a <mathjax>#K_b#</mathjax> of <mathjax>#"0.512 °C·kg·mol"^"-1"#</mathjax> of ions or molecules in solution.</p> <p>This means that, for every mole of particles in 1 kg of water, the interference with the water molecules will raise the boiling point by 0.512 °C.</p> <p>The normal boiling of water is 100.00 °C. </p> <p>101.70 - 100.00 = 1.70, so the increase of the boiling point is 1.70 °C.</p> <p><mathjax>#ΔT_b = K_bm#</mathjax></p> <p>∴ <mathjax>#m =( ΔT_b)/K_b = "1.70 °C"/("0.512 °C·kg·mol"^"-1") = "3.32 mol·kg"^"-1"#</mathjax></p> <p>The molality is 3.32 m.</p> <p>This molality could be achieved by dissolving 1 mol of a salt like <mathjax>#"CaCl"_2#</mathjax>, which ionizes into three particles, in 1 kg of water or by dissolving 3 mol of a compound like sugar in 1 kg of water.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution is 3.32 mol/kg.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Water has a <mathjax>#K_b#</mathjax> of <mathjax>#"0.512 °C·kg·mol"^"-1"#</mathjax> of ions or molecules in solution.</p> <p>This means that, for every mole of particles in 1 kg of water, the interference with the water molecules will raise the boiling point by 0.512 °C.</p> <p>The normal boiling of water is 100.00 °C. </p> <p>101.70 - 100.00 = 1.70, so the increase of the boiling point is 1.70 °C.</p> <p><mathjax>#ΔT_b = K_bm#</mathjax></p> <p>∴ <mathjax>#m =( ΔT_b)/K_b = "1.70 °C"/("0.512 °C·kg·mol"^"-1") = "3.32 mol·kg"^"-1"#</mathjax></p> <p>The molality is 3.32 m.</p> <p>This molality could be achieved by dissolving 1 mol of a salt like <mathjax>#"CaCl"_2#</mathjax>, which ionizes into three particles, in 1 kg of water or by dissolving 3 mol of a compound like sugar in 1 kg of water.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molality of a water solution that boils at 101.70°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molality" itemprop="url"> <span class="breadcrumb" itemprop="title">Molality</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296254" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-06T21:07:52" itemprop="dateCreated"> Aug 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution is 3.32 mol/kg.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Water has a <mathjax>#K_b#</mathjax> of <mathjax>#"0.512 °C·kg·mol"^"-1"#</mathjax> of ions or molecules in solution.</p> <p>This means that, for every mole of particles in 1 kg of water, the interference with the water molecules will raise the boiling point by 0.512 °C.</p> <p>The normal boiling of water is 100.00 °C. </p> <p>101.70 - 100.00 = 1.70, so the increase of the boiling point is 1.70 °C.</p> <p><mathjax>#ΔT_b = K_bm#</mathjax></p> <p>∴ <mathjax>#m =( ΔT_b)/K_b = "1.70 °C"/("0.512 °C·kg·mol"^"-1") = "3.32 mol·kg"^"-1"#</mathjax></p> <p>The molality is 3.32 m.</p> <p>This molality could be achieved by dissolving 1 mol of a salt like <mathjax>#"CaCl"_2#</mathjax>, which ionizes into three particles, in 1 kg of water or by dissolving 3 mol of a compound like sugar in 1 kg of water.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296254" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-molality-and-molarity-differ"> How do molality and molarity differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molality-be"> How high can molality be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molality-from-molarity"> How do you calculate molality from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-used-for-colligative-properties"> Why is molality used for colligative properties? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-independent-of-temperature"> Why is molality independent of temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-molality-when-75-0-grams-of-mgcl2-is-dissolved-in-500-0-"> How can I calculate the molality when 75.0 grams of MgCl2 is dissolved in 500.0 g of solvent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/49-8-grams-of-ki-is-dissolved-in-1-00-kg-of-solvent-what-is-the-molality"> 49.8 grams of KI is dissolved in 1.00 kg of solvent. 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2,741	ab462cc0-6ddd-11ea-959d-ccda262736ce	https://socratic.org/questions/combustion-of-a-0-9827-g-sample-of-a-compound-containing-only-carbon-hydrogen-an	C4H11O2	start chemical_formula qc_end physical_unit 8 8 3 4 mass qc_end c_other OTHER qc_end physical_unit 19 19 16 17 mass qc_end physical_unit 24 24 21 22 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]	[{"type":"chemical equation","value":"C4H11O2"}]	[{"type":"physical unit","value":"Mass [OF] a compound sample [=] \\pu{0.9827 g}"},{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{1.900 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{1.070 g}"},{"type":"other","value":"A sample of a compound contains only carbon, hydrogen, and oxygen."}]	<h1 class="questionTitle" itemprop="name">Combustion of a 0.9827 g sample of a compound containing only carbon, hydrogen, and oxygen produced 1.900 g of #CO_2# and 1.070 g of #H_2O#. What is the empirical formula of the compound? </h1>	null	C4H11O2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here is the equation with masses:</p> <p><mathjax>#"0.9827 g C"_a"H"_b"O"_c + "(1.900 g + 1.070 g - 0.9827 g) O"_2 rarr "1.070 g H"_2"O" + "1.900 g CO"_2#</mathjax></p> <p>Use 32.00 g/mol for the molar mass of <mathjax>#"O"_2#</mathjax><br/> Use 18.03 g/mol for the molar mass of <mathjax>#"H"_2"O"#</mathjax><br/> Use 44.01 g/mol for the molar mass of <mathjax>#"CO"_2#</mathjax></p> <p>We do not know the molar mass of the hydrocarbon so we allow <mathjax>#a, b#</mathjax>, and <mathjax>#c#</mathjax> to be any positive real number.</p> <p><mathjax>#"C"_a"H"_b"O"_c+ ("1.9873 g")/("32.00 g/mol") "O"_2 rarr ("1.070 g")/("18.03 g/mol") "H"_2"O" + ("1.900 g")/("44.01 g/mol") "CO"_2#</mathjax></p> <blockquote></blockquote> <p>Perform the division:</p> <p><mathjax>#"C"_a"H"_b"O"_c+ ("0.06210 mol") "O"_2 rarr ("0.05935 mol") "H"_2"O" + ("0.04317 mol") "CO"_2#</mathjax></p> <blockquote></blockquote> <p>Matching coefficients, we get:</p> <p><mathjax>#a = 0.04317#</mathjax><br/> <mathjax>#b = 2 xx 0.05935 = 0.1187#</mathjax> <br/> <mathjax>#c = 0.05935 + 2 xx 0.04317 - 2 xx 0.06210 = 0.02149#</mathjax></p> <blockquote></blockquote> <p>Divide every number by 0.02149:</p> <p><mathjax>#a/0.02149 = 2.009#</mathjax><br/> <mathjax>#b/0.02149 = 5.523#</mathjax> <br/> <mathjax>#c/0.02149 = 1#</mathjax></p> <blockquote></blockquote> <p>Multiply every number by 2:</p> <p><mathjax>#2.009 xx 2 = 4.018#</mathjax><br/> <mathjax>#5.523 xx 2 = 11.05#</mathjax><br/> <mathjax>#1 xx 2 = 2#</mathjax></p> <p>Round off each number to the nearest integer.</p> <p><mathjax>#4.018 ≈ color(white)(l)4#</mathjax><br/> <mathjax>#11.05 ≈ 11#</mathjax><br/> <mathjax>#color(white)(ll)2color(white)(ml) =color(white)(ll) 2#</mathjax></p> <blockquote></blockquote> <p>The empirical formula is <mathjax>#"C"_4"H"_11"O"_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"C"_4"H"_11"O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here is the equation with masses:</p> <p><mathjax>#"0.9827 g C"_a"H"_b"O"_c + "(1.900 g + 1.070 g - 0.9827 g) O"_2 rarr "1.070 g H"_2"O" + "1.900 g CO"_2#</mathjax></p> <p>Use 32.00 g/mol for the molar mass of <mathjax>#"O"_2#</mathjax><br/> Use 18.03 g/mol for the molar mass of <mathjax>#"H"_2"O"#</mathjax><br/> Use 44.01 g/mol for the molar mass of <mathjax>#"CO"_2#</mathjax></p> <p>We do not know the molar mass of the hydrocarbon so we allow <mathjax>#a, b#</mathjax>, and <mathjax>#c#</mathjax> to be any positive real number.</p> <p><mathjax>#"C"_a"H"_b"O"_c+ ("1.9873 g")/("32.00 g/mol") "O"_2 rarr ("1.070 g")/("18.03 g/mol") "H"_2"O" + ("1.900 g")/("44.01 g/mol") "CO"_2#</mathjax></p> <blockquote></blockquote> <p>Perform the division:</p> <p><mathjax>#"C"_a"H"_b"O"_c+ ("0.06210 mol") "O"_2 rarr ("0.05935 mol") "H"_2"O" + ("0.04317 mol") "CO"_2#</mathjax></p> <blockquote></blockquote> <p>Matching coefficients, we get:</p> <p><mathjax>#a = 0.04317#</mathjax><br/> <mathjax>#b = 2 xx 0.05935 = 0.1187#</mathjax> <br/> <mathjax>#c = 0.05935 + 2 xx 0.04317 - 2 xx 0.06210 = 0.02149#</mathjax></p> <blockquote></blockquote> <p>Divide every number by 0.02149:</p> <p><mathjax>#a/0.02149 = 2.009#</mathjax><br/> <mathjax>#b/0.02149 = 5.523#</mathjax> <br/> <mathjax>#c/0.02149 = 1#</mathjax></p> <blockquote></blockquote> <p>Multiply every number by 2:</p> <p><mathjax>#2.009 xx 2 = 4.018#</mathjax><br/> <mathjax>#5.523 xx 2 = 11.05#</mathjax><br/> <mathjax>#1 xx 2 = 2#</mathjax></p> <p>Round off each number to the nearest integer.</p> <p><mathjax>#4.018 ≈ color(white)(l)4#</mathjax><br/> <mathjax>#11.05 ≈ 11#</mathjax><br/> <mathjax>#color(white)(ll)2color(white)(ml) =color(white)(ll) 2#</mathjax></p> <blockquote></blockquote> <p>The empirical formula is <mathjax>#"C"_4"H"_11"O"_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Combustion of a 0.9827 g sample of a compound containing only carbon, hydrogen, and oxygen produced 1.900 g of #CO_2# and 1.070 g of #H_2O#. What is the empirical formula of the compound? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="387213" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/douglas-k"><img alt="" class="" src="https://graph.facebook.com/10206526058779249/picture?height=50&width=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/douglas-k"> Douglas K. </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-06T04:52:02" itemprop="dateCreated"> Mar 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"C"_4"H"_11"O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here is the equation with masses:</p> <p><mathjax>#"0.9827 g C"_a"H"_b"O"_c + "(1.900 g + 1.070 g - 0.9827 g) O"_2 rarr "1.070 g H"_2"O" + "1.900 g CO"_2#</mathjax></p> <p>Use 32.00 g/mol for the molar mass of <mathjax>#"O"_2#</mathjax><br/> Use 18.03 g/mol for the molar mass of <mathjax>#"H"_2"O"#</mathjax><br/> Use 44.01 g/mol for the molar mass of <mathjax>#"CO"_2#</mathjax></p> <p>We do not know the molar mass of the hydrocarbon so we allow <mathjax>#a, b#</mathjax>, and <mathjax>#c#</mathjax> to be any positive real number.</p> <p><mathjax>#"C"_a"H"_b"O"_c+ ("1.9873 g")/("32.00 g/mol") "O"_2 rarr ("1.070 g")/("18.03 g/mol") "H"_2"O" + ("1.900 g")/("44.01 g/mol") "CO"_2#</mathjax></p> <blockquote></blockquote> <p>Perform the division:</p> <p><mathjax>#"C"_a"H"_b"O"_c+ ("0.06210 mol") "O"_2 rarr ("0.05935 mol") "H"_2"O" + ("0.04317 mol") "CO"_2#</mathjax></p> <blockquote></blockquote> <p>Matching coefficients, we get:</p> <p><mathjax>#a = 0.04317#</mathjax><br/> <mathjax>#b = 2 xx 0.05935 = 0.1187#</mathjax> <br/> <mathjax>#c = 0.05935 + 2 xx 0.04317 - 2 xx 0.06210 = 0.02149#</mathjax></p> <blockquote></blockquote> <p>Divide every number by 0.02149:</p> <p><mathjax>#a/0.02149 = 2.009#</mathjax><br/> <mathjax>#b/0.02149 = 5.523#</mathjax> <br/> <mathjax>#c/0.02149 = 1#</mathjax></p> <blockquote></blockquote> <p>Multiply every number by 2:</p> <p><mathjax>#2.009 xx 2 = 4.018#</mathjax><br/> <mathjax>#5.523 xx 2 = 11.05#</mathjax><br/> <mathjax>#1 xx 2 = 2#</mathjax></p> <p>Round off each number to the nearest integer.</p> <p><mathjax>#4.018 ≈ color(white)(l)4#</mathjax><br/> <mathjax>#11.05 ≈ 11#</mathjax><br/> <mathjax>#color(white)(ll)2color(white)(ml) =color(white)(ll) 2#</mathjax></p> <blockquote></blockquote> <p>The empirical formula is <mathjax>#"C"_4"H"_11"O"_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/387213" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="390180" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-12T17:39:30" itemprop="dateCreated"> Mar 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"C"_4"H"_11"O"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>First, we calculate the masses of <mathjax>#"C"#</mathjax> and <mathjax>#"H"#</mathjax> from the masses of their oxides (<mathjax>#"CO"_2#</mathjax> and <mathjax>#"H"_2"O"#</mathjax>).</p> <p><mathjax>#"Mass of C" = 1.900 color(red)(cancel(color(black)("g CO"_2))) × "12.01 g C"/(44.01 color(red)(cancel(color(black)("g CO"_2)))) = "0.5185 g C"#</mathjax></p> <p><mathjax>#"Mass of H" = 1.070 color(red)(cancel(color(black)("g H"_2"O"))) × "2.016 g H"/(18.02 color(red)(cancel(color(black)("g H"_2"O")))) = "0.1197 g H"#</mathjax></p> <p><mathjax>#"Mass of C + Mass of H" = "0.5185 g + 0.1197 g" = "0.6382 g"#</mathjax></p> <p>This is less than the mass of the sample.</p> <p>The missing mass must be caused by <mathjax>#"O"#</mathjax>.</p> <p><mathjax>#"Mass of O = 0.9827 g - 0.6382 g = 0.3445 g"#</mathjax></p> <blockquote></blockquote> <p>Now, we must convert these masses to moles and find their ratios.</p> <p>From here on, I like to summarize the calculations in a table.</p> <p><mathjax>#bb("Element"color(white)(X) "Mass/g"color(white)(X) "Moles"color(white)(mm) "Ratio"color(white)(ml)×2color(white)(mm)"Integers")#</mathjax><br/> <mathjax>#color(white)(ml)"C" color(white)(XXXm)0.5185 color(white)(mll)0.04317color(white)(Xmlll)2.005color(white)(m)4.010color(white)(Xmmml)4#</mathjax><br/> <mathjax>#color(white)(ml)"H" color(white)(XXXm)0.1197 color(white)(mll)0.1188 color(white)(mmml)5.518 color(white)(m)11.04color(white)(Xmmm)11#</mathjax><br/> <mathjax>#color(white)(ml)"O" color(white)(XXXm)0.3445 color(white)(mll)0.02153 color(white)(mmm)1 color(white)(mmml)2color(white)(Xmmmmm)2#</mathjax></p> <p>The <strong>empirical formula</strong> is <mathjax>#"C"_4"H"_11"O"_2#</mathjax>.</p> <blockquote></blockquote> <p><strong>Note</strong>: This is an impossible empirical formula.</p> <p>The molecular formula must have an even number of <mathjax>#"H"#</mathjax> atoms, e.g. <mathjax>#"C"_8"H"_22"O"_4#</mathjax>.</p> <p>A compound with 8 <mathjax>#"C"#</mathjax> atoms can contain no more than 18 <mathjax>#"H"#</mathjax> atoms.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/390180" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 49777 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Combustion of a 0.9827 g sample of a compound containing only carbon, hydrogen, and oxygen produced 1.900 g of #CO_2# and 1.070 g of #H_2O#. What is the empirical formula of the compound?	null
2,742	aa90d83e-6ddd-11ea-a262-ccda262736ce	https://socratic.org/questions/how-many-oxygens-are-there-in-mg-3-po-4-2	8	start physical_unit 2 2 number none qc_end chemical_equation 6 6 qc_end end	[{"type":"physical unit","value":"Number [OF] oxygens"}]	[{"type":"physical unit","value":"8"}]	[{"type":"chemical equation","value":"Mg3(PO4)2"}]	<h1 class="questionTitle" itemprop="name">How many oxygens are there in #Mg_3(PO_4)_2#?</h1>	null	8	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All I have done is simply expand the formula using the multiplier on the brackets. One formula unit of <mathjax>#Mg_3(PO_4)_2#</mathjax> contains <mathjax>#3#</mathjax> <mathjax>#"magnesium atoms"#</mathjax>, <mathjax>#2#</mathjax> <mathjax>#"phosphorus atoms"#</mathjax>, and <mathjax>#3#</mathjax> <mathjax>#"magnesium atoms"#</mathjax>.</p> <p>Can you give the atom number breakdown of the salt magnesium biphosphate, <mathjax>#Mg(HPO_4)#</mathjax>? Why is this a 1:1 salt and not 3:2?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In the one formula unit of <mathjax>#Mg_3(PO_4)_2#</mathjax> there are <mathjax>#8#</mathjax> individual oxygen atoms. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All I have done is simply expand the formula using the multiplier on the brackets. One formula unit of <mathjax>#Mg_3(PO_4)_2#</mathjax> contains <mathjax>#3#</mathjax> <mathjax>#"magnesium atoms"#</mathjax>, <mathjax>#2#</mathjax> <mathjax>#"phosphorus atoms"#</mathjax>, and <mathjax>#3#</mathjax> <mathjax>#"magnesium atoms"#</mathjax>.</p> <p>Can you give the atom number breakdown of the salt magnesium biphosphate, <mathjax>#Mg(HPO_4)#</mathjax>? Why is this a 1:1 salt and not 3:2?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many oxygens are there in #Mg_3(PO_4)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232099" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-27T17:48:40" itemprop="dateCreated"> Feb 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In the one formula unit of <mathjax>#Mg_3(PO_4)_2#</mathjax> there are <mathjax>#8#</mathjax> individual oxygen atoms. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>All I have done is simply expand the formula using the multiplier on the brackets. One formula unit of <mathjax>#Mg_3(PO_4)_2#</mathjax> contains <mathjax>#3#</mathjax> <mathjax>#"magnesium atoms"#</mathjax>, <mathjax>#2#</mathjax> <mathjax>#"phosphorus atoms"#</mathjax>, and <mathjax>#3#</mathjax> <mathjax>#"magnesium atoms"#</mathjax>.</p> <p>Can you give the atom number breakdown of the salt magnesium biphosphate, <mathjax>#Mg(HPO_4)#</mathjax>? Why is this a 1:1 salt and not 3:2?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232099" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1735 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many oxygens are there in #Mg_3(PO_4)_2#?	null
2,743	ac1347d4-6ddd-11ea-9fda-ccda262736ce	https://socratic.org/questions/the-equation-for-the-combustion-of-glucose-is-c6h12o6-s-6o2-g-gt-6co2-g-6h2o-g-h	4.83 grams	start physical_unit 17 17 mass g qc_end physical_unit 6 6 27 28 mass qc_end chemical_equation 8 17 qc_end end	[{"type":"physical unit","value":"Mass [OF] H2O [IN] grams"}]	[{"type":"physical unit","value":"4.83 grams"}]	[{"type":"physical unit","value":"Mass [OF] glucose [=] \\pu{8.064 g}"},{"type":"chemical equation","value":"C6H12O6(s) + 6 O2(g) -> 6 CO2(g) + 6 H2O(g)"}]	<h1 class="questionTitle" itemprop="name">The equation for the combustion of glucose is: C6H12O6(s) + 6O2(g) --&gt; 6CO2(g) + 6H2O(g). How many grams of H2O will be produced when 8.064g of glucose is burned?</h1>	null	4.83 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_6H_12O_6(s) + 6O_2(g) rarr 6CO_2(g) + 6H_2O(g)#</mathjax></p> <p>Moles of glucose, <mathjax>#=#</mathjax> <mathjax>#(8.064cancel(g))/(180.16cancel(g)*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.476xx10^-2#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>From the equation above, there will be approximately 0.8 g water produced.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Between 0.5 and 1.0 g of water.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_6H_12O_6(s) + 6O_2(g) rarr 6CO_2(g) + 6H_2O(g)#</mathjax></p> <p>Moles of glucose, <mathjax>#=#</mathjax> <mathjax>#(8.064cancel(g))/(180.16cancel(g)*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.476xx10^-2#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>From the equation above, there will be approximately 0.8 g water produced.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The equation for the combustion of glucose is: C6H12O6(s) + 6O2(g) --&gt; 6CO2(g) + 6H2O(g). How many grams of H2O will be produced when 8.064g of glucose is burned?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192357" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-23T21:30:55" itemprop="dateCreated"> Nov 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Between 0.5 and 1.0 g of water.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_6H_12O_6(s) + 6O_2(g) rarr 6CO_2(g) + 6H_2O(g)#</mathjax></p> <p>Moles of glucose, <mathjax>#=#</mathjax> <mathjax>#(8.064cancel(g))/(180.16cancel(g)*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.476xx10^-2#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>From the equation above, there will be approximately 0.8 g water produced.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192357" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3761 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The equation for the combustion of glucose is: C6H12O6(s) + 6O2(g) --&gt; 6CO2(g) + 6H2O(g). How many grams of H2O will be produced when 8.064g of glucose is burned?	null
2,744	acf3d5e8-6ddd-11ea-9498-ccda262736ce	https://socratic.org/questions/calculate-e-cell-for-this-reaction-when-h-4-5-m-and-hso-4-4-5-m-if-e-cell-2-04-v	2.12 V	start physical_unit 3 4 ecell v qc_end physical_unit 3 4 18 19 ecell qc_end chemical_equation 20 33 qc_end end	[{"type":"physical unit","value":"Ecell [OF] this reaction [IN] V"}]	[{"type":"physical unit","value":"2.12 V"}]	[{"type":"physical unit","value":"[H+] [OF] solution [=] \\pu{4.5 M}"},{"type":"physical unit","value":"[HSO4-] [OF] solution [=] \\pu{4.5 M}"},{"type":"physical unit","value":"E^0_{cell} [OF] this reaction [=] \\pu{2.04 V}"},{"type":"chemical equation","value":"Pb(s) + PbO2(s) + 2 H+(aq) + 2 HSO4-(aq) <=> 2 PbSO4(s) + 2H2O(l)"}]	<h1 class="questionTitle" itemprop="name">Calculate #E_("cell")# for this reaction when [#H^+#] = 4.5 M and [#HSO_4^-#] = 4.5 M, if #E°_("cell")# = 2.04 V?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#Pb"(s)"+PbO_2"(s)"+2H^+"(aq)"+2HSO_4^-"(aq)"\rightleftharpoons2PbSO_4"(s)"+2H_2O"(l)"#</mathjax></p> <p>I can't find <mathjax>#n#</mathjax> in the formula.<br/> <mathjax>#E_(cell)=E°_(cell)-0.0592/nV\logQ#</mathjax></p> <p><mathjax>#Q=1/(4.5)^4#</mathjax></p></div> </h2> </div> </div>	2.12 V	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n#</mathjax> stands for the number of electrons transferred per mole of atom in the reaction. </p> <p>Find <mathjax>#n#</mathjax> by writing the half reactions going on in each cell at each electrode:</p> <p>Anode/Oxidation:</p> <blockquote> <p><mathjax>#stackrel(0)("Pb")(s)to stackrel(+2color(white)(D-))("Pb"^(2+))(aq) + color(blue)(2)color(white)(l) "e"^(-)#</mathjax></p> </blockquote> <p>Cathode/Reduction:</p> <blockquote> <p><mathjax>#stackrel(+4)("Pb")"O"_2(s) +2color(white)(l) "H"^(+) (aq) + color(blue)(2)color(white)(l) "e"^(-) to stackrel(+2color(white)(D-))("Pb"^(2+))(aq) + "H"_2"O"#</mathjax></p> </blockquote> <p>Thus each mole of the reaction involves the transfer of two moles of electrons, <mathjax>#n = 2#</mathjax>. The lead (II) ion would then combine with sulfate ions to form the lead (II) sulfate precipitate.</p> <p>The Nernst equation:</p> <blockquote> <p><mathjax>#E_(cell)=E°_(cell)-(0.0592 color(white)(l) "V")/n\logQ#</mathjax></p> <p>(<mathjax>#"V"#</mathjax> as in voltage)</p> <p><mathjax>#E_("cell") = "2.04 V" - ("0.0592 V"/("2 mol e"^(-)"/mol atoms")) * log(1/((4.5)^2(4.5)^2))#</mathjax></p> <p><mathjax>#= 2.12 color(white)(l) "V"#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#E_("cell") = 2.12 color(white)(l) "V"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n#</mathjax> stands for the number of electrons transferred per mole of atom in the reaction. </p> <p>Find <mathjax>#n#</mathjax> by writing the half reactions going on in each cell at each electrode:</p> <p>Anode/Oxidation:</p> <blockquote> <p><mathjax>#stackrel(0)("Pb")(s)to stackrel(+2color(white)(D-))("Pb"^(2+))(aq) + color(blue)(2)color(white)(l) "e"^(-)#</mathjax></p> </blockquote> <p>Cathode/Reduction:</p> <blockquote> <p><mathjax>#stackrel(+4)("Pb")"O"_2(s) +2color(white)(l) "H"^(+) (aq) + color(blue)(2)color(white)(l) "e"^(-) to stackrel(+2color(white)(D-))("Pb"^(2+))(aq) + "H"_2"O"#</mathjax></p> </blockquote> <p>Thus each mole of the reaction involves the transfer of two moles of electrons, <mathjax>#n = 2#</mathjax>. The lead (II) ion would then combine with sulfate ions to form the lead (II) sulfate precipitate.</p> <p>The Nernst equation:</p> <blockquote> <p><mathjax>#E_(cell)=E°_(cell)-(0.0592 color(white)(l) "V")/n\logQ#</mathjax></p> <p>(<mathjax>#"V"#</mathjax> as in voltage)</p> <p><mathjax>#E_("cell") = "2.04 V" - ("0.0592 V"/("2 mol e"^(-)"/mol atoms")) * log(1/((4.5)^2(4.5)^2))#</mathjax></p> <p><mathjax>#= 2.12 color(white)(l) "V"#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate #E_("cell")# for this reaction when [#H^+#] = 4.5 M and [#HSO_4^-#] = 4.5 M, if #E°_("cell")# = 2.04 V?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#Pb"(s)"+PbO_2"(s)"+2H^+"(aq)"+2HSO_4^-"(aq)"\rightleftharpoons2PbSO_4"(s)"+2H_2O"(l)"#</mathjax></p> <p>I can't find <mathjax>#n#</mathjax> in the formula.<br/> <mathjax>#E_(cell)=E°_(cell)-0.0592/nV\logQ#</mathjax></p> <p><mathjax>#Q=1/(4.5)^4#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/galvanic-cells" itemprop="url"> <span class="breadcrumb" itemprop="title">Galvanic Cells</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="644208" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jacob-t-3"><img alt="" class="" src="https://profilepictures.socratic.org/cDl6OiFtT16bIyMtJPfM_Protractor.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jacob-t-3"> Jacob T. </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-28T15:28:36" itemprop="dateCreated"> Jul 28, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#E_("cell") = 2.12 color(white)(l) "V"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n#</mathjax> stands for the number of electrons transferred per mole of atom in the reaction. </p> <p>Find <mathjax>#n#</mathjax> by writing the half reactions going on in each cell at each electrode:</p> <p>Anode/Oxidation:</p> <blockquote> <p><mathjax>#stackrel(0)("Pb")(s)to stackrel(+2color(white)(D-))("Pb"^(2+))(aq) + color(blue)(2)color(white)(l) "e"^(-)#</mathjax></p> </blockquote> <p>Cathode/Reduction:</p> <blockquote> <p><mathjax>#stackrel(+4)("Pb")"O"_2(s) +2color(white)(l) "H"^(+) (aq) + color(blue)(2)color(white)(l) "e"^(-) to stackrel(+2color(white)(D-))("Pb"^(2+))(aq) + "H"_2"O"#</mathjax></p> </blockquote> <p>Thus each mole of the reaction involves the transfer of two moles of electrons, <mathjax>#n = 2#</mathjax>. The lead (II) ion would then combine with sulfate ions to form the lead (II) sulfate precipitate.</p> <p>The Nernst equation:</p> <blockquote> <p><mathjax>#E_(cell)=E°_(cell)-(0.0592 color(white)(l) "V")/n\logQ#</mathjax></p> <p>(<mathjax>#"V"#</mathjax> as in voltage)</p> <p><mathjax>#E_("cell") = "2.04 V" - ("0.0592 V"/("2 mol e"^(-)"/mol atoms")) * log(1/((4.5)^2(4.5)^2))#</mathjax></p> <p><mathjax>#= 2.12 color(white)(l) "V"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/644208" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-galvanic-cell-become-an-electrolytic-cell"> How can a galvanic cell become an electrolytic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-electrons-flow-in-a-galvanic-cell"> How do electrons flow in a galvanic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-galvanic-cell-potential"> How do you calculate galvanic cell potential? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-sketch-galvanic-cells"> How do you sketch galvanic cells? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-might-a-galvanic-cell-go-dead"> Why might a galvanic cell go dead? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5350796902bf343989038b3d"> Question #38b3d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-galvanic-cell"> What is a galvanic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-galvanic-cells"> What are some common mistakes students make with galvanic cells? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-galvanic-cell-practice-problem"> What is an example of a galvanic cell practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-energy-conversion-takes-place-in-a-galvanic-cell"> What energy conversion takes place in a galvanic cell? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/galvanic-cells"> See all questions in Galvanic Cells </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1698 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calculate #E_("cell")# for this reaction when [#H^+#] = 4.5 M and [#HSO_4^-#] = 4.5 M, if #E°_("cell")# = 2.04 V?	#Pb"(s)"+PbO_2"(s)"+2H^+"(aq)"+2HSO_4^-"(aq)"\rightleftharpoons2PbSO_4"(s)"+2H_2O"(l)"# I can't find #n# in the formula. #E_(cell)=E°_(cell)-0.0592/nV\logQ# #Q=1/(4.5)^4#
2,745	a8646838-6ddd-11ea-81b4-ccda262736ce	https://socratic.org/questions/the-pressure-on-30ml-of-a-gas-at-constant-temperature-is-changed-from-4-atm-to-2	60.00 mL	start physical_unit 6 7 volume ml qc_end physical_unit 6 7 3 4 volume qc_end physical_unit 6 7 14 15 pressure qc_end physical_unit 6 7 17 18 pressure qc_end c_other constant_temperature qc_end end	[{"type":"physical unit","value":"Volume2 [OF] a gas [IN] mL"}]	[{"type":"physical unit","value":"60.00 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] a gas [=] \\pu{30 mL}"},{"type":"physical unit","value":"Pressure1 [OF] a gas [=] \\pu{4 atm}"},{"type":"physical unit","value":"Pressure2 [OF] a gas [=] \\pu{2 atm}"},{"type":"other","value":"ConstantTemperature"}]	<h1 class="questionTitle" itemprop="name">The pressure on 30mL of a gas at constant temperature Is changed from 4 atm to 2 atm. What Is the new volume of a gas?</h1>	null	60.00 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <mathjax>#PV = k#</mathjax>, under these condtions, <mathjax>#P_1V_1 = P_2V_2#</mathjax>, so <mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax>; here <mathjax>#(30mLxx4cancel(atm))/(2*cancel(atm))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mL#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>At constant pressure, and constant amount of gas, <mathjax>#Pprop1/V or PV = k#</mathjax>, <a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <mathjax>#PV = k#</mathjax>, under these condtions, <mathjax>#P_1V_1 = P_2V_2#</mathjax>, so <mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax>; here <mathjax>#(30mLxx4cancel(atm))/(2*cancel(atm))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mL#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The pressure on 30mL of a gas at constant temperature Is changed from 4 atm to 2 atm. What Is the new volume of a gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196729" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-05T19:53:44" itemprop="dateCreated"> Dec 5, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>At constant pressure, and constant amount of gas, <mathjax>#Pprop1/V or PV = k#</mathjax>, <a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <mathjax>#PV = k#</mathjax>, under these condtions, <mathjax>#P_1V_1 = P_2V_2#</mathjax>, so <mathjax>#V_2=(P_1V_1)/(P_2)#</mathjax>; here <mathjax>#(30mLxx4cancel(atm))/(2*cancel(atm))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mL#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196729" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1893 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The pressure on 30mL of a gas at constant temperature Is changed from 4 atm to 2 atm. What Is the new volume of a gas?	null
2,746	ac510266-6ddd-11ea-8f43-ccda262736ce	https://socratic.org/questions/what-mass-of-mg-no-3-2-is-present-in-145-ml-of-a-150-m-solution-of-m5-no-3-2	3.23 grams	start physical_unit 3 3 mass g qc_end physical_unit 11 11 6 7 volume qc_end physical_unit 3 3 9 10 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] Mg(NO3)2 [IN] grams"}]	[{"type":"physical unit","value":"3.23 grams"}]	[{"type":"physical unit","value":"Volume [OF] Mg(NO3)2 solution [=] \\pu{145 mL}"},{"type":"physical unit","value":"Molarity [OF] Mg(NO3)2 solution [=] \\pu{0.150 M}"}]	<h1 class="questionTitle" itemprop="name">What mass of #Mg(NO_3)_2# is present in 145 mL of a .150 M solution of #Mg(NO_3)_2#?</h1>	null	3.23 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> and <strong>volume</strong> of the solution to figure out how many <em>moles</em> of magnesium nitrate, <mathjax>#"Mg"("NO"_3)_2#</mathjax>, you have in that sample. </p> <p>To do that, use the molarity of the solution as a conversion factor, but keep in mind that you must also convert the volume of the solution from <em>milliliters</em> to <em>liters</em></p> <blockquote> <p><mathjax>#145 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * ("0.150 moles Mg"("NO"_ 3)_ 2)/(1color(red)(cancel(color(black)("L solution")))#</mathjax></p> <blockquote> <blockquote> <p><mathjax>#= "0.02175 moles Mg"("NO"_3)_2#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Now all you have to do is to convert the number of moles of magnesium nitrate to <em>grams</em> by using the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#0.02175 color(red)(cancel(color(black)("moles Mg"("NO"_3)_2))) * "148.3 g"/(1color(red)(cancel(color(black)("mole Mg"("NO"_3)_2)))) = color(darkgreen)(ul(color(black)("3.23 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.23 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> and <strong>volume</strong> of the solution to figure out how many <em>moles</em> of magnesium nitrate, <mathjax>#"Mg"("NO"_3)_2#</mathjax>, you have in that sample. </p> <p>To do that, use the molarity of the solution as a conversion factor, but keep in mind that you must also convert the volume of the solution from <em>milliliters</em> to <em>liters</em></p> <blockquote> <p><mathjax>#145 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * ("0.150 moles Mg"("NO"_ 3)_ 2)/(1color(red)(cancel(color(black)("L solution")))#</mathjax></p> <blockquote> <blockquote> <p><mathjax>#= "0.02175 moles Mg"("NO"_3)_2#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Now all you have to do is to convert the number of moles of magnesium nitrate to <em>grams</em> by using the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#0.02175 color(red)(cancel(color(black)("moles Mg"("NO"_3)_2))) * "148.3 g"/(1color(red)(cancel(color(black)("mole Mg"("NO"_3)_2)))) = color(darkgreen)(ul(color(black)("3.23 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of #Mg(NO_3)_2# is present in 145 mL of a .150 M solution of #Mg(NO_3)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="370962" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-30T00:01:27" itemprop="dateCreated"> Jan 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.23 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> and <strong>volume</strong> of the solution to figure out how many <em>moles</em> of magnesium nitrate, <mathjax>#"Mg"("NO"_3)_2#</mathjax>, you have in that sample. </p> <p>To do that, use the molarity of the solution as a conversion factor, but keep in mind that you must also convert the volume of the solution from <em>milliliters</em> to <em>liters</em></p> <blockquote> <p><mathjax>#145 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * ("0.150 moles Mg"("NO"_ 3)_ 2)/(1color(red)(cancel(color(black)("L solution")))#</mathjax></p> <blockquote> <blockquote> <p><mathjax>#= "0.02175 moles Mg"("NO"_3)_2#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Now all you have to do is to convert the number of moles of magnesium nitrate to <em>grams</em> by using the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#0.02175 color(red)(cancel(color(black)("moles Mg"("NO"_3)_2))) * "148.3 g"/(1color(red)(cancel(color(black)("mole Mg"("NO"_3)_2)))) = color(darkgreen)(ul(color(black)("3.23 g")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/370962" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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2,747	a8b248b6-6ddd-11ea-a494-ccda262736ce	https://socratic.org/questions/how-many-moles-are-there-in-a-sample-of-49-grams-of-h-2so-4	0.5 moles	start physical_unit 12 12 mole mol qc_end physical_unit 12 12 9 10 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] H2SO4 sample [IN] moles"}]	[{"type":"physical unit","value":"0.5 moles"}]	[{"type":"physical unit","value":"Mass [OF] H2SO4 sample [=] \\pu{49 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles are there in a sample of 49 grams of #H_2SO_4#?</h1>	null	0.5 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the relationship of the molecular weight of sulfuric acid (98.08 g/mol) we can calculate the desired answer in moles.<br/> <mathjax>#(49 g)/(98.08 (g/(mol)) #</mathjax>= 0.5 moles</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.5</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the relationship of the molecular weight of sulfuric acid (98.08 g/mol) we can calculate the desired answer in moles.<br/> <mathjax>#(49 g)/(98.08 (g/(mol)) #</mathjax>= 0.5 moles</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are there in a sample of 49 grams of #H_2SO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/avogadro-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Avogadro's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="358443" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-31T01:25:38" itemprop="dateCreated"> Dec 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.5</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the relationship of the molecular weight of sulfuric acid (98.08 g/mol) we can calculate the desired answer in moles.<br/> <mathjax>#(49 g)/(98.08 (g/(mol)) #</mathjax>= 0.5 moles</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/358443" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-avogadro-s-law-important"> Why is Avogadro's law important? 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2,748	ab720069-6ddd-11ea-baad-ccda262736ce	https://socratic.org/questions/58a9d10f7c014911ef9fb7b3	0.13 M	start physical_unit 7 7 [h2so4] mol/l qc_end physical_unit 5 7 1 2 volume qc_end physical_unit 5 7 9 10 concentration qc_end physical_unit 20 21 17 18 volume qc_end end	[{"type":"physical unit","value":"[H2SO4] [OF] solution [IN] M"}]	[{"type":"physical unit","value":"0.13 M"}]	[{"type":"physical unit","value":"Volume [OF] sodium hydroxide solution [=] \\pu{25 mL}"},{"type":"physical unit","value":"Concentration [OF] sodium hydroxide solution [=] \\pu{0.150 mol/L}"},{"type":"physical unit","value":"sulfuric acid [OF] sulfuric acid [=] \\pu{15.0 mL}"}]	<h1 class="questionTitle" itemprop="name">A #25mL# volume of sodium hydroxide solution of #0.150molL^-1# concentration is stoichiometrically equivalent to a #15.0mL# of sulfuric acid. What is #[H_2SO_4]#?</h1>	null	0.13 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2SO_4(aq) + 2NaOH rarr Na_2SO_4(aq) + 2H_2O(l)#</mathjax>.</p> <p>And (ii) equivalent quantities of sodium hydroxide,</p> <p><mathjax>#"Moles of NaOH"=25.0mLxx10^-3LmL^-1xx0.150molL^-1=3.75xx10^-3mol#</mathjax></p> <p>Given the equation, we KNOW that there was a half an equiv of sulfuric acid present in the original volume of <mathjax>#H_2SO_4(aq)#</mathjax>.</p> <p>And thus <mathjax>#[H_2SO_4]=(1/2xx3.75xx10^-3mol)/(15.0xx10^-3L)~=0.13mol*L^-1#</mathjax></p> <p>All I have done here is to use the relationship:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution."#</mathjax></p> <p>And thus,</p> <p><mathjax>#"Concentration"xx"Volume"="Moles of solute"#</mathjax>, etc. etc...........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>To find <mathjax>#[H_2SO_4]#</mathjax>, we need (i), a stoichiometrically balanced equation:</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2SO_4(aq) + 2NaOH rarr Na_2SO_4(aq) + 2H_2O(l)#</mathjax>.</p> <p>And (ii) equivalent quantities of sodium hydroxide,</p> <p><mathjax>#"Moles of NaOH"=25.0mLxx10^-3LmL^-1xx0.150molL^-1=3.75xx10^-3mol#</mathjax></p> <p>Given the equation, we KNOW that there was a half an equiv of sulfuric acid present in the original volume of <mathjax>#H_2SO_4(aq)#</mathjax>.</p> <p>And thus <mathjax>#[H_2SO_4]=(1/2xx3.75xx10^-3mol)/(15.0xx10^-3L)~=0.13mol*L^-1#</mathjax></p> <p>All I have done here is to use the relationship:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution."#</mathjax></p> <p>And thus,</p> <p><mathjax>#"Concentration"xx"Volume"="Moles of solute"#</mathjax>, etc. etc...........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A #25mL# volume of sodium hydroxide solution of #0.150molL^-1# concentration is stoichiometrically equivalent to a #15.0mL# of sulfuric acid. What is #[H_2SO_4]#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="382196" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-24T06:40:40" itemprop="dateCreated"> Feb 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>To find <mathjax>#[H_2SO_4]#</mathjax>, we need (i), a stoichiometrically balanced equation:</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2SO_4(aq) + 2NaOH rarr Na_2SO_4(aq) + 2H_2O(l)#</mathjax>.</p> <p>And (ii) equivalent quantities of sodium hydroxide,</p> <p><mathjax>#"Moles of NaOH"=25.0mLxx10^-3LmL^-1xx0.150molL^-1=3.75xx10^-3mol#</mathjax></p> <p>Given the equation, we KNOW that there was a half an equiv of sulfuric acid present in the original volume of <mathjax>#H_2SO_4(aq)#</mathjax>.</p> <p>And thus <mathjax>#[H_2SO_4]=(1/2xx3.75xx10^-3mol)/(15.0xx10^-3L)~=0.13mol*L^-1#</mathjax></p> <p>All I have done here is to use the relationship:</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution."#</mathjax></p> <p>And thus,</p> <p><mathjax>#"Concentration"xx"Volume"="Moles of solute"#</mathjax>, etc. etc...........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/382196" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1384 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A #25mL# volume of sodium hydroxide solution of #0.150molL^-1# concentration is stoichiometrically equivalent to a #15.0mL# of sulfuric acid. What is #[H_2SO_4]#?	null
2,749	abefe55c-6ddd-11ea-aa69-ccda262736ce	https://socratic.org/questions/kc-for-the-equation-shown-below-is-0-543-at-425-degrees-c-h2-g-i2-g-2hi-g-what-i	1.84	start physical_unit 19 21 equilibrium_constant_k none qc_end physical_unit 3 4 8 8 equilibrium_constant_k qc_end physical_unit 3 4 10 11 temperature qc_end chemical_equation 22 27 qc_end end	[{"type":"physical unit","value":"Kc [OF] the reverse equation"}]	[{"type":"physical unit","value":"1.84"}]	[{"type":"physical unit","value":"Kc [OF] the equation [=] \\pu{0.543}"},{"type":"physical unit","value":"Temperature [OF] the equation [=] \\pu{425 ℃}"},{"type":"chemical equation","value":"H2(g) + I2(g) <=> 2 HI(g)"}]	<h1 class="questionTitle" itemprop="name">The #K_c# for the equation shown below is #0.543# at #425^@"C"#. What is the value of #K_c# for the reverse equation?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"H"_2(g) + "I"_2(g) rightleftharpoons 2"HI"(g)#</mathjax></p></div> </h2> </div> </div>	1.84	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember here is that the equilibrium constant of the forward reaction is always equal to the <strong>inverse</strong> of the equilibrium constant of the reverse reaction or vice versa. </p> <blockquote> <p><mathjax>#K_ (c \ "forward") = 1/K_ (c \ "reverse"#</mathjax></p> </blockquote> <p>So in your case, you would have</p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = 1/K_ (c \ "forward")#</mathjax></p> <p><mathjax>#K_ (c \ "reverse") = 1/0.543 = color(darkgreen)(ul(color(black)(1.84)))#</mathjax></p> </blockquote> <p>To prove that this is the case, simply write the expression of the equilibrium constant for the <strong>forward reaction</strong></p> <blockquote> <p><mathjax>#"H"_ (2(g)) + "I"_ (2(g)) rightleftharpoons 2"HI"_ ((g))#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#K_ (c\ "forward") = (["HI"]^2)/(["H"_2] * ["I"_2])#</mathjax></p> </blockquote> <p>Now do the same for the <strong>reverse reaction</strong></p> <blockquote> <p><mathjax>#2"HI"_ ((g)) rightleftharpoons "H"_ (2(g)) + "I"_ (2(g))#</mathjax></p> </blockquote> <p>This time, you will have</p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = (["H"_2] * ["I"_2])/(["HI"]^2)#</mathjax></p> </blockquote> <p>As you can see, you have</p> <blockquote> <p><mathjax>#K_ (c \ "forward") = (["HI"]^2)/(["H"_ 2] * ["I"_ 2]) = 1/((["H"_ 2] * ["I"_ 2])/(["HI"]^2)) = 1/K_ (c \ "reverse")#</mathjax></p> </blockquote> <p>and so </p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = 1/0.543 = color(darkgreen)(ul(color(black)(1.84)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.84#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember here is that the equilibrium constant of the forward reaction is always equal to the <strong>inverse</strong> of the equilibrium constant of the reverse reaction or vice versa. </p> <blockquote> <p><mathjax>#K_ (c \ "forward") = 1/K_ (c \ "reverse"#</mathjax></p> </blockquote> <p>So in your case, you would have</p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = 1/K_ (c \ "forward")#</mathjax></p> <p><mathjax>#K_ (c \ "reverse") = 1/0.543 = color(darkgreen)(ul(color(black)(1.84)))#</mathjax></p> </blockquote> <p>To prove that this is the case, simply write the expression of the equilibrium constant for the <strong>forward reaction</strong></p> <blockquote> <p><mathjax>#"H"_ (2(g)) + "I"_ (2(g)) rightleftharpoons 2"HI"_ ((g))#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#K_ (c\ "forward") = (["HI"]^2)/(["H"_2] * ["I"_2])#</mathjax></p> </blockquote> <p>Now do the same for the <strong>reverse reaction</strong></p> <blockquote> <p><mathjax>#2"HI"_ ((g)) rightleftharpoons "H"_ (2(g)) + "I"_ (2(g))#</mathjax></p> </blockquote> <p>This time, you will have</p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = (["H"_2] * ["I"_2])/(["HI"]^2)#</mathjax></p> </blockquote> <p>As you can see, you have</p> <blockquote> <p><mathjax>#K_ (c \ "forward") = (["HI"]^2)/(["H"_ 2] * ["I"_ 2]) = 1/((["H"_ 2] * ["I"_ 2])/(["HI"]^2)) = 1/K_ (c \ "reverse")#</mathjax></p> </blockquote> <p>and so </p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = 1/0.543 = color(darkgreen)(ul(color(black)(1.84)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The #K_c# for the equation shown below is #0.543# at #425^@"C"#. What is the value of #K_c# for the reverse equation?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"H"_2(g) + "I"_2(g) rightleftharpoons 2"HI"(g)#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-constants" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Constants</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="573794" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-15T00:06:25" itemprop="dateCreated"> Mar 15, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.84#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to remember here is that the equilibrium constant of the forward reaction is always equal to the <strong>inverse</strong> of the equilibrium constant of the reverse reaction or vice versa. </p> <blockquote> <p><mathjax>#K_ (c \ "forward") = 1/K_ (c \ "reverse"#</mathjax></p> </blockquote> <p>So in your case, you would have</p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = 1/K_ (c \ "forward")#</mathjax></p> <p><mathjax>#K_ (c \ "reverse") = 1/0.543 = color(darkgreen)(ul(color(black)(1.84)))#</mathjax></p> </blockquote> <p>To prove that this is the case, simply write the expression of the equilibrium constant for the <strong>forward reaction</strong></p> <blockquote> <p><mathjax>#"H"_ (2(g)) + "I"_ (2(g)) rightleftharpoons 2"HI"_ ((g))#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#K_ (c\ "forward") = (["HI"]^2)/(["H"_2] * ["I"_2])#</mathjax></p> </blockquote> <p>Now do the same for the <strong>reverse reaction</strong></p> <blockquote> <p><mathjax>#2"HI"_ ((g)) rightleftharpoons "H"_ (2(g)) + "I"_ (2(g))#</mathjax></p> </blockquote> <p>This time, you will have</p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = (["H"_2] * ["I"_2])/(["HI"]^2)#</mathjax></p> </blockquote> <p>As you can see, you have</p> <blockquote> <p><mathjax>#K_ (c \ "forward") = (["HI"]^2)/(["H"_ 2] * ["I"_ 2]) = 1/((["H"_ 2] * ["I"_ 2])/(["HI"]^2)) = 1/K_ (c \ "reverse")#</mathjax></p> </blockquote> <p>and so </p> <blockquote> <p><mathjax>#K_ (c \ "reverse") = 1/0.543 = color(darkgreen)(ul(color(black)(1.84)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/573794" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-equilibrium-constant-change-with-temperature"> How does the equilibrium constant change with temperature? 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What is the Keq... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-for-water"> What is the equilibrium constant for water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-of-citric-acid"> What is the equilibrium constant of citric acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-rate-of-production-of-reactants-compared-with-the-rate-of-production"> What is the rate of production of reactants compared with the rate of production of products at... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-equilibrium/equilibrium-constants"> See all questions in Equilibrium Constants </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3006 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	The #K_c# for the equation shown below is #0.543# at #425^@"C"#. What is the value of #K_c# for the reverse equation?	#"H"_2(g) + "I"_2(g) rightleftharpoons 2"HI"(g)#
2,750	a9a0a0b0-6ddd-11ea-b64e-ccda262736ce	https://socratic.org/questions/how-do-you-balance-ni-no-3-2-naoh-ni-oh-2-nano-3	Ni(NO3)2 + 2 NaOH -> Ni(OH)2 + 2 NaNO3	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"Ni(NO3)2 + 2 NaOH -> Ni(OH)2 + 2 NaNO3"}]	[{"type":"chemical equation","value":"Ni(NO3)2 + NaOH -> Ni(OH)2 + NaNO3"}]	<h1 class="questionTitle" itemprop="name">How do you balance #"Ni(NO"_3)_2 + "NaOH"##rarr##"Ni(OH)"_2 + "NaNO"_3"#?</h1>	null	Ni(NO3)2 + 2 NaOH -> Ni(OH)2 + 2 NaNO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Equation</strong></p> <p><mathjax>#"Ni(NO"_3)_2+"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2"+NaNO"_3"#</mathjax></p> <p>First look for <strong><a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a></strong> . You can usually treat them as individual units.</p> <p>There are two polyatomic ions in the equation. One is the nitrate anion, <mathjax>#"NO"_3^(-)"#</mathjax>, and the other is the hydroxide ion, <mathjax>#"OH"^(-)"#</mathjax>.</p> <p><strong>When balancing a chemical equation, you may only change the amount of each substance by adding coefficients in front of the formula. You may not change subscripts</strong> .</p> <p>There are two nitrate ions on the left side of the equation and only one on the right side. Add a coefficient of 2 in front of the formula for <mathjax>#"NaNO"_3"#</mathjax>.</p> <p><mathjax>#"Ni(NO"_3)_2+"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2+color(red)("2")"NaNO"_3#</mathjax></p> <p>There is one hydroxide ion on the left side and two on the right side.<br/> Add a coefficient of <mathjax>#2#</mathjax> in front of sodium hydroxide, <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Ni(NO"_3)_2+color(green)("2")"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2+color(red)("2")"NaNO"_3#</mathjax></p> <p>Now there is one nickel ion on both sides of the equation, two sodium ions on both sides, two nitrate ions on both sides, and two hydroxide ions on both sides. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Ni(NO"_3)_2+"2NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2"+2NaNO"_3"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Equation</strong></p> <p><mathjax>#"Ni(NO"_3)_2+"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2"+NaNO"_3"#</mathjax></p> <p>First look for <strong><a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a></strong> . You can usually treat them as individual units.</p> <p>There are two polyatomic ions in the equation. One is the nitrate anion, <mathjax>#"NO"_3^(-)"#</mathjax>, and the other is the hydroxide ion, <mathjax>#"OH"^(-)"#</mathjax>.</p> <p><strong>When balancing a chemical equation, you may only change the amount of each substance by adding coefficients in front of the formula. You may not change subscripts</strong> .</p> <p>There are two nitrate ions on the left side of the equation and only one on the right side. Add a coefficient of 2 in front of the formula for <mathjax>#"NaNO"_3"#</mathjax>.</p> <p><mathjax>#"Ni(NO"_3)_2+"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2+color(red)("2")"NaNO"_3#</mathjax></p> <p>There is one hydroxide ion on the left side and two on the right side.<br/> Add a coefficient of <mathjax>#2#</mathjax> in front of sodium hydroxide, <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Ni(NO"_3)_2+color(green)("2")"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2+color(red)("2")"NaNO"_3#</mathjax></p> <p>Now there is one nickel ion on both sides of the equation, two sodium ions on both sides, two nitrate ions on both sides, and two hydroxide ions on both sides. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #"Ni(NO"_3)_2 + "NaOH"##rarr##"Ni(OH)"_2 + "NaNO"_3"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="320739" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-12T01:55:14" itemprop="dateCreated"> Oct 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Ni(NO"_3)_2+"2NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2"+2NaNO"_3"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Equation</strong></p> <p><mathjax>#"Ni(NO"_3)_2+"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2"+NaNO"_3"#</mathjax></p> <p>First look for <strong><a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a></strong> . You can usually treat them as individual units.</p> <p>There are two polyatomic ions in the equation. One is the nitrate anion, <mathjax>#"NO"_3^(-)"#</mathjax>, and the other is the hydroxide ion, <mathjax>#"OH"^(-)"#</mathjax>.</p> <p><strong>When balancing a chemical equation, you may only change the amount of each substance by adding coefficients in front of the formula. You may not change subscripts</strong> .</p> <p>There are two nitrate ions on the left side of the equation and only one on the right side. Add a coefficient of 2 in front of the formula for <mathjax>#"NaNO"_3"#</mathjax>.</p> <p><mathjax>#"Ni(NO"_3)_2+"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2+color(red)("2")"NaNO"_3#</mathjax></p> <p>There is one hydroxide ion on the left side and two on the right side.<br/> Add a coefficient of <mathjax>#2#</mathjax> in front of sodium hydroxide, <mathjax>#"NaOH"#</mathjax>.</p> <p><mathjax>#"Ni(NO"_3)_2+color(green)("2")"NaOH"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Ni(OH)"_2+color(red)("2")"NaNO"_3#</mathjax></p> <p>Now there is one nickel ion on both sides of the equation, two sodium ions on both sides, two nitrate ions on both sides, and two hydroxide ions on both sides. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/320739" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8023 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #"Ni(NO"_3)_2 + "NaOH"##rarr##"Ni(OH)"_2 + "NaNO"_3"#?	null
2,751	a9fb92a5-6ddd-11ea-8dae-ccda262736ce	https://socratic.org/questions/what-is-the-pka-of-acetic-acid	4.67	start physical_unit 5 6 pka none qc_end substance 5 6 qc_end end	[{"type":"physical unit","value":"pKa [OF] acetic acid"}]	[{"type":"physical unit","value":"4.67"}]	[{"type":"substance name","value":"Acetic acid"}]	<h1 class="questionTitle" itemprop="name">What is the pKa of acetic acid?</h1>	null	4.67	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this a strong or weak acid?</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For acetic acid, <mathjax>#pK_a=4.76#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this a strong or weak acid?</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pKa of acetic acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="323636" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-19T08:27:57" itemprop="dateCreated"> Oct 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For acetic acid, <mathjax>#pK_a=4.76#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this a strong or weak acid?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/323636" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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2,752	aaa323d9-6ddd-11ea-894e-ccda262736ce	https://socratic.org/questions/57a735b47c01491495f5f5dd	5.98 × 10^(-16) grams	start physical_unit 8 9 mass g qc_end physical_unit 8 9 6 7 number qc_end end	[{"type":"physical unit","value":"Mass [OF] water molecules [IN] grams"}]	[{"type":"physical unit","value":"5.98 × 10^(-16) grams"}]	[{"type":"physical unit","value":"Number [OF] water molecules [=] \\pu{20 million}"}]	<h1 class="questionTitle" itemprop="name">What is the mass associated with #"20 million water molecules?"#</h1>	null	5.98 × 10^(-16) grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#"Avogadro's number"-=6.022xx10^23mol^-1#</mathjax></p> <p>And thus the mass of <mathjax>#20xx10^6"water molecules"#</mathjax></p> <p><mathjax>#-=(20xx10^6"water molecules"xx18.01gmol^-1)/(6.022xx10^23"water molecules"mol^-1)#</mathjax></p> <p><mathjax>#=6xx10^-16g#</mathjax>.........or <mathjax>#1/8xx1/5xx1/32*"sweet F....... A..."#</mathjax></p> <p>And no balance could measure this........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well <mathjax>#"Avogadro's number"#</mathjax> of water molecules has a mass of <mathjax>#18.01g#</mathjax>.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#"Avogadro's number"-=6.022xx10^23mol^-1#</mathjax></p> <p>And thus the mass of <mathjax>#20xx10^6"water molecules"#</mathjax></p> <p><mathjax>#-=(20xx10^6"water molecules"xx18.01gmol^-1)/(6.022xx10^23"water molecules"mol^-1)#</mathjax></p> <p><mathjax>#=6xx10^-16g#</mathjax>.........or <mathjax>#1/8xx1/5xx1/32"sweet F....... A..."#</mathjax></p> <p>And no balance could measure this........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass associated with #"20 million water molecules?"#</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="444731" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-26T22:06:43" itemprop="dateCreated"> Jun 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well <mathjax>#"Avogadro's number"#</mathjax> of water molecules has a mass of <mathjax>#18.01g#</mathjax>.......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#"Avogadro's number"-=6.022xx10^23mol^-1#</mathjax></p> <p>And thus the mass of <mathjax>#20xx10^6"water molecules"#</mathjax></p> <p><mathjax>#-=(20xx10^6"water molecules"xx18.01gmol^-1)/(6.022xx10^23"water molecules"mol^-1)#</mathjax></p> <p><mathjax>#=6xx10^-16g#</mathjax>.........or <mathjax>#1/8xx1/5xx1/32"sweet F....... A..."#</mathjax></p> <p>And no balance could measure this........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/444731" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1752 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass associated with #"20 million water molecules?"#	null
2,753	a9fdb58b-6ddd-11ea-bf06-ccda262736ce	https://socratic.org/questions/a-335-0-ml-sample-of-oxygen-at-25-c-is-heated-to-50-c-if-the-pressure-remains-co	363.10 milliliters	start physical_unit 3 5 volume ml qc_end physical_unit 3 5 1 2 volume qc_end physical_unit 3 5 7 8 temperature qc_end physical_unit 3 5 12 13 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Volume2 [OF] oxygen sample [IN] milliliters"}]	[{"type":"physical unit","value":"363.10 milliliters"}]	[{"type":"physical unit","value":"Volume1 [OF] oxygen sample [=] \\pu{335.0 mL}"},{"type":"physical unit","value":"Temperature1 [OF] oxygen sample [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] oxygen sample [=] \\pu{50 ℃}"},{"type":"other","value":"Constant pressure."}]	<h1 class="questionTitle" itemprop="name">A 335.0 mL sample of oxygen at 25 C is heated to 50 C. If the pressure remains constant, what is the final volume in milliliters? </h1>	null	363.10 milliliters	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Charles Law Problem:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/Ru9Nr8GTB6zSIOJbJ1Rg_Socratic%20-%20Charles%20Law%20Problem.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Volume = 363 ml at <mathjax>#50^oC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Charles Law Problem:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/Ru9Nr8GTB6zSIOJbJ1Rg_Socratic%20-%20Charles%20Law%20Problem.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A 335.0 mL sample of oxygen at 25 C is heated to 50 C. If the pressure remains constant, what is the final volume in milliliters? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="424967" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-17T14:31:43" itemprop="dateCreated"> May 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Volume = 363 ml at <mathjax>#50^oC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Charles Law Problem:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/Ru9Nr8GTB6zSIOJbJ1Rg_Socratic%20-%20Charles%20Law%20Problem.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/424967" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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If the pressure remains constant, what is the final volume in milliliters?	null
2,754	aa3c3538-6ddd-11ea-9c1d-ccda262736ce	https://socratic.org/questions/how-do-you-balance-ca-h-3po-4-ca-3-po-4-2-h-2	3 Ca + 2 H3PO4 -> Ca3(PO4)2 + 3 H2	start chemical_equation qc_end chemical_equation 4 10 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"3 Ca + 2 H3PO4 -> Ca3(PO4)2 + 3 H2"}]	[{"type":"chemical equation","value":"Ca + H3PO4 -> Ca3(PO4)2 + H2"}]	<h1 class="questionTitle" itemprop="name">How do you balance #Ca+H_3PO_4 -> Ca_3(PO_4)_2 + H_2#?</h1>	null	3 Ca + 2 H3PO4 -> Ca3(PO4)2 + 3 H2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Make sure that the number of atoms for each element on the left side of the equation adds up to the the number of atoms for each element on the right side.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>Balanced Equation:</strong> </p> <p><mathjax>#3 Ca(s) + 2 H_3PO_4(aq) -> Ca_3(PO4)_2(s) + 3 H_2(g) #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Make sure that the number of atoms for each element on the left side of the equation adds up to the the number of atoms for each element on the right side.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance #Ca+H_3PO_4 -> Ca_3(PO_4)_2 + H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="218751" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/james-10"><img alt="" class="" src="https://profilepictures.socratic.org/eTjSa9W7Q08A7fzEGlAD_giphy.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/james-10"> James C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-29T11:08:04" itemprop="dateCreated"> Jan 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>Balanced Equation:</strong> </p> <p><mathjax>#3 Ca(s) + 2 H_3PO_4(aq) -> Ca_3(PO4)_2(s) + 3 H_2(g) #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Make sure that the number of atoms for each element on the left side of the equation adds up to the the number of atoms for each element on the right side.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/218751" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1513 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance #Ca+H_3PO_4 -> Ca_3(PO_4)_2 + H_2#?	null
2,755	aba5aee6-6ddd-11ea-bf83-ccda262736ce	https://socratic.org/questions/calculate-the-amount-of-water-in-grams-that-must-be-added-to-prepare-16-by-mass-	26.3 grams	start physical_unit 4 4 mass g qc_end physical_unit 22 22 13 13 mass_percent qc_end physical_unit 22 22 18 19 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] water [IN] grams"}]	[{"type":"physical unit","value":"26.3 grams"}]	[{"type":"physical unit","value":"Percent by mass [OF] (NH2)2CO in solution [=] \\pu{16%}"},{"type":"physical unit","value":"Mass [OF] (NH2)2CO [=] \\pu{5.0 g}"}]	<h1 class="questionTitle" itemprop="name">Calculate the amount of water, in grams, that must be added to prepare #16%# by mass solution with #"5.0 g"# of urea, #"(NH"_2)_2"CO"# ?</h1>	null	26.3 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that the solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong> tells you the mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"100 g"#</mathjax> <strong>of the solution</strong>.</p> <p>As you know, the mass of the solution <em>includes</em> the mass of the solute. In other words, the mass of the solution is given by the mass of the solute <strong>and</strong> the mass of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.</p> <p>So, a <mathjax>#16%#</mathjax> by mass urea solution will contain <mathjax>#"16 g"#</mathjax> of urea, the solute, <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of the solution. This means that the mass of the solution that contains <mathjax>#"5.0 g"#</mathjax> of urea will be equal to</p> <blockquote> <p><mathjax>#5.0 color(red)(cancel(color(black)("g urea"))) * overbrace("100 g solution"/(16color(red)(cancel(color(black)("g urea")))))^(color(blue)("= 16% by mass urea")) = "31.3 g solution"#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#overbrace("31.3 g")^(color(blue)("mass of solution")) = overbrace("5.0 g")^(color(blue)("mass of solute")) + "mass of solvent"#</mathjax></p> </blockquote> <p>you can say that this solution will require </p> <blockquote> <p><mathjax>#"mass of solvent" = "31.3 g " - " 5.0 g"#</mathjax></p> <p><mathjax>#"mass of solvent = 26.3 g"#</mathjax></p> </blockquote> <p>of water, your solvent. Rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#"mass of water" = color(darkgreen)(ul(color(black)("26 g")))#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"26 g H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that the solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong> tells you the mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"100 g"#</mathjax> <strong>of the solution</strong>.</p> <p>As you know, the mass of the solution <em>includes</em> the mass of the solute. In other words, the mass of the solution is given by the mass of the solute <strong>and</strong> the mass of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.</p> <p>So, a <mathjax>#16%#</mathjax> by mass urea solution will contain <mathjax>#"16 g"#</mathjax> of urea, the solute, <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of the solution. This means that the mass of the solution that contains <mathjax>#"5.0 g"#</mathjax> of urea will be equal to</p> <blockquote> <p><mathjax>#5.0 color(red)(cancel(color(black)("g urea"))) * overbrace("100 g solution"/(16color(red)(cancel(color(black)("g urea")))))^(color(blue)("= 16% by mass urea")) = "31.3 g solution"#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#overbrace("31.3 g")^(color(blue)("mass of solution")) = overbrace("5.0 g")^(color(blue)("mass of solute")) + "mass of solvent"#</mathjax></p> </blockquote> <p>you can say that this solution will require </p> <blockquote> <p><mathjax>#"mass of solvent" = "31.3 g " - " 5.0 g"#</mathjax></p> <p><mathjax>#"mass of solvent = 26.3 g"#</mathjax></p> </blockquote> <p>of water, your solvent. Rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#"mass of water" = color(darkgreen)(ul(color(black)("26 g")))#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the amount of water, in grams, that must be added to prepare #16%# by mass solution with #"5.0 g"# of urea, #"(NH"_2)_2"CO"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="515146" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-03T02:16:42" itemprop="dateCreated"> Dec 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"26 g H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that the solution's <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong> tells you the mass of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"100 g"#</mathjax> <strong>of the solution</strong>.</p> <p>As you know, the mass of the solution <em>includes</em> the mass of the solute. In other words, the mass of the solution is given by the mass of the solute <strong>and</strong> the mass of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>.</p> <p>So, a <mathjax>#16%#</mathjax> by mass urea solution will contain <mathjax>#"16 g"#</mathjax> of urea, the solute, <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of the solution. This means that the mass of the solution that contains <mathjax>#"5.0 g"#</mathjax> of urea will be equal to</p> <blockquote> <p><mathjax>#5.0 color(red)(cancel(color(black)("g urea"))) * overbrace("100 g solution"/(16color(red)(cancel(color(black)("g urea")))))^(color(blue)("= 16% by mass urea")) = "31.3 g solution"#</mathjax></p> </blockquote> <p>Since you know that</p> <blockquote> <p><mathjax>#overbrace("31.3 g")^(color(blue)("mass of solution")) = overbrace("5.0 g")^(color(blue)("mass of solute")) + "mass of solvent"#</mathjax></p> </blockquote> <p>you can say that this solution will require </p> <blockquote> <p><mathjax>#"mass of solvent" = "31.3 g " - " 5.0 g"#</mathjax></p> <p><mathjax>#"mass of solvent = 26.3 g"#</mathjax></p> </blockquote> <p>of water, your solvent. Rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the answer will be</p> <blockquote> <p><mathjax>#"mass of water" = color(darkgreen)(ul(color(black)("26 g")))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/515146" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23565 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Calculate the amount of water, in grams, that must be added to prepare #16%# by mass solution with #"5.0 g"# of urea, #"(NH"_2)_2"CO"# ?	null
2,756	a961bacc-6ddd-11ea-bc3e-ccda262736ce	https://socratic.org/questions/what-is-the-coefficient-of-o2-when-the-equation-mg-clo-3-2-s-mgcl-2-s-o-2-g-is-b	3	start physical_unit 5 5 coefficient none qc_end chemical_equation 9 13 qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Coefficient [OF] O2"}]	[{"type":"physical unit","value":"3"}]	[{"type":"chemical equation","value":"Mg(ClO3)2(s) -> MgCl(s) + O2(g) "},{"type":"other","value":"Use the smallest whole number coefficients."}]	<h1 class="questionTitle" itemprop="name">What is the coefficient of #"O"_2# when the equation #"Mg"("ClO"_3)_2(s) -> "MgCl"_2(s)+"O"_2(g)# is balanced correctly using the smallest whole number coefficients?</h1>	null	3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that magnesium chlorate, <mathjax>#"Mg"("ClO"_3)_2#</mathjax>, undergoes thermal decomposition to produce magnesium chloride, <mathjax>#"MgCl"_2#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>.</p> <p>The unbalanced chemical equation that describes this decomposition reaction looks like this</p> <blockquote> <p><mathjax>#"Mg"("ClO"_ 3)_ (color(blue)(2)(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) "MgCl"_ (2(s)) + "O"_ (2(g))#</mathjax></p> </blockquote> <p>Now, you know that one formula units of magnesium chlorate contains </p> <blockquote> <ul> <li><em><strong>one magnesium cation</strong></em>, <mathjax>#1 xx "Mg"^(2+)#</mathjax></li> <li><em><strong>two chlorate anions</strong></em>, <mathjax>#color(blue)(2) xx "ClO"_3^(-)#</mathjax></li> </ul> </blockquote> <p>Since each chlorate anion contains <mathjax>#1#</mathjax> <strong>atom</strong> of chlorine and <mathjax>#3#</mathjax> <strong>atoms</strong> of oxygen, you can say that the reactant's side contains</p> <blockquote> <ul> <li><em><strong>two atoms</strong> of chlorine</em>, <mathjax>#color(blue)(2) xx 1 xx "Cl"#</mathjax></li> <li><em><strong>six atoms</strong> of oxygen</em>, <mathjax>#color(blue)(2) xx 3 xx "O" = 6 xx "O"#</mathjax></li> </ul> </blockquote> <p>Notice that you have <mathjax>#1#</mathjax> <strong>atom</strong> of magnesium on the reactant's side <em>and</em> on the products' side, so you know that magnesium is balanced. </p> <p>The same can be said about chlorine since you have <mathjax>#2#</mathjax> <strong>atoms</strong> of chlorine on the reactant's side <em>and</em> on the products' side. </p> <p>Now, notice that you have a total of <mathjax>#6#</mathjax> <strong>atoms</strong> of oxygen on the reactant's side and only <mathjax>#2#</mathjax> <strong>atoms</strong> of oxygen on the products' side. In order to balance the atoms of oxygen, multiply the oxygen molecule by <mathjax>#3#</mathjax>.</p> <p>You will now have</p> <blockquote> <p><mathjax>#"Mg"("ClO"_ 3)_ (color(blue)(2)(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) "MgCl"_ (2(s)) + 3"O"_ (2(g))#</mathjax></p> </blockquote> <p>Since <mathjax>#1:1:3#</mathjax> is the <strong>smallest ratio</strong> that can be used to balance the chemical equation using whole number coefficients, you can thus say that the oxygen molecule has a coefficient of <mathjax>#3#</mathjax> in the balanced chemical equation that describes the decomposition of magnesium chlorate. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that magnesium chlorate, <mathjax>#"Mg"("ClO"_3)_2#</mathjax>, undergoes thermal decomposition to produce magnesium chloride, <mathjax>#"MgCl"_2#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>.</p> <p>The unbalanced chemical equation that describes this decomposition reaction looks like this</p> <blockquote> <p><mathjax>#"Mg"("ClO"_ 3)_ (color(blue)(2)(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) "MgCl"_ (2(s)) + "O"_ (2(g))#</mathjax></p> </blockquote> <p>Now, you know that one formula units of magnesium chlorate contains </p> <blockquote> <ul> <li><em><strong>one magnesium cation</strong></em>, <mathjax>#1 xx "Mg"^(2+)#</mathjax></li> <li><em><strong>two chlorate anions</strong></em>, <mathjax>#color(blue)(2) xx "ClO"_3^(-)#</mathjax></li> </ul> </blockquote> <p>Since each chlorate anion contains <mathjax>#1#</mathjax> <strong>atom</strong> of chlorine and <mathjax>#3#</mathjax> <strong>atoms</strong> of oxygen, you can say that the reactant's side contains</p> <blockquote> <ul> <li><em><strong>two atoms</strong> of chlorine</em>, <mathjax>#color(blue)(2) xx 1 xx "Cl"#</mathjax></li> <li><em><strong>six atoms</strong> of oxygen</em>, <mathjax>#color(blue)(2) xx 3 xx "O" = 6 xx "O"#</mathjax></li> </ul> </blockquote> <p>Notice that you have <mathjax>#1#</mathjax> <strong>atom</strong> of magnesium on the reactant's side <em>and</em> on the products' side, so you know that magnesium is balanced. </p> <p>The same can be said about chlorine since you have <mathjax>#2#</mathjax> <strong>atoms</strong> of chlorine on the reactant's side <em>and</em> on the products' side. </p> <p>Now, notice that you have a total of <mathjax>#6#</mathjax> <strong>atoms</strong> of oxygen on the reactant's side and only <mathjax>#2#</mathjax> <strong>atoms</strong> of oxygen on the products' side. In order to balance the atoms of oxygen, multiply the oxygen molecule by <mathjax>#3#</mathjax>.</p> <p>You will now have</p> <blockquote> <p><mathjax>#"Mg"("ClO"_ 3)_ (color(blue)(2)(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) "MgCl"_ (2(s)) + 3"O"_ (2(g))#</mathjax></p> </blockquote> <p>Since <mathjax>#1:1:3#</mathjax> is the <strong>smallest ratio</strong> that can be used to balance the chemical equation using whole number coefficients, you can thus say that the oxygen molecule has a coefficient of <mathjax>#3#</mathjax> in the balanced chemical equation that describes the decomposition of magnesium chlorate. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the coefficient of #"O"_2# when the equation #"Mg"("ClO"_3)_2(s) -> "MgCl"_2(s)+"O"_2(g)# is balanced correctly using the smallest whole number coefficients?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="440417" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-16T00:11:22" itemprop="dateCreated"> Jun 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that magnesium chlorate, <mathjax>#"Mg"("ClO"_3)_2#</mathjax>, undergoes thermal decomposition to produce magnesium chloride, <mathjax>#"MgCl"_2#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>.</p> <p>The unbalanced chemical equation that describes this decomposition reaction looks like this</p> <blockquote> <p><mathjax>#"Mg"("ClO"_ 3)_ (color(blue)(2)(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) "MgCl"_ (2(s)) + "O"_ (2(g))#</mathjax></p> </blockquote> <p>Now, you know that one formula units of magnesium chlorate contains </p> <blockquote> <ul> <li><em><strong>one magnesium cation</strong></em>, <mathjax>#1 xx "Mg"^(2+)#</mathjax></li> <li><em><strong>two chlorate anions</strong></em>, <mathjax>#color(blue)(2) xx "ClO"_3^(-)#</mathjax></li> </ul> </blockquote> <p>Since each chlorate anion contains <mathjax>#1#</mathjax> <strong>atom</strong> of chlorine and <mathjax>#3#</mathjax> <strong>atoms</strong> of oxygen, you can say that the reactant's side contains</p> <blockquote> <ul> <li><em><strong>two atoms</strong> of chlorine</em>, <mathjax>#color(blue)(2) xx 1 xx "Cl"#</mathjax></li> <li><em><strong>six atoms</strong> of oxygen</em>, <mathjax>#color(blue)(2) xx 3 xx "O" = 6 xx "O"#</mathjax></li> </ul> </blockquote> <p>Notice that you have <mathjax>#1#</mathjax> <strong>atom</strong> of magnesium on the reactant's side <em>and</em> on the products' side, so you know that magnesium is balanced. </p> <p>The same can be said about chlorine since you have <mathjax>#2#</mathjax> <strong>atoms</strong> of chlorine on the reactant's side <em>and</em> on the products' side. </p> <p>Now, notice that you have a total of <mathjax>#6#</mathjax> <strong>atoms</strong> of oxygen on the reactant's side and only <mathjax>#2#</mathjax> <strong>atoms</strong> of oxygen on the products' side. In order to balance the atoms of oxygen, multiply the oxygen molecule by <mathjax>#3#</mathjax>.</p> <p>You will now have</p> <blockquote> <p><mathjax>#"Mg"("ClO"_ 3)_ (color(blue)(2)(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) "MgCl"_ (2(s)) + 3"O"_ (2(g))#</mathjax></p> </blockquote> <p>Since <mathjax>#1:1:3#</mathjax> is the <strong>smallest ratio</strong> that can be used to balance the chemical equation using whole number coefficients, you can thus say that the oxygen molecule has a coefficient of <mathjax>#3#</mathjax> in the balanced chemical equation that describes the decomposition of magnesium chlorate. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/440417" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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2,757	aba0a5c2-6ddd-11ea-9cd7-ccda262736ce	https://socratic.org/questions/what-nacl-concentration-results-when-204-mlof-a-0-760-m-naci-solution-is-mixed-w	0.5 M	start physical_unit 1 1 concentration mol/l qc_end physical_unit 10 11 8 9 concentration qc_end physical_unit 10 11 15 16 volume qc_end physical_unit 10 11 19 20 concentration qc_end end	[{"type":"physical unit","value":"Concentration3 [OF] NaCl [IN] M"}]	[{"type":"physical unit","value":"0.5 M"}]	[{"type":"physical unit","value":"Volume1 [OF] NaCI solution [=] \\pu{204 mL}"},{"type":"physical unit","value":"Concentration1 [OF] NaCI solution [=] \\pu{0.760 M}"},{"type":"physical unit","value":"Volume2 [OF] NaCI solution [=] \\pu{417 mL}"},{"type":"physical unit","value":"Concentration2 [OF] NaCI solution [=] \\pu{0.430 M}"}]	<h1 class="questionTitle" itemprop="name">What NaCl concentration results when 204 mLof a 0.760 M NaCI solution is mixed with 417 mL of a 0.430 M NaCl solution?</h1>	null	0.5 M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Solution 1"#</mathjax>, <mathjax>#"moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#204xx10^-3Lxx0.760molL^-1=0.155mol#</mathjax>.</p> <p><mathjax>#"Solution 2"#</mathjax>, <mathjax>#"moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#417xx10^-3Lxx0.430molL^-1=0.179mol#</mathjax>.</p> <p>Since we must consider the volumes to be additive when these <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are mixed, we have the following concentration with respect to <mathjax>#NaCl#</mathjax>.</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#((0.155+0.179)mol)/((204+417)xx10^-3L)#</mathjax></p> <p><mathjax>#~=#</mathjax> <mathjax>#0.5molL^-1#</mathjax> with respect to <mathjax>#NaCl#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[NaCl]#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.5molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Solution 1"#</mathjax>, <mathjax>#"moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#204xx10^-3Lxx0.760molL^-1=0.155mol#</mathjax>.</p> <p><mathjax>#"Solution 2"#</mathjax>, <mathjax>#"moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#417xx10^-3Lxx0.430molL^-1=0.179mol#</mathjax>.</p> <p>Since we must consider the volumes to be additive when these <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are mixed, we have the following concentration with respect to <mathjax>#NaCl#</mathjax>.</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#((0.155+0.179)mol)/((204+417)xx10^-3L)#</mathjax></p> <p><mathjax>#~=#</mathjax> <mathjax>#0.5molL^-1#</mathjax> with respect to <mathjax>#NaCl#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What NaCl concentration results when 204 mLof a 0.760 M NaCI solution is mixed with 417 mL of a 0.430 M NaCl solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="303996" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-30T06:04:01" itemprop="dateCreated"> Aug 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[NaCl]#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.5molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Solution 1"#</mathjax>, <mathjax>#"moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#204xx10^-3Lxx0.760molL^-1=0.155mol#</mathjax>.</p> <p><mathjax>#"Solution 2"#</mathjax>, <mathjax>#"moles of NaCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#417xx10^-3Lxx0.430molL^-1=0.179mol#</mathjax>.</p> <p>Since we must consider the volumes to be additive when these <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are mixed, we have the following concentration with respect to <mathjax>#NaCl#</mathjax>.</p> <p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#((0.155+0.179)mol)/((204+417)xx10^-3L)#</mathjax></p> <p><mathjax>#~=#</mathjax> <mathjax>#0.5molL^-1#</mathjax> with respect to <mathjax>#NaCl#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/303996" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-a-solution"> How do you measure concentration of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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href="/chemistry/solutions-and-their-behavior/measuring-concentration"> See all questions in Measuring Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 40286 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What NaCl concentration results when 204 mLof a 0.760 M NaCI solution is mixed with 417 mL of a 0.430 M NaCl solution?	null
2,758	a8fa8782-6ddd-11ea-a541-ccda262736ce	https://socratic.org/questions/if-a-gas-has-an-initial-temperature-of-300-k-at-a-pressure-of-100-kpa-and-it-is-	200 kPa	start physical_unit 2 2 pressure kpa qc_end physical_unit 2 2 14 15 pressure qc_end physical_unit 2 2 8 9 temperature qc_end physical_unit 2 2 22 23 temperature qc_end end	[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] kPa"}]	[{"type":"physical unit","value":"200 kPa"}]	[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{100 kPa}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{300 K}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{600 K}"}]	<h1 class="questionTitle" itemprop="name">If a gas has an initial temperature of 300 K at a pressure of 100 kPa and it is then heated to 600 K, what is the new pressure? </h1>	null	200 kPa	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question requires you to use Gay-Lussac's law: </p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>The number 1 represents the initial conditions and the number 2 represents the final conditions.</p> <p>Identify your known and unknown variables: </p> <p><mathjax>#color(blue)("Knowns:"#</mathjax></p> <p><mathjax>#P_1#</mathjax>= 100kPa<br/> <mathjax>#T_1#</mathjax>= 300K<br/> <mathjax>#T_2#</mathjax> = 600K</p> <p><mathjax>#color(magenta) ("Unknowns:"#</mathjax></p> <p><mathjax>#P_2#</mathjax> </p> <p>Rearrange the equation to solve <mathjax>#P_2#</mathjax></p> <p><mathjax>#P_2=(P_1xxT_2)/T_1#</mathjax></p> <p>Plug in your given values to obtain the final pressure:</p> <p><mathjax>#P_2=(100 kPaxx600cancelK)/(300cancelK)#</mathjax> = <mathjax>#200 kPa#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new pressure is <mathjax>#200 kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question requires you to use Gay-Lussac's law: </p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>The number 1 represents the initial conditions and the number 2 represents the final conditions.</p> <p>Identify your known and unknown variables: </p> <p><mathjax>#color(blue)("Knowns:"#</mathjax></p> <p><mathjax>#P_1#</mathjax>= 100kPa<br/> <mathjax>#T_1#</mathjax>= 300K<br/> <mathjax>#T_2#</mathjax> = 600K</p> <p><mathjax>#color(magenta) ("Unknowns:"#</mathjax></p> <p><mathjax>#P_2#</mathjax> </p> <p>Rearrange the equation to solve <mathjax>#P_2#</mathjax></p> <p><mathjax>#P_2=(P_1xxT_2)/T_1#</mathjax></p> <p>Plug in your given values to obtain the final pressure:</p> <p><mathjax>#P_2=(100 kPaxx600cancelK)/(300cancelK)#</mathjax> = <mathjax>#200 kPa#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If a gas has an initial temperature of 300 K at a pressure of 100 kPa and it is then heated to 600 K, what is the new pressure? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="302767" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-26T01:43:05" itemprop="dateCreated"> Aug 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new pressure is <mathjax>#200 kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question requires you to use Gay-Lussac's law: </p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>The number 1 represents the initial conditions and the number 2 represents the final conditions.</p> <p>Identify your known and unknown variables: </p> <p><mathjax>#color(blue)("Knowns:"#</mathjax></p> <p><mathjax>#P_1#</mathjax>= 100kPa<br/> <mathjax>#T_1#</mathjax>= 300K<br/> <mathjax>#T_2#</mathjax> = 600K</p> <p><mathjax>#color(magenta) ("Unknowns:"#</mathjax></p> <p><mathjax>#P_2#</mathjax> </p> <p>Rearrange the equation to solve <mathjax>#P_2#</mathjax></p> <p><mathjax>#P_2=(P_1xxT_2)/T_1#</mathjax></p> <p>Plug in your given values to obtain the final pressure:</p> <p><mathjax>#P_2=(100 kPaxx600cancelK)/(300cancelK)#</mathjax> = <mathjax>#200 kPa#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/302767" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? 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If the gas is compressed to 23.52 L and the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-r-stand-for-in-the-ideal-gas-law-pv-nrt"> What does the R stand for in the ideal gas law (PV=nRT)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-mass-of-a-gas-that-occupies-48-9-liters-has-a-pressure-of-724-torr-a"> What is the mass of a gas that occupies 48.9 liters, has a pressure of 724 torr, a temperature... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-sample-of-neon-gas-occupies-a-volume-of-2-8l-at-1-8-atm-what-will-its-volum"> If a sample of neon gas occupies a volume of 2.8L at 1.8 atm. what will its volume be at 1.2 atm? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-laws"> See all questions in Gas Laws </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3004 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If a gas has an initial temperature of 300 K at a pressure of 100 kPa and it is then heated to 600 K, what is the new pressure?	null
2,759	ab4664e4-6ddd-11ea-be05-ccda262736ce	https://socratic.org/questions/what-is-the-formula-of-dinitrogen-pentoxide	N2O5	start chemical_formula qc_end substance 5 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] dinitrogen pentoxide [IN] default"}]	[{"type":"chemical equation","value":"N2O5"}]	[{"type":"substance name","value":"Dinitrogen pentoxide"}]	<h1 class="questionTitle" itemprop="name">What is the formula of dinitrogen pentoxide? </h1>	null	N2O5	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Lets have a look at the words involved:</p> <blockquote> <p><mathjax>#di#</mathjax>nitrogen and <mathjax>#pent#</mathjax>oxide. </p> </blockquote> <p>The <mathjax>#di#</mathjax> and <mathjax>#pent#</mathjax> are common prefixes to words which signify numbers, but which numbers? Have a look at this table, and you will find that in this case they signify 2 and 5 respectively. </p> <p><img alt="https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table (Slide 46)" src="https://useruploads.socratic.org/xdgYVSvWSZyqEVdZZRUn_c20-review-unit-01-matter-energy-and-the-periodic-table-46-728.jpg"/> <br/> Using this knowledge (note that "penta" has the "a" removed for words starting with a vowel like "oxide"), it is possible to say that there are 2 nitrogen's and 5 oxygen's in this chemical equation, thus <mathjax>#N ""_2O""_5"#</mathjax></p> <p>Hope that Helped!<br/> <a href="https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table" rel="nofollow" target="_blank">https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table</a></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#N_2O_5"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Lets have a look at the words involved:</p> <blockquote> <p><mathjax>#di#</mathjax>nitrogen and <mathjax>#pent#</mathjax>oxide. </p> </blockquote> <p>The <mathjax>#di#</mathjax> and <mathjax>#pent#</mathjax> are common prefixes to words which signify numbers, but which numbers? Have a look at this table, and you will find that in this case they signify 2 and 5 respectively. </p> <p><img alt="https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table (Slide 46)" src="https://useruploads.socratic.org/xdgYVSvWSZyqEVdZZRUn_c20-review-unit-01-matter-energy-and-the-periodic-table-46-728.jpg"/> <br/> Using this knowledge (note that "penta" has the "a" removed for words starting with a vowel like "oxide"), it is possible to say that there are 2 nitrogen's and 5 oxygen's in this chemical equation, thus <mathjax>#N ""_2O""_5"#</mathjax></p> <p>Hope that Helped!<br/> <a href="https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table" rel="nofollow" target="_blank">https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table</a></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula of dinitrogen pentoxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="434252" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/solace-m"><img alt="" class="" src="https://profilepictures.socratic.org/exTzgKejSe2yULTY6Ron_kratos.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/solace-m"> Solace M. </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-04T00:30:22" itemprop="dateCreated"> Jun 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#N_2O_5"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Lets have a look at the words involved:</p> <blockquote> <p><mathjax>#di#</mathjax>nitrogen and <mathjax>#pent#</mathjax>oxide. </p> </blockquote> <p>The <mathjax>#di#</mathjax> and <mathjax>#pent#</mathjax> are common prefixes to words which signify numbers, but which numbers? Have a look at this table, and you will find that in this case they signify 2 and 5 respectively. </p> <p><img alt="https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table (Slide 46)" src="https://useruploads.socratic.org/xdgYVSvWSZyqEVdZZRUn_c20-review-unit-01-matter-energy-and-the-periodic-table-46-728.jpg"/> <br/> Using this knowledge (note that "penta" has the "a" removed for words starting with a vowel like "oxide"), it is possible to say that there are 2 nitrogen's and 5 oxygen's in this chemical equation, thus <mathjax>#N ""_2O""_5"#</mathjax></p> <p>Hope that Helped!<br/> <a href="https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table" rel="nofollow" target="_blank">https://www.slideshare.net/mlacoursiere/c20-review-unit-01-matter-energy-and-the-periodic-table</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/434252" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6837 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the formula of dinitrogen pentoxide?	null
2,760	ab815a3f-6ddd-11ea-937b-ccda262736ce	https://socratic.org/questions/isooctane-has-the-molecular-formula-c-8h-18-what-is-its-empirical-formula	C4H9	start chemical_formula qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Formula [OF] isooctane [IN] empirical"}]	[{"type":"chemical equation","value":"C4H9"}]	[{"type":"other","value":"Isooctane has the molecular formula C8H18."}]	<h1 class="questionTitle" itemprop="name">Isooctane has the molecular formula #C_8H_18#. What is its empirical formula?</h1>	null	C4H9	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio that relates constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a species. The molecular formula is a whole number multiple of the empirical formula. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Isooctane"#</mathjax> has an empirical formula of <mathjax>#C_4H_9#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio that relates constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a species. The molecular formula is a whole number multiple of the empirical formula. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Isooctane has the molecular formula #C_8H_18#. What is its empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296413" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-07T10:24:20" itemprop="dateCreated"> Aug 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Isooctane"#</mathjax> has an empirical formula of <mathjax>#C_4H_9#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio that relates constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a species. The molecular formula is a whole number multiple of the empirical formula. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296413" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7706 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Isooctane has the molecular formula #C_8H_18#. What is its empirical formula?	null
2,761	a919fd94-6ddd-11ea-908e-ccda262736ce	https://socratic.org/questions/what-is-the-ph-of-a-1-15-10-12-m-solution-of-koh	7	start physical_unit 10 10 ph none qc_end physical_unit 12 12 6 9 molarity qc_end end	[{"type":"physical unit","value":"pH [OF] KOH solution"}]	[{"type":"physical unit","value":"7"}]	[{"type":"physical unit","value":"Molarity [OF] KOH solution [=] \\pu{1.15 × 10^(-12) M}"}]	<h1 class="questionTitle" itemprop="name">What is the pH of a #1.15 * 10^-12# M solution of #KOH#?</h1>	null	7	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is such a dilute solution of KOH that its concentration is negligible. As such I would expect the pH to be very close to 7.</p> <p>You need to consider the auto - ionisation of water:</p> <p><mathjax>#sf(H_2OrightleftharpoonsH^++OH^-)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_w=[H^+][OH^-]=10^(-14)color(white)(x)"mol"^2"/"l"^(-2))#</mathjax> at <mathjax>#sf(25^@C)#</mathjax></p> <p>This means that <mathjax>#sf([H^+])#</mathjax> and <mathjax>#sf([OH^-])#</mathjax> are both equal to <mathjax>#sf(10^(-7)color(white)(x)"mol/l")#</mathjax>.</p> <p>You might, therefore, conclude that in this solution the total <mathjax>#sf(OH^-)#</mathjax> concentration is equal to <mathjax>#(sf(10^(-7)+1.15xx10^(-12)))color(white)(x)"mol/l"#</mathjax> but this is not quite right.</p> <p>You have disturbed a system at equilibrium by adding extra <mathjax>#sf(OH^-)#</mathjax> ions so the system would shift to the left according to Le Chatelier's Principle.</p> <p>You could then set up an ICE table to find out the equilibrium concentration of the <mathjax>#sf(OH^-)#</mathjax> ions and find the pH.</p> <p>However, because <mathjax>#sf(10^(-7))#</mathjax> is so much greater than <mathjax>#sf(1.15xx10^(-12)#</mathjax> the perturbation will be negligible and it is a fair assumption that <mathjax>#sf([OH^-]=10^(-7)"mol/l")#</mathjax>.</p> <p>This gives a <mathjax>#sf(pH)#</mathjax> of <mathjax>#sf(7)#</mathjax>.</p> <p><strong>Thought experiment:</strong></p> <p>There are <mathjax>#sf(10^(12)#</mathjax> litres in <mathjax>#sf(1km^(3))#</mathjax> of water. It would be the typical volume of a Scottish Loch (a small lake).</p> <p>Take 1 litre of 1.15 M NaOH and make it up to <mathjax>#sf(1km^(3))#</mathjax> of water.</p> <p>That is the sort of dilution we are talking about. It should be dilute enough for a pH of 7.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(pH~=7)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is such a dilute solution of KOH that its concentration is negligible. As such I would expect the pH to be very close to 7.</p> <p>You need to consider the auto - ionisation of water:</p> <p><mathjax>#sf(H_2OrightleftharpoonsH^++OH^-)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_w=[H^+][OH^-]=10^(-14)color(white)(x)"mol"^2"/"l"^(-2))#</mathjax> at <mathjax>#sf(25^@C)#</mathjax></p> <p>This means that <mathjax>#sf([H^+])#</mathjax> and <mathjax>#sf([OH^-])#</mathjax> are both equal to <mathjax>#sf(10^(-7)color(white)(x)"mol/l")#</mathjax>.</p> <p>You might, therefore, conclude that in this solution the total <mathjax>#sf(OH^-)#</mathjax> concentration is equal to <mathjax>#(sf(10^(-7)+1.15xx10^(-12)))color(white)(x)"mol/l"#</mathjax> but this is not quite right.</p> <p>You have disturbed a system at equilibrium by adding extra <mathjax>#sf(OH^-)#</mathjax> ions so the system would shift to the left according to Le Chatelier's Principle.</p> <p>You could then set up an ICE table to find out the equilibrium concentration of the <mathjax>#sf(OH^-)#</mathjax> ions and find the pH.</p> <p>However, because <mathjax>#sf(10^(-7))#</mathjax> is so much greater than <mathjax>#sf(1.15xx10^(-12)#</mathjax> the perturbation will be negligible and it is a fair assumption that <mathjax>#sf([OH^-]=10^(-7)"mol/l")#</mathjax>.</p> <p>This gives a <mathjax>#sf(pH)#</mathjax> of <mathjax>#sf(7)#</mathjax>.</p> <p><strong>Thought experiment:</strong></p> <p>There are <mathjax>#sf(10^(12)#</mathjax> litres in <mathjax>#sf(1km^(3))#</mathjax> of water. It would be the typical volume of a Scottish Loch (a small lake).</p> <p>Take 1 litre of 1.15 M NaOH and make it up to <mathjax>#sf(1km^(3))#</mathjax> of water.</p> <p>That is the sort of dilution we are talking about. It should be dilute enough for a pH of 7.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #1.15 * 10^-12# M solution of #KOH#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="301678" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-22T16:05:59" itemprop="dateCreated"> Aug 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(pH~=7)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is such a dilute solution of KOH that its concentration is negligible. As such I would expect the pH to be very close to 7.</p> <p>You need to consider the auto - ionisation of water:</p> <p><mathjax>#sf(H_2OrightleftharpoonsH^++OH^-)#</mathjax></p> <p>For which:</p> <p><mathjax>#sf(K_w=[H^+][OH^-]=10^(-14)color(white)(x)"mol"^2"/"l"^(-2))#</mathjax> at <mathjax>#sf(25^@C)#</mathjax></p> <p>This means that <mathjax>#sf([H^+])#</mathjax> and <mathjax>#sf([OH^-])#</mathjax> are both equal to <mathjax>#sf(10^(-7)color(white)(x)"mol/l")#</mathjax>.</p> <p>You might, therefore, conclude that in this solution the total <mathjax>#sf(OH^-)#</mathjax> concentration is equal to <mathjax>#(sf(10^(-7)+1.15xx10^(-12)))color(white)(x)"mol/l"#</mathjax> but this is not quite right.</p> <p>You have disturbed a system at equilibrium by adding extra <mathjax>#sf(OH^-)#</mathjax> ions so the system would shift to the left according to Le Chatelier's Principle.</p> <p>You could then set up an ICE table to find out the equilibrium concentration of the <mathjax>#sf(OH^-)#</mathjax> ions and find the pH.</p> <p>However, because <mathjax>#sf(10^(-7))#</mathjax> is so much greater than <mathjax>#sf(1.15xx10^(-12)#</mathjax> the perturbation will be negligible and it is a fair assumption that <mathjax>#sf([OH^-]=10^(-7)"mol/l")#</mathjax>.</p> <p>This gives a <mathjax>#sf(pH)#</mathjax> of <mathjax>#sf(7)#</mathjax>.</p> <p><strong>Thought experiment:</strong></p> <p>There are <mathjax>#sf(10^(12)#</mathjax> litres in <mathjax>#sf(1km^(3))#</mathjax> of water. It would be the typical volume of a Scottish Loch (a small lake).</p> <p>Take 1 litre of 1.15 M NaOH and make it up to <mathjax>#sf(1km^(3))#</mathjax> of water.</p> <p>That is the sort of dilution we are talking about. It should be dilute enough for a pH of 7.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/301678" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2607 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the pH of a #1.15 * 10^-12# M solution of #KOH#?	null
2,762	aa0cb35e-6ddd-11ea-9c55-ccda262736ce	https://socratic.org/questions/a-substance-contains-35-0-g-nitrogen-5-05-g-hydrogen-and-60-0-g-of-oxygen-how-ma	7.17 grams	start physical_unit 8 8 mass g qc_end physical_unit 5 5 3 4 mass qc_end physical_unit 8 8 6 7 mass qc_end physical_unit 13 13 10 11 mass qc_end physical_unit 1 1 23 24 mass qc_end end	[{"type":"physical unit","value":"Mass2 [OF] hydrogen [IN] grams"}]	[{"type":"physical unit","value":"7.17 grams"}]	[{"type":"physical unit","value":"Mass1 [OF] nitrogen [=] \\pu{35.0 g}"},{"type":"physical unit","value":"Mass1 [OF] hydrogen [=] \\pu{5.05 g}"},{"type":"physical unit","value":"Mass1 [OF] oxygen [=] \\pu{60.0 g}"},{"type":"physical unit","value":"Mass2 [OF] the substance [=] \\pu{142 g}"}]	<h1 class="questionTitle" itemprop="name">A substance contains 35.0 g nitrogen, 5.05 g hydrogen, and 60.0 g of oxygen. How many grams of hydrogen are there in a 142-g sample of this substance?</h1>	null	7.17 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need to dtermine what is known as the "<a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> by mass" for this compound. Then, the portion of a larger sample can be found.</p> <p>The total mass of the three <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> is 100.05 g, which means that the percentages are virtually the same as the given masses:</p> <p>% N = <mathjax>#35.0/100.05 xx 100#</mathjax> = 34.98 %</p> <p>% H = <mathjax>#5.05/100.05 xx 100#</mathjax> = 5.047 %</p> <p>% O = <mathjax>#60.0/100.05 xx 100#</mathjax> = 59.97 %</p> <p>While only the middle value is required, it is worthwhile to find all three in the event that we need the other information in a follow-up problem.</p> <p>Since 5.047 % of the mass is due to hydrogen, we can now multiply this percentage by any otherr mass:</p> <p>0.05047 xx 142 = 7.17 g of hydrogen</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There will be 7.17 g of hydrogen in the 142-g sample.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need to dtermine what is known as the "<a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> by mass" for this compound. Then, the portion of a larger sample can be found.</p> <p>The total mass of the three <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> is 100.05 g, which means that the percentages are virtually the same as the given masses:</p> <p>% N = <mathjax>#35.0/100.05 xx 100#</mathjax> = 34.98 %</p> <p>% H = <mathjax>#5.05/100.05 xx 100#</mathjax> = 5.047 %</p> <p>% O = <mathjax>#60.0/100.05 xx 100#</mathjax> = 59.97 %</p> <p>While only the middle value is required, it is worthwhile to find all three in the event that we need the other information in a follow-up problem.</p> <p>Since 5.047 % of the mass is due to hydrogen, we can now multiply this percentage by any otherr mass:</p> <p>0.05047 xx 142 = 7.17 g of hydrogen</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A substance contains 35.0 g nitrogen, 5.05 g hydrogen, and 60.0 g of oxygen. How many grams of hydrogen are there in a 142-g sample of this substance?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="405796" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-12T16:37:32" itemprop="dateCreated"> Apr 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There will be 7.17 g of hydrogen in the 142-g sample.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We need to dtermine what is known as the "<a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> by mass" for this compound. Then, the portion of a larger sample can be found.</p> <p>The total mass of the three <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> is 100.05 g, which means that the percentages are virtually the same as the given masses:</p> <p>% N = <mathjax>#35.0/100.05 xx 100#</mathjax> = 34.98 %</p> <p>% H = <mathjax>#5.05/100.05 xx 100#</mathjax> = 5.047 %</p> <p>% O = <mathjax>#60.0/100.05 xx 100#</mathjax> = 59.97 %</p> <p>While only the middle value is required, it is worthwhile to find all three in the event that we need the other information in a follow-up problem.</p> <p>Since 5.047 % of the mass is due to hydrogen, we can now multiply this percentage by any otherr mass:</p> <p>0.05047 xx 142 = 7.17 g of hydrogen</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/405796" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11578 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A substance contains 35.0 g nitrogen, 5.05 g hydrogen, and 60.0 g of oxygen. How many grams of hydrogen are there in a 142-g sample of this substance?	null
2,763	ac94b474-6ddd-11ea-bd2a-ccda262736ce	https://socratic.org/questions/a-gas-occupies-a-volume-of-0-6-lat-10-1-kpa-what-volume-will-the-gas-occupy-at-1	0.06 L	start physical_unit 14 15 volume l qc_end physical_unit 14 15 6 7 volume qc_end physical_unit 14 15 9 10 pressure qc_end physical_unit 14 15 18 19 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"0.06 L"}]	[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{0.6 L}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{10.1 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{101 kPa}"}]	<h1 class="questionTitle" itemprop="name">A gas occupies a volume of 0.6 L at 10.1 kPa. What volume will the gas occupy at 101 kPa? </h1>	null	0.06 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for <strong>Boyle's Law</strong></p> <blockquote> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#("10.1 kPa") xx (".6 L") = ("101 kPa") xx V_2#</mathjax></p> <p><mathjax>#[(10.1cancel("kPa"))(".6 L")]/(101cancel("kPa"))= V_2#</mathjax></p> <p><mathjax>#V_2 = ".06 L"#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#".06 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for <strong>Boyle's Law</strong></p> <blockquote> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#("10.1 kPa") xx (".6 L") = ("101 kPa") xx V_2#</mathjax></p> <p><mathjax>#[(10.1cancel("kPa"))(".6 L")]/(101cancel("kPa"))= V_2#</mathjax></p> <p><mathjax>#V_2 = ".06 L"#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A gas occupies a volume of 0.6 L at 10.1 kPa. What volume will the gas occupy at 101 kPa? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="233000" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> <a class="secondContributorPic" href="/users/wil052"><img alt="" class="" src="https://profilepictures.socratic.org/0P5SVeaCSfqbcHcQzSFx_Visiblelight.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a>·<a class="topContributorLink" href="/users/wil052"> Wil052 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T13:51:48" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#".06 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for <strong>Boyle's Law</strong></p> <blockquote> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#("10.1 kPa") xx (".6 L") = ("101 kPa") xx V_2#</mathjax></p> <p><mathjax>#[(10.1cancel("kPa"))(".6 L")]/(101cancel("kPa"))= V_2#</mathjax></p> <p><mathjax>#V_2 = ".06 L"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233000" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5602 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A gas occupies a volume of 0.6 L at 10.1 kPa. What volume will the gas occupy at 101 kPa?	null
2,764	aaa91492-6ddd-11ea-a069-ccda262736ce	https://socratic.org/questions/what-is-the-formula-for-lead-iv-oxide	PbO2	start chemical_formula qc_end substance 5 7 qc_end end	[{"type":"other","value":"Chemical Formula [OF] lead (IV) oxide [IN] default"}]	[{"type":"chemical equation","value":"PbO2"}]	[{"type":"substance name","value":"Lead (IV) oxide"}]	<h1 class="questionTitle" itemprop="name">What is the formula for lead (IV) oxide?</h1>	null	PbO2	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For each <mathjax># Pb^(4+) #</mathjax> we need two negative oxide ions <mathjax>#O^(2-)#</mathjax> to balance out total positive and total negative charge. </p> <p>The ratio of <mathjax># Pb^(4+) #</mathjax> and <mathjax>#O^(2-)#</mathjax> ios is 1:2 and hence the formula is Pb<mathjax>#O_2#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Pb<mathjax>#O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For each <mathjax># Pb^(4+) #</mathjax> we need two negative oxide ions <mathjax>#O^(2-)#</mathjax> to balance out total positive and total negative charge. </p> <p>The ratio of <mathjax># Pb^(4+) #</mathjax> and <mathjax>#O^(2-)#</mathjax> ios is 1:2 and hence the formula is Pb<mathjax>#O_2#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula for lead (IV) oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="252757" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-11T07:16:48" itemprop="dateCreated"> Apr 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Pb<mathjax>#O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For each <mathjax># Pb^(4+) #</mathjax> we need two negative oxide ions <mathjax>#O^(2-)#</mathjax> to balance out total positive and total negative charge. </p> <p>The ratio of <mathjax># Pb^(4+) #</mathjax> and <mathjax>#O^(2-)#</mathjax> ios is 1:2 and hence the formula is Pb<mathjax>#O_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/252757" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? 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2,765	ab35c39c-6ddd-11ea-8a31-ccda262736ce	https://socratic.org/questions/what-is-the-boiling-point-of-a-solution-made-by-dissolving-31-g-of-nacl-in-559-g	100.97 ℃	start physical_unit 7 7 boiling_point_temperature °c qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 19 19 16 17 mass qc_end end	[{"type":"physical unit","value":"Boiling point [OF] the solution [IN] ℃"}]	[{"type":"physical unit","value":"100.97 ℃"}]	[{"type":"physical unit","value":"Mass [OF] NaCl [=] \\pu{31 g}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{559 g}"}]	<h1 class="questionTitle" itemprop="name">What is the boiling point of a solution made by dissolving 31 g of NaCl in 559 g of water?</h1>	null	100.97 ℃	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to recognize here is that sodium chloride is an <strong>electrolyte</strong>, which means that it will dissociate in aqueous solution to give sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and chloride anions, <mathjax>#"Cl"^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NaCl"_text((aq]) -> "Na"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>This means that <strong>one mole</strong> of sodium chloride will produce <strong>two moles</strong> of ions in solution, one mole of sodium cations and one mole of chloride anions. Keep this in mind. </p> <p>The equation for <em>boiling-point elevation</em> looks like this</p> <blockquote> <p><mathjax>#color(blue)(DeltaT_b = i * K_b * b)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#i#</mathjax> - the van't Hoff factor;<br/> <mathjax>#K_b#</mathjax> - the <strong>ebullioscopic constant</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>;<br/> <mathjax>#b#</mathjax> - the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution. <br/> <mathjax>#DeltaT_b#</mathjax> - the poiling point elevation - defined as <mathjax>#T_"b" - T_"b"^@#</mathjax></p> <p>The <em>ebullioscopic constant</em> of water is equal to <mathjax>#0.512^@"C kg mol"^(-1)#</mathjax></p> <p><a href="http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf" rel="nofollow" target="_blank">http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf</a></p> <p>To determine the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution, use sodium chloride's molar mass to help you find the number of moles you have in that <mathjax>#"31-g"#</mathjax> sample. </p> <blockquote> <p><mathjax>#31color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "0.5305 moles NaCl"#</mathjax></p> </blockquote> <p>This means that the molality of the solution will be - <strong>do not</strong> forget to convert the mass of the solvent from <em>grams</em> to <em>kilograms</em></p> <blockquote> <p><mathjax>#color(blue)(b = n_"solute"/m_"solvent")#</mathjax></p> <p><mathjax>#b = "0.5305 moles"/(559 * 10^(-3)"kg") = "0.949 molal"#</mathjax></p> </blockquote> <p>Now, the <strong>van't Hoff factor</strong>, <mathjax>#i#</mathjax>, will be equal to <mathjax>#2#</mathjax> because you get two moles of particles per mole of sodium chloride added to the solution. </p> <p>The boiling-point elevation will thus be </p> <blockquote> <p><mathjax>#DeltaT_"b" = 2 * 0.512^@"C" color(red)(cancel(color(black)("kg"))) color(red)(cancel(color(black)("mol"^(-1)))) * 0.949 color(red)(cancel(color(black)("moles"))) color(red)(cancel(color(black)("kg"^(-1)))) = 0.97^@"C"#</mathjax></p> </blockquote> <p>This means that the boiling point of the solution will be </p> <blockquote> <p><mathjax>#DeltaT_"b" = T_"b" - T_"b"^@ implies T_"b" = T_"b"^@ + DeltaT_"b"#</mathjax></p> <p><mathjax>#T_"b" = 100^@"C" + 0.97^@"C" = color(green)(101^@"C")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#101^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to recognize here is that sodium chloride is an <strong>electrolyte</strong>, which means that it will dissociate in aqueous solution to give sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and chloride anions, <mathjax>#"Cl"^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NaCl"_text((aq]) -> "Na"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>This means that <strong>one mole</strong> of sodium chloride will produce <strong>two moles</strong> of ions in solution, one mole of sodium cations and one mole of chloride anions. Keep this in mind. </p> <p>The equation for <em>boiling-point elevation</em> looks like this</p> <blockquote> <p><mathjax>#color(blue)(DeltaT_b = i * K_b * b)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#i#</mathjax> - the van't Hoff factor;<br/> <mathjax>#K_b#</mathjax> - the <strong>ebullioscopic constant</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>;<br/> <mathjax>#b#</mathjax> - the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution. <br/> <mathjax>#DeltaT_b#</mathjax> - the poiling point elevation - defined as <mathjax>#T_"b" - T_"b"^@#</mathjax></p> <p>The <em>ebullioscopic constant</em> of water is equal to <mathjax>#0.512^@"C kg mol"^(-1)#</mathjax></p> <p><a href="http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf" rel="nofollow" target="_blank">http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf</a></p> <p>To determine the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution, use sodium chloride's molar mass to help you find the number of moles you have in that <mathjax>#"31-g"#</mathjax> sample. </p> <blockquote> <p><mathjax>#31color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "0.5305 moles NaCl"#</mathjax></p> </blockquote> <p>This means that the molality of the solution will be - <strong>do not</strong> forget to convert the mass of the solvent from <em>grams</em> to <em>kilograms</em></p> <blockquote> <p><mathjax>#color(blue)(b = n_"solute"/m_"solvent")#</mathjax></p> <p><mathjax>#b = "0.5305 moles"/(559 * 10^(-3)"kg") = "0.949 molal"#</mathjax></p> </blockquote> <p>Now, the <strong>van't Hoff factor</strong>, <mathjax>#i#</mathjax>, will be equal to <mathjax>#2#</mathjax> because you get two moles of particles per mole of sodium chloride added to the solution. </p> <p>The boiling-point elevation will thus be </p> <blockquote> <p><mathjax>#DeltaT_"b" = 2 * 0.512^@"C" color(red)(cancel(color(black)("kg"))) color(red)(cancel(color(black)("mol"^(-1)))) * 0.949 color(red)(cancel(color(black)("moles"))) color(red)(cancel(color(black)("kg"^(-1)))) = 0.97^@"C"#</mathjax></p> </blockquote> <p>This means that the boiling point of the solution will be </p> <blockquote> <p><mathjax>#DeltaT_"b" = T_"b" - T_"b"^@ implies T_"b" = T_"b"^@ + DeltaT_"b"#</mathjax></p> <p><mathjax>#T_"b" = 100^@"C" + 0.97^@"C" = color(green)(101^@"C")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the boiling point of a solution made by dissolving 31 g of NaCl in 559 g of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="193977" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T15:18:39" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#101^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The important thing to recognize here is that sodium chloride is an <strong>electrolyte</strong>, which means that it will dissociate in aqueous solution to give sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and chloride anions, <mathjax>#"Cl"^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NaCl"_text((aq]) -> "Na"_text((aq])^(+) + "Cl"_text((aq])^(-)#</mathjax></p> </blockquote> <p>This means that <strong>one mole</strong> of sodium chloride will produce <strong>two moles</strong> of ions in solution, one mole of sodium cations and one mole of chloride anions. Keep this in mind. </p> <p>The equation for <em>boiling-point elevation</em> looks like this</p> <blockquote> <p><mathjax>#color(blue)(DeltaT_b = i * K_b * b)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#i#</mathjax> - the van't Hoff factor;<br/> <mathjax>#K_b#</mathjax> - the <strong>ebullioscopic constant</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>;<br/> <mathjax>#b#</mathjax> - the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution. <br/> <mathjax>#DeltaT_b#</mathjax> - the poiling point elevation - defined as <mathjax>#T_"b" - T_"b"^@#</mathjax></p> <p>The <em>ebullioscopic constant</em> of water is equal to <mathjax>#0.512^@"C kg mol"^(-1)#</mathjax></p> <p><a href="http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf" rel="nofollow" target="_blank">http://www.vaxasoftware.com/doc_eduen/qui/tcriosebu.pdf</a></p> <p>To determine the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution, use sodium chloride's molar mass to help you find the number of moles you have in that <mathjax>#"31-g"#</mathjax> sample. </p> <blockquote> <p><mathjax>#31color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "0.5305 moles NaCl"#</mathjax></p> </blockquote> <p>This means that the molality of the solution will be - <strong>do not</strong> forget to convert the mass of the solvent from <em>grams</em> to <em>kilograms</em></p> <blockquote> <p><mathjax>#color(blue)(b = n_"solute"/m_"solvent")#</mathjax></p> <p><mathjax>#b = "0.5305 moles"/(559 * 10^(-3)"kg") = "0.949 molal"#</mathjax></p> </blockquote> <p>Now, the <strong>van't Hoff factor</strong>, <mathjax>#i#</mathjax>, will be equal to <mathjax>#2#</mathjax> because you get two moles of particles per mole of sodium chloride added to the solution. </p> <p>The boiling-point elevation will thus be </p> <blockquote> <p><mathjax>#DeltaT_"b" = 2 * 0.512^@"C" color(red)(cancel(color(black)("kg"))) color(red)(cancel(color(black)("mol"^(-1)))) * 0.949 color(red)(cancel(color(black)("moles"))) color(red)(cancel(color(black)("kg"^(-1)))) = 0.97^@"C"#</mathjax></p> </blockquote> <p>This means that the boiling point of the solution will be </p> <blockquote> <p><mathjax>#DeltaT_"b" = T_"b" - T_"b"^@ implies T_"b" = T_"b"^@ + DeltaT_"b"#</mathjax></p> <p><mathjax>#T_"b" = 100^@"C" + 0.97^@"C" = color(green)(101^@"C")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193977" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-colligative-properties-determined"> How are colligative properties determined? 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2,766	a8cdbe46-6ddd-11ea-a77b-ccda262736ce	https://socratic.org/questions/what-is-the-mass-in-grams-of-3-75-x-10-15-atoms-of-gold	1.23 × 10^(-6) grams	start physical_unit 12 12 mass g qc_end end	[{"type":"physical unit","value":"Mass [OF] gold [IN] grams"}]	[{"type":"physical unit","value":"1.23 × 10^(-6) grams"}]	[{"type":"physical unit","value":"Number [OF] gold atoms [=] \\pu{3.75 × 10^15}"}]	<h1 class="questionTitle" itemprop="name">What is the mass, in grams, of #3.75 xx 10^15# atoms of gold?</h1>	null	1.23 × 10^(-6) grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax># 1 " mole " = 6.022 xx 10^23 #</mathjax> atoms</p> <p>Gold's (Au) molar mass from <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic table</a> is "196.966" g/mol</p> <p>Using dimensional analysis:</p> <p><mathjax>#3.75 xx 10^15 cancel(" atoms Au ") xx color(red)(cancel(1 mol))/(6.022 xx 10^23 cancel(" atoms Au ")) xx (196.966 " g")/ color(red)(cancel(1 mol)) = (3.75(196.966))/6.022 xx 10^(15-23) = 122.654 xx 10^-8 = 1.227 xx 10^-6 " g Au"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.227 xx 10^-6#</mathjax> g of gold</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax># 1 " mole " = 6.022 xx 10^23 #</mathjax> atoms</p> <p>Gold's (Au) molar mass from <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic table</a> is "196.966" g/mol</p> <p>Using dimensional analysis:</p> <p><mathjax>#3.75 xx 10^15 cancel(" atoms Au ") xx color(red)(cancel(1 mol))/(6.022 xx 10^23 cancel(" atoms Au ")) xx (196.966 " g")/ color(red)(cancel(1 mol)) = (3.75(196.966))/6.022 xx 10^(15-23) = 122.654 xx 10^-8 = 1.227 xx 10^-6 " g Au"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the mass, in grams, of #3.75 xx 10^15# atoms of gold?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="407315" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/marfre"><img alt="" class="" src="https://profilepictures.socratic.org/48J0XLK1To2NunsG33ct_11.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/marfre"> marfre </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-15T22:47:49" itemprop="dateCreated"> Apr 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.227 xx 10^-6#</mathjax> g of gold</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax># 1 " mole " = 6.022 xx 10^23 #</mathjax> atoms</p> <p>Gold's (Au) molar mass from <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic table</a> is "196.966" g/mol</p> <p>Using dimensional analysis:</p> <p><mathjax>#3.75 xx 10^15 cancel(" atoms Au ") xx color(red)(cancel(1 mol))/(6.022 xx 10^23 cancel(" atoms Au ")) xx (196.966 " g")/ color(red)(cancel(1 mol)) = (3.75(196.966))/6.022 xx 10^(15-23) = 122.654 xx 10^-8 = 1.227 xx 10^-6 " g Au"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/407315" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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<a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 60765 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the mass, in grams, of #3.75 xx 10^15# atoms of gold?	null
2,767	a842b05d-6ddd-11ea-aae1-ccda262736ce	https://socratic.org/questions/to-what-volume-must-440-0-ml-of-3-50-m-kno-3-be-diluted-to-produce-1-50-m-kno-3	1026.67 mL	start physical_unit 9 9 volume ml qc_end physical_unit 9 9 4 5 volume qc_end physical_unit 9 9 7 8 molarity qc_end physical_unit 9 9 14 15 molarity qc_end end	[{"type":"physical unit","value":"Volume2 [OF] KNO3 [IN] mL"}]	[{"type":"physical unit","value":"1026.67 mL"}]	[{"type":"physical unit","value":"Volume1 [OF] KNO3 [=] \\pu{440.0 mL}"},{"type":"physical unit","value":"Molarity1 [OF] KNO3 [=] \\pu{3.50 M}"},{"type":"physical unit","value":"Molarity2 [OF] KNO3 [=] \\pu{1.50 M}"}]	<h1 class="questionTitle" itemprop="name">To what volume must 440.0 mL of 3.50 M #KNO_3# be diluted to produce 1.50 M #KNO_3#?</h1>	null	1026.67 mL	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The product <mathjax>#C_1V_1#</mathjax> has units of <mathjax>#molcancel(L^-1)xxcancelL=mol#</mathjax>, and thus it is dimensionally consistent. </p> <p>And <mathjax>#V_2=(C_1V_1)/C_2=(440.0mLxx3.50cancel(molL^-1))/(1.50cancel(molL^-1))=??mL#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_1V_1=C_2V_2#</mathjax> </p> <p><mathjax>#V_2=" a bit over 1 litre"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The product <mathjax>#C_1V_1#</mathjax> has units of <mathjax>#molcancel(L^-1)xxcancelL=mol#</mathjax>, and thus it is dimensionally consistent. </p> <p>And <mathjax>#V_2=(C_1V_1)/C_2=(440.0mLxx3.50cancel(molL^-1))/(1.50cancel(molL^-1))=??mL#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">To what volume must 440.0 mL of 3.50 M #KNO_3# be diluted to produce 1.50 M #KNO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386770" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-05T10:14:25" itemprop="dateCreated"> Mar 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_1V_1=C_2V_2#</mathjax> </p> <p><mathjax>#V_2=" a bit over 1 litre"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The product <mathjax>#C_1V_1#</mathjax> has units of <mathjax>#molcancel(L^-1)xxcancelL=mol#</mathjax>, and thus it is dimensionally consistent. </p> <p>And <mathjax>#V_2=(C_1V_1)/C_2=(440.0mLxx3.50cancel(molL^-1))/(1.50cancel(molL^-1))=??mL#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386770" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1377 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	To what volume must 440.0 mL of 3.50 M #KNO_3# be diluted to produce 1.50 M #KNO_3#?	null
2,768	a8b6e114-6ddd-11ea-a49d-ccda262736ce	https://socratic.org/questions/what-mass-of-solid-aluminium-is-needed-to-react-with-excess-h2so4-aq-to-produced	15 g	start physical_unit 3 4 mass g qc_end physical_unit 17 17 14 15 volume qc_end physical_unit 17 17 19 20 pressure qc_end physical_unit 17 17 22 23 temperature qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] solid aluminium [IN] g"}]	[{"type":"physical unit","value":"15 g"}]	[{"type":"physical unit","value":"Volume [OF] H2(g) [=] \\pu{20.0 L}"},{"type":"physical unit","value":"Pressure [OF] H2(g) [=] \\pu{1.0 atm}"},{"type":"physical unit","value":"Temperature [OF] H2(g) [=] \\pu{298 K}"},{"type":"other","value":"Excess H2SO4(aq) "}]	<h1 class="questionTitle" itemprop="name">What mass of solid aluminium is needed to react with excess H2SO4(aq) to produced 20.0 L of H2(g) at 1.0 atm and 298 K?</h1>	null	15 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"H"_2#</mathjax></strong></p> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong>:#.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#n = (pV)/(RT)#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#p = "1.0 atm"#</mathjax><br/> <mathjax>#V = "20.0 L"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm· K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "298 K"#</mathjax></p> <p>∴ <mathjax>#n = (1.0 color(red)(cancel(color(black)("atm"))) × 20.0 color(red)(cancel(color(black)("L"))))/("0.082 06" color(red)(cancel(color(black)("L·atm· K"^"-1")))"mol"^"-1" × 298 color(red)(cancel(color(black)("K")))) = "0.818 mol"#</mathjax></p> <blockquote></blockquote> <p><strong>Calculate the mass of <mathjax>#"Al"#</mathjax></strong></p> <p><mathjax>#"2Al"+"3H"_2"SO"_4 → "Al"_2("SO"_4)_3 +"3H"_2#</mathjax></p> <p><mathjax>#"Mass of Al" = 0.818 color(red)(cancel(color(black)("mol H"_2))) × (2 color(red)(cancel(color(black)("mol Al"))))/(3 color(red)(cancel(color(black)("mol H"_2)))) × "26.98 g Al"/(1 color(red)(cancel(color(black)("mol Al")))) = "15 g Al"#</mathjax></p> <p><strong>Note</strong>: The answer can have only two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, because that is all you gave for the pressure of the hydrogen..</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of aluminium is 15 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"H"_2#</mathjax></strong></p> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong>:#.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#n = (pV)/(RT)#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#p = "1.0 atm"#</mathjax><br/> <mathjax>#V = "20.0 L"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm· K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "298 K"#</mathjax></p> <p>∴ <mathjax>#n = (1.0 color(red)(cancel(color(black)("atm"))) × 20.0 color(red)(cancel(color(black)("L"))))/("0.082 06" color(red)(cancel(color(black)("L·atm· K"^"-1")))"mol"^"-1" × 298 color(red)(cancel(color(black)("K")))) = "0.818 mol"#</mathjax></p> <blockquote></blockquote> <p><strong>Calculate the mass of <mathjax>#"Al"#</mathjax></strong></p> <p><mathjax>#"2Al"+"3H"_2"SO"_4 → "Al"_2("SO"_4)_3 +"3H"_2#</mathjax></p> <p><mathjax>#"Mass of Al" = 0.818 color(red)(cancel(color(black)("mol H"_2))) × (2 color(red)(cancel(color(black)("mol Al"))))/(3 color(red)(cancel(color(black)("mol H"_2)))) × "26.98 g Al"/(1 color(red)(cancel(color(black)("mol Al")))) = "15 g Al"#</mathjax></p> <p><strong>Note</strong>: The answer can have only two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, because that is all you gave for the pressure of the hydrogen..</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of solid aluminium is needed to react with excess H2SO4(aq) to produced 20.0 L of H2(g) at 1.0 atm and 298 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="419371" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-07T23:11:33" itemprop="dateCreated"> May 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of aluminium is 15 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Calculate the moles of <mathjax>#"H"_2#</mathjax></strong></p> <p>We can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong>:#.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(\|color(white)(a/a)pV = nRTcolor(white)(a/a)\|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#n = (pV)/(RT)#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#p = "1.0 atm"#</mathjax><br/> <mathjax>#V = "20.0 L"#</mathjax><br/> <mathjax>#R = "0.082 06 L·atm· K"^"-1""mol"^"-1"#</mathjax><br/> <mathjax>#T = "298 K"#</mathjax></p> <p>∴ <mathjax>#n = (1.0 color(red)(cancel(color(black)("atm"))) × 20.0 color(red)(cancel(color(black)("L"))))/("0.082 06" color(red)(cancel(color(black)("L·atm· K"^"-1")))"mol"^"-1" × 298 color(red)(cancel(color(black)("K")))) = "0.818 mol"#</mathjax></p> <blockquote></blockquote> <p><strong>Calculate the mass of <mathjax>#"Al"#</mathjax></strong></p> <p><mathjax>#"2Al"+"3H"_2"SO"_4 → "Al"_2("SO"_4)_3 +"3H"_2#</mathjax></p> <p><mathjax>#"Mass of Al" = 0.818 color(red)(cancel(color(black)("mol H"_2))) × (2 color(red)(cancel(color(black)("mol Al"))))/(3 color(red)(cancel(color(black)("mol H"_2)))) × "26.98 g Al"/(1 color(red)(cancel(color(black)("mol Al")))) = "15 g Al"#</mathjax></p> <p><strong>Note</strong>: The answer can have only two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, because that is all you gave for the pressure of the hydrogen..</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/419371" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li 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2,769	a9b967d4-6ddd-11ea-a1d6-ccda262736ce	https://socratic.org/questions/what-mass-of-glucose-c-6h-12o-6-would-be-required-to-prepare-5-10-3-l-of-a-0-215	193661.25 g	start physical_unit 4 4 mass g qc_end physical_unit 18 18 10 13 volume qc_end physical_unit 4 4 16 17 molarity qc_end end	[{"type":"physical unit","value":"Mass [OF] C6H12O6 [IN] g"}]	[{"type":"physical unit","value":"193661.25 g"}]	[{"type":"physical unit","value":"Volume [OF] C6H12O6 solution [=] \\pu{5 × 10^3 L }"},{"type":"physical unit","value":"Molarity [OF] C6H12O6 solution [=] \\pu{0.215 M}"}]	<h1 class="questionTitle" itemprop="name">What mass of glucose, #C_6H_12O_6#, would be required to prepare #5 * 10^3# #L# of a #0.215# #M# solution?</h1>	null	193661.25 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is defined as <mathjax>#M#</mathjax>= <mathjax>#(mols)/(1L solution)#</mathjax></p> <p>from this, we can deduct that .215<mathjax>#M#</mathjax> <mathjax>#C_6H_12O_6#</mathjax>= <mathjax>#(.215mol)/(1L solution)#</mathjax></p> <p><mathjax>#C#</mathjax> = 12.01 * 6 = 72.06g<br/> <mathjax>#H#</mathjax> = 1.0079 * 12 = 12.0948g<br/> <mathjax>#O#</mathjax> = 16.00 * 6 = 96.00g<br/> <mathjax>#C_6H_12O_6#</mathjax>= 180.15g</p> <p>Start with what is given</p> <p><mathjax>#5*10^3#</mathjax><mathjax>#L#</mathjax> <mathjax>#C_6H_12O_6#</mathjax> <mathjax>#(.215 molC_6H_12O_6)/(1L solution)#</mathjax> <mathjax>#(180.15g)/(1mol C_6H_12O_6)#</mathjax>= 193661.25g <mathjax>#C_6H_12O_6#</mathjax> (before sig figs)</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>193661.25g <mathjax>#C_6H_12O_6#</mathjax> (before sig figs)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is defined as <mathjax>#M#</mathjax>= <mathjax>#(mols)/(1L solution)#</mathjax></p> <p>from this, we can deduct that .215<mathjax>#M#</mathjax> <mathjax>#C_6H_12O_6#</mathjax>= <mathjax>#(.215mol)/(1L solution)#</mathjax></p> <p><mathjax>#C#</mathjax> = 12.01 * 6 = 72.06g<br/> <mathjax>#H#</mathjax> = 1.0079 * 12 = 12.0948g<br/> <mathjax>#O#</mathjax> = 16.00 * 6 = 96.00g<br/> <mathjax>#C_6H_12O_6#</mathjax>= 180.15g</p> <p>Start with what is given</p> <p><mathjax>#5*10^3#</mathjax><mathjax>#L#</mathjax> <mathjax>#C_6H_12O_6#</mathjax> <mathjax>#(.215 molC_6H_12O_6)/(1L solution)#</mathjax> <mathjax>#(180.15g)/(1mol C_6H_12O_6)#</mathjax>= 193661.25g <mathjax>#C_6H_12O_6#</mathjax> (before sig figs)</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of glucose, #C_6H_12O_6#, would be required to prepare #5 * 10^3# #L# of a #0.215# #M# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232987" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/wil052"><img alt="" class="" src="https://profilepictures.socratic.org/0P5SVeaCSfqbcHcQzSFx_Visiblelight.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/wil052"> Wil052 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T13:25:41" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>193661.25g <mathjax>#C_6H_12O_6#</mathjax> (before sig figs)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is defined as <mathjax>#M#</mathjax>= <mathjax>#(mols)/(1L solution)#</mathjax></p> <p>from this, we can deduct that .215<mathjax>#M#</mathjax> <mathjax>#C_6H_12O_6#</mathjax>= <mathjax>#(.215mol)/(1L solution)#</mathjax></p> <p><mathjax>#C#</mathjax> = 12.01 * 6 = 72.06g<br/> <mathjax>#H#</mathjax> = 1.0079 * 12 = 12.0948g<br/> <mathjax>#O#</mathjax> = 16.00 * 6 = 96.00g<br/> <mathjax>#C_6H_12O_6#</mathjax>= 180.15g</p> <p>Start with what is given</p> <p><mathjax>#5*10^3#</mathjax><mathjax>#L#</mathjax> <mathjax>#C_6H_12O_6#</mathjax> <mathjax>#(.215 molC_6H_12O_6)/(1L solution)#</mathjax> <mathjax>#(180.15g)/(1mol C_6H_12O_6)#</mathjax>= 193661.25g <mathjax>#C_6H_12O_6#</mathjax> (before sig figs)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232987" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight 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</a> </div> </div> </div> </div> </div> </div> </article>	What mass of glucose, #C_6H_12O_6#, would be required to prepare #5 * 10^3# #L# of a #0.215# #M# solution?	null
2,770	a9b4ffef-6ddd-11ea-ad95-ccda262736ce	https://socratic.org/questions/given-the-equation-cu-agno3-ag-cuno3-what-mass-of-silver-in-grams-is-precipitate	69.0 grams	start physical_unit 13 13 mass g qc_end chemical_equation 3 9 qc_end physical_unit 22 22 19 20 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] silver [IN] grams"}]	[{"type":"physical unit","value":"69.0 grams"}]	[{"type":"chemical equation","value":"Cu + AgNO3 -> Ag + CuNO3"},{"type":"physical unit","value":"Mass [OF] copper [=] \\pu{40.0 g}"},{"type":"other","value":"Excess of silver nitrate."}]	<h1 class="questionTitle" itemprop="name">Given the equation: Cu + AgNO3 --> Ag + CuNO3, what mass of silver in grams is precipitated when 40.0 g of copper reacts with an excess of silver nitrate in solution?</h1>	null	69.0 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#Cu(s)+AgNO_3(aq)->Ag(s)+CuNO_3(aq)#</mathjax></p> <p>Since the silver nitrate is in excess, then <strong>copper is the limiting reactant</strong> , and therefore, its mass will be used to calculate the mass of silver that will form:</p> <p><mathjax>#?gAg=40.0cancel(gCu)xx(cancel(1molCu))/(63.5cancel(gCu))xx(1cancel(molAg))/(1cancel(molCu))xx(107.9Ag)/(1cancel(molAg))=68.0gAg#</mathjax> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#68.0g#</mathjax> of silver. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#Cu(s)+AgNO_3(aq)->Ag(s)+CuNO_3(aq)#</mathjax></p> <p>Since the silver nitrate is in excess, then <strong>copper is the limiting reactant</strong> , and therefore, its mass will be used to calculate the mass of silver that will form:</p> <p><mathjax>#?gAg=40.0cancel(gCu)xx(cancel(1molCu))/(63.5cancel(gCu))xx(1cancel(molAg))/(1cancel(molCu))xx(107.9Ag)/(1cancel(molAg))=68.0gAg#</mathjax> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Given the equation: Cu + AgNO3 --> Ag + CuNO3, what mass of silver in grams is precipitated when 40.0 g of copper reacts with an excess of silver nitrate in solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196386" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-04T18:42:11" itemprop="dateCreated"> Dec 4, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#68.0g#</mathjax> of silver. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction is:</p> <p><mathjax>#Cu(s)+AgNO_3(aq)->Ag(s)+CuNO_3(aq)#</mathjax></p> <p>Since the silver nitrate is in excess, then <strong>copper is the limiting reactant</strong> , and therefore, its mass will be used to calculate the mass of silver that will form:</p> <p><mathjax>#?gAg=40.0cancel(gCu)xx(cancel(1molCu))/(63.5cancel(gCu))xx(1cancel(molAg))/(1cancel(molCu))xx(107.9Ag)/(1cancel(molAg))=68.0gAg#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196386" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight 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2,771	a865792d-6ddd-11ea-b7bb-ccda262736ce	https://socratic.org/questions/how-do-you-balance-c3h6-nh3-o2-c3h3n-h2o	2 C3H6 + 2 NH3 + 3 O2 -> 2 C3H3N + 6 H2O	start chemical_equation qc_end chemical_equation 4 12 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"2 C3H6 + 2 NH3 + 3 O2 -> 2 C3H3N + 6 H2O"}]	[{"type":"chemical equation","value":"C3H6 + NH3 + O2 -> C3H3N + H2O"}]	<h1 class="questionTitle" itemprop="name">How do you balance C3H6 + NH3 + O2 --> C3H3N + H2O? </h1>	null	2 C3H6 + 2 NH3 + 3 O2 -> 2 C3H3N + 6 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The above equation represents the formation of a very important commodity chemical, acrylonitrile, <mathjax>#H_2C=CHC-=N#</mathjax>. It is used in the synthesis of acrylates, such as acrylic acid.</p> <p>By the way, please check whether the equation is balanced; do not trust my arithmetic. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Do you refer to acrylonitrile synthesis?</p> <p><mathjax>#2H_3C-CH=CH_2 + 2NH_3 + 3O_2 rarr 2H_2C=CHC-=N + 6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The above equation represents the formation of a very important commodity chemical, acrylonitrile, <mathjax>#H_2C=CHC-=N#</mathjax>. It is used in the synthesis of acrylates, such as acrylic acid.</p> <p>By the way, please check whether the equation is balanced; do not trust my arithmetic. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance C3H6 + NH3 + O2 --> C3H3N + H2O? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212469" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-14T19:14:37" itemprop="dateCreated"> Jan 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Do you refer to acrylonitrile synthesis?</p> <p><mathjax>#2H_3C-CH=CH_2 + 2NH_3 + 3O_2 rarr 2H_2C=CHC-=N + 6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The above equation represents the formation of a very important commodity chemical, acrylonitrile, <mathjax>#H_2C=CHC-=N#</mathjax>. It is used in the synthesis of acrylates, such as acrylic acid.</p> <p>By the way, please check whether the equation is balanced; do not trust my arithmetic. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212469" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4039 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance C3H6 + NH3 + O2 --> C3H3N + H2O?	null
2,772	ac5f4e2f-6ddd-11ea-a39d-ccda262736ce	https://socratic.org/questions/56faed0f7c0149577ad10a90	Fe2S3	start chemical_formula qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 15 15 12 13 mass qc_end end	[{"type":"other","value":"Chemical Formula [OF] iron sulfide [IN] empirical"}]	[{"type":"chemical equation","value":"Fe2S3"}]	[{"type":"physical unit","value":"Mass [OF] metal [=] \\pu{2.561 g}"},{"type":"physical unit","value":"Mass [OF] sulfur [=] \\pu{2.206 g}"}]	<h1 class="questionTitle" itemprop="name">A sample of an iron sulfide contains #2.561g# of metal, and #2.206g# of sulfur. What is the empirical formula of iron sulfide? </h1>	null	Fe2S3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of iron"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.561g)/(55.85gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0459mol#</mathjax></p> <p><mathjax>#"Moles of sulfur"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.206g)/(32.06gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0688mol#</mathjax></p> <p>If we divide thru by the lower molar quantity, we get, <mathjax>#FeS_(1.5)#</mathjax>. However, by definition, the empirical formula is the simplest WHOLE number that defines constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a species, so we double the formula to get WHOLE numbers:</p> <p><mathjax>#Fe_2S_3#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2S_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of iron"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.561g)/(55.85gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0459mol#</mathjax></p> <p><mathjax>#"Moles of sulfur"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.206g)/(32.06gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0688mol#</mathjax></p> <p>If we divide thru by the lower molar quantity, we get, <mathjax>#FeS_(1.5)#</mathjax>. However, by definition, the empirical formula is the simplest WHOLE number that defines constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a species, so we double the formula to get WHOLE numbers:</p> <p><mathjax>#Fe_2S_3#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A sample of an iron sulfide contains #2.561g# of metal, and #2.206g# of sulfur. What is the empirical formula of iron sulfide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="276056" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-10T18:12:42" itemprop="dateCreated"> Jun 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2S_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of iron"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.561g)/(55.85gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0459mol#</mathjax></p> <p><mathjax>#"Moles of sulfur"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(2.206g)/(32.06gmol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.0688mol#</mathjax></p> <p>If we divide thru by the lower molar quantity, we get, <mathjax>#FeS_(1.5)#</mathjax>. However, by definition, the empirical formula is the simplest WHOLE number that defines constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in a species, so we double the formula to get WHOLE numbers:</p> <p><mathjax>#Fe_2S_3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/276056" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2112 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A sample of an iron sulfide contains #2.561g# of metal, and #2.206g# of sulfur. What is the empirical formula of iron sulfide?	null
2,773	a9a3d9d4-6ddd-11ea-bde6-ccda262736ce	https://socratic.org/questions/how-many-moles-of-sodium-nitrate-nano-3-would-be-produced-from-the-complete-reac	3.12 moles	start physical_unit 6 6 mole mol qc_end physical_unit 19 19 15 16 mass qc_end chemical_equation 23 30 qc_end end	[{"type":"physical unit","value":"Mole [OF] NaNO3 [IN] moles"}]	[{"type":"physical unit","value":"3.12 moles"}]	[{"type":"physical unit","value":"Mass [OF] Na2CrO4 [=] \\pu{253 g}"},{"type":"chemical equation","value":"Pb(NO3)2 + Na2CrO4 -> PbCrO4 + 2 NaNO3"}]	<h1 class="questionTitle" itemprop="name">How many moles of sodium nitrate, #NaNO_3#, would be produced from the complete reaction of 253g sodium chromate, #Na_2CrO_4#? </h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The reaction is <mathjax>#Pb(NO_3)_2+Na_2CrO_4 -> PbCrO_4 + 2NaNO_3#</mathjax>.</p></div> </h2> </div> </div>	3.12 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="My Worked Out Solution" src="https://useruploads.socratic.org/vrL5TUL8TxWxeTKqZkn9_FullSizeRender%20%281%29.jpg"/></p> <p>When performing mass to mole calculations, I use the following method:</p> <p>Quantity Sought = Quantity Given x Conversion Factor</p> <ul> <li>The quantity sought is what we are trying to find, in our case we are trying to determine the number of moles of <mathjax>#NaNO_3#</mathjax> </li> <li>The quantity given is the value that we have in the problem, which is 253g of <mathjax>#Na_2CrO_4#</mathjax></li> <li>The conversion factor is what allows us to go from grams of <mathjax>#Na_2CrO_4#</mathjax> to moles of <mathjax>#Na_2CrO_4#</mathjax>, which ultimately leads us to the number of moles of <mathjax>#NaNO_3#</mathjax>. </li> </ul> <p>The 161.97g represents the molar mass of <mathjax>#Na_2CrO_4#</mathjax> and the 2:1 ratio of <mathjax>#NaNO_3#</mathjax> to <mathjax>#Na_2CrO_4#</mathjax> comes from the coefficients of the balanced equation. </p> <p>As you set up these type of problems the units that you no longer need should cancel out, leaving the unit you want as your end result. </p> <p><a href="https://www.boundless.com/chemistry/textbooks/boundless-chemistry-textbook/mass-relationships-and-chemical-equations-3/reaction-stoichiometry-44/mass-to-mole-conversions-232-5142/" rel="nofollow">Mass-to-Mole Conversions</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.12 Moles of <mathjax>#NaNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="My Worked Out Solution" src="https://useruploads.socratic.org/vrL5TUL8TxWxeTKqZkn9_FullSizeRender%20%281%29.jpg"/></p> <p>When performing mass to mole calculations, I use the following method:</p> <p>Quantity Sought = Quantity Given x Conversion Factor</p> <ul> <li>The quantity sought is what we are trying to find, in our case we are trying to determine the number of moles of <mathjax>#NaNO_3#</mathjax> </li> <li>The quantity given is the value that we have in the problem, which is 253g of <mathjax>#Na_2CrO_4#</mathjax></li> <li>The conversion factor is what allows us to go from grams of <mathjax>#Na_2CrO_4#</mathjax> to moles of <mathjax>#Na_2CrO_4#</mathjax>, which ultimately leads us to the number of moles of <mathjax>#NaNO_3#</mathjax>. </li> </ul> <p>The 161.97g represents the molar mass of <mathjax>#Na_2CrO_4#</mathjax> and the 2:1 ratio of <mathjax>#NaNO_3#</mathjax> to <mathjax>#Na_2CrO_4#</mathjax> comes from the coefficients of the balanced equation. </p> <p>As you set up these type of problems the units that you no longer need should cancel out, leaving the unit you want as your end result. </p> <p><a href="https://www.boundless.com/chemistry/textbooks/boundless-chemistry-textbook/mass-relationships-and-chemical-equations-3/reaction-stoichiometry-44/mass-to-mole-conversions-232-5142/" rel="nofollow">Mass-to-Mole Conversions</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles of sodium nitrate, #NaNO_3#, would be produced from the complete reaction of 253g sodium chromate, #Na_2CrO_4#? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The reaction is <mathjax>#Pb(NO_3)_2+Na_2CrO_4 -> PbCrO_4 + 2NaNO_3#</mathjax>.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="274540" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-06T05:44:08" itemprop="dateCreated"> Jun 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.12 Moles of <mathjax>#NaNO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="My Worked Out Solution" src="https://useruploads.socratic.org/vrL5TUL8TxWxeTKqZkn9_FullSizeRender%20%281%29.jpg"/></p> <p>When performing mass to mole calculations, I use the following method:</p> <p>Quantity Sought = Quantity Given x Conversion Factor</p> <ul> <li>The quantity sought is what we are trying to find, in our case we are trying to determine the number of moles of <mathjax>#NaNO_3#</mathjax> </li> <li>The quantity given is the value that we have in the problem, which is 253g of <mathjax>#Na_2CrO_4#</mathjax></li> <li>The conversion factor is what allows us to go from grams of <mathjax>#Na_2CrO_4#</mathjax> to moles of <mathjax>#Na_2CrO_4#</mathjax>, which ultimately leads us to the number of moles of <mathjax>#NaNO_3#</mathjax>. </li> </ul> <p>The 161.97g represents the molar mass of <mathjax>#Na_2CrO_4#</mathjax> and the 2:1 ratio of <mathjax>#NaNO_3#</mathjax> to <mathjax>#Na_2CrO_4#</mathjax> comes from the coefficients of the balanced equation. </p> <p>As you set up these type of problems the units that you no longer need should cancel out, leaving the unit you want as your end result. </p> <p><a href="https://www.boundless.com/chemistry/textbooks/boundless-chemistry-textbook/mass-relationships-and-chemical-equations-3/reaction-stoichiometry-44/mass-to-mole-conversions-232-5142/" rel="nofollow">Mass-to-Mole Conversions</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/274540" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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The reaction is #Pb(NO_3)_2+Na_2CrO_4 -> PbCrO_4 + 2NaNO_3#.
2,774	ab9ef82e-6ddd-11ea-9a90-ccda262736ce	https://socratic.org/questions/how-do-you-balance-s8-o2-so3	S8 + 12 O2 -> 8 SO3	start chemical_equation qc_end chemical_equation 4 8 qc_end end	[{"type":"other","value":"Chemical Equation [OF] the equation"}]	[{"type":"chemical equation","value":"S8 + 12 O2 -> 8 SO3"}]	[{"type":"chemical equation","value":"S8 + O2 -> SO3"}]	<h1 class="questionTitle" itemprop="name">How do you balance S8 + O2 -->SO3? </h1>	null	S8 + 12 O2 -> 8 SO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balancing a chemical equation is actually an exercise where the balancing atoms is basically an adherence to the law of conservation of mass in Physics.</p> <p>On the left hand side of the equation, there are 8 (moles of) <mathjax>#S#</mathjax> atoms. Therefore on the right hand side, there would need to be <mathjax>#8#</mathjax> (moles of) <mathjax>#SO_3#</mathjax> molecules.</p> <p>If so, on the right hand side now, there would be a total of <mathjax>#24#</mathjax> (moles of) <mathjax>#O#</mathjax> atoms. Therefore we need to balance the O atoms on the left hand side giving us <mathjax>#12#</mathjax> (moles of) <mathjax>#O_2#</mathjax> gas.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S_8#</mathjax> + <mathjax>#12O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#8SO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balancing a chemical equation is actually an exercise where the balancing atoms is basically an adherence to the law of conservation of mass in Physics.</p> <p>On the left hand side of the equation, there are 8 (moles of) <mathjax>#S#</mathjax> atoms. Therefore on the right hand side, there would need to be <mathjax>#8#</mathjax> (moles of) <mathjax>#SO_3#</mathjax> molecules.</p> <p>If so, on the right hand side now, there would be a total of <mathjax>#24#</mathjax> (moles of) <mathjax>#O#</mathjax> atoms. Therefore we need to balance the O atoms on the left hand side giving us <mathjax>#12#</mathjax> (moles of) <mathjax>#O_2#</mathjax> gas.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance S8 + O2 -->SO3? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="177708" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/suryin"><img alt="" class="" src="https://profilepictures.socratic.org/W4fldR4wThKRlf9LjdWm_2347DB9D-DCD9-47D9-93C4-AAE285CF92AA.jpeg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/suryin"> Suryin =) </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-18T11:03:43" itemprop="dateCreated"> Oct 18, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S_8#</mathjax> + <mathjax>#12O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#8SO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balancing a chemical equation is actually an exercise where the balancing atoms is basically an adherence to the law of conservation of mass in Physics.</p> <p>On the left hand side of the equation, there are 8 (moles of) <mathjax>#S#</mathjax> atoms. Therefore on the right hand side, there would need to be <mathjax>#8#</mathjax> (moles of) <mathjax>#SO_3#</mathjax> molecules.</p> <p>If so, on the right hand side now, there would be a total of <mathjax>#24#</mathjax> (moles of) <mathjax>#O#</mathjax> atoms. Therefore we need to balance the O atoms on the left hand side giving us <mathjax>#12#</mathjax> (moles of) <mathjax>#O_2#</mathjax> gas.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/177708" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 33138 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How do you balance S8 + O2 -->SO3?	null
2,775	ad24fbf8-6ddd-11ea-8f52-ccda262736ce	https://socratic.org/questions/what-is-the-density-of-acetylene-gas-measured-at-pressure-of-0-75-atm-and-temper	0.45 g/L	start physical_unit 5 6 density g/l qc_end physical_unit 5 6 11 12 pressure qc_end physical_unit 5 6 16 17 temperature qc_end end	[{"type":"physical unit","value":"Density [OF] acetylene gas [IN] g/L"}]	[{"type":"physical unit","value":"0.45 g/L"}]	[{"type":"physical unit","value":"Pressure [OF] acetylene gas [=] \\pu{0.75 atm}"},{"type":"physical unit","value":"Temperature [OF] acetylene gas [=] \\pu{250 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the density of acetylene gas measured at pressure of 0.75 atm and temperature of 250°C?</h1>	null	0.45 g/L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong>molar mass</strong> of acetylene, <mathjax>#"C"_2"H"_2#</mathjax>, and the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to find an expression for the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the gas under those conditions for pressure and temperature. </p> <p>So, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, <strong>always</strong> expressed in <em>Kelvin</em></p> <p>Now, since you don't know how many <strong>moles</strong> of acetylene you have, you will have to work around it using the definition of <strong>molar mass</strong>. </p> <p>A substance's molar mass tells you what the mass of <strong>one mole</strong> of that substance is. You can thus write molar mass, <mathjax>#M_M#</mathjax>, as being equal to </p> <blockquote> <p><mathjax>#color(blue)(M_M = m/n)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#m#</mathjax> - the mass of a sample of the substance<br/> <mathjax>#n#</mathjax> - the number of moles that sample contains </p> <p>This means that you can express the number of moles, <mathjax>#n#</mathjax>, as being </p> <blockquote> <p><mathjax>#M_M = m/n implies n = m/M_M#</mathjax></p> </blockquote> <p>Plug this into the ideal gas law equation to get </p> <blockquote> <p><mathjax>#PV = m/M_M * RT" " " "color(red)((""))#</mathjax></p> </blockquote> <p>Now, density, <mathjax>#rho#</mathjax>, is defined as mass <em>per unit of volume</em>. </p> <blockquote> <p><mathjax>#color(blue)(rho = m/V)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#m#</mathjax> - the mass of a sample of the substance<br/> <mathjax>#V#</mathjax> - the volume it occupies</p> <p>Rearrange equation <mathjax>#color(red)((""))#</mathjax> to get the expression for density </p> <blockquote> <p><mathjax>#P * M_M = overbrace(m/V)^(color(blue)(=rho)) * RT#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#rho * RT = P * M_M implies rho = (P * M_M)/(RT)#</mathjax></p> </blockquote> <p>Acetylene has a molar mass of <mathjax>#"26.037 g/mol"#</mathjax>. Plug in your values and solve for <mathjax>#rho#</mathjax> - <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em></p> <blockquote> <p><mathjax>#rho = (0.75 color(red)(cancel(color(black)("atm"))) * 26.037"g"/color(red)(cancel(color(black)("mol"))))/(0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 250)color(red)(cancel(color(black)("K")))) = "0.4547 g/L"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the temperature and pressure of the gas, the answer will be </p> <blockquote> <p><mathjax>#rho = color(green)("0.45 g/L")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#rho = "0.45 g/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong>molar mass</strong> of acetylene, <mathjax>#"C"_2"H"_2#</mathjax>, and the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to find an expression for the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the gas under those conditions for pressure and temperature. </p> <p>So, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, <strong>always</strong> expressed in <em>Kelvin</em></p> <p>Now, since you don't know how many <strong>moles</strong> of acetylene you have, you will have to work around it using the definition of <strong>molar mass</strong>. </p> <p>A substance's molar mass tells you what the mass of <strong>one mole</strong> of that substance is. You can thus write molar mass, <mathjax>#M_M#</mathjax>, as being equal to </p> <blockquote> <p><mathjax>#color(blue)(M_M = m/n)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#m#</mathjax> - the mass of a sample of the substance<br/> <mathjax>#n#</mathjax> - the number of moles that sample contains </p> <p>This means that you can express the number of moles, <mathjax>#n#</mathjax>, as being </p> <blockquote> <p><mathjax>#M_M = m/n implies n = m/M_M#</mathjax></p> </blockquote> <p>Plug this into the ideal gas law equation to get </p> <blockquote> <p><mathjax>#PV = m/M_M * RT" " " "color(red)((""))#</mathjax></p> </blockquote> <p>Now, density, <mathjax>#rho#</mathjax>, is defined as mass <em>per unit of volume</em>. </p> <blockquote> <p><mathjax>#color(blue)(rho = m/V)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#m#</mathjax> - the mass of a sample of the substance<br/> <mathjax>#V#</mathjax> - the volume it occupies</p> <p>Rearrange equation <mathjax>#color(red)((""))#</mathjax> to get the expression for density </p> <blockquote> <p><mathjax>#P * M_M = overbrace(m/V)^(color(blue)(=rho)) * RT#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#rho * RT = P * M_M implies rho = (P * M_M)/(RT)#</mathjax></p> </blockquote> <p>Acetylene has a molar mass of <mathjax>#"26.037 g/mol"#</mathjax>. Plug in your values and solve for <mathjax>#rho#</mathjax> - <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em></p> <blockquote> <p><mathjax>#rho = (0.75 color(red)(cancel(color(black)("atm"))) * 26.037"g"/color(red)(cancel(color(black)("mol"))))/(0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 250)color(red)(cancel(color(black)("K")))) = "0.4547 g/L"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the temperature and pressure of the gas, the answer will be </p> <blockquote> <p><mathjax>#rho = color(green)("0.45 g/L")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the density of acetylene gas measured at pressure of 0.75 atm and temperature of 250°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="208604" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/mason-m"> mason m </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-05T19:11:35" itemprop="dateCreated"> Jan 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#rho = "0.45 g/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to use the <strong>molar mass</strong> of acetylene, <mathjax>#"C"_2"H"_2#</mathjax>, and the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to find an expression for the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the gas under those conditions for pressure and temperature. </p> <p>So, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this </p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.0821("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperature of the gas, <strong>always</strong> expressed in <em>Kelvin</em></p> <p>Now, since you don't know how many <strong>moles</strong> of acetylene you have, you will have to work around it using the definition of <strong>molar mass</strong>. </p> <p>A substance's molar mass tells you what the mass of <strong>one mole</strong> of that substance is. You can thus write molar mass, <mathjax>#M_M#</mathjax>, as being equal to </p> <blockquote> <p><mathjax>#color(blue)(M_M = m/n)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#m#</mathjax> - the mass of a sample of the substance<br/> <mathjax>#n#</mathjax> - the number of moles that sample contains </p> <p>This means that you can express the number of moles, <mathjax>#n#</mathjax>, as being </p> <blockquote> <p><mathjax>#M_M = m/n implies n = m/M_M#</mathjax></p> </blockquote> <p>Plug this into the ideal gas law equation to get </p> <blockquote> <p><mathjax>#PV = m/M_M * RT" " " "color(red)((""))#</mathjax></p> </blockquote> <p>Now, density, <mathjax>#rho#</mathjax>, is defined as mass <em>per unit of volume</em>. </p> <blockquote> <p><mathjax>#color(blue)(rho = m/V)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#m#</mathjax> - the mass of a sample of the substance<br/> <mathjax>#V#</mathjax> - the volume it occupies</p> <p>Rearrange equation <mathjax>#color(red)((""))#</mathjax> to get the expression for density </p> <blockquote> <p><mathjax>#P * M_M = overbrace(m/V)^(color(blue)(=rho)) * RT#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#rho * RT = P * M_M implies rho = (P * M_M)/(RT)#</mathjax></p> </blockquote> <p>Acetylene has a molar mass of <mathjax>#"26.037 g/mol"#</mathjax>. Plug in your values and solve for <mathjax>#rho#</mathjax> - <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em></p> <blockquote> <p><mathjax>#rho = (0.75 color(red)(cancel(color(black)("atm"))) * 26.037"g"/color(red)(cancel(color(black)("mol"))))/(0.0821(color(red)(cancel(color(black)("atm"))) * "L")/(color(red)(cancel(color(black)("mol"))) * color(red)(cancel(color(black)("K")))) * (273.15 + 250)color(red)(cancel(color(black)("K")))) = "0.4547 g/L"#</mathjax></p> </blockquote> <p>Rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the temperature and pressure of the gas, the answer will be </p> <blockquote> <p><mathjax>#rho = color(green)("0.45 g/L")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/208604" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? 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2,776	acc6a194-6ddd-11ea-8258-ccda262736ce	https://socratic.org/questions/how-do-you-write-the-formula-for-chromium-iii-sulfide	Cr2S3	start chemical_formula qc_end substance 7 9 qc_end end	[{"type":"other","value":"Chemical Formula [OF] chromium (III) sulfide [IN] default"}]	[{"type":"chemical equation","value":"Cr2S3"}]	[{"type":"substance name","value":"Chromium (III) sulfide"}]	<h1 class="questionTitle" itemprop="name">How do you write the formula for chromium (III) sulfide?</h1>	null	Cr2S3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Chromium III (Cr) has a charge of 3+<br/> Sulphur (S) has a charge of 2-</p> <p>When you cross the charges, Chromium ends up having 2 atoms and Sulphur ends up needing 3 atoms, as seen in the formula above</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cr_2S_3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Chromium III (Cr) has a charge of 3+<br/> Sulphur (S) has a charge of 2-</p> <p>When you cross the charges, Chromium ends up having 2 atoms and Sulphur ends up needing 3 atoms, as seen in the formula above</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you write the formula for chromium (III) sulfide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="400895" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/felicia-m-2"><img alt="" class="" src="https://graph.facebook.com/1825934064397892/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/felicia-m-2"> Felicia M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-03T13:19:18" itemprop="dateCreated"> Apr 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cr_2S_3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Chromium III (Cr) has a charge of 3+<br/> Sulphur (S) has a charge of 2-</p> <p>When you cross the charges, Chromium ends up having 2 atoms and Sulphur ends up needing 3 atoms, as seen in the formula above</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/400895" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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2,777	acdf3fa5-6ddd-11ea-b53e-ccda262736ce	https://socratic.org/questions/the-heat-of-vaporization-of-alcohol-is-879-j-g-what-is-the-energy-in-j-required--1	3955.50 J	start physical_unit 21 21 energy j qc_end physical_unit 21 21 18 19 mass qc_end physical_unit 5 5 7 8 enthalpy_of_vaporization qc_end end	[{"type":"physical unit","value":"Required energy [OF] C2H5OH [IN] J"}]	[{"type":"physical unit","value":"3955.50 J"}]	[{"type":"physical unit","value":"Mass [OF] C2H5OH [=] \\pu{4.50 g}"},{"type":"physical unit","value":"Heat of vaporization [OF] alcohol [=] \\pu{879 J/g}"}]	<h1 class="questionTitle" itemprop="name">The heat of vaporization of alcohol is 879 J/g. What is the energy in J required to vaporize 4.50 g of #C_2H_5OH#?</h1>	null	3955.50 J	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Practically, this process described the process:</p> <p><mathjax>#"Ethanol(l)"+Deltararr"Ethanol(g)"#</mathjax></p> <p>The ethanol would have to be at its normal boiling point.........</p> <p>And so, we calculate..................</p> <p><mathjax>#4.50gxx879Jg^-1=??J#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This simply the product <mathjax>#Delta=DeltaH_"vaporization"xx"amount of alcohol."#</mathjax> <mathjax>#~=4000J#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Practically, this process described the process:</p> <p><mathjax>#"Ethanol(l)"+Deltararr"Ethanol(g)"#</mathjax></p> <p>The ethanol would have to be at its normal boiling point.........</p> <p>And so, we calculate..................</p> <p><mathjax>#4.50gxx879Jg^-1=??*J#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">The heat of vaporization of alcohol is 879 J/g. What is the energy in J required to vaporize 4.50 g of #C_2H_5OH#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430417" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-27T07:32:35" itemprop="dateCreated"> May 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This simply the product <mathjax>#Delta=DeltaH_"vaporization"xx"amount of alcohol."#</mathjax> <mathjax>#~=4000J#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Practically, this process described the process:</p> <p><mathjax>#"Ethanol(l)"+Deltararr"Ethanol(g)"#</mathjax></p> <p>The ethanol would have to be at its normal boiling point.........</p> <p>And so, we calculate..................</p> <p><mathjax>#4.50gxx879Jg^-1=??*J#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430417" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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What is the energy in J required to vaporize 4.50 g of #C_2H_5OH#?	null
2,778	a9ef113e-6ddd-11ea-bc7c-ccda262736ce	https://socratic.org/questions/1-40-g-of-silver-nitrate-is-dissolved-in-125-ml-of-water-to-this-solution-is-add	5.71 × 10^(-3) molarity	start physical_unit 37 42 concentration mol/l qc_end physical_unit 3 4 0 1 mass qc_end physical_unit 11 11 8 9 volume qc_end physical_unit 14 14 17 18 volume qc_end physical_unit 22 23 20 21 concentration qc_end end	[{"type":"physical unit","value":"Concentration [OF] silver ions remaining in the solution [IN] molarity"}]	[{"type":"physical unit","value":"5.71 × 10^(-3) molarity"}]	[{"type":"physical unit","value":"Mass [OF] silver nitrate [=] \\pu{1.40 g}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{125 mL}"},{"type":"physical unit","value":"Volume [OF] hydrochloric acid solution [=] \\pu{5.00 mL}"},{"type":"physical unit","value":"Concentration [OF] hydrochloric acid solution [=] \\pu{1.50 M}"}]	<h1 class="questionTitle" itemprop="name">1.40 g of silver nitrate is dissolved in 125 mL of water. To this solution is added 5.00 mL of 1.50 M hydrochloric acid, and a precipitate forms. What is the concentration (in units of moiarity) of silver ions remaining in the solution? </h1>	null	5.71 × 10^(-3) molarity	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a> in which two <strong>soluble</strong> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> react in aqueous solution to form an <strong>insoluble solid</strong> that <em>precipitates out of solution</em>. </p> <p><em>Silver nitrate</em>, <mathjax>#"AgNO"_3#</mathjax>, a soluble ionic compound, will react with <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a strong acid that dissociates completely in aqueous solution, to form the insoluble <em>silver chloride</em>, <mathjax>#"AgCl"#</mathjax>, a white precipitate.</p> <p><img alt="http://fphoto.photoshelter.com/image/I0000EXBxAjprWZ0" src="https://useruploads.socratic.org/9WVWDHd0SVWmTjtS9qtR_Fphoto-69269101B-6CC.jpg"/> </p> <p>The balanced chemical equation for this reaction looks like this </p> <blockquote> <p><mathjax>#"AgNO"_text(3(aq]) + "HCl"_text((aq]) -> "AgCl"_text((s]) darr + "HNO"_text(3(aq])#</mathjax></p> </blockquote> <p>The <strong>net ionic equation</strong>, which you get after removing the <em>spectator ions</em>, looks like this</p> <blockquote> <p><mathjax>#"Ag"_text((aq])^(+) + "Cl"_text((aq])^(-) -> "AgCl"_text((s]) darr#</mathjax></p> </blockquote> <p>Notice that the reactants take part in the reaction in a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>, which means that the reaction will consume <strong>equal numbers of moles</strong> of silver nitrate and hydrochloric acid, which produce silver cations, <mathjax>#"Ag"^(+)#</mathjax>, and chloride anions, <mathjax>#"Cl"^(-)#</mathjax>, respectively. </p> <p>Your goal now is to figure out <em>how many moles of each reactant</em> you're mixing together. </p> <p>For starters, use silver nitrate's <strong>molar mass</strong> to determine how many moles you get in that <mathjax>#"1.40-g"#</mathjax> sample of silver nitrate</p> <blockquote> <p><mathjax>#1.40 color(red)(cancel(color(black)("g"))) * "1 mole AgNO"_3/(169.87color(red)(cancel(color(black)("g")))) = "0.008242 moles AgNO"_3#</mathjax></p> </blockquote> <p>Now use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the hydrochloric acid solution to determine how many moles of acid you have </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "1.50 M" * 5.00 * 10^(-3)"L" = "0.00750 moles HCl"#</mathjax></p> </blockquote> <p>Since you have <strong>fewer</strong> moles of chloride anions, these ions will be <strong>completely consumed</strong> by the reaction. The resulting solution will contain </p> <blockquote> <p><mathjax>#n_(Ag^(+)) = 0.008242 - 0.00750 = "0.000742 moles Ag"^(+)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"sol" = "125 mL" + "5.00 mL" = "130.0 mL"#</mathjax></p> </blockquote> <p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the silver cations will thus be - <strong>do not</strong> forget that the volume must be expressed in <em>liters</em>!</p> <blockquote> <p><mathjax>#["Ag"^(+)] = "0.000742 moles"/(130.0 * 10^(-3)"L") = color(green)("0.00571 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["Ag"^(+)] = "0.00571 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a> in which two <strong>soluble</strong> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> react in aqueous solution to form an <strong>insoluble solid</strong> that <em>precipitates out of solution</em>. </p> <p><em>Silver nitrate</em>, <mathjax>#"AgNO"_3#</mathjax>, a soluble ionic compound, will react with <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a strong acid that dissociates completely in aqueous solution, to form the insoluble <em>silver chloride</em>, <mathjax>#"AgCl"#</mathjax>, a white precipitate.</p> <p><img alt="http://fphoto.photoshelter.com/image/I0000EXBxAjprWZ0" src="https://useruploads.socratic.org/9WVWDHd0SVWmTjtS9qtR_Fphoto-69269101B-6CC.jpg"/> </p> <p>The balanced chemical equation for this reaction looks like this </p> <blockquote> <p><mathjax>#"AgNO"_text(3(aq]) + "HCl"_text((aq]) -> "AgCl"_text((s]) darr + "HNO"_text(3(aq])#</mathjax></p> </blockquote> <p>The <strong>net ionic equation</strong>, which you get after removing the <em>spectator ions</em>, looks like this</p> <blockquote> <p><mathjax>#"Ag"_text((aq])^(+) + "Cl"_text((aq])^(-) -> "AgCl"_text((s]) darr#</mathjax></p> </blockquote> <p>Notice that the reactants take part in the reaction in a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>, which means that the reaction will consume <strong>equal numbers of moles</strong> of silver nitrate and hydrochloric acid, which produce silver cations, <mathjax>#"Ag"^(+)#</mathjax>, and chloride anions, <mathjax>#"Cl"^(-)#</mathjax>, respectively. </p> <p>Your goal now is to figure out <em>how many moles of each reactant</em> you're mixing together. </p> <p>For starters, use silver nitrate's <strong>molar mass</strong> to determine how many moles you get in that <mathjax>#"1.40-g"#</mathjax> sample of silver nitrate</p> <blockquote> <p><mathjax>#1.40 color(red)(cancel(color(black)("g"))) * "1 mole AgNO"_3/(169.87color(red)(cancel(color(black)("g")))) = "0.008242 moles AgNO"_3#</mathjax></p> </blockquote> <p>Now use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the hydrochloric acid solution to determine how many moles of acid you have </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "1.50 M" * 5.00 * 10^(-3)"L" = "0.00750 moles HCl"#</mathjax></p> </blockquote> <p>Since you have <strong>fewer</strong> moles of chloride anions, these ions will be <strong>completely consumed</strong> by the reaction. The resulting solution will contain </p> <blockquote> <p><mathjax>#n_(Ag^(+)) = 0.008242 - 0.00750 = "0.000742 moles Ag"^(+)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"sol" = "125 mL" + "5.00 mL" = "130.0 mL"#</mathjax></p> </blockquote> <p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the silver cations will thus be - <strong>do not</strong> forget that the volume must be expressed in <em>liters</em>!</p> <blockquote> <p><mathjax>#["Ag"^(+)] = "0.000742 moles"/(130.0 * 10^(-3)"L") = color(green)("0.00571 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">1.40 g of silver nitrate is dissolved in 125 mL of water. To this solution is added 5.00 mL of 1.50 M hydrochloric acid, and a precipitate forms. What is the concentration (in units of moiarity) of silver ions remaining in the solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="198275" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-10T01:56:16" itemprop="dateCreated"> Dec 10, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["Ag"^(+)] = "0.00571 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a> in which two <strong>soluble</strong> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> react in aqueous solution to form an <strong>insoluble solid</strong> that <em>precipitates out of solution</em>. </p> <p><em>Silver nitrate</em>, <mathjax>#"AgNO"_3#</mathjax>, a soluble ionic compound, will react with <em>hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, a strong acid that dissociates completely in aqueous solution, to form the insoluble <em>silver chloride</em>, <mathjax>#"AgCl"#</mathjax>, a white precipitate.</p> <p><img alt="http://fphoto.photoshelter.com/image/I0000EXBxAjprWZ0" src="https://useruploads.socratic.org/9WVWDHd0SVWmTjtS9qtR_Fphoto-69269101B-6CC.jpg"/> </p> <p>The balanced chemical equation for this reaction looks like this </p> <blockquote> <p><mathjax>#"AgNO"_text(3(aq]) + "HCl"_text((aq]) -> "AgCl"_text((s]) darr + "HNO"_text(3(aq])#</mathjax></p> </blockquote> <p>The <strong>net ionic equation</strong>, which you get after removing the <em>spectator ions</em>, looks like this</p> <blockquote> <p><mathjax>#"Ag"_text((aq])^(+) + "Cl"_text((aq])^(-) -> "AgCl"_text((s]) darr#</mathjax></p> </blockquote> <p>Notice that the reactants take part in the reaction in a <mathjax>#1:1#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a>, which means that the reaction will consume <strong>equal numbers of moles</strong> of silver nitrate and hydrochloric acid, which produce silver cations, <mathjax>#"Ag"^(+)#</mathjax>, and chloride anions, <mathjax>#"Cl"^(-)#</mathjax>, respectively. </p> <p>Your goal now is to figure out <em>how many moles of each reactant</em> you're mixing together. </p> <p>For starters, use silver nitrate's <strong>molar mass</strong> to determine how many moles you get in that <mathjax>#"1.40-g"#</mathjax> sample of silver nitrate</p> <blockquote> <p><mathjax>#1.40 color(red)(cancel(color(black)("g"))) * "1 mole AgNO"_3/(169.87color(red)(cancel(color(black)("g")))) = "0.008242 moles AgNO"_3#</mathjax></p> </blockquote> <p>Now use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the hydrochloric acid solution to determine how many moles of acid you have </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(HCl) = "1.50 M" * 5.00 * 10^(-3)"L" = "0.00750 moles HCl"#</mathjax></p> </blockquote> <p>Since you have <strong>fewer</strong> moles of chloride anions, these ions will be <strong>completely consumed</strong> by the reaction. The resulting solution will contain </p> <blockquote> <p><mathjax>#n_(Ag^(+)) = 0.008242 - 0.00750 = "0.000742 moles Ag"^(+)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"sol" = "125 mL" + "5.00 mL" = "130.0 mL"#</mathjax></p> </blockquote> <p>The <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the silver cations will thus be - <strong>do not</strong> forget that the volume must be expressed in <em>liters</em>!</p> <blockquote> <p><mathjax>#["Ag"^(+)] = "0.000742 moles"/(130.0 * 10^(-3)"L") = color(green)("0.00571 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/198275" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 24290 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	1.40 g of silver nitrate is dissolved in 125 mL of water. To this solution is added 5.00 mL of 1.50 M hydrochloric acid, and a precipitate forms. What is the concentration (in units of moiarity) of silver ions remaining in the solution?	null
2,779	ab0c40a3-6ddd-11ea-89dc-ccda262736ce	https://socratic.org/questions/if-i-initially-have-a-gas-at-a-pressure-of-12-atm-a-volume-of-23-liters-and-a-te	29.57 L	start physical_unit 45 46 volume l qc_end physical_unit 45 46 21 22 temperature qc_end physical_unit 45 46 15 16 volume qc_end physical_unit 45 46 10 11 pressure qc_end physical_unit 45 46 37 38 temperature qc_end physical_unit 45 46 30 31 pressure qc_end end	[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]	[{"type":"physical unit","value":"29.57 L"}]	[{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{200 K}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{23 liters}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{12 atm}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{300 K}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{14 atm}"}]	<h1 class="questionTitle" itemprop="name">If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then l raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas? </h1>	null	29.57 L	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is an example of a <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">Combined Gas Laws</a> problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2\|)#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#P_1 = "12 atm"; V_1 = "23 L"; T_1 = "200 K"#</mathjax></p> <p><mathjax>#P_2 = "14 atm"; V_2 = "?";color(white)(mll) T_2 = "300 K"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1 = "23 L" × (12 color(red)(cancel(color(black)("atm"))))/(14 color(red)(cancel(color(black)("atm")))) × (300 color(red)(cancel(color(black)("K"))))/(200 color(red)(cancel(color(black)("K")))) = "30 L"#</mathjax></p> <p>The volume is 30 L.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume of the gas is 30 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is an example of a <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">Combined Gas Laws</a> problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2\|)#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#P_1 = "12 atm"; V_1 = "23 L"; T_1 = "200 K"#</mathjax></p> <p><mathjax>#P_2 = "14 atm"; V_2 = "?";color(white)(mll) T_2 = "300 K"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1 = "23 L" × (12 color(red)(cancel(color(black)("atm"))))/(14 color(red)(cancel(color(black)("atm")))) × (300 color(red)(cancel(color(black)("K"))))/(200 color(red)(cancel(color(black)("K")))) = "30 L"#</mathjax></p> <p>The volume is 30 L.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then l raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284080" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-03T00:26:54" itemprop="dateCreated"> Jul 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume of the gas is 30 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is an example of a <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">Combined Gas Laws</a> problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(\|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2\|)#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#P_1 = "12 atm"; V_1 = "23 L"; T_1 = "200 K"#</mathjax></p> <p><mathjax>#P_2 = "14 atm"; V_2 = "?";color(white)(mll) T_2 = "300 K"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1 = "23 L" × (12 color(red)(cancel(color(black)("atm"))))/(14 color(red)(cancel(color(black)("atm")))) × (300 color(red)(cancel(color(black)("K"))))/(200 color(red)(cancel(color(black)("K")))) = "30 L"#</mathjax></p> <p>The volume is 30 L.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284080" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? 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What is its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-situations-does-the-combined-gas-law-enable-you-to-do-calculations-when-th"> Which situations does the combined gas law enable you to do calculations when the other gas laws... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-small-research-submarine-with-a-volume-of-1-2x10-5-l-has-an-internal-pressure-"> A small research submarine with a volume of 1.2x10 ^5 L has an internal pressure of 1.0 atm and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-combined-gas-law-different-from-boyle-s-law"> How is the combined gas law different from boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-pressure-of-an-combined-gas-change-as-temperature-increases"> How does the pressure of an combined gas change as temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-ideal-gas-law-differ-from-the-combined-gas-law-1"> How does the ideal gas law differ from the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/combined-gas-law"> See all questions in Combined Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25318 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then l raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?	null
2,780	a9aa21d4-6ddd-11ea-ab64-ccda262736ce	https://socratic.org/questions/what-is-nh-4-in-a-solution-that-is-0-0200-m-nh-3-and-0100-m-koh	3.54 × 10^(-5) M	start physical_unit 5 5 [nh4+] mol/l qc_end physical_unit 10 10 8 9 molarity qc_end physical_unit 14 14 12 13 molarity qc_end end	[{"type":"physical unit","value":"[NH4+] [OF] the solution [IN] M"}]	[{"type":"physical unit","value":"3.54 × 10^(-5) M"}]	[{"type":"physical unit","value":"Molarity [OF] NH3 solution [=] \\pu{0.0200 M}"},{"type":"physical unit","value":"Molarity [OF] KOH solution [=] \\pu{0.0100 M}"}]	<h1 class="questionTitle" itemprop="name">What is #[NH_4^+]# in a solution that is 0.0200 M #NH_3# and .0100 M #KOH#?</h1>	null	3.54 × 10^(-5) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonia is a weak base and partially ionises in water:</p> <p><mathjax>#NH_3+H_2OrightleftharpoonsNH_4^++OH^-#</mathjax></p> <p>For which:</p> <p><mathjax>#K_b=([NH_4^+][OH^-])/([NH_3])=1.77xx10^(-5)" ""mol/l"#</mathjax></p> <p><mathjax>#:.[NH_4^+]=K_bxx[[NH_3]]/[[OH^-]]#</mathjax></p> <p>The concentrations given are at equilibrium so:</p> <p><mathjax>#[NH_4^+]=1.77xx10^(-5)xx0.02/0.01=3.54xx10^(-5)" ""mol/l"#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[NH_4^+]=3.54xx10^(-5)" ""mol/l"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonia is a weak base and partially ionises in water:</p> <p><mathjax>#NH_3+H_2OrightleftharpoonsNH_4^++OH^-#</mathjax></p> <p>For which:</p> <p><mathjax>#K_b=([NH_4^+][OH^-])/([NH_3])=1.77xx10^(-5)" ""mol/l"#</mathjax></p> <p><mathjax>#:.[NH_4^+]=K_bxx[[NH_3]]/[[OH^-]]#</mathjax></p> <p>The concentrations given are at equilibrium so:</p> <p><mathjax>#[NH_4^+]=1.77xx10^(-5)xx0.02/0.01=3.54xx10^(-5)" ""mol/l"#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is #[NH_4^+]# in a solution that is 0.0200 M #NH_3# and .0100 M #KOH#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="279443" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-20T17:00:25" itemprop="dateCreated"> Jun 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[NH_4^+]=3.54xx10^(-5)" ""mol/l"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonia is a weak base and partially ionises in water:</p> <p><mathjax>#NH_3+H_2OrightleftharpoonsNH_4^++OH^-#</mathjax></p> <p>For which:</p> <p><mathjax>#K_b=([NH_4^+][OH^-])/([NH_3])=1.77xx10^(-5)" ""mol/l"#</mathjax></p> <p><mathjax>#:.[NH_4^+]=K_bxx[[NH_3]]/[[OH^-]]#</mathjax></p> <p>The concentrations given are at equilibrium so:</p> <p><mathjax>#[NH_4^+]=1.77xx10^(-5)xx0.02/0.01=3.54xx10^(-5)" ""mol/l"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/279443" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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</ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1212 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is #[NH_4^+]# in a solution that is 0.0200 M #NH_3# and .0100 M #KOH#?	null
2,781	ad0c82de-6ddd-11ea-9404-ccda262736ce	https://socratic.org/questions/if-there-are-7-44-x-10-23-atoms-of-gold-how-many-moles-of-gold-are-there	1.24 moles	start physical_unit 8 8 mole mol qc_end end	[{"type":"physical unit","value":"Mole [OF] gold [IN] moles"}]	[{"type":"physical unit","value":"1.24 moles"}]	[{"type":"physical unit","value":"Number [OF] gold atoms [=] \\pu{7.44 × 10^23}"}]	<h1 class="questionTitle" itemprop="name">If there are 7.44 x 10(23) atoms of gold, how many moles of gold are there?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Reviewing for a final. Went through some old quizzes to work on stuff I got wrong, and all my teacher did be circle it, and I don't understand what I did wrong.</p></div> </h2> </div> </div>	1.24 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Given then <mathjax>#eta "atom "Au=7.44xx10^23#</mathjax>, this value can be translated to <mathjax>#etaAu#</mathjax> through molar conversion.</li> <li>Knowing <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> relationship as shown below, is your equivalence statement. This is actually the Avogadro's number <mathjax>#(N_A)#</mathjax> also known as mole; thus,<br/> <mathjax>#1molAu=6.02x10^23 (N_A)"atoms "Au#</mathjax></li> <li>From the given equivalence statement, two (2) conversion factors can be derived.<br/> <mathjax>#(1molAu)/(6.02xx10^23"atoms"Au) or (6.02xx10^23"atoms"Au)/(1molAu)#</mathjax> </li> <li>Choose the right conversion factor making sure that the unwanted unit are cancelled leaving the desired one.<br/> <mathjax>#=7.44xx10^23cancel("atoms"Au)xx(1molAu)/(6.02xx10^23cancel("atoms"Au))#</mathjax><br/> <mathjax>#=(7.44xx10^23molAu)/(6.02xx10^23)#</mathjax><br/> <mathjax>#=1.24molAu#</mathjax></li> </ol></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#=1.24molAu#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Given then <mathjax>#eta "atom "Au=7.44xx10^23#</mathjax>, this value can be translated to <mathjax>#etaAu#</mathjax> through molar conversion.</li> <li>Knowing <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> relationship as shown below, is your equivalence statement. This is actually the Avogadro's number <mathjax>#(N_A)#</mathjax> also known as mole; thus,<br/> <mathjax>#1molAu=6.02x10^23 (N_A)"atoms "Au#</mathjax></li> <li>From the given equivalence statement, two (2) conversion factors can be derived.<br/> <mathjax>#(1molAu)/(6.02xx10^23"atoms"Au) or (6.02xx10^23"atoms"Au)/(1molAu)#</mathjax> </li> <li>Choose the right conversion factor making sure that the unwanted unit are cancelled leaving the desired one.<br/> <mathjax>#=7.44xx10^23cancel("atoms"Au)xx(1molAu)/(6.02xx10^23cancel("atoms"Au))#</mathjax><br/> <mathjax>#=(7.44xx10^23molAu)/(6.02xx10^23)#</mathjax><br/> <mathjax>#=1.24molAu#</mathjax></li> </ol></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">If there are 7.44 x 10(23) atoms of gold, how many moles of gold are there?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Reviewing for a final. Went through some old quizzes to work on stuff I got wrong, and all my teacher did be circle it, and I don't understand what I did wrong.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="522820" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-16T04:00:09" itemprop="dateCreated"> Dec 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#=1.24molAu#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Given then <mathjax>#eta "atom "Au=7.44xx10^23#</mathjax>, this value can be translated to <mathjax>#etaAu#</mathjax> through molar conversion.</li> <li>Knowing <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> relationship as shown below, is your equivalence statement. This is actually the Avogadro's number <mathjax>#(N_A)#</mathjax> also known as mole; thus,<br/> <mathjax>#1molAu=6.02x10^23 (N_A)"atoms "Au#</mathjax></li> <li>From the given equivalence statement, two (2) conversion factors can be derived.<br/> <mathjax>#(1molAu)/(6.02xx10^23"atoms"Au) or (6.02xx10^23"atoms"Au)/(1molAu)#</mathjax> </li> <li>Choose the right conversion factor making sure that the unwanted unit are cancelled leaving the desired one.<br/> <mathjax>#=7.44xx10^23cancel("atoms"Au)xx(1molAu)/(6.02xx10^23cancel("atoms"Au))#</mathjax><br/> <mathjax>#=(7.44xx10^23molAu)/(6.02xx10^23)#</mathjax><br/> <mathjax>#=1.24molAu#</mathjax></li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/522820" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11953 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	If there are 7.44 x 10(23) atoms of gold, how many moles of gold are there?	Reviewing for a final. Went through some old quizzes to work on stuff I got wrong, and all my teacher did be circle it, and I don't understand what I did wrong.
2,782	a93564de-6ddd-11ea-b665-ccda262736ce	https://socratic.org/questions/what-is-the-standard-emf-of-a-cell-that-uses-the-mg-mg-2-and-cu-cu-2-half-cell-r	+2.71 V	start physical_unit 7 7 standard_emf v qc_end c_other OTHER qc_end physical_unit 7 7 17 18 temperature qc_end end	[{"type":"physical unit","value":"Standard EMF [OF] the cell [IN] V"}]	[{"type":"physical unit","value":"+2.71 V"}]	[{"type":"other","value":"Use the Mg/Mg^2+ and Cu/Cu^2+ half-cell."},{"type":"physical unit","value":"Temperature [OF] the cell [=] \\pu{25 ℃}"}]	<h1 class="questionTitle" itemprop="name">What is the standard EMF of a cell that uses the #"Mg/Mg"^(2+)# and #"Cu/Cu"^(2+)# half-cell reactions at #25^@"C"# ?</h1>	null	+2.71 V	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by looking up the <strong>standard reduction potentials</strong> of the magnesium cation and of the copper(II) anion, which you can find <strong><a href="https://en.wikipedia.org/wiki/Standard_electrode_potential_(data_page)" rel="nofollow">here</a></strong>.</p> <blockquote> <p><mathjax>#"Mg"^(2+) + 2"e"^(-) rightleftharpoons "Mg", " "E_"red"^@ = - "2.372 V"#</mathjax></p> <p><mathjax>#"Cu"^(2+) + 2"e"^(-) rightleftharpoons "Cu", " "E_"red"^@ = +"0.337 V"#</mathjax></p> </blockquote> <p>Now, your goal here is to figure out which element is being <strong>reduced</strong> and which element is being <strong>oxidized</strong>. To do that, you need to take a look at the values you have for the standard reduction potentials. </p> <p>When magnesium cations are being reduced to magnesium metal, the <strong>negative</strong> value of the standard reduction potential tells you that the reduction equilibrium <strong>lies to the left</strong>, meaning that magnesium cations are more difficult to reduce than hydrogen cations. </p> <p>In other words, magnesium <strong>releases</strong> electrons more readily than hydrogen.</p> <p>When copper(II) cations are being reduced to copper metal, the <strong>positive</strong> value of the standard reduction potential tells you that the equilibrium <strong>lies to the right</strong>, meaning that copper(II) cations are easier to reduce than hydrogen cations.</p> <p>In other words, copper <strong>releases</strong> electrons less readily than hydrogen.</p> <p>When you connect these two electrodes, the element that has the <strong>more negative</strong> standard reduction potential will be <strong>oxidized</strong> because it will lose electrons <em>more readily</em> and the element that has the <strong>more positive</strong> standard reduction potential will be <strong>reduced</strong> because it will lose electrons <em>less readily</em>. </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#E_ ("red Mg"^(2+))^@ < E_ ("red Cu"^(2+))^@ implies {("Mg is being oxized to Mg"^(2+)),("Cu"^(2+)color(white)(.)"is being reduced to Cu") :}#</mathjax></p> </blockquote> <p>so you can say that magnesium will be <strong>oxidized</strong> to magnesium cations and copper(II) cations will be <strong>reduced</strong> to copper metal. </p> <p>This means that you have--remember, when you flip the reduction half-reaction to get the <strong>oxidation half-reaction</strong>, you must <strong>change the sign</strong> of the standard reduction potential. </p> <blockquote> <p><mathjax>#{(color(white)(aaaaaaaa)"Mg" rightleftharpoons "Mg"^(2+) + 2"e"^(-), " "E_"oxi"^@ = - (-"2.372 V")), ("Cu"^(2+) + 2"e"^(-) rightleftharpoons "Cu", " "E_"red"^@ = +"0.337 V") :}#</mathjax></p> </blockquote> <p>To find the <mathjax>#"EMF"#</mathjax> of the cell, simply add the standard potentials of the two half-reactions.</p> <blockquote> <p><mathjax>#E_"cell"^@ = E_"oxi"^@ + E_"red"^@#</mathjax></p> </blockquote> <p>You will end up with </p> <blockquote> <p><mathjax>#E_"cell"^@ = +"2.372 V" + "0.337 V"#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(E_"cell"^@ = +"2.709 V")))#</mathjax></p> </blockquote> <p>So, your galvanic cell will consist of a magnesium electrode and a copper electrode. Since magnesium is being <strong>oxidized</strong> and copper is being <strong>reduced</strong>, the magnesium electrode will be the <strong>anode</strong> and the copper electrode will be the <strong>cathode</strong>.</p> <p><img alt="http://www.chegg.com/homework-help/questions-and-answers/1-balance-following-redox-equation-acid-blank-put-correct-stochiometric-coefficient-0-1-2--q12066173" src="https://useruploads.socratic.org/SQ0dChCkRCaqAZu5k0xG_MgCuCell.jpg"/> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#E_"cell"^@ = +"2.709 V"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by looking up the <strong>standard reduction potentials</strong> of the magnesium cation and of the copper(II) anion, which you can find <strong><a href="https://en.wikipedia.org/wiki/Standard_electrode_potential_(data_page)" rel="nofollow">here</a></strong>.</p> <blockquote> <p><mathjax>#"Mg"^(2+) + 2"e"^(-) rightleftharpoons "Mg", " "E_"red"^@ = - "2.372 V"#</mathjax></p> <p><mathjax>#"Cu"^(2+) + 2"e"^(-) rightleftharpoons "Cu", " "E_"red"^@ = +"0.337 V"#</mathjax></p> </blockquote> <p>Now, your goal here is to figure out which element is being <strong>reduced</strong> and which element is being <strong>oxidized</strong>. To do that, you need to take a look at the values you have for the standard reduction potentials. </p> <p>When magnesium cations are being reduced to magnesium metal, the <strong>negative</strong> value of the standard reduction potential tells you that the reduction equilibrium <strong>lies to the left</strong>, meaning that magnesium cations are more difficult to reduce than hydrogen cations. </p> <p>In other words, magnesium <strong>releases</strong> electrons more readily than hydrogen.</p> <p>When copper(II) cations are being reduced to copper metal, the <strong>positive</strong> value of the standard reduction potential tells you that the equilibrium <strong>lies to the right</strong>, meaning that copper(II) cations are easier to reduce than hydrogen cations.</p> <p>In other words, copper <strong>releases</strong> electrons less readily than hydrogen.</p> <p>When you connect these two electrodes, the element that has the <strong>more negative</strong> standard reduction potential will be <strong>oxidized</strong> because it will lose electrons <em>more readily</em> and the element that has the <strong>more positive</strong> standard reduction potential will be <strong>reduced</strong> because it will lose electrons <em>less readily</em>. </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#E_ ("red Mg"^(2+))^@ < E_ ("red Cu"^(2+))^@ implies {("Mg is being oxized to Mg"^(2+)),("Cu"^(2+)color(white)(.)"is being reduced to Cu") :}#</mathjax></p> </blockquote> <p>so you can say that magnesium will be <strong>oxidized</strong> to magnesium cations and copper(II) cations will be <strong>reduced</strong> to copper metal. </p> <p>This means that you have--remember, when you flip the reduction half-reaction to get the <strong>oxidation half-reaction</strong>, you must <strong>change the sign</strong> of the standard reduction potential. </p> <blockquote> <p><mathjax>#{(color(white)(aaaaaaaa)"Mg" rightleftharpoons "Mg"^(2+) + 2"e"^(-), " "E_"oxi"^@ = - (-"2.372 V")), ("Cu"^(2+) + 2"e"^(-) rightleftharpoons "Cu", " "E_"red"^@ = +"0.337 V") :}#</mathjax></p> </blockquote> <p>To find the <mathjax>#"EMF"#</mathjax> of the cell, simply add the standard potentials of the two half-reactions.</p> <blockquote> <p><mathjax>#E_"cell"^@ = E_"oxi"^@ + E_"red"^@#</mathjax></p> </blockquote> <p>You will end up with </p> <blockquote> <p><mathjax>#E_"cell"^@ = +"2.372 V" + "0.337 V"#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(E_"cell"^@ = +"2.709 V")))#</mathjax></p> </blockquote> <p>So, your galvanic cell will consist of a magnesium electrode and a copper electrode. Since magnesium is being <strong>oxidized</strong> and copper is being <strong>reduced</strong>, the magnesium electrode will be the <strong>anode</strong> and the copper electrode will be the <strong>cathode</strong>.</p> <p><img alt="http://www.chegg.com/homework-help/questions-and-answers/1-balance-following-redox-equation-acid-blank-put-correct-stochiometric-coefficient-0-1-2--q12066173" src="https://useruploads.socratic.org/SQ0dChCkRCaqAZu5k0xG_MgCuCell.jpg"/> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the standard EMF of a cell that uses the #"Mg/Mg"^(2+)# and #"Cu/Cu"^(2+)# half-cell reactions at #25^@"C"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/galvanic-cells" itemprop="url"> <span class="breadcrumb" itemprop="title">Galvanic Cells</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="528570" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-31T11:08:10" itemprop="dateCreated"> Dec 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#E_"cell"^@ = +"2.709 V"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by looking up the <strong>standard reduction potentials</strong> of the magnesium cation and of the copper(II) anion, which you can find <strong><a href="https://en.wikipedia.org/wiki/Standard_electrode_potential_(data_page)" rel="nofollow">here</a></strong>.</p> <blockquote> <p><mathjax>#"Mg"^(2+) + 2"e"^(-) rightleftharpoons "Mg", " "E_"red"^@ = - "2.372 V"#</mathjax></p> <p><mathjax>#"Cu"^(2+) + 2"e"^(-) rightleftharpoons "Cu", " "E_"red"^@ = +"0.337 V"#</mathjax></p> </blockquote> <p>Now, your goal here is to figure out which element is being <strong>reduced</strong> and which element is being <strong>oxidized</strong>. To do that, you need to take a look at the values you have for the standard reduction potentials. </p> <p>When magnesium cations are being reduced to magnesium metal, the <strong>negative</strong> value of the standard reduction potential tells you that the reduction equilibrium <strong>lies to the left</strong>, meaning that magnesium cations are more difficult to reduce than hydrogen cations. </p> <p>In other words, magnesium <strong>releases</strong> electrons more readily than hydrogen.</p> <p>When copper(II) cations are being reduced to copper metal, the <strong>positive</strong> value of the standard reduction potential tells you that the equilibrium <strong>lies to the right</strong>, meaning that copper(II) cations are easier to reduce than hydrogen cations.</p> <p>In other words, copper <strong>releases</strong> electrons less readily than hydrogen.</p> <p>When you connect these two electrodes, the element that has the <strong>more negative</strong> standard reduction potential will be <strong>oxidized</strong> because it will lose electrons <em>more readily</em> and the element that has the <strong>more positive</strong> standard reduction potential will be <strong>reduced</strong> because it will lose electrons <em>less readily</em>. </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#E_ ("red Mg"^(2+))^@ < E_ ("red Cu"^(2+))^@ implies {("Mg is being oxized to Mg"^(2+)),("Cu"^(2+)color(white)(.)"is being reduced to Cu") :}#</mathjax></p> </blockquote> <p>so you can say that magnesium will be <strong>oxidized</strong> to magnesium cations and copper(II) cations will be <strong>reduced</strong> to copper metal. </p> <p>This means that you have--remember, when you flip the reduction half-reaction to get the <strong>oxidation half-reaction</strong>, you must <strong>change the sign</strong> of the standard reduction potential. </p> <blockquote> <p><mathjax>#{(color(white)(aaaaaaaa)"Mg" rightleftharpoons "Mg"^(2+) + 2"e"^(-), " "E_"oxi"^@ = - (-"2.372 V")), ("Cu"^(2+) + 2"e"^(-) rightleftharpoons "Cu", " "E_"red"^@ = +"0.337 V") :}#</mathjax></p> </blockquote> <p>To find the <mathjax>#"EMF"#</mathjax> of the cell, simply add the standard potentials of the two half-reactions.</p> <blockquote> <p><mathjax>#E_"cell"^@ = E_"oxi"^@ + E_"red"^@#</mathjax></p> </blockquote> <p>You will end up with </p> <blockquote> <p><mathjax>#E_"cell"^@ = +"2.372 V" + "0.337 V"#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)(E_"cell"^@ = +"2.709 V")))#</mathjax></p> </blockquote> <p>So, your galvanic cell will consist of a magnesium electrode and a copper electrode. Since magnesium is being <strong>oxidized</strong> and copper is being <strong>reduced</strong>, the magnesium electrode will be the <strong>anode</strong> and the copper electrode will be the <strong>cathode</strong>.</p> <p><img alt="http://www.chegg.com/homework-help/questions-and-answers/1-balance-following-redox-equation-acid-blank-put-correct-stochiometric-coefficient-0-1-2--q12066173" src="https://useruploads.socratic.org/SQ0dChCkRCaqAZu5k0xG_MgCuCell.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/528570" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-galvanic-cell-become-an-electrolytic-cell"> How can a galvanic cell become an electrolytic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-electrons-flow-in-a-galvanic-cell"> How do electrons flow in a galvanic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-galvanic-cell-potential"> How do you calculate galvanic cell potential? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-sketch-galvanic-cells"> How do you sketch galvanic cells? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-might-a-galvanic-cell-go-dead"> Why might a galvanic cell go dead? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5350796902bf343989038b3d"> Question #38b3d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-galvanic-cell"> What is a galvanic cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-galvanic-cells"> What are some common mistakes students make with galvanic cells? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-galvanic-cell-practice-problem"> What is an example of a galvanic cell practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-energy-conversion-takes-place-in-a-galvanic-cell"> What energy conversion takes place in a galvanic cell? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/galvanic-cells"> See all questions in Galvanic Cells </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 76733 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the standard EMF of a cell that uses the #"Mg/Mg"^(2+)# and #"Cu/Cu"^(2+)# half-cell reactions at #25^@"C"# ?	null
2,783	aaac1eb5-6ddd-11ea-997e-ccda262736ce	https://socratic.org/questions/how-much-potassium-bromide-kbr-is-produced-if-20g-of-potassium-bromate-kbro-3-de	14.3 g	start physical_unit 4 4 mass g qc_end physical_unit 13 13 8 9 mass qc_end end	[{"type":"physical unit","value":"Mass [OF] KBr [IN] g"}]	[{"type":"physical unit","value":"14.3 g"}]	[{"type":"physical unit","value":"Mass [OF] KBrO3 [=] \\pu{20.0 g}"}]	<h1 class="questionTitle" itemprop="name">How much potassium bromide, #"KBr"#, is produced if 20.0g of potassium bromate, #"KBrO"_3#, decomposes?</h1>	null	14.3 g	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></strong>. </p> <p><em>Potassium bromate</em>, <mathjax>#"KBrO"_3#</mathjax>, will undergo thermal decomposition to form potassium bromide, <mathjax>#"KBr"#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>.</p> <blockquote> <p><mathjax>#2"KBrO"_ (3(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) 2"KBr"_ ((s)) + 3"O"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#2#</mathjax> <strong>moles</strong> of potassium bromate to form <mathjax>#2#</mathjax> <strong>moles</strong> of potassium bromide. This tells you that the reaction will produce <strong>as many moles</strong> of potassium bromide as you have moles of potassium bromate that undergo decomposition. </p> <p>Simply put, the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>. </p> <p>You can convert this <strong>mole ratio</strong> to a <strong>gram ratio</strong> by using the molar masses of the two compounds</p> <blockquote> <p><mathjax>#M_("M KBrO"_3) = "167.0 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M KBr") = "119.0 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that a <mathjax>#1:1#</mathjax> mole ratio is equivalent to a <mathjax>#167.0 : 119.0#</mathjax> <strong>gram ratio</strong>. </p> <p>All you have to do now is use this gram ratio to determine how many grams of potassium bromide are produced when <mathjax>#"20.0 g"#</mathjax> of potassium bromate undergo decomposition </p> <blockquote> <p><mathjax>#20.0 color(red)(cancel(color(black)("g KBrO"_3))) * "119.0 g KBr"/(167.0color(red)(cancel(color(black)("g KBrO"_3)))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("14.3 g KBr")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"14.3 g KBr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></strong>. </p> <p><em>Potassium bromate</em>, <mathjax>#"KBrO"_3#</mathjax>, will undergo thermal decomposition to form potassium bromide, <mathjax>#"KBr"#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>.</p> <blockquote> <p><mathjax>#2"KBrO"_ (3(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) 2"KBr"_ ((s)) + 3"O"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#2#</mathjax> <strong>moles</strong> of potassium bromate to form <mathjax>#2#</mathjax> <strong>moles</strong> of potassium bromide. This tells you that the reaction will produce <strong>as many moles</strong> of potassium bromide as you have moles of potassium bromate that undergo decomposition. </p> <p>Simply put, the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>. </p> <p>You can convert this <strong>mole ratio</strong> to a <strong>gram ratio</strong> by using the molar masses of the two compounds</p> <blockquote> <p><mathjax>#M_("M KBrO"_3) = "167.0 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M KBr") = "119.0 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that a <mathjax>#1:1#</mathjax> mole ratio is equivalent to a <mathjax>#167.0 : 119.0#</mathjax> <strong>gram ratio</strong>. </p> <p>All you have to do now is use this gram ratio to determine how many grams of potassium bromide are produced when <mathjax>#"20.0 g"#</mathjax> of potassium bromate undergo decomposition </p> <blockquote> <p><mathjax>#20.0 color(red)(cancel(color(black)("g KBrO"_3))) * "119.0 g KBr"/(167.0color(red)(cancel(color(black)("g KBrO"_3)))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("14.3 g KBr")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How much potassium bromide, #"KBr"#, is produced if 20.0g of potassium bromate, #"KBrO"_3#, decomposes?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="282001" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-27T23:14:37" itemprop="dateCreated"> Jun 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"14.3 g KBr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></strong>. </p> <p><em>Potassium bromate</em>, <mathjax>#"KBrO"_3#</mathjax>, will undergo thermal decomposition to form potassium bromide, <mathjax>#"KBr"#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>.</p> <blockquote> <p><mathjax>#2"KBrO"_ (3(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(->) 2"KBr"_ ((s)) + 3"O"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#2#</mathjax> <strong>moles</strong> of potassium bromate to form <mathjax>#2#</mathjax> <strong>moles</strong> of potassium bromide. This tells you that the reaction will produce <strong>as many moles</strong> of potassium bromide as you have moles of potassium bromate that undergo decomposition. </p> <p>Simply put, the two <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> are in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong>. </p> <p>You can convert this <strong>mole ratio</strong> to a <strong>gram ratio</strong> by using the molar masses of the two compounds</p> <blockquote> <p><mathjax>#M_("M KBrO"_3) = "167.0 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M KBr") = "119.0 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that a <mathjax>#1:1#</mathjax> mole ratio is equivalent to a <mathjax>#167.0 : 119.0#</mathjax> <strong>gram ratio</strong>. </p> <p>All you have to do now is use this gram ratio to determine how many grams of potassium bromide are produced when <mathjax>#"20.0 g"#</mathjax> of potassium bromate undergo decomposition </p> <blockquote> <p><mathjax>#20.0 color(red)(cancel(color(black)("g KBrO"_3))) * "119.0 g KBr"/(167.0color(red)(cancel(color(black)("g KBrO"_3)))) = color(green)(\|bar(ul(color(white)(a/a)color(black)("14.3 g KBr")color(white)(a/a)\|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/282001" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-balanced-equation-practice-problem"> What is an example of a balanced equation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-a-chemical-equation"> How can I balance a chemical equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-stoichiometry-be-used"> How can stoichiometry be used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-reactants-to-products"> How do stoichiometric ratios relate reactants to products? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/equation-stoichiometry"> See all questions in Equation Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4073 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How much potassium bromide, #"KBr"#, is produced if 20.0g of potassium bromate, #"KBrO"_3#, decomposes?	null
2,784	a8523a31-6ddd-11ea-834d-ccda262736ce	https://socratic.org/questions/5846caf0b72cff37b07d8506	253.8 g/mol	start physical_unit 7 8 molecular_weight g/mol qc_end substance 7 8 qc_end end	[{"type":"physical unit","value":"formula mass [OF] iodine molecule [IN] g/mol"}]	[{"type":"physical unit","value":"253.8 g/mol"}]	[{"type":"substance name","value":"iodine molecule"}]	<h1 class="questionTitle" itemprop="name">What is the formula mass of the iodine molecule?</h1>	null	253.8 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of iodine is <mathjax>#126.9gmol^-1#</mathjax> (from where did I get that figure?), and thus its formula mass is <mathjax>#253.8gmol^-1#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Iodine is a diatomic molecule, and we work out the mass of <mathjax>#I_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of iodine is <mathjax>#126.9gmol^-1#</mathjax> (from where did I get that figure?), and thus its formula mass is <mathjax>#253.8gmol^-1#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the formula mass of the iodine molecule?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="349568" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-10T04:23:15" itemprop="dateCreated"> Dec 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Iodine is a diatomic molecule, and we work out the mass of <mathjax>#I_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of iodine is <mathjax>#126.9gmol^-1#</mathjax> (from where did I get that figure?), and thus its formula mass is <mathjax>#253.8gmol^-1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/349568" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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2,785	a9f26e9d-6ddd-11ea-a262-ccda262736ce	https://socratic.org/questions/how-many-moles-are-in-54-6-grams-rubidium-sulfide	0.27 moles	start physical_unit 7 8 mole mol qc_end physical_unit 7 8 5 6 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] rubidium sulfide [IN] moles"}]	[{"type":"physical unit","value":"0.27 moles"}]	[{"type":"physical unit","value":"Mass [OF] rubidium sulfide [=] \\pu{54.6 grams}"}]	<h1 class="questionTitle" itemprop="name">How many moles are in 54.6 grams rubidium sulfide?</h1>	null	0.27 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get the corresponding number of moles from the given grams of the compound, simply divide the moles by its molecular mass.</p> <p>In this example,</p> <p><mathjax>#mol Rb_2S = 54.6 g Rb_2S * ([1 mol]/[203.00g Rb_2S]) #</mathjax><br/> <mathjax>#mol Rb_2S = 0.269#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.269 mol</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get the corresponding number of moles from the given grams of the compound, simply divide the moles by its molecular mass.</p> <p>In this example,</p> <p><mathjax>#mol Rb_2S = 54.6 g Rb_2S * ([1 mol]/[203.00g Rb_2S]) #</mathjax><br/> <mathjax>#mol Rb_2S = 0.269#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How many moles are in 54.6 grams rubidium sulfide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="213184" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kristhia-loren-maree-rafols-c"><img alt="" class="" src="https://profilepictures.socratic.org/LCQvyymMQmyD0Ro56Sh6_IMG_20161030_204540.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kristhia-loren-maree-rafols-c"> Kris Caceres </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-16T17:26:10" itemprop="dateCreated"> Jan 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.269 mol</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get the corresponding number of moles from the given grams of the compound, simply divide the moles by its molecular mass.</p> <p>In this example,</p> <p><mathjax>#mol Rb_2S = 54.6 g Rb_2S * ([1 mol]/[203.00g Rb_2S]) #</mathjax><br/> <mathjax>#mol Rb_2S = 0.269#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/213184" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1338 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How many moles are in 54.6 grams rubidium sulfide?	null
2,786	ab30664f-6ddd-11ea-808d-ccda262736ce	https://socratic.org/questions/what-is-the-empirical-formula-for-the-compound-p4o6-1	P2O3	start chemical_formula qc_end chemical_equation 8 8 qc_end end	[{"type":"other","value":"Chemical Formula [OF] the compound P4O6 [IN] empirical"}]	[{"type":"chemical equation","value":"P2O3"}]	[{"type":"chemical equation","value":"P4O6"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula for the compound P4O6? </h1>	null	P2O3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound is the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. To find the empirical formula for the compound <mathjax>#"P"_4"O"_6"#</mathjax>, divide the subscripts (which represent the ratio) by 2 to get <mathjax>#"P"_2"O"_3"#</mathjax>. This ratio cannot be further reduced as whole numbers.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula for <mathjax>#"P"_4"O"_6"#</mathjax> is <mathjax>#"P"_2"O"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound is the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. To find the empirical formula for the compound <mathjax>#"P"_4"O"_6"#</mathjax>, divide the subscripts (which represent the ratio) by 2 to get <mathjax>#"P"_2"O"_3"#</mathjax>. This ratio cannot be further reduced as whole numbers.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula for the compound P4O6? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="193773" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-27T20:42:26" itemprop="dateCreated"> Nov 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula for <mathjax>#"P"_4"O"_6"#</mathjax> is <mathjax>#"P"_2"O"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of a compound is the lowest whole number ratio of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the compound. To find the empirical formula for the compound <mathjax>#"P"_4"O"_6"#</mathjax>, divide the subscripts (which represent the ratio) by 2 to get <mathjax>#"P"_2"O"_3"#</mathjax>. This ratio cannot be further reduced as whole numbers.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193773" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14816 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula for the compound P4O6?	null
2,787	ab136313-6ddd-11ea-8e49-ccda262736ce	https://socratic.org/questions/how-would-you-balance-this-chemical-equation-c-3h-8-o-2-3co-2-4h-2o	C3H8 + 5 O2 -> 3 CO2 + 4 H2O	start chemical_equation qc_end chemical_equation 7 15 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this chemical equation"}]	[{"type":"chemical equation","value":"C3H8 + 5 O2 -> 3 CO2 + 4 H2O"}]	[{"type":"chemical equation","value":"C3H8 + O2 -> 3 CO2 + 4 H2O"}]	<h1 class="questionTitle" itemprop="name">How would you balance this chemical equation: #C_3H_8 + O_2 -> 3CO_2 + 4H_2O#?</h1>	null	C3H8 + 5 O2 -> 3 CO2 + 4 H2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's look for each element one by one to see which element(s) needs balancing.</p> <p>Carbon is balanced : there are 3 carbon atoms on the LHS, and 3 carbons on the RHS.</p> <p>Hydrogen is balanced : There are 8 hydrogen atoms on the LHS, and 4 of 2 hydrogen atoms on the RHS, making it 8 atoms in total.</p> <p>Oxygen is <strong>not</strong> balanced : there are 2 oxygen atoms on the LHS, but 10 oxygens on the RHS. </p> <p>How many times does 2 go into 10? The answer is 5</p> <p><mathjax>#C_3H_8+5O_2rarr3CO_2+4H_2O#</mathjax></p> <p>There are 6 carbon atoms, 16 hydrogen atoms and 14 oxygen atoms on each side of the equation. It is now balanced.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3H_8+5O_2rarr3CO_2+4H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's look for each element one by one to see which element(s) needs balancing.</p> <p>Carbon is balanced : there are 3 carbon atoms on the LHS, and 3 carbons on the RHS.</p> <p>Hydrogen is balanced : There are 8 hydrogen atoms on the LHS, and 4 of 2 hydrogen atoms on the RHS, making it 8 atoms in total.</p> <p>Oxygen is <strong>not</strong> balanced : there are 2 oxygen atoms on the LHS, but 10 oxygens on the RHS. </p> <p>How many times does 2 go into 10? The answer is 5</p> <p><mathjax>#C_3H_8+5O_2rarr3CO_2+4H_2O#</mathjax></p> <p>There are 6 carbon atoms, 16 hydrogen atoms and 14 oxygen atoms on each side of the equation. It is now balanced.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you balance this chemical equation: #C_3H_8 + O_2 -> 3CO_2 + 4H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428286" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/soya-s"><img alt="" class="" src="https://lh3.googleusercontent.com/-0gsdbRI26uE/AAAAAAAAAAI/AAAAAAAAACE/ho0eSqho828/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/soya-s"> SoySoy4444 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-23T10:58:21" itemprop="dateCreated"> May 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_3H_8+5O_2rarr3CO_2+4H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's look for each element one by one to see which element(s) needs balancing.</p> <p>Carbon is balanced : there are 3 carbon atoms on the LHS, and 3 carbons on the RHS.</p> <p>Hydrogen is balanced : There are 8 hydrogen atoms on the LHS, and 4 of 2 hydrogen atoms on the RHS, making it 8 atoms in total.</p> <p>Oxygen is <strong>not</strong> balanced : there are 2 oxygen atoms on the LHS, but 10 oxygens on the RHS. </p> <p>How many times does 2 go into 10? The answer is 5</p> <p><mathjax>#C_3H_8+5O_2rarr3CO_2+4H_2O#</mathjax></p> <p>There are 6 carbon atoms, 16 hydrogen atoms and 14 oxygen atoms on each side of the equation. It is now balanced.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428286" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------> H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -># ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4861 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you balance this chemical equation: #C_3H_8 + O_2 -> 3CO_2 + 4H_2O#?	null
2,788	ab44e164-6ddd-11ea-9cd4-ccda262736ce	https://socratic.org/questions/what-is-the-gram-formula-mass-of-cuso-4-5h-2o	63.55 g/mol	start physical_unit 7 7 molar_mass g/mol qc_end chemical_equation 7 7 qc_end end	[{"type":"physical unit","value":"Gram formula mass [OF] CuSO4.5H2O [IN] g/mol"}]	[{"type":"physical unit","value":"63.55 g/mol"}]	[{"type":"chemical equation","value":"CuSO4.5H2O"}]	<h1 class="questionTitle" itemprop="name">What is the gram formula mass of #CuSO_4•5H_2O#?</h1>	null	63.55 g/mol	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.........And the atomic mass of sulfur is <mathjax>#32.06gmol^-1#</mathjax>, of oxygen, <mathjax>#15.999gmol^-1#</mathjax>, and of hydrogen <mathjax>#1.00794gmol^-1#</mathjax>.</p> <p>Can you sum these together appropriately? You will need to do it yourself soon enough. Check <a href="https://pubchem.ncbi.nlm.nih.gov/compound/Copper_II__sulfate_pentahydrate" rel="nofollow">your value with this one!</a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of copper is <mathjax>#63.55gmol^-1#</mathjax>.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.........And the atomic mass of sulfur is <mathjax>#32.06gmol^-1#</mathjax>, of oxygen, <mathjax>#15.999gmol^-1#</mathjax>, and of hydrogen <mathjax>#1.00794gmol^-1#</mathjax>.</p> <p>Can you sum these together appropriately? You will need to do it yourself soon enough. Check <a href="https://pubchem.ncbi.nlm.nih.gov/compound/Copper_II__sulfate_pentahydrate" rel="nofollow">your value with this one!</a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the gram formula mass of #CuSO_4•5H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="352289" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-15T18:16:42" itemprop="dateCreated"> Dec 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of copper is <mathjax>#63.55gmol^-1#</mathjax>.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>.........And the atomic mass of sulfur is <mathjax>#32.06gmol^-1#</mathjax>, of oxygen, <mathjax>#15.999gmol^-1#</mathjax>, and of hydrogen <mathjax>#1.00794gmol^-1#</mathjax>.</p> <p>Can you sum these together appropriately? You will need to do it yourself soon enough. Check <a href="https://pubchem.ncbi.nlm.nih.gov/compound/Copper_II__sulfate_pentahydrate" rel="nofollow">your value with this one!</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/352289" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1568 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the gram formula mass of #CuSO_4•5H_2O#?	null
2,789	a8f66dde-6ddd-11ea-9d6f-ccda262736ce	https://socratic.org/questions/how-would-you-calculate-the-solubility-of-mn-oh-2-in-grams-per-liter-when-buffer	1.2 × 10^(-3) grams per liter	start physical_unit 7 7 solubility g/l qc_end end	[{"type":"physical unit","value":"Solubility [OF] Mn(OH)2 [IN] grams per liter"}]	[{"type":"physical unit","value":"1.2 × 10^(-3) grams per liter"}]	[{"type":"physical unit","value":"ph [OF] buffer [=] \\pu{9.5}"}]	<h1 class="questionTitle" itemprop="name">How would you calculate the solubility of Mn(OH)2 in grams per liter when buffered at ph = 9.5?</h1>	null	1.2 × 10^(-3) grams per liter	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, you need to look up the <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>, for <em>manganese(II) hydroxide</em>, <mathjax>#"Mn"("OH")_2#</mathjax>. which you can find here</p> <p><a href="http://owl.cengage.com/departments/NYInstitTechBrownHolme2e/appendix/ksp.html" rel="nofollow" target="_blank">http://owl.cengage.com/departments/NYInstitTechBrownHolme2e/appendix/ksp.html</a></p> <p>So, the <mathjax>#K_(sp)#</mathjax> of manganese(II) hydroxide is equal to <mathjax>#4.6 * 10^(-14)#</mathjax>. As you know, the <em>insoluble</em> manganese(II) hydroxide will not dissociate completely when placed in aqueous solution. </p> <p>What will happen is an <a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium rection</a> will take place between the <em>solid</em> manganese(II) hydroxide and the <em>dissolved ions</em> </p> <blockquote> <p><mathjax>#"Mn"("OH")_text(2(s]) rightleftharpoons "Mn"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, you're trying to determine what the solubility of <mathjax>#"Mn"("OH")_2#</mathjax> will be in <em>basic solution</em>. As you know, basic <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are characterized by an excess of hydroxide ions, <mathjax>#"OH"^(-)#</mathjax>, when compared with pure water. </p> <p>More specifically, a solution that has a <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> equal to <mathjax>#9#</mathjax> will contain</p> <blockquote> <p><mathjax>#pOH = 14 - pH = 14 - 9.5 = 4.5#</mathjax></p> <p><mathjax>#["OH"^(-)] = 10^-"pOH" = 10^(-4.5) = 3.16 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>You can set up an <strong>ICE table</strong> to help you find the <em>molar solubility</em> of manganese(II) hydroxide in this solution</p> <blockquote> <p><mathjax>#"Mn"("OH")_text(2(s]) " "rightleftharpoons" " "Mn"_text((aq])^(2+) " "+" " color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " "-" " " " " " " " " " " " " " "0" " " " " " " " " "3.16 * 10^(-5)#</mathjax><br/> <mathjax>#color(purple)("C")" " " "-" " " " " " " " " " " "(+s)" " " " " " "(+color(red)(2)s)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "-" " " " " " " " " " " " " "s" " " " " " "3.16 * 10^(-5) + color(red)(2)s#</mathjax></p> <p>By definition, the solubility product constant, <mathjax>#K_(sp)#</mathjax>, will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = ["Mn"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> <p><mathjax>#K_(sp) = s * (3.16 * 10^(-5) + 2s)^2 = 4.6 * 10^(-14)#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#4s^3 + 12.64 * 10^(-5)s^2 + 9.986 * 10^(-10)s - 4.6 * 10^(-14) = 0#</mathjax></p> </blockquote> <p>This cubic equation will produce three solutions, two <em>negative</em> and one <em>positive</em>. Since <mathjax>#s#</mathjax> represents molar solubility, the only one that will have any chemical and physical significance will be the positive one</p> <blockquote> <p><mathjax>#s = 1.34 * 10^(-5)#</mathjax></p> </blockquote> <p>SInce this represents <em>molar solubility</em>, you can say that </p> <blockquote> <p><mathjax>#s = 1.34 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>To get the solubility in <em>grams per liter</em>, use manganese(II) hydroxide's molar mass</p> <blockquote> <p><mathjax>#1.34 * 10^(-5)color(red)(cancel(color(black)("moles")))/"L" * "88.953 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(1.2 * 10^(-3)"g/L")#</mathjax></p> </blockquote></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.2 * 10^(-3)"g/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, you need to look up the <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>, for <em>manganese(II) hydroxide</em>, <mathjax>#"Mn"("OH")_2#</mathjax>. which you can find here</p> <p><a href="http://owl.cengage.com/departments/NYInstitTechBrownHolme2e/appendix/ksp.html" rel="nofollow" target="_blank">http://owl.cengage.com/departments/NYInstitTechBrownHolme2e/appendix/ksp.html</a></p> <p>So, the <mathjax>#K_(sp)#</mathjax> of manganese(II) hydroxide is equal to <mathjax>#4.6 * 10^(-14)#</mathjax>. As you know, the <em>insoluble</em> manganese(II) hydroxide will not dissociate completely when placed in aqueous solution. </p> <p>What will happen is an <a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium rection</a> will take place between the <em>solid</em> manganese(II) hydroxide and the <em>dissolved ions</em> </p> <blockquote> <p><mathjax>#"Mn"("OH")_text(2(s]) rightleftharpoons "Mn"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, you're trying to determine what the solubility of <mathjax>#"Mn"("OH")_2#</mathjax> will be in <em>basic solution</em>. As you know, basic <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are characterized by an excess of hydroxide ions, <mathjax>#"OH"^(-)#</mathjax>, when compared with pure water. </p> <p>More specifically, a solution that has a <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> equal to <mathjax>#9#</mathjax> will contain</p> <blockquote> <p><mathjax>#pOH = 14 - pH = 14 - 9.5 = 4.5#</mathjax></p> <p><mathjax>#["OH"^(-)] = 10^-"pOH" = 10^(-4.5) = 3.16 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>You can set up an <strong>ICE table</strong> to help you find the <em>molar solubility</em> of manganese(II) hydroxide in this solution</p> <blockquote> <p><mathjax>#"Mn"("OH")_text(2(s]) " "rightleftharpoons" " "Mn"_text((aq])^(2+) " "+" " color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " "-" " " " " " " " " " " " " " "0" " " " " " " " " "3.16 * 10^(-5)#</mathjax><br/> <mathjax>#color(purple)("C")" " " "-" " " " " " " " " " " "(+s)" " " " " " "(+color(red)(2)s)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "-" " " " " " " " " " " " " "s" " " " " " "3.16 * 10^(-5) + color(red)(2)s#</mathjax></p> <p>By definition, the solubility product constant, <mathjax>#K_(sp)#</mathjax>, will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = ["Mn"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> <p><mathjax>#K_(sp) = s * (3.16 * 10^(-5) + 2s)^2 = 4.6 * 10^(-14)#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#4s^3 + 12.64 * 10^(-5)s^2 + 9.986 * 10^(-10)s - 4.6 * 10^(-14) = 0#</mathjax></p> </blockquote> <p>This cubic equation will produce three solutions, two <em>negative</em> and one <em>positive</em>. Since <mathjax>#s#</mathjax> represents molar solubility, the only one that will have any chemical and physical significance will be the positive one</p> <blockquote> <p><mathjax>#s = 1.34 * 10^(-5)#</mathjax></p> </blockquote> <p>SInce this represents <em>molar solubility</em>, you can say that </p> <blockquote> <p><mathjax>#s = 1.34 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>To get the solubility in <em>grams per liter</em>, use manganese(II) hydroxide's molar mass</p> <blockquote> <p><mathjax>#1.34 * 10^(-5)color(red)(cancel(color(black)("moles")))/"L" * "88.953 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(1.2 * 10^(-3)"g/L")#</mathjax></p> </blockquote></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How would you calculate the solubility of Mn(OH)2 in grams per liter when buffered at ph = 9.5?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility" itemprop="url"> <span class="breadcrumb" itemprop="title">Factors Affecting Solubility</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="184411" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-05T23:49:46" itemprop="dateCreated"> Nov 5, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.2 * 10^(-3)"g/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First thing first, you need to look up the <em>solubility product constant</em>, <mathjax>#K_(sp)#</mathjax>, for <em>manganese(II) hydroxide</em>, <mathjax>#"Mn"("OH")_2#</mathjax>. which you can find here</p> <p><a href="http://owl.cengage.com/departments/NYInstitTechBrownHolme2e/appendix/ksp.html" rel="nofollow" target="_blank">http://owl.cengage.com/departments/NYInstitTechBrownHolme2e/appendix/ksp.html</a></p> <p>So, the <mathjax>#K_(sp)#</mathjax> of manganese(II) hydroxide is equal to <mathjax>#4.6 * 10^(-14)#</mathjax>. As you know, the <em>insoluble</em> manganese(II) hydroxide will not dissociate completely when placed in aqueous solution. </p> <p>What will happen is an <a href="http://socratic.org/chemistry/chemical-equilibrium/dynamic-equilibrium">equilibrium rection</a> will take place between the <em>solid</em> manganese(II) hydroxide and the <em>dissolved ions</em> </p> <blockquote> <p><mathjax>#"Mn"("OH")_text(2(s]) rightleftharpoons "Mn"_text((aq])^(2+) + color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, you're trying to determine what the solubility of <mathjax>#"Mn"("OH")_2#</mathjax> will be in <em>basic solution</em>. As you know, basic <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are characterized by an excess of hydroxide ions, <mathjax>#"OH"^(-)#</mathjax>, when compared with pure water. </p> <p>More specifically, a solution that has a <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> equal to <mathjax>#9#</mathjax> will contain</p> <blockquote> <p><mathjax>#pOH = 14 - pH = 14 - 9.5 = 4.5#</mathjax></p> <p><mathjax>#["OH"^(-)] = 10^-"pOH" = 10^(-4.5) = 3.16 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>You can set up an <strong>ICE table</strong> to help you find the <em>molar solubility</em> of manganese(II) hydroxide in this solution</p> <blockquote> <p><mathjax>#"Mn"("OH")_text(2(s]) " "rightleftharpoons" " "Mn"_text((aq])^(2+) " "+" " color(red)(2)"OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")" " " "-" " " " " " " " " " " " " " "0" " " " " " " " " "3.16 * 10^(-5)#</mathjax><br/> <mathjax>#color(purple)("C")" " " "-" " " " " " " " " " " "(+s)" " " " " " "(+color(red)(2)s)#</mathjax><br/> <mathjax>#color(purple)("E")" " " "-" " " " " " " " " " " " " "s" " " " " " "3.16 * 10^(-5) + color(red)(2)s#</mathjax></p> <p>By definition, the solubility product constant, <mathjax>#K_(sp)#</mathjax>, will be equal to</p> <blockquote> <p><mathjax>#K_(sp) = ["Mn"^(2+)] * ["OH"^(-)]^color(red)(2)#</mathjax></p> <p><mathjax>#K_(sp) = s * (3.16 * 10^(-5) + 2s)^2 = 4.6 * 10^(-14)#</mathjax></p> </blockquote> <p>This is equivalent to </p> <blockquote> <p><mathjax>#4s^3 + 12.64 * 10^(-5)s^2 + 9.986 * 10^(-10)s - 4.6 * 10^(-14) = 0#</mathjax></p> </blockquote> <p>This cubic equation will produce three solutions, two <em>negative</em> and one <em>positive</em>. Since <mathjax>#s#</mathjax> represents molar solubility, the only one that will have any chemical and physical significance will be the positive one</p> <blockquote> <p><mathjax>#s = 1.34 * 10^(-5)#</mathjax></p> </blockquote> <p>SInce this represents <em>molar solubility</em>, you can say that </p> <blockquote> <p><mathjax>#s = 1.34 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>To get the solubility in <em>grams per liter</em>, use manganese(II) hydroxide's molar mass</p> <blockquote> <p><mathjax>#1.34 * 10^(-5)color(red)(cancel(color(black)("moles")))/"L" * "88.953 g"/(1color(red)(cancel(color(black)("mole")))) = color(green)(1.2 * 10^(-3)"g/L")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/184411" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-a-solid-liquid-combination"> What factors affect solubility in a solid-liquid combination? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-water"> What factors affect solubility in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-of-ionic-compounds"> What factors affect solubility of ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-the-solubility-of-gases-in-liquids"> What factors affect the solubility of gases in liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-the-solubility-of-a-solid"> What factors affect the solubility of a solid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-of-potassium-nitrate"> How can I calculate solubility of potassium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-solubility-of-kno3-depend-on"> What does the solubility of KNO3 depend on? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-solubility-of-a-solution"> How can I calculate the solubility of solute in a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-solubility-is-affected-by-polymer-chain-structure"> How is solubility affected by polymer chain structure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-solubility-differ-from-molar-solubility"> Does solubility differ from molar solubility? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility"> See all questions in Factors Affecting Solubility </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 45551 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	How would you calculate the solubility of Mn(OH)2 in grams per liter when buffered at ph = 9.5?	null
2,790	ac14f63b-6ddd-11ea-80e1-ccda262736ce	https://socratic.org/questions/a-solution-contains-oh-4-0-times-10-5-m-what-is-the-concentration-of-h-3o	2.50 × 10^(-10) M	start physical_unit 14 14 concentration mol/l qc_end physical_unit 1 1 5 8 [oh-] qc_end end	[{"type":"physical unit","value":"Concentration [OF] [H3O+] [IN] M"}]	[{"type":"physical unit","value":"2.50 × 10^(-10) M"}]	[{"type":"physical unit","value":"[OH-] [OF] the solution [=] \\pu{4.0 × 10^(-5) M}"}]	<h1 class="questionTitle" itemprop="name">A solution contains #[OH^-] = 4.0 times 10^-5# #M#, what is the concentration of #[H_3O^+]#?</h1>	null	2.50 × 10^(-10) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In aqueous solution, it is a fact that the following equilibrium operates under standard conditions.........</p> <p><mathjax>#2H_2O(l) rightleftharpoons H_3O^(+) +HO^(-)#</mathjax></p> <p>Under standard conditions............</p> <p><mathjax>#K_"rxn"=K_w=[H_3O^+][HO^-]=10^-14#</mathjax>. And typically we would use logarithms to reduce this expression to.......</p> <p><mathjax>#pH+pOH=14#</mathjax>, where the <mathjax>#pH#</mathjax> function means <mathjax>#-log_10[H_3O^+]#</mathjax> etc. </p> <p>So <mathjax>#pOH=-log_10[4.0xx10^-5]=4.40#</mathjax>, and <mathjax>#pH=9.60#</mathjax>.</p> <p>And thus <mathjax>#[H_3O^+]=10^(-9.60)=2.50xx10^-10molL^-1.#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]=2.50xx10^-10molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In aqueous solution, it is a fact that the following equilibrium operates under standard conditions.........</p> <p><mathjax>#2H_2O(l) rightleftharpoons H_3O^(+) +HO^(-)#</mathjax></p> <p>Under standard conditions............</p> <p><mathjax>#K_"rxn"=K_w=[H_3O^+][HO^-]=10^-14#</mathjax>. And typically we would use logarithms to reduce this expression to.......</p> <p><mathjax>#pH+pOH=14#</mathjax>, where the <mathjax>#pH#</mathjax> function means <mathjax>#-log_10[H_3O^+]#</mathjax> etc. </p> <p>So <mathjax>#pOH=-log_10[4.0xx10^-5]=4.40#</mathjax>, and <mathjax>#pH=9.60#</mathjax>.</p> <p>And thus <mathjax>#[H_3O^+]=10^(-9.60)=2.50xx10^-10molL^-1.#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A solution contains #[OH^-] = 4.0 times 10^-5# #M#, what is the concentration of #[H_3O^+]#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="429338" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-25T07:35:15" itemprop="dateCreated"> May 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]=2.50xx10^-10molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In aqueous solution, it is a fact that the following equilibrium operates under standard conditions.........</p> <p><mathjax>#2H_2O(l) rightleftharpoons H_3O^(+) +HO^(-)#</mathjax></p> <p>Under standard conditions............</p> <p><mathjax>#K_"rxn"=K_w=[H_3O^+][HO^-]=10^-14#</mathjax>. And typically we would use logarithms to reduce this expression to.......</p> <p><mathjax>#pH+pOH=14#</mathjax>, where the <mathjax>#pH#</mathjax> function means <mathjax>#-log_10[H_3O^+]#</mathjax> etc. </p> <p>So <mathjax>#pOH=-log_10[4.0xx10^-5]=4.40#</mathjax>, and <mathjax>#pH=9.60#</mathjax>.</p> <p>And thus <mathjax>#[H_3O^+]=10^(-9.60)=2.50xx10^-10molL^-1.#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/429338" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="429339" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jacob-t-3"><img alt="" class="" src="https://profilepictures.socratic.org/cDl6OiFtT16bIyMtJPfM_Protractor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jacob-t-3"> Jacob T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-25T07:38:52" itemprop="dateCreated"> May 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]=2.510^(-10) M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given that no hydrolysis happened in the solution (inferred from question) Calculate <mathjax>#[H_3O^+]#</mathjax> from <mathjax>#k_w#</mathjax> directly.<br/> <mathjax>#[H_3O^+]#</mathjax><br/> <mathjax>#=k_w/([OH^-])#</mathjax><br/> <mathjax>#=10^-14/(4.010^-5)#</mathjax><br/> <mathjax>#=2.5*10^-10M#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/429339" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="429341" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mert-m"><img alt="" class="" src="https://profilepictures.socratic.org/saBhsgJSSti0HIIaFUp7_hqdefault.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mert-m"> Mert M. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-25T07:44:05" itemprop="dateCreated"> May 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5 xx 10 ^-10#</mathjax> <mathjax>#"M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="My own work (Mert METİN)" src="https://useruploads.socratic.org/010qHTHRUiX2eGsLU1gu_photo5852947402972047700.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/429341" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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2,791	a9909d69-6ddd-11ea-9a22-ccda262736ce	https://socratic.org/questions/0-465-g-sample-of-an-unknown-compound-occupies-245-ml-at-298k-and-1-22-atm-what-	38.43 g/mol	start physical_unit 22 24 molar_mass g/mol qc_end physical_unit 2 6 0 1 mass qc_end physical_unit 2 6 8 9 volume qc_end physical_unit 2 6 11 12 temperature qc_end physical_unit 2 6 14 15 pressure qc_end end	[{"type":"physical unit","value":"Molar mass [OF] the unknown compound [IN] g/mol"}]	[{"type":"physical unit","value":"38.43 g/mol"}]	[{"type":"physical unit","value":"Mass [OF] an unknown compound sample [=] \\pu{0.465 g}"},{"type":"physical unit","value":"Volume [OF] an unknown compound sample [=] \\pu{245 mL}"},{"type":"physical unit","value":"Temperature [OF] an unknown compound sample [=] \\pu{298 K}"},{"type":"physical unit","value":"Pressure [OF] an unknown compound sample [=] \\pu{1.22 atm}"}]	<h1 class="questionTitle" itemprop="name">0.465 g sample of an unknown compound occupies 245 mL at 298K and 1.22 atm. What is the molar mass of the unknown compound?</h1>	null	38.43 g/mol	<div class="answerDescription"> <div> <div class="markdown"><p>The molar mass of the gas is 38.0 g/mol.</p> <p>One way to solve this problem is to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>.</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#n = m/M_"r"#</mathjax>, where <mathjax>#m#</mathjax> is the mass and <mathjax>#M_r#</mathjax> is the relative molar mass. So,</p> <p><mathjax>#PV = (m/M_"r")RT#</mathjax></p> <p><mathjax>#M_"r" = (mRT)/(PV) = ("0.465 g" × 0.082 06 cancel("L·atm·K⁻¹")"mol⁻¹" × 298 cancel("K"))/(1.22 cancel("atm") × 0.245 cancel("L")) = "38.0 g/mol"#</mathjax></p> <p>The relative molar mass is 38.0 g/mol.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>The molar mass of the gas is 38.0 g/mol.</p> <p>One way to solve this problem is to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>.</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#n = m/M_"r"#</mathjax>, where <mathjax>#m#</mathjax> is the mass and <mathjax>#M_r#</mathjax> is the relative molar mass. So,</p> <p><mathjax>#PV = (m/M_"r")RT#</mathjax></p> <p><mathjax>#M_"r" = (mRT)/(PV) = ("0.465 g" × 0.082 06 cancel("L·atm·K⁻¹")"mol⁻¹" × 298 cancel("K"))/(1.22 cancel("atm") × 0.245 cancel("L")) = "38.0 g/mol"#</mathjax></p> <p>The relative molar mass is 38.0 g/mol.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">0.465 g sample of an unknown compound occupies 245 mL at 298K and 1.22 atm. What is the molar mass of the unknown compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="133031" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-03-20T19:49:17" itemprop="dateCreated"> Mar 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>The molar mass of the gas is 38.0 g/mol.</p> <p>One way to solve this problem is to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>.</p> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#n = m/M_"r"#</mathjax>, where <mathjax>#m#</mathjax> is the mass and <mathjax>#M_r#</mathjax> is the relative molar mass. So,</p> <p><mathjax>#PV = (m/M_"r")RT#</mathjax></p> <p><mathjax>#M_"r" = (mRT)/(PV) = ("0.465 g" × 0.082 06 cancel("L·atm·K⁻¹")"mol⁻¹" × 298 cancel("K"))/(1.22 cancel("atm") × 0.245 cancel("L")) = "38.0 g/mol"#</mathjax></p> <p>The relative molar mass is 38.0 g/mol.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/133031" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="133033" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/dwayne-1"><img alt="" class="" src="https://profilepictures.socratic.org/DibNg4wlRrG9KFZ5SeFe_IMG_2126.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a>·<a class="topContributorLink" href="/users/dwayne-1"> dwayne </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-03-20T20:06:15" itemprop="dateCreated"> Mar 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>38.4g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#M_r=38.4#</mathjax></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#P=1.22xx1.0xx10^(5)Pa#</mathjax></p> <p><mathjax>#T=298K#</mathjax></p> <p><mathjax>#V=245xx10^(-6)m^(3)#</mathjax></p> <p><mathjax>#R=8.31"J/K/mol"#</mathjax></p> <p><mathjax>#n=(PV)/(RT)=(1.22xx10^(5)xx245xx10^(-6))/(8.31xx298)#</mathjax></p> <p><mathjax>#n=0.0121#</mathjax></p> <p>So 0.0121 moles weigh 0.465g</p> <p>So 1 mole weighs <mathjax>#0.465/0.0121= 38.4"g"#</mathjax></p> <p>nb I converted to Pa and used 8.31 for R. It depends which R value you are given.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/133033" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 29849 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	0.465 g sample of an unknown compound occupies 245 mL at 298K and 1.22 atm. What is the molar mass of the unknown compound?	null
2,792	a9cd71f7-6ddd-11ea-8f39-ccda262736ce	https://socratic.org/questions/58ab394bb72cff4efe435d80	CH2O	start chemical_formula qc_end substance 6 6 qc_end end	[{"type":"other","value":"Chemical Formula [OF] glucose [IN] empirical"}]	[{"type":"chemical equation","value":"CH2O"}]	[{"type":"substance name","value":"Glucose"}]	<h1 class="questionTitle" itemprop="name">What is the empirical formula of glucose?</h1>	null	CH2O	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest WHOLE number ratio representing constituent atoms in a species. We know, or should know, that the formula of glucose is <mathjax>#C_6H_12O_6#</mathjax>, and I divide this thru by <mathjax>#6#</mathjax>, I get the empirical formula <mathjax>#CH_2O#</mathjax>, which is the same simplest whole number ratio. The <mathjax>#"molecular formula"#</mathjax> is always a multiple of the <mathjax>#"empirical formula"#</mathjax>. </p> <p>See <a href="https://socratic.org/questions/how-is-the-empirical-formula-used">here for a few more examples. </a> </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest WHOLE number ratio representing constituent atoms in a species. We know, or should know, that the formula of glucose is <mathjax>#C_6H_12O_6#</mathjax>, and I divide this thru by <mathjax>#6#</mathjax>, I get the empirical formula <mathjax>#CH_2O#</mathjax>, which is the same simplest whole number ratio. The <mathjax>#"molecular formula"#</mathjax> is always a multiple of the <mathjax>#"empirical formula"#</mathjax>. </p> <p>See <a href="https://socratic.org/questions/how-is-the-empirical-formula-used">here for a few more examples. </a> </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of glucose?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="380658" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-20T18:52:15" itemprop="dateCreated"> Feb 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest WHOLE number ratio representing constituent atoms in a species. We know, or should know, that the formula of glucose is <mathjax>#C_6H_12O_6#</mathjax>, and I divide this thru by <mathjax>#6#</mathjax>, I get the empirical formula <mathjax>#CH_2O#</mathjax>, which is the same simplest whole number ratio. The <mathjax>#"molecular formula"#</mathjax> is always a multiple of the <mathjax>#"empirical formula"#</mathjax>. </p> <p>See <a href="https://socratic.org/questions/how-is-the-empirical-formula-used">here for a few more examples. </a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/380658" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4460 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What is the empirical formula of glucose?	null
2,793	aa89ac19-6ddd-11ea-8b37-ccda262736ce	https://socratic.org/questions/what-mass-of-aluminum-contains-twice-as-many-atoms-as-35-00-grams-of-copper	29.72 grams	start physical_unit 3 3 mass g qc_end physical_unit 13 13 10 11 mass qc_end c_other OTHER qc_end end	[{"type":"physical unit","value":"Mass [OF] aluminum [IN] grams"}]	[{"type":"physical unit","value":"29.72 grams"}]	[{"type":"physical unit","value":"Mass [OF] copper [=] \\pu{35.00 grams}"},{"type":"other","value":"Aluminum contains twice as many atoms as copper."}]	<h1 class="questionTitle" itemprop="name">What mass of aluminum contains twice as many atoms as 35.00 grams of copper?</h1>	null	29.72 grams	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(35gCu)/(63.546g/(mol)Cu)=0.55078molCu#</mathjax></p> <p><mathjax>#0.55078mol2=1.1015molAl#</mathjax></p> <p><mathjax>#1.1015molAl26.982g/(mol)Al=29.72gAl#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#29.72gAl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(35gCu)/(63.546g/(mol)Cu)=0.55078molCu#</mathjax></p> <p><mathjax>#0.55078mol2=1.1015molAl#</mathjax></p> <p><mathjax>#1.1015molAl26.982g/(mol)Al=29.72gAl#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What mass of aluminum contains twice as many atoms as 35.00 grams of copper?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="465652" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tcw1"><img alt="" class="" src="https://profilepictures.socratic.org/Ox6b9VazRq1N5FiU8YFj_fractal-026.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tcw1"> tcw1 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-19T02:22:36" itemprop="dateCreated"> Aug 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#29.72gAl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(35gCu)/(63.546g/(mol)Cu)=0.55078molCu#</mathjax></p> <p><mathjax>#0.55078mol2=1.1015molAl#</mathjax></p> <p><mathjax>#1.1015molAl26.982g/(mol)Al=29.72gAl#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465652" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="465655" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-19T02:34:23" itemprop="dateCreated"> Aug 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"29.72 g Al"#</mathjax> contains twice the number of atoms of <mathjax>#"35.00 g Cu"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to determine the mass of Al that contains twice as many atoms of Cu in 35.00 g, first determine the number of Cu atoms found in 35.00 g. Then multiply by 2 to get the number of atoms of Al, then determine the mass of Al.</p> <p>To determine the number of atoms of copper in <mathjax>#"35.00 g"#</mathjax>, calculate the moles <mathjax>#"Cu"#</mathjax> and multiply by <mathjax>#6.022xx10^23#</mathjax> atoms/mol.</p> <p><strong>Atoms of Cu</strong></p> <p>The molar mass of <mathjax>#"Cu"#</mathjax> is <mathjax>#"63.546 g/mol"#</mathjax>. To get moles, divide the given mass by the molar mass. Since g/mol is a fraction, <mathjax>#"g"/"mol"#</mathjax>, multiply the given mass by the inverse of the molar mass. Then multiply by <mathjax>#6.022xx10^23#</mathjax> atoms/mol.</p> <p><mathjax>#35.00color(red)cancel(color(black)("g Cu"))xx(1color(red)cancel(color(black)("mol Cu")))/(63.546color(red)cancel(color(black)("g Cu")))xx(6.022xx10^23"atoms Cu")/(1color(red)cancel(color(black)("mol Cu")))=3.317xx10^23"atoms Cu"#</mathjax></p> <p><strong>Mass of Al (molar mass = 26.982 g/mol)</strong></p> <p>Do the reverse of finding the atoms of <mathjax>#"Cu"#</mathjax>.</p> <p><strong>Atoms of Al:</strong></p> <p><mathjax>#2xx(3.317xx10^23)=6.634xx10^23"atoms Al"#</mathjax></p> <p><strong>Mass of Al:</strong></p> <p><mathjax>#6.634xx10^23color(red)cancel(color(black)("atoms Al"))xx(1color(red)cancel(color(black)("mol Al")))/(6.022xx10^23color(red)cancel(color(black)("atoms Al")))xx(26.982"g Al")/(1color(red)cancel(color(black)("mol Al")))="29.72 g Al"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465655" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2511 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	What mass of aluminum contains twice as many atoms as 35.00 grams of copper?	null
2,794	a99f19f4-6ddd-11ea-b869-ccda262736ce	https://socratic.org/questions/alnico-is-a-strongly-magnetic-alloy-solid-mixture-of-co-ni-al-and-fe-a-100-0-g-s	0.42 moles	start physical_unit 41 41 mole mol qc_end c_other OTHER qc_end physical_unit 17 19 15 16 mass qc_end physical_unit 11 11 21 22 mass qc_end physical_unit 10 10 24 25 mass qc_end physical_unit 9 9 28 29 mass qc_end end	[{"type":"physical unit","value":"Mole [OF] aluminum [IN] moles"}]	[{"type":"physical unit","value":"0.42 moles"}]	[{"type":"other","value":"Alnico is a strongly magnetic alloy (solid mixture) of Co, Ni, Al and Fe."},{"type":"physical unit","value":"Mass [OF] Alnico sample [=] \\pu{100.0 g}"},{"type":"physical unit","value":"Mass [OF] Al [=] \\pu{11.2 g}"},{"type":"physical unit","value":"Mass [OF] Ni [=] \\pu{22.3 g}"},{"type":"physical unit","value":"Mass [OF] Co [=] \\pu{5.0 g}"}]	<h1 class="questionTitle" itemprop="name">Alnico is a strongly magnetic alloy (solid mixture) of Co, Ni, Al and Fe. A 100.0 g sample of Alnico has 11.2g Al, 22.3g Ni, and 5.0g Co in it; the rest is Fe. How many moles of aluminum are there?</h1>	null	0.42 moles	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#11.2#</mathjax> <mathjax>#g#</mathjax> Al x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#26.98#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.415#</mathjax> <mathjax>#mol#</mathjax> Al</p> <p><mathjax>#22.3#</mathjax> <mathjax>#g#</mathjax> Ni x(<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#58.69#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.380#</mathjax> <mathjax>#mol#</mathjax> Ni</p> <p><mathjax>#5.0#</mathjax> <mathjax>#g#</mathjax> Co x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#58.93#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.0848#</mathjax> <mathjax>#mol#</mathjax> Co</p> <p><mathjax>#100#</mathjax> <mathjax>#g -11.2#</mathjax> <mathjax>#g#</mathjax> Al <mathjax># -22.3g#</mathjax> <mathjax>#Ni -5.0#</mathjax> <mathjax>#g#</mathjax> Co = <mathjax>#61.5#</mathjax> <mathjax>#g#</mathjax> Fe </p> <p><mathjax>#61.5#</mathjax> <mathjax>#g#</mathjax> Fe <mathjax>#xx((1 mol)/55.84)=1.10#</mathjax> <mathjax>#mol#</mathjax> Fe</p> <p>Divide each one by the smallest number of moles: cobalt at <mathjax>#0.0848#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Al = <mathjax>#0.415/0.0848 = 4.89#</mathjax> <mathjax>#mol #</mathjax><br/> Ni = <mathjax>#0.380/0.0848 = 4.48#</mathjax> <mathjax>#mol #</mathjax><br/> Co =<mathjax># 0.0848/0.0848 = 1.00#</mathjax> <mathjax>#mol #</mathjax><br/> Fe= <mathjax>#1.10/0.0848= 12.97#</mathjax> <mathjax>#mol #</mathjax></p> <p>Since Ni is <mathjax>#4.48 ~~4.50#</mathjax>, we multiply everything by <mathjax>#2#</mathjax> to get a whole number, <mathjax>#9#</mathjax>, for Ni. </p> <p>Al = <mathjax>#4.89#</mathjax> <mathjax>#mol xx 2= 10#</mathjax> <mathjax>#mol#</mathjax> Al<br/> Ni = <mathjax>#4.48#</mathjax> <mathjax>#mol xx 2= 9#</mathjax> <mathjax>#mol#</mathjax> Ni<br/> Co = <mathjax>#1.00#</mathjax> <mathjax>#mol xx 2= 2#</mathjax> <mathjax>#mol#</mathjax> Co<br/> Fe= <mathjax>#12.97#</mathjax> <mathjax>#mol xx 2= 26#</mathjax> <mathjax>#mol#</mathjax> Fe</p> <p>This gives us an empirical formula of <mathjax>#Al_10Co_2Fe_26Ni_9#</mathjax>.</p> <p>If we add up the Fe, Co, Ni, and Al in the empirical formula, we get <mathjax>#2366.7#</mathjax> <mathjax>#gmol^-1#</mathjax> of Alnico</p> <p><mathjax>#100#</mathjax> <mathjax>#g#</mathjax> Alnico x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> Alnico/<mathjax>#2366.7#</mathjax> <mathjax>#g#</mathjax> Alnico) x (<mathjax>#10#</mathjax> <mathjax>#mol#</mathjax> Al/<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> Alnico) = <mathjax>#0.423#</mathjax> <mathjax>#mol#</mathjax> Al </p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.423#</mathjax> <mathjax>#mol#</mathjax> Al give or take w/ sig figs</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#11.2#</mathjax> <mathjax>#g#</mathjax> Al x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#26.98#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.415#</mathjax> <mathjax>#mol#</mathjax> Al</p> <p><mathjax>#22.3#</mathjax> <mathjax>#g#</mathjax> Ni x(<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#58.69#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.380#</mathjax> <mathjax>#mol#</mathjax> Ni</p> <p><mathjax>#5.0#</mathjax> <mathjax>#g#</mathjax> Co x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#58.93#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.0848#</mathjax> <mathjax>#mol#</mathjax> Co</p> <p><mathjax>#100#</mathjax> <mathjax>#g -11.2#</mathjax> <mathjax>#g#</mathjax> Al <mathjax># -22.3g#</mathjax> <mathjax>#Ni -5.0#</mathjax> <mathjax>#g#</mathjax> Co = <mathjax>#61.5#</mathjax> <mathjax>#g#</mathjax> Fe </p> <p><mathjax>#61.5#</mathjax> <mathjax>#g#</mathjax> Fe <mathjax>#xx((1 mol)/55.84)=1.10#</mathjax> <mathjax>#mol#</mathjax> Fe</p> <p>Divide each one by the smallest number of moles: cobalt at <mathjax>#0.0848#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Al = <mathjax>#0.415/0.0848 = 4.89#</mathjax> <mathjax>#mol #</mathjax><br/> Ni = <mathjax>#0.380/0.0848 = 4.48#</mathjax> <mathjax>#mol #</mathjax><br/> Co =<mathjax># 0.0848/0.0848 = 1.00#</mathjax> <mathjax>#mol #</mathjax><br/> Fe= <mathjax>#1.10/0.0848= 12.97#</mathjax> <mathjax>#mol #</mathjax></p> <p>Since Ni is <mathjax>#4.48 ~~4.50#</mathjax>, we multiply everything by <mathjax>#2#</mathjax> to get a whole number, <mathjax>#9#</mathjax>, for Ni. </p> <p>Al = <mathjax>#4.89#</mathjax> <mathjax>#mol xx 2= 10#</mathjax> <mathjax>#mol#</mathjax> Al<br/> Ni = <mathjax>#4.48#</mathjax> <mathjax>#mol xx 2= 9#</mathjax> <mathjax>#mol#</mathjax> Ni<br/> Co = <mathjax>#1.00#</mathjax> <mathjax>#mol xx 2= 2#</mathjax> <mathjax>#mol#</mathjax> Co<br/> Fe= <mathjax>#12.97#</mathjax> <mathjax>#mol xx 2= 26#</mathjax> <mathjax>#mol#</mathjax> Fe</p> <p>This gives us an empirical formula of <mathjax>#Al_10Co_2Fe_26Ni_9#</mathjax>.</p> <p>If we add up the Fe, Co, Ni, and Al in the empirical formula, we get <mathjax>#2366.7#</mathjax> <mathjax>#gmol^-1#</mathjax> of Alnico</p> <p><mathjax>#100#</mathjax> <mathjax>#g#</mathjax> Alnico x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> Alnico/<mathjax>#2366.7#</mathjax> <mathjax>#g#</mathjax> Alnico) x (<mathjax>#10#</mathjax> <mathjax>#mol#</mathjax> Al/<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> Alnico) = <mathjax>#0.423#</mathjax> <mathjax>#mol#</mathjax> Al </p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Alnico is a strongly magnetic alloy (solid mixture) of Co, Ni, Al and Fe. A 100.0 g sample of Alnico has 11.2g Al, 22.3g Ni, and 5.0g Co in it; the rest is Fe. How many moles of aluminum are there?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232923" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/wil052"><img alt="" class="" src="https://profilepictures.socratic.org/0P5SVeaCSfqbcHcQzSFx_Visiblelight.png" title=""/></a> <a class="secondContributorPic" href="/users/david-g-6"><img alt="" class="" src="https://graph.facebook.com/10153408096237887/picture?height=50&width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/wil052"> Wil052 </a>·<a class="topContributorLink" href="/users/david-g-6"> David G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-29T10:44:12" itemprop="dateCreated"> Feb 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.423#</mathjax> <mathjax>#mol#</mathjax> Al give or take w/ sig figs</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#11.2#</mathjax> <mathjax>#g#</mathjax> Al x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#26.98#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.415#</mathjax> <mathjax>#mol#</mathjax> Al</p> <p><mathjax>#22.3#</mathjax> <mathjax>#g#</mathjax> Ni x(<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#58.69#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.380#</mathjax> <mathjax>#mol#</mathjax> Ni</p> <p><mathjax>#5.0#</mathjax> <mathjax>#g#</mathjax> Co x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax>/<mathjax>#58.93#</mathjax> <mathjax>#g#</mathjax>)=<mathjax>#0.0848#</mathjax> <mathjax>#mol#</mathjax> Co</p> <p><mathjax>#100#</mathjax> <mathjax>#g -11.2#</mathjax> <mathjax>#g#</mathjax> Al <mathjax># -22.3g#</mathjax> <mathjax>#Ni -5.0#</mathjax> <mathjax>#g#</mathjax> Co = <mathjax>#61.5#</mathjax> <mathjax>#g#</mathjax> Fe </p> <p><mathjax>#61.5#</mathjax> <mathjax>#g#</mathjax> Fe <mathjax>#xx((1 mol)/55.84)=1.10#</mathjax> <mathjax>#mol#</mathjax> Fe</p> <p>Divide each one by the smallest number of moles: cobalt at <mathjax>#0.0848#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Al = <mathjax>#0.415/0.0848 = 4.89#</mathjax> <mathjax>#mol #</mathjax><br/> Ni = <mathjax>#0.380/0.0848 = 4.48#</mathjax> <mathjax>#mol #</mathjax><br/> Co =<mathjax># 0.0848/0.0848 = 1.00#</mathjax> <mathjax>#mol #</mathjax><br/> Fe= <mathjax>#1.10/0.0848= 12.97#</mathjax> <mathjax>#mol #</mathjax></p> <p>Since Ni is <mathjax>#4.48 ~~4.50#</mathjax>, we multiply everything by <mathjax>#2#</mathjax> to get a whole number, <mathjax>#9#</mathjax>, for Ni. </p> <p>Al = <mathjax>#4.89#</mathjax> <mathjax>#mol xx 2= 10#</mathjax> <mathjax>#mol#</mathjax> Al<br/> Ni = <mathjax>#4.48#</mathjax> <mathjax>#mol xx 2= 9#</mathjax> <mathjax>#mol#</mathjax> Ni<br/> Co = <mathjax>#1.00#</mathjax> <mathjax>#mol xx 2= 2#</mathjax> <mathjax>#mol#</mathjax> Co<br/> Fe= <mathjax>#12.97#</mathjax> <mathjax>#mol xx 2= 26#</mathjax> <mathjax>#mol#</mathjax> Fe</p> <p>This gives us an empirical formula of <mathjax>#Al_10Co_2Fe_26Ni_9#</mathjax>.</p> <p>If we add up the Fe, Co, Ni, and Al in the empirical formula, we get <mathjax>#2366.7#</mathjax> <mathjax>#gmol^-1#</mathjax> of Alnico</p> <p><mathjax>#100#</mathjax> <mathjax>#g#</mathjax> Alnico x (<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> Alnico/<mathjax>#2366.7#</mathjax> <mathjax>#g#</mathjax> Alnico) x (<mathjax>#10#</mathjax> <mathjax>#mol#</mathjax> Al/<mathjax>#1#</mathjax> <mathjax>#mol#</mathjax> Alnico) = <mathjax>#0.423#</mathjax> <mathjax>#mol#</mathjax> Al </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232923" itemprop="url">Answer link</a> </div> </div> </div> </div> <div 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</li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1408 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	Alnico is a strongly magnetic alloy (solid mixture) of Co, Ni, Al and Fe. A 100.0 g sample of Alnico has 11.2g Al, 22.3g Ni, and 5.0g Co in it; the rest is Fe. How many moles of aluminum are there?	null
2,795	abfb50a2-6ddd-11ea-bb20-ccda262736ce	https://socratic.org/questions/what-is-the-molarity-of-the-solution-produced-when-350-0-ml-of-water-and-75-0-ml	2.88 × 10^(-2) M	start physical_unit 5 6 molarity mol/l qc_end physical_unit 12 12 9 10 volume qc_end physical_unit 6 6 14 15 volume qc_end physical_unit 19 19 17 18 molarity qc_end physical_unit 6 6 26 27 volume qc_end end	[{"type":"physical unit","value":"Molarity2 [OF] the solution [IN] M"}]	[{"type":"physical unit","value":"2.88 × 10^(-2) M"}]	[{"type":"physical unit","value":"Volume [OF] water [=] \\pu{350.0 mL}"},{"type":"physical unit","value":"Volume1 [OF] NaNO3 solution [=] \\pu{75.0 mL}"},{"type":"physical unit","value":"Molarity1 [OF] NaNO3 solution [=] \\pu{0.125 M}"},{"type":"physical unit","value":"Volume2 [OF] NaNO3 solution [=] \\pu{325.0 mL}"}]	<h1 class="questionTitle" itemprop="name">What is the molarity of the solution produced when #"350.0 mL"# of water and #"75.0 mL"# of #"0.125 M"# #"NaNO"_3# are mixed an boiled down to #"325.0 mL"# ?</h1>	null	2.88 × 10^(-2) M	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that the number of moles of sodium nitrate present in the solution <strong>does not change</strong>. </p> <p>When you dilute the solution by adding the <mathjax>#"350.0 mL"#</mathjax> of water, the volume of the solution <strong>increases</strong>, but the number of moles of sodium nitrate <strong>remains unchanged</strong>. </p> <p>Similarly, when you boil the solution, you <strong>decrease</strong> its volume to <mathjax>#"325.0 mL"#</mathjax>, but once again, the number of moles of sodium nitrate <strong>remains unchanged</strong>.</p> <p>Basically, by diluting and boiling the solution, you're changing its <em>volume</em> without affecting the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> it contains. </p> <p>So, you know that the initial solution contains</p> <blockquote> <p><mathjax>#75.0 color(red)(cancel(color(black)("mL solution"))) * "0.125 moles NaNO"_3/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.009375 moles NaNO"_3#</mathjax></p> </blockquote> <p>This means that the final solution will contain <mathjax>#0.009375#</mathjax> <strong>moles</strong> of sodium nitrate in a total volume of <mathjax>#"325.0 mL"#</mathjax>, which implies that the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution will be--<strong>do not</strong> forget to convert the volume of the solution to <strong>liters</strong>!</p> <blockquote> <p><mathjax>#["NaNO"_3] = "0.009375 moles"/(325.0 * 10^(-3) quad "L") = color(darkgreen)(ul(color(black)("0.0288 M")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.0288 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that the number of moles of sodium nitrate present in the solution <strong>does not change</strong>. </p> <p>When you dilute the solution by adding the <mathjax>#"350.0 mL"#</mathjax> of water, the volume of the solution <strong>increases</strong>, but the number of moles of sodium nitrate <strong>remains unchanged</strong>. </p> <p>Similarly, when you boil the solution, you <strong>decrease</strong> its volume to <mathjax>#"325.0 mL"#</mathjax>, but once again, the number of moles of sodium nitrate <strong>remains unchanged</strong>.</p> <p>Basically, by diluting and boiling the solution, you're changing its <em>volume</em> without affecting the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> it contains. </p> <p>So, you know that the initial solution contains</p> <blockquote> <p><mathjax>#75.0 color(red)(cancel(color(black)("mL solution"))) * "0.125 moles NaNO"_3/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.009375 moles NaNO"_3#</mathjax></p> </blockquote> <p>This means that the final solution will contain <mathjax>#0.009375#</mathjax> <strong>moles</strong> of sodium nitrate in a total volume of <mathjax>#"325.0 mL"#</mathjax>, which implies that the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution will be--<strong>do not</strong> forget to convert the volume of the solution to <strong>liters</strong>!</p> <blockquote> <p><mathjax>#["NaNO"_3] = "0.009375 moles"/(325.0 * 10^(-3) quad "L") = color(darkgreen)(ul(color(black)("0.0288 M")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the molarity of the solution produced when #"350.0 mL"# of water and #"75.0 mL"# of #"0.125 M"# #"NaNO"_3# are mixed an boiled down to #"325.0 mL"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="550753" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-12T23:55:03" itemprop="dateCreated"> Feb 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.0288 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that the number of moles of sodium nitrate present in the solution <strong>does not change</strong>. </p> <p>When you dilute the solution by adding the <mathjax>#"350.0 mL"#</mathjax> of water, the volume of the solution <strong>increases</strong>, but the number of moles of sodium nitrate <strong>remains unchanged</strong>. </p> <p>Similarly, when you boil the solution, you <strong>decrease</strong> its volume to <mathjax>#"325.0 mL"#</mathjax>, but once again, the number of moles of sodium nitrate <strong>remains unchanged</strong>.</p> <p>Basically, by diluting and boiling the solution, you're changing its <em>volume</em> without affecting the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> it contains. </p> <p>So, you know that the initial solution contains</p> <blockquote> <p><mathjax>#75.0 color(red)(cancel(color(black)("mL solution"))) * "0.125 moles NaNO"_3/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.009375 moles NaNO"_3#</mathjax></p> </blockquote> <p>This means that the final solution will contain <mathjax>#0.009375#</mathjax> <strong>moles</strong> of sodium nitrate in a total volume of <mathjax>#"325.0 mL"#</mathjax>, which implies that the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the solution will be--<strong>do not</strong> forget to convert the volume of the solution to <strong>liters</strong>!</p> <blockquote> <p><mathjax>#["NaNO"_3] = "0.009375 moles"/(325.0 * 10^(-3) quad "L") = color(darkgreen)(ul(color(black)("0.0288 M")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/550753" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate 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#"NaNO"_3# are mixed an boiled down to #"325.0 mL"# ?	null
2,796	ac55e5f0-6ddd-11ea-ab60-ccda262736ce	https://socratic.org/questions/calculate-the-molality-of-a-solution-made-by-dissolving-a-compound-in-camphor-if	0.42 molal	start physical_unit 18 19 molality mol/g qc_end physical_unit 18 19 21 23 freezing_point_temperature qc_end physical_unit 28 29 34 36 melting_point_temperature qc_end physical_unit 12 12 41 43 kf qc_end end	[{"type":"physical unit","value":"Molality [OF] the solution [IN] molal"}]	[{"type":"physical unit","value":"0.42 molal"}]	[{"type":"physical unit","value":"Freezing point [OF] the solution [=] \\pu{162.33 degrees C}"},{"type":"physical unit","value":"Melting point [OF] pure camphor [=] \\pu{178.43 degrees C}"},{"type":"physical unit","value":"Kf [OF] camphor [=] \\pu{37.7 degrees C/m}"}]	<h1 class="questionTitle" itemprop="name">Calculate the molality of a solution made by dissolving a compound in camphor if the freezing point of the solution is 162.33 degrees C: the melting point of pure camphor was measured to be 178.43 degrees C. K sub f for camphor is 37.7 degrees C/m sub c?</h1>	<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Please explain the equation used for this problem and how to get to the answer. The answer isn't needed to be provided.</p></div> </h2> </div> </div>	0.42 molal	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To make any sense of this question, let's first write down what we are given.</p> <p><strong>Given</strong><br/> - <mathjax>#color(green)("Pure camphor freezing point" = 178.43^@C)#</mathjax><br/> - <mathjax>#color(green)(K_(f) = 37.7^@C/m)#</mathjax><br/> - <mathjax>#color(green)("Solution's freezing point" = 162.33^@C)#</mathjax></p> <p><mathjax>#color(white)(aaaaaa)"Now, what is this problem really saying and asking?"#</mathjax></p> <p>Well first off, we should understand the concept being tested - <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/colligative-properties">colligative properties</a>.</strong> </p> <p><strong>Colligative properties</strong> describe the physical properties of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that depend only on the amount of solutes dissolved in solutions and not the type dissolved. Here, melting point/freezing point is being affected. When you add solutes to a pure solution, the freezing point of the solution decreases. </p> <p>Clearly, <strong>the pure camphor</strong> and <strong>the camphor with the added compound</strong> have different freezing points.</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaa)color(blue)"pure camphor" = 178.43^@C#</mathjax><br/> <mathjax>#color(white)(aaaaa)color(red)"camphor with compound" = 162.33^@C#</mathjax> </p> <p><mathjax>#color(white)(aaaaaaa)DeltaT = 178.43^@C-162.33^@C = 16.10^@C#</mathjax></p> <p><mathjax>#---------------------#</mathjax></p> <p>To find the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the compound we need the following formula</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaa)color(magenta)(DeltaT = iK_(f)m)#</mathjax></p> <p><strong>Where</strong></p> <ul> <li><mathjax>#DeltaT = "change in the temperature" (color(white)(a)^@C)#</mathjax></li> <li><mathjax>#i = "vant Hoff factor"#</mathjax></li> <li><mathjax>#K_f = "molal freezing point constant" ((color(white)(a)^@C)/(m))#</mathjax></li> <li><mathjax>#m = "molality" ("moles of solute"/"1 kg of solvent" or m)#</mathjax></li> </ul> <p><em>The vant Hoff factor of a nonelectrolyte <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is 1.</em></p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaa)#</mathjax></p> <p><strong>Plugin, rearrange and solve (ignored units for simplicity sake)</strong></p> <ul> <li> <p><mathjax>#color(magenta)(DeltaT = iK_(f)m)#</mathjax></p> </li> <li> <p><mathjax>#16.10 = (1)(37.7)(m)#</mathjax></p> </li> <li> <p><mathjax>#(16.10)/[(1)(37.7)] = m#</mathjax></p> </li> <li> <p><mathjax>#"molality" = 0.42" m, where m equals molal"#</mathjax></p> </li> </ul> <p><mathjax>#"Answer": "molality" = 0.42" m#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.42" molal"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To make any sense of this question, let's first write down what we are given.</p> <p><strong>Given</strong><br/> - <mathjax>#color(green)("Pure camphor freezing point" = 178.43^@C)#</mathjax><br/> - <mathjax>#color(green)(K_(f) = 37.7^@C/m)#</mathjax><br/> - <mathjax>#color(green)("Solution's freezing point" = 162.33^@C)#</mathjax></p> <p><mathjax>#color(white)(aaaaaa)"Now, what is this problem really saying and asking?"#</mathjax></p> <p>Well first off, we should understand the concept being tested - <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/colligative-properties">colligative properties</a>.</strong> </p> <p><strong>Colligative properties</strong> describe the physical properties of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that depend only on the amount of solutes dissolved in solutions and not the type dissolved. Here, melting point/freezing point is being affected. When you add solutes to a pure solution, the freezing point of the solution decreases. </p> <p>Clearly, <strong>the pure camphor</strong> and <strong>the camphor with the added compound</strong> have different freezing points.</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaa)color(blue)"pure camphor" = 178.43^@C#</mathjax><br/> <mathjax>#color(white)(aaaaa)color(red)"camphor with compound" = 162.33^@C#</mathjax> </p> <p><mathjax>#color(white)(aaaaaaa)DeltaT = 178.43^@C-162.33^@C = 16.10^@C#</mathjax></p> <p><mathjax>#---------------------#</mathjax></p> <p>To find the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the compound we need the following formula</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaa)color(magenta)(DeltaT = iK_(f)m)#</mathjax></p> <p><strong>Where</strong></p> <ul> <li><mathjax>#DeltaT = "change in the temperature" (color(white)(a)^@C)#</mathjax></li> <li><mathjax>#i = "vant Hoff factor"#</mathjax></li> <li><mathjax>#K_f = "molal freezing point constant" ((color(white)(a)^@C)/(m))#</mathjax></li> <li><mathjax>#m = "molality" ("moles of solute"/"1 kg of solvent" or m)#</mathjax></li> </ul> <p><em>The vant Hoff factor of a nonelectrolyte <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is 1.</em></p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaa)#</mathjax></p> <p><strong>Plugin, rearrange and solve (ignored units for simplicity sake)</strong></p> <ul> <li> <p><mathjax>#color(magenta)(DeltaT = iK_(f)m)#</mathjax></p> </li> <li> <p><mathjax>#16.10 = (1)(37.7)(m)#</mathjax></p> </li> <li> <p><mathjax>#(16.10)/[(1)(37.7)] = m#</mathjax></p> </li> <li> <p><mathjax>#"molality" = 0.42" m, where m equals molal"#</mathjax></p> </li> </ul> <p><mathjax>#"Answer": "molality" = 0.42" m#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">Calculate the molality of a solution made by dissolving a compound in camphor if the freezing point of the solution is 162.33 degrees C: the melting point of pure camphor was measured to be 178.43 degrees C. K sub f for camphor is 37.7 degrees C/m sub c?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Please explain the equation used for this problem and how to get to the answer. The answer isn't needed to be provided.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="416171" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/maxwell-1"><img alt="" class="" src="https://profilepictures.socratic.org/eVKXLKEcRRaVNXSCjdU0_Climbing.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/maxwell-1"> Maxwell </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-02T02:13:17" itemprop="dateCreated"> May 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.42" molal"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To make any sense of this question, let's first write down what we are given.</p> <p><strong>Given</strong><br/> - <mathjax>#color(green)("Pure camphor freezing point" = 178.43^@C)#</mathjax><br/> - <mathjax>#color(green)(K_(f) = 37.7^@C/m)#</mathjax><br/> - <mathjax>#color(green)("Solution's freezing point" = 162.33^@C)#</mathjax></p> <p><mathjax>#color(white)(aaaaaa)"Now, what is this problem really saying and asking?"#</mathjax></p> <p>Well first off, we should understand the concept being tested - <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/colligative-properties">colligative properties</a>.</strong> </p> <p><strong>Colligative properties</strong> describe the physical properties of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that depend only on the amount of solutes dissolved in solutions and not the type dissolved. Here, melting point/freezing point is being affected. When you add solutes to a pure solution, the freezing point of the solution decreases. </p> <p>Clearly, <strong>the pure camphor</strong> and <strong>the camphor with the added compound</strong> have different freezing points.</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaa)color(blue)"pure camphor" = 178.43^@C#</mathjax><br/> <mathjax>#color(white)(aaaaa)color(red)"camphor with compound" = 162.33^@C#</mathjax> </p> <p><mathjax>#color(white)(aaaaaaa)DeltaT = 178.43^@C-162.33^@C = 16.10^@C#</mathjax></p> <p><mathjax>#---------------------#</mathjax></p> <p>To find the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the compound we need the following formula</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaa)color(magenta)(DeltaT = iK_(f)m)#</mathjax></p> <p><strong>Where</strong></p> <ul> <li><mathjax>#DeltaT = "change in the temperature" (color(white)(a)^@C)#</mathjax></li> <li><mathjax>#i = "vant Hoff factor"#</mathjax></li> <li><mathjax>#K_f = "molal freezing point constant" ((color(white)(a)^@C)/(m))#</mathjax></li> <li><mathjax>#m = "molality" ("moles of solute"/"1 kg of solvent" or m)#</mathjax></li> </ul> <p><em>The vant Hoff factor of a nonelectrolyte <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is 1.</em></p> <p><mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaa)#</mathjax></p> <p><strong>Plugin, rearrange and solve (ignored units for simplicity sake)</strong></p> <ul> <li> <p><mathjax>#color(magenta)(DeltaT = iK_(f)m)#</mathjax></p> </li> <li> <p><mathjax>#16.10 = (1)(37.7)(m)#</mathjax></p> </li> <li> <p><mathjax>#(16.10)/[(1)(37.7)] = m#</mathjax></p> </li> <li> <p><mathjax>#"molality" = 0.42" m, where m equals molal"#</mathjax></p> </li> </ul> <p><mathjax>#"Answer": "molality" = 0.42" m#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/416171" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-colligative-properties-determined"> How are colligative properties determined? 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K sub f for camphor is 37.7 degrees C/m sub c?	Please explain the equation used for this problem and how to get to the answer. The answer isn't needed to be provided.
2,797	a9393452-6ddd-11ea-8081-ccda262736ce	https://socratic.org/questions/590f4145b72cff7430f2021f	KClO3	start chemical_formula qc_end end	[{"type":"other","value":"Chemical Formula [OF] the salt [IN] empirical"}]	[{"type":"chemical equation","value":"KClO3"}]	[{"type":"physical unit","value":"Percentage by mass [OF] potassium in the salt [=] \\pu{31.84%}"},{"type":"physical unit","value":"Percentage by mass [OF] chlorine in the salt [=] \\pu{28.98%}"},{"type":"physical unit","value":"Percentage by mass [OF] oxygen in the salt [=] \\pu{39.18%}"}]	<h1 class="questionTitle" itemprop="name">A salt contains #31.84%# potassium, #28.98%# chlorine, and #39.18%# oxygen by mass. What is its empirical formula?</h1>	null	KClO3	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As always with these problems, we assume an <mathjax>#100g#</mathjax> mass of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>, and then interrogate the molar quantities of the constituent atoms...</p> <p><mathjax>#"Moles of potassium"-=(31.84g)/(39.10gmol^-1)=0.814mol#</mathjax>.</p> <p><mathjax>#"Moles of chlorine"-=(28.98g)/(35.45gmol^-1)=0.817mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"-=(39.18g)/(16.00gmol^-1)=2.45mol#</mathjax>.</p> <p>We divide thru by the lowest molar quantity to give an empirical formula of <mathjax>#KClO_3#</mathjax> (or close enuff to!), i.e. <mathjax>#"potassium chlorate"#</mathjax>.</p> <p>And the molecular formula is always a multiple of the empirical formula.....<mathjax>#(39.1+35.45+3xx16)_ngmol^-1=122,5g*mol^-1#</mathjax>. Clearly, <mathjax>#n=1#</mathjax>, and the molecular formula is <mathjax>#KClO_3#</mathjax>, <mathjax>#"potassium chlorate"#</mathjax>.</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#KClO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As always with these problems, we assume an <mathjax>#100g#</mathjax> mass of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>, and then interrogate the molar quantities of the constituent atoms...</p> <p><mathjax>#"Moles of potassium"-=(31.84g)/(39.10gmol^-1)=0.814mol#</mathjax>.</p> <p><mathjax>#"Moles of chlorine"-=(28.98g)/(35.45gmol^-1)=0.817mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"-=(39.18g)/(16.00gmol^-1)=2.45mol#</mathjax>.</p> <p>We divide thru by the lowest molar quantity to give an empirical formula of <mathjax>#KClO_3#</mathjax> (or close enuff to!), i.e. <mathjax>#"potassium chlorate"#</mathjax>.</p> <p>And the molecular formula is always a multiple of the empirical formula.....<mathjax>#(39.1+35.45+3xx16)_ngmol^-1=122,5g*mol^-1#</mathjax>. Clearly, <mathjax>#n=1#</mathjax>, and the molecular formula is <mathjax>#KClO_3#</mathjax>, <mathjax>#"potassium chlorate"#</mathjax>.</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">A salt contains #31.84%# potassium, #28.98%# chlorine, and #39.18%# oxygen by mass. What is its empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="475999" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-16T03:22:15" itemprop="dateCreated"> Sep 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#KClO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As always with these problems, we assume an <mathjax>#100g#</mathjax> mass of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>, and then interrogate the molar quantities of the constituent atoms...</p> <p><mathjax>#"Moles of potassium"-=(31.84g)/(39.10gmol^-1)=0.814mol#</mathjax>.</p> <p><mathjax>#"Moles of chlorine"-=(28.98g)/(35.45gmol^-1)=0.817mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"-=(39.18g)/(16.00gmol^-1)=2.45mol#</mathjax>.</p> <p>We divide thru by the lowest molar quantity to give an empirical formula of <mathjax>#KClO_3#</mathjax> (or close enuff to!), i.e. <mathjax>#"potassium chlorate"#</mathjax>.</p> <p>And the molecular formula is always a multiple of the empirical formula.....<mathjax>#(39.1+35.45+3xx16)_ngmol^-1=122,5g*mol^-1#</mathjax>. Clearly, <mathjax>#n=1#</mathjax>, and the molecular formula is <mathjax>#KClO_3#</mathjax>, <mathjax>#"potassium chlorate"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/475999" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9796 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>	A salt contains #31.84%# potassium, #28.98%# chlorine, and #39.18%# oxygen by mass. What is its empirical formula?	null
2,798	ab5231b6-6ddd-11ea-a222-ccda262736ce	https://socratic.org/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-hno3-aq-1	8 HNO3(aq) + 3 C2H6O(l) + K2Cr2O7(aq) -> 2 KNO3(aq) + 3 C2H4O(l) + 7 H2O(l) + 2 Cr(NO3)3(aq)	start chemical_equation qc_end chemical_equation 12 24 qc_end c_other OTHER qc_end end	[{"type":"other","value":"Chemical Equation [OF] this redox reaction"}]	[{"type":"chemical equation","value":"8 HNO3(aq) + 3 C2H6O(l) + K2Cr2O7(aq) -> 2 KNO3(aq) + 3 C2H4O(l) + 7 H2O(l) + 2 Cr(NO3)3(aq)"}]	[{"type":"chemical equation","value":"HNO3(aq) + C2H6O(l) + K2Cr2O7(aq) -> KNO3(aq) + C2H4O(l) + H2O(l) + Cr(NO3)3(aq)"},{"type":"other","value":"Use the oxidation number method."}]	<h1 class="questionTitle" itemprop="name">How do you balance this redox reaction using the oxidation number method? HNO3(aq) + C2H6O(l) + K2Cr2O7(aq) → KNO3(aq) + C2H4O(l) + H2O(l) + Cr(NO3)3(aq)</h1>	null	8 HNO3(aq) + 3 C2H6O(l) + K2Cr2O7(aq) -> 2 KNO3(aq) + 3 C2H4O(l) + 7 H2O(l) + 2 Cr(NO3)3(aq)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You can find the steps for balancing redox equations <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">here</a>.</p> <blockquote></blockquote> <p>Your unbalanced equation is</p> <p><mathjax>#"HNO"_3 + "C"_2"H"_6"O" + "K"_2"Cr"_2"O"_7 → "KNO"_3 + "C"_2"H"_4"O"+ "H"_2"O" + "Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 1.</strong> Calculate the <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of every atom.</p> <p>Left hand side: <mathjax>#"H= +1; N= +5; O = -2; C = -2; K = +1; Cr = +6"#</mathjax><br/> Right hand side: <mathjax>#"K = +1; N = +5; O = -2; C = -1; H = +1; Cr = +3"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2.</strong> Calculate the changes in oxidation number:</p> <p><mathjax>#"C: -2 → -1; Change = +1"#</mathjax><br/> <mathjax>#"Cr: +6 → +3; Change = -3"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3.</strong> Balance changes in oxidation number.</p> <p>You need 3 atoms of <mathjax>#"C"#</mathjax> for every 1 atom of <mathjax>#"Cr"#</mathjax>.</p> <p>You have 2 atoms of <mathjax>#"Cr"#</mathjax>, so you need 6 atoms of <mathjax>#"C"#</mathjax>.</p> <p>This gives you total changes of +6 and -6.</p> <blockquote></blockquote> <p><strong>Step 4.</strong> Insert coefficients to get these numbers.</p> <p><mathjax>#"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → "KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5a.</strong> Balance <mathjax>#"K"#</mathjax>.</p> <p><mathjax>#"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5b.</strong> Balance <mathjax>#"N"#</mathjax>.</p> <p><mathjax>#color(green)(8)"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6.</strong> Balance <mathjax>#"O"#</mathjax>.</p> <p><mathjax>#color(green)(8)"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ color(orange)(7)"H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7.</strong> Balance <mathjax>#"H"#</mathjax>.</p> <p>Done.</p> <blockquote></blockquote> <p><strong>Step 8.</strong> Check that all atoms balance.</p> <p><mathjax>#"Atom"color(white)(m)"Left hand side"color(white)(m)"Right hand side"#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mmmmm)26color(white)(mmmmmmm)26#</mathjax><br/> <mathjax>#color(white)(m)"N"color(white)(mmmmmll)8color(white)(mmmmmmml)8#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mmmmm)34color(white)(mmmmmmm)34#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mmmmmll)6color(white)(mmmmmmml)6#</mathjax><br/> <mathjax>#color(white)(m)"Cr"color(white)(mmmmml)2color(white)(mmmmmmml)2#</mathjax></p> <blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#8"HNO"_3 + 3"C"_2"H"_6"O" + "K"_2"Cr"_2"O"_7 → 2"KNO"_3 + 3"C"_2"H"_4"O"+ 7"H"_2"O" + 2"Cr"("NO"_3)_3#</mathjax></p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8"HNO"_3 + 3"C"_2"H"_6"O" + "K"_2"Cr"_2"O"_7 → 2"KNO"_3 + 3"C"_2"H"_4"O"+ 7"H"_2"O" + 2"Cr"("NO"_3)_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You can find the steps for balancing redox equations <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">here</a>.</p> <blockquote></blockquote> <p>Your unbalanced equation is</p> <p><mathjax>#"HNO"_3 + "C"_2"H"_6"O" + "K"_2"Cr"_2"O"_7 → "KNO"_3 + "C"_2"H"_4"O"+ "H"_2"O" + "Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 1.</strong> Calculate the <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of every atom.</p> <p>Left hand side: <mathjax>#"H= +1; N= +5; O = -2; C = -2; K = +1; Cr = +6"#</mathjax><br/> Right hand side: <mathjax>#"K = +1; N = +5; O = -2; C = -1; H = +1; Cr = +3"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2.</strong> Calculate the changes in oxidation number:</p> <p><mathjax>#"C: -2 → -1; Change = +1"#</mathjax><br/> <mathjax>#"Cr: +6 → +3; Change = -3"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3.</strong> Balance changes in oxidation number.</p> <p>You need 3 atoms of <mathjax>#"C"#</mathjax> for every 1 atom of <mathjax>#"Cr"#</mathjax>.</p> <p>You have 2 atoms of <mathjax>#"Cr"#</mathjax>, so you need 6 atoms of <mathjax>#"C"#</mathjax>.</p> <p>This gives you total changes of +6 and -6.</p> <blockquote></blockquote> <p><strong>Step 4.</strong> Insert coefficients to get these numbers.</p> <p><mathjax>#"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → "KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5a.</strong> Balance <mathjax>#"K"#</mathjax>.</p> <p><mathjax>#"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5b.</strong> Balance <mathjax>#"N"#</mathjax>.</p> <p><mathjax>#color(green)(8)"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6.</strong> Balance <mathjax>#"O"#</mathjax>.</p> <p><mathjax>#color(green)(8)"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ color(orange)(7)"H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7.</strong> Balance <mathjax>#"H"#</mathjax>.</p> <p>Done.</p> <blockquote></blockquote> <p><strong>Step 8.</strong> Check that all atoms balance.</p> <p><mathjax>#"Atom"color(white)(m)"Left hand side"color(white)(m)"Right hand side"#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mmmmm)26color(white)(mmmmmmm)26#</mathjax><br/> <mathjax>#color(white)(m)"N"color(white)(mmmmmll)8color(white)(mmmmmmml)8#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mmmmm)34color(white)(mmmmmmm)34#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mmmmmll)6color(white)(mmmmmmml)6#</mathjax><br/> <mathjax>#color(white)(m)"Cr"color(white)(mmmmml)2color(white)(mmmmmmml)2#</mathjax></p> <blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#8"HNO"_3 + 3"C"_2"H"_6"O" + "K"_2"Cr"_2"O"_7 → 2"KNO"_3 + 3"C"_2"H"_4"O"+ 7"H"_2"O" + 2"Cr"("NO"_3)_3#</mathjax></p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">How do you balance this redox reaction using the oxidation number method? HNO3(aq) + C2H6O(l) + K2Cr2O7(aq) → KNO3(aq) + C2H4O(l) + H2O(l) + Cr(NO3)3(aq)</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="106882" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-07-17T21:17:23" itemprop="dateCreated"> Jul 17, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8"HNO"_3 + 3"C"_2"H"_6"O" + "K"_2"Cr"_2"O"_7 → 2"KNO"_3 + 3"C"_2"H"_4"O"+ 7"H"_2"O" + 2"Cr"("NO"_3)_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You can find the steps for balancing redox equations <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">here</a>.</p> <blockquote></blockquote> <p>Your unbalanced equation is</p> <p><mathjax>#"HNO"_3 + "C"_2"H"_6"O" + "K"_2"Cr"_2"O"_7 → "KNO"_3 + "C"_2"H"_4"O"+ "H"_2"O" + "Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 1.</strong> Calculate the <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of every atom.</p> <p>Left hand side: <mathjax>#"H= +1; N= +5; O = -2; C = -2; K = +1; Cr = +6"#</mathjax><br/> Right hand side: <mathjax>#"K = +1; N = +5; O = -2; C = -1; H = +1; Cr = +3"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2.</strong> Calculate the changes in oxidation number:</p> <p><mathjax>#"C: -2 → -1; Change = +1"#</mathjax><br/> <mathjax>#"Cr: +6 → +3; Change = -3"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3.</strong> Balance changes in oxidation number.</p> <p>You need 3 atoms of <mathjax>#"C"#</mathjax> for every 1 atom of <mathjax>#"Cr"#</mathjax>.</p> <p>You have 2 atoms of <mathjax>#"Cr"#</mathjax>, so you need 6 atoms of <mathjax>#"C"#</mathjax>.</p> <p>This gives you total changes of +6 and -6.</p> <blockquote></blockquote> <p><strong>Step 4.</strong> Insert coefficients to get these numbers.</p> <p><mathjax>#"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → "KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5a.</strong> Balance <mathjax>#"K"#</mathjax>.</p> <p><mathjax>#"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5b.</strong> Balance <mathjax>#"N"#</mathjax>.</p> <p><mathjax>#color(green)(8)"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ "H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6.</strong> Balance <mathjax>#"O"#</mathjax>.</p> <p><mathjax>#color(green)(8)"HNO"_3 + color(red)(3)"C"_2"H"_6"O" + color(blue)(1)"K"_2"Cr"_2"O"_7 → color(brown)(2)"KNO"_3 + color(red)(3)"C"_2"H"_4"O"+ color(orange)(7)"H"_2"O" + color(blue)(2)"Cr"("NO"_3)_3#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7.</strong> Balance <mathjax>#"H"#</mathjax>.</p> <p>Done.</p> <blockquote></blockquote> <p><strong>Step 8.</strong> Check that all atoms balance.</p> <p><mathjax>#"Atom"color(white)(m)"Left hand side"color(white)(m)"Right hand side"#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mmmmm)26color(white)(mmmmmmm)26#</mathjax><br/> <mathjax>#color(white)(m)"N"color(white)(mmmmmll)8color(white)(mmmmmmml)8#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mmmmm)34color(white)(mmmmmmm)34#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mmmmmll)6color(white)(mmmmmmml)6#</mathjax><br/> <mathjax>#color(white)(m)"Cr"color(white)(mmmmml)2color(white)(mmmmmmml)2#</mathjax></p> <blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#8"HNO"_3 + 3"C"_2"H"_6"O" + "K"_2"Cr"_2"O"_7 → 2"KNO"_3 + 3"C"_2"H"_4"O"+ 7"H"_2"O" + 2"Cr"("NO"_3)_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/106882" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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2,799	ab729ce5-6ddd-11ea-a658-ccda262736ce	https://socratic.org/questions/what-is-the-chemical-equation-for-this-reaction-solid-phosphorous-oxygen-gas-and	P4(s) + 5 O2(g) -> P4O10(s)	start chemical_equation qc_end substance 8 9 qc_end substance 10 11 qc_end substance 15 17 qc_end end	[{"type":"other","value":"Chemical Equation [OF] this reaction"}]	[{"type":"chemical equation","value":"P4(s) + 5 O2(g) -> P4O10(s)"}]	[{"type":"substance name","value":"Solid phosphorous"},{"type":"substance name","value":"Oxygen gas"},{"type":"substance name","value":"Solid diphosphorous pentoxide"}]	<h1 class="questionTitle" itemprop="name">What is the chemical equation for this reaction: Solid phosphorous, oxygen gas, and heat yield solid diphosphorous pentoxide?</h1>	null	P4(s) + 5 O2(g) -> P4O10(s)	<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Diphosphorus pentoxide"#</mathjax>, <mathjax>#P_2O_5#</mathjax>, consists of <mathjax>#P_4O_10#</mathjax> molecules........</p></div> </div> </div>	<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_4(s)+5O_2(g) rarr P_4O_10(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Diphosphorus pentoxide"#</mathjax>, <mathjax>#P_2O_5#</mathjax>, consists of <mathjax>#P_4O_10#</mathjax> molecules........</p></div> </div> </div> </div>	<article> <h1 class="questionTitle" itemprop="name">What is the chemical equation for this reaction: Solid phosphorous, oxygen gas, and heat yield solid diphosphorous pentoxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="358095" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-30T06:10:03" itemprop="dateCreated"> Dec 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_4(s)+5O_2(g) rarr P_4O_10(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Diphosphorus pentoxide"#</mathjax>, <mathjax>#P_2O_5#</mathjax>, consists of <mathjax>#P_4O_10#</mathjax> molecules........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/358095" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? 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