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What are the names of the tourist attractions that have parking or shopping as their feature details?
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CREATE TABLE Tourist_Attraction_Features (tourist_attraction_id VARCHAR, Feature_ID VARCHAR); CREATE TABLE Features (Feature_ID VARCHAR, feature_Details VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, tourist_attraction_id VARCHAR)
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SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN Tourist_Attraction_Features AS T2 ON T1.tourist_attraction_id = T2.tourist_attraction_id JOIN Features AS T3 ON T2.Feature_ID = T3.Feature_ID WHERE T3.feature_Details = 'park' UNION SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN Tourist_Attraction_Features AS T2 ON T1.tourist_attraction_id = T2.tourist_attraction_id JOIN Features AS T3 ON T2.Feature_ID = T3.Feature_ID WHERE T3.feature_Details = 'shopping'
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### Context: CREATE TABLE Tourist_Attraction_Features (tourist_attraction_id VARCHAR, Feature_ID VARCHAR); CREATE TABLE Features (Feature_ID VARCHAR, feature_Details VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, tourist_attraction_id VARCHAR) ### Question: What are the names of the tourist attractions that have parking or shopping as their feature details? ### Answer: SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN Tourist_Attraction_Features AS T2 ON T1.tourist_attraction_id = T2.tourist_attraction_id JOIN Features AS T3 ON T2.Feature_ID = T3.Feature_ID WHERE T3.feature_Details = 'park' UNION SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN Tourist_Attraction_Features AS T2 ON T1.tourist_attraction_id = T2.tourist_attraction_id JOIN Features AS T3 ON T2.Feature_ID = T3.Feature_ID WHERE T3.feature_Details = 'shopping'
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What are the names of tourist attractions that can be reached by bus or is at address 254 Ottilie Junction?
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CREATE TABLE Tourist_Attractions (Name VARCHAR, Location_ID VARCHAR, How_to_Get_There VARCHAR); CREATE TABLE Locations (Location_ID VARCHAR, Address VARCHAR)
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SELECT T2.Name FROM Locations AS T1 JOIN Tourist_Attractions AS T2 ON T1.Location_ID = T2.Location_ID WHERE T1.Address = "254 Ottilie Junction" OR T2.How_to_Get_There = "bus"
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### Context: CREATE TABLE Tourist_Attractions (Name VARCHAR, Location_ID VARCHAR, How_to_Get_There VARCHAR); CREATE TABLE Locations (Location_ID VARCHAR, Address VARCHAR) ### Question: What are the names of tourist attractions that can be reached by bus or is at address 254 Ottilie Junction? ### Answer: SELECT T2.Name FROM Locations AS T1 JOIN Tourist_Attractions AS T2 ON T1.Location_ID = T2.Location_ID WHERE T1.Address = "254 Ottilie Junction" OR T2.How_to_Get_There = "bus"
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What are the names of the tourist attractions Vincent and Marcelle visit?
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CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR, Tourist_ID VARCHAR); CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR)
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SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Vincent" INTERSECT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Marcelle"
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### Context: CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR, Tourist_ID VARCHAR); CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR) ### Question: What are the names of the tourist attractions Vincent and Marcelle visit? ### Answer: SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Vincent" INTERSECT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Marcelle"
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What are the names of tourist attraction that Alison visited but Rosalind did not visit?
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CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR, Tourist_ID VARCHAR); CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR)
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SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Alison" EXCEPT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Rosalind"
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### Context: CREATE TABLE VISITS (Tourist_Attraction_ID VARCHAR, Tourist_ID VARCHAR); CREATE TABLE VISITORS (Tourist_Details VARCHAR, Tourist_ID VARCHAR); CREATE TABLE Tourist_Attractions (Name VARCHAR, Tourist_Attraction_ID VARCHAR) ### Question: What are the names of tourist attraction that Alison visited but Rosalind did not visit? ### Answer: SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Alison" EXCEPT SELECT T1.Name FROM Tourist_Attractions AS T1 JOIN VISITORS AS T2 JOIN VISITS AS T3 ON T1.Tourist_Attraction_ID = T3.Tourist_Attraction_ID AND T2.Tourist_ID = T3.Tourist_ID WHERE T2.Tourist_Details = "Rosalind"
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How many tourists did not make any visit?
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CREATE TABLE Visitors (Tourist_ID VARCHAR); CREATE TABLE Visits (Tourist_ID VARCHAR)
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SELECT COUNT(*) FROM Visitors WHERE NOT Tourist_ID IN (SELECT Tourist_ID FROM Visits)
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### Context: CREATE TABLE Visitors (Tourist_ID VARCHAR); CREATE TABLE Visits (Tourist_ID VARCHAR) ### Question: How many tourists did not make any visit? ### Answer: SELECT COUNT(*) FROM Visitors WHERE NOT Tourist_ID IN (SELECT Tourist_ID FROM Visits)
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How many video games exist?
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CREATE TABLE Video_games (Id VARCHAR)
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SELECT COUNT(*) FROM Video_games
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### Context: CREATE TABLE Video_games (Id VARCHAR) ### Question: How many video games exist? ### Answer: SELECT COUNT(*) FROM Video_games
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How many video game types exist?
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CREATE TABLE Video_games (gtype VARCHAR)
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SELECT COUNT(DISTINCT gtype) FROM Video_games
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### Context: CREATE TABLE Video_games (gtype VARCHAR) ### Question: How many video game types exist? ### Answer: SELECT COUNT(DISTINCT gtype) FROM Video_games
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Show all video game types.
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CREATE TABLE Video_games (gtype VARCHAR)
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SELECT DISTINCT gtype FROM Video_games
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### Context: CREATE TABLE Video_games (gtype VARCHAR) ### Question: Show all video game types. ### Answer: SELECT DISTINCT gtype FROM Video_games
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Show all video games and their types in the order of their names.
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CREATE TABLE Video_games (gname VARCHAR, gtype VARCHAR)
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SELECT gname, gtype FROM Video_games ORDER BY gname
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### Context: CREATE TABLE Video_games (gname VARCHAR, gtype VARCHAR) ### Question: Show all video games and their types in the order of their names. ### Answer: SELECT gname, gtype FROM Video_games ORDER BY gname
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Show all video games with type Collectible card game.
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CREATE TABLE Video_games (gname VARCHAR, gtype VARCHAR)
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SELECT gname FROM Video_games WHERE gtype = "Collectible card game"
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### Context: CREATE TABLE Video_games (gname VARCHAR, gtype VARCHAR) ### Question: Show all video games with type Collectible card game. ### Answer: SELECT gname FROM Video_games WHERE gtype = "Collectible card game"
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What is the type of video game Call of Destiny.
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CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR)
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SELECT gtype FROM Video_games WHERE gname = "Call of Destiny"
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### Context: CREATE TABLE Video_games (gtype VARCHAR, gname VARCHAR) ### Question: What is the type of video game Call of Destiny. ### Answer: SELECT gtype FROM Video_games WHERE gname = "Call of Destiny"
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How many video games have type Massively multiplayer online game?
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CREATE TABLE Video_games (gtype VARCHAR)
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SELECT COUNT(*) FROM Video_games WHERE gtype = "Massively multiplayer online game"
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### Context: CREATE TABLE Video_games (gtype VARCHAR) ### Question: How many video games have type Massively multiplayer online game? ### Answer: SELECT COUNT(*) FROM Video_games WHERE gtype = "Massively multiplayer online game"
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Show all video game types and the number of video games in each type.
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CREATE TABLE Video_games (gtype VARCHAR)
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SELECT gtype, COUNT(*) FROM Video_games GROUP BY gtype
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### Context: CREATE TABLE Video_games (gtype VARCHAR) ### Question: Show all video game types and the number of video games in each type. ### Answer: SELECT gtype, COUNT(*) FROM Video_games GROUP BY gtype
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Which game type has most number of games?
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CREATE TABLE Video_games (gtype VARCHAR)
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SELECT gtype FROM Video_games GROUP BY gtype ORDER BY COUNT(*) DESC LIMIT 1
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### Context: CREATE TABLE Video_games (gtype VARCHAR) ### Question: Which game type has most number of games? ### Answer: SELECT gtype FROM Video_games GROUP BY gtype ORDER BY COUNT(*) DESC LIMIT 1
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Which game type has least number of games?
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CREATE TABLE Video_games (gtype VARCHAR)
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SELECT gtype FROM Video_games GROUP BY gtype ORDER BY COUNT(*) LIMIT 1
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### Context: CREATE TABLE Video_games (gtype VARCHAR) ### Question: Which game type has least number of games? ### Answer: SELECT gtype FROM Video_games GROUP BY gtype ORDER BY COUNT(*) LIMIT 1
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Show ids for all students who live in CHI.
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CREATE TABLE Student (StuID VARCHAR, city_code VARCHAR)
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SELECT StuID FROM Student WHERE city_code = "CHI"
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### Context: CREATE TABLE Student (StuID VARCHAR, city_code VARCHAR) ### Question: Show ids for all students who live in CHI. ### Answer: SELECT StuID FROM Student WHERE city_code = "CHI"
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Show ids for all students who have advisor 1121.
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CREATE TABLE Student (StuID VARCHAR, Advisor VARCHAR)
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SELECT StuID FROM Student WHERE Advisor = 1121
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### Context: CREATE TABLE Student (StuID VARCHAR, Advisor VARCHAR) ### Question: Show ids for all students who have advisor 1121. ### Answer: SELECT StuID FROM Student WHERE Advisor = 1121
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Show first name for all students with major 600.
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CREATE TABLE Student (Fname VARCHAR, Major VARCHAR)
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SELECT Fname FROM Student WHERE Major = 600
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### Context: CREATE TABLE Student (Fname VARCHAR, Major VARCHAR) ### Question: Show first name for all students with major 600. ### Answer: SELECT Fname FROM Student WHERE Major = 600
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Show the average, minimum, and maximum age for different majors.
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CREATE TABLE Student (major VARCHAR, age INTEGER)
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SELECT major, AVG(age), MIN(age), MAX(age) FROM Student GROUP BY major
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### Context: CREATE TABLE Student (major VARCHAR, age INTEGER) ### Question: Show the average, minimum, and maximum age for different majors. ### Answer: SELECT major, AVG(age), MIN(age), MAX(age) FROM Student GROUP BY major
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Show all advisors who have at least two students.
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CREATE TABLE Student (advisor VARCHAR)
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SELECT advisor FROM Student GROUP BY advisor HAVING COUNT(*) >= 2
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### Context: CREATE TABLE Student (advisor VARCHAR) ### Question: Show all advisors who have at least two students. ### Answer: SELECT advisor FROM Student GROUP BY advisor HAVING COUNT(*) >= 2
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How many sports do we have?
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CREATE TABLE Sportsinfo (sportname VARCHAR)
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SELECT COUNT(DISTINCT sportname) FROM Sportsinfo
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### Context: CREATE TABLE Sportsinfo (sportname VARCHAR) ### Question: How many sports do we have? ### Answer: SELECT COUNT(DISTINCT sportname) FROM Sportsinfo
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How many students play sports?
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CREATE TABLE Sportsinfo (StuID VARCHAR)
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SELECT COUNT(DISTINCT StuID) FROM Sportsinfo
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### Context: CREATE TABLE Sportsinfo (StuID VARCHAR) ### Question: How many students play sports? ### Answer: SELECT COUNT(DISTINCT StuID) FROM Sportsinfo
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List ids for all student who are on scholarship.
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CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR)
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SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
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### Context: CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR) ### Question: List ids for all student who are on scholarship. ### Answer: SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
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Show last names for all student who are on scholarship.
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CREATE TABLE Student (Lname VARCHAR, StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR)
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SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = 'Y'
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### Context: CREATE TABLE Student (Lname VARCHAR, StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR, onscholarship VARCHAR) ### Question: Show last names for all student who are on scholarship. ### Answer: SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = 'Y'
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How many games are played for all students?
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CREATE TABLE Sportsinfo (gamesplayed INTEGER)
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SELECT SUM(gamesplayed) FROM Sportsinfo
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### Context: CREATE TABLE Sportsinfo (gamesplayed INTEGER) ### Question: How many games are played for all students? ### Answer: SELECT SUM(gamesplayed) FROM Sportsinfo
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How many games are played for all football games by students on scholarship?
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CREATE TABLE Sportsinfo (gamesplayed INTEGER, sportname VARCHAR, onscholarship VARCHAR)
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SELECT SUM(gamesplayed) FROM Sportsinfo WHERE sportname = "Football" AND onscholarship = 'Y'
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### Context: CREATE TABLE Sportsinfo (gamesplayed INTEGER, sportname VARCHAR, onscholarship VARCHAR) ### Question: How many games are played for all football games by students on scholarship? ### Answer: SELECT SUM(gamesplayed) FROM Sportsinfo WHERE sportname = "Football" AND onscholarship = 'Y'
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Show all sport name and the number of students.
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CREATE TABLE Sportsinfo (sportname VARCHAR)
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SELECT sportname, COUNT(*) FROM Sportsinfo GROUP BY sportname
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### Context: CREATE TABLE Sportsinfo (sportname VARCHAR) ### Question: Show all sport name and the number of students. ### Answer: SELECT sportname, COUNT(*) FROM Sportsinfo GROUP BY sportname
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Show all student IDs with the number of sports and total number of games played
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CREATE TABLE Sportsinfo (StuID VARCHAR, gamesplayed INTEGER)
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SELECT StuID, COUNT(*), SUM(gamesplayed) FROM Sportsinfo GROUP BY StuID
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### Context: CREATE TABLE Sportsinfo (StuID VARCHAR, gamesplayed INTEGER) ### Question: Show all student IDs with the number of sports and total number of games played ### Answer: SELECT StuID, COUNT(*), SUM(gamesplayed) FROM Sportsinfo GROUP BY StuID
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Show all student IDs with more than total 10 hours per week on all sports played.
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CREATE TABLE Sportsinfo (StuID VARCHAR, hoursperweek INTEGER)
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SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING SUM(hoursperweek) > 10
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### Context: CREATE TABLE Sportsinfo (StuID VARCHAR, hoursperweek INTEGER) ### Question: Show all student IDs with more than total 10 hours per week on all sports played. ### Answer: SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING SUM(hoursperweek) > 10
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What is the first name and last name of the student who have most number of sports?
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CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR)
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SELECT T2.Fname, T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY COUNT(*) DESC LIMIT 1
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### Context: CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR) ### Question: What is the first name and last name of the student who have most number of sports? ### Answer: SELECT T2.Fname, T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY COUNT(*) DESC LIMIT 1
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Which sport has most number of students on scholarship?
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CREATE TABLE Sportsinfo (sportname VARCHAR, onscholarship VARCHAR)
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SELECT sportname FROM Sportsinfo WHERE onscholarship = 'Y' GROUP BY sportname ORDER BY COUNT(*) DESC LIMIT 1
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### Context: CREATE TABLE Sportsinfo (sportname VARCHAR, onscholarship VARCHAR) ### Question: Which sport has most number of students on scholarship? ### Answer: SELECT sportname FROM Sportsinfo WHERE onscholarship = 'Y' GROUP BY sportname ORDER BY COUNT(*) DESC LIMIT 1
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Show student ids who don't have any sports.
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CREATE TABLE Sportsinfo (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR)
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SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo
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### Context: CREATE TABLE Sportsinfo (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR) ### Question: Show student ids who don't have any sports. ### Answer: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo
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Show student ids who are on scholarship and have major 600.
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CREATE TABLE Sportsinfo (StuID VARCHAR, major VARCHAR, onscholarship VARCHAR); CREATE TABLE Student (StuID VARCHAR, major VARCHAR, onscholarship VARCHAR)
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SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
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### Context: CREATE TABLE Sportsinfo (StuID VARCHAR, major VARCHAR, onscholarship VARCHAR); CREATE TABLE Student (StuID VARCHAR, major VARCHAR, onscholarship VARCHAR) ### Question: Show student ids who are on scholarship and have major 600. ### Answer: SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y'
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Show student ids who are female and play football.
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CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR); CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR)
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SELECT StuID FROM Student WHERE sex = 'F' INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname = "Football"
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### Context: CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR); CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR) ### Question: Show student ids who are female and play football. ### Answer: SELECT StuID FROM Student WHERE sex = 'F' INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname = "Football"
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Show all male student ids who don't play football.
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CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR); CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR)
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SELECT StuID FROM Student WHERE sex = 'M' EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname = "Football"
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### Context: CREATE TABLE Sportsinfo (StuID VARCHAR, sex VARCHAR, sportname VARCHAR); CREATE TABLE Student (StuID VARCHAR, sex VARCHAR, sportname VARCHAR) ### Question: Show all male student ids who don't play football. ### Answer: SELECT StuID FROM Student WHERE sex = 'M' EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname = "Football"
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Show total hours per week and number of games played for student David Shieber.
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CREATE TABLE Student (StuID VARCHAR, Fname VARCHAR, Lname VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR)
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SELECT SUM(hoursperweek), SUM(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.Fname = "David" AND T2.Lname = "Shieber"
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### Context: CREATE TABLE Student (StuID VARCHAR, Fname VARCHAR, Lname VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR) ### Question: Show total hours per week and number of games played for student David Shieber. ### Answer: SELECT SUM(hoursperweek), SUM(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.Fname = "David" AND T2.Lname = "Shieber"
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Show total hours per week and number of games played for students under 20.
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CREATE TABLE Student (StuID VARCHAR, age INTEGER); CREATE TABLE Sportsinfo (StuID VARCHAR)
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SELECT SUM(hoursperweek), SUM(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.age < 20
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### Context: CREATE TABLE Student (StuID VARCHAR, age INTEGER); CREATE TABLE Sportsinfo (StuID VARCHAR) ### Question: Show total hours per week and number of games played for students under 20. ### Answer: SELECT SUM(hoursperweek), SUM(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.age < 20
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How many students play video games?
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CREATE TABLE Plays_games (StuID VARCHAR)
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SELECT COUNT(DISTINCT StuID) FROM Plays_games
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### Context: CREATE TABLE Plays_games (StuID VARCHAR) ### Question: How many students play video games? ### Answer: SELECT COUNT(DISTINCT StuID) FROM Plays_games
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Show ids of students who don't play video game.
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CREATE TABLE Plays_games (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR)
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SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games
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### Context: CREATE TABLE Plays_games (StuID VARCHAR); CREATE TABLE Student (StuID VARCHAR) ### Question: Show ids of students who don't play video game. ### Answer: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games
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Show ids of students who play video game and play sports.
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CREATE TABLE Plays_games (StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR)
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SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games
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### Context: CREATE TABLE Plays_games (StuID VARCHAR); CREATE TABLE Sportsinfo (StuID VARCHAR) ### Question: Show ids of students who play video game and play sports. ### Answer: SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games
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Show all game ids and the number of hours played.
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CREATE TABLE Plays_games (gameid VARCHAR, hours_played INTEGER)
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SELECT gameid, SUM(hours_played) FROM Plays_games GROUP BY gameid
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### Context: CREATE TABLE Plays_games (gameid VARCHAR, hours_played INTEGER) ### Question: Show all game ids and the number of hours played. ### Answer: SELECT gameid, SUM(hours_played) FROM Plays_games GROUP BY gameid
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Show all student ids and the number of hours played.
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CREATE TABLE Plays_games (Stuid VARCHAR, hours_played INTEGER)
|
SELECT Stuid, SUM(hours_played) FROM Plays_games GROUP BY Stuid
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### Context: CREATE TABLE Plays_games (Stuid VARCHAR, hours_played INTEGER) ### Question: Show all student ids and the number of hours played. ### Answer: SELECT Stuid, SUM(hours_played) FROM Plays_games GROUP BY Stuid
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Show the game name that has most number of hours played.
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CREATE TABLE Plays_games (gameid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR)
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SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid ORDER BY SUM(hours_played) DESC LIMIT 1
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### Context: CREATE TABLE Plays_games (gameid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR) ### Question: Show the game name that has most number of hours played. ### Answer: SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid ORDER BY SUM(hours_played) DESC LIMIT 1
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Show all game names played by at least 1000 hours.
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CREATE TABLE Plays_games (gameid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR)
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SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid HAVING SUM(hours_played) >= 1000
|
### Context: CREATE TABLE Plays_games (gameid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR) ### Question: Show all game names played by at least 1000 hours. ### Answer: SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid HAVING SUM(hours_played) >= 1000
|
Show all game names played by Linda Smith
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CREATE TABLE Student (Stuid VARCHAR, Lname VARCHAR, Fname VARCHAR); CREATE TABLE Plays_games (gameid VARCHAR, Stuid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR)
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SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid JOIN Student AS T3 ON T3.Stuid = T1.Stuid WHERE T3.Lname = "Smith" AND T3.Fname = "Linda"
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### Context: CREATE TABLE Student (Stuid VARCHAR, Lname VARCHAR, Fname VARCHAR); CREATE TABLE Plays_games (gameid VARCHAR, Stuid VARCHAR); CREATE TABLE Video_games (gameid VARCHAR) ### Question: Show all game names played by Linda Smith ### Answer: SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid JOIN Student AS T3 ON T3.Stuid = T1.Stuid WHERE T3.Lname = "Smith" AND T3.Fname = "Linda"
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Find the last and first name of students who are playing Football or Lacrosse.
|
CREATE TABLE SportsInfo (StuID VARCHAR, SportName VARCHAR); CREATE TABLE Student (lname VARCHAR, fname VARCHAR, StuID VARCHAR)
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SELECT T2.lname, T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.SportName = "Football" OR T1.SportName = "Lacrosse"
|
### Context: CREATE TABLE SportsInfo (StuID VARCHAR, SportName VARCHAR); CREATE TABLE Student (lname VARCHAR, fname VARCHAR, StuID VARCHAR) ### Question: Find the last and first name of students who are playing Football or Lacrosse. ### Answer: SELECT T2.lname, T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.SportName = "Football" OR T1.SportName = "Lacrosse"
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Find the first name and age of the students who are playing both Football and Lacrosse.
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CREATE TABLE Student (fname VARCHAR, age VARCHAR, StuID VARCHAR, SportName VARCHAR); CREATE TABLE Sportsinfo (fname VARCHAR, age VARCHAR, StuID VARCHAR, SportName VARCHAR)
|
SELECT fname, age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName = "Football" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName = "Lacrosse")
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### Context: CREATE TABLE Student (fname VARCHAR, age VARCHAR, StuID VARCHAR, SportName VARCHAR); CREATE TABLE Sportsinfo (fname VARCHAR, age VARCHAR, StuID VARCHAR, SportName VARCHAR) ### Question: Find the first name and age of the students who are playing both Football and Lacrosse. ### Answer: SELECT fname, age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName = "Football" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName = "Lacrosse")
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Find the last name and gender of the students who are playing both Call of Destiny and Works of Widenius games.
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CREATE TABLE Plays_games (StuID VARCHAR, GameID VARCHAR); CREATE TABLE Student (lname VARCHAR, sex VARCHAR, StuID VARCHAR); CREATE TABLE Video_games (GameID VARCHAR, Gname VARCHAR)
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SELECT lname, sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Call of Destiny" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Works of Widenius")
|
### Context: CREATE TABLE Plays_games (StuID VARCHAR, GameID VARCHAR); CREATE TABLE Student (lname VARCHAR, sex VARCHAR, StuID VARCHAR); CREATE TABLE Video_games (GameID VARCHAR, Gname VARCHAR) ### Question: Find the last name and gender of the students who are playing both Call of Destiny and Works of Widenius games. ### Answer: SELECT lname, sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Call of Destiny" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Works of Widenius")
|
Find the name of all customers.
|
CREATE TABLE customers (customer_name VARCHAR)
|
SELECT customer_name FROM customers
|
### Context: CREATE TABLE customers (customer_name VARCHAR) ### Question: Find the name of all customers. ### Answer: SELECT customer_name FROM customers
|
What is the average amount of items ordered in each order?
|
CREATE TABLE order_items (order_quantity INTEGER)
|
SELECT AVG(order_quantity) FROM order_items
|
### Context: CREATE TABLE order_items (order_quantity INTEGER) ### Question: What is the average amount of items ordered in each order? ### Answer: SELECT AVG(order_quantity) FROM order_items
|
What are the names of customers who use payment method "Cash"?
|
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
|
SELECT customer_name FROM customers WHERE payment_method = "Cash"
|
### Context: CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR) ### Question: What are the names of customers who use payment method "Cash"? ### Answer: SELECT customer_name FROM customers WHERE payment_method = "Cash"
|
Find the "date became customers" of the customers whose ID is between 10 and 20.
|
CREATE TABLE customers (date_became_customer VARCHAR, customer_id INTEGER)
|
SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20
|
### Context: CREATE TABLE customers (date_became_customer VARCHAR, customer_id INTEGER) ### Question: Find the "date became customers" of the customers whose ID is between 10 and 20. ### Answer: SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20
|
Which payment method is used by most customers?
|
CREATE TABLE customers (payment_method VARCHAR)
|
SELECT payment_method FROM customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1
|
### Context: CREATE TABLE customers (payment_method VARCHAR) ### Question: Which payment method is used by most customers? ### Answer: SELECT payment_method FROM customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1
|
What are the names of customers using the most popular payment method?
|
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
|
SELECT customer_name FROM customers WHERE payment_method = (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1)
|
### Context: CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR) ### Question: What are the names of customers using the most popular payment method? ### Answer: SELECT customer_name FROM customers WHERE payment_method = (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1)
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What are all the payment methods?
|
CREATE TABLE customers (payment_method VARCHAR)
|
SELECT DISTINCT payment_method FROM customers
|
### Context: CREATE TABLE customers (payment_method VARCHAR) ### Question: What are all the payment methods? ### Answer: SELECT DISTINCT payment_method FROM customers
|
What are the details of all products?
|
CREATE TABLE products (product_details VARCHAR)
|
SELECT DISTINCT product_details FROM products
|
### Context: CREATE TABLE products (product_details VARCHAR) ### Question: What are the details of all products? ### Answer: SELECT DISTINCT product_details FROM products
|
Find the name of all customers whose name contains "Alex".
|
CREATE TABLE customers (customer_name VARCHAR)
|
SELECT customer_name FROM customers WHERE customer_name LIKE "%Alex%"
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### Context: CREATE TABLE customers (customer_name VARCHAR) ### Question: Find the name of all customers whose name contains "Alex". ### Answer: SELECT customer_name FROM customers WHERE customer_name LIKE "%Alex%"
|
Find the detail of products whose detail contains the word "Latte" or the word "Americano"
|
CREATE TABLE products (product_details VARCHAR)
|
SELECT product_details FROM products WHERE product_details LIKE "%Latte%" OR product_details LIKE "%Americano%"
|
### Context: CREATE TABLE products (product_details VARCHAR) ### Question: Find the detail of products whose detail contains the word "Latte" or the word "Americano" ### Answer: SELECT product_details FROM products WHERE product_details LIKE "%Latte%" OR product_details LIKE "%Americano%"
|
What is the address content of the customer named "Maudie Kertzmann"?
|
CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE addresses (address_content VARCHAR, address_id VARCHAR)
|
SELECT t3.address_content FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t1.customer_name = "Maudie Kertzmann"
|
### Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE addresses (address_content VARCHAR, address_id VARCHAR) ### Question: What is the address content of the customer named "Maudie Kertzmann"? ### Answer: SELECT t3.address_content FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t1.customer_name = "Maudie Kertzmann"
|
How many customers are living in city "Lake Geovannyton"?
|
CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, city VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR)
|
SELECT COUNT(*) FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.city = "Lake Geovannyton"
|
### Context: CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, city VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR) ### Question: How many customers are living in city "Lake Geovannyton"? ### Answer: SELECT COUNT(*) FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.city = "Lake Geovannyton"
|
Find the name of customers who are living in Colorado?
|
CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR)
|
SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = "Colorado"
|
### Context: CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR) ### Question: Find the name of customers who are living in Colorado? ### Answer: SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = "Colorado"
|
Find the list of cities that no customer is living in.
|
CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE addresses (city VARCHAR)
|
SELECT city FROM addresses WHERE NOT city IN (SELECT DISTINCT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id)
|
### Context: CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE addresses (city VARCHAR) ### Question: Find the list of cities that no customer is living in. ### Answer: SELECT city FROM addresses WHERE NOT city IN (SELECT DISTINCT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id)
|
Which city has the most customers living in?
|
CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR)
|
SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY COUNT(*) DESC LIMIT 1
|
### Context: CREATE TABLE customers (customer_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR) ### Question: Which city has the most customers living in? ### Answer: SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY COUNT(*) DESC LIMIT 1
|
Find the city with post code 255.
|
CREATE TABLE addresses (city VARCHAR, zip_postcode VARCHAR)
|
SELECT city FROM addresses WHERE zip_postcode = 255
|
### Context: CREATE TABLE addresses (city VARCHAR, zip_postcode VARCHAR) ### Question: Find the city with post code 255. ### Answer: SELECT city FROM addresses WHERE zip_postcode = 255
|
Find the state and country of all cities with post code starting with 4.
|
CREATE TABLE addresses (state_province_county VARCHAR, country VARCHAR, zip_postcode VARCHAR)
|
SELECT state_province_county, country FROM addresses WHERE zip_postcode LIKE "4%"
|
### Context: CREATE TABLE addresses (state_province_county VARCHAR, country VARCHAR, zip_postcode VARCHAR) ### Question: Find the state and country of all cities with post code starting with 4. ### Answer: SELECT state_province_county, country FROM addresses WHERE zip_postcode LIKE "4%"
|
List the countries having more than 4 addresses listed.
|
CREATE TABLE addresses (country VARCHAR, address_id VARCHAR)
|
SELECT country FROM addresses GROUP BY country HAVING COUNT(address_id) > 4
|
### Context: CREATE TABLE addresses (country VARCHAR, address_id VARCHAR) ### Question: List the countries having more than 4 addresses listed. ### Answer: SELECT country FROM addresses GROUP BY country HAVING COUNT(address_id) > 4
|
List all the contact channel codes that were used less than 5 times.
|
CREATE TABLE customer_contact_channels (channel_code VARCHAR, customer_id VARCHAR)
|
SELECT channel_code FROM customer_contact_channels GROUP BY channel_code HAVING COUNT(customer_id) < 5
|
### Context: CREATE TABLE customer_contact_channels (channel_code VARCHAR, customer_id VARCHAR) ### Question: List all the contact channel codes that were used less than 5 times. ### Answer: SELECT channel_code FROM customer_contact_channels GROUP BY channel_code HAVING COUNT(customer_id) < 5
|
Which contact channel has been used by the customer with name "Tillman Ernser"?
|
CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_contact_channels (customer_id VARCHAR)
|
SELECT DISTINCT channel_code FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser"
|
### Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_contact_channels (customer_id VARCHAR) ### Question: Which contact channel has been used by the customer with name "Tillman Ernser"? ### Answer: SELECT DISTINCT channel_code FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser"
|
What is the "active to date" of the latest contact channel used by "Tillman Ernser"?
|
CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_contact_channels (active_to_date INTEGER, customer_id VARCHAR)
|
SELECT MAX(t2.active_to_date) FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser"
|
### Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE customer_contact_channels (active_to_date INTEGER, customer_id VARCHAR) ### Question: What is the "active to date" of the latest contact channel used by "Tillman Ernser"? ### Answer: SELECT MAX(t2.active_to_date) FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser"
|
What is the average time span of contact channels in the database?
|
CREATE TABLE customer_contact_channels (active_to_date VARCHAR, active_from_date VARCHAR)
|
SELECT AVG(active_to_date - active_from_date) FROM customer_contact_channels
|
### Context: CREATE TABLE customer_contact_channels (active_to_date VARCHAR, active_from_date VARCHAR) ### Question: What is the average time span of contact channels in the database? ### Answer: SELECT AVG(active_to_date - active_from_date) FROM customer_contact_channels
|
What is the channel code and contact number of the customer contact channel that was active for the longest time?
|
CREATE TABLE customer_contact_channels (channel_code VARCHAR, contact_number VARCHAR, active_to_date VARCHAR, active_from_date VARCHAR)
|
SELECT channel_code, contact_number FROM customer_contact_channels WHERE active_to_date - active_from_date = (SELECT active_to_date - active_from_date FROM customer_contact_channels ORDER BY (active_to_date - active_from_date) DESC LIMIT 1)
|
### Context: CREATE TABLE customer_contact_channels (channel_code VARCHAR, contact_number VARCHAR, active_to_date VARCHAR, active_from_date VARCHAR) ### Question: What is the channel code and contact number of the customer contact channel that was active for the longest time? ### Answer: SELECT channel_code, contact_number FROM customer_contact_channels WHERE active_to_date - active_from_date = (SELECT active_to_date - active_from_date FROM customer_contact_channels ORDER BY (active_to_date - active_from_date) DESC LIMIT 1)
|
Find the name and active date of the customer that use email as the contact channel.
|
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_contact_channels (active_from_date VARCHAR, customer_id VARCHAR, channel_code VARCHAR)
|
SELECT t1.customer_name, t2.active_from_date FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t2.channel_code = 'Email'
|
### Context: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_contact_channels (active_from_date VARCHAR, customer_id VARCHAR, channel_code VARCHAR) ### Question: Find the name and active date of the customer that use email as the contact channel. ### Answer: SELECT t1.customer_name, t2.active_from_date FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t2.channel_code = 'Email'
|
What is the name of the customer that made the order with the largest quantity?
|
CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE order_items (order_quantity INTEGER); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
|
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t3.order_quantity = (SELECT MAX(order_quantity) FROM order_items)
|
### Context: CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE order_items (order_quantity INTEGER); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) ### Question: What is the name of the customer that made the order with the largest quantity? ### Answer: SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t3.order_quantity = (SELECT MAX(order_quantity) FROM order_items)
|
What is the name of the customer that has purchased the most items?
|
CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
|
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY SUM(t3.order_quantity) DESC LIMIT 1
|
### Context: CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) ### Question: What is the name of the customer that has purchased the most items? ### Answer: SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY SUM(t3.order_quantity) DESC LIMIT 1
|
What is the payment method of the customer that has purchased the least quantity of items?
|
CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (payment_method VARCHAR, customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
|
SELECT t1.payment_method FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY SUM(t3.order_quantity) LIMIT 1
|
### Context: CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER); CREATE TABLE customers (payment_method VARCHAR, customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) ### Question: What is the payment method of the customer that has purchased the least quantity of items? ### Answer: SELECT t1.payment_method FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY SUM(t3.order_quantity) LIMIT 1
|
How many types of products have Rodrick Heaney bought in total?
|
CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE order_items (product_id VARCHAR, order_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
|
SELECT COUNT(DISTINCT t3.product_id) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney"
|
### Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE order_items (product_id VARCHAR, order_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) ### Question: How many types of products have Rodrick Heaney bought in total? ### Answer: SELECT COUNT(DISTINCT t3.product_id) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney"
|
What is the total quantity of products purchased by "Rodrick Heaney"?
|
CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
|
SELECT SUM(t3.order_quantity) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney"
|
### Context: CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) ### Question: What is the total quantity of products purchased by "Rodrick Heaney"? ### Answer: SELECT SUM(t3.order_quantity) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney"
|
How many customers have at least one order with status "Cancelled"?
|
CREATE TABLE customer_orders (customer_id VARCHAR, order_status VARCHAR)
|
SELECT COUNT(DISTINCT customer_id) FROM customer_orders WHERE order_status = "Cancelled"
|
### Context: CREATE TABLE customer_orders (customer_id VARCHAR, order_status VARCHAR) ### Question: How many customers have at least one order with status "Cancelled"? ### Answer: SELECT COUNT(DISTINCT customer_id) FROM customer_orders WHERE order_status = "Cancelled"
|
How many orders have detail "Second time"?
|
CREATE TABLE customer_orders (order_details VARCHAR)
|
SELECT COUNT(*) FROM customer_orders WHERE order_details = "Second time"
|
### Context: CREATE TABLE customer_orders (order_details VARCHAR) ### Question: How many orders have detail "Second time"? ### Answer: SELECT COUNT(*) FROM customer_orders WHERE order_details = "Second time"
|
Find the customer name and date of the orders that have the status "Delivered".
|
CREATE TABLE customer_orders (order_date VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
|
SELECT t1.customer_name, t2.order_date FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE order_status = "Delivered"
|
### Context: CREATE TABLE customer_orders (order_date VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR) ### Question: Find the customer name and date of the orders that have the status "Delivered". ### Answer: SELECT t1.customer_name, t2.order_date FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE order_status = "Delivered"
|
What is the total number of products that are in orders with status "Cancelled"?
|
CREATE TABLE customer_orders (order_id VARCHAR, order_status VARCHAR); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR)
|
SELECT SUM(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_status = "Cancelled"
|
### Context: CREATE TABLE customer_orders (order_id VARCHAR, order_status VARCHAR); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR) ### Question: What is the total number of products that are in orders with status "Cancelled"? ### Answer: SELECT SUM(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_status = "Cancelled"
|
Find the total amount of products ordered before 2018-03-17 07:13:53.
|
CREATE TABLE customer_orders (order_id VARCHAR, order_date INTEGER); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR)
|
SELECT SUM(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_date < "2018-03-17 07:13:53"
|
### Context: CREATE TABLE customer_orders (order_id VARCHAR, order_date INTEGER); CREATE TABLE order_items (order_quantity INTEGER, order_id VARCHAR) ### Question: Find the total amount of products ordered before 2018-03-17 07:13:53. ### Answer: SELECT SUM(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_date < "2018-03-17 07:13:53"
|
Who made the latest order?
|
CREATE TABLE customer_orders (customer_id VARCHAR, order_date VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
|
SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.order_date DESC LIMIT 1
|
### Context: CREATE TABLE customer_orders (customer_id VARCHAR, order_date VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR) ### Question: Who made the latest order? ### Answer: SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.order_date DESC LIMIT 1
|
Which product has been ordered most number of times?
|
CREATE TABLE products (product_details VARCHAR, product_id VARCHAR); CREATE TABLE order_items (product_id VARCHAR)
|
SELECT t2.product_details FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY COUNT(*) DESC LIMIT 1
|
### Context: CREATE TABLE products (product_details VARCHAR, product_id VARCHAR); CREATE TABLE order_items (product_id VARCHAR) ### Question: Which product has been ordered most number of times? ### Answer: SELECT t2.product_details FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY COUNT(*) DESC LIMIT 1
|
Find the name and ID of the product whose total order quantity is the largest.
|
CREATE TABLE order_items (product_id VARCHAR, order_quantity INTEGER); CREATE TABLE products (product_details VARCHAR, product_id VARCHAR)
|
SELECT t2.product_details, t2.product_id FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY SUM(t1.order_quantity) LIMIT 1
|
### Context: CREATE TABLE order_items (product_id VARCHAR, order_quantity INTEGER); CREATE TABLE products (product_details VARCHAR, product_id VARCHAR) ### Question: Find the name and ID of the product whose total order quantity is the largest. ### Answer: SELECT t2.product_details, t2.product_id FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY SUM(t1.order_quantity) LIMIT 1
|
Find all the addresses in East Julianaside, Texas or in Gleasonmouth, Arizona.
|
CREATE TABLE addresses (address_content VARCHAR, city VARCHAR, state_province_county VARCHAR)
|
SELECT address_content FROM addresses WHERE city = "East Julianaside" AND state_province_county = "Texas" UNION SELECT address_content FROM addresses WHERE city = "Gleasonmouth" AND state_province_county = "Arizona"
|
### Context: CREATE TABLE addresses (address_content VARCHAR, city VARCHAR, state_province_county VARCHAR) ### Question: Find all the addresses in East Julianaside, Texas or in Gleasonmouth, Arizona. ### Answer: SELECT address_content FROM addresses WHERE city = "East Julianaside" AND state_province_county = "Texas" UNION SELECT address_content FROM addresses WHERE city = "Gleasonmouth" AND state_province_county = "Arizona"
|
Find the name of customers who did not pay with Cash.
|
CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR)
|
SELECT customer_name FROM customers WHERE payment_method <> 'Cash'
|
### Context: CREATE TABLE customers (customer_name VARCHAR, payment_method VARCHAR) ### Question: Find the name of customers who did not pay with Cash. ### Answer: SELECT customer_name FROM customers WHERE payment_method <> 'Cash'
|
Find the names of customers who never ordered product Latte.
|
CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_details VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR)
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SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte'
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### Context: CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_details VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR) ### Question: Find the names of customers who never ordered product Latte. ### Answer: SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte'
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Find the names of customers who never placed an order.
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CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR)
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SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id
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### Context: CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR) ### Question: Find the names of customers who never placed an order. ### Answer: SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id
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Find the names of customers who ordered both products Latte and Americano.
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CREATE TABLE products (product_id VARCHAR, product_details VARCHAR); CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
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SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte' INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Americano'
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### Context: CREATE TABLE products (product_id VARCHAR, product_details VARCHAR); CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR) ### Question: Find the names of customers who ordered both products Latte and Americano. ### Answer: SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte' INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Americano'
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List the age of all music artists.
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CREATE TABLE artist (Age VARCHAR)
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SELECT Age FROM artist
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### Context: CREATE TABLE artist (Age VARCHAR) ### Question: List the age of all music artists. ### Answer: SELECT Age FROM artist
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What is the average age of all artists?
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CREATE TABLE artist (Age INTEGER)
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SELECT AVG(Age) FROM artist
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### Context: CREATE TABLE artist (Age INTEGER) ### Question: What is the average age of all artists? ### Answer: SELECT AVG(Age) FROM artist
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What are the famous titles of the artist "Triumfall"?
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CREATE TABLE artist (Famous_Title VARCHAR, Artist VARCHAR)
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SELECT Famous_Title FROM artist WHERE Artist = "Triumfall"
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### Context: CREATE TABLE artist (Famous_Title VARCHAR, Artist VARCHAR) ### Question: What are the famous titles of the artist "Triumfall"? ### Answer: SELECT Famous_Title FROM artist WHERE Artist = "Triumfall"
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What are the distinct Famous release dates?
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CREATE TABLE artist (Famous_Release_date VARCHAR)
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SELECT DISTINCT (Famous_Release_date) FROM artist
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### Context: CREATE TABLE artist (Famous_Release_date VARCHAR) ### Question: What are the distinct Famous release dates? ### Answer: SELECT DISTINCT (Famous_Release_date) FROM artist
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Return the dates of ceremony and the results of all music festivals
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CREATE TABLE music_festival (Date_of_ceremony VARCHAR, RESULT VARCHAR)
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SELECT Date_of_ceremony, RESULT FROM music_festival
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### Context: CREATE TABLE music_festival (Date_of_ceremony VARCHAR, RESULT VARCHAR) ### Question: Return the dates of ceremony and the results of all music festivals ### Answer: SELECT Date_of_ceremony, RESULT FROM music_festival
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What are the category of music festivals with result "Awarded"?
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CREATE TABLE music_festival (Category VARCHAR, RESULT VARCHAR)
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SELECT Category FROM music_festival WHERE RESULT = "Awarded"
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### Context: CREATE TABLE music_festival (Category VARCHAR, RESULT VARCHAR) ### Question: What are the category of music festivals with result "Awarded"? ### Answer: SELECT Category FROM music_festival WHERE RESULT = "Awarded"
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What are the maximum and minimum week on top of all volumes?
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CREATE TABLE volume (Weeks_on_Top INTEGER)
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SELECT MAX(Weeks_on_Top), MIN(Weeks_on_Top) FROM volume
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### Context: CREATE TABLE volume (Weeks_on_Top INTEGER) ### Question: What are the maximum and minimum week on top of all volumes? ### Answer: SELECT MAX(Weeks_on_Top), MIN(Weeks_on_Top) FROM volume
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What are the songs in volumes with more than 1 week on top?
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CREATE TABLE volume (Song VARCHAR, Weeks_on_Top INTEGER)
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SELECT Song FROM volume WHERE Weeks_on_Top > 1
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### Context: CREATE TABLE volume (Song VARCHAR, Weeks_on_Top INTEGER) ### Question: What are the songs in volumes with more than 1 week on top? ### Answer: SELECT Song FROM volume WHERE Weeks_on_Top > 1
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Please list all songs in volumes in ascending alphabetical order.
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CREATE TABLE volume (Song VARCHAR)
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SELECT Song FROM volume ORDER BY Song
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### Context: CREATE TABLE volume (Song VARCHAR) ### Question: Please list all songs in volumes in ascending alphabetical order. ### Answer: SELECT Song FROM volume ORDER BY Song
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How many distinct artists do the volumes associate to?
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CREATE TABLE volume (Artist_ID VARCHAR)
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SELECT COUNT(DISTINCT Artist_ID) FROM volume
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### Context: CREATE TABLE volume (Artist_ID VARCHAR) ### Question: How many distinct artists do the volumes associate to? ### Answer: SELECT COUNT(DISTINCT Artist_ID) FROM volume
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