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video_games | Indicate, by region, which platform has sold the most games. | region refers to region_name; platform refers to game_platform; sold the most games refers to MAX(SUM(num_sales)); | SELECT T.region_name FROM ( SELECT T1.platform_name, T4.region_name, SUM(T3.num_sales) FROM platform AS T1 INNER JOIN game_platform AS T2 ON T1.id = T2.platform_id INNER JOIN region_sales AS T3 ON T1.id = T3.game_platform_id INNER JOIN region AS T4 ON T3.region_id = T4.id GROUP BY T1.platform_name, T4.region_name ORDER BY SUM(T3.num_sales) DESC LIMIT 1 ) t | 4,005 | moderate |
video_games | In which platform does the game titled 15 Days available? | platform refers to platform_name; the game titled 15 Days refers to game_name = '15 Days' | SELECT T1.platform_name FROM platform AS T1 INNER JOIN game_platform AS T2 ON T1.id = T2.platform_id INNER JOIN game_publisher AS T3 ON T2.game_publisher_id = T3.id INNER JOIN game AS T4 ON T3.game_id = T4.id WHERE T4.game_name = 'Counter Force' | 253 | moderate |
video_games | Among the games published by Nintendo, what is the percentage of those in the genre of sports? | published by Nintendo refers to publisher_name = 'Nintendo'; in the genre of sports refers to genre_name = 'Sports'; percentage = divide(count(game_id where genre_name = 'Sports'), count(game_id)) * 100% where publisher_name = 'Nintendo' | SELECT CAST(COUNT(CASE WHEN T4.genre_name = 'Sports' THEN T1.id ELSE NULL END) AS REAL) * 100/ COUNT(T1.id) FROM game AS T1 INNER JOIN game_publisher AS T2 ON T1.id = T2.game_id INNER JOIN publisher AS T3 ON T2.publisher_id = T3.id INNER JOIN genre AS T4 ON T1.genre_id = T4.id WHERE T3.publisher_name = 'Nintendo' | 5,198 | challenging |
video_games | Which publisher has published the game 'Pachi-Slot Kanzen Kouryaku 3: Universal Koushiki Gaido Volume 3'? | which publisher refers to publisher_name; 'Pachi-Slot Kanzen Kouryaku 3: Universal Koushiki Gaido Volume 3' refers to game_name = 'Pachi-Slot Kanzen Kouryaku 3: Universal Koushiki Gaido Volume 3'; | SELECT T1.publisher_name FROM publisher AS T1 INNER JOIN game_publisher AS T2 ON T1.id = T2.publisher_id INNER JOIN game AS T3 ON T2.game_id = T3.id WHERE T3.game_name = 'Pachi-Slot Kanzen Kouryaku 3: Universal Koushiki Gaido Volume 3' | 3,094 | moderate |
video_games | State the name of the publisher with the most games. | name of publisher refers to publisher_name; the most games refers to max(game_id) | SELECT T.publisher_name FROM ( SELECT T2.publisher_name, COUNT(DISTINCT T1.game_id) FROM game_publisher AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id GROUP BY T2.publisher_name ORDER BY COUNT(DISTINCT T1.game_id) DESC LIMIT 1 ) t | 5,827 | moderate |
video_games | How many Sports games did Nintendo publish? | Sports games refers to game_name WHERE genre_name = 'Sports'; Nintendo refers to publisher_name = 'Nintendo'; | SELECT COUNT(T3.id) FROM publisher AS T1 INNER JOIN game_publisher AS T2 ON T1.id = T2.publisher_id INNER JOIN game AS T3 ON T2.game_id = T3.id INNER JOIN genre AS T4 ON T3.genre_id = T4.id WHERE T4.genre_name = 'Sports' AND T1.publisher_name = 'Nintendo' | 3,365 | moderate |
video_games | Provide the number of games sold in North America on the PS4 platform. | number of games sold refers to sum(multiply(num_sales, 100000)); in North America refers to region_name = 'North America'; on the PS4 platform refers to platform_name = 'PS4' | SELECT SUM(T1.num_sales * 100000) FROM region_sales AS T1 INNER JOIN region AS T2 ON T1.region_id = T2.id INNER JOIN game_platform AS T3 ON T1.game_platform_id = T3.id INNER JOIN platform AS T4 ON T3.platform_id = T4.id WHERE T2.region_name = 'North America' AND T4.platform_name = 'PS4' | 6,449 | moderate |
video_games | In which year was Panzer Tactics released on DS? | year refers to release_year; Panzer Tactics refers to game_name = 'Panzer Tactics'; on DS refers to platform_name = 'DS' | SELECT T4.release_year FROM game_publisher AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN game AS T3 ON T1.game_id = T3.id INNER JOIN game_platform AS T4 ON T1.id = T4.game_publisher_id INNER JOIN platform AS T5 ON T4.platform_id = T5.id WHERE T3.game_name = 'Panzer Tactics' AND T5.platform_name = 'DS' | 245 | moderate |
video_games | Provide any five games and release year under the sports genre. | game refers to game_name; under the sports genre refers to genre_name = 'Sports' | SELECT T3.game_name, T1.release_year FROM game_platform AS T1 INNER JOIN game_publisher AS T2 ON T1.game_publisher_id = T2.id INNER JOIN game AS T3 ON T2.game_id = T3.id INNER JOIN genre AS T4 ON T3.genre_id = T4.id WHERE T4.genre_name = 'Sports' LIMIT 5 | 6,076 | moderate |
video_games | How many more games were sold on game platform ID 50 than on game platform ID 51 in region ID 1? | result = subtract(sum(num_sales where game_platform_id = 50), sum(num_sales where game_platform_id = 51)) | SELECT (SUM(CASE WHEN T.game_platform_id = 50 THEN T.num_sales ELSE 0 END) - SUM(CASE WHEN T.game_platform_id = 51 THEN T.num_sales ELSE 0 END)) * 100000 AS nums FROM region_sales AS T WHERE T.region_id = 1 | 6,451 | moderate |
video_games | How many publishers in Japan released a game on X360 in 2011? | in Japan refers to region_name = 'Japan'; on X360 refers to platform_name = 'X360'; in 2011 refers to release_year = 2011 | SELECT COUNT(T3.game_publisher_id) FROM region AS T1 INNER JOIN region_sales AS T2 ON T1.id = T2.region_id INNER JOIN game_platform AS T3 ON T2.game_platform_id = T3.id INNER JOIN platform AS T4 ON T3.platform_id = T4.id WHERE T4.platform_name = 'X360' AND T3.release_year = 2011 AND T1.region_name = 'Japan' | 4,692 | moderate |
video_games | How many publishers have published more than 3 puzzle games? | puzzle refers to genre_name = 'Puzzle'; more than 3 puzzle games refers to count(game_id where genre_name = 'Puzzle') > 3 | SELECT COUNT(T.publisher_name) FROM ( SELECT T3.publisher_name, COUNT(DISTINCT T1.id) FROM game AS T1 INNER JOIN game_publisher AS T2 ON T1.id = T2.game_id INNER JOIN publisher AS T3 ON T2.publisher_id = T3.id INNER JOIN genre AS T4 ON T1.genre_id = T4.id WHERE T4.genre_name = 'Puzzle' GROUP BY T3.publisher_name HAVING COUNT(DISTINCT T1.id) > 3 ) t | 2,734 | challenging |
video_games | Indicate the publisher who has published the most games of all time. | publisher refers to publisher_name; publisher who has published the most games of all time refers to MAX(COUNT(publisher_name)); | SELECT T.publisher_name FROM ( SELECT T2.publisher_name, COUNT(DISTINCT T1.game_id) FROM game_publisher AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id GROUP BY T2.publisher_name ORDER BY COUNT(DISTINCT T1.game_id) DESC LIMIT 1 ) t | 5,975 | moderate |
video_games | What is the name of the publisher that has published the most puzzle games? | name of publisher refers to publisher_name; puzzle refers to genre_name = 'Puzzle'; the most puzzle games refers to max(count(game_id where genre_name = 'Puzzle')) | SELECT T.publisher_name FROM ( SELECT T3.publisher_name, COUNT(DISTINCT T1.id) FROM game AS T1 INNER JOIN game_publisher AS T2 ON T1.id = T2.game_id INNER JOIN publisher AS T3 ON T2.publisher_id = T3.id INNER JOIN genre AS T4 ON T1.genre_id = T4.id WHERE T4.genre_name = 'Puzzle' GROUP BY T3.publisher_name ORDER BY COUNT(DISTINCT T1.id) DESC LIMIT 1 ) t | 873 | challenging |
video_games | In games that can be played on Wii, what is the percentage of games released in 2007? | Wii refers to platform_name = 'Wii'; percentage = MULTIPLY(DIVIDE(SUM(release_year = 2007), COUNT(release_year)), 100.0); released in 2007 refers to release_year = 2007; | SELECT CAST(COUNT(CASE WHEN T2.release_year = 2007 THEN T3.game_id ELSE NULL END) AS REAL) * 100 / COUNT(T3.game_id) FROM platform AS T1 INNER JOIN game_platform AS T2 ON T1.id = T2.platform_id INNER JOIN game_publisher AS T3 ON T2.game_publisher_id = T3.id WHERE T1.platform_name = 'Wii' | 5,775 | challenging |
video_games | Which platform is the most popular in Europe? | platform that is the most popular refers to platform_name WHERE MAX(num_sales); in Europe refers to region_name = 'Europe' ; | SELECT T.platform_name FROM ( SELECT T4.platform_name FROM region AS T1 INNER JOIN region_sales AS T2 ON T1.id = T2.region_id INNER JOIN game_platform AS T3 ON T2.game_platform_id = T3.id INNER JOIN platform AS T4 ON T3.platform_id = T4.id WHERE T1.region_name = 'Europe' ORDER BY T2.num_sales DESC LIMIT 1 ) t | 6,315 | moderate |
video_games | On which platform was Panzer Tactics released in 2007? | platform refers to platform_name; Panzer Tactics refers to game_name = 'Panzer Tactics'; released in 2007 refers to release_year = 2007 | SELECT T5.platform_name FROM game_publisher AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN game AS T3 ON T1.game_id = T3.id INNER JOIN game_platform AS T4 ON T1.id = T4.game_publisher_id INNER JOIN platform AS T5 ON T4.platform_id = T5.id WHERE T3.game_name = 'Panzer Tactics' AND T4.release_year = 2007 | 6,441 | moderate |
video_games | What is the title of the game that gained the most sales in Japan? | title of the game refers to game_name; gained the most sales refers to max(num_sales); in Japan refers to region_name = 'Japan' | SELECT T.game_name FROM ( SELECT T5.game_name FROM region AS T1 INNER JOIN region_sales AS T2 ON T1.id = T2.region_id INNER JOIN game_platform AS T3 ON T2.game_platform_id = T3.id INNER JOIN game_publisher AS T4 ON T3.game_publisher_id = T4.id INNER JOIN game AS T5 ON T4.game_id = T5.id WHERE T1.region_name = 'Japan' ORDER BY T2.num_sales DESC LIMIT 1 ) t | 2,830 | moderate |
video_games | Which publisher has published the most number of Action games? | which publisher refers to publisher_name; publisher that has published the most number of Action games refers to MAX(COUNT(publisher_name)) WHERE genre_name = 'Action'; Action games refers to game_name WHERE genre_name = 'Action'; | SELECT T.publisher_name FROM ( SELECT T4.publisher_name, COUNT(DISTINCT T2.id) FROM genre AS T1 INNER JOIN game AS T2 ON T1.id = T2.genre_id INNER JOIN game_publisher AS T3 ON T2.id = T3.game_id INNER JOIN publisher AS T4 ON T3.publisher_id = T4.id WHERE T1.genre_name = 'Action' GROUP BY T4.publisher_name ORDER BY COUNT(DISTINCT T2.id) DESC LIMIT 1 ) t | 2,255 | challenging |
works_cycles | Among the vendors that sell the product Hex Nut 5, how many of them have a good credit rating? | good credit rating refers to CreditRating between 1 and 3 | SELECT COUNT(DISTINCT T3.Name) FROM ProductVendor AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Vendor AS T3 ON T1.BusinessEntityID = T3.BusinessEntityID WHERE T2.Name = 'Hex Nut 5' AND T3.CreditRating = 1 AND 3 | 5,201 | moderate |
works_cycles | Among the employees in the Manufacturing group in 2007, how many of them are store contacts? | store contact refers to PersonType = 'SC'; year(EndDate)>2007 and year(StartDate)<2007; | SELECT COUNT(T1.BusinessEntityID) FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID INNER JOIN Person AS T3 ON T1.BusinessEntityID WHERE T3.PersonType = 'SC' AND T2.GroupName = 'Manufacturing' AND STRFTIME('%Y', T1.EndDate) >= '2007' AND STRFTIME('%Y', T1.StartDate) <= '2007' | 1,326 | challenging |
works_cycles | What proportion of work order is in Subassembly? | proportion = DIVIDE(SUM(Name = 'Subassembly'). (COUNT(WorkOrderID))); | SELECT 100.0 * SUM(CASE WHEN T1.Name = 'Subassembly' THEN 1 ELSE 0 END) / COUNT(T2.WorkOrderID) FROM Location AS T1 INNER JOIN WorkOrderRouting AS T2 ON T1.LocationID = T2.LocationID | 1,445 | moderate |
works_cycles | Among the salable products from the mountain product line, how many of them have the most reviews? | salable product refers to FinishedGoodsFlag = 1; mountain product line refers to ProductLine = 'M' | SELECT SUM(CASE WHEN T2.ProductLine = 'M' THEN 1 ELSE 0 END) FROM ProductReview AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID WHERE T2.FinishedGoodsFlag = 1 GROUP BY T1.ProductID ORDER BY COUNT(T1.ProductReviewID) DESC LIMIT 1 | 6,233 | moderate |
works_cycles | Among the store contact employees, how many of them have a Vista credit card? | store contact refers to PersonType = 'SC'; type of credit card refers to CardType; CardType = 'vista'; | SELECT COUNT(T1.FirstName) FROM Person AS T1 INNER JOIN PersonCreditCard AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN CreditCard AS T3 ON T2.CreditCardID = T3.CreditCardID WHERE T3.CardType = 'Vista' AND T1.PersonType = 'SC' | 2,385 | moderate |
works_cycles | Name all stores and its sales representative in France territory. | France territory refers to SalesTerritory.Name = 'France'; | SELECT T3.Name, T4.FirstName, T4.LastName FROM SalesTerritory AS T1 INNER JOIN Customer AS T2 ON T1.TerritoryID = T2.TerritoryID INNER JOIN Store AS T3 ON T2.StoreID = T3.BusinessEntityID INNER JOIN Person AS T4 ON T2.PersonID = T4.BusinessEntityID WHERE T1.Name = 'France' | 5,474 | moderate |
works_cycles | List down the email address of female single employees. | female refers to Gender = 'F'; single refers to MaritalStatus = 'S'; | SELECT T3.EmailAddress FROM Employee AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN EmailAddress AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID WHERE T1.Gender = 'F' AND T1.MaritalStatus = 'S' | 509 | moderate |
works_cycles | Among the products from the mountain product line, how many of them are sold by over 2 vendors? | mountain product line refers to ProductLine = 'M'; sold by over 5 vendors refers to count(Name)>5 | SELECT SUM(CASE WHEN T1.ProductLine = 'M' THEN 1 ELSE 0 END) FROM Product AS T1 INNER JOIN ProductVendor AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Vendor AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID GROUP BY T1.ProductID HAVING COUNT(T1.Name) > 2 | 1,738 | moderate |
works_cycles | How many days did it take to end the work order "425"? | days to end a work order = SUBTRACT(ActualEndDate, ActualStartDate); | SELECT 365 * (STRFTIME('%Y', ActualEndDate) - STRFTIME('%Y', ActualStartDate)) + 30 * (STRFTIME('%m', ActualEndDate) - STRFTIME('%m', ActualStartDate)) + STRFTIME('%d', ActualEndDate) - STRFTIME('%d', ActualStartDate) FROM WorkOrderRouting WHERE WorkOrderID = 425 | 6,140 | challenging |
works_cycles | What is the credit rating of the company whose average lead time is 16 days for a standard price of 18.9900 and whose last receipt date is August 27, 2011? | last receipt date is August 17, 2011 refers to LastReceiptDate> = '2011-08-17 00:00:00' and LastReceiptDate < '2011-08-18 00:00:00'; | SELECT T2.CreditRating FROM ProductVendor AS T1 INNER JOIN Vendor AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.StandardPrice = 18.9900 AND T1.AverageLeadTime = 16 AND STRFTIME('%Y-%m-%d', T1.LastReceiptDate) = '2011-08-27' | 3,585 | moderate |
works_cycles | What is the full name of the Document Control Manager who is in charge of all Level 1 approved documents? | full Name = FirstName+MiddleName+Last Name; approved document refers to Status = 2; | SELECT T1.FirstName, T1.MiddleName, T1.LastName FROM Person AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Document AS T3 ON T3.Owner = T2.BusinessEntityID WHERE T2.JobTitle = 'Document Control Manager' AND T3.DocumentLevel = 1 AND T3.Status = 2 GROUP BY T1.FirstName, T1.MiddleName, T1.LastName | 2,464 | challenging |
works_cycles | What is the job title of the oldest employee in the company? In which department is he in? | oldest employee refers to min(BirthDate) | SELECT T2.JobTitle, T4.Name FROM Person AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN EmployeeDepartmentHistory AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID INNER JOIN Department AS T4 ON T3.DepartmentID = T4.DepartmentID ORDER BY T2.HireDate LIMIT 1 | 2,409 | moderate |
works_cycles | How many products from the Clothing category were on the LL Road Frame Sale? | LL Road Frame Sale is a description of special offer | SELECT COUNT(T2.ProductID) FROM SpecialOffer AS T1 INNER JOIN SpecialOfferProduct AS T2 ON T1.SpecialOfferID = T2.SpecialOfferID INNER JOIN Product AS T3 ON T2.ProductID = T3.ProductID INNER JOIN ProductSubcategory AS T4 ON T3.ProductSubcategoryID = T4.ProductSubcategoryID INNER JOIN ProductCategory AS T5 ON T4.ProductCategoryID = T5.ProductCategoryID WHERE T1.Description = 'LL Road Frame Sale' AND T4.Name = 'Clothing' | 2,051 | moderate |
works_cycles | Among the companies to which Adventure Works Cycles purchases parts or other goods, what is the profit on net obtained from the vendor who has an above average credit rating? Kindly indicate each names of the vendor and the corresponding net profits. | above average credit rating refers to CreditRating = 3; profit on net = subtract(LastReceiptCost, StandardPrice); | SELECT T2.Name, T1.LastReceiptCost - T1.StandardPrice FROM ProductVendor AS T1 INNER JOIN Vendor AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T2.CreditRating = 3 | 6,079 | moderate |
works_cycles | Please list the website purchasing links of the vendors from whom the product Hex Nut 5 can be purchased. | website purchasing link refers to PurchasingWebServiceURL | SELECT T3.PurchasingWebServiceURL FROM ProductVendor AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Vendor AS T3 ON T1.BusinessEntityID = T3.BusinessEntityID WHERE T2.Name = 'Hex Nut 5' | 6,195 | moderate |
works_cycles | What is the average profit of all the low class universal road frames? Indicate how many variety of sizes are there and the available colors. | low class refers to Class = 'L'; universal refers to Style = 'U'; road frame is a name of product subcategory; average profit = AVG(SUBTRACT(ListPrice, StandardCost); | SELECT AVG(T1.ListPrice - T1.StandardCost), COUNT(DISTINCT T1.Size) , COUNT(DISTINCT T1.Style) FROM Product AS T1 INNER JOIN ProductSubcategory AS T2 ON T1.ProductSubcategoryID = T2.ProductSubcategoryID WHERE T1.Class = 'L' AND T2.Name = 'Road Frames' GROUP BY T1.Class, T1.Color | 2,035 | challenging |
works_cycles | Who is the company's highest-paid single female employee? Include her full name and job title. | full name = FirstName+MiddleName+LastName; highest-paid refers to max(Rate); single refers to Status = 'S'; female refers to Gender = 'F'; | SELECT T3.FirstName, T3.MiddleName, T3.LastName, T1.JobTitle FROM Employee AS T1 INNER JOIN EmployeePayHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Person AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID WHERE T1.MaritalStatus = 'S' AND T1.Gender = 'F' ORDER BY T2.Rate DESC LIMIT 1 | 4,162 | challenging |
works_cycles | For the employees who have the highest pay frequency, please list their vacation hours. | highest pay frequency refers to PayFrequency = 2 | SELECT T2.VacationHours FROM EmployeePayHistory AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T2.BusinessEntityID = ( SELECT BusinessEntityID FROM EmployeePayHistory ORDER BY Rate DESC LIMIT 1 ) | 3,915 | moderate |
works_cycles | List the name of employees who had left the company? When were they hired? | employee that has left the company refers to EndDate is not null | SELECT T1.FirstName, T1.LastName, T2.HireDate FROM Person AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN EmployeeDepartmentHistory AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID WHERE T3.EndDate IS NOT NULL | 4,854 | moderate |
works_cycles | Among the sales people who achieved projected sales quota 2013, is there any person from territory ID 1? If yes, state the business entity ID. | projected sales quota refers to SalesQuota; projected sales quota in 2013 refers to year(QuotaDate) = 2013; | SELECT DISTINCT T1.BusinessEntityID FROM SalesPerson AS T1 INNER JOIN SalesPersonQuotaHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.TerritoryID = 1 AND STRFTIME('%Y', QuotaDate) = '2013' | 3,075 | moderate |
works_cycles | What is the current payrate of Rob Walters? Calculate the percentage increment from his previous payrate. | current payrate refers to max(Rate); percentage increment = divide(subtract(max(Rate), min(Rate)), min(Rate))*100% | SELECT T2.Rate , (MAX(T2.Rate) - MIN(T2.Rate)) * 100 / MAX(T2.Rate) FROM Person AS T1 INNER JOIN EmployeePayHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.FirstName = 'Rob' AND T1.LastName = 'Walters' | 2,874 | moderate |
works_cycles | What is the total profit gained by the company from the product that has the highest amount of quantity ordered from online customers? Indicate the name of the product. | profit = MULTIPLY(SUBTRACT(ListPrice, Standardcost)), (Quantity))); | SELECT (T2.ListPrice - T2.StandardCost) * SUM(T1.Quantity), T2.Name FROM ShoppingCartItem AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID GROUP BY T1.ProductID, T2.Name, T2.ListPrice, T2.StandardCost, T1.Quantity ORDER BY SUM(T1.Quantity) DESC LIMIT 1 | 4,890 | challenging |
works_cycles | Which sales person achieved the highest sales YTD? What is the projected yearly sales quota in 2011 for this person? | Sales people refer to PersonType = 'SP'; projected yearly sales refers to SalesQuota | SELECT T1.BusinessEntityID, SUM(T1.SalesQuota) FROM SalesPerson AS T1 INNER JOIN SalesPersonQuotaHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE STRFTIME('%Y', T2.QuotaDate) = '2011' GROUP BY T1.BusinessEntityID ORDER BY SUM(T1.SalesYTD) DESC LIMIT 1 | 1,327 | moderate |
works_cycles | Which department, altogether, has the most personnel who work the evening shift? | evening shift also means night shift where Name = 'Night';most personnel in evening shift refers to Max(Count(Shift.ShiftID(Name = 'Night'))); | SELECT T3.Name FROM EmployeeDepartmentHistory AS T1 INNER JOIN Shift AS T2 ON T1.ShiftId = T2.ShiftId INNER JOIN Department AS T3 ON T1.DepartmentID = T3.DepartmentID WHERE T2.Name = 'Night' GROUP BY T3.Name ORDER BY COUNT(T1.BusinessEntityID) DESC LIMIT 1 | 2,881 | moderate |
works_cycles | For the document Control Assistant who was hired on 2009/1/22, what is the percentage of private documents did he/she have? | Document Control Assistant refers to the JobTitle = 'Document Control Assistant'; hired on 2009/1/22 means the person's hiring date is HireDate = '2009-01-22'; private documents indicate that DocumentSummary is null; DIVIDE(COUNT(DocumentSummary is null), COUNT(DocumentSummary))*100 | SELECT CAST(SUM(CASE WHEN T1.DocumentSummary IS NOT NULL THEN 1 ELSE 0 END) AS REAL) / COUNT(T1.DocumentSummary) FROM Document AS T1 INNER JOIN Employee AS T2 ON T1.Owner = T2.BusinessEntityID WHERE T2.JobTitle = 'Document Control Assistant' AND T2.HireDate = '2009-01-22' | 6,111 | challenging |
works_cycles | What are the names of the vendors to which the company purchased its women's tights products? | product is purchased refers to MakeFlag = 0; women's refers to Style = 'W'; ProductSubcategoryID = 'Tights'; | SELECT DISTINCT T4.Name FROM Product AS T1 INNER JOIN ProductVendor AS T2 ON T1.ProductID = T2.ProductID INNER JOIN ProductSubcategory AS T3 ON T1.ProductSubcategoryID = T3.ProductSubcategoryID INNER JOIN Vendor AS T4 ON T2.BusinessEntityID = T4.BusinessEntityID WHERE T1.MakeFlag = 0 AND T1.Style = 'W' AND T3.Name = 'Tights' | 3,951 | moderate |
works_cycles | Who is the top sales person who achived highest percentage of projected sales quota in 2013? | 2013 refers to QuotaDate = '2013'; DIVIDE(SalesLastYear), (SUM(SalesQuota where YEAR(QuotaDate) = 2013)) as percentage
| SELECT BusinessEntityID FROM SalesPerson WHERE BusinessEntityID IN ( SELECT BusinessEntityID FROM SalesPersonQuotaHistory WHERE STRFTIME('%Y', QuotaDate) = '2013' ) ORDER BY CAST(SalesLastYear AS REAL) / SalesQuota DESC LIMIT 1 | 6,406 | moderate |
works_cycles | What percentage of businesses in the Northwest US have forecasted annual sales of above 300,000? | Northwest refers to Name = 'Northwest'; US refers to CountryRegionCode = 'US'; forecasted annual sales of above 300,000 refers to SalesQuota >300000; Percentage = Divide(Count(TerritoryID(SalesQuota >300000)),Count(TerritoryID))*100 | SELECT CAST(SUM(CASE WHEN T1.SalesQuota > 300000 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.BusinessEntityID) FROM SalesPerson AS T1 INNER JOIN SalesTerritory AS T2 ON T1.TerritoryID = T2.TerritoryID WHERE T2.CountryRegionCode = 'US' AND T2.Name = 'Northwest' | 2,300 | moderate |
works_cycles | Which type of transaction was it for the "LL Road Handlebars" order happened in 2012/11/3? | Transactiontype = 'w' means 'WorkOrder'; transactiontype = 's' means 'SalesOrder'; transactiontype = 'P' means 'PurchaseOrder'; happened in refers to TransactionDate | SELECT T1.TransactionType FROM TransactionHistoryArchive AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID WHERE T2.Name = 'LL Road Handlebars' AND STRFTIME('%Y-%m-%d',T1.TransactionDate) = '2012-11-03' | 442 | moderate |
works_cycles | List all the pay rates of all employees that were hired at 20 years of age. | pay rate refers to Rate; 20 years old at the time of being hired refers to SUBTRACT(year(HireDate)), (year(BirthDate))) = 20; | SELECT T2.Rate FROM Employee AS T1 INNER JOIN EmployeePayHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE STRFTIME('%Y', T1.HireDate) - STRFTIME('%Y', T1.BirthDate) = 20 | 4,499 | moderate |
works_cycles | Calculate the average of the total ordered quantity of products purchased whose shipping method was Cargo Transport 5. | shipping method was Cargo Transport 5 refers to Name = 'Cargo Transport 5'; average = DIVIDE(SUM(OrderQty where Name = 'Cargo Transport 5'), COUNT(ShipMethodID)) | SELECT CAST(SUM(IIF(T1.ShipMethodID = 5, T3.OrderQty, 0)) AS REAL) / COUNT(T3.ProductID) FROM ShipMethod AS T1 INNER JOIN PurchaseOrderHeader AS T2 ON T1.ShipMethodID = T2.ShipMethodID INNER JOIN PurchaseOrderDetail AS T3 ON T2.PurchaseOrderID = T3.PurchaseOrderID | 497 | challenging |
works_cycles | What is the profit of the product with the highest list price and of the product with the lowest list price other than 0? Indicates the depth the component is from its parent. | profit = subtract(ListPrice, StandardCost); the depth the component from its parent refers to BOMLevel; | SELECT ( SELECT ListPrice - StandardCost FROM Product WHERE ListPrice != 0 ORDER BY ListPrice DESC LIMIT 1 ) , ( SELECT ListPrice - StandardCost FROM Product WHERE ListPrice != 0 ORDER BY ListPrice LIMIT 1 ) | 710 | moderate |
works_cycles | What is the profit on net of the products that have exactly 200 maximum order quantity? Indicate the name of the vendors to which these products were purchased from. | maximum orders refers to MaxOrderQty; MaxOrderQty = 200; profit on net = SUBTRACT(LastReceiptCost, StandardPrice); | SELECT T1.LastReceiptCost - T1.StandardPrice, T2.Name FROM ProductVendor AS T1 INNER JOIN Vendor AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.MaxOrderQty = 200 | 5,839 | moderate |
works_cycles | What is the percentage of the total products ordered were not rejected by Drill size? | rejected quantity refers to ScrappedQty; rejected by Drill size refers to Name in ('Drill size too small','Drill size too large'); percentage = DIVIDE(SUM(ScrappedQty) where Name in('Drill size too small','Drill size too large'), OrderQty) | SELECT CAST(SUM(CASE WHEN T2.VacationHours > 20 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.BusinessEntityID) FROM EmployeePayHistory AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T2.CurrentFlag = 1 AND T2.SickLeaveHours > 10 | 6,573 | moderate |
works_cycles | What percentage of people named Mary who wants Receive Email promotions of AdventureWorks and selected partners are store contacts? | wants Receive Email promotions of AdventureWorks and selected partners refers to EmailPromotion = 2; store contact refers to PersonType = 'SC'; percentage = DIVIDE(count(BusinessEntityID(FirstName = 'Marry'&EmailPromotion = '2')),count(BusinessEntityID)))
| SELECT CAST(SUM(CASE WHEN EmailPromotion = 2 THEN 1 ELSE 0 END) AS REAL) * 100 / SUM(CASE WHEN PersonType = 'SC' THEN 1 ELSE 0 END) FROM Person WHERE FirstName = 'Mary' | 5,637 | moderate |
works_cycles | When did the Senior Tool Designer, who was 33 years old at the time he was hired, stopped working in the Engineering department? | Senior Tool Designer is a JobTitle; 33 years old at the time of hiring refers to SUBTRACT(year(HireDate)), (year(BirthDate)) = 33; | SELECT T2.EndDate FROM Employee AS T1 INNER JOIN EmployeeDepartmentHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T2.DepartmentID = T3.DepartmentID WHERE T1.JobTitle = 'Senior Tool Designer' AND STRFTIME('%Y', T1.HireDate) - STRFTIME('%Y', T1.BirthDate) = 33 AND T2.EndDate IS NOT NULL | 6,312 | challenging |
works_cycles | Among the vendors with an average credit rating, what is the overall total due amount of purchases made by the company to the vendor that isn't preferrerd if another vendor is available? | average credit rating refers to CreditRating = 4; vendor that isn't preferrerd if another vendor is available refers to PreferredVendorStatus = 0; SUM(TotalDue); | SELECT SUM(T2.TotalDue) FROM Vendor AS T1 INNER JOIN PurchaseOrderHeader AS T2 ON T1.BusinessEntityID = T2.VendorID WHERE T1.CreditRating = 4 AND T1.PreferredVendorStatus = 0 | 5,696 | moderate |
works_cycles | Please list the credit card numbers of all the employees who have left the Finance Department. | credit card number refers to CardNumber; employees who left the department refers to EndDate NOT null; Engineering Department is a name of department; | SELECT T3.CardNumber FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID INNER JOIN CreditCard AS T3 ON T1.ModifiedDate = T3.ModifiedDate INNER JOIN PersonCreditCard AS T4 ON T3.CreditCardID = T4.CreditCardID WHERE T2.Name = 'Finance' AND T1.EndDate IS NOT NULL | 3,315 | moderate |
works_cycles | Which geographic area does the city with the second lowest tax rate belongs to? Indicate the name of the state or province as well. | geographic area to which the city belong refers to Group; | SELECT T3.'Group', T2.Name FROM SalesTaxRate AS T1 INNER JOIN StateProvince AS T2 ON T1.StateProvinceID = T2.StateProvinceID INNER JOIN SalesTerritory AS T3 ON T2.TerritoryID = T3.TerritoryID ORDER BY T1.TaxRate LIMIT 1, 1 | 3,185 | moderate |
works_cycles | What are the unit measure codes for product ID No.762? | SELECT T2.UnitMeasureCode FROM Product AS T1 INNER JOIN UnitMeasure AS T2 ON T1.SizeUnitMeasureCode = T2.UnitMeasureCode OR T1.WeightUnitMeasureCode = T2.UnitMeasureCode WHERE T1.ProductID = 762 GROUP BY T1.ProductID, T2.UnitMeasureCode | 1,226 | moderate |
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works_cycles | What are the full names of the 10 youngest married male production technicians? | youngest refers to latest BirthDate; married refers to MaritalStatus = 'M'; production technician is a JobTitle; full name = FirstName+MiddleName+LastName; | SELECT T2.FirstName, T2.MiddleName, T2.LastName FROM Employee AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.JobTitle LIKE 'Production Technician%' AND T1.Gender = 'M' AND T1.MaritalStatus = 'M' ORDER BY T1.BirthDate DESC LIMIT 10 | 2,329 | moderate |
works_cycles | How much is the total bonus received by sales person and what is the percentage of it against the projected yearly sales quota in 2013? | projected yearly sales quota refers to SalesQuota; projected yearly sales quota in 2013 refers to year(QuotaDate) = 2013; percentage = (MULTIPLY(DIVIDE(SUM(Bonus)), (SUM(SalesQuota))) as percentage; | SELECT SUM(T1.Bonus) , CAST(SUM(T1.Bonus) AS REAL) * 100 / SUM(T1.SalesQuota) FROM SalesPerson AS T1 INNER JOIN SalesPersonQuotaHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE STRFTIME('%Y', T2.QuotaDate) = '2013' | 2,721 | moderate |
works_cycles | Among the employees who are married and wish to receive e-mail promotions, how much higher is their highest pay rate from the average pay rate? | married refers to MaritalStatus = 'M'; Contact does wish to receive e-mail promotions from Adventure Works refers to EmailPromotion = 1; Average = Divide (Sum(Rate (MaritalStatus = 'M' & EmailPromotion = 1))), Count (BusinessEntityID (MaritalStatus = 'M' & EmailPromotion = 1)); MAX(Rate (MaritalStatus = 'M' & EmailPromotion = 1) - Average; | SELECT MAX(T1.Rate) - SUM(T1.Rate) / COUNT(T1.BusinessEntityID) FROM EmployeePayHistory AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Employee AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID WHERE T2.EmailPromotion = 2 AND T3.MaritalStatus = 'M' | 3,546 | challenging |
works_cycles | List the name of the rates that apply to the provinces that are in the territory that obtained the greatest increase in sales with respect to the previous year. | sales of previous year refers to SalesLastYear; SalesYTD refers to year to date sales; increase in sales = DIVIDE(SUBTRACT(SalesYTD, SalesLastYear), SalesLastYear)*100 | SELECT T2.Name FROM SalesTerritory AS T1 INNER JOIN StateProvince AS T2 ON T1.CountryRegionCode = T2.CountryRegionCode INNER JOIN SalesTaxRate AS T3 ON T2.StateProvinceID = T3.StateProvinceID ORDER BY (T1.SalesYTD - T1.SalesLastYear) / T1.SalesLastYear DESC LIMIT 1 | 4,665 | challenging |
works_cycles | What is the PreferredVendorStatus for the company which has the rowguid of "684F328D-C185-43B9-AF9A-37ACC680D2AF"? | PreferredVendorStatus = 1 means 'Do not use if another vendor is available'; CreditRating = 2 means 'Preferred over other vendors supplying the same product' | SELECT T1.PreferredVendorStatus FROM Vendor AS T1 INNER JOIN BusinessEntity AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T2.rowguid = '684F328D-C185-43B9-AF9A-37ACC680D2AF' | 1,068 | moderate |
works_cycles | List the first and last name of all unmarried male Production Supervisors. | unmarried refers to MaritalStatus = 'S', male refers to Gender = 'M', Production Supervisors is a job title | SELECT T2.FirstName, T2.LastName FROM Employee AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.MaritalStatus = 'S' AND T1.Gender = 'M' AND T1.JobTitle LIKE 'Production Supervisor%' | 3,007 | moderate |
works_cycles | For all phone numbers, what percentage of the total is cell phone? | Cellphone referes to the name of the phone type, therefore PhoneNumberTypeID = 1; DIVIDE(COUNT(PhoneNumberTypeID = 1), (COUNT(PhoneNumberTypeID)) as percentage | SELECT CAST(SUM(CASE WHEN T2.Name = 'Cell' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T2.Name) FROM PersonPhone AS T1 INNER JOIN PhoneNumberType AS T2 ON T1.PhoneNumberTypeID = T2.PhoneNumberTypeID | 2,648 | moderate |
works_cycles | Among the low quality product, which product has the highest line total? List the product name and its line total? | Low quality refers to the product's quality class, therefore Class = 'L' | SELECT T1.Name, T2.LineTotal FROM Product AS T1 INNER JOIN PurchaseOrderDetail AS T2 ON T1.ProductID = T2.ProductID WHERE Class = 'L' ORDER BY OrderQty * UnitPrice DESC LIMIT 1 | 3,617 | moderate |
works_cycles | Which vendor's selling price for Hex Nut 5 is the lowest, please give the vendor's name. | vendor's selling price refers to StandardPrice; lowest selling price = MIN(StandardPrice) | SELECT T3.Name FROM ProductVendor AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Vendor AS T3 ON T1.BusinessEntityID = T3.BusinessEntityID WHERE T2.Name = 'Hex Nut 5' ORDER BY T1.StandardPrice LIMIT 1 | 5,012 | moderate |
works_cycles | Provide the business entity ID who did not achieved projected yearly sales quota in 2013. | projected yearly sales quota refers to SalesQuota; sales quota in 2013 refers to year(QuotaDate) = 2013; person who did not achieve projected yearly sales quota refers to SalesQuota>SalesYTD; | SELECT DISTINCT T1.BusinessEntityID FROM SalesPerson AS T1 INNER JOIN SalesPersonQuotaHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE STRFTIME('%Y', T2.QuotaDate) = '2013' AND T1.SalesQuota < T1.SalesLastYear | 4,771 | moderate |
works_cycles | Calculate the average length of employment for employee working in the Research and Development deparment. | average length of employment = AVG(subtract(2022, year(HireDate))) | SELECT AVG(STRFTIME('%Y', CURRENT_TIMESTAMP) - STRFTIME('%Y', T1.HireDate)) FROM Employee AS T1 INNER JOIN EmployeeDepartmentHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T2.DepartmentID = T3.DepartmentID WHERE T3.Name = 'Research and Development' | 2,789 | challenging |
works_cycles | Who made the purchase order with the greatest total due before freight? Indicate her employee ID and calculate for his/her age when he/she was hired. | total due before freight = SUBTRACT(TotalDue, Freight); age at the time an employee was hired = SUBTRACT(HireDate, year(BirthDate); | SELECT T2.BusinessEntityID, STRFTIME('%Y', T2.HireDate) - STRFTIME('%Y', T2.BirthDate) FROM PurchaseOrderHeader AS T1 INNER JOIN Employee AS T2 ON T1.EmployeeID = T2.BusinessEntityID ORDER BY T1.TotalDue DESC LIMIT 1 | 3,793 | moderate |
works_cycles | Based on the lastet payrate of each employee, calculate the average hourly payrate for each department. | latest payrate refers to max(RateChangeDate); average hourly payrate = divide(sum(Rate), count(BusinessEntityID)) for each DepartmentID | SELECT AVG(T1.Rate) FROM EmployeePayHistory AS T1 INNER JOIN EmployeeDepartmentHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T2.DepartmentID = T3.DepartmentID WHERE T1.RateChangeDate = ( SELECT MAX(T1.RateChangeDate) FROM EmployeePayHistory AS T1 INNER JOIN Department AS T2 ON T1.BusinessEntityID = T2.DepartmentID ) | 5,618 | challenging |
works_cycles | What product has the fewest online orders from one customer? List the product's class, line of business, and list price. | fewest online orders refer to MIN(Quantity); | SELECT T2.Class, T2.ProductLine, T2.ListPrice FROM ShoppingCartItem AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID GROUP BY T1.ProductID ORDER BY SUM(Quantity) LIMIT 1 | 5,930 | moderate |
works_cycles | What is the salary rate per hour that the company paid to the first 5 employees that they hired? | salary rate per hour refers to Rate; first 5 employees that were hired refers to 5 oldest HireDate; | SELECT T1.Rate FROM EmployeePayHistory AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Person AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID ORDER BY T2.HireDate ASC LIMIT 0, 5 | 5,933 | moderate |
works_cycles | How much do the works data saved in English and Arabic differ from one another? | Data saved in English refers to the name of the language where Culture.Name = 'English'; data saved in Arabic refers to the name of the language where Culture.Name = 'Arabic'; SUBTRACT(count(Name = 'English'), count(Name = 'Bothell')) | SELECT SUM(CASE WHEN T1.Name = 'English' THEN 1 ELSE 0 END) - SUM(CASE WHEN T1.Name = 'Arabic' THEN 1 ELSE 0 END) FROM Culture AS T1 INNER JOIN ProductModelProductDescriptionCulture AS T2 ON T1.CultureID = T2.CultureID WHERE T1.Name = 'English' OR T1.Name = 'Arabic' | 2,586 | challenging |
works_cycles | Please give the personal information of the married employee who has the highest pay rate. | married refers to MaritalStatus = 'M'; Highest pay rate refers to Max(Rate) | SELECT T2.Demographics FROM Employee AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN EmployeePayHistory AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID WHERE T1.MaritalStatus = 'M' ORDER BY T3.Rate DESC LIMIT 1 | 1,375 | moderate |
works_cycles | Among the employees who wish to receive e-mail promotion from AdventureWorks, how many percent of them are female? | female refers to Gender = 'F'; employee who wish to receive email promotion refers to EmailPromotion = 1; percentage = DIVIDE(SUM(Gender = 'F')), (sum(Gender = 'F' or Gender = 'M'))) as percentage; | SELECT CAST(SUM(CASE WHEN T1.Gender = 'F' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.BusinessEntityID) FROM Employee AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T2.EmailPromotion = 1 | 3,161 | moderate |
works_cycles | How many accounts are in Bothell as opposed to Kenmore? What is the name of the State that comprises these two cities? | SUBTRACT(count(city = 'Bothell'), count(city = 'Kenmore')) | SELECT SUM(IIF(T1.city = 'Bothell', 1, 0)) - SUM(IIF(T1.city = 'Kenmore', 1, 0)) , stateprovincecode FROM Address AS T1 INNER JOIN StateProvince AS T2 ON T1.stateprovinceid = T2.stateprovinceid GROUP BY stateprovincecode | 1,590 | moderate |
works_cycles | Among the Production Technicians who are single, how many of them are vendor contact? | Production Technicians refer to the JobTitle = 'Production Technician%'; single refers to MaritalStatus = 'S'; Vendor contact refers to PersonType = 'VC' | SELECT COUNT(T1.BusinessEntityID) FROM Employee AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.JobTitle LIKE 'Production Technician%' AND T1.MaritalStatus = 'S' AND T2.PersonType = 'VC' | 2,449 | moderate |
works_cycles | What percentage of AdventureWorks employees are men? | male refers to Gender = 'M'; employee refers to PersonType = 'EM'; percentage = DIVIDE(COUNT(Gender = 'M'), COUNT(PersonType = 'MY'))*100%; | SELECT CAST(SUM(CASE WHEN T2.Gender = 'M' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.BusinessentityID) FROM Person AS T1 INNER JOIN Employee AS T2 ON T1.BusinessentityID = T2.BusinessentityID WHERE T1.PersonType = 'EM' | 5,016 | moderate |
works_cycles | What percentage of the AdventureWorks data is in Thai? | percentage = DIVIDE(Culture.Name = 'Thai', count(ALL Culture.Name))*100% | SELECT CAST(SUM(CASE WHEN T1.Name = 'Thai' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.CultureID) FROM Culture AS T1 INNER JOIN ProductModelProductDescriptionCulture AS T2 ON T1.CultureID = T2.CultureID | 4,462 | moderate |
works_cycles | Name all products that started selling in 2013. State its respective vendor's name. | Started selling in 2013 refers to year(SellStartDate) = 2013; | SELECT T1.Name, T3.Name FROM Product AS T1 INNER JOIN ProductVendor AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Vendor AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID WHERE STRFTIME('%Y', T1.SellStartDate) = '2013' | 608 | moderate |
works_cycles | As of 12/31/2011, how long has the employee assigned to all pending for approval papers been working in the company from the date he was hired? | pending for approval papers refer to Status = 1; length of stay in the company as of 12/31/2011 = SUBTRACT(2011, year(HireDate)); | SELECT 2011 - STRFTIME('%Y', T2.HireDate) FROM Document AS T1 INNER JOIN Employee AS T2 ON T1.Owner = T2.BusinessEntityID WHERE T1.Status = 1 | 6,466 | moderate |
works_cycles | If a married employee has a western name style, what is the probability of him or her working as a store contact? | married refers to MaritalStatus = 'M'; western name style refers to NameStyle = 0; store contact refers to PersonType = 'SC'; probability = Divide (Count (BusinessEntityID( PersonType = 'SC' & MaritalStatus = 'M')), Count (BusinessEntityID ( PersonType) & MariatlStatus = 'M'))
| SELECT CAST(COUNT(IIF(T1.PersonType = 'SC', T1.PersonType, NULL)) AS REAL) / COUNT(T1.PersonType) FROM Person AS T1 INNER JOIN Employee AS T2 WHERE T1.PersonType = 'SC' AND T1.NameStyle = 0 AND T2.MaritalStatus = 'M' | 678 | moderate |
works_cycles | Name the oldest employee who is working on night shift. How old is the employee? | working on night shift refers to ShiftID = 3; oldest employee refers to min(BirthDate); age = 2022-year(BirthDate)+1 | SELECT T1.FirstName, T1.LastName , STRFTIME('%Y', CURRENT_TIMESTAMP) - STRFTIME('%Y', BirthDate) FROM Person AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN EmployeeDepartmentHistory AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID WHERE T3.ShiftId = 3 ORDER BY STRFTIME('%Y', CURRENT_TIMESTAMP) - STRFTIME('%Y', BirthDate) DESC LIMIT 1 | 1,373 | challenging |
works_cycles | What is the position of the employee with the 10th highest salary? Indicate his/her salary amount and his/her full name. | salary and Rate are synonyms; full name = FirstName+MiddleName+LastName; | SELECT T2.JobTitle, T1.Rate, T3.FirstName, T3.MiddleName, T3.LastName FROM EmployeePayHistory AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Person AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID ORDER BY T1.Rate DESC LIMIT 9, 1 | 2,378 | challenging |
works_cycles | What is the highest amount of difference between the ordered quantity and actual quantity received in a single purchase order and to which vendor was the purchase order made? | highest amount of difference between the ordered quantity and actual quantity received in a single purchase order refers to MAX(SUBTRACT(OrderQty, ReceivedQty)); | SELECT T2.OrderQty - T2.ReceivedQty, VendorID FROM PurchaseOrderHeader AS T1 INNER JOIN PurchaseOrderDetail AS T2 ON T1.PurchaseOrderID = T2.PurchaseOrderID ORDER BY T2.OrderQty - T2.ReceivedQty DESC LIMIT 1 | 5,582 | moderate |
works_cycles | For all the employees that have left the Engineering Department, what is the average time of their stay? | employees who left a department refers to EndDate NOT null; average stay = AVG(SUBTRACT(year(EndDate)), (year(T1.StartDate))); | SELECT CAST(SUM(365 * (STRFTIME('%Y', T1.EndDate) - STRFTIME('%Y', T1.StartDate)) + 30 * (STRFTIME('%m', T1.EndDate) - STRFTIME('%m', T1.StartDate)) + STRFTIME('%d', T1.EndDate) - STRFTIME('%d', T1.StartDate)) AS REAL) / COUNT(T1.BusinessEntityID) FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID WHERE T2.Name = 'Engineering' AND T1.EndDate IS NOT NULL | 2,949 | challenging |
works_cycles | What is the age of the oldest Marketing Specialist by 12/31/2015 and what is his/her hourly rate? | age as of 12/31/2015 = SUBTRACT(2015, year(BirthDate)); hourly rate refers to Rate; | SELECT 2015 - STRFTIME('%Y', T1.BirthDate), T2.Rate FROM Employee AS T1 INNER JOIN EmployeePayHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.JobTitle = 'Marketing Specialist' ORDER BY 2015 - STRFTIME('%Y', T1.BirthDate) DESC LIMIT 1 | 2,428 | moderate |
works_cycles | If we discount the products that do not have any type of offer, how many different products have been sold in an amount greater than 2 units per order? | do not have any type of offer refers to Description = 'No Discount'; sold in an amount greater than 2 refers to OrderQty>2 | SELECT COUNT(DISTINCT T1.ProductID) FROM SalesOrderDetail AS T1 INNER JOIN SpecialOfferProduct AS T2 ON T1.SpecialOfferID = T2.SpecialOfferID INNER JOIN SpecialOffer AS T3 ON T2.SpecialOfferID = T3.SpecialOfferID WHERE T1.OrderQty > 2 AND T1.UnitPriceDiscount = 0 | 5,400 | challenging |
works_cycles | Name the sales person for store Area Bike Accessories. Which territory is he / she in? | SELECT T4.Name FROM Store AS T1 INNER JOIN SalesPerson AS T2 ON T1.SalesPersonID = T2.BusinessEntityID INNER JOIN Person AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID INNER JOIN SalesTerritory AS T4 ON T2.TerritoryID = T4.TerritoryID WHERE T1.Name = 'Area Bike Accessories' | 3,654 | moderate |
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works_cycles | What is the percentage, by number of sales order units, for orders with quantities not greater than 3 and a discount of 0.2? | quantities not greater than 3 refers to OrderQty<3; discount of 0.2 refers to UnitPriceDiscount = 0.2; percentage = DIVIDE(count(SalesOrderID(OrderQty<3 & UnitPriceDiscount = 0.2)), count(SalesOrderID))*100% | SELECT CAST(SUM(CASE WHEN OrderQty < 3 AND UnitPriceDiscount = 0.2 THEN 1 ELSE 0 END) AS REAL) / COUNT(SalesOrderID) FROM SalesOrderDetail | 2,753 | moderate |
works_cycles | Among the married employees with the highest pay frequency, how many of them have an eastern name style? | married refers to MaritalStatus = 'M'; Eastern name style refers to NameStyle = 1; | SELECT COUNT(T1.BusinessEntityID) FROM Employee AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN EmployeePayHistory AS T3 ON T2.BusinessEntityID = T3.BusinessEntityID WHERE T1.MaritalStatus = 'M' AND T2.NameStyle = 1 AND T3.Rate = ( SELECT Rate FROM EmployeePayHistory ORDER BY Rate DESC LIMIT 1 ) | 2,562 | challenging |
works_cycles | Among the employees whose pay frequencies are the highest, how many of them are married? | married refers to MaritalStatus = M; highest pay frequency refers to PayFrequency = 2 | SELECT COUNT(T1.BusinessEntityID) FROM EmployeePayHistory AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T2.MaritalStatus = 'M' AND T1.PayFrequency = ( SELECT PayFrequency FROM EmployeePayHistory ORDER BY PayFrequency DESC LIMIT 1 ) | 4,512 | moderate |
works_cycles | Where does the person with the BusinessEntityID "5555" live? | where the person live refers addresstype.Name = 'Home' | SELECT T3.City, T3.AddressLine1 FROM BusinessEntityAddress AS T1 INNER JOIN AddressType AS T2 ON T1.AddressTypeID = T2.AddressTypeID INNER JOIN Address AS T3 ON T1.AddressID = T3.AddressID WHERE T1.BusinessEntityID = 5555 AND T2.Name = 'Home' | 5,206 | moderate |
works_cycles | Among the active employees with over 10 hours of sick leave, what is the percentage of the employees with over 20 vacation hours? | CurrentFlag = 1 refers to the active status of employees; Percentage = Divide (Count (BusinessEntityID (CurrentFlag = 1 & VacationHours >20 & SickLeaveHours > 10)), Count (BusinessEntityID (CurrentFlag = 1 & SickLeaveHours>10))) * 100; | SELECT CAST(SUM(CASE WHEN T2.VacationHours > 20 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.BusinessEntityID) FROM EmployeePayHistory AS T1 INNER JOIN Employee AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T2.CurrentFlag = 1 AND T2.SickLeaveHours > 10 | 4,476 | challenging |
works_cycles | What are the total per assembly quantity for unit measure code EA, IN and OZ respectively? What are the name of these 3 code? | Pre assembly quantity refers to PerAssemblyQty | SELECT SUM(T1.PerAssemblyQty), T2.Name FROM BillOfMaterials AS T1 INNER JOIN UnitMeasure AS T2 ON T1.UnitMeasureCode = T2.UnitMeasureCode WHERE T1.UnitMeasureCode IN ('EA', 'IN', 'OZ') GROUP BY T2.Name | 1,768 | moderate |
works_cycles | What type of transaction was made with the only yellow product, size 62 and with a minimum inventory stock of 500 units? | yellow product refers to Color = 'Yellow'; minimum inventory stock of 500 units refers to SafetyStockLevel = 500 | SELECT DISTINCT T2.TransactionType FROM Product AS T1 INNER JOIN TransactionHistory AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Size = 62 AND T1.Color = 'Yellow' AND T1.SafetyStockLevel = 500 | 6,042 | moderate |
works_cycles | Please list the names of all the store contact employees whose credit cards expired in 2007. | year of credit card expiration refers to ExpYear; ExpYear = 2007; store contact refers to PersonType = 'SC'; | SELECT T1.FirstName, T1.LastName FROM Person AS T1 INNER JOIN PersonCreditCard AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN CreditCard AS T3 ON T2.CreditCardID = T3.CreditCardID WHERE T3.ExpYear = 2007 AND T1.PersonType = 'SC' | 6,359 | moderate |
works_cycles | How many people were there in the Engineering Department in the year 2009? | year(EndDate)>2009 and year(StartDate)<2009; | SELECT COUNT(T1.BusinessEntityID) FROM Person AS T1 INNER JOIN EmployeeDepartmentHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T2.DepartmentID = T3.DepartmentID WHERE T3.Name = 'Engineering' AND STRFTIME('%Y', T2.EndDate) > '2009' AND STRFTIME('%Y', T2.StartDate) < '2009' | 2,435 | challenging |
Subsets and Splits