# GNU Enterprise Forms - GF Object Hierarchy - Box
#
# Copyright 2001-2007 Free Software Foundation
#
# This file is part of GNU Enterprise
#
# GNU Enterprise is free software; you can redistribute it
# and/or modify it under the terms of the GNU General Public
# License as published by the Free Software Foundation; either
# version 2, or (at your option) any later version.
#
# GNU Enterprise is distributed in the hope that it will be
# useful, but WITHOUT ANY WARRANTY; without even the implied
# warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR
# PURPOSE. See the GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public
# License along with program; see the file COPYING. If not,
# write to the Free Software Foundation, Inc., 59 Temple Place
# - Suite 330, Boston, MA 02111-1307, USA.
#
# $Id: GFHBox.py,v 1.4 2009/07/24 15:00:16 oleg Exp $
"""
Logical box support
"""

from GFBox import GFBox
from GFVBox import GFVBox

__all__ = ['GFHBox']

# =============================================================================
# <hbox>
# =============================================================================

class GFHBox(GFBox):

	# -------------------------------------------------------------------------
	# Constructor
	# -------------------------------------------------------------------------

	def __init__(self, parent=None):
		GFBox.__init__(self, parent, "GFHBox")


	# -------------------------------------------------------------------------
	# Indicate whether this widget makes use of the separate label column
	# -------------------------------------------------------------------------

	def hasLabel(self):

		if not isinstance(self.getParent(), GFVBox):
			return False

		# If any of our children is a VBox or uses a label, we draw a box
		# around ourselves. Otherwise, use the label column of the containing
		# box.
		for child in self._children:
			if isinstance(child, GFVBox) or isinstance(child, GFHBox):
				return False
			if hasattr(child, 'has_label') and child.has_label:
				return False
		return True
