arviii/sql-create-context · Datasets at Hugging Face

What are names of the movies that are either made before 1980 or directed by James Cameron?

CREATE TABLE Movie (title VARCHAR, director VARCHAR, YEAR VARCHAR)

SELECT title FROM Movie WHERE director = "James Cameron" OR YEAR < 1980

### Context: CREATE TABLE Movie (title VARCHAR, director VARCHAR, YEAR VARCHAR) ### Question: What are names of the movies that are either made before 1980 or directed by James Cameron? ### Answer: SELECT title FROM Movie WHERE director = "James Cameron" OR YEAR < 1980

What are the names of reviewers who had rated 3 star and 4 star?

CREATE TABLE Reviewer (name VARCHAR, rID VARCHAR); CREATE TABLE Rating (rID VARCHAR, stars VARCHAR)

SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 3 INTERSECT SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 4

### Context: CREATE TABLE Reviewer (name VARCHAR, rID VARCHAR); CREATE TABLE Rating (rID VARCHAR, stars VARCHAR) ### Question: What are the names of reviewers who had rated 3 star and 4 star? ### Answer: SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 3 INTERSECT SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 4

What are the names of movies that get 3 star and 4 star?

CREATE TABLE Rating (mID VARCHAR, stars VARCHAR); CREATE TABLE Movie (title VARCHAR, mID VARCHAR)

SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 3 INTERSECT SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 4

### Context: CREATE TABLE Rating (mID VARCHAR, stars VARCHAR); CREATE TABLE Movie (title VARCHAR, mID VARCHAR) ### Question: What are the names of movies that get 3 star and 4 star? ### Answer: SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 3 INTERSECT SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 4

How many counties are there?

CREATE TABLE county_public_safety (Id VARCHAR)

SELECT COUNT(*) FROM county_public_safety

### Context: CREATE TABLE county_public_safety (Id VARCHAR) ### Question: How many counties are there? ### Answer: SELECT COUNT(*) FROM county_public_safety

List the names of counties in descending order of population.

CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR)

SELECT Name FROM county_public_safety ORDER BY Population DESC

### Context: CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR) ### Question: List the names of counties in descending order of population. ### Answer: SELECT Name FROM county_public_safety ORDER BY Population DESC

List the distinct police forces of counties whose location is not on east side.

CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR)

SELECT DISTINCT Police_force FROM county_public_safety WHERE LOCATION <> "East"

### Context: CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR) ### Question: List the distinct police forces of counties whose location is not on east side. ### Answer: SELECT DISTINCT Police_force FROM county_public_safety WHERE LOCATION <> "East"

What are the minimum and maximum crime rate of counties?

CREATE TABLE county_public_safety (Crime_rate INTEGER)

SELECT MIN(Crime_rate), MAX(Crime_rate) FROM county_public_safety

### Context: CREATE TABLE county_public_safety (Crime_rate INTEGER) ### Question: What are the minimum and maximum crime rate of counties? ### Answer: SELECT MIN(Crime_rate), MAX(Crime_rate) FROM county_public_safety

Show the crime rates of counties in ascending order of number of police officers.

CREATE TABLE county_public_safety (Crime_rate VARCHAR, Police_officers VARCHAR)

SELECT Crime_rate FROM county_public_safety ORDER BY Police_officers

### Context: CREATE TABLE county_public_safety (Crime_rate VARCHAR, Police_officers VARCHAR) ### Question: Show the crime rates of counties in ascending order of number of police officers. ### Answer: SELECT Crime_rate FROM county_public_safety ORDER BY Police_officers

What are the names of cities in ascending alphabetical order?

CREATE TABLE city (Name VARCHAR)

SELECT Name FROM city ORDER BY Name

### Context: CREATE TABLE city (Name VARCHAR) ### Question: What are the names of cities in ascending alphabetical order? ### Answer: SELECT Name FROM city ORDER BY Name

What are the percentage of hispanics in cities with the black percentage higher than 10?

CREATE TABLE city (Hispanic VARCHAR, Black INTEGER)

SELECT Hispanic FROM city WHERE Black > 10

### Context: CREATE TABLE city (Hispanic VARCHAR, Black INTEGER) ### Question: What are the percentage of hispanics in cities with the black percentage higher than 10? ### Answer: SELECT Hispanic FROM city WHERE Black > 10

List the name of the county with the largest population.

CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR)

SELECT Name FROM county_public_safety ORDER BY Population DESC LIMIT 1

### Context: CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR) ### Question: List the name of the county with the largest population. ### Answer: SELECT Name FROM county_public_safety ORDER BY Population DESC LIMIT 1

List the names of the city with the top 5 white percentages.

CREATE TABLE city (Name VARCHAR, White VARCHAR)

SELECT Name FROM city ORDER BY White DESC LIMIT 5

### Context: CREATE TABLE city (Name VARCHAR, White VARCHAR) ### Question: List the names of the city with the top 5 white percentages. ### Answer: SELECT Name FROM city ORDER BY White DESC LIMIT 5

Show names of cities and names of counties they are in.

CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR)

SELECT T1.Name, T2.Name FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID

### Context: CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR) ### Question: Show names of cities and names of counties they are in. ### Answer: SELECT T1.Name, T2.Name FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID

Show white percentages of cities and the crime rates of counties they are in.

CREATE TABLE city (White VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR)

SELECT T1.White, T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID

### Context: CREATE TABLE city (White VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR) ### Question: Show white percentages of cities and the crime rates of counties they are in. ### Answer: SELECT T1.White, T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID

Show the name of cities in the county that has the largest number of police officers.

CREATE TABLE city (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR); CREATE TABLE county_public_safety (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR)

SELECT name FROM city WHERE county_ID = (SELECT county_ID FROM county_public_safety ORDER BY Police_officers DESC LIMIT 1)

### Context: CREATE TABLE city (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR); CREATE TABLE county_public_safety (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR) ### Question: Show the name of cities in the county that has the largest number of police officers. ### Answer: SELECT name FROM city WHERE county_ID = (SELECT county_ID FROM county_public_safety ORDER BY Police_officers DESC LIMIT 1)

Show the number of cities in counties that have a population more than 20000.

CREATE TABLE county_public_safety (county_ID VARCHAR, population INTEGER); CREATE TABLE city (county_ID VARCHAR, population INTEGER)

SELECT COUNT(*) FROM city WHERE county_ID IN (SELECT county_ID FROM county_public_safety WHERE population > 20000)

### Context: CREATE TABLE county_public_safety (county_ID VARCHAR, population INTEGER); CREATE TABLE city (county_ID VARCHAR, population INTEGER) ### Question: Show the number of cities in counties that have a population more than 20000. ### Answer: SELECT COUNT(*) FROM city WHERE county_ID IN (SELECT county_ID FROM county_public_safety WHERE population > 20000)

Show the crime rate of counties with a city having white percentage more than 90.

CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR); CREATE TABLE city (County_ID VARCHAR, White INTEGER)

SELECT T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID WHERE T1.White > 90

### Context: CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR); CREATE TABLE city (County_ID VARCHAR, White INTEGER) ### Question: Show the crime rate of counties with a city having white percentage more than 90. ### Answer: SELECT T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID WHERE T1.White > 90

Please show the police forces and the number of counties with each police force.

CREATE TABLE county_public_safety (Police_force VARCHAR)

SELECT Police_force, COUNT(*) FROM county_public_safety GROUP BY Police_force

### Context: CREATE TABLE county_public_safety (Police_force VARCHAR) ### Question: Please show the police forces and the number of counties with each police force. ### Answer: SELECT Police_force, COUNT(*) FROM county_public_safety GROUP BY Police_force

What is the location shared by most counties?

CREATE TABLE county_public_safety (LOCATION VARCHAR)

SELECT LOCATION FROM county_public_safety GROUP BY LOCATION ORDER BY COUNT(*) DESC LIMIT 1

### Context: CREATE TABLE county_public_safety (LOCATION VARCHAR) ### Question: What is the location shared by most counties? ### Answer: SELECT LOCATION FROM county_public_safety GROUP BY LOCATION ORDER BY COUNT(*) DESC LIMIT 1

List the names of counties that do not have any cities.

CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR)

SELECT Name FROM county_public_safety WHERE NOT County_ID IN (SELECT County_ID FROM city)

### Context: CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR) ### Question: List the names of counties that do not have any cities. ### Answer: SELECT Name FROM county_public_safety WHERE NOT County_ID IN (SELECT County_ID FROM city)

Show the police force shared by counties with location on the east and west.

CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR)

SELECT Police_force FROM county_public_safety WHERE LOCATION = "East" INTERSECT SELECT Police_force FROM county_public_safety WHERE LOCATION = "West"

### Context: CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR) ### Question: Show the police force shared by counties with location on the east and west. ### Answer: SELECT Police_force FROM county_public_safety WHERE LOCATION = "East" INTERSECT SELECT Police_force FROM county_public_safety WHERE LOCATION = "West"

Show the names of cities in counties that have a crime rate less than 100.

CREATE TABLE county_public_safety (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER); CREATE TABLE city (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER)

SELECT name FROM city WHERE county_id IN (SELECT county_id FROM county_public_safety WHERE Crime_rate < 100)

### Context: CREATE TABLE county_public_safety (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER); CREATE TABLE city (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER) ### Question: Show the names of cities in counties that have a crime rate less than 100. ### Answer: SELECT name FROM city WHERE county_id IN (SELECT county_id FROM county_public_safety WHERE Crime_rate < 100)

Show the case burden of counties in descending order of population.

CREATE TABLE county_public_safety (Case_burden VARCHAR, Population VARCHAR)

SELECT Case_burden FROM county_public_safety ORDER BY Population DESC

### Context: CREATE TABLE county_public_safety (Case_burden VARCHAR, Population VARCHAR) ### Question: Show the case burden of counties in descending order of population. ### Answer: SELECT Case_burden FROM county_public_safety ORDER BY Population DESC

Find the names of all modern rooms with a base price below $160 and two beds.

CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, basePrice VARCHAR, beds VARCHAR)

SELECT roomName FROM Rooms WHERE basePrice < 160 AND beds = 2 AND decor = 'modern'

### Context: CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, basePrice VARCHAR, beds VARCHAR) ### Question: Find the names of all modern rooms with a base price below $160 and two beds. ### Answer: SELECT roomName FROM Rooms WHERE basePrice < 160 AND beds = 2 AND decor = 'modern'

Find all the rooms that have a price higher than 160 and can accommodate more than 2 people. Report room names and ids.

CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR, basePrice VARCHAR, maxOccupancy VARCHAR)

SELECT roomName, RoomId FROM Rooms WHERE basePrice > 160 AND maxOccupancy > 2

### Context: CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR, basePrice VARCHAR, maxOccupancy VARCHAR) ### Question: Find all the rooms that have a price higher than 160 and can accommodate more than 2 people. Report room names and ids. ### Answer: SELECT roomName, RoomId FROM Rooms WHERE basePrice > 160 AND maxOccupancy > 2

Find the most popular room in the hotel. The most popular room is the room that had seen the largest number of reservations.

CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR)

SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY COUNT(*) DESC LIMIT 1

### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) ### Question: Find the most popular room in the hotel. The most popular room is the room that had seen the largest number of reservations. ### Answer: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY COUNT(*) DESC LIMIT 1

How many kids stay in the rooms reserved by ROY SWEAZY?

CREATE TABLE Reservations (kids VARCHAR, FirstName VARCHAR, LastName VARCHAR)

SELECT kids FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY"

### Context: CREATE TABLE Reservations (kids VARCHAR, FirstName VARCHAR, LastName VARCHAR) ### Question: How many kids stay in the rooms reserved by ROY SWEAZY? ### Answer: SELECT kids FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY"

How many times does ROY SWEAZY has reserved a room.

CREATE TABLE Reservations (FirstName VARCHAR, LastName VARCHAR)

SELECT COUNT(*) FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY"

### Context: CREATE TABLE Reservations (FirstName VARCHAR, LastName VARCHAR) ### Question: How many times does ROY SWEAZY has reserved a room. ### Answer: SELECT COUNT(*) FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY"

Which room has the highest rate? List the room's full name, rate, check in and check out date.

CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR); CREATE TABLE Reservations (Rate VARCHAR, CheckIn VARCHAR, CheckOut VARCHAR, Room VARCHAR)

SELECT T2.roomName, T1.Rate, T1.CheckIn, T1.CheckOut FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY T1.Rate DESC LIMIT 1

### Context: CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR); CREATE TABLE Reservations (Rate VARCHAR, CheckIn VARCHAR, CheckOut VARCHAR, Room VARCHAR) ### Question: Which room has the highest rate? List the room's full name, rate, check in and check out date. ### Answer: SELECT T2.roomName, T1.Rate, T1.CheckIn, T1.CheckOut FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY T1.Rate DESC LIMIT 1

How many adults stay in the room CONRAD SELBIG checked in on Oct 23, 2010?

CREATE TABLE Reservations (Adults VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR)

SELECT Adults FROM Reservations WHERE CheckIn = "2010-10-23" AND FirstName = "CONRAD" AND LastName = "SELBIG"

### Context: CREATE TABLE Reservations (Adults VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR) ### Question: How many adults stay in the room CONRAD SELBIG checked in on Oct 23, 2010? ### Answer: SELECT Adults FROM Reservations WHERE CheckIn = "2010-10-23" AND FirstName = "CONRAD" AND LastName = "SELBIG"

How many kids stay in the room DAMIEN TRACHSEL checked in on Sep 21, 2010?

CREATE TABLE Reservations (Kids VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR)

SELECT Kids FROM Reservations WHERE CheckIn = "2010-09-21" AND FirstName = "DAMIEN" AND LastName = "TRACHSEL"

### Context: CREATE TABLE Reservations (Kids VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR) ### Question: How many kids stay in the room DAMIEN TRACHSEL checked in on Sep 21, 2010? ### Answer: SELECT Kids FROM Reservations WHERE CheckIn = "2010-09-21" AND FirstName = "DAMIEN" AND LastName = "TRACHSEL"

How many king beds are there?

CREATE TABLE Rooms (beds INTEGER, bedtype VARCHAR)

SELECT SUM(beds) FROM Rooms WHERE bedtype = 'King'

### Context: CREATE TABLE Rooms (beds INTEGER, bedtype VARCHAR) ### Question: How many king beds are there? ### Answer: SELECT SUM(beds) FROM Rooms WHERE bedtype = 'King'

List the names and decor of rooms that have a king bed. Sort the list by their price.

CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, bedtype VARCHAR, basePrice VARCHAR)

SELECT roomName, decor FROM Rooms WHERE bedtype = 'King' ORDER BY basePrice

### Context: CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, bedtype VARCHAR, basePrice VARCHAR) ### Question: List the names and decor of rooms that have a king bed. Sort the list by their price. ### Answer: SELECT roomName, decor FROM Rooms WHERE bedtype = 'King' ORDER BY basePrice

Which room has cheapest base price? List the room's name and the base price.

CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR)

SELECT roomName, basePrice FROM Rooms ORDER BY basePrice LIMIT 1

### Context: CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR) ### Question: Which room has cheapest base price? List the room's name and the base price. ### Answer: SELECT roomName, basePrice FROM Rooms ORDER BY basePrice LIMIT 1

What is the decor of room Recluse and defiance?

CREATE TABLE Rooms (decor VARCHAR, roomName VARCHAR)

SELECT decor FROM Rooms WHERE roomName = "Recluse and defiance"

### Context: CREATE TABLE Rooms (decor VARCHAR, roomName VARCHAR) ### Question: What is the decor of room Recluse and defiance? ### Answer: SELECT decor FROM Rooms WHERE roomName = "Recluse and defiance"

What is the average base price of different bed type? List bed type and average base price.

CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER)

SELECT bedType, AVG(basePrice) FROM Rooms GROUP BY bedType

### Context: CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER) ### Question: What is the average base price of different bed type? List bed type and average base price. ### Answer: SELECT bedType, AVG(basePrice) FROM Rooms GROUP BY bedType

What is the total number of people who could stay in the modern rooms in this inn?

CREATE TABLE Rooms (maxOccupancy INTEGER, decor VARCHAR)

SELECT SUM(maxOccupancy) FROM Rooms WHERE decor = 'modern'

### Context: CREATE TABLE Rooms (maxOccupancy INTEGER, decor VARCHAR) ### Question: What is the total number of people who could stay in the modern rooms in this inn? ### Answer: SELECT SUM(maxOccupancy) FROM Rooms WHERE decor = 'modern'

What kind of decor has the least number of reservations?

CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (decor VARCHAR, RoomId VARCHAR)

SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY COUNT(T2.decor) LIMIT 1

### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (decor VARCHAR, RoomId VARCHAR) ### Question: What kind of decor has the least number of reservations? ### Answer: SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY COUNT(T2.decor) LIMIT 1

List how many times the number of people in the room reached the maximum occupancy of the room. The number of people include adults and kids.

CREATE TABLE Rooms (RoomId VARCHAR, maxOccupancy VARCHAR); CREATE TABLE Reservations (Room VARCHAR, Adults VARCHAR, Kids VARCHAR)

SELECT COUNT(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids

### Context: CREATE TABLE Rooms (RoomId VARCHAR, maxOccupancy VARCHAR); CREATE TABLE Reservations (Room VARCHAR, Adults VARCHAR, Kids VARCHAR) ### Question: List how many times the number of people in the room reached the maximum occupancy of the room. The number of people include adults and kids. ### Answer: SELECT COUNT(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids

Find the first and last names of people who payed more than the rooms' base prices.

CREATE TABLE Reservations (firstname VARCHAR, lastname VARCHAR, Room VARCHAR, Rate VARCHAR); CREATE TABLE Rooms (RoomId VARCHAR, basePrice VARCHAR)

SELECT T1.firstname, T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0

### Context: CREATE TABLE Reservations (firstname VARCHAR, lastname VARCHAR, Room VARCHAR, Rate VARCHAR); CREATE TABLE Rooms (RoomId VARCHAR, basePrice VARCHAR) ### Question: Find the first and last names of people who payed more than the rooms' base prices. ### Answer: SELECT T1.firstname, T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0

How many rooms are there?

CREATE TABLE Rooms (Id VARCHAR)

SELECT COUNT(*) FROM Rooms

### Context: CREATE TABLE Rooms (Id VARCHAR) ### Question: How many rooms are there? ### Answer: SELECT COUNT(*) FROM Rooms

Find the number of rooms with a king bed.

CREATE TABLE Rooms (bedType VARCHAR)

SELECT COUNT(*) FROM Rooms WHERE bedType = "King"

### Context: CREATE TABLE Rooms (bedType VARCHAR) ### Question: Find the number of rooms with a king bed. ### Answer: SELECT COUNT(*) FROM Rooms WHERE bedType = "King"

Find the number of rooms for each bed type.

CREATE TABLE Rooms (bedType VARCHAR)

SELECT bedType, COUNT(*) FROM Rooms GROUP BY bedType

### Context: CREATE TABLE Rooms (bedType VARCHAR) ### Question: Find the number of rooms for each bed type. ### Answer: SELECT bedType, COUNT(*) FROM Rooms GROUP BY bedType

Find the name of the room with the maximum occupancy.

CREATE TABLE Rooms (roomName VARCHAR, maxOccupancy VARCHAR)

SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1

### Context: CREATE TABLE Rooms (roomName VARCHAR, maxOccupancy VARCHAR) ### Question: Find the name of the room with the maximum occupancy. ### Answer: SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1

Find the id and name of the most expensive base price room.

CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR)

SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1

### Context: CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR) ### Question: Find the id and name of the most expensive base price room. ### Answer: SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1

List the type of bed and name of all traditional rooms.

CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR, decor VARCHAR)

SELECT roomName, bedType FROM Rooms WHERE decor = "traditional"

### Context: CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR, decor VARCHAR) ### Question: List the type of bed and name of all traditional rooms. ### Answer: SELECT roomName, bedType FROM Rooms WHERE decor = "traditional"

Find the number of rooms with king bed for each decor type.

CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR)

SELECT decor, COUNT(*) FROM Rooms WHERE bedType = "King" GROUP BY decor

### Context: CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR) ### Question: Find the number of rooms with king bed for each decor type. ### Answer: SELECT decor, COUNT(*) FROM Rooms WHERE bedType = "King" GROUP BY decor

Find the average and minimum price of the rooms in different decor.

CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER)

SELECT decor, AVG(basePrice), MIN(basePrice) FROM Rooms GROUP BY decor

### Context: CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER) ### Question: Find the average and minimum price of the rooms in different decor. ### Answer: SELECT decor, AVG(basePrice), MIN(basePrice) FROM Rooms GROUP BY decor

List the name of all rooms sorted by their prices.

CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR)

SELECT roomName FROM Rooms ORDER BY basePrice

### Context: CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR) ### Question: List the name of all rooms sorted by their prices. ### Answer: SELECT roomName FROM Rooms ORDER BY basePrice

Find the number of rooms with price higher than 120 for different decor.

CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER)

SELECT decor, COUNT(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor

### Context: CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER) ### Question: Find the number of rooms with price higher than 120 for different decor. ### Answer: SELECT decor, COUNT(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor

List the name of rooms with king or queen bed.

CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR)

SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen"

### Context: CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR) ### Question: List the name of rooms with king or queen bed. ### Answer: SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen"

How many different types of beds are there?

CREATE TABLE Rooms (bedType VARCHAR)

SELECT COUNT(DISTINCT bedType) FROM Rooms

### Context: CREATE TABLE Rooms (bedType VARCHAR) ### Question: How many different types of beds are there? ### Answer: SELECT COUNT(DISTINCT bedType) FROM Rooms

Find the name and id of the top 3 expensive rooms.

CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR)

SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3

### Context: CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR) ### Question: Find the name and id of the top 3 expensive rooms. ### Answer: SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3

Find the name of rooms whose price is higher than the average price.

CREATE TABLE Rooms (roomName VARCHAR, basePrice INTEGER)

SELECT roomName FROM Rooms WHERE basePrice > (SELECT AVG(basePrice) FROM Rooms)

### Context: CREATE TABLE Rooms (roomName VARCHAR, basePrice INTEGER) ### Question: Find the name of rooms whose price is higher than the average price. ### Answer: SELECT roomName FROM Rooms WHERE basePrice > (SELECT AVG(basePrice) FROM Rooms)

Find the number of rooms that do not have any reservation.

CREATE TABLE rooms (roomid VARCHAR, room VARCHAR); CREATE TABLE reservations (roomid VARCHAR, room VARCHAR)

SELECT COUNT(*) FROM rooms WHERE NOT roomid IN (SELECT DISTINCT room FROM reservations)

### Context: CREATE TABLE rooms (roomid VARCHAR, room VARCHAR); CREATE TABLE reservations (roomid VARCHAR, room VARCHAR) ### Question: Find the number of rooms that do not have any reservation. ### Answer: SELECT COUNT(*) FROM rooms WHERE NOT roomid IN (SELECT DISTINCT room FROM reservations)

Return the name and number of reservations made for each of the rooms.

CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR)

SELECT T2.roomName, COUNT(*), T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room

### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) ### Question: Return the name and number of reservations made for each of the rooms. ### Answer: SELECT T2.roomName, COUNT(*), T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room

Find the names of rooms that have been reserved for more than 60 times.

CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR)

SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING COUNT(*) > 60

### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) ### Question: Find the names of rooms that have been reserved for more than 60 times. ### Answer: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING COUNT(*) > 60

Find the name of rooms whose base price is between 120 and 150.

CREATE TABLE rooms (roomname VARCHAR, baseprice INTEGER)

SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150

### Context: CREATE TABLE rooms (roomname VARCHAR, baseprice INTEGER) ### Question: Find the name of rooms whose base price is between 120 and 150. ### Answer: SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150

Find the name of rooms booked by some customers whose first name contains ROY.

CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR)

SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%'

### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) ### Question: Find the name of rooms booked by some customers whose first name contains ROY. ### Answer: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%'

what are the details of the cmi masters that have the cross reference code 'Tax'?

CREATE TABLE CMI_Cross_References (master_customer_id VARCHAR, source_system_code VARCHAR); CREATE TABLE Customer_Master_Index (cmi_details VARCHAR, master_customer_id VARCHAR)

SELECT T1.cmi_details FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T2.source_system_code = 'Tax'

### Context: CREATE TABLE CMI_Cross_References (master_customer_id VARCHAR, source_system_code VARCHAR); CREATE TABLE Customer_Master_Index (cmi_details VARCHAR, master_customer_id VARCHAR) ### Question: what are the details of the cmi masters that have the cross reference code 'Tax'? ### Answer: SELECT T1.cmi_details FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T2.source_system_code = 'Tax'

What is the cmi cross reference id that is related to at least one council tax entry? List the cross reference id and source system code.

CREATE TABLE Council_Tax (cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR)

SELECT T1.cmi_cross_ref_id, T1.source_system_code FROM CMI_Cross_References AS T1 JOIN Council_Tax AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T1.cmi_cross_ref_id HAVING COUNT(*) >= 1

### Context: CREATE TABLE Council_Tax (cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR) ### Question: What is the cmi cross reference id that is related to at least one council tax entry? List the cross reference id and source system code. ### Answer: SELECT T1.cmi_cross_ref_id, T1.source_system_code FROM CMI_Cross_References AS T1 JOIN Council_Tax AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T1.cmi_cross_ref_id HAVING COUNT(*) >= 1

How many business rates are related to each cmi cross reference? List cross reference id, master customer id and the n

CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR); CREATE TABLE Business_Rates (cmi_cross_ref_id VARCHAR)

SELECT T2.cmi_cross_ref_id, T2.master_customer_id, COUNT(*) FROM Business_Rates AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T2.cmi_cross_ref_id

### Context: CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR); CREATE TABLE Business_Rates (cmi_cross_ref_id VARCHAR) ### Question: How many business rates are related to each cmi cross reference? List cross reference id, master customer id and the n ### Answer: SELECT T2.cmi_cross_ref_id, T2.master_customer_id, COUNT(*) FROM Business_Rates AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T2.cmi_cross_ref_id

What is the tax source system code related to the benefits and overpayments? List the code and the benifit id, order by benifit id.

CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Benefits_Overpayments (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR)

SELECT T1.source_system_code, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Benefits_Overpayments AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id ORDER BY T2.council_tax_id

### Context: CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Benefits_Overpayments (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) ### Question: What is the tax source system code related to the benefits and overpayments? List the code and the benifit id, order by benifit id. ### Answer: SELECT T1.source_system_code, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Benefits_Overpayments AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id ORDER BY T2.council_tax_id

Wat is the tax source system code and master customer id of the taxes related to each parking fine id?

CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, master_customer_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Parking_Fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR)

SELECT T1.source_system_code, T1.master_customer_id, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Parking_Fines AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id

### Context: CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, master_customer_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Parking_Fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) ### Question: Wat is the tax source system code and master customer id of the taxes related to each parking fine id? ### Answer: SELECT T1.source_system_code, T1.master_customer_id, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Parking_Fines AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id

What are the renting arrears tax ids related to the customer master index whose detail is not 'Schmidt, Kertzmann and Lubowitz'?

CREATE TABLE Rent_Arrears (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Customer_Master_Index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR)

SELECT T1.council_tax_id FROM Rent_Arrears AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id JOIN Customer_Master_Index AS T3 ON T3.master_customer_id = T2.master_customer_id WHERE T3.cmi_details <> 'Schmidt , Kertzmann and Lubowitz'

### Context: CREATE TABLE Rent_Arrears (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Customer_Master_Index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR) ### Question: What are the renting arrears tax ids related to the customer master index whose detail is not 'Schmidt, Kertzmann and Lubowitz'? ### Answer: SELECT T1.council_tax_id FROM Rent_Arrears AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id JOIN Customer_Master_Index AS T3 ON T3.master_customer_id = T2.master_customer_id WHERE T3.cmi_details <> 'Schmidt , Kertzmann and Lubowitz'

What are the register ids of electoral registries that have the cross reference source system code 'Electoral' or 'Tax'?

CREATE TABLE Electoral_Register (electoral_register_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR)

SELECT T1.electoral_register_id FROM Electoral_Register AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id WHERE T2.source_system_code = 'Electoral' OR T2.source_system_code = 'Tax'

### Context: CREATE TABLE Electoral_Register (electoral_register_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR) ### Question: What are the register ids of electoral registries that have the cross reference source system code 'Electoral' or 'Tax'? ### Answer: SELECT T1.electoral_register_id FROM Electoral_Register AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id WHERE T2.source_system_code = 'Electoral' OR T2.source_system_code = 'Tax'

How many different source system code for the cmi cross references are there?

CREATE TABLE CMI_cross_references (source_system_code VARCHAR)

SELECT COUNT(DISTINCT source_system_code) FROM CMI_cross_references

### Context: CREATE TABLE CMI_cross_references (source_system_code VARCHAR) ### Question: How many different source system code for the cmi cross references are there? ### Answer: SELECT COUNT(DISTINCT source_system_code) FROM CMI_cross_references

List all information about customer master index, and sort them by details in descending order.

CREATE TABLE customer_master_index (cmi_details VARCHAR)

SELECT * FROM customer_master_index ORDER BY cmi_details DESC

### Context: CREATE TABLE customer_master_index (cmi_details VARCHAR) ### Question: List all information about customer master index, and sort them by details in descending order. ### Answer: SELECT * FROM customer_master_index ORDER BY cmi_details DESC

List the council tax ids and their related cmi cross references of all the parking fines.

CREATE TABLE parking_fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR)

SELECT council_tax_id, cmi_cross_ref_id FROM parking_fines

### Context: CREATE TABLE parking_fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) ### Question: List the council tax ids and their related cmi cross references of all the parking fines. ### Answer: SELECT council_tax_id, cmi_cross_ref_id FROM parking_fines

How many council taxes are collected for renting arrears ?

CREATE TABLE rent_arrears (Id VARCHAR)

SELECT COUNT(*) FROM rent_arrears

### Context: CREATE TABLE rent_arrears (Id VARCHAR) ### Question: How many council taxes are collected for renting arrears ? ### Answer: SELECT COUNT(*) FROM rent_arrears

What are the distinct cross reference source system codes which are related to the master customer details 'Gottlieb, Becker and Wyman'?

CREATE TABLE customer_master_index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE cmi_cross_references (source_system_code VARCHAR, master_customer_id VARCHAR)

SELECT DISTINCT T2.source_system_code FROM customer_master_index AS T1 JOIN cmi_cross_references AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T1.cmi_details = 'Gottlieb , Becker and Wyman'

### Context: CREATE TABLE customer_master_index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE cmi_cross_references (source_system_code VARCHAR, master_customer_id VARCHAR) ### Question: What are the distinct cross reference source system codes which are related to the master customer details 'Gottlieb, Becker and Wyman'? ### Answer: SELECT DISTINCT T2.source_system_code FROM customer_master_index AS T1 JOIN cmi_cross_references AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T1.cmi_details = 'Gottlieb , Becker and Wyman'

Which cmi cross reference id is not related to any parking taxes?

CREATE TABLE parking_fines (cmi_cross_ref_id VARCHAR); CREATE TABLE cmi_cross_references (cmi_cross_ref_id VARCHAR)

SELECT cmi_cross_ref_id FROM cmi_cross_references EXCEPT SELECT cmi_cross_ref_id FROM parking_fines

### Context: CREATE TABLE parking_fines (cmi_cross_ref_id VARCHAR); CREATE TABLE cmi_cross_references (cmi_cross_ref_id VARCHAR) ### Question: Which cmi cross reference id is not related to any parking taxes? ### Answer: SELECT cmi_cross_ref_id FROM cmi_cross_references EXCEPT SELECT cmi_cross_ref_id FROM parking_fines

Which distinct source system code includes the substring 'en'?

CREATE TABLE cmi_cross_references (source_system_code VARCHAR)

SELECT DISTINCT source_system_code FROM cmi_cross_references WHERE source_system_code LIKE '%en%'

### Context: CREATE TABLE cmi_cross_references (source_system_code VARCHAR) ### Question: Which distinct source system code includes the substring 'en'? ### Answer: SELECT DISTINCT source_system_code FROM cmi_cross_references WHERE source_system_code LIKE '%en%'

How many parties are there?

CREATE TABLE party (Id VARCHAR)

SELECT COUNT(*) FROM party

### Context: CREATE TABLE party (Id VARCHAR) ### Question: How many parties are there? ### Answer: SELECT COUNT(*) FROM party

List the themes of parties in ascending order of number of hosts.

CREATE TABLE party (Party_Theme VARCHAR, Number_of_hosts VARCHAR)

SELECT Party_Theme FROM party ORDER BY Number_of_hosts

### Context: CREATE TABLE party (Party_Theme VARCHAR, Number_of_hosts VARCHAR) ### Question: List the themes of parties in ascending order of number of hosts. ### Answer: SELECT Party_Theme FROM party ORDER BY Number_of_hosts

What are the themes and locations of parties?

CREATE TABLE party (Party_Theme VARCHAR, LOCATION VARCHAR)

SELECT Party_Theme, LOCATION FROM party

### Context: CREATE TABLE party (Party_Theme VARCHAR, LOCATION VARCHAR) ### Question: What are the themes and locations of parties? ### Answer: SELECT Party_Theme, LOCATION FROM party

Show the first year and last year of parties with theme "Spring" or "Teqnology".

CREATE TABLE party (First_year VARCHAR, Last_year VARCHAR, Party_Theme VARCHAR)

SELECT First_year, Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology"

### Context: CREATE TABLE party (First_year VARCHAR, Last_year VARCHAR, Party_Theme VARCHAR) ### Question: Show the first year and last year of parties with theme "Spring" or "Teqnology". ### Answer: SELECT First_year, Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology"

What is the average number of hosts for parties?

CREATE TABLE party (Number_of_hosts INTEGER)

SELECT AVG(Number_of_hosts) FROM party

### Context: CREATE TABLE party (Number_of_hosts INTEGER) ### Question: What is the average number of hosts for parties? ### Answer: SELECT AVG(Number_of_hosts) FROM party

What is the location of the party with the most hosts?

CREATE TABLE party (LOCATION VARCHAR, Number_of_hosts VARCHAR)

SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1

### Context: CREATE TABLE party (LOCATION VARCHAR, Number_of_hosts VARCHAR) ### Question: What is the location of the party with the most hosts? ### Answer: SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1

Show different nationalities along with the number of hosts of each nationality.

CREATE TABLE HOST (Nationality VARCHAR)

SELECT Nationality, COUNT(*) FROM HOST GROUP BY Nationality

### Context: CREATE TABLE HOST (Nationality VARCHAR) ### Question: Show different nationalities along with the number of hosts of each nationality. ### Answer: SELECT Nationality, COUNT(*) FROM HOST GROUP BY Nationality

Show the most common nationality of hosts.

CREATE TABLE HOST (Nationality VARCHAR)

SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1

### Context: CREATE TABLE HOST (Nationality VARCHAR) ### Question: Show the most common nationality of hosts. ### Answer: SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1

Show the nations that have both hosts older than 45 and hosts younger than 35.

CREATE TABLE HOST (Nationality VARCHAR, Age INTEGER)

SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35

### Context: CREATE TABLE HOST (Nationality VARCHAR, Age INTEGER) ### Question: Show the nations that have both hosts older than 45 and hosts younger than 35. ### Answer: SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35

Show the themes of parties and the names of the party hosts.

CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_Theme VARCHAR, Party_ID VARCHAR)

SELECT T3.Party_Theme, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID

### Context: CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_Theme VARCHAR, Party_ID VARCHAR) ### Question: Show the themes of parties and the names of the party hosts. ### Answer: SELECT T3.Party_Theme, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID

Show the locations of parties and the names of the party hosts in ascending order of the age of the host.

CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR, Age VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR)

SELECT T3.Location, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age

### Context: CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR, Age VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR) ### Question: Show the locations of parties and the names of the party hosts in ascending order of the age of the host. ### Answer: SELECT T3.Location, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age

Show the locations of parties with hosts older than 50.

CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Host_ID VARCHAR, Age INTEGER)

SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50

### Context: CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Host_ID VARCHAR, Age INTEGER) ### Question: Show the locations of parties with hosts older than 50. ### Answer: SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50

Show the host names for parties with number of hosts greater than 20.

CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Number_of_hosts INTEGER)

SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20

### Context: CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Number_of_hosts INTEGER) ### Question: Show the host names for parties with number of hosts greater than 20. ### Answer: SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20

Show the name and the nationality of the oldest host.

CREATE TABLE HOST (Name VARCHAR, Nationality VARCHAR, Age VARCHAR)

SELECT Name, Nationality FROM HOST ORDER BY Age DESC LIMIT 1

### Context: CREATE TABLE HOST (Name VARCHAR, Nationality VARCHAR, Age VARCHAR) ### Question: Show the name and the nationality of the oldest host. ### Answer: SELECT Name, Nationality FROM HOST ORDER BY Age DESC LIMIT 1

List the names of hosts who did not serve as a host of any party in our record.

CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Name VARCHAR, Host_ID VARCHAR)

SELECT Name FROM HOST WHERE NOT Host_ID IN (SELECT Host_ID FROM party_host)

### Context: CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Name VARCHAR, Host_ID VARCHAR) ### Question: List the names of hosts who did not serve as a host of any party in our record. ### Answer: SELECT Name FROM HOST WHERE NOT Host_ID IN (SELECT Host_ID FROM party_host)

Show all region code and region name sorted by the codes.

CREATE TABLE region (region_code VARCHAR, region_name VARCHAR)

SELECT region_code, region_name FROM region ORDER BY region_code

### Context: CREATE TABLE region (region_code VARCHAR, region_name VARCHAR) ### Question: Show all region code and region name sorted by the codes. ### Answer: SELECT region_code, region_name FROM region ORDER BY region_code

List all region names in alphabetical order.

CREATE TABLE region (region_name VARCHAR)

SELECT region_name FROM region ORDER BY region_name

### Context: CREATE TABLE region (region_name VARCHAR) ### Question: List all region names in alphabetical order. ### Answer: SELECT region_name FROM region ORDER BY region_name

Show names for all regions except for Denmark.

CREATE TABLE region (region_name VARCHAR)

SELECT region_name FROM region WHERE region_name <> 'Denmark'

### Context: CREATE TABLE region (region_name VARCHAR) ### Question: Show names for all regions except for Denmark. ### Answer: SELECT region_name FROM region WHERE region_name <> 'Denmark'

How many storms had death records?

CREATE TABLE storm (Number_Deaths INTEGER)

SELECT COUNT(*) FROM storm WHERE Number_Deaths > 0

### Context: CREATE TABLE storm (Number_Deaths INTEGER) ### Question: How many storms had death records? ### Answer: SELECT COUNT(*) FROM storm WHERE Number_Deaths > 0

List name, dates active, and number of deaths for all storms with at least 1 death.

CREATE TABLE storm (name VARCHAR, dates_active VARCHAR, number_deaths VARCHAR)

SELECT name, dates_active, number_deaths FROM storm WHERE number_deaths >= 1

### Context: CREATE TABLE storm (name VARCHAR, dates_active VARCHAR, number_deaths VARCHAR) ### Question: List name, dates active, and number of deaths for all storms with at least 1 death. ### Answer: SELECT name, dates_active, number_deaths FROM storm WHERE number_deaths >= 1

Show the average and maximum damage for all storms with max speed higher than 1000.

CREATE TABLE storm (damage_millions_USD INTEGER, max_speed INTEGER)

SELECT AVG(damage_millions_USD), MAX(damage_millions_USD) FROM storm WHERE max_speed > 1000

### Context: CREATE TABLE storm (damage_millions_USD INTEGER, max_speed INTEGER) ### Question: Show the average and maximum damage for all storms with max speed higher than 1000. ### Answer: SELECT AVG(damage_millions_USD), MAX(damage_millions_USD) FROM storm WHERE max_speed > 1000

What is the total number of deaths and damage for all storms with a max speed greater than the average?

CREATE TABLE storm (number_deaths INTEGER, damage_millions_USD INTEGER, max_speed INTEGER)

SELECT SUM(number_deaths), SUM(damage_millions_USD) FROM storm WHERE max_speed > (SELECT AVG(max_speed) FROM storm)

### Context: CREATE TABLE storm (number_deaths INTEGER, damage_millions_USD INTEGER, max_speed INTEGER) ### Question: What is the total number of deaths and damage for all storms with a max speed greater than the average? ### Answer: SELECT SUM(number_deaths), SUM(damage_millions_USD) FROM storm WHERE max_speed > (SELECT AVG(max_speed) FROM storm)

List name and damage for all storms in a descending order of max speed.

CREATE TABLE storm (name VARCHAR, damage_millions_USD VARCHAR, max_speed VARCHAR)

SELECT name, damage_millions_USD FROM storm ORDER BY max_speed DESC

### Context: CREATE TABLE storm (name VARCHAR, damage_millions_USD VARCHAR, max_speed VARCHAR) ### Question: List name and damage for all storms in a descending order of max speed. ### Answer: SELECT name, damage_millions_USD FROM storm ORDER BY max_speed DESC

How many regions are affected?

CREATE TABLE affected_region (region_id VARCHAR)

SELECT COUNT(DISTINCT region_id) FROM affected_region

### Context: CREATE TABLE affected_region (region_id VARCHAR) ### Question: How many regions are affected? ### Answer: SELECT COUNT(DISTINCT region_id) FROM affected_region

Show the name for regions not affected.

CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_name VARCHAR, region_id VARCHAR)

SELECT region_name FROM region WHERE NOT region_id IN (SELECT region_id FROM affected_region)

### Context: CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_name VARCHAR, region_id VARCHAR) ### Question: Show the name for regions not affected. ### Answer: SELECT region_name FROM region WHERE NOT region_id IN (SELECT region_id FROM affected_region)

Show the name for regions and the number of storms for each region.

CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR)

SELECT T1.region_name, COUNT(*) FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id

### Context: CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR) ### Question: Show the name for regions and the number of storms for each region. ### Answer: SELECT T1.region_name, COUNT(*) FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id

List the name for storms and the number of affected regions for each storm.

CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR)

SELECT T1.name, COUNT(*) FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id

### Context: CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) ### Question: List the name for storms and the number of affected regions for each storm. ### Answer: SELECT T1.name, COUNT(*) FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id